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Sindh Mdcat Reconduct 2024 — Solved Past Paper with Answers
All 131 MCQs from Sindh Mdcat Reconduct 2024, solved with the correct answer highlighted and a full explanation for every question. This is a free MDCAT Sindh / DUHS past paper — no signup, no ads. Practise it interactively in timed mode, drill more with free MDCAT MCQs, or browse all Sindh / DUHS papers.
Attempt this paper interactively →Q1. Choose the correct set of prepositions to complete the given sentence:Since she believed _ her abilities, she didn't ask _ any help.
- A. In, for✓
- B. With, about
- C. At, for
- D. On, for
Explanation: The correct phrase is "believe in" when referring to trust or confidence in someone or something & "ask for" is used in terms of requesting, hence it fits best.
Why the other options are wrong
- B. "Believe with" and "believe about" are incorrect prepositional combinations in this context & "ask about" means to inquire or get information, not to request help.
- C. "Believe at" and "believe for" are grammatically incorrect.
- D. "Believe on" is not the correct preposition; it should be "believe in."
Q2. Choose the sentence with the correct use of the comparative degree of an adjective:
- A. My bed is more big than my desk.
- B. My bed is bigger then my desk.
- C. My bed is bigger than my desk.✓
- D. My bed is more bigger than my desk.
Explanation: Correct: "Bigger than" is the correct comparative structure.
Why the other options are wrong
- A. Incorrect: "More big" is incorrect; "bigger" is the correct comparative form.
- B. Incorrect: "Then" is incorrect; the correct word is "than" when making comparisons.
- D. Incorrect: "More bigger" is incorrect because "bigger" is already a comparative form.
Q3. Choose the word closest in meaning to the underlined phrase in the sentence:The firemen took several hours to put out the fire.
- A. Dislocate
- B. Extinguish✓
- C. Producer
- D. Broadcast
Explanation: "Put out" means to extinguish a fire, making "extinguish" the correct answer.
Why the other options are wrong
- A. "Dislocate" means to move out of position, which does not fit the context.
- C. "Producer" is someone or something that creates or makes something is unrelated to the meaning of "put out" in this context.
- D. "Broadcast" means to spread information, which is not the intended meaning.
Q4. Punctuate the following sentence correctly:
- A. There was heavy fog in the morning the services at the airport were closed.
- B. There was heavy fog in the morning, the services at the airport were closed
- C. There was heavy fog in the morning; the services at the airport were closed.✓
- D. There was heavy fog in the morning: the services at the airport were closed.
Explanation: A semicolon is correctly used to join two closely related independent clauses.
Why the other options are wrong
- A. This sentence lacks proper punctuation, making it a run-on sentence.Two independent clauses are joined without proper punctuation. A period, semicolon, or conjunction is needed between them.
- B. A comma alone cannot join two independent clauses; this results in a comma splice.
- D. A colon is usually used before a list or explanation, not for joining two independent clauses in this context.
Q5. Identify the correct spelling of the given word:
- A. Greivous
- B. Grevuous
- C. Grievous✓
- D. Griveous
Explanation: "Grievous" is the correct spelling, meaning serious or severe.
Why the other options are wrong
- A. "Greivous" is a misspelling; the correct spelling is "grievous."
- B. "Grevuous" is not a valid spelling, the correct one is grievous.
- D. "Griveous" is an incorrect spelling, the correct one is grievous.
Q6. Complete the given sentence with the most appropriate pronoun: Scientists _ are turning away from the cruder mechanical ideas.
- A. Ourselves
- B. Herself
- C. Themselves✓
- D. Theirselves
Explanation: "Themselves" is the correct reflexive pronoun for "scientists" which is plural.
Why the other options are wrong
- A. "Ourselves" is a reflexive pronoun used for the first-person plural, which does not match "scientists".
- B. "Herself" is singular and does not match the plural subject "scientists".
- D. "Theirselves" is not a standard English word.
Q7. Identify the tense of the given sentence:The sick child has been sleeping for three hours
- A. Present Perfect Continuous Tense✓
- B. Present Perfect Tense
- C. Past Perfect Tense
- D. Present Continuous Tense
Explanation: The sentence uses "has been sleeping", which is the Present Perfect Continuous tense, indicating an action that started in the past and is still continuing.
Why the other options are wrong
- B. The Present Perfect Tense would use "has slept," which is not in the given sentence.
- C. The Past Perfect Tense would use "had been sleeping", as it is the helping verb used in this tense.
- D. The Present Continuous Tense would use "is sleeping," but the sentence refers to a continued action over time.
Q8. Choose the correct option.
- A. After several days of discussion, the committee agreed to the amount of money to donate.
- B. After several days of discussion, the committee agreed at the amount of money to donate
- C. After several days of discussion, the committee agreed with the amount of money to donate.
- D. After several days of discussion, the committee agreed on the amount of money to donate.✓
Explanation: "Agreed on" is the correct phrase when referring to a decision or an amount.
Why the other options are wrong
- A. “Agreed to” is incorrect here because when specifying what is being agreed upon, English uses “agreed on” rather than “agreed to.” “Agreed to” is used when consenting to an action, not the specifics of a decision. The correct phrasing is: “the committee agreed on the amount of money to donate.”
- B. “Agreed at” is incorrect because English does not pair “agree” with the preposition “at” when referring to reaching a decision. The correct preposition is “on” for agreeing about a thing or amount (agreed on the amount) and “to” when consenting to an action (*agreed to participate
- C. "Agreed with" is incorrect because "agree with" is used when agreeing with a person, not a decision.
Q9. Choose the correct option:
- A. I now feel sadly and inadequately that I don’t have enough money to buy the books I want.
- B. I now feel sad and inadequate that I don’t have enough money to buy the books I want.✓
- C. I now feel sad and inadequate that I don’t have money enough to buy the books I want.
- D. I now feel sad and inadequate that I have not enough money buying the books I want.
Explanation: The "sad" And "inadequate" are adjectives and grammatically correct and follows proper word order. The infinitive “to buy the books I want” clearly shows the purpose of needing money.
Why the other options are wrong
- A. "Sadly" and "inadequately" Are adverbs, but "sad" And "inadequate" should be used as adjectives here.
- C. "Money enough" is grammatically incorrect; it should be "enough money."The adjective should me placed before noun.
- D. “Have not enough money” is incorrect word order; it should be “do not have enough money.”The phrase “money buying the books” is wrong because it lacks “to buy,” making the meaning unclear.
Q10. Find the error:The judges on the panel declared that of the two singers, John’s song was more melodious.
- A. On
- B. Of the two
- C. John’s song
- D. More melodious✓
Explanation: The correct phrase should be 'the more melodious' when comparing two singers. The definite article 'the' is necessary to indicate a specific comparison between John’s song and the other singer's song. Without it, the phrase is grammatically incomplete. The other options are correct in their usage, but they do not address the primary error in the sentence, which lies in the comparative structure.
Why the other options are wrong
- A. The phrase 'on the panel' is correctly used to indicate the judges' location or role.
- B. The phrase 'of the two' is correctly utilized for making a comparison between two subjects.
- C. 'John's song' is grammatically correct and indicates possession.
Q11. CD4 receptor site is found in all types of cells except:
- A. Helper T cells
- B. MHCH
- C. Brain cells✓
- D. Suppressor T cells
Explanation: Brain cells – Correct. CD4 receptors are not present on brain cells as they are not part of the immune system.
Why the other options are wrong
- A. Helper T cells – Incorrect. CD4 receptors are primarily found on Helper T cells, which play a role in the immune response
- B. MHCH – Incorrect. MHCH (Major Histocompatibility Complex Class II) molecules interact with CD4 receptors but do not have CD4 themselves.
- D. Suppressor T cells – Incorrect. CD4 receptors are also found on some regulatory T cells (a subset of Suppressor T cells).
Q12. A Russian scientist discovered that certain diseases could be transmitted by an agent that could pass through a very fine filter, which is called:
- A. Bacteria
- B. Fungi
- C. Algae
- D. Viruses✓
Explanation: Dmitri Ivanovsky discovered that viruses could pass through filters that trapped bacteria, leading to the discovery of these infectious agents.
Why the other options are wrong
- A. Bacteria are considered “larger” only when you compare them to viruses. They’re still microscopic, but their size is big enough that they usually get trapped by fine filters that would let viruses slip through.
- B. Fungi are multicellular or unicellular organisms that are much larger and cannot pass through fine filters.
- C. Algae are generally much bigger than bacteria and viruses, which is why they don’t pass through laboratory filters. Many algae are multicellular or form long chains or colonies, and even the unicellular ones are large enough to be seen under a light microscope.
Q13. Examples of reverse transcribing diploid single-stranded RNA viruses are:
- A. Hepatitis B
- B. HIV✓
- C. Rabies
- D. Chicken Pox
Explanation: HIV (Human Immunodeficiency Virus) is a retrovirus that has diploid single-stranded RNA and uses reverse transcription.
Why the other options are wrong
- A. Hepatitis B is indeed a DNA virus. Its genome is partially double-stranded DNA, which is unusual because most other hepatitis viruses are RNA viruses.
- C. Rabies virus is an RNA virus but is not a retrovirus and does not use reverse transcription.
- D. Chickenpox is caused by the Varicella-Zoster Virus, and it’s a DNA virus. It belongs to the herpesvirus family, which all carry double-stranded DNA.
Q14. Viruses are called non-cellular infectious entities because:
- A. They are pathogens and cause infections
- B. They can replicate inside as well as outside the living cells
- C. They cause infections and can only replicate inside living cells✓
- D. They have a capsid to infect the host
Explanation: They cause infections and can only replicate inside living cells – Correct. Viruses are obligate intracellular parasites, meaning they need a host cell to reproduce.
Why the other options are wrong
- A. While viruses do cause infections, this is not the reason they are classified as non-cellular.
- B. Viruses can’t make copies of themselves on their own. They don’t have the machinery needed to produce proteins or replicate their genetic material.To multiply, a virus has to enter a living cell and take over the cell’s enzymes and structures. The host cell then ends up doing the work for the virus, producing new viral particles.
- D. A capsid is just the protein shell that protects a virus’s genetic material. Having a capsid doesn’t make something non-cellular — the key point is that viruses lack all the features that define a cell.They don’t have a cell membrane, cytoplasm, ribosomes, or any metabolic machinery. They can’t produce energy, can’t synthesize proteins on their own, and can’t divide by themselves. Because of this, they aren’t considered true cells and are classified as non-cellular infectious particles.So while the capsid is an important structure, the reason viruses are non-cellular comes from everything they don’t have, not just from the fact that they have a capsid.
Q15. Which statement is correct about the glycolysis process?
- A. 2 ATP are produced and 2 ATP are consumed
- B. 1 ATP is produced and 2 ATP are consumed
- C. 2 ATP are produced and 1 ATP is consumed
- D. 4 ATP are produced and 2 ATP are consumed✓
Explanation: 4 ATP are produced and 2 ATP are consumed – Correct. Glycolysis generates 4 ATP molecules but consumes 2, leading to a net gain of 2 ATP.
Why the other options are wrong
- A. 2 ATP are produced and 2 ATP are consumed – Incorrect. The net ATP gain in glycolysis is 2 ATP, but a total of 4 ATP are produced
- B. 1 ATP is produced and 2 ATP are consumed – Incorrect. Glycolysis produces more ATP than 1 and does not result in a net loss.
- C. 2 ATP are produced and 1 ATP is consumed – Incorrect. Glycolysis requires 2 ATP for activation but produces more than 2 ATP.
Q16. During the light-dependent phase of photosynthesis, the water molecule is broken down into:
- A. 2H, 2e and 1/2 O₂✓
- B. 4H, 4e and 2 O₂
- C. 2H, 2e and 2 O₂
- D. 4H, 2e and 4 O₂
Explanation: 2H, 2e and 1/2 O₂ – Correct. Photolysis of water during photosynthesis produces 2 protons (H⁺), 2 electrons (e⁻), and ½ molecule of oxygen (O₂) per water molecule.
Why the other options are wrong
- B. 4H, 4e and 2 O₂ – Incorrect. This option suggests an incorrect stoichiometry, as the oxygen released does not match water breakdown.
- C. 2H, 2e and 2 O₂ – Incorrect. The oxygen amount is incorrect, as each water molecule releases only ½ O₂.
- D. 4H, 2e and 4 O₂ – Incorrect. The number of oxygen molecules is not balanced according to the photolysis reaction.
Q17. ATP is best defined as:
- A. The molecule that has no role in muscle contraction
- B. The molecule that releases energy when a phosphate molecule is added
- C. The molecule that is only present inside the nucleus
- D. The molecule that releases energy when the phosphate molecule is removed✓
Explanation: The molecule that releases energy when the phosphate molecule is removed – Correct. ATP releases energy when hydrolyzed to ADP by removing a phosphate group.
Why the other options are wrong
- A. The molecule that has no role in muscle contraction – Incorrect. ATP is essential for muscle contraction as it provides the necessary energy.
- B. The molecule that releases energy when a phosphate molecule is added – Incorrect. ATP releases energy when a phosphate group is removed, not added.
- C. The molecule that is only present inside the nucleus – Incorrect. ATP is present throughout the cell, not just in the nucleus.
Q18. Erythrose is a type of monosaccharide that is commonly known as:
- A. Triose
- B. Tetrose✓
- C. Pentose
- D. Heptose
Explanation: Tetrose is the correct choice because erythrose contains four carbon atoms. Sugars with four carbons fall into the tetrose category, so erythrose fits this group.
Why the other options are wrong
- A. Triose is not correct because trioses contain three carbons, while erythrose has four, making it a tetrose instead.
- C. Pentose is not correct because pentose sugars contain five carbons, while erythrose has only four, so it cannot be placed in that group.
- D. Heptose is wrong because it has seven carbon atoms, while erythrose has four and is therefore a tetrose.
Q19. The hypothalamus regulates the signaling molecule like
- A. Granzyme
- B. Spermine
- C. Pyrogen✓
- D. Prostaglandin
Explanation: Pyrogen – Correct. Pyrogens are signaling molecules that induce fever and are regulated by the hypothalamus.
Why the other options are wrong
- A. Granzyme – Incorrect. Granzyme is an enzyme released by cytotoxic cells to induce apoptosis in target cells.
- B. Spermine – Incorrect. Spermine is a polyamine involved in cellular metabolism, but is not a signaling molecule from the hypothalamus.
- D. Prostaglandin – Incorrect. Prostaglandins are lipid compounds involved in inflammation, but are not directly produced by the hypothalamus.
Q20. In the electron transport chain, the ultimate electron acceptor is:
- A. NADH
- B. None of these
- C. Oxygen✓
- D. Cytochrome complex
Explanation: Oxygen – Correct. Oxygen acts as the final electron acceptor in the electron transport chain, forming water.
Why the other options are wrong
- A. NADH – Incorrect. NADH is an electron donor, not an acceptor.
- B. This is not correct, as we have the correct option present.
- D. Cytochrome complex – Incorrect. Cytochrome complexes transfer electrons but do not act as the ultimate acceptor.
Q21. The following are viral diseases except:
- A. Hepatitis
- B. Polio
- C. Syphilis✓
- D. AIDS
Explanation: Syphilis is caused by the bacterium Treponema pallidum, not a virus.It spreads mainly through sexual contact and can progress through several stages if untreated.
Why the other options are wrong
- A. Hepatitis, including types like B and C, is caused by specific viruses that target the liver. Hepatitis B is a DNA virus, while Hepatitis C is an RNA virus.
- B. Polio is caused by the poliovirus, which is an RNA virus from the enterovirus group.It mainly spreads through the fecal-oral route and can affect the nervous system in severe cases.
- D. AIDS develops when a person is infected with the Human Immunodeficiency Virus (HIV). The virus damages the immune system over time, making the body vulnerable to infections.
Q22. The property of water that is important to biological membrane stability is:
- A. Anomalous
- B. Amphoteric
- C. Hydrophobic exclusion✓
- D. Hydrophobic inclusion
Explanation: Hydrophobic exclusion – Correct. This property helps maintain the integrity of biological membranes by preventing the mixing of hydrophobic and hydrophilic components.
Why the other options are wrong
- A. Water exhibits anomalous properties, such as expanding upon freezing and having a high specific heat, but these characteristics do not directly affect the structural stability of cell membranes. Membrane stability is mainly determined by the lipid bilayer and interactions with membrane proteins, not by water’s anomalous behavior.
- B. Amphoteric substances can act as either acids or bases depending on the environment, but this chemical property does not directly influence the structural stability of cell membranes. Membrane stability primarily depends on the arrangement of phospholipids and interactions with proteins, not on amphoteric behavior.
- D. The term "hydrophobic inclusion" is not a standard concept in the context of membrane stability. Membrane integrity is primarily explained by hydrophobic exclusion, where the hydrophobic lipid tails cluster away from water. Using "hydrophobic inclusion" would be inaccurate and does not describe how membranes maintain their structure.
Q23. The glycosidic linkage between glucose and fructose is:
- A. Alpha-1, Beta-2✓
- B. Alpha-1, Beta-4
- C. Alpha-1, Alpha-4
- D. Beta-1,4
Explanation: Alpha-1, Beta-2 – Correct. Sucrose, formed by glucose and fructose, has an alpha-1, beta-2 glycosidic bond.
Why the other options are wrong
- B. Alpha-1,β-4 isn’t the bond in sucrose. Sucrose is α-1→β-2 between glucose and fructose. A β-1→4 linkage is found in cellulose (glucose–glucose) and in lactose (galactose–glucose).
- C. Alpha-1, alpha-4 is not the linkage in sucrose. That bond is typical of maltose, where two glucose units join through an α-1→4 connection, not a glucose–fructose pair.
- D. Beta-1,4 is not the bond in sucrose. That linkage shows up in cellulose and also in lactose, but sucrose uses an α-1→β-2 connection between glucose and fructose.
Q24. Cyclic phosphorylation is stimulated by:
- A. Low level of NADPH
- B. High level of NADPH✓
- C. Low light intensity
- D. High light intensity
Explanation: Cyclic phosphorylation is a process that occurs in the light-dependent reactions of photosynthesis, where electrons are recycled within the photosystem to generate ATP without producing NADPH. It is stimulated by a high level of NADPH because this indicates that the cell has sufficient reducing agents and needs more ATP to maintain balance in the energy supply. Therefore, when NADPH levels are high, the demand for ATP increases, leading to the activation of cyclic phosphorylation. The other options are incorrect because:Low level of NADPH would not stimulate cyclic phosphorylation as it indicates a shortage of reducing power needed for other processes.Low light intensity affects the overall efficiency of photosynthesis but does not specifically trigger cyclic phosphorylation.High light intensity could lead to increased overall activity but does not directly correlate with the stimulation of cyclic phosphorylation as it depends more on the ATP/NADPH ratio than light intensity alone.
Why the other options are wrong
- A. This option is incorrect. Low levels of NADPH would not stimulate cyclic phosphorylation, as this process is more active when there is a high demand for ATP relative to NADPH.
- C. This option is incorrect. While low light intensity can affect overall photosynthesis, cyclic phosphorylation is primarily stimulated by the ATP/NADPH ratio and not directly by light intensity.
- D. This option is incorrect. High light intensity can promote both cyclic and non-cyclic phosphorylation, but it does not specifically stimulate cyclic phosphorylation in the context of NADPH levels.
Q25. A process by which one glycerol molecule is linked with three fatty acids by the esterification molecule is known as:
- A. Acylglycerol✓
- B. Wax
- C. Cholesterol
- D. Phospholipids
Explanation: Acylglycerol is correct because triacylglycerols are made when glycerol reacts with three fatty acids to form ester bonds. This esterification produces the triglycerides that serve as the main storage form of fats in the body.
Why the other options are wrong
- B. Wax is not the right choice because waxes are made from long-chain fatty acids combined with long-chain alcohols. They don’t use glycerol as the backbone, so they’re not triacylglycerols.
- C. Cholesterol is not correct because it’s a steroid molecule made from a multi-ring structure. It isn’t produced by attaching fatty acids to glycerol, so it doesn’t fall under acylglycerols.
- D. Phospholipids are not the right answer because they include a phosphate group along with their fatty acids. This makes their structure different from triglycerides, which are built only from glycerol and three fatty acids.
Q26. The layer of the plant cell wall formed at the time of cytokinesis is
- A. Primary wall
- B. Secondary wall
- C. Middle lamella✓
- D. Tertiary wall
Explanation: The correct answer is the middle lamella, which is the layer that forms during cytokinesis, serving to bond adjacent plant cells together. This layer is rich in pectin and acts as a glue-like substance that helps maintain the integrity of plant tissue. The primary wall is established earlier during the cell's growth phase, providing initial structure but does not form at the time of cytokinesis. The secondary wall develops later, once the cell has ceased expanding, to provide further strength. Meanwhile, the tertiary wall is a specialized layer found in certain cells and does not relate to the cytokinesis process.
Why the other options are wrong
- A. The primary cell wall is the first layer synthesized during cell growth, providing flexibility and support. It is not specifically formed during cytokinesis, which is the process of cytoplasmic division following mitosis. During cytokinesis, the cell plate forms, eventually giving rise to the middle lamella and new cell walls, rather than the primary wall itself.
- B. Secondary wall – Incorrect. The secondary cell wall is deposited inside the primary wall after the cell has stopped expanding. It is thicker and often lignified, providing additional strength and rigidity. This wall helps support the plant structurally and allows specialized cells, like xylem vessels, to withstand pressure and transport water efficiently.
- D. Tertiary wall – Incorrect. The tertiary wall is an additional layer that may form in specialized cells after the secondary wall, but it does not occur during cytokinesis.
Q27. Cell membrane is selectively permeable due to:
- A. Proteins✓
- B. Cholesterol
- C. Phospholipids
- D. Enzymes
Explanation: The correct answer is Proteins, as they are essential for the selective permeability of the cell membrane. Embedded proteins act as channels or carriers that facilitate the movement of specific molecules in and out of the cell, thereby regulating its internal environment. While phospholipids create the structure of the membrane and cholesterol aids in fluidity, they do not selectively allow substances to pass. Enzymes, while crucial for metabolic processes, do not play a role in determining what can cross the cell membrane. Therefore, understanding the role of proteins is key to grasping how the cell membrane maintains its selective permeability.
Why the other options are wrong
- B. Cholesterol is interspersed within the phospholipid bilayer, where it stabilizes the membrane and prevents it from becoming too fluid or too rigid. While it supports overall membrane integrity, it does not directly determine which molecules can pass through. Selective permeability is primarily controlled by the lipid bilayer and specific membrane proteins.
- C. Phospholipids arrange into a bilayer, forming the fundamental barrier of the plasma membrane that separates the cell from its environment. While they create a hydrophobic core that restricts free passage of polar molecules, the selective transport of ions and larger molecules is mainly mediated by membrane proteins such as channels, carriers, and pumps. Proteins, therefore, play the key role in controlling what enters and exits the cell.
- D. Enzymes accelerate biochemical reactions within the cell or at the membrane surface but do not control which substances can cross the membrane. Selective permeability is mainly determined by the lipid bilayer and membrane proteins, such as channels, carriers, and pumps. Enzymes may assist in modifying molecules or signaling, but they are not the primary agents regulating membrane transport.
Q28. During photorespiration, an acid glycolate is formed, which is converted into glycine by:
- A. Lysosomes
- B. Golgi complex
- C. Peroxisome✓
- D. Vacuole
Explanation: Peroxisome – Correct. Peroxisomes process glycolate into glycine during photorespiration.
Why the other options are wrong
- A. Lysosomes are not involved in photorespiration. Their primary role is to digest and break down cellular waste, damaged organelles, and macromolecules, not to participate in the metabolic pathways of photosynthesis or photorespiration.
- B. Golgi complex is not involved in photorespiration. Its main function is to modify, package, and transport proteins and lipids within the cell, and it does not participate in the conversion of glycolate during photorespiration.
- D. Vacuole – Incorrect. Vacuoles mainly store water, nutrients, and waste products, and they do not participate in the metabolic processes of photorespiration.
Q29. The pulmonary volume is an essential part of pulmonary ventilation. It depends upon the:
- A. Physical activity✓
- B. Body volume
- C. Body composition
- D. Composition of air
Explanation: Physical activity – Correct. Pulmonary volume changes depending on physical activity; increased exertion requires higher lung ventilation.
Why the other options are wrong
- B. Body volume – Incorrect. Body size affects lung capacity but does not directly determine pulmonary volume.
- C. Body composition – Incorrect. While muscle and fat distribution can influence breathing mechanics, they do not directly control pulmonary volume.
- D. Composition of air – Incorrect. The composition of air affects gas exchange but does not directly determine pulmonary volume.
Q30. The human brain is different from an animal's brain due to:
- A. The cerebral cortex of the animal's brain is more developed
- B. The cerebral cortex is absent in the human brain
- C. Cerebral cortex is absent in all animals' brains
- D. The cerebral cortex of the human brain is more developed✓
Explanation: The cerebral cortex of the human brain is more developed – Correct. Humans have a highly developed cerebral cortex, responsible for advanced cognitive abilities like reasoning, language, and problem-solving.
Why the other options are wrong
- A. The cerebral cortex of the animal's brain is more developed – Incorrect. The human cerebral cortex is more developed than that of other animals.
- B. The cerebral cortex is absent in the human brain – Incorrect. The cerebral cortex is a major part of the human brain, responsible for higher cognitive functions.
- C. Cerebral cortex is absent in all animals' brains – Incorrect. Many animals have a cerebral cortex, though it is less developed compared to humans.
Q31. Who receives stimuli and conducts impulses to the cell body?
- A. Axon
- B. Dendrites✓
- C. Motor neurons
- D. Sensory neuron
Explanation: Dendrites – Correct. Dendrites receive stimuli from the environment or other neurons and conduct impulses to the cell body.
Why the other options are wrong
- A. Axon – Incorrect. The axon transmits impulses away from the cell body rather than receiving stimuli.
- C. Motor neurons – Incorrect. Motor neurons transmit impulses to muscles and glands, but do not primarily receive stimuli.
- D. Sensory neuron – Incorrect. Sensory neurons detect stimuli but transmit impulses rather than receiving them directly.
Q32. A nerve impulse arriving at the axon terminal causes the opening of:
- A. Calcium channel✓
- B. Potassium channel
- C. Calcium & sodium channels
- D. Chloride channel
Explanation: Calcium channel – Correct. When an impulse reaches the axon terminal, voltage-gated calcium channels open, allowing Ca²⁺ to enter and trigger neurotransmitter release.
Why the other options are wrong
- B. Potassium channel – Incorrect. Potassium channels are involved in repolarization, not neurotransmitter release.
- C. Calcium & sodium channels – Incorrect. Sodium channels are involved in impulse propagation, but only calcium channels trigger neurotransmitter release at the terminal.
- D. Chloride channel – Incorrect. Chloride channels are associated with inhibitory signals rather than impulse transmission.
Q33. The first stable product of the light-independent reaction having 3-carbons is:
- A. 3-phosphoglyceraldehyde
- B. 3-phosphoglyceric acid✓
- C. 1,3-biphosphate glycerate
- D. Dihydroxyacetone phosphate
Explanation: 3-phosphoglyceric acid – Correct. This is the first stable 3-carbon compound formed in the Calvin cycle.
Why the other options are wrong
- A. 3-phosphoglyceraldehyde – Incorrect. This is later formed in the Calvin cycle, but it is not the first stable product.
- C. 1,3-biphosphate glycerate – Incorrect. This is an intermediate and not the first stable product.
- D. Dihydroxyacetone phosphate – Incorrect. This is formed later in the Calvin cycle.
Q34. A disulfide bridge is found in which biomolecule?
- A. Enzyme
- B. Carbohydrate
- C. Protein✓
- D. Lipid
Explanation: Protein is correct because disulfide bonds form between cysteine residues and help stabilize a protein’s shape. These covalent links hold parts of the polypeptide together and strengthen the overall structure.
Why the other options are wrong
- A. Enzyme is not correct because enzymes are simply proteins, and only some of them have disulfide bonds. Disulfide links are present in certain proteins for stability, but they aren’t a universal feature of all enzymes.
- B. Carbohydrate is not correct because carbohydrates don’t form disulfide bonds. They’re linked through glycosidic bonds between sugar units, not sulfur–sulfur links.
- D. Lipids don’t have disulfide bonds. Those bonds form only in proteins, where two cysteine residues link together. Lipids lack the amino acids needed for that kind of sulfur–sulfur connection.
Q35. The number of spinal nerves that originate from the spinal cord:
- A. 24 nerves
- B. 40 nerves
- C. 48 nerves
- D. 62 nerves✓
Explanation: Spinal nerves are 31 pairs (62 total) of mixed nerves in the peripheral nervous system that connect the spinal cord to the rest of the body, carrying motor, sensory, and autonomic signals. They are grouped into five regions: eight cervical, 12 thoracic, five lumbar, five sacral, and one coccygeal pair. Each nerve has a dorsal root (sensory) and a ventral root (motor) that merge to form a mixed nerve trunk.
Why the other options are wrong
- A. 24 nerves – Incorrect. This is far fewer than the actual number.
- B. 40 nerves – Incorrect. The human body has more spinal nerves than this.
- C. 48 nerves – Incorrect. The correct number is higher.
Q36. Which of the following helps in long-term memory in humans?
- A. Cerebrum
- B. Medulla
- C. Cerebellum
- D. Hippocampus✓
Explanation: The hippocampus is a complex brain structure, curved like a seahorse, located deep in the temporal lobe, that is critical for learning and memory, especially for converting short-term memories into long-term ones.
Why the other options are wrong
- A. Cerebrum – Incorrect. The cerebrum processes complex thoughts and voluntary actions, but is not the primary center for long-term memory.
- B. Medulla – Incorrect. The medulla controls autonomic functions like breathing and heart rate, not memory.
- C. Cerebellum – Incorrect. The cerebellum coordinates movement and balance but is not directly responsible for long-term memory.
Q37. The pathway in which water & minerals are stopped by a Casparian strip is known as
- A. Amygdala
- B. Cerebellum
- C. Motor cortex
- D. Occipital lobe
- E. None of the given options✓
Explanation: None of the given options correctly refer to the Casparian strip, which is a structure in plant roots that regulates water and mineral uptake
Why the other options are wrong
- A. Amygdala – Incorrect. The amygdala is involved in emotions and memory, not in water and mineral regulation.
- B. Cerebellum – Incorrect. The cerebellum controls coordination and balance, unrelated to the Casparian strip.
- C. Motor cortex – Incorrect. The motor cortex is responsible for voluntary muscle movements.
- D. Occipital lobe – Incorrect. The occipital lobe processes vision, not mineral transport.
Q38. Nicotine stimulates heart rate, blood pressure, and muscular activity because:
- A. It has excitatory effects on acetylcholine receptors✓
- B. It has inhibitory effects on acetylcholine receptors
- C. It inhibits the synapse between neurons
- D. Causing drop in the heart rate
Explanation: It has excitatory effects on acetylcholine receptors – Correct. Nicotine binds to nicotinic acetylcholine receptors, stimulating the nervous system and increasing heart rate and blood pressure.
Why the other options are wrong
- B. It has inhibitory effects on acetylcholine receptors – Incorrect. Nicotine acts as an agonist, not an inhibitor, of these receptors.
- C. It inhibits the synapse between neurons – Incorrect. Nicotine enhances neurotransmission rather than inhibiting synapses.
- D. Causing a drop in the heart rate – Incorrect. Nicotine increases heart rate rather than decreasing it.
Q39. _Completes the life cycle in two boats snail, sheep, or man
- A. Liver Fluke✓
- B. Snail
- C. Earthworm
- D. Tapeworm
Explanation: Liver Fluke – Correct. The liver fluke (Fasciola) has a complex life cycle involving snails and mammals (e.g., sheep or humans) as hosts.
Why the other options are wrong
- B. Snail – Incorrect. Snails are intermediate hosts for various parasites, but do not complete their life cycle in two hosts.
- C. Earthworm – Incorrect. Earthworms have a simple life cycle without multiple hosts.
- D. Tapeworm – Incorrect. Tapeworms have a different life cycle, often involving a single host or intermediate hosts like cattle or fish.
Q40. Which statement is correct about cnidarians?
- A. They kill the prey with the help of stinging cells✓
- B. They kill the prey with the help of tentacles
- C. They kill the prey with the help of spicules
- D. They kill the prey with the help of barbs
Explanation: They kill the prey with the help of stinging cells – Correct. Cnidarians have specialized stinging cells (nematocysts) in their tentacles that help immobilize prey.
Why the other options are wrong
- B. They kill the prey with the help of tentacles – Incorrect. Tentacles assist in capturing prey, but the actual mechanism involves stinging cells.
- C. They kill the prey with the help of spicules – Incorrect. Spicules are found in sponges, not cnidarians.
- D. They kill the prey with the help of barbs – Incorrect. While nematocysts may contain barbs, the primary function is due to venom release from stinging cells.
Q41. What are the true characteristics of class Anthozoa?
- A. Mesoglea fibrous, predominantly medusoid
- B. Mesoglea cellular, both polyp & medusa
- C. Mesoglea fibrous, polypoid forms only✓
- D. Mesoglea, non-cellular, polypoids form
Explanation: Mesoglea fibrous, polypoid forms only – Correct. Class Anthozoa includes organisms such as corals and sea anemones, which exist only in the polyp stage.
Why the other options are wrong
- A. Mesoglea fibrous, predominantly medusoid – Incorrect. Anthozoans exist only in polyp form, not medusoid.
- B. Mesoglea cellular, both polyp & medusa – Incorrect. Anthozoans lack the medusa stage.
- D. Mesoglea, non-cellular, polypoids form – Incorrect. While Anthozoans have a polyp stage, their mesoglea structure is fibrous rather than purely non-cellular.
Q42. Common characteristics of Hirudinaria are:1. Setae & parapodia absent 2. Setae are present but parapodia absent 3. Blood suckers are present
- A. 1, 2 & 3
- B. 1 & 3✓
- C. 1 & 2
- D. 2 & 3
Explanation: 1 & 3 – Correct. Hirudinaria (a genus of leeches) lacks setae and parapodia and is a blood-sucking annelid.
Why the other options are wrong
- A. 1, 2 & 3 – Incorrect. Setae are absent in Hirudinaria, making statement 2 incorrect.
- C. 1 & 2 – Incorrect. If setae are absent (statement 1), then statement 2 contradicts it.
- D. 2 & 3 – Incorrect. Setae are completely absent, making statement 2 incorrect.
Q43. The flatworm that is the endoparasite of humans:
- A. Dugesia
- B. Fasciola
- C. Taenia✓
- D. Hydra
Explanation: Taenia – Correct. Taenia (tapeworm) is an endoparasite that resides in the human intestines.
Why the other options are wrong
- A. Dugesia – Incorrect. Dugesia is a free-living flatworm, not an endoparasite.
- B. Fasciola – Incorrect. Fasciola (liver fluke) is a parasite, but mainly infects sheep and cattle, not primarily humans.
- D. Hydra – Incorrect. Hydra is a freshwater cnidarian, not a flatworm or parasite.
Q44. Which statement about enzymes is essential to the lock & key hypothesis?
- A. Enzyme molecules each have a distinct shape✓
- B. Enzyme molecules are catalysts
- C. Enzyme molecules can be damaged by high temperature
- D. Enzyme molecules can be damaged by high pH value
Explanation: Enzyme molecules each have a distinct shape – Correct. The lock and key hypothesis states that enzymes have specific active sites complementary to their substrates.
Why the other options are wrong
- B. Enzyme molecules are catalysts – Incorrect. While true, this does not define the lock & key hypothesis.
- C. Enzyme molecules can be damaged by high temperature – Incorrect. This relates to enzyme denaturation, not the lock & key model.
- D. Enzyme molecules can be damaged by high pH value – Incorrect. High pH affects enzyme activity but is unrelated to substrate specificity.
Q45. The oxygen transported through blood plasma is about:
- A. 1%
- B. 3%✓
- C. 5%
- D. 7%
Explanation: 3% – Correct. Around 3% of oxygen is dissolved in plasma, while the majority is bound to hemoglobin in red blood cells.
Why the other options are wrong
- A. 1% – Incorrect. This underestimates the amount of oxygen dissolved in plasma, which is actually around 3% of the total oxygen in the blood.
- C. 5% – Incorrect. This overestimates the fraction of oxygen dissolved in plasma, which is closer to 3% of the total oxygen in the blood.
- D. 7% – Incorrect. The actual amount of oxygen dissolved in plasma is about 3%, so 7% is an overestimation.
Q46. Penicillin is a kind of antibiotic that works as
- A. Resistor
- B. Uncompetitive inhibitor
- C. Non-competitive inhibitor
- D. Competitive inhibitor✓
Explanation: Penicillin is classified as a competitive inhibitor because it competes with the substrate for binding to the active site of the bacterial enzyme transpeptidase, which is crucial for cell wall synthesis. By occupying the active site, penicillin prevents the substrate from binding, effectively inhibiting the enzyme's activity and leading to the death of the bacteria.The other options are incorrect for the following reasons:Resistor: This term is not related to enzyme kinetics or inhibition and thus does not apply.Uncompetitive inhibitor: This type of inhibitor only binds to the enzyme-substrate complex, which does not represent how penicillin functions.Non-competitive inhibitor: Non-competitive inhibitors can bind to both the free enzyme and the enzyme-substrate complex, but penicillin specifically competes for the active site, which is characteristic of competitive inhibition.
Why the other options are wrong
- A. Resistor – Incorrect. The term 'resistor' does not apply to enzyme inhibition and is irrelevant in this context.
- B. Uncompetitive inhibitor – Incorrect. Uncompetitive inhibitors bind exclusively to the enzyme-substrate complex, which does not describe the mechanism of penicillin.
- C. Non-competitive inhibitor – Incorrect. Non-competitive inhibitors can bind to both the enzyme and the enzyme-substrate complex, but penicillin specifically competes with the substrate for the active site of the enzyme.
Q47. All of the following are examples of polysynaptic transmissions except:
- A. Heartbeat
- B. Breathing
- C. Knee jerk✓
- D. Playing games
Explanation: The knee-jerk reflex, also known as the patellar reflex, is an involuntary and rapid kick of the lower leg in response to a tap on the patellar tendon. This stretch reflex is initiated by sensory neurons that detect the stretch in the quadriceps muscle, sending a signal to the spinal cord, which then sends a signal back to the muscle to contract and cause the leg to extend. The reflex is a monosynaptic reflex arc, meaning it involves a direct connection between a sensory and a motor neuron and occurs without brain involvement.
Why the other options are wrong
- A. Heartbeat – Incorrect. The heartbeat is regulated by autonomic pathways, involving multiple synapses.
- B. Breathing – Incorrect. Breathing is controlled by the brainstem and involves polysynaptic pathways.
- D. Playing games – Incorrect. Complex voluntary movements require multiple synapses, making them polysynaptic.
Q48. The cells which do not secrete/stimulate antibodies:
- A. T lymphocytes✓
- B. B lymphocytes
- C. T Helper cells
- D. None of these
Explanation: T lymphocytes – Correct. T cells do not produce antibodies; instead, they help regulate immune responses.
Why the other options are wrong
- B. B lymphocytes – Incorrect. B cells differentiate into plasma cells, which secrete antibodies.
- C. T Helper cells – Incorrect. Although T helper cells do not directly secrete antibodies, they stimulate B cells to produce them.
- D. This is not a correct option, as we have the answer within the given options.
Q49. Use & disuse of the postulate of organs was given by:
- A. Darwin
- B. Wallace
- C. Weismann
- D. Lamarck✓
Explanation: Lamarck – Correct. Lamarck's theory of evolution suggested that organs develop or diminish based on their usage.
Why the other options are wrong
- A. Darwin – Incorrect. Darwin proposed the theory of natural selection, not use and disuse
- B. Wallace – Incorrect. Wallace co-developed the idea of natural selection with Darwin, but did not propose the use and disuse concept.
- C. Weismann – Incorrect. Weismann rejected the inheritance of acquired traits and disproved Lamarck's theory.
Q50. All the living entities are created by God, the theory named as:
- A. Theory of natural selection
- B. Theory of survival of fittest
- C. Theory of inheritance of acquired characters
- D. Theory of special creation✓
Explanation: Theory of special creation – Correct. This theory states that all living beings were created by a divine power.The theory of special creation is a theological doctrine stating that the universe and all life were created in their current forms by a divine power, or God. This view posits that species were created individually and are not related to one another through evolution, but rather through a supernatural event. It is a religious belief, not a scientific one, and is contradicted by scientific evidence like the fossil record and genetic studies.
Why the other options are wrong
- A. Theory of natural selection – Incorrect. This theory explains evolution based on environmental adaptation, not divine creation.
- B. Theory of survival of fittest – Incorrect. This phrase, coined by Herbert Spencer, supports Darwin’s theory, not creationism.
- C. Theory of inheritance of acquired characters – Incorrect. This is Lamarck’s theory, unrelated to divine creation.
Q51. Choose the correct flow of impulse transmission in the human heart:
- A. AV node - SA node - Bundle of His - Purkinje fibers
- B. SA node - AV node - Bundle of His - Purkinje fibers✓
- C. SA node - AV node - Purkinje fibers - Bundle of His
- D. AV node - SA node - Purkinje fibers - Bundle of His
Explanation: SA node - AV node - Bundle of His - Purkinje fibers – Correct. The correct conduction pathway is: SA node → AV node → Bundle of His → Purkinje fibers.
Why the other options are wrong
- A. AV node - SA node - Bundle of His - Purkinje fibers – Incorrect. The SA node, not the AV node, initiates the impulse.
- C. SA node - AV node - Purkinje fibers - Bundle of His – Incorrect. Purkinje fibers come after the Bundle of His, not before.
- D. AV node - SA node - Purkinje fibers - Bundle of His – Incorrect. The SA node is the pacemaker and should come first.
Q52. A bone that lies in between the skull & postcranial skeleton is:
- A. Hyoid bone✓
- B. Incus bone
- C. Malleus bone
- D. Stapes bone
Explanation: Hyoid bone – Correct. The hyoid bone is located in the throat region and serves as a connection between the skull and the postcranial skeleton.
Why the other options are wrong
- B. Incus bone – Incorrect. The incus is a middle ear bone, not a connecting bone between the skull and the postcranial skeleton.
- C. Malleus bone – Incorrect. The malleus is also part of the middle ear.
- D. Stapes bone – Incorrect. The stapes, the smallest bone in the human body, is part of the middle ear, not a connecting bone between the skull and postcranial skeleton.
Q53. Which of the following is not a non-specific immune response?
- A. HCl
- B. T Cells✓
- C. Mucus
- D. Spermine
Explanation: T Cells – Correct. T cells are part of the adaptive immune system, providing specific immunity, not non-specific immunity.
Why the other options are wrong
- A. HCl – Incorrect. Hydrochloric acid in the stomach is a nonspecific defense mechanism that kills pathogens.
- C. Mucus – Incorrect. Mucus traps pathogens and is part of the innate (non-specific) immune system.
- D. Spermine – Incorrect. Spermine is an antimicrobial compound found in semen that helps non-specific immune defense.
Q54. The system that returns lost blood back from the body to the circulatory system is:
- A. Lymphatic system✓
- B. Digestive system
- C. Cardiovascular system
- D. Immune system
Explanation: Lymphatic system – Correct. The lymphatic system collects excess interstitial fluid and returns it to the bloodstream, preventing fluid accumulation.
Why the other options are wrong
- B. Digestive system – Incorrect. The digestive system is responsible for food breakdown and absorption, not blood drainage.
- C. Cardiovascular system – Incorrect. The cardiovascular system circulates blood but does not drain excess fluid back into the circulatory system.
- D. Immune system – Incorrect. The immune system fights infections but does not directly drain fluids into the circulatory system.
Q55. The most abundant type of WBC that reach rapidly at the site of infection are:
- A. Neutrophils✓
- B. Macrophages
- C. Basophils
- D. Lymphocytes
Explanation: Neutrophils – Correct. Neutrophils are the most abundant white blood cells and are the first responders to infections.
Why the other options are wrong
- B. Macrophages – Incorrect. Macrophages are important in immune response, but act later than neutrophils.
- C. Basophils – Incorrect. Basophils are involved in allergic reactions, not rapid infection response.
- D. Lymphocytes – Incorrect. Lymphocytes (T and B cells) provide adaptive immunity, which is slower than neutrophil response.
Q56. The example of carnivorous plants is:
- A. Funaria
- B. Polypodium glycyrrhiza
- C. Pinus
- D. Dionaea muscipula✓
Explanation: Dionaea muscipula – Correct. Also known as the Venus flytrap, this plant captures and digests insects. Dionaea muscipula is the scientific name for the Venus flytrap, a famous carnivorous plant known for its unique, bivalve-like traps that snap shut to capture and digest insects.
Why the other options are wrong
- A. Funaria – Incorrect. It is a type of moss, not a carnivorous plant. Funaria is a genus of mosses, commonly known as "cord moss" due to the characteristic twisted seta (stalk) of its sporophyte. It is a widespread bryophyte found in moist, shady environments globally and is a model organism for studying the life cycle of non-vascular plants.
- B. Polypodium glycyrrhiza – Incorrect. This is a type of fern, not a carnivorous plant. Polypodium glycyrrhiza is the scientific name for the liquorice fern (also known as many-footed fern or sweet root), an evergreen fern native to western North America, from Alaska to California. It is known for its creeping, reddish-brown rhizomes that have a distinct sweet, liquorice-like flavour.
- C. Pinus – Incorrect. It is a pine tree and not carnivorous. Pinus is the scientific name for the genus that includes all species of pine trees and shrubs. These evergreen conifers (family Pinaceae) are economically and ecologically important, known for their needle-like leaves, woody cones, and resinous wood.
Q57. The Casparian strip is present in:
- A. Epidermis layer
- B. Endodermis layer✓
- C. Xylem layer
- D. Phloem layer
Explanation: Endodermis layer – Correct. The Casparian strip is a waterproof barrier in the endodermis that controls water and nutrient flow into the vascular system.
Why the other options are wrong
- A. Epidermis layer – Incorrect. The epidermis is the outermost layer of plant tissue, not where the Casparian strip is found.
- C. Xylem layer – Incorrect. The xylem transports water but does not contain the Casparian strip.
- D. Phloem layer – Incorrect. The phloem transports nutrients but does not contain the Casparian strip.
Q58. The thoracic cavity is separated from the abdominal region by:
- A. Peritoneum membrane
- B. Mucous membrane
- C. Diaphragm✓
- D. Mediastinum
Explanation: Diaphragm – Correct. The diaphragm is a muscular partition that separates the thoracic and abdominal cavities.
Why the other options are wrong
- A. Peritoneum membrane – Incorrect. The peritoneum lines the abdominal cavity and covers abdominal organs, but it does not separate the abdominal cavity from the thoracic cavity.
- B. Mucous membrane – Incorrect. Mucous membranes line various body cavities and passages, but they do not act as a structural barrier between major body cavities.
- D. Mediastinum – Incorrect. The mediastinum is the central compartment of the thoracic cavity, not a divider between the thoracic and abdominal cavities.
Q59. The boiling point of water in the Kelvin scale is:
- A. 0 K
- B. 273 K
- C. 32 K
- D. 373 K✓
Explanation: 373 K – Correct. Water boils at 100°C, which equals 373 K.
Why the other options are wrong
- A. 0 K – Incorrect. 0 Kelvin is absolute zero, the lowest theoretical temperature.
- B. 273 K – Incorrect. This is the freezing point of water in Kelvin.
- C. 32 K – Incorrect. 32°F is the freezing point of water in Fahrenheit, not Kelvin.
Q60. Atomic Mass Unit (AMU) is equal to:
- A. Mass of one atom of H
- B. Equal to the mass of an electron
- C. 1.66 × 10-27 kg✓
- D. 1.66 × 10⁻²⁸ g
Explanation: The correct answer is 1.66 × 10-27 kg, which represents the mass of one atomic mass unit (AMU). This unit is used to express the mass of atomic and subatomic particles. 1 AMU is defined as one twelfth of the mass of an unbound neutral atom of carbon-12, and it is approximately equal to the mass of a proton or neutron. The other options are incorrect for the following reasons:Mass of one atom of H: While hydrogen's mass is close to 1 AMU, this option does not accurately reflect the definition of AMU, which is based on carbon-12.Equal to the mass of an electron: The mass of an electron is much smaller than that of protons and neutrons, and thus does not represent the AMU.1.66 × 10⁻²⁸ g: Although this numerical value is close, it is incorrect because AMU is conventionally expressed in kilograms, and the correct value is 1.66 × 10⁻²⁴ kg.
Why the other options are wrong
- A. Mass of one atom of H – Incorrect. Although hydrogen's mass is approximately 1 AMU, this option overlooks that AMU is defined relative to the mass of a carbon-12 atom, not just hydrogen.
- B. Equal to the mass of an electron – Incorrect. The mass of an electron is significantly smaller (~9.11 × 10⁻³¹ kg) and does not represent the AMU, which is concerned with the mass of protons and neutrons.
- D. 1.66 × 10⁻²⁸ g – Incorrect. Although this value is numerically close, the standard SI unit for atomic mass is kg, and the accurate conversion shows that 1 AMU = 1.66 × 10⁻²⁴ kg.
Q61. The average distance covered by the gas molecule between successive collisions is known as:
- A. Free path
- B. Mean free path✓
- C. Total free path
- D. Total path
Explanation: Mean free path – Correct. The mean free path is the average distance a gas molecule travels before colliding with another molecule.
Why the other options are wrong
- A. Free path – Incorrect. "Free path" alone does not specify an average value; it is just a general term.
- C. Total free path – Incorrect. The total free path would refer to the sum of all distances traveled, not an average.
- D. Total path – Incorrect. This term is not used in kinetic theory to describe molecular motion.
Q62. The gas law in which the pressure is kept constant is known as:
- A. Boyle’s Law
- B. Charles’s Law✓
- C. Dalton’s Law
- D. Graham’s Law
Explanation: Charles’s Law – Correct. Charles’s Law states that at constant pressure, the volume of a gas is directly proportional to its temperature (V/T = constant).
Why the other options are wrong
- A. Boyle’s Law – Incorrect. Boyle’s Law states that at constant temperature, the pressure and volume of a gas are inversely related (PV = constant).
- C. Dalton’s Law – Incorrect. Dalton’s Law deals with partial pressures of gases in a mixture.
- D. Graham’s Law – Incorrect. Graham’s Law describes the rate of diffusion of gases, not pressure-volume relationships.
Q63. The pressure 14.7 psi is equal to:
- A. 1 torr
- B. 1 pascal
- C. 1 atm✓
- D. 1 Nm
Explanation: 1 atm – Correct. 14.7 psi is equivalent to 1 atm (atmosphere) of pressure.
Why the other options are wrong
- A. 1 torr – Incorrect. 1 torr is equal to 1/760 of an atm, while 14.7 psi = 1 atm.
- B. 1 pascal – Incorrect. 1 pascal (Pa) is very small, and 14.7 psi equals 101,325 Pa (1 atm).
- D. 1 Nm – Incorrect. Newton-meter (Nm) is a unit of torque, not pressure
Q64. A magnetic field exerts a force on a charged particle:
- A. If the particle is moving across the field lines✓
- B. If the particle is moving along the field lines
- C. If the particle is at rest
- D. Always experiences force
Explanation: If the particle is moving across the field lines – Correct. A charged particle moving perpendicular to the field lines experiences a Lorentz force, given by F = q(v × B).
Why the other options are wrong
- B. If the particle is moving along the field lines – Incorrect. If the velocity is parallel to the magnetic field, the force is zero because sin(0°) = 0.
- C. If the particle is at rest – Incorrect. No force acts on a stationary charge in a magnetic field, as velocity is zero (v = 0).
- D. Always experiences force – Incorrect. A charged particle in a magnetic field only experiences force if it moves perpendicularly or at an angle to the field lines.
Q65. When the magnetic field and area vector are perpendicular, the magnetic flux will be
- A. Zero✓
- B. Minimum
- C. Maximum
- D. Optimum
Explanation: Zero – Correct. Magnetic flux is given by Φ = B A cos(θ), and when θ = 90°, cos(90°) = 0, so the flux is zero.
Why the other options are wrong
- B. Minimum – Incorrect. The minimum flux could still be nonzero, but at 90°, it is exactly zero.
- C. Maximum – Incorrect. Flux is maximum when the field is parallel to the area vector (θ = 0°).
- D. Optimum – Incorrect. "Optimum" is vague and does not describe flux behavior mathematically.
Q66. A coil of 600 turns is threaded by a magnetic flux of 8 webers. If this flux is reduced to 5 webers in 3 seconds, the induced EMF in the coil will be:
- A. 600V✓
- B. 700V
- C. 800V
- D. 900V
Explanation: 600V – Correct. The correct induced EMF calculated is 600V. Using Faraday’s Law:E=−N ΔΦ/ΔtE=−600×(5−8)/3E=−600×−3/3 =600V
Why the other options are wrong
- B. 700V – Incorrect. This does not match the correct calculation.
- C. 800V – Incorrect. The EMF is overestimated.
- D. 900V – Incorrect. The EMF is lower than this value.
Q67. A generator supplies 100V to the primary coil of a transformer. The primary has 150 turns, and the secondary has 500 turns. The secondary voltage is:
- A. 700V
- B. 333V✓
- C. 900V
- D. 1000V
Explanation: Using the transformer formula:Vs/Vp=Ns/NpVs=Vp×Ns/NpVs=100×500/150Vs=100×3.33=333V
Why the other options are wrong
- A. This is not correct as per the explanations.Using the transformer formula:Vs/Vp=Ns/NpVs=Vp×Ns/NpVs=100×500/150Vs=100×3.33=333V
- C. This is not correct as per the explanations.Using the transformer formula:Vs/Vp=Ns/NpVs=Vp×Ns/NpVs=100×500/150Vs=100×3.33=333V
- D. This is not correct as per the explanations.Using the transformer formula:Vs/Vp=Ns/NpVs=Vp×Ns/NpVs=100×500/150Vs=100×3.33=333V
Q68. The force responsible for binding the nucleus is:
- A. Coulomb's force
- B. Newton force
- C. Weak Nuclear force
- D. Strong Nuclear force✓
Explanation: Strong Nuclear force – Correct: This is the fundamental force that holds protons and neutrons together in the nucleus, overcoming the repulsive Coulomb force between protons.
Why the other options are wrong
- A. Coulomb's force – Incorrect: This force acts between charged particles, but it repels protons in the nucleus rather than binding them.
- B. Newton force – Incorrect: Newtonian gravitational force is too weak to have any significant effect at the nuclear scale.
- C. Weak Nuclear force – Incorrect: The weak nuclear force is responsible for certain types of radioactive decay (e.g., beta decay) but does not bind the nucleus.
Q69. When two negative beta particles are emitted from a nucleus, then the mass number:
- A. No change✓
- B. Increases by 1
- C. Increases by 2
- D. Increases by 3
Explanation: No change – Correct: Beta decay occurs when a neutron converts into a proton and an electron (beta particle). While the atomic number increases by 1 per beta emission, the mass number remains unchanged since a neutron is simply replaced by a proton. Emitting two beta particles means two neutrons have turned into protons, but the total nucleon count (mass number) stays the same.
Why the other options are wrong
- B. Increases by 1 – Incorrect: The atomic number increases, but the mass number does not change.
- C. Increases by 2 – Incorrect: The mass number remains unchanged because the number of nucleons is conserved.
- D. Increases by 3 – Incorrect: Mass number does not change due to beta decay.
Q70. A 40g radioactive material is placed in a chamber, having a half-life of 20 days. How much will be left after 80 days:
- A. 40gm
- B. 20gm
- C. 5gm
- D. 2.5gm✓
Explanation: Correct. Here's the calculation:Calculate the number of half-lives:Total time elapsed = 80 daysHalf-life = 20 daysNumber of half-lives = 80 days / 20 days = 4 half-livesCalculate the remaining mass:After 1 half-life: 40g / 2 = 20gAfter 2 half-lives: 20g / 2 = 10gAfter 3 half-lives: 10g / 2 = 5gAfter 4 half-lives: 5g / 2 = 2.5gTherefore, 2.5g of the radioactive material will be left after 80 days.
Why the other options are wrong
- A. This would only be true if no time had passed.
- B. This would be true after one half-life.
- C. 5 gm remains after 3 half-lives, hence it is incorrect.
Q71. Which of the following electromagnetic radiation has the highest penetrating power?
- A. Alpha rays
- B. Beta rays
- C. Gamma rays✓
- D. Proton rays
Explanation: Gamma rays – Correct: Gamma rays are highly penetrating and require thick lead or concrete shielding to stop them.
Why the other options are wrong
- A. Alpha rays – Incorrect: Alpha particles have very low penetrating power and can be stopped by a sheet of paper or even human skin.
- B. Beta rays – Incorrect: Beta particles penetrate further than alpha particles but can be stopped by a thin layer of aluminum.
- D. Proton rays – Incorrect: Protons, being massive charged particles, do not penetrate as deeply as gamma rays.
Q72. The skin cancer can be caused by :
- A. Alpha radiation
- B. Beta radiation
- C. Gamma radiation
- D. Ultraviolet radiation✓
Explanation: Ultraviolet radiation – Correct: UV radiation from the sun or artificial sources is the main cause of skin cancer, as it can directly damage DNA in skin cells.
Why the other options are wrong
- A. Alpha radiation – Incorrect: Alpha particles do not penetrate the skin deeply and are not a significant cause of skin cancer.
- B. Beta radiation – Incorrect: Beta particles can cause surface damage but are not the main cause of skin cancer.
- C. Gamma radiation – Incorrect: Gamma rays can cause deep tissue damage and mutations but are not the primary cause of skin cancer.
Q73. The speed of light in the vacuum is the same for all observers regardless of their relative motion or the motion of the source of the light", is the important postulate of:
- A. Special conductivity
- B. Special resistivity
- C. Special theory of relativity✓
- D. General theory of relativity
Explanation: Special theory of relativity – Correct: Einstein’s special theory of relativity states that the speed of light is constant for all observers, regardless of their motion or the motion of the source.
Why the other options are wrong
- A. Special conductivity – Incorrect: There is no such physical concept related to relativity.
- B. Special resistivity – Incorrect: This term does not relate to Einstein’s postulates.
- D. General theory of relativity – Incorrect: The general theory of relativity deals with gravity and spacetime curvature, not the constancy of light speed.
Q74. The process of converting an alternating current waveform into a direct current waveform is referred to as:
- A. Amplification
- B. Attenuation
- C. Filtration
- D. Rectification✓
Explanation: Rectification – Correct: Rectification is the process of converting AC to DC, typically using diodes.
Why the other options are wrong
- A. Amplification – Incorrect: Amplification increases the strength of a signal but does not convert AC to DC.
- B. Attenuation – Incorrect: Attenuation refers to the reduction in signal strength over distance.
- C. Filtration – Incorrect: Filtration removes unwanted components from a signal but does not convert AC to DC.
Q75. Consider three-point charges A, B, and C as shown in the figure. If the resultant force on charge A due to charge B and charge C is 0.024 N, the direction of resultant force will be:
- A. Towards Charge A
- B. Towards Charge B
- C. Towards Charge C
- D. Vertical to the surface the charges are placed✓
Explanation: Vertical to the surface the charges are placed – Correct (likely): In many charge configurations, the resultant force has components in multiple directions, leading to a vertical resultant force. However, the exact answer depends on the charge arrangement in the missing figure.
Why the other options are wrong
- A. Towards Charge A – Incorrect: The net force cannot be directed toward the charge experiencing it.
- B. Towards Charge B – Incorrect: The direction of force depends on charge interactions; without the figure, this cannot be assumed.
- C. Towards Charge C – Incorrect: The force may not necessarily point toward one charge alone.
Q76. The emf induced in a closed circuit is directly proportional to the rate of change of magnetic flux passing through the circuit" refers to:
- A. Lenz's law
- B. Faraday's law of electromagnetic induction✓
- C. Coulomb's law
- D. Ohm's law
Explanation: Faraday's law of electromagnetic induction – Correct: Faraday’s law states that the induced emf in a closed circuit is directly proportional to the rate of change of magnetic flux through the circuit.
Why the other options are wrong
- A. Lenz's law – Incorrect: Lenz's law states that the direction of induced current opposes the change in magnetic flux, but it does not define the proportionality of emf to flux change.
- C. Coulomb's law – Incorrect: Coulomb’s law describes the electrostatic force between two charged particles, unrelated to electromagnetic induction.
- D. Ohm's law – Incorrect: Ohm’s law relates voltage, current, and resistance but does not deal with electromagnetic induction.
Q77. A javelin is thrown by Arshad Nadeem at a projection angle of 45 degrees with an initial velocity of 30 m/s, the range of the javelin will be: (Consider g = 10 m/s²):
- A. 85m
- B. 90m✓
- C. 95m
- D. 100m
Explanation: Correct. Here's the calculation:Range formula for projectile motion:Range (R) = (v₀² * sin(2θ)) / gWhere:v₀ = initial velocity (30 m/s)θ = projection angle (45 degrees)g = acceleration due to gravity (10 m/s²)Calculate sin(2θ):sin(2 * 45°) = sin(90°) = 1Calculate the range:R = (30² * 1) / 10 = 900 / 10 = 90 m
Why the other options are wrong
- A. This is not correct as per the formula Range (R) = (v₀² * sin(2θ)) / g.
- C. This is not correct as per the formula Range (R) = (v₀² * sin(2θ)) / g.
- D. This is not correct as per the formula Range (R) = (v₀² * sin(2θ)) / g.
Q78. If a pendulum completes one cycle in half a second, its frequency is
- A. 1 Hz
- B. 2 Hz✓
- C. 3 Hz
- D. 4 Hz
Explanation: Correct. Here's the calculation:Relationship between frequency and period:Frequency (f) = 1 / Period (T)Where:f = frequency (Hz)T = period (seconds)Given period:T = 0.5 secondsCalculate frequency:f = 1 / 0.5 = 2 Hz
Why the other options are wrong
- A. This is not correct as per the formula Frequency (f) = 1 / Period (T).
- C. This is not correct as per the formula Frequency (f) = 1 / Period (T).
- D. This is not correct as per the formula Frequency (f) = 1 / Period (T).
Q79. The SI unit of electric charge is
- A. Ohm
- B. Farad
- C. Coulomb✓
- D. Ampere
Explanation: Coulomb – Correct: Coulomb (C) is the SI unit of electric charge, defined as the charge transported by a current of one ampere in one second.
Why the other options are wrong
- A. Ohm – Incorrect: Ohm (Ω) is the SI unit of electrical resistance, not charge.
- B. Farad – Incorrect: Farad (F) is the SI unit of capacitance, which measures a capacitor’s ability to store charge.
- D. Ampere – Incorrect: Ampere (A) is the SI unit of electric current, not charge.
Q80. At a stop light, a truck traveling at 15 m/s passes a car as it starts from rest. The truck travels at constant velocity, and the car accelerates at 3 m/s². How much time does the car take to catch up to the truck?
- A. 5 s
- B. 15 s
- C. 10 s✓
- D. 20 s
Explanation: Correct. Here's the calculation:Distance traveled by the truck:Distance_truck = velocity_truck * timeDistance_truck = 15t (where t is the time taken)Distance traveled by the car:Distance_car = initial_velocity_car * t + (1/2) * acceleration_car * t²Distance_car = 0 * t + (1/2) * 3 * t²Distance_car = 1.5t²When the car catches up, the distances are equal:Distance_truck = Distance_car15t = 1.5t²Solve for t:1.5t² - 15t = 01.5t(t - 10) = 0t = 0 (initial time) or t = 10 sTherefore the time taken is 10 seconds
Why the other options are wrong
- A. This option is incorrect according to the equations of motion.
- B. This option is incorrect according to the equations of motion.
- D. This option is incorrect according to the equations of motion.
Q81. A ball is in free fall. Its acceleration is:
- A. Downward during both ascent and descent✓
- B. Downward during ascent and upward during descent
- C. Upward during ascent and downward during descent
- D. Upward during both ascent and descent
Explanation: In free fall, the only force acting on the ball is gravity, which always points downward. Whether the ball is moving up or down, its acceleration due to gravity remains constant at 9.8 m/s² downward.
Why the other options are wrong
- B. This is incorrect because acceleration due to gravity does not change direction. It is always directed downward, regardless of whether the object is moving up or down.
- C. This suggests that acceleration reverses direction, which is incorrect. Gravity does not push the ball upward during ascent; instead, it slows the upward motion and then pulls the ball back down.
- D. This is incorrect because acceleration due to gravity is always directed downward. If acceleration were upward, the object would continue to rise instead of falling.
Q82. Which one of the following statements is correct for an object released from rest?
- A. The average velocity during the first second of time is 4.9 m/s✓
- B. During each second, the object falls 9.8 m
- C. The acceleration changes by 9.8 m/s² every second
- D. The object falls 9.8 m during the first second of time
Explanation: Since the object starts from rest and gains velocity due to gravity, its average velocity during the first second is 4.9 m/s.Given:The object is released from rest, so u=0 m/s Step 1: Motion under gravitySince the object is released from rest and falls freely, It is accelerating due to gravity, g=9.8 m/s^2 Step 2: Velocity after 1 secondUsing the equation of motion:v=u+(g)(t)v=0+9.8(1)=9.8 m/s The final velocity is 9.8 m/s downward.Step 3: Average velocityFor uniform acceleration, the average velocity is:v(avg)=(u+v)/2v(avg)=0+9.8/2 =4.9 m/s
Why the other options are wrong
- B. The object falls increasing distances each second due to acceleration. It does not fall 9.8 m in every second; instead, it falls progressively larger distances.
- C. Acceleration due to gravity remains constant at 9.8 m/s² and does not change over time.
- D. The actual distance fallen in the first second is 4.9 m, not 9.8 m. The 9.8 m refers to the velocity gained, not the distance covered.
Q83. Three persons X, Y, and Z wore pants of blue, khaki, and grey colors (not necessarily in this order) and shirts of white, blue, and pink colors (not necessarily in this order). No one wore pants and shirts of the same color.i. X did not wear a shirt of white color.ii. Y did not wear a shirt of blue color.iii. Z did not wear a shirt of pink color.iv. Y did not wear pants of blue color.v. Z wears pants of khaki color.What were the colors of pants and shirts (respectively) worn by X?
- A. Blue and pink✓
- B. Khaki and pink
- C. Green and blue
- D. Khaki and white
Explanation: A. Let's analyze the given conditions step by step:Given pants colors: Blue, Khaki, and Grey.Given shirt colors: White, Blue, and Pink.Z wears khaki pants.No one wore pants and shirts of the same color.Now, let's determine the shirt color for Z:Z did not wear a pink shirt (Condition iii).Since Z is already wearing khaki pants, he cannot wear a khaki shirt (not allowed).The remaining options for Z's shirt are white or blue.Now, let's determine Y’s pants color:Y did not wear blue pants (Condition iv).Since Z already took khaki pants, Y must have grey pants.Now, let’s determine Y’s shirt:Y did not wear a blue shirt (Condition ii).Y’s pants are grey, so he cannot wear a grey shirt.The remaining options for Y’s shirt are white or pink.Now, let's determine X’s clothing:X did not wear a white shirt (Condition i).The only remaining pants color for X is blue (since Z has khaki and Y has grey).X cannot wear a blue shirt (since no one can wear the same color pants and shirt).The only remaining shirt color for X is pink.Thus, X wore blue pants and a pink shirt.
Why the other options are wrong
- B. This is not correct as per the explanations.A. Let's analyze the given conditions step by step:Given pants colors: Blue, Khaki, and Grey.Given shirt colors: White, Blue, and Pink.Z wears khaki pants.No one wore pants and shirts of the same color.Now, let's determine the shirt color for Z:Z did not wear a pink shirt (Condition iii).Since Z is already wearing khaki pants, he cannot wear a khaki shirt (not allowed).The remaining options for Z's shirt are white or blue.Now, let's determine Y’s pants color:Y did not wear blue pants (Condition iv).Since Z already took khaki pants, Y must have grey pants.Now, let’s determine Y’s shirt:Y did not wear a blue shirt (Condition ii).Y’s pants are grey, so he cannot wear a grey shirt.The remaining options for Y’s shirt are white or pink.Now, let's determine X’s clothing:X did not wear a white shirt (Condition i).The only remaining pants color for X is blue (since Z has khaki and Y has grey).X cannot wear a blue shirt (since no one can wear the same color pants and shirt).The only remaining shirt color for X is pink.Thus, X wore blue pants and a pink shirt.
- C. This is not correct as per the explanations.A. Let's analyze the given conditions step by step:Given pants colors: Blue, Khaki, and Grey.Given shirt colors: White, Blue, and Pink.Z wears khaki pants.No one wore pants and shirts of the same color.Now, let's determine the shirt color for Z:Z did not wear a pink shirt (Condition iii).Since Z is already wearing khaki pants, he cannot wear a khaki shirt (not allowed).The remaining options for Z's shirt are white or blue.Now, let's determine Y’s pants color:Y did not wear blue pants (Condition iv).Since Z already took khaki pants, Y must have grey pants.Now, let’s determine Y’s shirt:Y did not wear a blue shirt (Condition ii).Y’s pants are grey, so he cannot wear a grey shirt.The remaining options for Y’s shirt are white or pink.Now, let's determine X’s clothing:X did not wear a white shirt (Condition i).The only remaining pants color for X is blue (since Z has khaki and Y has grey).X cannot wear a blue shirt (since no one can wear the same color pants and shirt).The only remaining shirt color for X is pink.Thus, X wore blue pants and a pink shirt.
- D. This is not correct as per the explanations.A. Let's analyze the given conditions step by step:Given pants colors: Blue, Khaki, and Grey.Given shirt colors: White, Blue, and Pink.Z wears khaki pants.No one wore pants and shirts of the same color.Now, let's determine the shirt color for Z:Z did not wear a pink shirt (Condition iii).Since Z is already wearing khaki pants, he cannot wear a khaki shirt (not allowed).The remaining options for Z's shirt are white or blue.Now, let's determine Y’s pants color:Y did not wear blue pants (Condition iv).Since Z already took khaki pants, Y must have grey pants.Now, let’s determine Y’s shirt:Y did not wear a blue shirt (Condition ii).Y’s pants are grey, so he cannot wear a grey shirt.The remaining options for Y’s shirt are white or pink.Now, let's determine X’s clothing:X did not wear a white shirt (Condition i).The only remaining pants color for X is blue (since Z has khaki and Y has grey).X cannot wear a blue shirt (since no one can wear the same color pants and shirt).The only remaining shirt color for X is pink.Thus, X wore blue pants and a pink shirt.
Q84. Look carefully at the sequence of symbols to find the pattern. Select the correct pattern:
- A. Option A
- B. Option B✓
- C. Option C
- D. Option D
Explanation: This is the correct sequence because the diagrams in the image are moving backwards.
Why the other options are wrong
- A. This is not the correct sequence, as the diagrams should move backward.
- C. This is not the correct sequence, as the diagrams should be moving backward according to the given question.
- D. This is not the correct sequence, as the diagrams should be moving backward as per the question.
Q85. Statements:All men are hardworking.Some men are kings.Conclusions: I. All men are kings. II. All kings are hardworking.Based on the above statements, which conclusion(s) is drawn correctly?
- A. Only I
- B. Only II
- C. I and II
- D. Neither I nor II✓
Explanation: Neither I nor II – Correct. Since neither conclusion logically follows from the given statements, this is the correct answer.
Why the other options are wrong
- A. Only I – Incorrect. The statement says "Some men are kings," but it does not state that "All men are kings." Since we cannot generalize "some" to "all," this conclusion does not follow.
- B. Only II – Incorrect. The statement says "All men are hardworking" and "Some men are kings," but this does not necessarily mean that all kings are hardworking. There might be kings who are not part of the "men" group in the statement.
- C. I and II – Incorrect. As discussed, neither conclusions logically follow from the given statements.
Q86. Three students, X, Y, and Z and Y, and Z run faster than X, then who will win?
- A. X wins
- B. Y wins
- C. Z wins
- D. X wins and Y has a tie
- E. Data Insufficient✓
Explanation: Since there is not enough information to determine the winner between Y and Z, the question lacks a definitive answer.
Why the other options are wrong
- A. X wins – Incorrect. Since Y and Z are faster than X, X cannot win the race.
- B. Y wins – Incorrect. The statement tells us that Y and Z are both faster than X but does not clarify whether Y is faster than Z.
- C. Z wins – Incorrect. Similar to option B, we do not have enough information to determine whether Y or Z is faster.
- D. X wins and Y has a tie – Incorrect. X is the slowest, so X cannot win, and the idea of Y having a tie is not supported by any given information
Q87. Statements: A large number of people die every year drinking polluted water.Course of Actions: i. The government should make adequate arrangements in providing safe drinking water. ii. The people should be educated about the dangers of drinking polluted water.Which of the given suggested courses of action is/are logically worth to follow?
- A. If only course of action I follows
- B. If only course of action II follows
- C. If either course of action I or II follows
- D. If both courses of action I and II follow✓
Explanation: If both courses of action I and II follow – Correct. The problem can be effectively tackled if both actions are taken together.
Why the other options are wrong
- A. If only course of action I follows – Incorrect. Providing safe water is important, but educating people about the risks is also necessary to prevent the issue entirely.
- B. If only course of action II follows – Incorrect. Educating people is beneficial, but without access to clean water, the problem remains unsolved.
- C. If either course of action I or II follows – Incorrect. Both actions are necessary. Simply implementing one without the other will not fully resolve the issue.
Q88. Statements: i. The majority of the people in the locality belong to the low-income group. ii. The quality of the products in the local supermarket is considerably lower than those in the other localities.Which of the following answer choices correctly depicts the cause & effect relationship between these two statements?
- A. Statement I is the cause, and statement II is its effect✓
- B. Statement II is the cause, and statement I is its effect
- C. Both statements I and II are independent causes
- D. Both statements I and II are effects of a common cause
Explanation: Statement I is the cause, and statement II is its effect – Correct. Since the people in the locality have a low income, businesses may offer lower-quality products that are more affordable, making Statement I the cause and Statement II its effect.
Why the other options are wrong
- B. Statement II is the cause, and statement I is its effect – Incorrect. Poor product quality in a supermarket does not directly lead to a lower-income population. It is more logical that income level influences product quality, not the other way around.
- C. Both statements I and II are independent causes – Incorrect. The statements are related, not independent. The presence of a low-income group affects the quality of products available.
- D. Both statements I and II are effects of a common cause – Incorrect. There is no third common cause given that could be affecting both statements.
Q89. The total number of moles present in 2.8 g of an ethylene molecule are:
- A. 0.1 g✓
- B. 0.2 g
- C. 1 g
- D. 2 g
Explanation: 0.1 g – Correct. The molar mass of ethylene (C₂H₄) is 28 g/mol. Moles = Mass / Molar Mass = 2.8 g / 28 g/mol = 0.1 moles.
Why the other options are wrong
- B. 0.2 g – Incorrect, as the calculated value is 0.1 moles.
- C. 1 g – Incorrect, this is an incorrect conversion.
- D. 2 g – Incorrect, as it is not the correct unit or value.
Q90. Find the change in internal energy of the system when a system absorbs 2 kilocalorie of heat and at the same time does 500 joule of work
- A. 7900 J✓
- B. 8200 J
- C. 5600 J
- D. 6400 J
Explanation: Correct. Applying the first law of thermodynamics: ΔU = Q - W Q = 2 kcal = 2000 cal = 2000 × 4.186 J = 8372 J W = 500 J ΔU = 8372 J - 500 J = 7872 J ≈ 7900 J
Why the other options are wrong
- B. Incorrect as per calculations.
- C. Incorrect as per calculations.
- D. Incorrect as per calculations.
Q91. The magnetic quantum number of the 4f orbital would be:
- A. -2, -3, -1, 0, +2, +3, +1, +4
- B. -2, -3, -1, 0, +2, +3, +1
- C. -3, -4, -2, -1, 0, +4, +3, +2, +1
- D. -3, -2, -1, 0, +1, +2, +3✓
Explanation: -3, -2, -1, 0, +1, +2, +3 – Correct. This includes all valid values for mₗ (-3 to +3) for an f-orbital. The magnetic quantum number (mₗ) ranges from -ℓ to +ℓ, where ℓ is the azimuthal quantum number for the given orbital. For an f-orbital, ℓ = 3, so mₗ can take values from -3 to +3.
Why the other options are wrong
- A. -2, -3, -1, 0, +2, +3, +1, +4 – Incorrect. +4 is not a valid value since the range is only -3 to +3.
- B. -2, -3, -1, 0, +2, +3, +1 – Incorrect. The value +4 is missing, but -3 is included
- C. -3, -4, -2, -1, 0, +4, +3, +2, +1 – Incorrect. The value -4 is not possible, as the range is only -3 to +3
Q92. Which of the following ions is readily hydrated?
- A. Mg2+✓
- B. Ba2+
- C. Na+
- D. Cs+
Explanation: The correct answer is Mg2+ because magnesium ions have a high charge (+2) and a small ionic radius, which allows them to effectively attract and hold onto water molecules, resulting in strong hydration. In contrast, Ba2+ ions, although also +2 charged, are larger and therefore less effective at hydration due to lower charge density. Na+ and Cs+ ions have a +1 charge, leading to weaker hydration capabilities; with cesium being the largest ion, it is the least hydrated of the options.
Why the other options are wrong
- B. Barium ions are larger than magnesium ions and, while they are also +2 charged, their larger size reduces their charge density. Consequently, they are less effective at hydration compared to smaller, more charged ions.
- C. Sodium ions have a +1 charge, which gives them a lower charge density than +2 ions. While they can be hydrated, they do not attract water molecules as effectively as magnesium ions.
- D. C cesium ions are larger than sodium ions and have the same +1 charge. Their size results in an even lower charge density, making them the least hydrated among the options presented.
Q93. What is the IUPAC name of the compound CH3-CH2(CH3)-CH2-CH2(CH3)-CH3?
- A. 1,2-Dimethylpentane
- B. 2,4-Dimethylpentane✓
- C. n-Heptane
- D. Di-isoheptane
Explanation: The correct IUPAC name for the compound CH3-CH2(CH3)-CH2-CH2(CH3)-CH3 is 2,4-dimethylpentane. To arrive at this name, you first identify the longest continuous carbon chain, which contains five carbon atoms (pentane). Next, you identify the positions of the two methyl branches, which are located on the second and fourth carbons of the main chain.Option A, 1,2-dimethylpentane, incorrectly places the methyl groups on the first and second carbons, which does not reflect the correct branching of the compound. Option C, n-heptane, incorrectly identifies the compound as a straight chain of seven carbons, while it actually has branching. Option D, di-isoheptane, is not a valid IUPAC name for this structure, as it does not follow the systematic naming conventions.
Why the other options are wrong
- A. This option suggests that there are two methyl groups on the first and second carbon of a pentane chain. However, this does not accurately reflect the structure of the compound provided, which has the groups on different carbons.
- C. This option incorrectly names the compound as n-heptane, which implies a straight-chain of seven carbon atoms, while the structure provided has branching and does not follow this pattern.
- D. This option suggests a complex branched structure that does not correspond to the compound given. The naming here is also not consistent with IUPAC guidelines for this structure.
Q94. What is the IUPAC name of the compound CH2= CH-CH=CH3-CH=CH-CH3?
- A. 1,3,5-Heptatriene✓
- B. 2,4,6-Heptatriene
- C. Hepta-1,3,5-triene
- D. Hepta-2,4,6-triene
Explanation: The correct answer is 1,3,5-Heptatriene because it accurately describes the structure of the compound CH2=CH-CH=CH3-CH=CH-CH3 with double bonds at the 1st, 3rd, and 5th carbon atoms. The longest continuous carbon chain comprises seven carbon atoms, which is indicated by the prefix 'hept-'. The suffix 'triene' signifies the presence of three double bonds.Option B, 2,4,6-Heptatriene, is incorrect because it misplaces the double bonds in the structure. Options C and D, while identifying the same structure, do not follow the conventional IUPAC naming format and are less preferred. Therefore, while C is technically correct, the standardized IUPAC name is preferred for clarity and consistency.
Why the other options are wrong
- B. This option incorrectly places the double bonds at the 2nd, 4th, and 6th carbon atoms, which does not correspond to the structure of the compound given.
- C. This option is a valid alternative naming convention for the compound, but it is less common than the IUPAC name format. It correctly describes the same structure as the correct answer.
- D. This option incorrectly indicates the positions of the double bonds as being at the 2nd, 4th, and 6th carbon atoms, which does not match the given structure.
Q95. How many active sets of electrons are in water (H2O)?
- A. 2
- B. 3
- C. 4✓
- D. 8
Explanation: Water (H2O) is comprised of two hydrogen atoms and one oxygen atom. Each hydrogen atom contributes one valence electron, while the oxygen atom contributes six valence electrons, making a total of eight electrons. However, in terms of active sets, we consider the bonding pairs and lone pairs. The oxygen atom forms two single covalent bonds with the hydrogen atoms, resulting in two active sets of bonding electrons. Additionally, oxygen has two lone pairs of electrons, which adds two more active sets, leading to a total of four active sets of electrons in the molecule. Thus, the correct answer is four. Options A (2) and B (3) do not reflect the complete bonding structure, while option D (8) incorrectly suggests an excess of active sets.
Why the other options are wrong
- A. This option is incorrect because it does not account for all the valence electrons present in the water molecule.
- B. This option is also incorrect as it underestimates the total number of active sets of electrons in a water molecule.
- D. This option is incorrect because it exceeds the actual number of active sets of electrons in a water molecule.
Q96. When alkaline earth metals react with nitrogen, the compound formed is:
- A. M3N2✓
- B. M2N2
- C. M2N3
- D. M3N3
Explanation: When alkaline earth metals (group 2 elements) react with nitrogen, they typically form compounds with the formula M3N2, where M represents the alkaline earth metal. This occurs because each alkaline earth metal generally has a +2 oxidation state, allowing it to bond with nitrogen (which typically has a -3 oxidation state). Thus, in a balanced reaction, three metals will combine with two nitrogen atoms to form the compound M3N2. The other options do not reflect the correct stoichiometry based on the oxidation states of the elements involved.
Why the other options are wrong
- B. This option suggests a 1:1 ratio of metals to nitrogen, which does not accurately reflect the typical reaction products of alkaline earth metals with nitrogen.
- C. This ratio implies that for each two alkaline earth metals, three nitrogen atoms are required, which does not align with the expected stoichiometry from these metals' reactions with nitrogen.
- D. This option suggests a 1:1 ratio of metals to nitrogen, which is incorrect. Alkaline earth metals typically form compounds with a 3:2 ratio when reacting with nitrogen.
Q97. The solubility of AgCl decreases by adding:
- A. H2SO4
- B. HF
- C. NaCl✓
- D. H2O
Explanation: The correct answer is NaCl because it provides Cl- ions, which are a common ion with AgCl (AgCl is composed of Ag+ and Cl- ions). The presence of the common ion (Cl-) shifts the equilibrium of the dissolution reaction of AgCl to the left, thereby decreasing its solubility according to Le Chatelier's principle.In contrast, H2SO4 and HF do not provide a common ion that interacts with AgCl, so they do not significantly influence its solubility. H2O merely dilutes the solution without affecting the ion concentration needed to alter AgCl solubility.
Why the other options are wrong
- A. H2SO4 is a strong acid that dissociates in water to produce H+ ions and SO42- ions. While it increases the acidity of the solution, it does not directly contribute a common ion to decrease the solubility of AgCl.
- B. HF is a weak acid that partially dissociates in solution, producing H+ ions and F- ions. However, it does not provide a common ion with AgCl, and thus does not significantly affect its solubility.
- D. Adding H2O dilutes the solution but does not provide any ions that would affect the solubility of AgCl. It does not decrease the solubility, making it an ineffective option.
Q98. Repulsion between lone pairs of electrons is:
- A. Low
- B. No repulsion
- C. High✓
- D. Moderate
Explanation: The correct answer is High because lone pairs of electrons are located closer to the nucleus of an atom and occupy more space than bonding pairs, resulting in greater repulsion. This phenomenon can alter molecular geometry and is a key consideration in theories such as VSEPR (Valence Shell Electron Pair Repulsion).Options such as Low and No repulsion are incorrect because they underestimate the effects of lone pairs. The option Moderate is also incorrect as it misrepresents the strength of lone pair repulsion, which is distinctly categorized as high compared to bonding pairs.
Why the other options are wrong
- A. This option suggests that the repulsion between lone pairs of electrons is minimal, which is incorrect. Lone pairs are known to exert significant repulsive forces due to their concentrated electron density.
- B. This option implies that there is no interaction between lone pairs, which contradicts the fundamental principles of electron repulsion in chemistry. Lone pairs do indeed repel each other.
- D. This option suggests a middle ground in repulsion, which is misleading. The repulsion caused by lone pairs is typically categorized as high, not moderate, as they repel more strongly than bonding pairs.
Q99. Which is the correct sequence of electron filling in subshells?
- A. 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s✓
- B. 1s, 2s, 3s, 3p, 3d, 4p, 4s, 5s
- C. 1s, 2p, 3s, 3d, 4s, 4p, 5s
- D. 1s, 2s, 2p, 3s, 4s, 4p, 3d
Explanation: The correct answer is Option A: 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s. This sequence follows the Aufbau principle, where electrons fill subshells in order of increasing energy. The order of filling is determined by the relative energy levels of the subshells, with 4s being filled before 3d despite its higher principal quantum number.Option B is incorrect because it fills 4s after 3p and 3d, which does not reflect the correct energy order. Option C is incorrect as it skips the filling of the 2s subshell and improperly orders the 3d subshell. Option D fills 4s before 3d, which is also incorrect. Understanding the energy levels of subshells is essential to correctly answering this question.
Why the other options are wrong
- B. This option incorrectly places 4s after 3p and before 3d, violating the correct sequence of filling according to energy levels.
- C. This option incorrectly starts with 2p instead of 2s, which is not in accordance with the Aufbau principle.
- D. This option correctly starts with 1s and 2s but places 4s before 3d, which is incorrect as 3d has a lower energy level than 4s.
Q100. Which of the following is not a redox reaction?
- A. CaCO3 ------ Ca + CO3✓
- B. Fe2+ ---- Fe3+
- C. 2H2 + O2 ------ 2H2O
- D. Cu2+ + 2e- ----- Cu
Explanation: The correct answer is Option A:CaCO3 ------ Ca + CO3because this reaction does not involve any transfer of electrons or changes in oxidation states, which are the hallmarks of redox reactions. In contrast, Options B, C, and D all involve either oxidation or reduction processes: Option B involves the oxidation of Fe2+ to Fe3+, Option C involves the reduction of O2 and oxidation of H2, and Option D shows the reduction of Cu2+ to Cu. Thus, they are all classified as redox reactions.
Why the other options are wrong
- B. This reaction represents the oxidation of iron (II) ions to iron (III) ions, which involves the loss of electrons and is thus a redox reaction.
- C. This is the combustion of hydrogen gas, where hydrogen is oxidized and oxygen is reduced, making it a classic example of a redox reaction.
- D. This reaction shows the reduction of copper ions to solid copper. The gain of electrons signifies a redox process.
Q101. In Cannizzaro's reaction, formaldehyde reacts with:
- A. Chloroform
- B. NaOH✓
- C. Water
- D. HCL
Explanation: Cannizzaro's reaction is a unique organic reaction in which aldehydes that lack alpha-hydrogens undergo disproportionation in the presence of a strong base, such as sodium hydroxide (NaOH). In this process, formaldehyde is converted into methanol and sodium formate. Thus, NaOH is essential for facilitating the reaction. The other options are incorrect because chloroform does not react with formaldehyde in this context, water is a product rather than a reactant, and HCl is an acid that does not provide the necessary conditions for Cannizzaro's reaction to occur.
Why the other options are wrong
- A. Chloroform is not involved in Cannizzaro's reaction. It is a halogenated hydrocarbon and does not participate in the reaction mechanism with formaldehyde.
- C. Water is not a reactant in Cannizzaro’s reaction. While it is a product formed during the reaction, it does not contribute to the disproportionation process of formaldehyde.
- D. HCl (hydrochloric acid) is an acid and does not participate in Cannizzaro's reaction, which requires a strong base like NaOH for the reaction to occur.
Q102. Carboxylic acids react with which of the following to form acyl halides?
- A. SOCl2✓
- B. HCl
- C. NaCl
- D. None of these
Explanation: Carboxylic acids can react with thionyl chloride (SOCl2) to form acyl halides, specifically acyl chlorides. The reaction involves the replacement of the hydroxyl group (-OH) of the carboxylic acid with a chlorine atom, resulting in the formation of the corresponding acyl chloride. This reaction is favored because SOCl2 is a strong chlorinating agent and drives the reaction to completion.In contrast, HCl is not strong enough to facilitate this transformation effectively; it is more likely to remain as a byproduct without converting the functional group. Sodium chloride (NaCl) is simply a salt with no reactive properties to convert the carboxylic acid into an acyl halide, as it does not provide the necessary halogen substitution.
Why the other options are wrong
- B. Hydrochloric acid (HCl) does not effectively convert carboxylic acids to acyl halides. It can participate in other reactions, but it does not facilitate the substitution needed for acyl halide formation.
- C. Sodium chloride (NaCl) is a neutral salt and does not react with carboxylic acids to form acyl halides. It lacks the necessary halogenating capability.
- D. Incorrect, as SOCl2 gives an acyl halide upon reacting with carboxylic acid.
Q103. Which of the following is more acidic?
- A. HF
- B. HCl
- C. HBr
- D. HI✓
Explanation: HI is the most acidic among the options given because it completely dissociates in water, releasing protons effectively. The bond between H and I is weaker compared to those in HF, HCl, and HBr, facilitating this dissociation. In contrast, HF is a weak acid due to the strong H-F bond, which resists breaking. While HCl and HBr are strong acids, they don't surpass HI in terms of acidity as they are less effective in proton donation compared to HI.
Why the other options are wrong
- A. HF (hydrofluoric acid) is a weak acid due to the strong bond between hydrogen and fluorine, making it less likely to donate a proton.
- B. HCl (hydrochloric acid) is a strong acid, but it is less acidic than HI because the bond between hydrogen and iodine is weaker, allowing HI to dissociate more easily.
- C. HBr (hydrobromic acid) is a strong acid and stronger than HCl, but still not as strong as HI due to the bond strength between hydrogen and bromine compared to iodine.
Q104. What is the general formula of an alkene?
- A. CnH2n✓
- B. CnH2n+2
- C. CnH2n-2
- D. None of these
Explanation: The correct answer isCnH2nIt, which represents the general formula for alkenes. In this formula, 'n' denotes the number of carbon atoms, and '2n' indicates the number of hydrogen atoms, accounting for the double bond that distinguishes alkenes from other hydrocarbon types. The other options are incorrect:CnH2n+2describes alkanes, which are saturated hydrocarbons;CnH2n-2corresponds to alkynes, which contain triple bonds; andNone of theseis incorrect because option A is valid.
Why the other options are wrong
- B. This formula represents alkanes, not alkenes. Alkanes are saturated hydrocarbons with single bonds only.
- C. This formula is for alkynes, which are unsaturated hydrocarbons with at least one carbon-carbon triple bond.
- D. This option is incorrect because the first option is indeed the correct general formula for alkenes.
Q105. Grignard reagent reacts with CO2 to form:
- A. Ester
- B. Alkane
- C. Carboxylic acid✓
- D. Ketone
Explanation: Grignard reagents are organomagnesium compounds that act as strong nucleophiles. When they react with carbon dioxide (CO2), they add to the carbon atom of the CO2 molecule, leading to the formation of a magnesium salt of a carboxylic acid. Upon hydrolysis, this salt is converted to a carboxylic acid. Hence, the correct answer is Carboxylic acid.Other options are incorrect because an ester is not formed directly from this reaction, nor are alkanes or ketones produced in this specific process. Alkanes are saturated hydrocarbons, while ketones are typically produced from different organic reactions.
Why the other options are wrong
- A. An ester is formed by the reaction of an alcohol with a carboxylic acid, but it is not the product of Grignard reagents reacting with CO2.
- B. An alkane is a saturated hydrocarbon, and Grignard reagents do not react with CO2 to produce alkanes.
- D. A ketone is typically formed from the oxidation of secondary alcohols or through other reactions, but not directly from the reaction of Grignard reagents with CO2.
Q106. Grignard reagent reacts with ------ to form carboxylic acid:
- A. CO2✓
- B. H2O
- C. Alcohol
- D. Ester
Explanation: The correct answer is CO2 because Grignard reagents react with carbon dioxide to form carboxylic acids. In this reaction, the Grignard reagent acts as a nucleophile, attacking the electrophilic carbon in CO2. This leads to the formation of a carboxylate ion, which upon acidification gives the corresponding carboxylic acid.The other options are incorrect as follows: H2O reacts with Grignard reagents but destroys them forming hydrocarbons; Alcohol leads to the formation of alkoxides, not carboxylic acids; and Ester reactions lead to tertiary alcohols instead of carboxylic acids.
Why the other options are wrong
- B. H2O (water) can react with Grignard reagents, but it does not lead to the formation of carboxylic acids; instead, it typically results in the degradation of the Grignard reagent to form hydrocarbons.
- C. Alcohols can react with Grignard reagents, but this reaction typically results in the formation of alkoxides. While alcohols can be formed through other reactions, they do not directly produce carboxylic acids from Grignard reagents.
- D. Ester compounds do not react with Grignard reagents to form carboxylic acids directly. Instead, Grignard reagents can react with esters to produce tertiary alcohols, which is a different reaction pathway.
Q107. In ethene, how many unhybridized p orbitals overlap to form π bonds?
- A. 1
- B. 2✓
- C. 4
- D. 8
Explanation: In ethene (C2H4), each carbon atom undergoes sp2 hybridization, resulting in three sp2 hybrid orbitals and one unhybridized p orbital per carbon. The two unhybridized p orbitals (one from each carbon) overlap side-by-side to form a π bond. Therefore, the correct answer is 2 unhybridized p orbitals. The other options are incorrect as they either miscount the number of orbitals or do not reflect the bonding mechanism in ethene.
Why the other options are wrong
- A. This option is incorrect because a single unhybridized p orbital cannot form the π bond in ethene, which requires two.
- C. This option is incorrect as ethene only involves the overlap of two unhybridized p orbitals from the two carbon atoms, not four.
- D. This option is incorrect because it greatly overestimates the number of unhybridized p orbitals involved in the formation of π bonds in ethene.
Q108. Which of the following does not belong to the s-block?
- A. Li
- B. Cs
- C. Fe✓
- D. He
Explanation: The correct answer is Fe because iron is located in the d-block of the periodic table, which includes transition metals and does not belong to the s-block. The s-block elements are primarily found in groups 1 and 2, which include metals like lithium (Li) and cesium (Cs), both of which are alkali metals. Helium (He), while located in group 18, is still classified as part of the s-block due to its electron configuration. Thus, Fe is the only option that does not belong to the s-block.
Why the other options are wrong
- A. Lithium (Li) is an alkali metal and belongs to group 1 of the periodic table, making it a member of the s-block.
- B. Cesium (Cs) is also an alkali metal found in group 1, thus it is part of the s-block.
- D. Helium (He) is a noble gas located in group 18, but it is still considered part of the s-block due to its electron configuration.
Q109. The number of electrons in a shell is is:
- A. n2
- B. 2n2✓
- C. 2 l + 2
- D. 2 (l + 2)
Explanation: The formula for calculating the maximum number of electrons in a shell is given by 2n2, where 'n' is the principal quantum number associated with the shell. This means that for each shell, the number of electrons it can hold increases with the square of the principal quantum number, multiplied by 2. For example, the first shell (n=1) can hold 2 electrons, the second shell (n=2) can hold 8 electrons, and so forth.Option A (n2) is incorrect because it does not include the factor of 2. Options C (2 l + 2) and D (2 (l + 2)) are both incorrect as they relate to the angular momentum quantum number 'l' and do not apply to the total number of electrons in a shell.
Why the other options are wrong
- A. This formula represents the maximum number of electrons in a subshell, but it does not account for the factor of 2 that is necessary for the total number of electrons in a shell.
- C. This formula is incorrect as it pertains to the angular momentum quantum number 'l' and does not relate to the total number of electrons in a shell.
- D. This expression does not correctly represent the number of electrons in a shell; it involves the angular momentum quantum number but fails to apply the principal quantum number 'n'.
Q110. The number of electrons in the M shell is:
- A. 2
- B. 10
- C. 18✓
- D. 6
Explanation: The M shell is the third shell in the electron configuration of an atom, corresponding to n=3. The formula to determine the maximum number of electrons in any shell is 2n². For the M shell, substituting n with 3 gives us 2(3)² = 2 x 9 = 18 electrons. Therefore, the correct answer is 18. The other options are incorrect because they do not reflect the maximum capacity of the M shell.
Why the other options are wrong
- A. This option is incorrect because the M shell can hold more than two electrons; it is not the first shell, which is limited to 2 electrons.
- B. This option is incorrect because while the M shell can hold 10 electrons, it actually has the capacity to hold more.
- D. This option is incorrect; the M shell can hold more than 6 electrons, as it exceeds the capacity of the previous shells.
Q111. Which of the following showvs maximum ideal behavior?
- A. He✓
- B. H2
- C. CO2
- D. SO2
Explanation: The correct answer is He because helium is a noble gas that is monatomic and has minimal intermolecular forces, making it behave very closely to an ideal gas. In contrast, H2 while relatively ideal, still has some intermolecular attractions due to its diatomic nature. CO2 and SO2 have stronger intermolecular forces due to their molecular structure and polarity, which leads to greater deviations from ideal gas behavior.
Why the other options are wrong
- B. Hydrogen (H2) is a diatomic molecule with some degree of intermolecular attraction, but it is still relatively close to ideal behavior compared to heavier gases.
- C. Carbon dioxide (CO2) is a molecular gas with stronger intermolecular forces and higher molecular weight, leading to deviations from ideal behavior.
- D. Sulfur dioxide (SO2) has polar characteristics and significant intermolecular forces, which cause it to deviate more significantly from ideal gas behavior compared to hydrogen.
Q112. Which law defines that if a chemical reaction can occur through multiple pathways, the net enthalpy change remains the same provided the initial and final states are the same?
- A. Hooke's Law
- B. Hess's Law✓
- C. First Law of Thermodynamics
- D. Henry's Law
Explanation: Hess's Law is the correct answer because it specifically addresses how the total enthalpy change in a chemical reaction is independent of the pathway taken, as long as the initial and final states remain unchanged. This is a fundamental principle in thermodynamics that allows chemists to calculate the enthalpy changes for reactions that are difficult to measure directly by using other, simpler reactions.In contrast, Hooke's Law deals with mechanical properties of materials (specifically springs), the First Law of Thermodynamics focuses on energy conservation without specifying enthalpy changes between states, and Henry's Law is concerned with the behavior of gases in liquids. Therefore, these options do not apply to the question about enthalpy and chemical pathways.
Why the other options are wrong
- A. This law pertains to the relationship between the force exerted on a spring and its extension, but it does not relate to chemical reactions or enthalpy changes.
- C. This law relates to the conservation of energy in a system, stating that energy cannot be created or destroyed, but it does not specifically address pathways of reactions or enthalpy changes.
- D. This law describes the solubility of gases in liquids and is not relevant to the concept of enthalpy changes in chemical reactions.
Q113. Which element is reduced in the equation Cl2+H2S →HCI+S?
- A. Cl2✓
- B. S
- C. H2
- D. H2S
Explanation: In the given reaction, Cl2 is the element that is reduced. Reduction involves gaining electrons, and in this case, chlorine gains electrons to form HCl. The oxidation state of chlorine decreases as it is converted from Cl2 to HCl, indicating it has been reduced. On the other hand, sulfur (S) is produced from H2S, which is oxidized during the reaction, making it incorrect to identify it as reduced. Hydrogen gas (H2) and hydrogen sulfide (H2S) do not gain electrons, thus they are not reduced either.
Why the other options are wrong
- B. Sulfur (S) is produced in the reaction, but it does not undergo reduction; thus, it is not the correct answer.
- C. Hydrogen gas (H2) serves as a reactant but is not reduced in this reaction, making this option incorrect.
- D. Hydrogen sulfide (H2S) is oxidized to form sulfur (S) in the reaction; therefore, it is not reduced.
Q114. Sigma bonds are formed by:
- A. Linear overlapping✓
- B. Sidewise overlapping
- C. Lateral overlapping
- D. Parallel overlapping
Explanation: The correct answer is Option A: Linear overlapping. Sigma bonds are formed when two atomic orbitals overlap linearly, which allows for a strong and stable bond. This type of overlap occurs when atomic orbitals, usually s or p orbitals, align end to end. In contrast, the other options describe types of overlap that do not lead to sigma bond formation. Option B: Sidewise overlapping describes how pi bonds are formed, which is through the side-to-side overlap of p orbitals. Option C: Lateral overlapping is also associated with pi bonds and does not create sigma bonds. Finally, Option D: Parallel overlapping is characteristic of pi bonding as well, as it involves orbitals that overlap parallel to each other rather than in a head-on manner. Therefore, the only correct choice that describes sigma bond formation is linear overlapping.
Why the other options are wrong
- B. This option refers to the type of overlap that typically forms pi bonds, not sigma bonds. Sigma bonds require direct, end-to-end overlap.
- C. Lateral overlap is not characteristic of sigma bonds; it is more aligned with pi bond formation, which involves overlap of orbitals that are parallel rather than directly aligned.
- D. This option is incorrect as sigma bonds do not form through parallel overlap. Such overlap is typical for pi bonds, which involve side-to-side interactions.
Q115. Unequal distribution of alkyl groups on both sides of a carbon atom is known as:
- A. Tautomerism
- B. Metamerism✓
- C. Functional isomerism
- D. Structural isomerism
Explanation: The correct answer is Metamerism, which specifically addresses the situation where alkyl groups are unequally distributed around a carbon atom, leading to different structural isomers. In metamerism, the structural differences arise from varying arrangements of the alkyl groups on either side of a functional group, particularly in compounds like ethers or amines.On the other hand, Tautomerism involves isomers that readily interconvert, usually differing in the positioning of a proton and a double bond. Functional isomerism refers to isomers that have the same molecular formula but different functional groups, which does not apply here. Lastly, while Structural isomerism is a broader term that includes types like metamerism, it does not capture the specific aspect of unequal alkyl distribution.
Why the other options are wrong
- A. Tautomerism refers to a specific type of isomerism where isomers (tautomers) can interconvert, typically involving the relocation of a hydrogen atom and a switch of single and double bonds. It does not pertain to alkyl group distribution.
- C. Functional isomerism involves compounds with the same molecular formula but different functional groups. This does not relate to the distribution of alkyl groups around a carbon atom.
- D. Structural isomerism is a broader category that includes different types of isomerism, such as metamerism and functional isomerism. While it may encompass the concept, it does not specifically refer to the unequal distribution of alkyl groups.
Q116. Dehydration of alcohol gives:
- A. Alkane
- B. Alkene✓
- C. Alkyne
- D. Ester
Explanation: Dehydration of alcohol involves the elimination of a water molecule from the alcohol, which typically results in the formation of an alkene, as it creates a carbon-carbon double bond. This is a common reaction in organic chemistry where alcohols lose water to form alkenes. The other options are incorrect because:Alkane: This would require the addition of hydrogen rather than the removal of water, as alkanes are saturated.Alkyne: The formation of alkynes involves the creation of triple bonds, which does not occur during alcohol dehydration.Ester: While esters are formed from alcohols, they typically result from a reaction with carboxylic acids, not from dehydration of alcohol alone.
Why the other options are wrong
- A. An alkane is a saturated hydrocarbon with single bonds only. Dehydration of alcohol does not lead to the formation of alkanes, as this process involves the elimination of water, which is more likely to produce unsaturated compounds.
- C. An alkyne is an unsaturated hydrocarbon with at least one carbon-carbon triple bond. The dehydration of alcohol does not produce alkynes, as this reaction typically does not involve the formation of triple bonds.
- D. An ester is a compound formed from the reaction of an alcohol and a carboxylic acid. Dehydration of alcohol does not directly yield esters; rather, it leads to alkenes through the removal of water
Q117. The bond angle between C-C in dịamond is:
- A. 104.5°
- B. 109°✓
- C. 180°
- D. 90°
Explanation: The correct bond angle between C-C in diamond is 109°, which arises from its tetrahedral arrangement of carbon atoms. In diamond, each carbon atom is bonded to four other carbon atoms at equal angles, leading to this specific bond angle due to sp3 hybridization. The other options are incorrect: 104.5° is associated with water's bent structure, 180° corresponds to linear molecules, and 90° relates to octahedral geometries, none of which apply to diamond's tetrahedral structure.
Why the other options are wrong
- A. This angle is commonly associated with water (H2O) due to its bent shape, but it does not apply to the structure of diamond.
- C. This angle is characteristic of linear molecules, which does not apply to diamond's three-dimensional structure.
- D. This angle is typical for octahedral geometries, which is not relevant to the tetrahedral structure of diamond.
Q118. In methanol, the hybridization of carbon is:
- A. sp3✓
- B. sp2
- C. sp
- D. sp2d
Explanation: In methanol (CH3OH), the carbon atom is bonded to three hydrogen atoms and one hydroxyl group (–OH). This configuration requires four sigma bonds, which corresponds to sp3 hybridization. The carbon atom's four valence electrons hybridize to form four equivalent sp3 hybrid orbitals, which then form sigma bonds with the surrounding atoms.The other options are incorrect because:sp2: This would imply the presence of a double bond or a pi bond, which does not occur in methanol.sp: This indicates two sigma bonds and two pi bonds, which does not match the bonding in methanol.sp2d: This hybridization involves d orbitals, which are not utilized by carbon in methanol.
Why the other options are wrong
- B. This hybridization suggests that the carbon atom has three sigma bonds and one pi bond. This is not applicable to methanol since there are no double bonds present.
- C. This hybridization indicates that the carbon atom would have two sigma bonds and two pi bonds, which is not the case in methanol.
- D. This hybridization suggests the involvement of d orbitals, which is not relevant for carbon in methanol as it only involves s and p orbitals.
Q119. Which reaction occurs at the cathode?
- A. Oxidation
- B. Reduction✓
- C. Redox
- D. None
Explanation: At the cathode, reduction occurs, meaning that the species present gains electrons. This is in direct contrast to the anode, where oxidation (loss of electrons) occurs. Therefore, the correct answer is Reduction. The other options are incorrect as follows: Oxidation takes place at the anode, not the cathode; Redox describes the overall process but does not specify the cathode reaction; and None is incorrect because a reaction does occur at the cathode.
Why the other options are wrong
- A. Oxidation is the process by which a species loses electrons. This reaction occurs at the anode, not the cathode.
- C. Redox is a term that describes reactions involving both oxidation and reduction, but it is not specific to the cathode reaction alone.
- D. This option suggests that no reaction occurs at the cathode, which is incorrect, as a reduction reaction does take place there.
Q120. Which catalyst is used in the halogenation of benzene?
- A. Ni
- B. Fe
- C. FeCl3✓
- D. N2O5
Explanation: The correct answer is FeCl3, which is commonly used as a catalyst in the halogenation of benzene. This catalyst facilitates the generation of a halogen cation (electrophile) that can attack the aromatic ring in a substitution reaction. The other options are incorrect because:Ni: Nickel is typically used in hydrogenation reactions, not halogenation.Fe: While iron can be a catalyst in some reactions, it is not effective for the halogenation of benzene.N2O5: This compound is not relevant to the halogenation process and is more associated with oxidation reactions.
Why the other options are wrong
- A. Nickel (Ni) is not typically used as a catalyst for the halogenation of benzene. It is more commonly associated with hydrogenation reactions.
- B. Iron (Fe) can act as a catalyst in some reactions, but it is not the most effective catalyst for the electrophilic halogenation of benzene.
- D. Nitrogen pentoxide (N2O5) is not used as a catalyst for the halogenation of benzene and is more commonly associated with oxidation reactions.
Q121. The electrophile in the nitration of benzene is:
- A. NO+
- B. NO2+✓
- C. N2O5+
- D. NO3+
Explanation: The correct answer is NO2+, which is the nitronium ion. It is the primary electrophile in the nitration of benzene, facilitating the introduction of a nitro group onto the aromatic ring. The other options are incorrect because:NO+ is a nitrosyl ion and does not participate in the nitration of benzene.N2O5+ can theoretically generate nitronium ions but is not the direct electrophile in the reaction.NO3+ refers to a nitrate ion, which does not act as the electrophile in this specific nitration reaction.Thus, understanding the role of the nitronium ion is crucial for mastering electrophilic aromatic substitution reactions.
Why the other options are wrong
- A. This option represents a nitrosyl cation, which is not the electrophile used in the nitration process of benzene.
- C. Nitrogen pentoxide can produce nitronium ions under certain conditions, but it is not the direct electrophile in the classic nitration of benzene.
- D. The nitrate ion is not a typical electrophile in the nitration of benzene. While it is associated with nitration reactions, it does not participate directly in the electrophilic attack.
Q122. Another name of London dispersion forces (LDF) is:
- A. Instantaneous dipole-induced dipole force✓
- B. Dipole force
- C. Ion-dipole force
- D. Electrostatic force
Explanation: London dispersion forces (LDF) are also known as instantaneous dipole-induced dipole forces because they arise when the electron distribution in a molecule creates a temporary dipole, which can then induce a dipole in a neighboring molecule. This force is particularly significant in non-polar molecules. The other options do not accurately describe LDF. 'Dipole force' refers to forces between permanent dipoles, 'ion-dipole force' involves interactions between ions and polar molecules, and 'electrostatic force' encompasses a broader range of forces between charged entities. Thus, the correct answer is option A.
Why the other options are wrong
- B. This option is incorrect because dipole forces refer to interactions between permanent dipoles, which is a different type of intermolecular force compared to London dispersion forces.
- C. This option is incorrect as ion-dipole forces occur between ions and polar molecules, which is not the same as London dispersion forces that involve non-polar molecules.
- D. This option is incorrect because electrostatic forces are a broader category that includes forces between charged particles, whereas London dispersion forces are specifically related to temporary dipoles.
Q123. The IUPAC name of picric acid is:
- A. 1,2,3-Trimethyl xylene
- B. 1,2,3-Trimethyl phenol
- C. 2,4,6-Trimethyl phenol
- D. None✓
Explanation: The correct IUPAC name for picric acid is 2,4,6-trinitrophenol, which indicates that it has three nitro (–NO2) groups attached to a phenolic structure at the 2, 4, and 6 positions. The other options incorrectly suggest the presence of methyl groups instead of nitro groups. Therefore, all other options are incorrect as they do not accurately reflect the structure of picric acid.
Why the other options are wrong
- A. This option refers to a compound that has a different structure than picric acid. Xylene is a dimethyl derivative of benzene and does not contain the functional groups present in picric acid.
- B. This name suggests a phenol derivative with three methyl groups, which does not match the structure of picric acid that has nitro groups instead of methyl groups.
- C. This name indicates a phenol with three methyl groups located at positions 2, 4, and 6. However, picric acid contains nitro groups, not methyl groups, making this incorrect.
Q124. VWhich has the same unit as work?
- A. Heat✓
- B. Power
- C. Mole
- D. Mass
Explanation: The correct answer is Heat, as both work and heat are measured in joules (J), which is the standard unit of energy in the International System of Units (SI). In contrast, Power is expressed in watts (W), which is derived from joules per second; therefore, it does not share the same unit as work. Mole is a unit of measurement for the quantity of substance, and Mass is quantified in kilograms. Neither of these relates to work or energy transfer.
Why the other options are wrong
- B. Power is measured in watts (W), which is defined as joules per second. While related to work, it is not measured in the same unit as work itself.
- C. A mole is a unit that measures the amount of substance, not energy or work. Therefore, it is not relevant to this question.
- D. Mass is measured in kilograms (kg) and does not have the same unit as work, which is energy. Hence, this option is incorrect.
Q125. In what ratio are nitrogen and hydrogen present in the formation of ammonia?
- A. 1:2
- B. 1:3✓
- C. 5:2
- D. 1:4
Explanation: Ammonia (NH3) is formed when nitrogen (N2) reacts with hydrogen (H2) in a 1:3 ratio. This means that for every 1 molecule of nitrogen, 3 molecules of hydrogen are needed. Thus, the correct option is 1:3. Other options are incorrect as they do not follow the correct stoichiometric ratios for the formation of ammonia, which are derived from its chemical formula.
Why the other options are wrong
- A. This option suggests that for every 1 part of nitrogen, there are 2 parts of hydrogen. This is incorrect as it does not reflect the actual stoichiometry involved in the formation of ammonia.
- C. This ratio suggests a much higher amount of nitrogen compared to hydrogen, which is not consistent with the known chemical formula for ammonia.
- D. This option indicates a 1:4 ratio which implies more hydrogen than is actually required to form ammonia, making it incorrect.
Q126. Reduction of benzene gives:
- A. Cyclohexane✓
- B. Phenol
- C. Anthracene
- D. Toluene
Explanation: The correct answer is Cyclohexane, which is formed when benzene undergoes a reduction reaction, typically through catalytic hydrogenation. This process leads to the saturation of the benzene ring, converting its double bonds into single bonds, resulting in cyclohexane.The other options are incorrect because:Phenol is produced by the hydroxylation of benzene, not through reduction.Anthracene is a larger polycyclic aromatic compound, not a product of benzene reduction.Toluene is created through the introduction of a methyl group to benzene, rather than being a product of its reduction.
Why the other options are wrong
- B. Phenol is formed from the hydroxylation of benzene, not from its reduction. Thus, it does not represent the product of benzene reduction.
- C. Anthracene is a polycyclic aromatic hydrocarbon and is not a product of benzene reduction. It consists of three fused benzene rings.
- D. Toluene is a methyl derivative of benzene, but it is not produced directly from the reduction of benzene. Instead, it is formed by the alkylation of benzene.
Q127. Which is a trihydric alcohol?
- A. Xylene
- B. Hydroquinone
- C. Resorcinol
- D. Pyrogallol✓
Explanation: The correct answer is Pyrogallol because it contains three hydroxyl (-OH) groups in its structure, qualifying it as a trihydric alcohol. In contrast, Xylene is an aromatic hydrocarbon and has no hydroxyl groups, making it irrelevant to this question. Hydroquinone and Resorcinol both contain only two hydroxyl groups, classifying them as dihydric alcohols, thus they do not fit the criteria for trihydric alcohols.
Why the other options are wrong
- A. Xylene is an aromatic hydrocarbon and does not contain any hydroxyl groups, making it not a trihydric alcohol.
- B. Hydroquinone is a dihydric alcohol, with two hydroxyl groups, and therefore does not qualify as a trihydric alcohol.
- C. Resorcinol is also a dihydric alcohol, containing two hydroxyl groups and is not classified as a trihydric alcohol.
Q128. Alcohol reacts with PCl5 to form:
- A. Aldehyde
- B. Ketone
- C. Alkyl halide✓
- D. Ester
Explanation: The correct answer is alkyl halide. When alcohol reacts with phosphorus pentachloride (PCl5), the hydroxyl group (-OH) of the alcohol is replaced by a chlorine atom, resulting in the formation of an alkyl halide. This reaction is a substitution reaction where the alcohol is converted into a more reactive alkyl halide.The other options are incorrect for the following reasons:Aldehyde: Aldehydes are formed through oxidation of primary alcohols, not through reaction with PCl5.Ketone: Ketones are typically produced from secondary alcohols through oxidation, not from direct reaction with PCl5.Ester: Esters are formed from the reaction of alcohols with carboxylic acids, not from PCl5.
Why the other options are wrong
- A. This is incorrect because the reaction of alcohol with PCl5 does not typically produce an aldehyde.
- B. This is incorrect as ketones are not formed in this reaction. PCl5 does not convert alcohols directly into ketones.
- D. This is incorrect as esters are formed through the reaction of alcohols with acids, not with PCl5.
Q129. Which test differentiates alcohol and phenol?
- A. Na metal test✓
- B. Ester test
- C. Tollen's reagent
- D. Benedict's test
Explanation: The correct answer is the Na metal test, which effectively distinguishes between alcohols and phenols based on their different reactivity with sodium metal. Alcohols react with sodium to generate hydrogen gas, while phenols show minimal reaction. The Ester test is unrelated since it focuses on identifying esters rather than differentiating between alcohols and phenols. Although Tollen's reagent can be used in organic chemistry for identifying aldehydes, it does not serve to differentiate between alcohols and phenols. Similarly, the Benedict's test is designed for detecting reducing sugars, making it irrelevant in the context of functional group differentiation.
Why the other options are wrong
- B. This test is designed to identify ester functional groups through their characteristic reactions, but it is not applicable for differentiating alcohols from phenols.
- C. Tollen's reagent is primarily used to test for aldehydes, and while it can indicate the presence of certain functional groups, it does not effectively differentiate between alcohols and phenols.
- D. This test is used for detecting reducing sugars and has no relevance in distinguishing between alcohols and phenols, as it targets a completely different class of compounds.
Q130. Which is a meta-directing group?
- A. Cl
- B. NO2✓
- C. R --- OH
- D. R --- NH2
Explanation: The correct answer is NO2, which is classified as a meta-directing group due to its electron-withdrawing properties that destabilize the negative charge in the intermediate during electrophilic aromatic substitution. In contrast, Cl, R --- OH, and R --- NH2 are all considered ortho/para-directing groups. Chlorine (Cl) is a weak electron-withdrawing group but does not stabilize the negative charge effectively in the meta position. Both hydroxyl (R --- OH) and amino (R --- NH2) groups are strong electron-donating groups that direct electrophiles to the ortho and para positions, not to the meta position.
Why the other options are wrong
- A. The chlorine atom (Cl) is a weak electron-withdrawing group due to its electronegativity. It directs substituents to the ortho and para positions, thus it is not a meta-directing group.
- C. The hydroxyl group (R --- OH) is an electron-donating group that stabilizes the intermediate in electrophilic aromatic substitution, directing substituents to the ortho and para positions instead of meta.
- D. The amino group (R --- NH2) is another strong electron-donating group that also directs substituents to the ortho and para positions, classifying it as not a meta-directing group.
Q131. The shape of iodotrichloride (ICI3) is:
- A. Trigonal planar✓
- B. Pyramidal
- C. Bipyramidal
- D. Linear
Explanation: The correct shape of iodotrichloride (ICI3) is trigonal planar. This geometry arises because the iodine atom is surrounded by three chlorine atoms, forming three sigma bonds and having no lone pairs. The arrangement minimizes electron pair repulsion, leading to a flat, trigonal shape. On the other hand, the pyramidal option suggests the presence of a lone pair on the iodine, which is not the case here. The bipyramidal option is incorrect as it requires five bonding pairs, while the linear shape is only applicable to molecules with two bonding pairs. Thus, the trigonal planar arrangement is the only correct answer.This paper contains fewer questions than the original exam because the official paper was not released by the testing agency. However, these questions represent the maximum number we could find and should provide a fairly good idea of the actual paper’s content and pattern.
Why the other options are wrong
- B. This option is incorrect. A pyramidal shape typically occurs when there is a lone pair on the central atom, which causes the bonded atoms to adopt a three-dimensional pyramidal arrangement. Iodotrichloride does not have lone pairs.
- C. This option is incorrect. A bipyramidal shape occurs in molecules with five bonding pairs. Iodotrichloride only has three bonding pairs and does not fit this geometry.
- D. This option is incorrect. A linear shape is characteristic of molecules with two bonding pairs and no lone pairs. Iodotrichloride has three chlorine atoms bonded to iodine, resulting in a trigonal planar structure instead.
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