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Chapter 6 of 16 · Physics
Fluid Dynamics
Fluid Dynamics averages 2 MCQs per paper — Bernoulli's equation, equation of continuity, and viscosity (Stokes' law) are perennial picks.
Fluid Dynamics is a Physics chapter on the official PMDC MDCAT 2026 syllabus, contributing roughly 2 MCQs to the 36-MCQ Physics section. Mastering the core concepts below typically secures the full chapter weightage.
Hydrostatics primer
Pressure in a static fluid increases with depth: P = P₀ + ρgh. A diver at 10 m in seawater (ρ ≈ 1030 kg/m³) experiences gauge pressure ≈ 1.01×10⁵ Pa, roughly one extra atmosphere. Pascal's principle states that pressure applied to an enclosed fluid is transmitted undiminished — the basis of hydraulic lifts where F₁/A₁ = F₂/A₂. Archimedes' principle gives buoyant force B = ρfluidVdisplacedg; a body floats when its average density is less than that of the fluid.
Equation of continuity
For an incompressible, steady flow, A₁v₁ = A₂v₂. The product Av is the volumetric flow rate (m³/s). Squeezing a hose nozzle from 1 cm² to 0.25 cm² quadruples the exit speed if the source flow is constant. This conservation law follows from mass conservation and underlies almost every fluid-flow MCQ on the MDCAT.
Bernoulli's equation
For non-viscous, incompressible, steady flow along a streamline, P + ½ρv² + ρgh = constant. Faster-moving fluid has lower pressure — explaining lift on aircraft wings, the curve of a spinning ball, and the operation of a Venturi meter. From a tank with a small hole at depth h, the efflux speed is v = √(2gh) (Torricelli's theorem), the same as a freely falling body. A 5 m deep tank delivers v = √(98) ≈ 9.9 m/s at the bottom.
Viscosity and Stokes' law
Viscosity η is the internal friction between adjacent fluid layers; SI unit is Pa·s. For a sphere of radius r falling through a viscous fluid at speed v, the drag is F = 6πηrv (Stokes' law). At terminal velocity, gravity = drag + buoyancy, giving vt = (2r²(ρs − ρf)g)/(9η). A small steel ball thus falls slower in glycerine than in water because η is much larger.
Reynolds number and turbulence
Re = ρvD/η classifies flow: laminar for Re < ~2000, turbulent for Re > ~3000, transitional in between. Bernoulli strictly applies only to laminar flow; for turbulent or viscous flow, energy losses must be added. The FSc Punjab Textbook Chapter 6 introduces Stokes and Reynolds explicitly; HRW Chapter 14 treats Bernoulli rigorously with worked Venturi-meter problems.
Key Concepts
- Equation of continuity
- Bernoulli's principle
- Viscosity
- Stokes' law
- Terminal velocity
Worked MCQs
Q1. Water flows at 2 m/s through a pipe of area 4 cm². Where the pipe narrows to 1 cm² the speed becomes:
- A. 0.5 m/s
- B. 2 m/s
- C. 4 m/s
- D. 8 m/s ✓
Explanation: A₁v₁ = A₂v₂ ⇒ v₂ = 4·2/1 = 8 m/s.
Common trap: Inverting the ratio — narrower pipe means higher speed, not lower.
Q2. Efflux speed from a tank with a hole 1.25 m below the surface is (g = 10 m/s²):
- A. 2.5 m/s
- B. 5 m/s ✓
- C. 10 m/s
- D. 12.5 m/s
Explanation: v = √(2gh) = √25 = 5 m/s (Torricelli).
Common trap: Forgetting the factor of 2.
Q3. Pressure at depth h in a fluid of density ρ above atmospheric is:
- A. ρg
- B. ρgh ✓
- C. ρgh²
- D. ½ρgh
Explanation: P_gauge = ρgh from hydrostatic equation.
Common trap: Choosing ½ρgh by analogy with ½kx² — pressure varies linearly, not quadratically, with depth.
Q4. Stokes' drag on a sphere of radius r moving at v through fluid of viscosity η is:
- A. 6πηrv ✓
- B. πηrv²
- C. ηrv
- D. (1/2)πηrv
Explanation: F = 6πηrv is Stokes' law for low-Re flow around a sphere.
Common trap: Picking πηrv² mixes Stokes with quadratic drag, which applies only at high Re.
Q5. Lift on an aircraft wing is explained primarily by:
- A. Pascal's principle
- B. Archimedes' principle
- C. Bernoulli's equation ✓
- D. Stokes' law
Explanation: Faster flow over the curved upper surface lowers pressure (Bernoulli), creating net upward force.
Common trap: Choosing Archimedes — that is buoyancy in static fluids, not aerodynamic lift.
Frequently Asked Questions
Does Bernoulli's equation apply to viscous flow?
No. It assumes non-viscous, incompressible, steady, streamline flow. For viscous flow, energy-loss terms must be added.
Why does a spinning ball curve in flight (Magnus effect)?
Spin drags air faster on one side, lowering pressure there (Bernoulli), producing a sideways force.
What is terminal velocity?
The constant speed at which gravitational force equals viscous drag plus buoyancy; net force is zero and acceleration vanishes.
Can fluids be both laminar and turbulent simultaneously?
In transitional Reynolds number regimes flow may switch intermittently between regimes, but at any point and instant it is one or the other.
Why does pressure at the bottom of a dam not depend on its shape?
Hydrostatic pressure depends only on depth and density, not on horizontal extent or shape — so a narrow column of water can support a wide one of equal height.
How Fluid Dynamics Is Tested
MDCAT questions on Fluid Dynamics are a mix of recall (definitions, classifications), application (predict outcomes, interpret diagrams), and basic numerical/analytical reasoning. PMDC papers from 2020–2025 emphasized the concepts above; older UHS papers (2008–2019) tested them too, with slight variations in question framing.
Practice
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See the full MDCAT 2026 syllabus or browse all Physics chapters.