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Punjab Chemistry 2017 Paper 1 — Solved Past Paper with Answers

All 17 MCQs from Punjab Chemistry 2017 Paper 1, solved with the correct answer highlighted and a full explanation for every question. This is a free MDCAT Punjab / UHS past paper — no signup, no ads. Practise it interactively in timed mode, drill more with free MDCAT MCQs, or browse all Punjab / UHS papers.

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Q1. Keeping in view the size of atoms,which order is correct one?

  • A. Mg > Sr
  • B. Ba>Mg
  • C. Lu>Ce
  • D. Cl>I

Explanation: Since barium is placed lower than magnesium i.e., at the bottom in the second group of periodic table, therefore barium atom are larger in size than magnesium atom and hence barium atoms loses its valence electron more readily than magnesium atom and forms positive ions i.e., cation.

Why the other options are wrong
  • A. Magnesium is a smaller atom with a smaller radius than strontium, this means the electron has a greater attraction to the nucleus. Also as strontium has more orbitals the electron has more shielding from the nucleus from the lower orbitals.
  • C. On moving from left to right in a periodic table, the atomic radius of an atom decreases due to the addition of an extra proton which leads to a stronger pull of electrons while the extra electron goes to the same principal energy level.While going down in a group, an extra energy level adds to the structure which leads to an increase in atomic radius. Thus, on moving down the group, the atomic radius increases.Cerium belongs to Lanthanoids, Tinbelongs to Group 16 and period 4, Ytterbium and Lutetiumalso belong to lanthanoids.Lanthanoids are considered in the sixth period.There is a sharp decrease in the atomic size of lanthanoids from as a result of lanthanoid contraction. The size of and is smaller than Sn.
  • D. Chlorine is a smaller atom than iodine so its outer electrons are closer to the nucleus.

Q2. Which ion will have maximum value of heat of hydration?

  • A. Na.
  • B. Cs”
  • C. Ba”
  • D. Mg”

Explanation: Therefore, lithium ion ($L{{i}^{+}}$) has the highest polarizing power. This polarizing power of the lithium is explained by the size and charge of the ion, as we know that the size of the lithium in the alkali metal ions is the smallest, due to which the ratio of charge and size is very high.

Why the other options are wrong
  • A. Higher the charge, greater the hydration energy. On the other hand, smaller the size, greater the hydration energy. Charge is considered first comparison. Hence, Mg2+ has higher hydration energy than Na+
  • C. Hydration energy increases with an increase in the charge density. So ba2+ has the highest hydration enthalpy.
  • D. Hydration energy increases with an increase in the charge density. So Mg has the highest hydration enthalpy.

Q3. Which element among the following belongs to group IVA of periodic table?

  • A. Barium
  • B. lodine
  • C. Tin
  • D. Oxygen

Explanation: Tin is a chemical element found in Group 14 (or IVa) of the periodic table (i.e., the carbon family). The tin element symbol is Sn, which is derived from the Latin name for the element - stannum. It is a silvery-white metal that is resistant to corrosion. The atomic number of tin is 50 and atomic mass is 118.71.

Why the other options are wrong
  • A. Barium is a metallic element, soft, and when pure is silvery white; it belongs to the alkaline earth group, chemically resembling calcium. The metal oxidizes very easily and should be kept under petroleum or other suitable oxygen-free liquids to exclude air. It is decomposed by water or alcohol.
  • B. iodine (I), chemical element, a member of the halogen elements, or Group 17 (Group VIIa) of the periodic table.
  • D. The oxygen family, also called the chalcogens, consists of the elements found in Group 16 of the periodic table and is considered among the main group elements. It consists of the elements oxygen, sulfur, selenium, tellurium and polonium. These can be found in nature in both free and combined states.

Q4. The oxidation of NO in air produces:

  • A. N,O -
  • B. N,O,
  • C. N,O,
  • D. N,O,

Explanation: Eventually, NO2 is oxidised to nitric acid (HNO3, vapour) which is absorbed directly at the ground, is converted into nitrate-containing particles, or dissolves in cloud droplets.

Why the other options are wrong
  • A. Eventually, NO2 is oxidised to nitric acid (HNO3, vapour) which is absorbed directly at the ground, is converted into nitrate-containing particles, or dissolves in cloud droplets.
  • B. Eventually, NO2 is oxidised to nitric acid (HNO3, vapour) which is absorbed directly at the ground, is converted into nitrate-containing particles, or dissolves in cloud droplets.
  • C. Eventually, NO2 is oxidised to nitric acid (HNO3, vapour) which is absorbed directly at the ground, is converted into nitrate-containing particles, or dissolves in cloud droplets.

Q5. Which halogen will react spontaneously with Au(s) to produce Au’?

  • A. Br, 2
  • B. F2
  • C. I2
  • D. cl2

Explanation: Chlorine ( Cl2 ) is the halogen react spontaneously with gold to produce gold ions.

Why the other options are wrong
  • A. Chlorine ( Cl2 ) is the halogen react spontaneously with gold to produce gold ions.
  • B. Chlorine ( Cl2 ) is the halogen react spontaneously with gold to produce gold ions.
  • C. Chlorine ( Cl2 ) is the halogen react spontaneously with gold to produce gold ions.

Q6. Which of the following is a typical transition metal?

  • A. Sc
  • B. Y
  • C. Co
  • D. Ra

Explanation: Group IIB elements (Zn, Cd and Hg) do not have a partially filled d-subshell either as elements or in any of their ionic state. Neither do they show typical properties of transition elements to any appreciable extent (except complex formation). Similarly, IIIB (Sc, Y and La) is another group of elements which do not show many of the properties associated with typical transition elements.

Q7. In t-butyl alcohol, the tertiary carbon atom is bonded to:

  • A. two hydrogen atoms
  • B. three hydrogen atoms
  • C. one hydrogen atom
  • D. no hydrogen atom

Explanation: tert-butyl alcohol is also called 2-methylpropan-2-ol in IUPAC system. Here the tertiary Carbon is bonded to three methyl groups and one OH group. And no hydrogen atom is bonded to the tertiary Carbon.

Why the other options are wrong
  • A. tert-butyl alcohol is also called 2-methylpropan-2-ol in IUPAC system. Here the tertiary Carbon is bonded to three methyl groups and one OH group. And no hydrogen atom is bonded to the tertiary Carbon.
  • B. tert-butyl alcohol is also called 2-methylpropan-2-ol in IUPAC system. Here the tertiary Carbon is bonded to three methyl groups and one OH group. And no hydrogen atom is bonded to the tertiary Carbon.
  • C. tert-butyl alcohol is also called 2-methylpropan-2-ol in IUPAC system. Here the tertiary Carbon is bonded to three methyl groups and one OH group. And no hydrogen atom is bonded to the tertiary Carbon.

Q8. The presence of double bond in a compound is sign of:

  • A. Saturation
  • B. Unsaturation
  • C. Substitution
  • D. Alkylation

Explanation: Compounds containing double bonds are said to be unsaturated because they are capable of reacting with hydrogen in the presence of a catalyst. The resulting compounds, which contain no multiple bonds, are said to be saturated.

Why the other options are wrong
  • A. Compounds containing double bonds are said to be unsaturated because they are capable of reacting with hydrogen in the presence of a catalyst. The resulting compounds, which contain no multiple bonds, are said to be saturated.
  • C. Compounds containing double bonds are said to be unsaturated because they are capable of reacting with hydrogen in the presence of a catalyst. The resulting compounds, which contain no multiple bonds, are said to be saturated.
  • D. Compounds containing double bonds are said to be unsaturated because they are capable of reacting with hydrogen in the presence of a catalyst. The resulting compounds, which contain no multiple bonds, are said to be saturated.

Q9. Which of the following acid can be used as a catalyst in Friedal-craft reactions?

  • A. HNO, 3
  • B. AICI, 3
  • C. Bel, 2
  • D. BCI, 3

Explanation: Aluminium trichloride (AlCl3) is often used as a catalyst in Friedel-Crafts reactions since it acts as a Lewis acid and coordinates with the halogens, generating an electrophile in the process.

Why the other options are wrong
  • A. Aluminium trichloride (AlCl3) is often used as a catalyst in Friedel-Crafts reactions since it acts as a Lewis acid and coordinates with the halogens, generating an electrophile in the process.
  • C. Aluminium trichloride (AlCl3) is often used as a catalyst in Friedel-Crafts reactions since it acts as a Lewis acid and coordinates with the halogens, generating an electrophile in the process.
  • D. Aluminium trichloride (AlCl3) is often used as a catalyst in Friedel-Crafts reactions since it acts as a Lewis acid and coordinates with the halogens, generating an electrophile in the process.

Q10. SN, reactions can be best carried out with:

  • A. Primary alkyl Halide (
  • B. Secondary alkyl Halide
  • C. Tertiary alkyl Halide
  • D. Vicinal dihalide

Explanation: Primary alkyl halides undergo SN2 reaction in a faster rate than secondary and tertiary. Of the simple alkyl halides, methyl halides react most rapidly in SN2 reactions because there are only three small hydrogen atoms.

Why the other options are wrong
  • B. Primary alkyl halides undergo SN2 reaction in a faster rate than secondary and tertiary. Of the simple alkyl halides, methyl halides react most rapidly in SN2 reactions because there are only three small hydrogen atoms.
  • C. Primary alkyl halides undergo SN2 reaction in a faster rate than secondary and tertiary. Of the simple alkyl halides, methyl halides react most rapidly in SN2 reactions because there are only three small hydrogen atoms.
  • D. Primary alkyl halides undergo SN2 reaction in a faster rate than secondary and tertiary. Of the simple alkyl halides, methyl halides react most rapidly in SN2 reactions because there are only three small hydrogen atoms.

Q11. Which compound shows maximum hydrogen bonding with water?

  • A. CH,OH
  • B. C2H6OH
  • C. CH3-O-CH3
  • D. C6H8OH

Explanation: Hydrogen bonding is defined as the formation of hydrogen bonds, which are a special type of attractive intermolecular forces that arise due to the dipole-dipole interaction between a hydrogen atom that is bonded to a highly electronegative atom and another highly electronegative atom that lies next to the hydrogen atom.In ethanol, Hydrogen is bound to more electronegative oxygen than triethylamine, where Hydrogen is bound to less electronegative nitrogen, which can be shown as;Hence, Hydrogen bonding is maximum in ethanol.

Why the other options are wrong
  • A. Hydrogen bonding is defined as the formation of hydrogen bonds, which are a special type of attractive intermolecular forces that arise due to the dipole-dipole interaction between a hydrogen atom that is bonded to a highly electronegative atom and another highly electronegative atom that lies next to the hydrogen atom.In ethanol, Hydrogen is bound to more electronegative oxygen than triethylamine, where Hydrogen is bound to less electronegative nitrogen,Hence, Hydrogen bonding is maximum in ethanol.
  • B. Hydrogen bonding is defined as the formation of hydrogen bonds, which are a special type of attractive intermolecular forces that arise due to the dipole-dipole interaction between a hydrogen atom that is bonded to a highly electronegative atom and another highly electronegative atom that lies next to the hydrogen atom.In ethanol, Hydrogen is bound to more electronegative oxygen than triethylamine, where Hydrogen is bound to less electronegative nitrogen, which can be shown as;Hence, Hydrogen bonding is maximum in ethanol.
  • D. Hydrogen bonding is defined as the formation of hydrogen bonds, which are a special type of attractive intermolecular forces that arise due to the dipole-dipole interaction between a hydrogen atom that is bonded to a highly electronegative atom and another highly electronegative atom that lies next to the hydrogen atom.In ethanol, Hydrogen is bound to more electronegative oxygen than triethylamine, where Hydrogen is bound to less electronegative nitrogen, which can be shown as;Hence, Hydrogen bonding is maximum in ethanol.

Q12. Ketones are prepared by oxidation of:

  • A. primary alcohol
  • B. secondary alcohol
  • C. tertiary alcohol
  • D. phenol

Explanation: The oxidation of alcohols is an important reaction in organic chemistry. Primary alcohols can be oxidized to form aldehydes and carboxylic acids; secondary alcohols can be oxidized to give ketones. Tertiary alcohols, in contrast, cannot be oxidized without breaking the molecule's C–C bonds.

Why the other options are wrong
  • A. The oxidation of alcohols is an important reaction in organic chemistry. Primary alcohols can be oxidized to form aldehydes and carboxylic acids; secondary alcohols can be oxidized to give ketones. Tertiary alcohols, in contrast, cannot be oxidized without breaking the molecule's C–C bonds.
  • C. The oxidation of alcohols is an important reaction in organic chemistry. Primary alcohols can be oxidized to form aldehydes and carboxylic acids; secondary alcohols can be oxidized to give ketones. Tertiary alcohols, in contrast, cannot be oxidized without breaking the molecule's C–C bonds.
  • D. The oxidation of alcohols is an important reaction in organic chemistry. Primary alcohols can be oxidized to form aldehydes and carboxylic acids; secondary alcohols can be oxidized to give ketones. Tertiary alcohols, in contrast, cannot be oxidized without breaking the molecule's C–C bonds.

Q13. Which acid is used in manufacture of synthetic fiber?

  • A. formic acid
  • B. oxalic acid
  • C. acetic acid
  • D. succinic acid

Explanation: Acetic acid is used in the synthesis of cellulose acetate, which is a synthetic fiber.

Why the other options are wrong
  • A. Acetic acid is used in the synthesis of cellulose acetate, which is a synthetic fiber.
  • B. Acetic acid is used in the synthesis of cellulose acetate, which is a synthetic fiber.
  • D. Acetic acid is used in the synthesis of cellulose acetate, which is a synthetic fiber.

Q14. Which of the following is not a fatty acid?

  • A. propanoic acid
  • B. acetic acid
  • C. phthalic acid
  • D. butanoic acid

Explanation: The term “acetic” comes from “acetum,” the Latin word for vinegar. Acetic acid is a short-chain fatty acid that dissolves into acetate and hydrogen in your body. About 5–6% of apple cider vinegar consists of acetic acid. It also contains water and trace amounts of other acids, such as malic acid

Why the other options are wrong
  • A. The term “acetic” comes from “acetum,” the Latin word for vinegar. Acetic acid is a short-chain fatty acid that dissolves into acetate and hydrogen in your body. About 5–6% of apple cider vinegar consists of acetic acid. It also contains water and trace amounts of other acids, such as malic acid
  • C. The term “acetic” comes from “acetum,” the Latin word for vinegar. Acetic acid is a short-chain fatty acid that dissolves into acetate and hydrogen in your body. About 5–6% of apple cider vinegar consists of acetic acid. It also contains water and trace amounts of other acids, such as malic acid
  • D. The term “acetic” comes from “acetum,” the Latin word for vinegar. Acetic acid is a short-chain fatty acid that dissolves into acetate and hydrogen in your body. About 5–6% of apple cider vinegar consists of acetic acid. It also contains water and trace amounts of other acids, such as malic acid

Q15. A polymeric substance that is formed in the liquid state and then hardened to a rigid solid is called a:

  • A. fiber
  • B. varnish
  • C. plastic
  • D. polyamide resin

Explanation: In materials science, a thermosetting polymer, often called a thermoset, is a polymer that is obtained by irreversibly hardening ("curing") a soft solid or viscous liquid prepolymer (resin).

Why the other options are wrong
  • A. In materials science, a thermosetting polymer, often called a thermoset, is a polymer that is obtained by irreversibly hardening ("curing") a soft solid or viscous liquid prepolymer (resin).
  • B. In materials science, a thermosetting polymer, often called a thermoset, is a polymer that is obtained by irreversibly hardening ("curing") a soft solid or viscous liquid prepolymer (resin).
  • C. In materials science, a thermosetting polymer, often called a thermoset, is a polymer that is obtained by irreversibly hardening ("curing") a soft solid or viscous liquid prepolymer (resin).

Q16. Phosphorous helps the growth of:

  • A. Root
  • B. leaf
  • C. Seed
  • D. Stem

Explanation: Phosphorus promotes healthy root growth, promotes early shoot growth, speeds ground cover for erosion protection, enhances the quality of fruit, vegetable and grain crops, and is vital to seed formation.

Why the other options are wrong
  • B. Phosphorus promotes healthy root growth, promotes early shoot growth, speeds ground cover for erosion protection, enhances the quality of fruit, vegetable and grain crops, and is vital to seed formation.
  • C. Phosphorus promotes healthy root growth, promotes early shoot growth, speeds ground cover for erosion protection, enhances the quality of fruit, vegetable and grain crops, and is vital to seed formation.
  • D. Phosphorus promotes healthy root growth, promotes early shoot growth, speeds ground cover for erosion protection, enhances the quality of fruit, vegetable and grain crops, and is vital to seed formation.

Q17. To avoid the formation of toxic compounds with chlorine which substance is used for disinfecting water:

  • A. KMnO, 4
  • B. chloramines
  • C. O3
  • D. Alums

Explanation: Most municipal drinking water treatment facilities now use chloramines instead of freely available chlorine to prevent the production of THMs. Ammonia is simply added to chlorine to create chloramines.

Why the other options are wrong
  • A. Most municipal drinking water treatment facilities now use chloramines instead of freely available chlorine to prevent the production of THMs. Ammonia is simply added to chlorine to create chloramines.
  • C. Most municipal drinking water treatment facilities now use chloramines instead of freely available chlorine to prevent the production of THMs. Ammonia is simply added to chlorine to create chloramines.
  • D. Most municipal drinking water treatment facilities now use chloramines instead of freely available chlorine to prevent the production of THMs. Ammonia is simply added to chlorine to create chloramines.

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