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Kpk Chemistry 2021 — Solved Past Paper with Answers

All 18 MCQs from Kpk Chemistry 2021, solved with the correct answer highlighted and a full explanation for every question. This is a free MDCAT KPK / ETEA past paper — no signup, no ads. Practise it interactively in timed mode, drill more with free MDCAT MCQs, or browse all KPK / ETEA papers.

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Q1. Aldehydes or Ketones are reduced to alkanes in the presence of basic medium by.

  • A. Clemson reduction
  • B. Wolf kishner reduction
  • C. Dow process
  • D. Williamsons synthesis

Explanation: This method involves converting aldehydes and ketones to alkanes using hydrazine and a base. The reaction converts a carbonyl group to a methylene group.

Why the other options are wrong
  • A. Incorrect as per given condition because this method uses acidic medium.
  • C. Incorrect as per given condition.
  • D. Incorrect as per given condition.

Q2. Which one of the given compounds will show Silver Mirror Test.

  • A. Ethanal
  • B. Ethanol
  • C. Ether
  • D. Acetone

Explanation: The Silver Mirror Test, also known as Tollens’ Test, is a used to distinguish between aldehydes and ketones. The test is generally given by compounds having an aldehydic group. This includes aldehydes, alpha-hydroxy ketones, and formic acid (its -COOH behaves like an aldehydic group).

Why the other options are wrong
  • B. Incorrect as per fact.
  • C. Incorrect as per fact.
  • D. Incorrect as per fact.

Q3. The more acidic compound among the given is:

  • A. C6H5OH
  • B. C2H5OH
  • C. H2CO3
  • D. CH3COOH

Explanation: This is a carboxylic acid, which are generally more acidic due to the presence of a carboxyl group (-COOH).

Why the other options are wrong
  • A. Phenols are more acidic than alcohols but less acidic than carboxylic acids or carbonic acid.
  • B. Alcohols are generally the least acidic among these compounds.
  • C. This is also an acidic compound, but less acidic than carboxylic acids.

Q4. The dehydrating agent which is used in preparation of acetic anhydride from acetic acid at high temperature is.

  • A. P2O5
  • B. H2SO4
  • C. AI2O3
  • D. H3PO4

Explanation: The most commonly used dehydrating agents for this reaction is concentrated sulphuric acid (H2SO4). These agents facilitate the removal of a water molecule from two molecules of acetic acid, resulting in the formation of acetic anhydride.

Why the other options are wrong
  • A. Incorrect as per fact and given condition.
  • C. Incorrect as per fact and given condition.
  • D. Incorrect as per fact and given condition.

Q5. Which one of the given is not a disaccharide?

  • A. Sucrose
  • B. Maltose
  • C. Galactose
  • D. Lactose

Explanation: Among the sugars listed, galactose is not a disaccharide. It’s a monosaccharide, which is a single sugar unit. On the other hand, lactose, maltose, and sucrose are all disaccharides, which means they are each composed of two monosaccharide units:Lactose is composed of glucose and galactose.Maltose is composed of two glucose units.Sucrose is composed of glucose and fructose.

Why the other options are wrong
  • A. Sucrose is a disaccharide composed of glucose and fructose.
  • B. Maltose is a disaccharide composed of two glucose units.
  • D. Lactose is a disaccharide composed of glucose and galactose.

Q6. The hydrolysis of triglycerides by alkalies is called

  • A. Saponification
  • B. Esterification
  • C. Dehydration
  • D. Transesterification

Explanation: The hydrolysis of triglycerides by alkalies is called saponification. This process involves the breakdown of a fat into glycerol and fatty acid salts, commonly known as ‘soap’. The reaction can be represented as follows: Fat/oil + Alkali → Soap + Glycerol

Why the other options are wrong
  • B. It is a chemical reaction that forms an ester from a carboxylic acid and an alcohol, often releasing water as a by-product.
  • C. It is a type of elimination reaction where two molecules are removed from a reactant to form a new product, typically water is removed in this process.
  • D. It is a process where an ester is reacted with an alcohol to form a different ester, often used in biodiesel production.

Q7. Nylon (6,6) is the polymer of hexamethylene diamine and _.

  • A. Acetic acid
  • B. Picnic acid
  • C. Adipic acid
  • D. Glycol

Explanation: Nylon (6,6) is the polymer of hexamethylene diamine and adipic acid. These two compounds undergo a condensation polymerization to form Nylon (6,6), a type of polyamide.

Why the other options are wrong
  • A. Incorrect as per fact and given condition.
  • B. Incorrect as per fact and given condition.
  • D. Incorrect as per fact and given condition.

Q8. The temperature range of troposphere is:

  • A. -2°C to -92°C
  • B. 56°C to -2°C
  • C. -92°C to 1200°C
  • D. 15°C to -56°C

Explanation: The temperature in the troposphere ranges from an average of 15°C at sea level to about -57°C at the top.

Why the other options are wrong
  • A. Incorrect as per fact and given condition.
  • B. Incorrect as per fact and given condition.
  • C. Incorrect as per fact and given condition.

Q9. The spectroscopic technique which is used for determination of functional group in a compound is:

  • A. IR spectroscopy
  • B. NMR
  • C. UV spectroscopy
  • D. Mass spectroscopy

Explanation: The spectroscopic technique commonly used for the determination of functional groups in a compound is Infrared (IR) Spectroscopy. This technique is used in organic chemistry to detect the presence or absence of common functional groups. It provides detailed information about the infrared absorptions observed for various bonded atoms and groups.

Why the other options are wrong
  • B. A spectroscopic technique that observes local magnetic fields around atomic nuclei, used to determine the structure of organic molecules in solution and study molecular physics.
  • C. A type of absorption spectroscopy where light of the ultra-violet region (200-400 nm) is absorbed by the molecule, resulting in the excitation of electrons from the ground state to a higher energy state.
  • D. An analytical technique that identifies chemical substances through the sorting of gaseous ions in electric and magnetic fields according to their mass-to-charge ratios.

Q10. Those elements of group IV-A which have no tendency to form a dichloride arc.

  • A. C ans Si
  • B. P and Si
  • C. Ga and C
  • D. Gn and Si

Explanation: Carbon and Silicon do not have a tendency to form dichlorides. This is because in their most stable oxidation state of +4, as seen in compounds like CCl4 and SiCl4, these compounds do not break down into dichlorides.

Why the other options are wrong
  • B. Incorrect as per fact and given condition as P have tendency to form dichlorides.
  • C. Incorrect as per fact and given condition as Ga have tendency to form dichlorides.
  • D. Incorrect as per fact and given condition as Gn have tendency to form dichlorides.

Q11. The oxidation number of cobalt in [Co(NH3)4Cl2]Cl is.

  • A. 1
  • B. 2
  • C. 3
  • D. 4

Explanation: The oxidation number of cobalt in [Co(NH3)4Cl2]Cl can be calculated by considering the charges of the individual ions and molecules in the complex.Ammonia (NH3) is a neutral ligand, so it does not contribute to the overall charge.Chloride ions (Cl-) each have a charge of -1.The complex ion [Co(NH3)4Cl2] has a charge of +1 (due to the extra Cl- outside the brackets). Therefore, the oxidation state of Co must balance the charges contributed by the two Cl- ions inside the brackets.Let’s denote the oxidation state of Co as "x". We can set up the following equation:x + 4(0) + 2(-1) = +1Solving for "x" gives:x = +1 + 2 = +3So, the oxidation number of cobalt in [Co(NH3)4Cl2]Cl is +3.

Why the other options are wrong
  • A. Incorrect as per calculation.
  • B. Incorrect as per calculation.
  • D. Incorrect as per calculation.

Q12. The catalyst used for the conversion of SO₂ to SO3 in the manufacture of H2SO4 by contact process is.

  • A. TiCl4
  • B. V2O5
  • C. Ni
  • D. Fe

Explanation: The catalyst used for the conversion of sulfur dioxide (SO₂) to sulfur trioxide (SO₃) in the manufacture of sulfuric acid (H₂SO₄) by the contact process is vanadium pentoxide (V₂O₅). However, vanadium pentoxide is more commonly used due to its cost-effectiveness.

Why the other options are wrong
  • A. Incorrect as per fact and given condition.
  • C. Incorrect as per fact and given condition.
  • D. Incorrect as per fact and given condition.

Q13. Aromatic compounds are obtained upon fractional distillation of.

  • A. Coke
  • B. Coal gas
  • C. Ammonical liquor
  • D. Coal tar

Explanation: Aromatic compounds, which are a type of hydrocarbon, are primarily obtained from the fractional distillation of coal tar. Coal tar is a byproduct of the coking process where coal is heated in the absence of air to produce coke. This process also produces coal gas, which is used as a fuel.During the fractional distillation of coal tar, various components are separated based on their boiling points. Aromatic compounds, such as benzene, toluene, and naphthalene, are among these components and they have relatively high boiling points.

Why the other options are wrong
  • A. Incorrect as per fact and given condition.
  • B. Incorrect as per fact and given condition.
  • C. Incorrect as per fact and given condition.

Q14. The electrophile in the aromatic sulphonation reaction of benzene is:

  • A. H2SO4
  • B. SO2
  • C. H3O+
  • D. SO3

Explanation: The electrophile in the aromatic sulphonation reaction of benzene is the sulphur trioxide (SO₃) molecule.In the sulphonation reaction, concentrated sulfuric acid (H₂SO₄) is used as a catalyst to generate the actual electrophile, sulphur trioxide. The reaction proceeds via an electrophilic aromatic substitution mechanism, where the sulphur trioxide molecule acts as the electrophile and attacks the aromatic benzene ring. This results in the substitution of a hydrogen atom on the benzene ring with a sulphonic acid group (-SO₃H), forming benzene sulphonic acid.

Why the other options are wrong
  • A. Incorrect as per fact and given condition.
  • B. Incorrect as per fact and given condition.
  • C. Incorrect as per fact and given condition.

Q15. A special type of functional group isomerism in which the isomers are in dynamic equilibrium with each other is called:

  • A. Metamerism
  • B. Tautomerism
  • C. Geometric isomerism
  • D. Configurational isomerism

Explanation: The special type of functional group isomerism in which the isomers are in dynamic equilibrium with each other is called Tautomerism. Tautomers only differ in the position of the protons and electrons within the molecule while the carbon skeleton of the compound remains unchanged.

Why the other options are wrong
  • A. It is the condition of possessing or forming a linear series of body segments, commonly seen in the repetition of homologous body segments in certain organisms.
  • C. It describes the spatial arrangement of atoms within molecules that have the same chemical formulas, especially in compounds that contain either double bonds or ring structures that prevent functional groups from freely rotating around a chemical bond.
  • D. It refers to the isomers that cannot be converted into one another by rotating the molecule around a single bond.

Q16. A two step mechanism in which a carbocation is formed in first step and in second step an unsaturated compound is formed is _ mechanism.

  • A. SN1
  • B. SN2
  • C. E1
  • D. E2

Explanation: The mechanism is known as the E1 mechanism, also known as unimolecular elimination. In this mechanism, there are usually two steps involved:Ionization: During this step, a carbocation is formed as an intermediate.Deprotonation: In this step, a proton is lost by the carbocation, resulting in the formation of an unsaturated compound.

Why the other options are wrong
  • A. It’s a two-step mechanism where a carbocation is formed first, and then it is attacked by a nucleophile.
  • B. This involves a single-step process where a nucleophile displaces the leaving group from the opposite side in a concerted reaction.
  • D. This is a single-step concerted reaction where a base removes a proton from the beta-carbon, forming a pi-bond, and the leaving group departs.

Q17. Grignard's reagent react with acetaldehyde to form addition products which upon acid hydrolysis yield _.

  • A. Primary alcohol
  • B. Secondary alcohol
  • C. Tertiary alcohol
  • D. Glycol

Explanation: If we use acetaldehyde (which is a form of aldehyde) in a reaction with a Grignard reagent, the exact type of alcohol that will be formed after acid hydrolysis is a secondary alcohol. This is because the Grignard reagent adds to the carbonyl carbon of the acetaldehyde, increasing the number of carbon atoms by one and resulting in a secondary alcohol. The general structure of the resulting alcohol would be R-CH(OH)-CH3, where R represents the alkyl or aryl group of the Grignard reagent.

Why the other options are wrong
  • A. Incorrect as per fact and given condition because resulting product is secondary alcohol.
  • C. Incorrect as per fact and given condition because resulting product is secondary alcohol.
  • D. Incorrect as per fact and given condition because resulting product is secondary alcohol.

Q18. Picric acid is derivative of:

  • A. Benzene
  • B. Benzoic acid
  • C. Perchloric acid
  • D. Phenol

Explanation: Picric acid, also known as 2,4,6-trinitrophenol, is a derivative of phenol. It can be prepared by sulfonating phenol and then treating it with nitric acid.

Why the other options are wrong
  • A. Incorrect as per given condition.
  • B. Incorrect as per given condition.
  • C. Incorrect as per given condition.

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