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Chapter 3 of 16 · Physics

Motion and Force

Motion and Force averages 3 MCQs per MDCAT paper — kinematic equations, Newton's laws, projectile motion, and momentum dominate.

Motion and Force is a Physics chapter on the official PMDC MDCAT 2026 syllabus, contributing roughly 3 MCQs to the 36-MCQ Physics section. Mastering the core concepts below typically secures the full chapter weightage.

Kinematics in one dimension

For uniform acceleration a, the four equations to memorise from FSc Punjab Textbook Chapter 3 (and HRW Chapter 2) are: v = u + at, s = ut + ½at², v² = u² + 2as, and s = ½(u+v)t. A car decelerating from u = 20 m/s to rest over s = 50 m needs a = (0 − 400)/(2·50) = −4 m/s². Free fall takes g = 9.8 m/s² downward; a stone dropped from a 45 m cliff hits the ground in t = √(2s/g) = √(90/9.8) ≈ 3.03 s with v = gt ≈ 29.7 m/s.

Newton's three laws

First law: a body remains at rest or in uniform motion unless acted on by a net external force (defines inertial frames). Second law: Fnet = ma, or more generally F = dp/dt. Third law: every action has an equal and opposite reaction, applied to different bodies. The MDCAT classic: a 70 kg person in a lift accelerating upward at 2 m/s² feels apparent weight N = m(g+a) = 70(11.8) = 826 N; downward acceleration reduces it to m(g−a).

Projectile motion

Horizontal and vertical motions are independent. For launch speed u at angle θ: range R = u² sin 2θ / g, time of flight T = 2u sin θ / g, maximum height H = u² sin² θ / 2g. R is maximum at θ = 45°. Two complementary angles (e.g. 30° and 60°) give the same range. A ball thrown at 20 m/s at 30°: H = 400·0.25/19.6 ≈ 5.1 m, R = 400·sin 60°/9.8 ≈ 35.3 m.

Momentum, impulse, and collisions

Linear momentum p = mv is conserved when the net external force is zero. Impulse J = FΔt = Δp. In a perfectly elastic collision both momentum and kinetic energy are conserved; in inelastic collisions only momentum is conserved. For a 1-D elastic collision between m1 with velocity u1 and m2 at rest, v1 = ((m1−m2)/(m1+m2))u1 and v2 = (2m1/(m1+m2))u1. Equal masses simply exchange velocities — a billiard-ball result loved by examiners.

Friction and inclined planes

Static friction fs ≤ μsN and kinetic friction fk = μkN, with μs > μk. On an incline of angle θ, the component of gravity along the slope is mg sin θ and normal to it is mg cos θ. A block slides if tan θ > μs; on a frictionless incline the acceleration down the slope is g sin θ regardless of mass. Always draw the free-body diagram before plugging numbers — a habit endorsed by Serway.

Key Concepts

  • Kinematic equations
  • Newton's laws
  • Friction
  • Projectile motion
  • Momentum & impulse

Worked MCQs

Q1. A car accelerates from rest at 4 m/s² for 5 s. The distance covered is:

  • A. 20 m
  • B. 40 m
  • C. 50 m
  • D. 100 m

Explanation: s = ½at² = ½(4)(25) = 50 m.

Common trap: Using s = at² gives 100 m — the ½ factor is the most-missed term in MDCAT history.

Q2. A projectile launched at 45° with speed 20 m/s has range (g = 10 m/s²):

  • A. 20 m
  • B. 40 m
  • C. 30 m
  • D. 10 m

Explanation: R = u²sin 2θ/g = 400·1/10 = 40 m.

Common trap: Using sin θ instead of sin 2θ gives 28 m.

Q3. A 2 kg ball moving at 3 m/s hits a wall and rebounds at 2 m/s. The impulse is:

  • A. 2 N·s
  • B. 10 N·s
  • C. 6 N·s
  • D. 1 N·s

Explanation: Δp = m(v_f − v_i) = 2(−2 − 3) = −10 N·s; magnitude 10 N·s.

Common trap: Subtracting magnitudes (3−2 = 1) ignores the reversal of direction.

Q4. On a frictionless incline of 30°, a block's acceleration is:

  • A. g
  • B. g/2
  • C. g·√3/2
  • D. 0

Explanation: a = g sin 30° = g/2 ≈ 4.9 m/s².

Common trap: Multiplying by cos θ instead of sin θ gives the normal component, not the slope acceleration.

Q5. Two equal masses collide elastically in 1-D, one at rest. After collision:

  • A. Both stop
  • B. They stick together
  • C. Velocities are exchanged
  • D. Both move forward at u/2

Explanation: For equal masses in 1-D elastic collisions the velocities swap.

Common trap: Choosing 'both move at u/2' — that is the inelastic (stick-together) case using momentum conservation.

Frequently Asked Questions

Why is range maximum at 45°?

R = u²sin 2θ/g is maximum when sin 2θ = 1, i.e. 2θ = 90°, so θ = 45°.

Are Newton's laws valid in all frames?

Only in inertial (non-accelerating) frames. In accelerating frames you must add pseudo-forces.

What is the difference between impulse and momentum?

Momentum p = mv is the state of motion at an instant; impulse J = Δp is the change produced by a force over a time interval.

Is kinetic energy conserved in inelastic collisions?

No — only momentum is. Some KE is converted into heat, sound, or deformation.

Why is μ_s greater than μ_k?

Stationary contact allows micro-welds and interlocking asperities to develop; once sliding begins these break, reducing friction.

How Motion and Force Is Tested

MDCAT questions on Motion and Force are a mix of recall (definitions, classifications), application (predict outcomes, interpret diagrams), and basic numerical/analytical reasoning. PMDC papers from 2020–2025 emphasized the concepts above; older UHS papers (2008–2019) tested them too, with slight variations in question framing.

Practice

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See the full MDCAT 2026 syllabus or browse all Physics chapters.