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Punjab Physics 2015 Paper 2 — Solved Past Paper with Answers
All 17 MCQs from Punjab Physics 2015 Paper 2, solved with the correct answer highlighted and a full explanation for every question. This is a free MDCAT Punjab / UHS past paper — no signup, no ads. Practise it interactively in timed mode, drill more with free MDCAT MCQs, or browse all Punjab / UHS papers.
Attempt this paper interactively →Q1. Electron-volt is the unit of:
- A. Potential difference
- B. Electric energy✓
- C. Electric current
- D. Capacitance
Explanation: An electron-volt (eV) is a unit of energy equal to the energy gained or lost by an electron when it moves across an electric potential difference of one volt. It is commonly used in atomic and nuclear physics to express energy on the atomic and subatomic scale.
Why the other options are wrong
- A. The unit of potential difference is the volt (V), not electron-volt (eV). Potential difference is the amount of work done per unit charge to move a charge between two points, and it is measured in volts.
- C. The unit of electric current is the ampere (A). Electric current is the flow of electric charge per unit time, and it is measured in amperes.
- D. The unit of capacitance is the farad (F). Capacitance is the ability of a system to store charge per unit voltage, and it is measured in farads.
Q2. Coulomb's electrostatic force is:
- A. Non conservative force
- B. Conservative force✓
- C. Gravitational force
- D. Mechanical force
Explanation: Coulomb's electrostatic force is a conservative force. This means that the work done by the electrostatic force on a charged particle moving between two points is independent of the path taken and depends only on the initial and final positions of the particle
Why the other options are wrong
- A. Coulomb's electrostatic force is a conservative force, not a non-conservative force. A non-conservative force is one for which the work done in moving an object between two points is dependent on the path taken, while a conservative force is path-independent.
- C. Gravitational force is another example of a conservative force, similar to Coulomb's electrostatic force. Like the electrostatic force, the gravitational force is path-independent and depends only on the positions of the objects involved.
- D. Coulomb's electrostatic force is a type of mechanical force, as it involves the interaction between charged particles. However, the term "mechanical force" is not typically used in the context of classifying forces as conservative or non-conservative.
Q3. In case of colour code for carbon resistance, tolerance for silver band is:
- A. ±5%
- B. ±6%
- C. ±10%✓
- D. ±20%
Explanation: This tolerance is not a standard tolerance for carbon resistors in the color code system. The closest standard tolerance to ±6% is ±5% (gold band) or ±10% (silver band).
Why the other options are wrong
- A. This tolerance is typically represented by a gold band in the color code for carbon resistors. A ±5% tolerance means that the actual resistance of the resistor can deviate by up to 5% from the nominal value marked on the resistor.
- B. This tolerance is not a standard tolerance for carbon resistors in the color code system. The closest standard tolerance to ±6% is ±5% (gold band) or ±10% (silver band).
- D. This tolerance is not a standard tolerance for carbon resistors in the color code system. The ±20% tolerance is typically used for carbon composition resistors, but in the color code system, it is not represented by a specific color band. Instead, it is indicated by the absence of a fourth band, with the first three bands providing the resistance value and multiplier.
Q4. The galvanometer can be made sensitive by making the factor a C/BAN:
- A. Large
- B. Small✓
- C. Constant
- D. Intermediate
Explanation: A galvanometer can be made more sensitive by making the factor C/BAN (coil turns/magnetic field strength) smaller. This means increasing the sensitivity of the galvanometer by either increasing the number of coil turns or decreasing the magnetic field strength.
Why the other options are wrong
- A. Increasing the number of coil turns would actually make the galvanometer less sensitive, as it would require a larger current to deflect the needle by the same amount. Conversely, decreasing the coil turns would make it more sensitive.
- C. Keeping the factor (frac{C}{BAN}) constant would maintain the sensitivity of the galvanometer at its current level. Changing this factor is necessary to increase the sensitivity.
- D. An intermediate value of the factor (frac{C}{BAN}) would not necessarily make the galvanometer more sensitive. To increase sensitivity, the factor should be made large, not kept at an intermediate value.
Q5. The S.I unit of magnetic flux is:
- A. NmA-1✓
- B. NAm-1
- C. NmA-2
- D. Nm2A-1
Explanation: The SI unit of magnetic flux is the weber (Wb), which is equivalent to volt-seconds (V·s) or tesla square meters (T·m²).
Why the other options are wrong
- B. This unit also does not correspond to the SI unit of magnetic flux. N represents newtons, A represents amperes (the unit of electric current), and m⁻¹ represents meters to the power of -1 (which is not a valid unit for magnetic flux).
- C. This unit does not correspond to the SI unit of magnetic flux. N represents newtons, m represents meters, and A⁻² represents amperes to the power of -2 (which is not a valid unit for magnetic flux).
- D. As per the explanation, this option is also not correct.
Q6. Lenz's law is in accordance with the law of conservation of:
- A. Momentum
- B. Charge
- C. Energy✓
- D. Mass
Explanation: Lenz's law is in accordance with the law of conservation of energy. It states that the direction of the induced electromotive force (emf) or current is always such that it opposes the change in magnetic flux that produced it. This opposition results in the dissipation of energy as heat in the conductor.
Why the other options are wrong
- A. Lenz's law is not directly related to the conservation of momentum. Lenz's law states that the direction of an induced current in a conductor will be such that it opposes the change in magnetic flux that produced it, in accordance with the law of conservation of energy.
- B. Lenz's law is not directly related to the conservation of charge. Conservation of charge states that the total electric charge in an isolated system remains constant over time, but this is not the principle that Lenz's law is based on.
- D. Lenz's law is not directly related to the conservation of mass. The conservation of mass states that the mass of a closed system will remain constant over time, but this is not the principle that Lenz's law is based on.
Q7. If back emf in a motor decreases, then it will draw:
- A. Zero current
- B. More current✓
- C. Steady current
- D. Small current
Explanation: f the back emf decreases, the motor will draw more current to compensate for the decrease in the back emf. This increased current is necessary to maintain the power output and overcome any additional resistance in the circuit.
Why the other options are wrong
- A. If the back electromotive force (emf) in a motor decreases, it does not mean that the current will be zero. The motor will still draw some current to overcome the internal resistance and produce the necessary torque to maintain rotation.
- C. If the back emf decreases but the overall conditions remain constant, the motor will draw more current to maintain a steady power output. The current will increase until a new equilibrium is reached.
- D. If the back emf decreases, the motor will draw more current, not less. A decrease in back emf typically leads to an increase in current drawn by the motor, not a decrease.
Q8. The total reactance of RLC- series circuit at reasonce is:
- A. Equal to resistance✓
- B. Infinity
- C. Zero
- D. One
Explanation: At resonance in an RLC series circuit, the total reactance is equal to the resistance. At resonance, the inductive reactance (XL) is equal to the capacitive reactance (XC), and they cancel each other out, leaving only the resistance (R) as the total impedance of the circuit.
Why the other options are wrong
- B. The total reactance of an RLC series circuit at resonance is not infinity. At resonance, the reactances cancel out, resulting in a total impedance that is purely resistive and equal to the resistance of the circuit.
- C. The total reactance of an RLC series circuit at resonance is not zero. While the reactances cancel each other out, they do not disappear entirely; they simply balance each other to leave only the resistance as the total impedance.
- D. The total reactance of an RLC series circuit at resonance is not one. The impedance of the circuit at resonance is purely resistive and is equal to the resistance of the circuit. The reactances do not play a significant role in the impedance calculation at resonance.
Q9. Electromagnetic waves transport:
- A. Current
- B. Wavelength
- C. Energy✓
- D. Voltage
Explanation: Electromagnetic waves transport energy through space. The energy carried by an electromagnetic wave is proportional to its frequency; higher frequency waves (such as X-rays and gamma rays) carry more energy than lower frequency waves (such as radio waves).
Why the other options are wrong
- A. Electromagnetic waves do not transport current. Current is the flow of electric charge, typically in a conductor, due to the movement of electrons. Electromagnetic waves consist of oscillating electric and magnetic fields that propagate through space but do not involve the flow of electric charge.
- B. While electromagnetic waves are characterized by their wavelengths, they do not transport wavelength itself. Wavelength is a property of the wave that describes its spatial extent. Different electromagnetic waves, such as radio waves, microwaves, visible light, and X-rays, have different wavelengths.
- D. Electromagnetic waves do not transport voltage. Voltage is a measure of the electric potential difference between two points in an electric circuit. While electromagnetic waves can induce voltage in conductors through electromagnetic induction, they do not themselves transport voltage.
Q10. The S.I unit of stress is:
- A. Nm
- B. NA-1
- C. Nm-1
- D. Nm-2✓
Explanation: Nm-2 is the correct SI unit of stress. Stress is defined as force per unit area, and its SI unit is newtons per square meter (Nm⁻²), which is also known as pascal (Pa).
Why the other options are wrong
- A. Newton-meter (Nm) is the unit of torque or moment of force, not stress. Stress is a measure of force applied over a unit area and is not represented by Nm.
- B. This unit is not a valid unit for stress. N represents newtons (the unit of force), and A⁻¹ represents amperes to the power of -1, which is not relevant to stress.
- C. This unit is not a valid unit for stress. Nm⁻¹ would represent torque per unit length, which is not the correct representation for stress. Stress is defined as force per unit area, so the correct unit is Nm⁻² or pascal.
Q11. In reverse biasing, p-n junction offers:
- A. Low resistance
- B. High resistance✓
- C. Zero resistance
- D. Infinite resistance
Explanation: In reverse biasing, the p-n junction offers high resistance to the flow of current. The reverse bias voltage increases the width of the depletion region, which inhibits the flow of majority carriers across the junction, resulting in high resistance.
Why the other options are wrong
- A. In reverse biasing, the p-n junction does not offer low resistance. Instead, it offers high resistance to the flow of current. When a reverse bias voltage is applied across the junction, the majority carriers (holes in the p-region and electrons in the n-region) are pushed away from the junction, creating a depletion region with very few charge carriers, leading to high resistance.
- C. The p-n junction does not offer zero resistance in reverse biasing. Zero resistance would imply that current flows freely across the junction, which is not the case in reverse biasing. Instead, the junction offers high resistance.
- D. While the resistance of a reverse-biased p-n junction is very high, it is not technically infinite. The resistance is high enough to prevent significant current flow, but there is still a small leakage current that can pass through the junction.
Q12. The value of potential barrier for silicon diode is:
- A. 0.7 volt✓
- B. 0.3 volt
- C. 0.5 volt
- D. 0.6 volt
Explanation: While this value is close to the correct potential barrier for a silicon diode, the standard value is typically considered to be 0.7 volts. Some silicon diodes may have a slightly lower forward voltage drop, but 0.7 volts is a commonly used approximation for silicon diodes.
Why the other options are wrong
- B. This value is not typically associated with the potential barrier of a silicon diode. A forward voltage drop of 0.3 volts is more commonly associated with a germanium diode, not a silicon diode.
- C. This value is not typically associated with the potential barrier of a silicon diode. The potential barrier for a silicon diode is closer to 0.7 volts.
- D. While this value is close to the correct potential barrier for a silicon diode, the standard value is typically considered to be 0.7 volts. Some silicon diodes may have a slightly lower forward voltage drop, but 0.7 volts is a commonly used approximation for silicon diodes.
Q13. If a material object moves with speed of light, its mass becomes:
- A. Equal to rest mass
- B. Four times of rest mass
- C. Zero✓
- D. Infinite
Explanation: According to the theory of relativity, as an object with mass approaches the speed of light, its relativistic mass increases without bound. At the speed of light, the relativistic mass would theoretically become infinite, but this is not physically achievable. The energy required to accelerate an object with mass to the speed of light would be infinite, making it impossible to reach that speed.
Why the other options are wrong
- A. According to the theory of relativity, as an object approaches the speed of light, its mass increases. However, at the speed of light, the mass of the object would become infinite, not equal to its rest mass.
- B. This is not correct. The mass of an object does not become four times its rest mass when it moves at the speed of light. Instead, it approaches infinity as the speed approaches the speed of light.
- D. While the relativistic mass of an object would approach infinity as it approaches the speed of light, it would not become infinite. The concept of infinite mass is more of a theoretical limit than a physical reality, as reaching the speed of light would require an infinite amount of energy.
Q14. Davisson-Germer confirmed the:
- A. Particle nature of light
- B. Wave nature of particles
- C. Dual nature of light✓
- D. Electromagnetic nature of light
Explanation: The Davisson-Germer experiment confirmed the dual nature of light, which is the idea that light exhibits both wave-like and particle-like properties. The experiment demonstrated the wave-like nature of electrons through electron diffraction, which is analogous to the diffraction of light waves.
Why the other options are wrong
- A. The particle nature of light, also known as the photon theory of light, was proposed by Albert Einstein to explain the photoelectric effect. Davisson-Germer's experiment did not directly confirm the particle nature of light.
- B. This option does not accurately describe any specific scientific concept. The wave-particle duality of matter is a fundamental principle in quantum mechanics, stating that particles exhibit both wave-like and particle-like properties.
- D. The electromagnetic nature of light refers to light being a form of electromagnetic radiation. While this is true, Davisson-Germer's experiment was not specifically focused on confirming this aspect of light. Instead, it provided evidence for the wave-particle duality of matter.
Q15. The diameter of an atom is of the order of:
- A. 10-12m✓
- B. 10-14m
- C. 10-18m
- D. 10-8m
Explanation: This is the correct order of magnitude for the diameter of an atom. The typical size of an atom is on the order of 0.1 nanometers, which is equivalent to 10⁻¹² meters.
Why the other options are wrong
- B. This value is smaller than the typical diameter of an atom. Atoms are much larger than 10⁻¹⁴ meters in size.
- C. This value is much smaller than the typical diameter of an atom. Atoms are significantly larger than 10⁻¹⁸ meters in size.
- D. This value is larger than the typical diameter of an atom. Atoms are much smaller than 10⁻⁸ meters in size.
Q16. The amount of energy equivalent to 1 a.m.u is:
- A. 9.315MeV
- B. 93.15MeV
- C. 931.5MeV✓
- D. 2.224MeV
Explanation: This is the correct value. The energy equivalent of 1 amu is approximately 931.5 MeV (million electron volts). This value is derived from Einstein's mass-energy equivalence principle, E=mc², where E is energy, m is mass, and c is the speed of light in a vacuum. 1 amu is equivalent to approximately 931.5 million electron volts
Why the other options are wrong
- A. This value is not correct. The correct value for the energy equivalent of 1 atomic mass unit (amu) is much higher.
- B. This value is also not correct. The correct energy equivalent of 1 amu is significantly higher.
- D. This value is not correct. It is much lower than the actual energy equivalent of 1 amu.
Q17. Natural radioactivity was discovered by:
- A. H.Becquerel✓
- B. J.J Thomson
- C. Rutherford
- D. Madame curies
Explanation: Henri Becquerel discovered natural radioactivity in 1896. He accidentally discovered that uranium salts emitted rays that could fog a photographic plate, indicating the presence of a previously unknown form of radiation.
Why the other options are wrong
- B. J.J. Thomson is known for his discovery of the electron and his work on the nature of cathode rays. However, he was not the one who discovered natural radioactivity.
- C. Ernest Rutherford is known for his contributions to the understanding of the atom's structure, including the discovery of the nucleus. He conducted the famous gold foil experiment but was not the one who discovered natural radioactivity.
- D. Marie Curie, along with her husband Pierre Curie and Henri Becquerel, conducted pioneering research on radioactivity. While she made significant contributions to the study of radioactivity, she did not discover natural radioactivity; that credit goes to Henri Becquerel.
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