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Sindh Mdcat Exclusive Course Chemistry Chemical Bonding — Solved Past Paper with Answers
All 19 MCQs from Sindh Mdcat Exclusive Course Chemistry Chemical Bonding, solved with the correct answer highlighted and a full explanation for every question. This is a free MDCAT Sindh / DUHS past paper — no signup, no ads. Practise it interactively in timed mode, drill more with free MDCAT MCQs, or browse all Sindh / DUHS papers.
Attempt this paper interactively →Q1. Which of the following substances exhibits hydrogen bonding?
- A. H2S
- B. SiH4
- C. NH3✓
- D. HI
Explanation: Hydrogen bonding occurs in those substances in which a highly electronegative atom (such as Fluorine (F), Oxygen (O) or Nitrogen (N)) is directly bonded to Hydrogen. The presence of one of these three atoms is a REQUIREMENT for hydrogen bonding to occur. Only option C mentions a substance which has one of these three atoms, i.e. Nitrogen in NH3, while the other options mention other atoms aside from the three highly electronegative species mentioned previously.
Q2. The shape of CO2 molecule is similar to:
- A. H2S
- B. SO2
- C. SnCl2
- D. BeF2✓
Explanation: CO2 has a linear structure with a bond angle of 180 degrees with the central atom (C) having no lone pairs and being sp hybrid. Beryllium in BeF2 has the same configuration. Other options are wrong because: H2S= sp3 SO2=sp2 SnCl2=sp2
Q3. Both ionic and covalent bonds are present in:
- A. CH4
- B. SO2
- C. KCl
- D. NaOH✓
Explanation: Sodium hydroxide (NaOH) contains both covalent and ionic bonds. The sodium ion (Na+) and hydroxide ion (OH-) are held together by an ionic bond, while the covalent bond is between the hydrogen and oxygen atoms in the hydroxide ion(-OH).
Why the other options are wrong
- A. Only covalent bonds are present in methane (CH4). Methane is a covalent molecule composed of one carbon atom and four hydrogen atoms.
- B. In SO2 (sulfur dioxide), the sulfur atom forms a covalent bond with two oxygen atoms.
- C. Potassium chloride (KCl) contains an ionic bond between the potassium cation (K+) and chloride anion (Cl-). The two ions are held together by strong electrostatic forces due to their opposite charges.
Q4. The valency of an atom will be one if there is a sufficient gap between first and second _.
- A. Electron affinity
- B. Ionization energy✓
- C. Electronegativity
- D. None of these options are correct
Explanation: The valency of an atom will be one if there is a sufficient gap between the first and second ionization energies. Ionization energy is the energy required to remove an electron from an atom in its gaseous state. The first ionization energy is the energy required to remove the first electron from the atom, and the second ionization energy is the energy required to remove the second electron from the atom.If there is a large gap between the first and second ionization energies, it means that it is much more difficult to remove the second electron than the first electron. This is because the first electron is loosely bound to the atom, but the second electron is more tightly bound.An atom with a large gap between the first and second ionization energies will tend to have a valency of one. This is because the atom will be more likely to lose one electron than two electrons.So the answer is ionization energy.
Why the other options are wrong
- A. Electron affinity is the energy released when an electron is added to an atom in its gaseous state.
- C. Electronegativity is the tendency of an atom to attract electrons.
- D. This option is incorrect.
Q5. The decreasing order of second ionization energy of K, Ca, Ba is:
- A. K > Ca > Ba✓
- B. Ca > Ba > K
- C. Ba > K > Ca
- D. K > Ba > Ca
Explanation: As we move down the group size increases and the electrons experience less effective nuclear charge. Due to this reason, ionization potential decreases down the group. Thus, the second ionization potential of Ca is greater than that of Ba. The second ionization potential of K is greater than that of Ca as K acquires stable noble gas configuration after losing one electron.
Q6. The bond, which is based on attractive forces between oppositely charged ions, is:
- A. Covalent bond
- B. Dative bond
- C. Ionic bond✓
- D. Metallic bond
Explanation: An Ionic bond, also called an electrovalent bond, type of linkage formed from the electrostatic attraction between oppositely charged ions in a chemical compound. Such a bond forms when the valence (outermost) electrons of one atom are transferred permanently to another atom.
Why the other options are wrong
- A. A covalent bond consists of the mutual sharing of one or more pairs of electrons between two atoms. These electrons are simultaneously attracted by the two atomic nuclei. A covalent bond forms when the difference between the electro negativities of two atoms is too small for an electron transfer to occur to form ions.
- B. In coordination chemistry, a coordinate covalent bond, also known as a dative bond dipolar bond, or coordinate bond is a kind of two-center, two-electron covalent bond in which the two electrons derive from the same atom. It is a form of covalent bond in which the shared pair of electrons comes from a single atom so, option B is also deemed incorrect.
- D. Metallic bonds result from the electrostatic attraction between metal cations and delocalized electrons. The nature of metallic bonding accounts for many of the physical properties of metals, such as conductivity and malleability
Q7. Which of the following indicate the correct variation of electronegativity?
- A. F > N > O < C
- B. F > N > O > C
- C. F< N < O < C
- D. F > O > N > C✓
Explanation: The relative tendency of a bonded atom in a molecule to attract the shared electron pair towards itself is called electronegativity. The positively charged protons in the nucleus attract the negatively charged electrons. As the number of protons in the nucleus increases, the electronegativity or attraction will increase. Therefore electronegativity increases from left to right in a row in the periodic table. Here, the correct order of electronegativity is: F > O > N > C
Why the other options are wrong
- A. It is incorrect because nitrogen has a higher electronegativity than oxygen.
- B. This option is incorrect because nitrogen has an electronegativity less than oxygen.
- C. This option is incorrect because the electronegativity order is shown as completely opposite.
Q8. Linear combination of atomic orbitals (LCAO) results in the formation of:
- A. Sigma bond
- B. Pi bond
- C. Bonding molecular orbitals only
- D. Bonding and antibonding molecular orbitals✓
- E. All of these options
Explanation: According to Molecular Orbital Theory (MOT), two atomic orbitals overlap resulting in the formation of molecular orbitals. Number of atomic orbitals overlapping together is equal to the molecular orbital formed. The two atomic orbital thus formed by LCAO (linear combination of atomic orbital) in the same phase or in the different phase are known as Bonding Molecular Orbital (BMO) and Antibonding Molecular Orbitals (ABMO) respectively.
Why the other options are wrong
- A. Option A is incorrect as sigma bond is formed by head-on overlapping of atomic orbitals.
- B. Option B is incorrect as pi bond is formed by parallel or sidewise overlapping of atomic orbitals.
- C. Option C is incorrect as only bonding molecular orbital is not formed rather both bonding and antibonding Molecular Orbitals are formed.
- E. Option E is incorrect as the answer cannot be all of these because only option D is correct.
Q9. An ionic compound is most likely to be formed when:
- A. Ionization energy of A is high but electron affinity of B is low
- B. The ionization energy of A is low but electron affinity of B is high✓
- C. Both ionization energy of A and electron affinity of B are high
- D. Both ionization energy of A and electron affinity of B are low
Explanation: The option "The ionization energy of A is low but electron affinity of B is high" is most likely to form an ionic compound. In an ionic compound, one element has a low ionization energy, which means it readily gives up electrons to form a cation, while the other element has a high electron affinity, which means it readily accepts electrons to form an anion. This results in the formation of an ionic bond between the cation and anion, forming an ionic compound.
Why the other options are wrong
- A. This is not correct as in ionic compound general represention is A is metal Cation and B is non-metal anion, so metal will have low ionization energy to be able to lose an electron and similarly non metals will have high electron affinity to be able to gain electron.
- C. The option "The ionization energy of A is low but electron affinity of B is high" is most likely to form an ionic compound. In an ionic compound, one element has a low ionization energy, which means it readily gives up electrons to form a cation, while the other element has a high electron affinity, which means it readily accepts electrons to form an anion. This results in the formation of an ionic bond between the cation and anion, forming an ionic compound.
- D. The option "The ionization energy of A is low but electron affinity of B is high" is most likely to form an ionic compound. In an ionic compound, one element has a low ionization energy, which means it readily gives up electrons to form a cation, while the other element has a high electron affinity, which means it readily accepts electrons to form an anion. This results in the formation of an ionic bond between the cation and anion, forming an ionic compound.
Q10. The raindrop acquires a spherical shape and ink spread over blotting paper due to:
- A. Surface tension✓
- B. Adhesive forces
- C. Viscosity
- D. Polarity
- E. Latent heat of vaporization
Explanation: A raindrop falling through the atmosphere forms a roughly spherical structure due to the surface tension of water. This surface tension is the “skin” of a body of water that makes the molecules stick together. The cause is the weak hydrogen bonds that occur between water molecules.
Why the other options are wrong
- B. Adhesive forces are not discussed in this scenario.
- C. Raidrop falling down to earth and attaining it's shape has no relationship with viscosity.
- D. Polarity has no link with shape of object at macrolevel.
- E. Latent heat of vaporization is not correct answer because heat is not been provided to the raindrop to attain it's spherical shape.
Q11. Which of the following molecules have zero Dipole Moment?
- A. CCl4
- B. CO2
- C. Cl2
- D. C6H6
- E. All of the above✓
Explanation: All the molecules listed have a zero dipole moment due to their symmetrical structures:CCl4: Although it has polar C-Cl bonds, the tetrahedral symmetry results in a net dipole moment of zero.CO2: The linear shape with two opposing C=O bonds results in the cancellation of dipole moments.Cl2: As it consists of identical atoms, no dipole moment arises.C6H6 (Benzene): The planar symmetrical structure leads to the cancellation of dipole moments of C-H bonds.Therefore, the correct answer is 'All of the above'.
Why the other options are wrong
- A. The CCl4 molecule has zero dipole moment. Despite the polar C-Cl bonds, the symmetrical tetrahedral shape causes the dipoles to cancel each other out.
- B. CO2 is a linear molecule. The bond dipole moments in the opposing C=O bonds cancel each other, resulting in a zero dipole moment.
- C. Cl2 consists of two identical atoms, resulting in no net dipole moment due to the absence of a charge difference.
- D. Benzene (C6H6) has a symmetrical planar structure. The dipole moments of the C-H bonds cancel out, leading to a zero net dipole moment.
Q12. Bond energy:I. is the energy required to break a bond between two atoms in a diatomic molecule II. Is taken as the energy released in forming a bond form free atoms III. Is the measure of the strength of bond.
- A. I only
- B. I and II only
- C. I and III only
- D. II only
- E. I, II and III✓
Explanation: Bond energy is a critical concept in understanding chemical bonding and is defined through multiple perspectives:Option I: It is indeed the energy required to break a bond between two atoms in a diatomic molecule, indicating how much energy is needed to overcome the bond's strength.Option II: The energy released when a bond is formed from free atoms is also a measure of bond energy, showing the stabilization energy provided during bond formation.Option III: Bond energy serves as an indicator of bond strength; stronger bonds require more energy to break, thus having higher bond energies.Therefore, all three options collectively provide a comprehensive understanding of bond energy, making Option E the correct choice. Each statement highlights a different but related aspect of bond energy, and understanding this concept requires integrating all perspectives.
Why the other options are wrong
- A. While option I correctly describes bond energy, it is not the only valid description. Options II and III also describe bond energy.
- B. Options I and II both describe bond energy, but option III is also a valid description as it relates to the strength of a bond.
- C. Options I and III describe bond energy, but option II is also a necessary component as it involves the energy released during bond formation.
- D. While option II describes bond energy in terms of energy released, options I and III are also correct descriptions.
Q13. GN Lewis described which one of the following bonds?
- A. Ionic bond
- B. Covalent bond
- C. Coordinate covalent bond
- D. All of the above✓
Explanation: G.N. Lewis is renowned for his work on the nature of chemical bonding, particularly the sharing of electron pairs between atoms, which forms the basis of covalent bonds. His theories extend to both ordinary covalent bonds and coordinate covalent bonds. While ionic bonds involve electron transfer and are not the primary focus of Lewis's theories, his work laid the groundwork for understanding chemical bonding as a whole. Therefore, 'All of the above' is the correct answer, as it encompasses the types of bonds Lewis described.
Why the other options are wrong
- A. An ionic bond involves the transfer of electrons from one atom to another, resulting in the formation of ions. G.N. Lewis primarily focused on electron pair sharing in covalent bonds rather than ionic bonds.
- B. G.N. Lewis is well-known for his description of covalent bonds, where atoms share electron pairs to attain stability. His work led to the concept of the Lewis structure, which represents covalent bonds.
- C. A coordinate covalent bond, also known as a dative bond, is a type of covalent bond where both electrons in the shared pair come from the same atom. Lewis's theory also encompasses this type of bond.
Q14. The order of force of repulsion between Lone pairs and Bond pairs is?
- A. Lone pair - Bond pair repulsion > Lone pair - Lone pair repulsion > Bond pair - Bond pair repulsion
- B. Bond pair - Bond pair repulsion > Lone pair - Lone pair repulsion > Lone pair - Bond pair repulsion
- C. Lone pair - Lone pair repulsion > Bond pair - Bond pair repulsion > Lone pair - Bond pair repulsion
- D. Lone pair - Lone pair repulsion > Lone pair - Bond pair repulsion > Bond pair - Bond pair repulsion✓
Explanation: The correct order of repulsions is: Lone pair - Lone pair repulsion > Lone pair - Bond pair repulsion > Bond pair - Bond pair repulsion. This is because lone pairs of electrons are not shared between atoms and are therefore more concentrated and closer to the central atom, leading to greater repulsion. Lone pair - bond pair repulsion is less than lone pair - lone pair but more than bond pair - bond pair, as the presence of a lone pair introduces more electron density compared to the shared electron density in bond pairs. Bond pair - bond pair repulsion is the weakest due to the attraction between the electrons and their respective nuclei, which stabilizes the electrons in the bond.
Why the other options are wrong
- A. This option is incorrect because lone pair - lone pair repulsion is stronger than lone pair - bond pair repulsion due to the lack of attraction to nuclei in lone pairs.
- B. This option is incorrect because bond pair - bond pair repulsion is the weakest due to the attraction between bonding electrons and nuclei.
- C. This option is incorrect because lone pair - bond pair repulsion is stronger than bond pair - bond pair repulsion due to the presence of non-bonding electron pairs.
Q15. Ionic, covalent and co-ordinate covalent bonds are simultaneously present in the molecular geometry of:
- A. Ammonia
- B. Ammonium hydroxide✓
- C. Hydrochloric acid
- D. Water
- E. Methane
Explanation: There are 3 covalent , 1 coordinate covalent bond in NH4+ ion, and 1 covalent bond in OH−. There is an ionic bond between NH4+ and OH-.So, this species simultaneously has 3 different types of bonds.
Why the other options are wrong
- A. Ammonia has a nitrogen atom bound with three hydrogen atoms by covalent bonds.
- C. Hydrochloric acid has ionic bonding between Hydrogen (H+) and chlorine(Cl-).
- D. Water has only covalent bonding between 2 hydrogen atoms and an oxygen atom.
- E. Methane also has 4 covalent bonds by which carbon atoms are bonded to 4 respective hydrogen atoms.
Q16. In HF the covalent bond is due to:
- A. S-S overlapping
- B. S-Pz overlapping✓
- C. S-Px overlapping
- D. Pz - Pz overlapping
Explanation: In formation of HF, 1s orbital of H overlaps with 2Pz orbital to F to form bond. Therefore bonding is due to S-Pz overlapping.
Why the other options are wrong
- A. This option suggests the overlap of two s orbitals, which is not applicable to the HF bond. HF involves an s orbital from hydrogen and a p orbital from fluorine.
- C. This option suggests overlap between an s orbital and a Px orbital, which is not the case in HF. The correct overlap involves the Pz orbital of fluorine.
- D. This option describes overlap between two Pz orbitals, which does not occur in HF. The bond involves an overlap between an s orbital from hydrogen and a Pz orbital from fluorine.
Q17. Which statement is incorrect regarding a chemical bond?
- A. Bond is formed by the overlapping of half-filled orbitals
- B. Bond is formed by the attraction of positive and negative ions
- C. Bond is formed by the overlapping of “s” orbital is strong
- D. Bond formed by the large sized atoms is strong✓
Explanation: Bonding tends to take place between the outermost electrons of an atom (or outermost shell). As you increase the atomic size, the electrons that make up an atom begin to fill up higher electron orbitals. These orbitals, which then take place in bonding, are physically further away from the nucleus and thus experience less attraction to it (based on Columb's law). That is the reason why D is an incorrect statement and thus the answer. A is true as the overlapping of half-filled orbitals occurs in covalent bonding; a type of chemical bond. B is true as it occurs in the formation of ionic bonds. C is also true as the s orbital is the smallest orbital because of which the distance between outermost electrons and the positively charged nucleus is small, rendering a stronger attractive force.
Why the other options are wrong
- A. When overlapping of half-filled atomic orbitals takes place along the inter-nuclear axis, the bond formed is called the sigma bond. Hence, the option is correct.
- B. An Ionic bond is formed by the attraction of positive and negative ions. Hence, this option is also correct.
- C. This is also true as the s orbital is the smallest because of which the distance between the outermost electrons and the positively charged nucleus is small, rendering a stronger attractive force.
Q18. For the formation of ionic bond, electronegativity difference should be:
- A. Equal to zero
- B. Equal to 0.5
- C. More than 1.7✓
- D. Less than 1.7
Explanation: Electronegativity is a measure of an atom's ability to attract electrons towards itself in a chemical bond. For the formation of an ionic bond, there should be a significant difference in electronegativity between the participating atoms. Typically, an electronegativity difference of 1.7 or greater on the Pauling scale is considered indicative of an ionic bond. In other words, if the electronegativity difference between two atoms is equal to or greater than 1.7, it suggests that one atom has a much stronger attraction for electrons than the other.
Why the other options are wrong
- A. Zero electronegativity difference results in the formation of non-polar covalent bond.
- B. 0.5 electronegativity difference also results in the formation of non-polar covalent bond.
- D. Less than 1.7 electronegativity difference results in the formation of polar covalent bond.
Q19. Which one of the following bonds has the highest bond energy?
- A. .C-C
- B. .C ≡ C
- C. N ≡ N✓
- D. H-F
Explanation: Triple bonds are stronger than single and double bonds, for understandable reasons. A nitrogen-nitrogen triple bond is stronger than a carbon-carbon triple bond because as we know that in the periodic table as we move from left to right the atomic sizes of elements decrease, this is due to the addition of electrons in the valence shell which increases nuclear charge. Carbon and nitrogen both elements are present in the same period but nitrogen (Z=7) is placed next to carbon (Z=6) thus it means the size of nitrogen is smaller than that of carbon and thus both the nitrogen atoms are much closer to each other unlike in case of carbon and hence more energy is required to break N-N triple bond compared to C-C triple bond.
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