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Chapter 14 of 20 · Chemistry
Hydrocarbons
Hydrocarbons averages 3 MCQs per MDCAT paper, dominated by Markovnikov addition, ozonolysis, Friedel-Crafts, and free-radical halogenation.
Hydrocarbons is a Chemistry chapter on the official PMDC MDCAT 2026 syllabus, contributing roughly 3 MCQs to the 45-MCQ Chemistry section. Mastering the core concepts below typically secures the full chapter weightage.
Alkanes — saturated, sp3, and sluggish
Alkanes (CnH2n+2) react only by free-radical substitution and combustion. Halogenation: CH4 + Cl2 → CH3Cl + HCl proceeds by initiation (Cl2 → 2Cl• under UV), propagation (Cl• + CH4 → HCl + CH3•; CH3• + Cl2 → CH3Cl + Cl•), and termination. Selectivity follows radical stability 3° > 2° > 1°, but Cl is less selective than Br because of its highly exothermic abstraction step (Hammond postulate, Clayden Chapter 39). Synthesis: Wurtz reaction (2RX + 2Na → R-R + 2NaX) couples two alkyl halides; Kolbe's electrolysis of carboxylate salts gives R-R at the anode.
Alkenes — electrophilic addition central
The π-bond is electron-rich and attacks electrophiles. HBr addition to propene gives 2-bromopropane via the more stable secondary carbocation (Markovnikov rule: H goes to the carbon with more H's, Br to the more substituted carbon). With peroxides (ROOR), the regiochemistry inverts: HBr adds anti-Markovnikov via a free-radical mechanism, giving 1-bromopropane. Hydration with dilute H2SO4 gives Markovnikov alcohols; oxymercuration-demercuration achieves the same without rearrangement; hydroboration-oxidation (BH3 then H2O2/OH−) gives anti-Markovnikov alcohols. Bromine adds via a bromonium ion to give anti dibromides. Ozonolysis (O3 then Zn/H2O) cleaves C=C to two carbonyls — used to locate double-bond positions. KMnO4 (cold, dilute) gives a syn-diol (Baeyer's test); hot KMnO4 cleaves to acids/ketones.
Alkynes — terminal acidity and triple-bond chemistry
Terminal alkynes (RC≡CH) are weakly acidic (pKa ≈ 25); NaNH2 deprotonates them to acetylides RC≡C−, powerful nucleophiles for SN2 alkylation. Hydration (HgSO4/H2SO4) gives an enol that tautomerises to a methyl ketone (Markovnikov), except for ethyne which gives acetaldehyde. Hydroboration-oxidation gives the anti-Markovnikov aldehyde. Lindlar's catalyst (Pd/CaCO3 + Pb) gives cis-alkenes; Na/liq NH3 gives trans-alkenes. Cu2Cl2/NH4Cl gives a red Cu acetylide, AgNO3/NH3 gives a white Ag acetylide — classic identification tests for terminal alkynes.
Aromatics and Friedel-Crafts
Benzene's six π electrons form a delocalised system stabilised by 150 kJ/mol of resonance energy. It undergoes electrophilic aromatic substitution (EAS) rather than addition, preserving aromaticity. The five named EAS reactions: nitration (HNO3/H2SO4, electrophile NO2+), sulphonation (oleum, SO3), halogenation (X2/FeX3), Friedel-Crafts alkylation (RCl/AlCl3, electrophile R+ — beware rearrangements!), Friedel-Crafts acylation (RCOCl/AlCl3, electrophile RC=O+). Activating, ortho/para-directing groups: -OH, -NH2, -OR, -R. Deactivating, meta-directing: -NO2, -CN, -COOH, -CHO. The halogens are deactivating but ortho/para-directing — the classic exception.
Mechanism summary and trap-spotters
Markovnikov vs anti-Markovnikov hinges on whether the intermediate is a carbocation (Markovnikov, polar HX) or a radical (anti-Markovnikov, HBr + ROOR). Carbocations rearrange (1,2-H or 1,2-CH3 shifts) — this is why Friedel-Crafts alkylation of benzene with 1-chloropropane gives mostly isopropylbenzene. Aldol, Cannizzaro, and other carbonyl reactions belong to the next chapter; for hydrocarbons, fixate on ozonolysis products, Lindlar/Na-NH3 stereochemistry, and EAS directing effects. Morrison & Boyd Chapters 6-12 and FSc Chemistry XII Chapters 9-10 cover these in MDCAT depth.
Key Concepts
- Alkanes (free radical)
- Alkenes (electrophilic addition)
- Alkynes
- Aromatics & benzene
- Markovnikov's rule
Worked MCQs
Q1. HBr adds to propene in the presence of peroxide to give predominantly:
- A. 2-bromopropane
- B. 1-bromopropane ✓
- C. 1,2-dibromopropane
- D. Propan-2-ol
Explanation: Peroxides switch the mechanism to free-radical, giving anti-Markovnikov addition; Br adds to the terminal (less substituted) carbon.
Common trap: Applying Markovnikov by reflex — the peroxide effect (Kharasch effect) reverses regiochemistry only for HBr, not HCl or HI.
Q2. Ozonolysis of 2-methylbut-2-ene followed by Zn/H2O gives:
- A. Acetone and acetaldehyde ✓
- B. Two equivalents of acetone
- C. Acetone and formaldehyde
- D. Butanone and methanol
Explanation: (CH3)2C=CHCH3 cleaves at the C=C: (CH3)2C=O (acetone) and CH3CHO (acetaldehyde).
Common trap: Forgetting that ozonolysis splits the C=C into two separate carbonyls.
Q3. Which catalyst gives cis-alkenes from alkynes?
- A. H2/Pt
- B. Lindlar's catalyst ✓
- C. Na/liq NH3
- D. BH3 then H2O2/OH-
Explanation: Lindlar (Pd/CaCO3 poisoned with Pb) does syn addition of H2 to give cis-alkene; Na/NH3 gives trans.
Common trap: Picking H2/Pt — it over-reduces to the alkane.
Q4. In Friedel-Crafts alkylation of benzene with 1-chloropropane and AlCl3, the major product is:
- A. n-propylbenzene
- B. Isopropylbenzene (cumene) ✓
- C. 3-chloropropylbenzene
- D. Propene
Explanation: The primary propyl cation rearranges via 1,2-H shift to the more stable secondary isopropyl cation before attack on benzene.
Common trap: Assuming the alkyl group attaches unchanged — carbocation rearrangement is the defining flaw of FC alkylation.
Q5. Which reagent distinguishes a terminal alkyne from an internal alkyne?
- A. Br2 in CCl4
- B. KMnO4
- C. Tollens' reagent (AgNO3/NH3) ✓
- D. HCl
Explanation: Terminal alkynes (RC≡CH) form a white silver acetylide precipitate with Tollens' reagent; internal alkynes have no acidic H and do not react.
Common trap: Picking Br2 — it adds to both terminal and internal alkynes equally.
Frequently Asked Questions
Why does HBr give anti-Markovnikov addition with peroxides but HCl and HI do not?
Energetics: HBr's homolysis (H-Br BDE 366 kJ/mol) and Br radical addition to the alkene are both favourable. For HCl, the propagation step is too endothermic; for HI, the I-H BDE is too low and I radical addition is reversible.
Why does benzene undergo substitution rather than addition?
Addition would destroy the aromatic 6-pi-electron system worth ~150 kJ/mol of resonance stabilisation. Substitution preserves aromaticity, restoring it after the electrophile departs (usually as H+).
Why are halogens ortho/para directing despite being deactivating?
Their -I effect deactivates the ring (slowing reaction), but their lone pairs donate +M into ortho and para positions, stabilising the sigma-complex at those sites.
What is the difference between hydroboration-oxidation and acid-catalysed hydration?
H2SO4/H2O gives Markovnikov alcohols (via carbocation, can rearrange). BH3 then H2O2/OH- gives anti-Markovnikov alcohols (concerted, no rearrangement, syn addition).
Why does Markovnikov's rule work?
The proton adds to the alkene to form the more stable carbocation; tertiary > secondary > primary by hyperconjugation and induction. Br- then attacks this stabler cation.
How Hydrocarbons Is Tested
MDCAT questions on Hydrocarbons are a mix of recall (definitions, classifications), application (predict outcomes, interpret diagrams), and basic numerical/analytical reasoning. PMDC papers from 2020–2025 emphasized the concepts above; older UHS papers (2008–2019) tested them too, with slight variations in question framing.
Practice
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