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Sindh Mdcat Exclusive Course Chemistry Aldehydes And Ketones — Solved Past Paper with Answers

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Q1. Which of the following will not undergo aldol condensation?

  • A. Acetaldehyde
  • B. Propanaldehyde
  • C. Formaldehyde
  • D. Trideuteroacetaldehyde

Explanation: The aldehydes that have alpha hydrogen atoms undergo aldol condensation reaction

Why the other options are wrong
  • A. As the alpha hydrogen is present so it can undergo aldol condensation reactions.
  • B. As the alpha hydrogen is present so it can undergo aldol condensation reactions.
  • D. As the alpha hydrogen is present so it can undergo aldol condensation reactions.

Q2. Which one of the following reagents is used to distinguish between aldehydes and ketones?

  • A. Alkaline Iodine
  • B. Tollen’s Reagent
  • C. Bromine
  • D. 2, 4 DNPH

Explanation: The Tollens' test is a reaction that is used to distinguish aldehydes from ketones, as aldehydes are able to be oxidized into a carboxylic acid while ketones cannot.Alkaline iodine is used in the iodoform test. When Iodine and sodium hydroxide are added to a compound that contains either a methyl ketone or a secondary alcohol with a methyl group in the alpha position, a pale yellow precipitate of iodoform or triiodomethane is formed. It can be used to identify aldehydes or ketones.A solution of bromine in CH2CL2 is used to either test for unsaturation or to check the ability to be oxidized for example in aldehydes. Bromine solution is naturally orange and when consumed in oxidation, it becomes colourless.2, 4 DNPH is used to detect ketones and aldehydes. A positive test is signalled by the formation of a yellow, orange or red precipitate of the dinitrophenylhydrazone.

Why the other options are wrong
  • A. Alkaline iodine is used in the iodoform test, which identifies compounds containing a methyl ketone group or secondary alcohols with a methyl group in the alpha position, but it does not distinguish between aldehydes and ketones.
  • C. Bromine is used to test for unsaturation or oxidation, such as in the case of aldehydes, but it is not specific enough to distinguish between aldehydes and ketones.
  • D. 2, 4 DNPH is used to detect both aldehydes and ketones through the formation of hydrazones, resulting in a yellow, orange, or red precipitate, but it does not differentiate between them.

Q3. Ketones can be made by oxidation of:

  • A. Aldehydes
  • B. Primary Alcohols
  • C. Secondary Alcohols
  • D. Tertiary Alcohols

Explanation: Option A; aldehydes oxidize into carboxylic acids.Option B; primary alcohols oxidize into aldehydes and then to carboxylic acids.Option C; secondary alcohols oxidize into ketones.Option D; tertiary alcohols are resistant to oxidation.

Why the other options are wrong
  • A. Option A; aldehydes oxidize into carboxylic acids.
  • B. Option B; primary alcohols oxidize into aldehydes and then to carboxylic acids.
  • D. Option D; tertiary alcohols are resistant to oxidation.

Q4. Phenylmethyl ketone can be converted into ethyl benzene in one step by using:

  • A. LiAlH4
  • B. Zn(Hg)-HCl
  • C. NaBH4
  • D. CH3MgI

Explanation: The reaction is Clemmensen reduction. The reaction of aldehydes and ketones with zinc amalgam (Zn/Hg alloy) in concentrated hydrochloric acid, which reduces the aldehyde or ketone to a hydrocarbon, is called Clemmensen reduction.

Why the other options are wrong
  • A. LiAlH4 would reduce the ketone group to an alcohol, but it would not introduce the ethyl group, so this option is incorrect.
  • C. NaBH4 would not introduce the ethyl group required to convert phenylmethyl ketone into ethyl benzene. Therefore, this option is incorrect.
  • D. CH3MgI is a Grignard reagent, commonly used to introduce an alkyl group into various organic compounds. While it could potentially react with phenylmethyl ketone, it would add a methyl group (CH3) rather than an ethyl group (C2H5). Therefore, this option is incorrect.

Q5. Which of the following does not give iodoform test?

  • A. Ethanol
  • B. Ethanal
  • C. Acetophenone
  • D. Benzophenone

Explanation: The reaction of iodine and base with methyl ketones is called the "iodoform test". It is used to probe the presence of a methyl ketone. However, Benzenophenone is a phenyl ketone and does not contain this group giving a negative test.

Q6. Why is water added after the reduction process of aldehyde and ketone with LiAlH4?

  • A. Because water reacts violently with LiAlH4
  • B. Because water will protonate LiAlH4
  • C. Because water inhibits the process
  • D. Because it will result to alkenes

Explanation: This is the correct option. LiAlH₄ is a highly reactive reducing agent. When water is added to a reaction mixture containing LiAlH₄, it reacts vigorously, leading to the release of hydrogen gas and the formation of aluminum hydroxide. Therefore, water is typically added after the reduction to safely quench the reaction and convert the reaction intermediates into alcohols.

Why the other options are wrong
  • B. This option is misleading. While water can protonate the aluminum-hydride species, this is not the primary reason for adding water after the reduction. The concern is more about the violent reaction that occurs when water contacts LiAlH₄ rather than protonation.
  • C. This option is not correct. Water does not inhibit the reduction process itself; rather, it is used to terminate the reaction after the reduction has taken place. The reduction of aldehydes and ketones to alcohols using LiAlH₄ is complete before water is added.
  • D. This option is incorrect. The addition of water after the reduction does not lead to the formation of alkenes. Instead, it converts the reaction intermediates (alkoxides) into alcohols. Alkenes are typically formed through dehydration reactions, which is not relevant to this process involving LiAlH₄.

Q7. Which of the following reaction takes place when acetone reacts with HCN ?

  • A. Electrophilic addition
  • B. Nucleophilic elimination
  • C. Nucleophilic addition
  • D. Electrophilic addition

Explanation: HCN provides a nucleophile (CN⁻) that attacks the electrophilic carbonyl carbon of acetone. This forms a tetrahedral alkoxide intermediate. Protonation gives the cyanohydrin, a classic nucleophilic addition product.

Why the other options are wrong
  • A. This option is incorrect because electrophilic addition typically involves an electrophile adding to a nucleophile, which is not the case here. The reaction between acetone and HCN involves the nucleophile (CN⁻) attacking the electrophilic carbon of the carbonyl group.
  • B. This option is incorrect as nucleophilic elimination refers to a mechanism where a nucleophile displaces a leaving group, which does not apply to the reaction of acetone with HCN.
  • D. This option is incorrect for the same reason as the first option. The reaction involves nucleophilic attack, not electrophilic addition.

Q8. The common name for 2-propanone is:

  • A. Formaldehyde
  • B. Acetone
  • C. Benzaldehyde
  • D. Acetaldehyde

Explanation: 2-Propanone is the systematic IUPAC name for the simplest ketone. Its widely used common name is acetone.

Why the other options are wrong
  • A. Formaldehyde (HCHO) is the simplest aldehyde, not a ketone. It is a colorless gas with a strong odor and is used in various applications, including as a preservative. However, it is not related to 2-propanone.
  • C. Benzaldehyde (C7H6O) is an aromatic aldehyde with a distinct almond-like odor. While it is an important organic compound, it is structurally different from 2-propanone and not the correct answer.
  • D. Acetaldehyde (C2H4O) is another aldehyde, known for its use in the production of acetic acid. Like formaldehyde and benzaldehyde, it is not a ketone and does not correspond to 2-propanone.

Q9. Which type of reaction takes place when a carbonyl compound is treated with a mixture of NaCN and an acid?

  • A. Electrophilic addition reaction
  • B. Substitution reaction
  • C. Nucleophilic addition reaction
  • D. Displacement reaction

Explanation: The given scenario is an example of a nucleophilic addition reaction, as the reactant, CN- is a nucleophile which adds across the carbonyl bond.Option A describes reactions undergone by alkenes, where an electrophile is added across the carbon-carbon double bond.Option B describes a reaction where one group of atoms is replaced by another group of atoms, but this is not the case here.Option D describes a reaction in which one element is replaced by another element in a compound.

Why the other options are wrong
  • A. Carbonyl compounds (aldehydes and ketones) do not undergo electrophilic addition because the carbonyl carbon is electron-deficient, making it susceptible to nucleophiles, not electrophiles.
  • B. In a substitution reaction, one atom or group is replaced by another. However, in this case, the cyanide ion (CN⁻) adds to the carbonyl carbon rather than replacing a group.
  • D. Displacement reactions typically involve the replacement of one element by another, which does not happen in this reaction.

Q10. The general formula for an aldehyde is:

  • A. R-OH
  • B. R-COOH
  • C. R-CO-R
  • D. R-X
  • E. R-CHO

Explanation: Aldehydes and ketones have a carbonyl group (C=O) as a functional group. A ketone has two alkyl or aryl groups attached to the carbonyl carbon (RCOR’). The simplest ketone is acetone, which has two methyl groups attached to the carbonyl carbon (CH3COCH3).An aldehyde is similar to a ketone, except that instead of two side groups connected to the carbonyl carbon, they have at least one hydrogen (RCOH or R-CHO). The simplest aldehyde is formaldehyde (HCOH), as it has two hydrogens connected to the carbonyl group. All other aldehydes have one hydrogen bonded to the carbonyl group, like the simple molecule acetaldehyde, which has one hydrogen and one methyl group (HCOCH3).The carbonyl carbon in both aldehydes and ketones is electrophilic, meaning that it has a dipole due to the electronegativity of the attached oxygen atom. This makes the carbonyl carbon an ideal target for nucleophiles in a nucleophilic addition reaction. During this reaction, the nucleophile, or electron donor, attacks the carbonyl to form the tetrahedral intermediate. The negatively charged oxygen accepts a hydrogen ion to form a hydroxyl group.Typically, nucleophiles possess a negative charge or lone pair on a heteroatom, which can take several forms (OH-, RO-, CN-, R3C-, RNH2, ROH). For primary amines (RNH2), the reaction does not stop at the formation of the tetrahedral intermediate with a hydroxyl group. Rather, an elimination reaction occurs that produces a double-bonded carbon and nitrogen functional group known as an imine. Understanding the reactions that aldehydes and ketones can undergo provides a way to differentiate between these similar organic compounds.

Why the other options are wrong
  • A. Option A is wrong as R-OH is the general formula of alcohol.
  • B. Option B is wrong R-COOH is the general formula of carboxylic acid.
  • C. Option C is wrong as R-CO-R is the general formula of ketone.
  • D. Option D is wrong as R-X is the general formula of alkyl halides.

Q11. Phenylmethyl ketone can be converted into ethyl benzene in one step by using:

  • A. LiAlH4
  • B. Zn(Hg)-HCl
  • C. NaBH4
  • D. CH3MgI

Explanation: The reaction is Clemmensen reduction. The reaction of aldehydes and ketones with zinc amalgam (Zn/Hg alloy) in concentrated hydrochloric acid, which reduces the aldehyde or ketone to a hydrocarbon, is called Clemmensen reduction.

Why the other options are wrong
  • A. LiAlH4 would reduce the ketone group to an alcohol, but it would not introduce the ethyl group, so this option is incorrect.
  • C. NaBH4 would not introduce the ethyl group required to convert phenylmethyl ketone into ethyl benzene. Therefore, this option is incorrect.
  • D. CH3MgI is a Grignard reagent, commonly used to introduce an alkyl group into various organic compounds. While it could potentially react with phenylmethyl ketone, it would add a methyl group (CH3) rather than an ethyl group (C2H5). Therefore, this option is incorrect.

Q12. Treatment of propionaldehyde with Dil. the NaOH solution gives:

  • A. CH3 CH2COOCH2C2H5
  • B. CH3 CH2 CHOH CH2 CH2 CHO
  • C. CH3 CH2 CH (OH) CH(CH3) CHO
  • D. CH3 CH2 COCH2 CH2 CHO

Explanation: When propionaldehyde (CH3CH2CHO) reacts with a dilute NaOH (sodium hydroxide) solution, it undergoes a nucleophilic addition reaction known as an aldol condensation. In this reaction, the aldehyde group of propionaldehyde is attacked by the hydroxide ion (OH-) from the NaOH solution.

Why the other options are wrong
  • A. This compound is an ester formed by the reaction of propionic acid with ethanol, not a product of the reaction between propionaldehyde and NaOH.
  • B. This compound is a dimer formed by the reaction of two molecules of propionaldehyde, not the product of the reaction with NaOH.
  • D. This compound is a linear ketone formed by the condensation of two molecules of propionaldehyde, not the product of the reaction with NaOH.

Q13. Which of the following reactions is NOT shown by ketones?

  • A. Reaction with HCN
  • B. Reaction with Fehling solution
  • C. Reaction with NaHSO3
  • D. Reaction with 2,4-dinitrophenyl-hydrazine

Explanation: Fehling's solution is a mixture of Rochelle salt (blue color) and copper sulphate (chso4). It is an oxidizing agent which is used to diffentiate between aldehydes and ketones. Ketones generally do not react with Fehling's solution. A red colored precipetate is formed when Fehling's solution is reacted with aldehyde.Reaction with HCN:Ketones when added with HCN give hydroxynitriles. HCN will be added with the carbon-oxygen double bond to produce hydroxynitriles.Rxn with NaHso3:Ketones generally get added with NaHSO3 by the process of nucleophilic addition.Rxn with 2,4 dinitrophenol hydrazine:Aldehydes and ketones on reaction with this generally form orange/yellow precipitates.

Why the other options are wrong
  • A. Ketone reacts readily with HCN, hence incorrect option.Fehling's solution is a mixture of Rochelle salt (blue color) and copper sulphate (chso4). It is an oxidizing agent which is used to diffentiate between aldehydes and ketones. Ketones generally do not react with Fehling's solution.A red colored precipetate is formed when Fehling's solution is reacted with aldehyde.Reaction with HCN:Ketones when added with HCN give hydroxynitriles. HCN will be added with the carbon-oxygen double bond to produce hydroxynitriles.Rxn with NaHso3:Ketones generally get added with NaHSO3 by the process of nucleophilic addition.Rxn with 2,4 dinitrophenol hydrazine:Aldehydes and ketones on reaction with this generally form orange/yellow precipitates.
  • C. Ketones can react with NaHSO3 by nucleophillic substitution reaction, hence incorrect.
  • D. Ketone reacts with 2,4 dinitrophenyl-hydrazine to give orange/red precipitates, hence also incorrect.

Q14. Which of the following reagent is used to separate and purify carbonyl and non carbonyl compounds?

  • A. HCN
  • B. BrMgCH3
  • C. NaHSO3
  • D. H2O

Explanation: Sodium bisulfite reacts selectively with carbonyl compounds to form stable, crystalline bisulfite adducts. Non-carbonyl compounds do not react, allowing easy separation. Regenerating the carbonyl from the adduct gives purified carbonyl compounds.

Why the other options are wrong
  • A. When a saturated solution of sodium hydrogen sulphite also called sodium bisulphite is mixed with an impure carbonyl compound, it produces an additional compound with white crystals. That is why sodium bisulphite is used for purification of carbonyl compounds from non carbonyl compounds.
  • B. When a saturated solution of sodium hydrogen sulphite also called sodium bisulphite is mixed with an impure carbonyl compound, it produces an additional compound with white crystals. That is why sodium bisulphite is used for purification of carbonyl compounds from non carbonyl compounds.
  • D. When a saturated solution of sodium hydrogen sulphite also called sodium bisulphite is mixed with an impure carbonyl compound, it produces an additional compound with white crystals. That is why sodium bisulphite is used for purification of carbonyl compounds from non carbonyl compounds.

Q15. Ketone reacts with Grignard reagent to form _ in acidic media?

  • A. Tertiary alcohol
  • B. Isopropyl alcohol
  • C. Primary alcohol
  • D. Carboxylic acid

Explanation: The correct answer is a tertiary alcohol. When a ketone, which has a carbonyl group (C=O) bonded to two carbon-containing groups, reacts with a Grignard reagent, the carbonyl carbon gets attacked. This nucleophilic addition forms an alkoxide intermediate. Upon protonation in acidic conditions, the alkoxide converts into an alcohol. As the carbonyl carbon is already attached to two other carbon groups, the alcohol formed is tertiary.Isopropyl alcohol is incorrect as it forms from acetaldehyde, not a ketone. A primary alcohol is produced from formaldehyde, and a carboxylic acid forms from carbon dioxide with Grignard reagents, making these options irrelevant for this reaction.

Why the other options are wrong
  • B. Isopropyl alcohol is a secondary alcohol that forms from the reaction of acetaldehyde with a Grignard reagent, not a ketone. Hence, this option is incorrect for the reaction involving a ketone.
  • C. A primary alcohol results from the reaction of formaldehyde with a Grignard reagent. Since a ketone is involved in the given reaction, this option is incorrect.
  • D. Carboxylic acids are formed when carbon dioxide reacts with a Grignard reagent. This reaction does not involve ketones, so this option is incorrect.

Q16. The following reaction is an example of:

  • A. Alkylation of benzene
  • B. Acylation of benzene
  • C. Oxidation of benzene
  • D. Halogenation of benzene
  • E. Both A and B

Explanation: Since the acyl group is added to the benzene as a result of this reaction process we can say that it is an acylation of benzene.

Why the other options are wrong
  • A. This involves adding an alkyl group to benzene, not an acyl group.
  • C. Oxidation would change the oxidation state of the benzene or its substituents, not add an acyl group.
  • D. Halogenation involves adding a halogen, not an acyl group.
  • E. Only the acylation of benzene is occurring, not alkylation.

Q17. Carbonyl group undergoes:

  • A. Electrophilic addition reaction
  • B. Nucleophilic addition reaction
  • C. Electrophilic substitution reaction
  • D. Nucleophilic substitution reaction

Explanation: t, the carbonyl group (C=O) undergoes nucleophilic addition reactions rather than electrophilic addition reactions. In a nucleophilic addition reaction, a nucleophile (electron-rich species) attacks the electrophilic carbon atom of the carbonyl group, leading to the formation of a new bond and subsequent addition of the nucleophile. One of the most common nucleophilic addition reactions involving carbonyl compounds is the reaction with a nucleophilic reagent, such as a primary or secondary amine. The lone pair of electrons on the nitrogen atom of the amine attacks the carbon atom of the carbonyl group, resulting in the formation of an imine or a Schiff base. Another important nucleophilic addition reaction is the reaction of carbonyl compounds with nucleophilic organometallic reagents, such as Grignard reagents or organolithium compounds. The nucleophile attacks the electrophilic carbon, breaking the carbon-oxygen double bond and forming a new carbon-carbon bond. This reaction is commonly used to synthesize alcohols, as the addition of water or an alcohol source after the initial reaction generates the alcohol product. Other nucleophiles, such as hydride ions (H-) or cyanide ions (CN-), can also add to the carbonyl carbon, resulting in the formation of alcohols (via reduction) or cyanohydrin derivatives, respectively. These are just a few examples of nucleophilic addition reactions involving the carbonyl group. The specific reaction conditions and mechanisms can vary depending on the nature of the carbonyl compound and the nucleophile used. In a carbonyl group, -CHO, the carbon is double bonded to an oxygen which is electronegative and so it pulls electron density, acquiring a partial negative charge. At the same time, the carbon acquires a partial positive charge. Nucleophiles are electron donors so they prefer the electron-deficient carbon centre and attack it. Furthermore, carbonyls undergo addition reactions because the double bond between Carbon and Oxygen can break, setting an electron free to bond with another group, the nucleophile. We can therefore establish that carbonyls (ketones and aldehydes) undergo nucleophilic addition reactions, hence, option B is correct.

Why the other options are wrong
  • A. Option A is incorrect because electrophiles cannot attack the partial positive carbon, as they are repelled by it and too much energy would be required for such a reaction to happen.
  • C. Option C is incorrect because electrophiles cannot attack the partial positive carbon, as they are repelled by it and too much energy would be required and because they do not undergo substitution because carbon is sp2 hybridised and has a double bond that can break to accommodate the nucleophile. That is why carbonyls undergo addition and not substitution.
  • D. Option D is incorrect because carbon is sp2 hybridised and has a double bond that can break to accommodate the nucleophile. That is why carbonyls undergo addition and not substitution.

Q18. What is the color of the precipitate when Brady’s reagent is used to test a benzaldehyde?

  • A. Green
  • B. Brown
  • C. Magenta
  • D. Red

Explanation: Brady’s reagent (2,4-dinitrophenylhydrazine) reacts with the carbonyl group of benzaldehyde. It forms a 2,4 -dinitrophenylhydrazone, which is an insoluble red-orange/red precipitate. This confirms the presence of an aldehyde or ketone group.

Why the other options are wrong
  • A. There is no specific indication of a green precipitate formed when using Brady's reagent to test benzaldehyde. The characteristic color associated with the reaction of benzaldehyde and Brady's reagent is red, not green.
  • B. There is no specific indication of a brown precipitate formed when using Brady's reagent to test benzaldehyde. The characteristic color associated with the reaction of benzaldehyde and Brady's reagent is red, not brown.
  • C. There is no specific indication of a magenta precipitate formed when using Brady's reagent to test benzaldehyde. The characteristic color associated with the reaction of benzaldehyde and Brady's reagent is red, not magenta.

Q19. Which of the following can be oxidized to an aldehyde?

  • A. 2-Ethanoic acid
  • B. 2-Ethanoate
  • C. Diethyl ether
  • D. Ethanol

Explanation: Ethanol can be oxidized to produce acetaldehyde, which is an aldehyde. The oxidation can be carried out using an oxidizing agent such as potassium permanganate or chromium trioxide. The other options, 2-Ethanoic acid, 2-Ethanoate, and Diethyl ether, do not contain a functional group that can be oxidized to form an aldehyde.

Why the other options are wrong
  • A. 2-Ethanoic acid is already in its highest oxidation state as a carboxylic acid. It cannot be further oxidized to an aldehyde.
  • B. 2-Ethanoate is the conjugate base of 2-ethanoic acid. It does not have any oxidizable functional groups and cannot be oxidized to an aldehyde.
  • C. Diethyl ether does not contain an oxidizable functional group. It is an ether, which is a relatively inert compound and does not undergo oxidation reactions to form aldehydes.

Q20. Select the reagent X from the following choices for this conversion:

  • A. Acidified Potassium hydroxide
  • B. Acidified Potassium dichromate (VI)
  • C. Acidified Phosphoric acid
  • D. Acidified Oxalic acid

Explanation: The reaction above is oxidation of a secondary alcohol into a ketone. As such, an oxidizing agent must be chosen for reagent X. Among the options, 'Potassium dichromate (VI)' is an oxidizing agent so, the correct option is B. Another answer could be 'potassium manganate (VII)', but it is not mentioned in any of the options. The other options do not oxidize alcohols.

Why the other options are wrong
  • A. The other options do not oxidize alcohols.Another answer could be 'potassium manganate (VII)', but it is not mentioned in any of the options. The other options do not oxidize alcohols.
  • C. The other options do not oxidize alcohols.Another answer could be 'potassium manganate (VII)', but it is not mentioned in any of the options. The other options do not oxidize alcohols.
  • D. The other options do not oxidize alcohols.Another answer could be 'potassium manganate (VII)', but it is not mentioned in any of the options. The other options do not oxidize alcohols.

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