Home/Past Papers/Sindh / DUHS/Sindh Mdcat 2024

Sindh Mdcat 2024 — Solved Past Paper with Answers

All 200 MCQs from Sindh Mdcat 2024, solved with the correct answer highlighted and a full explanation for every question. This is a free MDCAT Sindh / DUHS past paper — no signup, no ads. Practise it interactively in timed mode, drill more with free MDCAT MCQs, or browse all Sindh / DUHS papers.

Attempt this paper interactively →

Q1. Spot the error in the given sentence:The stories that she makes up for the children ought to be written down and published.

  • A. For
  • B. Down
  • C. Ought
  • D. Stories
  • E. No error

Explanation: The sentence 'The stories that she makes up for the children ought to be written down and published.' is grammatically correct. Each component of the sentence, including the preposition 'for', the phrase 'written down', and the modal verb 'ought', is used appropriately. The structure of the sentence clearly conveys that the stories are intended for children and should be recorded and published. Therefore, there is no error in the sentence. The other options suggest components that are actually used correctly, which confirms that the sentence itself stands without error.

Why the other options are wrong
  • A. This option is incorrect. The preposition 'for' is used correctly to indicate the purpose of the stories.
  • B. This option is incorrect. The word 'down' is appropriately used as part of the phrase 'written down'.
  • C. This option is incorrect. The word 'ought' is used correctly in the context of expressing advisability.
  • D. This option is correct. Stories she makes is absolutely correct and correct phrase to be written.

Q2. Read the passage and choose the best option:As the big door swung behind me, I heard the sound of a roar of laughter that went up to the roof of the bank. Since then I use a bank no more. I keep my money in my pocket and my savings in silver dollars in a sock.Where did the writer put his savings in?

  • A. Pocket
  • B. Silver box
  • C. Bank
  • D. Sock

Explanation: Option D is correct, as the writer put his savings in socks.

Why the other options are wrong
  • A. Incorrect. The writer keeps money in his pocket but not his savings.
  • B. Incorrect. The passage mentions silver dollars, but not a silver box.
  • C. Incorrect. The writer states that he no longer uses the bank; hence, his savings are not kept there.

Q3. Choose the correct option:

  • A. He managed to write a letter to his son.
  • B. He was very ill, he managed to write a letter to his son.
  • C. He managed to write a letter to his son although he was very ill.
  • D. Although he was very ill, he managed to write a letter to his son.

Explanation: Option D is correct. This option is correct. This is the best option as it clearly states the condition first and shows that despite being ill, he still managed to write the letter, enhancing the contrast.

Why the other options are wrong
  • A. This sentence is correct but lacks context about his illness. It does not convey any information about his condition affecting the action of writing.
  • B. This option is incorrect. This option incorrectly uses a comma to join two independent clauses without a coordinating conjunction, making it a comma splice.
  • C. This option is incorrect. This sentence is correct but places "although" in a less preferred position. It still conveys the intended meaning effectively.

Q4. Read the passage below and choose the best option for the statement:John Keats (1795-1821) was born in London and educated at the Enfield School, where a sympathetic headmaster inspired his passion for literature. After leaving school, he qualified himself for surgery but abandoned it for poetry. He published his first volume of verse in 1817 and "Endymion" in 1818. 1818 was indeed a tragic year for Keats. His brother Tom, whom he nursed devotedly through his last illness, died of Tuberculosis. Soon after his brother's death, Keats himself developed symptoms of the same disease. In a vain attempt to save his health and life, some of Keats' friends arranged for him to go to Italy. He died and was buried at Rome. His death at an early age was perhaps the greatest disaster to befall English poetry.John Keats and his brother died of this disease:

  • A. Diabetes
  • B. Alzheimer's disease
  • C. Pneumonia
  • D. Tuberculosis
  • E. Tuberculosis

Explanation: Tuberculosis is correct. The passage states that both Keats' brother Tom and Keats himself died of tuberculosis.

Why the other options are wrong
  • A. Incorrect. There is no mention of diabetes as the cause of death in the passage.
  • B. Incorrect. The passage does not suggest Alzheimer's disease as the cause of death for either Keats or his brother.
  • C. Incorrect. The passage specifies that both Keats and his brother died of tuberculosis, not pneumonia.
  • D. Correct. The passage states that both Keats' brother Tom and Keats himself died of tuberculosis.

Q5. Choose the correct phrase for the sentence given below:The aeroplane travelled 5,000 meters before it took on.

  • A. Take into
  • B. Took off
  • C. Take over
  • D. Took away
  • E. Take on

Explanation: The correct answer is 'Took off'. This phrasal verb is commonly used to describe an airplane beginning its flight. The other options do not convey the intended action of an airplane starting to fly. 'Take into' is not a proper phrasal verb in this context, 'Take over' suggests assuming control, 'Took away' implies removal, and 'Take on' suggests assuming responsibility, none of which are suitable for the situation described in the sentence.

Why the other options are wrong
  • A. This option is incorrect. 'Take into' is not a standard phrasal verb and does not fit the context of an airplane's action.
  • C. This option is incorrect. 'Take over' typically implies assuming control or responsibility, which does not match the context of the sentence.
  • D. This option is incorrect. 'Took away' implies removal, which is not appropriate for an airplane's action in this context.
  • E. This option is incorrect. 'Take on' means to assume a task or responsibility, not suitable for describing an airplane taking flight.

Q6. Choose the best possible option from the given homophones:How will they get across the river if the _ is not running?

  • A. Furry
  • B. Fairly
  • C. Fairy
  • D. Ferry
  • E. Fury

Explanation: Option D is correct. This option is correct. Ferry is a boat or ship that carries people or goods across a body of water, making it the correct choice.

Why the other options are wrong
  • A. This option is incorrect. Furry refers to something covered in fur, which does not fit the context.
  • B. This option is incorrect. Fairly means reasonably or moderately, but it doesn't relate to crossing a river.
  • C. This option is incorrect. Fairy refers to a mythical being, which is also not relevant in this context.
  • E. This option is incorrect. Fury means intense anger, which does not pertain to crossing a river.

Q7. Choose the best possible antonym for the underlined word:The general's problem was to get 20,000 troops swiftly across this river.

  • A. Slowly
  • B. Thoroughly
  • C. Anxiously
  • D. Strongly

Explanation: Option A is correct. Slowly directly opposes "swiftly," meaning at a reduced speed or without haste.

Why the other options are wrong
  • B. This option is incorrect. Thoroughly means completely or in detail, which does not relate to speed.
  • C. This option is incorrect. Anxiously refers to a state of worry or concern, which is unrelated to the concept of speed.
  • D. This option is incorrect. Strongly means with great strength or intensity, which is also not an antonym for "swiftly".

Q8. Choose the correct sequenced option for the underlined words in the paragraph below:_ the invention of the personal computer and the internet, a new age in communications begins. _ people could communicate fastest and more easily than ever before. _, _ and storing information became quick and easy. It was no _ necessary to write draft after draft when changes could be made so easily using a _ processor program.

  • A. Longer - With - Faster - Writing - Editing - Word - Now
  • B. With - Now - Writing - Editing - Longer - Word - Faster
  • C. With - Now - Faster - Writing - Editing - Longer - Word
  • D. With - Now - Faster - Writing - Editing - Longer - Word

Explanation: Option D is the correct sequence as it maintains a coherent narrative flow. It begins with 'With the invention of the personal computer...', which clearly sets the stage for the advancements in communication. Following this, 'Now' emphasizes the current state of technology, while 'Faster' highlights the improvement in communication speed. The sequence continues logically with 'Writing' and 'Editing', which describe the ease associated with these tasks due to technological advancements.Finally, 'Longer' is used to contrast the previous complexity in writing drafts, and 'Word' processor wraps up the statement by referring to the specific technology that facilitates these changes.

Why the other options are wrong
  • A. This option begins with 'Longer', which disrupts the logical introduction of the paragraph. The sequence does not appropriately reflect the advancements in communication technology.
  • B. Although this option starts with 'With', the placement of 'Now' and 'Faster' is incorrect, disrupting the flow. 'Faster' should follow 'communicate', not 'Word'.
  • C. This sequence correctly starts with 'With', but places 'Now' too early, which disrupts the logical progression. 'Faster' should follow 'communicate', which it does, but the overall flow remains awkward.

Q9. The synonym of the word "Oblivion" is:

  • A. Forgetfulness
  • B. Observant
  • C. Neglect
  • D. Daunted

Explanation: The correct answer is Option A: Forgetfulness. 'Oblivion' refers to a state of being forgotten or the condition of being unaware or unconscious. 'Forgetfulness' captures this idea because it implies a lack of memory or awareness.Observant is incorrect because it means being attentive and aware.Neglect is incorrect because it refers to a lack of care, not a state of being forgotten.Daunted is incorrect as it relates to feeling intimidated or discouraged, not forgotten.

Why the other options are wrong
  • B. 'Observant' describes someone who is attentive and notices details around them. This word is the opposite of 'Oblivion,' as it suggests heightened awareness rather than being forgotten.
  • C. 'Neglect' refers to the failure to care for or give attention to something. While it may lead to 'oblivion,' it is not synonymous with the state of being forgotten.
  • D. 'Daunted' means feeling intimidated or discouraged. It is unrelated to 'Oblivion,' which deals with being forgotten or unaware.

Q10. Choose the best option:Some of the race teams were still looking for _ equipment.

  • A. Its
  • B. It's
  • C. There
  • D. Their
  • E. It

Explanation: Option D is correct. This option is correct. Their is the possessive form for "they," indicating that the equipment belongs to the race teams, making it the correct choice.

Why the other options are wrong
  • A. This option is incorrect. It s is a possessive form used for singular objects or animals, not for multiple people or groups. The sentence requires a pronoun that represents possession for the race teams.
  • B. This option is incorrect. It's is a contraction for 'it is' or 'it has,' neither of which makes sense in the context of the sentence.
  • C. This option is incorrect. There is used to indicate a place or location, which does not fit the possessive requirement of the sentence.
  • E. This option is incorrect. It is a singular pronoun and does not indicate possession, which is required in this context.

Q11. Read the passage and choose the best option:Nobody has ever been able to compute with any exactness how many people took part in the great rout of 1913, for the panic, which extended from the Winslow Bottling Works in the south and to Clintonville, six miles north, ended abruptly as it began. The shouting, weeping, tangled evacuation of the city lasted not more than two hours in all. Few people got as far east as Reynoldsburg, twelve miles away; fifty or more reached the Country Club, eight miles away; most of the others gave up, exhausted, or climbed trees in Franklin Park, four miles out.Most of the people gave up and climbed trees in:

  • A. Winslow Bottling Works
  • B. Clintonville
  • C. Country Club
  • D. Franklin Park

Explanation: The correct answer is Franklin Park because the passage specifically mentions that most of the people gave up and climbed trees there. The other options are areas mentioned as boundaries or destinations that only a few people reached, making them incorrect choices for where most people ended up.

Why the other options are wrong
  • A. This option is incorrect. The passage mentions the Winslow Bottling Works as the southern boundary of the panic, not where people ended up.
  • B. This option is incorrect. Clintonville is mentioned as the northern boundary of the panic, not the final destination of the evacuees.
  • C. This option is incorrect. While some people reached the Country Club, it was not where most ended up.

Q12. Choose the correct prepositional phrase for the sentence given below:In today's session, he _the current situation of Pakistan.

  • A. Suffers from
  • B. Belongs to
  • C. Begs for
  • D. Compares with
  • E. Comments on

Explanation: This is correct because "comment on" is the right phrase used when someone is expressing their opinion or making a statement about something, like a situation.

Why the other options are wrong
  • A. This would be used if someone is enduring or experiencing pain or hardship, which doesn't fit the context of discussing a situation.
  • B. This phrase is used to indicate ownership or membership, and it doesn’t make sense in this context.
  • C. This implies asking or pleading for something desperately, which is unrelated to the action of discussing or analyzing a situation.
  • D. While this could technically be used if the sentence were rephrased (e.g., "he compares the current situation with something else"), it is not the right fit for simply commenting on or discussing the situation.

Q13. Spot the error in the given sentence:The bushes on the corner make it difficult for the driver to see the traffic approaching from the write.

  • A. Write
  • B. For
  • C. Make
  • D. Approaching
  • E. Bushes

Explanation: Option A is correct. This option is correct. Write is a misspelling of right, which refers to the direction from which the traffic is approaching. The correct word should be "right" instead of "write."

Why the other options are wrong
  • B. This is correct because "for the driver" correctly indicates the difficulty faced by the driver due to the bushes. There is no grammatical or contextual mistake with this word.
  • C. This is correct because "make it difficult" is a proper construction, meaning that the bushes cause difficulty for the driver. There is no error in this word.
  • D. This is correct because "approaching traffic" correctly describes the movement of vehicles coming from the right. The word is used appropriately in the sentence.
  • E. This is correct because "bushes" properly refers to the plants that obstruct the driver's view. There is no mistake with this word.

Q14. Punctuate the following sentence:He said will you have time to play regularly

  • A. He said,"Will you have time to play regularly?"
  • B. He said, Will you have time to play regularly?
  • C. He said, "Will you have time to play regularly."
  • D. He said "Will you have time to play regularly'.
  • E. He said, 'Will you have time to play regularly'.

Explanation: Option C is correct. This option is correct. This option is correct as it uses the proper quotation marks and punctuation for a direct question.

Why the other options are wrong
  • B. This option is incorrect. This option is incorrect because it lacks quotation marks around the spoken question.
  • C. This option is inorrect. This option is incorrect because it uses a period instead of a question mark.
  • D. This option is incorrect. This option is incorrect because it lacks a comma before the quotation and uses mismatched quotation marks.
  • E. This option is incorrect. This option is incorrect because it uses single quotation marks and a period instead of a question mark.

Q15. Complete the main clause of the following sentence:If I went to Paris, _

  • A. I can see the Eiffel Tower
  • B. I must see the Eiffel Tower
  • C. I should see the Eiffel Tower
  • D. I could see the Eiffel Tower
  • E. I would see the Eiffel Tower

Explanation: "If I went" is a past subjunctive, used to express a hypothetical or unreal condition. The appropriate verb to match this tense is "would", which indicates a possible outcome in that hypothetical situation.

Why the other options are wrong
  • A. "I can see the Eiffel Tower": "Can" is present tense and does not match the past subjunctive "went." It refers to an ability in the present, not a hypothetical situation.
  • B. "I must see the Eiffel Tower": "Must" implies obligation or necessity, which doesn't fit the hypothetical nature of the conditional sentence.
  • C. "I should see the Eiffel Tower": "Should" implies advice or a recommendation, but it doesn't match well with the past subjunctive form "went."
  • D. "I could see the Eiffel Tower": While grammatically possible, "could" implies possibility or ability, but "would" fits better for expressing what would actually happen in the hypothetical scenario.

Q16. Correct the spelling & capitalization errors in the paragraph below:It was in korea, june 1953. I had been wounded, and they had strapt me on a stretcher and dumped me by the roadside to wait for an ambulance, if I didn't pegg out first. I wanted to die anyway. I had nothing to live for. The pain was pretty bad, I guess I fainted. When I came to, there was a korean girl sitting beside me. She was about fourteen; not pretty, of course; but friendly blue eyes and long plates hanging in front of her shoulders. She didn't say anything. She just smiled. And I smiled back.

  • A. Korea - Pretty - Fainted-Korean - Sitting - Blue - Plaits - Shoulders
  • B. Strapped - Roadside - Peg - Pretty - Fainted - Korean - Sitting - Blue - Plaits - Shoulders
  • C. Korea - Strapped - June - Peg - Pretty - Fainted - Korean - Sitting - Blue - Plaits - Shoulders
  • D. Korea - Strapped - Roadside - Peg - Sitting - Blue - Plaits - Shoulders
  • E. Korea - June - Strapped - Pretty - Blue - Plaits - Shoulders

Explanation: Korea and June: These are proper nouns and need to be capitalized.Peg: The phrase "peg out" is a colloquial expression meaning "die," and "peg" is correctly used.Pretty: "Pretty" needs to be capitalized because it is in the middle of the sentence following a semicolon.Fainted: This should be in lowercase, unless it's at the start of a sentence. Here it is correctly used.Korean: As an adjective describing nationality, it needs to be capitalized.Sitting: This is correctly capitalized since it's after a period and begins a sentence.Blue: A color adjective, it should be lowercase unless starting a sentence.Plaits: "Plaits" (braids) is the correct spelling instead of "plates."Shoulders: Correctly used, describing where the plaits hang.

Why the other options are wrong
  • A. "Strapped" is missing as a correction for "strapt.""June" should be capitalized but is missing from this option.
  • B. "Korea" and "June" are not corrected; both should be capitalized."Roadside" does not need correction.
  • D. "June" is not corrected, and it should be capitalized."Pretty" is not corrected, and it should be capitalized."Fainted" is missing.
  • E. "Fainted" and "Korean" are missing corrections.

Q17. Choose the correct form of the tense:I would gladly have helped him if he _me into confidence.

  • A. Took
  • B. Has taken
  • C. Had taken
  • D. Have taken
  • E. Takes

Explanation: This is the correct form because it is in the past perfect tense, which is used to indicate an action that was completed before another past action (in this case, the helping). The phrase sets up a conditional situation that did not occur in the past.

Why the other options are wrong
  • A. This is the simple past tense, but it does not convey the prior completion of the action relative to another past action. It lacks the necessary nuance of the hypothetical condition
  • B. This is also present perfect, used with a singular subject in the present tense. Similar to "have taken," it does not fit the past conditional context of the sentence.
  • D. This form is present perfect, which indicates an action that has relevance to the present. It does not convey the necessary past context needed for this conditional sentence.
  • E. This is in the present simple tense, which does not fit the context of a hypothetical situation in the past. It implies a current or habitual action, which is not appropriate here.

Q18. Fill in the blank with the appropriate preposition. The thief made an escape by _.

  • A. Climbing up the wall
  • B. Climbing on the wall
  • C. Climbing to the wall
  • D. Climbing over the wall
  • E. Climbing into the wall

Explanation: "Climbing over the wall" indicates that the thief physically ascended the wall and then descended or moved beyond it, which aligns with the idea of escaping.Only "Climbing over the wall" effectively conveys the action of the thief successfully escaping by moving beyond the wall. The other options either limit the action to climbing without implying escape or suggest inappropriate directions or actions.

Why the other options are wrong
  • A. This phrase suggests that the thief is only ascending the wall. It implies that they reached the top but does not convey the action of escaping or moving beyond the wall.
  • B. This suggests that the thief is on the surface of the wall, possibly balancing or standing on it. It does not imply any movement beyond the wall or an action that would facilitate an escape.
  • C. This implies that the thief is moving toward the wall but does not indicate any action of climbing over or beyond it. It suggests a destination rather than an action leading to escape.
  • E. This implies that the thief is entering the wall, which doesn’t make sense in the context of escape. "Into" suggests going inside or becoming part of the wall, rather than escaping by going over it.

Q19. Stimuli such as pressure, touch, stretch, and motion stimulate which of the following receptors?

  • A. Thermoreceptors
  • B. Mechanoreceptors
  • C. Gustatory receptors
  • D. Olfactory receptors

Explanation: Mechanoreceptors are sensory receptors that respond to mechanical stimuli, such as pressure, touch, vibration, and stretch. They are found in the skin, muscles, and internal organs and play a crucial role in the sense of touch and proprioception (awareness of body position).

Why the other options are wrong
  • A. Thermoreceptors are sensory receptors in the body that detect temperature changes. They help regulate body temperature by responding to heat and cold, sending signals to the brain to initiate appropriate responses, such as sweating or shivering.
  • C. Gustatory receptors are specialized cells located on the tongue's taste buds that detect chemical substances in food and drinks. They are responsible for the sense of taste and identify five primary tastes: sweet, sour, salty, bitter, and umami.
  • D. Olfactory receptors are specialized sensory cells in the nasal cavity that detect airborne chemical molecules. They play a crucial role in the sense of smell, allowing the brain to identify and differentiate various odors.

Q20. The situation when two alternative forms are expressed completely is said to have:

  • A. Codominance
  • B. Sex-influenced traits
  • C. Multiple alleles
  • D. Incomplete dominance
  • E. Sex-limited traits

Explanation: Codominance is a genetic scenario where both alleles in a heterozygous individual are fully expressed, leading to a phenotype that exhibits traits from both alleles. For instance, in certain flowers, one allele may be responsible for producing red petals while another produces white petals; in the case of codominance, the resulting flowers can display both red and white petals concurrently.

Why the other options are wrong
  • B. "Sex-influenced traits are characteristics that are expressed differently in males and females, even though they are determined by the same gene. For instance, the presence of a specific allele may cause a trait to be dominant in one sex and recessive in the other. A common example is baldness, which tends to be more pronounced in men than in women.
  • C. Multiple alleles refer to a situation where a gene has more than two alternative forms (alleles) in a population. While an individual can only have two alleles for that gene (one from each parent), the presence of multiple alleles increases genetic diversity. A classic example is the ABO blood group system in humans, where the A, B, and O alleles determine blood type.
  • D. Incomplete dominance is a genetic situation where the phenotype of a heterozygous individual is an intermediate blend of the phenotypes of the two homozygous parents. For example, when a red flower (RR) is crossed with a white flower (WW), the offspring (RW) may have pink flowers, illustrating the blending of traits rather than full dominance of one allele over the other.
  • E. Sex-limited traits are characteristics that are expressed in only one sex, even though both sexes carry the genes for the trait. These traits are often influenced by sex hormones. A common example is milk production in dairy cows, which occurs only in females, despite both males and females having the genes associated with lactation.

Q21. The bacterium, with a tuft of flagella present at each of the two poles, is called:

  • A. Amphitrichous
  • B. Lophotrichous
  • C. Peritrichous
  • D. Monotrichous

Explanation: Amphitrichous refers to a type of bacterial flagellation where a single flagellum is present at both ends of the cell. This arrangement allows for movement in both directions, giving the bacteria greater mobility and versatility in navigating their environment.

Why the other options are wrong
  • B. Lophotrichous refers to a type of bacterial flagellation where multiple flagella are located at one or both ends of the cell. This arrangement enhances motility, allowing the bacteria to swim more effectively in their environment.
  • C. Peritrichous describes bacteria that have flagella distributed all around their surface. This arrangement allows for effective and versatile movement, enabling the bacteria to swim in various directions.
  • D. Monotrichous refers to bacteria that have a single flagellum at one end of the cell. This simple structure allows for directed movement, enabling the bacteria to swim efficiently in one direction.

Q22. What is the correct order of organelles in ultracentrifugation?

  • A. Ribosome → Nuclei → Mitochondria
  • B. Lysosome → Ribosome → Mitochondria
  • C. Nuclei→ Mitochondria
  • D. Mitochondria → Nuclei → Golgi bodies
  • E. Ribosome → Nuclei → Golgi bodies

Explanation: The correct order of organelles in ultracentrifugation, based on their size and density, is as follows: 1. Nuclei 2. Mitochondria Here's the explanation: Nuclei are the largest and heaviest organelles, so they sediment first. Mitochondria, while smaller than nuclei, are still quite dense, which is why they sediment next. Smaller and less dense organelles, such as ribosomes and Golgi bodies, sediment later at higher centrifugal forces.

Why the other options are wrong
  • A. This order is incorrect because ribosomes are the smallest and lightest organelles, so they sediment last, not first.In ultracentrifugation, heavier organelles (like nuclei) settle first, followed by medium ones (like mitochondria), and finally smaller particles (like ribosomes).
  • B. This order is incorrect. Lysosomes and ribosomes are smaller than mitochondria and cannot sediment before them.Mitochondria, being denser and larger, sediment earlier than both lysosomes and ribosomes.
  • D. This order is incorrect because mitochondria cannot sediment before nuclei.Nuclei always sediment first due to their greater mass and density.
  • E. This order is completely wrong.Ribosomes are the smallest, so they sediment last, not first.Golgi bodies are also lighter than mitochondria and nuclei, so they come even later in the process.

Q23. A peptide hormone released from Sertoli cells that inhibits the secretion of FSH is:

  • A. Testosterone
  • B. GnRH
  • C. FSH
  • D. Inhibin
  • E. Luteinizing hormone

Explanation: Inhibin is a hormone produced by the gonads (ovaries in females and testes in males) that inhibits the secretion of follicle-stimulating hormone (FSH) from the pituitary gland. It helps regulate reproductive functions by providing feedback to control the levels of FSH, thereby playing a role in regulating sperm production in males and follicle development in females.

Why the other options are wrong
  • A. Testosterone is a hormone primarily produced in the testes in males and the ovaries in females, with smaller amounts produced in the adrenal glands. It plays a key role in developing male sexual characteristics, muscle mass, and bone density, and also influences mood and energy levels in both genders.
  • B. Gonadotropin-releasing hormone (GnRH) is a hormone produced in the hypothalamus that stimulates the release of luteinizing hormone (LH) and follicle-stimulating hormone (FSH) from the pituitary gland. These hormones are crucial for regulating reproductive functions, including ovulation in females and testosterone production in males.
  • C. Follicle-stimulating hormone (FSH) is a hormone produced by the pituitary gland that plays a key role in regulating the reproductive processes. In females, it stimulates the growth and maturation of ovarian follicles, while in males, it supports sperm production in the testes. FSH is essential for normal fertility in both genders.
  • E. Luteinizing hormone (LH) is a hormone produced by the pituitary gland that plays a crucial role in the reproductive system. In females, it triggers ovulation and the development of the corpus luteum, which produces progesterone. In males, LH stimulates the testes to produce testosterone. LH is essential for normal reproductive function in both genders.

Q24. Name the protein complex that stabilizes the separated strand of DNA during replication:

  • A. Double Stranded binding proteins
  • B. Double-stranded binding enzymes
  • C. Single-stranded binding proteins
  • D. Single-stranded binding enzyme

Explanation: Single-stranded (SSBs) are proteins that bind to single-stranded DNA during processes such as DNA replication and repair. They stabilize the unwound DNA strands, preventing them from re-annealing or forming secondary structures. By keeping the strands separate, SSBs allow other enzymes, like DNA polymerases, to access the DNA for replication and repair.

Why the other options are wrong
  • A. Double-stranded binding proteins (DSBPs) are proteins that bind to double-stranded DNA, stabilizing it and preventing it from unwinding. They play a crucial role in various cellular processes, including DNA replication, repair, and transcription. By protecting DNA from degradation and assisting in its organization, DSBPs help maintain genomic integrity.
  • B. Double-stranded binding enzymes are proteins that interact with double-stranded DNA to facilitate processes like replication, repair, and recombination. They often help to unwind or manipulate DNA strands, ensuring proper access for other enzymes, such as polymerases and helicases. These enzymes are essential for maintaining DNA stability and supporting cellular functions related to genetic material.
  • D. Single-stranded binding enzymes typically refer to proteins that bind to single-stranded DNA to stabilize it during various cellular processes, such as replication and repair. While "enzyme" might imply a catalytic function, SSBs primarily have a stabilizing role rather than a catalytic one. They help prevent the re-formation of double-stranded DNA and assist other enzymes in accessing the DNA for replication or repair.

Q25. Which of the following is not essential for photosynthesis?

  • A. Oxygen
  • B. Chlorophyll
  • C. ATP
  • D. Light

Explanation: Oxygen is a chemical element (symbol O) essential for life on Earth. It is a colorless, odorless gas that makes up about 21% of the Earth's atmosphere. Oxygen is crucial for cellular respiration in most organisms, allowing them to produce energy by converting glucose and other nutrients. It also plays a key role in combustion and is involved in various chemical reactions.

Why the other options are wrong
  • B. Chlorophyll is a green pigment found in plants, algae, and some bacteria that is essential for photosynthesis. It absorbs light energy, primarily from the blue and red parts of the spectrum, and converts it into chemical energy by facilitating the conversion of carbon dioxide and water into glucose and oxygen. Chlorophyll gives plants their green color and is crucial for their growth and energy production.
  • C. Adenosine triphosphate (ATP) is a molecule that serves as the primary energy currency of cells. It consists of adenine, ribose, and three phosphate groups. ATP stores energy in its high-energy phosphate bonds, which is released when the bonds are broken. This energy powers various cellular processes, including muscle contraction, protein synthesis, and cell division.
  • D. Light is a form of electromagnetic radiation that is visible to the human eye. It travels in waves and is composed of photons. Light plays a crucial role in various processes, such as photosynthesis in plants, vision in animals, and communication in technologies like fiber optics. It has properties of both waves and particles, a phenomenon known as wave-particle duality.

Q26. Which size of sponge can filter an entire residential pool in one day?

  • A. Tennis ball-sized
  • B. Ladle-sized
  • C. Basketball-sized
  • D. Hockey ball-sized
  • E. Teaspoon-sized

Explanation: The correct answer is Option C: Basketball-sized. This size of sponge provides the necessary surface area and volume to handle the filtration of a large body of water, such as a residential pool, in a single day. Smaller sponges, like those the size of a tennis ball, ladle, hockey ball, or teaspoon, do not have sufficient capacity to filter such a large volume effectively within 24 hours.

Why the other options are wrong
  • A. While a tennis ball-sized sponge may have some filtering capability, its limited surface area and volume are insufficient to filter the large volume of water in an entire residential pool within a day.
  • B. A ladle-sized sponge is too small to effectively filter the entire volume of water in a residential pool within a day, as it lacks the necessary surface area and capacity.
  • D. Similar to the tennis ball-sized option, a hockey ball-sized sponge does not possess enough surface area or volume to filter an entire pool's water effectively in one day.
  • E. A teaspoon-sized sponge is far too small to have any significant impact on filtering the vast amount of water found in a residential pool within a day.

Q27. Proteins that cause disease in humans and animals are called:

  • A. Prions
  • B. Viroid
  • C. Prophage
  • D. Bacteriophage
  • E. Antigens

Explanation: Prions are misfolded proteins that can induce other proteins to also misfold, leading to the accumulation of abnormal protein structures in cells. This can result in neurodegenerative diseases, such as Creutzfeldt-Jakob disease in humans and mad cow disease in cattle. Prions are unique because they can propagate without nucleic acids (DNA or RNA), making them distinct from other infectious agents like bacteria and viruses.

Why the other options are wrong
  • B. Viroids are small, circular RNA molecules that can infect plants. Unlike viruses, viroids do not have a protein coat and consist solely of RNA. They are capable of replicating within plant cells and can disrupt normal cellular processes, leading to various plant diseases. Viroids are the simplest known infectious agents and are primarily associated with agricultural impact.
  • C. A prophage is a dormant form of a bacteriophage (a virus that infects bacteria) that has integrated its genetic material into the host bacterium's genome. In this state, the prophage can be replicated along with the host DNA during cell division without causing harm. Under certain conditions, the prophage can become activated, excise itself from the host genome, and enter the lytic cycle, leading to the production of new viral particles and eventual cell lysis.
  • D. A bacteriophage, or phage, is a type of virus that specifically infects bacteria. It consists of genetic material (either DNA or RNA) surrounded by a protein coat. Bacteriophages attach to bacterial cells, inject their genetic material, and can either enter a lytic cycle, resulting in the destruction of the host cell, or a lysogenic cycle, where the phage DNA integrates into the bacterial genome and remains dormant. Bacteriophages are important tools in molecular biology and have potential applications in treating bacterial infections.
  • E. Antigens are substances that provoke an immune response in the body, typically recognized as foreign. They can be proteins, carbohydrates, or other molecules found on the surface of pathogens (like bacteria and viruses), allergens, or even cancer cells. When an antigen enters the body, it can stimulate the production of antibodies, which are proteins that specifically target and neutralize the antigen, helping to protect the body from disease.

Q28. Koshland proposed a model for enzymes with the name of "induced fit model" in the year:

  • A. 1959
  • B. 1952
  • C. 1954
  • D. 1956
  • E. 1949

Explanation: Koshlan proposed the "Induced Fit Model" of enzyme action in the year 1959.

Why the other options are wrong
  • B. Incorrect. No such enzyme model was introduced in 1952. During this time, the lock and key model by Emil Fischer (1894) was still the dominant explanation, not Koshland’s induced fit model.
  • C. Incorrect. Although enzymology was an active field in the 1950s, the induced fit concept was not introduced until 1959. No significant enzyme theory publication by Koshland appeared in 1954.
  • D. Incorrect. This predates Koshland’s formal proposal of the induced fit model. In the mid-1950s, enzyme-substrate interaction was still explained mainly by the lock and key theory.
  • E. Incorrect. This is too early; Koshland’s model had not been developed yet. The induced fit model was only formulated in 1959 based on emerging biochemical evidence and protein flexibility studies.

Q29. Why do ribosomes require Mg²+ ions?

  • A. To synthesize protein
  • B. To transport amino acid to ribosome
  • C. To stabilize the ribosomal structure
  • D. To develop mRNA molecules
  • E. To break down RNA molecules

Explanation: Ribosomes are complex structures made of RNA and proteins. The RNA molecules have a lot of negative charges due to their phosphate backbone. Mg²⁺ ions help to neutralize these charges, acting like a "glue" to hold the different components of the ribosome together. This stability is crucial for the ribosome to function properly

Why the other options are wrong
  • A. Ribosomes need Mg²⁺ ions mainly to stabilize their structure. These ions help the large and small ribosomal subunits stay joined, allowing the ribosome to function properly. Mg²⁺ also maintains the correct folding of rRNA, which is essential for accurate translation. Without enough Mg²⁺, the ribosome becomes unstable and cannot work efficiently.
  • B. Transfer RNA carries specific amino acids from the cytoplasm to the ribosome during protein synthesis. Each tRNA has an anticodon that pairs with the corresponding codon on mRNA, ensuring the correct amino acid is added. As the ribosome moves along the mRNA, tRNA molecules keep delivering amino acids in sequence. This process helps form a growing polypeptide chain accurately.
  • D. This statement is correct. Transcription is the process in which DNA serves as a template to produce mRNA molecules. During this process, RNA polymerase binds to DNA and assembles complementary RNA nucleotides. The newly formed mRNA carries the genetic code from the nucleus to the ribosome. This allows the cell to use DNA instructions for protein synthesis.
  • E. This statement is correct. RNA degradation is the process through which cells break down RNA molecules that are damaged, no longer needed, or incorrectly formed. Specialized enzymes such as RNases cut the RNA into smaller fragments. This helps regulate gene expression by controlling how long RNA molecules stay active. It also maintains cellular balance by removing unwanted or excess RNA.

Q30. Hemoglobin fails to carry sufficient oxygen, leading to the death of a person then Glutamic acid is replaced by valine at which position?

  • A. 3rd position
  • B. 6h position
  • C. 5th position
  • D. 4th position

Explanation: The sixth position of the beta globin chain of the hemoglobin molecule is where glutamic acid is replaced by valine.

Why the other options are wrong
  • A. This is incorrect because in sickle cell anemia, the mutation does not occur at the 3rd position of the beta-globin chain. The substitution of valine for glutamic acid specifically happens at the 6th position.
  • C. This is incorrect because the mutation responsible for sickle cell disease does not occur at the 5th position of the beta-globin chain. Instead, it is the 6th amino acid in the sequence that is affected.
  • D. This is incorrect because no pathological hemoglobin disorder is associated with a mutation at the 4th position of the beta-globin chain. The sickle cell mutation specifically affects the 6th position.

Q31. The formation of hard uric acid crystals in the joints is identified as:

  • A. Rheumatoid arthritis
  • B. Ankylosing spondylitis
  • C. Osteoarthritis
  • D. Callus
  • E. Gout

Explanation: Gout is a form of inflammatory arthritis caused by the buildup of uric acid crystals in the joints.

Why the other options are wrong
  • A. Rheumatoid arthritis (RA) is an autoimmune disorder that primarily affects joints, causing inflammation, pain, and stiffness.
  • B. Ankylosing spondylitis (AS) is a type of inflammatory arthritis that primarily affects the spine and can lead to fusion of the vertebrae.
  • C. Osteoarthritis (OA) is a degenerative joint disease characterized by the breakdown of cartilage, leading to pain and stiffness.
  • D. A callus refers to the healing tissue that forms around a fracture during the bone healing process.

Q32. Which virus kills cancer cells and aids immunity?

  • A. Saccharomyces
  • B. Lactobacillus
  • C. Penicillium
  • D. Lymph Bacterium
  • E. Oncolytic

Explanation: Oncolytic viruses are viruses designed or naturally able to infect and destroy cancer cells while sparing normal tissue. They enter tumor cells, replicate inside them, and eventually cause those cells to break apart, which helps shrink the tumor and also alerts the immune system to attack remaining cancer cells.

Why the other options are wrong
  • A. Saccharomyces is a genus of fungi known mainly for its role in fermentation. Species such as Saccharomyces cerevisiae break down sugars to produce alcohol and carbon dioxide, which makes them important in baking, brewing, and winemaking.
  • B. Lactobacillus is a genus of bacteria that plays an important role in maintaining a healthy gut and supporting overall wellbeing. These bacteria help produce lactic acid, which keeps harmful microbes in check, aids digestion, and supports a balanced microbiome. They’re commonly found in yogurt, fermented foods, and probiotic supplements.
  • C. Penicillium is a genus of fungi known for its role in natural decomposition and in the production of antibiotic
  • D. The term “lymph bacterium” usually points to lymphogranuloma venereum (LGV), which is a sexually transmitted infection caused by specific strains of Chlamydia trachomatis. It mainly affects the lymphatic tissue in the genital area and can lead to swollen, painful lymph nodes if not treated.

Q33. The pigment in the muscles responsible for the binding of oxygen is:

  • A. Oxyhemoglobin
  • B. Plasmin
  • C. Myoglobin
  • D. Heme
  • E. Hemoglobin

Explanation: Myoglobin is a protein found in muscle tissue that binds oxygen.

Why the other options are wrong
  • A. Oxyhemoglobin transports oxygen to tissues throughout the body, releasing it where it's needed for cellular respiration and energy production
  • B. Plasmin is an enzyme that plays a key role in the process of fibrinolysis, which is the breakdown of blood clots
  • D. Heme is a complex molecule that contains an iron ion (Fe) at its center, surrounded by a porphyrin ring.
  • E. Hemoglobin is a protein found in red blood cells that binds and transports oxygen from the lungs to tissues throughout the body

Q34. In Gram -ve bacteria, the peptidoglycan layer is:

  • A. Condensed
  • B. Thick
  • C. Moderate
  • D. Thin
  • E. Entangled

Explanation: In gram-negative bacteria, the peptidoglycan layer is relatively thin compared to gram-positive bacteria.

Why the other options are wrong
  • A. This is incorrect because the peptidoglycan layer in Gram-negative bacteria is not tightly packed or condensed. Instead, it is thin and loosely arranged between the inner and outer membranes.
  • B. In Gram-positive bacteria, the layer of peptidoglycan is thick and located outside the cell membrane.
  • C. This is incorrect because, compared to Gram-positive bacteria, the peptidoglycan layer in Gram-negative bacteria is much thinner. The term "moderate" is not an accurate description of its structure.
  • E. This is incorrect because the peptidoglycan layer in Gram-negative bacteria is not entangled but rather forms a thin, mesh-like structure between the membranes.

Q35. The human enzymes are highly active at about:

  • A. 8°C
  • B. 15°C
  • C. 37°C
  • D. 45°C
  • E. 55°C

Explanation: The optimum temperature for enzyme action in humans is typically around 37°C (98.6°F), which is the normal body temperature. At this temperature, enzymes generally exhibit the highest activity.

Why the other options are wrong
  • A. This temperature is too low for human enzymes. At such cold conditions, enzyme activity drops sharply because molecular movement slows down, reducing the chances of enzyme–substrate collisions. Hence, enzymes become almost inactive.
  • B. Still too low for normal enzymatic activity in humans. Some enzymes may show minor activity, but this is far below their optimum level. At 15°C, metabolic reactions occur much slower than normal.
  • D. At this temperature, enzyme activity begins to decline, and enzymes may start to denature (lose their shape). The active site changes structure, reducing the enzyme’s ability to bind substrates effectively.
  • E. This temperature is too high. Most human enzymes become denatured and inactive at this point. The protein structure unravels, permanently damaging the active site and stopping enzyme function.

Q36. The locomotion in segmented worms is brought about by:

  • A. True Pods
  • B. Pseudopodia
  • C. Setae
  • D. Peritrichous flagella

Explanation: Locomotion in segmented worms, such as earthworms, occurs through a combination of muscular contractions and the movement of their bristle-like structures called setae. These worms have circular and longitudinal muscles that work together to elongate and shorten the body.

Why the other options are wrong
  • A. "True pods" in the context of worms, particularly in relation to the phylum Annelida (which includes earthworms and other segmented worms), refer to a type of reproductive structure. Some species of worms produce true pods, or egg cases, that protect their developing embryos
  • B. Pseudopodia are temporary, foot-like extensions of a cell's cytoplasm used for movement and feeding. Found in certain protozoa (like amoebas) and some immune cells, pseudopodia allow these cells to crawl along surfaces or engulf food particles through a process called phagocytosis.
  • D. Peritrichous flagella refer to a type of flagellar arrangement in bacteria where multiple flagella are distributed all around the bacterial cell surface. This arrangement allows for greater mobility and more complex movement patterns compared to polar flagella, which are located at one or both ends of the cell.

Q37. The type of carbohydrates, made up of 6 to 10 monosaccharides, which are comparatively less sweet in taste and less soluble in water, are called:

  • A. Oligosaccharides
  • B. Monosaccharides
  • C. Starch
  • D. Cellulose
  • E. Polysaccharides

Explanation: Oligosaccharides are carbohydrates composed of a small number (typically 2 to 10) of monosaccharide units linked together by glycosidic bonds. They can be found in various foods and are important for human health, serving as prebiotics that promote gut health and supporting immune function. Oligosaccharides are often found in legumes, onions, and garlic, and they can contribute to the flavor and texture of food.

Why the other options are wrong
  • B. Monosaccharides are the simplest form of carbohydrates, consisting of single sugar molecules. Common examples include glucose, fructose, and galactose. They serve as basic building blocks for more complex carbohydrates like disaccharides and polysaccharides. Monosaccharides are crucial for energy production in living organisms and are readily absorbed into the bloodstream, providing a quick source of energy.
  • C. Starch is a complex carbohydrate made up of long chains of glucose molecules. It serves as a major energy storage form in plants, found in roots, tubers, and seeds. Starch is composed of two components: amylose (linear chains) and amylopectin (branched chains). When consumed, starch is broken down into glucose by digestive enzymes, providing a sustained source of energy for humans and other animals.
  • D. Cellulose is a complex carbohydrate and a key structural component of plant cell walls. It is composed of long chains of glucose molecules linked by beta-glycosidic bonds, forming a rigid, fibrous structure. Cellulose is not digestible by humans but serves as an important source of dietary fiber, promoting digestive health. It provides strength and support to plants, helping them maintain their shape and resist external pressures.
  • E. Polysaccharides are complex carbohydrates made up of long chains of monosaccharide units linked together by glycosidic bonds. They can be linear or branched and serve various functions in living organisms. Common examples include starch (energy storage in plants), glycogen (energy storage in animals), and cellulose (structural support in plant cell walls). Polysaccharides are important for energy storage, providing structural integrity, and serving as a source of dietary fiber.

Q38. The technique is used to determine the growth of bacteria, rate of photosynthesis, and minute quantity of DNA:

  • A. Electrophoresis
  • B. Micrometry
  • C. Microscopy
  • D. Chromatography
  • E. Spectrophotometry

Explanation: Spectrophotometry is a quantitative analytical technique used to measure the absorbance or transmittance of light by a substance. It relies on the principle that different substances absorb light at specific wavelengths, allowing for identification and quantification.

Why the other options are wrong
  • A. Electrophoresis is a laboratory technique used to separate charged molecules, such as DNA, RNA, or proteins, based on their size and charge. During electrophoresis, a sample is placed in a gel or liquid medium and an electric field is applied. Charged molecules migrate towards the electrode with the opposite charge; negatively charged molecules move toward the positive electrode, while positively charged molecules move toward the negative electrode.
  • B. Micrometry is the measurement of small distances or dimensions, typically at the microscopic scale. It involves using a microscope equipped with a micrometer scale, which allows precise measurement of the size of small objects, cells, or structures that cannot be easily measured with standard rulers.
  • C. Microscopy is the technique of using microscopes to view and study small objects, structures, or organisms that are not visible to the naked eye.
  • D. Chromatography is a laboratory technique used to separate and analyze mixtures of substances based on their different interactions with a stationary phase and a mobile phase. It relies on the principle that different compounds will travel through a medium at different rates.

Q39. Which of the following is an example of a sub-viral particle that infects plants?

  • A. Prion
  • B. Viroid
  • C. Bacteriophage
  • D. Infectious protein

Explanation: Viroids are small, circular RNA molecules that can infect plants. They lack a protein coat and do not encode proteins, relying on the host's cellular machinery for replication. Viroids are responsible for various plant diseases, disrupting normal growth and development

Why the other options are wrong
  • A. Prions are misfolded proteins that can induce abnormal folding in normal proteins, leading to neurodegenerative diseases. They are infectious, lack nucleic acids, and are resistant to heat and chemical sterilization. Examples include Creutzfeldt-Jakob disease and mad cow disease.
  • C. Bacteriophages, or phages, are viruses that specifically infect bacteria. They consist of a protein coat and genetic material (DNA or RNA). Bacteriophages attach to bacterial cells, inject their genetic material, and hijack the bacterial machinery to replicate, often leading to the lysis (destruction) of the host cell.
  • D. Infectious proteins refer to misfolded proteins, primarily associated with prions. These proteins can induce abnormal folding in normal proteins, leading to neurodegenerative diseases. Unlike traditional infectious agents, such as viruses or bacteria, infectious proteins do not contain nucleic acids and propagate by converting healthy proteins into the misfolded form, resulting in diseases like Creutzfeldt-Jakob disease and mad cow disease.

Q40. In heterotrophs, during digestion, macromolecules are broken into monomers by hydrolysis with the help of:

  • A. Chymosin
  • B. Gastrin
  • C. Rennin
  • D. Hydrolytic enzyme
  • E. Endonuclease

Explanation: Hydrolytic enzymes are enzymes that catalyse the breakdown of complex molecules by adding water (hydrolysis). They facilitate the cleavage of chemical bonds in substrates, resulting in smaller molecules.

Why the other options are wrong
  • A. Chymosin is an enzyme primarily found in the stomachs of young ruminants, such as calves. It plays a crucial role in the digestion of milk by curdling it, which helps in breaking down proteins during digestion. Chymosin is widely used in cheese-making to coagulate milk, separating it into curds and whey. It is often produced through fermentation using genetically modified microorganisms for industrial purposes.
  • B. Gastrin is a hormone produced by G cells in the stomach lining. Its primary function is to stimulate the secretion of gastric acid (hydrochloric acid) from parietal cells, which aids in digestion. Gastrin also promotes gastric motility and helps regulate the growth of the gastric mucosa. Its release is triggered by the presence of food in the stomach, especially proteins, and is an essential part of the digestive process.
  • C. Rennin, also known as chymosin, is an enzyme found in the stomachs of young mammals, particularly calves. It plays a crucial role in digesting milk by coagulating it, which helps separate casein proteins from whey. This coagulation is essential for efficient digestion of milk in young animals. Rennin is commonly used in cheese-making to curdle milk, allowing the production of various types of cheese.
  • E. Endonucleases are enzymes that cleave the phosphodiester bonds within a nucleic acid strand, breaking it into shorter fragments. They can cut both DNA and RNA and are essential for various biological processes, including DNA repair, replication, and RNA processing.

Q41. Animals that have a ladder-type nervous system, consisting of two nerve cords and connecting nerves that look like a ladder, belong to the phylum:

  • A. Protozoa
  • B. Coelenterata
  • C. Cnidarian
  • D. Porifera
  • E. Platyhelminthes

Explanation: The ladder-like nervous system in flatworms features a centralized cerebral ganglion (brain) at the front, with two longitudinal nerve cords running along the body. Transverse nerves connect these cords, allowing for coordinated movement and responses to stimuli.

Why the other options are wrong
  • A. Protozoa do not have a nervous system in the way that more complex organisms do. Instead, they rely on a network of specialized structures and cellular responses to interact with their environment.
  • B. Coelenterates, also known as cnidarians (which include jellyfish, corals, and sea anemones), have a simple nervous system characterized by a decentralized network known as a nerve net.
  • C. Coelenterates, also known as cnidarians (which include jellyfish, corals, and sea anemones), have a simple nervous system characterized by a decentralized network known as a nerve net.
  • D. Porifera, or sponges, lack a true nervous system. Instead, they have a simple cellular organization that allows them to respond to environmental stimuli

Q42. The term enzyme was coined by:

  • A. Darwin
  • B. Lamarck
  • C. Friedrich Wilhelm Kuhn
  • D. Mendel
  • E. Thomas Cech

Explanation: The term enzyme was coined by the German physiologist Wilhelm Kühne in 1878. Kühne used the term to describe the catalytic substances found in living organisms that facilitate biochemical reactions.

Why the other options are wrong
  • A. Charles Darwin (1809–1882) was an English naturalist, geologist, and biologist best known for his contributions to the understanding of evolution.
  • B. Jean-Baptiste Lamarck (1744–1829) was a French naturalist known for his early theories on evolution. He is often remembered for his ideas that predate Charles Darwin’s theory of natural selection.
  • D. Gregor Mendel (1822–1884) was an Austrian monk and scientist who is often referred to as the father of modern genetics. His groundbreaking work on the inheritance of traits in pea plants laid the foundation for the field of genetics.
  • E. Thomas Cech is an American chemist and Nobel laureate known for his groundbreaking work in the field of molecular biology, particularly regarding the role of RNA in biological processes.

Q43. Which lipophilic hormone is found in every tissue of the body and is involved in dealing with inflammation, blood flow, and protection from injury?

  • A. Estradiol
  • B. Aldosterone
  • C. Testosterone
  • D. Prostaglandins
  • E. Oestrogen

Explanation: Prostaglandins are lipid compounds derived from fatty acids that have various physiological functions in the body. They act as local hormones, influencing processes such as inflammation, pain perception, blood flow, and the regulation of blood pressure. Prostaglandins play a key role in the menstrual cycle, mediating uterine contractions, and are involved in the healing process by promoting inflammation. They are produced in response to injury or infection and have diverse effects depending on their specific types and the tissues in which they act.

Why the other options are wrong
  • A. Estradiol is a potent estrogen hormone primarily produced in the ovaries. It plays a crucial role in regulating the menstrual cycle, supporting reproductive functions, and influencing secondary sexual characteristics in females. Estradiol also affects various tissues, including bones and the cardiovascular system, and has roles in both male and female health, influencing mood, cognition, and metabolism.
  • B. Aldosterone is a steroid hormone produced by the adrenal glands. It plays a key role in regulating blood pressure and fluid balance by promoting the reabsorption of sodium and water in the kidneys, while facilitating the excretion of potassium. This action helps maintain electrolyte balance and blood volume, crucial for overall cardiovascular health. Aldosterone secretion is primarily stimulated by factors such as low blood pressure, low sodium levels, and the hormone angiotensin II.
  • C. Testosterone is a steroid hormone primarily produced in the testes in males and, to a lesser extent, in the ovaries and adrenal glands in females. It plays a key role in the development of male reproductive tissues, the promotion of secondary sexual characteristics (such as increased muscle mass and body hair), and the regulation of libido. Testosterone also influences bone density, fat distribution, and mood. Its levels fluctuate throughout life, typically peaking in young adulthood and gradually declining with age.
  • E. Oestrogen (or estrogen) is a group of hormones primarily produced in the ovaries, although it is also produced in smaller amounts by the adrenal glands and fat tissue. It plays a crucial role in the development and regulation of the female reproductive system, menstrual cycle, and secondary sexual characteristics such as breast development. Oestrogen also influences bone health, cardiovascular function, and mood. It has various forms, with estradiol being the most potent and prevalent during the reproductive years. Oestrogen levels fluctuate throughout the menstrual cycle and decrease during menopause.

Q44. Hardy-Weinberg Equation is:

  • A. p² + 2pq + q2= 1
  • B. p + 2pq + q = 1
  • C. p + 2pq + q - 0
  • D. 2p + q² = 1
  • E. 2p + 2q = 1

Explanation: The Hardy-Weinberg equation, p² + 2pq + q2= 1, is used to predict the genetic variation of a population at equilibrium. In this equation, p represents the frequency of one allele, and q represents the frequency of the other allele in a diploid organism. The term p² represents the frequency of the homozygous genotype for the first allele, q² represents the frequency of the homozygous genotype for the second allele, and 2pq represents the frequency of the heterozygous genotype. This equation is a cornerstone of population genetics, illustrating how allele and genotype frequencies remain constant from generation to generation in the absence of evolutionary influences.Options B, C, D, and E are incorrect because they do not correctly represent the relationship between allele and genotype frequencies as outlined by the Hardy-Weinberg principle.

Why the other options are wrong
  • B. This option is incorrect. The Hardy-Weinberg equation requires squaring the allele frequencies, as seen in p² and q².
  • C. This option is incorrect. The equation structure is incorrect and does not equate to 1, nor does it involve squaring the allele frequencies.
  • D. This option is incorrect. The Hardy-Weinberg equation involves both p² and q², as well as the term 2pq, which are missing here.
  • E. This option is incorrect. It does not reflect the format of the Hardy-Weinberg equation, which includes the terms p², q², and 2pq.

Q45. F.C Steward used this plant for his experiment i.e (tissue culture):

  • A. Radish
  • B. Corn
  • C. Maize
  • D. Carrot
  • E. Mango

Explanation: The correct answer is Carrot. F.C Steward was a pioneer in plant tissue culture and used carrot phloem tissue to show that plant cells have the ability to develop into a whole plant, which is a demonstration of cellular totipotency. This was a significant breakthrough in biotechnology, as it laid the groundwork for modern plant tissue culture techniques. Radish, corn, maize, and mango were not used in Steward's experiments, which focused specifically on the carrot.

Why the other options are wrong
  • A. This option is incorrect. Radish was not used by F.C Steward in his tissue culture experiments.
  • B. This option is incorrect. Although corn is studied in tissue culture, it was not the plant used by F.C Steward.
  • C. This option is incorrect. Maize, another name for corn, was not the plant used by F.C Steward in his experiments.
  • E. This option is incorrect. Mango was not used in F.C Steward's tissue culture experiments.

Q46. Histone proteins are rich in:

  • A. Basic amino acid
  • B. Acidic fatty acid
  • C. Başic citric acid
  • D. Acidic amino acid

Explanation: Basic amino acids are amino acids that have a positively charged side chain at physiological pH (around 7.4), due to the presence of an additional amino group (-NH₃⁺) in their side chains. These amino acids can accept protons (H⁺), making them basic.They are found in histones.

Why the other options are wrong
  • B. Acidic fatty acids are fatty acids that have a carboxyl group (-COOH) at one end of their molecular structure, giving them acidic properties. However, typically all fatty acids are technically weak acids because they contain this carboxyl group.
  • C. Citric acid is a weak organic acid found in citrus fruits like lemons and limes. It plays an essential role in metabolism, particularly in the citric acid cycle (Krebs cycle), which is a key part of cellular respiration in all aerobic organisms.
  • D. Acidic amino acids are amino acids that have a negatively charged side chain at physiological pH due to the presence of a carboxyl group in their side chain. These amino acids donate protons (H⁺), making them acidic

Q47. The site of maturation and storage of sperms is:

  • A. Seminal vesicles
  • B. Scrotum
  • C. Testes
  • D. Epididymis
  • E. Vasa deferentia

Explanation: The epididymis is a coiled tube located at the back of each testis. Its primary function is to store and mature sperm produced in the testes. Sperm travel from the seminiferous tubules of the testes to the epididymis, where they undergo maturation, gaining motility and the ability to fertilize an egg. The epididymis also reabsorbs excess fluid and damaged sperm. During ejaculation, sperm are propelled from the epididymis into the vas deferens for transport.

Why the other options are wrong
  • A. Seminal vesicles are glandular structures located near the prostate gland in males. They produce a significant portion of semen, contributing fluid that contains fructose, proteins, enzymes, and prostaglandins. This fluid nourishes sperm and helps facilitate their motility and survival after ejaculation. The secretions from the seminal vesicles mix with sperm from the testes during ejaculation, forming semen. Their function is crucial for male fertility.
  • B. The scrotum is a pouch of skin that contains and protects the testicles (testes) in males. It helps regulate the temperature of the testes, which is essential for sperm production and viability. The scrotum accomplishes this by contracting or relaxing in response to temperature changes: it pulls closer to the body in cold conditions and drops away in warmth. This temperature regulation is vital for optimal sperm development.
  • C. The testes are the male reproductive organs responsible for producing sperm and hormones, primarily testosterone. Located in the scrotum, they are oval-shaped structures that contain seminiferous tubules, where sperm production occurs through a process called spermatogenesis. The testes also produce hormones that regulate male secondary sexual characteristics and reproductive functions. Overall, they play a crucial role in male fertility and endocrine function
  • E. The vasa deferentia (or vas deferens) are muscular tubes that transport sperm from the epididymis to the ejaculatory duct. Each vas deferens runs from the epididymis, travels up into the abdominal cavity, and loops over the bladder before merging with the seminal vesicle. They play a crucial role in the male reproductive system by facilitating the passage of sperm during ejaculation, where muscular contractions propel the sperm forward.

Q48. A disease resulting in complete lack of spermatozoa in ejaculate is:

  • A. Azoospermia
  • B. Obstruction
  • C. Oligospermia
  • D. Zoospermia
  • E. Ejaculation disorder

Explanation: Azoospermia is a medical condition characterized by the absence of sperm in a man's semen. This condition can result from various factors, including hormonal imbalances, blockages in the reproductive tract, or issues with sperm production in the testes

Why the other options are wrong
  • B. Obstruction refers to a blockage that prevents the normal flow or passage of substances within a system. In a medical context, it can occur in various bodily systems.
  • C. Oligospermia is a medical condition characterized by a low sperm count in a man's semen. Specifically, it is defined as having fewer than 15 million sperm per milliliter of ejaculate. Oligospermia can affect male fertility and may result from various factors, including hormonal imbalances, genetic conditions, certain medical conditions (like diabetes), environmental factors (such as exposure to toxins), and lifestyle choices (such as smoking or excessive alcohol consumption). Treatment options may include lifestyle changes, medication, or assisted reproductive technologies, depending on the underlying cause.
  • D. Zoospermia is a term used to describe the presence of sperm in semen. It is often discussed in contrast to conditions like azoospermia (absence of sperm) and oligospermia (low sperm count). In general, having a normal sperm count and quality is essential for male fertility. When evaluating fertility, various parameters of zoospermia are assessed, including sperm concentration, motility, and morphology. Healthy zoospermia is crucial for successful conception.
  • E. Ejaculation disorders are conditions that affect the ability to ejaculate normally during sexual activity.

Q49. The type of bacteria which oxidize CO into CO2 is:

  • A. Norcardia salmonicolor
  • B. Hydrogenomonas
  • C. Pseudomonas
  • D. Thiobacillus
  • E. Azobacter

Explanation: The correct answer is Pseudomonas because some species within this genus have the unique ability to oxidize carbon monoxide (CO) as a source of energy, facilitating their survival in environments where CO is present. The other options are incorrect because:Norcardia salmonicolor is involved in the degradation of organic compounds, not CO oxidation.Hydrogenomonas utilizes hydrogen rather than carbon monoxide.Thiobacillus is associated with sulfur and carbon cycles but does not oxidize CO.Azobacter is known for nitrogen fixation and does not rely on carbon monoxide for energy.Thus, Pseudomonas stands out as the only correct option in this context.

Why the other options are wrong
  • A. Norcardia salmonicolor is primarily known for its role in degrading organic matter and does not oxidize carbon monoxide.
  • B. Hydrogenomonas is a genus of bacteria that oxidizes hydrogen, not carbon monoxide, making it irrelevant to this question.
  • D. Thiobacillus is well-known for its involvement in sulfur oxidation and carbon cycling, but it does not oxidize carbon monoxide.
  • E. Azotobacter is primarily recognized for its nitrogen-fixing abilities in soil, and it does not utilize carbon monoxide as an energy source.

Q50. What structure holds sister chromatids together?

  • A. Gene
  • B. Nucleosome
  • C. Centrosome
  • D. Centromere

Explanation: A centromere is a region of a chromosome that plays a critical role during cell division. It is the constricted region where sister chromatids are held together.

Why the other options are wrong
  • A. A gene is a segment of DNA that contains the instructions for building proteins or RNA molecules, which are essential for the structure, function, and regulation of an organism's cells
  • B. A nucleosome is the basic structural unit of chromatin in eukaryotic cells.Nucleosomes are essential for DNA organization and regulation.
  • C. A centrosome is a cellular structure that plays a key role in cell division.Centrosomes are vital for maintaining cell shape, organization, and division

Q51. The most widely accepted explanation for ascent of sap is:

  • A. Role of root pressure
  • B. Transpiration
  • C. Capillarity
  • D. Role of atmospheric pressure
  • E. Cohesion and transpiration pull

Explanation: Cohesion and transpiration pull are two key concepts in the movement of water within plants.Cohesion provides the structural support needed for water movement, while transpiration pull drives the upward flow of water in plants.

Why the other options are wrong
  • A. Root pressure is the positive pressure generated in the roots of plants, primarily responsible for the upward movement of water and nutrients.
  • B. Transpiration is the process by which water is absorbed by plant roots, moves through the plant, and is released as water vapor from aerial parts, primarily leaves
  • C. Capillarity is the ability of a liquid to flow in narrow spaces without the assistance of external forces
  • D. Changes in atmospheric pressure can affect the overall pressure within the xylem, influencing the rate at which sap is drawn upward.

Q52. In which of the following environments are plants, with aerenchyma, most likely to be found?

  • A. Mesophytes
  • B. Sciophytes
  • C. Xerophytes
  • D. Hydrophytes
  • E. Halophytes

Explanation: Hydrophytes are aquatic plants that thrive in water-saturated environments.

Why the other options are wrong
  • A. Mesophytes are plants that thrive in environments with moderate water availability.
  • B. Sciophytes are shade-loving plants that thrive in low light conditions, typically found under the canopy of forests or in shaded areas
  • C. Xerophytes are plants adapted to survive in arid or dry environments.
  • E. Halophytes are salt-tolerant plants that thrive in saline environments, such as coastal areas, salt marshes, and saline soils.

Q53. Each helix of DNA is made up of four types of nucleotides and both helices are complementary to each other i.e. if one helix contains Adenine the opposite helix will contain:

  • A. Histidine
  • B. Uracil
  • C. Cytosine
  • D. Thymine

Explanation: According to Chargaff’s base pairing rule:Adenine (A) always pairs with Thymine (T) → by two hydrogen bondsCytosine (C) always pairs with Guanine (G) → by three hydrogen bondsSo,➡ If one helix (strand) contains Adenine,➡ The opposite helix (complementary strand) will contain Thymine.

Why the other options are wrong
  • A. Histidine is an amino acid, not a nitrogenous base. Amino acids form proteins, not DNA or RNA. Therefore, Histidine does not pair with Adenine in DNA.
  • B. Uracil pairs with Adenine only in RNA, not DNA. In RNA, Thymine is replaced by Uracil, but since the question is about DNA, Uracil is incorrect here.
  • C. Cytosine pairs with Guanine, not Adenine. They are linked by three hydrogen bonds in the DNA double helix. So Cytosine cannot pair with Adenine.

Q54. Bacteriophages escape from host cells by the activity of:

  • A. Non-Ribosome
  • B. Lysozyme
  • C. Peroxisome
  • D. Lysosome

Explanation: Lysozyme is an enzyme that plays a crucial role in the immune system and is involved in breaking down bacterial cell walls.

Why the other options are wrong
  • A. "Non-ribosome" generally refers to any aspect of cellular biology that does not involve ribosomes or the process of protein synthesis.
  • C. Peroxisomes are essential for cellular metabolism and detoxification, contributing to overall cell health.
  • D. A lysosome is a membrane-bound organelle in eukaryotic cells responsible for digestion and waste processing.

Q55. Which soft-bodied animal is usually Ambisexual?

  • A. Tapeworm
  • B. Earthworm
  • C. Jellyfish
  • D. Snail
  • E. Oyster

Explanation: Oysters are often considered ambisexual due to their ability to change sex during their lifecycle, starting as males and becoming females, depending on environmental conditions.

Why the other options are wrong
  • A. Tapeworms are hermaphroditic, having both male and female reproductive organs, but they are not referred to as ambisexual
  • B. Earthworms are hermaphroditic, possessing both male and female reproductive organs, but they are not typically described as ambisexual.
  • C. Snails are typically hermaphroditic, having both male and female reproductive organs, but the term ambisexual is not standard for describing their reproductive nature.
  • D. Snails are hermaphroditic organisms, meaning that a single snail possesses both male and female reproductive organs. This allows them to produce both eggs and sperm. However, they usually do not self-fertilize — instead, they mate with another snail and exchange sperm to ensure genetic diversity.

Q56. The number of teeth in deciduous and permanent teeth is:

  • A. 21 and 32 respectively
  • B. 18 and 22 respectively
  • C. 12 and 32 respectively
  • D. 10 and 32 respectively
  • E. 20 and 32 respectively

Explanation: The correct answers are 20 and 32, respectively. Deciduous teeth, commonly known as baby teeth, total 20 and are typically present from infancy until they are gradually replaced by permanent teeth. Permanent teeth, which include wisdom teeth, sum up to 32 in a complete adult set. Each incorrect option either underestimates the number of deciduous teeth or the number of permanent teeth, which are well-established figures in human dental anatomy.

Why the other options are wrong
  • A. This answer is incorrect. There are 20 deciduous teeth, not 21.
  • B. This answer is incorrect. The number of permanent teeth in adults is 32, not 22.
  • C. This answer is incorrect. There are 20 deciduous teeth, not 12.
  • D. This answer is incorrect. There are 20 deciduous teeth, not 10.

Q57. Which hormone is responsible to convert the ruptured follicle into a yellowish glandular mass known as corpus luteum?

  • A. FSH
  • B. ACTH
  • C. DHT
  • D. LH
  • E. TSH

Explanation: Luteinizing Hormone (LH) is a key hormone in the reproductive system. In females, it triggers ovulation and helps form the corpus luteum, which produces progesterone essential for maintaining pregnancy

Why the other options are wrong
  • A. Follicle-Stimulating Hormone (FSH) is produced by the pituitary gland and is crucial for reproductive health. In females, it stimulates the growth and maturation of ovarian follicles and promotes estrogen production, essential for the menstrual cycle. In males, FSH supports Sertoli cells in the testes, facilitating sperm production and maturation. FSH levels are regulated by gonadotropin-releasing hormone (GnRH) and influenced by sex hormone levels, making it vital for normal reproductive function in both genders.
  • B. Adrenocorticotropic Hormone (ACTH) is produced by the pituitary gland and is essential for the body’s stress response. It stimulates the adrenal glands to produce cortisol, which helps manage stress, metabolism, and immune function. ACTH also regulates the health of the adrenal cortex and operates within a feedback loop with corticotropin-releasing hormone (CRH) and cortisol levels to maintain hormonal balance. Overall, ACTH is crucial for homeostasis and responding to stress.
  • C. Dihydrotestosterone (DHT) is a potent androgen derived from testosterone, essential for the development of male characteristics such as facial hair and a deep voice during puberty. It plays a crucial role in prostate health, contributing to the growth and maintenance of the prostate gland, though excessive levels can lead to conditions like benign prostatic hyperplasia (BPH) and prostate cancer. DHT also regulates hair growth, being a factor in male-pattern baldness when it binds to hair follicle receptors. Additionally, it influences libido and erectile function in males, making it vital for various aspects of male development and health.
  • E. Thyroid-Stimulating Hormone (TSH) is produced by the pituitary gland and regulates thyroid function by stimulating the synthesis and release of thyroid hormones (T3 and T4), which are essential for metabolism. TSH levels are controlled by feedback mechanisms involving thyrotropin-releasing hormone (TRH) and circulating thyroid hormone levels, ensuring proper metabolic balance.

Q58. Phage genome incorporated with host DNA is called:

  • A. Bacteriophage
  • B. Viroids
  • C. Prophage
  • D. Prions

Explanation: A prophage is the latent form of a bacteriophage (a virus that infects bacteria) when it integrates its genetic material into the bacterial chromosome. In this state, the viral DNA is replicated along with the bacterial DNA during cell division without causing immediate harm to the host. The prophage can remain dormant for extended periods, but under certain conditions, it may reactivate and enter the lytic cycle, leading to the production of new viral particles and the lysis of the bacterial cell. Prophages can play a role in horizontal gene transfer, contributing to genetic diversity among bacteria and sometimes providing advantageous traits, such as antibiotic resistance. Understanding prophages is important in microbiology and virology, particularly in studying bacterial evolution and the dynamics of bacterial infections.

Why the other options are wrong
  • A. A bacteriophage (or phage) is a virus that specifically infects bacteria. Composed of genetic material (either DNA or RNA) surrounded by a protein coat, bacteriophages can have various shapes and sizes. They reproduce by attaching to a bacterial cell, injecting their genetic material, and hijacking the host's cellular machinery to produce new phage particles.
  • B. Viroids are small, circular RNA molecules that are pathogenic to plants. Unlike viruses, viroids lack a protein coat and do not encode proteins, consisting solely of a short strand of RNA. They replicate within host cells by hijacking the host's RNA polymerase, leading to disease by disrupting normal cellular functions.
  • D. Prions are misfolded proteins that can cause neurodegenerative diseases by inducing other normal proteins to misfold, leading to brain damage. Unlike viruses or bacteria, prions lack nucleic acids, making them unique in their mechanism of infection.

Q59. Plants oxidize sugar in chloroplasts during the day without production of energy. This process is called:

  • A. Photorespiration
  • B. Oxidative phosphorylation
  • C. Non-cyclic photophosphorylation
  • D. Cyclic oxidative phosphorylation

Explanation: The process you're describing is called photorespiration. During photorespiration, plants take up oxygen and release carbon dioxide, which occurs in chloroplasts when the enzyme RuBisCO reacts with oxygen instead of carbon dioxide. This process can lead to the oxidation of sugar, but it does not produce energy in the way that cellular respiration does.

Why the other options are wrong
  • B. Oxidative phosphorylation is a vital metabolic process that occurs in the mitochondria of eukaryotic cells, responsible for generating adenosine triphosphate (ATP) through the electron transport chain (ETC) and chemiosmosis. During this process, electrons from NADH and FADH2, generated in earlier metabolic pathways like glycolysis and the Krebs cycle, are transferred through a series of protein complexes in the inner mitochondrial membrane.
  • C. Non-cyclic photophosphorylation is a process occurring in the thylakoid membranes of chloroplasts during photosynthesis, primarily involving Photosystem II (PSII) and Photosystem I (PSI). This pathway is responsible for generating ATP and NADPH, which are essential for the Calvin cycle.
  • D. Cyclic oxidative phosphorylation is a variant of oxidative phosphorylation that occurs in the mitochondria, primarily involving the electron transport chain (ETC). Unlike non-cyclic photophosphorylation, which involves the transfer of electrons through multiple complexes and the reduction of NADP+, cyclic oxidative phosphorylation specifically refers to the cyclic flow of electrons through Photosystem I (PSI) in plants during photosynthesis.

Q60. Sufficient depolarization in neurolemma results in:

  • A. Potassium leakage
  • B. Resting membrane potential
  • C. Action potential
  • D. Repolarization
  • E. Sub-threshold potential

Explanation: An action potential is a rapid and temporary change in the membrane potential of a neuron or muscle cell that allows for the transmission of electrical signals. It occurs when a stimulus depolarizes the membrane to a threshold level, typically around -55 mV.

Why the other options are wrong
  • A. The function of K+ leakage is to help maintain the resting membrane potential by allowing a small, passive movement of potassium ions out of the cell.
  • B. Resting membrane potential is the electrical potential difference across the plasma membrane of a neuron or muscle cell when it is not actively transmitting signals. Typically around -70 mV, this potential is primarily established by the distribution of ions, particularly sodium (Na+), potassium (K+), chloride (Cl-), and various anions.
  • D. Repolarization is the phase of the action potential in neurons and muscle cells where the membrane potential returns to its resting state after depolarization. This process follows the peak of the action potential, where the inside of the cell becomes positively charged due to the influx of sodium ions (Na+).
  • E. Sub-threshold potential refers to the membrane potential that occurs in a neuron when a stimulus is not strong enough to reach the threshold needed to trigger an action potential. This potential represents a graded response, where the depolarization of the neuron's membrane occurs, but it does not reach the critical level required for the voltage-gated sodium channels to open.

Q61. Fusion of two genetically dissimilar parents through artificial pollination is:

  • A. Selection
  • B. Acclimatization
  • C. Hybridization
  • D. Evolution
  • E. Back crossing

Explanation: Hybridization is the process of crossing two different species or varieties to produce a hybrid organism that typically exhibits traits from both parents. This phenomenon occurs in plants and animals and can lead to increased genetic diversity and the introduction of desirable characteristics.

Why the other options are wrong
  • A. Selection refers to the process by which certain traits become more or less common in a population over time due to their impact on the survival and reproductive success of individuals. This concept is a fundamental mechanism of evolution.
  • B. Acclimatization genetics refers to the genetic mechanisms and processes that enable organisms to adjust to environmental changes through acclimatization. While acclimatization itself involves short-term physiological adjustments, the genetic basis for these responses can influence how effectively an organism can acclimatize.
  • D. Evolution is the process by which populations of organisms change over generations through variations in their genetic makeup, leading to the development of new species.
  • E. Backcrossing is a breeding method used in genetics and agriculture where an offspring (hybrid) is crossed with one of its parent species or a genetically similar individual. This technique aims to enhance specific traits or to introduce desired characteristics into a population while maintaining the genetic background of the parent.

Q62. In the flowering plant, food is translocated in the form of:

  • A. Starch
  • B. Sucrose
  • C. Glucose
  • D. Sugar
  • E. Fructose

Explanation: In flowering plants, the carbohydrate transported long-distance through the phloem is primarily sucrose. Sucrose is a disaccharide (glucose + fructose) that is chemically stable, water-soluble, and non-reducing, so it can be loaded into sieve elements without reacting with cellular components or causing osmotic/chemical damage the way free glucose might. In a typical source (mature leaf) the products of photosynthesis are converted to sucrose and actively loaded into companion cells and then into sieve tube elements (either via plasmodesmatal symplastic routes or by membrane transporters in apoplastic loading).

Why the other options are wrong
  • A. Starch is an insoluble storage carbohydrate found mainly in seeds, roots, and tubers. Because it is insoluble, starch cannot be translocated through the phloem. Instead, plants convert it into soluble sugars (like sucrose) before transport.
  • C. Although glucose is a simple sugar and a product of photosynthesis, it is too reactive and reducing in nature, which could damage plant tissues during transport. Therefore, glucose is converted into sucrose before movement through the phloem.
  • D. The term "sugar" is too general. While sucrose is a type of sugar, not all sugars are involved in translocation. The question asks for a specific form, and only sucrose serves as the primary transport molecule.
  • E. Fructose is a monosaccharide found in fruits and is not typically transported through the phloem. Like glucose, it is too reactive and is instead used locally or combined with glucose to form sucrose for transport.

Q63. Which reaction is also known as Z-scheme?

  • A. Oxidative phosphorylation
  • B. Cyclic photophosphorylation-
  • C. Non-cyclic oxidative phosphorylation
  • D. Non-cyclic photephosphorylation

Explanation: Non-cyclic photophosphorylation is often illustrated using the Z-scheme model. This model represents the linear flow of electrons during the light-dependent reactions of photosynthesis.

Why the other options are wrong
  • A. Oxidative phosphorylation is a crucial metabolic process that occurs in the mitochondria of eukaryotic cells and is responsible for the majority of adenosine triphosphate (ATP) production.
  • B. Cyclic photophosphorylation is a process that occurs during photosynthesis, specifically in the light-dependent reactions of plants and some bacteria.
  • C. Non-cyclic oxidative phosphorylation refers to the process of ATP production in cellular respiration, primarily in the mitochondria, involving both the electron transport chain (ETC) and the reduction of NADP⁺ to NADPH.

Q64. In gel electrophoresis, how do molecules migrate through the gel?

  • A. Under the influence of agar
  • B. By diffusion
  • C. Under the influence of an electric field
  • D. Active transport
  • E. By osmosis

Explanation: In gel electrophoresis, molecules migrate through the gel under the influence of an electric field. When an electric current is applied, charged molecules such as DNA, RNA, or proteins move toward the electrode with the opposite charge. The gel acts as a molecular sieve, allowing smaller molecules to move faster than larger ones, thus achieving separation based on size and charge. The incorrect options, such as agar, diffusion, active transport, and osmosis, do not involve the electric field mechanism that is central to gel electrophoresis.

Why the other options are wrong
  • A. This option is incorrect. Agar is used as a medium to form the gel but does not influence the movement of molecules.
  • B. This option is incorrect. Diffusion is a passive process and does not involve an electric field, which is essential in gel electrophoresis.
  • D. This option is incorrect. Active transport is a cellular process that requires energy, not applicable in the context of gel electrophoresis.
  • E. This option is incorrect. Osmosis involves the movement of water across a semi-permeable membrane, not the migration of molecules in an electric field.

Q65. In carbohydrates, hydrogen and oxygen are present in the simple ratio of:

  • A. 2:1
  • B. 3:1
  • C. 1:1
  • D. 3:4
  • E. 1:3

Explanation: Carbohydrates are organic molecules composed of carbon, hydrogen, and oxygen, commonly following the formula Cx(H2O)y. This reflects a 2:1 ratio of hydrogen to oxygen, similar to water. Option A is correct because it represents this fundamental characteristic of carbohydrates. Options B, C, D, and E are incorrect because they do not represent the standard 2:1 hydrogen to oxygen ratio found in carbohydrates.

Why the other options are wrong
  • B. This is incorrect. While some other compounds might have a 3:1 ratio, carbohydrates specifically have a 2:1 ratio of hydrogen to oxygen.
  • C. This is incorrect. A 1:1 ratio would suggest equal parts hydrogen and oxygen, which does not align with the formula for carbohydrates.
  • D. This is incorrect. A 3:4 ratio does not match the structure of carbohydrates, which is based on the 2:1 ratio of hydrogen to oxygen.
  • E. This is incorrect. Carbohydrates do not follow a 1:3 ratio; they are characterized by a 2:1 ratio of hydrogen to oxygen.

Q66. Which of the pigments are common in both humans and plants?

  • A. Carotenoids
  • B. Fucoxanthin
  • C. Xanthophyll
  • D. Chlorophyll

Explanation: Carotenoids are found in both plants and human.In plants,carotenoids play a role in photosynthesis by absorbing light, while inhumans, they act as precursors to vitamin A and have antioxidant properties.

Why the other options are wrong
  • B. Fucoxanthin: Found mainly in certain algae and brown seaweed, not in humans or typical plant tissues.
  • C. This is a type of carotenoid and is also found in both plants and humans. In plants, it helps in photosynthesis, while in humans, it contributes to eye health (especially in the retina).
  • D. Chlorophyll: Found in plants (and some algae) but not in humans.

Q67. Two different gene pairs, located at different loci, all work for the same trait and express in an additive manner. This phenomenon is called:

  • A. Codominance
  • B. Polygenic inheritance
  • C. Multiple alleles
  • D. Incomplete dominance
  • E. Epistasis

Explanation: Polygenic inheritance is a form of genetic inheritance where multiple genes (often located on different chromosomes) contribute to a single phenotype or trait. This results in a continuous range of phenotypic variation, rather than discrete categories.

Why the other options are wrong
  • A. Codominance is a genetic phenomenon in which two different alleles at a locus are expressed equally in the phenotype of a heterozygous individual. This results in a distinct expression of both alleles, rather than one being dominant over the other.
  • C. Multiple alleles refer to the presence of three or more alternative forms of a gene that occupy the same locus on a chromosome. While each individual typically carries only two alleles for a given gene (one inherited from each parent), the existence of multiple alleles within a population can lead to a wider variety of phenotypic expressions.
  • D. Incomplete dominance is a genetic phenomenon where the phenotype of a heterozygous individual is intermediate between the phenotypes of the two homozygous parents. This means that neither allele is completely dominant over the other, resulting in a blending of traits.
  • E. Epistasis is a genetic phenomenon where the effect of one gene is modified or suppressed by one or more other genes. This interaction can influence the expression of phenotypic traits, making it an important concept in understanding inheritance and genetic variation.

Q68. Isolation of cellular components to determine their structure and chemical composition is:

  • A. Cell fractionation
  • B. Chromatography
  • C. Microscopy
  • D. Spectrometry
  • E. Electrophoresis

Explanation: Cell fractionation is a laboratory technique used to separate different cellular components while preserving their function. It typically involves breaking open cells (lysis) and then using centrifugation to separate the cell contents based on size and density. This process allows researchers to isolate specific organelles, proteins, or other cellular structures for study and analysis.

Why the other options are wrong
  • B. Chromatography is a technique used to separate and analyze mixtures of substances. It involves passing a mixture through a medium (stationary phase) while a solvent (mobile phase) moves it along. Different components of the mixture move at different rates, allowing them to be separated. Chromatography is commonly used in chemistry, biochemistry, and environmental science for purifying compounds and analyzing complex mixtures.
  • C. Microscopy is the technique of using microscopes to observe small objects or structures that are not visible to the naked eye. There are various types of microscopy, including light microscopy, which uses visible light and lenses to magnify samples, and electron microscopy, which uses electron beams for higher resolution images. Microscopy is essential in fields like biology, materials science, and medicine for studying cells, tissues, and materials at microscopic levels.
  • D. Spectrometry is an analytical technique used to measure and analyze the mass or concentration of substances in a sample by detecting the interaction of electromagnetic radiation with matter. It involves the generation of a spectrum, which displays the intensity of light (or other forms of radiation) as a function of wavelength or mass. Common types include mass spectrometry (measuring mass-to-charge ratios) and infrared spectrometry (analyzing molecular vibrations). Spectrometry is widely used in chemistry, biology, and environmental science for identifying and quantifying compounds.
  • E. Electrophoresis is a technique used to separate charged molecules, such as proteins or nucleic acids, based on their size and charge. When an electric field is applied to a gel or liquid medium, the molecules migrate towards the electrode of opposite charge. Smaller or more highly charged molecules move faster than larger or less charged ones, resulting in separation. This method is commonly used in laboratories for DNA analysis, protein purification, and various diagnostic applications.

Q69. The type of cancer common in young men between the ages of 15 and 34 that has a high cure rate with early treatment is:

  • A. Skin cancer
  • B. Lung cancer
  • C. Blood cancer
  • D. Lymph cancer
  • E. Testicular cancer

Explanation: Testicular cancer primarily affects younger men, with the highest incidence occurring in those between the ages of 15 and 35.

Why the other options are wrong
  • A. The most common types of skin cancer—basal cell carcinoma, squamous cell carcinoma, and melanoma—are more frequently diagnosed in older adults. However, skin cancer can also affect younger individuals, especially those with fair skin or a history of intense sun exposure
  • B. Lung cancer typically affects older adults, with the majority of cases diagnosed in people aged 65 and older. The risk increases with age, largely due to the cumulative effects of risk factors like smoking and environmental exposure over time. However, lung cancer can also occur in younger individuals, particularly those with a history of smoking or exposure to carcinogens.
  • C. Blood cancers such as leukemia, lymphoma, and multiple myeloma can affect individuals of any age, but their prevalence varies.
  • D. Lymphoma, including Hodgkin and non-Hodgkin lymphoma, can affect individuals across various age groups. Hodgkin lymphoma is most commonly diagnosed in two age brackets: young adults (15-40 years) and older adults (over 55). In contrast, non-Hodgkin lymphoma is primarily seen in older adults, typically those over 60, though it can also occur in younger individuals. Overall, while lymphomas can arise at any age, the risk generally increases with age, particularly for non-Hodgkin lymphoma. Regular health screenings and awareness of symptoms are crucial for early detection.

Q70. This process inhibits the metabolism and growth of anaerobic microbes used for the treatment of gas gangrene.

  • A. Desiccation
  • B. Radiation
  • C. Hyperbaric oxygen therapy
  • D. High-pressure process
  • E. Lyophilization

Explanation: Hyperbaric oxygen therapy (HBOT) involves breathing pure oxygen in a pressurised chamber. This therapy enhances oxygen delivery to tissues, promotes healing, and can treat conditions like decompression sickness, carbon monoxide poisoning, and certain infections. It may also be used for chronic wounds and other medical conditions, though its effectiveness can vary.

Why the other options are wrong
  • A. Desiccation refers to the process of extreme drying or removal of moisture from an object, organism, or substance. It can occur naturally due to environmental conditions (like exposure to intense sunlight or wind), or it can be induced through artificial means (like using desiccants or specialised equipment).
  • B. Radiation refers to the emission and propagation of energy through space or a medium in the form of waves or particles. There are several types of radiation, each with different properties and effects.
  • D. A high-pressure process (HPP) uses elevated pressure to achieve specific results in various industries, especially in food preservation and material science.
  • E. Lyophilisation, or freeze-drying, is a dehydration process used to preserve perishable materials. It involves freezing the product, lowering the pressure, and removing the ice through sublimation, resulting in a dry, stable product. This method is commonly used for pharmaceuticals, food, and biological samples.

Q71. The branching network-like arrangement of cardiac muscles is called:

  • A. Epimysium
  • B. Syndesmosis
  • C. Gomphosis
  • D. Sarcolemma
  • E. Syncytium

Explanation: A syncytium is a large cell-like structure formed by the fusion of multiple cells, resulting in a mass of cytoplasm with multiple nuclei. It occurs naturally in certain tissues, like muscle fibers, and in some viral infections, where infected cells merge. Syncytia play a role in both normal biological processes and some pathological conditions.

Why the other options are wrong
  • A. Epimysium is a layer of dense connective tissue that surrounds the entire skeletal muscle. It acts as a protective sheath and separates the muscle from surrounding tissues and organs. The epimysium also helps maintain the structure of the muscle and plays a crucial role in transmitting the force generated by muscle fibers to tendons, which in turn move bones.
  • B. Syndesmosis is a type of fibrous joint where two bones are held together by a ligament, membrane, or interosseous tissue. It allows for more movement than sutures (another type of fibrous joint), but still only limited motion, classifying it as an amphiarthrosis joint (slightly movable).
  • C. Gomphosis is a type of fibrous joint where a conical process, such as a tooth, is anchored into a socket, like the alveolus in the jawbone. It is the type of joint that connects teeth to the mandible (lower jaw) or maxilla (upper jaw). Gomphoses are classified as synarthroses, meaning they allow very little or no movement. The fibrous connection in this joint is made by the periodontal ligament, which securely holds the tooth in place while still providing a small degree of flexibility to absorb forces during chewing.
  • D. The sarcolemma is the cell membrane surrounding a muscle fiber (muscle cell). It helps maintain the structure of the muscle cell, conducts electrical signals (action potentials), and regulates the exchange of ions, crucial for muscle contraction.

Q72. Molecules that bind to an enzyme away from the active site and increase the function of that active site are known as:

  • A. Activation energy without enzyme
  • B. Energy of reactants
  • C. Activation energy with enzyme
  • D. Energy of product
  • E. Allosteric activators

Explanation: The correct answer is allosteric activators. These molecules bind to an enzyme at a location other than the active site, known as the allosteric site. This binding causes a conformational shift in the enzyme's structure that improves the accessibility or functionality of the active site, thus increasing the enzyme's catalytic efficiency.The other options relate to different concepts: 'Activation energy without enzyme' and 'Activation energy with enzyme' are about the energy barriers in reactions; 'Energy of reactants' and 'Energy of product' describe the energy states of substances in a reaction, not the modulation of enzyme activity.

Why the other options are wrong
  • A. This option is incorrect. Activation energy without an enzyme refers to the energy required to start a reaction in the absence of a catalyst.
  • B. This option is incorrect. The energy of reactants refers to the initial energy level of the reactants before a reaction occurs, not to enzyme regulation.
  • C. This option is incorrect. Activation energy with an enzyme refers to the reduced energy barrier for a reaction facilitated by the enzyme, not to molecules that enhance enzyme function.
  • D. This option is incorrect. The energy of products refers to the energy level of the substances formed after a reaction, unrelated to enzyme modulation.

Q73. The number of oxygen molecules that are transported by one hemoglobin molecule is:

  • A. 1
  • B. 4
  • C. 3
  • D. 2
  • E. 5

Explanation: Hemoglobin is a protein found in red blood cells that has four heme groups, each capable of binding to one oxygen molecule. Thus, one hemoglobin molecule can transport a maximum of four oxygen molecules at a time. Options 1, 2, and 3 are incorrect as they suggest fewer binding sites than are available. Option 5 is incorrect as hemoglobin cannot bind more than four oxygen molecules.

Why the other options are wrong
  • A. This option is incorrect. A single hemoglobin molecule can bind up to four oxygen molecules, one on each of its four subunits, so the statement claiming otherwise is incorrect.
  • C. This option is incorrect. Although hemoglobin can transport partially saturated with three oxygen molecules, it has the capacity for four.
  • D. This option is incorrect. A single hemoglobin molecule can bind up to four oxygen molecules, one on each of its four subunits, so the statement claiming otherwise is incorrect.
  • E. This option is incorrect. Hemoglobin does not have the capacity to bind five oxygen molecules.

Q74. The top milk-producing animal is:

  • A. Nili-Ravi
  • B. Bhadawari
  • C. Godavari
  • D. Blue-Ravi
  • E. Jaffrabadi

Explanation: The Nili-Ravi is a breed of water buffalo recognised for its high milk yield, making it one of the top choices for dairy production, particularly in Pakistan and India. This breed's ability to produce large quantities of milk makes it highly prized among dairy farmers. Other options, such as the Bhadawari and Jaffrabadi, are also known for milk production but do not reach the same levels as the Nili-Ravi. The Godavari and Blue-Ravi are not established breeds known for high milk production.

Why the other options are wrong
  • B. The Bhadawari is a breed of buffalo known for its moderate milk production and high butterfat content, but it is not the top milk producer.
  • C. The Godavari is not a recognised breed of high milk-producing animals; it is more associated with a river name in India rather than livestock.
  • D. The Blue-Ravi is not a known breed of milk-producing animals, making this option incorrect.
  • E. The Jaffrabadi is a breed of buffalo found in India known for good milk production, but it does not surpass the Nili-Ravi in milk yield.

Q75. Which one of the following is the precursor for the synthesis of testosterone, progesterone, and estrogens?

  • A. Choline
  • B. Cholesterol
  • C. Oil
  • D. Waxes
  • E. Albumin

Explanation: Cholesterol serves as the building block for steroid hormones such as estrogen, testosterone, cortisol, and aldosterone, which are involved in processes like reproduction, stress response, and water balance.

Why the other options are wrong
  • A. Choline is a precursor to acetylcholine, a key neurotransmitter involved in memory, muscle control, and mood regulation.
  • C. Oils are the precursors of steroids. Certain oils also influence hormone synthesis by contributing to the balance of fatty acids that regulate hormonal pathways.
  • D. Waxes are a class of lipids composed of long-chain fatty acids esterified to long-chain alcohols. They are typically found in both plants and animals and serve primarily as protective coatings. While waxes themselves are not widely used as direct precursors in major biochemical pathways like oils or fats, they can serve certain roles in biological and industrial processes.
  • E. Albumin is a type of protein that plays a vital role in various physiological processes, particularly in maintaining the body’s fluid balance and transporting substances

Q76. A neural cable extending from the brain down through the backbone and enclosed in the vertebral column is called:

  • A. Meninges
  • B. Spinal cord
  • C. Axon
  • D. Brainstem
  • E. Hindbrain

Explanation: The spinal cord is a long, cylindrical bundle of nerve fibers and supporting cells that extends from the brainstem (specifically the medulla oblongata) down through the vertebral column. It serves as the main communication pathway between the brain and the rest of the body. The spinal cord is a crucial component of the central nervous system (CNS), along with the brain, and it is protected by the vertebrae, the meninges, and cerebrospinal fluid (CSF).

Why the other options are wrong
  • A. The meninges are three protective layers of connective tissue that cover the brain and spinal cord, forming a crucial part of the central nervous system's defense. Their primary function is to protect the brain and spinal cord, provide structural support, and ensure that the cerebrospinal fluid (CSF) circulates properly.
  • C. An axon is a long, slender projection of a nerve cell (neuron) that conducts electrical impulses away from the neuron's cell body (soma). It plays a critical role in transmitting signals within the nervous system. Axons are fundamental to communication between neurons, as well as between neurons and muscles or glands
  • D. The brainstem is a critical part of the brain that connects the cerebrum (the upper part of the brain) with the spinal cord. It controls several vital functions necessary for life, such as breathing, heart rate, blood pressure, and digestion, and serves as a relay station for sensory and motor information. The brainstem also houses many of the cranial nerves, which control functions such as eye movement, facial sensation, and swallowing.
  • E. The hindbrain, also known as the rhombencephalon, is the lower part of the brain and one of the three major divisions of the brain, along with the midbrain and forebrain. It plays a crucial role in regulating vital bodily functions, including motor control, balance, and basic life-sustaining activities like breathing and heart rate. The hindbrain consists of three main structures: the medulla oblongata, the pons, and the cerebellum.

Q77. Which of the following accurately describes Helicobacter pylori?

  • A. Flagellated rod-shaped bacterium
  • B. Flagellated chain bacterium
  • C. Flagellated spiral-shaped bacterium
  • D. Non-flagellated spiral-shaped bacterium
  • E. Non-flagellated rod-shaped bacterium

Explanation: Helicobacter pylori is a flagellated spiral-shaped bacterium. Its spiral shape and flagella help it move through the mucus lining of the stomach, contributing to its pathogenicity. The other options are incorrect because they do not accurately describe both the flagellation and the spiral shape of H. pylori. Options describing it as rod-shaped or non-flagellated do not match its known scientific characteristics.

Why the other options are wrong
  • A. This option is incorrect. While flagellated, Helicobacter pylori is not rod-shaped; it is spiral-shaped.
  • B. This option is incorrect. Helicobacter pylori does not form chains; it is a single, spiral-shaped organism.
  • D. This option is incorrect. While Helicobacter pylori is spiral-shaped, it is also flagellated, which aids in its motility.
  • E. This option is incorrect. Helicobacter pylori is both flagellated and spiral-shaped, not rod-shaped or non-flagellated.

Q78. Water has a very high heat of vaporization, i.e.:

  • A. 274 kcal/kg
  • B. 374 kcal/kg
  • C. 474 kcal/kg
  • D. 574 kcal/kg
  • E. 674 kcal/kg

Explanation: Water has a high heat of vaporization of 574 kcal/kg due to the extensive hydrogen bonding between its molecules. This property means that a significant amount of energy is needed to convert water from a liquid to a gas, impacting various biological processes such as temperature regulation in organisms. The other options are incorrect because they either underestimate or overestimate the energy required due to hydrogen bonding in water.

Why the other options are wrong
  • A. This option is incorrect. This value is too low and does not account for the strong hydrogen bonds in water that require more energy to break.
  • B. This option is incorrect. This value underestimates the energy needed to vaporize water due to its extensive hydrogen bonding.
  • C. This option is incorrect. Although closer, this value still does not accurately represent the energy required due to water's strong intermolecular forces.
  • E. This option is incorrect. This value is too high and overestimates the energy required to vaporize water.

Q79. Which cells are responsible for the formation of cartilage?

  • A. Neurosecretory cells
  • B. Lymphocytes
  • C. Osteocytes
  • D. Leukocytes
  • E. Chondrocytes

Explanation: Chondrocytes are the only cells found in healthy cartilage. They originate from chondroblasts and are responsible for producing and maintaining the cartilage matrix, which is made up of collagen and proteoglycans. Chondrocytes help maintain the structure and function of cartilage by regulating its repair and regeneration.

Why the other options are wrong
  • A. Neurosecretory cells are specialized neurons that produce and release hormones into the blood. Unlike typical neurons, which communicate through electrical signals and neurotransmitters, neurosecretory cells release hormones in response to neural signals. These hormones then travel through the bloodstream to regulate various physiological processes.
  • B. Lymphocytes are a type of white blood cell that plays a crucial role in the immune system. They are primarily responsible for identifying and attacking pathogens like viruses, bacteria, and abnormal cells.
  • C. Osteocytes are mature bone cells found within the bone matrix. They develop from osteoblasts and become embedded in the bone tissue they help form.
  • D. Leukocytes, or white blood cells, are immune cells that help protect the body against infections, foreign invaders, and diseases. They circulate in the blood and lymphatic system and play a key role in the body's immune response.

Q80. Behavioral responses are controlled by:

  • A. Pituitary gland
  • B. Cerebellum
  • C. Thalamus
  • D. Amygdala
  • E. Hippocampus

Explanation: The correct answer is Amygdala because it plays a key role in processing emotions and controlling behavioral responses that are related to those emotions, particularly fear and aggression. The amygdala is involved in the emotional aspect of behavior, making it a key structure in behavioral control. In contrast, the Pituitary gland regulates hormones and bodily functions but does not directly manage behavioral responses. The Cerebellum is primarily focused on coordination and motor control, while the Thalamus serves as a sensory relay and is not directly associated with behavioral control. Lastly, the Hippocampus is important for memory formation, but it does not have an immediate role in controlling behaviors.

Why the other options are wrong
  • A. The pituitary gland is known as the 'master gland' of the endocrine system, regulating various hormones, but it does not directly control behavioral responses.
  • B. The cerebellum is primarily responsible for motor control and coordination, rather than direct control of behavioral responses.
  • C. The thalamus acts as a relay station for sensory information, but it is not the primary structure for controlling behavioral responses.
  • E. The hippocampus is essential for forming new memories and spatial navigation, but it does not directly control behavioral responses.

Q81. In skeletal muscles, which tube runs perpendicularly and is connected with the sarcoplasmic reticulum?

  • A. Troponin
  • B. T-tubules
  • C. Monochondrion
  • D. Myosin
  • E. Actin

Explanation: T-tubules (transverse tubules) are invaginations of the cell membrane (sarcolemma) in muscle cells. They help transmit electrical impulses (action potentials) deep into the muscle fiber, ensuring that the signal for contraction reaches all parts of the muscle at the same time. This coordinated signaling triggers the release of calcium from the sarcoplasmic reticulum, which is essential for muscle contraction.

Why the other options are wrong
  • A. Troponin is a protein complex in muscle cells that helps regulate muscle contraction, particularly in the heart. It's released into the blood when the heart muscle is damaged, making it a key marker in diagnosing heart attacks.
  • C. A monochondrion refers to a single mitochondrion, which is an organelle in cells responsible for producing energy (ATP) through cellular respiration. It is often called the "powerhouse" of the cell.
  • D. Myosin is a motor protein that works with actin to produce muscle contraction. It converts chemical energy (from ATP) into mechanical force by pulling on actin filaments, enabling movement and contraction in muscle cells.
  • E. Actin is a protein that forms thin filaments in muscle cells and plays a crucial role in muscle contraction, cell movement, and maintaining cell shape. It interacts with myosin to enable these functions.

Q82. The active site of the enzyme is the region that:

  • A. Binds with the product of catalytic reaction
  • B. Is involved in catalytic reactions
  • C. Is inhibited by coenzymes and cofactors
  • D. Binds allosteric regulators of the enzyme
  • E. Is inhibited by coenzymes only

Explanation: The active site of an enzyme is crucial because it is the region where substrates bind and undergo chemical transformation during a catalytic reaction. This is what makes Option B correct. The other options are incorrect because they either misunderstand the role of the active site or confuse it with other parts of the enzyme, such as allosteric sites or the role of cofactors and coenzymes. Coenzymes and cofactors often assist in the enzyme's function, rather than inhibit the active site, and allosteric regulators affect enzyme activity through different sites.

Why the other options are wrong
  • A. This option is incorrect. The active site primarily interacts with substrates, not products.
  • C. This option is incorrect. Coenzymes and cofactors typically assist enzyme activity rather than inhibit it.
  • D. This option is incorrect. Allosteric regulators bind to sites other than the active site, known as allosteric sites.
  • E. This option is incorrect. Coenzymes do not inhibit the active site; they often play a crucial role in facilitating enzyme activity.

Q83. Frostbites are due to:

  • A. Fluid retention
  • B. Vasodilation
  • C. Muscular expansion
  • D. Vasoconstriction
  • E. Vascular contraction

Explanation: Vasoconstriction is the narrowing of blood vessels, which reduces blood flow and increases blood pressure. It can occur in response to cold temperatures, stress, or certain hormones, helping to regulate blood distribution and maintain body temperature.

Why the other options are wrong
  • A. Fluid retention, or edema, is the accumulation of excess fluid in the body's tissues. It can cause swelling, particularly in the legs, ankles, and feet. Common causes include heart failure, kidney problems, hormonal changes, and certain medications.
  • B. Vasodilation is the widening of blood vessels, which increases blood flow and decreases blood pressure. It occurs in response to factors like heat, increased carbon dioxide, or certain hormones, helping to regulate body temperature and improve oxygen delivery to tissues.
  • C. Muscular expansion refers to the process where muscles increase in size or volume, often as a result of exercise, particularly strength training. This occurs through muscle fiber hypertrophy, where individual muscle fibers grow in response to resistance or overload, leading to overall muscle growth.
  • E. Vascular contraction refers to the tightening of blood vessel walls, leading to vasoconstriction. This process decreases the diameter of the vessels, reducing blood flow and increasing blood pressure. It’s often regulated by the nervous system and hormones in response to various physiological needs.

Q84. In which part of the brain are a set of neurosecretory cells found that exert control over the anterior pituitary gland by secreting, releasing, and inhibiting hormones?

  • A. Pons
  • B. Hypothalamus
  • C. Hippocampus
  • D. Amygdala
  • E. Midbrain

Explanation: The hypothalamus is a small brain region that regulates essential bodily functions, including temperature, hunger, thirst, sleep-wake cycles, and emotional responses. It connects the nervous system to the endocrine system by controlling the pituitary gland, which releases hormones that influence various processes in the body.

Why the other options are wrong
  • A. The pons is a structure in the brainstem that plays a key role in regulating vital functions, relaying signals between different parts of the brain, and controlling sleep and arousal.
  • C. The hippocampus is a brain region involved in forming and organizing memories, as well as spatial navigation. It plays a key role in converting short-term memories into long-term ones.
  • D. The amygdala is a small, almond-shaped structure in the brain that plays a key role in processing emotions, especially fear and pleasure. It helps in emotional memory formation and is involved in the body's response to stress.
  • E. The midbrain is a part of the brainstem located between the forebrain and hindbrain. It is involved in functions such as vision, hearing, motor control, and the regulation of alertness and arousal.

Q85. It transports oxygen from the lungs to every tissue of the body.

  • A. Hemoglobin
  • B. Proteins
  • C. Hormones
  • D. Lipids
  • E. Antibodies

Explanation: Hemoglobin is a protein found in red blood cells responsible for transporting oxygen from the lungs to the body's tissues and returning carbon dioxide from the tissues back to the lungs. It consists of four subunits, each containing an iron atom that binds to oxygen, giving blood its red color.

Why the other options are wrong
  • B. Proteins are large, complex molecules made up of amino acids that perform essential roles in the body. They provide structural support to cells and tissues, act as enzymes to catalyze biochemical reactions, transport substances across membranes or in the bloodstream, defend against pathogens through antibodies, and regulate various biological processes. Vital for growth, repair, and overall function, proteins are crucial for the health of living organisms.
  • C. Hormones are chemical messengers produced by glands in the endocrine system. They regulate various physiological processes in the body, including metabolism, growth and development, mood, and reproductive functions. Hormones are released into the bloodstream and travel to target organs or tissues, where they bind to specific receptors to elicit responses. Examples include insulin (regulating blood sugar), adrenaline (involved in the stress response), and estrogen (affecting reproductive health). Hormones play a crucial role in maintaining homeostasis and overall bodily functions.
  • D. Lipids are hydrophobic molecules, including fats, oils, waxes, phospholipids, and steroids, that serve several vital functions in the body. They provide energy storage, serving more energy per gram than carbohydrates and proteins, and are essential structural components of cell membranes. Lipids also offer insulation and protection for vital organs and play a role in hormone production. Overall, they are crucial for metabolism, cellular structure, and physiological regulation.
  • E. Antibodies, also known as immunoglobulins, are specialized proteins produced by the immune system in response to foreign substances, such as bacteria, viruses, and toxins. They play a critical role in identifying and neutralizing these pathogens. Antibodies work by binding to specific antigens (the foreign molecules), marking them for destruction by other immune cells, or neutralizing their harmful effects. There are five main classes of antibodies (IgA, IgD, IgE, IgG, and IgM), each with distinct functions in the immune response. Overall, antibodies are essential for protecting the body against infections and maintaining immune health.

Q86. It is a condition of blindness where a person cannot distinguish blue color.

  • A. Protanopia
  • B. Monochromacy
  • C. Dichromacy
  • D. Deuteranopia
  • E. Tritanopia

Explanation: Tritanopia is a rare form of color blindness where a person is unable to perceive blue light due to the absence or malfunction of blue cone cells. This causes difficulty distinguishing between blues and yellows, and often makes the world appear in shades of red, pink, green, and grey.

Why the other options are wrong
  • A. Protanopia is a type of color blindness where a person is unable to perceive red light. It occurs due to the absence or malfunction of red cone cells in the eye, making reds and greens appear similar and often confused.
  • B. Monochromacy, or total color blindness, is a condition where a person can only see shades of gray, black, and white. It happens when all the cone cells in the eye (responsible for detecting color) are absent or non-functional. People with monochromacy lack the ability to perceive any color.
  • C. Dichromacy is a form of color blindness where a person can only perceive two of the three primary colors due to the absence of one type of cone cell in the eye. There are three types: protanopia (missing red cones), deuteranopia (missing green cones), and tritanopia (missing blue cones). People with dichromacy have limited color perception compared to those with normal vision.
  • D. Deuteranopia is a type of color blindness where a person cannot perceive green light due to the absence or malfunction of green cone cells in the eye. As a result, greens and reds often appear similar, leading to difficulty distinguishing between these colors.

Q87. Chelate means:

  • A. Bidentate
  • B. lon
  • C. Monodentate
  • D. Crab claws
  • E. Metal

Explanation: Chelates are sometimes metaphorically referred to as "crab claws" because of how they "grasp" a metal ion with multiple coordination sites, similar to how a crab uses its claws to hold onto something.

Why the other options are wrong
  • A. Bidentate refers to a ligand that can form two bonds with a central metal atom or ion in a coordination complex. The ligand has two donor atoms that can simultaneously bind to the same metal center, creating a more stable complex compared to monodentate ligands (which form only one bond).
  • B. In chemistry, an ion is an atom or molecule that has a net electrical charge due to the loss or gain of electrons.
  • C. Monodentate refers to a ligand that can form only one bond with a central metal atom or ion in a coordination complex. The ligand has a single donor atom that coordinates to the metal center.
  • E. Metals are elements characterized by their ability to conduct electricity and heat, possess high density, and generally exhibit properties like malleability, ductility, and luster.

Q88. The shape of an ammonia molecule is:

  • A. Angular
  • B. Tetrahedral
  • C. Linear
  • D. Planar
  • E. Pyramidal

Explanation: The shape of an ammonia (NH₃) molecule is trigonal pyramidal. This geometry arises because Nitrogen is at the center, bonded to three hydrogen atomst.It has one lone pair of electrons, which repels the bonded pairs, pushing the hydrogen atoms down into a pyramid shape.

Why the other options are wrong
  • A. An angular shape (also called bent or V-shaped) in molecular geometry refers to a structure where the atoms form an angle instead of being in a straight line. This occurs when there are lone pairs of electrons on the central atom, which repel the bonding pairs, causing the molecule to bend.
  • B. A tetrahedral shape in molecular geometry refers to a structure where a central atom is bonded to four other atoms or groups, arranged at the corners of a tetrahedron. The bond angles between the atoms are approximately 109.5°.
  • C. A linear shape in molecular geometry refers to a structure where atoms are arranged in a straight line with a bond angle of 180°. This geometry occurs when the central atom is bonded to two other atoms with no lone pairs affecting the geometry.
  • D. A planar shape in molecular geometry refers to a structure where all the atoms in a molecule lie in a single plane. This geometry often occurs in molecules with specific arrangements of bonding pairs and lone pairs of electrons.

Q89. It is used as a preservative and antibacterial agent in livestock feed:

  • A. Butyric acid
  • B. Formic acid
  • C. Caroic acid
  • D. Propionic acid
  • E. Valeric acid

Explanation: **Formic acid** (HCOOH) is the simplest carboxylic acid with a pungent odor. It's found in ant and bee venom and is used in textiles, leather production, and as a preservative. It also has antibacterial properties.

Why the other options are wrong
  • A. **Butyric acid** (C₄H₈O₂) is a short-chain fatty acid with a four-carbon structure (CH₃CH₂CH₂COOH). It has a strong, rancid odor and is found in rancid butter. It’s used in chemical production, including perfumes and flavorings, and is naturally produced in the human gut during fiber fermentation.
  • C. Caroic acid(H₂SO₅), also known as peroxymonosulfuric acid, is a strong oxidizing agent derived from sulfuric acid. It is used as a bleaching agent and disinfectant in industrial cleaning and wastewater treatment. Caro's acid is highly reactive and unstable, making it hazardous to handle.
  • D. Propionic acid (C₃H₆O₂) is a carboxylic acid with a three-carbon chain. It has a slightly pungent odor and is used as a food preservative to inhibit mold and bacteria growth, especially in baked goods. Additionally, it serves in the production of chemicals like herbicides and plastics.
  • E. Valeric acid (C₅H₁₀O₂) is a carboxylic acid with a five-carbon chain, characterized by a strong, pungent odor. It occurs naturally in valerian root and some cheeses. Valeric acid is used in producing esters for flavorings and fragrances, as well as in pharmaceuticals.

Q90. The charge of an electron is:

  • A. -1.602x10-19C
  • B. 1.602x10-15C
  • C. 1.602x10-2C
  • D. 1.602x10-18C
  • E. 1.602x10-1C

Explanation: The correct answer is Option A: -1.602x10-19C. This value is the recognized elementary charge representing the negative charge carried by an electron. The other options are incorrect as they either overestimate or underestimate this fundamental constant. Understanding the magnitude of elementary charge is crucial for solving problems related to atomic structure and electrostatics.

Why the other options are wrong
  • B. Incorrect. This value does not represent the charge of an electron. It is significantly larger by four orders of magnitude.
  • C. Incorrect. This option is incorrect because the magnitude is much larger than the actual charge of an electron.
  • D. Incorrect. This value is larger by an order of magnitude compared to the correct charge of an electron.
  • E. Incorrect. This option is incorrect as it represents a charge that is exceedingly larger than the actual charge of an electron.

Q91. The equilibrium of this reaction would not be affected by an increase in pressure:

  • A. 2SO2 + 02—-->2SO3
  • B. N2 + 02 —---> 2NO
  • C. 2NO + Cl —--› 2NOCI
  • D. PCl5 → PCl3 + Cl2
  • E. CO + 3H2 —--> CH4 + H20

Explanation: The correct answer is N₂ + O₂ → 2NO, because an increase in pressure doesn't affect the equilibrium since the number of gas molecules remains the same on both sides.

Why the other options are wrong
  • A. This reaction involves 3 moles of gas on the reactant side (2SO₂ + 1O₂) and 2 moles of gas on the product side (2SO₃). An increase in pressure would favor the formation of SO₃, reducing the number of gas molecules and shifting the equilibrium toward the products.
  • C. This reaction involves 3 moles of gas on the reactant side (2NO + 1Cl₂) and 2 moles of gas on the product side (2NOCl). An increase in pressure would shift the equilibrium toward NOCl, reducing the number of gas molecules
  • D. This reaction has 1 mole of gas (PCl₅) on the reactant side and 2 moles of gas (PCl₃ + Cl₂) on the product side. An increase in pressure would shift the equilibrium toward PCl₅ to reduce the number of gas molecules.
  • E. This reaction has 4 moles of gas on the reactant side (CO + 3H₂) and 2 moles of gas on the product side (CH₄ + H₂O). An increase in pressure would favor the products, as it reduces the number of gas molecules.

Q92. The density of benzene is:

  • A. 0.80 g/cm³
  • B. 0.88 g/cm³
  • C. 0.85 g/cm³
  • D. 0.82 g/cm³
  • E. 0.08 g/cm³

Explanation: Benzene is a hydrocarbon with a density of approximately 0.879 g/cm³ at 20°C. This means it is less dense than water (1.00 g/cm³) and will float when placed in it. The closest option,0.88 g/cm³, accurately reflects this property. Other options either significantly underestimate or are slightly lower than the actual density of benzene.

Why the other options are wrong
  • A. This option is incorrect. Benzene's density is slightly higher than this value.
  • C. This option is incorrect. Although closer than some other options, it still underestimates benzene's actual density.
  • D. This option is incorrect. It is lower than the actual density of benzene.
  • E. This option is incorrect. It is far too low and unlikely for any typical liquid, especially benzene.

Q93. According to Raoult's law, the relative lowering of vapor pressure is equal to:

  • A. Mole fraction of solute
  • B. Mole fraction of solvent
  • C. Molarity
  • D. Molality
  • E. Parts per million

Explanation: In Raoult's Law, the lowering of vapor pressure of a solvent in a solution is directly related to the mole fraction of the solute.

Why the other options are wrong
  • B. The mole fraction of the solvent in a solution is the ratio of the number of moles of solvent to the total number of moles of all components (solute and solvent) in the solution.
  • C. Molarity (M) is a measure of the concentration of a solution, defined as the number of moles of solute per liter of solution.
  • D. Molality (m) is a measure of the concentration of a solution, defined as the number of moles of solute per kilogram of solvent.
  • E. Parts per million (ppm) is a unit used to express very dilute concentrations of a substance in a solution. It represents the number of parts of solute per one million parts of the solution

Q94. When an unsymmetrical alkene undergoes addition reactions, the negative part of attacking reagent is added to that double-bonded carbon atom which contains:

  • A. Highest number of chloride atoms
  • B. Lesser number of hydrogen atoms
  • C. Highest number of hydrogen atoms
  • D. Moderate number of hydrogen atoms
  • E. Lesser number of chloride atoms

Explanation: This is based on Markovnikov's Rule, which states that in the addition of a protic acid (such as HCl, HBr, etc.) to an unsymmetrical alkene, the hydrogen atom (the positive part of the reagent) attaches to the carbon with the greater number of hydrogen atoms, and the negative part (such as Cl⁻, Br⁻, etc.) attaches to the carbon with the fewer hydrogen atoms.

Why the other options are wrong
  • A. Chloride atoms are not part of the unsaturated structure. The rule focuses on hydrogen atoms, not halogens or other substituents.
  • C. According to Markovnikov's Rule, the hydrogen from the attacking reagent adds to the carbon that already has more hydrogen atoms, leaving the negative part of the reagent (such as Cl⁻) to attach to the carbon with fewer hydrogen atoms.
  • D. This option is irrelevant because Markovnikov's Rule dictates that the addition depends on the relative number of hydrogen atoms (either more or less), not on a "moderate" amount.
  • E. The number of chloride atoms on the alkene is not relevant to the rule, as it concerns the distribution of hydrogen atoms on the double-bonded carbons.

Q95. According to Charles, at 0º K (-273.15°C), the volume of a gas should be:

  • A. -2
  • B. Zero
  • C. -1
  • D. +2
  • E. +1

Explanation: At 0 K (−273.15°C), the temperature is theoretically at absolute zero, where the kinetic energy of gas particles ceases. According to Charles's Law, which states that the volume of a gas is directly proportional to its temperature on the Kelvin scale, the volume would theoretically become zero as the temperature approaches absolute zero. This means the gas would occupy no space, as there would be no energy to maintain volume. Options suggesting negative or positive volumes are incorrect since they do not reflect the direct relationship outlined by Charles's Law.

Why the other options are wrong
  • A. This option is incorrect. Negative volumes are not physically meaningful for gases.
  • C. This option is incorrect. Negative volumes are not physically meaningful for gases.
  • D. This option is incorrect. At 0 K, the volume does not increase; it approaches zero.
  • E. This option is incorrect. At 0 K, the volume does not increase; it approaches zero.

Q96. The paramagnetic behavior of molecules such as oxygen molecules cannot be explained by:

  • A. Molecular orbital theory
  • B. Hybridization
  • C. Valence bond theory
  • D. Valence shell electron pair repulsion theory

Explanation: Molecular Orbital Theory (MOT): This theory accounts for paramagnetism by considering the arrangement of electrons in molecular orbitals, where unpaired electrons in these orbitals lead to paramagnetic properties.Valence Bond Theory (VBT): While VBT primarily focuses on the formation of bonds and hybridization, it can also address unpaired electrons in certain cases, indirectly linking to paramagnetism.Valence Shell Electron Pair Repulsion (VSEPR) Theory: This theory is primarily used to predict molecular shapes based on the repulsion between electron pairs. It does not consider the spin of electrons or their distribution in orbitals, and thus does not provide an explanation for paramagnetism.Hybridization: This concept can relate to paramagnetism when discussing the formation of bonds and the arrangement of unpaired electrons in hybrid orbitals.

Why the other options are wrong
  • A. Molecular Orbital (MO) theory explains bonding by combining atomic orbitals to form molecular orbitals that extend over the entire molecule. These orbitals are classified as bonding (which stabilize the molecule) or anti-bonding (which destabilize it). Electrons fill these orbitals based on energy levels, following specific rules. MO theory is useful for explaining molecular properties like magnetism and electron delocalization, providing a more detailed understanding than Valence Bond Theory.
  • B. Hybridization is the process where atomic orbitals mix to form new hybrid orbitals that explain the geometry of chemical bonds in molecules. This occurs during bonding to maximize orbital overlap, influencing molecular shapes. Common types include **sp** (linear), **sp²** (trigonal planar), and **sp³** (tetrahedral), each corresponding to different bond angles and spatial arrangements. Hybridization helps explain molecular geometry and bonding more effectively than basic atomic orbital concepts alone.
  • D. Valence Shell Electron Pair Repulsion (VSEPR) theory predicts the 3D shape of molecules based on the repulsion between electron pairs in the valence shell of the central atom. It helps explain molecular geometry by assuming that electron pairs, both bonding and non-bonding, repel each other and try to be as far apart as possible.Paramagnetic behavior occurs in atoms or molecules that have unpaired electrons. These unpaired electrons generate a magnetic moment, causing the substance to be attracted to an external magnetic field. In contrast, diamagnetic substances have all electrons paired and are weakly repelled by magnetic fields.

Q97. The decomposition of H2O2 is inhibited by:

  • A. MnO2
  • B. Ethanol
  • C. Glycerin
  • D. V203
  • E. Iron powder

Explanation: the decomposition of hydrogen peroxide is suppressed by adding glycerol to the solution of it. Thus, glycerine or glycerol acts as a negative catalyst

Why the other options are wrong
  • A. Manganese dioxide (MnO₂) serves multiple functions across various fields due to its unique properties. It acts as a catalyst, notably facilitating the decomposition of hydrogen peroxide and other oxidation-reduction reactions. MnO₂ is used as a cathode material in batteries, particularly alkaline batteries, and functions as an oxidizing agent in organic synthesis, converting alcohols to carbonyl compounds. Additionally, it serves as a black pigment in ceramics and glass, is employed in water treatment to remove impurities, and is utilized in environmental remediation to oxidize organic contaminants. Its versatility makes MnO₂ valuable in industrial, environmental, and chemical applications.
  • B. Ethanol can inhibit the breakdown of hydrogen peroxide (H₂O₂) through several mechanisms. It acts as a radical scavenger, reacting with free radicals that would otherwise catalyze H₂O₂ decomposition, thereby stabilizing it. Additionally, ethanol can compete with hydrogen peroxide for reactions with certain catalysts, further slowing down the decomposition process. As a solvent, ethanol also alters the environment around hydrogen peroxide, potentially enhancing its stability. Incorporating ethanol into formulations with hydrogen peroxide improves its shelf-life and effectiveness in applications like disinfectants and bleaching agents.
  • D. Vanadium(III) oxide (V₂O₃) has several important functions across various fields. It is commonly used as a catalyst in chemical reactions, particularly in the production of sulfuric acid and various oxidation processes. V₂O₃ also serves as an electrode material in lithium-ion batteries due to its good conductivity and electrochemical properties. In the ceramics industry, it is used as a pigment, providing colors ranging from green to black, and in the production of glass and tiles. Additionally, V₂O₃ is significant in materials science research, especially in studies of magnetic and electronic properties, and is explored for its potential applications in superconductivity. Its coatings can enhance the corrosion resistance of metals, making it valuable in industrial and technological applications.
  • E. Iron powder serves a variety of functions across multiple industries due to its unique properties. It is widely used in metal injection molding (MIM) to produce complex parts with high precision and low waste and as a feedstock in additive manufacturing (3D printing) for iron-based components. In magnetic applications, iron powder is essential for creating soft magnetic cores in transformers and inductors. Additionally, it acts as a catalyst in chemical reactions, such as the synthesis of ammonia, and serves as a reducing agent in various processes. Iron powder is also utilized in the production of steel and iron-based construction materials, included in dietary supplements to combat iron deficiency, and used to produce rust-resistant coatings and paints. These diverse applications make iron powder valuable in industrial, chemical, and nutritional sectors.

Q98. The bond length between C-C in benzene is:

  • A. 1.34 Å
  • B. 1.39 Å
  • C. 1.56 Å
  • D. 1.38 Å
  • E. 1.46 Å

Explanation: Option B is correct because the bond length of C-C in benzene is approximately 1.39 Å. This is due to the delocalization of electrons across the ring, resulting in bond lengths that are neither purely single nor double bonds. Option A (1.34 Å) is too short, suggesting a double bond, which does not apply here. Option C (1.56 Å) is indicative of a single bond, which is also not the case. Option D (1.38 Å) is close, but slightly off the experimentally determined value. Option E (1.46 Å) is too long and does not fit the resonance hybrid model of benzene.

Why the other options are wrong
  • A. This option is incorrect. This length is too short for the C-C bonds in benzene, which are not double bonds.
  • C. This option is incorrect. This length is more typical for single C-C bonds, which do not apply to benzene's structure due to resonance.
  • D. This option is incorrect. Although close, it does not match the experimentally determined average bond length in benzene.
  • E. This option is incorrect. This length is too long for benzene's C-C bonds and more characteristic of other types of carbon-carbon bonds.

Q99. "In an orbital of an atom, no two electrons can have the same set of four quantum numbers; at least one quantum number must be different." This statement is:

  • A. Aufbau principle
  • B. Pauli's exclusion principle
  • C. Hund's rule
  • D. Wissewser rule
  • E. Magnetic quantum number

Explanation: Pauli's exclusion principle states that no two fermions (such as electrons) can occupy the same quantum state simultaneously within an atom. This principle explains why electrons in an atom fill different orbitals and have distinct quantum numbers.

Why the other options are wrong
  • A. The Aufbau principle states that electrons fill atomic orbitals starting from the lowest energy level before moving to higher energy levels. This principle helps explain the electron configuration of atoms in their ground state.
  • C. Hund's rule states that electrons will fill degenerate orbitals (orbitals of the same energy) singly first, with parallel spins, before pairing up. This minimizes electron-electron repulsion and maximizes total spin, leading to greater stability in the atom.
  • D. Wiswesser's rule is a method used to determine the energy sequence of atomic subshells based on the quantum numbers nnn (the principal quantum number) and lll (the azimuthal quantum number).
  • E. The magnetic quantum number (mlm_lml​) specifies the orientation of an electron's orbital around the nucleus. It is one of the four quantum numbers that describe the state of an electron in an atom.

Q100. The IUPAC name of isopropyl alcohol is:

  • A. 1-butanol
  • B. 2-propanol
  • C. 1-propanol
  • D. 2-butanol
  • E. propanol

Explanation: The correct IUPAC name for isopropyl alcohol is propan-2-ol. This name reflects the structure of the molecule: a three-carbon chain (propane) with a hydroxyl group (-OH) attached to the second carbon atom. The prefix 'iso-' in isopropyl indicates the branching at the second carbon, which aligns with the IUPAC naming as 'propan-2-ol'.Option A (1-butanol) and Option D (2-butanol) are incorrect because they describe four-carbon alcohols, not three. Option C (1-propanol) is incorrect because the hydroxyl group is on the first carbon, not the second. Option E (propanol) is too vague as it doesn't specify the position of the hydroxyl group.

Why the other options are wrong
  • A. This option is incorrect. 1-butanol is a four-carbon alcohol, whereas isopropyl alcohol has only three carbon atoms.
  • C. This option is incorrect. 1-propanol has the hydroxyl group attached to the first carbon, not the second as in isopropyl alcohol.
  • D. This option is incorrect. 2-butanol has four carbon atoms, while isopropyl alcohol has only three.
  • E. This option is incorrect. 'Propanol' is not specific enough as it doesn't indicate the position of the hydroxyl group, which is crucial in IUPAC naming.

Q101. The unit of rate constant for the first-order reaction is:

  • A. conc.s-1
  • B. M2s-1
  • C. s-1
  • D. M-1s-1
  • E. M-1s-2

Explanation: The unit of the rate constant for a first-order reaction is s-1. This is because, for a first-order reaction, the rate is directly proportional to the concentration of one reactant, and the order of the reaction dictates the units of the rate constant. For a first-order reaction, the units of the rate (M s-1) divided by the concentration (M) give the rate constant units of s-1. Other options, like M2s-1 and M-1s-1, correspond to higher-order reactions or are not applicable to standard reaction orders.

Why the other options are wrong
  • A. This option is incorrect. 'conc.' is not a standard unit, and the correct unit for a first-order reaction is not dependent on concentration units.
  • B. This option is incorrect. This unit is typical of a third-order reaction rate constant, not a first-order.
  • D. This option is incorrect. This unit is typical of a second-order reaction rate constant.
  • E. This option is incorrect. This unit does not correspond to a common order of reaction.

Q102. Volume is a:

  • A. Intensive property
  • B. Entropy
  • C. Path function
  • D. Isolated system
  • E. State function

Explanation: A state function is a property of a system that depends only on its current state, rather than the path taken to reach that state. This means that the value of a state function is determined solely by the state of the system at a given moment, regardless of how the system arrived at that state.

Why the other options are wrong
  • A. An intensive property is a physical property of a substance that does not depend on the amount of matter present. Examples of intensive properties include temperature, pressure, density, and boiling point. These properties remain the same regardless of the size or mass of the sample.
  • B. Entropy is a measure of disorder or randomness in a system. In thermodynamics, it reflects how much energy in a system is unavailable to do work, and it tends to increase in natural processes, leading to the second law of thermodynamics, which states that the entropy of an isolated system will always increase or remain constant over time.
  • C. A path function is a property that depends on the specific route taken to achieve a particular state in a thermodynamic process. In contrast to state functions, which depend only on the initial and final states of a system (such as temperature, pressure, and volume), path functions are influenced by the specific path or process through which the system undergoes change.
  • D. An isolated system is a physical system that does not exchange matter or energy with its surroundings. In thermodynamics, this means that both heat and work cannot enter or leave the system, making it completely self-contained.

Q103. Collection of gas over water is an example of:

  • A. Boyle's law
  • B. Avogadro's law
  • C. Dalton's law
  • D. Graham's law
  • E. Gay-Lussac law

Explanation: Dalton's Law states that in a mixture of non-reacting gases, the total pressure exerted is equal to the sum of the partial pressures of each individual gas. When collecting gases over water, the total pressure of the gas collected is the sum of the partial pressure of the gas and the vapor pressure of the water at that temperature. For instance, if the vapor pressure of water at a certain temperature is 20 mmHg and the measured total pressure is 740 mmHg, the partial pressure of the gas collected can be found by subtracting the vapor pressure

Why the other options are wrong
  • A. Boyle's Law states that the pressure of a gas is inversely proportional to its volume when the temperature and the amount of gas are held constant.
  • B. Avogadro's Law states that, at a constant temperature and pressure, equal volumes of gases contain an equal number of molecules, regardless of the type of gas.
  • D. Graham's Law describes the rates at which two gases diffuse or effuse and states that the rate of diffusion of a gas is inversely proportional to the square root of its molar mass
  • E. Gay-Lussac's Law states that the pressure of a fixed amount of gas is directly proportional to its absolute temperature when the volume is held constant.

Q104. Dry ice is an example of:

  • A. Molecular solid
  • B. Metallic solid
  • C. Covalent solid
  • D. Ionic solid
  • E. Plastic

Explanation: In dry ice, the CO₂ molecules are held together in the solid by weak intermolecular forces (not by strong covalent or ionic bonds).Because of these weak forces, dry ice sublimates easily at −78.5°C instead of melting into a liquid under normal atmospheric pressure.

Why the other options are wrong
  • B. Metallic solids consist of metal atoms held together by a sea of delocalized electrons, which give them unique properties such as conductivity and malleability. This is not applicable to dry ice.
  • C. Covalent solids have atoms bonded together by covalent bonds in a network, resulting in hard and high-melting-point materials, like diamond. Dry ice does not fit this description.
  • D. Ionic solids are formed by the electrostatic attraction between cations and anions, creating a lattice structure. Dry ice, being molecular in nature, does not belong to this category.
  • E. Plastics are synthetic materials made from polymers, not naturally occurring molecular solids like dry ice. Plastics are versatile and used in many applications, unlike dry ice.

Q105. A low atmospheric pressure system is called:

  • A. Diffusion
  • B. Depression
  • C. Effusion
  • D. Contraction
  • E. Cooling

Explanation: In the context of atmospheric pressure, depression typically refers to the decrease in pressure experienced in specific situations, such as weather phenomena or within a closed system.

Why the other options are wrong
  • A. Diffusion is the process by which molecules move from an area of higher concentration to an area of lower concentration due to their random thermal motion. This process is fundamental to many natural and biological systems.
  • C. Effusion is the process by which gas molecules escape from a container through a small hole or orifice into a vacuum or another space. This phenomenon is significant in understanding the behavior of gases and is governed by Graham's Law.
  • D. In chemistry, contraction primarily refers to the reduction in volume of gases under pressure and the phenomenon where the volume of a solution is less than the combined volumes of its solute and solvent. In the case of gases, according to the ideal gas law, when pressure is applied, the gas particles are forced closer together, leading to a decrease in volume. This principle is critical for understanding how gases behave in various systems, such as engines and refrigeration.
  • E. Cooling in chemistry refers to the process of removing heat from a substance, which can lead to various physical and chemical changes.

Q106. The pH value of human blood is:

  • A. 7.80
  • B. 7.35
  • C. 7.33
  • D. 6.62
  • E. 7.05

Explanation: The pH of human blood is typically maintained between 7.35 and 7.45. This range is slightly basic, as a pH of 7 is considered neutral. The body has several mechanisms to regulate blood pH tightly, including the bicarbonate buffer system. Option B, 7.35, falls within this normal range. Option A, 7.80, is too alkaline for blood, whereas Options C, D, and E (7.33, 6.62, 7.05) are too acidic, indicating varying degrees of acidosis.

Why the other options are wrong
  • A. This option is incorrect. A pH of 7.80 is slightly too alkaline for blood and falls outside the normal physiological range.
  • C. This option is incorrect. While close, a pH of 7.33 is slightly lower than the typical lower limit of the normal blood pH range.
  • D. This option is incorrect. A pH of 6.62 is too acidic for blood and indicates severe acidosis.
  • E. This option is incorrect. A pH of 7.05 is below the normal range and suggests acidosis.

Q107. It is used to distinguish between primary, secondary, and tertiary alcohol:

  • A. Tollens Reagent
  • B. Grignard Reagent
  • C. Benedict Reagent
  • D. Bloor Reagent
  • E. Lucas Reagent

Explanation: Lucas reagent, a mixture of concentrated hydrochloric acid (HCl) and zinc chloride (ZnCl₂), is primarily used to distinguish between primary, secondary, and tertiary alcohols through a process known as the Lucas test. When an alcohol is treated with Lucas reagent, the reaction proceeds via the formation of an alkyl chloride. Tertiary alcohols react rapidly, often within minutes, to form insoluble alkyl chlorides, leading to an immediate cloudiness. Secondary alcohols take longer, while primary alcohols react very slowly, if at all, under these conditions. This differential reactivity helps in identifying the alcohol type based on the time taken for the reaction to occur.

Why the other options are wrong
  • A. Tollens' reagent is a chemical reagent used to detect the presence of aldehydes. It consists of a solution of silver nitrate (AgNO₃) in ammonia (NH₃), which forms a complex ion known as the diamminesilver(I) complex, [Ag(NH₃)₂]⁺. When an aldehyde is mixed with Tollens' reagent and heated, the aldehyde is oxidized to a carboxylic acid, while the silver ions in the reagent are reduced to metallic silver. This reaction typically results in the formation of a shiny silver mirror on the walls of the reaction vessel, hence the name "silver mirror test." Tollens' reagent is particularly useful for distinguishing aldehydes from ketones, as most ketones do not react with it.
  • B. Grignard reagents are organomagnesium compounds represented by the general formula R-MgX, where R is an organic group (alkyl or aryl) and X is a halogen (usually chlorine, bromine, or iodine). These reagents are formed by the reaction of an organic halide with magnesium metal, typically in an anhydrous ether solvent. Grignard reagents are highly reactive and serve as strong nucleophiles, making them invaluable in organic synthesis.
  • C. Benedict's reagent is a chemical solution used to test for the presence of reducing sugars, such as glucose and fructose. It consists of copper(II) sulfate (CuSO₄), sodium carbonate (Na₂CO₃), and sodium citrate. When a reducing sugar is heated with Benedict's reagent, the copper(II) ions (Cu²⁺) in the solution are reduced to copper(I) oxide (Cu₂O), which precipitates out of the solution, forming a colored precipitate. The color change can range from blue (no reducing sugar present) to green, yellow, orange, or brick red, depending on the amount of reducing sugar present. This colorimetric change makes Benedict's test a valuable tool in biochemistry and clinical settings for detecting sugars in urine and other biological samples.
  • D. Bloor's reagent is a solution used to identify the presence of hydroxyl (–OH) groups in organic compounds, particularly alcohols and phenols. It consists of a mixture of periodic acid (HIO₄) and a catalyst, often a strong acid, such as sulfuric acid (H₂SO₄). The reagent reacts with alcohols to oxidize them, producing aldehydes or ketones, which can then be detected through subsequent reactions or by observing color changes. Bloor's reagent is particularly useful for differentiating between primary, secondary, and tertiary alcohols, as the oxidation reactions proceed differently depending on the structure of the alcohol. This reagent is significant in organic chemistry for the characterization and identification of various organic compounds.

Q108. An example of an endothermic reaction is:

  • A. Photosynthesis
  • B. Synthesis of NH3
  • C. Nuclear fission
  • D. Oxidation of sulfur gases
  • E. Burning of fuel and coal

Explanation: Photosynthesis is an endothermic process. During photosynthesis, plants absorb light energy from the sun and convert it into chemical energy by synthesizing glucose from carbon dioxide and water.

Why the other options are wrong
  • B. The synthesis of ammonia (NH₃) from nitrogen (N₂) and hydrogen (H₂) gases, typically through the Haber process, is an exothermic reaction.
  • C. Nuclear fission is an exothermic process. During fission, the nucleus of a heavy atom, such as uranium-235 or plutonium-239, splits into smaller nuclei, along with the release of a significant amount of energy, neutrons, and gamma radiation
  • D. The oxidation of sulfur gases, such as the conversion of sulfur dioxide (SO₂) to sulfur trioxide (SO₃), is an exothermic reaction.
  • E. The burning of fuel and coal is an exothermic reaction. When hydrocarbons in fuels or carbon in coal combust with oxygen (O₂), they produce carbon dioxide (CO₂), water (H₂O), and release energy in the form of heat and light.

Q109. Stoichiometry is the study of _relationship between reactants and products in a chemical reaction by using a balanced chemical equation:

  • A. Quantitative
  • B. Qualitative
  • C. Chemical
  • D. Descriptive
  • E. Physical

Explanation: The correct answer is Option A: Quantitative. Stoichiometry is fundamentally about the quantitative relationships between reactants and products in chemical reactions, using balanced equations to determine the amounts involved. Option B (Qualitative) is incorrect because it deals with non-numeric properties. Option C (Chemical) is too broad, as it does not capture the quantitative nature. Option D (Descriptive) focuses on explanations rather than calculations. Option E (Physical) relates to physical properties, not the quantity-focused aspect of stoichiometry.

Why the other options are wrong
  • B. Qualitative: This relates to the characteristics or qualities of substances, such as color or texture, rather than their amounts. Stoichiometry is concerned with numerical data, not qualitative descriptions.
  • C. Chemical: While stoichiometry is a part of chemistry, the term "chemical" alone is too broad and does not specify the quantitative focus of stoichiometry.
  • D. Descriptive: This involves explaining or describing processes or phenomena, but stoichiometry specifically requires quantitative calculations rather than just descriptions.
  • E. Physical: This term pertains to the physical state or properties of substances, not the quantitative relationships central to stoichiometry.

Q110. Ketones, when treated with LiAlH4, reduce to:

  • A. Primary alcohol
  • B. Tertiary alcohol
  • C. Alcohol
  • D. Dihydric alcohol
  • E. Secondary alcohol

Explanation: Ketones reduce to form secondary alcohols in the presence of lithium aluminum hydride (LiAlH₄). LiAlH₄ is a strong reducing agent that donates hydride ions (H⁻) to the carbonyl carbon of the ketone, resulting in the formation of the corresponding alcohol. For example, if you reduce a ketone like acetone (2-propanone), it will be converted to isopropanol (2-propanol).

Why the other options are wrong
  • A. Primary alcohols are a type of alcohol characterized by the presence of a hydroxyl (–OH) group attached to a carbon atom that is bonded to only one other carbon atom (or none, in the case of methanol). This structural arrangement distinguishes primary alcohols from secondary and tertiary alcohols.
  • B. Tertiary alcohols are a type of alcohol characterized by the presence of a hydroxyl (–OH) group attached to a carbon atom that is bonded to three other carbon atoms. This structure makes tertiary alcohols distinct from primary and secondary alcohols, which have one or two carbon atoms, respectively, bonded to the carbon bearing the hydroxyl group.
  • C. Alcohols are organic compounds characterized by the presence of one or more hydroxyl (–OH) functional groups attached to a carbon atom. They can be classified based on the number of hydroxyl groups and the types of carbon atoms they are attached to.
  • D. Dihydric alcohols, also known as glycols or diols, are organic compounds that contain two hydroxyl (–OH) groups per molecule. The presence of these two hydroxyl groups gives dihydric alcohols unique properties compared to monohydric alcohols (which have one hydroxyl group).

Q111. The term "active mass" used in the Law of Mass Action means:

  • A. Number of moles per dm2
  • B. Number of moles per dm3
  • C. Gram per dm'
  • D. Number of moles
  • E. Number of molecules

Explanation: The term "active mass" in the Law of Mass Action refers to the concentration of a substance involved in a chemical reaction, usually expressed in moles per decimetercube (mol/dm3) for solutions or partial pressure for gases. The Law of Mass Action states that the rate of a chemical reaction is directly proportional to the product of the active masses (concentrations) of the reactants, each raised to the power of their respective stoichiometric coefficients in the balanced chemical equation.

Why the other options are wrong
  • A. This option is incorrect because “number of moles per dm²” represents surface concentration — the number of moles present per unit area, not volume. The Law of Mass Action deals with concentrations in a given volume (dm³), not on surfaces. Hence, the correct unit should relate to volume, not area. Surface concentration may be used in surface chemistry or adsorption studies, but not in the Law of Mass Action, which applies to reactions in bulk phases (gases or solutions).
  • C. This option is incorrect because it represents mass concentration, not molar concentration. Although grams per dm³ (g/dm³) can measure how much mass of a substance is present in one cubic decimeter of solution, it does not directly show the number of particles (moles) that actually participate in the chemical reaction. The Law of Mass Action depends on moles, since reaction rates depend on the number of reacting molecules, not just their mass. Thus, using g/dm³ would not correctly represent “active mass”.
  • D. This option is incorrect because the Law of Mass Action does not use the total number of moles alone; instead, it uses concentration (moles per unit volume). Simply knowing how many moles are present in a reaction mixture does not indicate how concentrated the solution or gas is. For example, 2 moles of solute in 1 dm³ solution have a different reactivity compared to 2 moles in 10 dm³ solution, even though the number of moles is the same. Hence, “number of moles” alone is not sufficient to define “active mass”.
  • E. This option is also incorrect because while chemical reactions do occur between molecules, the Law of Mass Action expresses concentration in terms of moles (a measurable macroscopic quantity), not the absolute number of molecules. The number of molecules is related to moles through Avogadro’s number (6.022 × 10²³), but expressing active mass this way would make calculations impractical and unnecessarily complex. Therefore, “number of molecules” does not represent “active mass” in the context of the Law of Mass Action.

Q112. The neutron was discovered by:

  • A. Max Planck
  • B. Neil Bohr
  • C. J.J. Thomson
  • D. Goldstein
  • E. James Chadwick

Explanation: James Chadwick is best known for his discovery of the neutron in 1932, a breakthrough that significantly advanced our understanding of atomic structure.

Why the other options are wrong
  • A. Max Planck is best known for his discovery of quantum theory, which revolutionized our understanding of atomic and subatomic processes. In 1900, Planck introduced the idea that energy is not emitted or absorbed continuously, but in discrete amounts, called quanta. His work was key to explaining blackbody radiation, and he proposed that the energy of these quanta is proportional to the frequency of the radiation.
  • B. Niels Bohr is best known for his Bohr model of the atom, which he introduced in 1913. His model significantly improved our understanding of atomic structure, particularly for hydrogen
  • C. J.J. Thomson is best known for his discovery of the electron in 1897 and his proposal of the plum pudding model of the atom.
  • D. Eugen Goldstein is best known for his discovery of anode rays, also known as canal rays, which led to the identification of protons as positively charged particles within the atom.

Q113. When chlorobenzene reacts with sodium hydroxide at 350°C and 150 atmospheric pressure, it gives rise to the formation of:

  • A. Sodium chromate
  • B. Phenol
  • C. Sodium phenoxide
  • D. Sodium sulfate
  • E. Phenoxide

Explanation: When chlorobenzene (C₆H₅Cl) reacts with sodium hydroxide (NaOH) at 350°C and 150 atmospheric pressure, it undergoes a nucleophilic substitution reaction known as the Dow process, resulting in the formation of sodium phenoxide (C₆H₅ONa). The reaction benefits from the high temperature and pressure, which facilitate the substitution of the chlorine atom with a hydroxide ion. Sodium phenoxide can later be acidified to produce phenol (C₆H₅OH). Other options, such as sodium chromate and sodium sulfate, are incorrect as they are not products of this reaction. Phenol is formed only after further processing of sodium phenoxide, and phenoxide alone does not specify the sodium salt form.

Why the other options are wrong
  • A. This option is incorrect. Sodium chromate is not produced from the reaction of chlorobenzene with sodium hydroxide.
  • B. This option is partially correct but not the immediate product. Phenol is obtained by acidifying sodium phenoxide, which is the direct product of the reaction.
  • D. This option is incorrect. Sodium sulfate is not involved in this reaction.
  • E. This option is incorrect. While phenoxide is a related term, the specific product is sodium phenoxide.

Q114. The carboxylic acid is stronger than:

  • A. PCl3
  • B. H2SO4
  • C. HNO3
  • D. HCI
  • E. СН3ОН

Explanation: Methanol is a very weak acid with a much higher pKa (around 15.5) compared to carboxylic acids (pKa around 4-5). Carboxylic acids, like acetic acid, are much stronger due to their ability to stabilize the negative charge on the conjugate base (carboxylate anion) through resonance.

Why the other options are wrong
  • A. PCl₃ is not an acid in the usual sense but reacts to form H₃PO₃ (phosphorous acid), which is a much stronger acid than carboxylic acids. Phosphorous acid has a pKa around 2.
  • B. Sulfuric acid is a very strong acid (pKa₁ ≈ -3), much stronger than carboxylic acids, due to the high stabilization of its conjugate base
  • C. Nitric acid is also a strong acid (pKa ≈ -1.4), much stronger than carboxylic acids because of its ability to fully dissociate in solution
  • D. HCl is a strong acid (pKa ≈ -6), which completely dissociates in water, making it much stronger than carboxylic acids.

Q115. The initial discovery of natural gas in Pakistan dates back to _ when it was found in the Sui area of Baluchistan:

  • A. 1955
  • B. 1954
  • C. 1956
  • D. 1952
  • E. 1992

Explanation: The discovery of natural gas in the Sui area of Balochistan in 1952 was a landmark event in Pakistan's history, initiating the development of its natural energy resources. This discovery was crucial for the country's energy infrastructure. Options 1955, 1954, and 1956 are incorrect because they do not align with the actual year of discovery, and 1992 is far too late, occurring decades after the initial event.

Why the other options are wrong
  • A. This option is incorrect. Although the 1950s were significant for energy discoveries in Pakistan, the actual year of discovery was earlier.
  • B. This option is incorrect. The discovery happened earlier than this year. Consider the early 1950s for the correct answer.
  • C. This option is incorrect. By this time, natural gas had already been discovered in Pakistan in an earlier year.
  • E. This option is incorrect. The discovery occurred much earlier, in the mid-20th century, not in the 1990s.

Q116. Reduction of aldehydes & ketones by Zn-Hg amalgam and concentrated HCl results in conversion to an alkane. This reaction is known as:

  • A. Down Reduction
  • B. Cope Reduction
  • C. Wolff-Kishner Reduction
  • D. Clemmensen reduction
  • E. Sodium tetrahydroboride

Explanation: Clemmensen reduction is a chemical reaction used to convert carbonyl compounds (such as aldehydes and ketones) into alkanes. This reduction is typically carried out using zinc amalgam (Zn/Hg) in the presence of hydrochloric acid (HCl).

Why the other options are wrong
  • A. There isn't any reaction names as down reaction.
  • B. The Cope reduction is a chemical reaction that involves the reduction of 1,2-dienes (or allylic alcohols) to alkenes using hydrogen gas in the presence of a metal catalyst, typically palladium or platinum
  • C. The Wolff-Kishner reduction is a chemical reaction used to convert carbonyl compounds (aldehydes and ketones) into alkanes by removing the oxygen. This reduction is particularly valuable in organic synthesis when a functional group needs to be transformed without affecting other functionalities.
  • E. Sodium tetrahydroborate (NaBH₄), commonly known as sodium borohydride, is a powerful reducing agent widely used in organic chemistry and industrial applications.

Q117. Deficiency causes loss of weight, appetite, and taste.

  • A. K
  • B. P
  • C. Fe
  • D. Zn

Explanation: Zinc plays a crucial role in the functioning of taste and smell receptors. A deficiency can result in altered taste perception (dysgeusia) or a diminished sense of smell (hyposmia), making food less appealing. zinc deficiency can lead to loss of appetite. This symptom is part of a broader range of effects that zinc deficiency can have on the body.

Why the other options are wrong
  • A. Potassium deficiency may result in muscle weakness and cramps, fatigue, constipation, irregular heartbeat, and high blood pressure.
  • B. Phosphorus deficiency can cause weakness, fatigue, bone pain, fragile bones, loss of appetite, muscle weakness, irritability, and poor growth in children. It typically results from malnutrition, medications, or absorption issues and is essential for energy production, bone health, and cellular function.
  • C. Iron deficiency often results in fatigue, weakness, pale skin, shortness of breath, dizziness, brittle nails, cold extremities, and restless legs syndrome.

Q118. The rate of SN1 mechanism depends upon:

  • A. Concentration of nucleophile
  • B. Concentration of both substrate and nucleophile
  • C. Polar non-polar solvent
  • D. Concentration of substrate only
  • E. Concentration of reactant

Explanation: The rate of an S_N1 reaction (unimolecular nucleophilic substitution) depends solely on the concentration of the substrate (the molecule undergoing substitution). This is because the rate-determining step is the formation of the carbocation after the leaving group departs. Once the carbocation is formed, the nucleophile can quickly react with it.

Why the other options are wrong
  • A. The nucleophile’s concentration does not affect the rate because the nucleophilic attack occurs after the slow, rate-determining step (formation of the carbohydrate).
  • B. In S_N1, the nucleophile concentration does not influence the rate; only the substrate concentration matters.
  • C. While solvent polarity can affect the reaction by stabilizing the carbocation, it is not directly related to the rate equation. Polar solvents generally stabilize carbocations, promoting S_N1 reactions, but the solvent doesn't appear in the rate law.
  • E. This term is vague, but if it refers to both substrate and nucleophile, it is incorrect because only the substrate concentration matters in S_N1.

Q119. The total number of alpha amino acids is:

  • A. 19
  • B. 27
  • C. 22
  • D. 25
  • E. 28

Explanation: The correct answer is 22. This includes the 20 standard amino acids that are the building blocks of proteins, plus 2 special amino acids: selenocysteine and pyrrolysine, which are incorporated into proteins in specific circumstances. Options such as 19, 25, 27, and 28 either underestimate or overestimate this total, not accounting properly for these additional amino acids.

Why the other options are wrong
  • A. This option is incorrect. There are more than 19 alpha amino acids when considering both standard and special ones.
  • B. This option is incorrect. While the number is higher than 22, it does not accurately represent the total number of alpha amino acids.
  • D. This option is incorrect. There is no evidence to suggest that there are 25 alpha amino acids, even when considering special cases.
  • E. This option is incorrect. The number 28 overestimates the count of alpha amino acids, even with selenocysteine and pyrrolysine included.

Q120. Which statement about tautomerism is correct?

  • A. Only occurs in organic compounds
  • B. Not influenced by temperature
  • C. Have same molecular formula
  • D. Have different molecular formula
  • E. Identical chemical properties

Explanation: Tautomers are a specific type of isomerism characterized by having the same molecular formula but differing in the connectivity of atoms, specifically the position of a proton and a double bond. This means that while they share the same chemical composition, their structural differences can lead to variations in their chemical behavior and properties.Option A is incorrect as tautomerism is not limited to organic compounds alone. Option B is incorrect because temperature can influence the equilibrium between tautomers. Option D is wrong since tautomers must have the same molecular formula, and Option E is misleading as tautomers can exhibit different chemical properties despite having similar structures.

Why the other options are wrong
  • A. This statement is incorrect because tautomerism is primarily observed in organic compounds, but it is not exclusive to them. There are inorganic compounds that can exhibit tautomeric behavior as well.
  • B. This statement is misleading. Tautomeric equilibria can be influenced by temperature, as changes in temperature can affect the stability and concentration of the tautomers.
  • D. This statement is incorrect. Tautomers must have the same molecular formula, as they are a specific type of isomerism where only the arrangement of atoms changes.
  • E. This statement is only partially correct. While tautomers can have similar chemical properties, they may also exhibit different reactivity and behavior due to their structural differences.

Q121. Aldehydes & ketones can be converted to alkane. This reaction is called:

  • A. Ozonolysis
  • B. Wolff-Kishner reaction
  • C. Grignard reaction
  • D. Friedel-Craft reaction
  • E. None of these

Explanation: The Wolff-Kishner reaction is a chemical reaction used to reduce aldehydes or ketones to alkanes. This reaction involves the treatment of the carbonyl compound with hydrazine (NH₂NH₂) in the presence of a strong base (like potassium hydroxide, KOH) and heat. During the reaction, the carbonyl group (C=O) is converted into a methylene group (CH₂), effectively removing the oxygen atom. The reaction is performed under strongly basic conditions and is often used when acidic conditions are not suitable, unlike the Clemmensen reduction.

Why the other options are wrong
  • A. Ozonolysis is a chemical reaction involving the cleavage of carbon-carbon double bonds (alkenes) using ozone (O₃). In this reaction, ozone reacts with the double bond to form an ozonide, which can then be hydrolyzed (treated with water or a reducing agent) to yield carbonyl compounds, such as aldehydes or ketones. Ozonolysis is commonly used in organic synthesis to break down alkenes into smaller, more functionalized molecules and is particularly useful for determining the structure of unsaturated compounds.
  • C. The Grignard reaction involves the reaction of a Grignard reagent (an organomagnesium compound, typically RMgX, where R is an alkyl or aryl group and X is a halide) with an electrophilic carbon atom, usually found in aldehydes, ketones, esters, or carbon dioxide, to form alcohols or carboxylic acids. This reaction is crucial in organic synthesis for forming carbon-carbon bonds, allowing the creation of complex alcohols from simple precursors. It typically requires anhydrous conditions because Grignard reagents are highly reactive with water.
  • D. The Friedel-Crafts reaction encompasses two key methods for introducing substituents into an aromatic ring: alkylation and acylation. In Friedel-Crafts alkylation, an alkyl group is added to an aromatic ring by reacting the ring with an alkyl halide in the presence of a Lewis acid catalyst like aluminum chloride (AlCl₃). This reaction is commonly used to synthesize alkyl-substituted aromatic compounds. In Friedel-Crafts acylation, an acyl group is added to the aromatic ring by reacting it with an acyl chloride (or acid anhydride) in the presence of the same catalyst. This process is valuable for introducing carbonyl groups and is often used to produce ketones. Both reactions are widely employed in organic synthesis for the functionalization of aromatic rings.
  • E. This is not correct

Q122. An example of a bidentate ligand among the following is:

  • A. Br
  • B. CN-
  • C. C204-
  • D. OH-
  • E. CI

Explanation: Oxalate ion (C₂O₄²⁻): Bidentate ligand, anionic, coordinates through both oxygen atoms, forming chelate complexes with metal ions.

Why the other options are wrong
  • A. Bromide ion (Br⁻) is a monodentate ligand, anionic, coordinates through a single bromine atom, and is commonly found in metal complexes.
  • B. It's is an monodentate ligand which donates one electron pair only.
  • D. Hydroxide ion (OH⁻): Monodentate ligand, anionic, coordinates through the oxygen atom, commonly found in metal hydroxide complexes.
  • E. Chloride ion (Cl⁻): monodentate ligand, anionic, coordinates through a single chlorine atom, often found in coordination complexes with metals.

Q123. A fuel cell is a typical galvanic cell that is based on a reaction between:

  • A. Hydrogen and copper
  • B. Methane and oxygen
  • C. Hydrogen and oxygen
  • D. Nitrogen and oxygen
  • E. Hydrogen and zinc

Explanation: Hydrogen and oxygen: This is the reaction in a hydrogen fuel cell, where hydrogen (H₂) reacts with oxygen (O₂) to produce electricity, water, and heat.

Why the other options are wrong
  • A. Hydrogen and copper: This combination is not a typical galvanic cell. Copper is not involved in the redox reaction in a hydrogen-based fuel cell.
  • B. Methane and oxygen: This is not a typical fuel cell reaction; methane is used in combustion engines, not standard fuel cells.
  • D. Nitrogen and oxygen: This combination does not typically occur in a galvanic or fuel cell. Nitrogen is inert and does not participate in the redox reactions.
  • E. Hydrogen and zinc: This is not the reaction in a fuel cell; zinc is part of a dry cell battery, not a fuel cell.

Q124. The alkali metal that gives a yellow color during a flame test is:

  • A. Ba
  • B. Na
  • C. K
  • D. Cs
  • E. Li

Explanation: Sodium (Na), an alkali metal from Group 1, gives a bright yellow flame during a flame test. The yellow color comes from the excitation of sodium atoms, particularly due to the sodium D-line emission at wavelengths around 589 nm. When sodium ions are heated in a flame, their electrons get excited to higher energy levels and then fall back to lower levels, releasing energy as visible yellow light. This test is so sensitive that even trace amounts of sodium can make the flame appear yellow.

Why the other options are wrong
  • A. Barium is not an alkali metal — it belongs to Group 2 (alkaline earth metals). In a flame test, barium compounds produce a yellowish-green or apple-green color, not bright yellow. This distinct color helps identify barium ions but differentiates them from sodium, which gives a pure bright yellow flame. Therefore, Ba is incorrect in this context.
  • C. Potassium produces a lilac or light purple color in a flame test, not yellow. The color is due to the emission of light at wavelengths around 766 nm and 404 nm. However, if sodium contamination is present (which is very common), the yellow color of sodium can mask the lilac color of potassium. Hence, potassium’s flame appears pale or faint lilac, but not yellow.
  • D. Cesium, another alkali metal, gives a blue-violet flame. The emission arises from transitions of cesium atoms that release energy in the violet region of the visible spectrum (around 455–460 nm). Although cesium belongs to the same group as sodium, its larger atomic size and different electronic transitions result in a different flame color. Therefore, Cs is not correct for yellow coloration.
  • E. Lithium produces a crimson red or deep red flame in a flame test. This striking red hue is due to emissions around 670 nm. Like sodium and potassium, lithium’s flame test color is also used for identification, but it is clearly red, not yellow. Hence, this option is incorrect.

Q125. Which of the following possesses the weakest London dispersion forces?

  • A. F2
  • B. Br2
  • C. Cl2
  • D. I2
  • E. He

Explanation: The correct answer is Option E: He. Helium is a noble gas characterized by its minimal atomic size and the lowest number of electrons among the options provided. This results in the weakest London dispersion forces. In comparison, F2 has more electrons than He, giving it stronger dispersion forces. Cl2 and Br2 are larger and have more electrons, further increasing their dispersion forces relative to He. I2 is the largest and heaviest, possessing the strongest dispersion forces of all.

Why the other options are wrong
  • A. F2: While it is small, it has more electrons than helium, resulting in slightly stronger dispersion forces compared to He.
  • B. Br2: Being larger and heavier, it exhibits stronger London dispersion forces than both F2 and Cl2 due to greater electron count and surface area.
  • C. Cl2: Larger than F2 and contains more electrons, leading to stronger dispersion forces compared to both F2 and He.
  • D. I2: The largest and heaviest molecule among the options, it possesses the most substantial dispersion forces due to its size and electron count.

Q126. Which of the following liquids shows maximum surface tension?

  • A. Water
  • B. Mercury
  • C. Ethyl alcohol
  • D. Chloroform
  • E. Benzene

Explanation: The correct answer is Mercury (Option B). Mercury has the highest surface tension because of the strong cohesive forces between its metal atoms, which are much stronger than the hydrogen bonds in water or the van der Waals forces in other liquids like benzene, chloroform, and ethyl alcohol. While water has significant surface tension due to hydrogen bonding, it is still less than mercury. Ethyl alcohol and chloroform have even lower surface tensions due to weaker intermolecular forces, and benzene, with its weak van der Waals forces, has the lowest surface tension among the given options.

Why the other options are wrong
  • A. Water: Although water has high surface tension due to strong hydrogen bonding, it is still lower than that of mercury.
  • C. Ethyl alcohol: It has moderate surface tension due to hydrogen bonding, but it is significantly less than that of water and mercury.
  • D. Chloroform: Chloroform lacks hydrogen bonding and therefore has a lower surface tension compared to water and mercury.
  • E. Benzene: Benzene has relatively low surface tension due to weak van der Waals forces between its molecules.

Q127. Hydroquinone is a phenol; it contains two OH groups at:

  • A. Position 1 and 2
  • B. Position 1 and 3
  • C. Position 1 and 4
  • D. Position 2 and 3

Explanation: The correct answer is Option C: Position 1 and 4. Hydroquinone is a type of phenol where the two hydroxyl (OH) groups are positioned opposite each other on a benzene ring, specifically at the 1 and 4 positions. This gives hydroquinone its distinct para configuration. Option A describes catechol, where the OH groups are adjacent. Option B refers to hydroxyquinone, where the OH groups are separated by one carbon. Option D describes resorcinol, which also has a separation by one carbon but at different positions than hydroquinone.

Why the other options are wrong
  • A. Position 1 and 2: These positions are characteristic of catechol, not hydroquinone, which has hydroxyl groups next to each other on the benzene ring.
  • B. Position 1 and 3: This arrangement is typical of hydroxyquinone, a different compound where the hydroxyl groups are separated by one carbon atom.
  • D. Position 2 and 3: These positions correspond to resorcinol, another phenolic compound, where the hydroxyl groups are separated by one carbon atom but are not the same as hydroquinone's arrangement.

Q128. Generally, actual yield is:

  • A. Less than theoretical yield
  • B. Equal to the theoretical yield
  • C. Greater than theoretical yield
  • D. Greater than percent yield

Explanation: The correct answer is Option A: Less than theoretical yield. In most real-world chemical reactions, the actual yield is less than the theoretical yield due to factors such as incomplete reactions, side reactions, and material losses during processing. Option B, 'Equal to the theoretical yield,' is incorrect because this scenario is rare and assumes perfect efficiency. Option C, 'Greater than theoretical yield,' is incorrect as the theoretical yield is the maximum possible yield. Option D, 'Greater than percent yield,' is also incorrect because percent yield is a percentage that cannot exceed 100%, and actual yield cannot exceed the theoretical yield.

Why the other options are wrong
  • B. Equal to the theoretical yield: While this would be ideal, it is seldom achieved in practice due to inefficiencies and material losses. Achieving a yield equal to the theoretical yield implies 100% efficiency with no losses, which is extremely rare.
  • C. Greater than theoretical yield: This is generally impossible because the theoretical yield is calculated as the maximum possible amount of product that can be obtained from a given amount of reactants based on stoichiometry.
  • D. Greater than percent yield: Since percent yield is the ratio of actual yield to theoretical yield expressed as a percentage, the actual yield cannot exceed this percentage under normal circumstances.

Q129. Formic acid is naturally found in:

  • A. Butter
  • B. Goat
  • C. Milk
  • D. Vinegar
  • E. Ants

Explanation: Ants produce formic acid.

Why the other options are wrong
  • A. Butter contains butyric acid.
  • B. This option is incorrect.
  • C. Milk contains lactic aid.
  • D. Vinegar contains acetic acid.

Q130. Urea was first synthesized by Wohler from an inorganic material named:

  • A. Ammonium bicarbonate
  • B. Ammonium nitrate
  • C. Ammonium oxalate
  • D. Ammonium cyanate
  • E. Ammonium chloride

Explanation: Urea was synthesized by Friedrich Wöhler in 1828 using ammonium cyanate. This synthesis was significant because it demonstrated that organic compounds could be created from inorganic materials, which contradicted the prevailing belief in 'vitalism' — the idea that organic compounds could only be produced by living organisms. The other options, such as ammonium bicarbonate, ammonium nitrate, ammonium oxalate, and ammonium chloride, were not involved in Wöhler's synthesis of urea.

Why the other options are wrong
  • A. This option is incorrect. Ammonium bicarbonate was not used by Wöhler for the synthesis of urea.
  • B. This option is incorrect. Ammonium nitrate is not related to the synthesis of urea by Wöhler.
  • C. This option is incorrect. Ammonium oxalate was not the inorganic material used by Wöhler to synthesize urea.
  • E. This option is incorrect. Ammonium chloride was not the compound Wöhler used to synthesize urea.

Q131. Oil of Vitriol refers to:

  • A. Caustic soda
  • B. Alum
  • C. Borax
  • D. Sulfuric acid
  • E. Nitric acid

Explanation: The correct answer is Sulfuric acid (Option D). Historically, sulfuric acid was called 'oil of vitriol' because it was produced by roasting iron sulfate (vitriol) and has an oily consistency. The other options are not connected to the term 'vitriol':Caustic soda (Option A) is an alkaline substance and not an acid.Alum (Option B) is a compound of aluminum and not an acid.Borax (Option C) is a boron compound also unrelated to acids.Nitric acid (Option E) is another type of acid but not referred to as 'oil of vitriol'.

Why the other options are wrong
  • A. Caustic soda is the common name for sodium hydroxide, a strong alkali used in cleaning and manufacturing, not related to vitriol.
  • B. Alum refers to a group of hydrated double sulfates, not an oil or an acid, and is unrelated to vitriol.
  • C. Borax is a boron compound used as a cleaning agent and in metallurgy, not known as oil of vitriol.
  • E. Nitric acid is a powerful oxidizing agent used in fertilizers and explosives, not referred to as oil of vitriol.

Q132. The number of five-membered and six-membered rings in Buckyball is, respectively:

  • A. 40 and 20
  • B. 12 and 12
  • C. 5 and 15
  • D. 5 and 10
  • E. 12 and 20

Explanation: The Buckyball, or C₆₀ fullerene, is a molecular structure composed of 60 carbon atoms arranged in a pattern similar to a soccer ball. This configuration includes 12 pentagonal (five-membered) rings and 20 hexagonal (six-membered) rings. The pentagons are crucial for the curvature of the spherical shape. Option E is correct because it accurately represents this structural composition. Other options either overestimate or underestimate the number of rings, failing to match the known structure of a Buckyball.

Why the other options are wrong
  • A. This option is incorrect. There are not 40 five-membered rings in a Buckyball, as this would not maintain the structural integrity of the C₆₀ molecule.
  • B. This option is incorrect. While there are 12 five-membered rings, there are more than 12 six-membered rings in a Buckyball.
  • C. This option is incorrect. A Buckyball does not contain 5 five-membered rings; it contains 12.
  • D. This option is incorrect. Both the numbers of five-membered and six-membered rings are underestimated here.

Q133. It is an example of a crystalline solid:

  • A. Plastics
  • B. Charcoal
  • C. Glass
  • D. Alum
  • E. Rubber

Explanation: Alum is a crystalline solid that typically forms in well-defined geometric shapes, often octahedral. It is a type of double salt, usually consisting of potassium aluminum sulfate (KAl(SO₄)₂·12H₂O) or sodium aluminum sulfate, and is known for its solubility in water. Alums are commonly used in water purification, as a mordant in dyeing processes, and in various food applications, such as pickling.

Why the other options are wrong
  • A. Charcoal is considered a porous solid, primarily composed of carbon, created through the pyrolysis of organic materials, such as wood, in the absence of oxygen. This process removes moisture and volatile compounds, resulting in a lightweight, black material with a high surface area. Charcoal is commonly used as a fuel in filtration systems and in various industrial applications, including metallurgy and air purification, due to its adsorptive properties.
  • B. Charcoal is considered a porous solid, primarily composed of carbon, created through the pyrolysis of organic materials, such as wood, in the absence of oxygen. This process removes moisture and volatile compounds, resulting in a lightweight, black material with a high surface area. Charcoal is commonly used as a fuel in filtration systems and in various industrial applications, including metallurgy and air purification, due to its adsorptive properties.
  • C. Glass is an amorphous solid, meaning it has a disordered molecular structure rather than a regular crystalline arrangement. This lack of a defined structure gives glass its characteristic transparency and brittleness. Typically made from silica (silicon dioxide) mixed with other compounds like soda and lime, glass is widely used in windows, containers, and various optical applications due to its ability to transmit light while being moldable during production.
  • E. Rubber is an amorphous solid that exhibits elastic properties, meaning it can deform under stress and return to its original shape when the stress is removed. Its molecular structure consists of long, flexible chains of polymers, which allow for significant stretch and flexibility, making it ideal for various applications, such as tires, seals, and elastic materials.

Q134. The structure of primary amines is:

  • A. Trigonal
  • B. Tetrahedral pyramidal
  • C. Planar
  • D. Linear
  • E. Regular tetrahedral

Explanation: Tetrahedral pyramidal molecular shape, often referred to as trigonal pyramidal, occurs when a central atom is bonded to three other atoms and has one lone pair of electrons, resulting in a three-dimensional shape with bond angles of approximately 107 degrees

Why the other options are wrong
  • A. Trigonal molecular shape, or trigonal planar, occurs when a central atom is bonded to three other atoms arranged in a flat triangle, resulting in bond angles of approximately 120 degrees.
  • C. Planar molecular shape, or trigonal planar, occurs when a central atom is bonded to three other atoms arranged in a flat, two-dimensional triangle, resulting in bond angles of approximately 120 degrees.
  • D. Linear molecular shape occurs when atoms are arranged in a straight line, typically formed by two atoms bonded with no lone pairs on the central atom, resulting in a bond angle of 180 degrees.
  • E. Regular tetrahedral molecular shape occurs when a central atom is bonded to four other atoms in a symmetrical arrangement, forming a three-dimensional shape with equal bond lengths and bond angles of approximately 109.5 degrees.

Q135. Mostly p-block elements react with-----each other to form binary compounds:

  • A. Oxygen
  • B. Water
  • C. Halogens
  • D. Nitrogen
  • E. Hydrogen

Explanation: Option C is correct. P-block elements primarily react with halogens to form binary compounds, such as halides. These elements can also react with hydrogen to form compounds like hydrides, but the most common reactivity for forming straightforward binary compounds is indeed with halogens.

Why the other options are wrong
  • A. Oxygen: While oxygen forms binary compounds, it doesn't primarily react with p-block elements to form many binary compounds.
  • B. Water: Water is not a binary compound of p-block elements but a compound of hydrogen and oxygen.
  • D. Nitrogen: Nitrogen can form binary compounds but is less reactive with other p-block elements compared to halogens.
  • E. Hydrogen: Hydrogen is not a p-block element but can form binary compounds with p-block elements like hydrides.

Q136. The maximum number of electrons in a given subshell is calculated by:

  • A. n2
  • B. 2(n+1)
  • C. 2n2
  • D. 2(2l+1)
  • E. 2+1

Explanation: 2(2l + 1) is the correct formula for the maximum number of electrons in a subshell, as it accounts for the number of orbitals (2l + 1) in a subshell, with each orbital able to hold 2 electrons.

Why the other options are wrong
  • A. n²: This represents the number of orbitals in a shell, not the maximum number of electrons in a subshell.
  • B. 2(n+1): This is not a valid formula for calculating the maximum number of electrons in a subshell.
  • C. 2n²: This formula gives the maximum number of electrons in a shell, not a subshell.
  • E. 2 + 1: This is not a correct formula for calculating the number of electrons in a subshell.

Q137. Which shape/geometry is found in AX2 when the bond angle is 180°?

  • A. Pyramidal
  • B. Bent
  • C. Triangle
  • D. Tetrahedral
  • E. Linear

Explanation: Linear molecular shape occurs when atoms are arranged in a straight line, typically resulting from two atoms bonded with no lone pairs on the central atom, leading to a bond angle of 180 degrees.

Why the other options are wrong
  • A. Pyramidal molecular shape, specifically trigonal pyramidal, occurs when a central atom is bonded to three other atoms and has one lone pair of electrons, resulting in a three-dimensional shape with bond angles of approximately 107 degrees.
  • B. Bent molecular shape occurs when a central atom is bonded to two other atoms with one or more lone pairs of electrons, resulting in an angular configuration with bond angles typically around 104.5 degrees.
  • C. Triangular molecular shape, often referred to as trigonal planar, occurs when a central atom is bonded to three other atoms arranged in a flat, triangular configuration with bond angles of approximately 120 degrees.
  • D. Tetrahedral molecular shape occurs when a central atom is bonded to four other atoms, forming a three-dimensional shape with bond angles of approximately 109.5 degrees.

Q138. A colloidal solution of liquid into liquid is known as:

  • A. Solid foam
  • B. Foam
  • C. Fog
  • D. Emulsion

Explanation: An emulsion is a stable mixture of two immiscible liquids, typically oil and water, where one liquid is dispersed in the other in the form of small droplets. Emulsions are commonly stabilized by emulsifiers, which are substances that reduce the surface tension between the two liquids, preventing them from separating. They are classified into two main types: oil-in-water (O/W) emulsions, where oil droplets are dispersed in water, and water-in-oil (W/O) emulsions, where water droplets are dispersed in oil. Emulsions are widely used in various industries, including food (e.g., mayonnaise), cosmetics (e.g., lotions), and pharmaceuticals, due to their ability to improve texture, stability, and delivery of active ingredients.

Why the other options are wrong
  • A. Solid foam, also known as rigid foam, is a type of foam that has a solid structure, providing a lightweight yet durable material. It is created by trapping gas bubbles within a solid matrix, resulting in a porous material that has low density and high thermal insulation properties. Solid foam is commonly made from materials such as polyurethane, polystyrene, or polyethylene and is widely used in construction for insulation, packaging, and in consumer products like furniture and mattresses. Its ability to absorb shock and provide thermal resistance makes it ideal for applications requiring energy efficiency and protection against impact.
  • B. Foam is a colloidal system consisting of a mass of tiny bubbles formed by trapping gas in a liquid or solid. It is created when a gas is dispersed in a liquid, leading to the formation of bubbles that are stabilized by surfactants—substances that reduce surface tension. Foams can be found in various forms, including shaving cream, whipped cream, and foamy beverages like beer or soda. They are also used in industrial applications, such as firefighting foams and insulation materials. The properties of foam, including its density and stability, depend on factors like the type of liquid, the presence of surfactants, and the method of generation.
  • C. Fog is a weather phenomenon characterized by the suspension of tiny water droplets or ice crystals in the air, which reduces visibility to less than 1 kilometer (0.62 miles). It forms when the air becomes saturated with moisture, often due to cooling or the presence of high humidity. Fog can develop in various ways, such as radiation fog, which occurs on clear nights when the ground cools rapidly, and advection fog, which forms when warm, moist air moves over a cooler surface. Fog can significantly impact transportation, causing hazardous driving conditions, and can create a unique, often eerie atmosphere in natural settings.

Q139. These hydrocarbons contain one or more double or triple bonds between the two adjacent carbon atoms in their structure:

  • A. Alkenes and alcohol
  • B. Alkenes and cycloalkanes
  • C. Alkanes and alkyl halides
  • D. Alkenes and alkynes
  • E. Alkanes and alkenes

Explanation: Alkenes are unsaturated hydrocarbons characterized by at least one carbon-carbon double bond (C=C) and have the general formula CₙH₂ₙ. They are more reactive than alkanes due to the presence of the double bond, allowing for various chemical reactions such as addition reactions. In contrast, alkynes are also unsaturated hydrocarbons but contain at least one carbon-carbon triple bond (C≡C), with the general formula CₙH₂ₙ₋₂. Alkynes are even more reactive than alkenes, making them useful in a variety of chemical synthesis processes. Both alkenes and alkynes are essential in organic chemistry, serving as key intermediates and building blocks for more complex organic compounds.

Why the other options are wrong
  • A. Alkenes are unsaturated hydrocarbons characterized by the presence of one or more carbon-carbon double bonds (C=C), making them more reactive than alkanes. Alcohols, on the other hand, are organic compounds that contain one or more hydroxyl (-OH) functional groups, resulting from the replacement of a hydrogen atom in a hydrocarbon with a hydroxyl group. The presence of the hydroxyl group in alcohols significantly increases their polarity and solubility in water compared to alkenes. Alkenes can be converted into alcohols through hydration reactions, where water is added across the double bond, typically in the presence of an acid catalyst. This reaction allows for the formation of various alcohols, which are important in industrial applications and as solvents.
  • B. Alkenes are unsaturated hydrocarbons that contain at least one carbon-carbon double bond (C=C), with the general formula (CnH2n). This double bond introduces reactivity, making alkenes capable of undergoing addition reactions, where atoms can be added across the double bond. Cycloalkanes are saturated hydrocarbons that consist of carbon atoms arranged in a ring structure, with the general formula CnH2n as well. They have single bonds between carbon atoms and can vary in size, typically forming stable cyclic structures. Both alkenes and cycloalkanes are important in organic chemistry and serve as key building blocks in the synthesis of various compounds.
  • C. Alkanes are saturated hydrocarbons consisting only of carbon and hydrogen atoms, connected by single bonds, with the general formula (CnH2n+2). They are typically non-polar, relatively unreactive, and can be straight-chain or branched. Alkyl halides, or haloalkanes, are derivatives of alkanes where one or more hydrogen atoms have been replaced by halogen atoms (fluorine, chlorine, bromine, or iodine). They can be classified as primary, secondary, or tertiary based on the carbon atom connected to the halogen. Alkyl halides are more reactive than alkanes and can undergo various chemical reactions, including nucleophilic substitution and elimination reactions.
  • E. Alkanes are saturated hydrocarbons that contain only single carbon-carbon bonds (C-C), following the general formula CₙH₂ₙ₊₂. They are typically less reactive than other hydrocarbons and are found in substances like natural gas and petroleum. In contrast, alkenes are unsaturated hydrocarbons that contain at least one carbon-carbon double bond (C=C), with the general formula CₙH₂ₙ. Alkenes are more reactive than alkanes due to the presence of the double bond, which allows them to undergo various chemical reactions, including addition reactions. Both alkanes and alkenes are fundamental in organic chemistry and serve as building blocks for more complex molecules.

Q140. The conjugated acid of NH3 is:

  • A. NH4+
  • B. NH
  • C. NH2
  • D. NH2-
  • E. NH3

Explanation: NH₄⁺: This is the conjugated acid of NH₃ (ammonia). When NH₃ accepts a proton (H⁺), it forms NH₄⁺.

Why the other options are wrong
  • B. NH: This is not the conjugated acid of NH₃; it's an unstable species.
  • C. NH₂: This is an amide group, not the conjugated acid of NH₃.
  • D. NH₂⁻: This is the conjugate base of NH₃, not the conjugated acid.
  • E. NH₃: Ammonia itself is a base, not its conjugated acid.

Q141. The linear momentum of a photon is given as:

  • A. me
  • B. mv
  • C. me²
  • D. moc²
  • E. hv/c

Explanation: hv/c: This is the correct formula for the linear momentum of a photon, where h is Planck's constant, v is the frequency of the photon, and c is the speed of light.

Why the other options are wrong
  • A. me: This is just a mass symbol and doesn't represent the linear momentum of a photon.
  • B. mv: This represents the momentum of an object with mass m moving at velocity v, but photons are massless and follow a different formula.
  • C. me²: This is incorrect and does not represent momentum; it’s just mass times the square of some quantity.
  • D. mₒc²: This represents the energy of a particle with rest mass (E = mc²), not the linear momentum of a photon.

Q142. The unit of resistance is:

  • A. Volt
  • B. Watt
  • C. Coulomb
  • D. Ohm
  • E. Ampere

Explanation: Resistance is measured in ohms.

Why the other options are wrong
  • A. This option is incorrect. A volt (V) is the unit of potential difference (voltage), not resistance. One volt is defined as the potential difference between two points when one joule of work is done to move one coulomb of charge between them..
  • B. This is also incorrect. A watt (W) is the unit of power, which represents the rate of doing electrical work or rate of energy conversion.
  • C. This option is incorrect because a coulomb (C) is the unit of electric charge. It measures the total amount of electric charge that passes a point in a given time. One coulomb equals the charge transported by a current of one ampere in one second
  • E. This option is incorrect because an ampere (A) is the unit of electric current, not resistance. One ampere represents the flow of one coulomb of charge per second.

Q143. Longitudinal waves do not exhibit:

  • A. Refleetion
  • B. Diffraction
  • C. Polarization
  • D. Interference
  • E. Refraction

Explanation: Polarization refers to the orientation of the oscillations of a wave, typically applied to electromagnetic waves like light. In an unpolarized wave, the oscillations occur in all directions perpendicular to the direction of wave propagation. When a wave is polarized, its oscillations are confined to a specific direction.

Why the other options are wrong
  • A. Reflection is the change in direction of a wavefront when it bounces off a surface and returns into the original medium. This occurs with various types of waves, including light, sound, and water waves. The angle of incidence (the angle at which the wave hits the surface) is equal to the angle of reflection, as described by the law of reflection:
  • B. Diffraction is the bending or spreading of waves when they encounter an obstacle or pass through a narrow opening. It occurs with all types of waves, including light, sound, and water waves. The extent of diffraction depends on the wavelength of the wave and the size of the obstacle or aperture.
  • D. Interference is the phenomenon where two or more waves overlap and combine to form a new wave pattern. It occurs with all types of waves, such as light, sound, and water waves. The result depends on the phase relationship between the waves.
  • E. Refraction is the bending of a wave as it passes from one medium into another where its speed changes. This occurs because waves travel at different speeds in different materials

Q144. One kilogram of mass is effectively converted into energy. The amount of energy will be:

  • A. 9x10^16 J
  • B. 3x10^10 J
  • C. 9x10^-16 eV
  • D. 9x10^6 J
  • E. 9x10^15 eV

Explanation: The energy conversion from mass to energy can be calculated using Einstein's equation E=mc2, where E is the energy, m is the mass, and c is the speed of light in a vacuum (3x108 m/s). For a mass of 1 kilogram, E = 1 kg × (3x108 m/s)2 = 9x1016 J. This calculation confirms that the correct energy amount is 9x1016 Joules.Options B, C, D, and E are incorrect as they fail to accurately apply this calculation or use inappropriate units like electronvolts (eV) for expressing the result.

Why the other options are wrong
  • B. This option is incorrect. It underestimates the energy produced from 1 kilogram of mass. The value does not align with calculations based on E=mc2.
  • C. This option is incorrect and uses the wrong unit (eV, electronvolt) for such a large energy conversion. The magnitude is also incorrect.
  • D. This option is incorrect. It significantly underestimates the energy produced from 1 kilogram of mass. The correct calculation according to E=mc2 is 9x10^16 J.
  • E. This option is incorrect as it uses electronvolts (eV), which is not appropriate for expressing the energy conversion from kilograms using E=mc2, and the magnitude is incorrect.

Q145. The unit of resistivity is:

  • A. Ohm m
  • B. Ampere
  • C. Volt
  • D. Watt
  • E. Ohm

Explanation: The unit of resistivity is ohm meter.

Why the other options are wrong
  • B. Ampere is the unit of current.
  • C. Volt is the unit of potential difference.
  • D. Watt is the unit of power.
  • E. Ohm is the unit of resistance.

Q146. The SI unit of power is:

  • A. Ampere
  • B. Coulomb
  • C. Ohm
  • D. Watt
  • E. Joule

Explanation: Power is measured in Watts.

Why the other options are wrong
  • A. This option is incorrect. Ampere (A) is the SI unit of electric current, not power. It measures the rate of flow of electric charge.
  • B. This is incorrect. Coulomb (C) is the unit of electric charge. It measures how much electric charge passes a point.
  • C. This option is also incorrect. Ohm (Ω) is the unit of electrical resistance. It measures the opposition a material offers to the flow of electric current.
  • E. This option is incorrect because Joule (J) is the unit of work or energy, not power. One joule is the work done when one newton of force moves an object one meter in the direction of the force:

Q147. Total potential difference across the combination of three similar cells becomes maximum when:

  • A. Two cells are connected in series and the third cell in parallel with the combination
  • B. All three cells are connected in parallel
  • C. Two cells are connected in parallel and the third cell in series with the combination
  • D. The load connected to the combination is minimum
  • E. All three cells are connected in series

Explanation: The potential difference is maximum across a circuit if cells are connected in series.

Why the other options are wrong
  • A. Two cells are connected in series and the third cell in parallel with the combination: This arrangement doesn't maximize the total potential difference, as the cells in parallel affect the total voltage across the combination.
  • B. All three cells are connected in parallel. In this case, the total potential difference would be equal to the potential difference of one cell, not maximizing the voltage.
  • C. Two cells are connected in parallel and the third cell in series with the combination: This arrangement results in a reduced effective voltage because the parallel combination doesn’t contribute to increasing the potential difference significantly.
  • D. The load connected to the combination is minimum: The load doesn't affect the total potential difference; this statement is not related to the maximum potential difference.

Q148. Which one of the following is correct for a transformer?

  • A. Transformer converts DC into AC
  • B. Transformer converts mechanical energy into electrical energy
  • C. Transformer works on the principle of mutual induction
  • D. Transformer converts AC into DC
  • E. Transformer converts electrical energy into mechanical energy

Explanation: Transformers work on the principle of electromagnetic induction to change the voltage level in an AC circuit.

Why the other options are wrong
  • A. Inverters are used to convert DC into AC.
  • B. Mechanical energy is converted into electrical energy by generators or dynamos. This process typically occurs through electromagnetic induction, where the mechanical motion of a conductor within a magnetic field induces an electric current.
  • D. AC is converted into DC by a diode.
  • E. Electrical energy is converted into mechanical energy by an AC motor.

Q149. The time rate of change of linear momentum is equal to:

  • A. Moment of force
  • B. Force
  • C. Angular momentum
  • D. Torque
  • E. Moment

Explanation: The rate of change of momentum (delta P) in unit time t is equal to force.

Why the other options are wrong
  • A. The moment of force, also known as torque, is the measure of the rotational effect of a force applied to an object.
  • C. Angular momentum is the rotational equivalent of linear momentum and represents the quantity of rotation of an object.
  • D. Torque is a measure of the rotational force that causes an object to rotate around an axis
  • E. In physics, moment refers to the rotational effect produced by a force acting on an object at a distance from a pivot or axis.

Q150. In projectile motion, the horizontal component of acceleration is:

  • A. Zero
  • B. 9.8m/s²
  • C. 19.6m/s
  • D. 4.9m/s²

Explanation: In projectile motion, the horizontal component of acceleration is zero. This is because no external force acts horizontally (assuming air resistance is negligible), so the horizontal velocity remains constant throughout the motion. The only acceleration is the vertical component, which is due to gravity.

Why the other options are wrong
  • B. 9.8 m/s²: This is the acceleration due to gravity, but it only affects the vertical motion of the projectile, not the horizontal.
  • C. This option is incorrect.19.6 m/s²: This is twice the acceleration due to gravity, and again, it only affects vertical motion.
  • D. 4.9 m/s²: This is half the acceleration due to gravity, but it also applies only to vertical motion, not horizontal.

Q151. Which of the following statements correct?

  • A. Work can never be converted into heat.
  • B. Work can be converted completely into heat.
  • C. Both heat and work are interconvertible.
  • D. Heat can never be converted into work.
  • E. Heat can be converted completely into work.

Explanation: Yes, heat and work are interconvertible forms of energy. In thermodynamics, they can be transformed into each other.

Why the other options are wrong
  • A. Work can be converted into heat. In fact, it's a fundamental principle in physics. When work is done on a system, such as through friction, compression, or resistance, the energy from the work can be entirely transformed into heat.
  • B. Some amount of heat is always lost while the conversion.
  • D. The statement "heat can never be converted into work" is not entirely accurate. While it's true that not all heat can be converted into work due to the Second Law of Thermodynamics, it is possible to convert some amount of heat into work.
  • E. No, heat cannot be completely converted into work according to the Second Law of Thermodynamics. Some energy is always lost as waste heat in the process. In real systems, only part of the heat energy can be converted into work, and the rest is dissipated, often to a cooler reservoir, as per the concept of entropy.

Q152. The force responsible for the simple harmonic motion of a simple pendulum is:

  • A. mg cosθ
  • B. mg tanθ
  • C. mg2 sinθ
  • D. mg sinθ

Explanation: The force responsible for the simple harmonic motion of a simple pendulum is the component of gravitational force that acts along the arc of the pendulum's swing. This is given by mg sinθ, where mg is the weight of the pendulum bob and θ is the angle from the vertical. This force acts to restore the pendulum to its equilibrium position, hence it is known as the restoring force.Option A (mg cosθ) represents the component of gravitational force that acts perpendicular to the motion and does not contribute to the restoring motion. Option B (mg tanθ) is not a standard expression related to pendulum motion. Option C (mg2 sinθ) incorrectly suggests a squared force term, which is not applicable here.

Why the other options are wrong
  • A. mg cosθ: This is the component of the gravitational force perpendicular to the direction of motion. It does not contribute to the restoring force that causes simple harmonic motion.
  • B. mg tanθ: This expression does not represent any standard component of the gravitational force in pendulum motion and is incorrect.
  • C. This option is incorrect as it suggests a force expression that involves squaring the gravitational force, which is not applicable in this context.

Q153. "The current through a conductor is directly proportional to the potential difference between the ends of the conductor, provided that physical conditions remain the same." This is:

  • A. Laplace's Law
  • B. Ohm's Law
  • C. Coulomb's Law
  • D. Charles's Law
  • E. Boyle's Law

Explanation: Ohm's Law states that the current through a conductor is directly proportional to the voltage across it and inversely proportional to its resistance.

Why the other options are wrong
  • A. Laplace's Law describes the relationship between the pressure, tension, and radius of a spherical or cylindrical structure, such as blood vessels or alveoli in the lungs. It states that the tension in the walls of the structure is directly proportional to the pressure inside and the radius of the structure.
  • C. Coulomb's Law describes the force between two charged objects. The force is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.
  • D. Charles's Law states that the volume of a gas is directly proportional to its temperature (in Kelvin), provided the pressure and the amount of gas remain constant. As temperature increases, volume increases, and vice versa.
  • E. Boyle's Law states that the pressure of a gas is inversely proportional to its volume, provided the temperature and the amount of gas remain constant. In simple terms, as the volume decreases, the pressure increases, and vice versa.

Q154. The measure of energy between any two points on a circuit is:

  • A. Resistance
  • B. Electromotive force
  • C. Internal resistance
  • D. Resistivity
  • E. Potentíal difference

Explanation: Potential difference, often referred to as voltage, is the difference in electric potential between two points in an electric field. It represents the work done per unit charge to move a charge between those two points.

Why the other options are wrong
  • A. Resistance is a measure of the opposition to the flow of electric current in a conductor or circuit. It quantifies how much a material resists the movement of electrons and is influenced by factors such as the material's properties, temperature, length, and cross-sectional area.
  • B. Electromotive force (emf) is the energy provided per unit charge by a power source, such as a battery or generator, to drive electric current through a circuit. It is not a force in the traditional sense but rather a measure of the potential difference generated by the source when no current is flowing. The unit of emf is volts (V).
  • C. Internal resistance refers to the resistance within a power source, such as a battery or capacitor, that opposes the flow of electric current. It affects the efficiency and performance of the device by causing energy losses in the form of heat when current flows through it.
  • D. Resistivity (ρ) is a material property that quantifies how strongly a given material opposes the flow of electric current. It is defined as the resistance of a uniform sample of the material per unit length and per unit cross-sectional area.

Q155. If electronic transitions in the hydrogen atom terminate in the second orbit, the emitted series is known as:

  • A. Brackett series
  • B. Paschen series
  • C. Lyman series
  • D. Balmer series
  • E. Pfund series

Explanation: The Balmer series is a set of spectral lines in the hydrogen emission spectrum corresponding to electron transitions from higher energy levels to the n=2 energy level. These transitions result in the emission of visible light, making the Balmer series one of the most well-known series in atomic spectroscopy.

Why the other options are wrong
  • A. The Brackett series is a set of spectral lines in the hydrogen emission spectrum corresponding to electron transitions from higher energy levels to the n=4 energy level. These transitions emit light in the infrared region of the electromagnetic spectrum.
  • B. The Paschen series is a set of spectral lines in the hydrogen emission spectrum that corresponds to electron transitions from higher energy levels to the n = 3 energy level. These transitions result in the emission of infrared light.
  • C. The Lyman series is a set of spectral lines in the hydrogen emission spectrum that corresponds to electron transitions from higher energy levels to the n=1 energy level. These transitions result in the emission of ultraviolet light.
  • E. The Pfund series is a series of spectral lines in the hydrogen emission spectrum that corresponds to transitions of electrons from higher energy levels to the n = 5 energy level. It is part of the infrared region of the electromagnetic spectrum.

Q156. The force experienced by a current-carrying conductor placed in a magnetic field is:

  • A. F = qBLθθ.
  • B. F = BL sin θ.
  • C. F = qvB sin θ
  • D. F BL cos θ
  • E. F = BIL sin θ

Explanation: The force experienced by a current-carrying conductor placed in a magnetic field is given by the formula F = BIL sin 0.

Why the other options are wrong
  • A. F = qBLθ: This is not the correct formula. It incorrectly includes an extra factor of θ and q, which does not apply here.
  • B. F = BL sinθ: This is a close formula but is missing the current I. The correct formula involves the current I in addition to the magnetic field and length of the conductor.
  • C. F = qvB sinθ: This is the formula for the magnetic force on a charged particle (with charge q moving at velocity v in a magnetic field), not for a current-carrying conductor.
  • D. F = BL cosθ: This is incorrect because it uses cosθ instead of sinθ. The correct force is related to the angle between the magnetic field and the direction of the current.

Q157. The ratio of'molar gas constant' to 'Avogadro's number' (R/Na) is called:

  • A. Stefan's constant
  • B. Boltzmann constant
  • C. Rydberg's constant
  • D. Coulomb's constant
  • E. Planck's constant

Explanation: The ratio of the molar gas constant to Avogadro's number is called the Boltzmann constant .

Why the other options are wrong
  • A. The Stefan-Boltzmann constant (σ) is a physical constant that describes the power radiated per unit area of a black body in terms of its temperature, with a value of approximately 5.67 × 10⁻⁸ W m⁻² K⁻⁴.
  • C. Rydberg's constant is a fundamental physical constant that characterizes the wavelengths of spectral lines of hydrogen and hydrogen-like atoms. It is used in the Rydberg formula to predict the wavelengths of transitions between energy levels in an atom.
  • D. Coulomb's constant is a proportionality factor in Coulomb's Law, which describes the electrostatic force between two point charges. It quantifies the strength of the electrostatic interaction in a vacuum.
  • E. Planck's constant is a fundamental constant in quantum mechanics that relates the energy of a photon to its frequency. It plays a crucial role in the field of quantum physics.

Q158. "The electric force between two static point charges varies directly to the product of charges with each charge and inversely with the square of the distance between them." This is:

  • A. Gay-Lussac's Law
  • B. Coulomb's Law
  • C. Faraday's Law
  • D. Charles's Law
  • E. Boyle's Law

Explanation: "The electric force between two static point charges varies directly to the product of charges with each charge and inversely with the square of the distance between them."

Why the other options are wrong
  • A. Gay-Lussac's Law states that the pressure of a gas is directly proportional to its absolute temperature (in Kelvin) when the volume is held constant.
  • C. Faraday's Law of Electromagnetic Induction states that the electromotive force (EMF) induced in a circuit is directly proportional to the rate of change of the magnetic flux through that circuit.
  • D. Charles's Law states that the volume of a gas is directly proportional to its temperature (in Kelvin) when the pressure is held constant.
  • E. Boyle's Law states that, for a given mass of gas at constant temperature, the pressure of the gas is inversely proportional to its volume.

Q159. In radioactivity, the product of half-life T1/2 and decay constant (4) is equal to:

  • A. 0.693
  • B. 0.396
  • C. 0.953
  • D. 0.963
  • E. 0.369

Explanation: In radioactivity, the product of half-life Tız and decay constant (4) is equal to 0.693.

Why the other options are wrong
  • B. This option is incorrect as per the explanation and calculations.
  • C. This option is incorrect as per the explanation and calculations.
  • D. This option is incorrect as per the explanation and calculations.
  • E. This option is incorrect as per the explanation and calculations.

Q160. The change in potential energy per unit charge between two points in an electric field is:

  • A. Retentivity
  • B. Potential difference
  • C. Intensity
  • D. Permittivity
  • E. Permeability

Explanation: Potential difference, also known as voltage, is the difference in electric potential energy between two points in an electric field. It represents the work needed to move a unit charge from one point to another and is a measure of the driving force that pushes electric charges through a circuit.

Why the other options are wrong
  • A. Retentivity is the ability of a magnetic material to retain a certain amount of residual magnetization after an external magnetic field is removed. It represents how well a material can remain magnetized without an applied field.
  • C. Intensity refers to the amount of energy transferred per unit area per unit time. It is commonly used in fields like physics, acoustics, and electromagnetism to describe the power of waves (such as light, sound, or electromagnetic waves) passing through a given area.
  • D. Permittivity is a measure of how easily a material can store electrical energy in an electric field. It indicates the material's ability to permit the formation of an electric field within it. Higher permittivity means the material can store more electric energy when exposed to an electric field.Permittivity is denoted by the symbol ε and is measured in farads per meter (F/m).
  • E. Permeability is a property of a material that measures its ability to support the formation of a magnetic field within itself. It quantifies how easily a material can become magnetized when exposed to an external magnetic field. The higher the permeability, the easier it is for magnetic lines of force to pass through the material.It is denoted by the symbol μ and measured in henries per meter (H/m)

Q161. Which of the following statements is correct?

  • A. A magnetic field exerts a force if the charged particle moves opposite to the magnetic field.
  • B. A magnetic field never exerts a force on a charged particle.
  • C. A magnetic field exerts a force if the charged particle moves parallel to the magnetic field.
  • D. A magnetic field exerts a force if the charged particle moves perpendicular to the magnetic field.

Explanation: A magnetic field exerts a force if the charge particle moves perpendicular to the magnetic field. This force is called Lorentz Force.

Why the other options are wrong
  • A. A magnetic field exerts a force if the charged particle moves opposite to the magnetic field: This is incorrect. A magnetic field only exerts a force on a moving charge when there is a perpendicular component between the velocity of the charge and the magnetic field. Opposite direction doesn't guarantee a force.
  • B. A magnetic field never exerts a force on a charged particle: This is incorrect. A magnetic field does exert a force on a charged particle, but only when the particle is in motion and the velocity has a perpendicular component to the field.
  • C. A magnetic field exerts a force if the charged particle moves parallel to the magnetic field: This is incorrect. If the charge is moving parallel (or antiparallel) to the magnetic field, there is no force because the velocity and magnetic field are aligned, and the sine of the angle between them is zero.

Q162. Resistivity depends on:

  • A. Weight of material
  • B. Charge of material
  • C. Shape of material
  • D. Size of material
  • E. Temperature of material

Explanation: The resistivity of a material depends upon its temperature.

Why the other options are wrong
  • A. Resistivity does not depend on the weight of a material. Resistivity is an intrinsic property of the material that describes its ability to resist the flow of electric current, and it is independent of the amount (weight) of the material present.
  • B. Resistivity does not depend on charge. Resistivity is an intrinsic property of a material that indicates how strongly it opposes the flow of electric current, and it is determined by the material's composition and temperature.
  • C. Resistivity does not depend on the shape of the material. Resistivity is an intrinsic property of a material that indicates its ability to resist the flow of electric current, and it is determined by the material's composition and temperature.
  • D. Resistivity itself is an intrinsic property of a material and does not depend on the size or shape of the material

Q163. The speed of electromagnetic waves 'e' in free space is:

  • A. c=3 x 108 m/s
  • B. c =3 x 106 m/s
  • C. c=3 x 10° m/s
  • D. c=3 x 10 m/s
Why the other options are wrong
  • B. The speed of electromagnetic waves (denoted as c ) in free space is the speed of light and is approximatelyc=3×108 m/s This is the speed at which all electromagnetic waves, including light, travel in a vacuum or free space.
  • C. The speed of electromagnetic waves (denoted as c ) in free space is the speed of light and is approximatelyc=3×108 m/s This is the speed at which all electromagnetic waves, including light, travel in a vacuum or free space.
  • D. The speed of electromagnetic waves (denoted as c ) in free space is the speed of light and is approximatelyc=3×108 m/s This is the speed at which all electromagnetic waves, including light, travel in a vacuum or free space.

Q164. The constant power output of a machine is 6 W. The energy delivered by it in 2 minutes is:

  • A. 12 joules
  • B. 720 joules
  • C. 72 joules
  • D. 3 joules
  • E. 120 joules
Why the other options are wrong
  • A. This is incorrect because it results from a wrong calculation or misunderstanding of units. The machine operates for 120 seconds, not 2 seconds or 0.2 minutes. Using the correct formula gives 720 J, not 12 J.
  • C. This is incorrect. It appears to be an error due to missing one zero (perhaps using 12 s instead of 120 s). Always convert minutes to seconds before substituting into the formula.
  • D. This option is incorrect and far too small. It would correspond to an extremely short operation time (less than a second). A 6 W machine working for 2 minutes can never deliver only 3 J of energy.
  • E. Also incorrect. This might come from using 20 s instead of 120 s. But since 2 minutes equals 120 s, the energy must be much greater. The correct answer remains 720 J.

Q165. The process in which all the supplied heat is converted into work is called:

  • A. Isochoric
  • B. Isobaric
  • C. Adiabatic
  • D. Isotropic
  • E. Isothermal

Explanation: The process in which all the supplied heat is converted into work is called a reversible isothermal process. However, it's important to note that in real-world scenarios, achieving 100% conversion of heat into work is impossible due to the Second Law of Thermodynamics, which states that some energy will always be lost as waste heat.

Why the other options are wrong
  • A. Isochoric refers to a thermodynamic process that occurs at constant volume. In an isochoric process, the volume of the system does not change, even as pressure and temperature may vary.
  • B. Isobaric refers to a process that occurs at constant pressure. In thermodynamics, this term is used to describe situations where the pressure of a system remains unchanged while other variables, such as volume and temperature, may change.
  • C. Adiabatic processes are important in thermodynamics, providing insight into how systems behave when no heat is exchanged, allowing for a better understanding of energy transformations and efficiency in various applications.
  • D. Isotropic refers to a property of a material or system that has the same physical properties in all directions. This term is often used

Q166. The charge-to-mass ratio (e/m) of an electron is:

  • A. 9 x 10^4 C/kg
  • B. 1.76 x 10° C/kg
  • C. 1.76 x 1011 C/kg
  • D. 1.602 x 10 C/kg
  • E. 1.602 x 1011 C/kg

Explanation: The charge to mass ratio (e/m) of an electron is:1.76 x 10^11 C/kg.

Why the other options are wrong
  • A. 9 x 10⁴ C/kg: This is not the correct charge-to-mass ratio for an electron.
  • B. 1.76 x 10⁰ C/kg: This is incorrect as it doesn't match the standard value for the electron's charge-to-mass ratio.
  • D. 1.602 x 10⁰ C/kg: This is the elementary charge (e), not the charge-to-mass ratio for an electron.
  • E. This option is incorrect.

Q167. If the instantaneous velocity of a body is equal to the average velocity, then:

  • A. The body moves with decreasing velocity
  • B. The body moves with variable acceleration
  • C. The body moves with uniform velocity
  • D. The body moves with uniform acceleration
  • E. The body moves with increasing velocity

Explanation: If the instantaneous velocity is equal to average velocity then the body is moving with uniform velocity.

Why the other options are wrong
  • A. The body moves with decreasing velocity. This would imply the velocity is slowing down over time, which would make the instantaneous velocity less than the average velocity, not equal to it.
  • B. The body moves with variable acceleration. Variable acceleration would imply changing acceleration, but if the instantaneous velocity equals the average velocity, the motion is uniform, meaning constant velocity and no changing acceleration.
  • D. The body moves with uniform acceleration: If the body had uniform acceleration, the instantaneous velocity would not be equal to the average velocity unless the time interval was very short.
  • E. The body moves with increasing velocity. This would imply the body is speeding up, which would make the instantaneous velocity greater than the average velocity, not equal to it.

Q168. The waves that require medium for their propagation are known as:

  • A. Electromagnetic waves
  • B. De Broglie waves
  • C. Mechanical waves
  • D. Particle waves
  • E. Matter waves

Explanation: Mechanical waves are waves that require a medium (solid, liquid, or gas) to propagate. They transfer energy through the vibration of particles in the medium.

Why the other options are wrong
  • A. Electromagnetic waves are oscillating electric and magnetic fields that propagate through space at the speed of light. They do not require a medium to travel and consist of varying wavelengths and frequencies
  • B. De Broglie waves, or matter waves, do not require a physical medium to propagate. They represent the wave-like behavior of particles, such as electrons or atoms, in quantum mechanics. These waves are a mathematical description of the probability of finding a particle in a particular location, so they exist wherever the particle exists, whether in a vacuum or any other environment.
  • D. Particle waves (or matter waves) do not require a physical medium to propagate. They represent the quantum wave-like behavior of particles, such as electrons or atoms, and are described by the wave function in quantum mechanics.
  • E. Matter waves do not require a physical medium to propagate, unlike sound waves that need air or water. Instead, they represent a fundamental aspect of quantum mechanics, illustrating that particles, such as electrons or atoms, can exhibit wave-like behavior. This behavior is described by the wave function in quantum mechanics, which provides probabilities for finding particles in various states or positions.

Q169. The SI unit of the electric field is:

  • A. JC-2
  • B. N C-I
  • C. Nm² C-1
  • D. CN2
  • E. Nm² C-2

Explanation: The SI unit of electric field is N C-I

Why the other options are wrong
  • A. JC⁻²: Incorrect. This unit represents energy per charge squared, which is not the unit for electric field. The electric field is related to force per charge.
  • C. Nm² C⁻¹: Incorrect. This unit is not appropriate for electric field; it combines units of force, distance, and charge incorrectly for electric field.
  • D. C N²: Incorrect. This unit doesn't align with the definition of electric field, as it doesn't properly represent force per charge.
  • E. Nm² C⁻²: Incorrect. This unit represents a combination of force, distance, and charge squared, which does not correspond to the electric field's definition.

Q170. An electron and proton enter a magnetic field perpendicularly with the same momentum:

  • A. They move undeflected in opposite directions
  • B. The electron deflects more than the proton
  • C. They will deflect equally
  • D. The proton deflects more than the electron.
  • E. They will not deflect at all

Explanation: When an electron and a proton enter a magnetic field perpendicularly with the same momentum, they experience the Lorentz force, which is given by F = q(v × B), where q is the charge, v is the velocity, and B is the magnetic field. Since both the electron and proton have the same momentum, they will deflect equally in the magnetic field, regardless of their mass differences. The charge of the electron is negative, and the charge of the proton is positive, but since they are both moving in the same perpendicular field, the direction of their deflections will be opposite, but the magnitude will be the same. Thus, the correct answer is that they will deflect equally.Option A is incorrect because they cannot move undeflected when entering a magnetic field perpendicularly. Option B is misleading as it suggests that the deflection depends solely on mass; they deflect equally with the same momentum. Option D is incorrect because the proton's greater mass results in a smaller deflection for the same momentum. Option E is also incorrect since both particles will deflect.

Why the other options are wrong
  • A. They move undeflected in opposite directions. This scenario is not possible since the question specifies they are entering the magnetic field perpendicularly, which means they will experience a magnetic force and deflect.
  • B. The electron deflects more than the proton. While the electron has less mass and would experience a greater acceleration, the deflection depends on their momentum and charge. Since they have the same momentum, this statement is misleading.
  • D. The proton deflects more than the electron. This is incorrect because the proton, being more massive and having the same momentum, moves slower and thus experiences less deflection compared to the electron.
  • E. They will not deflect at all. This is incorrect as both particles will definitely experience a magnetic force and deflect since they enter the field perpendicularly.

Q171. A body starts from rest and falls freely under gravity; the distance covered by it in t' seconds is:

  • A. 0.5gt^2
  • B. gt
  • C. 0.5g
  • D. g

Explanation: The distance s covered by a body falling freely under gravity in t seconds, starting from rest, is given by the equation:s=1/2gt2

Why the other options are wrong
  • B. This is incorrect because it represents the velocity (not the distance) of the object falling freely after time t. Velocity under free fall increases linearly with time, not the distance.
  • C. This is incorrect because it is a constant and doesn't depend on time t. It would be related to acceleration, not distance.
  • D. This is incorrect as well because g represents the acceleration due to gravity, not the distance traveled. The distance is proportional to t², not a constant acceleration.

Q172. The total energy E of a body at any instant, executing simple harmonic motion, is:

  • A. E =-2kx
  • B. E=0.5(kx^2)
  • C. E= -kx²
  • D. E = kx

Explanation: The total energy E of a body at any instant, executing simple harmonic motion, is given by E=0.5(kx^2).

Why the other options are wrong
  • A. E = -2kx: Incorrect. This equation does not represent the total energy in SHM; it suggests a force, not total energy.
  • C. E = -kx²: This is not correct. It only represents the potential energy in the case of a spring, but the total energy is positive and has the 0.5 factor.
  • D. E = kx: Incorrect. This expression does not correspond to the total energy in SHM; it incorrectly mixes force and displacement.

Q173. A reverse-biased semiconductor diode acts as:

  • A. Rectifier
  • B. On switch
  • C. Inverter
  • D. Off switch
  • E. Amplifier

Explanation: A reverse-biased semiconductor diode can be thought of as an off switch because it prevents current from flowing through the circuit, similar to an open switch. Only a very small leakage current passes through until the breakdown voltage is exceeded.

Why the other options are wrong
  • A. A rectifier is an electronic device that converts alternating current (AC) to direct current (DC). This process is known as rectification. Rectifiers are commonly used in power supplies, battery chargers, and various electronic circuits.
  • B. An ON switch refers to a device or mechanism that allows electrical current to flow through a circuit when activated, effectively turning the connected device or system on
  • C. An inverter is an electronic device that converts direct current (DC) into alternating current (AC). Inverters are essential in various applications, especially in renewable energy systems, where they facilitate the use of solar or wind power in electrical grids and appliances.
  • E. An amplifier is an electronic device that increases the amplitude of a signal, making it stronger without significantly altering its shape. Amplifiers are widely used in audio, radio, and other electronic applications to boost signals for various purposes.

Q174. For maximum work done by a constant force, the angle between force and displacement is:

  • A. 45°
  • B. 90°
  • C. 65°
  • D. 145°
  • E.

Explanation: Work done is given as F.dcosθ. cosθ is maximum at 0 degrees i.e 1.

Why the other options are wrong
  • A. 45°: This angle will result in less than maximum work, as the work done is W = Fd cos(θ), and cos(45°) is not equal to 1.
  • B. 90°: When the angle is 90°, the force is perpendicular to the displacement, meaning no work is done (since cos(90°) = 0).
  • C. 65°: This is not the angle that maximizes work, as cos(65°) is less than cos(0°).
  • D. 145°: This angle would result in negative work (since cos(145°) is negative), but not the maximum positive work.

Q175. A body is moving in a circle with constant speed. Which of the following statements is true?

  • A. There is a force acting on the body at a tangent to the circle
  • B. There is a force acting on the body toward the center of the circle
  • C. There is no acceleration in the body
  • D. There is a force acting on the body away from the center of the circle
  • E. The net force acting on the body is zero

Explanation: When a body is moving in a circle a centripital force acts on it and although its speed remains constant it has a centripital acceleration as well.

Why the other options are wrong
  • A. There is a force acting on the body at a tangent to the circle: This is incorrect. The force responsible for circular motion is directed toward the center of the circle (centripetal force), not tangentially.
  • C. There is no acceleration in the body: This is incorrect. Even though the speed is constant, the direction of the velocity is continuously changing as the object moves in a circle, which means there is centripetal acceleration.
  • D. There is a force acting on the body away from the center of the circle: This is incorrect. The force is directed toward the center, not away from it.
  • E. The net force acting on the body is zero: This is incorrect. There is a net force (centripetal force) acting on the body toward the center of the circle, which causes the acceleration necessary for circular motion.

Q176. The unit of potential difference is:

  • A. Ampere
  • B. Coulomb
  • C. Volt
  • D. Watt
  • E. Ohm

Explanation: The volt measures electric potential difference or voltage.

Why the other options are wrong
  • A. This option is incorrect. Ampere (A) is the SI unit of electric current, which measures the rate of flow of electric charge through a conductor.
  • B. This is also incorrect. Coulomb (C) is the unit of electric charge, not potential difference. One coulomb is the charge transported by a current of one ampere in one second.
  • D. This option is incorrect. Watt (W) is the unit of power, which represents the rate of doing work or energy per second.
  • E. This option is incorrect as well. Ohm (Ω) is the unit of electrical resistance, which measures how strongly a material opposes the flow of current.

Q177. In the SI system, the specific heat capacity is measured in:

  • A. J kg^-1 K^-1
  • B. J Kg
  • C. J kg-1 C
  • D. Jg-1 C-1

Explanation: The SI unit of specific heat capacity is J kg^-1 K^-1.

Why the other options are wrong
  • B. J kg: Incorrect. This unit represents energy (Joules) per unit mass, but does not account for temperature change, so it cannot be used for specific heat capacity.
  • C. J kg⁻¹ °C: Incorrect. While the units are close to specific heat capacity, °C (Celsius) is not strictly part of the SI system for temperature (K is preferred), and specific heat capacity is not typically measured with °C in SI.
  • D. J g⁻¹ °C⁻¹: Incorrect. This unit uses grams instead of kilograms and Celsius instead of Kelvin, which are not standard SI units for specific heat capacity.

Q178. The period of uniform circular motion is given as:

  • A. T = w/2r
  • B. T = 2π/ w
  • C. T=2n o
  • D. T = 2rT
  • E. T = 2π w²

Explanation: The time period in uniform circular motion is the time taken to complete one full revolution around the circular path and is given by the formula T= 2n/w.

Why the other options are wrong
  • A. T = ω / 2r: Incorrect. This expression does not correctly represent the period of uniform circular motion. It seems to mix angular velocity (ω) and radius (r), but the correct relation involves a factor of 2π.
  • C. T = 2n o: Incorrect. This is not a valid equation for the period of uniform circular motion, and the symbols used here do not correspond to the correct variables for period.
  • D. T = 2rT: Incorrect. This equation incorrectly suggests a direct proportionality between the period and the radius, which does not represent uniform circular motion. The period is independent of the radius in this incorrect form.
  • E. The equation T = 2π ω² is incorrect because the period of uniform circular motion (T) is inversely proportional to the angular velocity (ω), not squared. The correct formula is T = 2π / ω.

Q179. In the mathematical relationship Φ = hv, the symbol Φ represents:

  • A. Magnetic flux
  • B. Threshold frequency
  • C. Work function
  • D. Electric flux
  • E. Wave function

Explanation: The symbol Φ in the equation Φ = hv represents the work function, which is the minimum energy required to remove an electron from the surface of a material. In the context of the photoelectric effect, this energy is provided by photons with energy hv, where h is Planck's constant and v is the frequency of the photon. The other options are incorrect as they pertain to different physical concepts: magnetic flux and electric flux relate to field lines through a surface, threshold frequency is the minimum frequency for the photoelectric effect but not represented by Φ, and the wave function is a concept from quantum mechanics describing the state of a system.

Why the other options are wrong
  • A. This option is incorrect. Magnetic flux relates to the magnetic field passing through a surface and is not relevant in the context of quantum theory.
  • B. This option is incorrect. Threshold frequency is related to the minimum frequency needed to eject electrons but is represented as ν₀, not Φ.
  • D. This option is incorrect. Electric flux pertains to the electric field and its flow through a surface, not related to quantum theory.
  • E. This option is incorrect. The wave function describes the quantum state of a particle, not an energy quantity in the equation Φ = hv.

Q180. The unit of current is:

  • A. Volt
  • B. Ohm
  • C. Watt
  • D. Coulomb per second
  • E. Coulomb

Explanation: The unit of current is Ampere which can also be written as coulumb per second.

Why the other options are wrong
  • A. Volt is the SI unit of electric potential difference.
  • B. Ohm is the SI unit of electrical resistance.
  • C. Watt is the SI unit of power.
  • E. Coulomb is the SI unit of electric charge.

Q181. Fast moving electrons stopped by a heavy metallic target in an evacuated glass tube give rise to the:

  • A. Beta-rays
  • B. Gamma-rays
  • C. X-rays
  • D. Cosmic rays
  • E. Alpha-rays

Explanation: X-ray generation occurs when heated electrons are accelerated towards a tungsten target. Upon collision, these high-speed electrons produce X-rays through two main processes: Bremsstrahlung radiation, where electrons lose energy and emit X-rays, and characteristic X-rays, which arise when inner-shell electrons are displaced, prompting higher energy electrons to fall into lower energy levels and emit X-rays with specific energies. This process is fundamental to medical imaging and various industrial applications

Why the other options are wrong
  • A. Beta rays are high-energy electrons or positrons emitted during beta decay from the nucleus of unstable atoms. There are two types: beta-minus (β−) decay, where electrons are emitted as a neutron transforms into a proton, increasing the atomic number, and beta-plus (β+) decay, where positrons are emitted as a proton transforms into a neutron, decreasing the atomic number. Beta rays have moderate penetration power, capable of passing through paper but can be stopped by a few millimeters of plastic or several centimeters of air. They are utilized in medical applications, such as radiation therapy, and in various industrial and research contexts.
  • B. Gamma rays are high-energy electromagnetic radiation emitted from the nucleus of radioactive atoms during radioactive decay. They have no mass or charge and possess extremely short wavelengths, making them highly penetrating. Gamma rays are typically produced in processes such as nuclear fission, fusion, and the decay of certain isotopes. They are used in various applications, including medical imaging, cancer treatment (radiotherapy), and industrial radiography, but they can also pose health risks due to their ionizing nature.
  • D. Cosmic rays are high-energy particles from outer space that primarily consist of protons, but also include heavier atomic nuclei and high-energy electrons. They originate from various sources, such as supernovae, the sun, and other astronomical events. When cosmic rays enter Earth's atmosphere, they can collide with atoms, producing secondary particles, including muons and neutrinos. Cosmic rays can affect electronic devices and pose risks to astronauts in space due to their high energy and ionizing nature.
  • E. Alpha rays consist of alpha particles, which are made up of **two protons and two neutrons** (essentially helium nuclei). They are emitted during the radioactive decay of heavy elements, such as uranium and radium. Alpha rays have low penetration power and can be stopped by a sheet of paper or the outer layer of human skin.

Q182. The alternating emf (E) generated by an AC generator is given by:

  • A. E = BvL sin θ
  • B. E = - NBL sin θ
  • C. E = NBL cos θ
  • D. E = BNAω sin(ωt)
  • E. E = BvL cos θ

Explanation: The correct formula for the emf generated by an AC generator is E = BNAω sin(ωt). This expression accounts for the magnetic field strength (B), the number of turns in the coil (N), the area of the coil (A), and the angular velocity of the coil (ω). This formula reflects the fundamental principle that the emf induced in a coil is proportional to the rate of change of magnetic flux through the coil.The other options are incorrect as they either omit essential factors or apply to different scenarios, such as a straight conductor moving linearly through a magnetic field, rather than a rotating coil in an AC generator.

Why the other options are wrong
  • A. This option is incorrect. This formula is more appropriate for a straight conductor moving through a magnetic field rather than a rotating coil in an AC generator.
  • B. This option is incorrect. The negative sign and absence of key factors such as area (A) and angular velocity (ω) make this formula unsuitable for calculating the emf in an AC generator.
  • C. This option is incorrect. This formula does not include the necessary components for calculating emf in an AC generator, such as area (A) and angular velocity (ω).
  • E. This option is incorrect. This expression is more relevant for a straight conductor moving at an angle through a magnetic field and does not apply to a rotating coil in an AC generator.

Q183. In an N-type semiconductor, the minority carriers are:

  • A. Photons
  • B. Electrons
  • C. Protons
  • D. Holes
  • E. Neutrons

Explanation: In n-type semiconductors, the minority charge carriers are **holes**. These are created when electrons from the valence band are excited to the conduction band, leaving behind vacancies (holes) in the valence band.

Why the other options are wrong
  • A. PHOTONS: These are particles of light, not charge carriers in semiconductors.
  • B. Electrons: In an N-type semiconductor, electrons are the majority carriers, not the minority carriers.
  • C. Protons: These are not charge carriers in semiconductors.
  • E. Neutrons: These are neutral particles and do not play a role in semiconductor conduction.

Q184. The binding energy of a deuteron (IH) is 2.3 MeV, its binding energy per nucleon will be:

  • A. 0.51 MeV
  • B. 0.2 MeV
  • C. 1.02 MeV
  • D. 1.1 MeV
  • E. 1 MeV

Explanation: The correct answer is 1.1 MeV. To find the binding energy per nucleon, you must divide the total binding energy of the nucleus by the number of nucleons. For a deuteron, which consists of one proton and one neutron, there are two nucleons. Therefore, the binding energy per nucleon is calculated as:Binding Energy per Nucleon = Total Binding Energy / Number of Nucleons = 2.3 MeV / 2 = 1.15 MeV, which rounds to 1.1 MeV.Option D is correct. Option A (0.51 MeV) and Option C (1.02 MeV) result from incorrect division. Option B (0.2 MeV) largely underestimates the value, while Option E (1 MeV) rounds down the correct value inaccurately.

Why the other options are wrong
  • A. This option is incorrect because it miscalculates the division of total binding energy by the number of nucleons.
  • B. This option is incorrect as it significantly underestimates the binding energy per nucleon.
  • C. This option is incorrect due to a miscalculation of the division process.
  • E. This option is incorrect as it rounds down the correct value instead of accurately calculating it.

Q185. The mathematical relationship between magnetic flux and magnetic flux density is:

  • A. Φ = (B)(A)cosθ
  • B. Φ = (B)(Δt)cosθ
  • C. B = (ΔΦ)(Δt)cosθ
  • D. B = (ΔΦ)(Δt)
  • E. Φ = (B)(Δt)

Explanation: The correct mathematical relationship between magnetic flux (Φ) and magnetic flux density (B) is given by the formula: Φ = B ⋅ A ⋅ cos(θ). In this formula:Φ is the magnetic flux, representing the total magnetic field passing through a given area.B is the magnetic flux density, measuring the strength of the magnetic field.A is the area through which the magnetic field passes.θ is the angle between the magnetic field lines and the normal to the surface area.The other options are incorrect because they include inappropriate variables such as time (Δt) and changes in flux (ΔΦ), which do not belong in the formula relating magnetic flux and magnetic flux density.

Why the other options are wrong
  • B. This option is incorrect because it mistakenly includes time (Δt) in the relationship between magnetic flux and magnetic flux density, which does not belong in the formula.
  • C. This is incorrect because it incorrectly uses changes in flux (ΔΦ) and time (Δt), which are not part of the relationship between magnetic flux and magnetic flux density.
  • D. This option is incorrect as it does not correctly relate magnetic flux and magnetic flux density. It also incorrectly uses changes in flux (ΔΦ) and time (Δt).
  • E. This is incorrect because it incorrectly includes time (Δt) instead of area (A) in the relationship between magnetic flux and magnetic flux density.

Q186. If the length of a simple pendulum is increased four times, its frequency:

  • A. Increases 2 times
  • B. Decreases 4 times
  • C. Remains the same
  • D. Increases 4 times
  • E. Decreases 2 times

Explanation: The frequency of a simple pendulum is determined by the formula f = 1/2π√(g/L), which shows that the frequency is inversely proportional to the square root of the pendulum's length.When the length L is quadrupled, the new length is 4L. The new frequency is f' = 1/2π√(g/4L) = 1/2√4 × 1/2π√(g/L) = f/2.This means the frequency decreases by a factor of 2. Thus, Option E is correct.Other options are incorrect because they do not reflect the inverse square root relationship between frequency and length in a pendulum.

Why the other options are wrong
  • A. This option is incorrect. Increasing the length of a pendulum decreases its frequency, not increases it.
  • B. This option is incorrect. The frequency is inversely proportional to the square root of the length, not directly proportional to the length itself.
  • C. This option is incorrect. Changing the length of the pendulum affects its frequency.
  • D. This option is incorrect. The frequency decreases when the pendulum length is increased.

Q187. In the equation of nuclear decay p^1 → →n^1 + x , x is:

  • A. Proton
  • B. Positron
  • C. Electron
  • D. Photon
  • E. Gamma ray

Explanation: n the equation for nuclear decay p^1 →n^1 + x , the particle x represents a positively charged particle, typically a positron (e+) or beta plus particle (β+).

Why the other options are wrong
  • A. Proton: A proton cannot decay into another proton in this type of nuclear decay because it would violate conservation laws (such as charge).
  • C. Electron: An electron is emitted in beta-minus (β⁻) decay, not in the transformation of a proton into a neutron.
  • D. Photon: A photon is a quantum of electromagnetic radiation, not a particle emitted in this decay process.
  • E. Gamma rays: Gamma rays are high-energy photons emitted in nuclear reactions but not in this specific decay equation. They usually occur after other nuclear transitions, not from proton to neutron decay.

Q188. A force of magnitude 10N is acting along the x-axis; its component along the y-axis is:

  • A. Zero
  • B. 5N
  • C. 20N
  • D. 10N
  • E. 25N

Explanation: The correct answer is Zero. When resolving forces into components, a force acting along the x-axis has no y-component because it is entirely in the horizontal direction. Mathematically, the y-component of a force F acting at an angle θ from the x-axis is calculated as Fy = F sin θ. Here, θ is 0 degrees since the force is along the x-axis, resulting in sin(0) = 0. Therefore, Fy = 10 N × 0 = 0 N. The other options suggest non-zero y-components, which are incorrect since they imply that the force has a component along the y-axis, which it does not.

Why the other options are wrong
  • B. This is incorrect. A force acting solely along the x-axis cannot have a y-component unless it has a component in that direction.
  • C. This is incorrect. The force magnitude along the x-axis does not translate into the y-axis component in this scenario.
  • D. This is incorrect. While the force's total magnitude is 10N, it is entirely along the x-axis, yielding zero component along the y-axis.
  • E. This is incorrect. This value does not relate to the force's resolution into components.

Q189. The proton number of a nucleus increases after emission of:

  • A. Negative ß particle
  • B. Positive B particle
  • C. Proton
  • D. Alpha particle
  • E. Neutron

Explanation: In beta-minus decay, a neutron is converted into a proton, and an electron (beta particle) is emitted. The atomic number increases by 1, changing the element to the next higher one, while the mass number remains the same.

Why the other options are wrong
  • B. In beta-plus decay, a proton is converted into a neutron, and a positron (positive beta particle) is emitted. The atomic number decreases by 1, changing the element to the next lower one, while the mass number remains unchanged.
  • C. After a proton is emitted from a nucleus, the atom transforms into a new element with an atomic number reduced by one. This is because the number of protons defines the element. The nucleus becomes more stable or shifts toward a more stable configuration.
  • D. After the emission of an alpha particle (which consists of 2 protons and 2 neutrons) from a nucleus, the atomic number decreases by 2, and the mass number decreases by 4. This changes the element into a new one that is two positions lower on the periodic table.
  • E. After the emission of a neutron from a nucleus, the mass number of the atom decreases by one, but the atomic number (and hence the element) remains the same. The nucleus may become more unstable, as neutrons help stabilize protons in the nucleus.

Q190. E = k * Q / r^2 K is called:

  • A. Coulomb
  • B. Constant of proportionality
  • C. Relative permittivity of the medium
  • D. Permittivity of the space
  • E. Permittivity of the medium

Explanation: In Coulombs' law "k" is the constant of proportionality.

Why the other options are wrong
  • A. Coulomb: Incorrect. While Coulomb's law describes the force between charges, k specifically refers to Coulomb's constant in this equation.
  • C. Relative permittivity of the medium: Incorrect. This refers to the material's ability to permit an electric field, and is usually represented by εᵣ, not k.
  • D. Permittivity of the space: Incorrect. The permittivity of free space is represented by ε₀ and is related to k through the equation k = 1 / (4πε₀).
  • E. Permittivity of the medium: Incorrect. The permittivity of the medium is represented by ε and refers to the medium's ability to allow an electric field to pass through, distinct from k in Coulomb's law.

Q191. Newton (N) is not the SI unit of:

  • A. Centripetal force
  • B. Tension
  • C. Coulomb's force
  • D. Friction
  • E. Momentum

Explanation: The SI unit of momentum is kgm/s

Why the other options are wrong
  • A. Centipetal force: The unit of force is the Newton (N), so Newton is the SI unit of centripetal force.
  • B. Tension: Tension is a force, and Newton is the SI unit of force, so Newton is the SI unit of tension.
  • C. Coulomb force: Coulomb force is an electrostatic force, and its SI unit is also Newton (N).
  • D. Friction: Friction is a force, so the SI unit for friction is also Newton (N).

Q192. In law of radioactive decay N = Ne, the ratio N No is called:

  • A. Activity
  • B. Relative activity
  • C. Absolute activity
  • D. Stability
  • E. Decay constant

Explanation: Relative activity refers to the comparison of the activity level of a particular enzyme, catalyst, or biological substance under different conditions or in relation to a standard or control. It is often used to measure how changes in factors like temperature, pH, or substrate concentration affect the effectiveness or efficiency of the substance's activity. In enzyme studies, relative activity helps determine optimal conditions for maximum performance.

Why the other options are wrong
  • A. Radioactive activity refers to the process by which unstable atomic nuclei decay, releasing energy in the form of radiation. This decay can emit alpha particles, beta particles, or gamma rays, and it occurs naturally or can be induced in a lab. The activity is measured in becquerels (Bq), which indicates the number of decays per second.
  • C. Absolute radioactive activity is the total number of nuclear decays or disintegrations occurring in a radioactive material per second. It’s measured in units like becquerels (Bq), where 1 Bq equals one decay per second.
  • D. Stability in nuclear physics refers to the likelihood that a nucleus will remain intact without undergoing radioactive decay. A stable nucleus has a balanced ratio of protons to neutrons, and it does not emit radiation or change over time. Unstable nuclei, however, decay to become more stable, releasing radiation in the process. Stability depends on nuclear forces, the size of the nucleus, and the proton-to-neutron ratio.
  • E. The decay constant (λ) is a parameter that describes the rate at which a radioactive substance decays. It represents the probability of an atom decaying per unit time. The larger the decay constant, the faster the substance decays. It is related to the half-life (T₁/₂) of the substance.

Q193. In Einstein's photoelectric equation hv =ϕ +eV, the kinetic energy of photoelectrons is:

  • A. K.Emax=p+eV
  • B. K.Emax = -eV
  • C. K.Emax = -hv
  • D. K.Emax = hv - φ
  • E. K.Emax = hv-eVo

Explanation: The equation K.Emax=−eV refers to the maximum kinetic energy (K.E) of electrons in the context of the photoelectric effect or electron emission.

Why the other options are wrong
  • A. The equation K.Emax=−eV refers to the maximum kinetic energy (K.E) of electrons in the context of the photoelectric effect or electron emission.
  • C. The equation K.Emax=−eV refers to the maximum kinetic energy (K.E) of electrons in the context of the photoelectric effect or electron emission.
  • D. The equation K.Emax=−eV refers to the maximum kinetic energy (K.E) of electrons in the context of the photoelectric effect or electron emission.
  • E. The equation K.Emax=−eV refers to the maximum kinetic energy (K.E) of electrons in the context of the photoelectric effect or electron emission.

Q194. Faraday's law of electromagnetic induction is mathematically represented as:

  • A.
  • B.
  • C.
  • D.
  • E.

Explanation: Faraday's law of electromagnetic induction states that the electromotive force (EMF) induced in a circuit is proportional to the rate of change of magnetic flux through that circuit.

Why the other options are wrong
  • A. Faraday's law of electromagnetic induction states that the electromotive force (EMF) induced in a circuit is proportional to the rate of change of magnetic flux through that circuit.
  • B. Faraday's law of electromagnetic induction states that the electromotive force (EMF) induced in a circuit is proportional to the rate of change of magnetic flux through that circuit.
  • C. Faraday's law of electromagnetic induction states that the electromotive force (EMF) induced in a circuit is proportional to the rate of change of magnetic flux through that circuit.
  • E. Faraday's law of electromagnetic induction states that the electromotive force (EMF) induced in a circuit is proportional to the rate of change of magnetic flux through that circuit.

Q195. Read the statement given, assume it is true, and select the correct course of action:A public sector television channel is worried about the quality of its programs and, considering the competition from several private sector television channels, has decided to provide some incentives in order to attract talent for its programs.Course of action:a) Public sector television channel has decided to revise its fee structure for artists.b) It should not revise its fee structure until the private sector channels do so.

  • A. Both A and B follow
  • B. Only A follows
  • C. Only B follows
  • D. Neither A nor B follows
  • E. Either A or B follows

Explanation: By revising its fee structure, the public sector television channel can attract better talent, which can help improve the quality of its programs and make it more competitive against private sector channels.

Why the other options are wrong
  • A. This is incorrect because while statement A aligns with the television channel's concern for improving program quality, statement B contradicts the channel's proactive approach. Waiting for private channels to act first is not a logical course of action.
  • C. This is incorrect because waiting for private channels to revise their fee structure does not help the public sector television channel address its concern. Taking independent action is necessary.
  • D. This is incorrect because A is a valid course of action that supports the given statement.
  • E. This is incorrect because A is the only logical step, while B contradicts the intended goal of improving program quality.

Q196. Parveen, Qadir, Rehan, Salim, and Tehmina are five people in a family. If Parveen is the daughter of Qadir, Qadir is the son of Rehan, Rehan is the father of Salim, while Tehmina is the daughter of Parveen, then which of the following is true?

  • A. Rehan is the uncle of Parveen
  • B. Qadir is the grandfather of Parveen
  • C. Qadir is the daughter of Salim
  • D. Parveen is the sister of Tehmina
  • E. None of them

Explanation: Let’s break down the relationships based on the information given:Parveen is the daughter of Qadir: This means Qadir is Parveen's father.Qadir is the son of Rehan: This means Rehan is Qadir's father.Rehan is the father of Salim: This means Rehan has two children—Qadir and Salim.Tehmina is the daughter of Parveen: This means Parveen is Tehmina's mother.

Why the other options are wrong
  • A. This is incorrect. Rehan is Parveen's grandfather, not her uncle.
  • B. This is incorrect. Qadir is Parveen's father, not her grandfather.
  • C. This is incorrect. Qadir is Salim's brother, not his daughter.
  • D. This is incorrect. Parveen is Tehmina's mother, not her sister.

Q197. Look at the numbers below. Identify the pattern and logically deduce the correct option that should follow: 1, 4, 9, 16,

  • A. 54
  • B. 36
  • C. 49
  • D. 25

Explanation: These numbers are perfect squares of natural numbers.The next number should logically be 5^2 = 25

Why the other options are wrong
  • A. These numbers are perfect squares of natural numbers.The next number should logically be 5^2 = 25
  • B. These numbers are perfect squares of natural numbers.The next number should logically be 5^2 = 25
  • C. These numbers are perfect squares of natural numbers.The next number should logically be 5^2 = 25

Q198. Read the two statements given and select the correct optionA. Advances in cancer chemotherapy have made more drugs available today.B. A large number of cancer patients now have a better outcome.

  • A. Both statements A and B are effects of some common cause.
  • B. Statement A is the cause and statement B is the effect
  • C. Both statements A and B are effects of independent causes.
  • D. Statement B is the cause and statement A is the effect.
  • E. Both statements A and B are independent causes.

Explanation: Statement A describes a cause: new drugs are available because of advances in chemotherapy.Statement B is the effect of that cause. Because more drugs are available (A), cancer patients are benefiting and having better outcomes (B).

Why the other options are wrong
  • A. This is incorrect because A directly leads to B. There isn’t a separate common cause leading to both; advances in chemotherapy (A) directly improve patient outcomes (B).
  • C. This is incorrect because A and B are not independent; A directly causes B.
  • D. This is incorrect because patient outcomes improving (B) do not cause advances in chemotherapy (A). It's the other way around.
  • E. This is incorrect because A and B are not independent; one is the cause of the other.

Q199. Which number is a multiple of its digits?

  • A. 21
  • B. 47
  • C. 52
  • D. 24
  • E. 13

Explanation: The digits of 24 are 2 and 4. We need to check if 24 is divisible by both 2 and 4.-> 24 / 2 = 12, which means 24 is divisible by 2.-> 24 / 4 = 6, which means 24 is divisible by 4.Since 24 is divisible by both its digits (2 and 4), it is a multiple of its digits.

Why the other options are wrong
  • A. This is not correct according to calculations as 21 is not multiple of it's 2.
  • B. This is not correct as 47 is not an multiple of its own digits.
  • C. 52 is not a multiple of its digits (5 and 2) because 52 ÷ (5 * 2) = 52 ÷ 10.0 = 5.2, which is not an integer.
  • E. 13 is not a multiple of its digits (1 and 3) because 13 ÷ (1 * 3) = 13 ÷ 3 ≈ 4.33, which is not an integer.

Q200. Look at the alphabets below. Identify the pattern and choose the correct option that should follow next: VSA, WRD, XQG, YPJ,-----

  • A. VTC
  • B. TLK
  • C. MOZ
  • D. ZOM
  • E. ZNE

Explanation: Observing the pattern in each letter of the sequence:First Letter:V → W → X → Y → Z (Each letter moves forward by 1 position in the alphabet)Second Letter:S → R → Q → P → O (Each letter moves backward by 1 position)Third Letter:A → D → G → J → M (Each letter moves forward by 3 positions)Following this pattern, the next term should be ZOM.

Why the other options are wrong
  • A. Observing the pattern in each letter of the sequence:First Letter:V → W → X → Y → Z (Each letter moves forward by 1 position in the alphabet)Second Letter:S → R → Q → P → O (Each letter moves backward by 1 position)Third Letter:A → D → G → J → M (Each letter moves forward by 3 positions)Following this pattern, the next term should be ZOM.
  • B. Observing the pattern in each letter of the sequence:First Letter:V → W → X → Y → Z (Each letter moves forward by 1 position in the alphabet)Second Letter:S → R → Q → P → O (Each letter moves backward by 1 position)Third Letter:A → D → G → J → M (Each letter moves forward by 3 positions)Following this pattern, the next term should be ZOM.
  • C. Observing the pattern in each letter of the sequence:First Letter:V → W → X → Y → Z (Each letter moves forward by 1 position in the alphabet)Second Letter:S → R → Q → P → O (Each letter moves backward by 1 position)Third Letter:A → D → G → J → M (Each letter moves forward by 3 positions)Following this pattern, the next term should be ZOM.
  • E. Observing the pattern in each letter of the sequence:First Letter:V → W → X → Y → Z (Each letter moves forward by 1 position in the alphabet)Second Letter:S → R → Q → P → O (Each letter moves backward by 1 position)Third Letter:A → D → G → J → M (Each letter moves forward by 3 positions)Following this pattern, the next term should be ZOM.

More Sindh / DUHS Solved Papers