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Uhs Mdcat 2018 — Solved Past Paper with Answers
All 220 MCQs from Uhs Mdcat 2018, solved with the correct answer highlighted and a full explanation for every question. This is a free MDCAT Punjab / UHS past paper — no signup, no ads. Practise it interactively in timed mode, drill more with free MDCAT MCQs, or browse all Punjab / UHS papers.
Attempt this paper interactively →Q1. Choose the BEST Option.That is just an example of what I complain _.
- A. Of✓
- B. Off
- C. To
- D. With
Explanation: Of is a preposition that indicates relationships between other words, such as belonging, things made of other things, things that contain other things, or a point of reckoning. The object of "of" must be a problem of some kind: you could complain of a headache, an unreliable web server, an unfaithful spouse, mistreatment by police, etc.
Why the other options are wrong
- B. 'Off' is usually used as an adverb or a preposition. In both cases, it indicates separation or disconnection. For example: She got off the bus at the next stop.
- C. We can use to as a preposition to indicate a destination or direction: We're going to Liverpool next week. Does he want to come to the park with us?
- D. With means 'in the same place as someone or something' or 'accompanying': I don't like tea with milk. There was a free phone with the car.
Q2. Choose the BEST Option.The region _ which they were passing was known as the Land of Thirst and Death.
- A. Through✓
- B. By
- C. In
- D. From
Explanation: Through can be used as a preposition, an adverb, and an adjective. It has several meanings, including “from one side to the other,” “from beginning to end,” and “during an entire period”: He rode his bicycle through the door and onto the street. You have to read the book through if you want to be prepared for class.
Why the other options are wrong
- B. By means ‘as a means of’ something or someone. This preposition often comes in a passive sentence.Example:Do you travel by bus/train/plane/bike? He was undone by me. The letter was written by him.
- C. In is used to indicate a location, while doing something, to indicate opinion, belief, feeling, etc. It is used to specify day, month, season, year, and to indicate colour, shape and size.
- D. 'From' is used to show where somebody/something starts, what the origin of somebody/something is, how far apart two places are, somebody’s position or point of view etc
Q3. Choose the BEST Option.I know how to _ a throat for inspection.
- A. Force
- B. Prepare
- C. Expose✓
- D. Open
Explanation: Expose is defined as to make something visible or known. Jence this is the correct option.
Why the other options are wrong
- A. This means to make someone do something against their will or to exert physical strength. Forcing a throat for inspection would be inappropriate and medically incorrect.
- B. This means to make ready beforehand for a specific purpose. While you can prepare a patient for an inspection, it doesn't directly refer to the act of making the throat visible for inspection.
- D. This means to move something from a closed position to a more accessible one. While you might open a mouth, "expose" is more precise when referring to the throat specifically for inspection purposes.
Q4. Choose the BEST Option.It is better for me to _ than to shed the blood of an innocent boy.
- A. Died
- B. Die✓
- C. Had died
- D. Have died
Explanation: The sentence is structured in a way that requires an infinitive verb form ("to die")."Die" is the infinitive form of the verb that correctly fits after "to" in this sentence.
Why the other options are wrong
- A. "Died" is the past tense of the verb "to die," which does not fit the infinitive form required by "to."
- C. "Had died" is the past perfect tense, which is used to indicate an action completed before another past action. It doesn't fit the structure needed here.
- D. "Have died" is the present perfect tense, indicating an action that occurred at an unspecified time before now. It doesn't fit the infinitive structure required by "to."
Q5. In the following sentence some segments of each sentence are underlined. Your task is to identify that underlined segment of the sentence, which contains the mistake that needs to be corrected.The most important and the least difficult thing to achieve is a desire amongst individuals to limit the size of family.
- A. The most
- B. The least✓
- C. Is a desire
- D. Amongst individuals
Explanation: Reading this sentence, we understand it talks about reducing the size of a family. While it is most important, it is also a very difficult idea to propagate 'the least' should be replaced by 'the most' so it fits in with the meaning of the sentence.
Why the other options are wrong
- A. "The most" is perfectly positioned in sentence so it is not the incorrect part of given question.
- C. This portion doesn't contain any mistake so it is incorrect.
- D. There is no mistake in this portion of sentence so it is not correct option.
Q6. In the following sentence some segments of each sentence are underlined. Your task is to identify that underlined segment of the sentence, which contains the mistake that needs to be corrected.There is terror from the outset and there are all the components necessary to create a melodrama -- a dimly lit bus station, the storm accompanied by flashes of lightning and the promise of violent action or emotion.
- A. From the outset
- B. There are all
- C. The storm accompanied✓
- D. The promise of violent
Explanation: The best way of solving this question is to read the entire sentence in your head and decipher which part does not seem right.The sentence says a dimly lit station, hence similarly 'the storm' should be replaced by 'a storm accompanied by flashes of lightning....'
Why the other options are wrong
- A. “From the outset” is correct because it properly indicates the beginning of the action or situation. It fits the context, showing that terror is present right from the start of the scene.
- B. “There are all” is correct here because it introduces all the necessary components of the melodrama. It properly lists the elements that contribute to creating the intended atmosphere. Changing it would make the sentence ungrammatical or incomplete.
- D. “The promise of violent action or emotion” is correct because it completes the list of components contributing to the melodrama. It specifies what kind of tension or threat is present, so it fits grammatically and logically.
Q7. In the following sentence some segments of the sentence are underlined. Your task is to identify that underlined segment of the sentence, which contains the mistake that needs to be corrected.The king feels disturbed and on hearing these words he could not control his tears.
- A. Feels✓
- B. And on
- C. These words
- D. Could not control
Explanation: The sentence is a simple past tense sentence hence use 'felt' instead of 'feels'.
Why the other options are wrong
- B. "And on” is correct because it properly links the king’s emotional reaction to the moment he hears the words. Changing it would disrupt the sequence of events and make the sentence grammatically awkward.
- C. “These words” is correct because it clearly specifies what triggers the king’s reaction. Replacing it would make the sentence vague or change its meaning.
- D. “Could not control” is correct because it properly expresses the king’s inability to restrain his tears. Changing it would alter the meaning or tense of the sentence.
Q8. In the following sentence some segments of the sentence are underlined. Your task is to identify that underlined segment of the sentence, which contains the mistake that needs to be corrected.He had earned the reputation of being a great jester, and jests were expected from him.
- A. Of being
- B. A great jester
- C. Jests
- D. From him✓
Explanation: 'Expected from' can be appropriately used in a situation when one is anticipating to receive something, material or nonmaterial from someone. Example: 'The weekly sales report is expected from you' or 'A negative response was not expected from her after such good news.' 'Expected of' should be used when you believe that someone is capable of living up to a certain characteristic or adopting a typical behaviour. For example, 'This degree of good behaviour is expected of him.' or 'It is expected of the company to appropriately share the corporate and social responsibilities.'
Why the other options are wrong
- A. “Of being” is correct because it properly links “reputation” with the quality he earned. Replacing it would make the sentence grammatically incomplete or unclear.
- B. “A great jester” is correct as it’s the complement describing the reputation he earned; it’s not an error.
- C. “Jests” is correct here because it refers to the expected jokes or humorous acts from him; it fits the meaning and grammar of the sentence.
Q9. In the following sentence some segments of the sentence are underlined. Your task is to identify that underlined segment of the sentence, which contains the mistake that needs to be corrected.He glances back at the door, then turns his attention once more towards the paper and begins going through it casually.
- A. He glances
- B. At the door
- C. Towards the paper✓
- D. Through it casually
- E. No error
Explanation: There should be 'to the paper ' instead of 'towards the paper ' because 'to' is used for focus, for attention, for destination but 'towards' is used only for direction.
Why the other options are wrong
- A. “He glances” is correct. There’s no error; the sentence is grammatically fine as it describes his actions in the present tense narrative style.
- B. “At the door” is correct. There’s no error; it properly shows where he glances.
- D. “Through it casually” is correct. It shows how he goes through the paper, so there’s no error there.
- E. Incorrect because option C is the error in the sentence.
Q10. In the following sentence some segments of the sentence are underlined. Your task is to identify that underlined segment of the sentence, which contains the mistake that needs to be corrected.However, by being so long in lowest format I gained the immense advantage over the cleverer boys.
- A. However
- B. The✓
- C. An immense
- D. Cleverer boys
Explanation: “The” is incorrect here because “immense advantage” is used in a general sense, not referring to a specific advantage already known. It should be “an immense advantage” to indicate one of possibly many advantages, not a unique, definite one.
Why the other options are wrong
- A. “However” is correct. It properly introduces a contrast or exception, so there’s no error in using it here.
- C. “An immense” is correct because “immense” is a singular, countable idea here, so it needs the article “an.”
- D. “Cleverer boys” is correct because it properly compares the boys’ intelligence; no article or change is needed.
Q11. In the following question, four alternative sentences are given. Choose the CORRECT one.
- A. The manager looked on me in some alarm.
- B. The manager looked on me with some alarm.
- C. The manager looked at me with some alarm.✓
- D. The manager looked at me in some alarm.
Explanation: "Look at" means to direct your eyes in a particular direction. 'At' will be the most appropriate preposition to use here.With some alarm, means to look at someone with some caution and uncertainty. The best way to solve this question is to read each option in your head and then decide which one sounds the best and fits in well.
Why the other options are wrong
- A. "Looked on" generally means to observe or watch over a period of time, which doesn't fit the context of a momentary reaction of alarm.
- B. As with option a, "looked on" means to observe or watch over a period of time. This phrase still doesn't fit the context.
- D. While "looked at me" is correct, "in some alarm" is less common and less idiomatic than "with some alarm."
Q12. Select the correct meaning of the given word.ILK
- A. Breed✓
- B. Civilization
- C. Origin
- D. Culture
Explanation: Ilk: a type of person or thing similar to one already referred to. Breed: to be of some the heritage or nature. Hecne option A is the most suitable answer.
Why the other options are wrong
- B. Civilization: a complex human society, usually made up of different cities, with certain characteristics of cultural and technological development.
- C. Origin: the point or place where something begins, arises, or is derived
- D. Culture: the arts and other manifestations of human intellectual achievement regarded collectively.
Q13. Select the correct meaning of the given word.DUNCE
- A. Brainy
- B. Intellectual
- C. Cautious
- D. Oaf✓
Explanation: Dunce: a person who is slow at learning; a stupid person. Oaf: a man who is rough or clumsy and unintelligent. Hence it is the best answer.
Why the other options are wrong
- A. Brainy and Intellectual: Someone who is intelligent.
- B. Brainy and Intellectual: Someone who is intelligent.
- C. Cautious: Someone who is careful about things.
Q14. Select the NEAREST CORRECT MEANING of the given word.HIATUS
- A. Lull✓
- B. Longing
- C. Heretical
- D. Veneration
Explanation: Hiatus: a pause or break in continuity during an activity. Lull: a temporary interval of quiet or lack of activity. Hence it is the best answer.
Why the other options are wrong
- B. Longing: a desire of achieving something.
- C. Heretical: holding an opinion which is different from what is generally accepted.
- D. Veneration: having great respect
Q15. Select the NEAREST CORRECT MEANING of the given word.BUFFERS
- A. Shocks
- B. Shield✓
- C. Support
- D. Window
Explanation: Buffer: a person or thing that reduces a shock or that forms a barrier. Shield: a person or thing providing protection. Hence shield is the best answer.
Why the other options are wrong
- A. Shocks: a sudden upsetting or surprising event or experience
- C. Support: a thing that bears the weight of something or keeps it upright.
- D. Window: a hole through a solid object which can allow you to look inside and outside.
Q16. Select the NEAREST CORRECT MEANING of the given word:ENCUMBER
- A. Clear
- B. Spacious
- C. Convenient
- D. Strained✓
Explanation: Encumber: restrict in such a way that free action or movement is difficult. Strain: to tie up something, limiting movement. Hence it is the correct answer.
Why the other options are wrong
- A. Clear: easy to perceive,understand, or interpret.
- B. Spacious: (especially of a room or building) having ample space.
- C. Convenient: fitting in well with a person's needs, activities, and plans.
Q17. Select the NEAREST CORRECT MEANING of the given word.HECTOR
- A. Harass✓
- B. Helpmate
- C. Hellish
- D. Hefty
Explanation: Hector: talk to (someone) in a bullying way. Harass: make someone a subject to aggressive pressure or intimidation. Hence it is the best answer.
Why the other options are wrong
- B. A helpmate is a companion or a helpful partner, which is unrelated to the meaning of "hector."
- C. Hellish means extremely unpleasant or like hell, which is not the meaning of "hector."
- D. Hefty means large, heavy, or substantial in size, weight, or amount, which is not the meaning of "hector."
Q18. Select the NEAREST CORRECT MEANING of the given word.NEXUS
- A. Focal point✓
- B. Success
- C. Hinterland
- D. Politics
Explanation: Nexus: a central or focal point, and a connection or series of connections linking two or more things.
Why the other options are wrong
- B. Success: the accomplishment of an aim or purpose.
- C. Hinterland: an area lying beyond what is visible or known.
- D. Politics: the activities associated with the governance of a country or area.
Q19. Select the NEAREST CORRECT MEANING of the given word.PERPETUATE
- A. Skulk
- B. Deviate
- C. Eternize✓
- D. Perish
Explanation: Perpetuate: make (something) continue forever. Eternize: cause to live or last forever. Hence it is the best answer.
Why the other options are wrong
- A. To skulk means to move stealthily or to hide in a sneaky manner, which is unrelated to "perpetuate."
- B. To deviate means to depart from an established course or norm, which is the opposite of perpetuating something.
- D. To perish means to die or to cease to exist, which is also opposite in meaning to perpetuate.
Q20. Select the NEAREST CORRECT MEANING of the given word.AUGUST
- A. Local
- B. Old
- C. Venerable✓
- D. Foreign
Explanation: August: respected and impressive.Venerable: held in a great deal of respect, especially because of age, wisdom, or character.
Why the other options are wrong
- A. This refers to something pertaining to a particular place or locality, which is unrelated to the meaning of "August."
- B. While "August" can refer to something old, "venerable" more accurately captures the sense of respect and dignity associated with age or status.
- D. This refers to something or someone from another country or place, which is unrelated to the meaning of "August."
Q21. Select the NEAREST CORRECT MEANING of the given word.LAMPOON
- A. Appreciate
- B. Burlesque✓
- C. Approve
- D. Annoy
Explanation: Lampoon: publicly criticize (someone or something) by using ridicule, irony, or sarcasm. Burlesque: parody or imitate in an absurd or comically exaggerated way.
Why the other options are wrong
- A. To appreciate means to value or recognize the worth or quality of something, which is opposite in meaning to lampoon.
- C. To approve means to agree with or accept something, which is not related to lampooning.
- D. To annoy means to irritate or bother someone, which is not related to the meaning of lampoon.
Q22. The thickest chamber of the human heart is:
- A. Left atrium
- B. Right atrium
- C. Right ventricle
- D. Left ventricle✓
Explanation: The left ventricle of your heart is larger and thicker than the other chambers. This is because it has to pump the blood further around the body, and against a higher pressure. The right ventricle pumps the oxygen-poor blood to the lungs through the pulmonary valve. The right atrium receives oxygen-poor blood from the body and pumps it to the right ventricle through the tricuspid valve, and hence does not need very thick walls. The left atrium receives oxygen-rich blood from the lungs and pumps it to the left ventricle through the mitral valve; hence, it also doesn’t need thick walls.
Why the other options are wrong
- A. The left atrium receives oxygen- rich blood from the lungs and pumps it to the left ventricle through the mitral valve, hence it also doesn't need thick walls.
- B. The right atrium receives oxygen-poor blood from the body and pumps it to the right ventricle through the tricuspid valve and hence doesn't need very thick walls.
- C. The right ventricle pumps the oxygen-poor blood to the lungs through the pulmonary valve.
Q23. The enzymes required for the Kreb cycle are found in _.
- A. F¹ particles
- B. Lysosomes
- C. Cytoplasm
- D. Matrix✓
Explanation: The Krebs cycle enzymes are membrane proteins found within the matrix of the mitochondria, except for succinate dehydrogenase, which is an integral membrane protein locked to the inner mitochondrial membrane.
Why the other options are wrong
- A. F¹ particles are found in the matrix of mitochondria and is found attached to the cristae. It plays a very important role in the production of ATP molecules as it contains an enzyme called ATPase.
- B. A lysosome is a membrane-bound cell organelle that contains digestive enzymes.
- C. The cytoplasm is a thick solution that fills each cell and is enclosed by the cell membrane.
Q24. Coccyx vertebrae are located in:
- A. Cervical region
- B. Lumbar region
- C. Pelvic region✓
- D. Thoracic region
Explanation: The coccyx, also known as the tailbone, is a small, triangular bone resembling a shortened tail located at the bottom of the spine in the pelvic region. It is composed of three to five coccygeal vertebrae or spinal bones. The cervical spine is the most superior portion of the vertebral column, lying between the cranium and the thoracic vertebrae. It consists of seven distinct vertebrae. The thoracic spine is the longest region of the spine, and by some measures it is also the most complex. Connecting with the cervical spine above and the lumbar spine below, the thoracic spine runs from the base of the neck down to the abdomen. The thoracic spine has 12 vertebrae stacked on top of each other, labeled from T1 down to T12. The lumbar spine (lower back) consists of five vertebrae in the lower part of the spine, between the ribs and the pelvis. The five lumbar vertebrae are numbered L1 to L5
Why the other options are wrong
- A. The cervical spine is the most superior portion of the vertebral column, lying between the cranium and the thoracic vertebrae. It consists of seven distinct vertebrae.
- B. The lumbar spine (lower back) consists of five vertebrae in the lower part of the spine, between the ribs and the pelvis. The five lumbar vertebrae are numbered L1 to L5.
- D. The thoracic spine is the longest region of the spine, and by some measures it is also the most complex. Connecting with the cervical spine above and the lumbar spine below, the thoracic spine runs from the base of the neck down to the abdomen. The thoracic spine has 12 vertebrae stacked on top of each other, labelled from T1 down to T12.
Q25. Cell-mediated immune response is given by:
- A. T-lymphocytes✓
- B. B lymphocytes
- C. Neutrophils
- D. Macrophages
Explanation: Cell-mediated immunity is an immune response that does not involve antibodies. Rather, cell-mediated immunity is the activation of phagocytes, antigen-specific cytotoxic T-lymphocytes, and the release of various cytokines in response to an antigen. Humoral immunity is also called antibody-mediated immunity. With assistance from helper T cells, B cells will differentiate into plasma B cells that can produce antibodies against a specific antigen. The humoral immune system deals with antigens from pathogens that are freely circulating, or outside the infected cells. Antibodies produced by the B cells will bind to antigens, neutralizing them, or causing lysis (dissolution or destruction of cells by a lysin) or phagocytosis.
Why the other options are wrong
- B. B lymphocytes, or B cells, are a type of white blood cell involved in the immune system. They play a crucial role in the adaptive immune response by producing antibodies, which recognize and neutralize pathogens like bacteria and viruses.
- C. Neutrophils are a type of white blood cell that forms a significant part of the body's immune system. They are essential for fighting bacterial infections and are often the first responders to sites of infection or inflammation.
- D. Macrophages are a type of white blood cell that functions as a part of the immune system. They play a key role in engulfing and digesting cellular debris, foreign substances, and pathogens. Macrophages also contribute to the regulation of immune responses and tissue repair.
Q26. Crossing over takes place during _ of meiosis.
- A. Prophase I✓
- B. Telophase I
- C. Metaphase I
- D. Anaphase I
Explanation: Meiosis consists of two divisions, both of which follow the same stages as mitosis (prophase, metaphase, anaphase, telophase). Meiosis is preceded by interphase, in which DNA is replicated to produce chromosomes consisting of two sister chromatids. A second growth phase called interkinesis may occur between meiosis I and II, however no DNA replication occurs in this stage:Prophase I: Chromosomes condense, nuclear membrane dissolves, homologous chromosomes form bivalents, crossing over occurs.Crossing over occurs in Prophase I when homologous chromosomes pair up, forming a tetrad, and then non-sister chromatids exchange genetic material at points called chiasmata. This genetic exchange, known as recombination, shuffles alleles and creates new combinations of genes on the chromosomes. The process involves enzymes breaking DNA at similar locations on each chromosome and then reattaching the broken ends in a criss-cross pattern, resulting in genetically unique gametes. Metaphase I: Spindle fibres from opposing centrosomes connect to bivalents (at centromeres) and align them along the middle of the cell.Anaphase I: Spindle fibres contract and split the bivalent, homologous chromosomes move to opposite poles of the cell.Telophase I: Chromosomes decondense, nuclear membrane may reform, cell divides (cytokinesis) to form two haploid daughter cells.
Why the other options are wrong
- B. In Telophase I, chromosomes decondense, nuclear membrane may reform, cell divides (cytokinesis) to form two haploid daughter cells.
- C. In Metaphase I, spindle fibres from opposing centrosomes connect to bivalents (at centromeres) and align them along the middle of the cell.
- D. In Anaphase I, spindle fibres contract and split the bivalent, homologous chromosomes move to opposite poles of the cell.
Q27. During breathing, air from pharynx enters to:
- A. Trachea✓
- B. Bronchioles
- C. Alveoli
- D. Bronchi
Explanation: When you inhale through your nose or mouth, air travels down your pharynx (back of your throat), passes through your larynx (voice box) and into your trachea (windpipe). Your trachea is divided into two air passages called bronchial tubes. One bronchial tube leads to your left lung, the other to your right lung.
Why the other options are wrong
- B. Bronchioles are small, narrow air passages in the respiratory system that branch off from the bronchi, which are larger airways in the lungs. The bronchioles are part of the conducting zone of the respiratory system, meaning they function to conduct air to and from the gas exchange surfaces in the lungs.
- C. Alveoli are tiny, grape-like air sacs located at the end of the bronchioles in the lungs. These structures are the primary sites for the exchange of oxygen and carbon dioxide between the air and the bloodstream. The alveoli are essential for the respiratory system's main function: breathing and gas exchange.
- D. The bronchi are the two main branches of the trachea (windpipe) that lead into the lungs. These air passages play a crucial role in the respiratory system, facilitating the flow of air to and from the lungs during the process of breathing.
Q28. Gradual breakdown of the alveolar wall leads to which type of disease in a smoker?
- A. Coronary heart disease
- B. Bronchitis
- C. Emphysema✓
- D. Asthma
Explanation: In emphysema, the inner walls of the lungs' air sacs (alveoli) are damaged, causing them to eventually rupture. This creates one larger air space instead of many small ones and reduces the surface area available for gas exchange. Emphysema is a lung condition that causes shortness of breath.Asthma is a condition in which your airways narrow and swell and may produce extra mucus. This can make breathing difficult and trigger coughing, a whistling sound (wheezing) when you breathe out and shortness of breath.Bronchitis is an infection of the main airways of the lungs (bronchi), causing them to become irritated and inflamed. The main symptom is a cough, which may bring up yellow-grey mucus (phlegm)Coronary heart disease (CHD), or coronary artery disease, develops when the coronary arteries become too narrow. The coronary arteries are the blood vessels that supply oxygen and blood to the heart.CHD tends to develop when cholesterol builds up on the artery walls, creating plaques. These plaques cause the arteries to narrow, reducing blood flow to the heart. A clot can sometimes obstruct the blood flow, causing serious health problems.
Why the other options are wrong
- A. Coronary heart disease (CHD), or coronary artery disease, develops when the coronary arteries become too narrow. The coronary arteries are the blood vessels that supply oxygen and blood to the heart.CHD tends to develop when cholesterol builds up on the artery walls, creating plaques. These plaques cause the arteries to narrow, reducing blood flow to the heart. A clot can sometimes obstruct the blood flow, causing serious health problems.
- B. Bronchitis is an infection of the main airways of the lungs (bronchi), causing them to become irritated and inflamed. The main symptom is a cough, which may bring up yellow-grey mucus (phlegm).
- D. Asthma is a condition in which your airways narrow and swell and may produce extra mucus. This can make breathing difficult and trigger coughing, a whistling sound (wheezing) when you breathe out and shortness of breath
Q29. Which of the following holds the alpha helix of protein in its place:
- A. R group
- B. Disulfide bond
- C. Amino group
- D. Hydrogen bond✓
Explanation: The α-helix is a right-handed helix with the peptide bonds present on the inside and the side chains extending outward. It is stabilized by the regular formation of hydrogen bonds parallel to the axis of the helix; they are formed between the amino and carbonyl groups of every fourth peptide bond.
Why the other options are wrong
- A. The R group (or side chain) is part of the amino acids in a protein, but it does not hold the alpha helix in place. The R group can interact with other side chains or the environment, but it is not responsible for the helical structure.
- B. isulfide bonds are covalent bonds between the sulfur atoms of cysteine residues and help stabilize the overall three-dimensional structure of proteins. They are important for tertiary structure but not specifically for maintaining the alpha helix.
- C. The amino group is part of the amino acid and contributes to the peptide bond formation between amino acids, but it doesn't play a direct role in stabilizing the alpha helix structure.
Q30. If the molecule can bind to another site of the enzyme rather than the true active site, it is referred to as:
- A. Competitive inhibitors
- B. Allosteric inhibition
- C. Non-competitive inhibitors✓
- D. Irreversible inhibition
Explanation: Non-competitive inhibitors are molecules that bind to an enzyme at a location other than the active site, leading to a conformational change in the enzyme's structure. This conformational change makes the active site less effective at catalyzing the reaction, even though the inhibitor does not directly compete with the substrate for binding to the active site.
Why the other options are wrong
- A. A competitive inhibitor is any molecule that can bind to the active site of an enzyme with sufficient affinity such that it can compete with the enzyme's natural substrate and reduce enzyme activity as a result.
- B. When an inhibitor binds to the enzyme, all the active sites of the protein complex of the enzyme undergo conformational changes so that the activity of the enzyme decreases. In other words, an allosteric inhibitor is a type of molecule which binds to the enzyme specifically at an allosteric site.
- D. An irreversible inhibitor inactivates an enzyme by bonding covalently to a particular group at the active site. It permanently blocks the action of enzymes.
Q31. _ is the site of light-independent reaction.
- A. Thylakoid membrane
- B. Thylakoid space
- C. Stroma✓
- D. Grana
Explanation: The light-dependent reactions take place on the thylakoid membranes. The inside of the thylakoid membrane is called the lumen, and outside the thylakoid membrane is the stroma, where the light-independent reactions take place. Thylakoids are arranged in stacks called grana.The chloroplast matrix is called the stroma and contains enzymes that catalyse the light-independent reactions of photosynthesis. But stroma is not the site for light reactions. Stromal lamellae connect two or more grana to each other. In this way, the lamellae act as a skeleton of the chloroplast, maintaining efficient distances between the grana, thereby maximising the overall efficiency of the chloroplast. Dark reaction does not depend directly on the presence of light but is dependent on the products of light reaction i.e., ATP and NADPH. The dark reaction occurs through the Calvin cycle.
Why the other options are wrong
- A. It is incorrect.Thylakoid membrane: This is where the light-dependent reactions of photosynthesis take place.
- B. It is incorrect. Thylakoid space: This is the space inside the thylakoid, involved in generating the proton gradient for ATP synthesis during the light-dependent reactions.
- D. It is incorrect. Grana: Grana are stacks of thylakoids; they are the sites for the light-dependent reactions.
Q32. When a nerve impulse jumps from one node of Ranvier to the next in a myelinated neuron, it's called _.
- A. Synapses
- B. Saltatory conduction✓
- C. Resting potential
- D. Membrane potential
Explanation: Saltatory conduction is the propagation of action potentials along myelinated axons from one node of Ranvier to the next node, increasing the conduction velocity of action potentials. Saltatory conduction is the rapid "leap" of action potentials along a myelinated axon, moving quickly between gaps in the myelin sheath known as nodes of Ranvier. This process is significantly faster and more energy-efficient than conduction in unmyelinated axons because action potentials only need to be regenerated at these nodes, rather than along the entire length of the axon. The myelin sheath, a fatty insulating layer produced by Schwann cells and oligodendrocytes, prevents ion movement in the internodal regions, allowing the electrical signal to "jump" from node to node.
Why the other options are wrong
- A. In the central nervous system, a synapse is a small gap at the end of a neuron that allows a signal to pass from one neuron to the next.
- C. Resting potential is the imbalance of electrical charge that exists between the interior of electrically excitable neurons (nerve cells) and their surroundings.
- D. Membrane potential (also transmembrane potential or membrane voltage) is the difference in electric potential between the interior and the exterior of a biological cell.
Q33. The term “Loss of appetite” refers to disease:
- A. Botulism
- B. Anorexia nervosa✓
- C. Obesity
- D. Bulemia nervosa
Explanation: Anorexia nervosa is an eating disorder characterized by an abnormally low body weight, an intense fear of gaining weight and a distorted perception of weight.
Why the other options are wrong
- A. Botulism is a rare and potentially fatal illness caused by a toxin produced by the bacterium Clostridium botulinum.
- C. Obesity is a complex disease involving an excessive amount of body fat.
- D. Bulimia nervosa, commonly called bulimia, is an eating disorder characterised by an obsession for binge(consuming unusually large amounts of food and feel unable to stop eating) eating.
Q34. They serve as a scaffold for formation of higher order chromatin structure:
- A. Nucleosome✓
- B. Nucleus
- C. Chromosomes
- D. Histones
Explanation: Nucleosomes are the basic units of DNA packaging and serve as a scaffold for the formation of higher-order chromatin structures. They consist of DNA wrapped around histone proteins, allowing the DNA to be compacted efficiently within the nucleus. While histones are essential for nucleosome formation, they do not act as a scaffold themselves. The nucleus is the organelle that contains the DNA but does not directly influence the chromatin structure. Chromosomes are the end result of further condensation of chromatin, representing a more complex level of organization, but they do not serve as the starting scaffold for chromatin formation.
Why the other options are wrong
- B. The nucleus is the cellular organelle that contains the cell's genetic material, but it is not the structure that acts as a scaffold for chromatin formation. Instead, it is the site of DNA replication and transcription.
- C. Chromosomes are the highly organized structures formed from DNA and proteins during cell division. They represent a higher order of DNA packaging but do not serve as the initial scaffold for chromatin formation.
- D. Histones are the proteins around which DNA is wrapped to form nucleosomes. While they play a crucial role in the structure of chromatin, they do not serve as a scaffold in the same sense as nucleosomes.
Q35. Salivary Amylase begins to digest Starch to shorter polysaccharides and then to:
- A. Glucose
- B. Maltose✓
- C. Sucrose
- D. Lactose
Explanation: Salivary amylase breaks down starch into maltose, a disaccharide made of two glucose units.
Why the other options are wrong
- A. Salivary amylase breaks starch only into shorter polysaccharides and disaccharides (like maltose) — not glucose — because it cannot break all types of glycosidic bonds in starch.
- C. Sucrase is a digestive enzyme that catalyzes the hydrolysis of sucrose (table sugar) into its component monosaccharides, glucose and fructose.
- D. Lactase is an enzyme that breaks down lactose, the sugar in milk, into simpler sugars (glucose and galactose) that the body can absorb.
Q36. The chemical nature of primers used in the PCR process is _.
- A. RNA
- B. Protein
- C. Carbohydrate
- D. DNA✓
Explanation: Primers are small, chemically synthesised oligonucleotides that are complementary to the sequences, present at 3' end of the template DNA. They hybridise to the target DNA region, one to each strand of the double helix. These primers are oriented with their ends facing each other allowing synthesis of the DNA towards one another. Thus, the primer is a short, single-stranded DNA sequence which hybridises with the template DNA and defines the region of the DNA that needs to be amplified.
Why the other options are wrong
- A. RNA is not typically used as primers in PCR. PCR relies on the specificity and stability of DNA-DNA base pairing, and RNA is less stable and less commonly used for this purpose.
- B. Proteins are not used as primers in PCR. Primers need to be nucleic acids to participate in the DNA replication process, and proteins do not have the complementary base-pairing ability required for this function.
- C. Carbohydrates are not used as primers in PCR. Similar to proteins, carbohydrates lack the nucleotide sequences and base-pairing ability necessary for DNA replication in the PCR process.
Q37. In viruses, a combined structure formed by the core (nucleic acid) and the capsid is:
- A. Nucleocapsid✓
- B. Prion
- C. Envelope
- D. Capsomeres
Explanation: The capsid and nucleic acid together are known as the nucleocapsid.A prion is a type of protein that can trigger normal proteins in the brain to fold abnormally. Prion diseases can affect both humans and animals.A viral envelope is the outermost layer of many types of viruses. It protects the genetic material in its life cycle when travelling between host cells.The capsomere is a subunit of the capsid, an outer covering of protein that protects the genetic material of a virus.
Why the other options are wrong
- B. A prion is a type of protein that can trigger normal proteins in the brain to fold abnormally. Prion diseases can affect both humans and animals.
- C. A viral envelope is the outermost layer of many types of viruses. It protects the genetic material in their life cycle when travelling between host cells.
- D. The capsomere is a subunit of the capsid, an outer covering of protein that protects the genetic material of a virus.
Q38. Skull, vertebral column, ribs, and sternum form:
- A. Appendicular skeleton
- B. Hydrostatic skeleton
- C. Exoskeleton
- D. Axial skeleton✓
Explanation: The axial skeleton forms a vertical axis that includes the head, neck, back, and chest. It has 80 bones and consists of the skull, vertebral column, and thoracic cage. The appendicular skeleton is the portion of the skeleton of vertebrates consisting of the bones that support the appendages. There are 126 bones. The appendicular skeleton includes the skeletal elements within the limbs, as well as the supporting shoulder girdle, pectoral, and pelvic girdle. A hydrostatic skeleton is a skeleton formed by a fluid-filled compartment within the body, called the coelom. An exoskeleton is an external skeleton that supports and protects an animal's body.
Why the other options are wrong
- A. The appendicular skeleton is the portion of the skeleton of vertebrates consisting of the bones that support the appendages. There are 126 bones. The appendicular skeleton includes the skeletal elements within the limbs, as well as the supporting shoulder girdle, pectoral, and pelvic girdle.
- B. A hydrostatic skeleton is a skeleton formed by a fluid-filled compartment within the body, called the coelom.
- C. An exoskeleton is an external skeleton that supports and protects an animal's body.
Q39. Synthesis of microtubules increases in:
- A. M phase
- B. S phase
- C. G1 phase
- D. G2 phase✓
Explanation: Following the G1 is the S-phase (synthesis phase) during which the DNA is synthesised and (chromosome are replicated) which initiates G2 phase (pre- mitotic phase), thus preparing the cell for division e.g., energy storage for chromosome movements, mitosis specific proteins, RNA and microtubule subunits (for spindle fibres) synthesise.G2 phase is the second growth phase. It occurs after the synthesis phase in a typical cell cycle. In the G2 phase synthesis of tubulin protein which is the major component of microtubules takes place. The spindle fibres are made of microtubules.
Why the other options are wrong
- A. It is mitotic phase and is not related to synthesis of microtubules.
- B. It is related to DNA synthesis and chromosome replication.
- C. G1 (Gap 1) is the period of extensive metabolic activity, in which cell normally grows in size, speciic enzymes, are synthesized and DNA base units are accumulated for the DNA synthesis.
Q40. The region of the chromosome or, more specifically, the length of the DNA molecule, which has a particular function is called _.
- A. Kinetochore
- B. Locus
- C. Allele
- D. Gene✓
Explanation: The gene is the basic physical and functional unit of heredity. It consists of a specific sequence of nucleotides at a given position on a given chromosome that codes for a specific protein.In genetics, a locus is a specific, fixed position on a chromosome where a particular gene or genetic marker is located.
Why the other options are wrong
- A. A kinetochore is a disc-shaped protein structure associated with duplicated chromatids in eukaryotic cells where the spindle fibres attach during cell division to pull sister chromatids apart.
- B. In genetics, a locus is a specific, fixed position on a chromosome where a particular gene or genetic marker is located. Option C: An allele is one of two, or more, forms of a given gene variant.
- C. It is incorrect.The gene is the basic physical and functional unit of heredity. It consists of a specific sequence of nucleotides at a given position on a given chromosome that codes for a specific protein
Q41. Urea cycle helps in the the detoxification of:
- A. Creatine
- B. Amino acids
- C. Carbon dioxide
- D. Ammonia✓
Explanation: The urea cycle is a metabolic pathway that converts toxic ammonia (NH₃), produced from the breakdown of amino acids, into urea, which is less harmful and excreted in urine. Thus, the cycle primarily detoxifies ammonia.
Why the other options are wrong
- A. Creatine is a nitrogenous organic compound that plays a role in energy metabolism, particularly in the muscles. It is not directly involved in the detoxification of ammonia or any other waste products
- B. While the breakdown of amino acids can produce ammonia as a byproduct, the primary purpose of the urea cycle is to specifically detoxify and eliminate ammonia from the body.
- C. It is incorrect in the context of the urea cycle and detoxification. Carbon dioxide is not directly detoxified by the urea cycle.
Q42. Chitin, which makes the exoskeleton in insects, is further hardened by:
- A. Protein and Sodium Bicarbonate
- B. Protein and Calcium Carbonate✓
- C. Protein and Potassium Carbonate
- D. Protein and Sodium Carbonate
Explanation: Chitin is translucent and tough in its pure form, but it also combines with other materials to form a strong outer structure. For example, in arthropods, it combines with proteins, while in crustaceans, it combines with calcium carbonate. This material makes the exoskeleton and shells hard, tough, and stiff.
Why the other options are wrong
- A. Chitin is translucent and tough in its pure form, but it also combines with other materials to form a strong outer structure. For example, in arthropods, it combines with proteins, while in crustaceans, it combines with calcium carbonate. This material makes the exoskeleton and shells hard, tough, and stiff.
- C. Chitin is translucent and tough in its pure form, but it also combines with other materials to form a strong outer structure. For example, in arthropods, it combines with proteins, while in crustaceans, it combines with calcium carbonate. This material makes the exoskeleton and shells hard, tough, and stiff.
- D. Chitin is translucent and tough in its pure form, but it also combines with other materials to form a strong outer structure. For example, in arthropods, it combines with proteins, while in crustaceans, it combines with calcium carbonate. This material makes the exoskeleton and shells hard, tough, and stiff.
Q43. The number of salivary glands found in the human oral cavity.
- A. 4
- B. 3
- C. 6✓
- D. 2
Explanation: Human salivary glands are divided into two main types: major salivary glands (parotid, submandibular, and sublingual) and numerous minor salivary glands located throughout the mouth. The three pairs of major glands produce about 90% of saliva, while the minor glands provide a smaller volume but are important for lubrication and protection.
Why the other options are wrong
- A. Incorrect option. Humans have three paired major salivary glands (parotid, submandibular, and sublingual), which are 6 in total.
- B. Incorrect option. Humans have three paired major salivary glands (parotid, submandibular, and sublingual), which are 6 in total.
- D. Incorrect option. Humans have three paired major salivary glands (parotid, submandibular, and sublingual), which are 6 in total.
Q44. Following group is the example of acoelomates:
- A. Annelids
- B. Aschelminthes
- C. Molluscs
- D. Platyhelminthes✓
Explanation: Acoelomates do not possess a body cavity or coelom i.e the fluid-filled cavity between the digestive tract and the body wall that also surrounds the other internal organs is absent. Platyhelminthes and sponges are classic examples of acoelomates. In some animals, the embryonic blastocoel acts as a fluid-filled cavity. This body cavity is partially lined with the mesodermal derivative cells. Here, the coelom is much reduced or lost. It is not considered a true coelom, and hence the name pseudocoelomates. Examples include nematodes (roundworms). Animals that have their body cavities filled with fluid are called coelomates. Their internal organs are suspended in the fluid cavity. Examples include arthropods, annelids, molluscs, hemichordates, echinoderms and chordates.
Why the other options are wrong
- A. Annelids, such as earthworms and leeches, are true coelomates (eucoelomates). They possess a well-developed coelom, a fluid-filled cavity completely lined by mesoderm. This cavity allows the free movement and growth of internal organs. Therefore, annelids are not acoelomates, making this option incorrect.
- B. Aschelminthes (or Nematoda) are pseudocoelomates, meaning they have a body cavity called a pseudocoel, which is not completely lined by mesoderm. This cavity serves as a hydrostatic skeleton. Since they do have a body cavity (though false), they are not acoelomates, so this option is incorrect.
- C. Molluscs, including snails, clams, and octopuses, are true coelomates. They have a well-developed coelomic cavity that allows complex organ systems to function efficiently. Thus, they cannot be classified as acoelomates. This option is incorrect.
Q45. Glycosidic bond is formed by the:
- A. Removal of Oxygen
- B. Addition of Oxygen
- C. Removal of water✓
- D. Addition of water
Explanation: Glycosidic bond is a condensation reaction between two sugar units, where the H- group from one sugar interacts with the -OH group on another to release water and link the sugar units together to form a polysaccharide.
Why the other options are wrong
- A. This is incorrect. Glycosidic bonds are not formed by the removal of oxygen, but by a dehydration reaction involving the removal of water.
- B. This is incorrect. Glycosidic bonds do not involve the addition of oxygen; they are formed through the removal of water between two monosaccharides.
- D. This is incorrect. The addition of water would break the glycosidic bond (hydrolysis), not form it.
Q46. Which of the following statements is correct about the respiratory pigments?
- A. Myoglobin and Haemoglobin has higher affinity for nitrogen
- B. Cyanide and Haemoglobin has a low affinity for oxygen
- C. Myoglobin has more affinity for oxygen as compared to haemoglobin✓
- D. Albumin, Globulin and Globin proteins are present in respiratory pigments
Explanation: Myoglobin's affinity for oxygen is higher than haemoglobin's. And unlike haemoglobin, which is found in the red blood cells, myoglobin is found in muscle tissues. Thus, haemoglobin's lower affinity for oxygen serves it well because it allows haemoglobin to release oxygen more easily in the cells. Myoglobin, on the other hand, has a significantly higher affinity for oxygen and will therefore be much less inclined to release it once it is bound.
Why the other options are wrong
- A. Both myoglobin and hemoglobin have a higher affinity for oxygen than for nitrogen. Myoglobin and hemoglobin are proteins that play crucial roles in the transport and storage of oxygen in the body. Hence, this option is incorrect.
- B. Cyanide is a highly toxic compound that can interfere with cellular respiration, leading to a rapid and severe lack of oxygen in the body. It acts by inhibiting cytochrome c oxidase, a critical enzyme in the electron transport chain of cellular respiration. This disruption prevents cells from utilizing oxygen, despite its availability in the bloodstream. However, the interaction of cyanide with hemoglobin is indirect. Cyanide primarily affects the cells at the mitochondrial level rather than directly interacting with hemoglobin. Hemoglobin's function is to bind and transport oxygen, and under normal conditions, it does not have low affinity for oxygen.
- D. Respiratory pigments are proteins that play a crucial role in transporting gases, such as oxygen and carbon dioxide, in the blood. However, the proteins albumin, globulin, and globin are not typically considered respiratory pigments. Hence, this option is incorrect.
Q47. Conversion of ammonium into nitrates is:
- A. Nitrification✓
- B. Nitrogen Fixation
- C. Ammonification
- D. Denitrification
Explanation: The correct answer is Nitrification, as it specifically refers to the conversion of ammonium into nitrates by bacteria such as Nitrosomonas and Nitrobacter. Nitrogen Fixation is unrelated because it involves converting atmospheric nitrogen into ammonia. Ammonification involves the breakdown of organic matter into ammonium, not its conversion into nitrates. Denitrification involves the reduction of nitrates into nitrogen gas, not the conversion of ammonium to nitrates.
Why the other options are wrong
- B. Nitrogen fixation is the process by which atmospheric nitrogen (N2) is converted into ammonia (NH3), primarily by bacteria found in the roots of legumes or through industrial processes.
- C. Ammonification is the conversion of organic nitrogen from dead plants and animals back into ammonium (NH4+), which can then be used by plants or further processed in the nitrogen cycle.
- D. Denitrification is the process where nitrates (NO3-) are reduced back to nitrogen gas (N2) or nitrous oxide (N2O), typically in anaerobic conditions, effectively removing nitrogen from the soil.
Q48. An area previously supporting life is made barren, the subsequent recolonization is called _.
- A. Climax community
- B. Pioneer succession
- C. Primary succession
- D. Secondary succession✓
Explanation: Secondary succession occurs when the primary ecosystem is destroyed. For example, a climax community gets destroyed by fire. It gets recolonised after the destruction. A climax community is the final stage of succession, remaining relatively unchanged until destroyed by an event such as fire or human interference. Primary succession is an ecological succession that begins in essentially lifeless areas, such as regions in which there is no soil or where the soil is incapable of sustaining life. The pioneer species are hardy species that are the first to colonise barren environments or previously biodiverse steady-state ecosystems that have been disrupted, such as by fire. Therefore, the correct answer is secondary succession.
Why the other options are wrong
- A. A climax community is the final stage of succession, remaining relatively unchanged until destroyed by an event such as fire or human interference.
- B. Pioneer succession: The first organisms appearing in the regions of primary succession are pioneer species (usually lichens or mosses). They are the first species present. They must be strong and hardy. The development of a new community is a succession.
- C. Primary succession is an ecological succession that begins in essentially lifeless areas, such as regions in which there is no soil or where the soil is incapable of sustaining life.
Q49. In human female, the egg is fertilized in:
- A. Ovary
- B. Vagina
- C. Oviduct✓
- D. Uterus
Explanation: In human females, fertilization typically occurs in the fallopian tubes, also known as the oviducts. The process begins with the release of an egg (ovum) from one of the ovaries during ovulation. The released egg then travels through the fallopian tube. If sexual intercourse has taken place and sperm are present in the female reproductive tract, fertilization can occur in the fallopian tube.
Why the other options are wrong
- A. The ovary is where the egg (ovum) is produced and released during ovulation.However, fertilization does not occur in the ovary.After release, the egg is captured by the fimbriae of the oviduct and then travels toward the uterus.
- B. The vagina is the site where sperm is deposited during intercourse.It only serves as a passageway for sperm to enter the female reproductive tract.Fertilization does not take place here.
- D. The uterus is where the fertilized egg (zygote) gets implanted and develops into an embryo.Fertilization itself occurs before the egg reaches the uterus.
Q50. Which hormone is released in females in response to FSH from the pituitary gland?
- A. Estrogen✓
- B. ADH
- C. Oxytocin
- D. Progesterone
Explanation: Follicle-stimulating hormone (FSH) from the pituitary gland stimulates the ovaries in females. In response to FSH, the ovaries produce estrogen. Estrogen is a group of hormones that includes estradiol, estrone, and estriol. These hormones play crucial roles in the development and maturation of the ovarian follicles (structures that contain the developing eggs) and in regulating the menstrual cycle.
Why the other options are wrong
- B. ADH is produced by the hypothalamus and released by the posterior pituitary gland.Its function is to regulate water balance in the body by acting on the kidneys.It has no role in female reproductive hormone regulation.
- C. Oxytocin is released from the posterior pituitary gland.It plays a role in childbirth (causing uterine contractions) and milk ejection during lactation.It is not released in response to FSH.
- D. Progesterone is secreted by the corpus luteum after ovulation (under the influence of LH, not FSH).It helps maintain the uterine lining for possible pregnancy.So it is not produced in response to FSH.
Q51. In a cross section, each centriole consists of nine triplets of:
- A. Microfilaments
- B. Microvilli
- C. Microtubules✓
- D. Intermediate filaments
Explanation: In a cross section, each centriole appears as a ring of nine triplets of microtubules. The microtubules in the triplets are arranged in a clockwise or counterclockwise direction. The triplets are connected to each other by proteins, and they form a rigid structure that is essential for the function of the centriole.
Why the other options are wrong
- A. Microfilaments are the thinnest of the three types of cytoskeleton fibers. They are made up of actin filaments, and they are involved in a variety of cellular processes, including cell motility, cell division, and the formation of cell junctions.
- B. Microvilli are short, finger-like projections that are found on the surface of some cells. They are made up of actin filaments, and they are covered in a layer of membrane. Microvilli increase the surface area of cells, which allows them to absorb more nutrients and other molecules from the environment.
- D. Intermediate filaments are long, thin fibers that are found in the cytoplasm of cells. They are made up of a variety of different proteins, and they are arranged in bundles. Intermediate filaments provide strength and support to cells, and they also help to anchor organelles in place.
Q52. In immunoglobulins/antibodies, two light chains and two heavy chains are linked to each other by:
- A. Covalent bonds
- B. Hydrogen bonds
- C. Ionic bonds
- D. Disulphide bonds✓
Explanation: Each antibody is made up of two short light (L) peptide chains and two long heavy (H) peptide chains (H2L2) joined to each other by disulfide bonds. Disulfide bonds are covalent linkages between the sulphur-containing side chains of cysteine amino acids. The peptide chains are arranged in a Y-shaped structure. Each chain in the antibody has both constant and variable regions. The amino acid sequence and conformation of the variable region keep changing from one type of antibody to another. The conformation and amino acid sequence of the constant region remain the same. The unique antigen-binding site in each antibody that is compatible with specific antigens is composed of the variable regions of both the heavy and the light chains.
Why the other options are wrong
- A. This is incorrect. Covalent bonds: While strong, covalent bonds are not the primary linkage between light and heavy chains in immunoglobulins.
- B. This is incorrect. Hydrogen bonds: These are weaker bonds and contribute to the overall structure, but are not the main force linking the chains.
- C. This is incorrect. Ionic bonds: These bonds can play a role in protein structure, but disulfide bonds are the key link between the light and heavy chains.
Q53. In the nervous system chemical messengers are called _.
- A. Neurotransmitters✓
- B. Hormones
- C. Chemoreceptors
- D. Enzymes
Explanation: Neurotransmitters are often referred to as the body's chemical messengers. They are the molecules used by the nervous system to transmit messages between neurons, or from neurons to muscles.
Why the other options are wrong
- B. Hormones are your body's chemical messengers. They travel in your bloodstream to tissues or organs. They work slowly, over time, and affect many different processes, including Growth and development.
- C. Chemoreceptors are special nerve cells that detect changes in the chemical composition of the blood and send information to the brain to regulate cardiovascular and respiratory functions. There are two major types, which are peripheral and central chemoreceptors.
- D. Enzymes are proteins that help speed up chemical reactions in our bodies, i.e, biological catalysts.
Q54. The first part of the large intestine is:
- A. Colon
- B. Appendix
- C. Caecum✓
- D. Rectum
Explanation: The large intestine begins with the caecum, a pouch-like structure that connects with the ileum of the small intestine. The appendix is a small finger-like extension of the caecum, the colon is the longest part of the large intestine, and the rectum is the last part leading to the anus.
Why the other options are wrong
- A. The colon is right next to the cecum in the large intestine, which is the first part of the large intestine.
- B. The appendix is a small finger-like projection arising from the blind end of the caecum.
- D. The rectum is the last part of the large intestine, which stores the feces temporarily.
Q55. Scapula is a:
- A. Tail bone
- B. Hip bone
- C. Skull bone
- D. Shoulder bone✓
Explanation: The scapula or shoulder blade is the bone that connects the clavicle to the humerus. The scapula forms the posterior of the shoulder girdle. It is a sturdy, flat, triangular bone. The scapula provides attachment to several groups of muscles.
Why the other options are wrong
- A. The tailbone, scientifically known as the coccyx, is a small, triangular bone at the base of the spine. It consists of three to five fused vertebrae and is situated just above the cleft of the buttocks. The coccyx serves as an attachment point for various muscles, ligaments, and tendons. While it doesn't have a major role in weight-bearing or movement, it plays a part in supporting the pelvic floor and provides attachment points for muscles involved in posture and movement of the lower back and pelvis.
- B. The hip bone is a large, flat bone forming part of the pelvis. It consists of three fused bones: the ilium, ischium, and pubis. Together, they create the socket for the hip joint and contribute to the structure of the pelvis, providing support for the body and attachment points for muscles.
- C. The skull is the bony structure that encloses and protects the brain. It consists of two main parts: the cranium, which houses the brain, and the mandible (lower jaw), which is involved in chewing and speech. The skull also protects and supports sensory organs, such as the eyes and ears.
Q56. A complete turn of the double helix of DNA comprises of:
- A. 34 nanometer
- B. 3.4 Angstrom
- C. 3.4 nanometer✓
- D. 34 micrometers
Explanation: At a distance of 3.4nm, the double helix DNA produces one full turn. Each full turn of DNA consists of 10 base pairs. Pitch is the term for the distance covered by a DNA molecule in one full turn.
Why the other options are wrong
- A. At a distance of 3.4nm, the double helix DNA produces one full turn. Each full turn of DNA consists of 10 base pairs. Pitch is the term for the distance covered by a DNA molecule in one full turn.
- B. At a distance of 3.4nm, the double helix DNA produces one full turn. Each full turn of DNA consists of 10 base pairs. Pitch is the term for the distance covered by a DNA molecule in one full turn.
- D. At a distance of 3.4nm, the double helix DNA produces one full turn. Each full turn of DNA consists of 10 base pairs. Pitch is the term for the distance covered by a DNA molecule in one full turn.
Q57. The enzymes required in Glycolysis are present in:
- A. Golgi Apparatus
- B. Cell cytoplasm✓
- C. Inner Mitochondrial Membrane
- D. Matrix of Mitochondria
Explanation: Glycolysis is the process where glucose breaks partially to form pyruvic acid. Further the pyruvic acid enters as a substrate to continue the respiratory pathway. It takes place in the cytoplasm.It does not depend upon the availability of the oxygen.
Why the other options are wrong
- A. It is incorrect as glycolysis is the process where glucose breaks partially to form pyruvic acid. Further the pyruvic acid enters as a substrate to continue the respiratory pathway. It takes place in the cytoplasm.It does not depend upon the availability of the oxygen.
- C. It is incorrect as glycolysis is the process where glucose breaks partially to form pyruvic acid. Further the pyruvic acid enters as a substrate to continue the respiratory pathway. It takes place in the cytoplasm.It does not depend upon the availability of the oxygen.
- D. It is incorrect as glycolysis is the process where glucose breaks partially to form pyruvic acid. Further the pyruvic acid enters as a substrate to continue the respiratory pathway. It takes place in the cytoplasm.It does not depend upon the availability of the oxygen.
Q58. Which lipid is hydrophilic and soluble?
- A. Triglycerides
- B. Phospholipids✓
- C. Waxes
- D. Terpenoids
Explanation: Phospholipids are soluble in both water and oil (amphiphilic) because the hydrocarbon tails of two fatty acids are still hydrophobic, but the phosphate group end is hydrophilic. Phospholipids are the major component of cell membrane to form lipid bilayers.
Why the other options are wrong
- A. Triglycerides have 3 fatty acids and glycerin, they are hydrophobic.
- C. Waxes are similar to fats except that waxes are composed of only one long-chain fatty acid bonded to a long-chain alcohol group attached. Because of their long, nonpolar carbon chains, waxes are extremely hydrophobic (meaning they lack an affinity for water).
- D. In general, most of the terpenes are highly hydrophobic and insoluble in water but soluble in ethanol, chloroform and diethyl ether.
Q59. _ hormone is released from the posterior lobe of the pituitary gland.
- A. Adrenaline
- B. Thyroid stimulating hormone
- C. FSH
- D. Antidiuretic hormone✓
Explanation: The posterior lobe of the pituitary gland produces two hormones, vasopressin (Antidiuretic hormone) and oxytocin. Adrenaline is released from the adrenal glands and its major action, together with noradrenaline, is to prepare the body for 'fight or flight'. Thyroid-stimulating hormone, also known as TSH, is a glycoprotein hormone produced by the anterior pituitary. Follicle-stimulating hormone (FSH) is released by the anterior lobe of the pituitary gland.
Why the other options are wrong
- A. Adrenaline is released from the adrenal glands and its major action, together with noradrenaline, is to prepare the body for 'fight or flight'.
- B. Thyroid-stimulating hormone, also known as TSH, is a glycoprotein hormone produced by the anterior pituitary.
- C. Follicle-stimulating hormone (FSH) is released by the anterior lobe of the pituitary gland.
Q60. Ribosomes are made up of _ and _.
- A. Proteins and carbohydrates
- B. RNA and lipid
- C. RNA and proteins✓
- D. RNA and carbohydrates
Explanation: A ribosome is an intercellular structure made up of equal amounts of both RNA and protein, hence named as 'ribonucleo-protein particles 'and it is the site of protein synthesis in the cell. The ribosome reads the messenger RNA (mRNA) sequence and translates that genetic code into a specified string of amino acids, which grow into long chains that fold to form proteins.
Why the other options are wrong
- A. A ribosome is an intercellular structure made up of equal amounts of both RNA and protein, hence named as 'ribonucleo-protein particles 'and it is the site of protein synthesis in the cell.
- B. A ribosome is an intercellular structure made up of equal amounts of both RNA and protein, hence named as 'ribonucleo-protein particles 'and it is the site of protein synthesis in the cell.
- D. A ribosome is an intercellular structure made up of equal amounts of both RNA and protein, hence named as 'ribonucleo-protein particles 'and it is the site of protein synthesis in the cell.
Q61. A non-protein part which is essential for proper functioning of enzyme is called:
- A. Additional factor
- B. Cofactor✓
- C. Efficient cofactor
- D. Extra factor
Explanation: A non-protein part that is essential for the proper functioning of an enzyme is called a "cofactor." Cofactors are often inorganic ions or organic molecules that associate with the protein component (apoenzyme) of an enzyme to form the complete and catalytically active holoenzyme.
Why the other options are wrong
- A. This term is too vague and not specific to enzymatic activity. While additional factors can influence enzymes, they are not the essential non-protein components needed for enzyme function.
- C. The term 'efficient cofactor' is not standard in enzymology. While cofactors can enhance efficiency, the term does not uniquely identify the essential non-protein component.
- D. Similar to 'additional factor,' this term is too generic and does not specifically refer to the non-protein part essential for enzyme function.
Q62. DNA made by joining pieces from two or more different sources is called:
- A. Probes
- B. Restriction endonuclease
- C. Mutated DNA
- D. Recombinant DNA✓
Explanation: Recombinant DNA (or rDNA) is made by combining DNA from two or more sources.DNA probes are stretches of single-stranded DNA used to detect the presence of complementary nucleic acid sequences (target sequences) by hybridization.A restriction enzyme, restriction endonuclease, or restrictase is an enzyme that cleaves DNA into fragments at or near specific recognition sites within molecules known as restriction sites.A mutation is a change in a DNA sequence. Mutations can result from DNA copying mistakes made during cell division, exposure to ionizing radiation, exposure to chemicals called mutagens, or infection by viruses.
Why the other options are wrong
- A. Probes are a single-stranded sequence of DNA or RNA that is used to identify specific sequences of DNA or RNA. They are designed as complementary to the part of the genome of interest so that when the probe and the genome are brought together, the probe will hybridize with the target sequence.
- B. A restriction enzyme, restriction endonuclease, REase, ENase, or restrictase is an enzyme that cleaves DNA into fragments at or near specific recognition sites within molecules known as restriction sites. Restriction enzymes are one class of the broader endonuclease group of enzymes.
- C. A gene variant is a permanent change in the DNA sequence that makes up a gene. This type of genetic change used to be known as a gene mutation, but because changes in DNA do not always cause disease, it is thought that gene variant is a more accurate term.
Q63. The hormone which controls the uptake of Sodium ions in kidney and its maintenance in blood plasma is:
- A. Somatotrophic Hormone
- B. Aldosterone Hormone✓
- C. Gonadotrophic Hormone
- D. Thyroxine Hormone
Explanation: Aldosterone is a steroid hormone. Its main role is to regulate salt and water in the body, thus having an effect on blood pressure.Growth hormone (GH), also called somatotropin or human growth hormone, is a peptide hormone secreted by the anterior lobe of the pituitary gland. It stimulates the growth of essentially all tissues of the body, including bone.Gonadotropins: Luteinizing and Follicle Stimulating Hormones. Luteinizing hormone (LH) and follicle-stimulating hormone (FSH) are called gonadotropins because they stimulate the gonads - in males, the testes, and in females, the ovaries.Thyroxine is the main hormone secreted into the bloodstream by the thyroid gland. It plays vital roles in digestion, heart and muscle function, brain development and maintenance of bones.
Why the other options are wrong
- A. Growth hormone (GH), also called somatotropin or human growth hormone, is a peptide hormone secreted by the anterior lobe of the pituitary gland. It stimulates the growth of essentially all tissues of the body, including bone.
- C. Gonadotropins: Luteinizing and Follicle Stimulating Hormones. Luteinizing hormone (LH) and follicle-stimulating hormone (FSH) are called gonadotropins because they stimulate the gonads - in males, the testes, and in females, the ovaries.
- D. Thyroxine is the main hormone secreted into the bloodstream by the thyroid gland. It plays vital roles in digestion, heart and muscle function, brain development and maintenance of bones.
Q64. Which of the following statements are true for mitochondria and chloroplasts?A. ATP synthesis is seen in bothB. The outer membrane has more surface area in bothC. Circular naked DNA, RNA, and 70 ribosomes are seen in bothD. Oxidative phosphorylation occurs in both
- A. A and B
- B. B and C
- C. A and C✓
- D. A and D
Explanation: ATP synthesis is seen in both chloroplasts and mitochondria. The inner membrane of mitochondria is folded to increase surface area.Both mitochondria and chloroplasts have small, circular DNA, all kinds of RNA and 70S ribosomes.Oxidative phosphorylation takes place only in mitochondria.
Why the other options are wrong
- A. The inner membrane of mitochondria is folded to increase surface area.
- B. The inner membrane of mitochondria is folded to increase surface area.
- D. Oxidative phosphorylation takes place only in mitochondria.
Q65. The capillaries of glomerulus rejoin to form an _.
- A. Efferent arteriole✓
- B. Afferent arteriole
- C. Peritubular capillaries
- D. Collecting duct
Explanation: At the distal end of the glomerulus, the capillaries rejoin to form the afferent arteriole through which blood leaves the glomerulus.The afferent arterioles branch from the renal artery, which supplies blood to the kidneys. The afferent arterioles later diverge into the capillaries of the glomerulus.In the renal system, peritubular capillaries are tiny blood vessels, supplied by the efferent arteriole, that travel alongside nephrons allowing reabsorption and secretion between blood and the inner lumen of the nephron.The collecting duct system of the kidney consists of a series of tubules and ducts that physically connect nephrons to a minor calyx or directly to the renal pelvis.
Why the other options are wrong
- B. Afferent arterioles have two functions: they serve to connect the renal artery to the glomerular capillaries and they take an active role in controlling not only the local blood pressure inside the kidney but also your overall body's blood pressure.
- C. Peritubular capillaries are tiny blood vessels in your kidneys. They filter waste from your blood so the waste can leave your body through urine. Peritubular capillaries also reabsorb nutrients your body needs to work properly, such as minerals.
- D. The last part of a long, twisting tube that collects urine from the nephrons (cellular structures in the kidney that filter blood and form urine) and moves it into the renal pelvis and ureters. Also called renal collecting tubule.
Q66. How many sodium ions are pumped out in response to two potassium ions transported into the membrane?
- A. 4
- B. 1
- C. 2
- D. 3✓
Explanation: The sodium-potassium pump moves 3 Na+ out and 2 K+ in per cycle, maintaining the resting membrane potential (-70 mV) with more positive charge outside than inside.
Why the other options are wrong
- A. This option is incorrect because the sodium-potassium pump transports three sodium ions out of the cell for every two potassium ions it brings in. Therefore, four sodium ions do not correspond to the correct ratio of ion transport.
- B. This option is incorrect as it misrepresents the function of the sodium-potassium pump. The pump actually moves three sodium ions out of the cell in exchange for two potassium ions coming in, not just one sodium ion.
- C. This choice is inaccurate because the sodium-potassium pump actively transports three sodium ions out while taking in two potassium ions, not two sodium ions. Thus, the number provided does not reflect the correct ionic exchange ratio.
Q67. Chance of a crossing over between two loci is directly proportional to their:
- A. Thickening
- B. Width
- C. Length
- D. Distance✓
Explanation: The correct answer is 'Distance.' In genetics, the likelihood of a crossover event between two loci is directly proportional to the physical distance separating them on a chromosome. The greater this distance, the more likely it is that a crossover will occur during meiosis, resulting in genetic recombination. Other options like thickening, width, and length do not accurately describe the relationship between loci distance and crossover frequency, making them incorrect choices in this context.
Why the other options are wrong
- A. Thickening is not related to the genetic distance or crossover frequency between genes. It is not a factor in gene linkage and crossing over.
- B. Width does not pertain to genetic terms when discussing gene linkage and crossing over. It does not affect the probability of crossover events.
- C. Length might refer to physical characteristics but does not specifically relate to genetic distance between loci involved in crossing over.
Q68. Process ensuring the survival of species over long periods of time, even though individual members of the species die.
- A. Reproduction✓
- B. Adaptability
- C. Mitosis
- D. Respiration
Explanation: Reproduction is the biological process by which new individual organisms offspring are produced from their parents. Reproduction is the biological process by which new individual organisms are produced from preexisting ones. It is a fundamental characteristic of living organisms and is essential for the continuation of a species. Reproduction can occur through various mechanisms, and it is central to the life cycle of organisms.
Why the other options are wrong
- B. Adaptability means being able to rapidly learn new skills and behaviours in response to changing circumstances.
- C. Mitosis is a process where a single cell divides into two identical daughter cells.
- D. Respiration is a chemical reaction that happens in all living cells, including plant cells and animal cells. It is the way that energy is released from glucose so that all the other chemical processes needed for life can happen.
Q69. Phages which show lysogenic cycle are known as:
- A. Enveloped Phage
- B. Virulent Phage
- C. Temperate phages✓
- D. Bacteriophage
Explanation: Temperate phages are some bacteriophages which display a lysogenic life cycle. Lysogeny is characterized by an integration of the bacteriophage nucleic acid into the host bacteria genome and becomes prophage. In this condition, the bacterium continues to live and reproduce normally. Bacteriophages that only use the lytic cycle are called virulent phages. So, the correct answer is 'temperate phages'.
Why the other options are wrong
- A. There is no such term used in biology but it may refer to enveloped viruses.As it is a combined term used for more than .
- B. The phage which causes lysis of the host cell is known as lytic or virulent phage.
- D. Viruses that infect bacteria are called bacteriophages.
Q70. Organs specialized to perform different functions but structurally alike are:
- A. Analogous organs
- B. Homologous organs✓
- C. Autologous organs
- D. Anuclogous organs
Explanation: Organs that have the same internal structure but perform different functions are called homologous organs.Homologous organs result from divergent evolution, where a common ancestral structure evolves to perform different functions in different species, adapting to new environments. This occurs because populations become isolated and face different selective pressures, leading to diversification. A classic example is the forelimbs of vertebrates like humans, bats, whales, and cheetahs, which share a similar bone structure but are adapted for grasping, flying, swimming, and running, respectively. Analogous organs are the opposite of homologous organs, which have similar functions but different origins.
Why the other options are wrong
- A. The organs which have similar functions but are different in anatomical structures are called analogous organs. Examples of analogous organs are as follows: Wings of an insect and bird. Pectoral fins of sharks and flippers of dolphins.
- C. Autologous: Auto means self. The stem cells in autologous transplants come from the same person who will get the transplant, so the patient is their own donor.
- D. There is no term as anuclogous organs.
Q71. By PCR we mean:
- A. Polymerase chronic reaction
- B. Polymerase chain reaction✓
- C. Polymerase copy reaction
- D. Polymerase cross-reaction
Explanation: Polymerase chain reaction (abbreviated PCR) is a laboratory technique for rapidly producing (amplifying) millions to billions of copies of a specific segment of DNA, which can then be studied in greater detail.
Why the other options are wrong
- A. This is not the correct expansion. The correct term is "Polymerase Chain Reaction."
- C. This is not the correct expansion. PCR stands for Polymerase Chain Reaction, not Polymerase Copy Reaction.
- D. This is not the correct expansion. PCR specifically refers to the Polymerase Chain Reaction and does not involve cross-reactions in its standard usage.
Q72. If lipopolysaccharides did not appear in the wall of bacteria on staining then it will be known as _.
- A. Gram-negative
- B. Gram-positive✓
- C. Capsule
- D. Both Gram positive & negative
Explanation: The Gram stain procedure distinguishes between Gram positive and Gram negative groups by coloring these cells red or violet. Gram positive bacteria stain violet due to the presence of a thick layer of peptidoglycan in their cell walls, which retains the crystal violet these cells are stained with. Alternatively, Gram negative bacteria stain pink, which is attributed to a thinner peptidoglycan wall, which does not retain the crystal violet during the decoloring process. Gram-positive bacteria do not contain lipopolysaccharides, but carry surface teichoic acids, lipoteichoic acids and peptidoglycan instead. The outer membrane of Gram-negative bacteria contains lipopolysaccharides, proteins, and phospholipids. The bacterial capsule is a large structure of many bacteria. It is a polysaccharide layer that lies outside the cell envelope, and is thus deemed part of the outer envelope of a bacterial cell.
Why the other options are wrong
- A. The Gram stain procedure distinguishes between Gram positive and Gram negative groups by coloring these cells red or violet. Gram positive bacteria stain violet due to the presence of a thick layer of peptidoglycan in their cell walls, which retains the crystal violet these cells are stained with. Alternatively, Gram negative bacteria stain pink, which is attributed to a thinner peptidoglycan wall, which does not retain the crystal violet during the decoloring process. Gram-positive bacteria do not contain lipopolysaccharides, but carry surface teichoic acids, lipoteichoic acids and peptidoglycan instead. The outer membrane of Gram-negative bacteria contains lipopolysaccharides, proteins, and phospholipids. The bacterial capsule is a large structure of many bacteria. It is a polysaccharide layer that lies outside the cell envelope, and is thus deemed part of the outer envelope of a bacterial cell.
- C. The Gram stain procedure distinguishes between Gram positive and Gram negative groups by coloring these cells red or violet. Gram positive bacteria stain violet due to the presence of a thick layer of peptidoglycan in their cell walls, which retains the crystal violet these cells are stained with. Alternatively, Gram negative bacteria stain pink, which is attributed to a thinner peptidoglycan wall, which does not retain the crystal violet during the decoloring process. Gram-positive bacteria do not contain lipopolysaccharides, but carry surface teichoic acids, lipoteichoic acids and peptidoglycan instead. The outer membrane of Gram-negative bacteria contains lipopolysaccharides, proteins, and phospholipids. The bacterial capsule is a large structure of many bacteria. It is a polysaccharide layer that lies outside the cell envelope, and is thus deemed part of the outer envelope of a bacterial cell.
- D. The Gram stain procedure distinguishes between Gram positive and Gram negative groups by coloring these cells red or violet. Gram positive bacteria stain violet due to the presence of a thick layer of peptidoglycan in their cell walls, which retains the crystal violet these cells are stained with. Alternatively, Gram negative bacteria stain pink, which is attributed to a thinner peptidoglycan wall, which does not retain the crystal violet during the decoloring process. Gram-positive bacteria do not contain lipopolysaccharides, but carry surface teichoic acids, lipoteichoic acids and peptidoglycan instead. The outer membrane of Gram-negative bacteria contains lipopolysaccharides, proteins, and phospholipids. The bacterial capsule is a large structure of many bacteria. It is a polysaccharide layer that lies outside the cell envelope, and is thus deemed part of the outer envelope of a bacterial cell.
Q73. The low levels of surfactant produced by the alveolar epithelium cause:
- A. Respiratory distress syndrome✓
- B. Emphysema
- C. Bronchitis
- D. Asthma
Explanation: The key feature of respiratory distress syndrome (RDS) is the insufficient production of surfactant in the lungs.Emphysema is a lung condition that causes shortness of breath. In people with emphysema, the air sacs in the lungs (alveoli) are damaged. Over time, the inner walls of the air sacs weaken and rupture — creating larger air spaces instead of many small ones.Bronchitis is an infection of the main airways of the lungs (bronchi), causing them to become irritated and inflamed.Asthma is a condition in which your airways narrow and swell and may produce extra mucus. This can make breathing difficult and trigger coughing.
Why the other options are wrong
- B. Emphysema is a lung condition that causes shortness of breath. In people with emphysema, the air sacs in the lungs (alveoli) are damaged. Over time, the inner walls of the air sacs weaken and rupture - creating larger air spaces instead of many small ones.
- C. Bronchitis is an inflammation of the bronchi, the main airways of the lungs. This condition causes the airways to swell and produce excess mucus, leading to coughing, difficulty breathing, and discomfort.
- D. Asthma is a respiratory condition where the airways become narrowed, inflamed, and sometimes produce excess mucus. These changes make it harder to breathe and can cause symptoms like coughing, wheezing, and shortness of breath.
Q74. Deficiency of enzyme _ causes combined immunodeficiency syndrome.
- A. Adenosine transcriptase
- B. Adenosine transaminase
- C. Adenosine polymerase
- D. Adenosine deaminase✓
Explanation: Adenosine deaminase deficiency (ADA deficiency) is an inherited condition that damages the immune system and is a common cause of severe combined immunodeficiency (SCID).
Why the other options are wrong
- A. This is not a recognized enzyme. There is no enzyme with this name in the context of immunodeficiency.
- B. Transaminases are enzymes involved in amino acid metabolism, but adenosine transaminase is not a known enzyme. It is not associated with immunodeficiency.
- C. There is no enzyme called adenosine polymerase. Polymerases are enzymes involved in DNA or RNA synthesis, but none are specifically named adenosine polymerase.
Q75. Site of protein synthesis in cells are:
- A. Ribosomes✓
- B. Endoplasmic Reticulum
- C. Nucleolus
- D. Smooth Endoplasmic Reticulum
Explanation: The site of protein synthesis in the cell are ribosomes. These are present attached to the surface of the rough endoplasmic reticulum and also in the free state in the cytoplasm. These organelles are involved in the process of translation which is the conversion of the mRNA to protein.
Why the other options are wrong
- B. SER is involved in the synthesis of lipids, and RER is involved in the synthesis of proteins.
- C. It is involved in synthesis of ribosomes.
- D. SER is involved in synthesis of lipids.
Q76. Keeping correct balance of ions and water in our body is called as:
- A. Thermoregulation
- B. Osmoregulation✓
- C. Excretion
- D. Selective reabsorption
Explanation: Osmoregulation is the process of maintaining salt and water balance (osmotic balance) across membranes within the body.Thermoregulation is a process that allows your body to maintain its core internal temperature.Excretion is a process in which metabolic waste is eliminated from an organism. In vertebrates this is primarily carried out by the lungs, kidneys and skin.Selective reabsorption is the process whereby certain molecules (e.g. ions, glucose and amino acids), after being filtered out of the capillaries along with nitrogenous waste products (i.e. urea) and water in the glomerulus, are reabsorbed from the filtrate as they pass through the nephron.
Why the other options are wrong
- A. Thermoregulation is a process that allows your body to maintain its core internal temperature.
- C. Excretion is a process in which metabolic waste is eliminated from an organism. In vertebrates this is primarily carried out by the lungs, kidneys and skin.
- D. Selective reabsorption is the process whereby certain molecules (e.g. ions, glucose and amino acids), after being filtered out of the capillaries along with nitrogenous waste products (i.e. urea) and water in the glomerulus, are reabsorbed from the filtrate as they pass through the nephron.
Q77. There are _ number of linkage groups in humans.
- A. 46
- B. 22
- C. 80
- D. 23✓
Explanation: This phenomenon of staying together of all the genes of a chromosome is called linkage. Gene linkage is a physical relationship between genes. A chromosome carries its linked genes in the form of a linkage group. The number of linkage groups corresponds to the number of homologous pairs of chromosomes. Man has 23 linkage groups.
Why the other options are wrong
- A. This phenomenon of staying together of all the genes of a chromosome is called linkage. Gene linkage is a physical relationship between genes. A chromosome carries its linked genes in the form of a linkage group. The number of linkage groups corresponds to the number of homologous pairs of chromosomes. Man has 23 linkage groups.
- B. This phenomenon of staying together of all the genes of a chromosome is called linkage. Gene linkage is a physical relationship between genes. A chromosome carries its linked genes in the form of a linkage group. The number of linkage groups corresponds to the number of homologous pairs of chromosomes. Man has 23 linkage groups.
- C. This phenomenon of staying together of all the genes of a chromosome is called linkage. Gene linkage is a physical relationship between genes. A chromosome carries its linked genes in the form of a linkage group. The number of linkage groups corresponds to the number of homologous pairs of chromosomes. Man has 23 linkage groups.
Q78. The actual or preserved remains of the organisms that lived in the ancient past are called:
- A. Fossils✓
- B. Impression
- C. Ancient prints
- D. Ancient cast
Explanation: Fossils are the preserved remains, or traces of remains, of ancient organisms. An impression fossil is formed when the plant or animal decays completely but leaves behind an impression of itself.
Why the other options are wrong
- B. An impression fossil is formed when the plant or animal decays completely but leaves behind an impression of itself.
- C. This term doesn't fit the given statement.
- D. The term refers to any printed image, irrespective of the printing technique employed, that was created over a period of more than 600 years, from the beginning of printmaking in Europe to the end of the 18th century or early 19th century.
Q79. Which one of the following cells does not have a nucleus:
- A. Eosinophils
- B. Neutrophils
- C. Basophils
- D. Platelets✓
Explanation: Platelets are irregularly shaped and typically measure only 2–3 micrometers in diameter. Platelets do not possess a nucleus as they are not true cells, but are instead classified as cell fragments produced by megakaryocytes. These are involved in blood clotting.Neutrophils, eosinophils, and basophils are all types of white blood cells that contain a nucleus.
Why the other options are wrong
- A. Eosinophils have a nucleus. Their nucleus is bilobed. These cells inactivate inflammation-producing substances and attack parasites.
- B. Neutrophils have a nucleus that can be two to five-lobed. They destroy small particles by phagocytosis.
- C. Badophils possess a bilobed nucleus. They release heparin to prevent blood clots and histamine, which causes inflammation.
Q80. These structures are involved in the breakdown of old organelles:
- A. Leucoplasts
- B. Glyoxysomes
- C. Lysosomes✓
- D. Peroxisomes
Explanation: Lysosomes are membrane-bounded, dense granular structures containing hydrolytic enzymes responsible mainly for intracellular and extracellular digestion. They are also involved in the process called autophagy (self-eating). In this process, some old parts of the cell, such as old mitochondria, are engulfed and digested by lysosomes.
Why the other options are wrong
- A. This is an incorrect option. The function of leucoplasts is to store starches and oils in plant cells. It is not involved in the breakdown of any substance or organelle.
- B. This option is incorrect. Glyoxysomes are present in plant seeds rich in lipids. They are the sites for breakdown of fatty acids to succinate. They are not involved in breakdown of old organelles.
- D. This is an incorrect option. This organelle is specifically involved in the formation and decomposition of hydrogen peroxide in the cell.
Q81. Which combination is an example of ball and socket joints:
- A. Hip and shoulder joints✓
- B. Hip and knee joints
- C. Shoulder and knee joints
- D. Hip and elbow joints
Explanation: The ball and socket joint, also called the spheroidal joint, is a joint in which the ball-like rounded surface of a bone moves within a cup-like depression on another bone. This allows greater freedom of movement (full circle) than any other kind of joint. As evident from the figure, the shoulder joint and the hip joint are of a ball-and-socket type. Whereas the elbow, knee, and ankle joints are hinge joints.
Why the other options are wrong
- B. The hip joint connects the thigh bone (femur) to the pelvic bone, allowing for leg movement and flexibility. It is a ball-and-socket joint. The knee joint connects the thigh bone (femur) to the shinbone (tibia) and kneecap (patella). It functions as a hinge joint, facilitating bending and straightening of the leg. Both joints are crucial for mobility and weight-bearing activities.
- C. The shoulder joint is a ball-and-socket joint connecting the upper arm bone (humerus) to the shoulder blade (scapula). It provides a wide range of motion for arm movements. The knee joint is a hinge joint connecting the thigh bone (femur) to the shinbone (tibia) and kneecap (patella). It primarily allows for bending and straightening of the leg. Both joints are essential for various daily activities and movements.
- D. The hip joint is a ball-and-socket joint connecting the thigh bone (femur) to the pelvic bone, facilitating leg movement and rotation. The elbow joint is a hinge joint connecting the upper arm bone (humerus) to the forearm bones (radius and ulna), allowing for bending and straightening of the arm.
Q82. In aerobic respiration which of the following is correct?
- A. Pyruvate is completely oxidized to form carbon dioxide and water✓
- B. Pyruvate is completely oxidized to form oxygen and water
- C. Pyruvate carboxylated to produce citrate
- D. Pyruvate is converted to ethanol and carbon dioxide
Explanation: In aerobic respiration, glucose is oxidised to form pyruvate during glycolysis. This is followed by Link reaction, Krebs cycle and Electron transport chain all of which leads to the formation of ATP, water and CO2. During the citric acid cycle, pyruvate is completely oxidized, converting it into carbon dioxide (CO2) and high-energy electron carriers (NADH and FADH2).
Why the other options are wrong
- B. This option is incorrect because pyruvate itself is not oxidized to form oxygen and water. In aerobic respiration, oxygen (O2) is the terminal electron acceptor in the electron transport chain, but it is not formed during the oxidation of pyruvate. Pyruvate is oxidized to produce carbon dioxide (CO2) and high-energy electron carriers (NADH and FADH2) during the citric acid cycle.
- C. This option is incorrect because the formation of citrate occurs during the first step of the citric acid cycle, where acetyl-CoA combines with oxaloacetate to form citrate. Pyruvate is not directly carboxylated to produce citrate. Pyruvate is first converted to acetyl-CoA in the mitochondria before entering the citric acid cycle.
- D. This option is incorrect because it describes the process of alcoholic fermentation, not aerobic respiration. In alcoholic fermentation, pyruvate is converted to ethanol (alcohol) and carbon dioxide in the absence of oxygen. However, in aerobic respiration, pyruvate undergoes complete oxidation to produce carbon dioxide and water in the presence of oxygen.
Q83. Yeasts, the unicellular fungi belongs mostly to the group:
- A. Deuteromycota
- B. Zygomycota
- C. Basidiomycota
- D. Ascomycota✓
Explanation: Yeast is a eukaryotic organism that is single-celled and is classified under the kingdom of fungi. Most of the species of yeast reproduce asexually by budding. The most common species of yeast is the Saccharomyces cerevisiae which is used for fermentation and baking purpose. Ascomycetes are also called sac fungi because these fungi produce elongated sacs called asci. This is the largest subdivision of fungi and contains some very well-known genera such as Penicillium, Saccharomyces, Aspergillus, Neurospora, etc
Why the other options are wrong
- A. Some of the examples of the Deuteromycetes are Cercospora, Colletotrichum, Trichoderma, Pyricularia, and Fusarium.
- B. Molds on fruits and bread are often (but certainly not always) from the Mucorales, as well as molds that form on dog poop (specifically, a genus called Phycomyces). You can also find a diverse assortment of former "Zygomycota" members parasitizing other fungi and insects.
- C. The Phylum Basidiomycota is a major division of the Fungi. Known collectively as the Basidiomycetes fungi, this group includes mushrooms, smuts, rusts, the Cryptococcus pathogen, and others. This group contains both edible and poisonous species and includes an impressive range of sizes, colors, and shapes.
Q84. The enzyme used by the bacteria to cut the DNA of the invading virus for its protection is:
- A. Restriction Exonuclease
- B. Restriction Ligase
- C. Restriction Endonuclease✓
- D. DNA polymerase
Explanation: Restriction enzyme, also called restriction endonuclease, a protein produced by bacteria that cleaves DNA at specific sites along the molecule. In the bacterial cell, restriction enzymes cleave foreign DNA, thus eliminating infecting organisms.Specific endonucleases, also called restriction endonucleases, are available that cleave specific sites within a DNA sequence. Exonuclease is usually non-specific and does not have defensive properties against the entry of pathogenic microbes.Ligase is an enzyme that uses ATP to form bonds, and is used in recombinant DNA cloning to join restriction endonuclease fragments that have annealed. (There is no such thing as restriction ligase)A DNA polymerase is a member of a family of enzymes that catalyze the synthesis of DNA molecules from nucleoside triphosphates, the molecular precursors of DNA.
Why the other options are wrong
- A. Exonuclease is usually non-specific and does not have defensive properties against the entry of pathogenic microbes.
- B. Ligase is an enzyme that uses ATP to form bonds and is used in recombinant DNA cloning to join restriction endonuclease fragments that have annealed. (There is no such thing as restriction ligase)
- D. A DNA polymerase is a member of a family of enzymes that catalyze the synthesis of DNA molecules from nucleoside triphosphates, the molecular precursors of DNA.
Q85. The number and sequence of amino acids along a polypeptide chain is called _ structure of a protein.
- A. Quaternary
- B. Tertiary
- C. Primary✓
- D. Secondary
Explanation: Primary structure is the amino acid sequence.Secondary structure is local interactions between stretches of a polypeptide chain and includes α-helix and β-pleated sheet structures.Tertiary structure is the overall three-dimension folding driven largely by interactions between R groups.Quaternary structures is the orientation and arrangement of subunits in a multi-subunit protein.
Why the other options are wrong
- A. Quaternary structures is the orientation and arrangement of subunits in a multi-subunit protein. So, this option is not correct.
- B. Tertiary structure is the overall three-dimensional folding driven largely by interactions between R groups. So, this option is not correct.
- D. Secondary structure is local interactions between stretches of a polypeptide chain and includes a-helix and B-pleated sheet structures. So, this option is not correct.
Q86. Rod-shaped bacteria are known as
- A. Spirilla
- B. Bacilli✓
- C. Spirochete
- D. Cocci
Explanation: Bacilli are rod shaped bacteria. Cocci are spherical shaped bacteria. Spirillas are corkscrew shaped bacteria. Spirochetes are any group of spiral shaped bacteria.
Why the other options are wrong
- A. Spirillas are corkscrew shaped bacteria.
- C. Spirochetes are any group of spiral shaped bacteria.
- D. Cocci are spherical shaped bacteria.
Q87. _ is the exact position of a gene on the chromosome.
- A. Trait
- B. Centromere
- C. Genotype
- D. Locus✓
Explanation: The correct answer is locus. A locus is the precise, fixed location on a chromosome where a particular gene or genetic marker is situated. This term is specific to genetics and is used to identify the position of genes.In contrast, a trait is a characteristic of an organism, not a location on a chromosome. The centromere is a region of the chromosome that connects sister chromatids, and genotype refers to the overall genetic makeup of an organism, not the position of individual genes.
Why the other options are wrong
- A. A trait refers to a specific characteristic or feature of an organism, which is determined by genes. It is not a location on a chromosome.
- B. The centromere is the part of a chromosome that holds sister chromatids together and is important during cell division, but it is not specifically the location of a gene.
- C. Genotype refers to the genetic makeup of an organism, including all of its genes, rather than the location of a particular gene on a chromosome.
Q88. Parathormone production is controlled by the blood:
- A. Ca level✓
- B. Sugar level
- C. Na level
- D. Mg level
Explanation: Parathyroid hormone is mainly controlled by the negative feedback of calcium levels in the blood to the parathyroid glands. Low calcium levels in the blood stimulate parathyroid hormone secretion, whereas high calcium levels in the blood prevent the release of parathyroid hormone.
Why the other options are wrong
- B. Insulin and glucagon production are controlled by it.
- C. Aldosterone production is controlled by it.
- D. This option is incorrect. Mg level: Magnesium levels are important for various bodily functions, but they don't directly control parathormone production.
Q89. Which is the pacemaker of human heart:
- A. AV node
- B. SA node✓
- C. Purkinjie fibres
- D. Bundle of His
Explanation: SA node generates impulses that initiate heartbeats.
Why the other options are wrong
- A. The atrioventricular (AV) node is a cluster of cells in the heart that regulates the electrical signal between the atria and ventricles. It acts as a relay station, slowing down the electrical impulse, allowing the ventricles to fill with blood before contracting and pumping it out to the rest of the body.
- C. Purkinje fibers are specialized cardiac cells in the heart's conduction system, forming a network in the inner walls of the ventricles (subendocardium) that rapidly transmit electrical signals to trigger synchronized muscle contraction, ensuring efficient pumping of blood to the lungs and body.
- D. The bundle of His is a collection of heart muscle cells specialised for electrical conduction that transmits the electrical impulses from the AV node (located between the atria and the ventricles) to the apex of the fascicular branches via the bundle branches.
Q90. Single ringed pyrimidines are:
- A. Uracil, Cytosine and Thymine✓
- B. Cytosine, Guanine and Uracil
- C. Adenine and Guanine
- D. Cytosine, Adenine and Thymine
Explanation: The pyrimidines, Thymine, Cytosine and Uracil, are smaller and have a single ring, while the purines, Adenine and Guanine, are larger and have two rings.
Why the other options are wrong
- B. Single-ring nitrogenous bases are called pyrimidines, while double-ringed structures are called purines. Pyrimidines include Cytosine, Thymine (only in DNA), and Uracil (only in RNA). Purines include Adenine and Guanine.
- C. Single-ring nitrogenous bases are called pyrimidines, while double-ringed structures are called purines. Pyrimidines include Cytosine, Thymine (only in DNA), and Uracil (only in RNA). Purines include Adenine and Guanine.
- D. Single-ring nitrogenous bases are called pyrimidines, while double-ringed structures are called purines. Pyrimidines include Cytosine, Thymine (only in DNA), and Uracil (only in RNA). Purines include Adenine and Guanine.
Q91. Which one of the following is Multiple allelic characters?
- A. Colour of flower in pea plant
- B. Blood group of the human being✓
- C. Shape of seed in pea plant
- D. Length of stem in pea plant
Explanation: Multiple alleles are the alternative forms of the same gene so they influence the same trait. An excellent example of multiple allele inheritance is human blood type. Blood type exists as four possible phenotypes: A, B, AB, & O. There are 3 alleles for the gene that determines blood type.
Why the other options are wrong
- A. It is the incorrect option. Colour of flower in pea plant: Flower color in pea plants is typically determined by a single gene with two alleles (e.g., red and white), demonstrating simple Mendelian inheritance, not multiple alleles.
- C. It is the incorrect option. Shape of seed in pea plant: Seed shape in pea plants, like flower color, is governed by a single gene with two alleles (e.g., round and wrinkled), again following Mendelian inheritance.
- D. It is the incorrect option.Length of stem in pea plant: Stem length is also usually controlled by a single gene with two alleles (e.g., tall and dwarf), not multiple alleles.
Q92. Which statement is correct about atrial systole?
- A. Atria relax and ventricles contract
- B. Atria contract and ventricle also contract
- C. Atria and ventricles are relaxed
- D. Ventricles remain relax while atria contract✓
Explanation: During atrial systole following events occur:• AV valves open• SL valves close• Muscles of atria contract and pump blood to ventricles• Ventricles are relaxed and receive blood from atria.
Why the other options are wrong
- A. It is incorrect as atria relax when blood leaves them, while in atrial systole, blood fills the atria, which in turn contract to pump it into the relaxed ventricles.
- B. It is incorrect. During atrial systole, the ventricles are relaxed, ready to receive blood from the atria.
- C. It is incorrect. Atria will contract, and ventricles will relax. As atria pass the blood to the ventricles during atrial systole, they contract.
Q93. Growth in the larva of young arthropods is restricted by:
- A. Exoskeleton✓
- B. Appendages
- C. Endoskeleton
- D. Reduced mitosis
Explanation: As the body underneath the exoskeleton grows, the animal begins to outgrow its tough exterior. In order to cope with this situation, arthropods undergo a process of shedding their exoskeleton and forming a new one periodically throughout their lifetime. This process is called molting, or ecdysis.
Why the other options are wrong
- B. As the body underneath the exoskeleton grows, the animal begins to outgrow its tough exterior. In order to cope with this situation, arthropods undergo a process of shedding their exoskeleton and forming a new one periodically throughout their lifetime. This process is called molting, or ecdysis.
- C. As the body underneath the exoskeleton grows, the animal begins to outgrow its tough exterior. In order to cope with this situation, arthropods undergo a process of shedding their exoskeleton and forming a new one periodically throughout their lifetime. This process is called molting, or ecdysis.
- D. As the body underneath the exoskeleton grows, the animal begins to outgrow its tough exterior. In order to cope with this situation, arthropods undergo a process of shedding their exoskeleton and forming a new one periodically throughout their lifetime. This process is called molting, or ecdysis.
Q94. At the last step of Glycolysis, which of the following compound is formed:
- A. Pyruvic acid/ Pyruvate✓
- B. Lactic acid
- C. Ethyl Alcohol
- D. Fructose Phosphate
Explanation: The last step in glycolysis is catalyzed by the enzyme pyruvate kinase. Conversion of the PEP into pyruvate results in the production of a second ATP molecule by substrate-level phosphorylation and the compound pyruvic acid (or its salt form, pyruvate).
Why the other options are wrong
- B. This is formed in anaerobic respiration during lactic acid fermentation.
- C. This is formed in anaerobic respiration during alcoholic fermentation.
- D. It is incorrect as the last step in glycolysis is catalyzed by the enzyme pyruvate kinase. Conversion of the PEP into pyruvate results in the production of a second ATP molecule by substrate-level phosphorylation and the compound pyruvic acid (or its salt form, pyruvate).
Q95. NADP, nicotinamide adenine dinucleotide phosphate, is a carrier of:
- A. OH group
- B. O2 group
- C. Hydrogen✓
- D. Phosphate
Explanation: NADP+ is a coenzyme that functions as a universal electron carrier, accepting electrons and hydrogen atoms to form NADPH, or nicotinamide adenine dinucleotide phosphate.
Why the other options are wrong
- A. It is incorrect as NADP+ is a coenzyme that functions as a universal electron carrier, accepting electrons and hydrogen atoms to form NADPH, or nicotinamide adenine dinucleotide phosphate.
- B. It is incorrect as NADP+ is a coenzyme that functions as a universal electron carrier, accepting electrons and hydrogen atoms to form NADPH, or nicotinamide adenine dinucleotide phosphate. It does not carry oxygen
- D. It is incorrect as NADP+ is a coenzyme that functions as a universal electron carrier, accepting electrons and hydrogen atoms to form NADPH, or nicotinamide adenine dinucleotide phosphate.
Q96. When filtration is completed the waste products through distal tube of Nephrons empties to:
- A. Efferent Arteriole
- B. Collecting Tubules✓
- C. Peritubular capillaries
- D. Proximal tubules
Explanation: After filtration, the filtrate moves through the proximal tubule, loop of Henle, and then the distal convoluted tubule. The distal tubule empties its contents (including waste products) into the collecting tubules (or collecting ducts), which carry the urine toward the renal pelvis.
Why the other options are wrong
- A. The renal artery branches into afferent arterioles that deliver blood to the glomerulus, and the capillaries reunite at its distal end to form an efferent arteriole that carries blood away.
- C. In the renal system, peritubular capillaries are the branches of efferent arteriole, that travel alongside nephrons ensuring reabsorption and secretion between blood and the nephron before ultimately draining the blood in to renal vein.
- D. The proximal tubule is the segment of the nephron extends from Bowman's capsule to the beginning of loop of Henle to reabsorbs most of the filtered water, electrolytes and nutrient.
Q97. Blood solute potential is controlled by the following hormone.
- A. Estrogen
- B. Epinephrine
- C. Thyroxine
- D. Vasopressin✓
Explanation: Option B is correct.Antidiuretic hormone (ADH), also called vasopressin, is produced by the hypothalamus and released by the posterior pituitary. It helps the kidneys reabsorb water, reducing urine volume and making it more concentrated. By conserving water, ADH regulates blood volume, blood pressure, and osmolarity. In higher amounts, it also constricts blood vessels, further increasing blood pressure.
Why the other options are wrong
- A. Estrogen is a primary female sex hormone that regulates the development and maintenance of the female reproductive system, as well as secondary sexual characteristics such as breast development and pubic hair growth.
- B. Epinephrine, also known as adrenaline, is a hormone secreted by the adrenal medulla. It is released during strong emotions such as fear or anger and increases heart rate, blood pressure, muscle strength, and blood glucose levels to prepare the body for “fight-or-flight” responses.
- C. Thyroxine (T4) is the principal hormone secreted by the thyroid gland, and it plays essential roles in regulating metabolism, digestion, heart and muscle function, brain development, and bone maintenance.
Q98. The temperature that promotes the maximum activity of enzymes is referred to as:
- A. Fixed temperature
- B. Optimum temperature✓
- C. Controlled temperature
- D. Active temperature
Explanation: The optimum temperature is the specific temperature at which an enzyme's activity is at its maximum. This temperature allows the enzyme to function most efficiently without denaturation.
Why the other options are wrong
- A. The temperature that promotes the maximum activity of enzymes is referred to as the "optimum temperature." Each enzyme has an optimal temperature at which it functions most efficiently. This temperature allows the enzyme to reach its maximum catalytic activity, as the kinetic energy of the molecules is sufficient for effective collisions between the enzyme and its substrate.
- C. The temperature that promotes the maximum activity of enzymes is referred to as the "optimum temperature." Each enzyme has an optimal temperature at which it functions most efficiently. This temperature allows the enzyme to reach its maximum catalytic activity, as the kinetic energy of the molecules is sufficient for effective collisions between the enzyme and its substrate.
- D. The temperature that promotes the maximum activity of enzymes is referred to as the "optimum temperature." Each enzyme has an optimal temperature at which it functions most efficiently. This temperature allows the enzyme to reach its maximum catalytic activity, as the kinetic energy of the molecules is sufficient for effective collisions between the enzyme and its substrate.
Q99. Divergent evolution produces:
- A. Vital Organs
- B. Homologous Organs✓
- C. Vestigial Organs
- D. Analogous Organs
Explanation: Homologous organs are created in divergent evolution. Homologous organs refer to the organs with similar structures but having different functions. The evolution of apes and humans from common primate ancestors is an example of divergent evolution.
Why the other options are wrong
- A. The human body contains five organs that are considered vital for survival. They are the heart, brain, kidneys, liver, and lungs.
- C. Vestigial organs are rudimentary anatomical structures that are retained in a species despite having lost their primary ancestral function. These structures often lack an apparent purpose, in contrast to the full functionality of these organs observed in closely related and ancestral species.
- D. Analogous structures are anatomically different but perform similar functions and hence are a result of convergent evolution. It occurs when two groups of largely unrelated organisms are exposed to very similar environments and develop similar adaptations to survive.
Q100. Tonoplast bounds which organelle:
- A. Golgi complex
- B. Nucleus
- C. Endoplasmic Reticulum
- D. Vacuoles✓
Explanation: A cell can have membrane bound organelles and non-membrane bound organelles. Membrane bound organelles are mitochondria, endoplasmic reticulum, vacuoles, lysosomes, Golgi apparatus, plastids. Membrane which occurs around the vacuole is called a tonoplast and separates the contents of the vacuole from the cytoplasm.
Why the other options are wrong
- A. Golgi complex is bound by a single membrane. It is not bound by tonoplast. Tonoplast is a characteristic feature of vacoule.
- B. It is surrounded by nuclear envelope. Tonoplast is a characteristic feature of vacoule.
- C. The Endoplasmic Reticulum is bound by a single membrane (lipid bilayer). It is not bound by tonoplast.
Q101. Anti-venom given after a snake bite venom is an example of:
- A. Artificial active immunity
- B. Artificial passive immunity✓
- C. Natural active immunity
- D. Natural passive immunity
Explanation: Therefore, the correct answer is B) Artificial passive immunity, as the administration of anti-venom provides immediate protection through the transfer of preformed antibodies. Artificially acquired passive immunity is protection acquired by giving a person an injection or transfusion of antibodies made by someone else. These antibodies neutralize the infectious agents in the usual way, but the protection lasts only a few weeks because the antibodies gradually break down and are not replaced.
Why the other options are wrong
- A. Artificial active immunity refers to the development of immunity through the administration of a vaccine or antigen. In this case, the anti-venom given after a snakebite is not an example of artificial active immunity, as it does not involve the administration of a vaccine.
- C. Natural active immunity refers to the development of immunity through natural exposure to an infectious agent. It occurs when the body's immune system recognizes and responds to a pathogen, leading to the production of specific antibodies. It is not applicable in the context of receiving anti-venom after a snakebite.
- D. Natural passive immunity occurs when antibodies are transferred from a mother to her offspring, typically through breastfeeding or placental transfer. It provides temporary protection to the newborn until their own immune system develops. It is not relevant to the administration of anti-venom after a snakebite.
Q102. The cisternae breaks up into vesicles from _ , _ of Golgi complex.
- A. Convex, maturing face
- B. Concave, forming face
- C. Convex, forming face
- D. Concave, maturing face✓
Explanation: The trans face of golgi apparatus (concave surface) where the cisternae breaks up to form new vesicles is also known as the maturing face.
Why the other options are wrong
- A. The trans face of golgi apparatus (concave surface) where the cisternae breaks up to form new vesicles is also known as the maturing face.
- B. The trans face of golgi apparatus (concave surface) where the cisternae breaks up to form new vesicles is also known as the maturing face.
- C. The trans face of golgi apparatus (concave surface) where the cisternae breaks up to form new vesicles is also known as the maturing face.
Q103. Which hormone causes uterine contractions during childbirth?
- A. Progesterone
- B. Prolactin
- C. Oxytocin✓
- D. Relaxin
Explanation: Oxytocin stimulates strong uterine contractions during labor and aids milk ejection.
Why the other options are wrong
- A. Progesterone mainly maintains pregnancy and does not cause uterine contractions during childbirth.
- B. Prolactin, also known as lactotropin (LTH), is a protein best known for its role in enabling mammals, usually females, to produce milk.
- D. Relaxin is a hormone primarily known for its vital role in pregnancy, relaxing pelvic ligaments and softening the cervix to prepare for childbirth, while also preparing the uterus for implantation and preventing contractions.
Q104. Which of the following is Unsaturated “Fatty Acid”?
- A. Stearic Acid
- B. Palmitic Acid
- C. Butyric Acid
- D. Oleic Acid✓
Explanation: Oleic acid is a mono-unsaturated omega-9 fatty acid found in various animal and vegetable sources.
Why the other options are wrong
- A. Stearic acid is a saturated fatty acid with an 18-carbon chain. The IUPAC name is octadecanoic acid.
- B. Palmitic acid is a fatty acid with a 16-carbon chain. It is the most common saturated fatty acid found in animals, plants and microorganisms.
- C. Butyric Acid is a saturated short-chain fatty acid with a 4-carbon backbone. Butyric acid is commonly found in esterified form in animal fats and plant oils.
Q105. When we extract Carotenoids from its source we see that it is:
- A. Violet in color
- B. Blue green in color
- C. Yellow green in color
- D. Yellow to orange red in color✓
Explanation: Carotenoids also called tetraterpenoids, are yellow, orange, and red organic pigments that are produced by plants and algae, as well as several bacteria, and fungi.
Why the other options are wrong
- A. It is incorrect. Carotenoids are not violet. Violet in plants is present in vacuoles due to anthocyanin.
- B. It is incorrect. Carotenoids do not appear blue or green.
- C. It is incorrect. While some carotenoids can have a slightly yellowish hue, they are predominantly in the yellow to orange-red range.
Q106. When two or more alleles do not show complete dominance or both the alleles are expressing independently in heterozygotic conditions. Such a condition is called:
- A. Complete dominance
- B. Over-dominance
- C. Codominance✓
- D. Incomplete dominance
Explanation: Codominance, as it relates to genetics, refers to a type of inheritance in which two versions (alleles) of the same gene are expressed separately to yield different traits in an individual.
Why the other options are wrong
- A. Complete dominance is a form of dominance where in the dominant allele completely masks the effect of the recessive allele in heterozygous conditions. A gene (or allele) shows dominance when it suppresses the expression — or dominates the effects — of the recessive gene (or allele).
- B. In overdominance, the heterozygote produced by two homozygous parents show a phenotype that is more pronounced than that of the parents.
- D. Incomplete dominance is a form of Gene interaction in which both alleles of a gene at a locus are partially expressed, often resulting in an intermediate or different phenotype. It is also known as partial dominance.
Q107. Taste buds on the tongue are example of:
- A. Thermoreceptors
- B. Photoreceptors
- C. Mechanoreceptors
- D. Chemoreceptors✓
Explanation: The taste receptors are located around the small structures known as papillae found on the upper surface of the tongue; these are chemoreceptors. Taste receptors are proteins located on taste receptor cells within taste buds that bind to chemical compounds in food, initiating signals that the brain interprets as the basic tastes: sweet, salty, sour, bitter, and umami. These receptors are located on the microvilli that project from the taste cells into the taste pore, where they interact with food molecules, ultimately transmitting taste information to the brain via nerves.
Why the other options are wrong
- A. These are present in the skin dermis for the detection of changes in temperature. They include a ruffini ending for heat and Krause end bulbs for cold.
- B. These are receptors present in the eyes for the detection of light. For example, rods and cone cells in the retina.
- C. Mechanoreceptors are specialized sensory receptors that respond to mechanical stimuli such as touch, pressure, vibration, and stretch. They are responsible for detecting and transmitting information related to mechanical forces and changes in the environment.
Q108. Which of the following hormones acts on the uterus wall for thickening?
- A. Progesterone✓
- B. Zona pellucida
- C. Follicle stimulating hormone
- D. Oxytocin
Explanation: The hormone that acts on the uterus wall (endometrium) for thickening is progesterone. Progesterone is a steroid hormone that plays a key role in the menstrual cycle and the preparation of the uterus for potential pregnancy. During the menstrual cycle, after ovulation occurs, the ruptured follicle transforms into a structure called the corpus luteum. The corpus luteum is responsible for producing progesterone. Progesterone acts on the endometrial lining of the uterus to prepare it for the possible implantation of a fertilized egg.
Why the other options are wrong
- B. Zona pellucida is the thick transparent membrane surrounding a mammalian ovum before implantation.
- C. In women, FSH helps control the menstrual cycle and stimulates the growth of eggs in the ovaries. FSH levels in women change throughout the menstrual cycle, with the highest levels happening just before an egg is released by the ovary.
- D. The two main actions of oxytocin in the body are contraction of the womb (uterus) during childbirth and lactation.
Q109. If concentration time graph of a reactant indicates a constant half life, then the order reaction with respect to that reactant is:
- A. Zero order
- B. Half order
- C. Second order
- D. First order✓
Explanation: In First order reactions, the graph represents the half-life is different from zero order reaction in a way that the slope continually decreases as time progresses until it reaches zero. We can also easily see that the length of half-life will be constant, independent of concentration. For example, it takes the same amount of time for the concentration to decrease from one point to another point. The half-life of zero order reaction decreases as the concentration decreases. The half life of second order reactions increases as the concentration increases.
Why the other options are wrong
- A. If the concentration-time graph of a reactant indicates a constant half-life, the reaction is a first-order reaction with respect to that reactant. In first-order reactions, the half-life remains constant, and the rate of the reaction is directly proportional to the concentration of the reactant. Therefore this option is not correct.
- B. If the concentration-time graph of a reactant indicates a constant half-life, the reaction is a first-order reaction with respect to that reactant. In first-order reactions, the half-life remains constant, and the rate of the reaction is directly proportional to the concentration of the reactant. Therefore this option is not correct.
- C. If the concentration-time graph of a reactant indicates a constant half-life, the reaction is a first-order reaction with respect to that reactant. In first-order reactions, the half-life remains constant, and the rate of the reaction is directly proportional to the concentration of the reactant. Therefore this option is not correct.
Q110. Which of the following catalysts is used in the below reaction?
- A. Conc. H2SO4✓
- B. Pumice stone
- C. Pt
- D. Ni
Explanation: Esterification process is a slow process when it is performed at room temperature also the process does not complete at all in the room temperature. So to complete the process of esterification there should be something to complete the process as well as to speed up the process. Thus concentrated sulphuric acid is added. It is a catalyst which will speed up the process and esterification will proceed speedily and complete on time. Also concentrated sulphuric acid has a property to remove water. Therefore it also acts as a dehydrating agent. After adding this will take reaction in the equilibrium position and will be able to give a greater yield of ester as result.
Why the other options are wrong
- B. Incorrect. Pumice stone is an abrasive material and does not possess catalytic properties relevant to the esterification process, making it ineffective in this context.
- C. Incorrect. Platinum is a metal catalyst that is primarily used in hydrogenation and oxidation reactions, but it is not commonly used for esterification reactions, which specifically require acid catalysts.
- D. Incorrect. Nickel is another transition metal used mainly in hydrogenation reactions. It does not facilitate the esterification process, which is better served by acids like concentrated sulfuric acid.
Q111. Halothane is a halo derivative of:
- A. Methane
- B. Ethane✓
- C. Methanol
- D. Ethanol
Explanation: The chemical Formula for Halothane is F3CCHBRCI, which is a derivative of the chemical formula of Ethane (C2H6).
Why the other options are wrong
- A. The chemical Formula for Halothane is F3CCHBRCI, which is a derivative of the chemical formula of Ethane (C2H6)
- C. The chemical Formula for Halothane is F3CCHBRCI, which is a derivative of the chemical formula of Ethane (C2H6)
- D. The chemical Formula for Halothane is F3CCHBRCI, which is a derivative of the chemical formula of Ethane (C2H6)
Q112. The species which are produced by heterolytic bond breaking and can act as electron pair donors are known as:
- A. Nucleophiles✓
- B. Cations
- C. Free radicals
- D. Anions
Explanation: A nucleophile is a chemical species that donates an electron pair to form a chemical bond in relation to a reaction. Heterolytic bond cleavage (heterolytic cleavage; heterolysis): Bond breaking in which the bonding electron pair is split unevenly between the products. Heterolytic cleavage often produces at least one ion.Cation is a positively charged ion.Anion is a negatively charged ion.A free radical is an atom, molecule, or ion that has an unpaired valence electron.
Why the other options are wrong
- B. Cation is a positively charged ion.
- C. A free radical is an atom, molecule, or ion that has an unpaired valence electron.
- D. Anion is a negatively charged ion.
Q113. The product of the concentrations of each ion in a saturated solution of a sparingly soluble salt at 298 K, raised to the power of their relative concentrations, is the:
- A. Ksp✓
- B. Ka
- C. Kw
- D. Kb
Explanation: This is the definition of the solubility product constant (Ksp ). It represents the equilibrium constant for the dissolution of a sparingly soluble ionic compound into its constituent ions in a saturated solution.
Why the other options are wrong
- B. An acid dissociation constant (Ka ) is a quantitative measure of the strength of an acid in solution
- C. The equilibrium constant, Kw, is called the dissociation constant or ionization constant of water.
- D. Kb is the base dissociation constant. The base dissociation constant is a measure of how completely a base dissociates into its component ions in water. The equilibrium constant, Kw, is called the dissociation constant or ionization constant of water.
Q114. The catalyst used for the manufacture of H2SO4 by contact process is:
- A. SO3
- B. V2O5✓
- C. Fe2O3
- D. Pt/Pd
Explanation: The contact process is one of the most common methods of forming Sulphuric acid. In this process not only Sulphuric acid is formed, but Oleum and Sulphur trioxide is also formed.First, Sulphur dioxide and oxygen are combined in a 1:1 ratio. And it is then treated with the catalyst Vanadium pentoxide at a temperature between (400-450)° and pressure. This converts the Sulphur dioxide into Sulphur trioxide Now this Sulphur trioxide formed is reacted with Sulphuric acid in order to dilute it. In this process Oleum is formed. This Oleum formed is then diluted with water to ultimately yield Sulphuric acid:Therefore, the catalyst used in making the contact process is Vanadium pentoxide.
Why the other options are wrong
- A. The catalyst used for the manufacture of H2SO4 (sulfuric acid) by the contact process is vanadium(V) oxide, often represented as V₂O₅. Therefore this option is not correct.
- C. The catalyst used for the manufacture of H2SO4 (sulfuric acid) by the contact process is vanadium(V) oxide, often represented as V₂O₅. Therefore this option is not correct.
- D. The catalyst used for the manufacture of H2SO4 (sulfuric acid) by the contact process is vanadium(V) oxide, often represented as V₂O₅. Therefore this option is not correct.
Q115. Ligands having two lone pair of electrons for donation to the central transition metal ion are known as:
- A. Polydentate ligands
- B. Monodentate ligand
- C. Bidentate ligands✓
- D. Hexadentate ligands
Explanation: Bidentate ligands have two lone pairs, both of which can bond to the central metal ion. Monodentate ligand is a ligand that has only one atom that coordinates directly to the central atom in a complex. A polydentate ligand is a ligand that is attached to a central metal ion by bonds from two or more donor atoms. A hexadentate ligand in coordination chemistry is a ligand that combines with a central metal atom with six bonds.
Why the other options are wrong
- A. Polydentate ligand is attached to a central metal ion by bonds from two or more donor atoms. EDTA, a hexadentate ligand, is an example of a polydentate ligand that has six donor atoms with electron pairs that can be used to bond to a central metal atom or ion.
- B. Monodentate ligands are Lewis bases that donate a single pair ("mono") of electrons to a metal atom. Monodentate ligands can be either ions (usually anions) or neutral molecules.
- D. A hexadentate ligand in coordination chemistry is a ligand that combines with a central metal atom with six bonds.
Q116. The stability in the following structure is due to the:
- A. Disulphide bridges
- B. Weak Van Der Waal's forces
- C. Presence of unpaired electron in the structure.
- D. Hydrogen bonding between NH group of one peptide and CO group of another peptide.✓
Explanation: Residue in the given structure of alpha helix is due to the hydrogen bonding between the NH group of one peptide and carbonyl (C=O) of another peptide residue
Why the other options are wrong
- A. Disulphide bridges are strong covalent bonds formed between cysteine residues, providing structural support. However, they are not the primary stabilizing force in the context of the question.
- B. Van der Waals forces are indeed weak intermolecular attractions that can contribute to molecular stability, but they lack the strength needed to explain the specific stability mentioned in the context of hydrogen bonding.
- C. The presence of unpaired electrons typically refers to free radicals, which can introduce instability rather than contribute to structural stability in peptide chains.
Q117. Which is the structure of polyvinyl chloride (polychloroethane)?
- A. [CCl2-CCl2]
- B. [HCCl-CH-Cl]
- C. [H2C=CH-Cl]
- D. [H2C-CH-Cl]✓
Explanation: Poly(vinyl chloride) (PVC) is a synthetic resin made from vinyl chloride and is a member of a large family of polymers broadly referred to as “vinyls.” The chemical formula for vinyl chloride is H2C=CHCl, and the formula for PVC is (H2C–CHCl)n, where n is the degree of polymerization.
Why the other options are wrong
- A. This is incorrect. This structure would represent polytetrachloroethylene rather than polyvinyl chloride (PVC).
- B. This is incorrect. This structure suggests that both carbon atoms have a chlorine substituent, which is not the case for PVC.
- C. This is incorrect. This represents vinyl chloride (chloroethene), which is the monomer used to form polyvinyl chloride (PVC) but is not the polymer structure itself.
Q118. Nylon-6,6 is also called:
- A. Poly styrene
- B. Polyester
- C. Polyamide✓
- D. Polyvinyl alcohol
Explanation: Nylon-6,6 is a synthetic polymer called a polyamide because of the characteristic monomers of amides in the backbone chainPolystyrene is a plastic. It is made up of many styrenes. Styrene is a small organic compound with the chemical formula C6H5CH=CH2.Polyester is a synthetic fabric that's usually derived from petroleum. This fabric is one of the world's most popular textiles, and it is used in thousands of different consumer and industrial applications. Chemically, polyester is a polymer primarily composed of compounds within the ester functional group.Poly is a water-soluble synthetic polymer. It has the idealized formula [CH₂CH]ₙ.
Why the other options are wrong
- A. Polystyrene is a plastic. It is made up of many styrenes. Styrene is a small organic compound with the chemical formula C6H5CH=CH2.
- B. Polyester is a synthetic fabric that's usually derived from petroleum. This fabric is one of the world's most popular textiles, and it is used in thousands of different consumer and industrial applications. Chemically, polyester is a polymer primarily composed of compounds within the ester functional group.
- D. PVA is partially crystalline upon formation and is characterised by properties such as chemical resistance, water solubility, and biodegradability. The similarity in physical properties makes it compatible with human tissues.
Q119. Which compound will be produced by the oxidation of ethanal by acidified K2Cr2O7 ?
- A. Ethene
- B. Ethanol
- C. Ethanoic acid✓
- D. Ethanone
Explanation: Aldehyde when undergoes oxidation reaction in presence of acidified potassium dichromate or alkaline potassium permanganate forms carboxylic acid as a product.
Why the other options are wrong
- A. Aldehyde when undergoing oxidation reaction in presence of acidified potassium dichromate or alkaline potassium permanganate forms carboxylic acid as a product.
- B. Aldehyde when undergoing oxidation reaction in presence of acidified potassium dichromate or alkaline potassium permanganate forms carboxylic acid as a product.
- D. Aldehyde when undergoing oxidation reaction in presence of acidified potassium dichromate or alkaline potassium permanganate forms carboxylic acid as a product.
Q120. Alcohol in which carbon atom bonded to OH group is further attached with three alkyl group is:
- A. Tertiary alcohol✓
- B. Primary alcohol
- C. Aromatic alcohol
- D. Secondary alcohol
Explanation: A tertiary (3°) alcohol is one in which the carbon atom with the OH group is attached to three other carbon atoms. Its general formula is R3COHPrimary alcohols are those alcohols where the carbon atom of the hydroxyl group (OH) is attached to only one single alkyl group.The aromatic alcohols or aryl-alcohols are a class of chemical compounds containing a hydroxyl group (—OH) bonded directly to an aromatic hydrocarbon group.A secondary alcohol is a compound in which a hydroxyl group( ‒OH) is attached to a saturated carbon atom which has two other carbon atoms attached to it.
Why the other options are wrong
- B. Primary alcohols are those alcohols where the carbon atom of the hydroxyl group (OH) is attached to only one single alkyl group.
- C. The aromatic alcohols or aryl- alcohols are a class of chemical compounds containing a hydroxyl group (-OH) bonded directly to an aromatic hydrocarbon group.
- D. A secondary alcohol is a compound in which a hydroxyl group(-OH) is attached to a saturated carbon atom which has two other carbon atoms attached to it.
Q121. The following sketch shows the variation in a physical property of third period elements against their atomic numbers: What physical property is plotted in this sketch?
- A. Ionization energy
- B. Melting point✓
- C. Ionic radius
- D. Atomic radius
Explanation: Na, Mg, Al, Si are all GIANT LATTICE structures involving either metallic (Na, Mg, Al) or giant covalent macromolecule (Si) bonding. Whereas, P, S, Cl are COVALENT MOLECULES, with Ar being a monatomic nonmetal gas. Melting is achieved by disrupting the considerably weaker van der Waals intermolecular forces that exist between the molecules. Melting point steadily increases between Na and Al due to: increased metal cation charge (more protons), more delocalised e− per atom, smaller sized metal ions, hence stronger electrostatic attraction between cations and delocalised e− therefore stronger metallic bonding. Silicon has a significantly higher melting point because Silicon is a giant covalent macromolecule. In order to melt Silicon there is a need to break down many strong covalent bonds between Si atoms, that can only be achieved by applying considerable energy. Melting point of S8 > P4 > Cl2 > Ar because there is decreasing strength of vdW intermolecular forces of attraction as there is a decreasing size of molecule. This explanation is based on the known correlation between molecular size (molecular mass) and magnitude of vdW force of attraction between molecules.
Why the other options are wrong
- A. The ionization energy is a measure of the capability of an element to enter into chemical reactions requiring ion formation or donation of electrons. It is also generally related to the nature of the chemical bonding in the compounds formed by the elements. See also binding energy; electron affinity.
- C. The atomic radius of a chemical element is a measure of the size of its atom, usually the mean or typical distance from the center of the nucleus to the outermost isolated electron. Since the boundary is not a well-defined physical entity, there are various non-equivalent definitions of atomic radius
- D. The atomic radius of a chemical element is a measure of the size of its atom, usually the mean or typical distance from the center of the nucleus to the outermost isolated electron. Since the boundary is not a well-defined physical entity, there are various non-equivalent definitions of atomic radius.
Q122. The standard electrode potential of hydrogen is arbitrarily taken at 298 K is _
- A. 0.00 volt✓
- B. 0.10 volt
- C. 10.0 volt
- D. 1.00 volt
Explanation: SHE is a redox electrode which forms the basis of oxidation-reduction potential. The standard electrode potential value of hydrogen is declared to be zero.
Why the other options are wrong
- B. The standard electrode potential value of hydrogen is declared to be zero.
- C. The standard electrode potential value of hydrogen is declared to be zero.
- D. The standard electrode potential value of hydrogen is declared to be zero.
Q123. The potential difference of an electrochemical cell is measured by:
- A. Ammeter
- B. Voltmeter✓
- C. Galvanometer
- D. Calorimeter
Explanation: A voltmeter is an instrument used for measuring the electric potential difference between two points in an electric circuit. An ammeter (from an ampere meter) is a measuring instrument used to measure the current in a circuit. A galvanometer is an electromechanical instrument used for detecting and indicating an electric current. A calorimeter is an object used for calorimetry or the process of measuring the heat of chemical reactions or physical changes as well as heat capacity.
Why the other options are wrong
- A. An ammeter (from an ampere meter) is a measuring instrument used to measure the current in a circuit.
- C. A galvanometer is an electromechanical instrument used for detecting and indicating an electric current.
- D. A calorimeter is an object used for calorimetry or the process of measuring the heat of chemical reactions or physical changes as well as heat capacity.
Q124. Which of the following acts as a nucleophile in the reaction of alkyl halide with alcoholic / aqueous ammonia?
- A. H+
- B. NH3✓
- C. NO2+
- D. Br-
Explanation: Since ammonia is nucleophilic, it attacks the electropositive carbon and causes the Br- ion to leave, this allows for the formation of amines as a result of this reaction.
Why the other options are wrong
- A. A proton (H⁺) is an electrophile, not a nucleophile, as it accepts electrons rather than donating them.
- C. Nitronium ion (NO₂⁺) is an electrophile, not a nucleophile, as it lacks electrons to donate.
- D. Bromide ion (Br⁻) is a nucleophile, but in the reaction of alkyl halides with ammonia, NH₃ is the active nucleophile, not Br⁻.
Q125. The liquid in the container has a temperature of 70°C. What will be the temperature on the Kelvin scale?
- A. 350 K
- B. 343 K✓
- C. 300 K
- D. 283 K
Explanation: To convert temperature from celsius to kelvin scale the formula is°C + 273.15 K 70° + 273.15 =343 K.
Why the other options are wrong
- A. To convert temperature from celsius to kelvin scale the formula is°C + 273.15 K 70° + 273.15 =343 K.
- C. According to the solution, this is not the correct option.To convert temperature from celsius to kelvin scale the formula is°C + 273.15 K 70° + 273.15 =343 K.
- D. According to the solution, this is not the correct option. To convert temperature from celsius to kelvin scale the formula is°C + 273.15 K 70° + 273.15 =343 K.
Q126. The formula which shows the simplest whole number ratio for the atoms of different elements in a compound is:
- A. Ionic formula
- B. Structural formula
- C. Empirical formula✓
- D. Molecular formula
Explanation: The empirical formula of a chemical compound is the simplest positive integer ratio of atoms present in a compound.Ionic formula is the formula of an ionic compound.The structural formula of a chemical compound is a graphic representation of the molecular structure, showing how the atoms are possibly arranged in the real three-dimensional space.A molecular formula consists of the chemical symbols for the constituent elements followed by numeric subscripts describing the number of atoms of each element present in the molecule
Why the other options are wrong
- A. lonic formula is the formula of an ionic compound.
- B. The structural formula of a chemical compound is a graphic representation of the molecular structure, showing how the atoms are possibly arranged in the real three-dimensional space.
- D. A molecular formula consists of the chemical symbols for the constituent elements followed by numeric subscripts describing the number of atoms of each element present in the molecule.
Q127. Which one will act as a strong acid?
- A. Chloroethanoic acid
- B. Ethanoic acid
- C. Trichloroethanoic acid✓
- D. Dichloroethanoic acid
Explanation: Chloro groups cause an inductive effect(-I). i.e it is a withdrawing group because it is more electronegative than carbon to which it is attached. -Cl groups pull the bonded electrons from carbon and carbon in turn pulls the electron pair from hydrogen of -COOH group causing more electron deficiency on hydrogen. hydrogen becomes more partially positive hence more acidic. greater the withdrawing effect greater will be polarity and acidity. Since trichloro substituted acetic acid has greater no. of withdrawing groups (3 chloro groups)so it will be more polar and more acidic.
Why the other options are wrong
- A. False.Chloro groups cause an inductive effect(-I). i.e it is a withdrawing group because it is more electronegative than carbon to which it is attached. -Cl groups pull the bonded electrons from carbon and carbon in turn pulls the electron pair from hydrogen of -COOH group causing more electron deficiency on hydrogen. hydrogen becomes more partially positive hence more acidic. greater the withdrawing effect greater will be polarity and acidity. Since trichloro substituted acetic acid has greater no. of withdrawing groups (3 chloro groups)so it will be more polar and more acidic.
- B. False.Chloro groups cause an inductive effect(-I). i.e it is a withdrawing group because it is more electronegative than carbon to which it is attached. -Cl groups pull the bonded electrons from carbon and carbon in turn pulls the electron pair from hydrogen of -COOH group causing more electron deficiency on hydrogen. hydrogen becomes more partially positive hence more acidic. greater the withdrawing effect greater will be polarity and acidity. Since trichloro substituted acetic acid has greater no. of withdrawing groups (3 chloro groups)so it will be more polar and more acidic.
- D. False.Chloro groups cause an inductive effect(-I). i.e it is a withdrawing group because it is more electronegative than carbon to which it is attached. -Cl groups pull the bonded electrons from carbon and carbon in turn pulls the electron pair from hydrogen of -COOH group causing more electron deficiency on hydrogen. hydrogen becomes more partially positive hence more acidic. greater the withdrawing effect greater will be polarity and acidity. Since trichloro substituted acetic acid has greater no. of withdrawing groups (3 chloro groups)so it will be more polar and more acidic.
Q128. The shape of [Co(NH3)6]3+ complex is:
- A. Linear
- B. Square planar
- C. Tetrahedral
- D. Octahedral✓
Explanation: The cobalt ion is in +3 oxidation state and has an electronic configuration of 3d6. Six pairs of electrons, one from each ammonia molecule, occupy the six hybrid orbitals, hence the molecule is diamagnetic and octahedral in shape.
Why the other options are wrong
- A. As per the explanation, this option is incorrect. In [Co (NH3)6]3+, Co is in +3 oxidation state with the configuration 3d6. In the presence of NH3 a strong ligand, the 3d electrons pair up leaving two d-orbitals empty. Hence, the hybridization is d2sp3 forming an inner orbital octahedral complex.
- B. As per the explanation, this option is incorrect. In [Co (NH3)6]3+, Co is in +3 oxidation state with the configuration 3d6. In the presence of NH3 a strong ligand, the 3d electrons pair up leaving two d-orbitals empty. Hence, the hybridization is d2sp3 forming an inner orbital octahedral complex.
- C. As per the explanation, this option is incorrect.In [Co (NH3)6]3+, Co is in +3 oxidation state with the configuration 3d6. In the presence of NH3 a strong ligand, the 3d electrons pair up leaving two d-orbitals empty. Hence, the hybridization is d2sp3 forming an inner orbital octahedral complex.
Q129. Amino acids react with each other such that -COOH group of one amino acid reacts with the -NH2 group of another amino acid to give a condensed structure as shown below. What is the name of the circled part of this structure?
- A. Ester linkage
- B. Peptide linkage✓
- C. Carbide linkage
- D. Azide linkage
Explanation: A peptide linkage is a chemical bond formed between two molecules when the carboxyl group of one molecule reacts with the amino group of the other molecule, releasing a molecule of water (H2O) to form —CONH—. In an ester molecule, the bond connecting the atom doubly bonded to oxygen and the oxygen atom bearing the alkyl or aryl group is called the ester bond or, in biochemistry, ester linkage. ester linkage.
Why the other options are wrong
- A. Ester linkage: An ester linkage involves a carbon atom bonded to an oxygen atom, which is also bonded to another carbon atom (R-COO-R'). This is not the type of linkage shown in the image.
- C. This term is not relevant in the context of amino acid structures. Carbides typically refer to compounds of carbon with a less electronegative element.
- D. An azide group contains three nitrogen atoms (N3). This is not the type of linkage shown in the image.
Q130. 3.0 mole of Calcium will contain _ g of Calcium.
- A. 105 g
- B. 120 g✓
- C. 80 g
- D. 100 g
Explanation: Moles of Calcium = 3Molar mass of Calcium (Ca) = 40Mass of Calcium in grams = ?Moles = Mass/Molar massMass = Moles × Molar massMass = 3 x 40 → Mass 120g
Why the other options are wrong
- A. Moles of Calcium = 3Molar mass of Calcium (Ca) = 40Mass of Calcium in grams = ?Moles = Mass / Molar massMass = Moles × Molar massMass = 3 x 40 → Mass 120g
- C. Moles of Calcium = 3Molar mass of Calcium (Ca) = 40Mass of Calcium in grams = ?Moles = Mass / Molar massMass = Moles × Molar massMass = 3 x 40 → Mass 120g
- D. Moles of Calcium = 3Molar mass of Calcium (Ca) = 40Mass of Calcium in grams = ?Moles = Mass / Molar massMass = Moles × Molar massMass = 3 x 40 → Mass 120g
Q131. Which of the following is the correct equation to calculate the relative molecular mass of a gas?
- A. M = mPR / VT
- B. M = PV / mRT
- C. M = mPRT / V
- D. M = mRT / PV✓
Explanation: Since PV=NRT where n = m / MPV=MRT / MM=mRT / PV.
Why the other options are wrong
- A. Since PV=NRT where n = m / MPV=MRT / MM=mRT / PV.
- B. Since PV=NRT where n = m / MPV=MRT / MM=mRT / PV.
- C. Since PV=NRT where n = m / MPV=MRT / MM=mRT / PV.
Q132. Reaction of water with quicklime results in the rise in the temperature of the system. Using the concept of an energy change, indicates the nature of the reaction?
- A. Endothermic Reaction
- B. Non-Spontaneous Reaction
- C. Third Order Reaction
- D. Exothermic Reaction✓
Explanation: Calcium oxide reacts with water to form calcium hydroxide, also called slaked lime. Here are the for this reaction: Calcium oxide + water → calcium hydroxide CaO+H2O → Ca(OH)2 A lot of heat is produced in the reaction, which may even cause the water to boil. Hence it is a combination reaction as well as exothermic reaction.
Why the other options are wrong
- A. This type of reaction absorbs heat from the surroundings, resulting in a decrease in temperature. Since the reaction of water with quicklime (CaO) leads to a rise in temperature, it is not endothermic.
- B. Non-spontaneous reactions do not occur on their own and require external energy to proceed. The reaction of water with quicklime is spontaneous because it releases heat, indicating that it happens naturally without the need for external energy input.
- C. This refers to the order of a chemical reaction based on the rate law, which is unrelated to whether the reaction is exothermic or endothermic. The rise in temperature here indicates the nature of the energy change, not the order of the reaction.
Q133. Which one of the following compounds act as a catalyst when alcohols react with carboxylic acids.
- A. Pt
- B. Conc. HNO3
- C. Ni
- D. Conc. H2SO4✓
Explanation: When a carboxylic acid is treated with an alcohol and an acid catalyst (Conc H2SO4), an ester is formed (along with water).
Why the other options are wrong
- A. Option A) Pt: Platinum (Pt) is not typically used as a catalyst in the reaction between alcohols and carboxylic acids.
- B. Option B) Conc. HNO3: Concentrated nitric acid (HNO3) is not commonly used as a catalyst in this specific reaction.
- C. When alcohols react with carboxylic acids, the compound that acts as a catalyst is concentrated sulfuric acid (option D). Concentrated sulfuric acid helps facilitate the reaction by providing protons (H+) to initiate the reaction between the alcohol and carboxylic acid.
Q134. In Period 2 and Period 3 maximum melting point shown by elements:
- A. Nitrogen and Phosphorus
- B. Neon and Argon
- C. Lithium and Sodium
- D. Carbon and Silicon✓
Explanation: So in periods two and three, the highest melting point elements tend to be the metal elements with the most delocalized electrons.In period 2, Carbon has the highest melting point, whereas in period 3 silicon has the highest melting point.
Why the other options are wrong
- A. So in periods two and three, the highest melting point elements tend to be the metal elements with the most delocalized electrons.In period 2, Carbon has the highest melting point, whereas in period 3 silicon has the highest melting point.
- B. So in periods two and three, the highest melting point elements tend to be the metal elements with the most delocalized electrons.In period 2, Carbon has the highest melting point, whereas in period 3 silicon has the highest melting point.
- C. So in periods two and three, the highest melting point elements tend to be the metal elements with the most delocalized electrons.In period 2, Carbon has the highest melting point, whereas in period 3 silicon has the highest melting point.
Q135. Which one of the following reagents is used to distinguish between aldehydes and ketones?
- A. Alkaline Iodine
- B. Tollen’s Reagent✓
- C. Bromine
- D. 2, 4 DNPH
Explanation: The Tollens' test is a reaction that is used to distinguish aldehydes from ketones, as aldehydes are able to be oxidized into a carboxylic acid while ketones cannot.Alkaline iodine is used in the iodoform test. When Iodine and sodium hydroxide are added to a compound that contains either a methyl ketone or a secondary alcohol with a methyl group in the alpha position, a pale yellow precipitate of iodoform or triiodomethane is formed. It can be used to identify aldehydes or ketones.A solution of bromine in CH2CL2 is used to either test for unsaturation or to check the ability to be oxidized for example in aldehydes. Bromine solution is naturally orange and when consumed in oxidation, it becomes colourless.2, 4 DNPH is used to detect ketones and aldehydes. A positive test is signalled by the formation of a yellow, orange or red precipitate of the dinitrophenylhydrazone.
Why the other options are wrong
- A. Alkaline iodine is used in the iodoform test. When iodine and sodium hydroxide are added to a compound that contains either a methyl ketone or a secondary alcohol with a methyl group in the alpha position, a pale yellow precipitate of iodoform or triiodomethane is formed. It can be used to identify aldehydes or ketones.
- C. A solution of bromine in CH2CL2 is used to either test for unsaturation or to check the ability to be oxidised for example in aldehydes. Bromine solution is naturally orange and when consumed in oxidation, it becomes colourless.
- D. 2, 4 DNPH is used to detect ketones and aldehydes. A positive test is signalled by the formation of a yellow, orange or red precipitate of the dinitrophenylhydrazone.
Q136. Gas is enclosed in a container of 20 cm3 with a moving piston. According to the kinetic theory of gases, what will be the effect on freely moving molecules of the gas if the temperature is increased from 20 oC to 100 oC?
- A. Pressure will become one half
- B. The volume will be increased✓
- C. Temperature has no effect on freely moving molecules
- D. Colliding capability of molecule will become lower
Explanation: According to Charles's law, the volume occupied by a fixed amount of gas is directly proportional to its absolute temperature, if the pressure remains constant. Since the piston is movable, hence increased temperature causes the volume to be increased.
Why the other options are wrong
- A. This is not consistent with the kinetic theory. An increase in temperature typically leads to an increase in pressure.
- C. This is incorrect. Temperature has a significant effect on the kinetic energy of gas molecules.
- D. This is not consistent with the kinetic theory. An increase in temperature typically leads to an increase in the kinetic energy and, consequently, an increase in the colliding capability of gas molecules.
Q137. Which of these pollutants is produced by burning of coal and causes acid rain:
- A. NO
- B. CO2
- C. SO2✓
- D. CO
Explanation: SO2 is emitted by the burning of fossil fuels — coal, oil, and diesel. SO2 and other sulfur oxides can contribute to acid rain which can harm sensitive ecosystems.Nitrogen oxides are produced in combustion processes, partly from nitrogen compounds in the fuel, but mostly by direct combination of atmospheric oxygen and nitrogen in flames. They also contribute to acid rain.CO2 is a product of combustion reaction and is a greenhouse gas.Carbon monoxide (CO)—a colorless, odorless, tasteless, and toxic air pollutant—is produced in the incomplete combustion of carbon-containing fuels, such as gasoline, natural gas, oil, coal, and wood. It can cause carbon monoxide poisoning.
Why the other options are wrong
- A. Nitrogen oxides are produced in combustion processes, partly from nitrogen compounds in the fuel, but mostly by direct combination of atmospheric oxygen and nitrogen in flames. They also contribute to acid rain.
- B. CO2 is a product of combustion reaction and is a greenhouse gas.
- D. Carbon monoxide (CO)—a colourless, odourless, tasteless, and toxic air pollutant is produced in the incomplete combustion of carbon-containing fuels, such as gasoline, natural gas, oil, coal, and wood. It can cause carbon monoxide poisoning.
Q138. Role of a catalyst in a chemical reaction is to:
- A. Increase rate of a reaction✓
- B. Decrease rate of reaction
- C. Decrease yield of a reactant
- D. Increase yield of product
Explanation: A positive catalyst increase rate of reaction, decreases activation energy, decrease equilibrium time and changes mechanism of reaction.
Why the other options are wrong
- B. It increases the rate of reaction by lowering activation energy. A catalyst is a chemical substance which helps to increase the rate of the reaction. - It makes the reaction proceed faster by adjusting the activation energy of that reaction or by changing the mechanism of the reaction. - It does not get consumed by itself in the reaction.
- C. It only increases rate of reaction.
- D. It only increases rate of reaction. A catalyst is a chemical substance which helps to increase the rate of the reaction. - It makes the reaction proceed faster by adjusting the activation energy of that reaction or by changing the mechanism of the reaction. - It does not get consumed by itself in the reaction.
Q139. The essential property of a fertilizer is that is should be:
- A. Immiscible
- B. Highly soluble✓
- C. Insoluble
- D. Partially soluble
Explanation: There are three essential plant nutrients for healthy growth: nitrogen (N), phosphorous (P), potassium (K). Fertilisers contain one or more of these nutrients and different crops require different proportions of each of the three. For the fertiliser to be effective, it must be soluble so that it can reach the plant’s roots.
Why the other options are wrong
- A. There are three essential plant nutrients for healthy growth: nitrogen (N), phosphorous (P), potassium (K). Fertilisers contain one or more of these nutrients and different crops require different proportions of each of the three. For the fertiliser to be effective, it must be soluble so that it can reach the plant’s roots.
- C. There are three essential plant nutrients for healthy growth: nitrogen (N), phosphorous (P), potassium (K). Fertilisers contain one or more of these nutrients and different crops require different proportions of each of the three. For the fertiliser to be effective, it must be soluble so that it can reach the plant’s roots.
- D. There are three essential plant nutrients for healthy growth: nitrogen (N), phosphorous (P), potassium (K). Fertilisers contain one or more of these nutrients and different crops require different proportions of each of the three. For the fertiliser to be effective, it must be soluble so that it can reach the plant’s roots.
Q140. Which option shows all the molecules with bond angle 109.5 degrees:
- A. CH4 , NH4+ , PH3
- B. SiCl4 , H2O , BeCl2
- C. SiCl4 , NH4+ , CH4✓
- D. CH4 , CCl4 , NH3
Explanation: Since all molecules stated in option C are tetrahedral in shape, where a central atom is located at the center with four substituents that are located at the corners of a tetrahedron. Hence they all have bond angles that are 109.5 degrees.
Why the other options are wrong
- A. Methane and ammonium ion have bond angles of 109.5o but phosphine has bond angle of 93o
- B. SiCl4 has bond angle 109.5o but H2O has 104.5o and BeCl2 has 180o
- D. The bond angles in these molecules are influenced by their molecular geometries:Methane (CH₄)-Bond Angle: Approximately 109.5 degrees-The four hydrogen atoms around the central carbon atom are arranged in a tetrahedral shape, leading to bond angles close to 109.5 degrees.Carbon Tetrachloride (CCl₄)-Bond Angle: Approximately 109.5 degrees-Similar to methane, carbon tetrachloride adopts a tetrahedral geometry, resulting in bond angles around 109.5 degrees.Ammonia (NH₃)-Bond Angle: Approximately 107 degrees-The nitrogen atom in ammonia is bonded to three hydrogen atoms, creating a trigonal pyramidal shape. The bond angle is slightly less than the ideal tetrahedral angle due to the presence of a lone pair on nitrogen, which exerts a greater repulsion than bonding pairs.These bond angles are influenced by the arrangement of electron pairs around the central atom and follow the principles of valence shell electron pair repulsion (VSEPR) theory. Therefore this option is not correct.
Q141. Down the group acid-base behaviour of metallic oxides of group 2 elements changes to:
- A. More basic✓
- B. No change
- C. Less basic
- D. More acidic
Explanation: Group II metal oxides become more basic as you go down the column. As the electronegativities of the metals decrease down the group, hence the change in electronegativity difference between the metal and oxygen increases down the group. The greater the difference in electronegativity the more ionic the metal-oxygen bond becomes. The more ionic the metal-oxygen bond the more basic the oxide is.
Why the other options are wrong
- B. This option is incorrect as the further you go down the group the acid base character of metallic oxides change towards more basic.
- C. This option is incorrect as the further you go down the group the acid base character of metallic oxides change towards more basic.
- D. This option is incorrect as the further you go down the group the acid base character of metallic oxides change towards more basic.
Q142. Butane molecules can have a maximum number of isomers.
- A. 5
- B. 3
- C. 4
- D. 2✓
Explanation: Butane is an alkane with four carbon atoms so the molecular formula is C4H10. It has two isomers; n-butane and isobutane.
Why the other options are wrong
- A. Butane has 2 isomers therefore it is incorrect.
- B. Butane has 2 isomers therefore it is incorrect.
- C. Butane has 2 isomers therefore it is incorrect.
Q143. Select one which is alcohol.
- A. CH3 - CH2 - Br
- B. CH3 - O - CH3
- C. CH3COOH
- D. CH3 - CH2 - OH✓
Explanation: An alcohol is an organic compound that carries at least one hydroxyl functional group (−OH) bound to a saturated carbon atom, hence CH3-CH2-OH is an alcohol. CH3-CH2-Br is an example of an alkyl halide (also known as haloalkanes) which are compounds in which one or more hydrogen atoms in an alkane have been replaced by halogen atoms (fluorine, chlorine, bromine or iodine). Ethers are a class of organic compounds that contain an ether group—an oxygen atom connected to two alkyl or aryl groups. They have the general formula R–O–R′, where R and R′ represent the alkyl or aryl groups. Therefore CH3-O-CH3 is an ether. CH3COOH is a carboxylic acid that is an organic acid which contains a carboxyl group (C(=O)OH) attached to an R-group. The general formula of a carboxylic acid is R–COOH, with R referring to the alkyl, alkenyl, aryl, or other group.
Why the other options are wrong
- A. CH3-CH2-Br is an example of an alkyl halide (also known as haloalkanes) which are compounds in which one or more hydrogen atoms in an alkane have been replaced by halogen atoms (fluorine, chlorine, bromine or iodine).
- B. Ethers are a class of organic compounds that contain an ether group-an oxygen atom connected to two alkyl or aryl groups. They have the general formula R-O-R', where R and R' represent the alkyl or aryl groups. Therefore CH3-O-CH3 is an ether.
- C. CH3COOH is a carboxylic acid that is an organic acid which contains a carboxyl group (C(=O)OH) attached to an R- group. The general formula of a carboxylic acid is R-COOH, with R referring to the alkyl, alkenyl, aryl, or other group.
Q144. Which is the correct electronic configuration of Chromium (24Cr)?
- A. 1s2, 2s2, 3s2, 2p6, 3p6, 4s2, 3d6
- B. 1s2, 2s2, 2p6, 3s2, 3p6, 4s2, 3d4
- C. 1s1, 2s2, 2p6, 3s2, 3p6, 3d6
- D. 1s2, 2s2, 2p6, 3s2, 3p6, 4s1, 3d5✓
Explanation: The atomic number of chromium = 24. Cr (Z = 24) = 1s2, 2s2 2p6 3s2 3p6 4s1 3d5
Why the other options are wrong
- A. This is not the electronic configuration of chromium.Its electronic configuration in ground state is 1s2 2s2 2p6 3s2 3p6 4s1 3d5.
- B. This option is also incorrect.Its electronic configuration in ground state is 1s2 2s2 2p6 3s2 3p6 4s1 3d5.
- C. This option is also incorrect.Its electronic configuration in ground state is 1s2 2s2 2p6 3s2 3p6 4s1 3d5.
Q145. Which one of the following is the structure of Teflon?
- A. (-CF2-CF2-)n✓
- B. (-CF2-CCl2-)n
- C. (-CH2-CH2-)n
- D. (-CF2-CH2-)n
Explanation: Teflon is a synthetic polymer containing carbon and fluorine called polytetrafluoroethylene. Its formula is (C2F4)n.
Why the other options are wrong
- B. The polymer represented by (-CF2-CCl2-)n is commonly known as poly(chlorotrifluoroethylene) or PCTFE. It is a fluoropolymer that exhibits excellent chemical resistance, high thermal stability, and low friction properties. PCTFE is used in various applications such as coatings, films, gaskets, and seals due to its exceptional resistance to chemicals and extreme temperatures.
- C. The polymer represented by (-CH2-CH2-)n is commonly known as polyethylene, which is one of the most widely used polymers. Polyethylene has a range of applications due to its excellent physical and chemical properties, including its flexibility, low density, chemical resistance, and electrical insulation properties. It is used in various industries for packaging materials, plastic bags, containers, pipes, and many other everyday products.
- D. The polymer represented by (-CF2-CH2-)n can be classified as a fluorinated polymer. The incorporation of fluorine atoms into the polymer chain can impart unique properties such as chemical resistance, low surface energy, and thermal stability. These polymers find applications in various fields, including coatings, lubricants, electrical insulation, and membranes.
Q146. Which one of the following enthalpy changes is always exothermic?
- A. Enthalpy of combustion✓
- B. Enthalpy of formation
- C. Enthalpy of atomization
- D. Enthalpy of solution
Explanation: Combustion is an oxidation reaction that produces heat, and it is therefore always exothermic. Since these reactions are exothermic so the value for the enthalpy change (ΔH) is always negative
Why the other options are wrong
- B. The enthalpy of formation is the standard reaction enthalpy for the formation of the compound from its elements (atoms or molecules) in their most stable reference states at the chosen temperature (298.15K).It may be both exothermic & endothermic.
- C. Enthalpy of atomization is the change in enthalpy when one mole of bonds is completely broken to obtain atoms in the gas phase. For example: atomization of methane molecule.It is always endothermic.
- D. Enthalpies of solution may be either positive or negative - in other words, some ionic substances dissolve endothermically (for example, NaCl); others dissolve exothermically (for example NaOH).
Q147. While finding the relative atomic mass, which of the following standard is used to compare the atomic mass of chlorine (35.5 amu):
- A. Carbon - 13
- B. Neon - 20
- C. Carbon - 12✓
- D. Nucleon number
Explanation: By international agreement in 1961 for determining atomic masses, carbon-12 a distinct atom of carbon was chosen as standard with its atomic mass 12.00 atomic mass unit. It is defined as 1/12 the mass of an atom of carbon-12. Masses of all other atoms are determined relative to the mass of an atom of carbon 12. Relative atomic mass equals the average mass of all the atoms in an element compared to 1/12 the mass of a carbon-12. Carbon-12 is the standard while measuring the atomic masses. Because no other nuclides other than carbon-12 have exactly whole-number masses in this scale.
Why the other options are wrong
- A. By international agreement in 1961 for determining atomic masses, carbon-12, a distinct atom of carbon, was chosen as standard with its atomic mass 12.00 atomic mass unit. It is defined as 1/12 the mass of an atom of carbon-12. Masses of all other atoms are determined relative to the mass of an atom of carbon 12. Relative atomic mass equals the average mass of all the atoms in an element compared to 1/12 the mass of a carbon-12. Carbon-12 is the standard while measuring the atomic masses. Because no other nuclides other than carbon- 12 have exactly whole-number masses in this scale.
- B. By international agreement in 1961 for determining atomic masses, carbon-12, a distinct atom of carbon, was chosen as standard with its atomic mass 12.00 atomic mass unit. It is defined as 1/12 the mass of an atom of carbon-12. Masses of all other atoms are determined relative to the mass of an atom of carbon 12. Relative atomic mass equals the average mass of all the atoms in an element compared to 1/12 the mass of a carbon-12. Carbon-12 is the standard while measuring the atomic masses. Because no other nuclides other than carbon- 12 have exactly whole-number masses in this scale.
- D. By international agreement in 1961 for determining atomic masses, carbon-12, a distinct atom of carbon, was chosen as standard with its atomic mass 12.00 atomic mass unit. It is defined as 1/12 the mass of an atom of carbon-12. Masses of all other atoms are determined relative to the mass of an atom of carbon 12. Relative atomic mass equals the average mass of all the atoms in an element compared to 1/12 the mass of a carbon-12. Carbon-12 is the standard while measuring the atomic masses. Because no other nuclides other than carbon- 12 have exactly whole-number masses in this scale.
Q148. Which compound is obtained by the elimination of bromopropane?
- A. Propene✓
- B. Ether
- C. Aldehyde
- D. Ester
Explanation: In the elimination reaction involving 2-bromopropane and hydroxide ions. 2-bromopropane is heated under reflux with a concentrated solution of sodium or potassium hydroxide in ethanol. The resulting re-arrangement of the electrons expels the bromine as a bromide ion and produces propene.
Why the other options are wrong
- B. In the elimination reaction involving 2-bromopropane and hydroxide ions. 2-bromopropane is heated under reflux with a concentrated solution of sodium or potassium hydroxide in ethanol. The resulting re- arrangement of the electrons expels the bromine as a bromide ion and produces propene.
- C. In the elimination reaction involving 2-bromopropane and hydroxide ions. 2-bromopropane is heated under reflux with a concentrated solution of sodium or potassium hydroxide in ethanol. The resulting re- arrangement of the electrons expels the bromine as a bromide ion and produces propene.
- D. In the elimination reaction involving 2-bromopropane and hydroxide ions. 2-bromopropane is heated under reflux with a concentrated solution of sodium or potassium hydroxide in ethanol. The resulting re- arrangement of the electrons expels the bromine as a bromide ion and produces propene.
Q149. Which product is formed by the reaction of carboxylic acid with alcohol?
- A. Alkane
- B. Ether
- C. Aldehyde
- D. Ester✓
Explanation: When primary alcohol is treated with a carboxylic acid in the presence of sulphuric acid a compound is formed. This compound has a sweet smell. The compound obtained is called ester. The chemical reaction occurring in the formation of the ester is known as esterification reaction.
Why the other options are wrong
- A. False.When primary alcohol is treated with a carboxylic acid in the presence of sulphuric acid a compound is formed. This compound has a sweet smell. The compound obtained is called ester. The chemical reaction occurring in the formation of the ester is known as esterification reaction.
- B. False.When primary alcohol is treated with a carboxylic acid in the presence of sulphuric acid a compound is formed. This compound has a sweet smell. The compound obtained is called ester. The chemical reaction occurring in the formation of the ester is known as esterification reaction.
- C. False.When primary alcohol is treated with a carboxylic acid in the presence of sulphuric acid a compound is formed. This compound has a sweet smell. The compound obtained is called ester. The chemical reaction occurring in the formation of the ester is known as esterification reaction.
Q150. In an aqueous solution, amino acids exist in an ionic form as shown below. This ionic form of amino acid is known as:
- A. Zwitter ion✓
- B. Amphoteric ion
- C. Cation
- D. Anion
Explanation: A zwitter ion is a compound with no overall electrical charge, but which contains separate parts which are positively and negatively charged. In an aqueous solution, the carboxyl group can lose a proton (becomes a basic group) and the amino group can accept a proton (becomes acidic) giving rise to the dipolar ion known as zwitter ion. An amphoteric compound is a molecule or ion that can react both as an acid and as a base.
Why the other options are wrong
- B. An amphoteric compound is a molecule or ion that can react both as an acid and as a base.
- C. Cation is a positively charged specie. The given image shows a specie with both positive and negative ends making this option incorrect.
- D. Anion is a negatively charged specie. The given image shows a specie with both positive and negative ends making this option incorrect.
Q151. Reaction mechanism of alkanes with halogens is known as;
- A. Propagation
- B. Free radical substitution✓
- C. Addition
- D. Elimination
Explanation: Halogenation of alkanes means the substitution of a halogen atom(s) by the removal of one or more hydrogen atoms in the alkane. The mechanism of halogenations occurs in three steps: chain initiation, chain propagation, and chain termination.The order of reactivity of the halogens towards the halogenations reaction of alkanes as follows: F2> Cl2> Br2> I2.The iodination reaction is reversible as follows:CH4+I2⇌CH3−I+HI.
Why the other options are wrong
- A. The 2nd step of halogenation is known as propagation so this option is incorrect.
- C. In halogenation, the addition takes place but the mentioned step is free radical substitution
- D. This is not the correct option as the mention step is free radical substitution.
Q152. Why is it necessary to distill aldehyde formed from oxidation of primary alcohol through acidified potassium dichromate (VI) solution or acidified sodium dichromate (VI) solution?
- A. Aldehyde formed may be oxidized further to carboxylic acid concerned✓
- B. Aldehyde formed is unstable and decompose back to original precursor i.e. primary alcohol
- C. Aldehyde may be oxidised further to a ketone
- D. Aldehyde formed may react with primary alcohol, the original reactant.
Explanation: Aldehyde formed may be oxidized further to carboxylic acid Primary alcohols oxidized with acidified K2 Cr2O7/Na2Cr2O7 can form aldehydes. Aldehydes are easily further oxidized to carboxylic acids in the same reaction mixture. Distillation removes the aldehyde immediately, preventing over- oxidation.
Why the other options are wrong
- B. Oxidation of alcohols to aldehydes is partial oxidation, if aldehydes are further oxidized they form carboxylic acids. Therefore, the conditions required for making aldehydes are heat and distillation.
- C. Oxidation of alcohols to aldehydes is partial oxidation, if aldehydes are further oxidized they form carboxylic acids. Therefore, the conditions required for making aldehydes are heat and distillation.
- D. Oxidation of alcohols to aldehydes is partial oxidation, if aldehydes are further oxidized they form carboxylic acids. Therefore, the conditions required for making aldehydes are heat and distillation.
Q153. Electron affinity of the atom is the energy released when:
- A. Covalent bond of molecule is broken.
- B. Electron is added to gaseous atom.✓
- C. Electron is removed from gaseous atom.
- D. Covalent bond is formed between the atoms.
Explanation: The electron affinity (Eea) of an atom or molecule is defined as the amount of energy released when an electron is attached to a neutral atom or molecule in the gaseous state to form a negative ion.
Why the other options are wrong
- A. Electron affinity of an atom is the energy released when an electron is added to a neutral atom to form a negative ion (anion). It is a measure of how much the atom "likes" to gain an electron. Therefore this option is not correct.
- C. Electron affinity of an atom is the energy released when an electron is added to a neutral atom to form a negative ion (anion). It is a measure of how much the atom "likes" to gain an electron. Therefore this option is not correct.
- D. Electron affinity of an atom is the energy released when an electron is added to a neutral atom to form a negative ion (anion). It is a measure of how much the atom "likes" to gain an electron. Therefore this option is not correct.
Q154. Which mechanism of reactions is shown by carbonyl compounds?
- A. Electrophilic addition
- B. Electrophilic substitution
- C. Free radical substitution
- D. Nucleophilic addition✓
Explanation: The main reactions of the carbonyl group are nucleophilic additions to the carbon‐oxygen double bond. This addition consists of adding a nucleophile and a hydrogen across the carbon‐oxygen double bond. An electrophilic addition reaction is an addition reaction where, in a chemical compound, a π bond is broken and two new σ bonds are formed. The substrate of an electrophilic addition reaction must have a double bond or triple bond. Electrophilic substitution reactions are chemical reactions in which an electrophile displaces a functional group in a compound. Free radicals are atoms or groups of atoms which have a single unpaired electron. A free radical substitution reaction is one involving these radicals. Free radicals are formed if a bond splits evenly - each atom getting one of the two electrons. The name given to this is homolytic fission.
Why the other options are wrong
- A. An electrophilic addition reaction is an addition reaction where, in a chemical compound, a π bond is broken and two new o bonds are formed. The substrate of an electrophilic addition reaction must have a double bond or triple bond.
- B. Electrophilic substitution reactions are chemical reactions in which an electrophile displaces a functional group in a compound.
- C. Free radicals are atoms or groups of atoms which have a single unpaired electron. A free radical substitution reaction is one involving these radicals. Free radicals are formed if a bond splits evenly - each atom getting one of the two electrons. The name given to this is homolytic fission.
Q155. Which of the following compounds is solid at room temperature?
- A. Ethanol
- B. Butane
- C. Methanol
- D. Phenol✓
Explanation: Phenols occur as white solids at room temperature and may be highly toxic and caustic.
Why the other options are wrong
- A. At room temperature ethanol and methanol are both liquid.
- B. At room temperature ethanol and methanol are both liquid.
- C. Butane is a gas at room temperature and atmospheric pressure.
Q156. Halogens are being used as fire extinguishers, mild antiseptic CFCs and many other organic chemicals, Which of the following halogen is used to kill the bacteria in drinking water.
- A. Bromine
- B. Fluorine
- C. Chlorine✓
- D. Iodine
Explanation: One of the easiest and cost effective way to clean water is to add some amount of chlorine into it. But if chlorine is added in excess then the water becomes unfit for consumption. So, when chlorinated water from treatment plants is disposed into rivers etc then it becomes harmful for aquatic species as excess of chlorinated water can lead to death of living beings. Hence, chlorine must be removed from water before releasing the water from water treatment plants into rivers, lakes or oceans.
Why the other options are wrong
- A. Bromine is not typically used for disinfection of drinking water. It is more commonly employed in hot tubs and swimming pools as a disinfectant.
- B. Fluorine gas is not used for disinfection of drinking water. Fluoride, an ion derived from fluorine, is sometimes added to drinking water, but for dental health rather than as a disinfectant.
- D. Iodine is used for disinfection, but it is less common in the treatment of drinking water. It is sometimes used in camping or emergency situations where other disinfection methods are not readily available.
Q157. Which of the following acts as an electrophile in the electrophilic substitution of benzene with bromine?
- A. Br+✓
- B. FeCl4+
- C. Fe2+
- D. Fe3+
Explanation: Benzene reacts with bromine in an electrophilic substitution reaction, but only in the presence of a catalyst to yield bromobenzene. As a bromine molecule approaches the benzene ring, the delocalised electrons in the ring repel electrons in the bromine-bromine bond. It is the slightly positive end of the bromine molecule which acts as the electrophile. The presence of the aluminium chloride helps this polarisation.
Why the other options are wrong
- B. FeCl4- is an electrophile in acylation of benzene.Therefore it is incorrect.
- C. It is not an electrophile.Therefore this option is incorrect.
- D. Fe3+ is not an electrophile in this reaction.Therefore it is incorrect.
Q158. According to Lowry - Bronsted Acid & Base Concept, H2O is:
- A. An acid
- B. A base
- C. An amphoteric species✓
- D. A salt
Explanation: Water is an example of an amphiprotic substance. This means it is able to donate a proton or accept a proton. The Bronsted/Lowry theory defines an acid or base by how they behave in a chemical reaction. Depending on what water reacts with it can act as an acid (proton donor) or a base (proton acceptor).
Why the other options are wrong
- A. Water is an example of an amphiprotic substance. This means it is able to donate a proton or accept a proton. The Bronsted/Lowry theory defines an acid or base by how they behave in a chemical reaction. Depending on what water reacts with it can act as an acid (proton donor) or a base (proton acceptor).
- B. Water is an example of an amphiprotic substance. This means it is able to donate a proton or accept a proton. The Bronsted/Lowry theory defines an acid or base by how they behave in a chemical reaction. Depending on what water reacts with it can act as an acid (proton donor) or a base (proton acceptor).
- D. Water is an example of an amphiprotic substance. This means it is able to donate a proton or accept a proton. The Bronsted/Lowry theory defines an acid or base by how they behave in a chemical reaction. Depending on what water reacts with it can act as an acid (proton donor) or a base (proton acceptor).
Q159. Which one of the following compounds is known as tertiary alcohol?
- A. 1 - Propanol
- B. 2- methyl - 2- propanol✓
- C. 2- methyl - 1- propanol
- D. 2 - propanol
Explanation: 2-methyl-2-propanol / tert-Butyl alcohol, also called tert-butanol or t-butanol, is the simplest tertiary alcohol, with a formula of (CH₃)₃COH.
Why the other options are wrong
- A. This is primary alcohol.
- C. Isobutanol, also known as iso-butyl alcohol or 2-methylpropanol, belongs to the class of organic compounds known as primary alcohols.
- D. 2-Propanol, or isopropyl alcohol, is a three-carbon alcohol with the OH group on the middle carbon. Isopropyl alcohol is a secondary alcohol
Q160. Which of the following molecules has the largest number of shared pairs of electrons?
- A. C2H4✓
- B. N2
- C. CO2
- D. NH3
Explanation: C2H4 has the largest number of shared electrons as it has 12 valence electrons in total which are all part of a shared pair (4 electrons between the two central carbons and 2 electrons each between 4 carbon-Hydrogen bonds).N2 has 3 shared pairs of electron (6 electrons in total)CO2 has 4 shared pairs of electrons (8 electrons in total).NH3 has 3 shared pairs of electrons. (6 electrons in total)
Why the other options are wrong
- B. N2 has 3 shared pairs of electron (6 electrons in total).
- C. CO2 has 4 shared pairs of electrons (8 electrons in total).
- D. NH3 has 3 shared pairs of electrons. (6 electrons in total).
Q161. Which of the following gas, when ignited, burns with a blue flame and is not very soluble in water?
- A. O2
- B. CO2
- C. N2✓
- D. He
Explanation: Firstly we should be clear that each gas has a specific type of flame depending on the nature of combustion and the products formed and so does all these gases which are given in the option. Nitrogen when ignited in the presence of oxygen it forms various oxides of nitrogen like NO, NO2 and burns with a blue flame.
Why the other options are wrong
- A. O2 does not burn with blue flame. It is partially soluble in water.
- B. CO2 burns with blue flame but is highly soluble in water.
- D. He burns with pinkish orange flame and is insoluble in water.
Q162. The dilute solution of _ is called vinegar.
- A. Formic acid
- B. Oxalic acid
- C. Benzoic acid
- D. Acetic acid✓
Explanation: A dilute (approximately 5 percent by volume) solution of acetic acid produced by fermentation and oxidation of natural carbohydrates is called vinegar.
Why the other options are wrong
- A. A dilute (approximately 5 percent by volume) solution of acetic acid produced by fermentation and oxidation of natural carbohydrates is called vinegar
- B. A dilute (approximately 5 percent by volume) solution of acetic acid produced by fermentation and oxidation of natural carbohydrates is called vinegar
- C. A dilute (approximately 5 percent by volume) solution of acetic acid produced by fermentation and oxidation of natural carbohydrates is called vinegar
Q163. Percentage of nitrogen by volume in air is:
- A. 78%✓
- B. 50%
- C. 20%
- D. 98%
Explanation: By volume, the dry air in Earth's atmosphere is about 78.08 percent nitrogen, 20.95 percent oxygen, and 0.93 percent argon. A brew of trace gases accounts for the other approximately 0.04 percent, including the greenhouse gases carbon dioxide, methane, nitrous oxide and ozone.
Why the other options are wrong
- B. By volume, the dry air in Earth's atmosphere is about 78.08 percent nitrogen, 20.95 percent oxygen, and 0.93 percent argon. A brew of trace gases accounts for the other approximately 0.04 percent, including the greenhouse gases carbon dioxide, methane, nitrous oxide and ozone.
- C. By volume, the dry air in Earth's atmosphere is about 78.08 percent nitrogen, 20.95 percent oxygen, and 0.93 percent argon. A brew of trace gases accounts for the other approximately 0.04 percent, including the greenhouse gases carbon dioxide, methane, nitrous oxide and ozone.
- D. By volume, the dry air in Earth's atmosphere is about 78.08 percent nitrogen, 20.95 percent oxygen, and 0.93 percent argon. A brew of trace gases accounts for the other approximately 0.04 percent, including the greenhouse gases carbon dioxide, methane, nitrous oxide and ozone.
Q164. Bromination of alkene is shown in the following reaction. This reaction is used for:
- A. Detection of ketones
- B. Detection of double bond✓
- C. Identification of Primary and Secondary alcohols
- D. Detection of Aldehydes
Explanation: The electrophilic addition of bromine to Alkenes in the cold with pure liquid bromine, or with a solution of bromine in an organic solvent like tetrachloromethane allows for a testing of double bonds. Presence of double bonds causes the bromine to turn from red to colourless.
Why the other options are wrong
- A. This reaction is used for detection of unsaturation.Therefore this option is incorrect.
- C. This reaction is used for detection of unsaturation of double bond.Therefore this option is incorrect.
- D. This reaction is used for detection of unsaturation of double bond.Therefore this option is incorrect.
Q165. The correct order of increasing reactivity of the following alkyl halides, (I) CH3CH2CH2Cl(II) CH3CH2CH2CH2Br(III) (CH3)2C(Cl)CH2CH3(IV) CH3CH2CH(Br)CH3Towards SN2 displacement is:
- A. I < II < III < IV
- B. III < I < IV < II✓
- C. III < I < II < IV
- D. II < IV < I < III
- E. I < III < II < IV
Explanation: The reactivity of alkyl halides towards SN2 depends on:(i) Degree of C-atoms Reactivity Order:1°>2°>3°(ii)More good the leaving group more will be reactivity of alkyl halide in SN2 since order of leaving group is I>Br>Cl>F Hence, correct order is: III<I<IV<||. Hence option B is correct.
Why the other options are wrong
- A. The reactivity of alkyl halides towards SN2 depends on(i) Degree of C-atoms Reactivity Order:1°>2°>3°(ii)More good the leaving group more will be reactivity of alkyl halide in SN2 since order of leaving group is I>Br>Cl>F Hence, correct order is:III<I<IV<|| Hence option B is correct.
- C. The reactivity of alkyl halides towards SN2 depends on(i) Degree of C-atoms Reactivity Order:1°>2°>3°(ii)More good the leaving group more will be reactivity of alkyl halide in SN2 since order of leaving group is I>Br>Cl>F Hence, correct order is:III<I<IV<|| Hence option B is correct.
- D. The reactivity of alkyl halides towards SN2 depends on(i) Degree of C-atoms Reactivity Order:1°>2°>3°(ii)More good the leaving group more will be reactivity of alkyl halide in SN2 since order of leaving group is I>Br>Cl>F Hence, correct order is:III<I<IV<|| Hence option B is correct.
- E. The reactivity of alkyl halides towards SN2 depends on(i) Degree of C-atoms Reactivity Order:1°>2°>3°(ii)More good the leaving group more will be reactivity of alkyl halide in SN2 since order of leaving group is I>Br>Cl>F Hence, correct order is:III<I<IV<|| Hence option B is correct.
Q166. Which of the following would react with ozone in the atmosphere?
- A. F*
- B. O2
- C. O*
- D. Cl*✓
Explanation: Chlorine and bromine atoms are also known as free radicals. Other free radicals in the stratosphere can also remove ozone. The chlorine atoms react with ozone to produce chlorine oxide and O2 molecules. The chlorine oxide molecule is also very reactive and can react with oxygen atoms to regenerate the chlorine atom, hence catalysing the destruction of the ozone layer.
Why the other options are wrong
- A. Fluorine radicals are highly reactive but are not typically found in significant quantities in the Earth's atmosphere. Fluorine is a reactive element, but its reactivity with ozone is not a common atmospheric process.
- B. Oxygen molecules (O2) are not reactive with ozone (O3) under normal atmospheric conditions. Ozone is a less stable allotrope of oxygen and can react with certain substances, but oxygen itself is not one of them.
- C. Oxygen radicals (O*) can react with ozone, but they are not as common in the atmosphere as other reactive species. Oxygen radicals can be formed in certain atmospheric processes, but they are not a primary reactant in ozone depletion reactions.
Q167. A 5 watt LED bulb converts 80% of the power into light photons wavelength 660 nm. What is the number of photons emitted from the bulb in one second.
- A. 5.8 x 1034
- B. 7.5 x 1018
- C. 6.6 x 107
- D. 1.3 x 1019✓
Explanation: Photon energy formula: E=hc/λ , where h is planck's constantλ =660nmc= 3*108 m/sh= 6.626 × 10-34 JsE=6.626*10-34 * 3*108 / 660*10-9 (Js*m/s/m = J)E=3.01*10-19J(per photon)Total energy= 1sec*5watt*80/100(efficiency) = 4 ws = 4JNo. of photons = Total energy/E = 4J/3.01*10-19J = 1.3*1019
Why the other options are wrong
- A. Photon energy formula: E=hc/^, where h is planck's constant, λ =660nmc= 3*108 m/sh= 6.626 x10-34 Js.E=6.626*10-34 ×3*108 ÷ 660*10-9(Js*m/s/m = J)E=3.01*10-19J(per photon)Total energy= 1 sec×5 watt×80/100(efficiency) =4 ws = 4JNo. of photons = Total energy/E= 4J/3.01*10-19J = 1.3*1019.
- B. Photon energy formula: E=hc/^, where h is planck's constant, λ =660nmc= 3*108 m/sh= 6.626 x10-34 Js.E=6.626*10-34 ×3*108 ÷ 660*10-9(Js*m/s/m = J)E=3.01*10-19J(per photon)Total energy= 1 sec×5 watt×80/100(efficiency) =4 ws = 4JNo. of photons = Total energy/E= 4J/3.01*10-19J = 1.3*1019.
- C. Photon energy formula: E=hc/^, where h is planck's constant, λ =660nmc= 3*108 m/sh= 6.626 x10-34 Js.E=6.626*10-34 ×3*108 ÷ 660*10-9(Js*m/s/m = J)E=3.01*10-19J(per photon)Total energy= 1 sec×5 watt×80/100(efficiency) =4 ws = 4JNo. of photons = Total energy/E= 4J/3.01*10-19J = 1.3*1019.
Q168. If Cv = 5/2 R, Cp will be:
- A. 2 / 5 R
- B. 2 / 7 R
- C. 5 / 2 R
- D. 7 / 2 R✓
Explanation: Since Cp - Cv = Rhence , X - 5/2 R = RX = 7/2 R
Why the other options are wrong
- A. This option is incorrect. The specific heat at constant pressure (Cp) is related to the specific heat at constant volume (Cv) by the equation: Cp=Cv+R for an ideal gas. Since Cv= 5/2R, adding R to 5/2R yields 7/2R, not 2/5R.
- B. This option is incorrect. Similar to option A,2/7R is not the correct expression for Cp. The specific heat at constant pressure is always greater than the specific heat at constant volume for an ideal gas due to the energy required to work against the external pressure during expansion.
- C. This option is incorrect because it presents Cp as being equal to Cv. However, Cp is always greater than Cv for an ideal gas due to the energy required to do work against the external pressure during expansion.
Q169. The rate at which work is being done is called:
- A. Power✓
- B. Energy
- C. Density
- D. Force
Explanation: The rate at which work is done is called power. It is expressed as the amount of work per unit of time.
Why the other options are wrong
- B. In physics, energy is the quantitative property that is transferred to a body or to a physical system, recognizable in the performance of work and in the form of heat and light.
- C. Density is the measurement of how tightly a material is packed together. It is defined as the mass per unit volume.
- D. A force can cause an object with mass to change its velocity, i.e., to accelerate.
Q170. What is the instantaneous power dissipated through a resistor of resistance 10 ohm if it is connected to an AC source of frequency 15 Hz at 1/180 sec if peak value is 20 V?
- A. 10 W✓
- B. 100 W
- C. 40 W
- D. Cannot be determined
Explanation: UsingVo = V sin(2𝜋ft) = 20 x sin (2𝜋 x 15 x 1/180) = 10 VUsingP = v2/ R = 102 / 10 = 10 W
Why the other options are wrong
- B. Using, Vo= V sin(2πft) = 20 x sin (2π x 15 x 1/180) =10 VUsing,P = v²/R = 102/ 10 = 10 W.
- C. Using, Vo= V sin(2πft) = 20 x sin (2π x 15 x 1/180) =10 VUsing,P = v²/R = 102/ 10 = 10 W.
- D. Using, Vo= V sin(2πft) = 20 x sin (2π x 15 x 1/180) =10 VUsing,P = v²/R = 102/ 10 = 10 W.
Q171. A signal of -80 mV is applied to the inverting terminal of the amplifier while the non-inverting terminal is grounded. The gain of the amplifier is 25 using Rin(R1) equal to 3 ohms and Rf(R2) equal to 75 Ohms. What would be the value of the output signal?
- A. 200 mV
- B. -3 V
- C. 2 V✓
- D. 3 V
Explanation: Since Gain = 25Vout = Vin * Gain = -80mv * 25 = -2000 mv = -2V = 2V**** since a positive-going voltage at the inverting terminal gives a negative-going output voltage, hence the answer is positive 2V.
Why the other options are wrong
- A. This option suggests that the output signal would be 200mV.However, based on the given gain of the amplifier (25) and the input signal (-80mV), the output signal will be greater than 200mV.Therefore, option A) 200mV is incorrect.
- B. This option suggests that the output signal would be -3V.However, based on the given gain of the amplifier (25) and the input signal (-80mV), the output signal will be a positive voltage.Therefore, option B) -3V is incorrect.
- D. This option suggests that the output signal would be 3V.However, based on the given gain of the amplifier (25) and the input signal (-80mV), the output signal will be less than 3V.Therefore, option D) 3V is incorrect.
Q172. When the frequency of the applied force becomes equal to one of natural frequencies of body then the body oscillates with maximum displacement this phenomenon is called:
- A. Heating
- B. Resonance✓
- C. Reverberation
- D. Damping
Explanation: Resonance describes the phenomenon of increased amplitude that occurs when the frequency of a periodically applied force is equal or close to a natural frequency of the system on which it acts.
Why the other options are wrong
- A. Heating refers to the process of increasing the temperature of an object or substance. It occurs when energy is transferred to the object, typically resulting in an increase in kinetic energy of its particles, leading to higher temperature. In the context of oscillations and resonance, heating may occur due to friction or other dissipative processes that convert mechanical energy into thermal energy.
- C. Reverberation refers to the persistence of sound in an enclosed space due to repeated reflections off surfaces. It is commonly experienced in rooms with hard and reflective surfaces, such as concert halls or empty rooms. Reverberation can affect the clarity and quality of sound, and it is often controlled or mitigated in acoustic design to optimize the acoustic environment.
- D. Damping is the process by which energy is dissipated or removed from a vibrating system, causing its amplitude to decrease over time. Damping can occur due to various factors such as friction, air resistance, or energy transfer to other modes of vibration. It is essential for controlling oscillations and preventing excessive vibration in mechanical systems. In the context of resonance, damping is necessary to prevent the system from oscillating uncontrollably at resonance frequencies.
Q173. Force is a derived quantity, its derived unit can be expressed in terms of the base units as:
- A. Kgms-2✓
- B. Kgcms-2
- C. Kgm2s2
- D. Kgms2
Explanation: The following is the solution:Since F=ma ,where m: mass in kg,a: acceleration in m/s²,F = Kgms-2 = Newton
Why the other options are wrong
- B. Incorrect as per the formulaThe following is the solution:Since F=ma ,where m: mass in kg,a: acceleration in m/s²,F = Kgms-2 = Newton
- C. Incorrect as per the formulaThe following is the solution:Since F=ma ,where m: mass in kg,a: acceleration in m/s²,F = Kgms-2 = Newton
- D. Incorrect as per the formulaThe following is the solution:Since F=ma ,where m: mass in kg,a: acceleration in m/s²,F = Kgms-2 = Newton
Q174. E/m of an electron is given by the relationship.
- A. e/m2(VB2r2)
- B. e/m=(V/Br)2
- C. e/m=V.r/B
- D. e/m=2V/B2r2✓
Explanation: The E/m (charge-to-mass ratio) of an electron is given by the formula:em=2V/B2r2where:e = charge of electronm = mass of electronV = accelerating potential (voltage)B = magnetic field strengthr = radius of the circular path of the electron👉 This relationship comes from balancing the centripetal force and magnetic force on an electron moving in a circular path.
Why the other options are wrong
- A. The E/m (charge-to-mass ratio) of an electron is given by the formula:em=2V/B2r2where:e = charge of electronm = mass of electronV = accelerating potential (voltage)B = magnetic field strengthr = radius of the circular path of the electron👉 This relationship comes from balancing the centripetal force and magnetic force on an electron moving in a circular path.
- B. The E/m (charge-to-mass ratio) of an electron is given by the formula:em=2V/B2r2where:e = charge of electronm = mass of electronV = accelerating potential (voltage)B = magnetic field strengthr = radius of the circular path of the electron👉 This relationship comes from balancing the centripetal force and magnetic force on an electron moving in a circular path.
- C. The E/m (charge-to-mass ratio) of an electron is given by the formula:em=2V/B2r2where:e = charge of electronm = mass of electronV = accelerating potential (voltage)B = magnetic field strengthr = radius of the circular path of the electron👉 This relationship comes from balancing the centripetal force and magnetic force on an electron moving in a circular path.
Q175. Lenz’s law in electromagnetic induction is the direct consequence of the principle of conservation of:
- A. Energy✓
- B. Charge
- C. Momentum
- D. Mass
Explanation: Lenz’s law is used to determine the direction of the induced current by a change in magnetic field. This direction of the induced current always opposes the direction of the magnetic field which produced it.Complete step by step answer:Lenz’s law states that the direction of an induced current by a changing magnetic field is such that the magnetic field created by the induced current opposes that change responsible for its production. This means, a change in magnetic field (B1) produces an induced current and the induce current also generates some magnetic field (B2) which is different from the initial magnetic field (B1). Now, the generated magnetic field (B2) by the induced current opposes the initial changing magnetic field (B1). Consider a magnet and a coil, such that the magnet is approaching towards the coil. When the north pole of a magnet is moved towards a coil, the face of the coil near to the magnet behaves like a north pole and tries to repel the approaching North Pole. To do this, the coil generates an anticlockwise current in itself. Here, we can see that electrical energy is not generated just by moving the magnet towards the coil. There is an opposite for the change in flux. Hence we can say that Lenz’s law is a consequence of conservation of energy. Thus, the right answer is Option A; Lenz’s law is a consequence of law of conservation of energy.
Why the other options are wrong
- B. Lenz’s law is a consequence of law of conservation of energy.
- C. Lenz’s law is a consequence of law of conservation of energy.
- D. Lenz’s law is a consequence of law of conservation of energy.
Q176. Which material will follow the below stress-strain curve?
- A. Copper
- B. Iron
- C. Lead
- D. Glass✓
Explanation: A stress-strain curve is a graphical way to show the reaction of a material when a load is applied. It shows a comparison between stress and strain.Brittle materials, which comprise cast iron, glass, and stone, are characterized by the fact that rupture occurs without any noticeable prior change in the rate of elongation. Thus, for brittle materials, there is no difference between the ultimate strength and the breaking strength.
Why the other options are wrong
- A. A stress-strain curve is a graphical way to show the reaction of a material when a load is applied. It shows a comparison between stress and strain.Brittle materials, which comprise cast iron, glass, and stone, are characterized by the fact that rupture occurs without any noticeable prior change in the rate of elongation. Thus, for brittle materials, there is no difference between the ultimate strength and the breaking strength.Hence this option is incorrect since the given graph represents brittle solids only.
- B. A stress-strain curve is a graphical way to show the reaction of a material when a load is applied. It shows a comparison between stress and strain.Brittle materials, which comprise cast iron, glass, and stone, are characterized by the fact that rupture occurs without any noticeable prior change in the rate of elongation. Thus, for brittle materials, there is no difference between the ultimate strength and the breaking strength.Hence this option is incorrect since the given graph represents brittle solids only.
- C. A stress-strain curve is a graphical way to show the reaction of a material when a load is applied. It shows a comparison between stress and strain.Brittle materials, which comprise cast iron, glass, and stone, are characterized by the fact that rupture occurs without any noticeable prior change in the rate of elongation. Thus, for brittle materials, there is no difference between the ultimate strength and the breaking strength.Hence this option is incorrect since the given graph represents brittle solids only.
Q177. A wheel starts rotating from the result with an angular acceleration of 2 rads-2 till its angular speed becomes 6 rad/s. The angular displacement of the wheel will be equal to:
- A. 4 rad
- B. 9 rad✓
- C. 12 rad
- D. 7 rad
Explanation: V = u + at6 = 0 + 2tt = 3 secondsØ = ut + 1/2at2Ø = 0 + 1/2 • 2 • 3²Ø = 9 radian.
Why the other options are wrong
- A. It is incorrect as per the given formula.Using 1st eq. of motion in rotatory termsV = u + at , where u=06=0+2tt = 3 secondsØ = ut + 1/2at²Ø= 0+1/2.2.32Ø = 9 radian
- C. It is incorrect as per the given formula. Using 1st eq. of motion in rotatory termsV = u + at , where u=06=0+2tt = 3 secondsØ = ut + 1/2at²Ø= 0+1/2.2.32Ø = 9 radian
- D. It is incorrect as per the given formula. Using 1st eq. of motion in rotatory termsV = u + at , where u=06=0+2tt = 3 secondsØ = ut + 1/2at²Ø= 0+1/2.2.32Ø = 9 radian
Q178. Coulomb's law is given by the formula:F=kq1 q2 / r2The magnitude of k having the unit of Nm2 C-2 for free space is equal to:
- A. 9 x 107
- B. 6 x 107
- C. 10 x 109
- D. 9 x 109✓
Explanation: The Coulomb constant, the electric force constant, or the electrostatic constant (denoted ke, k or K) is a proportionality constant in electrostatics equations. In SI units it is equal to 8.9875517923(14)×109 (9*109)kg⋅m3⋅s−2⋅C−2
Why the other options are wrong
- A. Incorrect as per formulaThe Coulomb constant, the electric force constant, or the electrostatic constant (denoted ke, k or K) is a proportionality constant in electrostatics equations.In SI units, the constant k has the value k = 9×109N ⋅ m2 /C2.
- B. Incorrect as per formulaThe Coulomb constant, the electric force constant, or the electrostatic constant (denoted ke, k or K) is a proportionality constant in electrostatics equations.In SI units, the constant k has the value k = 9×109N ⋅ m2 /C2.
- C. Incorrect as per formulaThe Coulomb constant, the electric force constant, or the electrostatic constant (denoted ke, k or K) is a proportionality constant in electrostatics equations.In SI units, the constant k has the value k = 9×109N ⋅ m2 /C2.
Q179. Simple Harmonic Motion of a body is described by which statements mentioned below:K: K.E is maximum when displacement x = 0L: P.E is maximum when x = 0M: P.E is maximum when x = ± x0
- A. K and L
- B. K and M✓
- C. K, L and M
- D. L and M
Explanation: Option B is the correct choice because it accurately describes the energy conditions in simple harmonic motion. Kinetic energy (K.E) reaches its maximum when the displacement is zero (x = 0), as the body is moving fastest through the equilibrium position. Potential energy (P.E), on the other hand, is maximum at the extreme positions (x = ± x0) because these are the points of maximum displacement from the equilibrium position. Option A is incorrect because it incorrectly states that potential energy is maximum at x = 0. Option C includes the same incorrect statement as Option A. Option D is incorrect for the same reason as it includes the incorrect statement that potential energy is maximum at x = 0.
Why the other options are wrong
- A. This option includes one correct and one incorrect statement. Kinetic energy is indeed maximum at displacement x = 0, but potential energy is not maximum at x = 0; it is minimum there. Therefore, this option is incorrect.
- C. This option incorrectly includes the statement that potential energy is maximum at x = 0, which contradicts the true nature of simple harmonic motion. Thus, this option is incorrect.
- D. This option is incorrect because it contains the incorrect statement that potential energy is maximum at x = 0, which is not true in simple harmonic motion.
Q180. Which of the following gives the relationship between linear velocity and angular velocity?
- A. v = rω✓
- B. v = rθ
- C. v=sω
- D. v=sθ
Explanation: The greater the rotation angle in a given amount of time, the greater the angular velocity. Angular velocity (ω) is analogous to linear velocity (v). We can write the relationship between linear velocity and angular velocity in two different ways: v=rω or ω=v/r.
Why the other options are wrong
- B. It is incorrect as per the given explanation.v = rθ. This formula is incorrect. While θ represents angular displacement, it doesn't directly relate to linear velocity in the same way angular velocity (ω) does.
- C. It is incorrect as per the given explanation. v = sω and v = sθ. These options are also incorrect. 's' typically represents arc length, and while related, these formulas don't accurately describe the fundamental relationship between linear and angular velocity.
- D. v = sω and v = sθ. These options are also incorrect. 's' typically represents arc length, and while related, these formulas don't accurately describe the fundamental relationship between linear and angular velocity.
Q181. A torch is rated 2.2 V 0.25 A. Calculate the charge passing through the bulb in one second and energy transferred by the passage of each coulomb of charge.
- A. 2.5 C and 0.55 J
- B. 0.25 C and 0.55 J✓
- C. 0.25 C and 2.2 V
- D. 2.25 V and 0.55 J
Explanation: Q= I*t = 0.25*1 = 0.25 CV = U/q U= V*q = 2.2V*0.25C = 0.55J
Why the other options are wrong
- A. Q= I×t = 0.25×1 = 0.25 CV=U/qU=V×q= 2.2V×0.25C = 0.55J.
- C. Q= I×t = 0.25×1 = 0.25 CV=U/qU=V×q= 2.2V×0.25C = 0.55J.
- D. Q= I×t = 0.25×1 = 0.25 CV=U/qU=V×q= 2.2V×0.25C = 0.55J.
Q182. Energy consumed by 60 watt bulb in 2 minutes is equal to:
- A. 7.2 kilo joules✓
- B. 720 joules
- C. 120 joules
- D. 72000 joules
Explanation: Power=Energy/time Energy=power ×time 60 watt×120 sec =7200 J =7.2 kilo J.
Why the other options are wrong
- B. Incorrect as per the formulaThe following is the solution:Power=Energy/timeEnergy=power ×time60 watt×120 sec =7200 J =7.2 kilo J.
- C. Incorrect as per the formulaThe following is the solution:Power=Energy/timeEnergy=power ×time60 watt×120 sec =7200 J =7.2 kilo J.
- D. Incorrect as per the formulaThe following is the solution:Power=Energy/timeEnergy=power ×time60 watt×120 sec =7200 J =7.2 kilo J.
Q183. If one mole of an ideal gas is heated at constant pressure, then the first law of thermodynamics can be written as:
- A. CpΔT = CvΔT + PΔV✓
- B. CvΔT = CpΔT + PΔV
- C. CpΔT = CvΔT + VΔP
- D. ΔCpT = ΔCvT + PΔV
Explanation: Heat supplied to the gas at constant pressure isΔQ=nCPΔTChange in internal energy,ΔU=nCVΔTChange in work done,ΔW = PΔVAccording to the first law of thermodynamicsΔQ=ΔU+ΔWnCPΔT= nCVΔT + PΔV
Why the other options are wrong
- B. This equation incorrectly represents the first law of thermodynamics. It seems to mix up the roles of Cp and Cv, and it incorrectly includes PΔV on both sides of the equation. This option is incorrect.
- C. This equation introduces the VΔP term, which is inconsistent with the first law of thermodynamics for an ideal gas heated at constant pressure. The correct term should involve PΔV instead of VΔP. This option is incorrect.
- D. This equation introduces changes in heat capacities (ΔCp and ΔCv) which is not relevant to the first law of thermodynamics for an ideal gas heated at constant pressure. It also incorrectly represents the relationship between heat capacities and the change in internal energy or enthalpy. This option is incorrect.
Q184. The de Broglie wavelength of an electron travelling with a speed of 1.0 x 107m/s is equal to, (h=6.6 x 10-34 Js and me= 9.1 x 10-31 kg)
- A. 7.3 x 1011 m
- B. 7.3 x 108 m
- C. 7.3 x 10-11 m✓
- D. 7.3 x 10-13 m
Explanation: De broglie wavelength of any particle: λ = h/p and p = mv ∴λ = h/mvλ = 6.6* 10-34 / (9.1*10-31*1.0*107)λ= 7.2527473e-11m
Why the other options are wrong
- A. De broglie wavelength of any particle: λ = h/p and p = mv ∴λ = h/mvλ = 6.6* 10-34 / (9.1*10-31*1.0*107)λ= 7.2527473e-11m
- B. De broglie wavelength of any particle: λ = h/p and p = mv ∴λ = h/mvλ = 6.6* 10-34 / (9.1*10-31*1.0*107)λ= 7.2527473e-11m
- D. De broglie wavelength of any particle: λ = h/p and p = mv ∴λ = h/mvλ = 6.6* 10-34 / (9.1*10-31*1.0*107)λ= 7.2527473e-11m
Q185. Find the mean translational kinetic energy of ideal hydrogen gas at 17 degrees Celsius.
- A. 6.21 x 10-21 J
- B. 5 x 10-21 J
- C. 6.21 x 10-12 J
- D. 6 x 10-21 J✓
Explanation: The mean translational kinetic energy of an ideal gas is calculated using the formula: K.E. = (3/2)kT, where k is Boltzmann's constant (approximately 1.38 x 10-23 J/K) and T is the absolute temperature in Kelvin. First, convert 17 degrees Celsius to Kelvin: T = 17 + 273.15 = 290.15 K. Plugging in the values:K.E. = (3/2)(1.38 x 10-23 J/K)(290.15 K) ≈ 6 x 10-21 J.This is the correct answer. The other options provide either significantly lower or higher values, indicating calculation errors or incorrect applications of the kinetic theory principles.
Why the other options are wrong
- A. This option is incorrect. This value is close to the correct answer, but not precise. It may be a result of rounding. The correct calculation should yield a slightly different value.
- B. This option is incorrect. It's significantly lower than the correct value obtained using the formula for mean translational kinetic energy, indicating a misunderstanding of the temperature's effect on speed and energy.
- C. This option is incorrect. It is several orders of magnitude higher than the correct value, suggesting a major calculation error or a misunderstanding of the ideal gas behavior.
Q186. Calculate the activity (decaying atom per unit time) of radioactive strontium - 90 having 6.7 x 1021 atoms at t = 0. Decay constant of strontium - 90 is 8.3 x 10-10 s-1
- A. 8.01 x 1010 Bq
- B. 5.6 x 1011 s-1
- C. 5.6 x 1012 Bq✓
- D. 12 x 1011 Bq
Explanation: A=λN0e(-λt)where λ = decay constantA= (8.3*10-10)* (6.7*1021) * (e) (-8.3 x 10-10*0) = 5.561 *1012
Why the other options are wrong
- A. A=λNo( λt)where λ = decay constant A= (8.3*10-10)×(6.7*1021) × (-8.3 x 10-10) = 5.561 *1012.
- B. A=λNo( λt)where λ = decay constant A= (8.3*10-10)×(6.7*1021) × (-8.3 x 10-10) = 5.561 *1012.
- D. A=λNo( λt)where λ = decay constant A= (8.3*10-10)×(6.7*1021) × (-8.3 x 10-10) = 5.561 *1012.
Q187. If the time period of the oscillation is 20 micro-sec, then what will be the frequency of that oscillating body?
- A. 5000 Hz
- B. 50000 Hz✓
- C. 20000 Hz
- D. 1000 Hz
Explanation: T=1/FT=1/20×10-6F = 50000 Hz.
Why the other options are wrong
- A. This option suggests that the frequency of the oscillating body is 5000 Hz. However, this is not correct.The frequency (f) of an oscillating body is defined as the reciprocal of its time period (T). In this case, if the time period is 20 microseconds (20×10−6seconds), then the frequency is 1/20×10−6=50,000Hz, not 5000 Hz.
- C. This option suggests that the frequency of the oscillating body is 20000 Hz. However, this is not correct.The frequency (f) of an oscillating body is defined as the reciprocal of its time period (T). In this case, if the time period is 20 microseconds (20×10−6seconds), then the frequency is 1/20×10−6=50,000Hz, not 20000 Hz.
- D. This option suggests that the frequency of the oscillating body is 1000 Hz. However, this is not correct.The frequency (f) of an oscillating body is defined as the reciprocal of its time period (T). In this case, if the time period is 20 microseconds (20×10−6seconds), then the frequency is 1/20×10−6=50,000Hz, not 1000 Hz.
Q188. In photo-emission from a metal, if light of λ is replaced by light of wavelength λ / 4 , the maximum kinetic energy of the photoelectrons.
- A. Decreases by an amount equal to half of an incident photon of wavelength λ
- B. Increases by an amount equal to four times energy of an incident photon of wavelength λ✓
- C. Increases by an amount equal to the work function of the metal
- D. Decreases by an amount equal to the energy of an incident photon of wavelength λ
Explanation: The maximum kinetic energy KEe of ejected electrons (photoelectrons) is given by KEe=hf−BE , where hf is the photon energy and BE is the binding energy (or work function) of the electron to the particular material.Since f = v/ λ when λ is replaced by λ/4 , f increases by 4 times and hence the energy of incident photons increases by 4 times.
Why the other options are wrong
- A. When the wavelength of the incident light is decreased to λ/4 the energy of each photon increases. The energy of a photon is directly proportional to its frequency and inversely proportional to its wavelength. So, if the wavelength decreases to λ/4 the energy of each photon increases by a factor of 4. When a photoelectron is emitted, it gains energy from absorbing a photon. Since each photon now carries four times the energy compared to before, the photoelectron would gain four times the energy compared to when the wavelength was λ Thus, the correct choice would involve an increase in kinetic energy, not a decrease.
- C. The work function represents the minimum energy required to eject an electron from the metal surface. However, changing the wavelength of the incident light doesn't change the work function of the metal. Therefore, this option doesn't accurately describe the effect of changing the wavelength of the incident light.
- D. This choice contradicts the fact that decreasing the wavelength of the incident light increases the energy of each photon, which in turn increases the kinetic energy of the emitted photoelectrons. So, this option is not correct.
Q189. A cyclist is travelling at 15 ms-1, she applies brakes so that she doesn't collide with the wall in front of her at a distance of 18 m. Calculate the magnitude of deceleration.
- A. 6.3 ms-2✓
- B. 5.3 ms-1
- C. 13 ms-1
- D. 12.5 ms-1
Explanation: Initial velocity, u=15m/sFinal velocity, v=0m/sDistance, s=18mAcceleration, a=?Using relation, v2 −u2 =2as02 −(15)2 =2a×18−225=36aa= 36 −225 =−6.25m/s2So, deceleration is 6.25m/s2 which is equal 6.3m/s2
Why the other options are wrong
- B. This is incorrect as per explanation.Initial velocity, J = 15m / sFinal velocity, v = 0m / sDistance, s = 18m, Acceleration, a=?Using relation, v2 - u2 = 2as 02 - (15)2= 2a×18- 225 = 36aa = -225/ 36 = - 6.25 m /s2So, deceleration is 6.25m/s² which is equal to 6.3m/s².
- C. This is incorrect as per explanation.Initial velocity, J = 15m / sFinal velocity, v = 0m / sDistance, s = 18m, Acceleration, a=?Using relation, v2 - u2 = 2as 02 - (15)2= 2a×18- 225 = 36aa = -225/ 36 = - 6.25 m /s2So, deceleration is 6.25m/s² which is equal to 6.3m/s².
- D. This is incorrect as per explanation.Initial velocity, J = 15m / sFinal velocity, v = 0m / sDistance, s = 18m, Acceleration, a=?Using relation, v2 - u2 = 2as 02 - (15)2= 2a×18- 225 = 36aa = -225/ 36 = - 6.25 m /s2So, deceleration is 6.25m/s² which is equal to 6.3m/s².
Q190. In a practical transformer mutual induction between primary and secondary coils takes place. In such transformer what can be deduced about the power.
- A. Power output = Power input
- B. Power output > Power input
- C. Power output ≥ Power input
- D. Power output < Power input✓
Explanation: The output power in a transformer is always less than the input power because of the different losses in a transformer. The losses may be Iron loss or core loss, hysteresis loss, eddy current loss, copper loss etc.
Why the other options are wrong
- A. The output power in a transformer is always less than the input power because of the different losses in a transformer. The losses may be Iron loss or core loss, hysteresis loss, eddy current loss, copper loss etc.
- B. The output power in a transformer is always less than the input power because of the different losses in a transformer. The losses may be Iron loss or core loss, hysteresis loss, eddy current loss, copper loss etc.
- C. The output power in a transformer is always less than the input power because of the different losses in a transformer. The losses may be Iron loss or core loss, hysteresis loss, eddy current loss, copper loss etc.
Q191. If slope of velocity time graph is not constant at different points then body is moving with:
- A. Uniform velocity
- B. changing acceleration✓
- C. Average acceleration
- D. Constant acceleration
Explanation: Since the slope of the velocity time graph represents the acceleration of the body, hence a changing slope of the graph means that the acceleration is also changing.
Why the other options are wrong
- A. If a body is moving with uniform velocity (i.e., velocity remains constant with respect to time), the velocity-time graph is a straight line parallel to the time axis.
- C. From a particle's velocity-time graph, its average velocity can be found by calculating the total area under the graph and then dividing it by the corresponding time-interval. For a particle with uniform acceleration, the velocity-time graph is a straight line.
- D. If a particle is moving under constant acceleration, then the velocity –time graph is a straight line passing through the origin.
Q192. Electric potential due to 2uC charge at distance of one meter is equal to:
- A. 18 x 104 volt
- B. 1.8 x 106 volt
- C. 1.8 x 109 volt
- D. 1.8 x 104 volt✓
Explanation: V=KQ/r where K= coulomb's constantV=(9*109)*(2*10-6)/1 = 18000 volts = 1.8*104
Why the other options are wrong
- A. Incorrect as per formulaV=KQ/r where K= coulomb's constantV=(9*109)*(2*10-6)/1 = 18000 volts = 1.8*104
- B. Incorrect as per formulaV=KQ/r where K= coulomb's constantV=(9*109)*(2*10-6)/1 = 18000 volts = 1.8*104
- C. Incorrect as per formulaV=KQ/r where K= coulomb's constantV=(9*109)*(2*10-6)/1 = 18000 volts = 1.8*104
Q193. Kirchhoff's first law is manifestation of:
- A. Law of conservation of momentum
- B. Law of conservation mass
- C. Law of conservation of energy
- D. Law of conservation of charge✓
Explanation: Kirchhoff's first law states that the algebraic sum of current flowing into a junction is zero. This rule corresponds to conservation of charge which states that total charge in a closed system remains constant because current is the rate of flow of charge.
Why the other options are wrong
- A. This law states that the total linear momentum of an isolated system remains constant if no external forces act on it. Kirchhoff's first law is not related to the conservation of momentum; it primarily deals with the conservation of electric charge in a circuit.
- B. This law states that the mass of a closed system remains constant over time. Kirchhoff's first law is not related to the conservation of mass; it specifically addresses the conservation of electric charge in electrical circuits.
- C. This law states that energy cannot be created or destroyed, only converted from one form to another. Kirchhoff's first law is not directly related to the conservation of energy; instead, it deals with the conservation of charge.
Q194. Light photons, each of energy 3.5 x 10-19J falls on the cathode of a photocell. The current through the cell is reduced to zero by taking the cathode to a potential +0.25 V relative to anode. The work function of the cathode is:
- A. 3.35 x 10-19 J
- B. 3.5 x 10-19 J
- C. 3.25 x 10-19 J
- D. 3.1 x 10-19 J✓
Explanation: Explanation is given below.
Why the other options are wrong
- A. This option is incorrect as per the calculationsusing the following formula:Φ = E - KEWhere: * E is the energy of the photon (3.5 x 10^-19 J) * KE is the maximum kinetic energy of the emitted electron. Since the current is reduced to zero by a potential of 0.25V, the KE = eV = 0.25 eV. Convert this to Joules: 0.25 eV * (1.6 x 10^-19 J/eV) = 0.4 x 10^-19 JTherefore:Φ = 3.5 x 10^-19 J - 0.4 x 10^-19 J = 3.1 x 10^-19 J
- B. This option is incorrect as per the calculationsusing the following formula:Φ = E - KEWhere: * E is the energy of the photon (3.5 x 10^-19 J) * KE is the maximum kinetic energy of the emitted electron. Since the current is reduced to zero by a potential of 0.25V, the KE = eV = 0.25 eV. Convert this to Joules: 0.25 eV * (1.6 x 10^-19 J/eV) = 0.4 x 10^-19 JTherefore:Φ = 3.5 x 10^-19 J - 0.4 x 10^-19 J = 3.1 x 10^-19 J
- C. This option is incorrect as per the calculationsusing the following formula:Φ = E - KEWhere: * E is the energy of the photon (3.5 x 10^-19 J) * KE is the maximum kinetic energy of the emitted electron. Since the current is reduced to zero by a potential of 0.25V, the KE = eV = 0.25 eV. Convert this to Joules: 0.25 eV * (1.6 x 10^-19 J/eV) = 0.4 x 10^-19 JTherefore:Φ = 3.5 x 10^-19 J - 0.4 x 10^-19 J = 3.1 x 10^-19 J
Q195. A diffraction grating has 500 lines per mm, its grating element d is equal to:
- A. 2 x 10-6 meter✓
- B. 2 x 10-2 meter
- C. 2 x 10-2 cm
- D. 2 x 10-6 cm
Explanation: The explanation is given below.Grating element = 1/N = 1/500 = 0.2 * 10-2 mm = 2 * 10-3 mm = 2 * 10-6 meter.
Why the other options are wrong
- B. This option is incorrect as per the formula.Grating element = 1/N = 1/500 = 0.2*10-2mm= 2 * 10-3mm = 2 * 10-6 m.
- C. This option is incorrect as per the formula.Grating element = 1/N = 1/500 = 0.2*10-2mm= 2 * 10-3mm = 2 * 10-6 m.
- D. This option is incorrect as per the formula.Grating element = 1/N = 1/500 = 0.2*10-2mm= 2 * 10-3mm = 2 * 10-6 m.
Q196. In the case of linear deformation, the ratio of tensile stress to tensile strain is called:
- A. Energy stored in a stretched wire
- B. Young’s double slit phenomenon
- C. Bulk Modulus
- D. Young’s Modulus✓
Explanation: The Young's modulus (E) is a property of the material that tells us how easily it can stretch and deform and is defined as the ratio of tensile stress (σ) to tensile strain (ε). Where stress is the amount of force applied per unit area (σ = F/A) and strain is extension per unit length (ε = dl/l).
Why the other options are wrong
- A. Elastic potential energy is the potential energy stored by stretching or compressing an elastic object by an external force such as the stretching of a spring.
- B. Young's original double-slit experiments were in fact the first to demonstrate the phenomenon of interference. When he shone light through two narrow slits and observed the pattern created on a distant screen, Young didn't find two bright regions corresponding to the slits, but instead saw bright and dark fringes.
- C. The bulk modulus of a substance is a measure of how resistant to compression the substance is. It is defined as the ratio of the infinitesimal pressure increase to the resulting relative decrease of the volume.
Q197. What is the name of the energy which is released when an atom is formed from its constituent particles?
- A. Atomic Energy
- B. Radioactive Energy
- C. Nuclear Energy
- D. Binding Energy✓
Explanation: Binding energy, amount of energy required to separate a particle from a system of particles or to disperse all the particles of the system. Binding energy is especially applicable to subatomic particles in atomic nuclei, to electrons bound to nuclei in atoms, and to atoms and ions bound together in crystals.
Why the other options are wrong
- A. The energy that is released through a nuclear reaction or radioactive decay process.
- B. Radioactive decay is the process by which an unstable atomic nucleus loses energy by radiation. A material containing unstable nuclei is considered radioactive. Three of the most common types of decay are alpha decay, beta decay, and gamma decay, all of which involve emitting one or more particles.
- C. Nuclear energy is a form of energy released from the nucleus, the core of atoms, made up of protons and neutrons. This source of energy can be produced in two ways: fission – when nuclei of atoms split into several parts – or fusion – when nuclei fuse together.
Q198. Calculate the half life of Bismuth-214 which has a decay constant of 4.3 x 10-4 s-1:
- A. 2.9 x 10-3 s
- B. 1.6 x 10^3 s✓
- C. 3.9 x 103 s
- D. 2.9 x 103 s
Explanation: T1/2 = ln 2/𝞴 = 0.693/ 4.3 x 10-4 = 1.6 x 103 where 𝞴 = decay constant.
Why the other options are wrong
- A. T1/2 = In 2/λ = 0.693/ 4.3 x 10-4 = 1.6 x 103 where λ = decay constant.
- C. T1/2 = In 2/λ = 0.693/ 4.3 x 10-4 = 1.6 x 103 where λ = decay constant.
- D. T1/2 = In 2/λ = 0.693/ 4.3 x 10-4 = 1.6 x 103 where λ = decay constant.
Q199. What is the main feature required by the optical fiber for the propagation of light in an optical fiber?
- A. Optical glass should be cleaned
- B. Light should be totally confined within the fiber✓
- C. They are cheaper than copper wire
- D. LED light must be used
Explanation: Optical fibers typically include a core surrounded by a transparent cladding material with a lower index of refraction. Light is kept in the core by the phenomenon of total internal reflection which causes the fiber to act as a waveguide. To ensure proper transmission light should be confined within the fiber.
Why the other options are wrong
- A. Optical fibers typically include a core surrounded by a transparent cladding material with a lower index of refraction. Light is kept in the core by the phenomenon of total internal reflection which causes the fiber to act as a waveguide. To ensure proper transmission light should be confined within the fibre.
- C. Optical fibers typically include a core surrounded by a transparent cladding material with a lower index of refraction. Light is kept in the core by the phenomenon of total internal reflection which causes the fiber to act as a waveguide. To ensure proper transmission light should be confined within the fibre.
- D. Optical fibers typically include a core surrounded by a transparent cladding material with a lower index of refraction. Light is kept in the core by the phenomenon of total internal reflection which causes the fiber to act as a waveguide. To ensure proper transmission light should be confined within the fibre.
Q200. Two long, parallel conductors which are free to move are arranged 1.0 cm apart. A steady current of 20 A flows in each of the conductors in the same direction. The conductors:
- A. Remains stationary
- B. Move towards each other✓
- C. Move away from each other
- D. Move at right angles to each other
Explanation: When two parallel wires carry current in the same direction, they exert equal and opposite attractive forces on each other. This causes them to move towards one another.
Why the other options are wrong
- A. Remains stationary: This would only be true if there was no current or if the currents were flowing in opposite directions.
- C. Move away from each other: This would happen if the currents were flowing in opposite directions, creating a repulsive force.
- D. Move at right angles to each other: The force between the conductors is either attractive or repulsive, acting along the line connecting them, not at right angles.
Q201. A stone of mass 2.0 kg is dropped from a rest position 5.0 m above the ground. What is its velocity at a height of 3.0 m above the ground?
- A. 12.5 m/s
- B. 6.3m/s✓
- C. 9.3 m/s
- D. 16.0 m/s
Explanation: Refer to following explanation
Why the other options are wrong
- A. We can use the following kinematic equation to solve this:v² = u² + 2asWhere: * v = final velocity (what we want to find) * u = initial velocity (0 m/s since it's dropped from rest) * a = acceleration due to gravity (approximately 9.8 m/s²) * s = displacement (the distance it falls, which is 5.0 m - 3.0 m = 2.0 m)Plugging in the values:v² = 0² + 2 * 9.8 m/s² * 2.0 mv² = 39.2 m²/s²v = √39.2 m²/s²v ≈ 6.3 m/s
- C. We can use the following kinematic equation to solve this:v² = u² + 2asWhere: * v = final velocity (what we want to find) * u = initial velocity (0 m/s since it's dropped from rest) * a = acceleration due to gravity (approximately 9.8 m/s²) * s = displacement (the distance it falls, which is 5.0 m - 3.0 m = 2.0 m)Plugging in the values:v² = 0² + 2 * 9.8 m/s² * 2.0 mv² = 39.2 m²/s²v = √39.2 m²/s²v ≈ 6.3 m/s
- D. We can use the following kinematic equation to solve this:v² = u² + 2asWhere: * v = final velocity (what we want to find) * u = initial velocity (0 m/s since it's dropped from rest) * a = acceleration due to gravity (approximately 9.8 m/s²) * s = displacement (the distance it falls, which is 5.0 m - 3.0 m = 2.0 m)Plugging in the values:v² = 0² + 2 * 9.8 m/s² * 2.0 mv² = 39.2 m²/s²v = √39.2 m²/s²v ≈ 6.3 m/s
Q202. In case of half wave rectification the resistance of diode during negative half of A.C is:
- A. Very high✓
- B. Very low
- C. A few ohms
- D. Negative
Explanation: A half-wave rectifier converts an AC signal to DC by passing either the negative or positive half-cycle of the waveform and blocking the other. Half-wave rectifiers can be easily constructed using only one diode, but are less efficient than full-wave rectifiers. During negative half of half wave rectifier, the diode is reverse biased i.e the current of few ohms and hence very high resistance.
Why the other options are wrong
- B. Incorrect. A diode has low resistance only when it is forward biased, which happens during the positive half-cycle of AC. In the negative half-cycle, the resistance is very high, not low.
- C. Incorrect. A resistance of a few ohms would indicate that the diode allows some current to pass, which does not happen in reverse bias during half-wave rectification.
- D. Incorrect. Resistance cannot be negative in this scenario. The diode’s resistance in reverse bias is high, but still a positive value.
Q203. Newton first law of motion is also known as:
- A. Law of inertia✓
- B. Law of electromagnetism
- C. Law of universal gravity
- D. Law of conservation of momentum
Explanation: The property of a body to remain at rest or to remain in motion with constant velocity is called inertia. Newton's first law is often called the law of inertia.
Why the other options are wrong
- B. Incorrect. Electromagnetism deals with electric and magnetic fields, which are covered under Maxwell’s equations, not Newton’s laws of motion.
- C. Incorrect. This refers to Newton’s Law of Universal Gravitation, which describes the gravitational force between two masses, not motion and inertia.
- D. Incorrect. The conservation of momentum is related to Newton's Third Law, which states that for every action, there is an equal and opposite reaction. Newton’s First Law is specifically about inertia.
Q204. When a potential difference is applied across the ends of a uniform wire of length l and radius r, a current I flows in the wire. If same potential difference is applied to the ends of another wire of the same material but of length 2l and radius 2r, the current in the wire is:
- A. I/4
- B. 2I✓
- C. I
- D. I/2
Explanation: R=ρl/AWhen radius is doubled : Area=2*pi*(2r) = 2*pi*4rHence the area has increased by 4 times.New resistance : Rx = ρ*2l/4A = ½ RV=IR where V remains same and R becomes halfI = V / ½RI become equal to 2I.
Why the other options are wrong
- A. R=pl/AWhen radius is doubled:Area=2π(2r) = 2π4rHence the area has increased by 4 times.New resistance: R'= p2l/4A =1/2 RV=IRwhere V remains same and R becomes halfI = V / ½RI became 2I.
- C. R=pl/AWhen radius is doubled:Area=2π(2r) = 2π4rHence the area has increased by 4 times.New resistance: R'= p2l/4A =1/2 RV=IRwhere V remains same and R becomes halfI = V / ½RI became 2I.
- D. R=pl/AWhen radius is doubled:Area=2π(2r) = 2π4rHence the area has increased by 4 times.New resistance: R'= p2l/4A =1/2 RV=IRwhere V remains same and R becomes halfI = V / ½RI became 2I.
Q205. A shock wave is produced due to an earthquake which makes the buildings move in the direction of the shock wave. Which progressive wave would this be?
- A. Longitudinal wave✓
- B. Transverse wave
- C. Material wave
- D. Particle wave
Explanation: The correct answer is Longitudinal wave because shock waves, such as those produced during an earthquake, cause the particles in the medium (like the ground) to oscillate in the same direction as the wave travels. This parallel movement of particles is characteristic of longitudinal waves. In contrast, Transverse waves have particle motion perpendicular to the wave direction, which does not apply to shock waves in this context. The term Material wave is too vague and does not specifically describe seismic waves, while Particle wave is not a recognized category in wave physics and does not provide a meaningful description of any wave type.
Why the other options are wrong
- B. A transverse wave involves particle movement perpendicular to the direction of wave propagation. While some seismic waves can be transverse, the specific wave mentioned in the context (shock wave) is primarily longitudinal.
- C. A material wave typically refers to waves that propagate through a medium due to the medium's physical properties. However, this term is not specific enough to describe the type of wave produced by an earthquake shock wave.
- D. A particle wave is not a standard term used in wave mechanics. It does not accurately describe the nature of waves like shock waves, which are defined based on the movement of energy through a medium.
Q206. A neutron having mass equal to a proton (mp = 1.6 x 10-27 kg) is moving in a magnetic field of intensity 1.20 x 10-3 T with a speed of 2.0 x 107 ms-1 . What is the maximum force experienced by the neutron?
- A. 3.84 x 10-15 N
- B. 0✓
- C. 3.84 x 10-12 N
- D. 38.4 x 10-15 N
Explanation: Neutrons do not experience magnetic fields because it's a neutral particle, moving charged particles only experience the magnetic force
Why the other options are wrong
- A. Neutrons do not experience magnetic fields because it's a neutral particle, moving charged particles only experience the magnetic force.
- C. Neutrons do not experience magnetic fields because it's a neutral particle, moving charged particles only experience the magnetic force.
- D. Neutrons do not experience magnetic fields because it's a neutral particle, moving charged particles only experience the magnetic force.
Q207. In SHM the kinetic energy of the body is maximum when:
- A. The body is at mean position✓
- B. The body is at extreme position from the mean
- C. The body is exactly half way down between mean and extreme position
- D. The body is somewhere between mean and extreme position
Explanation: In simple harmonic motion, there is a continuous interchange of kinetic energy and potential energy. At maximum displacement from the equilibrium point, potential energy is a maximum while kinetic energy is zero. At the equilibrium point (mean position) the potential energy is zero and the kinetic energy is a maximum.
Why the other options are wrong
- B. At extreme positions, the displacement of the body from the equilibrium position is maximum.However, while the potential energy is maximum at extreme positions, the kinetic energy is zero because the velocity of the body is momentarily zero.Hence, option B is incorrect.
- C. At this position, the body has both kinetic and potential energy, but neither is maximum.The kinetic energy is not maximum because the velocity of the body is not maximum at this position.Hence, option C is incorrect.
- D. Similar to option C, the body at positions between the mean and extreme positions has both kinetic and potential energy, but neither is maximum.The kinetic energy is not maximum because the velocity of the body is not maximum at these positions.Hence, option D is incorrect.
Q208. The different magnitudes of same physical quantities are measured by comparing them to:
- A. Available scale
- B. Standard size✓
- C. Each other
- D. Other physical quantities
Explanation: When the different magnitudes of certain physical quantities are measured then it should be measured according to a standard measure which is the same for everyone throughout the world. So that the distinguished quantities and the differences in the magnitude can be perfectly measured.
Why the other options are wrong
- A. Available scale is a tool used for measurement, not the standard itself.
- C. Each other is incorrect because you need an external standard for comparison.
- D. Other physical quantities are different in nature and cannot be used to measure the magnitude of a specific quantity.
Q209. Force experienced per unit positive test charge at a point in an electric field is the definition of:
- A. Electric potential energy
- B. Electric field strength✓
- C. Electric potential
- D. Electric field
Explanation: The strength of an electric field E at any point may be defined as the electric, or Coulomb, force F exerted per unit positive electric charge q at that point, or simply E = F/q.
Why the other options are wrong
- A. Electric potential energy is the energy that is needed to move a charge against an electric field. FormulaUE=kq1q2/r2
- C. Electric potential, the amount of work needed to move a unit charge from a reference point to a specific point against an electric field. Typically, the reference point is Earth, although any point beyond the influence of the electric field charge can be used.
- D. An electric field (sometimes E-field) is the physical field that surrounds electrically charged particles and exerts force on all other charged particles in the field, either attracting or repelling them. It also refers to the physical field for a system of charged particles
Q210. A metal rod of length 10.0 cm is moving at a speed of 0.5 ms-1 in a direction perpendicular to a 0.20 T magnetic field. Find the emf produced in the rod.
- A. 2.0 x 10-3 V
- B. 0.50 x 10-2 V
- C. 1.0 x 10-2 V✓
- D. 1.0 x 10-3 V
Explanation: Motional emf = Bℓv (B,ℓ, and v perpendicular)Emf = (0.20T) * (0.1m) * (0.5m/s) = 0.01 = 1 * 10-2 V
Why the other options are wrong
- A. Motional emf = Blv (B,l, and v are perpendicular to each other)Motional emf= (0.20T)* (0.1m) *(0.5m/s) =0.01= 1.0 ×10-2 V.
- B. Motional emf = Blv (B,l, and v are perpendicular to each other)Motional emf= (0.20T)* (0.1m) *(0.5m/s) =0.01= 1.0 ×10-2 V.
- D. Motional emf = Blv (B,l, and v are perpendicular to each other)Motional emf= (0.20T)* (0.1m) *(0.5m/s) =0.01= 1.0 ×10-2 V.
Q211. Demonstrate correct use of articles and prepositions to clarify meaning:The dog sprang _ him.
- A. On
- B. Upon✓
- C. In
- D. Over
Explanation: The sentence "The dog sprang upon him" suggests that the dog leaped or jumped aggressively towards him. The preposition "upon" is used to indicate a sudden or forceful action in this context.
Why the other options are wrong
- A. "On," could also be used to indicate the dog's movement towards him, but "upon" is a more appropriate and commonly used preposition in this context.
- C. "In," does not accurately convey the action of the dog leaping towards him."In," does not accurately convey the action of the dog leaping towards him.
- D. "Over," suggests that the dog jumped over him rather than directly towards him.
Q212. I _ cricket every morning.
- A. Playing
- B. Plays
- C. Play✓
- D. Played
Explanation: When talking about a fact or a habitual activity, we use the present indefinite tense (also called the simple present tense). Hence, the correct option here would be 'play'.
Why the other options are wrong
- A. "playing" is the present participle and would be used in a continuous or progressive verb form, like "I am playing cricket every morning."
- B. "plays" is the third-person singular present tense, which doesn't match the subject "I".
- D. "played" is the simple past tense, which would indicate a completed action in the past, not a habitual one.
Q213. Demonstrate correct use of articles and prepositions to clarify meaning:I advised her _ drink it.
- A. Don't
- B. Not to✓
- C. To not
- D. To don't
Explanation: A preposition must be placed before the adverb. Hence, the correct option is option B.
Why the other options are wrong
- A. A and D are incorrect as the sentence already has a main verb. In a single clause we use 1 main verb. If a sentence has multiple clauses, each clause has its own main verb.
- C. C is incorrect because the positioning of the adverb and preposition is wrong. Prepositions are written after adverbs.
- D. A and D are incorrect as the sentence already has a main verb. In a single clause we use 1 main verb. If a sentence has multiple clauses, each clause has its own main verb.
Q214. My parents _ near Lahore.
- A. Living
- B. Are living
- C. Lives
- D. Live✓
Explanation: Parents is a plural noun so the verb used should be singular.
Why the other options are wrong
- A. "Living near" is incorrect as it does not agree with the subject-verb agreement.
- B. "Are living" is also incorrect as it uses the present continuous tense, which is not suitable for describing a present state.
- C. "Lives" is incorrect as it is in the third-person singular form, which does not agree with the subject "my parents," which is in the plural form.
Q215. The two machines _ considerably. One has an electric motor, and the other one runs on oil.
- A. Different
- B. Differentiate
- C. Differ✓
- D. Difference
Explanation: the verb "differ" is the correct choice to complete the sentence and describe how the two machines have considerable differences between them.
Why the other options are wrong
- A. "Different" is an adjective, not a verb, so it doesn't fit the sentence structure.
- B. "Differentiate" means to recognize or ascertain the difference, which is not what the sentence is conveying.
- D. "Difference" is a noun, not a verb and so, it doesn't work in this context.
Q216. Which one has proper use of preposition?
- A. "If I am lying, the curse of Allah be on me and may I be drowned in some period. May I even be deprived from a decent burial!"
- B. "If I am lying. the curse of Allah be on me and may I be drowned in some period, May I even be deprived at a decent burial!"
- C. "If I am lying, the curse of Allah be on me and may I be drowned in some period. May I even deprived off a decent burial."
- D. "If I am lying, the curse of Allah be on me and may I be drowned in some period. May I even be deprived of a decent burial!"✓
Explanation: The preposition “of” is used to show possession or belonging. In this sentence, the speaker is saying that they may be deprived of something that they would normally have or deserve, which is a decent burial. The other options use incorrect prepositions or omit them altogether.
Why the other options are wrong
- A. This option includes the preposition "from" in the phrase "deprived from a decent burial." However, the more commonly used preposition in this context is "of," as mentioned in option D. So, option A does not have the proper use of preposition.
- B. This option includes the preposition "at" in the phrase "deprived at a decent burial." However, similar to option A, the more appropriate preposition to use in this context is "of," as mentioned in option D. Therefore, option B does not have the proper use of preposition.
- C. This option does not include a preposition in the phrase "deprived off a decent burial." The correct usage would be "deprived of a decent burial," as mentioned in option D. Therefore, option C does not have the proper use of preposition
Q217. Which of the following sentences is grammatically incorrect?
- A. Is this your jacket?
- B. Whose jacket is this?
- C. Is this jacket yours?
- D. Who's jacket is this?✓
Explanation: Another way to ask this question is to say “To whom does this jacket belong?”, so we’re talking about possession. “Who’s” is a contraction that’s short for “who is” or "who has", and it does not show ownership. The corrected form is noted above.
Why the other options are wrong
- A. This sentence is grammatically correct. It is a simple question asking if the jacket belongs to the person being addressed.
- B. This sentence is also grammatically correct. It is a question asking about the ownership of the jacket.
- C. This sentence is grammatically correct. It is another way of asking if the jacket belongs to the person being addressed, with a slight variation in word order.
Q218. Which of the following is grammatically correct?
- A. In the end, they found there money over they're by the ATM.
- B. In the end, they found they're money over their by the ATM.
- C. In the end, they found their money over there by the ATM.✓
- D. In the end, they found there money over their by the ATM.
Explanation: In this sentence, we have two homophones—their and there. In this first instance, we need to show possession, so the correct form is their. In the second instance, we need an adverb representing a place, so the correct form is there.
Why the other options are wrong
- A. This option is incorrect because it contains several grammatical errors. "There" should be "their" to indicate possession, and "they're" is the contraction of "they are" and doesn't fit in this context. Additionally, "over they're" is not a valid phrase.
- B. Similar to option A, this choice has errors. "They're" should be "their" to show possession. "Over their" is correct to indicate the location, but the placement of "by the ATM" is awkward.
- D. Option D contains two errors. "There" should be "their" to indicate possession. Additionally, "over their" is correct for indicating location, but the placement of "by the ATM" is incorrect.
Q219. Pick the correct option.
- A. No star is brighter than the moon.✓
- B. No star is more bright than the moon.
- C. No star is brighter then the moon.
- D. No star is brighter than moon.
Explanation: Option A is correct because it follows proper comparative structure: "No [noun] is brighter than [another noun]." It clearly states that the moon’s brightness exceeds that of any star.
Why the other options are wrong
- B. It’s wrong because “more bright” is not the standard comparative form of “bright.” The correct comparative is “brighter”, so it should be: “No star is brighter than the moon.”
- C. It’s incorrect because “then” is used for time or sequence, not comparison. The correct word for comparison is “than”, so it should be: “No star is brighter than the moon.”
- D. It’s incorrect because “the” is missing before “moon.” We need the definite article when referring to a specific celestial object: “No star is brighter than the moon.”
Q220. The ability to distinguish between two separate points/objects is:
- A. Magnification
- B. Fractionation
- C. Centrifugation
- D. Resolution✓
Explanation: The correct answer is Resolution. Resolution is a key concept in microscopy and imaging, as it defines the ability to distinguish between two closely positioned objects as separate entities. This clarity is essential for detailed analysis in cell biology.While Magnification increases the size of the image, it does not enhance clarity or detail necessary for resolving two close points. Fractionation and Centrifugation are techniques related to separating components of mixtures based on size or density, and do not pertain to the optical resolution of images.
Why the other options are wrong
- A. Magnification enlarges the image of an object but does not improve the ability to distinguish between two closely spaced points. It merely makes objects appear larger.
- B. Fractionation is a technique used to separate different components of a mixture based on their physical properties, not related to distinguishing between two close points.
- C. Centrifugation is a process used to separate particles from a solution based on size and density, not on their ability to be distinguished as separate points.
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