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Sindh Mcat Nts 2002 Iba — Solved Past Paper with Answers
All 100 MCQs from Sindh Mcat Nts 2002 Iba, solved with the correct answer highlighted and a full explanation for every question. This is a free MDCAT Sindh / DUHS past paper — no signup, no ads. Practise it interactively in timed mode, drill more with free MDCAT MCQs, or browse all Sindh / DUHS papers.
Attempt this paper interactively →Q1. _ child must respect his parents.
- A. A✓
- B. An
- C. This
- D. That
Explanation: The correct answer is 'A'. The indefinite article 'a' is used before words that begin with a consonant sound, such as 'child.' This choice ensures the sentence is grammatically correct. 'An' is incorrect because it is used before vowel sounds. 'This' and 'That' are demonstrative pronouns and do not fit the sentence structure, which requires an article.
Why the other options are wrong
- B. 'An' is used before words that start with a vowel sound. Since 'child' begins with a consonant sound, 'an' is incorrect here.
- C. 'This' is a demonstrative pronoun used to indicate something specific that is close by. It does not fit grammatically in this sentence structure.
- D. 'That' is used to refer to something specific that is farther away or less immediate. It is not suitable for the indefinite context of this sentence.
Q2. Read the paragraph carefully and gives the best answer of the given questions:College is the practising ground for the student. It is not sufficient that he gives himself up to studies. He must develop the noble qualities of showing respect to elders and teachers create a team spirit and participate in the various extracurricular activities and maintain college discipline to raise the prestige of his college.What part does college life play in the training of the students?
- A. College life groom and prepares a student for life✓
- B. Prepare the student in academics
- C. Develops noble dualities in academics
- D. Help the students to take part in extracurricular activities
Explanation: College is described as a place where the student must not only advance in his studies but improve and develop his skills by participation in various activities, learn to show respect to his seniors and teachers and do things that raise the prestige of his college. These will provide the perfect stage for grooming the student for his life and responsibilities ahead, and he must maintain a balance, only studies or studies or activities alone are not sufficient.
Why the other options are wrong
- B. The word co curricular activities broadens the horizon and states that college life is not just a source of better academics . So the option does not suit well.
- C. The word co curricular activities broadens the horizon and states that college life is not just a source of better academics . So the option does not suit well.
- D. It doesn't suit the subject of the sentence because college life enhances the academic qualities of a person along with the co curricular activities.
Q3. The branch of biology which deals with the process and the function of processes is known as:
- A. Physiology✓
- B. Pathology
- C. Histology
- D. Evolution
Explanation: The word physiology is derived from Ancient Greek (physis), meaning "nature, origin", and (logia), meaning "study of'" is the scientific study of function in living systems. This branch of biology tells us how organisms, organ systems, organs, cells, and biomolecules function in living organisms
Why the other options are wrong
- B. Pathology deals with causes and effects of diseases and laboratory examination.
- C. Histology is the microscopic anatomy of living cells .
- D. Evolution is a process that results in change in the genetic material of a population over time. Hence B,C and D are incorrect.
Q4. Read the paragraph carefully and gives the best answer of the given questions:College is the practising ground for the student. It is not sufficient that he gives himself up to studies. He must develop the noble qualities of showing respect to elders and teachers create a team spirit and participate in the various extracurricular activities and maintain college discipline to raise the prestige of his college.What part does college life play in the training of the students?
- A. College life groom and prepares a student for life✓
- B. Prepare the student in academics
- C. Develops noble dualities in academics
- D. Help the students to take part in extracurricular activities
Explanation: College is described as a place where the student must not only advance in his studies but improve and develop his skills by participation in various activities, learn to show respect to his seniors and teachers and do things that raise the prestige of his college. These will provide the perfect stage for grooming the student for his life and responsibilities ahead, and he must maintain a balance, only studies or studies or activities alone are not sufficient.
Why the other options are wrong
- B. The word co curricular activities broadens the horizon and states that college life is not just a source of better academics . So the option does not suit well.
- C. The word co curricular activities broadens the horizon and states that college life is not just a source of better academics . So the option does not suit well.
- D. It doesn't suit the subject of the sentence because college life enhances the academic qualities of a person along with the co curricular activities.
Q5. Choose the suitable preposition:Rich lady found grate pleasure _ showing off her riches.
- A. In✓
- B. For
- C. At
- D. By
Explanation: A preposition is a word or group of words used before a noun, pronoun, or noun phrase to show direction, time, place, location, spatial relationships, or to introduce an object. Some examples of prepositions are words like "in," "at," "on," "of," and "to." Option A is correct. The correct sentence is Rich woman found great pleasure in showing off her riches.
Why the other options are wrong
- B. Rich woman found great pleasure for showing off her riches is grammatically incorrect .The correct sentence is Rich woman found great pleasure in showing off her riches.
- C. Rich woman found great pleasure at showing off her riches is grammatically incorrect .
- D. Rich woman found great pleasure by showing off her riches is grammatically incorrect .The correct sentence is Rich woman found great pleasure in showing off her riches.The correct preposition here will be in because according to the statement the term pleasure is used as a noun and the term showing off is a verb, so the phrase “the lady finds pleasure in showing off her wealth is the most appropriate”
Q6. Bane (Synonym)
- A. Banter
- B. Mystery
- C. Exile
- D. Affliction✓
Explanation: The term bane is commonly used to describe something that causes death, ruin, or great distress. The correct synonym in this context is affliction, which conveys a similar meaning of causing harm or suffering. Conversely, the other options do not align with this concept: Banter refers to light-hearted conversation, mystery is about something unknown or puzzling, and exile pertains to being forced out of one's homeland, none of which imply the same sense of harm or destruction.
Why the other options are wrong
- A. Banter refers to a playful and friendly exchange of teasing remarks. It is not related to harm or suffering, making it an incorrect synonym for 'bane'.
- B. Mystery denotes something that is difficult or impossible to understand or explain. It lacks the notion of harm or distress associated with 'bane'.
- C. Exile is the state of being barred from one's native country, usually for political or punitive reasons. It does not necessarily imply harm or ruin, thus is not a synonym for 'bane'.
Q7. _said that protoplasm is the physical basis of life.
- A. Robert Brown
- B. Robert Hooke
- C. Jan Evangelista Purkinje
- D. Thomas Huxley✓
Explanation: Thomas Huxley is credited with the statement that protoplasm is the 'physical basis of life.' He highlighted the importance of protoplasm in the cellular structure and its role in life's processes. Robert Brown discovered the cell nucleus, Robert Hooke is known for inventing the term 'cell', and Jan Evangelista Purkinje identified Purkinje fibers in the heart. None of these scientists are associated with the concept of protoplasm as Huxley is.
Why the other options are wrong
- A. Robert Brown is known for his discovery of the cell nucleus, not protoplasm.
- B. Robert Hooke coined the term 'cell' but did not describe protoplasm as the basis of life.
- C. Jan Evangelista Purkinje is known for his work on the Purkinje fibers in the heart, not protoplasm.
Q8. Infoldings in the mitochondrial inner membrane is called :
- A. Cristae✓
- B. Thylakoid
- C. Glyoxysome
- D. Chromatin network
Explanation: The correct answer is Cristae. Cristae are the infoldings in the mitochondrial inner membrane that increase surface area for ATP production and the electron transport chain. The other options are incorrect because they are not related to the structure and function of the mitochondria.
Why the other options are wrong
- B. Thylakoid is the membrane disk of chloroplast, not found in mitochondria.
- C. Glyoxysomes are specialized plant peroxisomes for lipid to sugar conversion, not related to mitochondrial inner membrane.
- D. Chromatin network is a condensed form of chromosome, not part of the mitochondria structure.
Q9. The bond present between carbohydrate units :
- A. Peptide bond
- B. Covalent bond
- C. Glycosidic bond✓
- D. Electrostatic bond
Explanation: The correct answer is the glycosidic bond, which is a specific type of covalent bond that links carbohydrate molecules. It occurs when the hemiacetal or hemiketal group of one saccharide forms a bond with the hydroxyl group of another, creating a glycoside. Peptide bonds, in contrast, connect amino acids in proteins. Electrostatic bonds are formed by electrical charge interactions and do not connect carbohydrate units.
Why the other options are wrong
- A. Peptide bonds connect amino acids in proteins, not carbohydrates.
- B. While glycosidic bonds are a type of covalent bond, this option is too broad. Specifically, carbohydrates are linked by glycosidic bonds.
- D. Electrostatic bonds involve attraction between charged particles and are not involved in joining carbohydrate units.
Q10. _discovered microscopic creatures under the microscope in the blood cells of malarial patients.
- A. Ronald Ross
- B. Leveran✓
- C. Grassy
- D. A.F.A King
Explanation: Our understanding of the malaria parasites began in 1880 with the discovery of the parasites in the blood of malaria patients by Alphonse Laveran. Ronald Ross , A.F.A king and grassy were the contributors to the causes and treatment of malaria.
Why the other options are wrong
- A. a) Ronald Ross: Sir Ronald Ross was a British medical doctor who is known for his discovery that mosquitoes transmit malaria parasites. He was awarded the Nobel Prize in Physiology or Medicine in 1902 for his work on the transmission of malaria.
- C. c) Grassy: "Grassy" does not seem to be related to the discovery of microscopic creatures in the blood cells of malarial patients. It might be a typo or a misinterpretation of another name.
- D. d) A.F.A King: This name does not seem to be associated with the discovery of microscopic creatures in the blood cells of malarial patients.
Q11. The nonliving part of protoplasm is :
- A. Golgi bodies
- B. Inclusion✓
- C. Organelles
- D. E. R
Explanation: Cells consist of various cell organelles like chloroplast, nucleus, endoplasmic reticulum, mitochondria etc. which form the living component of the cell which also include the protoplasm of a cell. ∙ The various non-living inclusions are metabolic by-products which are either organic or inorganic in nature. ∙ As they are not included in the protoplasm such non-living components are also called as non-protoplasmic contents/ ergastic substances/ Hyaloplasm. Golgi bodies endoplasmic reticulum and all organelles of the cell are considered living. Hence options A, C and D are incorrect.
Why the other options are wrong
- A. a) Golgi bodies: Golgi bodies, also known as Golgi apparatus, are organelles found in eukaryotic cells. They are involved in modifying, sorting, and packaging proteins and lipids for transport to various parts of the cell or for secretion outside the cell. Golgi bodies are considered organelles and are a living part of the cell.
- C. c) Organelles: Organelles are specialized structures within a cell that perform specific functions. Examples of organelles include the nucleus, mitochondria, chloroplasts (in plant cells), endoplasmic reticulum (ER), Golgi apparatus, and more. While organelles are part of the protoplasm, they are not the nonliving part.
- D. d) E. R (Endoplasmic Reticulum): The endoplasmic reticulum (ER) is a network of membranous tubules and sacs that are involved in protein synthesis, lipid metabolism, and other cellular processes. The ER is considered an organelle and is part of the living protoplasm.
Q12. The movement of cytoplasm is called
- A. Exocytosis
- B. Endocytosis
- C. Pinocytosis
- D. Cyclosis✓
Explanation: Cyclosis, or cytoplasmic streaming, is the correct term for the movement of cytoplasm within cells. This process is crucial for the distribution of materials and organelles within the cell. The other options—exocytosis, endocytosis, and pinocytosis—are processes related to the transport of substances into or out of the cell, rather than movement within the cytoplasm itself.
Why the other options are wrong
- A. Exocytosis is the process by which cells expel materials to the outside environment. It is not related to the movement of cytoplasm within the cell.
- B. Endocytosis is the process of taking materials into the cell from the outside. It does not describe the internal movement of cytoplasm.
- C. Pinocytosis is a form of endocytosis where the cell engulfs liquid substances. It is unrelated to the internal movement of cytoplasm.
Q13. Some bacteria live on dead organic matter they are called :
- A. Parasites
- B. Phages
- C. Saprophytes✓
- D. Symbionts
Explanation: The correct answer is Saprophytes. These organisms feed on dead and decaying organic matter, recycling nutrients back into the ecosystem. Parasites, on the other hand, feed on living hosts, often harming them in the process. Phages are viruses that infect bacteria and do not feed on dead organic matter. Symbionts engage in mutually beneficial relationships with living organisms, rather than obtaining nutrients from dead matter.
Why the other options are wrong
- A. Parasites rely on living hosts for their nutrients and can cause harm to their hosts.
- B. Phages are viruses that infect and replicate within bacteria, not organisms that feed on dead organic matter.
- D. Symbionts live in close association with another organism, often benefitting both parties, rather than feeding on dead matter.
Q14. Blue green pigment found only in blue green algae is:
- A. Chlorophyll
- B. Xanthophyll
- C. Carotene
- D. Phycobilin✓
Explanation: Blue-green algae or cyanobacteria also contain chlorophyll a, yellowish carotenoids, and blue-pigment phycobilins. Only the appearance of these pigments causes the blue-green colour of the algae. Chlorophyll is a true green pigment. Xanthophylls are yellow pigments. Carotene are yellow and orange pigments. Hence A, B and C are incorrect.
Why the other options are wrong
- A. a) Chlorophyll: Chlorophyll is a green pigment found in plants and cyanobacteria (blue-green algae). It plays a key role in photosynthesis by capturing light energy and converting it into chemical energy.
- B. b) Xanthophyll: Xanthophylls are yellow pigments found in the chloroplasts of plant cells. They assist in capturing light energy and also help protect the plant from excess light.
- C. c) Carotene: Carotenes are orange pigments found in various plants and some photosynthetic bacteria. They are important in photosynthesis and serve as antioxidants.
Q15. Sexual reproduction in bacteria is taken by:
- A. Binary fission
- B. Conidia
- C. Conjugation✓
- D. Zoospore
Explanation: Conjugation is the correct answer because it involves the transfer of genetic material between bacterial cells through direct contact, usually mediated by a structure known as a pilus. This process allows for genetic variation, which is a key feature of sexual reproduction, although bacteria do not reproduce sexually in the traditional sense. In contrast, binary fission is an asexual process of cell division, conidia are asexual spores of fungi, and zoospores are motile asexual spores found in some other organisms. None of these involve the exchange of genetic material in bacteria.
Why the other options are wrong
- A. Binary fission is a method of asexual reproduction where a single bacterium divides into two identical cells without exchanging genetic material.
- B. Conidia are asexual spores found in fungi, not involved in bacterial reproduction or genetic exchange.
- D. Zoospores are motile asexual spores found in some fungi, algae, and protists, not involved in bacterial genetic exchange.
Q16. Cyanobacteria is a typical example of:
- A. Chlorophyceae
- B. Cyanophyceae✓
- C. Green algae
- D. Fungi
Explanation: Cyanobacteria, also known as Cyanophyta, are a phylum of gram-negative bacteria that obtain energy via photosynthesis. They are classified under Cyanophyceae, a group of prokaryotic organisms capable of photosynthesis. Unlike Chlorophyceae and green algae, which are eukaryotic, cyanobacteria lack a true nucleus. Fungi do not perform photosynthesis and are unrelated to cyanobacteria.
Why the other options are wrong
- A. Chlorophyceae are a class of green algae, which are eukaryotic organisms, unlike cyanobacteria which are prokaryotic.
- C. Green algae are eukaryotic photosynthetic organisms with chlorophyll, different from cyanobacteria which are prokaryotic.
- D. Fungi are non-photosynthetic organisms that reproduce via spores and are not classified as cyanobacteria.
Q17. Saliva in mouth helps in digestion of :
- A. Bread✓
- B. Meat
- C. Fat
- D. Table Salt
Explanation: Saliva contains special enzymes that help digest the starches in your food. An enzyme called amylase breaks down starches (complex carbohydrates) into sugars, which your body can more easily absorb. Saliva amylase in mouth only digests carbs upto 3 to 5%. It cannot digest protein (meat), lipid (fat), and salts.
Why the other options are wrong
- B. b) Meat: Saliva primarily contains enzymes that begin the digestion of carbohydrates. The digestion of meat primarily occurs in the stomach, where gastric juices break down proteins with the help of the enzyme pepsin.
- C. c) Fat: Saliva does not play a significant role in the digestion of fats. Fat digestion primarily takes place in the small intestine, where bile and pancreatic enzymes break down fats into fatty acids and glycerol.
- D. d) Table Salt: Saliva does not play a role in the digestion of table salt (sodium chloride). Salt is not a complex molecule that requires enzymatic digestion. It dissolves in saliva and is then swallowed.
Q18. Major metabolic factory, detoxification centre and storage organ of body is :
- A. Stomach
- B. Brain
- C. Kidney
- D. Liver✓
Explanation: The correct answer is the liver. It is a vital organ that performs a wide range of functions, including detoxifying chemicals, metabolizing drugs, and storing nutrients like glycogen. It also produces bile, which is essential for digestion. The liver is often referred to as the body's metabolic hub due to its numerous roles in maintaining homeostasis. In contrast, the stomach primarily aids in digestion, the brain controls bodily functions and cognition, and the kidneys focus on filtering blood to produce urine.
Why the other options are wrong
- A. The stomach primarily stores food temporarily and aids in digestion by secreting gastric acid, but it is not involved in detoxification or major metabolic activities.
- B. The brain is the central organ for processing information and controlling bodily functions, but it is not involved in detoxification or storage of nutrients.
- C. The kidneys filter blood to form urine and help in waste removal and regulation of electrolytes, but they are not a major metabolic or storage organ.
Q19. The actual visual receptor of the eye are :
- A. Iris and pupil
- B. Iris and lens
- C. Rods and cones✓
- D. Cornea and retina
Explanation: Cones are active at higher light levels (photopic vision), are capable of colour vision and are responsible for high spatial acuity. Iris is the coloured part, pupil is the central black spot from where light enters the eye. Lens is responsible for focusing light. Cornea is a membrane that protects structures inside eye while retina contains layers of photoreceptors (rods and cones).
Why the other options are wrong
- A. a) Iris and Pupil: The iris is the colored part of the eye that controls the size of the pupil, which is the opening in the center of the iris. However, these structures are not the actual visual receptors responsible for detecting light and forming images.
- B. b) Iris and Lens: The iris regulates the amount of light entering the eye by adjusting the size of the pupil, and the lens helps focus light onto the retina. While the lens is involved in focusing light, it is not the actual visual receptor.
- D. d) Cornea and Retina: The cornea is the clear front surface of the eye that helps focus light onto the retina. The retina, located at the back of the eye, contains the actual visual receptors (rods and cones) that detect light and transmit visual signals to the brain.
Q20. Haemoglobin is :
- A. Respiratory pigment✓
- B. Excretory pigment
- C. Digestive pigment
- D. Storage pigment
Explanation: Haemoglobin is a respiratory pigment found in red blood cells. Its main function is to carry oxygen from the lungs to the rest of the body and return carbon dioxide from the body to the lungs to be exhaled. It is not involved in excretion, digestion, or storage functions, which are associated with other types of pigments and processes in the body or in plants.
Why the other options are wrong
- B. Excretory pigments are not related to haemoglobin. They are typically involved in the removal of waste products from the body, primarily found in organs like the liver and kidneys.
- C. Digestive pigments, such as bile pigments, are involved in the digestion process, not in the respiratory function. Haemoglobin plays no role in digestion.
- D. Storage pigments are found in plants and are responsible for storing energy or nutrients. Haemoglobin does not store substances; it transports oxygen.
Q21. The excretory organ in insects are :
- A. Flame cells
- B. Malpighian tubules✓
- C. Contractile vacuoles
- D. Kidneys
Explanation: In insects, the primary excretory organs are the Malpighian tubules. These tubules play a crucial role in osmoregulation and excretion, helping insects to maintain internal homeostasis by removing metabolic wastes and regulating water balance. The other options are incorrect because flame cells are found in flatworms, contractile vacuoles are found in protozoans, and kidneys are found in vertebrates, none of which apply to insects.
Why the other options are wrong
- A. Flame cells are specialized excretory cells found in flatworms (Platyhelminthes), not in insects.
- C. Contractile vacuoles are organelles in protozoans used for expelling excess water, not found in insects.
- D. Kidneys are complex excretory organs found in vertebrates, not in insects.
Q22. The kidneys does not perform the function of :
- A. Regulation of blood pressure
- B. Secretion of bile✓
- C. Regulation of pH
- D. Homeostasis
Explanation: The correct answer is Secretion of bile. The kidneys do not secrete bile; this is a function of the liver. The kidneys are responsible for regulating blood pressure, maintaining pH balance, and supporting overall homeostasis through their filtration and excretion processes. Regulation of blood pressure and pH, as well as maintaining homeostasis, are all key functions of the kidneys.
Why the other options are wrong
- A. The kidneys contribute to blood pressure regulation by adjusting the volume of fluids and sodium in the body, which impacts blood volume and pressure.
- C. The kidneys help maintain the body's pH balance by excreting excess acids or bases, playing a key role in acid-base homeostasis.
- D. The kidneys are involved in maintaining homeostasis by regulating blood pressure, pH levels, and electrolyte balance.
Q23. Which of following statement is true about Euglena:
- A. Autotrophic animal✓
- B. Unicellular Algae
- C. Prokaryotic autotroph
- D. A-cellular animal
Explanation: Euglena is a class of single cell flog eukaryotic. The species Euglena gracilis has been utilised widely in the research centre as a model creature. Most types of Euglena have photosynthesizing chloroplasts inside the body of the cell, which empower them to nourish via autotrophy, similar to plants.
Why the other options are wrong
- B. Euglena is not an algae so option B is incorrect.
- C. Neither euglena is prokaryotic, rather it is eukaryotic. Also euglena is not acellular.
- D. Neither euglena is prokaryotic, rather it is eukaryotic. Also euglena is not acellular.
Q24. During inspiration, the path of air is :
- A. Nostril-pharynx-lung-trachea-bronchi
- B. Nostril-bronchi-pharynx-trachea-lungs
- C. Nostril-pharynx-trachea-bronchi-lungs✓
- D. Nostril-pharynx-lungs-trachea-bronchi
Explanation: When you inhale through your nose or mouth, air travels down your pharynx (back of your throat), passes through your larynx (voice box) and into your trachea (windpipe). Your trachea is divided into two air passages called bronchial tubes. One bronchial tube leads to your left lung, the other to your right lung.
Why the other options are wrong
- A. a) Nostril-pharynx-trachea-bronchi-lungs: This option is incorrect. The air doesn't pass through the lungs before reaching the trachea and bronchi.
- B. b) Nostril-bronchi-pharynx-trachea-lungs: This option is incorrect. The correct order of air passage during inspiration is nostril-pharynx-trachea-bronchi-lungs.
- D. d) Nostril-pharynx-lungs-trachea-bronchi: This option is incorrect. The correct order is nostril-pharynx-trachea-bronchi-lungs.
Q25. The manufactured food is transported to various regions by a process called:
- A. Translocation✓
- B. Transpiration
- C. Osmosis
- D. Diffusion
Explanation: The correct answer is 'Translocation'. This is the process responsible for moving the products of photosynthesis, such as sugars, from the leaves where they are made to other parts of the plant for growth, storage, or energy. 'Transpiration' is unrelated as it deals with the loss of water. 'Osmosis' and 'Diffusion' are general processes that involve the movement of water and solutes, not specifically the transport of food substances in plants.
Why the other options are wrong
- B. Transpiration refers to the process of water vapor loss from the aerial parts of plants, primarily leaves, not the transport of food.
- C. Osmosis involves the movement of water molecules through a semipermeable membrane from a region of lower solute concentration to a region of higher solute concentration, not the transport of manufactured food.
- D. Diffusion is the movement of particles from a region of higher concentration to a region of lower concentration and does not specifically refer to the transport of food within plants.
Q26. The protoplasm is shrinked in the solution of :
- A. Normal saline solution
- B. Isotonic solution
- C. Hypotonic solution
- D. Hypertonic solution✓
Explanation: When a cell is placed in a hypertonic solution, the environment outside the cell has a higher solute concentration than inside the cell. This causes water to move out of the cell through osmosis to balance the solute concentrations. As a result, the cell loses water, leading to shrinkage of the protoplasm. In contrast, isotonic solutions do not change the cell's size, hypotonic solutions cause swelling, and normal saline is isotonic, hence does not lead to shrinkage.
Why the other options are wrong
- A. Normal saline solution is isotonic to the cell's cytoplasm, meaning it has the same osmotic pressure. Therefore, it does not cause the protoplasm to shrink, as there is no net movement of water.
- B. An isotonic solution has the same concentration of solutes as the cell's cytoplasm. It maintains the normal shape and size of the cell, with no net water movement, so the protoplasm does not shrink.
- C. A hypotonic solution has a lower concentration of solutes compared to the cell's cytoplasm. Water enters the cell, causing it to swell, not shrink, as the protoplasm takes in excess water.
Q27. The natural clock in the human body :
- A. Pineal body✓
- B. Medulla
- C. Pons
- D. Cerebellum
Explanation: Circadian rhythms are physical, mental, and behavioural changes that follow a 24-hour cycle. These natural processes respond primarily to light and dark and affect most living things, including animals, plants, and microbes. Chronobiology is the study of circadian rhythms.
Why the other options are wrong
- B. b) Medulla: The medulla oblongata is a part of the brainstem that controls involuntary functions such as breathing, heart rate, and blood pressure. While it's involved in regulating various bodily processes, it is not the natural clock.
- C. c) Pons: The pons is another part of the brainstem that plays a role in regulating certain involuntary functions. It is not primarily associated with the body's natural clock.
- D. d) Cerebellum: The cerebellum is responsible for coordinating voluntary muscle movements and maintaining balance and posture. While it has important functions, it is not the natural clock.
Q28. The forebrain is divisible into two components :
- A. Cerebrum and cerebral hemispheres
- B. Medulla and pons
- C. Telencephalon and diencephalon✓
- D. Telencephalon and medulla
Explanation: Weighing at just 2% of the total body weight, the human brain is probably the most complex structure. It is the centre of control of all the body functions and senses. The average weight of the human brain is around 1.5 kg and it contains about 86 billion nerve cells (neurons) that control every action you take. Medulla and pons are part of the hindBrain.
Why the other options are wrong
- A. a) Cerebrum and cerebral hemispheres: The cerebrum is the largest part of the brain and is responsible for higher cognitive functions such as thinking, reasoning, memory, and sensory perception. It is divided into two cerebral hemispheres (left and right) that are connected by a bundle of nerve fibers called the corpus callosum.
- B. b) Medulla and pons: The medulla and pons are part of the brainstem, which controls vital functions like breathing, heart rate, and blood pressure. While important, these are not components of the forebrain.
- D. d) Telencephalon and medulla: The medulla is part of the brainstem, as mentioned earlier. The correct division of the forebrain is telencephalon and diencephalon.
Q29. Sugar level in blood is maintained by :
- A. Liver
- B. Kidney
- C. Adrenal gland
- D. Islets of Langerhans✓
Explanation: The alpha cells of the islets of Langerhans produce an opposing hormone, glucagon, which releases glucose from the liver and fatty acids from fat tissue. Liver performs detoxification, the kidney makes urine, while adrenal glands secrete hormones that control mineral and glucose levels and combat emergency situations. Hence options A, B and C are incorrect.
Why the other options are wrong
- A. a) Liver: The liver plays a crucial role in regulating blood sugar levels. It stores excess glucose as glycogen and releases glucose into the bloodstream when needed to maintain stable blood sugar levels.
- B. b) Kidney: While the kidneys play a role in maintaining electrolyte balance and fluid levels in the body, they are not the primary organs responsible for regulating blood sugar levels.
- C. c) Adrenal gland: The adrenal glands are involved in producing hormones such as adrenaline and cortisol, which play a role in the body's response to stress. However, they are not the main organs responsible for regulating blood sugar levels.
Q30. In meiosis I , crossing over takes place in :
- A. Pachytene✓
- B. Diplotene
- C. Zygotene
- D. Diakinesis
Explanation: Crossing over occurs during the pachytene stage of prophase I in meiosis. It is a critical process where homologous chromosomes exchange genetic segments, resulting in new combinations of alleles. This enhances genetic diversity in gametes. The other stages have distinct roles: in zygotene, chromosomes pair up but do not yet exchange material; diplotene is characterized by the visible chiasmata post-crossing over; and diakinesis is marked by complete chromosome condensation and preparation for metaphase, with crossing over already finished.
Why the other options are wrong
- B. In the diplotene stage, which follows pachytene, homologous chromosomes begin to separate, but chiasmata (the physical manifestations of crossing over) become visible. Crossing over itself has already occurred in the pachytene stage.
- C. During zygotene, homologous chromosomes start pairing in a process called synapsis, but crossing over has not yet taken place. It's a preparatory stage for the genetic exchange in pachytene.
- D. Diakinesis is the final substage of prophase I where chromosomes are fully condensed, and preparations for metaphase begin. Crossing over is complete by this stage.
Q31. Vertebral column is the part of _ skeleton :
- A. Axial✓
- B. Appendicular
- C. Exoskeleton
- D. Hydrostatic
Explanation: The correct answer is the axial skeleton, which is the central part of the human skeleton. It includes the vertebral column, which supports the body and protects the spinal cord. The axial skeleton also consists of the skull and rib cage. In contrast, the appendicular skeleton involves limbs and girdles, the exoskeleton pertains to external skeletons in some invertebrates, and the hydrostatic skeleton is found in certain invertebrates, relying on fluid pressure for support.
Why the other options are wrong
- B. The appendicular skeleton consists of the limbs and girdles (shoulder and pelvic) and is involved in movement. It is not part of the central axis of the body.
- C. An exoskeleton is an external skeleton that supports and protects an animal's body, found in arthropods like insects and crustaceans, not in humans.
- D. A hydrostatic skeleton is a structure found in soft-bodied animals like worms and mollusks, which rely on fluid pressure for support. It is not present in vertebrates.
Q32. The science of ageing is called :
- A. Ethnology
- B. Gerontology✓
- C. Embryology
- D. Genetics
Explanation: Gerontology is the study of ageing and older adults. The science of gerontology has evolved as longevity has improved. Researchers in this field are diverse and are trained in areas such as physiology, social science, psychology, public health, and policy.
Why the other options are wrong
- A. Ethnology is the study of different peoples and differences and relationships between them
- C. Embryology is the study of a developing embryo.
- D. Genetics is the study of genes
Q33. The possible result of crossing over between heterozygous tall (Tt)and homozygous dwarf (tt) is :
- A. 50 %tall and 50%dwarf✓
- B. 100% tall
- C. 100%dwarf
- D. 75%tall and 25% dwarf
Explanation: a) 50% tall and 50% dwarf: This is the correct answer. When crossing over occurs between a heterozygous tall (Tt) and a homozygous dwarf (tt), the possible outcomes of the offspring are half tall (Tt) and half dwarf (tt).
Why the other options are wrong
- B. b) 100% tall: If there is no crossing over between the heterozygous tall (Tt) and homozygous dwarf (tt), the result would be all tall (Tt) offspring.
- C. c) 100% dwarf: If there is no crossing over between the heterozygous tall (Tt) and homozygous dwarf (tt), the result would be all dwarf (tt) offspring.
- D. d) 75% tall and 25% dwarf: This does not accurately represent the possible outcomes of crossing over between a heterozygous tall (Tt) and a homozygous dwarf (tt). The correct ratio is 50% tall and 50% dwarf.
Q34. _muscle pulls the limb outward away from the body :
- A. Adductor
- B. Protractor
- C. Abductor✓
- D. Extensor
Explanation: The correct answer is Abductor. Abductor muscles are responsible for moving limbs away from the midline of the body, such as when you raise your arms or legs to the side. In contrast, Adductor muscles do the opposite by pulling limbs toward the body’s midline. Protractor is not a relevant term in this context, as it is not used to describe muscle functions. Extensor muscles are involved in straightening limbs or increasing the angle between body parts, not moving them outward.
Why the other options are wrong
- A. Adductor muscles are responsible for moving a limb toward the midline of the body, not away from it.
- B. Protractor is not a term used to describe muscles that move limbs; it is more commonly associated with drawing instruments.
- D. Extensor muscles function to straighten a limb or increase the angle between body parts, not to move them outward from the body.
Q35. _hormone stimulates mammary gland to secrete milk and process of labour :
- A. Oxytocin✓
- B. F.S.H
- C. L.H
- D. T.S.H
Explanation: Oxytocin is the hormone that facilitates both the process of labor by causing uterine contractions and the secretion of milk by stimulating the mammary glands. During childbirth, it induces contractions of the uterine muscles, which are essential for delivery. In terms of lactation, it enables the milk ejection reflex, allowing milk to be released from the mammary glands. The other hormones mentioned, such as F.S.H, L.H, and T.S.H, have different roles in the body related to reproductive health and thyroid function, and do not directly influence labor or lactation.
Why the other options are wrong
- B. F.S.H, or Follicle-Stimulating Hormone, is primarily involved in regulating the menstrual cycle and stimulating the growth of eggs in the ovaries, not directly linked to milk secretion or labor.
- C. L.H, or Luteinizing Hormone, triggers ovulation and stimulates testosterone production in males, not involved in milk secretion or labor processes.
- D. T.S.H, or Thyroid-Stimulating Hormone, is responsible for stimulating the thyroid gland to release hormones like thyroxine, and does not play a role in labor or lactation.
Q36. _germinal layer gives rise to all the body muscles.
- A. Ectoderm
- B. Endoderm
- C. Mesoderm✓
- D. Chorion
Explanation: The three germ layers are the endoderm, the ectoderm, and the mesoderm. Cells in each germ layer differentiate into tissues and embryonic organs. The ectoderm gives rise to the nervous system and the epidermis, among other tissues. The mesoderm gives rise to the muscle cells and connective tissue in the body.
Why the other options are wrong
- A. a) Ectoderm: The ectoderm is one of the three primary germinal layers in the early embryo. It gives rise to structures such as the nervous system, epidermis (outer layer of skin), and hair.
- B. b) Endoderm: The endoderm is another of the three primary germinal layers. It gives rise to the epithelial lining of the digestive tract and various internal organs like the liver, pancreas, and lungs.
- D. d) Chorion: The chorion is an extraembryonic membrane that surrounds and protects the developing embryo in some animals. It plays a role in gas exchange and nutrient transport.
Q37. The tendency of gene in chromosome to remain together is called :
- A. Crossing over
- B. Synapsis
- C. Terminalization
- D. Linkage✓
Explanation: Genetic linkage is the tendency of DNA sequences that are close together on a chromosome to be inherited together during the meiosis phase of sexual reproduction. Crossing is the exchange of genetic material . Synapsis is the fusion of chromosome pairs at the start of meiosis. Terminalization is the movement of bonds towards the ends of paired chromosomes
Why the other options are wrong
- A. a) Crossing over: Crossing over is the exchange of genetic material between homologous chromosomes during meiosis. It can lead to the recombination of alleles and the creation of new combinations of genes.
- B. b) Synapsis: Synapsis is the pairing of homologous chromosomes during meiosis. It allows for the alignment of corresponding genes and facilitates crossing over.
- C. c) Terminalization: Terminalization is not a recognized term in genetics. It doesn't relate to any specific genetic process.
Q38. The bond between adenine and thymine is :
- A. Single
- B. Double✓
- C. Triple
- D. Covalent
Explanation: The bases of one strand bond to the bases of the second strand with hydrogen bonds. Adenine always bonds with thymine, and cytosine always bonds with guanine. The bonding causes the two strands to spiral around each other in a shape called a double helix. Ribonucleic acid (RNA) is a second nucleic acid found in cells.
Why the other options are wrong
- A. a) Single: A single bond involves the sharing of one pair of electrons between two atoms. In the context of DNA, adenine (A) and thymine (T) are complementary bases that form a single hydrogen bond with each other.
- C. c) Triple: A triple bond involves the sharing of three pairs of electrons between two atoms. While triple bonds are found in certain molecules, they are not present in the adenine-thymine pairing in DNA.
- D. d) Covalent: The bond between adenine and thymine is a hydrogen bond, not a covalent bond. Covalent bonds involve the sharing of electrons between atoms to form molecules.
Q39. _mono consists of deeper layer of water :
- A. Lentic
- B. Littoral
- C. Limnetic
- D. Profundal✓
Explanation: The profundal zone is correctly identified as the deeper layer of water in an inland body of water like a lake or pond. It is located below the limnetic zone and is beyond the reach of sunlight, making it colder and darker. This zone is typically below the thermocline, where the temperature drops rapidly. Other zones like the lentic, littoral, and limnetic zones are either not specific to deeper layers or refer to areas closer to the shore or surface of the water.
Why the other options are wrong
- A. The lentic zone refers to standing water bodies like lakes and ponds, which can include various zones like littoral, limnetic, and profundal. However, it is not specifically the deeper layer.
- B. The littoral zone is the area near the shore where sunlight penetrates all the way to the sediment and allows aquatic plants to grow. It is not the deeper layer of water.
- C. The limnetic zone is the open and well-lit area of a lake, away from the shore. It is not the deepest layer.
Q40. Lichen is associated between:
- A. Fungus and Algae✓
- B. Algae and Bacteria
- C. Bacteria and Fungus
- D. Bacteria and Virus
Explanation: Lichens are commonly recognized as a symbiotic association of a fungus and a chlorophyll containing partner, either green algae or cyanobacteria, or both. The fungus provides a suitable habitat for the partner, which provides photosynthetically fixed carbon as energy source for the system. Bacteria can never be a part of lichen. Hence all options except A are incorre
Why the other options are wrong
- B. b) Algae and Bacteria: While both algae and bacteria are involved in various ecological interactions, lichens specifically involve a fungal partner along with algae or cyanobacteria.
- C. c) Bacteria and Fungus: This option is not correct. Lichens involve a fungus and algae or cyanobacteria, not bacteria.
- D. d) Bacteria and Virus: Lichens do not involve viruses. They are a mutualistic relationship between a fungus and algae or cyanobacteria.
Q41. Extra circular chromosome present in bacteria is called :
- A. Centrosome
- B. Centromere
- C. Plasmid✓
- D. DNA
Explanation: Plasmids carry only a few genes and exist independently of chromosomes, the primary structures that contain DNA in cells. Able to self-replicate, plasmids can be picked up from the environment and transferred between bacteria. Plasmids are used by their host organism to cope with stress-related conditions.
Why the other options are wrong
- A. Centrosome is an animal cell organelle (also found in lower plants) that is involved in spindle formation during cell division.
- B. Centromere is the point where two sister chromatids attach with each other.
- D. DNA is not circular, it is a double helix.
Q42. The person with down's syndrome has :
- A. One extra chromosome✓
- B. One less chromosome
- C. Two extra chromosome
- D. Two less chromosome
Explanation: Down syndrome results when abnormal cell division involving chromosome 21 occurs. These cell division abnormalities result in an extra partial or full chromosome 21. This extra genetic material is responsible for the characteristic features and developmental problems of Down syndrome.
Why the other options are wrong
- B. b) One less chromosome: This is not correct. Down's syndrome is characterized by an extra chromosome, not a missing one.
- C. c) Two extra chromosomes: This is not correct. Down's syndrome is caused by the presence of an extra copy of chromosome 21, not two extra chromosomes.
- D. d) Two less chromosomes: This is not correct. Down's syndrome involves an extra chromosome, not a deficiency of chromosomes.
Q43. The menstrual stage lasts for:
- A. 1 to 5 days✓
- B. 14 to 16 days
- C. 25 to 28 days
- D. 8 to 18 days
Explanation: The first phase is the menstrual phase, which is from day 1 to 5. During this stage, the uterus sheds its inner lining through the vagina in the form of fluid. Women generally have cramps caused due to the contraction of the uterine wall during this phase.
Why the other options are wrong
- B. b) 14 to 16 days: This is not correct. The menstrual stage does not last for 14 to 16 days. This range of days is more commonly associated with the ovulation phase of the menstrual cycle, which occurs roughly in the middle of the cycle.
- C. c) 25 to 28 days: This is not correct. The range of 25 to 28 days is more commonly associated with the length of the entire menstrual cycle, which includes various phases such as the follicular phase, ovulation, and luteal phase, in addition to menstruation.
- D. d) 8 to 18 days: This is not correct. The range of 8 to 18 days is not typical for the duration of the menstrual stage. It's important to note that individual variations can occur, but the average duration of menstruation is around 5 days.
Q44. The eyespot in Euglena is sensitive for :
- A. Dark
- B. Light✓
- C. Red light
- D. Blue light
Explanation: In the green one-celled organism Euglena, the eyespot is located in the gullet, at the base of the flagellum (a whiplike locomotory structure). A cup-shaped mass of pigment rods shields a sensitive area of the flagellar base from light coming from the direction of the opposite end of the organism.
Why the other options are wrong
- A. a) Dark: This option is not correct. The eyespot in Euglena is sensitive to light and plays a role in phototaxis, which is the movement of the organism in response to light.
- C. c) Red light: This option is not correct. While the eyespot is sensitive to light in general, it is not specifically sensitive to red light.
- D. d) Blue light: This option is not correct. The eyespot in Euglena is generally more sensitive to light in the visible spectrum, and while it may respond to blue light, it is not specific to blue light.
Q45. The whole tail of the tadpole and its gills are lost during metamorphosis . The change is :
- A. Progressive
- B. Retroactive✓
- C. Organisational
- D. None of these
Explanation: Tadpoles hatch from the eggs and live in the pond. The tadpoles turn into Froglets. The body shrinks and legs form. The Froglets' tail shrinks, the lungs develop and the back legs grow and then we have a Frog. Retroactive changes are those that take effect from a date in the past
Why the other options are wrong
- A. a) Progressive: This option is not correct. "Progressive" refers to a continuous advancement or development, but in the context of tadpole metamorphosis, the change is not necessarily considered "progressive."
- C. c) Organisational: This option is not correct. "Organisational" typically refers to the arrangement or structure of components within an organization or system, and it is not the most relevant term to describe the specific change occurring during tadpole metamorphosis.
- D. d) None of these: The correct answer is b) Retroactive. The change in tadpole metamorphosis, involving the loss of the tail and gills, is best described as retroactive, indicating a reversal or undoing of specific features that were present in the earlier tadpole stage.
Q46. _no of ATP are produced during Aerobic respiration in prokaryotes :
- A. 32 ATP
- B. 34 ATP
- C. 36 ATP
- D. 38 ATP✓
Explanation: Without oxygen, organisms can split glucose into just two molecules of pyruvate. This releases only enough energy to make two ATP molecules. With oxygen, organisms can break down glucose all the way to carbon dioxide. This releases enough energy to produce up to 38 ATP molecules. 36 ATPs is produced by eukaryotes during Aerobic respiration.
Why the other options are wrong
- A. a) 32 ATP: This option is not correct. While 32 ATP molecules are produced during the complete oxidation of glucose in eukaryotic cells through aerobic respiration, the number of ATP molecules produced during aerobic respiration in prokaryotes is different.
- B. b) 34 ATP: This option is not correct either. While 34 ATP molecules are generated during oxidative phosphorylation in eukaryotic cells, it's important to note that the exact number of ATP produced in prokaryotic cells through aerobic respiration can vary based on specific conditions and factors.
- C. c) 36 ATP: This option is often cited as the estimated net yield of ATP during aerobic respiration in prokaryotes. It considers the total ATP produced through glycolysis, the citric acid cycle, and oxidative phosphorylation. However, the actual number can vary.
Q47. The dark band in muscle fibres is due to :
- A. Actin
- B. Myosin and Actin✓
- C. Tropomyosin
- D. I band
Explanation: The arrangement of the thick myosin filaments across the myofibrils and the cell causes them to refract light and produce a dark band known as the A Band. In between the A bands is a light area where there are no thick myofilaments, only thin actin filaments. These are called the I Bands.
Why the other options are wrong
- A. a) Actin: The dark band in muscle fibers is not primarily due to actin. Actin is a thin filament that is present in both the light (I) band and the dark (A) band.
- C. c) Tropomyosin: Tropomyosin is a protein that is associated with the actin filaments in muscle fibers. It plays a role in regulating muscle contraction by blocking the myosin-binding sites on actin. However, the dark band itself is not primarily due to tropomyosin.
- D. d) I band: The I band, or light band, is the region of a muscle fiber where only actin filaments are present. It appears lighter under a microscope. The dark band (A band) is primarily due to the overlapping arrangement of myosin and actin filaments.
Q48. Neurospora is a fungus which is used to understand the principle of :
- A. Reproduction
- B. Locomotion
- C. Inheritance✓
- D. None of these
Explanation: Neurospora is an ascomycete fungus and a classic model for genetic research. It was crucial in the early studies of genetics, especially in formulating the 'one gene-one enzyme' hypothesis. Neurospora's simple life cycle and clear genetic traits make it ideal for studying inheritance. Other options like Reproduction and Locomotion do not align with its primary use in scientific research, as there are more specialized organisms for those studies. 'None of these' is incorrect because 'Inheritance' is the correct principle associated with Neurospora.
Why the other options are wrong
- A. Reproduction: Although Neurospora undergoes reproduction as a fungus, it is not primarily known for elucidating reproductive principles. Other organisms serve better for such studies.
- B. Locomotion: Neurospora is a non-motile organism, making it unsuitable for locomotion studies.
- D. None of these: This option is incorrect as 'Inheritance' is the correct answer.
Q49. The total autosomes in human are :
- A. 44✓
- B. 46
- C. 22
- D. 23
Explanation: These chromosomes are present in equal pairs and they can be defined as the thread-like structure found inside the nucleus of every cell. Out of which 22 pairs are autosomes and remaining 1 pair is a sex chromosome. So there will be 44 autosomes
Why the other options are wrong
- B. b) 46: This is not the correct answer. While humans do have 22 pairs of autosomes, this option does not account for the sex chromosomes, which are not included in the total chromosome count.
- C. c) 22: This is not the correct answer. While humans do have 22 pairs of autosomes, this option does not account for the sex chromosomes, which are also included in the total chromosome count.
- D. d) 23: This is not the correct answer. While humans do have 23 pairs of chromosomes, this option only considers the total number of pairs, not the total number of individual chromosomes.
Q50. The result of nondisjunction are :
- A. Down's Syndrome
- B. Turner's Syndrome
- C. Klinefelter's Syndrome
- D. All of these✓
Explanation: Nondisjunction is a cell division error where chromosomes do not separate properly, leading to disorders like Down's Syndrome, Turner's Syndrome, and Klinefelter's Syndrome. Each of these conditions is caused by an abnormal number of sex chromosomes or autosomes due to nondisjunction. Therefore, the correct answer is 'All of these.' The individual syndromes listed (Down's, Turner's, and Klinefelter's) are specific examples of nondisjunction outcomes, but they are not the only possible results, hence selecting 'All of these' encompasses all scenarios.
Why the other options are wrong
- A. Down's Syndrome is caused by an extra copy of chromosome 21 due to nondisjunction during gamete formation. This results in characteristic developmental and physical challenges.
- B. Turner's Syndrome occurs in females when one X chromosome is missing or partially missing due to nondisjunction, leading to specific physical and developmental features.
- C. Klinefelter's Syndrome affects males who have an extra X chromosome (XXY) due to nondisjunction, resulting in symptoms like reduced testosterone levels and infertility.
Q51. The process during which solid is directly converted into gaseous state is called :
- A. Boiling
- B. Evaporation
- C. Sublimation✓
- D. Freezing
Explanation: The correct answer is Sublimation. Sublimation is a phase transition in which a substance goes directly from a solid to a gaseous state without passing through the liquid phase. For instance, dry ice (solid carbon dioxide) sublimates into carbon dioxide gas. Boiling and Evaporation involve the phase change from liquid to gas, not directly from solid to gas. Freezing is the transition from liquid to solid, which is unrelated to the process described in the question.
Why the other options are wrong
- A. Boiling involves heating a liquid until it becomes a gas, not directly from a solid to a gas.
- B. Evaporation is the process where a liquid turns into a gas at the surface, typically at room temperature, not directly from a solid.
- D. Freezing is the process of a liquid becoming a solid, the opposite of what is asked in the question.
Q52. The number of atoms of nitrogen represented in the formula NH4NO is :
- A. 1
- B. 2✓
- C. 3
- D. 4
Explanation: The compound NH4NO consists of ammonium (NH4) and a nitrate (NO) group. The ammonium part contributes one nitrogen atom, and the nitrate part contributes another nitrogen atom. Thus, the total number of nitrogen atoms in NH4NO is two. Options A, C, and D are incorrect as they do not account for the correct number of nitrogen atoms in the compound.
Why the other options are wrong
- A. Option A: This option suggests that there is only one atom of nitrogen in the formula NH4NO. However, this is incorrect because NH4NO actually contains two nitrogen atoms.
- C. Option C: This option incorrectly suggests that there are three nitrogen atoms in the formula NH4NO. The correct count is two nitrogen atoms.
- D. Option D: This option incorrectly suggests that there are four nitrogen atoms in the formula NH4NO. There are actually only two nitrogen atoms.
Q53. Which of the following techniques could be used to separate the colored dyes from black ink :
- A. Chromatography✓
- B. Filtration
- C. Fractional distillation
- D. Precipitation
Explanation: Chromatography is the correct method for separating colored dyes from black ink. It works by exploiting the different rates at which the components of a mixture move through a stationary phase. This allows the dyes to be separated based on their affinities to the stationary phase and their solubility in the solvent. Filtration is not suitable as it separates particles based on size, not solubility or chemical properties. Fractional distillation is used for mixtures of liquids based on boiling points, not for dyes. Precipitation involves solid formation from a solution, which is not applicable in separating dye components.
Why the other options are wrong
- B. Filtration is used to separate solids from liquids or gases using a filter medium that allows only the fluid to pass through. It is not effective for separating dissolved dyes.
- C. Fractional distillation separates components based on differences in boiling points. It is typically used for liquid mixtures, not for separating dyes in ink.
- D. Precipitation involves forming a solid from a solution when a reaction occurs, usually due to saturation. This method does not apply to separating dyes in ink.
Q54. The crystalline form of allotropes are called:
- A. Chemically identical✓
- B. Chemically distinct
- C. Varies between being the same and different
- D. Depends on the element
Explanation: Allotropes are different structural forms of the same element that exist in more than one crystalline form. They have the same chemical properties because they consist of the same type of atoms, but their physical properties differ due to the distinct arrangement of these atoms. For example, carbon exists as diamond and graphite, which are allotropes. Although they have vastly different physical properties, their chemical properties are the same because they are both forms of carbon. The other options are incorrect because they suggest variability or dependency that does not exist in the chemical properties of allotropes of the same element.
Why the other options are wrong
- B. This option is incorrect because although allotropes have different physical structures, they are composed of the same element and therefore share the same chemical properties.
- C. This option is incorrect as the chemical properties of allotropes do not vary; they are consistent since the allotropes are composed of the same element.
- D. This option is misleading. While different elements can have allotropes, the chemical properties of allotropes of a particular element are always the same, regardless of the element.
Q55. Alpha rays are :
- A. Single negatively charged particles
- B. Single positively charged particles
- C. Double negatively charged particles
- D. Double positively charged particles✓
Explanation: Alpha particles have a positive charge and are identical with helium nuclei and consist of two protons and two neutrons. They result from the radioactive decay of heavy elements such as radium, thorium, uranium, and plutonium.
Why the other options are wrong
- A. a) Single negatively charged particles: This option suggests that alpha rays are single particles with a negative charge. However, this is not accurate. Alpha particles are made up of two protons and two neutrons, and they have a positive charge.
- B. b) Single positively charged particles: This option is inaccurate. Alpha rays, also known as alpha particles, are composed of two protons and two neutrons. Due to the presence of two protons, they have a double positive charge.
- C. c) Double negatively charged particles: This option is not accurate. Alpha particles are positively charged, not negatively charged.
Q56. Which is the lightest among following:
- A. An atom of hydrogen
- B. An electron✓
- C. A neutron
- D. A proton
Explanation: The electron is the lightest stable subatomic particle, making it the correct answer. Electrons have a much smaller mass compared to protons and neutrons, which are subatomic particles found in the nucleus of an atom. A hydrogen atom, while the lightest atom, still contains a proton and an electron, making it heavier than a standalone electron. Neutrons and protons are significantly heavier than electrons, with protons being about 1,836 times and neutrons about 1,839 times as heavy.
Why the other options are wrong
- A. A hydrogen atom consists of one proton and one electron, making it heavier than a single electron.
- C. A neutron is significantly heavier than an electron, with a mass approximately 1,839 times that of an electron. Neutrons have no charge and reside in the atomic nucleus.
- D. A proton is also heavier than an electron, being about 1,836 times as massive. Protons carry a positive charge and are found in the nucleus of an atom.
Q57. In an atom no two electrons can have same set of quantum numbers”, this statement was given by:
- A. Uncertainty principle
- B. Pauli’s exclusion principle✓
- C. Hund’s rule
- D. Aufbau’s principle
Explanation: Pauli's Exclusion Principle states that no two electrons in the same atom can have identical values for all four of their quantum numbers. In other words, (1) no more than two electrons can occupy the same orbital and (2) two electrons in the same orbital must have opposite spins.
Why the other options are wrong
- A. Position and momentum of a particle cannot both be measured simultaneously with perfect accuracy. There is always a fundamental uncertainty associated with any measurement. This uncertainty is not associated with the measuring instrument. It is a consequence of the wave particle duality of matter and radiation. This was first proposed by Werner Heisenberg in 1927 and hence is known as the Heisenberg Uncertainty Principle. This fundamental uncertainty is completely negligible for measurements of position and momentum of macroscopic objects but is a predominant fact of life in the atomic domain.
- C. If degenerate orbitals are available and more than one electrons are to be placed in them, they should be placed in separate orbitals with the same spin rather than putting them in the same orbital with opposite spins. According to the rule, the two electrons in a 2p subshell of carbon will be distributed as follows. C 1s² 2s² 2px¹ 2py¹ 2pz⁰ The three orbitals of the 2p subshell are degenerate.
- D. The electrons should be filled in energy subshells in order of increasing energy values. The electrons are first placed in Is, 2s, 2p and so on.
Q58. The bond formed by the electrostatic attraction between negative end of one molecule and positive end of other is called:
- A. Covalent bond
- B. Hydrogen bond
- C. Ionic bond✓
- D. Coordinate covalent bond
Explanation: According to the Lewis theory, ionic bond is formed by the complete transfer of electrons or electrons from an atom with low ionisation energy to another atom with high electron affinity. In energy terms, the electropositive elements are at a higher energy state than the electronegative elements. The energy difference will be responsible for the transfer of electrons from a higher energy state to a lower energy state.
Why the other options are wrong
- A. According to Lewis and Kossel, a covalent bond is formed by the mutual sharing of electrons between two atoms. While sharing, each atom completes its valence shell and attains the nearest inert gas configuration. A covalent bond may be nonpolar or polar in character.
- B. Hydrogen bonding is a special type of dipole-dipole interaction that occurs between the lone pair of a highly electronegative atom (typically N, O, or F) and the hydrogen atom in a N–H, O–H, or F–H bond.The strength of hydrogen bond is generally twenty times less than that of a covalent bond..
- D. A coordinate covalent bond is formed between two atoms when the shared pair of electrons is donated by one of the bonded atoms. Let us consider the example of bond formation between NH3 and BF3 . NH, has three covalent bonds and there is a lone pair of electrons on the nitrogen atom. On the other hand, the boron atom in BF3 is deficient in electrons. Actually, the octet of B is not complete in BF3 . Therefore, nitrogen can donate the pair of electrons to the acceptor BF3 and this results in the formation of a coordinate covalent bond.
Q59. The bond angle in a molecule having Sp3 hybridization with no lone pair is:
- A. 120°
- B. 180°
- C. 109.5°✓
- D. 90°
Explanation: In sp3 hybridization, one s and three p orbitals combine to form four equivalent hybrid orbitals. These orbitals arrange themselves in a tetrahedral geometry to minimize electron repulsion, resulting in bond angles of approximately 109.5°. Option C correctly identifies this angle. Options A and B describe bond angles for other types of hybridization (sp2 and sp, respectively), while Option D suggests an angle typical of different molecular shapes not associated with sp3 hybridization.
Why the other options are wrong
- A. This is the bond angle typically associated with sp2 hybridization, which forms a trigonal planar shape, not sp3.
- B. This angle is characteristic of sp hybridization, resulting in a linear geometry, not applicable to sp3 hybridization.
- D. This angle is typical for square planar or octahedral geometries, not for sp3 hybridization.
Q60. Properties of system, which depend upon the amount of substance present in the system are called:
- A. Chemical properties
- B. Intensive properties
- C. Extensive properties✓
- D. Physical properties
Explanation: An extensive property of a system depends on the system size or the amount of matter in the system. If the value of the property of a system is equal to the sum of the values for the parts of the system then such a property is called extensive property. Volume, energy, and mass are examples of extensive properties
Why the other options are wrong
- A. The chemical properties of an element are determined by the number of electrons in its atom, which in turn is determined by the number of protons.
- B. An intensive property is one that does not depend on the mass of the substance or system. Temperature (T), pressure (P) and density (r) are examples of intensive properties.An intensive property is a property of matter that depends only on the type of matter in a sample and not on the amount. Other intensive properties include colour, temperature, density, and solubility.
- D. Physical properties of any compound depend largely on both mass and type of intermolecular and intramolecular forces of attractions
Q61. Enthalpy is the expression for the:
- A. Reaction rate
- B. Heat content✓
- C. Energy state
- D. Activation state
Explanation: Enthalpy is the measurement of energy in a thermodynamic system. The quantity of enthalpy equals the total content of heat of a system, equivalent to the system’s internal energy plus the product of volume and pressure. A change in enthalpy of a system can be written as: ∆ H = ∆E + ∆(PV) ∆ H = ∆E + V∆ P + P ∆V Since, the gas is kept at constant pressure, = 0 Hence ∆ H =∆ E + P ∆V …….(4) In case of liquids and solids, the changes in state do not cause significant volume change i.e. ∆V = 0 For such process, ∆H and ∆E are approximately the same i.e. ∆E ≈∆ H According to first law of thermodynamics: ∆E = q + wIf w is pressure - volume work done by the system, then: w = - P∆ V So ∆ E = q - P ∆V Putting the value of ∆E in equation 4 we get: ∆ H = q - P∆ V + P ∆V ∆H = q Since the pressure is constant, therefore, ∆H = qp......... (5) This shows that change in enthalpy is equal to heat of reaction at constant pressure. The reactions are carried out at constant pressure more frequently than at constant volume. So, working with ∆H is more convenient than ∆E .
Why the other options are wrong
- A. Reaction rate is the speed at which a chemical reaction proceeds. It is often expressed in terms of either the concentration (amount per unit volume) of a product that is formed in a unit of time or the concentration of a reactant that is consumed in a unit of time.
- C. Energy level, also called energy state, any discrete value from a set of values of total energy for a subatomic particle confined by a force to a limited space or for a system of such particles, such as an atom or a nucleus.
- D. Activation energy is the minimum amount of energy that is required to activate atoms or molecules to a condition in which they can undergo chemical transformation or physical transport.
Q62. The heat require to change 1 mole of Iodine (solid) to Iodine (gas) is called:
- A. Heat of vaporisation
- B. Heat of sublimation✓
- C. Heat of fusion
- D. Melting point
Explanation: The heat absorbed by one gram or unit mass of a substance in the process of changing, at a constant temperature and pressure, from a solid to a gaseous state.Like vaporisation, the process of sublimation requires an input of energy to overcome intermolecular attractions. The enthalpy of sublimation, ΔHsub, is the energy required to convert one mole of a substance from the solid to the gaseous state.
Why the other options are wrong
- A. The heat of vaporisation is defined as the amount of heat needed to turn 1g of a liquid into a vapour, without a rise in the temperature of the liquid.
- C. The heat of fusion is the quantity of heat necessary to change 1 g of a solid to a liquid with no temperature change (Weast, 1964, p. F-44). It is also a latent heat and is sometimes called the latent heat of fusion.
- D. The melting point is usually defined as the point at which materials change from a solid to a liquid. The temperature at which solid changes its state to liquid at atmospheric pressure is called the melting point of that liquid. This is the point at which both liquid and solid phases exist at equilibrium
Q63. In the electrolysis of CuCl2 (Copper Chloride) the substance liberated at the anode:
- A. Copper
- B. Chlorine Gas✓
- C. Hydrogen
- D. Copper Chloride
Explanation: In the electrolysis of CuCl2, the anode is the positive electrode that attracts negatively charged ions, such as chloride ions (Cl-). At the anode, these chloride ions lose electrons (are oxidized) to form chlorine gas (Cl2), which is liberated.The correct answer is 'Chlorine Gas' because the anode facilitates oxidation reactions, and chlorine gas is the result of chloride ions losing electrons.Other options are incorrect because:Copper: This is deposited at the cathode, not the anode.Hydrogen: Hydrogen is not involved in the anode reaction during CuCl2 electrolysis.Copper Chloride: It dissociates in solution and is not a product of the anode reaction.
Why the other options are wrong
- A. Copper ions are attracted to the cathode, where they gain electrons and deposit as metallic copper. Thus, copper is not liberated at the anode.
- C. Hydrogen ions are reduced at the cathode, not at the anode, thus hydrogen is not liberated at the anode during the electrolysis of CuCl2.
- D. Copper chloride, as a compound, is not liberated at the anode. Instead, it dissociates into copper and chloride ions in the solution.
Q64. Factors affecting the balance of a chemical equilibrium are following except:
- A. Concentration
- B. Temperature
- C. Enthalpy✓
- D. Pressure
Explanation: The correct answer is 'Enthalpy'. Enthalpy is a thermodynamic property that represents heat content, but it does not directly affect the position of a chemical equilibrium. In contrast, changes in concentration, temperature, and pressure can shift the equilibrium according to Le Châtelier's principle. Concentration changes affect the availability of reactants or products. Temperature changes can shift the equilibrium, especially if the reaction is exothermic or endothermic. Pressure changes affect equilibria involving gases, as they can change the volume and thus the concentration of gaseous reactants or products.
Why the other options are wrong
- A. Changes in concentration of reactants or products can shift the equilibrium position according to Le Châtelier's principle.
- B. Temperature changes can affect the equilibrium position, favoring either the forward or reverse reaction depending on the endothermic or exothermic nature of the reactions.
- D. Changes in pressure, especially in gaseous systems, can shift the equilibrium position if the number of moles of gas changes in the reaction.
Q65. The formula for general gas equation is:
- A. P1 V1 = P2V2
- B. V1/T1 = V2/T2
- C. E = mc2
- D. P1V1/T1 = P2V2/T2✓
Explanation: The ideal gas equation is formulated as: PV = nRT. In this equation, P refers to the pressure of the ideal gas, V is the volume of the ideal gas, n is the total amount of ideal gas that is measured in terms of moles, R is the universal gas constant, and T is the temperature.
Why the other options are wrong
- A. It represents the boyle's law. Boyle's Law is a basic law in chemistry describing the behaviour of a gas held at a constant temperature. The law, discovered by Robert A. Boyle in 1662, states that at a fixed temperature, the volume of gas is inversely proportional to the pressure exerted by the gas.
- B. It represents the equation for charles law.Charles law states that the volume of an ideal gas is directly proportional to the absolute temperature at constant pressure. The law also states that the Kelvin temperature and the volume will be in direct proportion when the pressure exerted on a sample of a dry gas is held constant.
- C. It represents the energy mass equation by einstein.,E or energy, which is the entirety of one side of the equation, and represents the total energy of the system. m, or mass, which is related to energy by a conversion factor. And c2, which is the speed of light squared: the right factor we need to make mass and energy equivalent.
Q66. The electronic configurations of the noble gases are:
- A. ns2, np5
- B. ns2, np6✓
- C. ns2, np4 , nd8
- D. ns2, np5, nd10
Explanation: Noble gases are characterized by having a completely filled outer electron shell, typically with the configuration ns2np6. This full valence shell makes them exceptionally stable and chemically inert. Helium is a special case with a 1s2 configuration due to its position in the periodic table. Option B correctly represents this configuration. Options A, C, and D do not represent the electronic configurations of noble gases and are thus incorrect. Option A corresponds to halogens, group 17 elements, while Options C and D do not represent valid configurations for any known element.
Why the other options are wrong
- A. This configuration represents halogens, which belong to group 17 (group 7A) elements, not noble gases.
- C. This is not a valid electronic configuration for any known stable element.
- D. This configuration does not exist in the context of noble gases or any stable element in the periodic table.
Q67. The electro-negativity of the element is increased:
- A. Down the group
- B. Across the period from right to left
- C. Across the period from left to right✓
- D. None of the above
Explanation: Electronegativity refers to the ability of an atom to attract shared electrons in a chemical bond. Across a period from left to right, electronegativity increases due to increasing nuclear charge and decreasing atomic radius, which enhances the atom's ability to attract electrons. Option C correctly describes this trend. In contrast, down a group, electronegativity decreases because of the increased atomic radius and electron shielding, making Option A incorrect. Option B is incorrect because it reverses the trend, suggesting a decrease across the period from right to left. Option D is incorrect as there is a correct option provided.
Why the other options are wrong
- A. Electronegativity decreases down a group due to increased atomic radius and electron shielding, which outweigh the increase in nuclear charge.
- B. Electronegativity decreases from right to left across a period as atomic size increases and effective nuclear charge decreases.
- D. This option is incorrect because there is a correct statement among the provided options.
Q68. Which of the following is the most suitable alotropy of sulphur:
- A. Plastic sulphur
- B. Monoclinic sulphur
- C. Rhombic sulphur✓
- D. Laughing gas
Explanation: Rhombic sulphur is crystalline in nature and has an octahedral shape.Octahedral sulphur:- this is also known as rhombic sulphur and is the most stable form as it is insoluble in water and is prepared by evaporating the solution of roll sulphur in carbon disulphide.. On heating the solution of roll sulphur in CS2 we get rhombic sulphur. It is yellow with a melting point of 385.8K and specific gravity of 2.06. Rhombic sulphur cannot be dissolved in water but can be dissolved in benzene, ether, alcohol etc
Why the other options are wrong
- A. Plastic sulphur:- it is a type of amorphous sulphur and is not stable at all temperatures. Hence this option is also incorrect.
- B. Monoclinic sulphur:- it is prepared by melting rhombic sulphur in a dish and cooling , till the crust is formed. Two holes are made in the crust and remaining liquid is poured out . On removing the crust, colourless needle shaped crystals of monoclinic sulphur are formed.This allotrope is only stable at temperature above 369K . So this option is not correct.
- D. Nitrous oxide, commonly known as laughing gas, nitrous, or nos, is a chemical compound, an oxide of nitrogen with the formula N ₂O. At room temperature, it is a colourless non-flammable gas, and has a slightly sweet scent and taste.
Q69. S — black element have the folowing properties except:
- A. Reaction with water gives hydroxides
- B. Reaction with water gives different oxides
- C. Reaction with metals to give binary ionic salts✓
- D. Reaction with non-metals to give binary ionic salts
Explanation: Alkali and alkaline metals are reducing in natureThey have low ionisation enthalpies They lose the outermost electron(s) to form cation .Group 1 elements lose 1 electron while the group 2 elements loses 2 electrons .Metallic character increases down the group .Because of high reactivity they are never found pure in nature .Reactivity increases down the group .Compounds of s-Block are ionic in nature.They form binary ionic compounds with non metals .Exception to this is beryllium and lithium
Why the other options are wrong
- A. Very rapid reactions occur when alkali metals react with water. A small piece of sodium (potassium or lithium) floated on water reacts vigorously to liberate hydrogen and produce metal hydroxide. The reaction is highly exothermic. The energy produced by the reaction may even ignite the hydrogen 2Na + 2H2O—-----> 2NaOH + H 2 The reaction becomes increasingly vigorous from lithium to caesium. Potassium, rubidium and caesium are so highly reactive that they react with ice even at -100°C.Similar reactions are shown by alkaline earth metals. The option is incorrect as they react with H2O to give hydroxides
- B. Alkali metals of the s-block elements react with water very fast with formic hydroxides along with the release of H2 gas. • Least reactive metal with water will is Li and maximum is Cs igneous reactivity water increases from Li to Cs.• Alkaline earth metals will react slowly with water and give hydrogen with metal •Be does not react with water Mg reacts with only hot water.Ca and Ba react with cold water but not like that alkali metals.
- D. Lithium is the only Group IA metal that combines with nitrogen and carbon to form nitride and carbide, respectively. Lithium nitride 6Li + N 2—--->2Li3N Lithium carbide 4Li + C—---> Li4C Alkali metals react easily with halogens to give halides. Lithium and sodium, for example, react slowly with chlorine at room temperature. Molten sodium burns with a brilliant yellow flame in a chlorine atmosphere to form sodium chloride. 2Na + 2Cl—----> 2NaCl Potassium, rubidium and caesium react vigorously with all the halogens, forming metal halides. All alkali metals form their sulphides when treated with molten sulphur. The general reaction is: 2M + S —--> M2SSimilar reactions are shown by alkaline earth metals.
Q70. Melting and Boiling points of transitive elements is high because:
- A. Half filled d-orbit
- B. Metallic bond✓
- C. Small atomic size and valence electrons
- D. None of the above
Explanation: Transition metals have high melting and boiling points primarily due to the strong metallic bonds formed by the involvement of delocalized 3d and 4s electrons. This delocalization allows for stronger attractions between metal atoms, resulting in higher energy requirements to break these bonds during melting and boiling. Option B is correct because it addresses the role of metallic bonding and electron delocalization in transition metals. Option A incorrectly focuses on d-orbital filling, which affects other properties but not directly the melting and boiling points. Option C incorrectly attributes these high points to atomic size, which is not the primary factor. Option D is incorrect as a correct explanation exists.
Why the other options are wrong
- A. While half-filled d-orbitals do influence certain properties of transition metals, such as magnetic behavior and stability, they are not the primary reason for high melting and boiling points.
- C. Transition metals generally have larger atomic sizes compared to non-transition elements in the same period. The high melting and boiling points are not due to small atomic size but rather the strong metallic bonding.
- D. This option is incorrect as there is a correct explanation for the high melting and boiling points of transition metals.
Q71. The compound formed by the action of the water on the Calcium carbide is
- A. Ethane
- B. Ethene
- C. Acetylene✓
- D. Methane
Explanation: The correct answer is Acetylene. When calcium carbide (CaC2) reacts with water, it produces acetylene gas (C2H2) and calcium hydroxide. This is a well-known industrial process for producing acetylene, which is used in welding and as a building block for organic synthesis. The other options, such as ethane, ethene, and methane, are not products of this reaction. Ethane and ethene are different hydrocarbons, while methane is a simple alkane, none of which are produced from the reaction of calcium carbide with water.
Why the other options are wrong
- A. Ethane is not produced in the reaction between calcium carbide and water. The reaction produces acetylene instead.
- B. Ethene is not the product of this reaction. The reaction produces acetylene.
- D. Methane is not formed in this reaction. The reaction between calcium carbide and water produces acetylene.
Q72. The fat soluble vitamins is:
- A. Vitamin A✓
- B. Vitamin B-12
- C. Niacin
- D. None of the above
Explanation: The correct answer is Vitamin A, which is a fat-soluble vitamin. Fat-soluble vitamins, like Vitamin A, D, E, and K, dissolve in fats and are stored in the body's fatty tissue and liver. Vitamin B-12 and Niacin (Vitamin B-3) are water-soluble vitamins, meaning they dissolve in water, are not stored in the body, and need to be consumed more regularly. Therefore, options B and C are incorrect as they describe water-soluble vitamins.
Why the other options are wrong
- B. Vitamin B₁₂, or cobalamin, is a water-soluble vitamin crucial for nerve function and the production of DNA and red blood cells. Unlike fat-soluble vitamins, water-soluble vitamins dissolve in water and are not stored in the body.
- C. Niacin, also known as vitamin B-3, is a water-soluble vitamin important for energy metabolism and maintaining healthy skin and nerves. It is not stored in the body like fat-soluble vitamins and needs to be consumed regularly.
- D. This option is incorrect. Vitamin A is indeed a fat-soluble vitamin, and choosing this option would disregard that fact.
Q73. The formula which indicates the relative numbers of different kinds of the atoms in a molecule is called:
- A. Structural formula
- B. Empirical formula
- C. Molecular formula✓
- D. None of the above
Explanation: The molecular formula specifies the exact number of each kind of atom in a molecule, making it the correct choice for defining the relative numbers of different atoms. The structural formula gives more information about the arrangement and bonding of atoms, not just their counts. The empirical formula provides a simplified ratio of atoms rather than the actual count, and 'None of the above' is incorrect because the molecular formula is the type of formula described in the question.
Why the other options are wrong
- A. A structural formula represents the arrangement of atoms in a molecule and the bonds between them. It shows more detail than just the number of each type of atom.
- B. The empirical formula shows the simplest whole-number ratio of atoms in a compound, not the exact number of atoms per molecule. It is a reduced form of the molecular formula.
- D. This option is incorrect as the correct answer is provided among the given choices.
Q74. Methane is obtained by which following method:
- A. Electrolysis of sodium acetate
- B. Electrolysis of aluminium carbide
- C. Heating sodium acetate with soda lime✓
- D. All of these
Explanation: The correct method for obtaining methane is by heating sodium acetate with soda lime. This process involves a decarboxylation reaction where sodium acetate reacts with soda lime to produce methane (CH4) and sodium carbonate. The other options are incorrect: Electrolysis of sodium acetate produces ethane, not methane, due to the formation of methyl radicals. Electrolysis of aluminium carbide is not used for methane production, as it involves different reactions consuming carbon electrodes.
Why the other options are wrong
- A. Electrolysis of sodium acetate does not produce methane. Instead, it produces ethane due to the formation of methyl radicals that combine to form ethane. This method is not suitable for producing methane.
- B. This process does not produce methane. The electrolysis of aluminium carbide is not typically used to produce hydrocarbons. Instead, it involves reactions that consume carbon electrodes.
- D. This option is incorrect because only heating sodium acetate with soda lime produces methane. The other methods do not produce methane.
Q75. The following reactions is an example of C.H8 + → heat → C3H6Cl2 + 2HCL
- A. Addition reaction
- B. Reduction reaction
- C. Oxidation reaction
- D. Substitution reaction✓
Explanation: Alkanes react with chlorine and bromine in the presence of sunlight or UV light or at high temperature resulting in the successive replacement of hydrogen atoms with halogens called halogenation. Extent of halogenation depends upon the amount of halogen used. Reaction of alkanes with fluorine is highly violent and results in a mixture of carbon, fluorinated alkanes and hydrofluoric acid. Iodine does not substitute directly because the reaction is too slow and reversible. The order of reactivity of halogens is F2 >Cl2 >Br2 >I2. CH4+Cl2→CH3Cl+HCl.
Why the other options are wrong
- A. In organic chemistry, an addition reaction is an organic reaction in which two or more molecules combine to generate a bigger one (the adduct). Molecules with carbon—hetero double bonds, such as carbonyl (C=O) or imine (C=N) groups, can be added because they have double-bond character as well
- B. Any process in which there is a increase in the number of covalent bonds between an atom and atom(s) that are less electronegative. Commonly seen as, but not limited to, increasing the number of bonds between carbon and hydrogen.
- C. Oxidation of an organic compound results in an increase in the number of carbon-heteroatom bonds, and/or a decrease in the number of carbon-hydrogen bonds. Reduction of an organic compound results in a decrease in the number of carbon-heteroatom bonds, and/or an increase in the number of carbon-hydrogen bonds.
Q76. In which of the following reaction the rate of nucleophilic substitution depend upon the concentration of the alkyl halide only:
- A. SN1✓
- B. SN2
- C. SN3
- D. Addition reaction
Explanation: In nucleophilic substitution reactions, the SN1 mechanism is characterized by its dependence on the concentration of the alkyl halide only. This is due to its unimolecular rate-determining step, where the leaving group departs first, forming a carbocation. The nucleophile then attacks this intermediate, but since this step is not rate-determining, the nucleophile's concentration doesn't affect the rate, resulting in first-order kinetics. In contrast, SN2 reactions depend on the concentrations of both the alkyl halide and the nucleophile due to its bimolecular, concerted mechanism. SN3 is not a recognized mechanism in this context, and addition reactions are a different type of reaction altogether.
Why the other options are wrong
- B. In an SN2 reaction, the rate depends on both the concentration of the alkyl halide and the nucleophile. This is because the nucleophile attacks the substrate at the same time the leaving group departs, making it a bimolecular reaction.
- C. There is no known SN3 reaction mechanism in nucleophilic substitution chemistry.
- D. An addition reaction involves the addition of atoms or groups to a molecule, rather than nucleophilic substitution, which involves replacing a leaving group with a nucleophile.
Q77. In the phenol:
- A. Alcoholic group attached on ring structure
- B. Hydroxyl group attached on benzene ring✓
- C. Alcoholic group attached on benzene ring
- D. All of the above
Explanation: Phenol is an aromatic organic compound characterized by a hydroxyl group (−OH) bonded to a benzene ring. This specific arrangement classifies it as a phenolic compound, not an alcohol, which typically involves hydroxyl groups attached to saturated carbon atoms. The hydroxyl group in phenol allows for intermolecular hydrogen bonding, contributing to its solubility in water. Options A and C incorrectly describe the functional group as 'alcoholic,' which applies to aliphatic alcohols, not aromatic structures like phenol. Option D is incorrect as only option B accurately describes phenol's structure.
Why the other options are wrong
- A. This is incorrect. Phenol features a hydroxyl group, not an alcoholic group, attached to a benzene ring. The term 'alcoholic group' refers to aliphatic alcohols, not aromatic compounds like phenol.
- C. This is incorrect. The term 'alcoholic group' is misleading in this context. Phenol has a hydroxyl group, which is different from the typical aliphatic alcohol structure.
- D. This option is incorrect because the correct description of phenol's structure is only provided in option B.
Q78. P.V.C. prepared from:
- A. Ethene and hydrogen chloride✓
- B. Ethane and hydrogen chloride
- C. Methane and hydrogen chloride
- D. Acetylene and hydrogen chloride
Explanation: PVC, or polyvinyl chloride, is primarily manufactured through the polymerization of vinyl chloride. The process starts with ethene, which reacts with chlorine to form ethylene dichloride. This compound is then converted to vinyl chloride monomer at high temperatures. The vinyl chloride monomers are subsequently polymerized to form PVC resin. Option A is correct as it accurately reflects this industrial synthesis route.Option B is incorrect because ethane does not have the necessary double bond to react with hydrogen chloride to form vinyl chloride. Option C is incorrect because methane, being a simple alkane with no double bonds, cannot participate in this process. Option D, while technically possible, is not the industrial standard due to higher costs and safety concerns associated with using acetylene.
Why the other options are wrong
- B. Ethane does not react with hydrogen chloride to form vinyl chloride. Instead, ethane lacks the necessary reactivity for this process as it does not contain a double bond like ethene.
- C. Methane is not used in this process as it is a saturated hydrocarbon and does not partake in the formation of vinyl chloride. The lack of a double bond makes it unreactive in this context.
- D. Acetylene does react with hydrogen chloride to form vinyl chloride; however, the typical industrial route to PVC involves ethene, not acetylene, as the starting material for economic and safety reasons.
Q79. Methyl alcohol is also known as:
- A. Wood spirit
- B. Wood naphtha
- C. Methanol
- D. All of these✓
Explanation: Methanol (also called methyl alcohol and wood spirit, amongst other names) is an organic chemical and the simplest aliphatic alcohol, with the formula CH3OH (a methyl group linked to a hydroxyl group, often abbreviated as MeOH). It is a light, volatile, colourless, flammable liquid with a distinctive alcoholic odour similar to that of ethanol (potable alcohol).A polar solvent, methanol acquired the name wood alcohol because it was once produced chiefly by the destructive distillation of wood. Today, methanol is mainly produced industrially by hydrogenation of carbon monoxide.Methanol consists of a methyl group linked to a polar hydroxyl group. With more than 20 million tons produced annually, it is used as a precursor to other commodity chemicals, including formaldehyde, acetic acid, methyl tert-butyl ether, methyl benzoate, anisole, peroxyacids, as well as a host of more specialised chemicalsUseful search terms for methyl alcohol include “methanol,” “carbinol,” “columbian spirits,” “pyroligneous spirits,” “wood alcohol,” “wood naphtha,” and “wood spirits.”
Why the other options are wrong
- A. Methanol (also called methyl alcohol and wood spirit, amongst other names) is an organic chemical and the simplest aliphatic alcohol, with the formula CH3OH (a methyl group linked to a hydroxyl group, often abbreviated as MeOH). It is a light, volatile, colourless, flammable liquid with a distinctive alcoholic odour similar to that of ethanol (potable alcohol).A polar solvent, methanol acquired the name wood alcohol because it was once produced chiefly by the destructive distillation of wood. Today, methanol is mainly produced industrially by hydrogenation of carbon monoxide. Methanol consists of a methyl group linked to a polar hydroxyl group. With more than 20 million tons produced annually, it is used as a precursor to other commodity chemicals, including formaldehyde, acetic acid, methyl tert-butyl ether, methyl benzoate, anisole, peroxyacids, as well as a host of more specialised chemicals Useful search terms for methyl alcohol include “methanol,” “carbinol,” “columbian spirits,” “pyroligneous spirits,” “wood alcohol,” “wood naphtha,” and “wood spirits.”
- B. b) Wood naphtha: Wood naphtha is not the same as methyl alcohol. Wood naphtha refers to a mixture of volatile hydrocarbons obtained from the distillation of wood tar.
- C. c) Methanol: Methanol is the systematic name for methyl alcohol. It is a simple alcohol with the chemical formula CH3OH. Methanol is commonly used as an industrial solvent, antifreeze, fuel, and in the production of various chemicals.
Q80. Commercially nitric acid is prepared by the:
- A. Oxidation of ammonia by Bayer's method
- B. Oxidation of ammonia by Ostwald’s method✓
- C. Reduction of ammonia by Ostwald’s method
- D. Oxidation of ammonia by Hoopes process
Explanation: The Ostwald process is the commercial method for producing nitric acid, starting with the oxidation of ammonia. In this process, ammonia is oxidized to form nitric oxide and nitrogen dioxide, which is then absorbed in water to produce nitric acid. This process is efficient and widely used in the industrial production of nitric acid, which is essential for fertilizers and explosives.Other options are incorrect because they either describe processes unrelated to nitric acid production, such as the Bayer and Hoopes processes, or incorrectly describe the Ostwald process as involving reduction instead of oxidation.
Why the other options are wrong
- A. The Bayer process is not related to the production of nitric acid; it is used for refining bauxite ore to produce alumina (aluminum oxide).
- C. The Ostwald process involves oxidation, not reduction, of ammonia to produce nitric acid.
- D. The Hoopes process is used for refining aluminum and does not involve the oxidation of ammonia or the production of nitric acid.
Q81. Which of the following quantities are vector:
- A. Time and Mass
- B. Force and Displacement✓
- C. Length and Weight
- D. Temperature and Density
Explanation: A vector is a quantity that has both magnitude and direction. In this question, Force and Displacement are vector quantities because they involve direction; force has a direction in which it is applied, and displacement involves movement from one point to another in a specific direction. The other options include scalars: Time and Mass are scalars as they have no directional component. Length is scalar, though Weight is a vector as it represents gravitational force. Temperature and Density are purely scalar, having magnitude but no direction.
Why the other options are wrong
- A. Time and mass are scalar quantities because they only have magnitude, not direction.
- C. Weight is a vector because it's a force that acts in a specific direction, but length is a scalar, having only magnitude.
- D. Temperature and density are both scalar quantities as they lack direction.
Q82. momentum of the body increase by 20% what is the % increase in it’s K.E.:
- A. 36
- B. 44✓
- C. 52
- D. 60
Explanation: The correct answer is 44%. The relationship between kinetic energy (KE) and momentum (p) is given by the formula KE = p²/2m. When momentum increases by 20%, the new momentum is p' = 1.2p. Substituting this into the kinetic energy formula, we get KE' = (1.2p)²/2m = 1.44p²/2m. This shows the kinetic energy increases by 44% (since 1.44 - 1 = 0.44 or 44%). Option A (36%), Option C (52%), and Option D (60%) are incorrect as they do not accurately reflect the calculated increase in kinetic energy when momentum increases by 20%.
Why the other options are wrong
- A. If the momentum increases by 20%, the kinetic energy does not increase by 36%. Recalculate using the relationship between momentum and kinetic energy.
- C. An increase of 52% is incorrect. The percentage increase in kinetic energy is calculated using the squared increase in momentum.
- D. 60% is too high for the increase in kinetic energy. Apply the formula KE = p²/2m to find the correct percentage increase.
Q83. Which one of the following statement is incorrect:
- A. A body has a constant velocity but varying speed✓
- B. A body has a constant speed but varying acceleration
- C. A body has a constant velocity and same speed
- D. A body has a constant speed but can have varying velocity
Explanation: The correct answer is Option A: A body cannot have a constant velocity yet varying speed because velocity is a vector that includes speed (a scalar) as its magnitude. If the velocity is constant, both the speed and direction of motion must remain unchanged. In contrast, it's possible to have constant speed with varying acceleration (as in circular motion), constant speed with varying velocity (again in circular motion), or constant speed without acceleration (uniform motion in a straight line).
Why the other options are wrong
- B. A body can maintain a constant speed yet have varying acceleration if it changes direction. For example, an object moving in a circular path at a constant speed is accelerating because its direction is constantly changing.
- C. A body's velocity is a vector quantity, which includes both magnitude and direction. If the velocity is constant, both speed and direction must remain constant.
- D. Yes, this is possible. A body moving at constant speed on a circular track experiences changes in velocity because its direction changes while speed stays the same.
Q84. Centripetal force ‘FC' is given by:
- A. mv2/r✓
- B. mv/r
- C. m2v/r
- D. mv/l
Explanation: Centripetal force is the force required to keep an object moving in a circular path. The correct formula is FC = mv2/r, where m is the mass of the object, v is the velocity, and r is the radius of the circle. This formula arises from the requirement that the force must change the direction of the velocity without changing its magnitude. Option A is correct because it includes all the necessary components: mass, velocity squared, and radius. Option B is incorrect because it lacks the velocity squared term. Option C is incorrect because it incorrectly squares the mass rather than the velocity. Option D is incorrect because it uses an incorrect denominator (l instead of r) and lacks the velocity squared term.
Why the other options are wrong
- B. This formula is incorrect because it does not include the velocity squared (v2), which is necessary for calculating centripetal force.
- C. This formula is incorrect because it incorrectly squares the mass (m) instead of the velocity (v).
- D. This formula is incorrect because it uses length (l) instead of radius (r) and does not include velocity squared (v2).
Q85. Value of 'G' is:
- A. 6.667 x 1011 N-m2/Kg
- B. 6.667 x 10-11 Nm/Kg2
- C. 6.667 x 1013 Nm2/Kg
- D. 6.667 x 10-11 Nm2/Kg2✓
Explanation: The universal gravitational constant (G) relates the magnitude of the gravitational attractive force between two bodies to their masses and the distance between them. Its value is extremely difficult to measure experimentally.
Why the other options are wrong
- A. The units used are not correct.It is not 6.6x10^-11Nm²\KgThe value is 6.6x10^-11 Nm²\kg².
- B. The units used are not correct.It is not 6.6 x10 ^-11 Nm \kg².The value is 6.6x10^-11 Nm²\kg².
- C. The units used are not correct.It is not 6.6 x10 ^-11 Nm \kg².The value is 6.6x10^-11 Nm²\kg².
Q86. If we go away from the surface of the earth at a distance equal to radius of the earth then the value of 'g' will be:
- A. 1/4✓
- B. 1/8
- C. 1/2
- D. 1/9
Explanation: The acceleration due to gravity at the surface of the Earth is given by the formula g = GM/R^2, where R is the radius of the Earth. If you move to a distance equal to the Earth's radius above the surface, the total distance from the Earth's center becomes 2R. Therefore, the new value of 'g' will be GM/(2R)^2 = GM/4R^2 = g/4. This means the acceleration due to gravity becomes one-fourth of its original value. The other options are incorrect because they do not correctly apply the inverse square law of gravitation, which dictates that gravitational force decreases with the square of the distance from the source.
Why the other options are wrong
- B. This option is incorrect as the gravitational force decreases with the square of the distance, not directly proportional.
- C. This option is incorrect; 'g' does not decrease linearly with distance but rather with the square of the distance.
- D. This option is incorrect because the formula for gravitational force decrease involves a factor of 4, not 9, when distance is doubled.
Q87. The energy of a body at height 'h' from the center of earth to the which g = 0 is called:
- A. Kinetic energy
- B. Potential energy
- C. Gravitational energy
- D. Absolute potential energy✓
Explanation: Absolute potential energy is defined as the amount of work that needs to be done on an object to bring an object to its current location from a point of infinite distance. It can also be defined as the energy needed for an object to reach escape velocity So the absolute potential energy is the correct answer and has a non zero value .
Why the other options are wrong
- A. It is not correct as F=1\2 mv2.it doesn't depend on the height of object and a static object is being considered so v =0 hence KEV =0 Kinetic energy is the energy an object has because of its motion.Kinetic energy can be transferred between objects and transformed into other kinds of energy.
- B. It is incorrect as P.E=mgh and g=0.Potential energy, stored energy that depends upon the relative position of various parts of a system. A spring has more potential energy when it is compressed or stretched. A steel ball has more potential energy raised above the ground than it has after falling to Earth.
- C. It is incorrect as U=mgh and g=0.Gravitational energy is the energy stored in an object due to its height above the Earth (e.g. if it's further away or closer to the ground). It is a form of potential energy. An object's height above the ground gives it gravitational energy.
Q88. Which one of the following is not regarded as a fundamental quantity in physics:
- A. Length
- B. Time
- C. Mass
- D. Force✓
Explanation: A fundamental quantity is a basic measure that is not derived from other quantities. Force is a derived quantity because it is calculated using the formula F = ma, where m is mass and a is acceleration. On the other hand, length, time, and mass are fundamental quantities as they are independent and form the basis for other measurements. Fundamental quantities are part of the International System of Units (SI) and include length (metre), mass (kilogram), and time (second), among others.
Why the other options are wrong
- A. Length is a fundamental quantity because it is one of the basic building blocks for measuring physical phenomena.
- B. Time is a fundamental quantity as it is essential for defining motion and change.
- C. Mass is a fundamental quantity as it measures the amount of matter in an object.
Q89. Acoustics is the study:
- A. The production of sound
- B. The production and properties of sound✓
- C. The source of sound
- D. The intensity, frequency, and quality of sound
Explanation: Acoustics is the science that deals with the study of mechanical waves in various media, including gases, liquids, and solids. It covers the production, control, transmission, reception, and effects of sound. Therefore, the correct answer is the study of the production and properties of sound. Options that focus only on production, source, or specific characteristics like intensity and frequency do not fully encompass the breadth of the field of acoustics.
Why the other options are wrong
- A. While acoustics does involve the production of sound, it encompasses much more than just that aspect.
- C. Acoustics extends beyond just identifying the source of sound, covering its behavior and properties as well.
- D. While these aspects are related to sound, acoustics is broader and includes other elements such as production and propagation.
Q90. Which of the given condition is not a possible to discuss the Doppler's effect:
- A. When the listener is at moving and the source as at rest
- B. When the listener is at rest and the source is at moving
- C. When the listener and the source are at rest✓
- D. When the listener and source are at moving
Explanation: Doppler effect in physics is defined as the increase (or decrease) in the frequency of sound, light, or other waves as the source and observer move towards (or away from) each other. Waves emitted by a source travelling towards an observer get compressed.Doppler Effect is applicable only when the velocities of the source of the sound and the observer are much less than the velocity of sound. The motion of both source and the observer should be along the same straight line.
Why the other options are wrong
- A. Case I: An observer moving away from the stationary source.Case II:An observer moving towards the stationary source
- B. Case I: A source moving away from the stationary observerCase II:A source moving towards the stationary observer.
- D. Source and listener move away from each other.Source and observer move towards each other.
Q91. Michelson interferometer is the instrument used to record the interference pattern of the light used to calculate:
- A. Interaction of light
- B. Wavelength of light✓
- C. Refraction of light
- D. Diffraction of light
Explanation: The Michelson interferometer is a precise instrument used mainly for measuring the wavelength of light through interference patterns. When light waves are split and then recombined in the interferometer, they produce an interference pattern that can be analyzed to determine wavelengths. This makes it a critical tool in optical research and applications. The other options, such as interaction, refraction, and diffraction of light, represent different phenomena that the Michelson interferometer is not specifically designed to measure.
Why the other options are wrong
- A. Although the Michelson interferometer involves the interaction of light waves, its main function is not to study this interaction but to measure specific properties of light such as wavelength.
- C. Refraction involves the bending of light as it passes through different media, which is not the focus of a Michelson interferometer. Instead, it is designed to study interference and wavelength.
- D. Diffraction deals with the bending and spreading of light waves around obstacles. Michelson interferometers do not primarily address diffraction but focus on interference and wavelength determination.
Q92. The specific heat time the mass of a body is called:
- A. Specific heat mass✓
- B. Thermal capacity
- C. Internal energy
- D. Heat capacity
Explanation: The specific heat times the mass of a body is referred to as the specific heat mass. This term represents the product of the specific heat and the mass of the body, which is essential in understanding the thermal behavior of a substance. The other options, such as thermal capacity, internal energy, and heat capacity, do not directly relate to the specific heat mass and represent different concepts in thermodynamics.
Why the other options are wrong
- B. Although thermal capacity is related to the heat capacity of a substance, it does not specifically refer to the product of specific heat and mass. Thermal capacity is the product of the mass of the substance times its specific heat capacity.
- C. Internal energy represents the total energy contained within a system, including potential and kinetic energy. It is not directly related to the specific heat times the mass of a body.
- D. Heat capacity is the amount of heat required to produce a unit change in temperature in an object. While related to thermal properties, it does not specifically refer to the specific heat times the mass of a body.
Q93. The electric field intensity at a distance of 1m from a point of charge to 1 micro coulomb is:
- A. A: 1/4 N/C
- B. B: 9 x 109 N/C
- C. C: 9 x 106 N/C
- D. D: 9 x 103 N/C✓
Explanation: The electric field intensity E at a distance r from a point charge Q is given by the formula: E = KQ/r², where K is the Coulomb's constant (9 x 109 Nm²/C²). For a charge Q = 1 microcoulomb (1 x 10-6 C) at a distance of 1 meter, the calculation is: E = (9 x 109)(1 x 10-6) / 12 = 9 x 103 N/C. Options A, B, and C do not correctly apply this formula, leading to incorrect values.
Why the other options are wrong
- A. This option is incorrect. The calculation does not align with the formula for electric field intensity.
- B. This value is incorrect as it represents the constant K, not the electric field at 1 meter.
- C. This option is incorrect. The calculation does not correctly apply the formula for electric field intensity.
Q94. The unit of rate of change of momentum is:
- A. N✓
- B. NC
- C. NS2
- D. N/S
Explanation: Rate of change in momentum is newton(N).
Why the other options are wrong
- B. The unit of rate of change in momentum is newton(N).
- C. The unit of rate of change in momentum is newton(N).
- D. The unit of rate of change in momentum is newton(N)
Q95. Dot product of force and displacement is:
- A. Momentum
- B. Moment
- C. Power
- D. Work✓
Explanation: The correct answer is Work, which is calculated as the dot product of force and displacement (W = F · S). This means work is done when a force causes displacement in the direction of the force. The other options do not fit this definition: Momentum is a vector related to mass and velocity, Moment involves rotational forces and uses the cross product, and Power relates to the rate of doing work, involving force and velocity, not displacement.
Why the other options are wrong
- A. Momentum is the product of mass and velocity, represented as a vector quantity. It involves linear motion and is not related to the dot product of force and displacement.
- B. Moment, also known as torque, is associated with rotational effect and is calculated using the cross product, not the dot product, of force and distance from a pivot point.
- C. Power is the rate at which work is done, expressed as the dot product of force and velocity, not displacement.
Q96. Work done in unit time is:
- A. Pressure
- B. Work
- C. Energy
- D. Power✓
Explanation: Power is defined as the rate of doing work or the amount of work done per unit time. It is crucial in understanding how quickly or efficiently work can be performed. The SI unit of power is the watt (W), which is equivalent to one joule per second. Other options such as pressure, work, and energy do not account for the time factor in the context of doing work. Pressure is about force over an area, work is the energy transfer by force, and energy is the capacity to perform work, none of which directly relate to the rate at which work is done.
Why the other options are wrong
- A. Pressure is the force applied perpendicular to the surface of an object per unit area. It is not related to the rate at which work is done.
- B. Work refers to the energy transferred when a force is applied over a distance. It is not concerned with the rate at which this transfer occurs.
- C. Energy is the capacity to do work. It does not inherently involve time, so it is not the rate of doing work.
Q97. Erg is unit of energy in:
- A. MKS
- B. SI
- C. FPS
- D. CGS✓
Explanation: The CGS system is a coherent system of units based on the fundamental units of centimetre for distance, gram for mass, and second for time. It was superseded by the MKS system, which was based on the fundamental units of metre for distance, kilogram for mass, and second for time.The erg (symbol, erg, i.e. the same as the unit) is the unit of energy in the cgs system, where one erg represents the work done when a force of one dyne is acting over a distance of one cm and is equivalent to 1 x 10-7 joules.
Why the other options are wrong
- A. The MKS system of units is a physical system of measurement that uses the metre, kilogram, and second as base units. It forms the base of the International System of Units, though SI has since been redefined by different fundamental constants. Joule (J) is the MKS unit of energy, equal to the force of one Newton acting through one metre
- B. Joule [J] is the basic energy unit of the metric system, or in a later more comprehensive formulation, the International System of Units (SI). It is ultimately defined in terms of the metre, kilogram, and second.
- C. The foot-pound-second (fps) system of units is a scheme for measuring dimensional and material quantities. The fundamental units are the foot for length, the pound for weight, and the second for time.Its unit in FPS is poundal x Foot
Q98. Number of vibration in 1 sec is:
- A. Time period
- B. Frequency✓
- C. Amplitude
- D. None of these
Explanation: The correct answer is Frequency. Frequency is defined as the number of complete cycles of a periodic signal occurring per unit time, typically one second. It is measured in hertz (Hz), which is equivalent to one cycle per second. The time period refers to the duration of one complete cycle, and amplitude measures the height or strength of the wave, neither of which indicate the number of vibrations in one second. Option D is incorrect because the correct term is provided among the choices.
Why the other options are wrong
- A. The time period is the duration of one complete cycle of a wave, measured in seconds. It is not the count of cycles in one second.
- C. Amplitude is the maximum extent of a vibration or oscillation, measured from the position of equilibrium. It is not related to the count of vibrations per second.
- D. This option is incorrect; one of the options correctly defines the term for cycles per second.
Q99. Total energy of vibrating body is:
- A. Increase
- B. Decrease
- C. Constant✓
- D. None of these
Explanation: In an ideal oscillating system, such as a mass-spring system or a simple pendulum, the total mechanical energy remains constant. This is due to the continuous exchange between kinetic energy (KE) and potential energy (PE). When KE is at its maximum, PE is at its minimum, and vice versa. This energy transformation is a hallmark of oscillatory motion. External forces, such as friction, can cause energy dissipation, but in an ideal case, these are negligible. Options A and B describe scenarios where energy would change, which is not accurate for a closed system without external forces. Option D is incorrect as the constant nature of total energy applies to ideal vibrating systems.
Why the other options are wrong
- A. The total energy of a closed oscillatory system remains constant unless external forces are applied.
- B. The total energy of a closed oscillatory system remains constant unless energy is lost to the surroundings.
- D. The total energy of an ideal vibrating system remains constant unless acted upon by external forces.
Q100. The waves in which motion of particles of medium and propagation of wave are in same direction are called :
- A. Longitudinal✓
- B. Transverse
- C. Electromagnetic
- D. None of these
Explanation: The correct answer is Longitudinal waves. These waves are characterized by the displacement of the medium's particles in the same direction as the wave's travel, resulting in areas of compression and rarefaction. In contrast, Transverse waves have particle motion perpendicular to the wave's direction. Electromagnetic waves differ as they are not mechanical and involve oscillating electric and magnetic fields. The option None of these is incorrect as longitudinal waves match the description given.
Why the other options are wrong
- B. Transverse waves have particle motion perpendicular to the direction of wave propagation, unlike longitudinal waves. Examples include water waves.
- C. Electromagnetic waves consist of oscillating electric and magnetic fields and do not require a medium for propagation, differing from mechanical waves like longitudinal and transverse waves.
- D. This option is incorrect because longitudinal waves fit the description provided in the question.
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