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Uhs Mdcat 2014 — Solved Past Paper with Answers
All 220 MCQs from Uhs Mdcat 2014, solved with the correct answer highlighted and a full explanation for every question. This is a free MDCAT Punjab / UHS past paper — no signup, no ads. Practise it interactively in timed mode, drill more with free MDCAT MCQs, or browse all Punjab / UHS papers.
Attempt this paper interactively →Q1. It is our national duty to _ our vote in the general election.
- A. Throw
- B. Cast✓
- C. Drop
- D. Refuse
Explanation: Votes are always "cast", which means "to direct an entry"The verb "cast" is commonly used to refer to the act of voting in an election. The other options do not fit the context and would not make sense in this sentence.
Why the other options are wrong
- A. "Throw" is not an appropriate verb when voting in an election. It does not convey the sense of deliberate action or responsibility that is associated with voting
- C. "Drop" could describe physically placing a ballot in a box, but it is not commonly used when voting in an election.
- D. "Refuse" means to decline or reject something, and it is the opposite of what is being discussed in the sentence. The sentence is suggesting that it is a national duty to vote in the general election, so "refuse" would not make sense in this context.
Q2. She is intelligent enough to _ things to serve her own purpose.
- A. Pick
- B. Maneuver✓
- C. Give
- D. Take
Explanation: "Maneuver" is a verb, which means to perform a movement in order to secure an advantage. This is the actual context in which this vocabulary word is used here.
Why the other options are wrong
- A. "Pick" means to select something, which does not necessarily imply the skill or intentionality suggested by the sentence.
- C. "Give" means to provide or offer something, which does not fit the context of doing things to serve one's purpose.
- D. "Take" means to acquire or remove something, which also does not fit the context of doing things to serve one's own purpose.
Q3. She _ about with the excitement of hearing the news of her sister’s wedding.
- A. Ran
- B. Jigged✓
- C. Talked
- D. Wept
Explanation: Dance performed out of excitement is called a “jig”, which is the proper context for using this word in this case.Weep means to cry which happens in cases of sadness.Talking and running also do not suit the sense of the sentence.
Why the other options are wrong
- A. Talking and running also do not suit the sense of the sentence.
- C. Talking and running also do not suit the sense of the sentence
- D. Weep means to cry which happens in cases of sadness.
Q4. Everyone should be _ duties and assignments according to his/her abilities.
- A. Prevented
- B. Advised
- C. Delegated✓
- D. Suggested
Explanation: “To delegate a task” means “to assign a task” which fits most appropriately in this context that “Everyone should be assigned duties...according to his/her abilities.
Why the other options are wrong
- A. "Prevented" means to stop something from happening, which is not related to assigning duties based on abilities.
- B. "Advised" means to offer suggestions or recommendations, but it is not related to assigning duties based on abilities.
- D. "Suggested" means to propose an idea or recommend a course of action, but it does not convey the sense of assigning tasks or responsibilities to someone based on their abilities.
Q5. Spot the error.We were ten miles up the highway when I happened to saw this classified advertisement in the newspaper.
- A. We were
- B. Up the
- C. To saw this✓
- D. In the
Explanation: There is a grammatical error in option C: “happened to saw this”.We always use the present tense of the verb so it should be “see” not “saw”.
Why the other options are wrong
- A. "Prevented" means to stop something from happening, which is not related to assigning duties based on abilities.
- B. "Advised" means to offer suggestions or recommendations, but it is not related to assigning duties based on abilities.
- D. "Suggested" means to propose an idea or recommend a course of action, but it does not convey the sense of assigning tasks or responsibilities to someone.
Q6. Spot the error. “All is well what ends well”, said the father when he had finished the story.
- A. Is well what✓
- B. Said the
- C. When he had
- D. The story
Explanation: The correct phrase should be “All is well when it ends well”. 'What' doesn’t make sense here as it does not refer to a time frame.
Why the other options are wrong
- B. It is correct part of sentence so this option is incorrect.
- C. It is correct part of sentence so this option is incorrect.
- D. It is correct part of sentence so this option is incorrect.
Q7. Spot the error. Rubber tubes upon which children had swing in backyards hung suspended like stopped clock pendulums in the blazing air.
- A. Upon which
- B. Had swing in the backyards✓
- C. Suspended like
- D. In the
Explanation: “Had swing” is wrong. We always use the third form of the verb with has/have/had. Students should also note that the past tense of suspend is used i.e 'suspended' which is why we will use 'swung' instead of 'swing'.
Why the other options are wrong
- A. This phrase is a prepositional phrase, correctly used to indicate the relationship between the rubber tubes and the action of children swinging.
- C. This phrase is a simile, correctly used to compare the rubber tubes to stopped clock pendulums.
- D. This phrase is a prepositional phrase, correctly used to indicate the location of the rubber tubes.
Q8. Spot the error. The child was fully dressed and sitting in her father’s lap near the kitchen table.
- A. Fully
- B. Sitting in✓
- C. Kitchen table
- D. No error
Explanation: Dressed is past tense while “sitting” is present continuous tense making the sentence incoherent.
Why the other options are wrong
- A. The word 'fully' correctly modifies 'dressed,' so this part of the sentence is correct.
- C. 'Kitchen table' is a standard phrase referring to a piece of furniture, and there is no error here.
- D. There is indeed an error in the sentence due to the tense inconsistency, so this option is incorrect.
Q9. Spot the error. The three Abdul Rehman, like his illustrious predecessor, was a young man of twenty-three when he took office.
- A. The three✓
- B. Like his
- C. Was a
- D. When he
Explanation: "The three" is a wrong use as "the" is not used to describe a proper noun like it is done in this case. Correct use would have been "Abdul Rehman the third"
Why the other options are wrong
- B. It is correct part of sentence so this option is incorrect.
- C. It is correct part of sentence so this option is incorrect.
- D. It is correct part of sentence so this option is incorrect.
Q10. Spot the error. Enlarged and beautified by later Caliphs, Al-Zahra become the nucleus of a royal suburb whose remains partly evacuated in and after 1910, can still be seen.
- A. By later
- B. Become the✓
- C. Whose remains
- D. In and after
Explanation: The sentence is in past tense so the verb should also be in past tense hence it is wrong to use “become” instead we should use “became”.
Why the other options are wrong
- A. It is correct part of sentence so this option is incorrect.
- C. It is correct part of sentence so this option is incorrect.
- D. It is correct part of sentence so this option is incorrect.
Q11. Choose the correct sentence from the following options.
- A. I thought it over very carefully before broaching the subject to Asma.✓
- B. I thought it by very carefully before broaching the subject to Asma.
- C. I thought through very carefully before broaching the subject to Asma.
- D. I thought over very carefully before broaching the subject to Asma.
Explanation: Correct sentence structure is present in option A, having proper use of subject-verb and object. Options B and C are wrong because of the use of “by”, “through” and “over”, which goes against the basic rules of subject-verb-object.
Why the other options are wrong
- B. "I thought it by very carefully before broaching the subject to Asma" is incorrect because, "thought it by" is not a correct phrasal verb in English.
- C. "I thought through very carefully before broaching the subject to Asma" is grammatically correct, but it does not accurately convey the meaning intended in the sentence. "Think through" means to analyze or solve a problem by considering all its aspects, whereas "think over" means to consider carefully or thoroughly.
- D. "I thought over very carefully before broaching the subject to Asma" is almost identical to the correct sentence in option A), but it is missing the pronoun "it."
Q12. Select the NEAREST CORRECT MEANING of the given wordDISDAIN
- A. Vice
- B. Dislike
- C. Contempt✓
- D. Ignorance
Explanation: “The feeling that someone or something is unworthy of one's consideration or respect.” is called disdain, the same as what is meant by contempt.
Why the other options are wrong
- A. Vice means a habitual or repeated immoral behavior or practice.
- B. Dislike means a feeling of distaste or aversion towards something or someone.
- D. Ignorance means a lack of knowledge, understanding, or information about something.
Q13. Select the NEAREST CORRECT MEANING of the given wordSAGACITY
- A. Suspicious
- B. Cruelty
- C. Wisdom✓
- D. Foolishness
Explanation: SAGACITY means the quality of being intelligent which is synonymous with “WISDOM”.
Why the other options are wrong
- A. Suspicion is a feeling of distrust or doubt. It is not related to sagacity, which means having or showing good judgment.
- B. Cruelty is the willingness to cause harm or suffering to others. It is not related to sagacity, which means having or showing good judgment.
- D. Foolishness means lacking good sense or judgment. It is the opposite of sagacity, which means having or showing good judgment.
Q14. Select the NEAREST CORRECT MEANING of the given wordFLAUNT
- A. Snipe
- B. Dance
- C. Show off✓
- D. Preserve
Explanation: FLAUNT means to “display (something) ostentatiously, especially in order to provoke envy or admiration or to show defiance” which is what is meant by “show off”
Why the other options are wrong
- A. Snipe means to make a malicious or petty verbal attack.
- B. Dance means to move rhythmically to music.
- D. Preserve means to maintain something in its original state.
Q15. Select the NEAREST CORRECT MEANING of the given wordURBANE
- A. Suave✓
- B. Rough
- C. Bad
- D. Dishonest
Explanation: URBANE means a person who is courteous and refined in manner which is exactly what is meant by suave.
Why the other options are wrong
- B. Rough is the opposite of urbane, and means having an uneven surface or texture, or being crude or harsh.
- C. Bad is unrelated in meaning to urbane, and means something of poor quality or not favorable.
- D. Dishonest is also unrelated in meaning to urbane, and means not truthful or deceitful
Q16. Select the NEAREST CORRECT MEANING of the given wordDIASPORA
- A. Gathering
- B. Dispersion✓
- C. Alliance
- D. Animosity
Explanation: A diaspora is a scattered population whose origin lies in a separate geographic locale.
Why the other options are wrong
- A. This is not the correct meaning of "diaspora". While a diaspora involves a group of people, it refers specifically to the dispersion of that group.
- C. This is not the correct meaning of "diaspora". While a diaspora may involve groups forming connections with one another, it specifically refers to the dispersion of a particular group of people.
- D. This is not the correct meaning of "diaspora". Diaspora does not involve hostility or enmity.
Q17. Select the NEAREST CORRECT MEANING of the given wordIMPETUOUS
- A. Honest
- B. Impulsive✓
- C. Lazy
- D. Liar
Explanation: Impetuous suggests eagerness, violence, and rashness. Impulsivity is the tendency to act without thinking. Being impulsive leads to being impetuous. These two words are most closely related to the given options, hence impulsive is our answer.
Why the other options are wrong
- A. Honest means truthful and sincere; upright.
- C. Lazy means unwilling to work or use energy; inactive.
- D. Liar means a person who tells lies.
Q18. Select the NEAREST CORRECT MEANING of the given wordVOCIFEROUS
- A. Hidden
- B. Loud✓
- C. Strong
- D. Weak
Explanation: VOCIFEROUS is characterized by being “loud and forceful.”
Why the other options are wrong
- A. "Hidden" is not correct because "vociferous" means something loud, forceful, and characterized by a strong voice or outcry. It has nothing to do with being hidden or secretive.
- C. While "vociferous" can be associated with strong opinions or beliefs, it specifically refers to how those opinions are expressed. "Strong" doesn't capture that same idea.
- D. This option is essentially the opposite of the correct answer. "Vociferous" implies a sense of strength and conviction in one's beliefs or opinions, while "weak" suggests the opposite.
Q19. Select the NEAREST CORRECT MEANING of the given word.TRANSIENT
- A. Permanent
- B. Temporary✓
- C. Long
- D. Good
Explanation: Transient means something that ends after a a certain time/fades away, which is synonymous to “temporary”.
Why the other options are wrong
- A. Permanent: The opposite of temporary, meaning lasting or intended to last for a long time.
- C. Long: Refers to something that is of great length in time or distance.
- D. Good: Refers to something positive or desirable, and is not related to the meaning of "transient".
Q20. Select the NEAREST CORRECT MEANING of the given wordPROWESS
- A. Hindrance
- B. Skill✓
- C. Reservation
- D. Bad name
Explanation: PROWESS means “a skill or expertise in a particular activity or field”, hence the answer is B.
Why the other options are wrong
- A. "Hindrance" means an obstacle or impediment, which is the opposite of "prowess" which means skill or ability.
- C. "Reservation" can mean either an arrangement to secure something, or an area of land set aside for a particular group. It is not related to "prowess", which means skill or expertise.
- D. "Bad name" means a negative reputation or stigma, which has no connection to "prowess", which means a high level of skill or ability.
Q21. Select the NEAREST CORRECT MEANING of the given wordBEQUEATH
- A. Grant✓
- B. Imbibe
- C. Irrigate
- D. Hope
Explanation: To BEQUEATH means “to leave (property) to a person or other beneficiary by a will”. Exactly what is meant by grant.
Why the other options are wrong
- B. Imbibe: This means to drink or absorb something. It is not related to the meaning of "bequeath".
- C. Irrigate: This means to supply water to land or crops to help them grow. It is not related to the meaning of "bequeath".
- D. Hope: This means to have a feeling of expectation and desire for a certain thing to happen. It is not related to the meaning of "bequeath.
Q22. The use of living organisms in industry for the production of useful products is known as:
- A. Parasitology
- B. Biochemistry
- C. Biotechnology✓
- D. Molecular biology
Explanation: The exploitation of biological process for industrial and other purposes, especially the genetic manipulation of microorganisms for the production of useful products.
Why the other options are wrong
- A. Parasitology is the study of the interaction between parasites and their hosts. In general, parasitologists tend to concentrate on eukaryotic parasites, such as lice, mites, protozoa, and worms, with prokaryotic parasites and other infectious agents the focus of fields such as bacteriology, microbiology, and virology.
- B. Biochemistry explores chemical processes related to living organisms. It is a laboratory-based science combining biology and chemistry.
- D. Molecular biology is the branch of biology that seeks to understand the molecular basis of biological activity in and between cells, including biomolecular synthesis, modification, mechanisms, and interactions.
Q23. Plants having foreign DNA incorporated in their cells are called:
- A. Clone plants
- B. Transgenic plants✓
- C. Parthenocarpic plpants
- D. Mutant plants
Explanation: Transgenic plants are plants into which one or more genes from another species have been introduced into the genome, using genetic engineering processes.
Why the other options are wrong
- A. Creating new plants through asexual propagation, or “plant cloning”, is a successful and widely used horticultural technique that allows plant growers and gardeners to reproduce faithful copies of a source plant, otherwise known as a “mother plant”. The progeny is termed Clone plants.
- C. Parthenocarpy is a form of asexual reproduction in flowering plants. The plant growth hormones help the ovaries to mature without fertilization, which grows and produces fruit without the seeds.
- D. To artificially induce hereditary changes in plants, either physical or chemical agents are used. Such plants are called mutant plants.
Q24. Treatment by using attenuated culture of bacteria is called _.
- A. Chemotherapy
- B. Sterilization
- C. Antisepsis
- D. Vaccination✓
Explanation: An attenuated vaccine consists of live, whole bacterial celis viral particles that are treated in such a way that they have reduced virulence with in the host but retain their ability to provoke an immune response.
Why the other options are wrong
- A. Chemotherapy involves the use of drugs to treat cancer and is not related to the use of attenuated bacteria for immune responses.
- B. Sterilization is a process that eliminates all forms of life, including bacteria, and does not pertain to using weakened bacteria to provoke an immune response.
- C. Antisepsis involves the use of antiseptic agents to eliminate pathogens and is not related to the administration of attenuated bacteria.
Q25. The major cause of hepatitis B is _.
- A. Blood transfusion✓
- B. Blood clotting
- C. Absence of fibrinogen
- D. Contaminated soil
Explanation: Hepatitis B is a potentially life-threatening liver infection caused by the hepatitis B virus (HBV). It is a major global health problem. Hepatitis B is spread when blood, semen, or other body fluids from a person infected with the virus enter the body of someone who is not infected. Hepatitis B is primarily transmitted through contact with infected blood or other body fluids through blood transfusion.
Why the other options are wrong
- B. Blood clotting, or coagulation, is an important process that prevents excessive bleeding when a blood vessel is injured. Blood is clotted in the presence of fibrinogen.
- C. If the levels of fibrinogen are minimally reduced, there is less risk of bleeding but if they are low, the risk of bleeding is increased.
- D. This option is incorrect.Hepatitis B is a potentially life-threatening liver infection caused by the hepatitis B virus (HBV). It is a major global health problem. Hepatitis B is spread when blood, semen, or other body fluids from a person infected with the virus enters the body of someone who is not infected.
Q26. During animal cell division, the spindle fibres are formed from:
- A. Mitochondria
- B. Centrioles✓
- C. Ribosomes
- D. Lysosomes
Explanation: At the beginning of the nuclear division, two wheel-shaped protein structures called centrioles position themselves at opposite ends of the cell forming cell poles. Long protein fibers called microtubules extend from the centrioles in all possible directions, forming what is called a spindle.
Why the other options are wrong
- A. Mitochondria are often referred to as the powerhouses of the cell. They help turn the energy we take from food into energy that the cell can utilize.
- C. ribosome is an intercellular structure made of both RNA and protein, and it is the site of protein synthesis in the cell. The ribosome reads the messenger RNA (mRNA) sequence and translates that genetic code into a specified string of amino acids, which grow into long chains that fold to form proteins.
- D. lysosome is a membrane-bound cell organelle that contains digestive enzymes. Lysosomes are involved with various cell processes. They break down excess or worn-out cell parts. They may be used to destroy invading viruses and bacteria.
Q27. Which component of the cell is concerned with cell secretions?
- A. Plasma membrane
- B. Golgi complex✓
- C. Cytoskeleton
- D. Mitochondria
Explanation: The Golgi complex is the correct answer because it is the organelle responsible for modifying, sorting, and packaging proteins and lipids that are either secreted from the cell or sent to other locations. Proteins synthesized in the rough endoplasmic reticulum (RER) are transported to the Golgi complex for further processing. Once processed, these proteins are packaged into vesicles for secretion. The other options are not primarily involved in cell secretions: the plasma membrane regulates transport and communication, the cytoskeleton provides structural support, and mitochondria are involved in energy production.
Why the other options are wrong
- A. The plasma membrane primarily functions as a barrier controlling the entry and exit of substances from the cell. It is not directly involved in the secretion of cellular products.
- C. The cytoskeleton provides structural support for the cell, facilitates cell movement, and assists in intracellular transport, but it is not involved in cell secretions.
- D. Mitochondria are the powerhouse of the cell, generating ATP through cellular respiration. They are not involved in the secretion of cellular materials.
Q28. During which period of interphase (cell cycle) DNA is synthesized?
- A. G1
- B. G2
- C. S✓
- D. G0
Explanation: The S phase of a cell cycle occurs during interphase, before mitosis or meiosis, and is responsible for the synthesis or replication of DNA. In this way, the genetic material of a cell is doubled before it enters mitosis or meiosis, allowing there to be enough DNA to be split into daughter cells
Why the other options are wrong
- A. G1 phase (Gap 1) – G1 phase is the phase of the cell between mitosis and initiation of replication of the genetic material of the cell. During this phase, the cell is metabolically active and continues to grow without replicating its DNA.
- B. G2 phase is a period of rapid cell growth and protein synthesis during which the cell prepares itself for mitosis.
- D. The G0 phase is the phase in the cell cycle in which the cell is neither dividing nor preparing for division; hence it's in a resting phase. The cell enters this phase after it is done dividing or duplicating (mitosis).
Q29. Peptidoglycan or murein is a special or distinctive feature of the cell wall in:
- A. Algae
- B. Fungi
- C. Bacteria✓
- D. Plants
Explanation: The peptidoglycan (murein) sacculus is a unique and essential structural element in the cell wall of most bacteria. Peptidoglycan or murein is a unique large macromolecule, a polysaccharide, consisting of sugars and amino acids that form a mesh-like peptidoglycan layer outside the plasma membrane, the rigid cell wall characteristic of most bacteria.
Why the other options are wrong
- A. Algae are the plants with the simplest organization. Many of them are single-celled, some have no cell wall, and others do though their composition and structure differ strongly from that of higher plants. They are good specimens for tracing back the evolution of the cell wall.
- B. The cell wall in fungi provides structural support and protection against environmental stress. It is made of glucans for rigidity, chitin for strength, and glycoproteins for stability and signaling. This composition differs from bacterial cell walls, which contain peptidoglycan.
- D. The plant cell wall is primarily composed of cellulose, a polysaccharide that provides strength and rigidity. It helps maintain cell shape, resists turgor pressure, and protects against mechanical stress. Cellulose also allows plants to grow upright and form complex tissues.
Q30. In mitochondria, small knob-like structures called F1 particles are found in:
- A. Outer membrane
- B. Outer compartment
- C. Inner membrane✓
- D. Inner compartment
Explanation: The inner membrane of mitochondria has infoldings called cristae. Small knob-like structures are present on cristae. These knob-like structures are called F1 particles.
Why the other options are wrong
- A. This option is incorrect. The outer mitochondrial membrane is smooth and has pores that allow free movement of substances. It does not contain knob-like structures or F1 particles.
- B. This option is incorrect. Outer compartment is the space between inner and outer mitochondrial membranes. It does not contain F1 particles.
- D. This option is incorrect. The inner compartment is the space enclosed by the inner mitochondrial membrane. It contains a fluid called matrix that contains many enzymes required for certain metabolic processes.
Q31. The most critical phase of mitosis which ensures equal distribution of chromatids in the daughter cells is:
- A. Prophase
- B. Metaphase
- C. Anaphase✓
- D. Telophase
Explanation: The third stage of cell division, between metaphase and telophase, during which the chromosomes move away from one another to opposite poles of the spindle.
Why the other options are wrong
- A. Prophase is the first stage of cell division in both mitosis and meiosis. Beginning after interphase, DNA has already been replicated when the cell enters prophase. The main occurrences in prophase are the condensation of the chromatin reticulum and the disappearance of the nucleolus.
- B. It is the second stage of cell division, between prophase and anaphase, during which the chromosomes become attached to the spindle fibres.
- D. The final phase of cell division, between anaphase and interphase, in which the chromatids or chromosomes move to opposite ends of the cell and two nuclei are formed.
Q32. Non-disjunction of the 21st pair of chromosomes in one of the gametes leads to 47 chromosomes in one individual. This condition is called
- A. Turner’s syndrome
- B. Klinefelter’s syndrome
- C. Down syndrome✓
- D. Jacob’s syndrome
Explanation: Down syndrome is usually caused by an error in cell division called “nondisjunction.” Nondisjunction results in an embryo with three copies of chromosome 21 instead of the usual two. Before or at conception, a pair of 21st chromosomes in either the sperm or the egg fails to separate.
Why the other options are wrong
- A. Turner syndrome, a condition that affects only females, results when one of the X chromosomes (sex chromosomes) is missing or partially missing. Turner syndrome can cause a variety of medical and developmental problems, including short height, failure of the ovaries to develop, and heart defects.
- B. The 47, XXY karyotype of Klinefelter syndrome spontaneously arises when paired X chromosomes fail to separate (nondisjunction in stage I or II of meiosis, during oogenesis or spermatogenesis). Maternal and paternal meiotic nondisjunction each account for approximately 50% of Klinefelter syndrome cases.
- D. Jacob's syndrome is a rare genetic abnormality in which a male receives an extra Y chromosome from his father.
Q33. The intake of liquid materials across the cell membrane is:
- A. Phagocytosis
- B. Pinocytosis✓
- C. Endocytosis
- D. Exocytosis
Explanation: The ingestion of liquid material into a cell by the budding of small vesicles from the cell membrane is called pinocytosis while the process by which certain living cells called phagocytes ingest or engulf other cells or solid particles is called phagocytosis.
Why the other options are wrong
- A. Phagocytosis is a process wherein a cell binds to the item it wants to engulf on the cell surface and draws the item inward while engulfing around it. It is the taking in of solid particles.
- C. Endocytosis is a cellular process by which the extracellular materials or cargo are transported into intracellular compartments by a series of pathways followed by the formation of vesicles.
- D. Exocytosis is the fusion of secretory vesicles with the plasma membrane and results in the discharge of vesicle content into the extracellular space and the incorporation of new proteins and lipids into the plasma membrane.
Q34. Which one of the following is the site of oxidative phosphorylation in mitochondria?
- A. Cristae✓
- B. Matrix
- C. Outer membrane
- D. Ribosomes
Explanation: The site of oxidative phosphorylation in mitochondria is the inner mitochondrial membrane. While the inner mitochondrial membrane is the primary site of oxidative phosphorylation, it is essential to mention that the specific structures within the inner membrane called cristae play a crucial role in this process. Cristae are the infoldings or protrusions of the inner mitochondrial membrane, and they significantly increase the surface area available for the various proteins involved in oxidative phosphorylation. Within the inner mitochondrial membrane, there is a series of protein complexes collectively known as the electron transport chain (ETC). This is where the transfer of electrons takes place, and the energy released during this process is used to pump protons across the inner mitochondrial membrane, creating a proton gradient. The enzyme ATP synthase, also located in the inner mitochondrial membrane, utilizes the energy from the proton gradient to synthesize ATP from ADP and inorganic phosphate. This entire process of electron transport and ATP synthesis is referred to as oxidative phosphorylation.
Why the other options are wrong
- B. This is incorrect. The mitochondrial outer membrane separates the intermembrane space from the cytosol. The whole exchange of metabolites, cations and information between mitochondria and the cell occurs through the outer membrane.
- C. This is incorrect. The mitochondrial outer membrane separates the intermembrane space from the cytosol. The whole exchange of metabolites, cations and information between mitochondria and the cell occurs through the outer membrane.
- D. This is incorrect. Mitochondrial ribosomes (mitoribosomes) perform protein synthesis inside mitochondria.
Q35. Organelle involved in the synthesis of ATP is
- A. Ribosome
- B. Mitochondria✓
- C. Nucleus
- D. Centriole
Explanation: The classic role of mitochondria is oxidative phosphorylation, which generates ATP by utilizing the energy released during the oxidation of the food we eat. ATP is used in turn as the primary energy source for most biochemical and physiological processes, such as growth, movement, and homeostasis.
Why the other options are wrong
- A. Ribosome is an intracellular structure made of both RNA and protein, and it is the site of protein synthesis in the cell. The ribosome reads the messenger RNA (mRNA) sequence and translates that genetic code into a specified string of amino acids, which grow into long chains that fold to form proteins.
- C. The nucleus is the membrane-enclosed organelle within a cell that contains the chromosomes. An array of holes, or pores, in the nuclear membrane allows for the selective passage of certain molecules (such as proteins and nucleic acids) into and out of the nucleus.
- D. Centrioles are paired barrel-shaped organelles located in the cytoplasm of animal cells near the nuclear envelope. Centrioles play a role in organizing microtubules that serve as the cell's skeletal system. They help determine the locations of the nucleus and other organelles within the cell.
Q36. The most common respiratory substrate as an energy source is:
- A. Glucose✓
- B. Sucrose
- C. Fructose
- D. Insulin
Explanation: The most common respiratory substrate (a substance that undergoes oxidation in cellular respiration to produce energy) is glucose. Glucose is a simple sugar and is a primary source of energy for many organisms. In cellular respiration, glucose is oxidized to produce carbon dioxide, water, and energy in the form of adenosine triphosphate (ATP).
Why the other options are wrong
- B. Sucrose is an easily assimilated macronutrient that provides a quick source of energy, provoking a rapid rise in blood glucose upon ingestion. Sucrose, as a pure carbohydrate, has an energy content of 3.94 kilocalories per gram.
- C. Fructose cannot be directly used as an energy source by all cells of the human body and needs first to be converted into glucose, lactate or fatty acids in the liver, intestine and kidney.
- D. Insulin allows cells in the muscles, liver and fat (adipose tissue) to take up this glucose and use it as a source of energy so they can function properly. Without insulin, cells are unable to use glucose as fuel and they will start malfunctioning.
Q37. The simplest monosaccharide containing keto group is:
- A. Glyceraldehyde
- B. Dihydroxyacetone✓
- C. Glucose
- D. Ribose
Explanation: Dihydroxy acetone is the simplest monosaccharide with a keto group. It is a 3-carbon sugar (a triose) and is classified as a ketotriose.
Why the other options are wrong
- A. Glyceraldehyde is a three-carbon monosaccharide (a triose) with an aldehyde functional group. It lacks a keto group, thus cannot be the simplest monosaccharide with a keto group.
- C. Glucose is a six-carbon monosaccharide (a hexose) with an aldehyde group in its linear form. It is not a keto sugar and is more complex than the simplest monosaccharide containing a keto group.
- D. Ribose is a five-carbon monosaccharide (a pentose) with an aldehyde group. It does not have a keto group and is not the simplest monosaccharide with a keto group.
Q38. If the genetic code is made up of three nucleotides, then total possible genetic codes will be:
- A. 4
- B. 20
- C. 64✓
- D. 61
Explanation: Each group of three nucleotides encodes an amino acid. The total number of genetic codes can be found by 4^3 = 64, where 4 is the total number of nucleotide bases and 3 is the number of bases that can be in one genetic code.
Why the other options are wrong
- A. Four is the total number of nucleotide bases.
- B. The smallest combination of four bases that could encode all 20 amino acids would be a triplet code. Thus, figure 20 depicts the total number of amino acids.
- D. The electron transport chain is a series of four protein complexes that couple redox reactions, creating an electrochemical gradient that leads to the creation of ATP in a complete system named oxidative phosphorylation. It occurs in mitochondria in cellular respiration.
Q39. Waterproof surfaces like cuticle of leaf and protective covering of an insect’s body are
- A. Phospholipids
- B. Waxes✓
- C. Terpenoids
- D. Acylglycerols
Explanation: Cutin in leaves and exoskeleton of insects is made up of wax. Cutin and suberin are complex bio polyesters composed of fatty acids and aromatic compounds. Cutin is the major component of the cuticle, the waxy, water-repelling surface layer of cell walls exposed to the environment aboveground An insect's exoskeleton (integument) serves not only as a protective covering over the body, but also as a surface for muscle attachment, a water-tight barrier against desiccation, and a sensory interface with the environment.
Why the other options are wrong
- A. Phospholipids are major membrane lipids that consist of lipid bilayers. This basic cellular structure acts as a barrier to protect the cell against various environmental insults and more importantly, enables multiple cellular processes to occur in subcellular compartments.
- C. Several terpenoids have their roles in plant defense against biotic and abiotic stresses or they are treated as signal molecules to attract the insects of pollination.
- D. Their primary function is to serve as fat storage molecules. They may be classified based on the number of fatty acids reacting with glycerol.
Q40. In translation, the terminating codon is:
- A. GUA
- B. UAA✓
- C. UUG
- D. AGU
Explanation: UAA, UAG, and UGA are stop codons. They do not code for any amino acid, instead signal termination of translation.
Why the other options are wrong
- A. It is not a stop codon. The RNA codon GAU codes for the amino acid Aspartic Acid.
- C. This option is incorrect because UUG is not a nonsense codon. The UUG codon codes for the essential amino acid Leucine (Leu).
- D. This codon codes for serine, not a stop codon.
Q41. All coenzymes are derived from
- A. Proteins
- B. Carbohydrates
- C. Metal ions
- D. Vitamins✓
Explanation: Coenzymes are organic compounds required by many enzymes for catalytic activity. Coenzymes are mostly derived from vitamins and other organic essential nutrients in small amounts.
Why the other options are wrong
- A. Enzymes are proteins comprised of amino acids linked together in one or more polypeptide chains.
- B. Carbohydrates, or carbs, are sugar molecules. Along with proteins and fats, carbohydrates are one of three main nutrients found in foods and drinks.
- C. Metal ions are essential for the catalytic action of some enzymes. Metal ions contribute to the catalytic process through their ability to attract or donate electrons. Iron is an example.
Q42. The competitive inhibitors have structural similarity with:
- A. Active site
- B. Binding site
- C. Substrate✓
- D. Coenzyme
Explanation: The competitive inhibitor has structural similarity with the substrate, hence it interferes with the substrate binding to the enzyme molecule.
Why the other options are wrong
- A. The active site is a groove or crevice on an enzyme in which a substrate binds to facilitate the catalyzed chemical reaction.
- B. The binding site on enzymes is often referred to as the active site because it contains amino acids that both bind the substrate and aid in its conversion to product.
- D. Coenzymes are organic compounds required by many enzymes for catalytic activity. Coenzymes are mostly derived from vitamins and other organic essential nutrients in small amounts.
Q43. Which one of the following is the optimum pH of pancreatic lipase enzyme?
- A. 7.60
- B. 8.00
- C. 9.00✓
- D. 9.70
Explanation: Pancreatic lipase has an optimum pH of 9.00, which aligns with its role in the alkaline environment of the small intestine, where it aids in the digestion of fats. Other enzymes like catalase and chymotrypsin have different pH optima due to their distinct functions and locations. For example, catalase works best at a neutral pH of 7.60, and chymotrypsin is optimal in the range of 7.00-8.00. Arginase, on the other hand, functions well at a pH closer to 9.70.
Why the other options are wrong
- A. This option is incorrect. A pH of 7.60 is optimal for the enzyme catalase, which operates in a more neutral environment.
- B. This option is incorrect. The pH range of 7.00-8.00 is optimal for chymotrypsin, which functions in a slightly less alkaline environment compared to pancreatic lipase.
- D. This option is incorrect. A pH of 9.70 is closer to the optimum for arginase, another enzyme, and is too alkaline for pancreatic lipase.
Q44. A cofactor tightly bound to the enzyme on the permanent basis is called:
- A. Activator
- B. Coenzyme
- C. Prosthetic group✓
- D. Apo-enzyme
Explanation: Prosthetic groups are cofactors very tightly bound to the inactive enzyme (called apoenzyme), even covalently in some cases. Examples of them are the biotin and heme groups, cytochrome C, flavin mononucleotide, and FAD.
Why the other options are wrong
- A. Enzyme activators are molecules that bind to enzymes and increase their activity.
- B. Coenzymes are organic compounds required by many enzymes for catalytic activity. Coenzymes are mostly derived from vitamins and other organic essential nutrients in small amounts.
- D. Apoenzyme or apoprotein is an enzymatically inactive protein part of an enzyme, which requires a cofactor for its activity.
Q45. Which of the following cells are mainly infected by HIV?
- A. T-killer lymphocytes
- B. T-helper lymphocytes✓
- C. B-plasma cells
- D. B-memory cells
Explanation: The correct answer is option B—helper T-lymphocytes (CD4+ T-cells). These cells, derived from T-cells maturing in the thymus, coordinate the immune response by activating other immune cells. T-killer (cytotoxic) T-cells destroy infected cells, while B-plasma cells produce antibodies, and B-memory cells provide long-term immunity. HIV specifically targets helper T-lymphocytes, impairing immune coordination, which makes the other options incorrect.
Why the other options are wrong
- A. T-killer lymphocytes, also known as cytotoxic T-cells, are a type of T-cell that is responsible for killing infected cells. They are a part of the adaptive immune system and play a role in cell-mediated immunity. T-killer lymphocytes are derived from T-cells that mature in the thymus gland. In the thymus, T-cells are exposed to a variety of antigens, which helps them to develop the ability to recognize and respond to specific invaders. HIV attacks on helper T-lymphocytes so this option is incorrect.
- C. B-plasma cells are mature B-cells that produce antibodies. They are found in the bone marrow and lymph nodes. B-plasma cells are responsible for the humoral immune response, which is the part of the immune system that fights infection using antibodies. HIV attacks helper T-lymphocytes, so this option is incorrect.
- D. B-memory cells are a type of B-cell that is produced during the primary immune response. They are long-lived cells that can survive for many years. B-memory cells are important for the secondary immune response, which is the faster and more robust immune response that occurs when a person is exposed to an antigen that they have been exposed to before. HIV attacks helper T-lymphocytes, so this option is incorrect.
Q46. Which one of the following antibiotics causes permanent discoloration of teeth in young children if it is misused?
- A. Penicillin
- B. Streptomycin
- C. Sulfonamide
- D. Tetracycline✓
Explanation: Tetracycline is a short-acting antibiotic that inhibits bacterial growth by inhibiting translation. Intrinsic, permanent tooth discoloration is well known to occur with the use of tetracycline antibiotics if taken during tooth development (ie, the last half of pregnancy, infancy, and in childhood up to eight years of age). Hence, option D is correct.
Why the other options are wrong
- A. Penicillin is a medication used to manage and treat a wide range of infections. It is in the beta-lactam antibiotic class of drugs. This activity describes penicillin's indications, action, and contraindications as a valuable agent in treating a bacterial infection.
- B. Streptomycin is the first discovered aminoglycoside antibiotic, originally isolated from the bacteria Streptomyces griseus. It is now primarily used as part of the multi-drug treatment of pulmonary tuberculosis. It has additional activity against several aerobic gram-negative bacteria.
- C. Sulfonamides belong to an important class of synthetic antimicrobial drugs that are pharmacologically used as broad spectrum for the treatment of human and animal bacterial infections.
Q47. What are the sequences of steps in which a bacteriophage attacks bacteria and injects its DNA?
- A. Landing → Tail contraction → Penetration → DNA Injection✓
- B. Penetration → Landing → Tail contraction → DNA Injection
- C. Tail contraction → Landing → DNA Injection → Penetration
- D. Landing → Penetration → Tail contraction → DNA Injection
Explanation: The phage first attaches itself by its tail to the cell wall of bacterium at a point called receptor site. The phage contains an enzyme called lysosome, which digest the cell wall of bacterium. Thus an opening is formed in the bacterial cell wall. The phage contracts and injects its DNA inside the host while the protein coat and the tail remain outside. Thus, Option A is correct
Why the other options are wrong
- B. These are ruled out because of incorrect sequence.The phage first attaches itself by its tail to the cell wall of bacterium at a point called receptor site. The phage contains an enzyme called lysosome, which digest the cell wall of bacterium. Thus an opening is formed in the bacterial cell wall. The phage contracts and injects its DNA inside the host while the protein coat and the tail remain outside.
- C. These are ruled out because of incorrect sequence.The phage first attaches itself by its tail to the cell wall of bacterium at a point called receptor site. The phage contains an enzyme called lysosome, which digest the cell wall of bacterium. Thus an opening is formed in the bacterial cell wall. The phage contracts and injects its DNA inside the host while the protein coat and the tail remain outside.
- D. These are ruled out because of incorrect sequence.The phage first attaches itself by its tail to the cell wall of bacterium at a point called receptor site. The phage contains an enzyme called lysosome, which digest the cell wall of bacterium. Thus an opening is formed in the bacterial cell wall. The phage contracts and injects its DNA inside the host while the protein coat and the tail remain outside.
Q48. Athlete’s Foot is a disease caused by
- A. Bacteria
- B. Virus
- C. Fungus✓
- D. Arthropod
Explanation: Athlete's foot is an infection of the feet caused by fungus. The medical term is tinea pedis or ringworm of the foot.
Why the other options are wrong
- A. Bacteria includes a number of microorganisms which are responsible for various infections in humans.
- B. A virus is an infectious microbe consisting of a segment of nucleic acid (either DNA or RNA) surrounded by a protein coat. A virus cannot replicate alone; instead, it must infect cells and use components of the host cell to make copies of itself.
- D. Arthropods are invertebrates with jointed legs. They make up about 75% of all animals on Earth and have a major role in maintaining ecosystems.
Q49. Ascaris is which one of the following?
- A. Ectoparasite
- B. Respiratory tract parasite
- C. Intestinal parasite✓
- D. Urinogenital tract parasite
Explanation: Ascaris lumbricoides is an intestinal parasite of man.
Why the other options are wrong
- A. Parasites that live on the external surface of their host organisms. Ascaris is not an ectoparasite.
- B. Ascaris primarily infests the intestines, not the respiratory tract.
- D. Ascaris does not primarily infect the urinogenital tract; its main location is the intestines.
Q50. Polymorphism is a feature exhibited by members of:
- A. Coelenterates✓
- B. Arthropoda
- C. Porifera
- D. Platyhelminthes
Explanation: Polymorphism is the phenomenon where individuals within the species exhibit various functional and structural differences. Phylum coelenterata which shows polymorphism as individuals are sighting of it possessing modified polyp-like structures. It is particularly seen in its member Hydrozoa.
Why the other options are wrong
- B. Arthropods are invertebrates with jointed legs. They make up about 75% of all animals on Earth and have a major role in maintaining ecosystems.
- C. Poriferans are pore-bearing first multicellular animals. The pores are known as Ostia. The poriferans have a spongy appearance and are therefore called sponges.
- D. The simplest animals that are bilaterally symmetrical and triploblastic (composed of three fundamental cell layers) are the Platyhelminthes, the flatworms.
Q51. _is a process by which the cell takes in fluids along with dissolved small molecules. In this process, the cell membrane folds and creates small pockets and captures the cellular fluid and dissolved substances.
- A. Pinocytosis✓
- B. Phagocytosis
- C. Transcytosis
- D. Active Transport
Explanation: Pinocytosis is the cellular process by which a cell takes in fluids along with dissolved small molecules. It involves the folding of the cell membrane to form small pockets or vesicles. Unlike phagocytosis, pinocytosis is a passive process that does not require energy expenditure by the cell. Transcytosis involves transporting molecules across a cell, while active transport requires energy to move molecules against their concentration gradient.
Why the other options are wrong
- B. Phagocytosis, on the other hand, is a process where the cell engulfs large solid particles, such as bacteria or cellular debris. This is often referred to as cellular eating.
- C. Transcytosis involves the transport of molecules or particles across a cell by first endocytosing them on one side of the cell and then exocytosing them on the opposite side.
- D. Active transport is a process that requires the cell to expend energy (usually in the form of ATP) to move molecules or ions against their concentration gradient, from an area of lower concentration to an area of higher concentration.
Q52. Which one of the following is an example of a free living carnivorous flatworm?
- A. Liver fluke
- B. Dugesia✓
- C. Tapeworm
- D. Schistosoma
Explanation: Dugesia is a member of the phylum Planaria. Planarians are free-living flatworms and have a much simpler life history. They inhabit freshwater and are carnivores (even without teeth) or scavengers.
Why the other options are wrong
- A. Liver flukes are an important cause of fascioliasis in grazing sheep and cattle. The primary host for liver fluke is sheep and intermediate host is snail.
- C. Tapeworms are flat, segmented worms that live in the intestines of some animals. Animals can become infected with these parasites when grazing in pastures or drinking contaminated water.
- D. Schistosoma are trematodes whose complex life cycles require an intermediate freshwater snail host; they infect approximately 200 million people worldwide.
Q53. The sources of staple food for man are plants that belong to the family:
- A. Mimosaceae
- B. Poaceae✓
- C. Rosaceae
- D. Fabaceae
Explanation: Poaceae, commonly known as the grass family, is one of the largest and most economically important families of flowering plants. The Poaceae family includes a wide variety of grasses, ranging from small, herbaceous plants to large, woody bamboos. Many grasses in the Poaceae family are of great economic importance for humans and animals. They are used as staple food crops, for forage, as ornamental plants, and for the production of materials such as paper and thatch. This family includes major cereal crops that serve as staples worldwide, such as rice (Oryza sativa), wheat (Triticum aestivum), maize (corn, Zea mays), barley (Hordeum vulgare), and oats (Avena sativa).
Why the other options are wrong
- A. It is commonly called the Acacia family. It includes 40 genera and 2000 species. The members are mostly distributed in tropical and subtropical regions. Some of the most important commercial species include soybeans (Glycine max), garden peas (Pisum sativum), peanuts (Arachis hypogaea), and alfalfa (Medicago sativa).
- C. The family Rosaceae includes herbs, shrubs, and trees. Most species are deciduous, but some are evergreen.
- D. Fabaceae, also called Leguminosae, pea family of flowering plants (angiosperms), within the order Fabales.
Q54. In humans, Escherichia coli is involved in the formation of?
- A. Calcium
- B. Vitamin D
- C. Vitamin A
- D. Vitamin K✓
Explanation: E. coli benefits its host in several ways. It produces vitamin K and vitamin B12, both of which are required by mammalian hosts. They live upon the undigested food passing through the caecum and help in the better absorption of food. The deficiencies of these vitamins cause many diseases, like beriberi or pernicious anemia. Therefore, option D is correct.
Why the other options are wrong
- A. The body only gets the calcium it needs through the food you eat, or from supplements. If you do not get enough calcium in your diet, or if your body does not absorb enough calcium, your bones can get weak or will not grow properly.
- B. Vitamin D3 is synthesized in human skin from 7-dehydrocholesterol following exposure to ultraviolet B (UVB) radiation with a wavelength of 290 to 320 nm.
- C. Vitamin A is synthesised from plant and bacterial carotenoid precursors. Vitamin A is soluble in lipid solvents. Many of the steps that are involved in the digestion, absorption, distribution, and transport of vitamin A are analogous to those associated with lipid metabolism.
Q55. The function of Goblet cells is to secrete:
- A. Gastrin
- B. Hydrochloric acid
- C. Pepsinogen
- D. Mucus✓
Explanation: The primary function of goblet cells is to secrete mucin and create a protective mucus layer. Goblet cells are also thought to be involved with immunoregulation. Samples of goblet cells can be preserved through cryopreservation and analyzed with light microscopy.
Why the other options are wrong
- A. G-cells are neuroendocrine cells responsible for the synthesis and secretion of gastrin. They are primarily found in the pyloric antrum but can also be found in the duodenum and the pancreas.
- B. Hydrochloric acid secretion by the gastric parietal cell is necessary for pepsinogen activation (pH <5.0) and to reduce bacterial colonization.
- C. Gastric chief cells secrete pepsin as an inactive zymogen called pepsinogen. Parietal cells within the stomach lining secrete hydrochloric acid that lowers the pH of the stomach. A low pH (1.5 to 2) activates pepsin.
Q56. Gastric glands are composed of _ types of cells.
- A. Two
- B. Three
- C. Four✓
- D. Five
Explanation: The gastric glands are composed of 4 types of cells: Mucus cells: These cells secrete mucus that protects the stomach lining from the corrosive nature of stomach acid. Parietal cells: These cells secrete hydrochloric acid (HCl) and intrinsic factor. Hydrochloric acid is crucial for digestion, while intrinsic factor is needed for vitamin B12 absorption. Chief cells: These cells secrete pepsinogen, an inactive enzyme that is converted to the active enzyme pepsin when exposed to hydrochloric acid. Endocrine cells: These cells secrete hormones like gastrin, which stimulate the production of stomach acid.
Why the other options are wrong
- A. Incorrect options. The gastric glands are composed of 4 types of cells;1. Mucus Cells2. Parietal Cells3. Chief Cells4. Endocrine Cells
- B. Incorrect options. The gastric glands are composed of 4 types of cells;1. Mucus Cells2. Parietal Cells3. Chief Cells4. Endocrine Cells
- D. Incorrect options. The gastric glands are composed of 4 types of cells;1. Mucus Cells2. Parietal Cells3. Chief Cells4. Endocrine Cells
Q57. HCL in gastric Juice is secreted by which one of the following cells?
- A. Chief cells
- B. Mucous cells
- C. Oxyntic cells✓
- D. Kupffer cells
Explanation: Oxyntic (or parietal) cells of the stomach secrete hydrochloric acid.
Why the other options are wrong
- A. Chief cells are also found in the stomach and secrete pepsinogen, an inactive form of the enzyme pepsin. Pepsin is activated by HCl and helps to digest proteins.
- B. Mucous cells are found throughout the digestive tract and secrete mucus, a thick fluid that protects the lining of the tract from the acidic environment of the stomach.
- D. Kupffer cells are found in the liver and are involved in the removal of bacteria and other foreign particles from the blood.
Q58. Histamine is produced by which one of the following cells
- A. Basophils✓
- B. Platelets
- C. Monocyte
- D. Eosinophils
Explanation: Histamine is synthesized primarily by mast cells, basophils, histaminergic neurons in the basal ganglia of the brain, and enterochromaffin-like cells (ECL) in the stomach. These cells produce large amounts of histamine and are thought to be the major histamine-producing cells. Histamine is released from cells in response to an antibody called immunoglobulin E (IgE). This antibody may be secreted in response to an invading pathogen such as a virus, or bacteria, or an allergenic substance such as pollen. Histamine can also be released in response to injury caused by toxins.
Why the other options are wrong
- B. Platelets, or thrombocytes, are small, colorless cell fragments in our blood that form clots and stop or prevent bleeding. Platelets are made in our bone marrow, the sponge-like tissue inside our bones.
- C. monocytes, also called inflammatory monocytes, can infiltrate tissues, produce inflammatory cytokines, and differentiate into inflammatory macrophages.
- D. Eosinophils produce and store many secondary granule proteins prior to their exit from the bone marrow. They are involved in allergic reactions.
Q59. Which one of the following is the most numerous / commonest of white blood cells
- A. Eosinophils
- B. Monocytes
- C. Neutrophils✓
- D. Lymphocytes
Explanation: Neutrophils are the most abundant WBCs. These are phagocytic. They kill and digest bacteria and fungi. They are the most numerous white blood cells and your first line of defense when infection strikes. They constitute around 60% of the entire WBC count.
Why the other options are wrong
- A. Eosinophils are involved in allergic reactions. Eosinophils produce and store many secondary granule proteins prior to their exit from the bone marrow.
- B. Monocytes are the largest WBCs. They are phagocytic in nature.
- D. Lymphocytes are responsible for the production of antibodies against specific antigens.
Q60. The oxygenated blood from lungs to heart is transport by the:
- A. Pulmonary artery
- B. Pulmonary vein✓
- C. Coronary artery
- D. Hepatic artery
Explanation: The pulmonary veins are the only veins in the body that carry oxygenated blood. They are four in number, two from each lung, and they drain into the left atrium of the heart. The pulmonary veins transport oxygenated blood from the lungs to the heart. The lungs are responsible for exchanging oxygen and carbon dioxide with the blood. The blood that enters the lungs is deoxygenated, meaning that it has lost most of its oxygen. The lungs take in oxygen from the air and transfer it to the blood. The blood then leaves the lungs oxygenated and returns to the heart. The pulmonary veins are important for transporting oxygenated blood to the heart. Without the pulmonary veins, the heart would not be able to receive oxygenated blood and would not be able to pump blood to the rest of the body.
Why the other options are wrong
- A. No, the pulmonary artery does not carry oxygenated blood from the lungs to the heart. The pulmonary artery is a large artery that carries deoxygenated blood from the right ventricle of the heart to the lungs. The pulmonary artery branches into smaller arteries that deliver the deoxygenated blood to the alveoli in the lungs. The alveoli are small air sacs where the deoxygenated blood exchanges carbon dioxide for oxygen. The oxygenated blood then travels back to the heart through the pulmonary veins.
- C. No, the oxygenated blood from the lungs to the heart is not transported by the coronary artery. The coronary arteries are the blood vessels that supply the heart muscle with oxygenated blood. They do not transport oxygenated blood from the lungs to the heart.
- D. No, the oxygenated blood from the lungs to the heart is not transported by the hepatic artery. The hepatic artery is a blood vessel that supplies oxygenated blood to the liver. It does not carry blood from the lungs to the heart.The hepatic artery is one of the two arteries that supply blood to the liver. The other artery is the portal vein. The portal vein carries deoxygenated blood from the digestive tract to the liver.
Q61. Which one of the following proteins takes part in blood clotting
- A. Prothrombin
- B. Fibrinogen
- C. Immunoglobulin
- D. Globulin
- E. Both A and B✓
Explanation: Prothrombin is a protein made by the liver. Prothrombin helps blood to clot. The "prothrombin time" (PT) is one way of measuring how long it takes blood to form a clot, and it is measured in seconds (such as 13.2 seconds). A normal PT indicates that a normal amount of blood-clotting protein is available.Fibrinogen is a protein produced by the liver. This protein helps stop bleeding by helping blood clots to form. When blood clotting is activated, fibrinogen circulating in the blood is converted to fibrin which in turn helps in forming a stable clot at the site of vascular disruption.
Why the other options are wrong
- A. Prothrombin is a protein made by the liver. Prothrombin helps blood to clot. The "prothrombin time" (PT) is one way of measuring how long it takes blood to form a clot, and it is measured in seconds (such as 13.2 seconds). A normal PT indicates that a normal amount of blood-clotting protein is available.
- B. Fibrinogen is a protein produced by the liver. This protein helps stop bleeding by helping blood clots to form. When blood clotting is activated, fibrinogen circulating in the blood is converted to fibrin which in turn helps in forming a stable clot at the site of vascular disruption.
- C. Immunoglobulins, also known as antibodies, are glycoprotein molecules produced by plasma cells (white blood cells). Immunoglobulins play a key role in the body's immune system.
- D. Globulins are a group of proteins in blood. They are made in liver by the immune system.
Q62. Which one of the following is responsible for the production of concentrated urine
- A. Juxtamedullary nephrons✓
- B. Cortical nephrons
- C. Proximal tubule
- D. Distal tubule
Explanation: Juxtamedullary nephrons have long loops of Henle that extend deep into the medulla, enabling the countercurrent multiplier system which establishes a strong osmotic gradient in the renal medulla. This gradient allows the kidneys to reabsorb water efficiently and produce concentrated urine. Cortical nephrons have shorter loops and are less involved in concentration. The proximal and distal tubules are segments of the nephron involved in reabsorption and secretion but do not directly create urine concentration.
Why the other options are wrong
- B. Cortical nephrons primarily function in filtering blood and reabsorbing nutrients in the outer cortex of the kidney. While they contribute to urine formation, their shorter loops of Henle do not extend deep into the medulla and are less effective at concentrating urine compared to juxtamedullary nephrons.
- C. The proximal tubule plays a crucial role in reabsorbing a large portion of filtered substances, such as glucose and amino acids, but it is not specifically responsible for urine concentration. It reabsorbs water but does not create concentrated urine on its own.
- D. The distal convoluted tubule is involved in the fine-tuning of electrolyte balance and further reabsorption of water, but it does not play a primary role in producing concentrated urine. Its influence is less significant compared to the juxtamedullary nephrons.
Q63. Reabsorption of useful constituents normally takes place in which one of the following
- A. Proximal tubule✓
- B. Distal tubule
- C. Bowman’s capsule
- D. Glomerulus
Explanation: Option A is correct.Reabsorption mostly takes place in the proximal tube of nephron. Nearly all of the glucose, water, potassium, and amino acids lost during glomerular filtration re enter the blood through tubules.
Why the other options are wrong
- B. The distal convoluted tubule is the nephron segment that lies immediately downstream of the macula densa. Although short in length, the distal convoluted tubule plays a critical role in sodium, potassium, and divalent cation homeostasis.
- C. Bowman's capsule is a part of the nephron that forms a cup-like sack surrounding the glomerulus. Bowman's capsule encloses a space called “Bowman's space,” which represents the beginning of the urinary space and is contiguous with the proximal convoluted tubule of the nephron.
- D. Each nephron contains a network of small blood vessels, called glomerulus, which are enclosed in a sac called Bowman's capsule.
Q64. Which one of the following parts of the excretory system in humans acts as a countercurrent multiplier?
- A. Kidney
- B. Cortex
- C. Medulla
- D. Loop of Henle✓
Explanation: The loop of Henle functions as a countercurrent multiplier in the kidney’s nephron. It creates a concentration gradient in the medulla by actively transporting ions out of the tubular fluid, enabling the kidney to concentrate urine efficiently.
Why the other options are wrong
- A. The kidneys are two bean-shaped organs. They are located just below the rib cage, one on each side of your spine. Healthy kidneys filter about a half cup of blood every minute, removing wastes and extra water to make urine.
- B. The cortex provides a space for arterioles and venules from the renal artery and vein, as well as the glomerular capillaries, to perfuse the nephrons of the kidney. Erythropoietin, a hormone necessary for the synthesis of new red blood cells, is also produced in the renal cortex.
- C. The mature renal medulla, the inner part of the kidney, consists of the medullary collecting ducts, loops of Henle, vasa recta and the interstitium.
Q65. Antidiuretic Hormone (ADH) is released from:
- A. Anterior pituitary lobe
- B. Posterior pituitary lobe✓
- C. Hypothalamus
- D. Thalamus
Explanation: Antidiuretic hormone (ADH) is produced in the area of the brain called the hypothalamus. This hormone is stored in and released by the posterior pituitary gland. ADH controls how our body releases and conserves water.
Why the other options are wrong
- A. Antidiuretic hormone (ADH) is produced in the area of the brain called the hypothalamus. This hormone is stored in and released by the posterior pituitary gland. ADH controls how our body releases and conserves water.
- C. ADH is produced by the hypothalamus. It can be the answer, but not very appropriate.
- D. This option is incorrect. Antidiuretic hormone (ADH) is produced in the area of the brain called the hypothalamus. This hormone is stored in and released by the posterior pituitary gland. ADH controls how our body releases and conserves water.
Q66. Which one of the following is the main nitrogenous waste product in humans?
- A. Ammonia
- B. Uric acid
- C. Urea✓
- D. Creatinine
Explanation: Urea is the main nitrogenous waste in human, excreted in urine after protein metabolism.
Why the other options are wrong
- A. Ammonia is a highly toxic byproduct of protein metabolism. While it is produced during the breakdown of amino acids, it is converted into urea for safer excretion in humans, making it unsuitable as the main waste product.
- B. Uric acid is produced as a nitrogenous waste product by some animals, but in humans, it is not the primary waste product. It is excreted in smaller amounts compared to urea, which is the main form of nitrogenous waste.
- D. Creatinine is a waste product generated from muscle metabolism and is excreted in urine; however, it is not the main nitrogenous waste product in humans, which is urea.
Q67. The right and left cerebral hemispheres are connected by a thick band of nerve fibres called
- A. Medulla
- B. Corpus callosum✓
- C. Pons
- D. Hippocampus
Explanation: The two hemispheres in the brain are connected by a thick bundle of nerve fibres called the corpus callosum, which ensures both sides of the brain can communicate and send signals to each other.
Why the other options are wrong
- A. The Medulla oblongata is the bottom-most part of the brain. Its location means it's where the brain and spinal cord connect, making it a key conduit for nerve signals to and from the body. It also helps control vital processes like heartbeat, breathing, and blood pressure.
- C. The pons is the largest part of the brain stem, located above the medulla and below the midbrain.
- D. This option is incorrect. Hippocampus: The hippocampus is located in the temporal lobe and is primarily associated with memory and learning.
Q68. The part of the brain that guides smooth and accurate motions and maintains body position is called
- A. Cerebrum
- B. Cerebellum✓
- C. Pons
- D. Medulla
Explanation: The cerebellum is located at the back of the head. Its function is to coordinate voluntary muscle movements, maintain postures, balance, and equilibrium.
Why the other options are wrong
- A. The cerebrum is the largest part of the brain, which initiates and coordinates movement and regulates temperature. Other areas of the cerebrum enable speech, judgment, thinking and reasoning, problem-solving, emotions, and learning. Other functions relate to vision, hearing, touch, and other senses.
- C. The pons is the largest part of the brain stem, located above the medulla and below the midbrain.
- D. The Medulla oblongata is the bottom-most part of the brain. Its location means it's where the brain and spinal cord connect, making it a key conduit for nerve signals to and from the body. It also helps control vital processes like heartbeat, breathing, and blood pressure.
Q69. Which one of the following is the effect of a sympathetic nervous system?
- A. Constriction of bronchi
- B. Decrease in heart rate
- C. Promotes digestion or peristalsis
- D. Dilates the pupil✓
Explanation: The sympathetic nervous system activates during flight or fight conditions. It can accelerate heart rate, widen bronchial passage, decrease the motility of the large intestine, constrict blood vessels, increase peristalsis in the esophagus cause pupillary dilation. The sympathetic nervous system is also responsible for goosebumps, sweating, and a rise in blood pressure.
Why the other options are wrong
- A. Constriction of the bronchi is done by the parasympathetic nervous system.
- B. A decrease in heart rate is done by the parasympathetic nervous system.
- C. Promoting digestion or peristalsis is done by the parasympathetic nervous system.
Q70. High levels of aluminium may contribute to the onset of which one of the following?
- A. Parkinson’s disease
- B. Epilepsy
- C. Alzheimer’s disease✓
- D. Gonorrhea
Explanation: Aluminium is increased in the brains of people with Alzheimer's disease. A convincing relationship between the amount of exposure or aluminum in the body and the development of Alzheimer's in the body has been established.
Why the other options are wrong
- A. Parkinson's disease is a brain disorder that causes unintended or uncontrollable movements, such as shaking, stiffness, and difficulty with movement.
- B. Epilepsy is a disorder of the brain characterised by repeated seizures.
- D. Gonorrhea is a sexually transmitted disease caused by bacterial infection. The agent for Gonorrhea is Neisseria Gonorrhoeae. It invades the mucus membranes of reproductive tracts, including the cervix, vagina, uterus, fallopian tubes in women, and the urethra in both men and women.
Q71. Testosterone is produced by which one of the following:
- A. Sertoli cells
- B. Germinal epithelium
- C. Interstitial cells✓
- D. Spermatogonia
Explanation: Leydig cells are also called Interstitial cells as they are present in between the tubules. They have pale cytoplasm because of the large number of cholesterol droplets in them. The Leydig cells make and secrete testosterone in response to LH from the pituitary gland.
Why the other options are wrong
- A. Type of somatic cells around which spermatids develop in the tubules of the testis is called sertoli cells. They help in supporting, protecting and providing nutrition to spermatogenic cells.
- B. The germinal epithelium is the epithelial layer of the seminiferous tubules of the testicles. It is also known as the wall of the seminiferous tubule.
- D. A cell produced at an early stage in the formation of spermatozoa, formed in the wall of a seminiferous tubule and giving rise by mitosis to spermatocytes is called spermatogonia.
Q72. The oocyte released during ovulation is in:
- A. Anaphase I
- B. Prophase I
- C. Metaphase I
- D. Metaphase II✓
Explanation: When a female ovulates the secondary oocyte is in metaphase II. It then completes the second phase of meiosis to make a mature ovum only if fertilization takes place.
Why the other options are wrong
- A. This option is incorrect because anaphase I occurs much earlier during the first meiotic division. In this phase, homologous chromosomes are pulled apart toward opposite poles of the cell. However, this stage is completed long before ovulation. By the time ovulation occurs, meiosis I has already ended, and the oocyte has progressed to the second meiotic division, where it halts at metaphase II until fertilization.
- B. This option is also incorrect. The primary oocyte is arrested at prophase I during fetal development and remains in this stage until puberty. When a girl reaches reproductive age, hormonal changes trigger some of these primary oocytes to resume meiosis I. Once meiosis I finishes, a secondary oocyte is formed, which then begins meiosis II. Therefore, prophase I is not the stage of the oocyte at ovulation — it is the stage before puberty.
- C. This option is incorrect because metaphase I occurs before the completion of the first meiotic division. In this phase, homologous chromosomes align at the metaphase plate before being separated during anaphase I. After meiosis I is completed, the oocyte becomes a secondary oocyte, which proceeds into meiosis II and then halts at metaphase II — the stage at which ovulation occurs.
Q73. Yellowish glandular structure formed after the release of egg from follicle is called:
- A. Corpus callosum
- B. Graffian follicle
- C. Corpus luteum✓
- D. Follicle atresia
Explanation: The Corpus luteum is a yellowish glandular structure formed after the release of an egg in the female reproductive system. It is formed in the ovary at the site of a follicle or sac that has matured and released its egg in the process known as ovulation.
Why the other options are wrong
- A. The corpus callosum is the primary commissural region of the brain consisting of white matter tracts that connect the left and right cerebral hemispheres.
- B. A fluid-filled structure in the mammalian ovary within which an ovum develops prior to ovulation is called Graffian Follicle.
- D. Ovarian follicular atresia is the periodic process in which immature ovarian follicles degenerate and are subsequently re-absorbed during the follicular phase of the menstrual cycle. Typically around 20 follicles mature each month but only a single follicle is ovulated. The rest undergo atresia.
Q74. On puberty, the development of primary follicles is stimulated by:
- A. ICSH
- B. FSH✓
- C. LH
- D. Estrogen
Explanation: FSH lays an important role in sexual development and functionality. In women, FSH controls the menstrual cycle and stimulates the development of primary Follicles in the ovary. The levels of FSH continuously change in a female body throughout the menstrual cycle, with the highest levels happening just before an egg is released from the ovary.
Why the other options are wrong
- A. Luteinizing hormone (LH) is also called interstitial cell stimulating hormone ICSH in males.
- C. LH is called Interstitial cell stimulating Hormones (ICSH) in males. It acts on the Leydig cells and stimulates the production of androgens which in turn stimulate spermatogenesis.
- D. Oestrogen regulates the growth, development, and physiology of the female reproductive system.
Q75. Causative agent of a sexually transmitted disease that affects mucous membrane of the urogenital tract is:
- A. Staphylococcus aureus
- B. Treponema pallidum
- C. Neisseria gonorrhoeae✓
- D. Escherichia coli
Explanation: Sexually transmitted diseases (STDs), or sexually transmitted infections (STIs), are infections that are passed from one person to another through sexual contact. They are usually spread during vaginal, oral, or anal sex. Gonorrhea is a sexually transmitted disease caused by bacterial infection. The agent for Gonorrhea is Neisseria Gonorrhoeae. It invades the mucus membranes of reproductive tracts including the cervix, vagina, uterus, fallopian tubes in women, and urethra in both men and women.
Why the other options are wrong
- A. Staphylococcus aureus is a gram-positive bacteria that causes a wide variety of clinical diseases.
- B. Syphilis is a sexually transmitted disease (STD) caused by the bacterium Treponema pallidum. If not treated properly, Syphilis can cause serious health effects.
- D. Urinary tract infections, respiratory illness and pneumonia are some of the diseases caused by Escherichia coli.
Q76. In a human vertebral column, the number of _ vertebrae is 7.
- A. Cervical✓
- B. Thoracic
- C. Lumber
- D. Sacrum
Explanation: There are 7 cervical vertebrae in the human neck.
Why the other options are wrong
- B. 12 Thoracic vertebrae are found in the human body.
- C. There are five bones in the lower back, i.e, the lumbar region.
- D. There are five sacral vertebrae, which are fused.
Q77. Which one of the following structures holds the bones together:
- A. Joints
- B. Cartilages
- C. Fibrous capsules
- D. Ligaments✓
Explanation: The correct answer is Ligaments. Ligaments are fibrous connective tissues that connect bones to other bones, providing joint stability and holding the skeletal structure together. Joints are places where bones meet to allow movement, but they do not connect bones. Cartilage acts as a cushion at the ends of bones to reduce friction and absorb shock but does not join bones together. Fibrous capsules are part of the joint structure, providing an enclosing sheath around the joint, but they do not hold the bones together like ligaments do.
Why the other options are wrong
- A. Joints are where two or more bones meet, allowing for movement and flexibility. While they are crucial for mobility, they are not primarily responsible for holding bones together.
- B. Cartilage is a resilient and smooth elastic tissue that covers and protects the ends of long bones at the joints, but it does not hold bones together.
- C. Fibrous capsules are part of a joint structure, surrounding the joint to provide stability and contain synovial fluid, but they do not directly hold bones together.
Q78. Which one of the following cartilages is the most abundant in the human body:
- A. Elastic cartilage
- B. Chondral cartilage
- C. Fibrous Cartilage
- D. Hyaline Cartilage✓
Explanation: A translucent bluish-white type of cartilage present in the joints, the respiratory tract, and the immature skeleton is known as hyaline cartilage. It is the most abundant cartilage in the human body.
Why the other options are wrong
- A. Elastic cartilage is a structural cartilaginous tissue for non-load-bearing body parts, such as the ears, nose, and epiglottis.
- B. Chondral cartilage is a thin, smooth material that covers the ends of the thigh bone and shinbone (the femur and tibia). It reduces friction as the bones glide against each other during movement of the knee.
- C. Fibrocartilage is the tough, very strong tissue found predominantly in the intervertebral disks and at the insertions of ligaments and tendons.
Q79. The repeated protein pattern of myofibrils is called:
- A. Sarcomere✓
- B. Sarcolemma
- C. Zyomere
- D. Cross bridges
Explanation: The correct answer is the sarcomere, which is the repeating unit within myofibrils responsible for muscle contraction. Sarcomeres contain actin and myosin filaments that slide past each other to facilitate contraction. The sarcolemma is the muscle cell membrane and not part of the repeating protein pattern. Zygomere is not a valid term in muscle anatomy. Cross bridges are temporary structures formed during contraction, not the repeating pattern within myofibrils.
Why the other options are wrong
- B. The sarcolemma is the cell membrane of a muscle fiber, not involved in the repeated pattern of proteins within myofibrils. It plays a role in protecting muscle cells and transmitting signals, but not as the structural repeating unit.
- C. Zyomere is not a recognized term in muscle anatomy or physiology and does not refer to any known structure within muscle cells.
- D. Cross bridges are temporary links formed between actin and myosin during contraction, crucial for muscle contraction, but not the repeating structural unit within myofibrils.
Q80. When more energy is required in muscle contraction then that energy can also be produced by _ as a secondary source.
- A. Glucose
- B. Phosphocreatine✓
- C. Fructose
- D. Lactic acid
Explanation: After glucose, Phosphocreatine serves as a secondary source of energy.
Why the other options are wrong
- A. After glucose, Phosphocreatine serves as a secondary source of energy.
- C. Lactic acid is fuel for your cells during intense exercise.
- D. Fructose is a five-carbon sugar that can not be used by muscles as an energy source during the contraction process.
Q81. Which one of the following is a steroid hormone?
- A. Glucagon
- B. Epinephrine
- C. Thyroxin
- D. Estrogen✓
Explanation: Estrogen is a steroid hormone that plays a crucial role in the development and regulation of the female reproductive system. It is produced mainly by the ovaries and helps control the menstrual cycle, promote secondary sexual characteristics in females, and maintain pregnancy.
Why the other options are wrong
- A. Glucagon is not a steroid hormone. It is a peptide hormone produced by the pancreas and plays a role in regulating blood glucose levels by promoting the release of glucose from the liver into the bloodstream.
- B. Epinephrine (also known as adrenaline) is not a steroid hormone. It is a catecholamine hormone and a neurotransmitter produced by the adrenal glands. Epinephrine is involved in the body's "fight or flight" response, preparing the body for emergencies.
- C. Thyroxine, also known as T4, is not a steroid hormone. It is an iodine-containing hormone produced by the thyroid gland and is involved in regulating the body's metabolism.
Q82. The gonadotropic hormones of the anterior lobe of the pituitary include:
- A. Prolactin, Thyroid Stimulating Hormone, Somatotropin Hormone
- B. Follicle Stimulating Hormone, Luteinizing Hormone, Prolactin✓
- C. Adrenocorticotropic Hormone, Luteinizing Hormone, Follicle Stimulating Hormone
- D. Luteinizing Hormone, Follicle Stimulating Hormone, Thyroid Stimulating Hormone
Explanation: Gonadotropins are glycoprotein hormones secreted by gonadotropic cells of the anterior pituitary gland. Luteinizing Hormone (LH), Follicle Stimulating Hormone (FSH), and prolactin are the three hormones secreted by the anterior pituitary.
Why the other options are wrong
- A. Luteinizing Hormone (LH), Follicle Stimulating Hormone (FSH), and prolactin are the three hormones secreted by the anterior pituitary.
- C. Adrenocorticotropic Hormone (ACTH) is not a gonadotropin; it stimulates the adrenal glands. Follicle-stimulating hormone (FSH) and luteinizing hormone (LH) are the gonadotropins produced by the anterior pituitary, which regulate the gonads.
- D. Luteinizing Hormone (LH), Follicle Stimulating Hormone (FSH), and prolactin are the three hormones secreted by the anterior pituitary. TSH is not a gonadotropin hormone; it is a glycoprotein hormone.
Q83. Overactivity of the cortical hormone of the adrenal gland causes:
- A. Addison’s disease
- B. Parkinson’s disease
- C. Cushing’s disease✓
- D. Down’s syndrome
Explanation: Cushing syndrome occurs when the level of cortisol is too high in the body. This can occur because the pituitary gland is making too much Adrenocorticotropic hormone, which in turn causes the adrenal gland to make corticosteroids in excessive amounts. It can also be caused by taking steroid medicines for a long period.
Why the other options are wrong
- A. Addison's disease is a disorder that occurs when the adrenal glands don't make enough of certain hormones.
- B. Parkinson's disease is a brain disorder that causes unintended or uncontrollable movements, such as shaking, stiffness, and difficulty with walking. It is also called a movement disorder.
- D. Down syndrome is a condition in which a person has an extra chromosome. Symptoms include mental disability, distinctive facial characteristics, and increased risk for heart defects and digestive problems, which can range from mild to severe.
Q84. How many iodine atoms are present in thyroxine T4?
- A. 3
- B. 4✓
- C. 2
- D. 5
Explanation: The thyroid is a small, butterfly-shaped gland located at the front of the neck. It's part of the endocrine system and controls many of the body's important functions by producing and releasing (secreting) certain hormones such as thyroxine and triiodothyronine. Thyroxine is produced by attaching iodine atoms to the ring structure of proteins' tyrosine residues. Thyroxine T4 contains 4 iodine atoms, while tri-iodothyronine contains 3 iodine atoms.
Why the other options are wrong
- A. Thyroxine T4 contains 4 iodine atoms, while tri-iodothyronine contains 3 iodine atoms.
- C. Thyroxine T4 contains 4 iodine atoms, while tri-iodothyronine contains 3 iodine atoms.
- D. Thyroxine T4 contains 4 iodine atoms, while tri-iodothyronine contains 3 iodine atoms.
Q85. T-lymphocytes recognize antigens and attack microorganisms or transplanted organs and tissues. This effect is called
- A. Cell-mediated response✓
- B. Humoral immune response
- C. Active immunity
- D. Passive immunity
Explanation: T lymphocytes recognize an antigen and then attack microorganisms and the connection to it. Since this occurs cell to cell, it is called a cell-mediated response and opt a is right.
Why the other options are wrong
- B. Humoral immunity is also called antibody-mediated immunity. With assistance from helper T cells, B cells will differentiate into plasma B cells that can produce antibodies against a specific antigen. The humoral immune system deals with antigens from pathogens that are freely circulating, or outside the infected cells.
- C. The immunity which results from the production of antibodies by the immune system in response to the presence of an antigen is called Active Immunity.
- D. The short-term immunity that results from the introduction of antibodies from another person or animal is called passive immunity.
Q86. Which part of the antibody recognizes the antigen during immune response?
- A. Heavy part
- B. Light part
- C. Constant part
- D. Variable part✓
Explanation: Antibodies are immune system-related proteins called immunoglobulins. Each antibody consists of four polypeptide chains 2 heavy chains and 2 light chains joined together to form Y Y-shaped molecule. Each antibody has a variable region and a constant region. The variable region is composed of 110-130 amino acids which gives the antibody its specificity to bind to antigen. The variable region consists of the end of both light and heavy chains.
Why the other options are wrong
- A. Heavy part: The heavy chains contribute to the overall structure of the antibody, but do not directly participate in antigen recognition.
- B. Light part: Similar to the heavy chains, the light chains contribute to the antibody's structure but do not have the variable regions necessary for antigen binding.
- C. Constant part: This region is the same for all antibodies of a particular class and is involved in effector functions (like activating the complement system) rather than antigen recognition.
Q87. What type of immunity is achieved by injecting antibodies, antiserum, anti-venom serum
- A. Active immunity
- B. Passive immunity✓
- C. Artificially induced immunity
- D. Naturally induced immunity
Explanation: The short-term immunity which results from the introduction of antibodies from another person or animal is called as passive immunity.
Why the other options are wrong
- A. The immunity which results from the production of antibodies by the immune system in response to the presence of an antigen is called Active Immunity.
- C. Artificial induction of immunity is immunization achieved by human efforts in preventive healthcare. Artificial active immunity is the result of vaccination.
- D. Natural immunity is acquired from exposure to the disease organism through infection with the actual disease.
Q88. Which one of the following glands is involved in the production of lymphocytes:
- A. Pineal
- B. Thymus✓
- C. Pituitary
- D. Andrenal
Explanation: The thymus is a specialized primary lymphoid organ of the immune system. Within the thymus, lymphocytes or T cells mature. T cells are critical to the adaptive immune system, where the body adapts specifically to foreign invaders.
Why the other options are wrong
- A. The main function of the pineal gland is to receive information about the state of the light-dark cycle from the environment and convey this information by the production and secretion of the hormone melatonin.
- C. It regulates growth, metabolism, and reproduction through the hormones that it produces. The production of these hormones is either stimulated or inhibited by chemical messages sent from the hypothalamus to the pituitary. The posterior lobe produces two hormones, vasopressin and oxytocin.
- D. Adrenal glands, also known as suprarenal glands, are small, triangular-shaped glands located on top of both kidneys. Adrenal glands produce hormones that help regulate your metabolism, immune system, blood pressure, response to stress and other essential functions.
Q89. Antibodies are proteins and made up of how many polypeptide chains
- A. One
- B. Two
- C. Three
- D. Four✓
Explanation: Antibodies are immune system-related proteins called immunoglobulins. Each antibody consists of four polypeptide chains 2 heavy chains and 2 light chains joined together to form Y Y-shaped molecule. Hence opt D is the right choice here. Each antibody has a variable region and a constant region. The variable region is composed of 110-130 amino acids which gives the antibody its specificity to bind to antigen. The variable region consists of the end of both light and heavy chains.
Why the other options are wrong
- A. This is incorrect because an antibody is composed of 4 polypeptide chains, not one.
- B. This is also incorrect because antibodies are composed of 4 polypeptide chains.
- C. This is incorrect because antibodies are made of 4 polypeptide chains; 2 heavy chains and 2 light chains.
Q90. Oxidative phase of glycolysis starts with dehydrogenation of:
- A. Glycolysis
- B. Ribulose Bisphosphate
- C. Glyceraldehyde 3-phosphate✓
- D. NADH
Explanation: In the oxidative phase, each molecule of glyceraldehyde 3-phosphate (produced earlier in the preparatory phase) undergoes dehydrogenation. This involves the removal of a hydrogen atom from glyceraldehyde 3-phosphate, which is transferred to a molecule of NAD+ (nicotinamide adenine dinucleotide) to form NADH. The resulting molecule is 1,3-bisphosphoglycerate.
Why the other options are wrong
- A. Glycolysis is a fundamental metabolic pathway that occurs in the cytoplasm of cells, and it is the first stage of cellular respiration. During glycolysis, a molecule of glucose (a six-carbon sugar) is broken down into two molecules of pyruvate (a three-carbon compound).
- B. This is incorrect. In the oxidative phase, each molecule of glyceraldehyde 3-phosphate (produced earlier in the preparatory phase) undergoes dehydrogenation. This involves the removal of a hydrogen atom from glyceraldehyde 3-phosphate, which is transferred to a molecule of NAD+ (nicotinamide adenine dinucleotide) to form NADH. The resulting molecule is 1,3-bisphosphoglycerate.
- D. This is incorrect. In the oxidative phase, each molecule of glyceraldehyde 3-phosphate (produced earlier in the preparatory phase) undergoes dehydrogenation. This involves the removal of a hydrogen atom from glyceraldehyde 3-phosphate, which is transferred to a molecule of NAD+ (nicotinamide adenine dinucleotide) to form NADH. The resulting molecule is 1,3-bisphosphoglycerate.
Q91. In one turn, the Krebs’s cycle produces one molecule of ATP, one molecule of FADH2 and _ molecules of NADH.
- A. 1
- B. 2
- C. 3✓
- D. 4
Explanation: In one turn of the Krebs cycle, one molecule of ATP, one molecule of FADH2, and three molecules of NADH are produced. The ATP is generated through substrate-level phosphorylation, while FADH2 and NADH carry high-energy electrons that will be used in the electron transport chain to produce additional ATP during oxidative
Why the other options are wrong
- A. This is incorrect. In one turn of the Krebs cycle, one molecule of ATP, one molecule of FADH2, and three molecules of NADH are produced. The ATP is generated through substrate-level phosphorylation, while FADH2 and NADH carry high-energy electrons that will be used in the electron transport chain to produce additional ATP during oxidative
- B. This is incorrect. In one turn of the Krebs cycle, one molecule of ATP, one molecule of FADH2, and three molecules of NADH are produced. The ATP is generated through substrate-level phosphorylation, while FADH2 and NADH carry high-energy electrons that will be used in the electron transport chain to produce additional ATP during oxidative
- D. This is incorrect. In one turn of the Krebs cycle, one molecule of ATP, one molecule of FADH2, and three molecules of NADH are produced. The ATP is generated through substrate-level phosphorylation, while FADH2 and NADH carry high-energy electrons that will be used in the electron transport chain to produce additional ATP during oxidative.
Q92. Which one of the following is the stage of cellular respiration for which oxygen is not essential:
- A. Glycolysis✓
- B. Pyruvate oxidation
- C. Krebs’s cycle
- D. Electron Transport Chain
Explanation: The stage of cellular respiration for which oxygen is not essential is glycolysis. Glycolysis is the first step in cellular respiration and takes place in the cytoplasm of the cell. It does not require oxygen and can occur under both aerobic (with oxygen) and anaerobic (without oxygen) conditions. In the absence of oxygen, glycolysis is followed by either fermentation (in anaerobic conditions) or the continuation of the aerobic respiration process (if oxygen is available).
Why the other options are wrong
- B. During pyruvic oxidation, each pyruvate molecule loses a carbon dioxide (CO2) and is oxidized, producing one molecule of NADH. The remaining two-carbon fragment combines with coenzyme A (CoA) to form acetyl CoA. This process is an integral part of aerobic respiration and takes place in the mitochondrial matrix. It precedes the entry of acetyl CoA into the citric acid cycle, where further oxidation and energy production occur.
- C. The Krebs cycle, also known as the citric acid cycle or tricarboxylic acid (TCA) cycle, is a key component of cellular respiration in aerobic organisms. It takes place in the mitochondrial matrix, and its primary function is to harvest high-energy electrons from acetyl coenzyme A (acetyl CoA), derived from the breakdown of carbohydrates, fats, and proteins.
- D. The electron transport chain is a series of four protein complexes that couple redox reactions, creating an electrochemical gradient that leads to the creation of ATP in a complete system named oxidative phosphorylation. It occurs in mitochondria in cellular respiration.
Q93. Pyruvate, the end product of glycolysis moves from cytosol to mitochondrial matrix where it is oxidized into _ producing CO2 as a by-product.
- A. Acetic acid (active)✓
- B. Citrate
- C. NAD
- D. FAD
Explanation: Pyruvate, the end product of glycolysis, moves from the cytosol to the mitochondrial matrix, where it undergoes oxidative decarboxylation. During this process, pyruvate is converted into Active Acetic acid or acetyl-CoA (acetyl coenzyme A). The reaction involves the removal of a carbon dioxide (CO2) molecule as a by-product. This step is known as the pyruvate decarboxylation reaction. The acetyl-CoA then enters the citric acid cycle (also known as the Krebs cycle) within the mitochondrial matrix.
Why the other options are wrong
- B. This is incorrect. Pyruvate, the end product of glycolysis, moves from the cytosol to the mitochondrial matrix, where it undergoes oxidative decarboxylation. During this process, pyruvate is converted into acetyl-CoA (acetyl coenzyme A). The reaction involves the removal of a carbon dioxide (CO2) molecule as a by-product. This step is known as the pyruvate decarboxylation reaction. The acetyl-CoA then enters the citric acid cycle (also known as the Krebs cycle) within the mitochondrial matrix.
- C. This is incorrect. Pyruvate, the end product of glycolysis, moves from the cytosol to the mitochondrial matrix, where it undergoes oxidative decarboxylation. During this process, pyruvate is converted into acetyl-CoA (acetyl coenzyme A). The reaction involves the removal of a carbon dioxide (CO2) molecule as a by-product. This step is known as the pyruvate decarboxylation reaction. The acetyl-CoA then enters the citric acid cycle (also known as the Krebs cycle) within the mitochondrial matrix.
- D. This is incorrect. Pyruvate, the end product of glycolysis, moves from the cytosol to the mitochondrial matrix, where it undergoes oxidative decarboxylation. During this process, pyruvate is converted into acetyl-CoA (acetyl coenzyme A). The reaction involves the removal of a carbon dioxide (CO2) molecule as a by-product. This step is known as the pyruvate decarboxylation reaction. The acetyl-CoA then enters the citric acid cycle (also known as the Krebs cycle) within the mitochondrial matrix.
Q94. pBR 322 have antibiotic resistance gene for:
- A. Ampicillin and aspirin
- B. Streptomycin and metronidazole
- C. Ampicillin and Tetracycline✓
- D. Penicillin and metronidazole
Explanation: Ampicillin is a medication used to manage and treat certain bacterial infections. Tetracyclines are a class of medication used to manage and treat various bacterial infections.
Why the other options are wrong
- A. Ampicillin is a medication used to manage and treat certain bacterial infections. Aspirin is used to reduce fever and to relieve mild to moderate pain from headaches, menstrual periods, arthritis, toothaches, and muscle aches.
- B. Streptomycin is primarily used as part of the multidrug treatment of pulmonary tuberculosis. It has additional activity against several aerobic gram-negative bacteria. Metronidazole is an antibiotic. It's used to treat skin infections, rosacea, and mouth infections, including infected gums and dental abscesses. It's also used to treat conditions such as bacterial vaginosis and pelvic inflammatory disease.
- D. Penicillin is an antibiotic. It is used to treat infections caused by bacteria. It does not work on viral infections. Metronidazole is an antibiotic. It's used to treat skin infections, rosacea, and mouth infections, including infected gums and dental abscesses. It's also used to treat conditions such as bacterial vaginosis and pelvic inflammatory disease.
Q95. Cystic Fibrosis affects which one of the following cells of the body?
- A. Epithelial cells✓
- B. Endothelial cells
- C. Plasma cells
- D. Blood cells
Explanation: Cystic fibrosis is an autosomal recessive disease caused by the loss of function of cystic fibrosis transmembrane conductance regulator (CFTR) protein which primarily acts as a protein channel. Since CFTR is mainly studied in the Epithelial cells so opt A is the right choice here.
Why the other options are wrong
- B. Cystic fibrosis is an autosomal recessive disease caused by the loss of function of cystic fibrosis transmembrane conductance regulator (CFTR) protein which primarily acts as a protein channel. Since CFTR is mainly studied in the Epithelial cells so opt A is the right choice here.
- C. Cystic fibrosis is an autosomal recessive disease caused by the loss of function of cystic fibrosis transmembrane conductance regulator (CFTR) protein which primarily acts as a protein channel. Since CFTR is mainly studied in the Epithelial cells so opt A is the right choice here.
- D. Cystic fibrosis is an autosomal recessive disease caused by the loss of function of cystic fibrosis transmembrane conductance regulator (CFTR) protein which primarily acts as a protein channel. Since CFTR is mainly studied in the Epithelial cells so opt A is the right choice here.
Q96. The enzymes which act as molecular scissors in recombinant DNA technology is
- A. Exonucleases
- B. Endonucleases✓
- C. Polymerases
- D. Reverse transcriptases
Explanation: Endonucleases also known as restriction enzymes are molecular scissors as they cleave DNA at or near specific sequences known as restriction sites. These enzymes make one incision on each of the two strands of DNA and are also called restriction Endonucleases.
Why the other options are wrong
- A. Exonuclease is an enzyme which removes successive nucleotides from the end of a polynucleotide molecule.
- C. A polymerase is an enzyme that synthesises long chains of polymers or nucleic acids. DNA polymerase and RNA polymerase are used to assemble DNA and RNA molecules, respectively.
- D. A reverse transcriptase is an enzyme used to generate complementary DNA from an RNA template, a process termed reverse transcription.
Q97. Which of the following is the correct sequence of PCR?
- A. Heating→ Cooling → Add Primer→ Copying of strand✓
- B. Heating→ Add Primer→ Cooling→ Copying of strand
- C. Add Primer →Heating→ Cooling →Copying of strand
- D. Cooling→ Add Primer→ Heating →Copying of strand
Explanation: Polymerase chain Reaction The polymerase chain reaction is a method widely used to rapidly make millions to billions of copies of a specific DNA sample in a short period. Process PCR involves using short synthetic DNA fragments called primers to select a segment of the genome to be amplified, and then multiple rounds of DNA synthesis to amplify that segment. The process has 4 steps in total. Sequence The correct sequence of PCR is Heating it breaks the double-stranded structure Cooling Adding the primer which then annealed to make a copy of the strand. Opt A is the right choice here.
Why the other options are wrong
- B. Heating → Add Primer → Cooling → Copying of strand: Primers need to anneal (bind) to the DNA strands at a lower temperature, which happens during the cooling phase, not immediately after heating.
- C. Add Primer → Heating → Cooling → Copying of strand: Heating is the first step to denature (separate) the DNA strands. Primers cannot bind before the strands are separated.
- D. Cooling → Add Primer → Heating → Copying of strand: Again, heating must come first to separate the DNA strands. Cooling needs to happen before the primers are added. Copying of the strand happens at an intermediate temperature, after the primers have attached.
Q98. When two different pieces of DNA are joined together, the result is which one of the following?
- A. Complementary DNA
- B. Mutated DNA
- C. Recombinant DNA✓
- D. Cloned DNA
Explanation: A recombinant Dna is a dna molecule from two different species that are inserted into host organism to produce new genetic combinations that are of great value to science, medicine and agriculture.
Why the other options are wrong
- A. A complementary DNA is a DNA synthesized from a single-stranded RNA template in a reaction catalyzed by the enzyme reverse transcriptase.
- B. Any change in the DNA sequence of a cell is said to be mutation and the DNA is called mutant DNA.
- D. DNA cloning is the process of making multiple, identical copies of a particular piece of DNA. The dna then produced are known as clonned Dna.
Q99. Individual successions are known as
- A. Primary successions
- B. Secondary successions
- C. Seres✓
- D. Xeroses
Explanation: The term specifically used for each individual succession in animal or plant is called seres. Therefore this is the right option here.
Why the other options are wrong
- A. Primary succession is the beginning step of ecological succession after an extreme disturbance, which usually occurs in an environment devoid of vegetation and other organisms. These environments are typically lacking in the soil, as disturbances like lava flow or retreating glaciers shred the environment of nutrients.
- B. Secondary succession occurs when the severity of disturbance is insufficient to remove all the existing vegetation and soil from a site. Many different kinds of disturbances, such as fire, flooding, windstorms, and human activities (e.g., logging of forests) can initiate secondary succession.
- D. The term specifically used for each individual succession in animal or plant is called seres. Therefore this is the right option here.
Q100. Which one of the following is the ultimate distributional unit within which a species is restrained by the limitations of its physical structure and physiology?
- A. Niche✓
- B. Biome
- C. Ecosystem
- D. Habitat
Explanation: The given statement is the definition of Niche given by Grinnell. Therefore opt A is the right choice here.
Why the other options are wrong
- B. A biome is a biogeographical unit consisting of a biological community that has formed in response to the physical environment in which they are found and a shared regional climate. Biomes may span more than one continent. Biome is a broader term than habitat and can comprise a variety of habitats.
- C. A biological community of interacting organisms and their physical environment is called an ecosystem.
- D. In ecology, the term habitat summarises the array of resources, physical and biotic factors that are present in an area, such as to support the survival and reproduction of a particular species.
Q101. All herbivores belong to which trophic level in the food chain?
- A. T1
- B. T2✓
- C. T3
- D. T4
Explanation: Herbivores which are the primary consumers belong to trophic level 2.
Why the other options are wrong
- A. Autotrophs belong to trophic level 1
- C. Secondary consumers also known as Carnivores belong to the third trophic level.
- D. Top carnivores belong to this level.
Q102. How many food chains are present in the following food web?
- A. 5
- B. 3
- C. 6
- D. 4✓
Explanation: A series of organisms each dependent on the next as a source of food is called a food chain. Food web A system of interlocking and interdependent food chains. There are four food chains in the given food web.
Why the other options are wrong
- A. A series of organisms each dependent on the next as a source of food is called a food chain. Food web A system of interlocking and interdependent food chains.There are four food chains in the given food web.
- B. A series of organisms each dependent on the next as a source of food is called a food chain. Food web A system of interlocking and interdependent food chains.There are four food chains in the given food web.
- C. A series of organisms each dependent on the next as a source of food is called a food chain. Food web A system of interlocking and interdependent food chains.There are four food chains in the given food web.
Q103. The relationship in which one organism gets benefit and the other is not affected is called
- A. Mutualism
- B. Commensalism✓
- C. Predation
- D. Parasitism
Explanation: The relationship in which one organism gets benefit and the other is not affected is called commensalism.
Why the other options are wrong
- A. A mutualistic relationship is when two organisms of different species "work together," each benefiting from the relationship.
- C. In predation, one organism kills and consumes another
- D. A parasitic relationship is one in which one organism, the parasite, lives off of another organism, the host, harming it and possibly causing death.
Q104. In male the sex determining gene is
- A. XY
- B. SRY✓
- C. SYX
- D. SXX
Explanation: Y chromosome has an SRY gene. It is the sex determining region Y gene. It is Y linked gene because it is found only on the Y chromosome.
Why the other options are wrong
- A. The X and Y chromosomes, also known as the sex chromosomes, determine the biological sex of an individual: females inherit an X chromosome from the father for a XX genotype, while males inherit a Y chromosome from the father for an XY genotype.
- C. Y chromosome has an SRY gene. It is the sex determining region Y gene. It is Y linked gene because it is found only on the Y chromosome.
- D. Y chromosome has an SRY gene. It is the sex determining region Y gene. It is Y linked gene because it is found only on the Y chromosome.
Q105. A gene which affects two or more unrelated characteristics is called
- A. Pleiotropic✓
- B. Epistatic
- C. Dominant
- D. Mutant
Explanation: Pleiotropy is defined as the expression of multiple traits by a single gene. A simple example of Pleiotropy is phenylketonuria which is a disease. It is a genetic disorder caused by the low metabolism of the amino acid phenylalanine in the body cells.
Why the other options are wrong
- B. Epistasis is a condition where the expression of one gene is modified (e.g., masked, inhibited, or suppressed) by the expression of one or more other genes. The gene which suppresses the effect of other genes is called the Epistatic gene and the gene which is suppressed is known as the hypostatic gene.
- C. A mutant gene is a gene that has undergone a permanent change in the DNA sequence that makes up a gene
- D. Pleiotropy is defined as the expression of multiple traits by a single gene. A simple example of Pleiotropy is phenylketonuria which is a disease. It is a genetic disorder caused by the low metabolism of the amino acid phenylalanine in the body cells.
Q106. Position of a gene within a DNA molecule is
- A. Locus✓
- B. Origin
- C. Amplicon
- D. Filial
Explanation: The position of genes on a chromosome is known as locus.
Why the other options are wrong
- B. The position of genes on a chromosome is known as locus.
- C. In molecular biology, amplicons represent DNA or RNA fragments that are the source or product of amplification or replication events. They can be naturally formed through gene duplication. Natural gene duplication plays a crucial role in genomic evolution.
- D. Any generation resulting from a genetically controlled mating following parental generation is known as filial generation.
Q107. Sickle cell anemia is a type of
- A. Insertion
- B. Transposition
- C. Deletion
- D. Base Substitution✓
Explanation: In Sickle cell anemia, the gene for beta-globin is mutated. As a result, the amino acid valine is replaced by glutamic acid and the RBC adopts a sickle shape. Since it is a type of base substitution therefore opt D is the right choice here.
Why the other options are wrong
- A. Insertion is a type of mutation that involves the addition of one or more nucleotides into a segment of DNA. An insertion can involve the addition of any number of nucleotides, from a single nucleotide to an entire piece of a chromosome.
- B. DNA transposition is the movement of a defined DNA segment (a transposon) from one genomic site to another.
- C. A deletion is a type of mutation that involves the loss of one or more nucleotides from a segment of DNA. A deletion can involve the loss of any number of nucleotides, from a single nucleotide to an entire piece of a chromosome.
Q108. A polymer of empirical formula CH2 has molar mass of 28000 gmol-1. Its molecular formula will be
- A. 100 times that of its empirical formula
- B. 200 times that of its empirical formula
- C. 500 times that of its empirical formula
- D. 2000 times that of its empirical formula✓
Explanation: The empirical mass of CH4 is 12+2=14g. Dividing molar mass by observed mass will give us the answer: 28000/14=2000 times. As it is numerical, it can have only one possible answer.
Why the other options are wrong
- A. The empirical mass of CH4 is 12+2=14g. Dividing molar mass by empirical mass will give us the answer: 28000/14=2000 times.As it is numerical, it can have only one possible answer.
- B. The empirical mass of CH4 is 12+2=14g. Dividing molar mass by empirical mass will give us the answer: 28000/14=2000 times.As it is numerical, it can have only one possible answer.
- C. The empirical mass of CH4 is 12+2=14g. Dividing molar mass by empirical mass will give us the answer: 28000/14=2000 times.As it is numerical, it can have only one possible answer.
Q109. The number of molecules in 9 g of ice (H2O) is
- A. 6.02 x 1024
- B. 6.02 x 1023
- C. 3.01 x 1024
- D. 3.01 x 1023✓
Explanation: Water has a mass of 18g (16+2). So, 9g of ice(H2O) means 0.5 mol. 1 mol has a 6.02x1023 number of molecules, so 0.5 mol will have a 3.01x1023 number of molecules. As it is numerical, it can have only one possible answer.
Why the other options are wrong
- A. Water has a mass of 18g (16+2). So, 9g of ice(H2O) means 0.5 mol. 1 mol has a 6.02x10^23 number of molecules, so 0.5 mol will have a 3.01 x 1023 number of molecules.As it is numerical, it can have only one possible answer.
- B. Water has a mass of 18g (16+2). So, 9g of ice(H2O) means 0.5 mol. 1 mol has a 6.02x10^23 number of molecules, so 0.5 mol will have a 3.01 x 1023 number of molecules.As it is numerical, it can have only one possible answer.
- C. Water has a mass of 18g (16+2). So, 9g of ice(H2O) means 0.5 mol. 1 mol has a 6.02x10^23 number of molecules, so 0.5 mol will have a 3.01 x 1023 number of molecules.As it is numerical, it can have only one possible answer.
Q110. Ice is less dense than water at:
- A. 0C✓
- B. 4C
- C. 2C
- D. -4C
Explanation: At 0oC, Ice is less dense than water. It is a fact.
Why the other options are wrong
- B. At 4C, water has its highest density.
- C. At 0oC, Ice is less dense than water. It is a fact.
- D. At 0oC, Ice is less dense than water. It is a fact.
Q111. At a given temperature and pressure, the one which shows marked deviation from ideal behavior is
- A. N2
- B. N3
- C. CO2✓
- D. He
Explanation: The gas with higher intermolecular forces has the most marked deviation, as one of the assumptions of an ideal gas is that ideal gases have negligible forces of attraction.CO2 is above all intermolecular forces in all of the above hence is our answer.
Why the other options are wrong
- A. N2 is inert gas that follows ideal gas behaviour to a large extent at normal conditions, as they have negligible intermolecular forces.
- B. He is inert gas that follows ideal gas behaviour to a large extent at normal conditions, as they have negligible intermolecular forces.
- D. N3 is not a stable compound and does not exist.
Q112. According to the number of protons, neutrons and electrons given in the table, which one of the following options is correct?
- A. As-3, Ga+3, Ca
- B. As+1, Ga+2, Ca
- C. As+3, Ga+3, Ca✓
- D. As+1, Ga, Ca+2
Explanation: Charge on any species is equal to protons-electrons:In this case:For As, 33-30=+3For Ga: 31-28=+3For Ca: 20-20-0Hence our answer is CAs it is numerical, it can have only one possible answer.
Why the other options are wrong
- A. False.Charge on any species is equal to protons-electrons:In this case:For As, 33-30=+3For Ga: 31-28=+3For Ca: 20-20-0Hence our answer is C
- B. False.Charge on any species is equal to protons-electrons:In this case:For As, 33-30=+3For Ga: 31-28=+3For Ca: 20-20-0Hence our answer is C
- D. False.Charge on any species is equal to protons-electrons:In this case:For As, 33-30=+3For Ga: 31-28=+3For Ca: 20-20-0Hence our answer is C
Q113. If the e/m value of electron is 1.7588 x 1011 C/kg, then what would be the mass of electron in grams (charge on electron is 1.6022 x 10-19 coulombs)?
- A. 9.1095 x 10-31 g
- B. 91.095 x 10-31 g
- C. 9.1095 x 10-28 g✓
- D. 0.919095 x 10-33 g
Explanation: If e/m is equal to 1.7588x10^11 and the charge on an electron is 1.6 x10^-19 then the mass can be calculated as: 1.7588x10^11=1.6x10^-19/m m-9.109 x 10^-31kg. In g, 9.1x10^-28 g As it is numerical, it can have only one possible answer.
Why the other options are wrong
- A. False.If e/m is equal to 1.7588x10^11 and the charge on an electron is 1.6 x10^-19 then the mass can be calculated as: 1.7588x10^11=1.6x10^-19/m m-9.109 x 10^-31kg. In g, 9.1x10^-28 g
- B. False.If e/m is equal to 1.7588x10^11 and the charge on an electron is 1.6 x10^-19 then the mass can be calculated as: 1.7588x10^11=1.6x10^-19/m m-9.109 x 10^-31kg. In g, 9.1x10^-28 g
- D. Incorrect.If e/m is equal to 1.7588x10^11 and the charge on an electron is 1.6 x10^-19 then the mass can be calculated as: 1.7588x10^11=1.6x10^-19/m m-9.109 x 10^-31kg. In g, 9.1x10^-28 g
Q114. The suitable representation of dot structure of chlorine molecule is :
- A. A
- B. B✓
- C. C
- D. D
Explanation: The suitable structure of the dot structure of the chlorine molecule is shown in option B as it shows 7 electrons in each of the chlorine atom's outermost shells, making a total of 14. In other options, chlorine combinations do not sum up to the real number 14.
Why the other options are wrong
- A. Incorrect.The suitable structure of the dot structure of the chlorine molecule is shown in option B as it shows 7 electrons in each of the chlorine atom's outermost shells, making a total of 14. In other options, chlorine combinations do not sum up to the factual number 14.real
- C. Incorrect.The suitable structure of the dot structure of the chlorine molecule is shown in option B as it shows 7 electrons in each of the chlorine atom's outermost shells, making a total of 14. In other options, chlorine combinations do not sum up to the factual number 14.real
- D. Incorrect.The suitable structure of the dot structure of the chlorine molecule is shown in option B as it shows 7 electrons in each of the chlorine atom's outermost shells, making a total of 14. In other options, chlorine combinations do not sum up to the factual number 14.real
Q115. When the two partially filled atomic orbitals overlap in such a way that the probability of finding electron is maximum around the line joining the two nuclei, the result is the formation of
- A. Sigma Bond✓
- B. Pi-Bond
- C. Hydrogen Bond
- D. Metallic Bond
Explanation: When two partially filled (half-filled) atomic orbitals overlap in such a way that the probability of finding the electrons is maximum around the line joining the two nuclei, then it is called a sigma bond.
Why the other options are wrong
- B. Pi-Bond: A pi bond is formed by the sideways overlapping of two p orbitals. This type of bond occurs in double and triple bonds, while a single bond is a sigma bond.
- C. Hydrogen Bond: A hydrogen bond is an intermolecular force that occurs when hydrogen atoms are bonded to highly electronegative atoms such as nitrogen, oxygen, or fluorine. This type of bond occurs between molecules, while a sigma bond occurs between atoms.
- D. Metallic Bond: A metallic bond occurs between metal atoms, where the outermost electrons are delocalized and shared among all the atoms in the metal lattice. This type of bond is not formed by overlapping orbitals.
Q116. What will be the enthalpy change in the reaction given below?2H2 + O2→ 2H2O ∆H = +205.5 kJ mol-1
- A. 205.5 kJ/mol
- B. Zero kJ/mol
- C. -205.5 kJ/mol✓
- D. 1 kJ/mol
Explanation: This is a trick question. Most students choose A however that is wrong. It should be remembered that ∆H for combustion is an exothermic process and energy is released thus option C is correct. It is a fact.
Why the other options are wrong
- A. This could be correct answer if it has negative sign because the given reaction exothermic and it's ∆H value is always in negative sign.
- B. Zero kJ/mol: An enthalpy change of zero would indicate no heat is exchanged, which is not the case here. Chemical reactions typically involve energy changes.
- D. 1 kJ/mol: There is no basis in the given information to suggest an enthalpy change of +1 kJ/mol or -1 kJ/mol for either the forward or reverse reaction. The magnitude of the enthalpy change is directly related to the energy difference between the reactants and products, which is given as 205.5 kJ/mol for the forward reaction.
Q117. Combustion of graphite to form CO2 can be done by two ways. Reactions are given as follows: 1.C + O2 -> CO2 ∆H = -393.7 kJ mol-12.C + ½O2 -> CO ∆H = ?3.CO + ½O2 -> CO2 ∆H = -283 kJ mol-1What will be the enthalpy of the formation of CO?
- A. -676 kJ mol-1
- B. -110 kJ mol-1✓
- C. 110 kJ mol-1
- D. 676 kJ mol-1
Explanation: Writing equation 1 as it is and flipping equation 3: 1.C+02--> CO2 H=-393.7 kJ 3.CO2 --> CO +1/2O2 H=+283 kJ Adding these two equations gives equation 2, hence the enthalpy of these two equations is also equal to the enthalpy of equation 2. -393.7+283-110kJ As it is numerical, it can have only one possible answer.
Why the other options are wrong
- A. -676 kJ mol-1: This value doesn't arise from any simple combination of the given enthalpy changes. It seems like an arbitrary number.
- C. 110 kJ mol-1: This has the correct magnitude but the wrong sign. It would be the enthalpy change for the reverse of the formation of CO under these specific manipulations.
- D. 676 kJ mol-1: Similar to -676 kJ mol-1, this value doesn't result from a logical application of Hess's Law to the given data.
Q118. The value of equilibrium constant (Kc) for the reaction 2HF(g) ⇌ H2(g) + F2(g) is 10-13 at 2000°C. Calculate the value of Kp for this reaction:
- A. 2 x 10-13
- B. 10-13✓
- C. 186 x 10-13
- D. 3.48 x 10-9
Explanation: When the number of gaseous molecules at the reactant and product side is equal the Kc=Kp; making it 10-13 As it is numerical, it can have only one possible answer.
Why the other options are wrong
- A. When the number of gaseous molecules at the reactant and product side is equal the Kc=Kp; making it 10-13 As it is numerical, it can have only one possible answer.
- C. When the number of gaseous molecules at the reactant and product side is equal the Kc=Kp; making it 10-13 As it is numerical, it can have only one possible answer.
- D. When the number of gaseous molecules at the reactant and product side is equal the Kc=Kp; making it 10-13As it is numerical, it can have only one possible answer.
Q119. The vapor pressure lines for pure as well as solutionsof different concentrations are shown. Which line represents pure water?
- A. 1✓
- B. 2
- C. 3
- D. 4
Explanation: Pure water (with the highest vapor pressure) will boil at the lowest temperature.Boiling occurs when vapor pressure = external pressure.Since pure water already has a higher vapor pressure, it reaches that point sooner — i.e., at a lower temperature
Why the other options are wrong
- B. Pure water (with the highest vapor pressure) will boil at the lowest temperature.Boiling occurs when vapor pressure = external pressure.Since pure water already has a higher vapor pressure, it reaches that point sooner — i.e., at a lower temperature
- C. Pure water (with the highest vapor pressure) will boil at the lowest temperature.Boiling occurs when vapor pressure = external pressure.Since pure water already has a higher vapor pressure, it reaches that point sooner — i.e., at a lower temperature
- D. Pure water (with the highest vapor pressure) will boil at the lowest temperature.Boiling occurs when vapor pressure = external pressure.Since pure water already has a higher vapor pressure, it reaches that point sooner — i.e., at a lower temperature
Q120. In SO4-2 the oxidation number of Sulphur is
- A. -8
- B. +8
- C. -6
- D. +6✓
Explanation: The oxidation of sulphur is 6+:it is because the oxide ion has a charge of -2 making it -8 overall, for four oxide ions. x-8=-2 x=+6 As it is numerical, it can have only one possible answer.
Why the other options are wrong
- A. The oxidation of sulphur is 6+:it is because the oxide ion has a charge of -2 making it -8 overall, for four oxide ions. x-8=-2 x=+6
- B. The oxidation of sulphur is 6+:it is because the oxide ion has a charge of -2 making it -8 overall, for four oxide ions. x-8=-2 x=+6
- C. The oxidation of sulphur is 6+:it is because the oxide ion has a charge of -2 making it -8 overall, for four oxide ions. x-8=-2 x=+6
Q121. Coinage metals Cu, Ag, and Au are the least reactive because they have:
- A. Negative reduction potential
- B. Positive reduction potential✓
- C. Negative oxidation potential
- D. Positive oxidation potential
Explanation: Positive reduction potential means that the element is less reactive, which is the case in the three metals above. Coinage metals Cu (copper), Ag (silver), and Au (gold) are the least reactive metals among all transition metals. This is due to their positive reduction potential, meaning they have a high tendency to undergo reduction (gain electrons) during a redox reaction. This also makes them very unreactive towards oxidation reactions, making them highly resistant to corrosion.
Why the other options are wrong
- A. Incorrect option as positive reduction potential is the correct option. Negative Reduction Potential: Metals with negative reduction potentials readily lose electrons and are easily oxidized. These metals are generally very reactive (e.g., alkali metals, alkaline earth metals).
- C. Incorrect option as positive reduction potential is the correct option. Negative Oxidation Potential: Oxidation potential is the reverse of reduction potential. A negative oxidation potential means the metal has a tendency to gain electrons (get reduced), which aligns with high reactivity as a reducing agent, not low reactivity as a metal.
- D. Incorrect option as positive reduction potential is the correct option.Positive Oxidation Potential: A positive oxidation potential indicates that a metal readily loses electrons and is easily oxidized. This signifies high reactivity, the opposite of what is observed for coinage metals.
Q122. What will be the pH of a solution of NaOH with a concentration of 10-3 M?
- A. 3
- B. 14
- C. 11✓
- D. 7
Explanation: pOH of NaOH will be => pOH=- log[OH-]=-log[10-3]= 3 pH + pOH = 14 pH+3=14 pH= 11 As it is numerical, it can have only one possible answer.
Why the other options are wrong
- A. pOH of NaOH will be => pOH=- log[OH-]=-log[10-3]= 3. pH + pOH = 14 pH+3=14pH= 11
- B. pOH of NaOH will be => pOH=- log[OH-]=-log[10-3]= 3. pH + pOH = 14 pH+3=14pH= 11
- D. pOH of NaOH will be => pOH=- log[OH-]=-log[10-3]= 3. pH + pOH = 14 pH+3=14pH= 11
Q123. If the reactant or product of a chemical reaction can absorb ultraviolet, visible or infrared radiation, then the rate of a chemical reaction can best be measured by which one of the following methods?
- A. Chemical method
- B. Spectrometry✓
- C. Graphical method
- D. Differential method
Explanation: A general method employed to measure the rate of a reaction involves substances that can absorb radiations like UV, visible light, or infra-red radiation using spectrophotometers.
Why the other options are wrong
- A. The chemical method involves measuring the change in the concentration of a reactant or product over time, which can be done by titration or some other analytical technique. This method may not be suitable if the species of interest cannot be easily measured by chemical means.
- C. Graphical method involves plotting the concentration of a reactant or product versus time and determining the slope of the line. This method may be difficult to use if the reaction is not first order.
- D. Differential method involves measuring the change in temperature, pressure, or volume over time. This method may not be suitable if the reaction is not exothermic or if the reaction mixture is not in a closed system.
Q124. For the reaction 2NO + O2 ⇌ 2NO2, the rate equation for the forward reaction is:
- A. Rate = k [NO] [O2]
- B. Rate = k [NO]2[O2]✓
- C. Rate = k [NO2]2
- D. Rate = k [NO2]
Explanation: The rate equation involves reactants, not products. Assuming the coefficients in the reaction equation represent the orders of reaction with respect to that reactant the correct rate equation will be B.
Why the other options are wrong
- A. The rate equation involves reactants, not products. Assuming the coefficients in the reaction equation represent the orders of reaction with respect to that reactant the correct rate equation will be B.
- C. The rate equation involves reactants, not products. Assuming the coefficients in the reaction equation represent the orders of reaction with respect to that reactant the correct rate equation will be B.
- D. The rate equation involves reactants, not products. Assuming the coefficients in the reaction equation represent the orders of reaction with respect to that reactant the correct rate equation will be B.
Q125. Radon is _ emitter and being radioactive is used in _ treatment in radiotherapy.
- A. β, cancer
- B. α, cancer✓
- C. α, kidney stone
- D. β, kidney stone
Explanation: Radon emits alpha particles that are used for therapeutic purposes to treat cancer. Radon is a gas and as a radioactive element, it is used in the treatment of cancer. It emits alpha, beta, and gamma rays that can damage or destroy cancer cells. Radon is not used in the treatment of kidney stones. Therefore, option B is the correct answer.
Why the other options are wrong
- A. Option A is incorrect because it suggests that radon is a beta emitter, which is not true. Radon is an alpha emitter, not a beta emitter. Additionally, radon is not used in the treatment of kidney stones, so the second part of the option is also incorrect.
- C. Option C is incorrect because radon is not used in kidney stone treatment. Kidney stones are typically treated with medications, drinking plenty of fluids, and in some cases, with surgical interventions.
- D. Option D is also incorrect because radon is not used in kidney stone treatment. Kidney stones are typically treated with medications, drinking plenty of fluids, and in some cases, with surgical interventions.
Q126. One mole of glucose was dissolved in 1 kg of water, ethanol, ether, and benzene separately and the molal boiling point constant of each solution was found to be 0.52, 1.75,2.16, and 2.70 in the units of / °C kg mol-1 respectively. Which of the following figures shows benzene as a solvent in solution?
- A. 1
- B. 2
- C. 3
- D. 4✓
Explanation: Since the solution of benzene and glucose has the highest molal boiling point constant of 2.70, this means that the equilibrium between benzene vapor and the solution will be shifted toward the solution side. Hence vapor pressure of Benzene will be the lowest and the level of mercury will be the highest. As it is numerical, it can have only one possible answer.
Why the other options are wrong
- A. Since the solution of benzene and glucose has the highest molal boiling point constant of 2.70, this means that the equilibrium between benzene vapor and the solution will be shifted toward the solution side. Hence vapor pressure of Benzene will be the lowest and the level of mercury will be the highest.As it is numerical, it can have only one possible answer.
- B. Since the solution of benzene and glucose has the highest molal boiling point constant of 2.70, this means that the equilibrium between benzene vapor and the solution will be shifted toward the solution side. Hence vapor pressure of Benzene will be the lowest and the level of mercury will be the highest.
- C. Since the solution of benzene and glucose has the highest molal boiling point constant of 2.70, this means that the equilibrium between benzene vapor and the solution will be shifted toward the solution side. Hence vapor pressure of Benzene will be the lowest and the level of mercury will be the highest.
Q127. The trends, in melting points of the elements of the 3rd period, are depicted in the figure below.The sharp decrease observed from ‘Si’ to ‘P’ is due to
- A. Decrease in atomic radius from ‘Si’ to ‘P’
- B. Change in bonding and structure of two elements✓
- C. Different universities of two elements
- D. Increase in electron density from ‘Si’ to ‘P’
Explanation: From Si onwards, the bonding and structure of the element change from covalent to weak van der Waal forces that cause the decrease in melting point, as shown in the diagram. Options A, C, D: As explained above, they are incorrect options
Why the other options are wrong
- A. From Si onwards, the bonding and structure of the element change from covalent to weak van der Waal forces that cause the decrease in melting point, as shown in the diagram.
- C. From Si onwards, the bonding and structure of the element change from covalent to weak van der Waal forces that cause the decrease in melting point, as shown in the diagram.
- D. From Si onwards, the bonding and structure of the element change from covalent to weak van der Waal forces that cause the decrease in melting point, as shown in the diagram.
Q128. Arrange the following elements according to the trend of ionization energies. (C, N, Ne, B)
- A. Ne < N < C < B
- B. B < N < C < Ne
- C. B < C < N < Ne✓
- D. Ne < B < C < N
Explanation: As they move along the period towards the right the ionization energy increases. It is a fact and should be memorised.
Why the other options are wrong
- A. As they move along the period towards the right the ionization energy increases. It is a fact and should be memorized
- B. As they move along the period towards the right the ionization energy increases.It is a fact and should be memorized
- D. As they move along the period towards the right the ionization energy increases. It is a fact and should be memorized
Q129. Which one of the following noble gases are used for providing an inert atmosphere for welding?
- A. Helium
- B. Neon
- C. Argon✓
- D. Krypton
Explanation: Argon is used for welding and cutting. It is a factual recall from the book.
Why the other options are wrong
- A. Argon is used for welding and cutting. It is a factual recall from the book.
- B. Argon is used for welding and cutting. It is a factual recall from the book.
- D. Argon is used for welding and cutting. It is a factual recall from the book.
Q130. The electronic configuration of Manganese (Mn) is
- A. A✓
- B. B
- C. C
- D. D
Explanation: The electronic configuration Mn is [Ar] 3d5 4s2. Option A is the only option that depicts this electronic configuration. It is a fact and should be memorized.
Why the other options are wrong
- B. Option A is the only option that depicts correct electronic configuration. The electronic configuration Mn is [Ar] 3d5 4s2.
- C. Option A is the only option that depicts correct electronic configuration. The electronic configuration Mn is [Ar] 3d5 4s2.
- D. Option A is the only option that depicts correct electronic configuration. The electronic configuration Mn is [Ar] 3d5 4s2.
Q131. The percentage of carbon in different types of iron products is in the order of
- A. Cast Iron > Wrought Iron > Steel
- B. Wrought Iron > Steel > Cast Iron
- C. Cast Iron > Steel > Wrought Iron✓
- D. Cast Iron < Steel > Wrought Iron
Explanation: Wrought iron is an iron alloy with a very low carbon content (less than 0.08%). Typically there is less than 0.40% carbon in most steels. In contrast to that of cast iron (2.1% to 4%)
Why the other options are wrong
- A. The percentage of carbon in cast iron is greater than steel and steel's carbon percentage is greater than wrought iron.
- B. The percentage of carbon in cast iron is greater than steel and steel's carbon percentage is greater than wrought iron.
- D. Wrought iron is an iron alloy with a very low carbon content (less than 0.08%). Typically there is less than 0.40% carbon in most steels. In contrast to that of cast iron (2.1% to 4%). The percentage of carbon in cast iron is not less than steel but steel's carbon percentage is greater than wrought iron.
Q132. Which one of the following is the correct equation of 1st ionization of sulphuric acid?
- A. H2SO4(aq) + H2O(l) --> H+ + SO42-
- B. H2SO4(aq) + H2O(l) --> H+(aq) + HSO4-✓
- C. H2SO4(aq) + H2O(l) --> 2H+ + SO42-
- D. H2SO4(aq) + H2O(l) --> H3O+ + SO42-
Explanation: The 1st ionisation equation involves dissociation of 1 H+ ion from H2SO4, followed by second H+ dissociation in the second ionisation.
Why the other options are wrong
- A. This equation represents the complete ionization of sulfuric acid, where both protons are released. The question specifically asks for the first ionization step, where only one proton is lost.
- C. As per the explanation, this is an incorrect option. This is the same as option A and is incorrect for the same reason. It shows complete ionization, not the first ionization.
- D. As per the explanation, this is an incorrect option. This equation is incorrect because it shows the formation of the sulfate ion (\ce{SO4^2-}) in the first ionization step. Sulfuric acid is a strong acid for its first proton, but the bisulfate ion (\ce{HSO4-}) is a weak acid and only partially ionizes further to form the sulfate ion. The first ionization primarily produces the bisulfate ion. Additionally, while \ce{H3O+} (hydronium ion) is the more accurate representation of a proton in aqueous solution, the other correct option (B) also accurately depicts the first ionization step.
Q133. Which one of the following is the correct chemical reaction for Ammonia formationby Haber process?
- A. N2(g) + H2(g) ⇌ 2NH(g)
- B. 2N(g) + 3H2(g) ⇌ NH3(g)
- C. 2N(g) + 3H2(g) ⇌ 2NH3(g)
- D. N2(g) + 3H2(g) ⇌ 2NH3(g)✓
Explanation: Below is the true reaction of haber's process:N2(g) + 3H2(g) = 2NH3(g)It is a fact and should be memorized.
Why the other options are wrong
- A. Below is the true reaction of haber's process:N2(g) + 3H2(g) = 2NH3(g)It is a fact and should be memorized.
- B. Below is the true reaction of haber's process:N2(g) + 3H2(g) = 2NH3(g)It is a fact and should be memorized.
- C. Below is the true reaction of haber's process:N2(g) + 3H2(g) = 2NH3(g)It is a fact and should be memorized.
Q134. The pH of acid rain is:
- A. 7
- B. Between 5 and 7
- C. Below 5✓
- D. Between 7 and 14
Explanation: Acid rain has a pH of below 5.It is a fact and should be memorized.
Why the other options are wrong
- A. Acid rain has a pH of below 5.It is a fact and should be memorized.
- B. Acid rain has a pH of below 5.It is a fact and should be memorized.
- D. Acid rain has a pH of below 5.It is a fact and should be memorized.
Q135. Which one of the following products is obtained when sulphur trioxide is absorbed inconcentrated sulphuric acid?
- A. Oleum✓
- B. Aqua Regia
- C. Hydrogen sulphide
- D. Sulphate ion
Explanation: The sulphur trioxide is first dissolved in concentrated sulphuric acid: The product is known as fuming sulphuric acid or oleum.
Why the other options are wrong
- B. Aqua Regia is a mixture of concentrated nitric acid and hydrochloric acid. It is used to dissolve noble metals like gold and platinum.
- C. Hydrogen sulphide is a gas with a characteristic rotten egg smell. It is produced by the action of acid on sulphide ions.
- D. Sulphate ion is a negatively charged ion consisting of one sulphur atom and four oxygen atoms. It is formed by the reaction of sulphuric acid with a metal oxide, hydroxide or carbonate. However, it is not a product of the reaction of sulphur trioxide with concentrated sulphuric acid.
Q136. Which one of the following pair of compounds is cis and trans isomers of eachother?
- A. A✓
- B. B
- C. C
- D. D
Explanation: Isomers are those compounds that have diff structures but the same molecular formula, which is the case in A only, they form cis- trans isomers. (having equal no. of carbon and hydrogen atoms)
Why the other options are wrong
- B. does not have isomers as there is a difference of one carbon between two carbons.
- C. doesn't have isomers, they both are the same compound structurally.
- D. is also not isomers because they too also have a difference of one carbon atom between them.
Q137. Which one of the following compounds is a ketone?
- A. CH3 ― O ― CH2 ― CH3
- B. CH3 ― CO ― CH2 ― CH3✓
- C. CH3COCOOH
- D. CH3 ― CH2CHO
Explanation: Ketone has a general formula of R- CO-R, meaning that there are two radical groups surrounding a carbonyl group(C=0).This is shown in option B only. The radical group surrounds O in option A so it is either, not a ketone. Option C has a COOH group so it is a carboxylic acid. Option D has a CHO group, making it aldehyde. Ketone has a general formula of R- CO-R, meaning that there are two radical groupssurrounding a carbonyl group(C=0).This is shown in option B only. The radical group surrounds O in option A so it is either, not a ketone. Option C has a COOH group so it is a carboxylic acid. Option D has a CHO group, making it aldehyde.p surrounds O in option A so it is either, not a ketone. Option C has a COOH group so it is a carboxylic acid. Option D has a CHO group, making it aldehyde.
Why the other options are wrong
- A. This compound is an ether, not a ketone. Ethers have an oxygen atom bonded to two alkyl or aryl groups.
- C. This compound is a carboxylic acid, not a ketone. Carboxylic acids contain a carboxyl group (COOH), which consists of a carbonyl group (C=O) bonded to a hydroxyl group (-OH).
- D. This compound is an aldehyde, not a ketone. Aldehydes contain a carbonyl group (C=O) bonded to at least one hydrogen atom and an alkyl or aryl group.
Q138. Addition of unsymmetrical reagent to an unsymmetrical alkene is governed by:
- A. Cannizzaro’s Reaction
- B. Kirchhoff Rule
- C. Aldol Condensation
- D. Markownikov’s Rule✓
Explanation: The addition of unsymmetrical reagents to unsymmetrical alkenes follows Markovnikov's rule. This rule dictates that the negative part of the reagent will attach to the unsaturated carbon atom with fewer hydrogen atoms. For example, the addition of hydrogen bromide to propene results in isopropyl bromide as the major product due to Markovnikov's rule.The other options are incorrect as they describe different reactions or rules that are not relevant to the addition of unsymmetrical reagents to unsymmetrical alkenes.
Why the other options are wrong
- A. Cannizzaro's Reaction: Cannizzaro's reaction is a disproportionation reaction of an aldehyde or a ketone in the presence of a strong base, which results in the formation of a salt of a carboxylic acid and an alcohol
- B. Kirchhoff Rule: Kirchhoff's rules are used to find the direction of current flow in a circuit. It is not related to additional reactions in organic chemistry
- C. Aldol Condensation: Aldol condensation is a reaction between a carbonyl compound (aldehyde or ketone) and an enolizable aldehyde or ketone to form a β-hydroxyaldehyde or β-hydroxy ketone, followed by dehydration to form α,β-unsaturated carbonyl compounds
Q139. Ethylene glycols are used as
- A. Anesthetic
- B. Knocking agent
- C. Freezing agent
- D. Anti-freezing agent✓
Explanation: Ethylene glycol is used as an antifreeze agent and polyester.
Why the other options are wrong
- A. Ethylene glycols are not used as anesthetics in the context of medical or veterinary anesthesia. Anesthetics for these purposes are typically pharmaceutical compounds designed for inducing a reversible loss of sensation.
- B. Ethylene glycols are not used as knocking agents. Knocking, in the context of internal combustion engines, refers to the undesirable phenomenon of uncontrolled combustion leading to a knocking or pinging sound. Knocking agents are typically anti-knock additives in fuels, such as tetraethyl lead (previously used but now mostly phased out due to environmental concerns), to reduce the tendency of fuel to detonate prematurely.
- C. Ethylene glycols are not used as freezing agents in the sense of inducing freezing. Instead, they are used as antifreeze agents to lower the freezing point of liquids, especially in automotive and industrial applications.
Q140. The halothane used in hospitals as an anesthetic is chemically
- A. 1-Bromo-1-chloro-2, 2, 2-trifluoroethane
- B. 2-Bromo-2-chloro-1, 1, 1-trifluoroethane✓
- C. 1, 1, 1-Trifluoro-2-bromo-2-chloroethane
- D. 2-Chloro-2-bromo-1, 1, 1-trifluoroethane
Explanation: 2-Bromo-2-chloro-1,1,1- trifluoroethane is the IUPAC name for halothanes that are used in hospitals as an anaesthetic. it is a fact and should be memorized.
Why the other options are wrong
- A. This is not the correct chemical structure for halothane. The presence of three fluorine atoms (trifluoro) at the end indicates a different compound.
- C. This option has the correct elements but the order is different. The numbering in the chemical name indicates the position of the substituents on the carbon chain, and in the case of halothane, it is 2-bromo-2-chloro-1,1,1-trifluoroethane.
- D. This option has the correct elements but the order is different. The correct order, as mentioned earlier, is 2-bromo-2-chloro-1,1,1-trifluoroethane.
Q141. If halogenoalkanes are mixed with an excess of ammonia and heated under pressure, amine are formed. Which amine is formed in the following reaction?CH2CH3Br + NH3 ----> Amine
- A. CH3―CH2―NH―CH2―CH3
- B. CH3―CH2―NH2✓
- C. CH3―CH2―CH2―NH2
- D. H2N―CH2―CH2―NH2
Explanation: With bromoethane and ammonia, ethyl ammonium bromide is formed as shown below:
Why the other options are wrong
- A. CH₃-CH₂-NH-CH₂-CH₃: This represents a secondary amine, specifically diethylamine. Secondary amines are formed when a primary amine reacts further with another molecule of haloalkane. Since the question states an excess of ammonia, the primary amine will be the major product.
- C. CH₃-CH₂-CH₂-NH₂: This is propylamine. The starting haloalkane has an ethyl group (CH₃CH₂), so the resulting amine will also have an ethyl group attached to the nitrogen.
- D. H₂N-CH₂-CH₂-NH₂: This is ethylenediamine, a diamine with two amino groups. This would require a dihaloalkane as a reactant, not a monohaloalkane like ethyl bromide.
Q142. A primary alcohol, C₃H₈O (A), and a secondary alcohol, C₃H₈O(B), can be distinguished by:
- A. Lucas reagent
- B. Victor-Meyer test
- C. I₂/NaOH
- D. All of these✓
Explanation: All three tests can distinguish between propan-1-ol (A) and propan-2-ol (B). The Lucas test gives a rapid reaction with B but not A. The Victor-Meyer test gives different colors. The iodoform test (I₂/NaOH) gives a positive result (yellow precipitate) with B but not with A.
Why the other options are wrong
- A. The Lucas test differentiates between primary, secondary, and tertiary alcohols. It works because secondary carbocations are more stable and form faster than primary carbocations, and tertiary carbocations are so stable that the reaction takes place almost immediately.
- B. The iodoform test is used to detect the presence of methyl ketones and those compounds that can be oxidized to methyl ketones, and not for the identification of alcohols.
- C. Baeyer's test is used to distinguish between unsaturated and saturated compounds. In this test, the organic compound is treated with a solution of potassium permanganate in dilute sulphuric acid. Unsaturated compounds will decolorize the solution while saturated compounds will not.
Q143. Which one of the following alcohol is indicated by formation of yellow crystals in theIodoform test?
- A. MethanoL
- B. Ethanol✓
- C. Butanol
- D. Propanol
Explanation: Ethanol is the only primary alcohol to give the triiodomethane (iodoform) reaction.If "R" is a hydrocarbon group, then you have secondary alcohol. Lots of secondaryalcohols give this reaction, but those that do all have a methyl group attached to thecarbon with the -OH group.All other alcohols do not have -OH group attached to carbon attached to a methylgroup
Why the other options are wrong
- A. Methanol does not have a methyl ketone group and cannot be oxidized to one. Therefore, it will not give a positive iodoform test.
- C. Butanol is a primary alcohol, but its oxidation product, butanal does not have a methyl ketone group Therefore, butanol will not give a positive iodoform test.
- D. Propanol is also a primary alcohol, and its oxidation product, propanal lacks the methyl ketone group. Hence, propanol will not yield a positive iodoform test.
Q144. Ethyl butyrate and butyl butanoate are esters with the flavor of:
- A. Pear
- B. Banana
- C. Pineapple✓
- D. Apple
Explanation: Ethyl butyrate and butyl butanoate are esters with the flavour of pineapple.It is a fact and should be memorized.
Why the other options are wrong
- A. Pear flavor is often associated with propyl acetate.
- B. Amyl Acetate has flavour of banana so this option is incorrect.
- D. Apple flavor is often associated with methyl butyrate.
Q145. The formula of 2, 4, 6-tribromo phenol is
- A. A
- B. B✓
- C. C
- D. D
Explanation: Carbons are numbered according to the placement of the -OH group. The carbon to which the OH group is attached is C1. The bromines must be attached to C2, C4 and C6 on the benzene going in a clockwise direction from C1.
Why the other options are wrong
- A. Carbons are numbered according to the placement of the -OH group. The carbon to which the OH group is attached is C1. The bromines must be attached to C2, C4 and C6 on the benzene going in a clockwise direction from C1.
- C. Carbons are numbered according to the placement of the -OH group. The carbon to which the OH group is attached is C1. The bromines must be attached to C2, C4 and C6 on the benzene going in a clockwise direction from C1.
- D. Carbons are numbered according to the placement of the -OH group. The carbon to which the OH group is attached is C1. The bromines must be attached to C2, C4 and C6 on the benzene going in a clockwise direction from C1.
Q146. Which one of the following groups is indicated when HCl is formed by reaction ofethanol with phosphorus pentachloride:
- A. Amino group
- B. Hydroxyl group✓
- C. Halide group
- D. Hydride group
Explanation: When a -OH group(hydroxyl group) containing organic compound is reacted with with phosphorus pentachloride, it forms HCI an halogen by the reaction equation shown below:The reaction is represented as:CH3CH2OH + PCl5 → CH3CH2Cl + POCl3 + HClTherefore, the correct answer is (B) Hydroxyl group, which is the functional group present in ethanol that is replaced by a chlorine atom during the reaction.
Why the other options are wrong
- A. Amino group: Ethanol does not contain an amino group (-NH₂). Therefore, HCl formation in this reaction is not directly indicative of an amino group.
- C. Halide group: While the product chloroethane contains a halide group (-Cl), the HCl formed is a byproduct of the reaction where the hydroxyl group is replaced. The HCl itself doesn't indicate the presence of a halide group in the starting ethanol.
- D. Hydride group: The term "hydride group" typically refers to a hydrogen atom with a negative charge (H⁻). Ethanol does not contain a hydride group that would be indicated by the formation of HCl in this reaction. The hydrogen in HCl comes from the hydroxyl group of ethanol.
Q147. A student mixed ethyl alcohol with a small amount of sodium dichromate and added it to the hot solution of dilute sulphuric acid. A vigorous reaction took place. He distilled the product formed immediately. What was the product?
- A. Acetone
- B. Acetic acid
- C. Dimethyl ether
- D. Acetaldehyde✓
Explanation: Acetaldehyde is the product of the described reaction. The oxidation of ethanol with sodium dichromate and dilute sulfuric acid results in the formation of acetaldehyde as an intermediate product. Acetaldehyde is an aldehyde and is often further oxidized to acetic acid under more vigorous conditions or in the presence of excess oxidizing agents.
Why the other options are wrong
- A. Acetone is not the product of the described reaction. Acetone is a ketone, and it is not formed by the oxidation of ethanol under the conditions described.
- B. Acetic acid is also not the product of the described reaction. Acetic acid is a carboxylic acid, and while it can be produced from the oxidation of ethanol, the conditions described (using a small amount of sodium dichromate and dilute sulfuric acid) are more likely to result in the formation of acetaldehyde as an intermediate product rather than acetic acid.
- C. Dimethyl ether is not the product of the described reaction. Dimethyl ether is an ether and is not formed by the oxidation of ethanol under the conditions described.
Q148. The structural formula of the product of reaction of acetone with 2,4-dinitrophenyl hydrazine is:
- A. A
- B. B
- C. C
- D. D✓
Explanation: The reaction of 2,4- dinitrophenylhydrazine (2,4-DNPH) and acetone in the presence of acid leads to the formation of acetone 2,4-dinitrophenylhydrazone as shown in the equation below. 2,4-dinitrophenylhydrazine + acetone + acid → acetone 2,4-dinitrophenylhydrazone + water
Why the other options are wrong
- A. As per the explanation, this option is incorrect.The reaction of 2,4- dinitrophenylhydrazine (2,4-DNPH) and acetone in the presence of acid leads to the formation of acetone 2,4-dinitrophenylhydrazone as shown in the equation below.2,4-dinitrophenylhydrazine + acetone + acid → acetone 2,4-dinitrophenylhydrazone + water
- B. As per the explanation, this option is incorrect.The reaction of 2,4- dinitrophenylhydrazine (2,4-DNPH) and acetone in the presence of acid leads to the formation of acetone 2,4-dinitrophenylhydrazone as shown in the equation below.2,4-dinitrophenylhydrazine + acetone + acid → acetone 2,4-dinitrophenylhydrazone + water
- C. As per the explanation, this option is incorrect.The reaction of 2,4- dinitrophenylhydrazine (2,4-DNPH) and acetone in the presence of acid leads to the formation of acetone 2,4-dinitrophenylhydrazone as shown in the equation below.2,4-dinitrophenylhydrazine + acetone + acid → acetone 2,4-dinitrophenylhydrazone + water
Q149. For the following reaction, what does the question mark represent?
- A. C2H5COCH3✓
- B. C2H5CH(CH3)OH
- C. CH3COCH3
- D. C2H5CH2CHO
Explanation: When HCN reacts with a ketone, two new bonds form. The H from HCN adds to 0 in C=O to form C-OH bond and -CN adds to C to form C- CN bond. The ketone is given in option A and C, but the one having the same number of carbon atoms as the product is in option A. The product formed is called 'cyanohydrin' and it has the CN and OH group on the same carbon.
Why the other options are wrong
- B. As per the explanation, this option is incorrect.When HCN reacts with a ketone, two new bonds form. The H from HCN adds to 0 in C=O to form C-OH bond and -CN adds to C to form C- CN bond. The ketone is given in option A and C, but the one having the same number of carbon atoms as the product is in option A. The product formed is called 'cyanohydrin' and it has the CN and OH group on the same carbon.
- C. As per the explanation, this option is incorrect.When HCN reacts with a ketone, two new bonds form. The H from HCN adds to 0 in C=O to form C-OH bond and -CN adds to C to form C- CN bond. The ketone is given in option A and C, but the one having the same number of carbon atoms as the product is in option A. The product formed is called 'cyanohydrin' and it has the CN and OH group on the same carbon.
- D. As per the explanation, this option is incorrect.When HCN reacts with a ketone, two new bonds form. The H from HCN adds to 0 in C=O to form C-OH bond and -CN adds to C to form C- CN bond. The ketone is given in option A and C, but the one having the same number of carbon atoms as the product is in option A. The product formed is called 'cyanohydrin' and it has the CN and OH group on the same carbon.
Q150. Acetamide is formed by dehydration of
- A. Oxalic acid
- B. Ethanoic acid✓
- C. Butanoic acid
- D. Propanoic acid
Explanation: Acetamide is a two carbon amide so when it is reduced it will turn into a two-carbon carboxylic acid,ethanoic acid. Hence the answer to this is B. The answer is not c or d because it has more carbon than what acetamide has. Oxalic acid is not the answer because it has two carboxyl groups while the -NH2 group that has to be replaced in acetamide is only one.
Why the other options are wrong
- A. Oxalic acid does not form acetamide upon dehydration, but instead forms carbon monoxide and carbon dioxide gases
- C. Butanoic acid and propanoic acid can undergo decarboxylation upon heating instead of dehydration, forming the corresponding alkane and carbon dioxide gas.
- D. Butanoic acid and propanoic acid can undergo decarboxylation upon heating instead of dehydration, forming the corresponding alkane and carbon dioxide gas.
Q151. Organic compounds ‘X’ and ‘Y’ both can react with Na-Metal to evolve hydrogen gas. If ‘X’ and ‘Y’ react with each other form an organic compound ‘Z’ which gives a fruity smell. What type of compound ‘X’, ‘Y’ and ‘Z’ are?
- A. Option A
- B. Option B
- C. Option C✓
- D. Option D
Explanation: Z gives a fruity smell that means it is an ester. Esters are formed by reaction between carboxylic acid and alcohol. All three of are mentioned in correct order in option C.
Why the other options are wrong
- A. Incorrect option. A) X = Alcohol, Y = Ester, Z = Acetic Acid: An ester (Y) does not typically react with sodium metal to produce hydrogen gas. The reaction of an alcohol (X) with an ester (Y) also does not yield acetic acid (Z) with a fruity smell.
- B. Incorrect option. B) X = Alcohol, Y = Alcohol, Z = Acetic Acid: While alcohols (X and Y) can react with sodium, the reaction between two alcohols does not result in the formation of acetic acid (Z) with a fruity smell.
- D. Incorrect option. D) X = Alcohol, Y = Mineral Acid, Z = Ester: Although an alcohol (X) reacts with sodium, a mineral acid (Y) like sulfuric acid is not considered an organic compound. Furthermore, the reaction between an alcohol and a mineral acid typically produces an alkyl halide or an alkyl sulfate, not an ester with a fruity aroma.
Q152. The amino acids which are not prepared in the human body are called.
- A. Essential amino acids✓
- B. Non-essential amino acids
- C. Alpha amino acids
- D. Beta amino acids
Explanation: The amino acids which are not synthesized by the human body and must be obtained from the diet are called "Essential amino acids."Essential amino acids are those amino acids that the body cannot produce on its own in sufficient quantities to meet its physiological needs. Therefore, they must be obtained through dietary sources. There are nine essential amino acids for humans: histidine, isoleucine, leucine, lysine, methionine, phenylalanine, threonine, tryptophan, and valine.
Why the other options are wrong
- B. Non-essential amino acids are those that the body can synthesize on its own, so they are not considered essential in the diet.
- C. Alpha amino acids refer to amino acids where the amino group (-NH2) is attached to the alpha carbon relative to the carboxyl group (-COOH). Most amino acids, whether essential or non-essential, are alpha amino acids.
- D. Beta amino acids are a different class of amino acids where the amino group is attached to the beta carbon. They are less common in biological systems compared to alpha amino acids.
Q153. Indicate the cyclic amino acid from the following
- A. Cysteine
- B. Serine
- C. Haloamine
- D. Proline✓
Explanation: Haloamine is not an amino acid but is rather a class of organic compounds containing an amine and halogen group. The structures of Cysteine, serine, and proline are shown below. Only Proline contains a ring in its structure and hence is cyclic.
Why the other options are wrong
- A. Cystine is not a cyclic amino acid. It is a dimer of the amino acid cysteine, formed by the oxidation of two cysteine residues, resulting in a covalent linkage between the sulfur atoms of two cysteine molecules. It forms disulfide bonds in proteins, contributing to their tertiary and quaternary structures.
- B. Serine is not a cyclic amino acid either. It is a nonpolar amino acid with a hydroxyl group (-OH) as its side chain. It plays important roles in protein structure and function, often participating in hydrogen bonding and enzymatic reactions.
- C. Halomine" doesn't appear to be a commonly known amino acid. It's possible you meant "histidine," which contains an imidazole side chain, but histidine is not cyclic in the same sense as proline.
Q154. Which one of the following is Glutamic Acid?
- A. A✓
- B. B
- C. C
- D. D
Explanation: The chemical formula for glutamic acid is C5H9NO4. Glutamic acid is an amino acid with a carboxylic acid functional group (-COOH) and an amino functional group (-NH2) attached to the same carbon atom (known as the alpha carbon), along with a side chain consisting of a carboxylic acid group.
Why the other options are wrong
- B. This option is incorrect.B) This molecule has a side chain with a single carboxylic acid group attached to a carbon that is directly bonded to the central carbon. While it has a carboxylic acid, the structure of the side chain is different from that of glutamic acid.
- C. This is the formula for Glycine.C) This molecule has a methyl group (-CH₃) as its side chain. This is the structure of alanine, a nonpolar amino acid.
- D. This is the formula for Alanine.D) This molecule has a hydrogen atom (-H) as its side chain. This is the structure of glycine, the simplest amino acid.
Q155. At low pH or in acidic condition amino acid exists as
- A. Anion
- B. Cation✓
- C. Zwitterion
- D. Neutral Specie
Explanation: In acidic conditions, excess H⁺ ions from the solution protonate the amino acid. The amino group (–NH₂) gets protonated to –NH₃⁺, while the carboxyl group (–COOH) remains in its acidic form. This gives the molecule an overall positive charge, making it a cation.
Why the other options are wrong
- A. Anion: Amino acids are negatively charged in basic conditions.
- C. Amino acids are neutral at their isoelectric point, with both positive and negative charges.
- D. Neutral speciesAmino acids can also be neutral at certain pH levels where the positive and negative charges balance out.
Q156. The structure shown below represents:
- A. Proline
- B. Histidine✓
- C. Glycine
- D. Lysine
Explanation: The above structure represents histidine, as it has five carbon ring structures along -CH2 attached as a radical group.
Why the other options are wrong
- A. Proline is unique because its side chain forms a ring structure that links back to the nitrogen atom of its amino group, making it an imino acid, not a standard amino acid with a free alpha-amino group.
- C. Glycine is the simplest amino acid, with a side chain consisting of just a single hydrogen atom. Its structure is a central carbon bonded to two hydrogen atoms, an amino group, and a carboxyl group, which is a much simpler, non-cyclic structure than the one presented.
- D. Lysine has a long, linear side chain made up of four methylene (-CH₂) units and a terminal primary amino group (-NH₂). This basic, positively charged side chain is an open chain structure, distinctly different from the imidazole ring in the provided image.
Q157. Which one of the following reagents is used for identification of amino acids?
- A. Fehling’s solution
- B. Benedict’s solution
- C. Ninhydrin✓
- D. Copper (II) Sulphate
Explanation: The reagent used for the identification of amino acids is Ninhydrin.Ninhydrin is a chemical compound that reacts with amino acids to produce a colored compound. This reaction is known as the Ninhydrin test. When amino acids are treated with Ninhydrin, they form colored complexes, with different amino acids producing different colors. This property makes Ninhydrin a useful reagent for the detection and identification of amino acids in various chemical and biological samples.
Why the other options are wrong
- A. Fehling's solution is also used to test for the presence of reducing sugars, particularly in qualitative chemical analysis. Like Benedict's solution, Fehling's solution contains copper ions which react with reducing sugars to form a precipitate of red copper(I) oxide. The solution changes color from blue to brick red in the presence of reducing sugars.
- B. Benedict's solution is a chemical reagent used to test for the presence of reducing sugars, such as glucose and fructose. It is commonly used in biochemical assays to detect the presence of sugars in solutions. Benedict's solution changes color in the presence of reducing sugars, forming a precipitate of red copper(I) oxide.
- D. Copper (II) Sulphate is commonly used as a reagent in various chemical reactions. In the context of biology or biochemistry, it may be used in assays or tests related to enzyme activity or as a component of culture media. However, it is not specifically used for the identification of amino acids.
Q158. Which one of the following is an example of a condensation polymer?
- A. Polyvinyl Chloride
- B. Polystyrene
- C. Polyethene
- D. Polyamide✓
Explanation: Condensation polymerization is a form of step-growth polymerization.Linear polymers are produced from bifunctional monomers, i.e. compounds with two reactive end groups.Common condensation polymers include polyamides, polyacetals, and proteins.It is a fact.
Why the other options are wrong
- A. Condensation polymerization is a form of step-growth polymerization.Linear polymers are produced from bifunctional monomers, i.e. compounds with two reactive end groups.Common condensation polymers include polyamides, polyacetals, and proteins.It is a fact.
- B. Condensation polymerization is a form of step-growth polymerization.Linear polymers are produced from bifunctional monomers, i.e. compounds with two reactive end groups.Common condensation polymers include polyamides, polyacetals, and proteins.It is a fact.
- C. Condensation polymerization is a form of step-growth polymerization.Linear polymers are produced from bifunctional monomers, i.e. compounds with two reactive end groups.Common condensation polymers include polyamides, polyacetals, and proteins.It is a fact.
Q159. Among the most common disaccharides, one of the following is present in the milk?
- A. Sucrose
- B. Maltose
- C. Fructose
- D. Lactose✓
Explanation: Lactose is the primary disaccharide in virtually all mammalian milks. It is unique among the major dietary sugars because of the B-1-4 linkagebetween its component monosaccharides,galactose and glucose.It is a fact.
Why the other options are wrong
- A. Sucrose occurs naturally in sugarcane, sugar beets, sugar maple sap, dates, and honey. It is produced commercially in large amounts (especially from sugarcane and sugar beets) and is used almost entirely as food.
- B. Maltose is a disaccharide that's made up of 2 glucose units joined together. It is found naturally in a range of different foods (like cooked sweet potato, pears and honey, for example) and also in a variety of manufactured food stuffs like beer, bread, breakfast cereals and high-maltose corn syrup
- C. Sometimes called “fruit sugar,” fructose is a naturally occurring sugar found primarily in fruits (such as apples, dates, figs, pears and prunes), but also in vegetables (such as artichokes, asparagus, mushrooms, onions and red peppers), honey, sugar beets and sugar cane
Q160. Fats are a type of lipid called glycerides. They are esters of long chain carboxylic acids:
- A. Propene-1, 2, 3-triol
- B. Propane-1, 2, 3-triol✓
- C. Propene-1, 2, 3-diol
- D. Propane-1, 2, 3-diol
Explanation: The correct term for the compound is "Propane-1, 2, 3-triol."Fats, also known as triglycerides, are esters formed from glycerol (propane-1,2,3-triol) and three fatty acid molecules. Glycerol is a triol, meaning it has three hydroxyl (OH) groups. When esterified with fatty acids, these hydroxyl groups react with the carboxyl groups (-COOH) of the fatty acids, forming ester bonds. Therefore, the compound "Propane-1, 2, 3-triol" is the correct chemical name for glycerol, which is a component of fats.
Why the other options are wrong
- A. This option is incorrPropene-1, 2, 3-triol: This molecule has a double bond between two carbon atoms (indicated by "ene"), which is not part of the glycerol structure. Glycerol is a saturated molecule.ect.
- C. This option is incorrect.Propene-1, 2, 3-diol: This molecule has a double bond and only two hydroxyl groups, not three. Glycerol has three hydroxyl groups.
- D. This option is incorrect.Propane-1, 2, 3-diol: This molecule has three carbon atoms (propane) and two hydroxyl groups (diol). Glycerol has three hydroxyl groups (triol).
Q161. Which one of the following bases is NOT present in RNA?
- A. Cytosine
- B. Adenine
- C. Thyamine✓
- D. Guanine
Explanation: The base "Thymine" (T) is not present in RNA. Instead, RNA contains the base "Uracil" (U). Thyamine is a nucleotide base found in DNA but not in RNA. In DNA, thymine pairs with adenine through two hydrogen bonds, forming a T-A base pair.
Why the other options are wrong
- A. Cytosine is one of the four nucleotide bases found in RNA and DNA. In RNA, cytosine pairs with guanine through three hydrogen bonds, forming a C-G base pair.
- B. Adenine is one of the four nucleotide bases found in both RNA and DNA. In RNA, adenine pairs with uracil through two hydrogen bonds, forming an A-U base pair. In DNA, adenine pairs with thymine, forming an A-T base pair.
- D. Guanine is one of the four nucleotide bases found in RNA and DNA. It pairs with cytosine through three hydrogen bonds in DNA, forming a G-C base pair.
Q162. Collagen proteins are present in _ throughout the body.
- A. Muscle
- B. Red blood cells
- C. Tendons✓
- D. Blood Plasma
Explanation: Collagen proteins are present in tendons throughout the body.Collagen is a fibrous protein that is a major component of the extracellular matrix in various connective tissues throughout the body. Tendons are strong, flexible bands of connective tissue that attach muscles to bones, providing stability and transmitting the force generated by muscles to bones to move. Collagen fibers are abundant in tendons, providing tensile strength and resilience to withstand the forces exerted during muscle contraction and movement. Therefore, collagen proteins are predominantly found in tendons among the options listed, although they are also present in other connective tissues such as ligaments, skin, cartilage, and bones.
Why the other options are wrong
- A. Collagen is not the primary protein found in muscles, it does play a role in muscle structure and function. Collagen fibers help to connect muscle fibers to each other and to surrounding connective tissues, providing structural support and facilitating the transmission of force during muscle contraction. However, the predominant proteins in muscle tissue are contractile proteins such as actin and myosin.
- B. Red blood cells, or erythrocytes, are specialized cells that primarily function to transport oxygen from the lungs to the rest of the body tissues and carry carbon dioxide back to the lungs for exhalation. Collagen is not a major component of red blood cells; instead, they are mainly composed of hemoglobin, a protein that binds oxygen and carbon dioxide.
- D. Blood plasma is the liquid component of blood, composed mainly of water, electrolytes, and various proteins, including albumin, globulins, and fibrinogen. While collagen is not typically found in blood plasma in its intact form, small amounts of collagen breakdown products, such as collagen peptides, may be present as a result of tissue turnover and metabolism. However, these are not the primary constituents of blood plasma.
Q163. _ is an eye irritant.
- A. Peroxyacetyl nitrate✓
- B. Peroxyacetyl nitrite
- C. Peroxy Methoxy aniline
- D. Peroxyacetyl aniline
Explanation: Peroxyacetyl nitrate (PAN) is a ubiquitous air pollutant formed from NO(2) reacting with acetoxy radicals generated from ambient aldehydes in the presence of sunlight and ozone. It contributes to eye irritation associated with photochemical smog and is present in most urban air.It is a fact.
Why the other options are wrong
- B. As per the explanation, this is not the correct option.Peroxyacetyl nitrate (PAN) is a ubiquitous air pollutant formed from NO(2) reacting with acetoxy radicals generated from ambient aldehydes in the presence of sunlight and ozone. It contributes to eye irritation associated with photochemical smog and is present in most urban air.It is a fact.
- C. As per the explanation, this is not the correct option.Peroxyacetyl nitrate (PAN) is a ubiquitous air pollutant formed from NO(2) reacting with acetoxy radicals generated from ambient aldehydes in the presence of sunlight and ozone. It contributes to eye irritation associated with photochemical smog and is present in most urban air.It is a fact.
- D. As per the explanation, this is not the correct option.Peroxyacetyl nitrate (PAN) is a ubiquitous air pollutant formed from NO(2) reacting with acetoxy radicals generated from ambient aldehydes in the presence of sunlight and ozone. It contributes to eye irritation associated with photochemical smog and is present in most urban air.It is a fact.
Q164. Polystyrene is an additional polymer. Which one of the following structures representsthe monomer of polystyrene?
- A. CH2=CH2
- B. CH2=CH-CH3
- C. CH2=CH-Cl
- D. CH2=CH-C6H5✓
Explanation: Polystyrene (PS) is a synthetic aromatic hydrocarbon polymer made from the monomer known as styrene.
Why the other options are wrong
- A. As per the explanation, this is not the correct option.CH₂=CH₂: This is ethene (also known as ethylene). Polymerization of ethene produces polyethylene, a different type of plastic.
- B. As per the explanation, this is not the correct option.CH₂=CH-CH₃: This is propene (also known as propylene). Polymerization of propene produces polypropylene, another distinct polymer with different properties than polystyrene.
- C. As per the explanation, this is not the correct option.CH₂=CH-Cl: This is vinyl chloride. Polymerization of vinyl chloride produces polyvinyl chloride (PVC), which is also chemically different from polystyrene.
Q165. Which one of the following pollutants can cause death of a person by binding withhaemoglobin of red blood cells?
- A. Chlorofluorocarbons
- B. Oxides of Sulphur
- C. Carbon monoxide✓
- D. Oxides of nitrogen
Explanation: Carbon monoxide poisoning occurs when carbon monoxide builds up in your bloodstream. When too much carbon monoxide is in the air, your body replaces the oxygen in your red blood cells with carbon monoxide. This can lead to serious tissue damage, or even death.
Why the other options are wrong
- A. Carbon monoxide poisoning occurs when carbon monoxide builds up in your bloodstream. When too much carbon monoxide is in the air, your body replaces the oxygen in your red blood cells with carbon monoxide. This can lead to serious tissue damage, or even death.
- B. Carbon monoxide poisoning occurs when carbon monoxide builds up in your bloodstream. When too much carbon monoxide is in the air, your body replaces the oxygen in your red blood cells with carbon monoxide. This can lead to serious tissue damage, or even death.
- D. Carbon monoxide poisoning occurs when carbon monoxide builds up in your bloodstream. When too much carbon monoxide is in the air, your body replaces the oxygen in your red blood cells with carbon monoxide. This can lead to serious tissue damage, or even death.
Q166. The formula for electric field strength is ‘E = F/Q’, where E is electric field strength and F is force and Q is a charge. Which one of the following options gives the correct base units for electric field strength?
- A. kg m s-3 A-1✓
- B. kg s-2 A-3
- C. kg2 m-2 s-3 A
- D. m s-1 A-3
Explanation: Force-mass x acceleration-kg x ms-2.Q=current(1) x time(t)=IT=A.sE=F/Q-kg ms-2/As .E=kgms-3A-1As it is numerical, it can have only one possible answer. So option A is the correct choice.
Why the other options are wrong
- B. Force=mass x acceleration-kg x ms-2.Q=current(1) x time(t)=IT=A.sE=F/Q -kg m s-2/As E=kg m s-3 A-1
- C. Force=mass x acceleration-kg x ms-2.Q=current(1) x time(t)=IT=A.sE=F/Q -kg m s-2/As E=kg m s-3 A-1
- D. Force=mass x acceleration-kg x ms-2.Q=current(1) x time(t)=IT=A.sE=F/Q -kg m s-2/As E=kg m s-3 A-1
Q167. Which set of the prefixes gives values in increasing order?
- A. Pico, Mega, Kilo, Tera
- B. Pico, Micro, Mega, Giga✓
- C. Tera, Pico, Micro, Kilo
- D. Giga, Kilo, Milli, Nano
Explanation: Pico, Micro, Mega, Giga are the prefixes in increasing order as highlighted below:
Why the other options are wrong
- A. Pico (p), Mega (M), Kilo (k), Tera (T) are prefixes used in the International System of Units (SI) to denote multiples or fractions of units.Among these prefixes, Pico (10-12) represents the smallest value, followed by Kilo (103), Mega (106), and Tera (1012), which represents the largest value.Therefore, the set of prefixes in option a does not give values in increasing order.
- C. Tera (T), Pico (p), Micro (μ), Kilo (k) are SI prefixes.Tera represents 1012, Pico represents 10-12, Micro represents 10-6, and Kilo represents 103.This set does not present values in increasing order as Tera represents a larger value than Pico.
- D. Giga (G), Kilo (k), Milli (m), Nano (n) are SI prefixes.Giga represents 10^9, Kilo represents 103, Milli represents 10-3, and Nano represents 10-9.This set also does not provide values in increasing order as Giga represents a larger value than Kilo.
Q168. Two forces, 5 N and 10 N are acting at ‘O’ and ‘P’ respectively on a uniform rod of 100 cm is suspended at the position of center of gravity 50 cm mark as shown in the figure. What is position of P on meter rod?
- A. 80 cm
- B. 75 cm✓
- C. 70 cm
- D. 65 cm
Explanation: For the rod to be balanced, the clockwise moment must be equal to the anticlockwise moment.5×50=10×xx=25cm 50+25=75cm.250/10=xAs it is a numerical, it can have only one possible answer.
Why the other options are wrong
- A. A) 80 cm: If P were at 80 cm, the distance from the pivot would be 80 - 50 = 30 cm (0.3 m). The clockwise torque would be 0.3 \text{ m} \times 10 \text{ N} = 3 \text{ Nm}. This would not balance the 2.5 Nm counter-clockwise torque.
- C. B) 70 cm: If P were at 70 cm, the distance from the pivot would be 70 - 50 = 20 cm (0.2 m). The clockwise torque would be 0.2 \text{ m} \times 10 \text{ N} = 2 \text{ Nm}. This would not balance the 2.5 Nm counter-clockwise torque.
- D. D) 65 cm: If P were at 65 cm, the distance from the pivot would be 65 - 50 = 15 cm (0.15 m). The clockwise torque would be 0.15 \text{ m} \times 10 \text{ N} = 1.5 \text{ Nm}. This would not balance the 2.5 Nm counter-clockwise torque.
Q169. An oil film floating on water surface exhibits color pattern due to the phenomenon of:
- A. Diffraction
- B. Polarization
- C. Interference✓
- D. Surface tension
Explanation: The bright colors seen in an oil slick floating on water or in a sunlight, soap bubble are caused by interference. The brightest colors are those that interfere constructively. This interference is between the light reflected from different surfaces of a thin film; thus, the effect is known as thin-film interference.
Why the other options are wrong
- A. The bright colors seen in an oil slick floating on water or in a sunlight, soap bubble are caused by interference. The brightest colors are those that interfere constructively. This interference is between the light reflected from different surfaces of a thin film; thus, the effect is known as thin-film interference.
- B. The bright colors seen in an oil slick floating on water or in a sunlight, soap bubble are caused by interference. The brightest colors are those that interfere constructively. This interference is between the light reflected from different surfaces of a thin film; thus, the effect is known as thin-film interference.
- D. The bright colors seen in an oil slick floating on water or in a sunlight, soap bubble are caused by interference. The brightest colors are those that interfere constructively. This interference is between the light reflected from different surfaces of a thin film; thus, the effect is known as thin-film interference.
Q170. Which of the following is the best graphical representation between drag force ‘F’ on a spherical object of radius ‘r’ and its speed ‘v’ through a fluid of viscosity ‘η’?
- A. A✓
- B. B
- C. C
- D. D
Explanation: The equation of stokes law (given below) shows that force and velocity are directly proportional to each other for a sphere with constant radius 'r' moving through a liquid of viscosity n. Hence the graph must be a straight line passing through the origin F = 6πιην
Why the other options are wrong
- B. B) shows an inverse relationship between drag force and speed, where the drag force decreases as the speed increases. This contradicts Stokes' Law.
- C. C) shows a constant drag force regardless of the speed of the object. This also contradicts Stokes' Law, which clearly indicates that drag force depends on speed.
- D. D) shows an infinite drag force at a specific speed and no drag force at other speeds, which is not physically possible according to Stokes' Law for a moving object.
Q171. What is the speed of an incompressible non-viscous liquid flowing out from ‘B’ containedin a container as shown in the figure? Where AB = 5 m and g = 10 m/s2.
- A. 5 m/s
- B. 10 m/s✓
- C. 2 m/s
- D. 50 m/s
Explanation: v2=u2+2as v2=0+2(5)(10) v2=100 v= 10m/s As it is a numerical, it can have only one possible answer.
Why the other options are wrong
- A. v2=u2+2asv2=0+2(5)(10)v2=100v= 10m/s
- C. v2=u2+2asv2=0+2(5)(10)v2=100v= 10m/s
- D. v2=u2+2asv2=0+2(5)(10)v2=100v= 10m/s
Q172. For the horizontal pipe, the fluid inside it is flowing horizontally then Bernoulli’s equation can be written as
- A. P + ρv = constant
- B. 2P + ρv2 = constant
- C. P + 1/2ρv2 = constant✓
- D. 2P + 2ρv2 = constant
Explanation: In a horizontal pipe, the fluid's height does not change, so the gravitational potential energy term in Bernoulli's equation is zero. Thus, the equation simplifies to P + 1/2ρv2 = constant, where P is the pressure and 1/2ρv2 is the kinetic energy per unit volume. Option A and D incorrectly modify the coefficients, and Option B improperly simplifies the velocity term, leading to inaccurate representations of the equation.
Why the other options are wrong
- A. This option incorrectly simplifies the velocity term and omits the kinetic energy component, which should be 1/2ρv2.
- B. This option incorrectly doubles the pressure term and uses an incomplete expression for the kinetic energy term.
- D. This option incorrectly doubles both the pressure and kinetic energy terms, which is not supported by Bernoulli's equation.
Q173. The value of the least distance of distinct vision or near point is _ for a normal human eye.
- A. 20 cm
- B. 25 cm✓
- C. 10 cm
- D. 15 cm
Explanation: The near point of the eye is the minimum distance of the object from the eye, which can be seen distinctly without strain. For a normal human eye, this distance is 25 cm. The far point of the eye is the maximum distance to which the eye can see the objects clearly.
Why the other options are wrong
- A. The near point of the eye is the minimum distance of the object from the eye, which can be seen distinctly without strain. For a normal human eye, this distance is 25 cm. The far point of the eye is the maximum distance to which the eye can see the objects clearly.
- C. The near point of the eye is the minimum distance of the object from the eye, which can be seen distinctly without strain. For a normal human eye, this distance is 25 cm. The far point of the eye is the maximum distance to which the eye can see the objects clearly.
- D. The near point of the eye is the minimum distance of the object from the eye, which can be seen distinctly without strain. For a normal human eye, this distance is 25 cm. The far point of the eye is the maximum distance to which the eye can see the objects clearly.
Q174. In a compound microscope, the magnification by objective = 20, magnification by eyepiece = 11, then the total magnification is
- A. M = -220
- B. M = -0.19
- C. M = -0.05
- D. M = 220✓
Explanation: The explanation is given below:To find the total magnification of two lenses combined we must multiply individual magnifications:20x11 = -220
Why the other options are wrong
- A. This option is incorrect as per the formula.M = M_{objective} \times M_{eyepiece}Given:M_{objective} = 20M_{eyepiece} = 11Therefore, the total magnification is:M = 20 \times 11 = 220
- B. This option is incorrect as per the formula.M = M_{objective} \times M_{eyepiece}Given:M_{objective} = 20M_{eyepiece} = 11Therefore, the total magnification is:M = 20 \times 11 = 220
- C. This option is incorrect as per the formula.M = M_{objective} \times M_{eyepiece}Given:M_{objective} = 20M_{eyepiece} = 11Therefore, the total magnification is:M = 20 \times 11 = 220
Q175. The distance between atoms is 0.30 nm. What will be the wavelength of X-rays at an angle θ=30 for 1st-order diffraction?
- A. λ = 0.60 nm
- B. λ = 0.30 nm✓
- C. λ = 0.20 nm
- D. λ = 0.90 nm
Explanation: The explanation is given below:According to Bragg's law:2dsine=nX 2(0.3*10^-9) sin(30)=1λ=0.3x10^-9= 0.3nm
Why the other options are wrong
- A. This option is incorrect as per the formula.According to Bragg's law:2dsine=nX 2(0.3*10^-9) sin(30)=1λ=0.3x10^-9= 0.3nm
- C. This option is incorrect as per the formula.According to Bragg's law:2dsine=nX 2(0.3*10^-9) sin(30)=1λ=0.3x10^-9= 0.3nm
- D. This option is incorrect as per the formula.According to Bragg's law:2dsine=nX 2(0.3*10^-9) sin(30)=1λ=0.3x10^-9= 0.3nm
Q176. A 100kg man is standing in an elevator, which accidentally falls freely. What will be the weight of the person in the freely falling elevator (take g=10 m/s^2)
- A. 1000 N
- B. 10 N
- C. 500 N
- D. Zero✓
Explanation: Being free fall, the man will be in a state of weightlessness As it is a numerical, it can have only one possible answer.
Why the other options are wrong
- A. 1000 N: This would be the weight of the person if the elevator were stationary or moving at a constant velocity (W = mg = 100 \, \text{kg} \times 10 \, \text{m/s}^2 = 1000 \, \text{N}). This doesn't account for the free fall.
- B. 10 N: This value doesn't have a clear physical basis in this scenario.
- C. 500 N: This is also an arbitrary value and doesn't represent the forces acting on the person during free fall.
Q177. The frequency of a simple pendulum of length 9.8 m will be
- A. 2 π Hertz
- B. π/2 Hertz
- C. 1/2π Hertz✓
- D. π/4 Hertz
Explanation: The frequency of the pendulum is: 1/2π/g/l F= 1/2π/9.8/9.8 F=1/2π Hz. As it is a numerical, it can have only one possible answer.
Why the other options are wrong
Q178. A body performs simple harmonic motion with a period of 0.063 s. The maximum speed of 3.0 ms-1. What are the values of the amplitude ‘xo (m)’ and angular frequency ‘ω(rads-1)’?
- A. xo = 0.03, ω = 100✓
- B. xo = 0.19, ω = 16
- C. xo = 5.3, ω = 16
- D. xo = 3.3, ω = 100
Explanation: Following is the correct solution:
Why the other options are wrong
- B. This option suggests an amplitude of 0.19m and an angular frequency of 16rad/s. However, these values do not match the calculations based on the given period and maximum speed. Therefore, option B) is incorrect.
- C. This option suggests an amplitude of 5.3m and an angular frequency of 16rad/s. These values do not match the calculations based on the given period and maximum speed. Therefore, option C) is incorrect.
- D. This option suggests an amplitude of 3.3m and an angular frequency of 100rad/s. However, these values do not match the calculations based on the given period and maximum speed. Therefore, option D) is incorrect.
Q179. Food being cooked in a microwave oven is an example of :
- A. Beats
- B. Overtones
- C. Resonance✓
- D. Stationary waves
Explanation: Resonance occurs when an external force matches the natural frequency of a system, leading to an increase in amplitude of vibrations. In the case of cooking food in a microwave oven, the microwaves generated match the natural frequency of water molecules, causing them to vibrate and generate heat through friction. This process is an example of resonance. Therefore, option c) is the correct choice.
Why the other options are wrong
- A. Beats occur when two waves of slightly different frequencies interfere with each other, resulting in alternating periods of constructive and destructive interference. This phenomenon is not typically associated with cooking food in a microwave oven. Therefore, option a) is incorrect.
- B. Overtones are higher frequency components of a complex waveform, typically present in harmonic systems. While overtones can be present in certain cooking processes (such as in convection ovens), they are not specifically associated with cooking food in a microwave oven. Therefore, option b) is incorrect.
- D. Stationary waves, also known as standing waves, are formed by the interference of two waves with the same frequency traveling in opposite directions. While stationary waves can occur in certain cooking processes (such as in microwave cavity resonators), they are not specific to the process of cooking food in a microwave oven. Therefore, option d) is incorrect.
Q180. Which of the following represents the total energy of the mass-spring system during SHM?
- A. A
- B. B
- C. C
- D. D✓
Explanation: Potential energy and Kinetic energy interconvert into one another during simple harmonic motion, but the total energy remains constant, which is shown by a straight line in diagram in D.
Why the other options are wrong
- A. Graph A represents Potential energy during SHM rather than the total energy hence, option A is incorrect.
- B. C represents Kinetic energy during SHM not the total energy therefore, option C is incorrect.
- C. This waveform does not represent any energy change during SHM.
Q181. Three graphs for three types of materials are shown in the figure. Which row describes the correct materials?
- A. A
- B. B
- C. C
- D. D✓
Explanation: X is a ductile object; Y is a brittle object and Z is a polymer these graphs are a factual recall
Why the other options are wrong
- A. X is a ductile object; Y is a brittle object and Z is a polymer. Hence this option is incorrect.
- B. X is a ductile object; Y is a brittle object and Z is a polymer. Hence this option is incorrect.
- C. X is a ductile object; Y is a brittle object and Z is a polymer. Hence this option is incorrect.
Q182. A gas containing ‘N’ number of molecules of a gas having mass of each molecule‘m’ is in a cubic container having length of each side ‘a’. What is the density of gascontained in a cube?
- A. N/a^2
- B. m/a^3
- C. Nm/a^3✓
- D. Na^3/m
Explanation: Density=Total mass/Total volume Density=N*m/a^3. As it is a numerical, it can have only one possible answer.
Why the other options are wrong
- A. This option is incorrect as per the formula and calculationDensity=Total mass/Total volumeDensity=N*m/a^3.
- B. This option is incorrect as per the formula and calculationDensity=Total mass/Total volumeDensity=N*m/a^3.
- D. This option is incorrect as per the formula and calculationDensity=Total mass/Total volumeDensity=N*m/a^3.
Q183. In ‘General Gas Equation PV=nRT’, ‘n’ represents the number of moles of gas.Which of the following represents the relation of ‘n’?
- A. n = NNA
- B. n = N/NA✓
- C. n = NA/N
- D. n = N + NA
Explanation: The mathematical equation is: N = n × NA, n= N/ NA
Why the other options are wrong
- A. This option is incorrect as per the formulan = NNA: This would mean the number of moles is the total number of molecules multiplied by Avogadro's number, resulting in a very large and incorrect value for the number of moles.
- C. This option is incorrect as per the formulan = NA/N: This would represent the inverse of the number of moles, which is not what 'n' signifies in the ideal gas equation.
- D. This option is incorrect as per the formulan = N + NA: This suggests that the number of moles is the sum of the total number of molecules and Avogadro's number, which is dimensionally incorrect and doesn't represent the relationship between moles, molecules, and Avogadro's number.
Q184. Which feature of the following graph represents Young’s Modulus?
- A. Area under graph
- B. Gradient of the graph
- C. Reciprocal of the gradient✓
- D. Product of gradient and area of the curve
Explanation: Young's modulus of elasticity (E), also known as the elastic modulus, is the ratio between stress and strain. Since the gradient of graph is strain/stress (gradient = x-axis/y-axis). So, its reciprocal would be equal to Young's modulus.
Why the other options are wrong
- A. Young's modulus of elasticity (E), also known as the elastic modulus, is the ratio between stress and strain. Hence the it is only represented by the reciprocal of the gradient of the graph. This option is incorrect.
- B. Young's modulus of elasticity (E), also known as the elastic modulus, is the ratio between stress and strain. Hence the it is only represented by the reciprocal of the gradient of the graph. This option is incorrect.
- D. Young's modulus of elasticity (E), also known as the elastic modulus, is the ratio between stress and strain. Hence the it is only represented by the reciprocal of the gradient of the graph. This option is incorrect.
Q185. At the triple point of water, the pressure of a gas is 2680 Pa, by changing ‘T’ the pressureincreases to 4870 Pa. Then ‘T’ is:
- A. 496.38 K✓
- B. 438.96 K
- C. 0
- D. 496.38 oF
Explanation: P₁/T₁ = P2/T₂=>T₂ = T1*P2/P₁ 2T, is the triple point temperature 1 of the water, i.e T₁ = 0.01°C=273.16KHence:T₂ = 273.16K 4870 Pa / 2680 Pa =496.37KAs it is a numerical, it can have only one possible answer.
Why the other options are wrong
- B. This option is incorrect as per the formula and calculationsB) 438.96 K: This temperature is lower than 496.38 K. According to the Clausius-Clapeyron equation, a higher pressure should correspond to a higher temperature (assuming \Delta H_{vap} is positive). Since the pressure increased significantly, we would expect a considerable increase in temperature from the triple point (273.16 K), making 438.96 K plausible but potentially too low for such a pressure jump.
- C. This option is incorrect as per the formula and calculationsC) 0: This is an absolute zero temperature, which is physically impossible in this scenario with increased pressure.
- D. This option is incorrect as per the formula and calculationsD) 496.38 °F: This is a temperature in Fahrenheit. Converting it to Kelvin: T(K) = (T(°F) - 32) \times \frac{5}{9} + 273.15 T(K) = (496.38 - 32) \times \frac{5}{9} + 273.15 = 464.38 \times \frac{5}{9} + 273.15 = 257.99 + 273.15 = 531.14
Q186. The relation between Celsius and Fahrenheit scales is:C/100 = (F−32)/180At what temperature do both scales give the same reading?
- A. -100
- B. -40✓
- C. -180
- D. -273
Explanation: Water boils at temperatures=100°C, 212°F and water freezes at =0°C,32°F. 100-°C/100-0-212-°F/212-32 In this formula, 100-boiling point of water in °C and 0° is freezing temperature of water in °C and the same goes for 212 and 32 for Fahrenheit scale. And after simplifying this formula we get our desired formula °F 32 +1.8° C. Now we have to calculate which temperature has equal value in Celsius and Fahrenheit. So let that temperature be x becomes x = 32 +1.8x Now solving this simple equation we get the value of x =-40°. As it is a numerical, it can have only one possible answer.
Why the other options are wrong
- A. To find the temperature at which both Celsius and Fahrenheit scales give the same reading, you can set the two expressions equal to each other and solve for the common temperature.Therefore, -40 degrees Celsius is the temperature at which both Celsius and Fahrenheit scales give the same reading.
- C. To find the temperature at which both Celsius and Fahrenheit scales give the same reading, you can set the two expressions equal to each other and solve for the common temperature.Therefore, -40 degrees Celsius is the temperature at which both Celsius and Fahrenheit scales give the same reading.
- D. To find the temperature at which both Celsius and Fahrenheit scales give the same reading, you can set the two expressions equal to each other and solve for the common temperature.Therefore, -40 degrees Celsius is the temperature at which both Celsius and Fahrenheit scales give the same reading.
Q187. A heat engine working according to the second law of thermodynamics has 50% efficiency.What will be the temperature of its low-temperature reservoir if the high-temperaturereservoir is 327 K?
- A. 27 0C✓
- B. 127 0C
- C. 300 0 C
- D. 600 0 C
Explanation: 327k means 327-273-54 degrees celsius. For a reservoir to work at a 50% efficiency, the low reservoir must have half the temperature than the high reservoir, which makes the temperature 27 degrees celsius. As it is a numerical, it can have only one possible answer.
Why the other options are wrong
- B. This option is incorrect as per the calculation327k means 327-273-54 degrees celsius. For a reservoir to work at a 50% efficiency, the low reservoir must have half the temperature than the high reservoir, which makes the temperature 27 degrees celsius.
- C. This option is incorrect as per the calculation327k means 327-273-54 degrees celsius. For a reservoir to work at a 50% efficiency, the low reservoir must have half the temperature than the high reservoir, which makes the temperature 27 degrees celsius.
- D. This option is incorrect as per the calculation327k means 327-273-54 degrees celsius. For a reservoir to work at a 50% efficiency, the low reservoir must have half the temperature than the high reservoir, which makes the temperature 27 degrees celsius.
Q188. Three NAND gates are connected as shown in the figure.Which of the following logic gates is formed in the connected circuit?
- A. OR✓
- B. AND
- C. NOR
- D. NAND
Explanation: We can check to which gate this diagram refers to by sending in 1 from A and 0 from B.Output at X, after working, will be 1. This means that this gate is working as an OR gate. Asonly in the OR gate, when two inputs are 1 and 0 respectively the output is 1.
Why the other options are wrong
- B. We can check to which gate this diagram refers to by sending in 1 from A and 0 from B.Output at X, after working, will be 1. This means that this gate is working as an OR gate. Asonly in the OR gate, when two inputs are 1 and 0 respectively the output is 1.
- C. We can check to which gate this diagram refers to by sending in 1 from A and 0 from B.Output at X, after working, will be 1. This means that this gate is working as an OR gate. Asonly in the OR gate, when two inputs are 1 and 0 respectively the output is 1.
- D. We can check to which gate this diagram refers to by sending in 1 from A and 0 from B.Output at X, after working, will be 1. This means that this gate is working as an OR gate. Asonly in the OR gate, when two inputs are 1 and 0 respectively the output is 1.
Q189. What is the output of the truth table?
- A. A
- B. A AND C
- C. B
- D. NO CORRECT OPTION✓
Explanation: A.B means that A AND B imply that 0 AND 0 should give 1, 1 and 0 should give 1 and 1 and 1 should give 0.
Why the other options are wrong
- A. A.B means that A AND B imply that 0 AND 0 should give 1, 1 and 0 should give 1 and 1 and1 should give 0.
- B. A.B means that A AND B imply that 0 AND 0 should give 1, 1 and 0 should give 1 and 1 and1 should give 0.
- C. A.B means that A AND B imply that 0 AND 0 should give 1, 1 and 0 should give 1 and 1 and1 should give 0.
Q190. What is the reading of Ammeter as shown in the circuit diagram?
- A. 1 A
- B. 15 A
- C. 4 A✓
- D. 10 A
Explanation: The total voltage, in this case, will be 6+6=12V; R=3 ohms I=V/R=12/3= 4A. As it is a numerical, it can have only one possible answer.
Why the other options are wrong
- A. This option is incorrect as per the calculationsThe total voltage, in this case, will be 6+6=12V; R=3 ohms I=V/R=12/3= 4A.
- B. This option is incorrect as per the calculationsThe total voltage, in this case, will be 6+6=12V; R=3 ohms I=V/R=12/3= 4A.
- D. This option is incorrect as per the calculationsThe total voltage, in this case, will be 6+6=12V; R=3 ohms I=V/R=12/3= 4A.
Q191. Three 6 Ω are connected as shown in the diagram What is the resistance between points ‘A’ and ‘B’
- A. 6 Ω
- B. 16 Ω
- C. 4 Ω
- D. 2 Ω V✓
Explanation: If looked into closely, these resistors are actually parallel to each other. The total resistance is equal to: 1/R-1/R1+1/R2+1/R3 1/R=1/6+1/6+1/6=3/6 1/R=2 R=2 ohms. As it is a numerical, it can have only one possible answer.
Why the other options are wrong
- A. This option is incorrect as per the calculationsIf looked into closely, these resistors are actually parallel to each other. The total resistance is equal to:1/R-1/R1+1/R2+1/R3 1/R=1/6+1/6+1/6=3/61/R=2R=2 ohms.
- B. This option is incorrect as per the calculationsIf looked into closely, these resistors are actually parallel to each other. The total resistance is equal to:1/R-1/R1+1/R2+1/R3 1/R=1/6+1/6+1/6=3/61/R=2R=2 ohms.
- C. This option is incorrect as per the calculationsIf looked into closely, these resistors are actually parallel to each other. The total resistance is equal to:1/R-1/R1+1/R2+1/R3 1/R=1/6+1/6+1/6=3/61/R=2R=2 ohms.
Q192. The difference between the plates of a parallel plate capacitor is 2.0 mm and the area of each plate is 2.0 m2. The plates are in a vacuum. A potential difference of 1.0x104 V is applied across the plates. Find the capacitance.
- A. 4.0 x 10-3 F
- B. 3.54 x 10-9 F
- C. 8.85 x 10-9 F✓
- D. 9.0 x 10-9 F
Explanation: The capacitance of a parallel plate capacitor isC=ЄA/dC=(8.85x10^-12)x(2)/(2x10^-3)=8.85 x 10^-9CAs it is numerical, it can have only one possible answer.
Why the other options are wrong
- A. This option suggests that the capacitance is 4x10^-3 F but using the formula C=ЄA/d, we get a capacitance of 8.85x10^-9 F.
- B. This option suggests that the capacitance is 3.54x10^-9 F but using the formula C=ЄA/d, we get a capacitance of 8.85x10^-9 F.
- D. This option suggests that the capacitance is 9x10^-9 F but using the formula C=ЄA/d, we get a capacitance of 8.85x10^-9 F.
Q193. A solenoid 15 cm long has 300 turns of wire. A current of 5 A flows through it. What is the magnitude of the magnetic field inside the solenoid?
- A. 75 x 107 T
- B. 60 x 10+3 T
- C. 4π x 10-3✓
- D. 750π x 10+3
Explanation: The magnetic field inside a solenoid is given by the formula:B=μ0nIwhere:B = Magnetic field (T)μ0 = Permeability of free space (4π×10−7n = Number of turns per unit length (N/L)I = Current (A)Given data:N=300N = 300N=300 turnsL=15L = 15L=15 cm = 0.15 mI=5I = 5I=5 AFirst, calculate n:n=NL=3000.15=2000 turns/mNow, calculate BBB:B=(4π×10−7)×(2000)×(5)Approximating π≈3.1416B≈4×3.1416×10−3
Why the other options are wrong
- A. This is not correct as per calculation.
- B. This is not correct as per calculation.
- D. This is not correct as per calculation.
Q194. Due to the current in a straight conductor the difference between magnetic field lines:
- A. Increases away from conductor✓
- B. Decreases away from conductor
- C. Increases towards conductor
- D. Decreases and then increases towards conductor
Explanation: The difference between the magnetic field lines increases as shown below:
Why the other options are wrong
- B. This option is incorrect. As explained above, the density of magnetic field lines increases as you move away from the conductor, resulting in an increase in the difference between magnetic field lines, not a decrease.
- C. This option is incorrect. The density of magnetic field lines decreases as you move towards the conductor, resulting in a decrease in the difference between magnetic field lines, not an increase.
- D. This option is incorrect. The magnetic field lines form concentric circles around the conductor, and as you move towards the conductor, the density of these magnetic field lines increases, leading to an increase in the difference between magnetic field lines, not a decrease followed by an increase.
Q195. Magnetic Resonance Imaging (MRI) is used to identify the image of:
- A. Tumors and inflamed tissues✓
- B. Blood cells
- C. Skin cells
- D. Bone structures
Explanation: MRI is used to identify images of tumours and inflamed tissues. Blood cells are identified by smear stain, skin cells are identified under a microscope, and bone structures are looked at using X-rays.It is a fact.
Why the other options are wrong
- B. Blood cells are identified by smear stain hence this option is incorrect.
- C. Skin cells are identified under a microscope hence this option is incorrect.
- D. Bone structures are looked at using X-rays hence this option is incorrect.
Q196. The stimulated emission of two photons ‘A’ and ‘B’ during LASER action is shown in the figure. What is the relation between wavelengths of two photons?
- A. λA = λB✓
- B. λA > λB
- C. λA < λB
- D. λA = 2λB
Explanation: Wavelengths of photons in a laser action are all the same hence the wavelength of A is equal to the wavelength of B. Lasers are monochromatic, having the same wavelengths.
Why the other options are wrong
- B. Wavelengths of photons in a laser action are all the same hence the wavelength of A is equal to the wavelength of B. Lasers are monochromatic, having the same wavelengths.
- C. Wavelengths of photons in a laser action are all the same hence the wavelength of A is equal to the wavelength of B. Lasers are monochromatic, having the same wavelengths.
- D. Wavelengths of photons in a laser action are all the same hence the wavelength of A is equal to the wavelength of B. Lasers are monochromatic, having the same wavelengths.
Q197. Bones absorb greater amounts of incident X-rays than flesh. This is because:
- A. Bones lie between the flesh
- B. Bones are light in color
- C. Bones contain material of low densities
- D. Bones contain material of high densities✓
Explanation: Bones absorb more amounts of incident X-rays than flesh because bones contain a very large amount of calcium which makes it highly dense.The colour of bones has nothing to do with radiation absorption,nor does the position of bones in flesh.It is a fact.
Why the other options are wrong
- A. The color of bones has nothing to do with radiation absorption, nor does the position of bones in the flesh. Hence this option is incorrect.
- B. The color of bones has nothing to do with radiation absorption, nor does the position of bones in the flesh. Hence this option is incorrect.
- C. Bones absorb more amounts of incident X-rays than flesh because bones contain a very large amount of calcium which makes it highly dense. Hence this option is incorrect.
Q198. Which of the following techniques is the practical application of X-rays?
- A. Magnetic Resonance Imaging
- B. Ultrasonography
- C. Computerized Axial Topography✓
- D. Positron Emission Tomography
Explanation: Computed tomography (CT) scanning, also known as, especially in the older literature and textbooks, computerized axial tomography (CAT) scanning, is a diagnostic imaging procedure that uses x-rays to build cross-sectional images ("slices") of the body.It is a fact.
Why the other options are wrong
- A. This is not the practical application of X rays
- B. This is not the practical application of X rays
- D. This is not the practical application of X rays
Q199. Which of the following spectra is most typical of the output of an X-ray tube?
- A. A✓
- B. B
- C. C
- D. D
Explanation: The graph, shown in option A, comprises of two types of X-rays, labeled in the graph presented below;1. Characteristic X-rays;These X-rays are produced on instances when outer-shell electrons fill a vacancy in the inner shell of an atom, releasing X-rays.2. Bremsstrahlung/Braking Continnuum;This release of X-ray is exclusive to instances where a charged, accelerated particle i.e. Electrons is decelerated, upon striking against a metal surface or any surface. The outcome is the release of electromagnetic radiation, in the form of photons.
Why the other options are wrong
- B. It is against the characteristics of X-rays.
- C. It is against the characteristics of X- rays.
- D. It is against the characteristics of X- rays.
Q200. Which one of the following has the largest energy content?
- A. γ-rays✓
- B. X-rays
- C. Infra-red radiations
- D. Ultra-violet radiations
Explanation: Gamma rays have the highest energy in all of the above mentioned, it is because of their highest frequency among all, as shown below:
Why the other options are wrong
- B. Higher the frequency, higher will be the energy of the waves
- C. Higher the frequency, higher will be the energy of the waves
- D. Higher the frequency, higher will be the energy of the waves
Q201. What will be the energy of the accelerated electron used to produce X-rays when theaccelerating potential is 2 kV?
- A. 2 x 10-19 J
- B. 1.6 x 10-19 J
- C. 3.2 x 1019 J
- D. 3.2 x 10-16 J✓
Explanation: The formula relating energy, charges, and voltages is:APE = qAV. PE=(2x10^3)*(1.6x10^-19)PE=3.2x10^-16 J.As it is a numerical, it can have only one possible answer.
Why the other options are wrong
- A. This option is incorrect as per the calculationsThe formula relating energy, charges, and voltages is:APE = qAV. PE=(2x10^3)*(1.6x10^-19)PE=3.2x10^-16 J.
- B. This option is incorrect as per the calculationsThe formula relating energy, charges, and voltages is:APE = qAV. PE=(2x10^3)*(1.6x10^-19)PE=3.2x10^-16 J.
- C. This option is incorrect as per the calculationsThe formula relating energy, charges, and voltages is:APE = qAV. PE=(2x10^3)*(1.6x10^-19)PE=3.2x10^-16 J.
Q202. Process of generating three dimensional images of objects by using laser beam is called
- A. Photography
- B. 3-D cinema
- C. Holography✓
- D. Tomography
Explanation: Holography is a process that creates three-dimensional images called holograms using laser beams, the properties of intensity interference and diffraction, light recording, and illumination of the recording.
Why the other options are wrong
- A. Photography: Photography is a process of capturing two-dimensional images of objects using cameras. It does not involve the use of laser beams to generate three-dimensional images.
- B. 3-D cinema: 3-D cinema involves the projection of two different images, one for each eye, to create the illusion of depth perception. However, it is not a process of generating three-dimensional images using laser beams.
- D. Tomography: Tomography is a technique used to produce cross-sectional images of objects by capturing data from multiple angles. It is commonly used in medical imaging to generate images of the inside of the body. However, it does not involve the use of laser beams to generate three-dimensional images.
Q203. Which one of the following isotopes of Iodine is used for the treatment of thyroid cancer?
- A. I-113
- B. I-120
- C. I-131✓
- D. I-140
Explanation: Because of this, radioactive iodine (RAI, also called I-131) can be used to treat thyroid cancer. The RAI collects mainly in thyroid cells, where the radiation can destroy the thyroid gland and any other thyroid cells (including cancer cells) that take up iodine, with little effect on the rest of your body.It is a fact.
Why the other options are wrong
- A. Because of this, radioactive iodine (RAI, also called I-131) can be used to treat thyroid cancer. The RAI collects mainly in thyroid cells, where the radiation can destroy the thyroid gland and any other thyroid cells (including cancer cells) that take up iodine, with little effect on the rest of your body.It is a fact.
- B. Because of this, radioactive iodine (RAI, also called I-131) can be used to treat thyroid cancer. The RAI collects mainly in thyroid cells, where the radiation can destroy the thyroid gland and any other thyroid cells (including cancer cells) that take up iodine, with little effect on the rest of your body.It is a fact.
- D. Because of this, radioactive iodine (RAI, also called I-131) can be used to treat thyroid cancer. The RAI collects mainly in thyroid cells, where the radiation can destroy the thyroid gland and any other thyroid cells (including cancer cells) that take up iodine, with little effect on the rest of your body.It is a fact.
Q204. A beta (β) particle is a fast-moving electron. During a β – decay how does the atomic number and mass number of a nucleus change?
- A. A
- B. B
- C. C✓
- D. D
Explanation: In beta decay, one of the neutrons in the nucleus suddenly changes into a proton, causing an increase in the atomic number of an element while the mass number remains the same, as shown below:
Why the other options are wrong
- A. In beta decay, one of the neutrons in the nucleus suddenly changes into a proton, causing an increase in the atomic number of an element while the mass number remains the same.
- B. In beta decay, one of the neutrons in the nucleus suddenly changes into a proton, causing an increase in the atomic number of an element while the mass number remains the same.
- D. In beta decay, one of the neutrons in the nucleus suddenly changes into a proton, causing an increase in the atomic number of an element while the mass number remains the same.
Q205. A Uranium isotope 92U232 undergoes one α–decay and two β-1 – decay. What is the final product?
- A. 90
- B. 92✓
- C. 89
- D. 88
Explanation: Alpha decay causes a decrease in atomic number by 2 and mass number by 4. One beta decay causes increases in atomic number by one while the mass number remains the same. Since there are two beta-decay the atomic numbers increase by two making the atomic number back to 92.It is numerical and can have only one possible answer.
Why the other options are wrong
- A. Alpha decay causes a decrease in atomic number by 2 and mass number by 4. One beta decay causes increases in atomic number by one while the mass number remains the same. Since there are two beta-decay the atomic numbers increase by two making the atomic number back to 92.It is numerical and can have only one possible answer.
- C. Alpha decay causes a decrease in atomic number by 2 and mass number by 4. One beta decay causes increases in atomic number by one while the mass number remains the same. Since there are two beta-decay the atomic numbers increase by two making the atomic number back to 92.It is numerical and can have only one possible answer.
- D. Alpha decay causes a decrease in atomic number by 2 and mass number by 4. One beta decay causes increases in atomic number by one while the mass number remains the same. Since there are two beta-decay the atomic numbers increase by two making the atomic number back to 92.It is numerical and can have only one possible answer.
Q206. A naturally occurring radioactive element decays into two alpha particles. Which one of the following represents the status of the daughter element concerning the mass number ‘A’ and charge number ‘Z’?
- A. ‘Z’ decreases by 4 and ‘A’ decreases by 2
- B. ‘Z’ decreases by 2 and ‘A’ decreases by 4
- C. ‘Z’ decreases by 4 and ‘A’ decreases by 8✓
- D. ‘Z’ decreases by 8 and ‘A’ decreases by 4
Explanation: Alpha particle has 2 neutrons and 2 protons, thus alpha decay causes. the decrease of mass number by 4 and proton number by 2. One alpha decay causes the decrease of mass number by 4 and atomic number by 2. Two alpha decays thus causes the decrease of mass number by 8 and decrease of atomic number by 4.It is numerical and can have only one possible answer.
Why the other options are wrong
- A. Alpha particle has 2 neutrons and 2 protons, thus alpha decay causes. the decrease of mass number by 4 and proton number by 2. One alpha decay causes the decrease of mass number by 4 and atomic number by 2. Two alpha decays thus causes the decrease of mass number by 8 and decrease of atomic number by 4.It is numerical and can have only one possible answer.
- B. Alpha particle has 2 neutrons and 2 protons, thus alpha decay causes. the decrease of mass number by 4 and proton number by 2. One alpha decay causes the decrease of mass number by 4 and atomic number by 2. Two alpha decays thus causes the decrease of mass number by 8 and decrease of atomic number by 4.It is numerical and can have only one possible answer.
- D. Alpha particle has 2 neutrons and 2 protons, thus alpha decay causes. the decrease of mass number by 4 and proton number by 2. One alpha decay causes the decrease of mass number by 4 and atomic number by 2. Two alpha decays thus causes the decrease of mass number by 8 and decrease of atomic number by 4.It is numerical and can have only one possible answer.
Q207. A radioactive isotope ‘W’ decays to ‘X’ which decays to ‘Y’ and ‘Y’ decays to ‘Z’ as represented by the figure below. What is the change in the atomic number from ‘W’ to ‘Z’?
- A. Increases by 3
- B. Decreases by 3✓
- C. Increases by 5
- D. Decreases by 5
Explanation: The atomic number decreases by two during an alpha-decay and increases by 1 during beta-decay. There are two alpha decays(decreases by 4) and one beta decay(increases by 1). So the overall change is -4+1=-3(decrease by 3). It is numerical and can have only one possible answer.
Why the other options are wrong
- A. This option suggests that the atomic number increases by 3 from W to Z. However, as we determined earlier, each decay step results in a decrease in the atomic number. Therefore, the atomic number decreases by 3 units from W to Z, making option A incorrect.
- C. This option suggests that the atomic number increases by 5 from W to Z. However, as discussed earlier, each decay step leads to a decrease in the atomic number. Therefore, the atomic number decreases, and option C is incorrect.
- D. This option implies that the atomic number decreases by 5 from W to Z. However, as we established earlier, the net change in the atomic number is a decrease of 3 units, not 5 units. Therefore, option D is incorrect.
Q208. Three paths of radioactive radiation are observed as shown in the figure in the presence of an electric field. Which type of radiation is shown in path 1?
- A. Alpha
- B. Beta
- C. Gamma✓
- D. Cathode Rays
Explanation: 1 is the particle that remains undeflected which means it does not have charge, which is gamma rays.
Why the other options are wrong
- A. Alpha particles are positively charged and their path would not be straight.
- B. Beta particles are negatively charged and their path would not be straight.
- D. Cathode rays are electrons which are negatively charged and their path would not be straight.
Q209. What is the absorbed dose ‘D’ of a sample of 2 kg which is given an amount of 100 J of radioactive energy?
- A. 200 Gy
- B. 102 Gy
- C. 50 Gy✓
- D. 98 Gy
Explanation: Radioactive energy absorbed per kg is called an absorbed dose(D).Absorbed dose=Energy/MassD=100/2=50Gy
Why the other options are wrong
- A. Calculations show that the absorbed dose is 50 Gy hence this option is incorrect.
- B. Calculations show that the absorbed dose is 50 Gy hence this option is incorrect.
- D. Calculations show that the absorbed dose is 50 Gy hence this option is incorrect.
Q210. Fill in the blank with appropriate article as required._ umbrella is of no avail against a thunderstorm.
- A. The
- B. A
- C. An✓
- D. No article required
Explanation: "An" umbrella is of no avail against a thunderstorm. The indefinite article "an" is used in this sentence because it introduces the general concept of an umbrella without specifying a particular umbrella. It implies that any umbrella in general would not be effective against a thunderstorm.
Why the other options are wrong
- A. This is incorrect. The indefinite article "an" is used in this sentence because it introduces the general concept of an umbrella without specifying a particular umbrella. It implies that any umbrella in general would not be effective against a thunderstorm.
- B. This is incorrect. The indefinite article "an" is used in this sentence because it introduces the general concept of an umbrella without specifying a particular umbrella. It implies that any umbrella in general would not be effective against a thunderstorm.
- D. This is incorrect. The indefinite article "an" is used in this sentence because it introduces the general concept of an umbrella without specifying a particular umbrella. It implies that any umbrella in general would not be effective against a thunderstorm.
Q211. Not only the parents but also their son _ for interview.
- A. Has called
- B. Have called
- C. Have been called
- D. Has been called✓
Explanation: Parents are plural but the blank follows the noun 'son' which is singular. Hence "has" instead of "have" is the right option.The sentence refers to an act being done to the noun instead of the son doing something. Hence it will be: ‘been called’ instead of just ‘called’
Why the other options are wrong
- A. This option is incorrect because "has called" implies that the son is the one who made phone calls. The sentence structure, however, suggests that the son is the one who received a call or invitation.
- B. This option is incorrect because "have called" is plural, but the subject "son" is singular. The verb form should agree with the singular subject.
- C. This option is incorrect because "have been called" is plural, but the subject "son" is singular.
Q212. Neither they nor their friend _ solved the question.
- A. Has✓
- B. Have
- C. Was
- D. Were
Explanation: In this sentence, 'neither...nor' indicates that the verb should agree with the subject that is closest to it. Since 'friend' is singular, the correct verb is 'has.' The other options are incorrect: 'Have' would be used if the subject closest to the verb were plural; 'Was' and 'Were' do not fit because they do not appropriately express the current action of solving the question.
Why the other options are wrong
- B. This is incorrect. Although 'they' is plural and would typically take 'have,' the verb must agree with the subject closest to it, which is 'their friend,' a singular noun.
- C. This is incorrect because 'was' is not suitable for expressing the completion of the action 'solved.' Furthermore, 'was' does not match the present context of solving a question.
- D. This is incorrect. 'Were' is a past tense plural verb which does not match the present context of the sentence. The verb should be singular to match 'friend.'
Q213. Fill in the blank with the correct option:He was _ with theft in the court.
- A. Charged✓
- B. Reported
- C. Blamed
- D. Accused
Explanation: In a legal context, being charged means that a person has been formally accused of committing a crime. It implies that there are legal proceedings taking place or about to take place in a court of law. Option A fits the context of the sentence, indicating that the person is facing legal accusations related to theft.
Why the other options are wrong
- B. Reporting refers to informing the authorities or providing information about an incident. It does not necessarily imply a legal accusation or formal charges.
- C. Blaming someone typically involves assigning responsibility for a particular action or outcome. However, it does not imply a formal legal accusation or charges.
- D. Accusing someone is similar to blaming them, but it specifically refers to making a formal charge or allegation against them. While "accused" is a stronger option than "blamed," it is not as precise as "charged" in the context of a court proceeding.
Q214. Complete the sentence by choosing the most appropriate option, from the given lettered choices (A to E) below:It is quite _ for poor people to be happier than rich people.
- A. Possible✓
- B. Risky
- C. Potential
- D. Liable
- E. Different
Explanation: The best option is "possible", as it expresses the idea that it is indeed possible for poor people to be happier than rich people.
Why the other options are wrong
- B. This option suggests that it is risky for poor people to be happier than rich people, which doesn't make logical sense in the context of the sentence. Happiness is not typically associated with risk.
- C. While it is true that poor people have the potential to be happier than rich people, this option doesn't fully convey the idea that poor people can actually achieve happiness. It leaves room for uncertainty.
- D. This option implies that poor people are more likely to be happier than rich people, which is not necessarily the case. Happiness is not determined solely by one's financial status.
- E. This option suggests that poor people being happier than rich people is merely a matter of being different, without indicating whether it is possible or not.
Q215. The headmaster _ to speak to you.
- A. Wants✓
- B. Is wanting
- C. Was wanting
- D. Want
Explanation: “The headmaster wants to speak to you” in Option A sounds most appropriate because "headmaster" is a singular noun so we should complement it with a singular verb - eliminating Option D. The tense is simple present indicated by the verb "speak", hence the present continuous form "is wanting" in Option B is also incorrect. while the past tense form in Option C is also incorrect.
Why the other options are wrong
- B. “The headmaster wants to speak to you” in Option A sounds most appropriate because "headmaster" is a singular noun so we should complement it with a singular verb - eliminating Option D. The tense is simple present indicated by the verb "speak", hence the present continuous form "is wanting" in Option B is also incorrect. while the past tense form in Option C is also incorrect.
- C. “The headmaster wants to speak to you” in Option A sounds most appropriate because "headmaster" is a singular noun so we should complement it with a singular verb - eliminating Option D. The tense is simple present indicated by the verb "speak", hence the present continuous form "is wanting" in Option B is also incorrect. while the past tense form in Option C is also incorrect.
- D. “The headmaster wants to speak to you” in Option A sounds most appropriate because "headmaster" is a singular noun so we should complement it with a singular verb - eliminating Option D. The tense is simple present indicated by the verb "speak", hence the present continuous form "is wanting" in Option B is also incorrect. while the past tense form in Option C is also incorrect.
Q216. Several times during the session the director _ to tell his success story to the other promotion.
- A. Asked he
- B. Asked who
- C. Asked him✓
- D. Asked his
Explanation: The correct answer is C. "Asked him."Explanation:In this sentence, the director is the subject who wants to tell his success story. The verb "asked" is followed by an object pronoun to indicate whom the director is asking.Let's analyze the given options:A. "Asked he" - This option is incorrect because "he" is a subject pronoun, and after the verb "asked," we need an object pronoun.B. "Asked who" - This option is incorrect because "who" is an interrogative pronoun used for asking questions about the subject, not the object. In this context, we need an object pronoun to indicate whom the director is asking.C. "Asked him" - This option is correct. "Him" is the objective pronoun and the correct choice to indicate the person the director is asking. This option correctly conveys the intended meaning.D. "Asked his" - This option is incorrect because "his" is a possessive pronoun used to indicate ownership, not the person being asked. It does not convey the meaning of the director asking someone to tell his success story.Therefore, option C, "Asked him," is the correct answer as it uses the appropriate object pronoun to indicate the person the director is asking to tell his success story.
Why the other options are wrong
- A. Asked he" - This option is incorrect because "he" is a subject pronoun, and after the verb "asked," we need an object pronoun.
- B. Asked who" - This option is incorrect because "who" is an interrogative pronoun used for asking questions about the subject, not the object. In this context, we need an object pronoun to indicate whom the director is asking.
- D. Asked his" - This option is incorrect because "his" is a possessive pronoun used to indicate ownership, not the person being asked. It does not convey the meaning of the director asking someone to tell his success story.
Q217. Did anybody do the work _?
- A. Themselves
- B. Himself✓
- C. His self
- D. None
Explanation: Since "anybody" is singular, therefore "himself" should be used.
Why the other options are wrong
- A. Since "anybody" is singular, therefore "himself" should be used.
- C. Since "anybody" is singular, therefore "himself" should be used.
- D. Since "anybody" is singular, therefore "himself" should be used.
Q218. Ahmed _ me for a long time.
- A. Know
- B. Has known✓
- C. Knows
- D. Knew
Explanation: The most appropriate word to fill in the blank would be "has known."The complete sentence would be: "Ahmed has known me for a long time."Using the present perfect tense "has known" indicates that Ahmed developed knowledge or familiarity with the speaker in the past and that this knowledge or familiarity has continued up until the present time.
Why the other options are wrong
- A. This option is incorrect because "know" is the base form (infinitive) of the verb and does not fit the tense needed in the sentence.
- C. This option is incorrect because "knows" is the present tense form of the verb, which does not fit the context of the sentence describing a past duration.
- D. This option is incorrect because "knew" is the past tense form of the verb "know." It describes a completed action in the past, which does not indicate a continuing state from the past to the present.
Q219. When your friend _, he’ll be very tired.
- A. Arrived
- B. Will arrive
- C. Arrives✓
- D. Is arriving
Explanation: Future is always followed by the present. In the given sentence, in the second clause there is use of simple future so its grammatical rule that the first clause must be in simple present.
Why the other options are wrong
- A. This option is incorrect because "arrived" is in the past tense, which does not match the future tense implied by the phrase "when your friend." We need a verb form that corresponds to a future event.
- B. This option is incorrect because the phrase "when your friend" already implies a future event, so using "will arrive" would create redundancy. The verb form "will arrive" is not necessary in this context.
- D. This option is incorrect because "is arriving" is in the present continuous tense, which indicates an ongoing action in the present. However, the sentence implies a future event, not a current ongoing action.
Q220. Select the correct option:He was killed _ a robber _ a hatchet.
- A. From, with
- B. By, at
- C. Through, far
- D. By, with✓
Explanation: The first blank needs a preposition, that shows property and accountability, hence ‘by’ is the best choice here.The second blank needs a word that means 'to refer to something', hence 'with' will be the best option here.
Why the other options are wrong
- A. The preposition ”from” typically indicates a point of origin its source, rather than an agent of an action. Additionally “with” is used to describe the instrument or means, in this case the instrument is the hatchet, not the robber.
- B. The preposition “at” typically indicates a location or place but “by” is the correct preposition.
- C. The preposition “through” typically indicates a movement or a process of passing from one side to another. Similarly, “far” indicates distance.
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