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Punjab Chemistry 2022 Paper 1 — Solved Past Paper with Answers

All 17 MCQs from Punjab Chemistry 2022 Paper 1, solved with the correct answer highlighted and a full explanation for every question. This is a free MDCAT Punjab / UHS past paper — no signup, no ads. Practise it interactively in timed mode, drill more with free MDCAT MCQs, or browse all Punjab / UHS papers.

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Q1. Ethanol can be converted to ethanoic acid by:

  • A. Hydorgenation
  • B. Hydration
  • C. Oxidation
  • D. Fermentation

Explanation: Primary alcohols and aldehydes are readily oxidised to corresponding carboxylic acids by oxidising agents such as potassium dichromate in an acidic medium.

Why the other options are wrong
  • A. Hydrogenation is incorrect because hydrogenation involves the addition of hydrogen to a molecule, typically in the presence of a catalyst, to produce an alkane or alkene. It does not convert ethanol to ethanoic acid.
  • B. Hydration is incorrect because hydration involves the addition of water to a molecule. While hydration of ethene can produce ethanol, it does not convert ethanol to ethanoic acid.
  • D. Fermentation is incorrect because fermentation is a biological process in which sugars are converted into alcohol and carbon dioxide by yeast or bacteria. It does not directly convert ethanol to ethanoic acid.

Q2. Which of following will react with both aldehydes and ketones?

  • A. Grignard reagent
  • B. Tollen's reagent
  • C. Fehling's reagent
  • D. Benedict's reagent

Explanation: Benedicts reagent, Gehlings reagent and Tollens reagent are used in identification tests for aldehydes and they do not react with ketones. Grignard reagent reacts with both aldehydes and ketones. With aldehydes it gives primary and secondary alcohols and with ketones it gives tertiary alcohols.

Why the other options are wrong
  • B. Tollen's reagent is incorrect because it is used to test for aldehydes, not ketones. Tollen's reagent is a solution of silver nitrate (AgNO3) and ammonia (NH3) that is used to oxidize aldehydes to carboxylic acids, producing a silver mirror on the test tube.
  • C. Fehling's reagent is incorrect because it is also used to test for aldehydes, not ketones. Fehling's reagent is a solution of copper(II) sulfate (CuSO4) and sodium hydroxide (NaOH) that is used to oxidize aldehydes to carboxylic acids, forming a red precipitate of copper(I) oxide.
  • D. Benedict's reagent is incorrect because, like Fehling's reagent and Tollen's reagent, it is used to test for aldehydes, not ketones. Benedict's reagent is a solution of copper(II) sulfate (CuSO4) and sodium citrate that is used to oxidize aldehydes to carboxylic acids, forming a red precipitate of copper(I) oxide.

Q3. Which reagent reduces carboxylic acid to an alcohol?

  • A. H2/Ni
  • B. H2/Pt
  • C. NaBH4
  • D. LiAlH4

Explanation: Carboxylic acids on reaction with lithium aluminium hydride (LiAIH4) are reduced to alcohols.

Why the other options are wrong
  • A. H2/Ni is incorrect because this reaction is typically used to reduce alkenes or alkynes to alkanes, not carboxylic acids to alcohols.
  • B. H2/Pt is incorrect for the same reason as H2/Ni. This reaction is also used to reduce alkenes or alkynes, not carboxylic acids.
  • C. NaBH4 is incorrect because it is a milder reducing agent that is typically used to reduce aldehydes and ketones to alcohols. It is not strong enough to reduce carboxylic acids to alcohols.

Q4. Which of these polymers is an addition polymer?

  • A. Nylon–6, 6
  • B. Polystrene
  • C. Terylene
  • D. Epoxy resin

Explanation: Polystyrene is an addition polymer and is obtained by the polymerization of styrene in the presence of a catalyst. Polystyrene is used in the manufacture of food containers, cosmetic bottles, toys and packing material, etc.

Why the other options are wrong
  • A. Nylon-6,6 is incorrect because it is a condensation polymer. It is formed by the condensation reaction between adipoyl chloride and hexamethylenediamine, resulting in the elimination of a small molecule, such as water, during polymerization.
  • C. Terylene is incorrect because it is also a condensation polymer. It is formed by the condensation reaction between ethylene glycol and terephthalic acid, resulting in the elimination of a small molecule, such as water, during polymerization.
  • D. Epoxy resin is incorrect because it is a thermosetting polymer, not an addition polymer. Thermosetting polymers are formed by the polymerization of monomers that cross-link to form a three-dimensional network structure. Epoxy resins are typically cured with a hardener, such as amines, to form a rigid, cross-linked polymer network.

Q5. Which is not a calcarious material?

  • A. Lime
  • B. Clay
  • C. Marble
  • D. Marine Shell

Explanation: The important raw materials used for the manufacture of cement are:1. Calcarious material (limestone, marble, chalks, marine shell) as source of CaO.2. Argillaceous material (clay, shale, slate, blast furnace slag) They provide acidic components such as aluminates and silicates,3. Other raw material being used is gypsum.

Why the other options are wrong
  • A. Lime is incorrect because it is a calcareous material. Lime is calcium oxide (CaO), which can be produced by heating limestone (calcium carbonate).
  • C. Marble is incorrect because it is a calcareous material. Marble is a metamorphic rock composed of recrystallized carbonate minerals, usually calcite or dolomite.
  • D. Marine shell is incorrect because it is also a calcareous material. Marine shells, such as those from mollusks, are composed primarily of calcium carbonate.

Q6. Satrosphere region has range of:

  • A. 0-15 km
  • B. 15-20 km
  • C. 0-5 km
  • D. 15-40 km

Explanation: The stratosphere where the ozone layer exists in the atmosphere is approximately at 15 to 40 kilometer altitudes and is just above the troposphere which extends to an altitude of 0-15 kilometer from the earth.

Why the other options are wrong
  • A. 0-15 km is incorrect because this range corresponds more closely to the troposphere, which is the lowest layer of Earth's atmosphere where most weather events occur.
  • B. 15-20 km is incorrect because it falls within the lower part of the stratosphere, but the stratosphere extends beyond 20 km.
  • C. 0-5 km is incorrect because this range corresponds to the lower portion of the troposphere, not the stratosphere.

Q7. Residence time of NO in atmosphere is:

  • A. 1 day
  • B. 2 days
  • C. 3 days
  • D. 4 days

Explanation: The residence time of NO and NO2 in the atmosphere are 4 and 3 days respectively.

Why the other options are wrong
  • A. 1 day is incorrect because this is too short for the residence time of NO in the atmosphere.
  • B. 2 days is incorrect because it is also too short for the residence time of NO in the atmosphere.
  • C. 3 days is incorrect because it is also too short for the residence time of NO in the atmosphere.

Q8. Mark the correct statement:

  • A. Na+is smaller than Na
  • B. Na+is larger than Na
  • C. Cl- is smaller than Cl
  • D. Cl- ion and Cl are equal

Explanation: When a neutral atom loses one or more electrons, it becomes a positive ion. The size of the atom is decreased in this process because of two reasons. First, the removal of one or more electrons from a neutral atom usually results in the loss of the outermost shell. Second, the removal of electrons causes an imbalance in the proton-electron ratio. Due to the greater attraction of the nuclear charge, the remaining electrons of the ion are drawn closer to the nucleus. Thus, a positive ion is always smaller than the neutral atom from which it is derived. The radius of Na is 157 pm, and the radius of Na+ is 95 pm

Why the other options are wrong
  • B. Wrong
  • C. The anionic size is larger than atomic size
  • D. The anionic size is larger than atomic size

Q9. Which of the following sulphates is not soluble in water?

  • A. Sodium sulphate
  • B. Potassium sulphate
  • C. Zinc sulphate
  • D. Barium sulphate

Explanation: Barium sulphate is insoluble in water. It forms a white precipitate when it comes into contact with water, which settles at the bottom of the container. Due to its low solubility, barium sulphate is often used as a contrast agent in medical imaging procedures like barium swallow tests.

Why the other options are wrong
  • A. Sodium sulphate is soluble in water. Most sodium salts are soluble in water, and sodium sulphate is no exception.
  • B. Potassium sulphate is also soluble in water. Similar to sodium salts, most potassium salts are soluble in water.
  • C. Zinc sulphate is soluble in water. It forms a clear solution when dissolved in water.

Q10. Which element belongs to a group of IVA of periodic table?

  • A. Ba
  • B. I
  • C. Pb
  • D. O

Explanation: The group IVA of the periodic table contains the following elements: C, Si, Ge, Sn, Pb

Why the other options are wrong
  • A. Ba (Barium) is incorrect because it belongs to Group IIA (Group 2) of the periodic table, not Group IVA.
  • B. I (Iodine) is incorrect because it belongs to Group VIIA (Group 17) of the periodic table, not Group IVA.
  • D. O (Oxygen) is incorrect because it belongs to Group VIA (Group 16) of the periodic table, not Group IVA.

Q11. The brown gas formed, when metal reduces HNO3 to:

  • A. N2O5
  • B. N2O3
  • C. NO2
  • D. NO

Explanation: The brown gas formed when HNO_3 is reduced by metal to form nitrogen dioxide which is a poisonous brown gas with an irritating odou

Why the other options are wrong
  • A. The brown gas formed when HNO_3 is reduced by metal to form nitrogen dioxide which is a poisonous brown gas with an irritating odou
  • B. The brown gas formed when HNO_3 is reduced by metal to form nitrogen dioxide which is a poisonous brown gas with an irritating odou
  • D. The brown gas formed when HNO_3 is reduced by metal to form nitrogen dioxide which is a poisonous brown gas with an irritating odor

Q12. Which is the strongest acid?

  • A. HClO
  • B. HClO2
  • C. HClO3
  • D. HClO4

Explanation: The acid strength increases with the increase in the number of oxygen atoms. As the oxidation state of the halogen increases, the bonding electrons are shifted away from the Hatom and the tendency of the molecule to lose a proton increases. This accounts for the change of strength of oxyacids. The oxyacids of halogens show their strength in the order given below:HXO4>HXO3 >HXO2 >HXO

Why the other options are wrong
  • A. HClO (hypochlorous acid) is incorrect because it is a weak acid compared to the others listed. It partially dissociates in water to produce H+ ions and hypochlorite ions (ClO-).
  • B. HClO2 (chlorous acid) is incorrect because it is a weaker acid than HClO4. It partially dissociates in water to produce H+ ions and chlorite ions (ClO2-).
  • C. HClO3 (chloric acid) is incorrect because it is weaker than HClO4. It partially dissociates in water to produce H+ ions and chlorate ions (ClO3-).

Q13. Group VIB of transition metal contains:

  • A. Zn, Cd, Hg
  • B. Fe, Ru, Os
  • C. Cr, Mo, W
  • D. Mn, Te, Re

Explanation: Group VIB of transition elements contains: Cr, Mo, W

Why the other options are wrong
  • A. Zn, Cd, Hg is incorrect because these elements are not part of Group VIB. Zinc (Zn), cadmium (Cd), and mercury (Hg) are transition metals, but they are not in Group VIB. Zinc and cadmium are in Group IIB, and mercury is in Group IIB.
  • B. Fe, Ru, Os is incorrect because these elements are not part of Group VIB. Iron (Fe), ruthenium (Ru), and osmium (Os) are transition metals, but they are not in Group VIB. Iron is in Group VIIIB, and ruthenium and osmium are in Group VIIIB.
  • D. Mn, Te, Re is incorrect because these elements are not part of Group VIB. Manganese (Mn), tellurium (Te), and rhenium (Re) are transition metals, but they are not in Group VIB. Manganese is in Group VIIB, tellurium is a metalloid in Group VIA, and rhenium is in Group VIIB.

Q14. Ether show the phenomenon:

  • A. Position isomerism
  • B. Functional group isomerism
  • C. Metamerism
  • D. Cis-trans isomerism

Explanation: This type of isomerism arises due to the unequal distribution of carbon atoms on either side of the functional group. Such compounds belong to the same homologous series. For example, diethyl ether and methyl n-propyl ether are metamers.

Why the other options are wrong
  • A. Position isomerism is incorrect because this type of isomerism involves compounds with the same molecular formula but different positions of functional groups or multiple bonds within the molecule, not alkyl groups around the functional group.
  • B. Functional group isomerism is incorrect because this type of isomerism involves compounds with the same atoms but different functional groups. Ethers do not exhibit functional group isomerism because they have the same functional group (ether linkage) in all their isomers.
  • D. Cis-trans isomerism is incorrect because this type of isomerism is specific to compounds with restricted rotation around a double bond, leading to different spatial arrangements. Ethers do not have double bonds and therefore do not exhibit cis-trans isomerism.

Q15. Synthetic rubber is made by polymerization of:

  • A. Chloroform
  • B. Acetylene
  • C. Divinylacetylene
  • D. Chloroprene

Explanation: When acetylene is passed through an acidic solution of cuprous chloride and ammonium chloride and then allowed to stand for several hours at room temperature, vinyl acetylene and divinyl acetylene are obtained. If HCl is added to vinyl acetylene, chloroprene is obtained which readily polymerize to neoprene, used as synthetic rubber.

Q16. Benzene can not undergo:

  • A. Substitution
  • B. Addition
  • C. Oxidation
  • D. Elimination

Explanation: The highly stable, delocalized electrons of benzene ring are not readily available for the nucleophillic attack like the electrons of alkenes. Therefore, the electrons of benzene ring do not assist in the attack of weak electrophiles. It means that more powerful electrophiles are required to penetrate and break the continuous sheath of electron cloud in benzene.Hence benzene undergoes electrophilic substitution. It is also oxidised in the presence of strong oxidising agent. It shows addition reaction in presence of appropriate catalyst.Benzene does not show any sort of elimination reaction.

Why the other options are wrong
  • A. Substitution is incorrect because benzene is well known for undergoing substitution reactions, such as electrophilic aromatic substitution. In these reactions, a hydrogen atom on the benzene ring is replaced by an electrophile.
  • B. Addition is incorrect because benzene does not readily undergo addition reactions like alkenes do. The delocalized electron cloud in benzene makes it more stable than typical alkenes, which makes addition reactions less favorable.
  • C. Oxidation is incorrect because benzene can undergo oxidation reactions under certain conditions. However, these reactions typically require harsh conditions or specialized reagents to oxidize benzene to compounds like phenol or benzoic acid.

Q17. For which mechanisms, the first step involved is the same:

  • A. E1 and E2
  • B. E2 and SN2
  • C. SN1 and E2
  • D. E1 and SN1

Explanation: :In E1 mechanism, like SN1 mechanism, the first step is the slow and ionization of substrate give carbocation

Why the other options are wrong
  • A. E1 has two step and E2 has single step
  • B. As the both have one step but the product are different
  • C. SN1 IS A TWO STEP REACTION WHILE E2 IS SINGLE STEP

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