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Sindh Mcat Nts 2002 — Solved Past Paper with Answers

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Q1. _ child must respect his parents.

  • A. A
  • B. An
  • C. This
  • D. That

Explanation: a. A:This is the correct answer. The indefinite article "a" is used before words that begin with a consonant sound, such as "child."

Why the other options are wrong
  • B. b. An:This is not the correct answer. The indefinite article "an" is used before words that begin with a vowel sound.
  • C. c.This:This is not the correct answer. "This" is a demonstrative pronoun used to refer to something specific that is nearby in space or time.
  • D. d.That:This is not the correct answer. "That" is a demonstrative pronoun used to refer to something specific that is not nearby.

Q2. Read the paragraph carefully and gives the best answer of the given questions:College is the practising ground for the student. It is not sufficient that he gives himself up to studies. He must develop the noble qualities of showing respect to elders and teachers create a team spirit and participate in the various extracurricular activities and maintain college discipline to raise the prestige of his college.What part does college life play in the training of the students?

  • A. College life groom and prepares a student for life
  • B. Prepare the student in academics
  • C. Develops noble dualities in academics
  • D. Help the students to take part in extracurricular activities

Explanation: College is described as a place where the student must not only advance in his studies but improve and develop his skills by participation in various activities, learn to show respect to his seniors and teachers and do things that raise the prestige of his college. These will provide the perfect stage for grooming the student for his life and responsibilities ahead, and he must maintain a balance, only studies or studies or activities alone are not sufficient.

Why the other options are wrong
  • B. The word co curricular activities broadens the horizon and states that college life is not just a source of better academics . So the option does not suit well.
  • C. The word co curricular activities broadens the horizon and states that college life is not just a source of better academics . So the option does not suit well.
  • D. It doesn't suit the subject of the sentence because college life enhances the academic qualities of a person along with the co curricular activities.

Q3. The branch of biology which deals with the process and the function of processes is known as:

  • A. Physiology
  • B. Pathology
  • C. Histology
  • D. Evolution

Explanation: The word physiology is derived from Ancient Greek (physis), meaning "nature, origin", and (logia), meaning "study of'" is the scientific study of function in living systems. This branch of biology tells us how organisms, organ systems, organs, cells, and biomolecules function in living organisms

Why the other options are wrong
  • B. Pathology deals with causes and effects of diseases and laboratory examination.
  • C. Histology is the microscopic anatomy of living cells .
  • D. Evolution is a process that results in change in the genetic material of a population over time. Hence B,C and D are incorrect.

Q4. Note: Read the paragraph carefully and gives the best answer of the given questions:College is the practising ground for the student. It is not sufficient that he gives himself up to studies. He must develop the noble qualities of showing respect to elders and teachers create a team spirit and participate in the various extracurricular activities and maintain college discipline to raise the prestige of his college.What part does college life play in the training of the students:?

  • A. College life groom and prepares a student for life
  • B. Prepare the student in academics
  • C. Develops noble dualities in academics
  • D. Help the students to take part in extracurricular activities

Explanation: College is described as a place where the student must not only advance in his studies but improve and develop his skills by participation in various activities, learn to show respect to his seniors and teachers and do things that raise the prestige of his college. These will provide the perfect stage for grooming the student for his life and responsibilities ahead, and he must maintain a balance, only studies or studies or activities alone are not sufficient.

Why the other options are wrong
  • B. The word co curricular activities broadens the horizon and states that college life is not just a source of better academics . So the option does not suit well.
  • C. ;The word co curricular activities broadens the horizon and states that college life is not just a source of better academics . So the option does not suit well.
  • D. it doesn't suit the subject of the sentence because college life enhances the academic qualities of a person along with the co curricular activities.

Q5. Choose the suitable preposition:Rich lady found grate pleasure _ showing off her riches.

  • A. In
  • B. For
  • C. At
  • D. By

Explanation: A preposition is a word or group of words used before a noun, pronoun, or noun phrase to show direction, time, place, location, spatial relationships, or to introduce an object. Some examples of prepositions are words like "in," "at," "on," "of," and "to." Option A is correct. The correct sentence is Rich woman found great pleasure in showing off her riches.

Why the other options are wrong
  • B. Rich woman found great pleasure for showing off her riches is grammatically incorrect .The correct sentence is Rich woman found great pleasure in showing off her riches.
  • C. Rich woman found great pleasure at showing off her riches is grammatically incorrect .
  • D. Rich woman found great pleasure by showing off her riches is grammatically incorrect .The correct sentence is Rich woman found great pleasure in showing off her riches.The correct preposition here will be in because according to the statement the term pleasure is used as a noun and the term showing off is a verb, so the phrase “the lady finds pleasure in showing off her wealth is the most appropriate”

Q6. Bane (Synonym)

  • A. Banter
  • B. Mystery
  • C. Exile
  • D. Affliction

Explanation: The term bane means death, ruin and destruction.

Why the other options are wrong
  • A. Banter means the playful and friendly exchange of teasing remarks which is not the synonym of bane
  • B. Mystery means something that is difficult or impossible to understand or explain which is also not a synonym of bane.
  • C. Exile means the state of being barred from one's native country, typically for political or punitive reasons which is also not a synonym of bane.

Q7. _said that protoplasm is the physical basis of life.

  • A. Robert Brown
  • B. Robert Hook
  • C. Purkinje
  • D. Huxley

Explanation: Thomas Huxley referred to protoplasm as the "physical basis of life" and considered that the property of life resulted from the distribution of molecules within this substance.

Why the other options are wrong
  • A. A. Robert Brown discovered the nucleus.
  • B. Robert Hook invented the term "cell".
  • C. Jan Evanjelista Purkinje discovered purkinje fibres in the heart .

Q8. Infoldings in the mitochondrial inner membrane is called :

  • A. Cristae
  • B. Thylakoid
  • C. Glyoxysome
  • D. Chromatin network

Explanation: The mitochondria is a double-membraned cell organelle, known as the powerhouse of the cell which is present in all eukaryotic cells. It has an outer membrane and an inner membrane. The inner mitochondrial membrane has folds called cristae which helps in increasing the surface area. The enzyme ATP synthase is embedded in the inner mitochondrial membrane helps in the synthesis of ATP molecules (energy currency of the cell). It is also the site of the electron transport chain (aerobic respiration).

Why the other options are wrong
  • B. Thylakoid is the membrane disk of chloroplast .
  • C. Glyoxysomes specialised type of plant peroxisomes that perform conversion of lipids to sugar in oilseeds.
  • D. Chromatin network is a condensed form of chromosome.

Q9. The bond present between carbohydrate units :

  • A. Peptide bond
  • B. Covalent bond
  • C. Glycosidic bond
  • D. Electrostatic bond

Explanation: The bonds present between two carbohydrate molecules are glycosidic. A glycosidic bond is a type of covalent bond that joins a carbohydrate molecule to another group, which may or may not be another carbohydrate. A glycosidic bond is formed between the hemiacetal or hemiketal group of a saccharide and the hydroxyl group of some compound such as an alcohol. A substance containing a glycosidic bond is a glycoside.

Why the other options are wrong
  • A. Peptide Bond joins two alpha amino acids.
  • B. Covalent bond is found in DNA.
  • D. Electrostatic bond is formed by loss or gain of electrons.

Q10. _discovered microscopic creatures under the microscope in the blood cells of malarial patients.

  • A. Ronald Ross
  • B. Leveran
  • C. Grassy
  • D. A.F.A King

Explanation: Our understanding of the malaria parasites began in 1880 with the discovery of the parasites in the blood of malaria patients by Alphonse Laveran. Ronald Ross , A.F.A king and grassy were the contributors to the causes and treatment of malaria.

Why the other options are wrong
  • A. a) Ronald Ross: Sir Ronald Ross was a British medical doctor who is known for his discovery that mosquitoes transmit malaria parasites. He was awarded the Nobel Prize in Physiology or Medicine in 1902 for his work on the transmission of malaria.
  • C. c) Grassy: "Grassy" does not seem to be related to the discovery of microscopic creatures in the blood cells of malarial patients. It might be a typo or a misinterpretation of another name.
  • D. d) A.F.A King: This name does not seem to be associated with the discovery of microscopic creatures in the blood cells of malarial patients.

Q11. The nonliving part of protoplasm is :

  • A. Golgi bodies
  • B. Inclusion
  • C. Organelles
  • D. E. R

Explanation: Cells consist of various cell organelles like chloroplast, nucleus, endoplasmic reticulum, mitochondria etc. which form the living component of the cell which also include the protoplasm of a cell. ∙ The various non-living inclusions are metabolic by-products which are either organic or inorganic in nature. ∙ As they are not included in the protoplasm such non-living components are also called as non-protoplasmic contents/ ergastic substances/ Hyaloplasm. Golgi bodies endoplasmic reticulum and all organelles of the cell are considered living. Hence options A, C and D are incorrect.

Why the other options are wrong
  • A. a) Golgi bodies: Golgi bodies, also known as Golgi apparatus, are organelles found in eukaryotic cells. They are involved in modifying, sorting, and packaging proteins and lipids for transport to various parts of the cell or for secretion outside the cell. Golgi bodies are considered organelles and are a living part of the cell.
  • C. c) Organelles: Organelles are specialized structures within a cell that perform specific functions. Examples of organelles include the nucleus, mitochondria, chloroplasts (in plant cells), endoplasmic reticulum (ER), Golgi apparatus, and more. While organelles are part of the protoplasm, they are not the nonliving part.
  • D. d) E. R (Endoplasmic Reticulum): The endoplasmic reticulum (ER) is a network of membranous tubules and sacs that are involved in protein synthesis, lipid metabolism, and other cellular processes. The ER is considered an organelle and is part of the living protoplasm.

Q12. The movement of cytoplasm is called

  • A. Exocytosis
  • B. Endocytosis
  • C. Pinocytosis
  • D. Cyclosis

Explanation: Cytoplasmic streaming, known as cyclosis, is a movement of cytoplasm in various organisms including bacteria, higher plants, and animals (Williamson and Ashley, 1982; Theurkauf, 1994).

Why the other options are wrong
  • A. Exocytosis is the movement of materials inside the cell .
  • B. Endocytosis is the movement of materials outside the cell.
  • C. Pinocytosis is engulfing liquid materials (cell drinking) e.g fat droplets.

Q13. Some bacteria live on dead organic matter they are called :

  • A. Parasites
  • B. Phages
  • C. Saprophytes
  • D. Symbionts

Explanation: saprotroph, also called saprophyte or saprobe, is an organism that feeds on nonliving organic matter known as detritus at a microscopic level.

Why the other options are wrong
  • A. Parasites are the hosts of living cells.
  • B. Phages are bacterial viruses.
  • D. Symbionts attach to living organisms , "give" and "take" advantage .

Q14. Blue green pigment found only in blue green algae is:

  • A. Chlorophyll
  • B. Xanthophyll
  • C. Carotene
  • D. Phycobilin

Explanation: Blue-green algae or cyanobacteria also contain chlorophyll a, yellowish carotenoids, and blue-pigment phycobilins. Only the appearance of these pigments causes the blue-green colour of the algae. Chlorophyll is a true green pigment. Xanthophylls are yellow pigments. Carotene are yellow and orange pigments. Hence A, B and C are incorrect.

Why the other options are wrong
  • A. a) Chlorophyll: Chlorophyll is a green pigment found in plants and cyanobacteria (blue-green algae). It plays a key role in photosynthesis by capturing light energy and converting it into chemical energy.
  • B. b) Xanthophyll: Xanthophylls are yellow pigments found in the chloroplasts of plant cells. They assist in capturing light energy and also help protect the plant from excess light.
  • C. c) Carotene: Carotenes are orange pigments found in various plants and some photosynthetic bacteria. They are important in photosynthesis and serve as antioxidants.

Q15. Sexual reproduction in bacteria is taken by:

  • A. Binary fission
  • B. Conidia
  • C. Conjunction
  • D. Zoospore

Explanation: So, bacteria can't reproduce sexually, but they can exchange genetic information with each other. Using a pilus, two bacteria make contact with each other and exchange genetic material. This is called conjugation.

Why the other options are wrong
  • A. Binary fission is asexual reproduction.
  • B. Conidia is an asexual non-motile spore of a fungus.
  • D. Zoospore is a motile asexual spore in bacteria, fungi and protists.

Q16. Cyanobacteria is a typical example of:

  • A. Chlorophyceae
  • B. Cyanophyceae
  • C. Green algae
  • D. Fungi

Explanation: Cyanobacteria, also known as Cyanophyta, are a phylum of gram-negative bacteria that obtain energy via photosynthesis.

Why the other options are wrong
  • A. Chlorophyceae are a class of green algae.
  • C. Green algae are photosynthetic algae having chlorophyll
  • D. Fungi are spore producing organisms.Cyanobacteria don't belong to anyone among.

Q17. Saliva in mouth helps in digestion of :

  • A. Bread
  • B. Meat
  • C. Fat
  • D. Table Salt

Explanation: Saliva contains special enzymes that help digest the starches in your food. An enzyme called amylase breaks down starches (complex carbohydrates) into sugars, which your body can more easily absorb. Saliva amylase in mouth only digests carbs upto 3 to 5%. It cannot digest protein (meat), lipid (fat), and salts.

Why the other options are wrong
  • B. b) Meat: Saliva primarily contains enzymes that begin the digestion of carbohydrates. The digestion of meat primarily occurs in the stomach, where gastric juices break down proteins with the help of the enzyme pepsin.
  • C. c) Fat: Saliva does not play a significant role in the digestion of fats. Fat digestion primarily takes place in the small intestine, where bile and pancreatic enzymes break down fats into fatty acids and glycerol.
  • D. d) Table Salt: Saliva does not play a role in the digestion of table salt (sodium chloride). Salt is not a complex molecule that requires enzymatic digestion. It dissolves in saliva and is then swallowed.

Q18. Major metabolic factory, detoxification centre and storage organ of body is :

  • A. Stomach
  • B. Brain
  • C. Kidney
  • D. Liver

Explanation: Your main detoxification organs are the liver and kidneys.The bowels and urinary tract are extensions of these organs as wastes exit your body.The skin (via sweat) and the lungs (via breathing/expelling CO2) Are also considered detoxification organs.

Why the other options are wrong
  • A. Stomach stores undigested food and secretes avid i to it.
  • B. Brain controls thinking.
  • C. Kidney is concerned with urine formation

Q19. The actual visual receptor of the eye are :

  • A. Iris and pupil
  • B. Iris and lens
  • C. Rods and cones
  • D. Cornea and retina

Explanation: Cones are active at higher light levels (photopic vision), are capable of colour vision and are responsible for high spatial acuity. Iris is the coloured part, pupil is the central black spot from where light enters the eye. Lens is responsible for focusing light. Cornea is a membrane that protects structures inside eye while retina contains layers of photoreceptors (rods and cones).

Why the other options are wrong
  • A. a) Iris and Pupil: The iris is the colored part of the eye that controls the size of the pupil, which is the opening in the center of the iris. However, these structures are not the actual visual receptors responsible for detecting light and forming images.
  • B. b) Iris and Lens: The iris regulates the amount of light entering the eye by adjusting the size of the pupil, and the lens helps focus light onto the retina. While the lens is involved in focusing light, it is not the actual visual receptor.
  • D. d) Cornea and Retina: The cornea is the clear front surface of the eye that helps focus light onto the retina. The retina, located at the back of the eye, contains the actual visual receptors (rods and cones) that detect light and transmit visual signals to the brain.

Q20. Haemoglobin is :

  • A. Respiratory pigment
  • B. Excretory pigment
  • C. Digestive pigment
  • D. Storage pigment

Explanation: Haemoglobin (Hb) is a protein found in the red blood cells that carries oxygen in your body and gives blood its red colour. Haemoglobin levels vary from person to person. Men usually have higher levels than women.

Why the other options are wrong
  • B. Excretory pigments are found in liver and pancreas and digestive pigments are found in bile while storage pigments are found in plants.
  • C. Excretory pigments are found in liver and pancreas and digestive pigments are found in bile while storage pigments are found in plants.
  • D. this option is incorrect.

Q21. The excretory organ in insects are :

  • A. Flame cells
  • B. Malpighian tubules
  • C. Contractile vacuoles
  • D. Kidneys

Explanation: In insects, Malpighian tubules (MTs) are the main osmoregulatory and excretory organs and are considered analogous to the nephridia of annelids or the kidneys of vertebrates.

Why the other options are wrong
  • A. Flame cells are found in flatworms.
  • C. Contractile vacuoles are present in protozoans.
  • D. Kidneys are present in higher animals.

Q22. The kidneys does not perform the function of :

  • A. Regulation of blood pressure
  • B. Secretion of bile
  • C. Regulation of pH
  • D. Homeostasis

Explanation: Kidney regulates B.P and blood pH and hence performs homeostasis. Bile is secreted by the liver. It is not a function of the kidneys. Therefore option B is incorrect while all others are correct.

Why the other options are wrong
  • A. a) Regulation of Blood Pressure: The kidneys do play a role in regulating blood pressure. They help maintain blood pressure by adjusting the amount of water and sodium reabsorbed into the bloodstream, which affects overall blood volume and pressure.
  • C. c) Regulation of pH: The kidneys do indeed play a significant role in regulating the body's pH levels. They help maintain the acid-base balance in the blood by excreting excess acids or bases in the urine.
  • D. d) Homeostasis: The incorrect answer. Homeostasis refers to the body's ability to maintain a stable internal environment despite external changes.

Q23. Which of following statement is true about Euglena:

  • A. Autotrophic animal
  • B. Unicellular Algae
  • C. Prokaryotic autotroph
  • D. A-cellular animal

Explanation: Euglena is a class of single cell flog eukaryotic. The species Euglena gracilis has been utilised widely in the research centre as a model creature. Most types of Euglena have photosynthesizing chloroplasts inside the body of the cell, which empower them to nourish via autotrophy, similar to plants.

Why the other options are wrong
  • B. Euglena is not an algae so option B is incorrect.
  • C. Neither euglena is prokaryotic, rather it is eukaryotic. Also euglena is not acellular.
  • D. Neither euglena is prokaryotic, rather it is eukaryotic. Also euglena is not acellular.

Q24. During inspiration, the path of air is :

  • A. Nostril-pharynx-lung-trachea-bronchi
  • B. Nostril-bronchi-pharynx-trachea-lungs
  • C. Nostril-pharynx-trachea-bronchi-lungs
  • D. Nostril-pharynx-lungs-trachea-bronchi

Explanation: When you inhale through your nose or mouth, air travels down your pharynx (back of your throat), passes through your larynx (voice box) and into your trachea (windpipe). Your trachea is divided into two air passages called bronchial tubes. One bronchial tube leads to your left lung, the other to your right lung.

Why the other options are wrong
  • A. a) Nostril-pharynx-trachea-bronchi-lungs: This option is incorrect. The air doesn't pass through the lungs before reaching the trachea and bronchi.
  • B. b) Nostril-bronchi-pharynx-trachea-lungs: This option is incorrect. The correct order of air passage during inspiration is nostril-pharynx-trachea-bronchi-lungs.
  • D. d) Nostril-pharynx-lungs-trachea-bronchi: This option is incorrect. The correct order is nostril-pharynx-trachea-bronchi-lungs.

Q25. The manufactured food is transported to various regions by a process called:

  • A. Translocation
  • B. Transpiration
  • C. Osmosis
  • D. Diffusion

Explanation: The manufactured food is transported to various regions by a process called Translocation.

Why the other options are wrong
  • B. Transpiration is loss of water from leaf surface.
  • C. Osmosis is movement of solute particles from lower to higher concentration across a semipermeable membrane.
  • D. Diffusion is movement through a membrane from higher to lower concentration.

Q26. The protoplasm is shrinked in the solution of :

  • A. Normal saline solution
  • B. Isotonic solution
  • C. Hypotonic solution
  • D. Hypertonic solution

Explanation: When the cell is placed in a hypertonic solution, the protoplasm of the cell shrinks due to outward movement of solvent from the cell to the surrounding. A, B and D are incorrect.

Why the other options are wrong
  • A. a) Normal saline solution: This is a solution with the same concentration of solutes as the cells. It is isotonic to the cell's cytoplasm, meaning it has the same osmotic pressure. Therefore, it does not cause the protoplasm to shrink.
  • B. b) Isotonic solution: An isotonic solution has the same concentration of solutes as the cell's cytoplasm. It does not cause the protoplasm to shrink. Instead, it maintains the normal shape and size of the cell.
  • C. c) Hypotonic solution: A hypotonic solution has a lower concentration of solutes compared to the cell's cytoplasm. When a cell is placed in a hypotonic solution, water enters the cell to equalize the concentration. This can cause the cell to swell and even burst (lyse) due to excessive water uptake. The protoplasm would not shrink in a hypotonic solution.

Q27. The natural clock in the human body :

  • A. Pineal body
  • B. Medulla
  • C. Pons
  • D. Cerebellum

Explanation: Circadian rhythms are physical, mental, and behavioural changes that follow a 24-hour cycle. These natural processes respond primarily to light and dark and affect most living things, including animals, plants, and microbes. Chronobiology is the study of circadian rhythms.

Why the other options are wrong
  • B. b) Medulla: The medulla oblongata is a part of the brainstem that controls involuntary functions such as breathing, heart rate, and blood pressure. While it's involved in regulating various bodily processes, it is not the natural clock.
  • C. c) Pons: The pons is another part of the brainstem that plays a role in regulating certain involuntary functions. It is not primarily associated with the body's natural clock.
  • D. d) Cerebellum: The cerebellum is responsible for coordinating voluntary muscle movements and maintaining balance and posture. While it has important functions, it is not the natural clock.

Q28. The forebrain is divisible into two components :

  • A. Cerebrum and cerebral hemispheres
  • B. Medulla and pons
  • C. Telencephalon and diencephalon
  • D. Telencephalon and medulla

Explanation: Weighing at just 2% of the total body weight, the human brain is probably the most complex structure. It is the centre of control of all the body functions and senses. The average weight of the human brain is around 1.5 kg and it contains about 86 billion nerve cells (neurons) that control every action you take. Medulla and pons are part of the hindBrain.

Why the other options are wrong
  • A. a) Cerebrum and cerebral hemispheres: The cerebrum is the largest part of the brain and is responsible for higher cognitive functions such as thinking, reasoning, memory, and sensory perception. It is divided into two cerebral hemispheres (left and right) that are connected by a bundle of nerve fibers called the corpus callosum.
  • B. b) Medulla and pons: The medulla and pons are part of the brainstem, which controls vital functions like breathing, heart rate, and blood pressure. While important, these are not components of the forebrain.
  • D. d) Telencephalon and medulla: The medulla is part of the brainstem, as mentioned earlier. The correct division of the forebrain is telencephalon and diencephalon.

Q29. Sugar level in blood is maintained by :

  • A. Liver
  • B. Kidney
  • C. Adrenal gland
  • D. Islets of Langerhans

Explanation: The alpha cells of the islets of Langerhans produce an opposing hormone, glucagon, which releases glucose from the liver and fatty acids from fat tissue. Liver performs detoxification, the kidney makes urine, while adrenal glands secrete hormones that control mineral and glucose levels and combat emergency situations. Hence options A, B and C are incorrect.

Why the other options are wrong
  • A. a) Liver: The liver plays a crucial role in regulating blood sugar levels. It stores excess glucose as glycogen and releases glucose into the bloodstream when needed to maintain stable blood sugar levels.
  • B. b) Kidney: While the kidneys play a role in maintaining electrolyte balance and fluid levels in the body, they are not the primary organs responsible for regulating blood sugar levels.
  • C. c) Adrenal gland: The adrenal glands are involved in producing hormones such as adrenaline and cortisol, which play a role in the body's response to stress. However, they are not the main organs responsible for regulating blood sugar levels.

Q30. In meiosis I , crossing over takes place in :

  • A. Pachytene
  • B. Diplotene
  • C. Zygotene
  • D. Diakinesis

Explanation: Crossing over mainly takes place in the pachytene stage of the prophase I of the meiosis. During crossing over, the homologous chromosomes exchange their genetic material which leads to the formation of recombinants.

Why the other options are wrong
  • B. Diplotene is the fourth stage of meiosis prophase-1 (a five-stage process). It is preceded by the crossing over in the pachytene stage. Diplotene stage is characterized by desynapsis and chiasmata formation.
  • C. c) Zygotene: In the zygotene stage of meiosis I, homologous chromosomes begin to pair up, but crossing over has not yet taken place.
  • D. d) Diakinesis: The diakinesis stage is the final substage of prophase I. During this stage, the chromosomes condense further, and the nuclear envelope breaks down. Crossing over has already occurred during the earlier stages of prophase I.

Q31. Vertebral column is the part of _ skeleton :

  • A. Axial
  • B. Appendicular
  • C. Exoskeleton
  • D. Hydrostatic

Explanation: The axial skeleton is the part of the skeleton that consists of the bones of the head and trunk of a vertebrate. In the human skeleton, it consists of 80 bones and is composed of six parts; the skull (22 bones), also the ossicles of the middle ear, the hyoid bone, the rib cage, sternum and the vertebral column.

Why the other options are wrong
  • B. Appendicular skeleton consists of arms and legs.
  • C. Exoskeleton is present outside the body
  • D. Hydrostatic skeleton is found in mollusks.

Q32. The science of ageing is called :

  • A. Ethnology
  • B. Gerontology
  • C. Embryology
  • D. Genetics

Explanation: Gerontology is the study of ageing and older adults. The science of gerontology has evolved as longevity has improved. Researchers in this field are diverse and are trained in areas such as physiology, social science, psychology, public health, and policy.

Why the other options are wrong
  • A. Ethnology is the study of different peoples and differences and relationships between them
  • C. Embryology is the study of a developing embryo.
  • D. Genetics is the study of genes

Q33. The possible result of crossing over between heterozygous tall (Tt)and homozygous dwarf (tt) is :

  • A. 50 %tall and 50%dwarf
  • B. 100% tall
  • C. 100%dwarf
  • D. 75%tall and 25% dwarf

Explanation: a) 50% tall and 50% dwarf: This is the correct answer. When crossing over occurs between a heterozygous tall (Tt) and a homozygous dwarf (tt), the possible outcomes of the offspring are half tall (Tt) and half dwarf (tt).

Why the other options are wrong
  • B. b) 100% tall: If there is no crossing over between the heterozygous tall (Tt) and homozygous dwarf (tt), the result would be all tall (Tt) offspring.
  • C. c) 100% dwarf: If there is no crossing over between the heterozygous tall (Tt) and homozygous dwarf (tt), the result would be all dwarf (tt) offspring.
  • D. d) 75% tall and 25% dwarf: This does not accurately represent the possible outcomes of crossing over between a heterozygous tall (Tt) and a homozygous dwarf (tt). The correct ratio is 50% tall and 50% dwarf.

Q34. _muscle pulls the limb outward away from the body :

  • A. Adductor
  • B. Protractor
  • C. Abductor
  • D. Extensor

Explanation: :In general terms, abduction, in the anatomical sense, is classified as the motion of a limb or appendage away from the midline of the body. In the case of arm abduction, it is the movement of the arms away from the body within the plane of the torso.

Why the other options are wrong
  • A. Adductor muscles move the limb inward.
  • B. Protractor muscles pull forward.
  • D. Extensor muscles pull backwards.

Q35. _hormone stimulates mammary gland to secrete milk and process of labour :

  • A. Oxytocin
  • B. F.S.H
  • C. L.H
  • D. T.S.H

Explanation: :The two main actions of oxytocin in the body are contraction of the womb (uterus) during childbirth and lactation. Oxytocin stimulates the uterine muscles to contract and also increases production of prostaglandins, which increase the contractions further.

Why the other options are wrong
  • B. F.S.H regulates the menstrual cycle.
  • C. L.H stimulates testosterone secretion in males.
  • D. T.S.H releases thyroxine.

Q36. _germinal layer gives rise to all the body muscles.

  • A. Ectoderm
  • B. Endoderm
  • C. Mesoderm
  • D. Chorion

Explanation: The three germ layers are the endoderm, the ectoderm, and the mesoderm. Cells in each germ layer differentiate into tissues and embryonic organs. The ectoderm gives rise to the nervous system and the epidermis, among other tissues. The mesoderm gives rise to the muscle cells and connective tissue in the body.

Why the other options are wrong
  • A. a) Ectoderm: The ectoderm is one of the three primary germinal layers in the early embryo. It gives rise to structures such as the nervous system, epidermis (outer layer of skin), and hair.
  • B. b) Endoderm: The endoderm is another of the three primary germinal layers. It gives rise to the epithelial lining of the digestive tract and various internal organs like the liver, pancreas, and lungs.
  • D. d) Chorion: The chorion is an extraembryonic membrane that surrounds and protects the developing embryo in some animals. It plays a role in gas exchange and nutrient transport.

Q37. The tendency of gene in chromosome to remain together is called :

  • A. Crossing over
  • B. Synapsis
  • C. Terminalization
  • D. Linkage

Explanation: Genetic linkage is the tendency of DNA sequences that are close together on a chromosome to be inherited together during the meiosis phase of sexual reproduction. Crossing is the exchange of genetic material . Synapsis is the fusion of chromosome pairs at the start of meiosis. Terminalization is the movement of bonds towards the ends of paired chromosomes

Why the other options are wrong
  • A. a) Crossing over: Crossing over is the exchange of genetic material between homologous chromosomes during meiosis. It can lead to the recombination of alleles and the creation of new combinations of genes.
  • B. b) Synapsis: Synapsis is the pairing of homologous chromosomes during meiosis. It allows for the alignment of corresponding genes and facilitates crossing over.
  • C. c) Terminalization: Terminalization is not a recognized term in genetics. It doesn't relate to any specific genetic process.

Q38. The bond between adenine and thymine is :

  • A. Single
  • B. Double
  • C. Triple
  • D. Covalent

Explanation: The bases of one strand bond to the bases of the second strand with hydrogen bonds. Adenine always bonds with thymine, and cytosine always bonds with guanine. The bonding causes the two strands to spiral around each other in a shape called a double helix. Ribonucleic acid (RNA) is a second nucleic acid found in cells.

Why the other options are wrong
  • A. a) Single: A single bond involves the sharing of one pair of electrons between two atoms. In the context of DNA, adenine (A) and thymine (T) are complementary bases that form a single hydrogen bond with each other.
  • C. c) Triple: A triple bond involves the sharing of three pairs of electrons between two atoms. While triple bonds are found in certain molecules, they are not present in the adenine-thymine pairing in DNA.
  • D. d) Covalent: The bond between adenine and thymine is a hydrogen bond, not a covalent bond. Covalent bonds involve the sharing of electrons between atoms to form molecules.

Q39. _mono consists of deeper layer of water :

  • A. Letic
  • B. Littoral
  • C. Limnetic
  • D. Profundal

Explanation: The profundal zone is a deep zone of an inland body of freestanding water, such as a lake or pond, located below the range of effective light penetration. This is typically below the thermocline, the vertical zone in the water through which temperature drops rapidly.

Why the other options are wrong
  • A. The Lentic zone forms a boundary of water . It is shallow
  • B. Littoral zone is the one closer to the shore.
  • C. Limnetic zone is the area where light does not penetrate all the way to the bottom.

Q40. Lichen is associated between:

  • A. Fungus and Algae
  • B. Algae and Bacteria
  • C. Bacteria and Fungus
  • D. Bacteria and Virus

Explanation: Lichens are commonly recognized as a symbiotic association of a fungus and a chlorophyll containing partner, either green algae or cyanobacteria, or both. The fungus provides a suitable habitat for the partner, which provides photosynthetically fixed carbon as energy source for the system. Bacteria can never be a part of lichen. Hence all options except A are incorre

Why the other options are wrong
  • B. b) Algae and Bacteria: While both algae and bacteria are involved in various ecological interactions, lichens specifically involve a fungal partner along with algae or cyanobacteria.
  • C. c) Bacteria and Fungus: This option is not correct. Lichens involve a fungus and algae or cyanobacteria, not bacteria.
  • D. d) Bacteria and Virus: Lichens do not involve viruses. They are a mutualistic relationship between a fungus and algae or cyanobacteria.

Q41. Extra circular chromosome present in bacteria is called :

  • A. Centrosome
  • B. Centromere
  • C. Plasmid
  • D. DNA

Explanation: Plasmids carry only a few genes and exist independently of chromosomes, the primary structures that contain DNA in cells. Able to self-replicate, plasmids can be picked up from the environment and transferred between bacteria. Plasmids are used by their host organism to cope with stress-related conditions.

Why the other options are wrong
  • A. Centrosome is an animal cell organelle (also found in lower plants) that is involved in spindle formation during cell division.
  • B. Centromere is the point where two sister chromatids attach with each other.
  • D. DNA is not circular, it is a double helix.

Q42. The person with down's syndrome has :

  • A. One extra chromosome
  • B. One less chromosome
  • C. Two extra chromosome
  • D. Two less chromosome

Explanation: Down syndrome results when abnormal cell division involving chromosome 21 occurs. These cell division abnormalities result in an extra partial or full chromosome 21. This extra genetic material is responsible for the characteristic features and developmental problems of Down syndrome.

Why the other options are wrong
  • B. b) One less chromosome: This is not correct. Down's syndrome is characterized by an extra chromosome, not a missing one.
  • C. c) Two extra chromosomes: This is not correct. Down's syndrome is caused by the presence of an extra copy of chromosome 21, not two extra chromosomes.
  • D. d) Two less chromosomes: This is not correct. Down's syndrome involves an extra chromosome, not a deficiency of chromosomes.

Q43. The menstrual stage lasts for:

  • A. 1 to 5 days
  • B. 14 to 16 days
  • C. 25 to 28 days
  • D. 8 to 18 days

Explanation: The first phase is the menstrual phase, which is from day 1 to 5. During this stage, the uterus sheds its inner lining through the vagina in the form of fluid. Women generally have cramps caused due to the contraction of the uterine wall during this phase.

Why the other options are wrong
  • B. b) 14 to 16 days: This is not correct. The menstrual stage does not last for 14 to 16 days. This range of days is more commonly associated with the ovulation phase of the menstrual cycle, which occurs roughly in the middle of the cycle.
  • C. c) 25 to 28 days: This is not correct. The range of 25 to 28 days is more commonly associated with the length of the entire menstrual cycle, which includes various phases such as the follicular phase, ovulation, and luteal phase, in addition to menstruation.
  • D. d) 8 to 18 days: This is not correct. The range of 8 to 18 days is not typical for the duration of the menstrual stage. It's important to note that individual variations can occur, but the average duration of menstruation is around 5 days.

Q44. The eyespot in Euglena is sensitive for :

  • A. Dark
  • B. Light
  • C. Red light
  • D. Blue light

Explanation: :In the green one-celled organism Euglena, the eyespot is located in the gullet, at the base of the flagellum (a whiplike locomotory structure). A cup-shaped mass of pigment rods shields a sensitive area of the flagellar base from light coming from the direction of the opposite end of the organism.

Why the other options are wrong
  • A. a) Dark: This option is not correct. The eyespot in Euglena is sensitive to light and plays a role in phototaxis, which is the movement of the organism in response to light.
  • C. c) Red light: This option is not correct. While the eyespot is sensitive to light in general, it is not specifically sensitive to red light.
  • D. d) Blue light: This option is not correct. The eyespot in Euglena is generally more sensitive to light in the visible spectrum, and while it may respond to blue light, it is not specific to blue light.

Q45. The whole tail of the tadpole and its gills are lost during metamorphosis . The change is :

  • A. Progressive
  • B. Retroactive
  • C. Organisational
  • D. None of these

Explanation: Tadpoles hatch from the eggs and live in the pond. The tadpoles turn into Froglets. The body shrinks and legs form. The Froglets' tail shrinks, the lungs develop and the back legs grow and then we have a Frog. Retroactive changes are those that take effect from a date in the past

Why the other options are wrong
  • A. a) Progressive: This option is not correct. "Progressive" refers to a continuous advancement or development, but in the context of tadpole metamorphosis, the change is not necessarily considered "progressive."
  • C. c) Organisational: This option is not correct. "Organisational" typically refers to the arrangement or structure of components within an organization or system, and it is not the most relevant term to describe the specific change occurring during tadpole metamorphosis.
  • D. d) None of these: The correct answer is b) Retroactive. The change in tadpole metamorphosis, involving the loss of the tail and gills, is best described as retroactive, indicating a reversal or undoing of specific features that were present in the earlier tadpole stage.

Q46. _no of ATP are produced during Aerobic respiration in prokaryotes :

  • A. 32 ATP
  • B. 34 ATP
  • C. 36 ATP
  • D. 38 ATP

Explanation: Without oxygen, organisms can split glucose into just two molecules of pyruvate. This releases only enough energy to make two ATP molecules. With oxygen, organisms can break down glucose all the way to carbon dioxide. This releases enough energy to produce up to 38 ATP molecules. 36 ATPs is produced by eukaryotes during Aerobic respiration.

Why the other options are wrong
  • A. a) 32 ATP: This option is not correct. While 32 ATP molecules are produced during the complete oxidation of glucose in eukaryotic cells through aerobic respiration, the number of ATP molecules produced during aerobic respiration in prokaryotes is different.
  • B. b) 34 ATP: This option is not correct either. While 34 ATP molecules are generated during oxidative phosphorylation in eukaryotic cells, it's important to note that the exact number of ATP produced in prokaryotic cells through aerobic respiration can vary based on specific conditions and factors.
  • C. c) 36 ATP: This option is often cited as the estimated net yield of ATP during aerobic respiration in prokaryotes. It considers the total ATP produced through glycolysis, the citric acid cycle, and oxidative phosphorylation. However, the actual number can vary.

Q47. The dark band in muscle fibres is due to :

  • A. Actin
  • B. Myosin and Actin
  • C. Tropomyosin
  • D. I band

Explanation: The arrangement of the thick myosin filaments across the myofibrils and the cell causes them to refract light and produce a dark band known as the A Band. In between the A bands is a light area where there are no thick myofilaments, only thin actin filaments. These are called the I Bands.

Why the other options are wrong
  • A. a) Actin: The dark band in muscle fibers is not primarily due to actin. Actin is a thin filament that is present in both the light (I) band and the dark (A) band.
  • C. c) Tropomyosin: Tropomyosin is a protein that is associated with the actin filaments in muscle fibers. It plays a role in regulating muscle contraction by blocking the myosin-binding sites on actin. However, the dark band itself is not primarily due to tropomyosin.
  • D. d) I band: The I band, or light band, is the region of a muscle fiber where only actin filaments are present. It appears lighter under a microscope. The dark band (A band) is primarily due to the overlapping arrangement of myosin and actin filaments.

Q48. Neurospora is a fungus which is used to understand the principle of :

  • A. Reproduction
  • B. Locomotion
  • C. Inheritance
  • D. None of these

Explanation: Neurospora - an ascomycetes fungus has been used as a biological tool to understand the mechanism of plant genetics much in the same way as Drosophila has been used to study animal genetics. Hence option C is correct.

Why the other options are wrong
  • A. a) Reproduction: While Neurospora is a fungus and does undergo reproduction, it is not specifically known for being a model organism to study the principles of reproduction. Other organisms are often used for reproductive studies.
  • B. b) Locomotion: Neurospora is a stationary organism and does not exhibit locomotion. Therefore, it is not used to study the principles of locomotion.
  • D. d) None of these: The correct option is "c) Inheritance."

Q49. The total autosomes in human are :

  • A. 44
  • B. 46
  • C. 22
  • D. 23

Explanation: These chromosomes are present in equal pairs and they can be defined as the thread-like structure found inside the nucleus of every cell. Out of which 22 pairs are autosomes and remaining 1 pair is a sex chromosome. So there will be 44 autosomes

Why the other options are wrong
  • B. b) 46: This is not the correct answer. While humans do have 22 pairs of autosomes, this option does not account for the sex chromosomes, which are not included in the total chromosome count.
  • C. c) 22: This is not the correct answer. While humans do have 22 pairs of autosomes, this option does not account for the sex chromosomes, which are also included in the total chromosome count.
  • D. d) 23: This is not the correct answer. While humans do have 23 pairs of chromosomes, this option only considers the total number of pairs, not the total number of individual chromosomes.

Q50. The result of nondisjunction are :

  • A. Down's Syndrome
  • B. Turner's Syndrome
  • C. Klinefelter's Syndrome
  • D. All of these

Explanation: Nondisjunction causes abnormal number chromosomes in all the cells called aneuploidy or in some cells called mosaicism. Some of the important examples are: Down's syndrome, Turner's syndrome, Klinefelter syndrome.

Why the other options are wrong
  • A. a) Down's Syndrome: Down's Syndrome is a genetic disorder caused by the presence of an extra copy of chromosome 21. This condition is a result of nondisjunction during cell division, specifically in the formation of gametes (sperm or egg cells). Nondisjunction can lead to the inheritance of an extra chromosome 21, resulting in the characteristic features and health issues associated with Down Syndrome.
  • B. b) Turner's Syndrome: Turner's Syndrome is a genetic disorder that affects females and is characterized by the absence of one X chromosome or the presence of a partially deleted X chromosome. This condition is caused by nondisjunction during either egg or sperm formation. As a result, affected individuals have specific physical characteristics and may experience health concerns related to the missing or altered X chromosome.
  • C. c) Klinefelter's Syndrome: Klinefelter's Syndrome is a genetic disorder that affects males and is characterized by the presence of an extra X chromosome (XXY). Like the other syndromes mentioned, Klinefelter's Syndrome is a result of nondisjunction during the formation of gametes. Individuals with Klinefelter's Syndrome may have certain physical features and can experience hormonal and reproductive challenges.

Q51. The process during which solid is directly converted into gaseous state is called :

  • A. Boiling
  • B. Evaporation
  • C. Sublimation
  • D. Freezing

Explanation: conversion of a substance from the solid to the gaseous state without its becoming liquid. An example is the vaporisation of frozen carbon dioxide (dry ice) at ordinary atmospheric pressure and temperature. The phenomenon is the result of vapour pressure and temperature relationships.

Why the other options are wrong
  • A. Boiling is the conversion of liquid into gas on heating.
  • B. Evaporation is the conversion of liquid into gas at room temperature.
  • D. Freezing is the conversion of liquid into solid.

Q52. The number of atoms of nitrogen represented in the formula NH4NO is :

  • A. 1
  • B. 2
  • C. 3
  • D. 4

Explanation: The molecule of ammonium nitrate is formed by the union of 2 nitrogen atoms, 4 hydrogen atoms and 3 oxygen atoms. Ammonium has a chemical formula NH4+ and nitrate has the chemical formula NO3-.

Why the other options are wrong
  • A. a) 1: This option suggests that there are one atoms of nitrogen in the formula NH4NO. Since there are only two nitrogen atoms in NH4NO, this option is not correct.
  • C. c) 3: This option suggests that there are three atoms of nitrogen in the formula NH4NO. However, as demonstrated, there are only two nitrogen atoms in NH4NO.
  • D. d) 4: This option suggests that there are four atoms of nitrogen in the formula NH4NO. Since there are only two nitrogen atoms in NH4NO, this option is not correct.

Q53. Which of the following techniques could be used to separate the colored dyes from black ink :

  • A. Chromatography
  • B. Filtration
  • C. Fractional distillation
  • D. Precipitation

Explanation: chromatography is the method used for the separation of the mixture of dye from black ink.

Why the other options are wrong
  • B. Filtration is a process by which liquid or solid particles are separated by a filter.
  • C. Fractional distillation is the separation of a mixture of boiling liquids and vapours in a fractionating column
  • D. Precipitation is the process of transforming a dissolve substance into an insoluble solid from a supersaturated solution .

Q54. The crystalline form of allotropes are called:

  • A. Chemically same
  • B. Chemically different
  • C. Some time same and sometime different
  • D. Depend upon substance

Explanation: Allotropes are the crystalline forms of an element that exist in more than one crystalline form with varying physical properties but comparable chemical properties. Diamond and graphite are the two most popular allotropes of carbon. Carbon is a nonmetallic element that is required for life to exist.

Why the other options are wrong
  • B. b) Chemically different: This option suggests that the crystalline forms of allotropes have different chemical compositions. This is not accurate because allotropes of the same element have the same chemical composition, but they differ in the way their atoms are bonded and arranged in the crystal lattice.
  • C. this option is incorrect.
  • D. d) Depend upon substance: This option suggests that whether the crystalline forms of allotropes are chemically same or different depends on the specific substance being considered. This is partially accurate, as the chemical composition of allotropes of the same element remains the same, but their arrangement can vary.

Q55. Alpha rays are :

  • A. Single negatively charged particles
  • B. Single positively charged particles
  • C. Double negatively charged particles
  • D. Double positively charged particles

Explanation: Alpha particles have a positive charge and are identical with helium nuclei and consist of two protons and two neutrons. They result from the radioactive decay of heavy elements such as radium, thorium, uranium, and plutonium.

Why the other options are wrong
  • A. a) Single negatively charged particles: This option suggests that alpha rays are single particles with a negative charge. However, this is not accurate. Alpha particles are made up of two protons and two neutrons, and they have a positive charge.
  • B. b) Single positively charged particles: This option is inaccurate. Alpha rays, also known as alpha particles, are composed of two protons and two neutrons. Due to the presence of two protons, they have a double positive charge.
  • C. c) Double negatively charged particles: This option is not accurate. Alpha particles are positively charged, not negatively charged.

Q56. Which is the lightest among following:

  • A. An atom of hydrogen
  • B. An electron
  • C. A neutron
  • D. A proton

Explanation: Electron, lightest stable subatomic particle known. It carries a negative charge of 1.602176634 × 10−19 coulomb, which is considered the basic unit of electric charge.

Why the other options are wrong
  • A. The hydrogen atom is the heaviest among the given options.
  • C. Neutron is heavier than the electron.Mass of neutron is 1.0086654 a.m.u. Neutron is 1842 times heavier than an electron.
  • D. Proton is heavier than electron.The proton is about 1,836 times as heavy as the electron;

Q57. In an atom no two electrons can have same set of quantum numbers”, this statement was given by:

  • A. Uncertainty principle
  • B. Pauli’s exclusion principle
  • C. Hund’s rule
  • D. Aufbau’s principle

Explanation: Pauli's Exclusion Principle states that no two electrons in the same atom can have identical values for all four of their quantum numbers. In other words, (1) no more than two electrons can occupy the same orbital and (2) two electrons in the same orbital must have opposite spins.

Why the other options are wrong
  • A. Position and momentum of a particle cannot both be measured simultaneously with perfect accuracy. There is always a fundamental uncertainty associated with any measurement. This uncertainty is not associated with the measuring instrument. It is a consequence of the wave particle duality of matter and radiation. This was first proposed by Werner Heisenberg in 1927 and hence is known as the Heisenberg Uncertainty Principle. This fundamental uncertainty is completely negligible for measurements of position and momentum of macroscopic objects but is a predominant fact of life in the atomic domain.
  • C. If degenerate orbitals are available and more than one electrons are to be placed in them, they should be placed in separate orbitals with the same spin rather than putting them in the same orbital with opposite spins. According to the rule, the two electrons in a 2p subshell of carbon will be distributed as follows. C 1s² 2s² 2px¹ 2py¹ 2pz⁰ The three orbitals of the 2p subshell are degenerate.
  • D. The electrons should be filled in energy subshells in order of increasing energy values. The electrons are first placed in Is, 2s, 2p and so on.

Q58. The bond formed by the electrostatic attraction between negative end of one molecule and positive end of other is called:

  • A. Covalent bond
  • B. Hydrogen bond
  • C. Ionic bond
  • D. Coordinate covalent bond

Explanation: According to the Lewis theory, ionic bond is formed by the complete transfer of electrons or electrons from an atom with low ionisation energy to another atom with high electron affinity. In energy terms, the electropositive elements are at a higher energy state than the electronegative elements. The energy difference will be responsible for the transfer of electrons from a higher energy state to a lower energy state.

Why the other options are wrong
  • A. According to Lewis and Kossel, a covalent bond is formed by the mutual sharing of electrons between two atoms. While sharing, each atom completes its valence shell and attains the nearest inert gas configuration. A covalent bond may be nonpolar or polar in character.
  • B. Hydrogen bonding is a special type of dipole-dipole interaction that occurs between the lone pair of a highly electronegative atom (typically N, O, or F) and the hydrogen atom in a N–H, O–H, or F–H bond.The strength of hydrogen bond is generally twenty times less than that of a covalent bond..
  • D. A coordinate covalent bond is formed between two atoms when the shared pair of electrons is donated by one of the bonded atoms. Let us consider the example of bond formation between NH3 and BF3 . NH, has three covalent bonds and there is a lone pair of electrons on the nitrogen atom. On the other hand, the boron atom in BF3 is deficient in electrons. Actually, the octet of B is not complete in BF3 . Therefore, nitrogen can donate the pair of electrons to the acceptor BF3 and this results in the formation of a coordinate covalent bond.

Q59. The bond angle in a molecule having Sp3 hybridization with no lone pair is:

  • A. 120 Angle
  • B. 180 Angle
  • C. 109 Angle
  • D. 90 angle

Explanation: According to the hybridization theory, atomic orbitals differ slightly in energy intermix to form new orbitals, which are called hybrid atomic orbitals. They differ from the parent atomic orbitals in shape and possess specific geometry. The atomic orbital hybridization gives a satisfactory explanation for the valency of the elements. In some cases, the electrons belonging to the ground state are promoted to the excited state as a result of which there is an increase in the number of unpaired electrons.energy changes occur in hybridization.

Why the other options are wrong
  • A. It is formed when the three half filled sp2 hybrid orbitals are planar and are oriented at an angle of 120°, The sp2 hybridization explains the geometry of planar molecules such as BF3.
  • B. The option is incorrect as the angle formed i of 109.5 degree.
  • D. The option is incorrect as the angle formed is 109.5 degree.

Q60. Properties of system, which depend upon the amount of substance present in the system are called:

  • A. Chemical properties
  • B. Intensive properties
  • C. Extensive properties
  • D. Physical properties

Explanation: An extensive property of a system depends on the system size or the amount of matter in the system. If the value of the property of a system is equal to the sum of the values for the parts of the system then such a property is called extensive property. Volume, energy, and mass are examples of extensive properties

Why the other options are wrong
  • A. The chemical properties of an element are determined by the number of electrons in its atom, which in turn is determined by the number of protons.
  • B. An intensive property is one that does not depend on the mass of the substance or system. Temperature (T), pressure (P) and density (r) are examples of intensive properties.An intensive property is a property of matter that depends only on the type of matter in a sample and not on the amount. Other intensive properties include colour, temperature, density, and solubility.
  • D. Physical properties of any compound depend largely on both mass and type of intermolecular and intramolecular forces of attractions

Q61. Enthalpy is the expression for the:

  • A. Reaction rate
  • B. Heat content
  • C. Energy state
  • D. Activation state

Explanation: Enthalpy is the measurement of energy in a thermodynamic system. The quantity of enthalpy equals the total content of heat of a system, equivalent to the system’s internal energy plus the product of volume and pressure. A change in enthalpy of a system can be written as: ∆ H = ∆E + ∆(PV) ∆ H = ∆E + V∆ P + P ∆V Since, the gas is kept at constant pressure, = 0 Hence ∆ H =∆ E + P ∆V …….(4) In case of liquids and solids, the changes in state do not cause significant volume change i.e. ∆V = 0 For such process, ∆H and ∆E are approximately the same i.e. ∆E ≈∆ H According to first law of thermodynamics: ∆E = q + wIf w is pressure - volume work done by the system, then: w = - P∆ V So ∆ E = q - P ∆V Putting the value of ∆E in equation 4 we get: ∆ H = q - P∆ V + P ∆V ∆H = q Since the pressure is constant, therefore, ∆H = qp......... (5) This shows that change in enthalpy is equal to heat of reaction at constant pressure. The reactions are carried out at constant pressure more frequently than at constant volume. So, working with ∆H is more convenient than ∆E .

Why the other options are wrong
  • A. Reaction rate is the speed at which a chemical reaction proceeds. It is often expressed in terms of either the concentration (amount per unit volume) of a product that is formed in a unit of time or the concentration of a reactant that is consumed in a unit of time.
  • C. Energy level, also called energy state, any discrete value from a set of values of total energy for a subatomic particle confined by a force to a limited space or for a system of such particles, such as an atom or a nucleus.
  • D. Activation energy is the minimum amount of energy that is required to activate atoms or molecules to a condition in which they can undergo chemical transformation or physical transport.

Q62. The heat require to change 1 mole of Iodine (solid) to Iodine (gas) is called:

  • A. Heat of vaporisation
  • B. Heat of sublimation
  • C. Heat of fusion
  • D. Melting point

Explanation: The heat absorbed by one gram or unit mass of a substance in the process of changing, at a constant temperature and pressure, from a solid to a gaseous state.Like vaporisation, the process of sublimation requires an input of energy to overcome intermolecular attractions. The enthalpy of sublimation, ΔHsub, is the energy required to convert one mole of a substance from the solid to the gaseous state.

Why the other options are wrong
  • A. The heat of vaporisation is defined as the amount of heat needed to turn 1g of a liquid into a vapour, without a rise in the temperature of the liquid.
  • C. The heat of fusion is the quantity of heat necessary to change 1 g of a solid to a liquid with no temperature change (Weast, 1964, p. F-44). It is also a latent heat and is sometimes called the latent heat of fusion.
  • D. The melting point is usually defined as the point at which materials change from a solid to a liquid. The temperature at which solid changes its state to liquid at atmospheric pressure is called the melting point of that liquid. This is the point at which both liquid and solid phases exist at equilibrium

Q63. In the electrolysis of CuCl2 (Copper Chloride) the substance liberated at the anode:

  • A. Copper
  • B. Chloride
  • C. Hydrogen
  • D. Copper Chloride

Explanation: Electrolysis is a process by which electrical energy is used to produce a chemical change.The electrolysis cell consists of two metallic rods known as electrodes that are connected to a battery and dipped into molten electrolyte or electrolyte solution.The electrode connected to the positive side of the battery is called the anode.The electrode connected to the negative side of the battery is called the cathode.The electrically charged cations and anions present in the electrolyte move towards the respective electrodes.That is, positively charged cations move toward the cathode and negatively charged anions move towards the anode.When the anions reach the anode, they are discharged through electron removal(oxidation), liberating neutral atoms or molecules at the electrode.When cations reach the cathode, they are neutralised through electron addition(reduction).

Why the other options are wrong
  • A. The cathode is a negative electrode and it attracts protons and Cupric ions.Cupric ions have a higher reduction potential than the water moleculeThus, the Cupric ions will be deposited at the cathode.Cupric ions accept two electrons to form Cumetal and get deposited on the cathode. Cu2+2e−→Cu
  • C. This option is incorrect as H2 isn't produced.
  • D. CuCl2 isn't produced at the anode and breaks to Cl and Cu.

Q64. Factors affecting the balance of a chemical equilibrium are following except:

  • A. Concentration
  • B. Temperature
  • C. Enthalpy
  • D. Pressure

Explanation: temperature, pressure, and concentration of the system are all factors that affect equilibrium. When one of these factors changes, the equilibrium of the system is disrupted, and the system readjusts itself until it returns to equilibrium.Le Châtelier's principle states that if a dynamic equilibrium is disturbed by changing the conditions, the position of equilibrium shifts to counteract the change to reestablish an equilibrium.The change in ENTHALPY doesn't effect the dynamic equilibrium.

Why the other options are wrong
  • A. Change in concentration affects the dynamic equilibrium
  • B. Change in temperature affects the dynamic equilibrium
  • D. Change in Pressure affect the dynamic equilibrium

Q65. The formula for general gas equation is:

  • A. P1 V1 = P2V2
  • B. V1/T1 = V2/T2
  • C. E = mc2
  • D. P1V1/T1 = P2V2/T2

Explanation: The ideal gas equation is formulated as: PV = nRT. In this equation, P refers to the pressure of the ideal gas, V is the volume of the ideal gas, n is the total amount of ideal gas that is measured in terms of moles, R is the universal gas constant, and T is the temperature.

Why the other options are wrong
  • A. It represents the boyle's law. Boyle's Law is a basic law in chemistry describing the behaviour of a gas held at a constant temperature. The law, discovered by Robert A. Boyle in 1662, states that at a fixed temperature, the volume of gas is inversely proportional to the pressure exerted by the gas.
  • B. It represents the equation for charles law.Charles law states that the volume of an ideal gas is directly proportional to the absolute temperature at constant pressure. The law also states that the Kelvin temperature and the volume will be in direct proportion when the pressure exerted on a sample of a dry gas is held constant.
  • C. It represents the energy mass equation by einstein.,E or energy, which is the entirety of one side of the equation, and represents the total energy of the system. m, or mass, which is related to energy by a conversion factor. And c2, which is the speed of light squared: the right factor we need to make mass and energy equivalent.

Q66. The electronic configurations of the noble gases are:

  • A. ns2, np5
  • B. ns2, np6
  • C. ns2, np4 , nd8
  • D. ns2, np5, nd10

Explanation: The electronic configuration of noble gases will have 8 electrons in the outermost shell except helium. Therefore they are the most stable. (b) Atoms form chemical bonds to achieve stability by acquiring inert gas electron configuration ( to fulfil the octet rule)A noble gas configuration of an atom consists of the elemental symbol of the last noble gas prior to that atom, followed by the configuration of the remaining electrons.

Why the other options are wrong
  • A. The electronic configuration represents group 5A elements .
  • C. The electronic configuration does not exist.
  • D. The electronic configuration does not exist.

Q67. The electro-negativity of the element is increased:

  • A. Down the group
  • B. Across the period from right to left
  • C. Across the period from left to right
  • D. None of the above

Explanation: In a bond between dissimilar atoms such as in HF the electron density of the bonding electrons lies more towards the fluorine atom than towards the hydrogen atom. The tendency of an atom to attract a shared electron pair towards itself is called its electronegativity.

Why the other options are wrong
  • A. From top to bottom down a group, electronegativity decreases. This is because atomic number increases down a group, and thus there is an increased distance between the valence electrons and nucleus, or a greater atomic radius.
  • B. It decreases from right to left due to increase in size.
  • D. It isn't correct.

Q68. Which of the following is the most suitable alotropy of sulphur:

  • A. Plastic sulphur
  • B. Monoclinic sulphur
  • C. Rhombic sulphur
  • D. Laughing gas

Explanation: Rhombic sulphur is crystalline in nature and has an octahedral shape.Octahedral sulphur:- this is also known as rhombic sulphur and is the most stable form as it is insoluble in water and is prepared by evaporating the solution of roll sulphur in carbon disulphide.. On heating the solution of roll sulphur in CS2 we get rhombic sulphur. It is yellow with a melting point of 385.8K and specific gravity of 2.06. Rhombic sulphur cannot be dissolved in water but can be dissolved in benzene, ether, alcohol etc

Why the other options are wrong
  • A. Plastic sulphur:- it is a type of amorphous sulphur and is not stable at all temperatures. Hence this option is also incorrect.
  • B. Monoclinic sulphur:- it is prepared by melting rhombic sulphur in a dish and cooling , till the crust is formed. Two holes are made in the crust and remaining liquid is poured out . On removing the crust, colourless needle shaped crystals of monoclinic sulphur are formed.This allotrope is only stable at temperature above 369K . So this option is not correct.
  • D. Nitrous oxide, commonly known as laughing gas, nitrous, or nos, is a chemical compound, an oxide of nitrogen with the formula N ₂O. At room temperature, it is a colourless non-flammable gas, and has a slightly sweet scent and taste.

Q69. S — black element have the folowing properties except:

  • A. Reaction with water gives hydroxides
  • B. Reaction with water gives different oxides
  • C. Reaction with metals to give binary ionic salts
  • D. Reaction with non-metals to give binary ionic salts

Explanation: Alkali and alkaline metals are reducing in natureThey have low ionisation enthalpies They lose the outermost electron(s) to form cation .Group 1 elements lose 1 electron while the group 2 elements loses 2 electrons .Metallic character increases down the group .Because of high reactivity they are never found pure in nature .Reactivity increases down the group .Compounds of s-Block are ionic in nature.They form binary ionic compounds with non metals .Exception to this is beryllium and lithium

Why the other options are wrong
  • A. Very rapid reactions occur when alkali metals react with water. A small piece of sodium (potassium or lithium) floated on water reacts vigorously to liberate hydrogen and produce metal hydroxide. The reaction is highly exothermic. The energy produced by the reaction may even ignite the hydrogen 2Na + 2H2O—-----> 2NaOH + H 2 The reaction becomes increasingly vigorous from lithium to caesium. Potassium, rubidium and caesium are so highly reactive that they react with ice even at -100°C.Similar reactions are shown by alkaline earth metals. The option is incorrect as they react with H2O to give hydroxides
  • B. Alkali metals of the s-block elements react with water very fast with formic hydroxides along with the release of H2 gas. • Least reactive metal with water will is Li and maximum is Cs igneous reactivity water increases from Li to Cs.• Alkaline earth metals will react slowly with water and give hydrogen with metal •Be does not react with water Mg reacts with only hot water.Ca and Ba react with cold water but not like that alkali metals.
  • D. Lithium is the only Group IA metal that combines with nitrogen and carbon to form nitride and carbide, respectively. Lithium nitride 6Li + N 2—--->2Li3N Lithium carbide 4Li + C—---> Li4C Alkali metals react easily with halogens to give halides. Lithium and sodium, for example, react slowly with chlorine at room temperature. Molten sodium burns with a brilliant yellow flame in a chlorine atmosphere to form sodium chloride. 2Na + 2Cl—----> 2NaCl Potassium, rubidium and caesium react vigorously with all the halogens, forming metal halides. All alkali metals form their sulphides when treated with molten sulphur. The general reaction is: 2M + S —--> M2SSimilar reactions are shown by alkaline earth metals.

Q70. Melting and Boiling points of transitive elements is high because:

  • A. Half filled d-orbit
  • B. Metabolic bond
  • C. Small atomic size and valence electrons
  • D. None of the above

Explanation: Transition metals have very high melting and boiling points due to strong binding forces present between their atoms Melting points increase up to the middle of the series and the Transition metals tend to have particularly high melting points and boiling points. The reason is that they can involve the 3d electrons in the delocalisation as well as the 4s. The more electrons you can involve, the stronger the attractions tend to be.Transition elements have a high melting point because of the presence of metallic properties. They also have large ionisation enthalpies that increase their melting and boiling points. Transition elements can also form covalent bonds with other elements

Why the other options are wrong
  • A. The transition metals are characterised by partially filled d subshells in the free elements and cations. The ns and (n − 1)d subshells have similar energies, so small influences can produce electron configurations that do not conform to the general order in which the subshells are filled.The transition metal ions containing unpaired d-electrons undergoes electronic transition from one d-orbital to another. During this d-d transition process the electrons absorb certain energy from the radiation and emit the remainder of energy as colored light.
  • C. They are large in size and have greater atomic radii as compared to s and p block elements.The atomic and ionic radii of the transition elements decrease from group 3 to group 6 due to the poor shielding offered by the small number of d-electrons. Those placed between groups 7 and 10 have somewhat similar atomic radii and those placed in groups 11 and 12 have larger radii.
  • D. This option is incorrect.

Q71. The compound formed by the action of the water on the Calcium carbide is

  • A. Ethane
  • B. Ethene
  • C. Acetylene
  • D. Methane

Explanation: On industrial scale ethyne is prepared by the reaction of calcium carbide (CaC2 ) with water Calcium carbide is prepared by heating lime (CaO) and coke (C) at a very high temperature in an electric furnace at 2000 C CaO+3C—--> CaC +CO CaC2+2H2O→AcetyleneCH≡CH+Ca(OH)2 ​The reaction of calcium carbide and water produces acetylene gas (C2H2) and calcium hydroxide.

Why the other options are wrong
  • A. Acetylene is produced when calcium carbide reacts with water.
  • B. Acetylene is produced when calcium carbide reacts with water
  • D. Acetylene is produced when calcium carbide reacts with water.

Q72. The fat soluble vitamins is:

  • A. Vitamin A
  • B. Vitamin B-12
  • C. Niacin
  • D. None of the above

Explanation: Vitamins A are called the fat-soluble vitamins, because they are soluble in organic solvents and are absorbed and transported in a manner similar to that of fats.Vitamin A is an essential nutrient for humans. It is a group of organic compounds that includes retinol, retinal, retinoic acid, and several provitamin A carotenoids.

Why the other options are wrong
  • B. Vitamin B₁₂, also known as cobalamin, is a water-soluble vitamin involved in metabolism. It is one of eight B vitamins. It is required by animals, which use it as a cofactor in DNA synthesis, in both fatty acid and amino acid metabolism.
  • C. Niacin is a B vitamin that's made and used by your body to turn food into energy. .It is a water soluble vitamin.It helps keep your nervous system, digestive system and skin healthy. Niacin (vitamin B-3) is often part of a daily multivitamin, but most people get enough niacin from the food they eat.
  • D. This option is incorrect .

Q73. The formula which indicates the relative numbers of different kinds of the atoms in a molecule is called:

  • A. Structural formula
  • B. Empirical formula
  • C. Molecular formula
  • D. None of the above

Explanation: The molecular formula is an expression that defines the number of atoms of each element in one molecule of a compound. It shows the actual number of each atom in a molecule. For example, the molecular formula of propane is C4H10. In this formula, there are 4 carbon atoms and 10 hydrogen atoms in the given compound

Why the other options are wrong
  • A. A structural formula displays the atoms of the molecule in the order they are bonded. It also depicts how the atoms are bonded to one another, for example single, double, and triple covalent bonds. Covalent bonds are shown using a line.
  • B. The empirical formula of a compound gives the simplest ratio of the number of different atoms present, whereas the molecular formula gives the actual number of each different atom present in a molecule. If the formula is simplified then it is an empirical formula. The molecular formula is commonly used and is a multiple of the empirical formulaThe general statement relating molecular formula and the empirical formula is:Molecular Formula = n × Empirical Formula
  • D. This option is incorrect.

Q74. Methane is obtained by which following method:

  • A. Electrolysis of sodium acetate
  • B. Electrolysis of aluminium carbide
  • C. Heating sodium acetate with soda lime
  • D. All of these

Explanation: When sodium acetate(CH3COONa)reacts with soda lime(NaOH + CaO), it undergoes a decarboxylation reaction and gives methane (CH4) and sodium carbonate.

Why the other options are wrong
  • A. When sodium acetate is electrolysed, ethane is producedWhen a concentrated solution of sodium or potassium salt of a mono carboxylic acid is electrolysed, an alkane is produced. This method is only suitable for the preparation of symmetrical alkanes i.e. those of the type R—R. Methane cannot be prepared by this method.. When potassium salt of acetic acid is electrolysed, acetate ion migrates towards the anode gives up one electron to produce acetate free radical (CH3 COO), which decomposes to give a methyl free radical (CH3 ) and CO2 .Two such methyl radicals combine to give ethane. .;
  • B. Methane is not produced by the electrolysis of molten aluminium carbide.The carbon electrode acting as the anode (positively charged) is burnt away. In the electrolysis of molten aluminium oxide using carbon electrodes, the pure metal is formed at the cathode (negatively charged electrode) and oxygen is formed at the anode (positively-charged electrode). This oxygen reacts with positively-charged carbon electrodes and produces carbon dioxide gas. Due to this reaction between oxygen and carbon electrode (anode), the carbon electrode burns away gradually and has to be replaced.
  • D. This option is incorrect.

Q75. The following reactions is an example of C.H8 + → heat → C3H6Cl2 + 2HCL

  • A. Addition reaction
  • B. Reduction reaction
  • C. Oxidation reaction
  • D. Substitution reaction

Explanation: Alkanes react with chlorine and bromine in the presence of sunlight or UV light or at high temperature resulting in the successive replacement of hydrogen atoms with halogens called halogenation. Extent of halogenation depends upon the amount of halogen used. Reaction of alkanes with fluorine is highly violent and results in a mixture of carbon, fluorinated alkanes and hydrofluoric acid. Iodine does not substitute directly because the reaction is too slow and reversible. The order of reactivity of halogens is F2 >Cl2 >Br2 >I2. CH4+Cl2→CH3Cl+HCl.

Why the other options are wrong
  • A. In organic chemistry, an addition reaction is an organic reaction in which two or more molecules combine to generate a bigger one (the adduct). Molecules with carbon—hetero double bonds, such as carbonyl (C=O) or imine (C=N) groups, can be added because they have double-bond character as well
  • B. Any process in which there is a increase in the number of covalent bonds between an atom and atom(s) that are less electronegative. Commonly seen as, but not limited to, increasing the number of bonds between carbon and hydrogen.
  • C. Oxidation of an organic compound results in an increase in the number of carbon-heteroatom bonds, and/or a decrease in the number of carbon-hydrogen bonds. Reduction of an organic compound results in a decrease in the number of carbon-heteroatom bonds, and/or an increase in the number of carbon-hydrogen bonds.

Q76. In which of the following reaction the rate of nucleophilic substitution depend upon the concentration of the alkyl halide only:

  • A. SN1
  • B. SN2
  • C. SN3
  • D. Addition reaction

Explanation: the bond breaks first followed by the formation of a new bond, the mechanism is called SN1.Since the first step involves the breakage of a covalent bond, it is a slow step as compared to the second step which involves the energetically favourable combination of ions. The first step is, therefore, called the rate-determining step. The mechanism is called unimolecular because only one molecule takes part in the rate determining step.In SN1 mechanism, the nucleophile attacks when the leaving group has already gone, so the question of the direction of the attack does not arise. Moreover, the intermediate carbocation is a planar species allowing the nucleophile to attack it from both directions with equal ease. We, therefore, observe 50% inversion of configuration and 50% retention of configuration. Reactions involving SN1 mechanism show first order kinetics and the rates of such reactions depend only upon the concentration of the alkyl halide. The rate equation of such reactions can be written as follows. Rate = k [Alkyl halide] Tertiary alkyl halides when attacked by a nucleophile always follow SN1 mechanism R

Why the other options are wrong
  • B. the two processes occur simultaneously the mechanism is called SN2 This is a single step mechanism. As soon as the nucleophile starts attacking the electrophilic carbon of the substrate, the bond with which the leaving group is attached, starts breaking. In other words the extent of bond formation is equal to the extent of bond breakage. Another important feature of this mechanism is the direction of the attack of the attacking nucleophile. It attacks from the side which is opposite to the leaving group.Kinetic studies of the reactions involving SN2 mechanism have shown that the rates of such reactions depend upon the concentrations of alkyl halide as well as the attacking nucleophile. Mathematically, the rate can be expressed as : Rate = k [Alkyl halide]1 [Nucleophile]1 Since the exponents of the concentration terms in the above expression are unity, so the order of a typical SN2 reaction will be 1 + 1 = 2. Among the alkyl halides, the primary alkyl halides always follow SN2 mechanism whenever they are attacked by nucleophiles.
  • C. This type of reaction does not occur .
  • D. This option is incorrect.

Q77. In the phenol:

  • A. Alcoholic group attached on ring structure
  • B. Hydroxyl group attached on benzene ring
  • C. Alcoholic group attached on benzene ring
  • D. All of the above

Explanation: It consists of a phenyl group ( −C 6H 5) bonded to a hydroxyl group ( −OH). Mildly acidic, it requires careful handling because it can cause chemical burns.:The hydroxyl group in phenol is involved in the formation of intermolecular hydrogen bonding. Thus, hydrogen bonds are formed between water and phenol molecules which make phenol soluble in water. However, the aryl group attached to the hydroxyl group is hydrophobic in nature

Why the other options are wrong
  • A. Phenol (also called carbolic acid) is an aromatic organic compound with the molecular formula C 6H 5OH. It is a white crystalline solid that is volatile. The molecule does not contain an alcoholic groupIt consists of a phenyl group ( −C 6H 5) bonded to a hydroxyl group ( −OH).
  • C. Phenol does not contain an alcoholic group It consists of a phenyl group ( −C 6H 5) bonded to a hydroxyl group ( −OH).
  • D. This option is incorrect.

Q78. P.V.C. prepared from:

  • A. Ethene and hydrogen chloride
  • B. Ethane and hydrogen chloride
  • C. Methane and hydrogen chloride
  • D. Acetylene and hydrogen chloride

Explanation: It is an addition polymer obtained by polymerizing vinyl chloride at 52°C and 9 atmospheric pressure.Ethene reacts with hcl to form vinyl chloride. The electrolysis of salt water produces chlorine. The chlorine is then combined with ethylene that has been obtained from oil. The resulting element is ethylene dichloride, which is converted at very high temperatures to vinyl chloride monomer. These monomer molecules are polymerized forming polyvinyl chloride resin.

Why the other options are wrong
  • B. HCl is not used in chlorination of any alkane as the bond between them is highly polar which dissociates to give H+ and Cl− that will not be able to initiate the formation of free radicals in alkane. In this case H+ will be released from the alkane as carbon is more electronegative than hydrogen
  • C. HCl is not used in chlorination of any alkane as the bond between them is highly polar which dissociates to give H+ and Cl− that will not be able to initiate the formation of free radicals in alkane. In this case H+ will be released from the alkane as carbon is more electronegative than hydrogen

Q79. Methyl alcohol is also known as:

  • A. Wood spirit
  • B. Wood naphtha
  • C. Methanol
  • D. All of these

Explanation: Methanol (also called methyl alcohol and wood spirit, amongst other names) is an organic chemical and the simplest aliphatic alcohol, with the formula CH3OH (a methyl group linked to a hydroxyl group, often abbreviated as MeOH). It is a light, volatile, colourless, flammable liquid with a distinctive alcoholic odour similar to that of ethanol (potable alcohol).A polar solvent, methanol acquired the name wood alcohol because it was once produced chiefly by the destructive distillation of wood. Today, methanol is mainly produced industrially by hydrogenation of carbon monoxide.Methanol consists of a methyl group linked to a polar hydroxyl group. With more than 20 million tons produced annually, it is used as a precursor to other commodity chemicals, including formaldehyde, acetic acid, methyl tert-butyl ether, methyl benzoate, anisole, peroxyacids, as well as a host of more specialised chemicalsUseful search terms for methyl alcohol include “methanol,” “carbinol,” “columbian spirits,” “pyroligneous spirits,” “wood alcohol,” “wood naphtha,” and “wood spirits.”

Why the other options are wrong
  • A. Methanol (also called methyl alcohol and wood spirit, amongst other names) is an organic chemical and the simplest aliphatic alcohol, with the formula CH3OH (a methyl group linked to a hydroxyl group, often abbreviated as MeOH). It is a light, volatile, colourless, flammable liquid with a distinctive alcoholic odour similar to that of ethanol (potable alcohol).A polar solvent, methanol acquired the name wood alcohol because it was once produced chiefly by the destructive distillation of wood. Today, methanol is mainly produced industrially by hydrogenation of carbon monoxide. Methanol consists of a methyl group linked to a polar hydroxyl group. With more than 20 million tons produced annually, it is used as a precursor to other commodity chemicals, including formaldehyde, acetic acid, methyl tert-butyl ether, methyl benzoate, anisole, peroxyacids, as well as a host of more specialised chemicals Useful search terms for methyl alcohol include “methanol,” “carbinol,” “columbian spirits,” “pyroligneous spirits,” “wood alcohol,” “wood naphtha,” and “wood spirits.”
  • B. b) Wood naphtha: Wood naphtha is not the same as methyl alcohol. Wood naphtha refers to a mixture of volatile hydrocarbons obtained from the distillation of wood tar.
  • C. c) Methanol: Methanol is the systematic name for methyl alcohol. It is a simple alcohol with the chemical formula CH3OH. Methanol is commonly used as an industrial solvent, antifreeze, fuel, and in the production of various chemicals.

Q80. Commercially nitric acid is prepared by the:

  • A. Oxidation of ammonia by Bayer's method
  • B. Oxidation of ammonia by Oswald’s method
  • C. Reduction of ammonia by Oswald’s method
  • D. Oxidation of ammonia by Hoop's process

Explanation: Nitric oxide is a colourless liquid that is used in the manufacture of inorganic and organic nitrates and nitro compounds for fertilisers, dye intermediates, explosives, and many different organic chemicals. Nitric acid is most commonly manufactured by the Ostwald process. The Ostwald process converts ammonia to nitric acid and involves two steps. In step 1,NH3 is oxidised to form nitric oxide and also NO2. Then in step 2, the nitrogen dioxide that was formed is absorbed in water. This in-turn forms nitric acid. The Ostwald process has many well-known uses in both the industrial and health field. Through the Ostwald process, nitric acid is commonly used in fertilisers and pharmaceuticals, and because of its chemical reaction with some compounds, it is used in rocket fuel and explosives like trinitrotoluene (TNT). OSTWALD PROCESS FOR MAKING NITRIC ACID: Step 1 - Primary oxidation (formation of nitric acid) Oxidation of ammonia is carried out in a catalyst chamber in which one part of ammonia and eight parts of oxygen by volume are introduced. The temperature of the chamber is about 600oC. This chamber contains a platinum gauze which serves as the catalyst. Oxidation of ammonia is a reversible and exothermic process. Therefore according to Le- chatelier’s principle, a decrease in temperature favours reaction in forwarding direction. In primary oxidation, 95 percent of ammonia is converted into nitric oxide (NO). 4NH3 + 5O2 ↔ 4NO + 6H2O ?H -24.8 Kcal/mol Step 2 - Secondary oxidation (formation of nitrogen dioxide) Nitric oxide gas obtained by the oxidation of ammonia is very hot. In order to reduce its temperature, it is passed through a heat exchanger where the temperature of nitric oxide is reduced to 150oC NITRIC OXIDE after cooling is transferred to another oxidising tower where at about 50oC it is oxidised to nitrogen dioxide (NO2). 2NO + O2 ↔2 NO2 Step 3 - Absorption of NO2 (formation of HNO3) Nitrogen dioxide from the secondary oxidation chamber is introduced into a special absorption tower. NO2 gas passes through the tower and water is showered over it. By the absorption, nitric acid is obtained. 3NO2 + H2O -> 2HNO3 + NO Nitric acid obtained is very dilute. It is recycled in the absorption tower so that more and more NO2 gets absorbed. HNO3, after recycling, becomes about 68 percent concentrated. Step 4 - Concentration In order to increase the concentration of HNO3, vapours of HNO3 are passed over concentrated H2SO4. Being a dehydrating agent, H2SO4 absorbs water from HNO3 and concentrated HNO3 is obtained.

Why the other options are wrong
  • A. In the Bayer process, prepared bauxite ore is digested under pressure in a hot aqueous solution of sodium hydroxide and then 'seeded' to induce precipitation of Al(OH)3 crystals, usually referred to by the mineral term 'gibbsite'.
  • C. Ammonia is not reduced it is oxidised in the ostwald process.
  • D. Ammonia is reduced in the Hoopes process.The Hoopes process is a metallurgical process, used to obtain the aluminium metal of very high purity(about 99.9% pure). The process was patented by William Hoopes, a chemist of the Aluminum Company of America (ALCOA) in 1925.The cell used in this process consists of an iron tank lined with carbon at the bottom. A molten alloy of copper, crude aluminium and silicon is used as the anode. It forms the lowermost layer in the cell. The middle layer consists of a molten mixture of fluorides of sodium, aluminium and barium (cryolite + BaF2). The uppermost layer consists of molten aluminium. A set of graphite rods dipped in molten aluminium serve as the cathode. During electrolysis, Al3+ ions from the middle layer migrate to the upper layer, where they are reduced to aluminium by gaining 3 electrons. Equal numbers of Al3+ ions are produced in the lower layer. These ions migrate to the middle layer. Pure aluminium is tapped off from time to time. The Hoopes process gives about 99.99% pure aluminium.

Q81. Which of the following quantities are vector:

  • A. Time and Mass
  • B. Force and Displacement
  • C. Length and Weight
  • D. Temperature and Density

Explanation: A vector is a quantity or phenomenon that has two independent properties: magnitude and direction. Vector quantities refer to the physical quantities characterised by the presence of both magnitude as well as direction.The term also denotes the mathematical or geometrical representation of such a quantity. For example, displacement, force, torque, momentum, acceleration, velocity, etc.

Why the other options are wrong
  • A. Time and mass are scalar quantities.
  • C. Weight is a force which is a vector and length is a scalar quantity.
  • D. Temperature and density both are scalars .

Q82. momentum of the body increase by 20% what is the % increase in it’s K.E.:

  • A. 36
  • B. 44
  • C. 52
  • D. 60

Explanation: The percentage increase in the KE is 44 %.

Why the other options are wrong
  • A. The percentage increase in the KE is 44 %.
  • C. The percentage increase in the KE is 44 %.
  • D. The percentage increase in the KE is 44 %.

Q83. Which one of the following statement is incorrect:

  • A. A body has a constant velocity but varying speed
  • B. A body has a constant speed but varying acceleration
  • C. A body has a constant speed can not has a acceleration
  • D. Body has a constant speed can has varying velocity

Explanation: A body's velocity cannot be constant while its speed fluctuates.

Why the other options are wrong
  • B. A body can have a constant speed and still be accelerating. Note: All circular motions where the object is moving with constant velocity are a great example of cases where the body will have constant speed but it will be still accelerating since the velocity changes due to a change in direction of the object. An example of the motion of a body moving with the constant speed with variable velocity is the motion of a body in a circular path as in a circular path, the direction of motion of the body changes continuously with time.
  • C. Yes, an object that was set in motion in the past by some force, but that is no longer being acted on by a net force, is moving but with zero acceleration, i.e. it is moving at constant velocity. {SPEED}
  • D. Yes if the body is travelling with uniform speed in a circular track its speed remains the same but the velocity is non-uniform as the direction of the body is changing every time.

Q84. Centripetal force ‘FC' is given by:

  • A. mv2/r
  • B. mv/r
  • C. m2v/r
  • D. mv/l

Explanation: The centripetal force has the formula mv2\r.

Why the other options are wrong
  • B. The centripetal force has the formula mv2\r.
  • C. The centripetal force has the formula mv2\r.
  • D. The centripetal force has the formula mv2\r.

Q85. Value of 'G' is:

  • A. 6.667 x 1011 N-m2/Kg
  • B. 6.667 x 10-11 Nm/Kg2
  • C. 6.667 x 1013 Nm2/Kg
  • D. 6.667 x 10-11 Nm2/Kg2

Explanation: The universal gravitational constant (G) relates the magnitude of the gravitational attractive force between two bodies to their masses and the distance between them. Its value is extremely difficult to measure experimentally.

Why the other options are wrong
  • A. The units used are not correct.It is not 6.6x10^-11Nm²\KgThe value is 6.6x10^-11 Nm²\kg².
  • B. The units used are not correct.It is not 6.6 x10 ^-11 Nm \kg².The value is 6.6x10^-11 Nm²\kg².
  • C. The units used are not correct.It is not 6.6 x10 ^-11 Nm \kg².The value is 6.6x10^-11 Nm²\kg².

Q86. If we go away from the surface of the earth at a distance equal to radius of the earth then the value of 'g' will be:

  • A. 1/4
  • B. 1/8
  • C. 1/2
  • D. 1/9

Explanation: If we go away from the earth surface equal to the radius of earth the value of G becomes ¼ of it. Acceleration due to gravity = g=GM earth \R2 R = distance from the centre of the earth At a height = R above earth's surface g=GMearth\(R+R)2 GM earth\4R2=g\4

Why the other options are wrong
  • B. The value of g will be g\4.this otion is incorrect.
  • C. The value of g will be g\4.this otion is incorrect.
  • D. The value of g will be g\4.this otion is incorrect.

Q87. The energy of a body at height 'h' from the center of earth to the which g = 0 is called:

  • A. Kinetic energy
  • B. Potential energy
  • C. Gravitational energy
  • D. Absolute potential energy

Explanation: Absolute potential energy is defined as the amount of work that needs to be done on an object to bring an object to its current location from a point of infinite distance. It can also be defined as the energy needed for an object to reach escape velocity So the absolute potential energy is the correct answer and has a non zero value .

Why the other options are wrong
  • A. It is not correct as F=1\2 mv2.it doesn't depend on the height of object and a static object is being considered so v =0 hence KEV =0 Kinetic energy is the energy an object has because of its motion.Kinetic energy can be transferred between objects and transformed into other kinds of energy.
  • B. It is incorrect as P.E=mgh and g=0.Potential energy, stored energy that depends upon the relative position of various parts of a system. A spring has more potential energy when it is compressed or stretched. A steel ball has more potential energy raised above the ground than it has after falling to Earth.
  • C. It is incorrect as U=mgh and g=0.Gravitational energy is the energy stored in an object due to its height above the Earth (e.g. if it's further away or closer to the ground). It is a form of potential energy. An object's height above the ground gives it gravitational energy.

Q88. Which one of the following is not regarded as a fundamental quantity in physics:

  • A. Length
  • B. Time
  • C. Mass
  • D. Force

Explanation: Any physical quantity can be measured and expressed in terms of magnitude and a unit. The physical quantities which do not depend on any other physical quantities for their measurements are known as fundamental quantities or base quantities.Following are the seven fundamental quantities:Length (metre),Mass (kilogram),Time (second),Electric current (ampere),Thermodynamic temperature (kelvin),Amount of substance (mole),Luminous intensity (candela.

Why the other options are wrong
  • A. Length is a fundamental quantity.
  • B. Time is a fundamental quantity.
  • C. Mass is a fundamental constant.

Q89. Acoustics is the study:

  • A. Production of sound
  • B. Production and properties of the sound
  • C. Source of sound
  • D. Intensity, Frequency and quality of sound

Explanation: Acoustics deal with production and properties of the sound

Why the other options are wrong
  • A. Acoustics is defined as the science that deals with the production, control, transmission, reception, and effects of sound.Acoustics is a branch of physics that deals with the study of mechanical waves in gases, liquids, and solids including topics such as vibration, sound, ultrasound and infrasound. Acoustics deal with the study of production of sound.
  • C. Acoustics deal with the source of sound.
  • D. Acoustics doesn't deal with them.

Q90. Which of the given condition is not a possible to discuss the Doppler's effect:

  • A. When the listener is at moving and the source as at rest
  • B. When the listener is at rest and the source is at moving
  • C. When the listener and the source are at rest
  • D. When the listener and source are at moving

Explanation: Doppler effect in physics is defined as the increase (or decrease) in the frequency of sound, light, or other waves as the source and observer move towards (or away from) each other. Waves emitted by a source travelling towards an observer get compressed.Doppler Effect is applicable only when the velocities of the source of the sound and the observer are much less than the velocity of sound. The motion of both source and the observer should be along the same straight line.

Why the other options are wrong
  • A. Case I: An observer moving away from the stationary source.Case II:An observer moving towards the stationary source
  • B. Case I: A source moving away from the stationary observerCase II:A source moving towards the stationary observer.
  • D. Source and listener move away from each other.Source and observer move towards each other.

Q91. Michelson interferometer is the instrument used to record the interference pattern of the light used to calculate:

  • A. Interaction of light
  • B. Wave length
  • C. Refraction of light
  • D. Diffraction of light

Explanation: A Michelson interferometer is an instrument used to measure the wavelength of light or to observe interference patterns generated by light waves. It is a valuable tool in the field of optics and interferometry, allowing for precise measurements of wavelengths and other optical phenomena.

Why the other options are wrong
  • A. While Michelson interferometers do involve the interaction of light waves, their primary purpose is to measure the wavelength of light or to observe interference patterns.
  • C. Michelson interferometers are not specifically designed to measure or study the refraction of light. They are more focused on studying interference phenomena and determining the wavelength of light.
  • D. Michelson interferometers primarily deal with interference patterns and wavelength measurement rather than the diffraction of light. Diffraction refers to the bending of light waves around obstacles and the creation of various patterns.

Q92. The specific heat time the mass of a body is called:

  • A. Specific heat mass
  • B. Thermal capacity
  • C. Internal energy
  • D. Heat capacity

Explanation: The specific heat time the mass of the body is specific heat mass.

Why the other options are wrong
  • B. Heat capacity is the heat required to increase an object temperature by one degree. Heat gain or loss results in changes in temperature, state, and performance of the work. Heat is a transfer of energy. The heat capacity of a defined object is usually expressed in joules or calories and temperature in Kelvin or Celsius. Thermal capacity or heat capacity is the product of the mass of the substance times its specific heat capacity. Thus thermal capacity = Mass of substance X Specific heat capacity of the substance.
  • C. Internal energy is the sum of all the microscopic forms of energy of a system; the internal energy of a thermodynamic system is the total energy contained within it. It is the energy necessary to create or prepare the system in its given internal state, and includes the contributions of potential energy and internal kinetic energy.
  • D. Heat capacity or thermal capacity is a physical property of matter, defined as the amount of heat to be supplied to an object to produce a unit change in its temperature. The SI unit of heat capacity is joule per kelvin (J/K). Heat capacity is an extensive property.

Q93. The electric field intensity at a distance of 1m from a point of charge to 1 micro coulomb is:

  • A. 1/4
  • B. 9 x 109 N/C
  • C. 9 x 106 N/C
  • D. 9 x 103 N/C

Explanation: AS we know F=KQ\r2Q=1 MICRO C r=1m K=9X10 ^9 Nm2\C2 F=(9x10⁹) x( 1 x 10-⁶) \1 F=9x10 ⁹-⁶F=9x10 ³F=9000N

Why the other options are wrong
  • A. The force is 9000N .this option is incorrect.
  • B. The force is 9000N .this option is incorrect.
  • C. The force is 9000N . this option is incorrect.

Q94. The unit of rate of change of momentum is:

  • A. N
  • B. NC
  • C. NS2
  • D. N/S

Explanation: Rate of change in momentum is newton(N).

Why the other options are wrong
  • B. The unit of rate of change in momentum is newton(N).
  • C. The unit of rate of change in momentum is newton(N).
  • D. The unit of rate of change in momentum is newton(N)

Q95. Dot product of force and displacement is:

  • A. Momentum
  • B. Moment
  • C. Power
  • D. Work

Explanation: Work is defined as the dot product of force and displacement.(F.S)

Why the other options are wrong
  • A. The expression for this angular momentum is l=r×p where the vector r is from the origin to the particle, and p is the particle’s linear momentum.Linear momentum is a vector quantity, and in Newtonian mechanics the linear momentum of a particle is given by p=mv.A dot product takes two vectors and returns a scalar value, not a vector, so it returns the wrong type of value to be linear momentum.A cross product takes two vectors and returns a pseudovector, which is subtly different from a vector, and is also of the wrong type of value to be a linear momentum
  • B. Moment of inertia is defined as the quantity expressed by the body resisting angular acceleration which is the sum of the product of the mass of every particle with its square of a distance from the axis of rotation.
  • C. Power is a vector product of force and velocity. P=FXV

Q96. Work done in unit time is:

  • A. Pressure
  • B. Work
  • C. Energy
  • D. Power

Explanation: Power, (P) is defined as the rate of doing work or work done, W per unit time, (t). ⟹P=Wt. The SI unit of power is watt and is represented by W.

Why the other options are wrong
  • A. Pressure is the force applied perpendicular to the surface of an object per unit area over which that force is distributed. Gauge pressure is the pressure relative to the ambient pressure. Various units are used to express pressure
  • B. Work done on an object is defined as the magnitude of the force multiplied by the distance moved by the object in the direction of the applied force. Work done = force × distance.
  • C. Energy is the capacity to do work. The SI unit of energy is Joule (J). The various forms include potential energy, kinetic energy, heat energy, chemical energy, electrical energy and light energy.

Q97. Erg is unit of energy in:

  • A. MKS
  • B. SI
  • C. FPS
  • D. CGS

Explanation: The CGS system is a coherent system of units based on the fundamental units of centimetre for distance, gram for mass, and second for time. It was superseded by the MKS system, which was based on the fundamental units of metre for distance, kilogram for mass, and second for time.The erg (symbol, erg, i.e. the same as the unit) is the unit of energy in the cgs system, where one erg represents the work done when a force of one dyne is acting over a distance of one cm and is equivalent to 1 x 10-7 joules.

Why the other options are wrong
  • A. The MKS system of units is a physical system of measurement that uses the metre, kilogram, and second as base units. It forms the base of the International System of Units, though SI has since been redefined by different fundamental constants. Joule (J) is the MKS unit of energy, equal to the force of one Newton acting through one metre
  • B. Joule [J] is the basic energy unit of the metric system, or in a later more comprehensive formulation, the International System of Units (SI). It is ultimately defined in terms of the metre, kilogram, and second.
  • C. The foot-pound-second (fps) system of units is a scheme for measuring dimensional and material quantities. The fundamental units are the foot for length, the pound for weight, and the second for time.Its unit in FPS is poundal x Foot

Q98. Number of vibration in 1 sec is:

  • A. Time period
  • B. Frequency
  • C. Amplitude
  • D. none of these

Explanation: The number of vibrations made by the vibrating body in one second is called frequency.It is measured in hertz[Hz]

Why the other options are wrong
  • A. The time period is the time taken by a complete cycle of the wave to pass a point.The time is measured in s (seconds).
  • C. The amplitude of a periodic variable is a measure of its change in a single period. The amplitude of a non-periodic signal is its magnitude compared with a reference value. There are various definitions of amplitude, which are all functions of the magnitude of the differences between the variable's extreme values.
  • D. this option is incorrect.

Q99. Total energy of vibrating body is:

  • A. Increase
  • B. Decrease
  • C. Constant
  • D. None of these

Explanation: The total energy of the vibrating mass and spring is constant. When the KE of the mass is maximum, the PE of the spring is zero. Conversely, when the PE of the spring is maximum, the K.E. of the mass is zero The interchange occurs continuously from one form to the other as the spring is compressed and released alternately The variation of PE and KE with displacement is essential for maintaining oscillations. This periodic exchange of energy is a basic property of all oscillatory systems. In the case of simple pendulum gravitational PE of the mass, when displaced, is converted into K.E at the equilibrium position. The K.E. is converted into PE as the mass rises to the top of the swing. Because of the frictional forces, energy is dissipated and consequently, the systems do not oscillate indefinitely.

Why the other options are wrong
  • A. The total energy of the vibrating mass and spring is constant.
  • B. The total energy of the vibrating mass and spring is constant.
  • D. The total energy of the vibrating mass and spring is constant.

Q100. The waves in which motion of particles of medium and propagation of wave are in same direction are called :

  • A. Longitudinal
  • B. Transverse
  • C. Electromagnetic
  • D. None of these

Explanation: Longitudinal waves, also known as l-waves, are waves in which the displacement of the medium is in the same direction as the direction of travel of the wave. Longitudinal waves are also called compressional waves or compression waves, because they produce compression and rarefaction when travelling through a medium

Why the other options are wrong
  • B. A transverse wave is a wave whose oscillations are perpendicular to the direction of the wave's advance. This is in contrast to a longitudinal wave which travels in the direction of its oscillations. Water waves are an example of transverse waves.
  • C. Electromagnetic waves or EM waves are waves that are created as a result of vibrations between an electric field and a magnetic field. In other words, EM waves are composed of oscillating magnetic and electric.
  • D. this option is incorrect.

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