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Punjab Physics 2022 Paper 3 — Solved Past Paper with Answers
All 17 MCQs from Punjab Physics 2022 Paper 3, solved with the correct answer highlighted and a full explanation for every question. This is a free MDCAT Punjab / UHS past paper — no signup, no ads. Practise it interactively in timed mode, drill more with free MDCAT MCQs, or browse all Punjab / UHS papers.
Attempt this paper interactively →Q1. Sec/ohm is equal to?
- A. Coloumbs
- B. Farad✓
- C. Joule
- D. Ampere
Explanation: The unit of sec/ohm is equivalent to the unit of capacitance, which is the farad. This is because when you multiply resistance (ohms) by capacitance (farads), the result is time (seconds). Therefore, sec/ohm is equal to farad. In mathematical terms, this can be represented as:1sec/ohm=1Fwhere F stands for farad, the SI unit of capacitance.
Why the other options are wrong
- A. This is equivalent to the charge transported by a current of one ampere in one second.
- C. This is the standard unit used for energy (and work). A joule of energy is defined as the energy expended by one ampere at one volt, moving in one second.
- D. This is the unit of electric current in the International System of Units (SI). It represents the steady current produced by one volt driving a one-ohm resistance.
Q2. S.l unit of electric flux is?
- A. N/C
- B. Nm2/C✓
- C. Nm/C
- D. NCm-1
Explanation: The SI unit of electric flux is volt-meters (V m), which is also equivalent to newton-meters squared per coulomb (N m² C⁻¹).
Why the other options are wrong
- A. This unit is used for electric field strength, not electric flux. Electric field strength is measured in newtons per coulomb (N/C) because it represents the force experienced by a unit positive charge at that point.
- C. This unit doesn't have a specific physical meaning. It is not the correct unit for electric flux because it does not relate to the area through which the electric field passes.
- D. This unit does not correspond to any physical quantity related to electric flux. It seems to be a combination of newtons (N) and coulombs per meter (C/m), which are not the correct units for electric flux.
Q3. If there is a single black colour band around the body of a resistor, then the value of its resistance will be:
- A. Zero ohm✓
- B. 10 ohm
- C. 100 ohm
- D. Infinity
Explanation: A resistor with a single black band is known as a zero-ohm resistor. It’s primarily used as a wire link to connect traces on a printed circuit board (PCB). The resistor package allows the same automated pick-and-place machines to place the components on a circuit board. So, the resistance value of a resistor with a single black band is 0 ohms.
Why the other options are wrong
- B. If the first band were brown, it would represent the digit 1. However, since the band is black, the value is not 10 ohms.
- C. If the first band were brown, the second band were black (representing 0), and the third band were brown (representing the multiplier 1), the value would be 100 ohms. However, with only a single black band, this option is incorrect.
- D. This option is incorrect because the presence of a single black band indicates a specific resistance value according to the resistor color code, which is zero ohms. Infinity (∞) represents an open circuit or a resistor with extremely high resistance, which is not the case here.
Q4. If 300 turns of wire are wound on 30 cm length , then number of turns per unit length is?
- A. 10
- B. 20
- C. 100
- D. 1000✓
Explanation: The number of turns per unit length, often referred to as the turn density, can be calculated by dividing the total number of turns by the total length. In this case, you have 300 turns of wire wound on a length of 30 cm.To find the number of turns per centimeter, you would calculate:Length in cm/Number of turns=30300So, the number of turns per centimeter is 10 turns/cm.If you want the number of turns per meter (since 1 meter = 100 cm), you would multiply the number of turns per centimeter by 100:Turns per meter=10turns/cm×100=1000turns/meterSo, the number of turns per meter is 1000 turns/meter.
Why the other options are wrong
- A. This option is incorrect because 300 turns divided by 30 cm is 10 turns per cm, not per unit length.
- B. This option is incorrect because 300 turns divided by 30 cm is 10 turns per cm, not per unit length.
- C. This option is incorrect because 300 turns divided by 30 cm is 10 turns per cm, not per unit length.
Q5. Which of the following is not accurate potential measuring device?
- A. Voltmeter✓
- B. CRO
- C. Potentiometer
- D. Digital Multimeter
Explanation: It is designed to measure the electric potential difference between two points in an electric circuit. However, the accuracy of a voltmeter can be affected by factors such as its calibration, the quality of its components, and the conditions under which it is used.
Why the other options are wrong
- B. A CRO is a device used to visualize the waveform of electrical signals.
- C. A potentiometer is a variable resistor that can be used to measure potential difference (voltage) by comparing it with a known voltage. It is often used for accurate voltage measurements in electrical circuits, especially in situations where a high degree of precision is required.
- D. A digital multimeter is a versatile device that can measure several electrical properties, including voltage, current, and resistance. It typically provides accurate voltage measurements and is widely used in various electrical and electronic applications.
Q6. The rod of unit length is moving at 30° through a magnetic field of IT. If the velocity of rod is 1 m/s, then induced emf in the rod will be:
- A. 1 V
- B. 0.25 V
- C. 0.5 V✓
- D. 0.6 V
Explanation: This option states that the induced emf is 0.5 V. This is the correct answer, as the calculation using the formula for induced emf results in an emf of 0.5 V.
Why the other options are wrong
- A. This option implies that the induced emf is 1 V. However, the calculation using the given formula for induced emf does not result in 1 V. The correct calculation yields an emf of 0.5 V.
- B. This option suggests that the induced emf is 0.25 V. Again, the actual calculation using the formula yields an emf of 0.5 V, not 0.25 V.
- D. This option indicates that the induced emf is 0.6 V. However, the calculation using the formula does not support this value. The correct calculation yields an emf of 0.5 V.
Q7. In alternating current circuit, inductors behave like:
- A. Semiconductor
- B. Insulator
- C. Resistor✓
- D. Conductor
Explanation: In AC circuits, inductors behave like resistors by resisting changes in current flow, similar to how resistors oppose the flow of current.
Why the other options are wrong
- A. Semiconductors are materials with conductivity between that of conductors and insulators. They do not exhibit the same behavior as inductors in an AC circuit. Semiconductors are used in electronic devices like diodes and transistors.
- B. Insulators are materials that do not conduct electricity. They do not exhibit the same behavior as inductors in an AC circuit. Insulators are used to prevent the flow of electric current.
- D. Conductors are materials that allow the flow of electric current. While inductors do allow current to flow through them in an AC circuit, their behavior in terms of opposing changes in current is more similar to resistors than conductors.
Q8. Resistance of pure choke is:
- A. Zero
- B. Large
- C. Very small✓
- D. Infinite
Explanation: The resistance of a pure choke, which is another term for an inductor, is very small but not zero. This small resistance is often referred to as the "AC resistance" or "winding resistance" of the inductor. This resistance arises due to the resistance of the wire used to make the inductor's coil. It is typically small because the wire used for inductor coils is chosen to have low resistance to minimize energy losses.
Why the other options are wrong
- A. This is incorrect because, as mentioned above, inductors have a small but non-zero resistance due to the resistance of the wire used in their construction.
- B. This is incorrect because inductors are designed to have low resistance. A large resistance would result in significant energy losses and would not be desirable in most applications of inductors.
- D. This is incorrect because no real component can have infinite resistance. Even though the resistance of an inductor is small, it is not infinite.
Q9. The device which allows only the flow of D.C. is.
- A. Capacitor
- B. Transformer
- C. Inductor✓
- D. Generator
Explanation: An inductor allows only the flow of direct current (DC) while resisting the flow of alternating current (AC). This is because an inductor opposes changes in current, which is a characteristic of AC. In DC circuits, inductors essentially act as wires with negligible resistance.
Why the other options are wrong
- A. A capacitor blocks DC while allowing AC to pass through. It stores electrical energy in an electric field, which prevents the flow of DC once it is fully charged. In an AC circuit, a capacitor allows current to flow, but it blocks DC.
- B. A transformer is a device used to change the voltage of an alternating current (AC). It does not allow or block the flow of DC; its function is to transform AC voltages.
- D. A generator converts mechanical energy into electrical energy. It does not block or allow the flow of DC; its function is to generate electricity from mechanical energy.
Q10. Curie temperature for iron is?
- A. 1115K
- B. 1039K
- C. 750K✓
- D. 700K
Explanation: The Curie temperature for iron is approximately 770°C or 1043K. This is the temperature at which iron loses its magnetic properties. The correct option is close to this value.
Why the other options are wrong
- A. This value is not correct for the Curie temperature of iron. It is significantly higher than the actual value.
- B. This value is closer to the actual Curie temperature of iron compared to option A, but it is still lower than the correct value.
- D. This value is too low for the Curie temperature of iron. The correct temperature is higher than 700K.
Q11. If R= 10k ohm and Rz= 100k ohm, the gain of inverting amplifier is:
- A. -11
- B. -10✓
- C. 11
- D. 10
Explanation: This is the correct answer. The gain of the inverting amplifier is -10, as calculated using the formula (text{Gain} = -frac{R_{text{f}}}{R_{text{in}}}), where (R_{text{f}} = 100 text{ k}Omega ) and ( R_{text{in}} = 10 \text{ k}Omega ).
Why the other options are wrong
- A. This option suggests that the gain of the inverting amplifier is -11. However, the correct calculation yields a gain of -10, not -11. The gain is determined by the ratio of the feedback resistor to the input resistor, which in this case is -10.
- C. This option suggests that the gain of the inverting amplifier is 11. However, the gain is negative because the amplifier inverts the input signal. The correct gain is -10, not 11.
- D. This option implies that the gain of the inverting amplifier is 10. However, the gain is negative because the amplifier inverts the input signal. The correct gain is -10, not 10.
Q12. The open loop gain of op-amp is of the order of:
- A. 102
- B. 103
- C. 104
- D. 105✓
Explanation: This is the correct answer. The open-loop gain of an op-amp is typically on the order of (105) or higher, making it a very useful component for amplifying weak signals.
Why the other options are wrong
- A. This is too low for the open-loop gain of an op-amp. Op-amps are designed to have much higher gain.
- B. This is also too low for the open-loop gain of an op-amp. Op-amps typically have gains in the range of (105) or higher.
- C. While closer, this is still lower than the typical open-loop gain of an op-amp. Op-amps are designed to have gains in the range of (105) or higher.
Q13. 0.1 kg is equivalent to the energy of:
- A. 9x1016
- B. 9x1015✓
- C. 8×106
- D. 3x107
Explanation: Option B is correct because 0.1 kg is equivalent to 9x1015 joules of energy, based on the mass-energy equivalence principle stated by Einstein's famous equation E=mc2.
Why the other options are wrong
- A. This option is incorrect because 9x1016 joules is the energy equivalent of 1 kg, not 0.1 kg.
- C. This option is incorrect because 8x106 joules is much smaller than the correct value for 0.1 kg, which is 9x1015 joules.
- D. This option is incorrect because 3x107 joules is also smaller than the correct value for 0.1 kg.
Q14. The rest mass energy of an electron positron pair is:
- A. 0.51 MeV
- B. 1.02 MeV✓
- C. 0.52 MeV
- D. 3 MeV
Explanation: This option is correct because the rest mass energy of an electron is approximately 0.511 MeV and for a positron (antiparticle of the electron) is also approximately 0.511 MeV. When you add these two energies together, you get the total rest mass energy of the electron-positron pair, which is 1.022 MeV (approximately 1.02 MeV).
Why the other options are wrong
- A. This option is incorrect because 0.51 MeV is approximately the rest mass energy of a single electron or a single positron, not the total energy of an electron-positron pair.
- C. This option is incorrect because 0.52 MeV is not the correct sum of the rest mass energies of an electron and a positron.
- D. This option is incorrect because 3 MeV is much larger than the sum of the rest mass energies of an electron and a positron.
Q15. First spectral series of hydrogen atom was identified by:
- A. Lyman
- B. Balmer✓
- C. Rydberg
- D. Paschen
Explanation: The first spectral series of hydrogen, known as the Balmer series, was identified by Johann Balmer. He discovered a formula that described the wavelengths of the lines in this series, which are produced when electrons in hydrogen atoms transition from higher energy levels to the second energy level.
Why the other options are wrong
- A. This option is incorrect because the Lyman series, not the first spectral series, describes transitions of electrons in hydrogen atoms from higher energy levels to the first energy level.
- C. This option is incorrect because the Rydberg formula is a general formula for the wavelengths of spectral lines of hydrogen and other similar one-electron species, not specific to the first spectral series.
- D. This option is incorrect because the Paschen series describes transitions of electrons in hydrogen atoms from higher energy levels to the third energy level, not the first spectral series.
Q16. Slow neutrons can cause fission in a:
- A. Uranium 235✓
- B. Uranium 238
- C. Lithium
- D. Neptonium
Explanation: Slow neutrons can cause fission in Uranium-235. Slow neutrons are more likely to be captured by Uranium-235 nuclei, leading to nuclear fission reactions.
Why the other options are wrong
- B. This option is incorrect because Uranium-238 is more likely to absorb fast neutrons rather than slow neutrons. It can undergo fission with fast neutrons in a fast-neutron reactor or after being converted to Plutonium-239.
- C. This option is incorrect because Lithium is not a fissile material; it is used in some nuclear reactors as a neutron moderator or to produce Tritium, but it does not undergo fission with slow neutrons.
- D. This option is incorrect because Neptunium is not a common fissile material. It can absorb neutrons and undergo radioactive decay but is not a primary material for nuclear fission reactions.
Q17. Radio therapy is generally done with gamma rays emitted from:
- A. Sodium 24
- B. Cobalt 60✓
- C. Iodine 131
- D. Strontium 90
Explanation: Radiotherapy is often done with gamma rays emitted from Cobalt-60 sources. Cobalt-60 is a synthetic radioactive isotope with a half-life of about 5.26 years. It decays by emitting beta particles and gamma rays, and these gamma rays are used in radiotherapy to treat various medical conditions, particularly cancer.
Why the other options are wrong
- A. This option is incorrect because Sodium-24 is primarily a beta emitter and is not commonly used in radiotherapy with gamma rays.
- C. This option is incorrect because Iodine-131 is primarily a beta and gamma emitter used in nuclear medicine for diagnostics and therapies related to the thyroid gland but is not commonly used in external beam radiotherapy.
- D. This option is incorrect because Strontium-90 is a beta emitter and is not commonly used in radiotherapy with gamma rays.
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