Home/Past Papers/Sindh / DUHS/Sindh Mcat Nts 2017
Sindh Mcat Nts 2017 — Solved Past Paper with Answers
All 100 MCQs from Sindh Mcat Nts 2017, solved with the correct answer highlighted and a full explanation for every question. This is a free MDCAT Sindh / DUHS past paper — no signup, no ads. Practise it interactively in timed mode, drill more with free MDCAT MCQs, or browse all Sindh / DUHS papers.
Attempt this paper interactively →Q1. Choose the lettered word or phrase that is most nearly opposite in meaning to the word in capital letters. MANDATORY:
- A. Dispassionate
- B. Obligatory
- C. Voluntary✓
- D. Confirmed
Explanation: Mandatory means something that is compulsory/obligatory to do. The opposite of which will be voluntary, which implies an element of intent in doing work.
Why the other options are wrong
- A. Option A is incorrect as dispassionate means not to be influenced by emotions and feelings, to be emotionless towards something. It is not opposite in meaning to Mandatory.
- B. Option B is incorrect as obligatory means something that is compulsory to do, which is similar in meaning to Mandatory..
- D. Confirmed means something that is for sure , established, firm , through and through and committed.
Q2. Choose the lettered word or phrase that is most nearly opposite in meaning to the word in capital letters. HONESTY:
- A. Clever
- B. Dishonesty✓
- C. Resolution
- D. Failure
Explanation: Dishonesty is the word opposite in meaning to Honesty as it means to show deceitfulness in one's behavior.
Why the other options are wrong
- A. Option A is wrong as clever means having or showing the ability to learn and understand things quickly and easily. Hence, it is not opposite in meaning to Honesty.
- C. Option C is wrong as resolution means a firm decision regarding doing something or not. It is not related to Honesty.
- D. Option D is wrong as failure means inability to succeed in something.
Q3. Read the passage to answer question:Due to the extremely hot weather, the electric company is planning to turn off power in certain districts during the day. This will reduce the total demand for electricity and prevent a city-wide shutdown of electrical services. Power will not be out longer than two hours in your area. For further information, please visit our Web site at www.electricity.com. All areas affected by the shutdown are listed there, as well as the times that the power will be turned off in each area.Why is the power being turned off?
- A. To reduce total demand✓
- B. To save money
- C. To make it cooler
- D. To make the city pay its bill
Explanation: As it says in line 2 that “ to reduce the demand”. "Power is being shut down” so it will be safe to say that Option A is correct and makes sense even without the passage.
Why the other options are wrong
- B. To save money is the incorrect option as none of the statements given in these options are the reasons due to which power is being shut down. Passage clearly mentions the reason for shutting the power down.
- C. To make it cooler is the incorrect option as none of the statements given in these options are the reasons due to which power is being shut down. Passage clearly mentions the reason for shutting the power down.
- D. To make the city pay its bill is the incorrect option as none of the statements given in these options are the reasons due to which power is being shut down. Passage clearly mentions the reason for shutting the power down.
Q4. Read the passage and answer the following question:Due to the extremely hot weather, the electric company is planning to turn off power in certain districts during the day. This will reduce the total demand for electricity and prevent a city-wide shutdown of electrical services. Power will not be out longer than two hours in your area. For further information, please visit our Web site at www.electricity.com. All areas affected by the shutdown are listed there, as well as the times that the power will be turned off in each area.How long will power be off?
- A. Longer than two hours
- B. Less than two hours✓
- C. For one day
- D. Until the weather changes
Explanation: Line 4 of the passage clearly mentions that power will not be shut for more than two hours.
Why the other options are wrong
- A. Option A is incorrect as it mentions power will be shut for more than 2 hours which is incorrect according to the passage.
- C. Option C is incorrect as power will not be shut for one day rather only for 2 hours.
- D. Option D is incorrect as power will not be off till the weather changes, it will be only off for a maximum two hours.
Q5. Complete the sentence by choosing the most appropriate option:There _ many students waiting to hear the results of the test.
- A. Has
- B. Have
- C. Was
- D. Are✓
Explanation: Students are plural. So, the helping verb should also be plural, which are “have” and “are”.Have can not be used here because it is used in perfect tense which has the 3rd form of verb while here we have the continuous form of verb i.e. “waiting”. So, the answer is D.
Why the other options are wrong
- A. Students are plural so the helping verb should also be plural, which are "have" and "are". So that eliminates option A and C. As the verb in the sentence is in continuous form so the correct option is D "are".
- B. Option B is incorrect because Have cannot be used here as it is used in the sentence having 3rd form of verb i.e. Perfect tense.
- C. Students are plural so the helping verb should also be plural, which are "have" and "are". So that eliminates option A and C. Moreover, "was" is used with singular nouns. As the verb in the sentence is in continuous form so the correct option is D "are".
Q6. Complete the sentence by choosing the most appropriate option: Some people _ claim to be vegetarians actually allow themselves to eat fish and chicken.
- A. That
- B. Which
- C. Whom
- D. Who✓
Explanation: People are nouns referring to person, the best pronoun to use in this case thus will be to use “who”.
Why the other options are wrong
- A. Option A is wrong as "that" is usually used to refer to a particular thing and not to a person.
- B. Option B is wrong as "which" is used to refer to a thing in general, not to a person.
- C. Option C is wrong as whom is used to refer to the object of the sentence, not the subject. Who is referring to the subject of the sentence, so that is why it's the correct answer.
Q7. Identify errors in the sentences:During the day, there is often two guards at the entrance.
- A. During
- B. There is✓
- C. Guards
- D. No error
Explanation: It should be “there are” as guards are plural nouns so the helping verb used should also be plural.
Why the other options are wrong
- A. Option A is incorrect as "During" does not need to be changed, it is a correct word.
- C. Option C is incorrect as there is no error in the word "guards".
- D. Option D is incorrect as the phrase "there is" is incorrect that needs to be changed.
Q8. Identify errors in the sentences:Because of their identical appearance and dress, the twins were often mistaken for each other.
- A. Because of
- B. Identical
- C. And dress
- D. Were
- E. No error✓
Explanation: There is no error in the sentence above according to grammar.
Why the other options are wrong
- A. Option A is wrong as "Because" word is correct in the sentence according to the rules of grammar.
- B. Option B is wrong as "identical" word does not need to be changed.
- C. Option C is wrong as "and dress" is correct in the context of the sentence.
- D. Option D is wrong as word "were" is correct in the context of the sentence according to the rules of grammar.
Q9. Choose the word most similar in meaning to the capitalized word: PROVOKE
- A. Deface
- B. Lionize
- C. Aggravate
- D. Aggravate✓
Explanation: To provoke something means to trigger something, the closest word to which will be "aggravate."
Why the other options are wrong
- A. "Deface" means "to spoil the appearance of something" , that eliminates option A .
- B. "Lionize" means "to make someone famous or treat them with great importance" , that makes option B incorrect.
- C. "To punish" someone means "to inflict a penalty on someone who has done something illegal or wrong" , that is not similar in meaning to "Provoke" .
Q10. Choose the word most similar in meaning to the capitalized word:THREATENING:
- A. Flighty
- B. Aggressive✓
- C. Chaste
- D. Hallowed
Explanation: "Being threatening" means "to be very intimidating and horrifying". The closest word in meaning from above will be “aggressive”.
Why the other options are wrong
- A. Option A is wrong as "flighty" means "to be irresponsible" . So, it's not similar in meaning to "threatening".
- C. Option C is wrong as "chaste" means "someone who refrains from immoral activities" .
- D. Option D is wrong as "hallowed" means "something that is holy" or "sacred".
Q11. A student studied a drop of pond water with the low power of compound microscope and made the following exact drawing of an organism she observed, Which kingdom is the organism classified as?
- A. Protista✓
- B. Monera
- C. Metazoa
- D. Animalia
- E. Bryophyta
Explanation: Kingdom Protista has membrane-bound organelles, as shown in the diagram and a true nucleus. That is why option A is correct
Why the other options are wrong
- B. Option B is wrong because organisms belonging to Kingdom Monera cannot have a true nucleus and membrane bound organelles
- C. Option C is wrong because it is not a kingdom rather a subclassification of Kingdom Animalia
- D. Option D is wrong because the organism shown is unicellular
- E. Option E is wrong because bryophyta is not a kingdom but a subclassification of plant kingdom
Q12. The following organism moves by means of:
- A. Peristalsis
- B. Pinocytosis
- C. Porifera
- D. Protozoa
- E. Pseudopodia✓
Explanation: The organism moves by means of pseudopodia. That is why option E is the correct option. Pseudopodium is a temporary arm-like projection of a eukaryotic cell membrane that is developed in the direction of movement of the organism.
Why the other options are wrong
- A. Option A is wrong because peristalsis is the movement by which the food bolus moves in the gut.
- B. Option B is wrong because pinocytosis is the process by which small droplets or liquid substances are endocytosed.
- C. Option C is wrong because Porifera is not a process but a phylum of the Kingdom Animalia.
- D. Option D is wrong because protozoa is not a process but a kingdom type.
Q13. In a pyramid of energy, which level represents the greatest amount of energy?
- A. Producers✓
- B. First-order consumers
- C. Second-order consumers
- D. Third-order consumers
- E. Decomposers
Explanation: In all the ecological pyramids, producers (organisms that produce their own food) are found at the lowest trophic level. This trophic level contains the highest amount of energy. The energy in each trophic level of an energy pyramid is just 10 percent of the energy in the level below it.
Why the other options are wrong
- B. Option B is incorrect as first order consumers have energy 10% less than the producers.
- C. Option C is incorrect as second order consumers have energy 10% less than the first order consumers.
- D. Option D is incorrect as third order consumers have 10% less energy than the second order consumers. While the decomposers feed on all of the other levels of energy, having the least energy amongst all, that makes
- E. Decomposers occupy the last trophic level or the top of the ecological pyramid. They have less energy than third order consumers.
Q14. The phenomenon known as crossing-over occurs during:
- A. Mitosis
- B. Meiosis✓
- C. Geographic distribution
- D. Active transport
Explanation: Crossing over is the exchange of genetic material between non-sister chromatids of homologous chromosomes during meiosis, which results in new allelic combinations in the daughter cells.
Why the other options are wrong
- A. Option A is wrong as mitosis is the process in which a parent cell divides into two daughter cells without any crossing over of genetic material. Mitosis produces offspring identical to the parent cell.
- C. Option C is wrong as geographic distribution is a totally unrelated process and it does not involve crossing over.
- D. Option D is wrong as Active transport is the process of transporting materials against their concentration gradient by the expenditure of energy in the form of ATP.
Q15. The following sequence of events occurs at the neuromuscular junction. Nerve impulse -> release of V -> end plate potential -> W produced in muscle fibre -> X release from sarcoplasmic reticulum -> Formation of Y -> muscle contraction. Which one of the following shows the correct sequence from V -> Y?
- A. Option A✓
- B. Option B
- C. Option C
- D. Option D
- E. Option E
Explanation: Neurotransmitters called acetylcholine (V) are released, and an action potential (W) is generated. After an action potential is generated in the muscle fibre, calcium ions (X) are released from the sarcoplasmic reticulum. Ca ions act on troponin and displace it so that myosin can attach to the sites on the actin molecule, forming an actomyosin (Y) complex for muscle contraction.
Why the other options are wrong
- B. Neurotransmitters called acetylcholine (V) are released, and an action potential (W) is generated. After an action potential is generated in the muscle fibre, calcium ions (X) are released from the sarcoplasmic reticulum. Ca ions act on troponin and displace it so that myosin can attach to the sites on the actin molecule, forming an actomyosin (Y) complex for muscle contraction.
- C. Neurotransmitters called acetylcholine (V) are released, and an action potential (W) is generated. After an action potential is generated in the muscle fibre, calcium ions (X) are released from the sarcoplasmic reticulum. Ca ions act on troponin and displace it so that myosin can attach to the sites on the actin molecule, forming an actomyosin (Y) complex for muscle contraction.
- D. Neurotransmitters called acetylcholine (V) are released, and an action potential (W) is generated. After an action potential is generated in the muscle fibre, calcium ions (X) are released from the sarcoplasmic reticulum. Ca ions act on troponin and displace it so that myosin can attach to the sites on the actin molecule, forming an actomyosin (Y) complex for muscle contraction.
- E. Neurotransmitters called acetylcholine (V) are released, and an action potential (W) is generated. After an action potential is generated in the muscle fibre, calcium ions (X) are released from the sarcoplasmic reticulum. Ca ions act on troponin and displace it so that myosin can attach to the sites on the actin molecule, forming an actomyosin (Y) complex for muscle contraction.
Q16. Which group of organisms has the following features? I. Three pairs of jointed legs II. Three-part segmented body III. One pair of antennae
- A. Arachnids
- B. Crustaceans
- C. Insects✓
- D. Myriapods
Explanation: Insects are arthropods that have three body segments, three pairs of legs, one pair of antennae, and many have one or two pairs of wings. The three body sections are called the head, the thorax, and the abdomen. Wings and legs are attached to the thorax, the middle section.
Why the other options are wrong
- A. Option A is incorrect as Arachnids have 4 pairs of jointed legs
- B. Option B is incorrect as Crustaceans have 5 pairs of legs.
- D. Option D is incorrect as myriapods include centipedes,etc that have one pair of legs per segment of their body and there are 100 segments in their body.
Q17. The table shows some characteristics of four different vertebrates. Which vertebrate is a reptile?
- A. A
- B. B✓
- C. C
- D. D
Explanation: Characteristics of Reptiles:✓ Reptiles are four-legged vertebrate animals.✓ Most reptiles lay eggs.The skin of reptiles is covered with scales. ✓ Reptiles have cold-blooded metabolisms. ✓ Reptiles breathe with the aid of lungs.
Why the other options are wrong
- A. Chordate's skin has embedded dermal scales which may be ganoid, cycloid, or ctenoid scales. Fins both, median (single) or paired and have rays of cartilage or bone.
- C. Amphibians, like frogs, toads, and salamanders, possess legs for locomotion on land or in water but typically do not have scales or hair.
- D. The vertebrates possessing legs and hair but lacking fins and scales are mammals.
Q18. The diagram shows some organs of the digestive system. Where is amylase present?
- A. 1,4 and 5✓
- B. 1,2 and 3
- C. 2,6 and 4
- D. 3,5 and 4
Explanation: Amylase is mostly present in the mouth, in pancreatic juice, and ileum; hence, option A is correct. Amylase is not present in the liver, no enzyme is present in the large intestine and only pepsin (protease) is present in the stomach. That is why, all other options B, C and D are wrong.
Why the other options are wrong
- B. Amylase is not present in the stomach and liver. So, it is the wrong option.
- C. Amylase is not present in the stomach and large intestine. So, it also will be the wrong option.
- D. Amylase is not present in liver. So, it is the wrong option.
Q19. Which bones meet at the elbow joint, and what kind of movement do they allow?
- A. Option A
- B. Option B
- C. Option C
- D. Option D✓
Explanation: At the elbow joint, the ulna and humerus meet, and they cause back-and-forth movement of the forearm. At the shoulder joint, the humerus and scapula meet, and there they cause full axial movement.
Why the other options are wrong
- A. Option A is incorrect as the humerus and scapula meet at the shoulder joint, and there they cause full axial movement, not the sliding movement.
- B. Option B is incorrect as the humerus and scapula meet at the shoulder joint, and there they cause full axial movement, not back-and-forth movement.
- C. Option C is incorrect as the ulna and humerus do not cause sliding movement rather back and forth movement.
Q20. The diagram below represents the process of:
- A. Hydrolysis
- B. Condensation✓
- C. Neutralization
- D. Metabolism
Explanation: When two monomers join together to form a single product, with the removal of H2O, the process is called the condensation process. Hence, option B is correct.
Why the other options are wrong
- A. Option A is wrong as hydrolysis is the opposite of condensation; it is the breakdown into smaller molecules by the addition of H2O.
- C. Option C is wrong as neutralization is the process by which acid neutralizes base to form salt and water.
- D. Metabolism is the breakdown of substances. That makes option D incorrect.
Q21. Which of the following is correctly matched?
- A. AF, BG, CJ, DI, EH
- B. AH, BI, DF, CG, EJ✓
- C. AJ, BI, CH, DG, EF
- D. AH, BF, DG, CI, EJ
Explanation: To solve this quickly just match one or two organelles to their correct function,crossing out the wrong options while doing so. Peroxisomes carry out detoxification of alcohol which is only in option B so we can easily choose it,no other options have DF. To check others, we know that smooth ER deals with cholesterol and fats that is why E goes with J.Ribosomes carry out protein synthesis.Centrioles form astral rays.Lysosomes destroy foreign particles.Hence,AH, BI, DF, CG, EJ is correct.
Why the other options are wrong
- A. Option A is incorrect as all of the options are mismatched.
- C. Option C is incorrect as except option B, all other options are mismatched with their functions.
- D. Option D is incorrect because except option A and E, all other options are mismatched with their functions.
Q22. Pyruvic acid is the end product of:
- A. Glycolysis✓
- B. Krebs cycle
- C. Oxidation
- D. Electron transport system
Explanation: Pyruvic acid is the end product of glycolysis, the first stage of cellular respiration. During glycolysis, one glucose molecule is enzymatically converted into two molecules of pyruvic acid in the cytoplasm, with a net gain of ATP and NADH. Glycolysis does not involve oxygen and precedes the Krebs cycle and electron transport chain, which occur in the mitochondria. The Krebs cycle processes acetyl-CoA, not pyruvic acid, and the electron transport system produces ATP and water. Oxidation is a broader term referring to electron loss and is not specific to producing pyruvic acid.
Why the other options are wrong
- B. Incorrect. The Krebs cycle does not produce pyruvic acid as an end product. Instead, it processes acetyl-CoA to produce ATP, NADH, and FADH2, with oxaloacetic acid being regenerated.
- C. Incorrect. Oxidation is a general chemical process involving the loss of electrons. It is not a specific stage in cellular respiration that ends with pyruvic acid.
- D. Incorrect. The electron transport system, the final stage of cellular respiration, results in the production of water and ATP, not pyruvic acid.
Q23. Humoral immunity is carried by a special group of cells called:
- A. B-cells✓
- B. Killer cells
- C. Helper cells
- D. Null cells
Explanation: Humoral immunity is also called antibody-mediated immunity. B-cells differentiate into plasma B cells that can produce antibodies against a specific antigen.
Why the other options are wrong
- B. Option B is wrong as killer cells or natural killer cells are a type of immune cell that have granules with enzymes that can kill tumor cells or virally infected cells. They do not exhibit humoral immunity.
- C. Option C is wrong as helper cells (T-helper cells) are involved in cell-mediated immunity.
- D. Option D is wrong as null cells are large granular lymphocytes produced in the bone marrow and attack pathogens and toxic substances.
Q24. Identify the correctly matched pair relating to a term and its meaning/function/example:
- A. nitrogen cycle... Rhizopus
- B. denitrifying bacteria..change protein to ammonia
- C. biosphere.. where life exists✓
- D. lithosphere...water , air and soil on the surface of earth
Explanation: The biosphere is a global ecosystem composed of living organisms (biota) and the abiotic (nonliving) factors from which they derive energy and nutrients. Hence option C is correct. Rhizopus is a fungus that has nothing to with the nitrogen cycle. Denitrifying bacteria carry out the conversion of nitrates in the soil to free atmospheric nitrogen, not protein to ammonia. The lithosphere includes the brittle upper portion of the mantle and the crust, the outermost layers of Earth's structure, not water, air and soil.
Why the other options are wrong
- A. Option A is incorrect as rhizopus is a fungus that has nothing to do with the nitrogen cycle.
- B. Option B is incorrect as denitrifying bacteria carry out the conversion of nitrates in the soil to free atmospheric nitrogen, not protein to ammonia.
- D. Option D is incorrect as the lithosphere includes the brittle upper portion of the mantle and the crust, the outermost layers of Earth's structure, not water, air and soil.
Q25. Which of the following RNA sequences would be transcribed from the DNA sequence ATGGCTAGGAC?
- A. TACGGATCCTG
- B. UAGCGAUCCUG
- C. AUGCCUAGGAC
- D. UACCGAUCCUG✓
Explanation: DNA strand serves as the template for RNA synthesis. The RNA nucleotide sequence is complementary to that of DNA template strand except the presence of uracil in place of thymine. As we know that adenine base pairs with thymine and guanine with cytosine; the RNA sequence of given DNA strand would be UACGGAUCCUG. This makes option D correct answer.
Why the other options are wrong
- A. TACGGATCCTG is incorrect as the base pairs in this option are mismatched.
- B. UAGCGAUCCUG is incorrect as the base pairs in this option are mismatched.
- C. AUGCCUAGGAC is incorrect as the base pairs in this option are mismatched.
Q26. Human cells maintain concentration gradients across their plasma membranes, such that there is a high sodium concentration outside the cell and a high potassium concentration inside the cell. Suppose that within the cell membrane are sodium leak channels or carrier proteins. These channels would allow sodium to:
- A. Move out of the cell by simple diffusion
- B. Move into the cell by simple diffusion
- C. Move out of the cell by facilitated diffusion
- D. Move into the cell by facilitated diffusion✓
Explanation: As the question mentions, there is a high concentration of sodium ions outside the cell, which means that through sodium leaky channels, the sodium ions should move inside the cell, not outside. The type of movement that occurs through channels or carrier proteins down the concentration gradient is called facilitated diffusion. That is why the answer is D.
Why the other options are wrong
- A. Option A is wrong because neither sodium moves out of the cell nor is it transported via simple diffusion.
- B. Option B is wrong because sodium does not transport via simple diffusion.
- C. Option C is wrong because sodium moves inside the cell, not out of the cell.
Q27. The hormone labeled X in the diagram is often used in over-the-counter diagnostic tests to determine when ovulation has occurred. This hormone is:
- A. Estrogen
- B. Progesterone
- C. FSH
- D. LH✓
Explanation: The correct answer is LH, as it is the hormone whose surge triggers ovulation and is detected by ovulation prediction kits. Estrogen and progesterone play roles in preparing and maintaining the uterine lining, not in the detection of ovulation. FSH is involved in follicle development but not directly in ovulation prediction. Testosterone is a predominantly male hormone and irrelevant to this context.
Why the other options are wrong
- A. Estrogen is primarily involved in regulating the menstrual cycle and preparing the uterine lining, not directly involved in signaling ovulation.
- B. Progesterone is mainly responsible for maintaining the uterine lining after ovulation but is not used in ovulation prediction kits.
- C. FSH stimulates follicle growth in the ovaries but does not directly indicate ovulation.
Q28. Based on the peak levels of hormone X, on what day of the cycle is ovulation most likely to occur?
- A. Day 21
- B. Day 14✓
- C. Day 12
- D. Day 25
- E. Day 28
Explanation: Peak of LH hormone occurs at 14th day. So, the ovulation occurs at 14th day.
Why the other options are wrong
- A. Option A is incorrect as on Day 21, progesterone level is higher as compared to LH, which is not a suitable condition for ovulation.
- C. Option C is incorrect as on Day 12, LH concentration is less than that on Day 14.
- D. Option D is incorrect as on Day 25, the LH level is negligible and the menstruation phase of the cycle is about to start.
- E. Option E is incorrect as on Day 28, the LH level is negligible and the menstruation phase of the cycle is about to start.
Q29. The hormone labeled X in the diagram is:
- A. Estrogen
- B. Progesterone
- C. FSH
- D. LH✓
- E. Testosterone
Explanation: Hormone X is LH because at 14th day of menstrual cycle, LH has highest peak which causes ovulation and stimulate ovaries to produce progesterone.
Why the other options are wrong
- A. Hormone X in the labelled diagram is not estrogen because on 14th day of menstrual cycle, peak of estrogen is not high.
- B. Hormone X in the labelled diagram is not progesterone because on 14th day of menstrual cycle, there is not highest peak of progesterone. Hormone Y is progesterone.
- C. Hormone X is not FSH because at 14th day of menstrual cycle, FSH is at its lowest level.
- E. Testosterone is the hormone of male reproductive system. Testosterone has no major link with female menstrual cycle.
Q30. Which of the following statement(s) is/are correct regarding a nucleus? I.Stores wastes and other SubstancesII.Contains genetic materialIII.Helps in cellular transport systemIV.Control centre of the cell
- A. I only
- B. I&II
- C. II & III
- D. II & IV✓
- E. III & IV
Explanation: Nucleus is the control centre of the cell and stores the genetic material of the cell,so we say that statements II and IV are correct, making option D correct. Nucleus does not store wastes and other substances plus it also does not help in cellular transport system, that eliminate option A,B,C and E.
Why the other options are wrong
- A. Nucleus doesn't store wastes and any other kind of substances. Nucleus is the governor house of cell. It controls the life and activities of cells.
- B. Nucleus stores genetic material but doesn't store any kind of wastes . So , statement II makes option B incorrect.
- C. Nucleus doesn't help in cellular transport system. So , this option is incorrect.
- E. Nucleus is the control center of cell but does not help in cellular respiration. Thus , statement III makes option E incorrect.
Q31. Bacteria having a tuft of flagella at one end are called:
- A. Peritrichous
- B. Monotrichous
- C. Lophotrichous✓
- D. Amphitrichous
Explanation: There are four types of flagellar arrangements based on the number and placement of flagella on the cell. These are, 1. Monotrichous - A single flagellum extends from one end of the cell. 2. Amphitrichous - A single flagellum or multiple flagella extend from two ends of the cell. 3. Lophotrichous - Tuft of flagella extend from one end of the cell. 4. Peritrichous – Multiple flagella randomly distributed over the entire bacterial cell. Thus, the correct answer is 'Lophotrichous.' Option A, B and D are incorrect as their description does not match the requirement of the question i.e. bacteria having a tuft of flagella at one end of the cell.
Why the other options are wrong
- A. In peritrichous form , flagella surround the whole cell.
- B. When single polar flagellum is present, then condition is known as monotrichous.
- D. Amphitrichous is the condition in which tuft of flagella at each of two poles is present.
Q32. Cystic fibrosis patients lack a gene that codes for a transmembrane carrier of:
- A. Cl- ions✓
- B. Na+ ions
- C. K+ ions
- D. Ca2+ ions
Explanation: This is the correct answer. Cystic fibrosis (CF) is a genetic disorder caused by mutations in the gene that codes for the cystic fibrosis transmembrane conductance regulator (CFTR) protein. This protein is responsible for regulating the flow of chloride (Cl-) ions across the cell membranes of various organs, including the lungs, pancreas, and intestines. In CF patients, mutations in the CFTR gene disrupt the normal functioning of the CFTR protein, leading to an imbalance of salt and water in these organs. This imbalance results in the thick, sticky mucus characteristic of CF, which can cause respiratory problems, digestive issues, and other complications
Why the other options are wrong
- B. This is incorrect. While sodium (Na+) ions are also important for maintaining fluid balance in the body, they are not the primary ion affected in cystic fibrosis.
- C. This is incorrect. Potassium (K+) ions play a role in nerve and muscle function, but they are not directly involved in the pathophysiology of cystic fibrosis.
- D. This is incorrect. Calcium (Ca2+) ions are essential for many cellular processes, but they are not the primary ion affected in cystic fibrosis.
Q33. Which features do animal cells share with plant cells?
- A. Option A
- B. Option B
- C. Option C✓
- D. Option D
Explanation: Mitochondria, cytoplasm and nucleus are found in both plant and animal cells. However, chloroplast is the organelle found in plant cells but lacking in animal cells.
Why the other options are wrong
- A. Option A is wrong as it shows that chloroplast is also shared among plant and animal cells, which is incorrect. Chlorophyll is only present in plant cells not in animal cells.
- B. Option B is wrong as it shows that cytoplasm is not shared among plant and animal cells, which is wrong.
- D. Option D shows that only mitochondria is the shared organelle, not the nucleus and cytoplasm, that makes it incorrect.
Q34. Platyhelminthes means:
- A. Flatworms✓
- B. Roundworms
- C. Segmented worms
- D. None of the above
Explanation: Flatworms are known as Platyhelminthes. Free-living flatworms are mostly predators, and live in water or in shaded, humid terrestrial environments, such as leaf litter.
Why the other options are wrong
- B. Option B is wrong as Roundworms are known as Nematodes. Species in the phylum inhabit a broad range of environments.
- C. Option C is wrong as Segmented worms are Annelids.The annelids also known as the segmented worms, are animals that comprise the phylum Annelida
- D. Option D is wrong as Option A is correct so it cannot be none of the above.
Q35. All of the following are mammals except the:
- A. Porpoise
- B. Shark✓
- C. Whale
- D. Walrus
- E. Seal
Explanation: Shark is a cartilaginous fish belonging to the class Chondrichthyes. All other options are wrong as they are mammals
Why the other options are wrong
- A. Porpoises are distinguished from dolphins by their flattened, spade-shaped teeth, distinct from the conical teeth of dolphins, and lack of a pronounced beak.
- C. Whale is a mammal .Whales are a widely distributed and diverse group of fully aquatic placental marine mammals. As an informal and colloquial grouping, they correspond to large members of the infraorder Cetacea, i.e. all cetaceans apart from dolphins and porpoises
- D. Walrus is a mammal.The walrus is a large pinniped marine mammal with discontinuous distribution about the North Pole in the Arctic Ocean and subarctic seas of the Northern Hemisphere
- E. Seal is a mammals. Seals are streamlined, aquatic mammals with streamlined bodies, flippers instead of feet, and a thick layer of blubber for insulation and buoyancy
Q36. In the pedigree of a family shown above, brown eyes are indicated as white circles and blue eyes as dark circles. Javeria and Juhi are twins. From this chart, it can be determined that:
- A. Tahir and Mary are homozygous for brown eyes
- B. Jawaria and Juhi are identical twins
- C. Juhi is heterozygous for blue eyes
- D. Juhi is homozygous for blue eyes✓
- E. Jawaria and Saad are homozygous for brown eyes
Explanation: It is imperative for a recessive trait present in a homozygous state to show up in phenotype so answer D is correct.
Why the other options are wrong
- A. Option A is wrong because if they would have been homozygous then they couldn't produce a child having blue eyes (which is a recessive trait), rather they are a confirmed case of heterozygous
- B. Option B is wrong because genotypically in identical twins not even a single gene can differ and Jawaria and Juhi have differences in genes of eye color.
- C. Option C is wrong as Juhi can not be heterozygous for blue eyes as a recessive trait should always be homozygous to be expressed in phenotype.
- E. Option E is wrong because Jawaria and Saad can be both homozygous or heterozygous for brown eyes as their parents are heterozygous. So it cannot be predicted from the diagram shown.
Q37. Viruses resemble living things because they:
- A. Circulate
- B. Move
- C. Reproduce✓
- D. Are crystalline
- E. Are able to respond to stimuli in the environment
Explanation: Only thing that makes a group of scientists want the virus to be classified as a living thing is its ability to reproduce. All other options are incorrect as non-living things can also exhibit these characteristics
Why the other options are wrong
- A. Circulation is not the trait that makes viruses resemble with living things.
- B. Movement is not the trait that makes viruses resemble with living things.
- D. Viruses also have no metabolic processes (it is a set of chemical reactions which leads to growth, reproduction, and help respond to surroundings of any organism) like other living organisms. Thus they can be crystallized and understand the viral particles.
- E. This is not the characteristic that makes viruses resemble with living things .
Q38. A part of the digestive system that is not in contact with food is the:
- A. Small intestine
- B. Stomach
- C. Liver✓
- D. Large intestine
- E. Oesophagus
Explanation: The liver aids in digestion by producing bile, a fluid that emulsifies fats in the small intestine, breaking them down into smaller, more manageable droplets for absorption. While the liver doesn't "digest" food directly, it creates the bile necessary for fat digestion, which is then stored in the gallbladder before being released into the small intestine when food is present. All others are those parts of the digestive tract that come in contact with the food.
Why the other options are wrong
- A. The small intestine is the part of the digestive system that comes in contact with the food. Digestion in the small intestine is a process of chemical breakdown and nutrient absorption, where enzymes from the pancreas, liver, and the intestine itself break down food into smaller molecules like sugars, amino acids, and fatty acids.
- B. The stomach is the part of the digestive system that comes in contact with the food. Digestion in the stomach involves mechanical and chemical processes where food is mixed with gastric juices, a mix of acid and enzymes, to break down food into a semi-liquid substance called chyme.
- D. Large intestine is the part of digestive system that comes in contact with the food. The large intestine's primary roles are absorbing water and electrolytes, housing beneficial bacteria, and forming and storing feces for elimination.
- E. The oesophagus is that part of the digestive system that comes in contact with the food. Digestion in the esophagus is primarily a process of mechanical movement, not chemical digestion. After food is swallowed, the esophagus uses muscular contractions called peristalsis.
Q39. All of the following protect the body against the entrance of germs except:
- A. Tears
- B. Mucous membranes
- C. Ciliated cells
- D. Red blood cells,✓
Explanation: Red blood cells are responsible for transporting O2 via hemoglobin stored in them from the lungs to the body's cells and tissues. Options A, B, and C are incorrect because they are physical barriers (part of the first line of defense) that protect our body from germs.
Why the other options are wrong
- A. Tears are physical barriers (part of the first line of defense ) that protect our body from germs.
- B. Mucous membranes are physical barriers (part of the first line of defense) that protect our body from germs.
- C. Ciliated cells are physical barriers (part of the first line of defense) that protect our body from germs.
Q40. The diagram below illustrates:
- A. Hemophilia
- B. Phenylketonuria
- C. Sickle cell anemia
- D. Down’s Syndrome✓
Explanation: Trisomy 21 i.e. the presence of 3 chromosomes at the 21th pair is the characteristic of Down's syndrome.
Why the other options are wrong
- A. Option A is incorrect as Hemophilia is a genetic disorder in which blood fails to clot, due to lack of clotting factors.
- B. Option B is incorrect as Phenylketonuria is a point mutation in the gene making phenylalanine hydroxylase enzyme due to which the amino acid, phenylalanine accumulates in the body.
- C. Option C is incorrect as Sickle cell anemia is a point mutation caused by sickle cell. Anemia is a point mutation in hemoglobin gene called hemoglobin S that is inherited by the child. It causes the red blood cells to become irregular shaped or sickle shaped that cause a lot of consequences.
Q41. What will be the product of the following reaction?
- A. A
- B. B
- C. C
- D. D✓
Explanation: Step 1: Starting compoundWe have p-cresol (4-methylphenol).Step 2: Reaction with CHCl₃/NaOHThis is the Reimer–Tiemann reaction.In this reaction, an aldehyde group –CHO gets introduced at the ortho position to the –OH group.So product A is o-formyl-p-cresol (4-methyl-2-hydroxybenzaldehyde).Step 3: Reaction with HCNAn aldehyde reacts with HCN to give a cyanohydrin.The –CHO group becomes –CH(OH)CN.So compound B is o-(CH(OH)CN)-p-cresol.Step 4: Hydrolysis with H₃O⁺On hydrolysis, –CN group converts to –COOH.So the final product C is o-(CH(OH)COOH)-p-cresol.Step 5: Match with given optionsLooking at the options:(a) has –CH₂COOH (wrong, no hydroxyl group)(b) also has –CH₂COOH (wrong)(c) has –CH(OH)COOH but with two methyls (wrong position)(d) has –CH(OH)COOH correctly at the ortho position to OH, with a para –CH₃ substituent (correct).
Why the other options are wrong
- A. Option A suggests a reaction product that does not involve the correct sequence of reactions or the correct functional group transformations.
- B. Option B presents an incorrect intermediate that might result from a misunderstanding of the nitrile hydrolysis step.
- C. this is not correctThis option shows the correct -CH(OH)COOH group, but the positions of the other groups on the benzene ring are different from the starting material. The reaction does not change the position of the methyl (CH_3) or hydroxyl (OH) groups.
Q42. The product for the given reaction is:
- A. Option A✓
- B. Option B
- C. Option C
- D. Option D
Explanation: Structure: Cyclohexene with a =CH₂ group (i.e., methylene cyclohexane).Explanation:This is the correct product.The –CH₂OH group loses water and forms a double bond at the exocyclic position.This is called an exocyclic alkene (double bond between ring carbon and exo carbon).Matches expected product of alcohol dehydration
Why the other options are wrong
- B. Structure: Cyclohexane (saturated six-membered ring).Explanation:This is fully saturated and has no functional group.Does not match the product of acid-catalyzed alcohol dehydration (which should be an alkene).❌ Incorrect. No elimination took place.
- C. Structure: Cyclohexene (a double bond inside the ring).Explanation:A double bond within the ring suggests a rearranged product.However, in this case, dehydration of –CH₂OH on cyclohexyl does not lead to internal cyclohexene.There's no hydride shift possible to move the carbocation into the ring.❌ Incorrect. Wrong position of double bond.
- D. Structure: Cyclohexene with a CH₃ substituent at exo position.Explanation:This is methylcyclohexene.It suggests that the –CH₂OH group became a methyl group, which is not possible under dehydration.No such methylation occurs in this acid-catalyzed reaction.❌ Incorrect. Does not follow reaction mechanism.
Q43. What will be the product of the following reaction?
- A. A
- B. B
- C. C
- D. D✓
Explanation: Step 1: Starting compoundWe have p-cresol (4-methylphenol).Step 2: Reaction with CHCl₃/NaOHThis is the Reimer–Tiemann reaction.In this reaction, an aldehyde group –CHO gets introduced at the ortho position to the –OH group.So product A is o-formyl-p-cresol (4-methyl-2-hydroxybenzaldehyde).Step 3: Reaction with HCNAn aldehyde reacts with HCN to give a cyanohydrin.The –CHO group becomes –CH(OH)CN.So compound B is o-(CH(OH)CN)-p-cresol.Step 4: Hydrolysis with H₃O⁺On hydrolysis, –CN group converts to –COOH.So the final product C is o-(CH(OH)COOH)-p-cresol.Step 5: Match with given optionsLooking at the options:(a) has –CH₂COOH (wrong, no hydroxyl group)(b) also has –CH₂COOH (wrong)(c) has –CH(OH)COOH but with two methyls (wrong position)(d) has –CH(OH)COOH correctly at the ortho position to OH, with a para –CH₃ substituent (correct).
Why the other options are wrong
- A. Option A suggests a reaction product that does not involve the correct sequence of reactions or the correct functional group transformations.
- B. Option B presents an incorrect intermediate that might result from a misunderstanding of the nitrile hydrolysis step.
- C. this is not correctThis option shows the correct -CH(OH)COOH group, but the positions of the other groups on the benzene ring are different from the starting material. The reaction does not change the position of the methyl (CH_3) or hydroxyl (OH) groups.
Q44. Which of the following values of heat of formation indicates that the product is least stable?
- A. - 94 kcal
- B. + 21.4 kcal
- C. - 231 kcal
- D. + 64.8 kcal✓
Explanation: In the context of heat of formation (ΔH), a negative value indicates that the formation of the compound is exothermic, meaning the compound is more stable compared to its constituent elements in their standard states.So, the least stable compound among the options provided would have the most positive (ΔH) value and option d has the most positive value ,hence that is the correct option.
Why the other options are wrong
- A. A negative value indicates that the formation of the compound is exothermic, meaning the compound is more stable compared to its constituent elements in their standard states.So, the least stable compound among the options provided would have the most positive (ΔH) value ,hence this option is incorrect.
- B. A negative value indicates that the formation of the compound is exothermic, meaning the compound is more stable compared to its constituent elements in their standard states.So, the least stable compound among the options provided would have the most positive (ΔH) value ,hence this option is not correct as option d)+64.8 has a more positive value.
- C. A negative value indicates that the formation of the compound is exothermic, meaning the compound is more stable compared to its constituent elements in their standard states.So, the least stable compound among the options provided would have the most positive (ΔH) value ,hence this option is incorrect.
Q45. The enthalpy of certain reactions at 273 K is -20.75 kJ. The enthalpy of the same reaction at 373 K (if heat capacities of reactants and products are the same) will be:
- A. -20.75 kJ✓
- B. -2075 kJ
- C. Zero
- D. -20.75 x 373/273 kJ
Explanation: As it is provided in the given statement that heat capacities of reactants and products are the same, therefore there will be no energy change in the reaction. By Kirchoff's Rule; ∆Cp=∆H2-H1/T2-T1∆Cp(T2-T1)=∆H2-H1As, ∆Cp= 0 , ∆H2=H1 , therefore;H2= -20.75KJ
Why the other options are wrong
- B. Calculations show enthalpy is -20.75 kJ not -2075kJ.
- C. Calculations show enthalpy is -20.75 kJ not zero.
- D. Calculations show enthalpy is -20.75 kJ not -20.75 × 373/273kJ.
Q46. Most abundant salt of sodium in nature is:
- A. NaNO3
- B. Na2SO4
- C. NaOH
- D. NaCl✓
Explanation: The most abundant salt of sodium in nature is sodium chloride (NaCl).The concentration of salt in seawater (its salinity) is about 35 parts per thousand; in other words, about 3.5% of the weight of seawater comes from the dissolved salts.
Why the other options are wrong
- A. NaNO3 is not abundant salt of sodium in nature.
- B. Na2SO4 is not abundant salt of sodium in nature.
- C. NaOH is not abundant salt of sodium in nature.
Q47. A gas that reacts with CaO and not with NaHCO3 is:
- A. None of these
- B. CI2✓
- C. O2
- D. N2
- E. Na
Explanation: Chlorine gas does react with calcium oxide (CaO) to form calcium chloride (CaCl2):Cl2 + CaO → CaCl2But it doesnot react with NaHCO3
Why the other options are wrong
- A. This is not correct.
- C. Oxygen gas does not react with calcium oxide (CaO) in a direct manner, so it is not the correct answer. Oxygen gas is generally not reactive with most metal oxides.
- D. Nitrogen gas is generally unreactive under normal conditions and does not readily form compounds with most elements.
- E. Carbon dioxide (CO2) and Clorine are the gas that reacts with calcium oxide (CaO) but does not react with sodium bicarbonate (NaHCO3).
Q48. Which of the following statements is correct?
- A. H3PO3 is dibasic and reducing✓
- B. H3PO3 is tribasic and reducing
- C. H3PO3 is tribasic and non-reducing
- D. H3PO3 is dibasic and non-reducing
Explanation: H3PO3 is correctly identified as dibasic because it has two -OH groups that can release hydrogen ions. Additionally, the presence of a P-H bond in its structure allows it to donate hydrogen atoms, making it a reducing agent. The incorrect options either misidentify it as tribasic or incorrectly label it as non-reducing.
Why the other options are wrong
- B. This is incorrect because H3PO3 only has two -OH groups, making it dibasic, not tribasic.
- C. This option is incorrect as H3PO3 is dibasic due to two -OH groups, and it is a reducing agent because of the P-H bond.
- D. While it is correct that H3PO3 is dibasic, it is incorrect to say it is non-reducing. The P-H bond present allows it to act as a reducing agent.
Q49. Which of the following statements about H2S is false?
- A. It is a covalent compound
- B. It is a gas with bad smell
- C. It is a stronger reducing agent than H2O
- D. It is a weak base in water✓
Explanation: H2S acts as weak acid in water, not as a weak base. In H2S, the influence of the nucleus is less and hence, it can give away its electrons.
Why the other options are wrong
- A. Both H atoms remain covalently bonded to the S atom by two single bonds, as shown below: Hence, H2S is a covalent compound.
- B. Hydrogen sulphide(also known as H2S, sewer gas, swamp gas, stink damp, and sour damp) is a colourless gas known for its pungent "rotten egg" odour at low concentrations. It is extremely flammable and highly toxic. Hydrogen sulphide also occurs naturally in sewers, manure pits, well water, oil and gas wells, and volcanoes.
- C. In H2O Bond dissociation enthalpy of O–H is more than S – H bond of H2S therefore H2S is a better reducing agent than H2O.
Q50. What is the volume in cm3 of 3.01 x 10^23 molecules of O2 gas at S.T.P.?
- A. 1000 cm3
- B. 11000 cm3
- C. 1120 cm3
- D. 11200 cm3✓
Explanation: 3.01*10^23 /6.02*10^23 = 0.5 mole at STP,1 mole of gas –––> 22,4 L 0,5 mole –––––––> x x= 11,2 L 11,2 L = 11200 cm3 As this is a numerical, it can only have one correct answer which is option D
Why the other options are wrong
- A. Volume is 11200cm³ not 1000cm³.
- B. Volume is 11200cm³ not 11000cm³.
- C. Volume is 11200cm³ not 1120 cm³.
Q51. The amount of solute present in the given amount of solvent is called:
- A. Molarity
- B. Molality
- C. Concentration✓
- D. Solubility
Explanation: The concentration of the solution tells you how much solute has been dissolved in the solvent. For example, if you add one teaspoon to two cups of water, the concentration could be reported as 1 teaspoon salt per 2 cups of water.
Why the other options are wrong
- A. Molarity is defined as the moles of a solute per litres of a solution(not per litre of solvent).
- B. Molality is defined as the “total moles of a solute contained in a kilogram of a solvent.”
- D. Solubility is defined as the maximum amount of a substance that will dissolve in a given amount of solvent at a specified temperature.
Q52. In the reaction 2Fe+Cl2 -> 2FeCl3
- A. Fe is reduced
- B. Fe is oxidized✓
- C. Cl2 oxidized
- D. None of the above
Explanation: The Oxidation state of iron(Fe) is changed from "0" to "+3". Hence it is oxidised.
Why the other options are wrong
- A. The Oxidation state of iron(Fe) is changed from "0" to +3. Hence it is oxidised and not reduced.
- C. The Oxidation state of chlorine is reduced from "0" to "-1".
- D. Incorrect option.
Q53. The process in which electric current is used to carry out a non-spontaneous redox reaction is called:
- A. Electrolyte
- B. Electrolysis✓
- C. Metallic conductor
- D. None of the above
Explanation: Electrolysis is a process by which an electric current is passed through a substance to effect a chemical change. A chemical change is one in which the substance loses or gains an electron (oxidation or reduction).
Why the other options are wrong
- A. Electrolytes are substances that have a natural positive or negative electrical charge when dissolved in water.
- C. These are the metals that contain free electrons for the conduction of electricity hence metallic conductors a good conductors of heat and electricity.
- D. This is not correct.
Q54. The molecular structure of a hydrocarbon is shown below.
- A. Option A
- B. Option B✓
- C. Option C
- D. Option D
Explanation: B is a structural isomer of the structure shown above. Structure in A is the same as the structure shown. Structure C is not an isomer because it does not have the same number of carbon and hydrogen atoms as in the diagram shown. Structure D has a double bond that reduces two hydrogen atoms from it as compared to the structure shown that is why D can not also be an isomer of the diagram shown above.
Q55. The formula of Plaster of Paris is:
- A. (CaSO4).1/2H2O✓
- B. (CaSO4).5H2O
- C. (CaSO4).7H2O
- D. (CaSO4).9H2O
Explanation: The chemical name of the Plaster of Paris is calcium sulphate hemihydrate because half a molecule of water is attached with calcium sulphate. The chemical formula of plaster of Paris is CaSO4.1/2H2O
Why the other options are wrong
- B. (CaSO4).5H2O is not formula of plaster of Paris.
- C. (CaSO4).7H2O is not formula of plaster of Paris.
- D. (CaSO4).9H2O is not formula of plaster of Paris.
Q56. Ionic, covalent and co-ordinate covalent bonds are simultaneously present in the molecular geometry of:
- A. Ammonia
- B. Ammonium hydroxide✓
- C. Hydrochloric acid
- D. Water
- E. Methane
Explanation: There are 3 covalent , 1 coordinate covalent bond in NH4+ ion, and 1 covalent bond in OH−. There is an ionic bond between NH4+ and OH-.So, this species simultaneously has 3 different types of bonds.
Why the other options are wrong
- A. Ammonia has a nitrogen atom bound with three hydrogen atoms by covalent bonds.
- C. Hydrochloric acid has ionic bonding between Hydrogen (H+) and chlorine(Cl-).
- D. Water has only covalent bonding between 2 hydrogen atoms and an oxygen atom.
- E. Methane also has 4 covalent bonds by which carbon atoms are bonded to 4 respective hydrogen atoms.
Q57. All amino acids contain the functional group:
- A. NH2✓
- B. CO2
- C. S2-
- D. Both A and B
Explanation: All amino acids contain an amino group (-NH2), a carboxyl group (-COOH), a hydrogen atom and a part where radical attaches.-CO2 is different from -COOH. -CO2 can be present in esters.
Why the other options are wrong
- B. CO2- can be present in esters not in amino acids.
- C. S²- is not present in amino acids.
- D. NH2 is present in amino acids but CO2 is not present in amino acids.
Q58. Alanine, lysine and tryptophan are:
- A. Carbohydrates
- B. Lipids
- C. Enzymes
- D. Amino acids✓
Explanation: Alanine, lysine, and tryptophan are all building blocks of proteins. Each is a distinct amino acid with its own structure and properties. They are not carbohydrates, lipids, or enzymes.
Why the other options are wrong
- A. Alanine, lysine, and tryptophan are not in this chemical class, as they all contain nitrogen and complex structures unlike simple sugars.
- B. Lipids are a diverse group of compounds including fats, waxes, oils, and some hormones. They are typically non-polar molecules, which makes them insoluble in water but soluble in organic solvents.
- C. Enzymes are a specific class of proteins that act as biological catalysts, speeding up biochemical reactions. While alanine, lysine, and tryptophan are the components that make up enzymes, they are the raw materials (monomers) themselves, not the functional enzyme (polymer) itself. Therefore, this classification is incorrect for the specific listed molecules.
Q59. What happens when one mole of ethane is mixed in the dark at room temperature with six moles of chlorine?
- A. There is no reaction.✓
- B. CH3CH2Cl and HCl are formed.
- C. CH3CCl3 and HCl are formed.
- D. CCl3CCl3 and HCl are formed.
- E. Carbon and HCl are formed.
Explanation: Hydrocarbons react with chlorine by free radical mechanism but this reaction only proceeds in the presence of light because it is necessary to break Cl-Cl bond. As in the given condition, it's a dark room, therefore there'll be no reaction in this case.
Why the other options are wrong
- B. There will be no reaction in dark.Therefore this option is incorrect.
- C. There will be no reaction in dark.Therefore this option is incorrect.
- D. There will be no reaction in dark.Therefore this option is incorrect.
- E. There will be no reaction in dark.Therefore this option is incorrect.
Q60. How would an ammino group affect the benzene ring for subsequent reactions?
- A. Deactivate the ring; meta directing
- B. Activate the ring; ortho-para directing✓
- C. Deactivate the ring; ortho-para directing
- D. Activate the ring; meta directing
- E. A and b
Explanation: Activate the ring: The ammino group is an electron-donating group due to its lone pair of electrons. This donation increases the electron density on the benzene ring, making it more reactive towards electrophilic aromatic substitution reactions. Thus, the presence of –NH₂ activates the benzene ring.Ortho-para directing: The –NH₂ group directs incoming electrophiles to the ortho and para positions relative to itself. This is because the lone pair on the nitrogen can participate in resonance with the benzene ring, stabilizing the positive charge that forms during the reaction at these positions. As a result, the ortho and para positions are favored for substitution over the meta position.
Why the other options are wrong
- A. This is incorrect because the ammino group does not deactivate the benzene ring; it activates it instead. Also, meta directing is associated with electron-withdrawing groups.
- C. This is also incorrect for the same reason as above; the ammino group activates, not deactivates.
- D. While it is true that the ammino group activates the ring, it does not direct substituents to the meta position.
Q61. Which of the following would be the best solvent for an SN2 reaction?
- A. H2O
- B. CH3CH2OH
- C. CH3SOCH3✓
- D. CH3CH2CH2CH2CH2CH3
Explanation: Polar aprotic solvents are used in SN2 mechanism. As CH3SOCH3 is polar and also aprotic , so it is used as solvent in SN2 reactions.
Why the other options are wrong
- A. H2O is not best solvent for SN2 reactions.
- B. CH3CH2OH is not best solvent for SN2 reactions.
- D. CH3CH2CH2CH2CH2CH3 is not best solvent for SN2 reactions.
Q62. A chemical reaction is catalyzed by a catalyst X. Hence, X:
- A. Increases activation energy of the reaction
- B. Does not affect equilibrium constant of the reaction✓
- C. Decreases rate constant of the reaction
- D. Reduces enthalpy of the reaction
Explanation: A catalyst provides an alternative reaction pathway with lower activation energy, increasing the reaction rate. It does not change the energies of reactants or products, so the equilibrium position remains unchanged. Therefore, the correct answer is B .
Why the other options are wrong
- A. A catalyst lowers activation energy, not increases it, enabling faster reactions by providing alternative pathways energetically.
- C. A catalyst increases the rate constant by lowering activation energy, speeding up both forward and reverse reactions equally.
- D. A catalyst does not affect reaction enthalpy (ΔH), which is a state function independent of reaction pathway or catalyst.
Q63. A compound was found to contain nitrogen and oxygen in the ratio 28g:80g. The formula of the compound is:
- A. NO
- B. N2O3
- C. N2O4
- D. N2O5✓
Explanation: Mass of nitrogen is 14 g and mass of oxygen is 16 g. Dividing nitrogen’s mass in compound (28g) by 14g gives us 2. Dividing oxygen’s mass in compound (80g) by 16g gives us 5. So we can now say that the molar ratio of N to O is 2:5 that means the formula is N2O5
Why the other options are wrong
- A. Compound is N2O5 not NO.
- B. Compound is N2O5 not N2O3.
- C. Compound is N2O5 not N2O4.
Q64. When B- particles are sent through a thin metal foil, most of them go straight through the foil as:
- A. B- particles are much heavier than electrons
- B. B- particles are positively charged
- C. Most part of the atom is empty space✓
- D. B- particles move with high velocity
Explanation: They pass through tin metal foil because most space of the atom is empty, explained by Rutherford in his gold foil experiment.
Why the other options are wrong
- A. B- particles are not heavier than electrons. Infact, beta particles are considered as electrons.
- B. Beta particles are negatively charged.(Not positively)
- D. Beta particles have high velocity in contrast to alpha particles but this is not the reason they move straight when passed through thin metal foil.
Q65. Electronic configuration of M2+ ion is 2, 8, 14 and its atomic mass is 56 amu. The number of neutrons in its nucleus are:
- A. 30✓
- B. 32
- C. 42
- D. 52
Explanation: Total number of electrons in M2+ ions are 2+8+14=24, since they lost two electrons to become this ion that means neutral M will have 26 electrons. Since neutral atoms have the same numbers of electrons and protons so the number of protons in M is also 26. As the question states that the mass number of M2+ is 56. Mass number, being the sum of protons and neutrons, can be used to calculate neutrons, by subtracting protons from it(56-26=30)
Why the other options are wrong
- B. Number of neutrons is 30 not 32.
- C. Number of neutrons is 30 not 42.
- D. Number of neutrons is 30 not 52.
Q66. The quantum numbers +½ and -½ for the electron spin represent:
- A. Rotation of the electron in clockwise and anticlockwise direction respectively
- B. Rotation of the electron in anticlockwise and clockwise direction respectively
- C. Magnetic movement of the electron pointing up and down respectively
- D. Two quantum mechanical spin states which have no classical analogue✓
Explanation: This is the most suitable option as it covers all aspects of describing the spin quantum number and its states.The two states +1/2 and -1/2, describes the spin of an electron. It is the term used for denoting the property of an electron only in Quantum physics and it does not have any proof in classical physics. That's why the term "no classical analogue" is used.
Why the other options are wrong
- A. Incorrect. Electron spin quantum numbers do not describe physical rotation like a planet spinning.
- B. Incorrect. The concept of electron spin does not involve literal clockwise or anticlockwise rotations.
- C. Incorrect. While electron spin does relate to magnetic properties, this description is overly simplistic and does not capture the full quantum mechanical nature.
Q67. 1 liter of a gas weighs 2 g at 300 K and 1 atm pressure. If the pressure is made 0.75 atm, at which of the following temperatures will 1 L of the same gas weigh 1 g?
- A. 450 K✓
- B. 800 K
- C. 600 K
- D. 900 K
Explanation: So we know that,P₁V₁ / P₂V₂ = W₁T₁ / W₂T₂Substituting in the above formula we get,=> 1 × 1 / 0.75 × 1 = 2 × 300 / 1 × T₂=> 1 / 0.75 = 600 / T₂Cross Multiplying we get,=> T₂ × 1 = 600 × 0.75=> T₂ = 450 K
Why the other options are wrong
- B. So, we know that,P₁V₁ / P₂V₂ = W₁T₁ / W₂T₂Substituting in the above formula we get,=> 1 × 1 / 0.75 × 1 = 2 × 300 / 1 × T₂=> 1 / 0.75 = 600 / T₂Cross Multiplying we get,=> T₂ × 1 = 600 × 0.75=> T₂ = 450 K
- C. So, we know that,P₁V₁ / P₂V₂ = W₁T₁ / W₂T₂Substituting in the above formula we get,=> 1 × 1 / 0.75 × 1 = 2 × 300 / 1 × T₂=> 1 / 0.75 = 600 / T₂Cross Multiplying we get,=> T₂ × 1 = 600 × 0.75=> T₂ = 450 K
- D. So, we know that,P₁V₁ / P₂V₂ = W₁T₁ / W₂T₂Substituting in the above formula we get,=> 1 × 1 / 0.75 × 1 = 2 × 300 / 1 × T₂=> 1 / 0.75 = 600 / T₂Cross Multiplying we get,=> T₂ × 1 = 600 × 0.75=> T₂ = 450 K
Q68. Which of the following pairs of gases have the same rate of diffusion?
- A. CO2 and N2O✓
- B. CO2 and CO
- C. NO2 and CO2
- D. CO2 and N2O4
Explanation: According to Graham's Law, the rate of diffusion or effusion is inversely proportional to the square root of molar mass. Both CO2 and N2O have the same mass (44). So, they have a similar rate of diffusion.
Why the other options are wrong
- B. Masses of CO(28 )and CO2 (44) are different. So, they don't have a similar rate of diffusion.
- C. Masses of NO2 (46) and CO2 (44) are also different.
- D. Masses of N2O4(92) and CO2 (44) are also different.
Q69. For the equilibrium reaction 2NO2 ⇌ N2O4 (g) (-61 kJ), increase of temperature would:
- A. Favour the Formation of N2O4
- B. Favour the Decomposition of N2O4✓
- C. No Effect on Equilibrium
- D. Stop the Reaction
Explanation: The reaction is exothermic (ΔH = -61 kJ) in the forward direction (2NO₂ → N₂O₄). Increasing temperature adds heat, which the system counteracts by shifting toward the endothermic reverse reaction. Thus, the equilibrium shifts to decompose N₂O₄ into NO₂.
Why the other options are wrong
- A. Option A is wrong according to given reaction conditions.
- C. Option C is wrong according to given reaction conditions.
- D. Option D is wrong according to given reaction conditions.
Q70. The value K for H2(g) + CO2(g) <-> H2O(g) + CO(g) is 1.80 at 1000 C. If 1.0 mole of each H2 and CO2 are placed in 1 litre flask, the final equilibrium concentration of CO at 1000 C will be:
- A. 0.295 M
- B. 0.385 M
- C. 0.531 M
- D. 0.573 M✓
Explanation: The given reaction is :- H2(g)+CO2(g)⇌H2O(g)+CO(g) Initial moles : 1 1 0 0 At eqm : 1−x 1−x x x Now, KC=[H2O][CO]/[H2][CO2] 1.8=x.x/(1-x)(1-x) ⇒x2=1.8(1−x)2 Taking square root on both sides ⇒x=1.34(1−x)⇒2.34x=1.34 ⇒x=0.573 So, concentration of CO at eqb=0.573M
Why the other options are wrong
- A. According to given data, this option is incorrect.The given reaction is :- H2(g)+CO2(g)⇌H2O(g)+CO(g)Initial moles : 1 1 0 0At eqm : 1−x 1−x x xNow, KC=[H2O][CO]/[H2][CO2]1.8=x.x/(1-x)(1-x)⇒x2=1.8(1−x)2Taking square root on both sides⇒x=1.34(1−x)⇒2.34x=1.34⇒x=0.573So, concentration of CO at eqb =0.573M
- B. According to given data, this option is incorrect.The given reaction is :- H2(g)+CO2(g)⇌H2O(g)+CO(g)Initial moles : 1 1 0 0At eqm : 1−x 1−x x xNow, KC=[H2O][CO]/[H2][CO2]1.8=x.x/(1-x)(1-x)⇒x2=1.8(1−x)2Taking square root on both sides⇒x=1.34(1−x)⇒2.34x=1.34⇒x=0.573So, concentration of CO at eqb =0.573M
- C. According to given data, this option is incorrect.The given reaction is :- H2(g)+CO2(g)⇌H2O(g)+CO(g)Initial moles : 1 1 0 0At eqm : 1−x 1−x x xNow, KC=[H2O][CO]/[H2][CO2]1.8=x.x/(1-x)(1-x)⇒x2=1.8(1−x)2Taking square root on both sides⇒x=1.34(1−x)⇒2.34x=1.34⇒x=0.573So, concentration of CO at eqb =0.573M
Q71. A row of 25 decorative lights, connected in series, is connected to a main transformer. When the supply is switched on, the lights do not work. The owner uses a voltmeter to test the circuit. When the voltmeter is connected across the third bulb in the row, a reading of zero is obtained. Which of the following cannot be the only fault in the circuit?
- A. The filament of one of the other bulbs has broken
- B. The filament of the third bulb has broken.✓
- C. The fuse in the mains transformer has blown.
- D. There is a break in the wire from the supply to the transformer.
Explanation: When a filament of a bulb in a series circuit is broken, it creates an open circuit causing the voltage to be maximum across that bulb. In this case, the third bulb's broken filament would result in a high voltage reading, not zero. The correct answer is that the filament of the third bulb has broken. This creates an open circuit, leading to the absence of current flow and hence zero voltage. The other options are incorrect because they do not explain the observed zero voltage across the third bulb.
Why the other options are wrong
- A. If the third filament is broken, the voltage across that bulb will not be zero but it will be maximum due to maximum resistance. There should be another issue leading to the voltage drop.
- C. If the third filament is broken, the voltage across that bulb will not be zero but it will be maximum due to maximum resistance. There should be another issue leading to the voltage drop.
- D. If the third filament is broken, the voltage across that bulb will not be zero but it will be maximum due to maximum resistance. There should be another issue leading to the voltage drop.
Q72. Charges of +2 μC and -2 μC are situated at points P and Q respectively, as shown below. X is midway between P and Q. Which of the following correctly describes the electric field and the electric potential at point X?
- A. Option A✓
- B. Option B
- C. Option C
- D. Option D
- E. Option E
Explanation: As the electric field moves away from positive charges and towards negative charges, the direction of the electric field should be towards Q. Electric potential is a scalar quantity that means it should be added without considering the directions. At pSince the charges are equal and opposite with the same distance from point X, the potential at point X will be zero.
Why the other options are wrong
- B. Incorrect as per formulaAs the electric field moves away from positive charges and towards negative charges, the direction of the electric field should be towards Q. Electric potential is a scalar quantity that means it should be added without considering the directions. At pSince the charges are equal and opposite with the same distance from point X, the potential at point X will be zero.
- C. Incorrect as per formulaAs the electric field moves away from positive charges and towards negative charges, the direction of the electric field should be towards Q. Electric potential is a scalar quantity that means it should be added without considering the directions. At pSince the charges are equal and opposite with the same distance from point X, the potential at point X will be zero.
- D. Incorrect as per formulaAs the electric field moves away from positive charges and towards negative charges, the direction of the electric field should be towards Q. Electric potential is a scalar quantity that means it should be added without considering the directions. At pSince the charges are equal and opposite with the same distance from point X, the potential at point X will be zero.
- E. Incorrect as per formulaAs the electric field moves away from positive charges and towards negative charges, the direction of the electric field should be towards Q. Electric potential is a scalar quantity that means it should be added without considering the directions. At pSince the charges are equal and opposite with the same distance from point X, the potential at point X will be zero.
Q73. A fixed mass of gas in a thermally insulated container is compressed. After compression, the temperature of the gas will have:
- A. Fallen, since more molecules bombarded the container and so they must be moving slower
- B. Fallen, since more molecules collide more frequently with one another and so their average speed is lower
- C. Remains constant if the compression is very slow
- D. Risen, since doing work on the gas increases the kinetic energy of the molecules✓
- E. Risen, since there are more intermolecular collisions and so more heat is produced by them
Explanation: If an ideal gas is compressed adiabatically, its temperature rises because the heat produced cannot be lost to the surroundings. Each molecule has more KE than before because of collisions of molecules with moving parts of the wall (i.e., piston compressing the gas).
Why the other options are wrong
- A. If the compression process is adiabatic and reversible, meaning there is no heat exchange with the surroundings and the process is conducted slowly enough to maintain equilibrium at each stage, then the temperature of the gas will increase. This is because work is done on the gas during compression, increasing its internal energy and therefore raising its temperature.
- B. If the compression process is adiabatic and reversible, meaning there is no heat exchange with the surroundings and the process is conducted slowly enough to maintain equilibrium at each stage, then the temperature of the gas will increase. This is because work is done on the gas during compression, increasing its internal energy and therefore raising its temperature.
- C. When a fixed mass of gas is compressed in a thermally insulated container, the temperature of the gas will increase. This is known as adiabatic compression.
- E. In an adiabatic process, there is no heat exchange with the surroundings because the container is thermally insulated, so any change in temperature is solely due to the work done on the gas during compression.
Q74. A fixed mass of an ideal gas absorbs 1000 J of heat and expands under a constant pressure of 20 kPa from a volume of 25 x 10-3 m3 to a volume of 50 x 10-3 m3. What is the change in the internal energy of the gas?
- A. -1000J
- B. -900J
- C. Zero
- D. +500 J✓
- E. +1000J
Explanation: This is the following solution:
Why the other options are wrong
- A. This option suggests that the change in internal energy of the gas is -1000 J. However, this is not correct. The change in internal energy is determined by the heat added to the gas and the work done by the gas. While the heat added is 1000 J, the work done by the gas is not zero, so the change in internal energy cannot be equal to the heat added.
- B. This option suggests that the change in internal energy of the gas is -900 J. However, this is not correct. The change in internal energy is determined by the heat added to the gas and the work done by the gas. While the heat added is 1000 J, the work done by the gas is not zero, so the change in internal energy cannot be equal to the heat added minus 100 J.
- C. This option suggests that the change in internal energy of the gas is zero. However, this is not correct. The gas absorbs 1000 J of heat, so its internal energy increases. Although the gas expands, it does work on the surroundings, so the change in internal energy is not zero.
- E. This option suggests that the change in internal energy of the gas is +1000 J. However, this is not correct. The gas absorbs 1000 J of heat, so its internal energy increases. Although the gas expands, it does work on the surroundings, so the change in internal energy is not equal to the heat added.
Q75. In an experiment, an object was placed on the principal axis of a convex lens 25 centimeters away from the lens. A real image 4 times the size of the object was obtained. The focal length of the lens is:
- A. 20 cm✓
- B. 25 cm
- C. 33 cm
- D. 50 cm
- E. 100 cm
Explanation: The explanation is given below:u = 25 cmm = -4 [a real image so it must be inverted]v = - m * u = - * (-4) * 25 = 100 cmf = u * v / (u + v) = 25 * 100 / (25 + 100) = 2500 / 125 = 20 cmSo the focal length of the lens is 20 cm.
Why the other options are wrong
- B. This option is incorrect as per the formula.This option is correct.u = 25 cmm = -4 [a real image so it must be inverted]v = - m * u = - * (-4) * 25 = 100 cmf = u * v / (u + v) = 25 * 100 / (25 + 100) = 2500 / 125 = 20 cmSo the focal length of the lens is 20 cm.
- C. This option is incorrect as per the formula.This option is correct.u = 25 cmm = -4 [a real image so it must be inverted]v = - m * u = - * (-4) * 25 = 100 cmf = u * v / (u + v) = 25 * 100 / (25 + 100) = 2500 / 125 = 20 cmSo the focal length of the lens is 20 cm.
- D. This option is incorrect as per the formula.This option is correct.u = 25 cmm = -4 [a real image so it must be inverted]v = - m * u = - * (-4) * 25 = 100 cmf = u * v / (u + v) = 25 * 100 / (25 + 100) = 2500 / 125 = 20 cmSo the focal length of the lens is 20 cm.
- E. This option is incorrect as per the formula.This option is correct.u = 25 cmm = -4 [a real image so it must be inverted]v = - m * u = - * (-4) * 25 = 100 cmf = u * v / (u + v) = 25 * 100 / (25 + 100) = 2500 / 125 = 20 cmSo the focal length of the lens is 20 cm.
Q76. An object with constant mass rests on a horizontal surface whose coefficient of friction is 0.2. If a horizontal force F is applied to the object, what will be the effect(s) on the object? I. It may move with constant speed in the direction of F once it has been set in motion.II. It may remain at rest.III. It may accelerate.IV. It may move with constant speed in an opposite direction
- A. I, II and III only✓
- B. I and III only
- C. II and IV only
- D. IV only
- E. III only
Explanation: 1. It is possible that object starts to accelerate when the frictional force becomes greater enough due to objects motion to equalize the forward force, so the object starts moving at a constant speed.2. Now, if the force is less than product of coefficients of friction and weight of the object may remain at rest.3. If the force applied is greater than product of coefficient of friction and weight of the object, the object accelerates on the direction of force.
Why the other options are wrong
- B. 1. Object may not move with constant speed in the direction of F once it has been set in motion.3. Object may not accelerate
- C. 2. Object may not remain at rest.4. Object may not move with constant speed in an opposite direction
- D. Object may not move with constant speed in an opposite direction.
- E. Object may not accelerate .
Q77. A person having a mass of 60 kilograms exerts a horizontal force of 200 Newtons in pushing a 90 kilogram object a distance of 6 meters along a horizontal floor. He does this at constant velocity in 3 seconds. The weight of this person approximately, in Newtons, is: (g=9.8m/s2)
- A. 40 N
- B. 90 N
- C. 200 N
- D. 400 N
- E. 600 N✓
Explanation: To find the weight of a person, use the formula W = mg, where W is the weight, m is the mass (60 kg), and g is the acceleration due to gravity (approximated here as 10 m/s2). Thus, the weight is calculated as:W = 60 kg × 10 m/s2 = 600 NTherefore, the correct answer is 600 N. Other options are incorrect as they underestimate the weight given the mass of 60 kg and the gravitational acceleration.
Why the other options are wrong
- A. The calculated weight should be significantly more than 40 N since the mass is 60 kg.
- B. The calculated weight is higher than 90 N for a 60 kg mass.
- C. A 60 kg mass would have a weight greater than 200 N under Earth's gravity.
- D. While closer, 400 N is still less than the correct weight for 60 kg mass.
Q78. If 500 cm3 of gas, having a pressure of 760 millimeters of mercury, is compressed into a volume of 300 cm3 given the temperature remains constant, the pressure of the gas will be, in millimeters of mercury, approximately:
- A. 500 mm of Hg
- B. 900 mm of Hg
- C. 1,100 mm of Hg
- D. 1,270 mm of Hg✓
- E. 1,500
Explanation: Solution: This problem can be solved by ideal gas equation; PV=nRTSince, the temperature remains constant, therefore: Given: Initial Pressure of gas - 760mm of HgInitial Volume of gas - 560 cm³Final volume of gas - 300 cm³Find - Final pressure of gasSolution - The pressure of gas can be calculated by the help of formula; P1V1 = P2V2. In the equation, P1 and P2 are initial and final pressures and V1 and V2 are initial and final pressures.Keeping the values in equation-760x500 = P2x300P2 = 1266.67 mm of Hg.Hence, the pressure of gas is 1266.67 mm of Hg and the correct option closest to answer is D. 1,270.
Why the other options are wrong
- A. Calculations show pressure of gas is 1270 mm of Hg not 500.
- B. Calculations show pressure of gas is 1270 mmof Hg not 900.
- C. Calculations show pressure of gas is 1270 mm of Hg not 1100.
- E. Calculations show pressure of gas is 1270 mm of Hg not 1500.
Q79. Two springs fixed at one end are stretched by 5 cm and 10 cm, respectively, when masses 0.5 kg and 1 kg are suspended at their lower ends. When displaced slightly from their mean positions and released, they will oscillate with time periods in the ratio
- A. 1:√2✓
- B. 1:2
- C. 2:1
- D. √2:1
Explanation: This is the correct answer. The time period of a spring-mass system is given by T = 2π√(m/k), where T is the time period, m is the mass, and k is the spring constant. Since the spring constant is the same for both springs (as the same force produces the same extension), the ratio of the time periods will only depend on the ratio of the masses: T1/T2 = √(m1/m2). Substituting the given masses, we get T1/T2 = √(0.5 kg / 1 kg) = √(1/2) = 1/√2.
Why the other options are wrong
- B. This is incorrect. The ratio of the time periods is not directly proportional to the ratio of the masses. Instead, it depends on the square root of the mass ratio.
- C. This is incorrect. The ratio of the time periods is not inversely proportional to the ratio of the masses.
- D. This is incorrect. The square root of the mass ratio is 1/√2, not √2.
Q80. A unit of induction is said to exist at a point where the force per unit charge experienced by a positive test charge, moving with a velocity of 1ms-1 in the direction perpendicular to the field is 1 Newton. What is this phenomenon called?
- A. Gravitational Field
- B. Magnetic Field✓
- C. Magnetic Flux
- D. Flux
Explanation: The correct answer is Magnetic Field. A magnetic field is defined by the force it exerts on moving charges. In this question, the force per unit charge experienced by a test charge moving perpendicularly to the field indicates the presence of a magnetic field. The force is proportional to the velocity of the charge and the strength of the magnetic field.Option A (Gravitational Field) is incorrect because it deals with forces due to gravity, not magnetic forces.Option C (Magnetic Flux) is incorrect because it describes the number of magnetic field lines passing through a surface, not the force on a moving charge.Option D (Flux) is too general and does not specifically relate to magnetic fields affecting moving charges.
Why the other options are wrong
- A. A gravitational field is a region of space around a mass where another mass experiences a force of attraction. It is unrelated to the force experienced by a charge moving perpendicularly to a magnetic field.
- C. Magnetic flux is the measure of the number of magnetic field lines passing through a surface, not directly related to the force experienced by a moving charge.
- D. Flux generally refers to the rate of flow of a property per unit area, and is not specific to the magnetic force experienced by a moving charge.
Q81. A _ is a positively charged particle with properties similar to the α-particle. Its mass is one fourth and charge is one half of that of an α-particle. It is smaller in size and carries less energy at the same velocity.
- A. Beta particle
- B. Gamma ray
- C. Neutron
- D. Proton✓
Explanation: The correct answer is a proton. A proton is a positively charged particle with a mass that is one fourth that of an alpha particle and a charge that is one half of an alpha particle, making it the particle described in the question.Beta particles are incorrect as they are negatively charged particles akin to electrons. Gamma rays are a form of electromagnetic radiation and do not have mass or charge. Neutrons have no charge, so they do not fit the description of a positively charged particle.
Why the other options are wrong
- A. Beta particle is negatively charged particle with properties similar to electron.
- B. Gamma rays are a form of electromagnetic radiation (EMR). They are the similar to X-rays.
- C. Neutrons are a type of subatomic particle with no charge i.e they are neutral.
Q82. is defined as the sensation that sound produces in the ear of a listener and is clearly related to the frequency of sound. Frequency and _ are both measured in Hertz (Hz). Thus greater the frequency the greater the _ and lower the frequency lower the _.
- A. Quality ... Pitch ... Loudness ... Pitch
- B. Pitch ... Pitch ... Pitch ... Pitch✓
- C. Loudness ... Quality ... Pitch ... Quality
- D. Quality ... Quality ... Quality ... Quality
- E. Loudness ... Loudness ... Loudness ... Loudness
Explanation: The quality of a sound governed by the rate of vibrations producing it; the degree of highness or lowness of a tone is generally called pitch. Pitch is defined as the sensation of sound in the ear related to frequency.Pitches are measured by using a tool called hertz. Hertz measures one second of sound pitches and creates a calculated visual of the sound wave. Pitch is related to the frequency as pitch increases when the frequency is increased and decreases with the decrease in frequency.
Why the other options are wrong
- A. Greater the frequency, greater will be the pitch not loudness.Frequency and pitch both are measured in hertz not quality.
- C. Frequency and pitch both are measured in hertz not loudness that is measured in hertz.
- D. Frequency and pitch both are measured in hertz not the quality that is measured in hertz.
- E. Frequency and pitch are measured in hertz not the loudness that is measured in hertz.Greater the frequency, greater will be the pitch not loudness . Lower the frequency, lower will be the pitch not loudness.
Q83. Light can be polarized by: reflection double refraction scattering of light
- A. I only
- B. II only
- C. III only
- D. I and II only
- E. I, II and III✓
Explanation: 1. Scattering: When light interacts with particles or molecules in a medium, it can be scattered. Depending on the scattering mechanism, polarization can occur.2. Double refraction: Double refraction, also known as birefringence, is a property exhibited by certain transparent materials like calcite. In such materials, light is split into two beams, each polarized differently. This phenomenon is often used to polarize light.3. Reflection: When light reflects off a surface, the reflected light can be partially polarized, especially if the surface is non-metallic and the angle of incidence is specific (known as Brewster's angle). This polarized reflection is commonly used in polarizing filters.
Why the other options are wrong
- A. When light reflects off a surface, the reflected light can be partially polarized, especially if the surface is non-metallic and the angle of incidence is specific (known as Brewster's angle). This polarized reflection is commonly used in polarizing filters.
- B. Double refraction, also known as birefringence, is a property exhibited by certain transparent materials like calcite. In such materials, light is split into two beams, each polarized differently. This phenomenon is often used to polarize light.
- C. When light interacts with particles or molecules in a medium, it can be scattered. Depending on the scattering mechanism, polarization can occur.
- D. Light can be polarized by all the processes mentioned above.
Q84. Incident rays of light parallel to the principal axis of a convex lens, after refraction by the lens, will:
- A. Converge at the principal focus✓
- B. Converge inside the principal focus
- C. Converge outside the principal focus
- D. Converge at the center of curvature
- E. diverge as long as theý are close to the lens
Explanation: Incident rays of light parallel to the principal axis of the convex lens converge at the principal focus.A convex lens also known as a converging lens is thick in the middle and thin at the edges. It converges the light rays coming from a source on the principal focus. A principle focus of a convex lens is defined as the point on the principal axis on which the light rays coming parallel to the principal axis converge after getting refracted from the convex lens.
Why the other options are wrong
- B. Incident rays of light parallel to the principal axis of a convex lens, after refraction by the lens, will converge at the principal focus instead of converging inside the principal focus.
- C. Incident rays of light parallel to the principal axis of a convex lens, after refraction by the lens, will converge at the principal focus instead of converging outside the principal focus.
- D. Incident rays of light parallel to the principal axis of a convex lens, after refraction by the lens, will converge at principle focus instead of converging at the center of curvature.
- E. Incident rays of light parallel to the principal axis of a convex lens, after refraction by the lens, will converge at principle focus instead of diverging as long as they are close to the lens.
Q85. If two sounds have the same wavelength in air at the same temperature, what other property must they also have in common?Intensity Amplitude Frequency
- A. I only
- B. III only✓
- C. I and II only
- D. II and III only
- E. I, II and III
Explanation: If the two sounds have the same wavelength in air at the same temperature, it means they have the same speed of propagation in that medium. Since the speed of sound is constant, if the wavelength is the same, the frequency must also be the same. The relationship between frequency and wavelength is inversely proportionalv=f x wavelength
Why the other options are wrong
- A. Intensity wouldn't be the common property .
- C. Intensity and Amplitude wouldn't be the common properties.
- D. Amplitude and frequency wouldn't be the common properties.
- E. All are not common properties.Only frequency is the common property.
Q86. Which unit expresses work per unit charge?
- A. Hertz
- B. Watt
- C. Joule
- D. Volt✓
- E. Half-life
Explanation: The correct answer is Volt. A volt measures the electrical potential difference and is defined as the work done per unit charge, expressed as 1V = 1J/1C. This means that one volt is equivalent to one joule of work done per one coulomb of charge. The other options are incorrect because:Hertz measures frequency, not related to work or charge.Watt measures power, defined as work per unit time, not charge.Joule is a unit of energy or work, not per unit charge.Half-life is a concept related to radioactive decay, not applicable to work or charge.
Why the other options are wrong
- A. Hertz measures frequency, which is cycles per second, not related to work or charge.
- B. Watt is the unit of power, which is work done per unit time, not work per unit charge.
- C. Joule is the unit of work or energy itself, not work per unit charge.
- E. Half-life relates to the time it takes for half of a radioactive substance to decay, irrelevant to work or charge.
Q87. The time of open vibration of a simple pendulum may be decreased by:
- A. Increasing the length of the pendulum
- B. Decreasing the length of the pendulum✓
- C. Using a heavier bob
- D. Using a lighter bob
Explanation: The 'time of one vibration' of the simple pendulum can be decreased by decreasing the pendulum length. The period of simple pendulum is given by;T=,2π√l/g,So there is direction relation between time period and length of pendulum. Therefore in order to decrease the time period the length of pendulum is decreased.Time period has nothing to concern with mass so option C & D are not related to the given question.
Why the other options are wrong
- A. Time of open vibration of a simple pendulum may be decreased by decreasing length of pendulum instead of increasing length of pendulum .
- C. Time period has nothing to concern with the mass. So this option is incorrect.
- D. Time period has nothing to concern with the mass. So , this option is incorrect.
Q88. The sum of all forms of molecular energies in a thermodynamic system is known as:
- A. Entropy
- B. Enthalpy
- C. Internal energy✓
- D. Red shift
Explanation: Internal energy is the sum of potential energy of the system and the system's kinetic energy. It is the sum of all possible molecular energies in a thermodynamic system.
Why the other options are wrong
- A. Entropy is the measure of a system's thermal energy per unit temperature that is unavailable for doing useful work.
- B. A thermodynamic quantity equivalent to the total heat content of a system is known as enthalpy.
- D. The displacement of spectral lines towards longer wavelengths (the red end of the spectrum) in radiation from distant galaxies and celestial objects is called red shift. This is interpreted as a Doppler shift that is proportional to the velocity of recession and thus to distance.
Q89. is also known as anti-electron.
- A. Photon
- B. Proton
- C. Positron✓
- D. Nucleon
Explanation: The positron, also known as the antielectron, is the correct answer because it is the antimatter counterpart of the electron, with +1 charge and annihilation upon collision with an electron. Photons have zero charge, protons have antiprotons as antiparticles, and nucleons are a collection of protons and neutrons, not the antiparticle of an electron.
Why the other options are wrong
- A. Photons are not the antiparticles of electrons; they have zero charge and behave differently.
- B. The antiparticle of the proton is the antiproton, not the positron.
- D. Nucleons refer to protons and neutrons collectively, not the antiparticle of an electron.
Q90. When describing the isotopes of the same element, the most accurate statement is that they have:
- A. the same spin
- B. the same atomic mass but different atomic numbers
- C. the same atomic number but different atomic masses✓
- D. the same chemical properties and therefore can not be separated
- E. a coexistence limit, that is, no element can have more than three isotopes
Explanation: Those elements that have the same atomic number but a different mass number are referred to as isotopes.
Why the other options are wrong
- A. Isotopes with integer values of spin are very uncommon. So this is not an essential feature to define isotopes.
- B. The atoms of different elements having same mass number but different atomic number are known as isobars.
- D. They share almost the same chemical properties, but this is not an essential feature to define isotopes.
- E. There is no limit to number of isotopes an element can exhibit. For example: Tin has 10 isotopes.
Q91. In nuclear reactions, we have the conservation of:
- A. Mass Only
- B. Energy Only
- C. Momentum Only
- D. Mass-Energy and Momentum✓
Explanation: In a nuclear reaction, the total (relativistic) energy is conserved. It means that mass, energy and momentum all are conserved. The total momentum of the interacting particles before and after a reaction is the same
Why the other options are wrong
- A. In nuclear reactions , there is not only mass conservation but energy and momentum also conserve.
- B. In nuclear reactions, there is not only energy cinservation but momentum and mass also conserve.
- C. In nuclear reactions, there is not only momentum conservation but energy and mass also conserve.
Q92. The lightest element which exhibits radioactivity is:
- A. Hydrogen
- B. Deuteron
- C. Tritium✓
- D. Helium
Explanation: Tritium is the only radioactive isotope of hydrogen and the other two have stable nuclei. As hydrogen is the lightest element in the periodic table, tritium will be the lightest radioactive isotope in the periodic table.
Why the other options are wrong
- A. Hydrogen, specifically the most common isotope (protium), has a stable nucleus and is not radioactive.
- B. Deuteron, the nucleus of deuterium, is another stable isotope of hydrogen and is not radioactive.
- D. Helium, including its isotopes, does not exhibit natural radioactivity.
Q93. Nucleus with an excess of neutrons may decay radioactivity with the emission of:
- A. a neutron
- B. a proton
- C. an electron✓
- D. a positron
Explanation: When an unstable atomic nucleus has an excess of neutrons, it may undergo β− decay, where a neutron is converted into a proton and electron. This is why the correct answer is the emission of an electron. The other options, such as emitting a neutron, proton, or positron, do not align with the known decay processes of nuclei with excess neutrons.
Why the other options are wrong
- A. Nucleus with an excess of neutrons do not decay radioactivity with the emission of a neutron.
- B. Nucleus with an excess of neutrons do not decay radioactivity with the emission of a proton.
- D. Nucleus with an excess of neutrons do not decay radioactivity with the emission of a positron.
Q94. Which pair includes a vector quantity and a scalar quantity respectively?
- A. Power, speed
- B. Work, potential energy
- C. Displacement, acceleration
- D. Force, kinetic energy✓
Explanation: Force is vector quantity and kinetic energy is scalar quantity.
Why the other options are wrong
- A. Power & speed both are scalar quantities.
- B. Work & potential energy both are scalar quantities.
- C. Displacement and acceleration are vector quantities.
Q95. A ball falls vertically and bounces on the ground. The following statements are about the forces acting while the ball is in contact with the ground. Which statement is correct?
- A. The force that the ball exerts on the ground is always equal to the weight of the ball.
- B. The force that the ball exerts on the ground is always equal in magnitude and opposite in direction to the force the ground exerts on the ball.✓
- C. The force that the ball exerts on the ground is always greater than the weight of the ball.
- D. Both A and C
Explanation: According to Newton’s Third Law of Motion, when a ball falls and bounces on the ground, the force that the ball exerts on the ground is always equal in magnitude and opposite in direction to the force the ground exerts on the ball. This is why Option B is correct. Option A is incorrect because the forces involved are not constant and equal to the weight of the ball. Option C is incorrect as it erroneously claims that the force is always greater than the weight of the ball, which is not necessarily true. Option D is incorrect because it includes both incorrect statements from Options A and C.
Why the other options are wrong
- A. This statement is incorrect because the force exerted by the ball on the ground can vary depending on the collision dynamics. It is not constant and equal to the weight of the ball.
- C. This statement is incorrect because there is no requirement for the force to always be greater than the weight of the ball. The forces depend on the interaction and can vary.
- D. This option is incorrect because both Option A and Option C are incorrect. Neither statement accurately describes the forces according to Newton's Third Law.
Q96. A car is traveling with uniform acceleration along a straight road. The road has marker posts every 100 m. When the car passes one post, it has a speed of 10 m/s and when it passes the next one, its speed is 20 m/s. What is the car's acceleration?
- A. 0.67 m/s2
- B. 1.5 m/s2✓
- C. 2.5 m/s2
- D. 6.0 m/s2
Explanation: A car is travelling with uniform acceleration along a straight road. The road has marker posts every 100 m, d = 100 mInitial speed of the car, u = 10 m/sFinal speed of the car, v = 20 m/sLet a is the acceleration of the car. It is equal to the rate of change of velocity per unit time.
Why the other options are wrong
- A. Calculations show acceleration is 1.5m/s² . This makes option A incorrect.
- C. Calculations show acceleration is 1.5m/s² . This makes option C incorrect.
- D. Calculations show acceleration is 1.5m/s² . This makes option D incorrect.
Q97. A sample of an ideal gas may: expand adiabatically or expand isothermally. The net flow of heat into the gas from the exterior is:
- A. Positive in each case
- B. Negative for I and positive for II
- C. Positive for I and negative for II
- D. Zero in each case
- E. Zero in I and positive for II✓
Explanation: An adiabatic process is a thermodynamic process that involves the transfer of energy without transfer of heat or mass to the surrounding that it is zero in the case of I. While isothermal processes are those in which the temperature change is zero, that only implies the temperature change is zero, not the heat energy change.
Why the other options are wrong
- A. It will be zero in I and for II , it will be positive.
- B. It will be zero in I and for II, it will be positive.
- C. It will be zero in I and in II , it will be positive.
- D. It will be zero in only I and for II it is positive.
Q98. With the usual notation, the first law of thermodynamics applied to one mole of an ideal gas can be written in the following form:CVΔT=ΔQ - PΔVIn a change for which Boyle's law is obeyed, which of the following would necessarily be zero?
- A. ΔQ
- B. CV
- C. ΔT✓
- D. P
- E. ΔV
Explanation: Boyle's Law states that when the temperature of a given mass of confined gas is constant, the product of its pressure and volume is also constant. So for Boyles law to be observed change in temperature (∆T) must be equal to zero.
Why the other options are wrong
- A. Boyle's Lawhas nothing to do with the ∆Q . So, it will remain constant.
- B. Boyle's Law has nothing to do with the CV . So , it will remain constant.
- D. Boyle's Law states that when the temperature of a given mass of confined gas is constant, the product of its pressure and volume is also constant. So for Boyles law to be observed change in temperature (∆T) must be equal to zero.
- E. Boyle's Law states that when the temperature of a given mass of confined gas is constant, the product of its pressure and volume is also constant. So for Boyles law to be observed change in temperature (∆T) must be equal to zero.
Q99. Four particles independently move at the same speed in a direction perpendicular to the same magnetic field. Which particle is deflected the most?
- A. a copper ion
- B. a helium nucleus
- C. an electron✓
- D. a proton
Explanation: The deflection of a particle depends upon its mass to charge ratio. Since the mass of electron is too less as compared to its charge so it possesses maximum deflection. The electron would divert the most, the proton next and afterward the three particles. The amount they redirect relies upon their ionic states.
Why the other options are wrong
- A. The deflection of a particle depends upon its mass to charge ratio. Since the mass of electron is too less as compared to its charge so it possesses maximum deflection. The electron would divert the most, the proton next and afterward the three particles. The amount they redirect relies upon their ionic states.
- B. The deflection of a particle depends upon its mass to charge ratio. Since the mass of electron is too less as compared to its charge so it possesses maximum deflection. The electron would divert the most, the proton next and afterward the three particles. The amount they redirect relies upon their ionic states.
- D. The deflection of a particle depends upon its mass to charge ratio. Since the mass of electron is too less as compared to its charge so it possesses maximum deflection. The electron would divert the most, the proton next and afterward the three particles. The amount they redirect relies upon their ionic states.
Q100. The circuit diagram shows a network of resistors each of resistance R. What is the effective resistance between the points X and Y?
- A. 2R/7
- B. R/2
- C. 5R/8✓
- D. 2R/3
- E. 3R/4
Explanation: Top two resistors placed in series have resistance, R+R=2R1 /R=1 /R+1 /2R=>1/R=3 /2R=> R=2/3*R (for combination two series with one parallel,on topmost side of diagram)1 /R=1 /R+1 /2R=>1/R=3 /2R=> R=2/3*R (for combination two series with one parallel,on topmost side ofdiagram)⅔ R+R=>(5/3)*R (for upper branch), which is in parallel with R of lower branch1 /R=3 /5R+R=>1/R=8 /5R=> R=5/8R,HENCE C is the correct option
Why the other options are wrong
- A. Calculations show effective resistance is 5R/8 . So , A is incorrect option.
- B. Calculations show effective resistance is 5R/8. So , B is incorrect option.
- D. Calculations show 5R/8 is the value of effective resistance. So , D is incorrect option.
- E. Calculations show 5R/8 is the value of effective resistance.So , E is incorrect option.
More Sindh / DUHS Solved Papers
Biology
Sindh Botany 2018
38 solved MCQs
Biology
Sindh Botany 2019
32 solved MCQs
Biology
Sindh Botany 2021
27 solved MCQs
Biology
Sindh Botany 2022
21 solved MCQs
Biology
Sindh Botany 2024 Model Paper
22 solved MCQs
Chemistry
Sindh Chemistry 2018
39 solved MCQs
Chemistry
Sindh Chemistry 2019
43 solved MCQs
Chemistry
Sindh Chemistry 2021
56 solved MCQs
Chemistry
Sindh Chemistry 2022
54 solved MCQs