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Most Repeated MDCAT Physics: Magnetism and Electromagnetic Induction MCQs
The most repeated Magnetism and Electromagnetic Induction questions in MDCAT Physics, measured from 377 real past papers. Magnetism and Electromagnetic Induction contributed 625 questions across those papers, and 24 distinct questions recurred with the same verified answer across 2 or more different exam years — listed below (ranked by how many years each recurs in), with the answer, an explanation, and the exact years.
Measured from 377 real past papers · updated July 2026
- 1Repeated in 3 yearsMagnetism and Electromagnetic Induction
A 3-cm length of wire is moved at right angles across a uniform magnetic field with a speed of 2.0 m/s . If the flux density is 5.0 teslas, what is the magnitude of the induced e.m.f?
- A0.03 V
- B0.3 V✓
- C0.6 V
- D10 V
- E20 V
Appeared in the past papers of: 2012, 2014, 2016
- 2Repeated in 3 yearsMagnetism and Electromagnetic Induction
A conductor carrying a current I has length L. when it is placed in a magnetic field, B at 90° it experiences a force
- ABIL✓
- BB/IL
- CIL/B
Appeared in the past papers of: 2016, 2023, 2024
- 3Repeated in 2 yearsMagnetism and Electromagnetic Induction
The diagram shows a wire, carrying a current 'I', placed between the poles of a magnet. In which direction does the force on the wire act?
- AUpwards
- BDownwards✓
- CTowards the ‘N’ pole of the magnet
- DTowards the ‘S’ pole of the magnet
Explanation
We can determine the direction of the force on the current-carrying wire using Fleming's Left-Hand Rule.Step-by-step explanation:Magnetic field direction (B):It is from the North (N) pole to the South (S) pole (left to right).Current direction (I):The current is going upwards (as shown by the arrow labeled I).Force direction (F):By Fleming's Left-Hand Rule:First finger = Magnetic field (left to right),Second finger = Current (upwards),Thumb = Force (direction of motion).When you align your left hand as per this rule, the thumb points out of the page (towards you).
Appeared in the past papers of: 2011, 2013
- 4Repeated in 2 yearsMagnetism and Electromagnetic Induction
A proton is projected with a uniform velocity ‘v’ along the axis of a current carrying solenoid.
- AThe proton will be accelerated along the axis.
- BThe proton path will be circular about the axis.
- CThe proton moves along a helical path.
- DThe proton will continue to move with velocity ‘v’ along the axis.✓
Explanation
The proton is traveling in the same direction as the solenoid’s axis. Because the magnetic field inside the solenoid is homogenous and parallel to the solenoid, it has no effect on the proton's velocity and it is parallel to the magnetic field( net force on proton is zero) The angle between B and V= 00 According to Lorentz's formula F=q(VxB) or F=qVBsinΘ Here sinΘ =0 this means there will be no force due to the magnetic field at all hence the proton will continue to move with the same velocity along the axis. Since there is no effect on the velocity of the proton so the proton cannot be accelerated along the axis. The proton cannot move in a helical path also.
Appeared in the past papers of: 2017, 2020
- 5Repeated in 2 yearsMagnetism and Electromagnetic Induction
The induced current flow in such a direction so as to oppose the cause that produces it. The statement is:
- AAmpere’s Law
- BFaraday’s Law
- CLenz’s Law✓
- DJoule’s Law
Explanation
Lenz's law, in electromagnetism, states that an induced electric current flows in a direction such that the current opposes the change that induced it.
Appeared in the past papers of: 2023, 2024
- 6Repeated in 2 yearsMagnetism and Electromagnetic Induction
A magnetic field is a region in which a force is experienced on a moving charge or a magnet. This force depends upon:I. The magnitude of charge qII. The speed of the moving charge vIII. The magnetic field of induction B
- AI only
- BII only
- CIII only
- D. I and II only
- EI, II and III✓
Explanation
We know that the force acting on the charge is F = qvBAccording to the formula, it depends on the charge q, its velocity v and the magnetic field in the region B. Hence, option E is correct.
Appeared in the past papers of: 2010, 2011
- 7Repeated in 2 yearsMagnetism and Electromagnetic Induction
When a transformer is connected to 120-volt ac, it supplies 3000 V to a device. The current through the secondary winding then is o.06 A and the current through the primary is 2 A. The number of turns in the primary winding is 400. The number of turns in the secondary winding is:
- A16
- B30
- C1000
- D2000
- E10000✓
Appeared in the past papers of: 2012, 2016
- 8Repeated in 2 yearsMagnetism and Electromagnetic Induction
Which of the following refers to the DC current that does not change its intensity?
- AEddy's current
- BSurge current
- CLeakage current
- DSteady current✓
Explanation
The DC current which does not change its intensity is known as steady current. Hence option D is correct.
Appeared in the past papers of: 2023, 2024
- 9Repeated in 2 yearsMagnetism and Electromagnetic Induction
On which principle does the transformer work?
- ASelf induction
- BMutual induction✓
- CMotional EMF
- DMagnetic torque
Explanation
Transformer works on the principal of mutual induction, according to which; "The phenomenon in which a changing current in one coil induces an emf in anofher coil is called the mutual inductance." Hence, option B is correct.
Appeared in the past papers of: 2023, 2024
- 10Repeated in 2 yearsMagnetism and Electromagnetic Induction
If 1 transformer has 500 turns on the primary coil and 250 turns on the secondary coil, then
- AOutput voltage is half of input voltage✓
- BOutput and input voltages are equal
- COutput voltage is double the input voltage
- DOutput voltage is zero
Explanation
Using formula; Np/Ns = Vp/ Vs 500/250 = Vp/Vs 2 = Vp/Vs So Vp = 2Vs or Vs = Vp/2 Hence, secondary voltage or output voltage is half of input or primary voltage. So, option A is correct.
Appeared in the past papers of: 2023, 2024
- 11Repeated in 2 yearsMagnetism and Electromagnetic Induction
Which of the following defines the change in magnetic flux per unit area?
- AMagnetic field
- BMagnetic force
- CMagnetic dipole
- DMagnetic flux density✓
Explanation
Change in magnetic flux per unit area is Φ/A which is equal to B i.e. magnetic flux density. Φ = B . A Hence, option D is correct.
Appeared in the past papers of: 2023, 2024
- 12Repeated in 2 yearsMagnetism and Electromagnetic Induction
What is the dot product of magnetic induction and unit area?
- AMagnetic flux✓
- BMagnetic induction
- CMagnetic field
- DMagnetic pole
Explanation
Magnetic induction per unit Area is B/A which is equal to Φ i.e., magnetic flux Φ = B . A Hence, option A is correct.
Appeared in the past papers of: 2023, 2024
- 13Repeated in 2 yearsMagnetism and Electromagnetic Induction
What does the magnetic flux measure?
- AArea surrounded by a magnet
- BStrength of the magnetic field
- CRate of change of magnetic force
- DThe number of magnetic lines of force✓
Explanation
Magnetic flux is number of magnetic field lines passing through a surface placed perpendicular to it. Hence, option D is correct.
Appeared in the past papers of: 2023, 2024
- 14Repeated in 2 yearsMagnetism and Electromagnetic Induction
The function of a main transformer is to convert:
- Aone direct voltage to another direct voltage of different magnitude.
- Bone alternating voltage to another alternating voltage of different magnitude.✓
- Ca high value alternating voltage to low value direct voltage.
- DA high value alternating current to low value direct voltage
Explanation
A transformer converts a high voltage low current alternating current to a low voltage high current one and vice versa. Therefore the answer will be B.
Appeared in the past papers of: 2013, 2023
- 15Repeated in 2 yearsMagnetism and Electromagnetic Induction
When a transformer is connected to 120-volt ac, it supplies 300 V to a device. The current through the secondary winding then is 0.06 A and the current through the primary is 2 A. The number of turns in the primary winding is 400. The number of turns in the secondary winding is:
- A1200 turns
- B1000 turns✓
- C800 turns
- D600 turns
Explanation
To calculate the number of turns in the secondary winding, we can use the relationship between the voltage, current, and number of turns in a transformer:Formula:(Vs / Vp) = (Ns / Np)Where: Vs is the voltage in the secondary winding Vp is the voltage in the primary winding Ns is the number of turns in the secondary winding Np is the number of turns in the primary winding We are given: Vs = 300 V Vp = 120 V Np = 400 turns Is = 0.06 A Ip = 2 Substituting the values into the formula: (300 V / 120 V) = (Ns / 400 turns) Simplifying: 2.5 = (Ns / 400 turns) Solving for Ns: Ns = 2.5 * 400 turns = 1000 turnsTherefore, the number of turns in the secondary winding is 1000 turns.
Appeared in the past papers of: 2023, 2024
- 16Repeated in 2 yearsMagnetism and Electromagnetic Induction
The motional E.M.F depends upon:
- AStrength of magnetic field
- BSpeed of the conductor
- CLength of conductor
- DAll answers are correct✓
Explanation
The factors on which motional emf depends are the magnetic field and velocity and length of the rod. Thus option D is the correct answer.
Appeared in the past papers of: 2011, 2019
- 17Repeated in 2 yearsMagnetism and Electromagnetic Induction
The time rate of change of magnetic flux has the same dimension as that of:
- ACurrent
- BResistance
- CMagnetic induction
- DPotential difference✓
Explanation
The time rate of change of magnetic flux has the same dimensions as potential difference, which is measured in volts (V). Therefore, option d is correct.
Appeared in the past papers of: 2012, 2023
- 18Repeated in 2 yearsMagnetism and Electromagnetic Induction
A hydrogen atom that has lost its electron is moving east in a region where the magnetic field is directed from south to north. It will be deflected:
- AUp✓
- BDown
- CNorth
- DSouth
Explanation
The hydrogen atom, which is effectively a proton in this context since it has lost its electron, is moving east in a magnetic field directed from south to north. To find the direction of the magnetic force acting on the proton, we can use the right-hand rule. For a positive charge like a proton, point your right thumb in the direction of the velocity (east), and your fingers in the direction of the magnetic field (north). The direction in which your palm pushes will indicate the direction of the magnetic force, which is upwards in this case. Therefore, the correct answer is up.Option B (down) is incorrect because the right-hand rule does not support this direction.
Appeared in the past papers of: 2016, 2023
- 19Repeated in 2 yearsMagnetism and Electromagnetic Induction
A moving charged particle is surrounded by?
- A1 field
- B3 fields✓
- C2 fields
- D4 fields
Explanation
A moving charged particle is surrounded by three fields:Electric Field: This field arises due to the charge of the particle itself and affects other charges in its vicinity.Magnetic Field: Generated due to the movement of the charge. The interaction between charge and motion creates this field.Gravitational Field: The mass of the particle generates a gravitational field, albeit usually very weak compared to the other two fields.Option A (1 field) is incorrect because it ignores the presence of the magnetic and gravitational fields. Option C (2 fields) is incorrect as it overlooks the gravitational field.
Appeared in the past papers of: 2016, 2023
- 20Repeated in 2 yearsMagnetism and Electromagnetic Induction
A photon while passing through a magnetic field is deflected towards:
- ANorth pole
- BAre ionized
- CSouth pole
- DNone of these✓
Explanation
Option D) "None of these" is the correct optionPhotons, as electromagnetic waves, do not carry an electric charge, and they are not affected by magnetic fields. Magnetic fields only interact with charged particles, causing them to experience a magnetic force and possibly get deflected.Since photons are uncharged, they do not experience any deflection or interaction with a magnetic field. Therefore, the correct choice is "none of these" because the magnetic field does not affect photons.
Appeared in the past papers of: 2016, 2023
- 21Repeated in 2 yearsMagnetism and Electromagnetic Induction
The unit of magnetic flux is:
- ATesla
- BWeber✓
- CGauss
- DHenry
Explanation
The unit of magnetic flux is the Weber (Wb).
Appeared in the past papers of: 2022, 2023
- 22Repeated in 2 yearsMagnetism and Electromagnetic Induction
An electron is moving along the axis of a solenoid carrying a current. Which of the following is a correct statement about the electromagnetic force acting on the electron?
- AThe force acts radially inwards
- BThe force acts radially outwards
- CThe force acts in the direction of motion
- DNo force acts✓
Explanation
The question states along the axis of a solenoid. This implies that the Magnetic feild is parallel to the direction of current (For magnetic force to act, it is necessary that the direction of current and magentic feild are perpendicular to eachother) Therefore, no force acts and electron moves straight through without getting deflected.
Appeared in the past papers of: 2017, 2018
- 23Repeated in 2 yearsMagnetism and Electromagnetic Induction
Find the radius of an orbit of an electron moving at a rate of 2.0 x 107 m/s in a uniform magnetic field of 1.20 x 10-3 T.
- A3.15 m
- B4.25 m
- C9.93 m✓
- D17.77 m
- E19.91 m
Explanation
r = (m * v) / (q * B) Given:m = 9.109 x 10^-31 kgv = 2.0 x 10^7 m/s q = -1.6 x 10^-19 C B = 1.20 x 10^-3 T Now, let's calculate the radius (r):r = (9.109 x 10^-31 kg * 2.0 x 10^7 m/s) / (1.6 x 10^-19 C * 1.20 x 10^-3 T)r ≈ 9.93 mThe correct option is C. 9.93 m.
Appeared in the past papers of: 2014, 2015
- 24Repeated in 2 yearsMagnetism and Electromagnetic Induction
In fleming's right hand rule, the second finger indicates:
- AOption A: Force
- BOption B: Induced current✓
- COption C: Magnetic field
- DOption D: Motion
Explanation
In Fleming's right hand rule, the fingers of the right hand are used to determine the direction of induced current in a conductor moving through a magnetic field. The thumb indicates the direction of motion, the index finger represents the direction of the magnetic field (from North to South), and the middle finger, which is the second finger, indicates the direction of the induced current in the conductor. Therefore, option B is correct as it accurately reflects the role of the second finger in this rule. Options A, C, and D are incorrect because they misattribute the functions of the fingers to different concepts related to electromagnetism.
Appeared in the past papers of: 2022, 2024