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Sindh Mcat Nts 2016 Smbbmc Lyari — Solved Past Paper with Answers
All 100 MCQs from Sindh Mcat Nts 2016 Smbbmc Lyari, solved with the correct answer highlighted and a full explanation for every question. This is a free MDCAT Sindh / DUHS past paper — no signup, no ads. Practise it interactively in timed mode, drill more with free MDCAT MCQs, or browse all Sindh / DUHS papers.
Attempt this paper interactively →Q1. Identify the word or phrase that needs to be changed for the sentence to be correct:Haven’t you buy too many pieces of furniture for your new house. No error
- A. Haven’t
- B. Buy✓
- C. Pieces
- D. Furniture
- E. No Error
Explanation: The question clearly is in the past tense form. Hence the word buy seems out of place as it is in the present tense, and accordingly it should be replaced by its past tense form: bought.
Why the other options are wrong
- A. This part of the sentence is correct because 'Haven’t' is the correct contraction for 'have not' in the present perfect tense.
- C. This part of the sentence is correct because 'pieces of furniture' is a standard way to quantify furniture.
- D. This part of the sentence is correct because 'furniture' is uncountable and correctly used here in the context of 'pieces of furniture'.
- E. This option is incorrect because there is an error in the sentence, specifically the verb form 'buy' which should be 'bought'.
Q2. Identify the word or phrase that needs to be changed for the sentence to be correct:The destruction of forests commonly brings about great changes of climate.
- A. The destruction
- B. Forests
- C. Commonly
- D. Changes
- E. No error✓
Explanation: There are no mistakes in the question hence we will go with Option E.
Why the other options are wrong
- A. There is no grammatical error in the phrase 'The destruction'. The use of 'destruction' as a noun is appropriate in this context.
- B. The word 'forests' is correctly used as a plural noun to indicate more than one forest.
- C. The adverb 'commonly' is correctly used to describe the frequency or generality of the occurrence.
- D. The word 'changes' is correctly used as a plural noun to indicate more than one change.
Q3. Choose the word most similar in meaning to the capitalized one.WILD:
- A. Uncivilized✓
- B. Cultivated
- C. Domestic
- D. Cultured
Explanation: If anything is wild, it might be unrestrained, crazy, and having no sense of culture and traditions. Hence uncivilized is the best option here.
Why the other options are wrong
- B. The word 'cultivated' implies being refined or developed, opposite of the uncontrolled nature of 'wild.'
- C. The term 'domestic' refers to something tamed or suitable for home life, which contrasts the essence of 'wild.'
- D. The word 'cultured' denotes sophistication and education, which is contrary to the raw and untamed nature of 'wild.'
Q4. Choose the word most similar in meaning to the capitalized one.FAINT:
- A. Strong
- B. Pale✓
- C. Tough
- D. Powerful
Explanation: Faint refers to being weak and not strong. All options except Option B are synonyms of strong.
Why the other options are wrong
- A. a) Strong – 'Strong' is the opposite of 'faint' as it implies power or intensity, which 'faint' lacks (incorrect).
- C. c) Tough – 'Tough' means durable or resilient, which does not relate to the meaning of 'faint' (incorrect).
- D. d) Powerful – 'Powerful' implies strength and intensity, which is the opposite of 'faint' (incorrect).
Q5. Choose the lettered word or phrase that is most nearly opposite in meaning to the word in capital letters.RAPID:
- A. Fast
- B. Speedy
- C. Quick
- D. Slow✓
Explanation: Rapid refers to being fast. All options other than Option D are synonyms of fast.
Why the other options are wrong
- A. 'Fast' is synonymous with 'rapid' as both refer to high speed.
- B. 'Speedy' is another word for 'rapid', indicating a quick pace.
- C. 'Quick' means moving or happening with great speed, similar to 'rapid'.
Q6. Choose the lettered word or phrase that is most nearly opposite in meaning to the word in capital letters.DISCARD:
- A. Reject
- B. Keep✓
- C. Throw away
- D. Dispose of
Explanation: Discard means to throw something away. Option B is the only choice which refers to retaining and keeping back the item.
Why the other options are wrong
- A. 'Reject' means to refuse to accept, which is similar to 'discard' because both involve not keeping something.
- C. 'Throw away' is synonymous with 'discard' since both mean to get rid of something.
- D. 'Dispose of' means to get rid of something, similar to 'discard' as both involve removing or eliminating an item.
Q7. Every year a large number of English people spend their summer holidays on the continent of Europe. It is not expensive to cross the English Channel, either by sea, or by air, and once on the other side is an endless variety of things to do and see, new countries to explore, new kinds of food to eat.Young people, students mostly, travel by bicycle or on foot, hitchhiking, when possible, and staying at Youth Hostels. The older people with less energy and more money, travel by bus or by train and stay in hotels. Many people, too, take their own cars with them and travel and wide in search of enjoyment and novelty, If you have your car you can go farther and see more with less inconvenience.You don't have to worry about catching buses and trains, or finding porters and taxis.How do young people usually travel?
- A. By bicycle or on foot✓
- B. By bus
- C. By personal cars
- D. By bus or by personal cars
Explanation: The passage (Second Paragrah, first line) clearly mentions young people who have more energy and less money travel by either bicycle or on foot.
Why the other options are wrong
- B. This option is incorrect. The passage specifies that older people, likely with more money, use buses for travel, not the young people.
- C. This option is incorrect. The passage mentions that people with cars tend to be older with more resources, which does not describe the young travelers.
- D. This option is incorrect. The passage separates the travel habits of young people from those who travel by bus or personal cars, who are typically older.
Q8. Every year a large number of English people spend their summer holidays on the continent of Europe. It is not expensive to cross the English Channel, either by sea, or by air, and once on the other side is an endless variety of things to do and see, new countries to explore, new kinds of food to eat.Young people, students mostly, travel by bicycle or on foot, hitchhiking, when possible, and staying at Youth Hostels. The older people with less energy and more money, travel by bus or by train and stay in hotels. Many people, too, take their own cars with them and travel and wide in search of enjoyment and novelty, If you have your car you can go farther and see more with less inconvenience.You don't have to worry about catching buses and trains, or finding porters and taxis.What are the advantages of travelling by personal car?
- A. You can go farther and explore more✓
- B. It is more economical
- C. You don't have to worry about catching buses and trains
- D. You don't have to find porters and taxis
Explanation: The passage (Second Paragraph, last line) clearly mentions that if one has a car, it allows them to go farther and explore more. The passage also mentions that it results in less inconvenience, but both options C and D can be correct then, hence using Process of Elimination we ignore both of these options.
Why the other options are wrong
- B. This option is incorrect because the passage does not mention anything about traveling by car being more economical. In fact, it suggests that older people with more money often choose this option.
- C. While this is a true statement from the passage, it is not the primary advantage of traveling by car as indicated in the question. The main focus is on the ability to explore more locations.
- D. This option is also true according to the passage, but it is not the primary advantage discussed. The question specifically asks for the main benefit, which is the ability to go farther.
Q9. Complete the sentences by choosing the most appropriate option, from the given lettered choices (A to D) below each.He composed a great many pieces _ music in his life time.
- A. Too
- B. Of✓
- C. At
- D. In
Explanation: The best strategy in attempting these questions is to read them in your head while fitting each option respectively. The sentence refers to a property hence ‘of’ will be the best option here.
Why the other options are wrong
- A. 'Too' is typically an adverb used to indicate excess or degree, not suitable for this context.
- C. 'At' is a preposition often used to indicate location or time, which does not fit the context of the sentence.
- D. 'In' generally indicates location or position within something, which is not applicable here.
Q10. Complete the sentences by choosing the most appropriate option, from the given lettered choices (A to D) below each.If he wants his salary to be _, he will have to take it up with the manager.
- A. Raised✓
- B. Raise
- C. Has raised
- D. Raised off
Explanation: The best strategy in attempting these questions is to read them in your head while fitting each option respectively. The sentence is a simple past tense example hence ‘raised’ is the best option here.
Why the other options are wrong
- B. This option is incorrect because 'raise' is the base form of the verb and does not fit grammatically in the sentence structure.
- C. This option is incorrect because it uses the present perfect tense, which does not fit the request context in the sentence.
- D. This option is incorrect as it uses an inappropriate phrase that does not convey the intended meaning in the sentence.
Q11. Which of the following processes is the reverse of condensation?
- A. Hydrolysis✓
- B. Dehydration synthesis
- C. Polymerization
- D. Vapourization
Explanation: The correct answer is Hydrolysis because it involves breaking down molecules by adding water, which is the reverse of condensation reactions like dehydration synthesis. This is crucial in biological systems for breaking down complex molecules like proteins into amino acids. Dehydration synthesis involves removing water to form bonds, which is part of the condensation process itself. Polymerization is about forming large molecules from small units and can involve various types of reactions, not specifically the reverse of condensation. Vapourization is a physical change from liquid to gas, not related to the chemical processes described.
Why the other options are wrong
- B. This is a type of condensation reaction where two molecules are joined together, resulting in the release of a water molecule. It is not the reverse of condensation but rather a specific form of it.
- C. This is a process where many monomers link together to form a polymer. While dehydration synthesis might be involved in some polymerization reactions, polymerization itself is not the reverse of condensation.
- D. This process involves a liquid turning into a gas, which is unrelated to the chemical processes of condensation and hydrolysis within biological molecules. It is more relevant to physical state changes than chemical reactions.
Q12. In which of the following phases of bacterial growth, is the death rate more rapid than the multiplication rate?
- A. Stationary phase
- B. Lag phase
- C. Decline phase✓
- D. Log phase
Explanation: The correct answer is the Decline phase. During this phase, the environment becomes less favorable for bacterial growth due to the depletion of nutrients and accumulation of toxic waste products, leading to a higher death rate than the reproduction rate. In contrast, during the Stationary phase, the death and reproduction rates are balanced, leading to a stable population size. The Lag phase is primarily a period of adjustment with little to no reproduction, and the Log phase is when bacteria experience exponential growth, with reproduction rates far exceeding death rates.
Why the other options are wrong
- A. During the stationary phase, the rate of bacterial death is roughly equal to the rate of reproduction, leading to a stable population size.
- B. In the lag phase, bacteria are acclimating to their environment, and there is little to no cell division. The death rate is not more rapid than reproduction.
- D. The log phase is characterized by exponential growth, where the reproduction rate far exceeds the death rate.
Q13. Which of the following is the correct sequence of missing events in the diagram given below:
- A. Cleavage -> Fertilization -> Organogenesis -> Gastrulation
- B. Organogenesis -> Gastrulation -> Fertilization -> Cleavage
- C. Fertilization -> Cleavage -> Gastrulation -> Organogenesis✓
- D. Gastrulation -> Fertilization -> Organogenesis -> Cleavage
Explanation: After gamete formation, the first process that occurs is fertilization, which means the fusion of gametes to form a zygote. Then this zygote divides which is termed as cleavage, then after that and before organogenesis, we have the gastrula stage. Hence option C is correct.
Why the other options are wrong
- A. This sequence is incorrect. Fertilization must occur first to form a zygote, followed by cleavage, gastrulation, and finally organogenesis.
- B. This sequence is incorrect. Development starts with fertilization, creating a zygote, followed by cleavage, gastrulation, and then organogenesis.
- D. This sequence is incorrect as it starts with gastrulation. The correct process begins with fertilization, followed by cleavage, gastrulation, and organogenesis.
Q14. The process of membrane fusion and the movement of material out of the cell, is called:
- A. Phagocytosis
- B. Endocytosis
- C. Pinocytosis
- D. Exocytosis✓
Explanation: The process of moving substances out of the cell is called exocytosis.Endocytosis is moving substances into the cell.Phagocytosis is movement of substances into the cell which are solid and massive.Pinocytosis is movement of substances into the cell in liquid state.
Why the other options are wrong
- A. Phagocytosis is the process of a cell engulfing large particles or cells, forming an internal vesicle known as a phagosome. It is a type of endocytosis, not related to exporting materials.
- B. Endocytosis involves the cellular process of taking substances into the cell. This process is the opposite of exocytosis.
- C. Pinocytosis is a form of endocytosis where cells ingest extracellular fluids and small molecules. It is not involved in the export of materials from the cell.
Q15. Which of the following types and functions of the neuron is correct?
- A. Sensory neurons carry impulses from sensory receptors to the CNS; interneurons relay signals within the CNS; motor neurons transmit impulses from the CNS to muscles or glands✓
- B. Motor neurons carry sensory impulses to the CNS; interneurons transmit impulses to muscles; sensory neurons relay signals within the CNS
- C. Interneurons carry impulses from effectors to the CNS; sensory neurons transmit impulses from the CNS to interneurons; motor neurons pass signals within the CNS
- D. Sensory neurons transmit impulses from the CNS to effectors; motor neurons carry sensory information to the CNS; interneurons connect sensory to motor neurons outside the CNS
Explanation: Sensory neurons function to carry the sensory information to the CNS. Interneurons transfer impulses from sensory to motor neurons, remaining within the CNS. Motor neurons are neurons that transmit impulses fromthe CNS to the effectors.
Why the other options are wrong
- B. This option incorrectly assigns the functions of motor, interneurons, and sensory neurons, mixing up their roles.
- C. This option incorrectly describes the pathways of interneurons, sensory neurons, and motor neurons, misrepresenting their functions.
- D. This option reverses the functions of sensory and motor neurons and misplaces the role of interneurons.
Q16. All of the followings are the effects of red light on plant, EXCEPT:
- A. Causes epicotyl (plumule) hook to unbend
- B. Induces increase in leaf area
- C. Elongation of internodes is promoted✓
- D. Stimulate flowering in long day plants
- E. Phytochrome 660 changes to phytochrome 730
Explanation: Red light does not promote internode elongation in plants. Promoting elongation of internodes: This is known as the stem elongation response. It is thought to be caused by the production of auxin, which stimulates cell elongation in the internodes.
Why the other options are wrong
- A. This effect is part of the photomorphogenic response, where red light triggers gibberellin release from cotyledons, stimulating cell elongation in the hypocotyl and causing the epicotyl hook to straighten.
- B. This is a shade avoidance response where red light, through ethylene production, promotes cell division and expansion, leading to increased leaf area.
- D. Red light affects the photoperiodic response by activating gibberellins, which can stimulate flowering in plants that require long days.
- E. Exposure to red light converts phytochrome 660 (inactive form) to phytochrome 730 (active form), triggering various physiological responses in plants.
Q17. Treponema pallidum causes:
- A. AIDS
- B. Genital herpes
- C. Syphilis✓
- D. Gonorrhea
Explanation: Treponema pallidum is the bacterium responsible for causing syphilis, a sexually transmitted infection.
Why the other options are wrong
- A. This option is incorrect. AIDS (Acquired Immunodeficiency Syndrome) is not caused by Treponema pallidum. Instead, it is caused by the Human Immunodeficiency Virus (HIV). HIV attacks and weakens the immune system by targeting CD4 T cells, making the body vulnerable to infections and certain cancers. Treponema pallidum, on the other hand, is a bacterium, not a virus, and is unrelated to AIDS.
- B. This option is incorrect as well. Genital herpes is caused by the Herpes Simplex Virus (HSV), most commonly HSV-2, and sometimes HSV-1. It is a viral infection characterized by painful sores or blisters around the genital and anal areas. Treponema pallidum does not cause viral infections; it is a bacterium that causes syphilis, a completely different type of sexually transmitted infection (STI).
- D. This option is incorrect. Gonorrhea is caused by a completely different bacterium, Neisseria gonorrhoeae, not Treponema pallidum. It is another sexually transmitted infection that primarily affects the reproductive tract, causing symptoms such as painful urination and abnormal discharge. Unlike syphilis, which can affect multiple body systems, gonorrhea is generally localized to the reproductive organs and nearby tissues.
Q18. Below the point at which the cotyledons are attached, the embryo axis is called _.
- A. Radicle
- B. Epicotyl
- C. Hypocotyl✓
- D. Coleoptile
Explanation: Below the point at which the cotyledons are attached, the embryo axis in a plant is called the "hypocotyl." The hypocotyl is the region of the embryo axis between the attachment point of the cotyledons (seed leaves) and the radicle, which is the embryonic root. The hypocotyl plays a crucial role during seed germination, as it often elongates to lift the cotyledons and the shoot tip (plumule) above the soil surface, allowing the young plant to emerge and initiate photosynthesis.
Why the other options are wrong
- A. The radicle is the embryonic root of the plant, which emerges first during germination. It is not located below the cotyledons but is part of the root system.
- B. The epicotyl is the region above the cotyledons, leading to the formation of the stem and leaves. It is not the part below the attachment point of the cotyledons.
- D. The coleoptile is a sheath protecting the young shoot in monocots, not a part of the embryo axis related to cotyledons. It is unrelated to the position below cotyledons in dicots.
Q19. The radius and ulna join at the wrist with the _ small carpal bones.
- A. 4
- B. 6
- C. 7
- D. 8✓
Explanation: There are eight carpal bones in the hand, arranged in two rows of four and four.
Why the other options are wrong
- A. This option is incorrect. The wrist contains more than 4 small carpal bones that connect with the radius and ulna.
- B. This option is incorrect. While this number is close, there are more than 6 carpal bones involved in the wrist joint with the radius and ulna.
- C. This option is incorrect. The number of carpal bones connecting the radius and ulna is not 7; there are actually more.
Q20. Prosopis glandulosa is the botanical name of _.
- A. Chhui mui
- B. Kikar
- C. Bauble
- D. Devi✓
Explanation: Prosopis glandulosa is the botanical name of Devi. The plant has been used for a variety of medicinal purposes, including lice control and treatment of sore throat, skin sores and ulcers
Why the other options are wrong
- A. This is incorrect. Chhui mui is the common name for the plant Mimosa pudica, known for its sensitive leaves that close upon touch.
- B. Kikar, or Acacia nilotica, is not the same as Prosopis glandulosa. It is known for its thorny branches and is commonly found in Africa and the Indian subcontinent.
- C. This is incorrect. 'Bauble' refers to a decorative object and has no botanical relevance to Prosopis glandulosa.
Q21. The diagram is taken from an electron micrograph of a cell, name the organelle labelled B:
- A. Nucleus
- B. Golgi complex✓
- C. Lysosome
- D. Mitochondrion
- E. Vacuole
Explanation: Organelle labelled B is Golgi complex.
Why the other options are wrong
- A. The nucleus is typically a large, round organelle that contains genetic material, not a series of flattened sacs like the Golgi complex.
- C. Lysosomes are small, spherical organelles containing digestive enzymes, unlike the stacked structure of the Golgi complex.
- D. Mitochondria have a double membrane with inner folds known as cristae, which differ from the flattened sacs of the Golgi complex.
- E. Vacuoles are large, fluid-filled organelles that maintain cell pressure and storage, not the structured appearance of a Golgi complex.
Q22. In the Hardy-Weinberg principle, p2 + 2pq + q2 = ?
- A. 0
- B. 1✓
- C. Infinity
- D. Any value between 0 to 1
Explanation: In the Hardy - Weinberg principle, p2 + 2pq + q2 =1
Why the other options are wrong
- A. No, in the Hardy-Weinberg equilibrium, the sum of the genotype frequencies equals 1, representing the entire population.
- C. No, the Hardy-Weinberg principle defines a closed system where the sum of genotype frequencies is finite and equals 1.
- D. Incorrect. While individual genotype frequencies can vary between 0 and 1, their sum in a population at equilibrium is always 1.
Q23. The diagram shows the teeth of the lower jaw of a human. Which tooth is an incisor?
- A. A
- B. B✓
- C. C
- D. D
Explanation: Incisors: These are the sharp, flat teeth at the front of your mouth used for biting and cutting food into smaller pieces. Canines: Located next to the incisors, these pointed teeth are used for tearing and gripping food. Premolars: Situated behind the canines, premolars have a flat surface and are used for crushing and shredding food. Molars: These are the large, flat teeth at the back of your mouth that are designed for grinding and crushing food to prepare it for swallowing.
Why the other options are wrong
- A. This is a premolar, which is located behind the canines and used for grinding food.
- C. This is a canine, which is pointed and used for tearing food.
- D. This is a molar, which is located at the back of the mouth and used for grinding food.
Q24. The diagram shows a tree trunk, with a ring of bark, which includes the phloem removed.The tree will eventually die because this action cuts off the supply of:
- A. Mineral salts to the leaves
- B. Organic nutrients from the leaves✓
- C. Oxygen to the roots
- D. Water to the leaves
Explanation: Organic nutrients such as sugar molecules are transported through phloem tubes,cutting off this tube cuts off this organic nutrients supply. Moreover, Oxygen supply to the roots is through oxygen dissolved in soil.Mineral salts and water supply to the leaves is through xylem vessels.
Why the other options are wrong
- A. Mineral salts are transported via the xylem, not the phloem.
- C. Oxygen is not transported through phloem; it is taken up by the roots from the soil.
- D. Water is transported through the xylem, not the phloem.
Q25. Which statement about dominant and recessive alleles is not correct?
- A. A dominant characteristic is seen in the phenotype of a heterozygote.
- B. A homozygous genotype may be either dominant or recessive.
- C. Recessive phenotypes always have two recessive alleles.
- D. The phenotype of a homozygote is always dominant.✓
Explanation: Phenotype of a homozygote can be dominant or recessive both AA or aa. Hence statement D is incorrect and our answer.
Why the other options are wrong
- A. This statement is correct. In a heterozygote (e.g., Aa), the dominant allele (A) will determine the phenotype, masking the effect of the recessive allele (a).
- B. This statement is correct. Homozygous genotypes can be either dominant (AA) or recessive (aa), depending on the alleles present.
- C. This statement is correct. A recessive phenotype appears only when the individual has two recessive alleles (aa).
Q26. What is the correct sequence of the bones in the arm of a mammal, from the hand to the shoulder?
- A. Phalanges -> Carpal -> Humerus -> Radius and Ulna -> Scapula
- B. Phalanges -> Radius and Ulna -> Carpal -> Humerus -> Scapula
- C. Phalanges -> Carpal -> Radius and Ulna -> Humerus -> Scapula✓
- D. Carpal -> Phalanges -> Radius and Ulna -> Humerus -> Scapula
Explanation: In a mammalian arm, the correct sequence of bones from the hand to the shoulder is: Phalanges -> Carpal -> Radius and Ulna -> Humerus -> Scapula. The Phalanges are the bones of the fingers, followed by the Carpal bones forming the wrist. The Radius and Ulna are the two bones of the forearm, the Humerus is the upper arm bone, and the Scapula is the shoulder blade. Incorrect sequences either misplace the Carpal bones, the Humerus, or the Radius and Ulna.
Why the other options are wrong
- A. This sequence incorrectly places the Humerus before the Radius and Ulna.
- B. This sequence incorrectly places the Radius and Ulna before the Carpal bones.
- D. This sequence incorrectly places the Carpal bones before the Phalanges.
Q27. The table shows the characteristics of the blood in one vessel. Which vessel contains blood with these characteristics?
- A. Aorta✓
- B. Pulmonary artery
- C. Pulmonary vein
- D. Vena cava
Explanation: The aorta carries oxygen-rich blood at high pressure from the left ventricle to systemic circulation.
Why the other options are wrong
- B. The pulmonary artery carries deoxygenated blood from the heart to the lungs. It has a low oxygen concentration and a high carbon dioxide concentration, making it unsuitable given the characteristics in the question.
- C. The pulmonary veins carry oxygenated blood from the lungs to the heart. Although they have a high oxygen concentration, their blood pressure is lower compared to systemic arteries, which doesn't match the characteristics described.
- D. The vena cava returns deoxygenated blood from the body back to the heart. It has a low oxygen concentration and a high carbon dioxide concentration, and lower blood pressure, which does not match the characteristics of the vessel in question.
Q28. The gas-exchange portion of the human respiratory system is the:
- A. Larynx
- B. Trachea
- C. Bronchi
- D. Alveoli✓
Explanation: The gaseous exchange in the human respiratory system takes place between the alveoli and capillaries of the lungs. Both the alveoli and capillaries are single made of a single layer of cells, the endothelium or the squamous epithelium that permits the exchange or diffusion of gases, that is oxygen (alveoli) and carbon dioxide (capillaries). So, the correct answer is 'Alveoli'.
Why the other options are wrong
- A. The larynx acts as a passageway for air between the pharynx and the trachea, and is primarily responsible for voice production. It does not facilitate gas exchange.
- B. The trachea is a rigid tube that carries air from the larynx down to the bronchi. Its main role is to provide a clear passage for air, not to exchange gases. The structure is reinforced with cartilage rings to keep it open during breathing.
- C. The bronchi are large air passages that lead air from the trachea into the lungs. While they branch into smaller bronchioles, they are not the site of gas exchange.
Q29. Encircle the miss-match:
- A. Colds-Rhinovirus
- B. Yellow fever-Bacteria✓
- C. Encephalitis-Virus
- D. Negative-strand RNA virus-Paramyxovirus
- E. Rabies-Dog bite
Explanation: Yellow fever is caused by a virus that is spread by the Aedes aegypti mosquito, not by a bacteria.
Why the other options are wrong
- A. Rhinovirus is the main culprit behind the common cold. The illness typically starts with symptoms like a runny nose, sore throat, and sneezing. It can lead to more severe conditions like bronchiolitis and pneumonia, especially in young children.
- C. Encephalitis refers to inflammation of the brain and is most commonly caused by viral infections. Other causes may include autoimmune responses and bacterial infections.
- D. The negative-strand RNA viruses include several important human pathogens, such as those causing measles and mumps, which are part of the Paramyxoviridae family.
- E. Rabies is a viral disease that can be transmitted through the bite or scratch of a rabid animal. Dogs are common carriers in many parts of the world, although in the United States, rabies is typically found in wild animals.
Q30. The light dependent reaction of photosynthesis occurs in:
- A. Stroma of chloroplast
- B. Guard cells of stomata
- C. Thylakoid membrane of chloroplast✓
- D. Cytoplasm of leaf cell
Explanation: The light-dependent reactions use light energy to make two molecules needed for the next stage of photosynthesis: the energy storage molecule ATP and the reduced electron carrier NADPH. In plants, the light reactions take place in the thylakoid membranes of organelles called chloroplasts.
Q31. Which of the following nutrients is incorrectly paired with its function in a plant?
- A. Potassium - Formation of the cell wall✓
- B. Magnesium - Constituent of chlorophyll
- C. Nitrogen - Constituent of protein
- D. Phosphorus - Component of nucleic acid
Explanation: The plant cell wall is made of Cellulose. Potassium creates the cell membrane potential, which allows the cell to generate an action potential. Magnesium in plants is located in the enzymes, in the heart of the chlorophyll molecule. A phosphate backbone is the portion of the DNA double helix that provides structural support to the molecule.
Why the other options are wrong
- B. This is correct. Magnesium is a central component of the chlorophyll molecule, essential for photosynthesis.
- C. This is correct. Nitrogen is a key component of amino acids, the building blocks of proteins.
- D. This is correct. Phosphorus is a crucial part of nucleic acids like DNA and RNA.
Q32. The diploid human chromosome set has:
- A. 22 pairs of autosomes and 1 pair of sex chromosomes✓
- B. 22 pairs of autosomes and XY chromosomes
- C. 22 pairs of autosomes and XX chromosomes
- D. Haploid somatic cells and diploid germinal cells
Explanation: Diploid set of human chromosomes have 22 pairs of autosomes and 1 pair of sex chromosomes. That is why A is correct. B is wrong because this is only specific for male. C is wrong because it is specific for females.
Why the other options are wrong
- B. This statement is partially correct since it describes the male karyotype but does not account for the female karyotype, which is XX. The phrase should indicate 1 pair of sex chromosomes to be universally accurate.
- C. This statement only describes the female karyotype and neglects the male karyotype, which is XY. The correct description should include 1 pair of sex chromosomes, accommodating both male and female configurations.
- D. This statement is incorrect in the context of the diploid chromosome set. Somatic cells are diploid, containing the full set of chromosomes, while germ cells are haploid, containing half the number of chromosomes.
Q33. An Rh-negative woman is married to an Rh-positive man whose father was also Rh-negative. What are the chances that their child will have Rh negative blood group?
- A. 25%
- B. 50%✓
- C. 75%
- D. 100%
Explanation: Given that the man’s father was Rh-negative and the man is Rh-positive, the man must be heterozygous for Rh-positive. A negative woman should be homozygous as a recessive allele only expresses itself in homozygous conditions. When a heterozygous dominant individual is crossed with a homozygous recessive individual, the offspring show the dominant and recessive phenotypes in a ratio of 1:1. Hence, there is a fifty percent chance of their child being “affected” with Rh negative phenotype.
Why the other options are wrong
- A. If the man were homozygous for Rh-positive, there would be no chance for an Rh-negative child. However, since he is heterozygous, this percentage is incorrect.
- C. This percentage would imply that both parents contribute a higher chance of an Rh-negative allele, which doesn't match the given genetic make-up.
- D. This would only be possible if both parents were homozygous Rh-negative, which is not the case here.
Q34. Which part of the brain regulates body temperature?
- A. Cerebellum
- B. Cerebrum
- C. Hypothalamus✓
- D. Medulla
Explanation: Much like a thermostat regulates the temperature inside your home, the hypothalamus regulates your body temperature, responding to internal and external stimuli and making adjustments to keep the body within one or two degrees of 98.6 degrees.
Why the other options are wrong
- A. The cerebellum is primarily responsible for coordinating voluntary movements and balance. It does not regulate body temperature.
- B. The cerebrum is the largest part of the brain, involved in higher brain functions like thought and action. It is not directly responsible for regulating body temperature.
- D. The medulla controls autonomic functions such as heart rate and breathing, but it does not regulate body temperature.
Q35. Atherosclerosis is disease of:
- A. Immune system
- B. Arterial wall✓
- C. Vein wall
- D. Lungs
Explanation: Atherosclerosis is the buildup of plaques (fats, cholesterol) in artery walls, restricting blood flow and risking clot formation.
Why the other options are wrong
- A. Atherosclerosis is related to the circulatory system, not the immune system.
- C. Atherosclerosis specifically affects arteries, not veins.
- D. Atherosclerosis affects blood vessels, not the lungs directly.
Q36. In an isotonic solution there would be:
- A. No net movement of water✓
- B. Net movement of water into the cell
- C. Net movement of water out of the cell
- D. Bursting of the cell
Explanation: In an isotonic solution there is a movement of water into and out of the cell but no net movement of water into or out of the cell as they contain the same concentration of water and solutes as the cell cytoplasm.
Why the other options are wrong
- B. This occurs when the external solution is hypotonic, meaning it has a lower concentration of solutes compared to the inside of the cell, causing water to move into the cell.
- C. This occurs in a hypertonic solution, where the external environment has a higher concentration of solutes than the inside of the cell, causing water to move out of the cell.
- D. Cell bursting, or lysis, typically occurs when a cell is placed in a hypotonic solution, leading to excessive water intake. In an isotonic solution, this does not happen.
Q37. The disease, which is caused by a defect in a single gene or pair of genes is referred to as:
- A. Unifactorial✓
- B. Multifactorial
- C. Down syndrome
- D. Turner syndrome
Explanation: The disease, which is caused by a defect in a single gene or pair of genes is referred to as a unifactorial gene.
Why the other options are wrong
- B. Multifactorial diseases involve multiple genes and often environmental factors. These are complex traits, and examples include heart disease and diabetes.
- C. Down syndrome is a chromosomal disorder caused by an extra copy of chromosome 21, not by a defect in a single gene.
- D. Turner syndrome is a chromosomal disorder caused by the complete or partial absence of one X chromosome, not by a defect in a single gene.
Q38. Fungi whose growth is favored by fire is called:
- A. Pyrophilus✓
- B. Prodophilus
- C. Pinophilus
- D. Prephylus
Explanation: Fungi whose growth is favoured by fire are called pyrophilous (fire-loving). The answer can be determined through the root words, even if a student doesn't recall the exact term. There are no fungi named Prephylus, Prophylus or Philus. You can see examples of pyrophilous fungi in the image provided.
Why the other options are wrong
- B. Prodophilus is a term associated with probiotics and is not related to fungi or fire. It refers to beneficial bacteria that support gut health.
- C. Pinophilus refers to a type of mushroom, specifically the pine bolete, which is unrelated to fire-adapted fungi.
- D. There is no known fungus or biological term called 'Prephylus' that is associated with fungi or fire.
Q39. Which of the following is not the type(s) of abiotic components?
- A. Climatic factors
- B. Edaphic factors
- C. Topographic factors
- D. Phytoplanktons✓
Explanation: Abiotic components are those that are non-living parts of the ecosystem. Phytoplanktons are living things hence are not abiotic components but biotic components of the ecosystem.
Why the other options are wrong
- A. Climatic factors such as temperature, humidity, and sunlight are non-living and influence the environment, making them abiotic components.
- B. Edaphic factors relate to soil properties like pH, texture, and mineral content, which are non-living and thus abiotic components.
- C. Topographic factors include landforms and elevation, which are non-living aspects affecting ecosystems, classifying them as abiotic components.
Q40. The disease night blindness is caused by deficiency of vitamin:
- A. Vitamin A✓
- B. Vitamin B
- C. Vitamin C
- D. Vitamin D
Explanation: Night blindness, or nyctalopia, is the inability to see in low light and is a symptom of an underlying eye condition, not a disease itself. It can be caused by conditions like cataracts, glaucoma, or retinal diseases, as well as genetic factors, injury, or nutritional deficiencies, such as a lack of Vitamin A.
Why the other options are wrong
- B. Vitamin B deficiencies can lead to various issues, such as anemia and neurological disorders, but they do not typically cause night blindness.
- C. Vitamin C is important for the immune system and skin health. A deficiency leads to scurvy, not night blindness.
- D. Vitamin D deficiency can lead to bone problems such as rickets and osteomalacia, not night blindness.
Q41. Heat evolved or absorbed in a chemical reaction does not depend upon?
- A. Amount of reactants
- B. Pressure of reaction✓
- C. Physical state of reactants and products
- D. Temperature
Explanation: The correct answer is Pressure of reaction. Enthalpy is a thermodynamic state function that represents the heat content of a system. Under constant pressure conditions, the change in enthalpy (ΔH) reflects the heat evolved or absorbed during a chemical reaction and is independent of the pressure at which the reaction occurs, as long as the initial and final states are the same. This is because enthalpy is determined by the internal energy, pressure, and volume of the system, which are all state properties.Amount of reactants: This affects the total enthalpy change because more reactants generally lead to a larger heat change. Thus, it does affect the heat evolved or absorbed.Physical state of reactants and products: Different physical states have different enthalpy values (e.g., the enthalpy of vaporization or fusion), so this factor also affects the heat change.Temperature: Changes in temperature can affect the enthalpy of a system, as it influences the energy levels and distribution of molecules, thereby affecting the heat evolved or absorbed.
Why the other options are wrong
- A. The amount of reactants affects the extent of the reaction and therefore the total heat evolved or absorbed. Enthalpy change is proportional to the amounts involved.
- C. The physical state (solid, liquid, gas) affects the enthalpy change due to different energy content in these states. Thus, it affects the heat evolved or absorbed.
- D. Temperature can influence the enthalpy change because it affects the energy levels of the molecules. Thus, it affects the heat evolved or absorbed.
Q42. For a reaction given below C(s) + O2 (g) -> CO2 (g) -394 kJ / molThe enthalpy of reaction is
- A. 394 kJ / mol
- B. -394 kJ / mol✓
- C. 197 kJ / mol
- D. -197 kJ / mol
Explanation: The formation of carbon dioxide from carbon and oxygen is an exothermic reaction, meaning it releases heat. The enthalpy change, denoted as ΔH, is negative for exothermic reactions. In this case, the reaction releases 394 kJ/mol of energy, so the correct enthalpy change is -394 kJ/mol. The negative sign is crucial as it indicates the direction of heat flow (from the system to the surroundings). Option B correctly reflects this with -394 kJ/mol. The other options are incorrect either due to the wrong sign or incorrect magnitude.
Why the other options are wrong
- A. This option is incorrect because the positive sign would indicate an endothermic reaction, but the reaction given is exothermic.
- C. This option is incorrect. Not only is the sign incorrect (indicating an endothermic reaction), but the magnitude is also incorrect. The reaction releases 394 kJ/mol.
- D. This option is incorrect. While the sign correctly indicates an exothermic reaction, the magnitude is incorrect. The reaction releases 394 kJ/mol, not 197 kJ/mol.
Q43. 1 mole of N2O4 (g) was placed in an empty 1 dm^3 container and allowed to reach equilibrium according to the following equation:N2O4(g) <-> 2NO2(g)At equilibrium, x mole Of N2O4 (g) had dissociated. What is the value of the equilibrium constant, Kc, at the temperature of the Experiment?
- A. 2x / (1 - x)
- B. 4x2 / (1 - x)2
- C. 2x / (1 - x)2
- D. 4x2 / (1 - x)✓
Explanation: This is the following solution:
Why the other options are wrong
- A. This expression incorrectly assumes a different relationship between the concentration changes of N2O4 and NO2. It does not account for the stoichiometry of the reaction.
- B. This expression mistakenly squares the denominator, which does not align with the stoichiometry of the equilibrium expression.
- C. This option incorrectly uses an exponent in the denominator, which does not properly reflect the stoichiometry of the reaction.
Q44. Which of the following ions will show maximum hydration?
- A. Al3+✓
- B. Na1+
- C. Mg2+
- D. Ca2+
Explanation: The greater the charge density, the greater the hydration enthalpy. All the atoms, given in the options, are in the same period, hence their valence shells would be the same. The same applies to electronic configurations since elements are in their ionic forms. However, the size of Al3+ would be the smallest, since it has more protons in its nucleus so, the nuclear attraction on the valence electrons increases, bringing the valence electrons, and thus the valence shell closer to the nucleus. Moreover, Al3+ has the highest charge, hence Al3+ would have the greatest charge density and hydration enthalpy The formula for calculating charge density = charge of the ion/size of the ion. Reference:
Why the other options are wrong
- B. Sodium ion has a smaller charge and larger size compared to Al3+, resulting in lower hydration enthalpy.
- C. Magnesium ion has a higher charge than sodium but lower than Al3+, affecting its hydration enthalpy.
- D. Calcium ion has a larger size than magnesium but lower charge density than Al3+, impacting its hydration enthalpy.
Q45. In which of the following chromium has different oxidation state?
- A. K2Cr2O7
- B. CrCl3✓
- C. CrO3
- D. K2CrO4
Explanation: i.Oxidation state in K2Cr2O7=2+2x+(-14)=0 =2x=12;x=6.ii.Oxidation state in CrCl3=x+(-3)=0 =x=3iii.Oxidation state in CrO3=x+(-6)=0 =x=6.There is no need to further find out the oxidation state of Cr in K2CrO4 because we already have a compound(CrCl3) having an odd oxidation state,so that is our answer.
Why the other options are wrong
- A. The oxidation state of Cr in K2Cr2O7 is +6. Each oxygen contributes -2, and potassium contributes +1, leading to the equation: 2(1) + 2x + 7(-2) = 0, which simplifies to x = 6.
- C. The oxidation state of Cr in CrO3 is +6. Each oxygen contributes -2, leading to the equation: x + 3(-2) = 0, which simplifies to x = 6.
- D. The oxidation state of Cr in K2CrO4 is +6. Each oxygen contributes -2, and potassium contributes +1, resulting in the equation: 2(1) + x + 4(-2) = 0, which simplifies to x = 6.
Q46. Which of the following catalysts is used in the decomposition of laughing gas N2O at 1000 K?2N2O <-> 2N2 + O2
- A. Glycine
- B. V2O5
- C. Fe
- D. Traces of Cl2✓
Explanation: Cl2 is used as a catalyst in decomposition of N2O4.
Why the other options are wrong
- A. Glycine is an amino acid and not typically used as a catalyst for the decomposition of gases.
- B. V2O5 is a catalyst used in the oxidation of SO2 to SO3, not in the decomposition of N2O.
- C. Iron (Fe) is commonly used in the Haber process for ammonia synthesis, not in the decomposition of N2O.
Q47. An element has configuration 2, 8, 1. It belongs to, _.
- A. IA group and 3rd period✓
- B. IIIA group and 1st period
- C. IA group and 8th period
- D. VIIA group and 3rd period
Explanation: Elements’ position in the periodic table can be determined by its electronic configuration. Period can be determined by counting the number of shells its electrons occupy. Since the element shown occupies three shells so we can say that it is in Period III. Group can be determined number of electrons in the last shell. Since the element has 1 electron in its last shell so the group number of this element is 1.Hence the answer is A.
Why the other options are wrong
- B. This configuration does not match the given electronic structure, which has three shells and cannot be in the 1st period or Group IIIA.
- C. The element only occupies three shells, so it cannot be in the 8th period despite being in Group IA.
- D. The configuration does not match Group VIIA, which requires seven electrons in the outermost shell, but it is correctly in the 3rd period.
Q48. Hydrogen resembles with alkali metals in all respects except:
- A. Half-filled valence shell✓
- B. Formation of unipositive ion
- C. Reducing nature
- D. Valence shell electronic configuration
Explanation: Alkali metals do not have half filled electrons in their last orbit,rather just 1 electron out of place of 8.Hydrogen has also has 1 electron in its last orbit but this does fill “half” of the last orbit as last orbit of hydrogen has capacity to hold 2 electrons in last orbit.Hence option A is correct.
Why the other options are wrong
- B. While alkali metals and hydrogen both have 1 electron in their last orbit, hydrogen's half-filled valence shell sets it apart from alkali metals, making this option incorrect.
- C. Hydrogen's resemblance to alkali metals does not extend to its reducing nature, as the key difference lies in the half-filled valence shell. Therefore, this option is incorrect.
- D. Although valence shell electronic configuration is an important aspect, the defining characteristic distinguishing hydrogen from alkali metals is the presence of a half-filled valence shell in hydrogen. This makes option D incorrect.
Q49. Which of the following is not the use of bleaching powder?
- A. Sterilization of drinking water
- B. Oxidation of alcohols✓
- C. Bleaching Linen
- D. Preparation of Chlorine
Explanation: Bleaching powder is used in the preparation of chlorine that is used in sterilization water. Bleaching powder is also used in the bleaching of linen. However it has no role in oxidation of alcohols hence B is our answer.
Why the other options are wrong
- A. Bleaching powder is commonly used to disinfect and sterilize drinking water due to its chlorine content.
- C. Bleaching powder is used in the textile industry for bleaching linen and cotton fabrics.
- D. Bleaching powder releases chlorine gas when it reacts with acids, which is useful in various applications including water treatment.
Q50. Aqua regia can dissolve noble metal due to the formation of:
- A. Nitrous acid
- B. Nitric oxide
- C. Nitrosyl chloride✓
- D. Nascent nitrogen
Explanation: Aqua regia is formed upon mixing of concentrated hydrochloric acid and concentrated nitric acid, chemical reactions occur. These reactions result in the volatile products nitrosyl chloride and chlorine gas:HNO3 (aq) + 3 HCl (aq) → NOCl (g) + Cl2 (g) + 2 H2O (l)NOCl formed is actually that which can dissolve these noble metals.
Why the other options are wrong
- A. Nitrous acid is not formed in the reactions between hydrochloric acid and nitric acid in aqua regia. The volatility and reactivity of nitrosyl chloride and chlorine are key to dissolving noble metals.
- B. Nitric oxide is not a product of the reaction that forms aqua regia. Instead, nitrosyl chloride is one of the main products responsible for dissolving noble metals.
- D. Nascent nitrogen is not involved in the dissolution of noble metals by aqua regia. The critical components are nitrosyl chloride and chlorine gas.
Q51. The chemical formula of chromyl chloride gas is?
- A. Cr2O3
- B. CrO2Cl2✓
- C. CrOCl2
- D. CrCl3
Explanation: Chromyl chloride is the inorganic compound with the formula CrO₂Cl₂.
Why the other options are wrong
- A. This is the formula for chromium(III) oxide, not chromyl chloride.
- C. This formula is incorrect for chromyl chloride. It does not account for the proper number of oxygen atoms.
- D. This is the formula for chromium(III) chloride, not chromyl chloride.
Q52. How many chain isomers are possible for the alkane C6H14?
- A. Six
- B. Five✓
- C. Four
- D. Nine
Explanation: Five isomers are possible for hexane with the formula of C6H14, as shown below.
Why the other options are wrong
- A. There are only 5 chain isomers possible for hexane, not 6. Thus, this option is incorrect.
- C. There are 5 chain isomers possible for hexane, not just 4. Therefore, this option is incorrect.
- D. Having 9 chain isomers is incorrect for hexane, as only 5 chain isomers can be formed.
Q53. Which of the following is the correct IUPAC name?
- A. 3 - ethyl - 4,4 - dimethylheptane
- B. 4,4 - dimethyl - 3 - ethylheptane
- C. 5 - ethyl - 4,4 - dimethylheptane
- D. 3,4 - dimethylheptane✓
Explanation: While naming a hydrocarbon, we take the longest carbon chain (heptane), then consider the additional groups (methyl), and finally number them from the one closest to the end of the main chain (3,4). Therefore, the IUPAC name is 3,4 - dimethylheptane.
Why the other options are wrong
- A. False. The substituents should be listed in alphabetical order, and this name incorrectly numbers the main chain.
- B. False. The substituents are not listed in alphabetical order, and the numbering does not give the lowest numbers to the substituents.
- C. False. The numbering does not provide the lowest possible numbers to the substituents.
Q54. The reaction between fat and NaOH called:
- A. Esterification
- B. Hydrogenolysis
- C. Hydrogenation
- D. Saponification✓
Explanation: Saponification is a process that involves the conversion of fat, oil, or lipid, into soap and alcohol by the action of heat in the presence of aqueous alkali (e.g. NaOH).
Why the other options are wrong
- A. Esterification is the process of forming an ester from an alcohol and an acid, not the process of soap formation from fats.
- B. Hydrogenolysis is the breaking of chemical bonds with the addition of hydrogen, not related to the formation of soap from fats.
- C. Hydrogenation refers to the addition of hydrogen to unsaturated bonds, typically in oils, to create saturated fats, not soap formation.
Q55. For a chemical reaction A + B, the threshold energy of the reaction is 31 KJ.mole. The average internal energy of A is 12 KJ/mole. What will be the activation energy of A?
- A. 43 KJ/mole
- B. 37 KJ/mole
- C. 25 KJ/mole
- D. 19 KJ/mole✓
Explanation: Threshold E = activation E + normal E of reactant 31 = A + 12 A = 31 - 12 = 19 kJ/mol
Why the other options are wrong
- A. 43 KJ/mole: This is incorrect. The activation energy cannot be greater than the threshold energy.
- B. 37 KJ/mole: This is incorrect. The activation energy cannot be greater than the average internal energy of A.
- C. 25 KJ/mole: This is incorrect. The activation energy is the difference between the threshold energy and the average internal energy of A. Therefore, the activation energy cannot be less than the average internal energy of A.
Q56. 1.8 x 10 -5 is the dissociation constant of:
- A. Formic acid
- B. Acetic acid✓
- C. Chloroacetic acid
- D. Hydrocyanic acid
Explanation: 1.8 x 10 -5 is the dissociation constant of Acetic acid.
Why the other options are wrong
- A. Formic acid has a dissociation constant higher than 1.8 x 10^-5, indicating it is a slightly stronger acid. Therefore, this option is incorrect.
- C. Chloroacetic acid is a stronger acid compared to acetic acid and has a higher dissociation constant. Therefore, this option is incorrect.
- D. Hydrocyanic acid is a very weak acid with a dissociation constant lower than 1.8 x 10^-5, making this option incorrect.
Q57. Electrical conductivity depends upon _.
- A. Temperature✓
- B. Degree of dilution
- C. Nature of electrolyte
- D. Speed of ions
Explanation: Electrical conductivity depends on temperature. The electrical conductivity of a metal decreases with increase in temperature because the thermal energy increases the collision of electrons and disturbs the free flow.
Why the other options are wrong
- B. Electrical conductivity is not significantly influenced by the degree of dilution, making this option incorrect.
- C. The nature of the electrolyte does not directly affect electrical conductivity in the context of this question, making this option incorrect.
- D. The speed of ions is not the primary factor determining electrical conductivity as compared to temperature, so this option is incorrect.
Q58. If 4.6 gm of ethyl alcohol and 6.0 gm of acetic acid is kept at a constant temperature until equilibrium was established, 2.0 gm of unused acetic acid were present. What is the Kc?
- A. 2.0
- B. 3.0
- C. 4.0✓
- D. 5.0
Explanation: Initially the moles of ethyl alcohol are:4.6/46=0.1 mol and acetic acid are:6/60=0.1 mol.In the end, we have 2gm of acetic acid that means 2/60=0.0333 mol of acetic acid is left or conversely speaking 0.0667 mol of acetic acid reacted to produce the same amount of ethyl acetate and water.So now Kc can be calculated as we now at the final stage of reaction we have 0.0333 mol of acetic acid and thus 0.0333 mol ethyl alcohol present as reactants, as molar ratio is same in the equation. We also know that since 0.0667 mol reacted so ethyl acetate is present in the same amount as water.Kc=[0.0667]2/[0.0333]2=4.0
Why the other options are wrong
- A. This value results from an incorrect calculation of equilibrium concentrations. Review the stoichiometry of the reaction.
- B. This option reflects an error in calculating the change in moles of reactants and products. Ensure all stoichiometric ratios are applied correctly.
- D. This option is incorrect because it assumes incorrect equilibrium concentrations. Re-evaluate the moles reacted and remaining at equilibrium.
Q59. Identify from the following the example in which the complex is an anion:
- A. [Co(en)3](NO3)3
- B. [Co(NH3)3(NO2)3]
- C. K3[Co(NO2)6]✓
- D. [Pt(NH3)2Cl4]
Explanation: Only option that has complex ion attached to cation is K3[Co(NO2)6], giving a definite evidence of it being anion. Hence it is the answer.
Why the other options are wrong
- A. This complex is positively charged because the coordination complex carries a positive charge balanced by three nitrate anions. Hence, it is a cationic complex.
- B. This complex is neutral as the charges from the ligands and the central metal atom cancel out, resulting in no net charge.
- D. This complex is neutral, as the charges on the platinum and the ligands cancel each other out, resulting in no net charge.
Q60. C12H22O11 + conc. H2SO4 → 12 C + ? + H2SO4
- A. 11 H2O✓
- B. 11 O2
- C. 11 CO2
- D. 11 H2
Explanation: Comparing reactant and product side we can see that there is a difference of 22 H and 11 O. That means the compound that we can make of it is 11 H2O. Hence the answer is A.
Why the other options are wrong
- B. This is incorrect. Oxygen in the form of O2 would imply a different reaction and doesn't account for the hydrogen atoms present in the sugar molecule.
- C. This is incorrect. Carbon from the sugar is converted to elemental carbon (C), not carbon dioxide (CO2), in this reaction.
- D. This is incorrect. The hydrogen is balanced in the form of water (H2O) and not as molecular hydrogen (H2).
Q61. Which one of the following is NOT an advantage of synthetic fiber?
- A. Lightness of weight
- B. Ease of ironing
- C. Softness
- D. Heat retention
- E. Absorbs the sweat✓
Explanation: Synthetic fibres can not absorb sweat.
Why the other options are wrong
- A. Synthetic fibers are often lightweight, making them convenient for various applications.
- B. Synthetic fibers generally require less ironing because they resist wrinkling.
- C. Many synthetic fibers are soft and comfortable to wear, mimicking natural fibers like cotton.
- D. Synthetic fibers can retain heat, which is beneficial in colder environments.
Q62. Ferritin deposits iron in spleen. It is an example of:
- A. Structural protein
- B. Respiratory protein
- C. Storage protein✓
- D. Contractile protein
Explanation: Ferritin are actually the stores of iron that are utilized when the serum iron depletes.
Why the other options are wrong
- A. This option is incorrect. Structural proteins are involved in providing support and shape to cells and tissues, not in storing substances.
- B. This option is incorrect. Respiratory proteins, like hemoglobin, are involved in the transport of gases, not storage of iron.
- D. This option is incorrect. Contractile proteins are involved in muscle contraction and movement, not in storing substances like iron.
Q63. Which of the following is NOT a “raw material” used in the Solvay process?
- A. Sodium Chloride
- B. Sodium Carbonate✓
- C. Limestone
- D. Ammonia gas
Explanation: Sodium carbonate is the product of the Solvay process so it can definitely not be the raw material required for this process.
Why the other options are wrong
- A. Sodium chloride (NaCl) is a key raw material in the Solvay process, used to provide chloride ions.
- C. Limestone (calcium carbonate, CaCO3) is a raw material in the Solvay process, providing carbonate ions.
- D. Ammonia gas (NH3) is used in the Solvay process to react with brine and form ammonium ions.
Q64. In SN1 reaction “1” stands for?
- A. Polar solvents
- B. Unimolecular✓
- C. Bimolecular
- D. Nucleophile
Explanation: The SN1 reaction is a substitution reaction in organic chemistry, the name of which refers to the Hughes-Ingold symbol of the mechanism. "SN" stands for "nucleophilic substitution", and the "1" says that the rate-determining step is unimolecular.
Why the other options are wrong
- A. Polar solvents can stabilize the carbocation intermediate in SN1 reactions, but the '1' in SN1 does not refer to the solvent type. It refers to the molecularity of the rate-determining step.
- C. In an SN2 reaction, the rate-determining step is bimolecular, involving two reacting species. However, this does not apply to SN1 reactions.
- D. While the 'SN' in SN1 stands for 'nucleophilic substitution', the '1' refers to the unimolecular nature of the rate-determining step, not the nucleophile itself.
Q65. The following reaction is an example of:
- A. Alkylation of benzene
- B. Acylation of benzene✓
- C. Oxidation of benzene
- D. Halogenation of benzene
- E. Both A and B
Explanation: Since the acyl group is added to the benzene as a result of this reaction process we can say that it is an acylation of benzene.
Why the other options are wrong
- A. This involves adding an alkyl group to benzene, not an acyl group.
- C. Oxidation would change the oxidation state of the benzene or its substituents, not add an acyl group.
- D. Halogenation involves adding a halogen, not an acyl group.
- E. Only the acylation of benzene is occurring, not alkylation.
Q66. 22.4 dm3 of volume of each H2 and O2 are sparked to produce water vapours (considered as ideal gas) on completion of reaction. What is the decrease in the volume of the vessel?
- A. 44 dm3
- B. 22.4 dm3
- C. 33.6 dm3
- D. 11.2 dm3✓
Explanation: In the reaction, 2 moles of H2 react with 1 mole of O2 to form water vapor. Initially, there are 44.8 dm3 of gas (22.4 dm3 of each gas). According to the stoichiometry, 22.4 dm3 of H2 reacts with only 11.2 dm3 of O2, forming 22.4 dm3 of water vapor. The remaining 11.2 dm3 of O2 adds to the water vapor for a total final volume of 33.6 dm3. The initial volume was 44.8 dm3, so the decrease in the volume is 44.8 - 33.6 = 11.2 dm3. The other options misunderstand either the stoichiometry or the ideal gas volume concept.
Why the other options are wrong
- A. This option is incorrect because it assumes the entire volume of gases remains unchanged, neglecting the formation of water.
- B. This is incorrect. It suggests that the reaction yields the same volume of gas as initially present, which is not the case.
- C. Incorrect. This assumes that the entire volume of hydrogen and oxygen is converted, without considering the stoichiometry of the reaction properly.
Q67. Which of the following is the chemical formula of a compound indicating the relative number of atoms in the simplest ratio?
- A. Empirical formula✓
- B. Empirical formula mass
- C. Molecular formula
- D. Molecular mass
Explanation: The empirical formula expresses the simplest, most reduced ratio of the different types of atoms in a chemical compound. It provides information about the relative numbers of each type of atom present, and the ratios are always in the smallest whole numbers.
Why the other options are wrong
- B. The empirical formula mass is the total mass of the atoms in an empirical formula, calculated by summing the atomic masses of each element in the smallest ratio. While it relates to the empirical formula, it does not describe the formula itself.
- C. The molecular formula specifies the exact number of each type of atom in a molecule. Unlike the empirical formula, which shows the simplest ratio, the molecular formula reflects the actual composition of the compound.
- D. The molecular mass is the mass of one molecule of a substance, calculated by summing the atomic masses of all atoms in the molecule. It differs from the empirical formula, as it pertains to the mass rather than the ratio of atoms.
Q68. Which of the following shows maximum penetration?
- A. Electrons
- B. Protons
- C. Alpha particles
- D. Beta-particles✓
Explanation: Beta particles penetrate farther than alpha particles and protons because they are lighter and less charged. Alpha particles are heavy and stopped quickly, while protons are massive but slow down faster. Electrons (in general atomic context) are less penetrating than beta radiation from radioactive decay.
Why the other options are wrong
- A. Electrons, with their relatively low mass and charge, have moderate penetration power but are less penetrating than neutrons due to interactions with matter.
- B. Protons, being charged particles, interact with electrons and nuclei in matter, limiting their penetration power compared to neutrons.
- C. Alpha particles have a large mass and positive charge, leading to significant interaction with matter and therefore very low penetration power.
Q69. Which pair has species with different shapes?
- A. BeCl2 and CO2
- B. NH3 and BF3✓
- C. SCl2 and H2O
- D. CH4 and NH4+
Explanation: The correct answer is option B: NH3 and BF3. According to VSEPR theory, NH3 has a trigonal pyramidal shape due to the lone pair on the nitrogen atom, while BF3 has a trigonal planar shape with no lone pairs on the boron atom, resulting in different geometries for these two molecules.Option A: BeCl2 and CO2 both have a linear shape due to their bonding arrangements with no lone pairs affecting the geometry.Option C: SCl2 and H2O both have a bent or angular shape due to the presence of lone pairs on the central atom, leading to similar geometries.Option D: CH4 and NH4+ both have a tetrahedral shape, as each central atom is bonded to four atoms with no lone pairs, resulting in identical geometries.
Why the other options are wrong
- A. In BeCl2 (beryllium chloride), the central atom (Be) is bonded to two chlorine atoms, resulting in a linear molecular geometry.In CO2 (carbon dioxide), the central atom (C) is bonded to two oxygen atoms, also leading to a linear molecular geometry. Both have the same shape.
- C. In SCl2 (sulfur dichloride), the central atom (S) is bonded to two chlorine atoms, resulting in a bent or angular shape due to lone pairs.In H2O (water), the central oxygen atom is bonded to two hydrogen atoms, also forming a bent or angular shape. Both have the same shape.
- D. In CH4 (methane), the central carbon atom is bonded to four hydrogen atoms, forming a tetrahedral shape.In NH4+ (ammonium ion), the central nitrogen atom is bonded to four hydrogen atoms, also forming a tetrahedral shape. Both have the same shape.
Q70. In HF the covalent bond is due to:
- A. S-S overlapping
- B. S-Pz overlapping✓
- C. S-Px overlapping
- D. Pz - Pz overlapping
Explanation: In formation of HF, 1s orbital of H overlaps with 2Pz orbital to F to form bond. Therefore bonding is due to S-Pz overlapping.
Why the other options are wrong
- A. This option suggests the overlap of two s orbitals, which is not applicable to the HF bond. HF involves an s orbital from hydrogen and a p orbital from fluorine.
- C. This option suggests overlap between an s orbital and a Px orbital, which is not the case in HF. The correct overlap involves the Pz orbital of fluorine.
- D. This option describes overlap between two Pz orbitals, which does not occur in HF. The bond involves an overlap between an s orbital from hydrogen and a Pz orbital from fluorine.
Q71. A 50 watt bulb is operated by 120 volts. What is the current through the bulb?
- A. 0.416 A✓
- B. 1.5 A
- C. 2.5 A
- D. 3.5 A
- E. 5.5 A
Explanation: P=IV(50)=(120)(I)50/120=II=0.416A
Why the other options are wrong
- B. This is incorrect. Using P = IV, solving for I gives I = 50 W / 120 V = 0.416 A, not 1.5 A.
- C. This is incorrect. Solving for current using I = P/V gives 0.416 A, not 2.5 A.
- D. This is incorrect. The correct calculation for I = 50 W / 120 V results in 0.416 A, not 3.5 A.
- E. This is incorrect. The calculation using I = P/V results in 0.416 A, not 5.5 A.
Q72. A battery of 6 volts is connected to two resistors of 3 ohm and 2 ohm joined together in series. What will be the current through the circuit?
- A. 6.2 A
- B. 5.2 A
- C. 4.2 A
- D. 2.2 A
- E. 1.2 A✓
Explanation: Resistance of resistors placed in series is calculated by adding the resistance,3+2=5 ohms.Formula connecting voltage,resistance and current is V=IR.V=IR(6)=(5)(I)6/5=I=1.2 Ohms.
Why the other options are wrong
- A. This option is incorrect. The total resistance is not low enough to allow such a high current with a 6V battery.
- B. This option is incorrect. The resistance calculation and application of Ohm's Law do not support this current value.
- C. This option is incorrect. The total resistance in the circuit is greater, which would result in a lower current than suggested here.
- D. This option is incorrect. The calculated resistance and voltage do not allow for this high of a current.
Q73. There is a current of 25 A in a long straight wire. What is the flux density at a point 3 cm from the wire?
- A. 1.67 x 10-4 T✓
- B. 3.67 x 10-4 T
- C. 5.67 x 10-4 T
- D. 7.67 x 10-4 T
- E. 9.67 x 10-4 T
Explanation: Given, a=3cm=9×10−2m, I=25AB=μoI/2πa=4π×10−7×25/2π×3×10−2=1.67 x 10-4 T
Why the other options are wrong
- B. This option results from incorrectly calculating the flux density. Double-check the values used in the formula.
- C. This option is incorrect. Verify if you used the correct distance and constants in the formula.
- D. This calculation is incorrect. Ensure that you are using the correct units for distance in the formula.
- E. This option is incorrect. Recheck the formula and values to ensure accurate calculations.
Q74. A circuit in which there is a current of 5 amp is changed so that the current falls to zero in 0.1 s. If an average e.m.f of 200 volts is induced, what is the self inductance of the circuit?
- A. 1 Henry
- B. 2 Henry
- C. 3 Henry
- D. 4 Henry✓
- E. 6 Henry
Explanation: Initial current, I1=5.0AFinal current, I2=0AChange in current, dl=I1−I2=5ATime taken for the charge, t=0.1sAverage emf, e=200VFor self inductance(L) of the coil, we have the relation for average emf as:e=L x rate of change of currentL=e/rate of change of currentL=200/ 5/0.1L=4HHence the self inductance of the coil is 4H.
Why the other options are wrong
- A. This is incorrect. The calculation does not match the given average e.m.f and rate of current change.
- B. This is incorrect. The calculation does not match the given average e.m.f and rate of current change.
- C. This is incorrect. The calculation does not match the given average e.m.f and rate of current change.
- E. This is incorrect. The calculation does not match the given average e.m.f and rate of current change.
Q75. What will be the energy of an X-ray quantum of wave length 1.0 x 10-10 m?
- A. 0.6 x 10^-15 J
- B. 1.98 x 10^-15 J✓
- C. 3.7 x 10^-15 J
- D. 4.7 x 10^-15 J
- E. 7.7 x 10^-15 J
Explanation: So, the energy of x rays is 1.98 x 10 -15 J. Hence, this is the required solution.
Why the other options are wrong
- A. This option is incorrect because it does not correctly calculate the energy using the given wavelength.
- C. This option is incorrect because it does not correctly calculate the energy using the given wavelength.
- D. This option is incorrect because it does not correctly calculate the energy using the given wavelength.
- E. This option is incorrect because it does not correctly calculate the energy using the given wavelength.
Q76. A neutron travels a distance of 24 m in a time interval of 3.6 x 10-4 s. Assuming its speed was constant, find its kinetic energy. Take 1.7 x 10-27 kg as the mass of the neutron:
- A. 37.2 x 10-19 joule✓
- B. 27.702 x 10-19 joule
- C. 17.70 x 10-19 joule
- D. 7.702 x 10-29 joule
Explanation: The following is the solution:speed of neutron = distance travelled by neutron / time taken by neutron for covered that distance .speed of neutron = 24/3.6 × 10‐4 m/sspeed of neutron ( V)= 6.6 × 10⁴ m/sno ,kinetic energy = 1/2mv²K.E = 1/2 × 1.7 × 10-27 ×( 6.6 × 10⁴)² J= 1/2 × 1.7 × (6.6)² × 10-19 j=37.2 × 10-19 jso,K.E = 37.2 × 10-19.Hence the correct answer is A which is closest to the correct answer
Why the other options are wrong
- B. This value is incorrect. It arises from a miscalculation of speed or energy.
- C. This value does not account for the correct speed of the neutron, leading to an incorrect kinetic energy result.
- D. This is incorrect due to a significant error in calculations, resulting in an order of magnitude mistake.
Q77. A 60 kg boy runs up a hill through a height of 6 m in 3 seconds. How much work does he do against gravitational force?
- A. 3000 J
- B. 2528 J
- C. 3500 J
- D. 3528 J✓
Explanation: W=mgh=(60)(6)(9.8)=3528J
Why the other options are wrong
- A. This option mistakenly uses an incorrect value for gravity or miscalculates the product.
- B. This option results from a calculation error, either in mass, height, or gravity.
- C. This answer is slightly off due to rounding errors in calculation.
Q78. The nature of the force of gravitation in the universe is:
- A. Repulsive only
- B. Attractive only✓
- C. Electric
- D. Magnetic
- E. Both attractive and repulsive
Explanation: Both in the Newton theory of gravitation and in the General Theory of Relativity the gravitational force is an exclusively attractive one.
Why the other options are wrong
- A. Repulsive → In classical physics, the gravitational force is never repulsive; it always attracts.
- C. Electric → Gravitation is a distinct force that operates due to mass, not electric charge.
- D. Magnetic → Gravitation does not involve magnetic interactions; it is a separate fundamental force.
- E. Gravitational force is only attractive. There is no known repulsive component in classical gravitational physics.
Q79. The third law of motion given by Newton deals with an action- reaction pair of forces.Consider two bodies: if the action is due to one body, the reaction will be due to:
- A. The other body✓
- B. The same body
- C. Both the bodies
- D. Atmosphere
Explanation: Newton's third law: If an object A exerts a force on object B, then object B must exert a force of equal magnitude and opposite direction back on object A.
Why the other options are wrong
- B. This is incorrect because the reaction force is not exerted by the same body that applies the action force. The forces act on two different bodies.
- C. While both bodies are involved, the reaction force specifically acts on the other body, not both simultaneously as an action-reaction pair.
- D. This is incorrect because the atmosphere is not involved in the action-reaction pair of forces unless specified in a particular scenario. Newton's third law deals with interactions between two specific bodies.
Q80. Beta particles are the particles emitted from the _ of an atom.
- A. Inner atomic shells
- B. Outer atomic shells
- C. Innermost atomic shell
- D. Nucleus✓
Explanation: The beta particle, which may be either negatively charged (negatrons) or positively charged (positrons), originates from the nucleus of an atom. A beta particle is emitted from the nucleus of an atom during radioactive decay. The electron, however, occupies regions outside the nucleus of an atom.
Why the other options are wrong
- A. Inner atomic shells: Incorrect. These contain electrons, which are not emitted as beta particles. Beta particles originate from nuclear processes.
- B. Outer atomic shells: Incorrect. Electrons in these shells are not related to beta decay. Beta particles emerge from the nucleus.
- C. Innermost atomic shell: Incorrect. This refers to the K-shell electrons, not the nucleus where beta particles originate.
Q81. Magnetic force on a moving charge depends upon:
- A. Magnetic field and charge only
- B. Magnetic field and speed of the charge only
- C. Charge and speed of the charge only
- D. Magnetic field, charge, and speed of the charge✓
Explanation: The magnitude of the magnetic force between them depends on how much charge is in how much velocity in each of the two objects and magnetic field.
Why the other options are wrong
- A. While these factors are important, the speed of the charge is also crucial in determining the magnetic force. A stationary charge will not be affected by a magnetic field.
- B. The charge of the particle is also essential. A neutral particle, regardless of its speed, will not experience a magnetic force.
- C. Without a magnetic field, even a moving charge will not experience any force. All three factors are necessary.
Q82. Name the pulmonary disease in which alveolar surface area involved in gas exchange is drastically reduced due to damage in the alveolar walls.
- A. Pneumonia
- B. Asthma
- C. Pleurisy
- D. Emphysema✓
Explanation: Note:The correct option is d) Emphysema.Explanation of each option:a)Pneumonia: Pneumonia is an inflammatory lung condition primarily caused by infection, not by damage to the alveolar walls. It typically results in the air sacs (alveoli) filling with fluid or pus due to infection, rather than damage to alveolar walls.b)cAsthma: Asthma is a chronic respiratory condition characterized by airway inflammation, bronchoconstriction, and excess mucus production. It does not primarily involve damage to the alveolar walls but rather affects the airways.c)Pleurisy: Pleurisy, or pleuritis, is inflammation of the pleura, the lining around the lungs. It does not directly involve damage to the alveolar walls or impact the alveolar surface area responsible for gas exchange.d)Emphysema: This is the correct answer. Emphysema is a pulmonary disease characterized by the gradual destruction of the alveolar walls. This damage reduces the surface area available for gas exchange, leading to impaired lung function, shortness of breath, and other respiratory symptoms. Smoking is a common cause of emphysema. The destruction of the alveolar walls leads to the enlargement of the air sacs and loss of elasticity in the lungs. As a result, the surface area available for gas exchange is drastically reduced, impairing the lung's ability to efficiently transfer oxygen to the bloodstream and remove carbon dioxide. Summary: The correct answer is "Emphysema." Emphysema is a pulmonary disease characterized by damage to the alveolar walls, which drastically reduces the alveolar surface area involved in gas exchange. The other options, pneumonia, asthma, and pleurisy, do not primarily involve damage to the alveolar walls and are distinct conditions with different characteristics.
Why the other options are wrong
- A. Pneumonia is an inflammatory lung condition primarily caused by infection, not by damage to the alveolar walls. It typically results in the air sacs (alveoli) filling with fluid or pus due to infection, rather than damage to alveolar walls.
- B. Asthma: Asthma is a chronic respiratory condition characterized by airway inflammation, bronchoconstriction, and excess mucus production. It does not primarily involve damage to the alveolar walls but rather affects the airways.
- C. Pleurisy: Pleurisy, or pleuritis, is inflammation of the pleura, the lining around the lungs. It does not directly involve damage to the alveolar walls or impact the alveolar surface area responsible for gas exchange.
Q83. If modulated signal frequency is represented by fm, carrier frequency by fc, fmin and fmax represent minimum and maximum values respectively, then the lower sideband refers to the range:
- A. fc - fmax to fc - fmin✓
- B. fc + fmin to fc + fmax
- C. fc - fm
- D. fm - fc
Explanation: Lower sidebands (LSB) range from fc-fmax to fc-fmin.
Why the other options are wrong
- B. This range refers to the upper sideband, which is formed by adding modulating frequencies to the carrier frequency.
- C. This represents a single frequency point rather than a range, and is not sufficient to describe the lower sideband.
- D. This expression is incorrect because it implies a negative frequency range, which is not applicable in this context.
Q84. How many types of modulations are possible with sinusoidal carrier?
- A. Only one
- B. Two
- C. Three✓
- D. Four
Explanation: The carrier signal is a sine wave at the carrier frequency. The sine wave has three characteristics that can be altered. The term that may be varied is the carrier voltage Ec, the carrier frequency FC, and the carrier phase angle θ. So three forms of modulations are possible.
Why the other options are wrong
- A. This is incorrect. Modulation can involve altering amplitude, frequency, or phase, not just one aspect.
- B. This is incorrect. While it's possible to use just two types of modulation, the standard practice involves three types: amplitude, frequency, and phase modulation.
- D. This is incorrect. There are three main types of analog modulation: amplitude, frequency, and phase. A fourth type is not standard for sinusoidal carriers.
Q85. The range of wavelengths for visible light is between _.
- A. 4.6 x 107 to 7.8 x 10 -7 m
- B. 4.0 x 10 -7 to 7.6 x 10 -7 m✓
- C. 4.0 x 10 -6 to 7.6 x 10 -6 m
- D. 4.0 x 10 -8 to 7.6 x 10 -8 m
Explanation: The range of visible light is from 400nm to 760nm. Conversion of 400nm to meters will be 400x10-9=4x10-7. Conversion of 760 nm to meters will be 760x10-9=7.6x10-7.Hence the answer is B.
Why the other options are wrong
- A. The range of visible light is from 400nm to 760nm. Conversion of 400nm to meters will be 400x10-9=4x10-7. Conversion of 760 nm to meters will be 760x10-9=7.6x10-7.
- C. The range of visible light is from 400nm to 760nm. Conversion of 400nm to meters will be 400x10-9=4x10-7. Conversion of 760 nm to meters will be 760x10-9=7.6x10-7.
- D. The range of visible light is from 400nm to 760nm. Conversion of 400nm to meters will be 400x10-9=4x10-7. Conversion of 760 nm to meters will be 760x10-9=7.6x10-7.
Q86. In an astronomical telescope, the lens called eyepiece forms an image of a distant object that is:
- A. Real and diminished
- B. Real and magnified
- C. Virtual and diminished
- D. Virtual and magnified✓
Explanation: An astronomical telescope is an optical instrument which is used to see the magnified image of distant heavenly bodies. The final image formed by an astronomical telescope is always virtual, inverted and magnified.
Why the other options are wrong
- A. The eyepiece of an astronomical telescope does not form a real image. Its purpose is to magnify the image formed by the objective lens, and the final image is virtual.
- B. While the image formed by the objective lens is real, the eyepiece forms a virtual image of this real image. The final image seen through the telescope is virtual and magnified.
- C. The eyepiece does form a virtual image, but it is not diminished. The purpose of the telescope is to magnify the image, making it appear larger.
Q87. If the volume of a gas is fixed then on increasing its temperature, its pressure_
- A. Gets negligible
- B. Gets constant
- C. Rises✓
- D. Falls
Explanation: Gay-Lussac's Law. This law states that the pressure of a given amount of gas held at constant volume is directly proportional to the Kelvin temperature. With an increase in temperature, the pressure will go up.If the volume of a gas is fixed (constant volume), the relationship between pressure P, temperature T and the other gas properties is described by the ideal gas law:PV=nRTFrom this equation, we can derive that, for a fixed volume:P∝TThis means that pressure is directly proportional to temperature when volume is constant. Therefore, if the temperature is increased, the pressure also increase.
Why the other options are wrong
- A. If the volume of a gas is fixed (constant volume), the relationship between pressure P, temperature T and the other gas properties is described by the ideal gas law:PV=nRTFrom this equation, we can derive that, for a fixed volume:P∝TThis means that pressure is directly proportional to temperature when volume is constant. Therefore, if the temperature is increased, the pressure also increase.
- B. If the volume of a gas is fixed (constant volume), the relationship between pressure P, temperature T and the other gas properties is described by the ideal gas law:PV=nRTFrom this equation, we can derive that, for a fixed volume:P∝TThis means that pressure is directly proportional to temperature when volume is constant. Therefore, if the temperature is increased, the pressure also increase.
- D. If the volume of a gas is fixed (constant volume), the relationship between pressure P, temperature T and the other gas properties is described by the ideal gas law:PV=nRTFrom this equation, we can derive that, for a fixed volume:P∝TThis means that pressure is directly proportional to temperature when volume is constant. Therefore, if the temperature is increased, the pressure also increase.
Q88. Which of the following is not a base unit in the SI system?
- A. Ampere
- B. Second
- C. Meter per second✓
- D. Candela
Explanation: In summary, the correct answer is option c) Meter per second, as it is not a base unit in the SI system. The other options (a, b, and d) represent base units: ampere for electric current, second for time, and candela for luminous intensity.
Why the other options are wrong
- A. The ampere (symbol: A) is the SI base unit for measuring electric current. It is a fundamental unit in the SI system, establishing the magnitude of an electrical flow.
- B. The second (symbol: s) serves as the SI base unit of time. Defined by atomic properties, it is a cornerstone in the precise measurement of time intervals.
- D. The candela (symbol: cd) is the SI base unit of luminous intensity, quantifying the power emitted by a light source in a specific direction. It is pivotal in light measurement.
Q89. The force which will accelerate a 25 kg mass at 98 cm/s2 on a smooth horizontal plane is:
- A. 200 Newton
- B. 1950 Newton
- C. 19.6 Newton
- D. 24.5 Newton✓
- E. 1960 Newton
Explanation: F=maF=(25 kg)(98/100 m/s2)F=24.5 N
Why the other options are wrong
- A. This is an incorrect calculation of the force. Remember to convert the acceleration from cm/s2 to m/s2.
- B. This is an incorrect calculation. Ensure you are using the correct units and formula to find the force.
- C. This option miscalculates the force by not properly converting the acceleration to meters per second squared.
- E. This is an incorrect calculation, possibly due to a misunderstanding of unit conversion or arithmetic error.
Q90. When photons are incident on a metal, electrons are emitted. The process is called:
- A. Photoelectric effect✓
- B. Pair production
- C. X-ray production
- D. Gamma ray production
- E. Radioactive capture
Explanation: Photoelectric effect, a phenomenon in which electrically charged particles are released from or within a material when it absorbs electromagnetic radiation. The effect is often defined as the ejection of electrons from a metal plate when light falls on it.
Why the other options are wrong
- B. Pair production involves a photon interacting with a nucleus or an electron to create an electron-positron pair. This requires a photon energy of at least 1.02 MeV and is not related to the emission of electrons due to photon interaction with a metal surface.
- C. X-ray production typically occurs when high-energy electrons strike a material and generate X-rays. Although X-rays can cause electrons to be emitted from a material, the process of generating X-rays is distinct from the photoelectric effect.
- D. Gamma ray production involves the emission of high-energy photons from nuclear processes. While gamma rays can interact with materials to cause electron emissions, this process is not the same as the photoelectric effect.
- E. Radioactive capture, or radiative capture, is a process where a nucleus captures a particle, often leading to nuclear reactions. It does not describe the emission of electrons from a metal due to incident photons.
Q91. Which of the following types of force can do no work on the body on which it operates?
- A. Centripetal force✓
- B. Frictional force
- C. Gravitational force
- D. Shearing force
- E. Elastic force
Explanation: For circular motion, the centripetal force always acts at right angles to the motion. Thus, it changes the direction of the motion, but it does zero work on the object. The rest of the forces mentioned in other options directly work on the object.
Why the other options are wrong
- B. Frictional force opposes motion and can do work by converting kinetic energy into thermal energy, causing displacement in the opposite direction.
- C. Gravitational force can do work when it causes an object to move in the direction of the force, such as an object falling under gravity.
- D. Shearing force can do work by causing deformation or displacement parallel to the force.
- E. Elastic force does work when it stretches or compresses an object, storing energy in the form of potential energy.
Q92. The frequency of a man's voice is 300 Hz. If velocity of sound is 336 m/s, the wavelength of the sound is:
- A. 1.12 m✓
- B. 300 m
- C. 330 m
- D. 112 m
- E. 11201 m
Explanation: We are given thatfrequency=300Hz, and velocity v=336ms−1From the relation v=f×λ,λ=v/f=336/300=1.12mOption "A" is correct.
Why the other options are wrong
- B. This option is incorrect. This value seems to incorrectly consider the velocity of sound as the wavelength without using the formula λ = v/f.
- C. This option is incorrect. It may have been calculated by mistakenly using the frequency as the wavelength instead of applying the correct formula.
- D. This option is incorrect, possibly due to a miscalculation or misplacement of the decimal point when using the formula λ = v/f.
- E. This option is incorrect and is likely an error due to a significant miscalculation or misplacement of the decimal point.
Q93. A camera of 6 cm focal length is used to photograph a distant scene. The distance from the lens to the image is approximately:
- A. 6 cm✓
- B. 1 m
- C. 80 cm
- D. 4 m
- E. 3 cm
Explanation: The distance from the lens to the image is of 6 cm as focal length is used to photograph at distance.
Why the other options are wrong
- B. If the focal length were 1 m, the lens would have to be significantly larger, which is not the case here. The focal length given is 6 cm, so the image forms at 6 cm for distant objects.
- C. 80 cm is much larger than the given focal length of the lens. The image forms at the focal length, which is 6 cm for distant scenes.
- D. A 4 m distance is unrealistic for a small focal length of 6 cm. The image forms at the focal length, 6 cm, when photographing a distant scene.
- E. 3 cm is half the focal length of the lens. For distant objects, the image forms at the focal length, which is 6 cm.
Q94. A bomb is dropped from an airplane moving horizontally with a speed of 200 km/h. If the air resistance is negligible, the bomb will reach the ground in 5 s, the altitude of the plane approximately is: (g = 9.8 m/s2)
- A. 50 m
- B. 75 m
- C. 122.5 m✓
- D. 250 m
- E. 300 m
Explanation: Data:u = t = 5 sec v = 200km/hr Solution: h = ut + 1/2gt2h = 1/2 x 9.8(5)2h = 1/2 * 245= 122.5Hence, option C is correct. The correct approach involves utilizing the equation of motion for free fall to calculate the vertical distance accurately. Option A underestimates, Option B does not consider the full effect of gravity, Option D overestimates, and Option E significantly overestimates the altitude due to misinterpretation of time and acceleration relationships.
Why the other options are wrong
- A. This option underestimates the altitude. Review the formula for vertical motion and consider the time given.
- B. This option does not account for the complete effect of gravity over the 5 seconds of free fall.
- D. This option overestimates the altitude by not properly applying the equation for vertical motion.
- E. This option significantly overestimates the altitude, suggesting a misunderstanding of the time and acceleration relationship.
Q95. An object whose mass is 100 g starts from rest and moves with constant acceleration of 20 cm/s2. At the end of 8s its momentum in g cm / s is:
- A. 500
- B. 8000
- C. 16,000✓
- D. 33,000
- E. 64,000
Explanation: Step 1:force = mass * accelerationforce = 100 * 20force = 2000 g cm / s2Step 2:change in momentum = force * timechange in momentum = 2000 * 8change in momentum = 16000 g cm/s
Why the other options are wrong
- A. This option is incorrect. It does not match the calculated change in momentum based on the given data.
- B. This option is incorrect. It is half of the correct value and does not account for the full time duration.
- D. This option is incorrect. It is much higher than the correct calculated value.
- E. This option is incorrect. It is four times the correct answer, indicating a miscalculation in the process.
Q96. Physics is an experimental science which depends heavily on:
- A. The objective observations
- B. Measurement of natural phenomena
- C. Study of chemical solutions only
- D. Both A and B✓
Explanation: Physics depends on objective observations and measurement of natural phenomena.Not on studying chemical solutions,which is actually chemistry.
Why the other options are wrong
- A. Objective observations are essential in physics as they provide the basis for forming hypotheses and theories. However, without quantitative measurements, these observations alone are not sufficient to fully comprehend physical phenomena.
- B. Measurement is a crucial component of physics, allowing scientists to quantify observations, test hypotheses, and validate theoretical models. However, it must be combined with objective observations to be fully effective.
- C. This option is incorrect as it pertains more to chemistry than to physics. Physics covers a wide array of topics beyond chemical solutions, such as mechanics, electromagnetism, and quantum physics.
Q97. If the unit vectors i, j, k are perpendicular to each other therefore;i.i = j.j = k.k = _.I.j = j.k = k.i = _.
- A. 0 … 1
- B. 1 … 0✓
- C. 0 … 0
- D. 1 … 1
Explanation: The dot product of two vectors A and B is given by A.B = |A||B| cosθ. If the angle θ between the vectors is 0°, cosθ = 1, so a vector dotted with itself (i.i, j.j, k.k) is 1, due to the unit magnitude of the vectors. If θ is 90°, cosθ = 0, so the dot product of two perpendicular vectors (i.j, j.k, k.i) is 0. Therefore, the correct answer is 1 for i.i = j.j = k.k, and 0 for i.j = j.k = k.i. The other options are incorrect as they do not accurately reflect these properties of the dot product for unit vectors.
Why the other options are wrong
- A. This option is incorrect because the dot product of a unit vector with itself is always 1, not 0.
- C. This option is incorrect because the dot product of a unit vector with itself is not 0; it is 1.
- D. This option is incorrect because the dot product of two different perpendicular unit vectors is 0, not 1.
Q98. Whenever the average and instantaneous velocities are equal the body is said to have a:
- A. Simple velocity
- B. Uniform velocity✓
- C. Directional velocity
- D. Centripetal velocity
Explanation: Instantaneous velocity can be equal to average velocity when the acceleration is zero or velocity is constant because in this condition all the instantaneous velocities will be equal to each other and also equal to the average velocity. Or distance -time graph will be a straight line whose slope (velocity) is the same at every point .
Why the other options are wrong
- A. Simple velocity is not a standard term in physics and does not describe any condition regarding average or instantaneous velocity.
- C. Directional velocity is not a standard term; velocity inherently includes directional information but does not imply equality of average and instantaneous velocities.
- D. Centripetal velocity refers to velocity in circular motion and does not imply equality between average and instantaneous velocities.
Q99. A ball is thrown vertically upward with a velocity of 98 m/s. How long does it take to reach its highest point?
- A. 2 seconds
- B. 5 seconds
- C. 7 seconds
- D. 10 seconds✓
- E. 15 seconds
Explanation: Given :u = 98 m/sg = -9.8 m/s². ( As it is thrown upwards)v = 0 (As it will stop after reaching the highest point)Using2gs = v² - u²2 × -9.8 × s = - (98 × 98)s = (98 × 98)/(2 × 9.8)s = 98 × 5s = 490 m.Now, Usingv = u + at0 = 98 - 9.8 × tt = 10 s
Why the other options are wrong
- A. This is incorrect. The time is too short given the initial velocity.
- B. This is incorrect. The time needed is longer due to the high initial velocity.
- C. This is incorrect. The calculation shows that the time should be longer.
- E. This is incorrect. The time is too long based on the given initial velocity and acceleration.
Q100. A/An _ is that in which the momentum of the system as well as the kinetic energy of the system before and after the collision is conserved i.e. remains the same.
- A. Elastic collision✓
- B. Inelastic collision
- C. Conserved collision
- D. Direct collision
Explanation: An elastic collision is one where both momentum and kinetic energy of the system are conserved, meaning they remain the same before and after the collision. Inelastic collisions conserve momentum but lose some kinetic energy to other forms of energy. The term conserved collision lacks specificity and does not indicate which quantities are conserved. Direct collisions describe the nature of the impact rather than conservation laws.
Why the other options are wrong
- B. In an inelastic collision, momentum is conserved, but some kinetic energy is transformed into other forms of energy, such as thermal energy or sound, resulting in a net loss of kinetic energy in the system after the collision.
- C. The term conserved collision is not an accurate scientific term as it suggests conservation without specifying which quantities are conserved. It is essential to distinguish whether both momentum and kinetic energy are conserved, which is the hallmark of an elastic collision.
- D. A direct collision refers to the orientation of the impact, specifically a head-on collision. This term does not imply any specific conservation laws regarding momentum or kinetic energy and thus is not suitable for describing the type of collision based on energy conservation.
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