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Sindh Mdcat Exclusive Course Biology Biological Molecules — Solved Past Paper with Answers
All 20 MCQs from Sindh Mdcat Exclusive Course Biology Biological Molecules, solved with the correct answer highlighted and a full explanation for every question. This is a free MDCAT Sindh / DUHS past paper — no signup, no ads. Practise it interactively in timed mode, drill more with free MDCAT MCQs, or browse all Sindh / DUHS papers.
Attempt this paper interactively →Q1. Which of the following are not polymer?
- A. Proteins
- B. Polysaccharides
- C. Lipids✓
- D. Nucleic acids
Explanation: The correct answer is Lipids. Unlike proteins, polysaccharides, and nucleic acids, lipids do not consist of repeating monomer units and therefore are not classified as polymers. Proteins are polymers because they are made up of amino acids linked in chains. Polysaccharides are polymers of monosaccharides, and nucleic acids are polymers of nucleotides, each consisting of a series of repeated structural units.
Why the other options are wrong
- A. Proteins are formed by long chains of amino acids, which are their monomers. Hence, they are polymers.
- B. Polysaccharides consist of repeated units of monosaccharides, making them polymers.
- D. Nucleic acids are formed from long chains of nucleotides, their monomers, thus classifying them as polymers.
Q2. Which of the following is the least likely to be involved in stabilizing the three dimensional folding of most proteins?
- A. Hydrogen Bonds
- B. Electrostatic Interaction
- C. Hydrophobic Interaction
- D. Ester Bonds✓
Explanation: Protein folding is the process by which a protein structure assumes its functional shape or conformation by allowing interaction between amino acids by various bond formations. All protein molecules are heterogeneous unbranched chains of amino acids. Different types of weak interactions hold the interacting segments together in protein. Hydrophobic interaction, H bonds, and electrostatic interactions are the weak ones and stabilize the tertiary structure of proteins, while ester bonds are covalent bonds and are least likely to be involved in stabilizing the three-dimensional folding of most proteins.
Why the other options are wrong
- A. Hydrogen bonds stabilize the secondary structure of proteins and is a weak one. Hydrogen bonds are weak because they involve partial charges from an electrostatic attraction, not a full sharing or transfer of electrons as in covalent or ionic bonds. These bonds form between molecules rather than within them, making them more transient and easily broken compared to the strong intramolecular bonds. However, despite being individually weak, a large number of hydrogen bonds acting together can create significant collective strength, as seen in the stability of DNA and proteins.
- B. Electrostatic interactions in proteins are forces between charged or polar amino acid side chains that influence protein structure, folding, stability, and function. These interactions include ion pairs (salt bridges) between oppositely charged amino acids, hydrogen bonds, and long-range electrostatic forces that attract or repel molecules, affecting protein-protein binding and overall activity.
- C. Hydrophobic interaction stabilize the tertiary structure of proteins and is a weak one.Hydrophobic interactions are a major force driving protein folding, where non-polar amino acid side chains cluster together in the protein's interior to minimize their contact with water.
Q3. Which one of the following statements is wrong?
- A. Uracil is a pyrimidine
- B. Glycine is a sulfur-containing amino acid✓
- C. Sucrose is a disaccharide
- D. Cellulose is a polysaccharide
Explanation: Option A: Uracil is a pyrimidine: This statement is correct. Uracil is one of the four nitrogenous bases found in RNA. It is a pyrimidine base, along with cytosine and thymine. Pyrimidines are a type of organic molecule characterized by a six-membered ring structure.Option B: Glycine is a sulfur-containing amino acid: This statement is incorrect. Glycine is the simplest amino acid and does not contain sulfur. It is the only amino acid that is not chiral and has a hydrogen atom as its side chain. Some amino acids, such as cysteine and methionine, do contain sulfur in their structures.Option C: Sucrose is a disaccharide: This statement is correct. Sucrose is a disaccharide composed of glucose and fructose units joined by a glycosidic bond. It is commonly known as table sugar and is found in various plant sources, including sugarcane and sugar beets.Option D: Cellulose is a polysaccharide: This statement is correct. Cellulose is a polysaccharide and one of the main structural components of plant cell walls. It is composed of long chains of glucose units linked by βglycosidic bonds. Cellulose is indigestible by humans but serves as a valuable dietary fiber
Why the other options are wrong
- A. This statement is correct. Uracil is one of the four nitrogenous bases found in RNA. It is a pyrimidine base, along with cytosine and thymine. Pyrimidines are a type of organic molecule characterized by a six-membered ring structure.
- C. This statement is correct. Sucrose is a disaccharide composed of glucose and fructose units joined by a glycosidic bond. It is commonly known as table sugar and is found in various plant sources, including sugarcane and sugar beets.
- D. This statement is correct. Cellulose is a polysaccharide and one of the main structural components of plant cell walls. It is composed of long chains of glucose units linked by βglycosidic bonds. Cellulose is indigestible by humans but serves as a valuable dietary fiber
Q4. The chitinous exoskeleton of arthropods is formed by the polymerisation of _?
- A. N-acetyl glucosamine✓
- B. Lipoglycans
- C. Keratin sulfate and chondroitin sulfate
- D. D glucosamine
Explanation: Option A: N-acetyl glucosamine is a monosaccharide and a derivative of glucose. It is a key component in the formation of the chitinous exoskeleton of arthropods. Chitin, which is the primary component of the exoskeleton, is a polymer of N-acetyl glucosamine. Option B: Lipoglycans are not directly involved in the formation of the chitinous exoskeleton of arthropods. They are a class of molecules that consist of both lipid (fat) and glycan (sugar) components. They have diverse functions in various biological systems but are not responsible for the structure of arthropod exoskeletons.Option C: Keratin sulfate and chondroitin sulfate are not involved in the formation of the chitinous exoskeleton of arthropods. Keratin sulfate is a component of certain tissues like hair and nails in vertebrates, while chondroitin sulfate is a major component of cartilage. Option D: D glucosamine is a form of glucosamine, which is a naturally occurring amino sugar. While glucosamine plays a role in the synthesis of certain molecules like glycosaminoglycans found in cartilage, it is not directly involved in the polymerization process of chitin to form the chitinous exoskeleton of arthropods.
Why the other options are wrong
- B. Lipoglycans are not directly involved in the formation of the chitinous exoskeleton of arthropods. They are a class of molecules that consist of both lipid (fat) and glycan (sugar) components. They have diverse functions in various biological systems but are not responsible for the structure of arthropod exoskeletons.
- C. Keratin sulfate and chondroitin sulfate are not involved in the formation of the chitinous exoskeleton of arthropods. Keratin sulfate is a component of certain tissues like hair and nails in vertebrates, while chondroitin sulfate is a major component of cartilage.
- D. D glucosamine is a form of glucosamine, which is a naturally occurring amino sugar. While glucosamine plays a role in the synthesis of certain molecules like glycosaminoglycans found in cartilage, it is not directly involved in the polymerization process of chitin to form the chitinous exoskeleton of arthropods.
Q5. Uridine, present only in RNA is a _.
- A. Nucleoside✓
- B. Nucleotide
- C. Purine
- D. Pyrimidine
Explanation: Option A: A nucleoside consists of a nitrogenous base (either a purine or a pyrimidine) bonded to a sugar molecule (ribose or deoxyribose) via a glycosidic bond. Uridine is a nucleoside because it contains the pyrimidine base uracil bonded to the sugar ribose.Option B: A nucleotide, on the other hand, is a nucleoside with one or more phosphate groups attached to the sugar molecule. Nucleotides are the building blocks of DNA and RNA, and they play crucial roles in various cellular processes. Uridine alone does not have any phosphate groups attached to it, so it is not considered a nucleotide.Option C: Purines are a class of nitrogenous bases that include adenine and guanine. Uridine contains the pyrimidine base uracil, not a purine base, so it is not a purine.Option D: Pyrimidines are a class of nitrogenous bases that include cytosine, thymine (in DNA), and uracil (in RNA). Uridine contains the pyrimidine base uracil, making it a pyrimidine.
Why the other options are wrong
- B. A nucleotide, on the other hand, is a nucleoside with one or more phosphate groups attached to the sugar molecule. Nucleotides are the building blocks of DNA and RNA, and they play crucial roles in various cellular processes. Uridine alone does not have any phosphate groups attached to it, so it is not considered a nucleotide.
- C. Purines are a class of nitrogenous bases that include adenine and guanine. Uridine contains the pyrimidine base uracil, not a purine base, so it is not a purine.
- D. Pyrimidines are a class of nitrogenous bases that include cytosine, thymine (in DNA), and uracil (in RNA). Uridine contains the pyrimidine base uracil, making it a pyrimidine.
Q6. The given diagrammatic representation shows one of the categories of small molecular weight organic compounds in the living tissues. Identify the category is shown and the blank component “X” in it.
- A. Cholesterol, Guanine
- B. Amino acid: NH-2
- C. Nucleotide: Adenine
- D. Nucleoside: Uracil✓
Explanation: The structure depicted in the diagram illustrates a pentose sugar (ribose) attached to uracil, which classifies it as a nucleoside. Nucleosides consist of a sugar and a nitrogenous base but lack a phosphate group. The other options are incorrect for the following reasons:Option A: Cholesterol is a sterol and not related to nucleic acids.Option B: Amino acids are building blocks of proteins, not nucleic acids.Option C: Nucleotides must contain a phosphate group; since this structure does not, it cannot be classified as a nucleotide.Thus, the correct identification of the structure is a nucleoside with uracil.
Why the other options are wrong
- A. This option is incorrect because cholesterol is a sterol and not classified as a nucleic acid component. Guanine is a nitrogenous base, but the structure shown does not represent it.
- B. This option is incorrect as amino acids are not nucleic acid components. The structure shown indicates a sugar and base, not an amino acid.
- C. This option is incorrect because the structure depicted lacks a phosphate group, which is essential for a nucleotide. The correct base in the diagram is uracil, not adenine.
Q7. Which one of the following biomolecules is correctly characterized?
- A. Lecithin a phosphorylated glyceride found in the cell membrane.✓
- B. Palmitic acid an unsaturated fatty acid with 18 carbon atoms.
- C. Adenylic acid adenosine with a glucose phosphate molecule.
- D. Alanine amino acid contains an amino group and an acidic group anywhere in the molecule.
Explanation: Lecithin is a triglyceride lipid where one fatty acid is replaced by phosphoric acid, which is linked to an additional nitrogenous group called choline. It is a common membrane lipid. It is an amphipathic phospholipid, having both hydrophilic polar and hydrophobic nonpolar groups. The hydrocarbon chains of two fatty acids function as hydrophobic nonpolar tails, whereas the phosphate and choline behave as a hydrophilic polar head group of the molecule. Palmitic acid is a saturated fatty acid (as it does not possess double bonds in its carbon chain) and contains 16 carbon atoms with formula C 16 H 32 O2. Adenylic acid or adenosine monophosphate is a nucleotide formed by the union of adenine (nitrogenous base), ribose (pentose sugar), and phosphate. It is formed through phosphorylation of nucleoside as phosphate combines with sugar molecule at its 5 carbon atom. Amino acids are organic acids with a carboxylic group (–COOH) having an amino group (– NH 2) generally attached to a carbon or carbon next to a carboxylic group. Alanine is a nonpolar and neutral amino acid having one methyl group and having an amino group attached to the carbon next to the carboxylic group.
Why the other options are wrong
- B. Palmitic acid is a saturated fatty acid (as it does not possess double bonds in its carbon chain) and contains 16 carbon atoms with formula C 16 H 32 O2.
- C. Adenylic acid or adenosine monophosphate is a nucleotide formed by the union of adenine (nitrogenous base), ribose (pentose sugar), and phosphate. It is formed through phosphorylation of nucleoside as phosphate combines with sugar molecule at its 5 carbon atom.
- D. Amino acids are organic acids with a carboxylic group (–COOH) having an amino group (– NH 2) generally attached to a carbon or carbon next to a carboxylic group. Alanine is a nonpolar and neutral amino acid having one methyl group and having an amino group attached to the carbon next to the carboxylic group.
Q8. Carbohydrates are commonly found as starch in plants storage organs. Which of the following five properties of starch make it useful as a storage material?(1) Easily translocated(2) Chemically nonreactive(3) Easily digested by animals(4) Osmotically inactive(5) Synthesized during photosynthesisThe useful properties are?
- A. (1), (3) and (5)
- B. (1) and (5)
- C. (2) and (3)
- D. (2) and (4)✓
Explanation: Starch is the major storage carbohydrate of plants. In most plant species it is accumulated in the chloroplast of leaves, whereas in storage organs it accumulates in the amyloplast as reserve starch. It is the osmotically inactive form of photosynthetic product and is a hexosan polysaccharide made of a large number of glucose units so it is chemically non-reactive.
Why the other options are wrong
- A. 1st,3rd and 5th properties don't tell about its storage function.Starch is not easily translocated; it is stored where it is made or moved to specific storage organs as a soluble sugar (sucrose) first.While it is digestible by animals, this is a property useful for animals, not the plant itself in terms of storage function within the plant's cells.It is synthesized during photosynthesis, but the process of synthesis is not the property that makes it a good storage material.
- B. 1st and 5th properties are irrelevant to its storage function.Starch is not easily translocated; it is stored where it is made or moved to specific storage organs as a soluble sugar (sucrose) first.It is synthesized during photosynthesis, but the process of synthesis is not the property that makes it a good storage material.
- C. 3rd property doesn't tell anything about its storage function.While it is digestible by animals, this is a property useful for animals, not the plant itself in terms of storage function within the plant's cells.
Q9. About 98 percent of the mass of every living organism is composed of just six elements including carbon, hydrogen, nitrogen, oxygen and :
- A. Carbon and Sulfur
- B. Phosphorus and Calcium✓
- C. Sulfur and Magnesium
- D. Magnesium and Sodium
Explanation: The correct answer is Phosphorus and Calcium. In the context of biological molecules, the six elements that make up about 98% of the mass of living organisms are carbon (C), hydrogen (H), nitrogen (N), oxygen (O), phosphorus (P), and sulfur (S). Although phosphorus is included, calcium is more of a structural element in bones and is not one of the primary elements constituting the majority of living organism mass.Option A (Carbon and Sulfur) is incorrect because, while carbon is essential, sulfur is not one of the six key elements. Option C (Sulfur and Magnesium) is incorrect as magnesium is a trace element and not one of the primary six. Option D (Magnesium and Sodium) is also incorrect for similar reasons: both are trace elements and do not account for the bulk of the mass of living organisms.
Why the other options are wrong
- A. While carbon is one of the primary elements, sulfur is not among the six major elements that constitute most of the mass of living organisms.
- C. Sulfur is considered one of the major elements, but magnesium is classified as a trace element and is not part of the primary six elements.
- D. Both magnesium and sodium are important but are classified as trace elements and do not comprise the bulk of the mass of living organisms.
Q10. The major role of minor elements inside living organisms is to act as?
- A. Cofactors of enzymes✓
- B. Building blocks of important amino acids
- C. Constituent of hormones
- D. Binder of cell structure
Explanation: Minor elements are those which are required in the quantity of less than milligram/gram of dry matter, but they are essential for proper growth and development of an organism e.g., Cl, Mn, B, Zn, Cu, Mo, etc. These elements work as nonprotein cofactor in enzymes e.g., Zn, Cu, etc. They also take part in oxidation-reduction reactions, e.g., Cu, with variable valency. Chloride ion enhances the activity of salivary amylase. Zinc is required for the activity of carbonic anhydrase and alcohol dehydrogenase, etc.
Why the other options are wrong
- B. Minor elements do not form building blocks of amino acids. So this option is incorrect because in building amino acids major elements are included.
- C. Hormones are glycoproteins, having sugar attached with proteins. Therefore, minor elements are not constituents of hormones.
- D. Minor elements are not binder of cell structure. Elements like calcium are used as binder of cells which are major elements. So this option is not correct.
Q11. Which of the following is a reducing sugar?
- A. Galactose✓
- B. Gluconic acid
- C. B-methyl galactoside
- D. Sucrose
Explanation: All those sugars which have free aldehyde or ketone group are called reducing sugars. These are able to reduce cupric ions (Cu+2) into cuprous ions (Cu+). Sucrose and starch are non-reducing sugars.
Why the other options are wrong
- B. These are not pure carbohydrates. Pure carbohydrates like monosaccharides, oligosaccharides, and polysaccharides are classified as reducing and non-reducing sugar.
- C. These are not pure carbohydrates. Pure carbohydrates like monosaccharides, oligosaccharides, and polysaccharides are classified as reducing and non-reducing sugar.
- D. Since, sucrose is a disaccharide which is basically used as a transport sugar so, sucrose is non-reducing sugar making this option incorrect.
Q12. Which of the following have carbohydrates as a prosthetic group?
- A. Glycoprotein✓
- B. Chromoprotein
- C. Lipoprotein
- D. Nucleoprotein
Explanation: Glycoproteins are proteins that contain sugars like carbohydrates as a prosthetic group. In most glycoproteins, the linkage is between asparagine and N-acetyl D-glucosamine. Some glycoproteins are immunoglobulins, membrane proteins, and muscle proteins. Lipoproteins are protein complexed with lipids like triglycerides, phospholipids, etc. Nucleoproteins are proteins associated with nucleic acids and chromoproteins are proteins associated with pigments e.g., cytochrome, phytochrome.
Why the other options are wrong
- B. Chromoproteins are proteins associated with pigments, e.g., cytochrome, phytochrome.
- C. Lipoproteins are protein complexed with lipids like triglycerides, phospholipids, etc
- D. Nucleoproteins are proteins associated with nucleic acids. So they don't have carbohydrates. So, this option is not correct.
Q13. Cellulose, the most important constituent of the plant cell wall, is made up of:
- A. Branched-chain of glucose molecules linked by B-1,4 glycosidic bonds in straight-chain and Alpha1,6 glycosidic bonds at the site of branching
- B. Unbranched chain of glucose molecules linked by b1, 4 glycosidic bond✓
- C. Branched-chain of glucose molecules linked by Alpha-1,6 glycosidic bonds at the site of branching
- D. Unbranched chain of glucose molecules linked by a1, 4 glycosidic bond
Explanation: Cellulose is the most abundant carbohydrate. Cellulose molecule is composed of 1600 to 6000 glucose molecules joined together. Those polymers form long-twisting macromolecules of cellulose. The chains are unbranched and linear. The successive glucose residues are joined together by B-1,4 linkages.
Why the other options are wrong
- A. Unbranded chain of glucose molecules linked by B-1,4 glycosidic linkage.
- C. Unbranded chain of glucose molecules linked by B-1,4 glycosidic linkage.
- D. Unbranded chain of glucose molecules linked by B-1,4 glycosidic linkage.
Q14. Which of the following nucleotide sequence contain 3 pyrimidine bases?
- A. GCUAGACAAU
- B. GATCAATGC
- C. UAGCGGUAA✓
- D. Both A and C
Explanation: In DNA and RNA, these bases form hydrogen bonds with their complementary purines. Thus, in DNA, the purines adenine (A) and guanine (G) pair up with the pyrimidines thymine (T) and cytosine (C), respectively.Normally the Nucleotides contain Nitrogenous base,pentose sugar,phosphate groups.
Why the other options are wrong
- A. Pyrimidine bases are of three types, i.e., cytosine (C), thymine (T) and uracil (U). Thymine is only found in DNA, while the uracil is only found in RNA. Thus, this option is incorrect.
- B. Pyrimidine bases are of three types, i.e., cytosine (C), thymine (T) and uracil (U). Thymine is only found in DNA, while the uracil is only found in RNA. Thus, this option is incorrect.
- D. Pyrimidine bases are of three types, i.e., cytosine (C), thymine (T) and uracil (U). Thymine is only found in DNA, while the uracil is only found in RNA. Thus, this option is incorrect.
Q15. How many water molecules will be released upon the formation of a trisaccharide?
- A. 1
- B. 2✓
- C. 3
- D. 4
Explanation: To form a trisaccharide, three monosaccharides are linked together. Each link between two monosaccharides is a glycosidic bond, which releases one water molecule. Thus, two glycosidic bonds are formed to link three monosaccharides, releasing two water molecules in total. Option B is correct because it reflects the correct number of water molecules released during this process. Options A, C, and D are incorrect because they represent the number of water molecules released when forming disaccharides, tetrasaccharides, and pentasaccharides, respectively.
Why the other options are wrong
- A. Incorrect. One water molecule is released for each glycosidic bond. A single glycosidic bond forms a disaccharide, not a trisaccharide.
- C. Incorrect. Releasing three water molecules corresponds to forming a tetrasaccharide, which involves four monosaccharides and three glycosidic bonds.
- D. Incorrect. Four water molecules would indicate the formation of a pentasaccharide, requiring five monosaccharides and four glycosidic bonds.
Q16. How many carbon atoms are present inside the ring of fructose?
- A. 6
- B. 4✓
- C. 5
- D. 3
Explanation: Frustose is an keto hexose, it has keto group on carbon no 2 so when it forms an Ring the oxygen from carbon no 2 forms an bond with carbon no 5 and form ring, due to this bonding there's only 4 carbon atoms inside the ring while 2 carbon atoms remains outside the ring.Four carbon atoms are present inside the ring of fructose, while two carbon atoms are present outside of the ring.
Why the other options are wrong
- A. This option is incorrect, as 4 carbon atoms are present inside the ring of fructose.
- C. This option is incorrect, as 4 carbon atoms are present inside the ring of fructose.
- D. This option is incorrect, as 4 carbon atoms are present inside the ring of fructose.
Q17. Which of the following is an amino acid and part of phospholipids?
- A. Serine✓
- B. Choline
- C. Ethanolamine
- D. Aspartic acid
Explanation: Serine and aspartic acids are examples of amino acids, while choline and ethanolamine are Nz-containing bases. Serine can be a constituent of phospholipids and can act as a nitrogenous base.
Why the other options are wrong
- B. Choline is not an amino acid, but it is a crucial component of phospholipids. It's a quaternary ammonium salt containing a hydrophilic head, making it important for the structure of phosphatidylcholine, a common phospholipid in cell membranes.
- C. Ethanolamine is not an amino acid, but like choline, it is a vital part of phospholipids. It contributes to the structure of phosphatidylethanolamine, another phospholipid in cell membranes.
- D. Aspartic acid is an amino acid, but is not typically found as a component of phospholipids.
Q18. Myelin sheath of neuron is composed of:
- A. Sphingolipids✓
- B. Ethanolamine
- C. Choline
- D. Waxes
Explanation: The myelin sheath is an essential part of the nervous system, acting as an insulating layer around nerve fibers to facilitate efficient transmission of electrical signals. It is primarily composed of lipids, with sphingolipids being a major component. Sphingomyelin, in particular, is a crucial sphingolipid in the myelin sheath, comprising a combination of a fatty acid, sphingosine, and a phosphate group. This structure allows it to effectively insulate nerve fibers. Other options, such as ethanolamine, choline, and waxes, play different roles in lipid metabolism or cellular functions but do not form the myelin sheath.
Why the other options are wrong
- B. This option is incorrect. Ethanolamine is a component of phospholipids like phosphatidylethanolamine but is not a primary constituent of the myelin sheath. It plays a role in lipid synthesis but is not specifically associated with myelin formation.
- C. This option is incorrect. While choline is involved in the synthesis of phosphatidylcholine, a lipid found in cell membranes, it is not a major component of the myelin sheath. Choline is more directly associated with neurotransmitter production rather than myelin structure.
- D. This option is incorrect. Waxes are a type of lipid but are not involved in the composition of the myelin sheath. They are primarily used for water resistance and protection in various organisms, not as components of neural insulation.
Q19. How many amino acids are present in the cell?
- A. 170✓
- B. 20
- C. 25
- D. 3000
Explanation: About 170 types of amino acids have been found to occur in cells and tissues. Of these, about 25 are constituents of proteins. Most of the proteins are, however, made of 20 types of amino acids.
Why the other options are wrong
- B. About 170 types of amino acids have been found to occur in cells and tissues. Of these, about 25 are constituents of proteins. Most of the proteins are, however, made of 20 types of amino acids.
- C. About 170 types of amino acids have been found to occur in cells and tissues. Of these, about 25 are constituents of proteins. Most of the proteins are, however, made of 20 types of amino acids.
- D. About 170 types of amino acids have been found to occur in cells and tissues. Of these, about 25 are constituents of proteins. Most of the proteins are, however, made of 20 types of amino acids.
Q20. A protein having secondary structure possesses:
- A. Hydrogen bonding
- B. Peptide bond
- C. Disulfide bond
- D. Both A and B✓
Explanation: The correct answer is 'Both A and B' because proteins with a secondary structure rely on hydrogen bonding for the stabilization of structures like alpha-helices and beta-sheets. Peptide bonds, while important, are relevant to the primary structure, linking amino acids in a linear chain. Disulfide bonds, on the other hand, contribute to tertiary and quaternary structures, not secondary.
Why the other options are wrong
- A. This option is correct. Hydrogen bonds are critical for stabilizing the secondary structures of proteins, such as alpha-helices and beta-sheets. In an alpha-helix, these bonds occur between the backbone atoms of the polypeptide chain, specifically between the carbonyl oxygen of one amino acid and the amide hydrogen of another, several residues away. Beta-sheets are also stabilized by hydrogen bonds between strands.
- B. This option is incorrect in terms of secondary structure. While peptide bonds are crucial for linking amino acids in a polypeptide chain (primary structure), they do not contribute to the stabilization of secondary structures like alpha-helices and beta-sheets.
- C. This option is incorrect. Disulfide bonds are involved in stabilizing the tertiary and quaternary structures of proteins by forming covalent links between cysteine residues. They do not play a role in the formation of secondary structures.
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