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Uhs Mdcat 2024 — Solved Past Paper with Answers

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Q1. _words spoken in earnest will convince him

  • A. A few
  • B. The few
  • C. Few
  • D. Fewer

Explanation: A is the correct option. This phrase indicates some words that are spoken seriously, which fits well in the context of the sentence, suggesting that certain words can convince him.

Why the other options are wrong
  • B. This phrase implies a specific, previously mentioned set of words, which does not fit as well in this context where we are not referring to a specific set.
  • C. This option is incorrect. This option implies a lack of words, suggesting that there aren’t many words spoken in earnest. This does not convey the intended meaning of convincing him.
  • D. This option is incorrect. This term is used to compare two groups and would not fit in this context since it’s not a comparative sentence.

Q2. Choose the correct sentence.

  • A. It was greatly good by you to proposed day's picnic at murree.
  • B. It was awfully good by you to proposed a day's picnic in Murree.
  • C. It was awfully good of you to propose a day's picnic at Murree.
  • D. It was very good off you too propose days picnic in Murree.

Explanation: Option C is correct. This option is correct. This is the correct option. It uses the right phrases and punctuation, and both "a day's picnic" and "at Murree" are properly used.

Why the other options are wrong
  • A. This option is incorrect. This option contains several errors: "greatly" should be "awfully" (though "very" could also work), "by you" should be "of you," "proposed" should be "propose," and "murree" should be capitalized as "Murree." Also, it lacks "a" before "day's picnic."
  • B. This option is incorrect. This option uses "by you" instead of the correct "of you," and "proposed" should be "propose." The phrase "in Murree" is acceptable but less common than "at Murree."
  • D. This option is incorrect. This option contains several errors: "off" should be "of," "too" should be "to," and "days" should be "day's." Also, "in Murree" is less preferred compared to "at Murree."

Q3. Choose the correct sentence

  • A. The first space traveller was Dennis Tito from the United States.
  • B. The First Space Traveller Was Dennis Tito, from, the United states
  • C. The first space traveller was Dennis Tito-from united State
  • D. The first space travaler was Dennis Tito, from the United States

Explanation: A is the correct option. This option is correct. This is the correct option. It uses proper capitalization of proper nouns, punctuation, and structure.

Why the other options are wrong
  • B. This option is incorrect. This option has multiple errors: it capitalizes unnecessary words ("First" and "Traveller") and incorrectly uses commas around "from." Additionally, "states" should be capitalized as "States."
  • C. This option is incorrect. This option incorrectly uses a hyphen instead of a comma before "from," and "United State" should be "United States" with proper capitalization.
  • D. This option is incorrect. This option has a spelling error; "travaler" should be spelled "traveller," but it does have correct punctuation.

Q4. Choose the correct sentence

  • A. You have often heard of me speeking of my friend Wahaj waheed a barrister here
  • B. You have often heard me speak of my friend, Wahaj Waheed, who is a barrister here.
  • C. You have often heard me. Speak off my friend, wahaj waheed who is a Barrister here
  • D. you have often heard me speak about my friend ; wahaj waheed-a barrister hear

Explanation: B is the correct option. This option is correct. This is the correct option. It properly uses "speak," includes the correct capitalization for "Wahaj Waheed," and has appropriate commas to set off the name and the relative clause.

Why the other options are wrong
  • A. This option is incorrect. This option has multiple errors: "speeking" should be "speaking," "Wahaj waheed" should be capitalized as "Wahaj Waheed," and it lacks necessary punctuation, including commas.
  • C. This option is incorrect. This option incorrectly uses a period that disrupts the sentence flow, and "off" should be "of." It also has capitalization errors.
  • D. This option is incorrect. This option has several issues: "Wahaj Waheed" should be capitalized, the semicolon is incorrectly used, "hear" should be "here," and it lacks proper punctuation before "a barrister."

Q5. Choose the correct sentence

  • A. “The unexamined life,” said Socrates, “is unfit to be lived by man.”
  • B. The inexamined life, said Socrates, is unfit to be lived by man”
  • C. “The unexamined life said Socrates” is disfit to be lived by man.
  • D. The disexamined life” said Socrates is unfit to be lived by man.

Explanation: A is the correct answer Because it has Correct sentence structure, proper punctuation, and the correct wording of Socrates’ famous quote.

Why the other options are wrong
  • B. "Inexamined" is incorrect; the correct word is "unexamined."
  • C. Incorrect punctuation and "disfit" is not a proper word.The words of Socrates should be punctuated properly: the comma should be inside the quotation marks before the attribution. Correct: “The unexamined life,” said Socrates,
  • D. "Disexamined" is incorrect; the correct word is "unexamined."

Q6. Choose the correct sentence.

  • A. Gulliver travels was writen to swift.
  • B. Gulliver travels was writen at swift.
  • C. Gulliver's Travels was written by Swift.
  • D. Gulliver's travel was written by swift.

Explanation: This option is correct because all the punctuation marks are used according to punctuation rules

Why the other options are wrong
  • A. This option is incorrect. This option has multiple errors: "travels" should be "Travels" (capitalized), "writen" is a misspelling of "written," and "to swift" is incorrect in this context; it should be "by Swift."
  • B. This option is incorrect. Similar to the first option, this one contains errors: "travels" should be "Travels," "writen" is incorrect and should be "written," and "at swift" is not the right preposition; it should be "by Swift."
  • D. This option is incorrect. This option is incorrect because "travel" should be plural ("Travels"), and "swift" should be capitalized to "Swift."

Q7. Choose the correct sentence:

  • A. There's mr. hashim whome they say is the best portrait painter in the town.
  • B. There's Mr. Hashim, who they say is the best portrait painter in the town.
  • C. Theres’ Mr. Hashim which they say is the portrait painter in the town.
  • D. There's Mr. Hashim who they say is best portrait painter in the town.

Explanation: B is the correct option. This is the correct option. It uses the proper capitalization for "Mr. Hashim" and correctly employs "who" to introduce the relative clause. The comma before "who" is also appropriately placed.

Why the other options are wrong
  • A. This option has multiple errors: "mr" should be capitalized to "Mr," and "whome" should be "whom," but "who" is the correct word to use in this context.
  • C. This option is incorrect. This option contains a typo; "Theres’" should be "There's." Additionally, "which" should be "who" because it refers to a person, not a thing.
  • D. This option is incorrect. This option is almost correct but lacks the article "the" before "best portrait painter," and it should also have a comma before "who" to set off the relative clause.

Q8. Fill in the blank with appropriate preposition.He takes _ his father.

  • A. Up
  • B. Down
  • C. After
  • D. In

Explanation: C is the correct option. This is the correct choice. "Takes after" means to resemble or have similar characteristics to someone, usually a parent.

Why the other options are wrong
  • A. This preposition does not fit this context; "takes up" usually means starting a new hobby or activity.
  • B. This option does not work in this context. "Takes down" typically means to remove or dismantle something.
  • D. This option is incorrect. The preposition "takes in" is unsuitable here; "takes in" usually means absorbing or understanding something.

Q9. Choose the correct option according to the subject verb agreement sentence.

  • A. In 1838 schleiden suggested that all plants were made of cells
  • B. In 1838 schleiden suggest that all plants were made of cells
  • C. In 1838 schleiden suggested that all plants were make of cells.
  • D. In 1838 schleiden suggested to all plants were made of cells

Explanation: Correct grammar and structure tense "suggested" matches the past tense of 1838.

Why the other options are wrong
  • B. Incorrect verb tense "suggest" should be "suggested" to match past tense.
  • C. Incorrect verb form "make" should be "made" for proper past tense.
  • D. Incorrect phrasing: "Suggested to all plants" is grammatically incorrect.

Q10. Choose the correct sentence.

  • A. She has beauty brains and wealth- a rare combination.
  • B. She has beauty, brains, and wealth- a rare combination.
  • C. She has beauty, brains and wealth- a rare combination.
  • D. She has beauty, brains, and wealth: a rare combination.

Explanation: The correct answer is Option B: She has beauty, brains, and wealth- a rare combination. This sentence uses the Oxford comma correctly, enhancing clarity in a list. However, a space is required before the dash to fully adhere to punctuation rules. The other options either omit necessary punctuation marks (like the Oxford comma) or incorrectly use punctuation marks (like a colon instead of a dash).

Why the other options are wrong
  • A. This option lacks commas between the items in the list and also lacks a space before the dash, which makes it incorrect.
  • C. This sentence omits the Oxford comma before 'and' and also lacks a space before the dash, making it incorrect.
  • D. This sentence uses the Oxford comma correctly, but it incorrectly uses a colon instead of a dash to introduce the phrase 'a rare combination.'

Q11. Choose the correct spellings;

  • A. Pharaoh
  • B. Pharoah
  • C. Pheroh
  • D. Pheraoh

Explanation: 'Pharaoh" is correct spellings. It refers to the title given to the ancient Kings of Egypt. Hence, option A is correct.

Why the other options are wrong
  • B. This is not correct spelling as option A is correct.
  • C. This is not correct spellings as option A is correct.
  • D. This is not correct spellings as option A is correct.

Q12. Choose the sentence that is punctuated correctly :

  • A. He said to his disciples “Watch and pray. ”
  • B. He said to his disciples, “Watch and pray.”
  • C. He said to his disciples, “watch and, pray”
  • D. He said to his disciples’ “ watch and pray. ”

Explanation: This option has correct Grammer and Punctuations. The direct speech “Watch and pray.” is correctly enclosed in quotation marks.

Why the other options are wrong
  • A. This option is missing a comma before the quotation. The correct punctuation requires a comma before the opening quotation mark.
  • C. This option incorrectly capitalizes "watch" and improperly places a comma after "and." The words within the quotation should be punctuated correctly without that comma.
  • D. This option incorrectly uses an apostrophe after "disciples." The apostrophe is unnecessary and incorrect in this context.

Q13. I……….. him for a long time.

  • A. Have never known
  • B. Had never knew
  • C. Had never been known
  • D. Would never knew

Explanation: Option A is the correct choice. It uses the present perfect tense to indicate that up until now, the speaker has not known him for a long time.

Why the other options are wrong
  • B. This option is incorrect because "knew" is the past tense form. The correct past participle form should be "known." Additionally, "had" is not appropriate here since it suggests a past perfect context without a clear prior point in time.
  • C. This option is also incorrect. It uses the passive voice and does not correctly fit the subject and context provided in the sentence.
  • D. This option is incorrect due to the use of "knew," which is the past tense. The correct form should be "known." Furthermore, "would" is not suitable in this context.

Q14. The soup _ good

  • A. Taste
  • B. Tastes
  • C. Is tasting
  • D. Has taste

Explanation: The correct answer is 'Tastes.' In the sentence 'The soup tastes good,' 'tastes' is the present simple form of the verb, which is used to describe a general truth or characteristic. The subject 'soup' is singular, so the verb must also be in a singular form. The other options are incorrect for the following reasons: 'Taste' does not agree with the singular subject, 'Is tasting' suggests a temporary action rather than a general quality, and 'Has taste' is awkward in this context and not commonly used to describe food.

Why the other options are wrong
  • A. This form suggests an action but does not agree with the singular subject 'soup' and is not in the correct tense.
  • C. This form suggests an ongoing action but is not suitable here as it implies that the soup is currently being tasted, rather than describing its inherent quality.
  • D. While this is grammatically correct, it is not a common way to express the flavor of the soup in this context and does not fit the sentence structure.

Q15. Pick the correct option.

  • A. The supervisor has nor will ever compromise.
  • B. The supervisor have nor will ever compromise.
  • C. The supervisor has not compromised nor will ever compromise.
  • D. The supervisor has nor will ever compromised.

Explanation: This is the correct option. It uses the appropriate verb form and structure to convey the intended meaning.

Why the other options are wrong
  • A. This option contains an incorrect word choice; "nor" should be "not" to make sense in this context.
  • B. This option uses the incorrect form of the verb "have" with the singular subject "supervisor."
  • D. This option incorrectly uses "nor" instead of "not" and also has a tense issue with "compromised," which should be "compromise."

Q16. What does the word "SPILL" mean?

  • A. Coil
  • B. Deliver
  • C. Spoil
  • D. Spread

Explanation: The word 'spill' refers to the act of causing a liquid or substance to flow over the edges of its container, which inherently means to spread it out over a surface. Therefore, the most accurate synonym is 'spread'.

Why the other options are wrong
  • A. To coil means to wind something into a circular or spiral shape. This is unrelated to the concept of spilling, which involves spreading.
  • B. To deliver means to bring something to a destination. While it involves an action, it does not convey the idea of spreading something out.
  • C. To spoil means to damage or ruin something. Although spilling can spoil contents, it does not directly mean to spread out.

Q17. What does the word "ANCESTOR" mean?

  • A. Collection of stars
  • B. Branch of astrology
  • C. Forefathers
  • D. Type of receptors

Explanation: A person who was in someone's family in past times. Therefore, "forefathers" is the most suitable option.

Why the other options are wrong
  • A. It's not a correct option as it means galaxy or cluster which is not a synonym for ancestors.
  • B. It's not the correct option as ancestors mean forefathers or predecessors.
  • D. It's not a synonym for ancestors.

Q18. Which of the following neurotransmitters is lying outside the central nervous system?

  • A. Acetylcholine
  • B. Endorphins
  • C. Gamma-aminobutyric acid
  • D. Dopamine

Explanation: Acetylcholine is a neurotransmitter involved in both the central and peripheral nervous systems. It plays a key role in muscle contraction, memory, learning, and attention. In the central nervous system, acetylcholine is important for cognitive functions, while in the peripheral nervous system, it enables communication between nerves and muscles. Low levels of acetylcholine are associated with conditions like Alzheimer's disease.

Why the other options are wrong
  • B. Endorphins are natural chemicals produced by the brain that act as pain relievers and mood boosters. They are released during activities like exercise, laughter, and eating certain foods, helping to reduce stress and enhance well-being. Often called "feel-good" hormones, endorphins contribute to feelings of happiness and relaxation.
  • C. Gamma-aminobutyric acid (GABA) is the primary inhibitory neurotransmitter in the brain. It reduces neuronal excitability throughout the nervous system, helping to calm neural activity and prevent overstimulation, which is essential for maintaining balance in brain function. GABA plays a crucial role in regulating anxiety, mood, and muscle tone.
  • D. Dopamine has some functions outside the brain, like in the kidneys, blood vessels, and digestive system. However, it mainly works as a neurotransmitter in the central nervous system (CNS). Its main jobs, such as controlling movement, motivation, and reward, happen in the brain. Unlike acetylcholine, which is widely used in the peripheral nervous system (PNS), dopamine has only a few effects outside the brain.

Q19. Depolarization during conduction of nerve impulse is due to:

  • A. Inward movement of Na+
  • B. Inward movement of K+
  • C. Outward movement of K+
  • D. Outward movement of Na+

Explanation: The inward movement of Na+ (sodium ions) occurs during the depolarization phase of a nerve impulse. When a neuron is stimulated, voltage-gated sodium channels open, allowing Na+ to rush into the cell. This influx of positively charged sodium ions causes the inside of the neuron to become less negative (or more positive), leading to the generation of an action potential. This rapid change in membrane potential is what propagates the nerve impulse along the axon.

Why the other options are wrong
  • B. The inward movement of K+ (potassium ions) is not typical during normal nerve impulse conduction. Potassium ions generally move outward during repolarization. However, the sodium-potassium pump, which helps to maintain the resting membrane potential, moves K+ inward (and Na+ outward) actively against their concentration gradients. This process restores and maintains the appropriate ion balance, keeping the inside of the neuron more negatively charged than the outside, which is essential for the neuron's readiness to fire again.
  • C. The outward movement of K+ (potassium ions) occurs during the repolarization phase of a nerve impulse. After the neuron depolarizes (when Na+ flows in), voltage-gated potassium channels open, allowing K+ to flow out of the cell. This outward movement helps in restoring the negative membrane potential, bringing the neuron toward its resting state. It is a crucial step in resetting the neuron's electrical charge so it can fire another action potential when needed.
  • D. The outward movement of Na+ (sodium ions) during nerve impulse conduction typically occurs during the repolarization phase. After an action potential has peaked, sodium channels close, and potassium channels open, allowing K+ to leave the cell. Although Na+ ions generally move inward during depolarization, if Na+ is actively pumped out by the sodium-potassium pump, it helps restore the resting membrane potential by maintaining the balance of ions. This outward movement of Na+ is essential for resetting the neuron for future impulses.

Q20. Which of the following is NOT a feature of the autonomic nervous system?

  • A. Regulate response of visceral organs
  • B. Regulate response of skeletal muscles
  • C. Regulate response of glands
  • D. Regulate response of smooth muscles

Explanation: The autonomic nervous system (ANS) does not directly regulate the response of skeletal muscles. Skeletal muscles are controlled by the somatic nervous system, which governs voluntary movements. However, the ANS can indirectly affect skeletal muscles by regulating blood flow, oxygen delivery, and metabolic processes during physical activity, especially through the sympathetic division during "fight or flight" responses.

Why the other options are wrong
  • A. The autonomic nervous system (ANS) regulates the involuntary functions of visceral organs, including the heart, lungs, stomach, and intestines. It controls processes such as heart rate, digestion, respiratory rate, and blood pressure, ensuring the body maintains homeostasis. The ANS is divided into the sympathetic division, which prepares the body for "fight or flight" responses, and the parasympathetic division, which promotes "rest and digest" activities. Together, these systems work to balance organ functions based on the body's needs.
  • C. The autonomic nervous system (ANS) regulates the activity of glands, controlling their secretion levels based on the body's needs. The sympathetic division typically stimulates glands like sweat glands to increase secretion during stress, while the parasympathetic division enhances activities like saliva and digestive enzyme secretion to aid in digestion during rest. This ensures that glandular functions align with either stress responses or restful states.
  • D. The autonomic nervous system (ANS) regulates the contraction and relaxation of smooth muscles, which are found in the walls of organs like blood vessels, the digestive tract, and the respiratory system. The sympathetic division typically causes smooth muscles to contract, such as constricting blood vessels during stress, while the parasympathetic division relaxes smooth muscles, promoting functions like digestion and lowering heart rate. This helps maintain bodily functions like blood pressure, digestion, and respiration.

Q21. Taste receptor is an example of:

  • A. Mechanoreceptors
  • B. Nociceptors
  • C. Photoreceptors
  • D. Chemoreceptors

Explanation: Chemoreceptors are specialized sensory receptors that detect changes in the chemical composition of the environment. They respond to specific chemical stimuli, such as the levels of oxygen (O₂), carbon dioxide (CO₂), and pH in the blood or other body fluids. Chemoreceptors play a critical role in regulating respiratory and cardiovascular functions by signaling the nervous system to adjust breathing rate, heart rate, and blood pressure based on changes in blood gas levels. They are primarily located in the carotid bodies, aortic bodies, and the medulla of the brainstem.

Why the other options are wrong
  • A. Mechanoreceptors are sensory receptors that respond to mechanical stimuli such as pressure, vibration, stretch, and touch. They are found in the skin, muscles, joints, and internal organs, helping the body sense physical forces and movements. Mechanoreceptors play a key role in various functions, including detecting touch, maintaining balance, and sensing changes in joint position and body movement. Different types of mechanoreceptors are specialized for different types of mechanical stimuli, such as Pacinian corpuscles for vibration and deep pressure or Meissner's corpuscles for light touch.
  • B. Nociceptors are specialized sensory receptors that detect painful stimuli, signaling potential damage to the body. They respond to various harmful stimuli such as mechanical (e.g., cuts or pressure), thermal (e.g., extreme heat or cold), or chemical (e.g., irritants or inflammation). When activated, nociceptors send pain signals to the brain through the nervous system, triggering protective responses like withdrawal from the source of pain. These receptors play a key role in alerting the body to injury or danger.
  • C. Photoreceptors are specialized cells in the retina of the eye that detect light and convert it into electrical signals, which are sent to the brain for visual processing. There are two main types of photoreceptors: rods, which are sensitive to low light and enable black-and-white vision, and cones, which are responsible for color vision and function best in bright light. Together, these cells enable vision by responding to different wavelengths of light.

Q22. Mesosomes are the invaginations of which bacterial cell structure?

  • A. Cell Wall
  • B. Cell Membrane
  • C. Plasmid
  • D. Cysts

Explanation: Mesosomes were once thought to be infoldings of the plasma membrane found in some bacteria, particularly Gram-positive species, and were believed to play roles in cell division, respiration, DNA replication, and nutrient absorption by increasing the surface area of the cell membrane. They were hypothesized to help anchor the cell division machinery, contain respiratory enzymes, and assist in organizing the bacterial chromosome during replication. However, subsequent research has demonstrated that mesosomes are artifacts resulting from chemical fixation techniques used during electron microscopy sample preparation. Therefore, they are not considered part of the natural structure of bacterial cells.

Why the other options are wrong
  • A. The cell wall is a rigid outer layer that surrounds the plasma membrane of bacterial cells, providing structural support and protection. Composed primarily of peptidoglycan in bacteria, the cell wall helps maintain cell shape, prevents osmotic lysis, and protects against environmental stresses.There are two main types of bacterial cell walls: Gram-positive, which have a thick peptidoglycan layer and retain the crystal violet stain used in Gram staining, and Gram-negative, which have a thinner peptidoglycan layer surrounded by an outer membrane containing lipopolysaccharides. The differences in cell wall structure are crucial for antibiotic susceptibility and are important for bacterial classification and identification.
  • C. A plasmid is a small, circular, double-stranded DNA molecule found in many bacteria and some archaea and eukaryotic organisms. Plasmids are separate from the chromosomal DNA and can replicate independently. They often carry genes that provide advantages, such as antibiotic resistance, metabolic capabilities, or virulence factors.
  • D. Cysts in bacterial cells are dormant, highly resistant structures formed by certain bacteria as a survival strategy under adverse conditions, such as nutrient depletion, extreme temperatures, or desiccation. These cysts typically have thick walls and can withstand harsh environments, allowing bacteria to remain viable for extended periods.

Q23. Which of the following belongs to chordates?

  • A. Spider
  • B. Earthworm
  • C. Trout Fish
  • D. Star Fish

Explanation: Trout fish belong to the phylum Chordata, which is characterized by animals that possess a notochord at some stage of development, a dorsal nerve cord, pharyngeal slits, and a post-anal tail. Trout specifically belong to the class Actinopterygii (ray-finned fishes) and the order Salmoniformes. They are typically found in freshwater habitats like rivers and lakes and are known for their streamlined bodies and gills for respiration. Trout are popular among anglers and play a significant role in freshwater ecosystems as both predators and prey.

Why the other options are wrong
  • A. Spiders belong to the phylum Arthropoda, specifically the class Arachnida. This phylum is characterized by animals with jointed appendages, an exoskeleton made of chitin, and segmented bodies. Spiders have two main body segments: the cephalothorax (a fused head and thorax) and the abdomen, connected by a narrow pedicel. They are known for having eight legs, unlike insects, which have six. Spiders are predominantly terrestrial predators that capture their prey using silk webs or by ambush. They play an essential role in controlling insect populations in various ecosystems. Additionally, they possess specialized mouthparts called chelicerae, which they use to inject venom into their prey. Spiders also have pedipalps—appendages near the mouth—that assist in manipulating prey and, in males, are used during reproduction.
  • B. Earthworms belong to the phylum Annelida, which is characterized by segmented bodies, a true coelom (body cavity), and a well-developed nervous system. Annelids, commonly known as segmented worms, have bodies divided into segments called annuli, which allow for greater flexibility and movement. Earthworms are important soil organisms, contributing to soil aeration, nutrient cycling, and organic matter decomposition through their burrowing and feeding activities. They play a crucial role in maintaining healthy ecosystems and are often used in composting and as indicators of soil health.
  • D. Starfish, or sea stars, belong to the phylum Echinodermata. This phylum is characterized by marine animals with radial symmetry, a calcareous endoskeleton, and a water vascular system that aids in movement and feeding. Echinoderms typically exhibit a five-part body plan, as seen in starfish, which have arms radiating from a central disk. They are known for their ability to regenerate lost arms and play important roles in marine ecosystems, often serving as predators or scavengers. Other examples of echinoderms include sea urchins, sand dollars, and sea cucumbers.

Q24. What is true about enzymes?

  • A. Fibrous proteins
  • B. No effect on end product
  • C. Consumed in reaction
  • D. Non-specific

Explanation: The Enzymes do not change the end product of a reaction; they only speed up the process without being consumed.

Why the other options are wrong
  • A. Fibrous proteins are structural proteins, not enzymes. They do not catalyze reactions.
  • C. Enzymes are not consumed in reactions; they can be reused multiple times to catalyze the same reaction.
  • D. Most enzymes are specific to their substrates, meaning this statement is incorrect regarding enzyme characteristics.

Q25. Induced fit model of enzyme activity suggests that enzyme:

  • A. Cannot modify its active sites
  • B. Can bind to a single substrate
  • C. Can catalyze related reaction
  • D. Usually belongs to non-regulatory enzyme

Explanation: The flexibility in the induced fit model allows some enzymes to catalyze related reactions, particularly when similar substrates can fit into the active site after the enzyme undergoes a conformational change.

Why the other options are wrong
  • A. The induced fit model implies that the active site can change shape to better accommodate the substrate upon binding.
  • B. While enzymes typically have a specific substrate they act on, the induced fit model allows for some flexibility, which means an enzyme can bind to related substrates, though it is usually more specific.
  • D. Enzymes that operate under the induced fit model can be regulatory enzymes, which means they can be subject to allosteric regulation and other control mechanisms.

Q26. Female reproductive system consists all of the following except:

  • A. Ovaries
  • B. Oviduct
  • C. Cervix
  • D. Seminiferous tubules

Explanation: Seminiferous tubules are coiled structures located within the testes and are the site of sperm production (spermatogenesis) in males. Each testis contains several hundred meters of these tubules, which are lined with germinal epithelium consisting of spermatogenic cells that develop into spermatozoa.

Why the other options are wrong
  • A. The ovaries are a pair of female reproductive organs located in the pelvic cavity, one on each side of the uterus. They serve several crucial functions in the female reproductive system.
  • B. The oviduct, also known as the fallopian tube, is a pair of tubular structures in female mammals that connect the ovaries to the uterus.
  • C. The cervix is a cylindrical, narrow structure that forms the lower part of the uterus, connecting it to the vagina. It serves several important functions in the female reproductive system.Cervix is plugged my mucus.

Q27. Chromosomal abnormality in Turner syndrome is represented by?

  • A. XXX
  • B. XYY
  • C. XO
  • D. XXY

Explanation: XO refers to a specific chromosomal condition known as Turner syndrome, which occurs in females. This condition is characterized by the complete or partial absence of one of the two X chromosomes, leading to a total of 45 chromosomes instead of the typical 46 (XX).

Why the other options are wrong
  • A. Triple X syndrome, also known as XXX syndrome, is a specific chromosomal condition that occurs in females. It is characterized by the presence of an extra X chromosome, resulting in a total of 47 chromosomes instead of the typical 46 (XX).
  • B. XYY syndrome is a specific chromosomal condition that occurs in males. It is characterized by the presence of an extra Y chromosome, which leads to 47 chromosomes instead of the typical 46 (XY).
  • D. XXY denotes a chromosomal condition called Klinefelter syndrome, found in males. This syndrome is marked by an additional X chromosome, leading to a total of 47 chromosomes instead of the usual 46 (XX or XY).

Q28. Which one of the following hormones is responsible for the labor pains in a human female at the time of the birth of a baby?

  • A. Estrogen
  • B. Progesterone
  • C. Oxytocin
  • D. Corticosteroid

Explanation: During labor, oxytocin stimulates contractions of the uterine muscles, facilitating childbirth. It is sometimes administered artificially to induce or strengthen labor.

Why the other options are wrong
  • A. Primarily produced in the ovaries, estrogen is crucial for the development of female secondary sexual characteristics, the regulation of the menstrual cycle, and the maintenance of reproductive tissues.
  • B. Progesterone is a steroid hormone primarily produced by the ovaries, specifically by the corpus luteum after ovulation, and in smaller amounts by the adrenal glands and placenta during pregnancy.
  • D. Corticosteroids are a class of steroid hormones produced by the adrenal cortex. They play essential roles in various physiological processes in the body. The two main types of corticosteroids are glucocorticoids (like cortisol) and mineralocorticoids (like aldosterone).

Q29. The change in frequency of alleles at a locus that occurs by chance is known as:

  • A. Mutation
  • B. Genetic Drift
  • C. Non-Random mating
  • D. Speciation

Explanation: Genetic drift is a mechanism of evolution that refers to random changes in allele frequencies within a population, especially in small populations. Unlike natural selection, which involves traits being favored due to survival or reproductive advantages, genetic drift occurs by chance. Over time, it can lead to the loss of genetic variation, fixation of certain alleles, or even the divergence of populations. Events like the bottleneck effect (drastic population size reduction) or the founder effect (a new population started by a small group) are examples where genetic drift can have a strong impact.

Why the other options are wrong
  • A. A mutation is a change in the DNA sequence of an organism's genome. Mutations can occur naturally during DNA replication or be induced by environmental factors like radiation or chemicals. They are the primary source of genetic variation, introducing new alleles into a population. Mutations can be beneficial, neutral, or harmful, depending on their effect on the organism’s survival or reproduction. While most mutations have little to no effect, beneficial mutations can be acted on by natural selection, contributing to evolutionary change over time.
  • C. Non-random mating occurs when individuals in a population choose mates based on specific traits rather than randomly. This can lead to certain traits being passed on more frequently than others, influencing the genetic structure of the population. Types of non-random mating include assortative mating, where individuals prefer mates with similar traits, and disassortative mating, where they prefer those with different traits. Non-random mating can affect allele frequencies, increase genetic differentiation, and sometimes contribute to reproductive isolation, potentially playing a role in speciation.
  • D. Speciation is the evolutionary process by which new species arise. It typically occurs when populations of the same species become isolated from each other, either geographically (allopatric speciation) or through behavioral, ecological, or genetic differences (sympatric speciation). Over time, these populations evolve independently, accumulating genetic differences that eventually prevent them from interbreeding, leading to the formation of distinct species. Factors like natural selection, genetic drift, and mutations drive this divergence. Speciation is a key mechanism of biodiversity on Earth.

Q30. Fluid secreted by Sertoli cells provides a liquid medium, protection, and nourishment to:

  • A. Oocyte
  • B. Sperms
  • C. Polar body
  • D. Spermatogonia

Explanation: Sertoli cells secrete testicular fluid into the seminiferous tubules, providing a liquid medium that supports sperm development. This fluid nourishes and protects sperm cells, facilitating their maturation and transport within the male reproductive system. Additionally, Sertoli cells form the blood-testis barrier, shielding developing sperm from harmful substances and immune responses.

Why the other options are wrong
  • A. An oocyte is an immature egg cell involved in female reproduction. It is produced in the ovaries and develops through a process called oogenesis. Oocytes are initially formed during fetal development and remain arrested in a specific stage of meiosis until puberty. Each menstrual cycle, a few oocytes resume development, but typically only one fully matures into an ovum (egg) ready for fertilization. Oocytes are haploid cells, meaning they contain half the genetic material needed for reproduction, and upon fertilization by a sperm cell, they form a zygote, the first stage of a new organism.
  • C. A polar body is a small cell that is a byproduct of oocyte (egg cell) development during meiosis in females. During meiosis, the oocyte undergoes unequal cytoplasmic division, where most of the cytoplasm is retained in one large cell, which becomes the mature egg, while the smaller polar bodies contain the remaining genetic material. Polar bodies typically do not play a role in reproduction and eventually degenerate. Their formation ensures that the egg retains sufficient cytoplasm to support early development after fertilization.
  • D. Spermatogonia are the precursor cells found in the testes that develop into sperm through a process called spermatogenesis. These diploid cells are located in the seminiferous tubules and undergo mitotic divisions to maintain their population and produce primary spermatocytes. These primary spermatocytes then undergo meiosis, ultimately resulting in the formation of sperm cells. Spermatogonia play a crucial role in the continuous production of sperm throughout a male's reproductive life. There are two types of spermatogonia: Type A, which act as stem cells, and Type B, which differentiate into primary spermatocytes.

Q31. Identify the correct pair of vestigial organs:

  • A. Ear Muscles & Vermiform appendix
  • B. Heart and Liver
  • C. Ear Muscles & Liver
  • D. Vermiform appendix & Heart

Explanation: The ear muscles, which assist in the movement of the outer ear, are considered vestigial in humans. While they allow for minor ear movement, their function has diminished over time, reflecting an evolutionary past when they may have played a more significant role in sound localization. In contrast, the vermiform appendix is also regarded as a vestigial organ. It is thought to be a remnant of a larger cecum used by herbivorous ancestors for digesting cellulose. Although it has some potential immune functions related to gut flora, its digestive role in humans is minimal, underscoring its vestigial status.

Why the other options are wrong
  • B. The heart is not vestigial or unnecessary; it is a vital organ that pumps blood throughout the body. This function is essential for delivering oxygen and nutrients to tissues while also removing waste products. The continuous operation of the heart is crucial for survival.Similarly, the liver is not vestigial. It performs a variety of essential functions, including detoxifying harmful substances, metabolizing carbohydrates, proteins, and fats, producing bile for digestion, and regulating blood sugar levels. Both the heart and liver play indispensable roles in maintaining overall health and homeostasis in the body.
  • C. The ear muscles, specifically the muscles that help move the outer ear (auricle), are considered vestigial in humans. While they allow for some minor movement of the ear, these muscles are largely non-functional and play no significant role in hearing or directional sound localization, reflecting our evolutionary past when they may have helped in better ear movement for sound detection. On the other hand, the liver is not vestigial; it is a vital organ with numerous essential functions, including detoxification, metabolism of nutrients, production of bile, and regulation of blood composition. The liver plays a crucial role in maintaining overall health and homeostasis.
  • D. The vermiform appendix is considered a vestigial organ in humans, as it no longer plays a crucial role in digestion, thought to be a remnant of a larger cecum used by herbivorous ancestors for digesting cellulose. However, it may still have some immune functions related to gut bacteria. In contrast, the heart is not vestigial; it is a vital organ essential for survival, responsible for pumping blood throughout the body, delivering oxygen and nutrients to tissues, and removing waste.

Q32. Which of the following increases genetic variation the most?

  • A. Cloning
  • B. Self-pollination
  • C. Crossing over
  • D. Asexual reproduction

Explanation: Crossing over produces new allele combinations during meiosis, greatly enhancing variation. Asexual methods do not increase variation.

Why the other options are wrong
  • A. Cloning is a form of asexual reproduction that produces genetically identical organisms. While cloning can create a large number of individuals, it does not introduce new genetic variations. As a result, genetic diversity remains low, which can limit the adaptability of a population.
  • B. Self-pollination occurs when pollen from a flower fertilizes the ovule of the same flower. While this method can produce offspring, it tends to result in less genetic diversity compared to cross-pollination, as the genes come from a single parent, limiting the introduction of new alleles.
  • D. Asexual reproduction involves a single organism producing offspring that are genetically identical to itself. While this method allows for rapid population growth, it does not promote genetic variation, making populations more susceptible to environmental changes and diseases.

Q33. Corpus luteum during female reproductive cycle produces:

  • A. Testosterone
  • B. Follicle stimulating hormone
  • C. Luteinizing hormone
  • D. Progesterone

Explanation: Progesterone is a steroid hormone produced primarily by the corpus luteum in the ovaries after ovulation and, during pregnancy, by the placenta. Its production begins with the conversion of cholesterol into pregnenolone through a series of enzymatic steps. Pregnenolone is then converted into progesterone via enzymes such as 3β-hydroxysteroid dehydrogenase. This hormone plays a key role in regulating the menstrual cycle, preparing the uterus for pregnancy, and maintaining pregnancy if fertilization occurs. Additionally, small amounts of progesterone are produced by the adrenal glands in both sexes.

Why the other options are wrong
  • A. Testosterone is mainly produced by Leydig cells in the testes of males, with smaller amounts produced by the ovaries in females and the adrenal glands in both sexes. Its production is triggered by the luteinizing hormone (LH) from the anterior pituitary gland. Cholesterol is converted into pregnenolone and then into testosterone through various enzymatic processes.Testosterone is essential for male sexual development, maintaining reproductive tissues, and developing secondary sexual characteristics like muscle mass and facial hair. It also contributes to overall health in both genders.
  • B. Follicle-stimulating hormone (FSH) is produced by the anterior pituitary gland in response to the release of the gonadotropin-releasing hormone (GnRH) from the hypothalamus. Like luteinizing hormone (LH), FSH is a glycoprotein hormone consisting of alpha and beta subunits, synthesized through gene expression in pituitary cells. In females, FSH stimulates the growth and maturation of ovarian follicles, which contain the oocytes and play a crucial role in estrogen production. In males, FSH is essential for spermatogenesis, stimulating the Sertoli cells in the testes to support sperm production.
  • C. Luteinizing hormone (LH) is produced by the anterior pituitary gland in response to the release of gonadotropin-releasing hormone (GnRH) from the hypothalamus. LH is a glycoprotein hormone composed of two subunits, alpha and beta, synthesized through gene expression in pituitary cells. Once produced, LH is secreted into the bloodstream, where it plays a crucial role in regulating reproductive processes. In females, it triggers ovulation and stimulates the formation of the corpus luteum, which produces progesterone. In males, LH stimulates the Leydig cells in the testes to produce testosterone.

Q34. Which of the following statements about natural selection is not true?

  • A. It affects variations that are heritable
  • B. It is selected by a breeder
  • C. It can improve the adaptation of species
  • D. It is regional in nature

Explanation: When traits are selected by a breeder, this process is known as artificial selection, not natural selection. In artificial selection, breeders choose individuals with specific desirable traits—such as size, color, or temperament—to reproduce, thereby directly influencing which traits are passed on to the next generation. This is different from natural selection, where environmental pressures determine which traits are advantageous, and there is no human intervention. While both processes involve the passing of favorable traits to future generations, artificial selection is driven by human preferences, whereas natural selection is governed by the natural environment

Why the other options are wrong
  • A. Natural selection affects heritable variations because it operates on traits that can be passed down from one generation to the next. For natural selection to influence a population, the traits being selected must be genetically based and capable of being inherited. Variations arise from mutations, genetic recombination, and other genetic processes, creating differences among individuals in a population. Those individuals with heritable traits that provide a survival or reproductive advantage are more likely to survive and reproduce, passing those advantageous traits to their offspring. Over time, this process leads to the accumulation of beneficial traits in the population, enhancing the overall adaptation of the species.
  • C. Natural selection improves the adaptation of species by favoring individuals with traits that enhance their survival and reproductive success in a given environment. Over time, these advantageous traits become more common within the population, helping the species better cope with environmental challenges like predators, climate, food availability, or disease. As these traits accumulate across generations, the species becomes more well-suited or adapted to its environment. This process allows species to evolve in ways that improve their fitness, enhancing their ability to thrive in their ecological niche.
  • D. Natural selection is regional because the selective pressures that drive it vary depending on the local environment and conditions. Different regions have distinct climates, ecosystems, predators, food sources, and other factors that influence which traits are advantageous for survival and reproduction. For example, a trait beneficial in one region, like thick fur in cold climates, may not be useful or could even be a disadvantage in a warmer region. As a result, natural selection acts differently in different areas, shaping populations based on the unique challenges and resources of their specific environments.

Q35. The formula calculating the frequency of genotypes and alleles in a population gene pool is known as:

  • A. Hardy-Weinberg Equation
  • B. Lamarck Equation
  • C. Darwin Equation
  • D. James Hutton Equation

Explanation: The Hardy-Weinberg equation is a mathematical model used in population genetics to describe the genetic equilibrium within a population. It predicts how gene frequencies will behave under ideal conditions, assuming no evolution is occurring.

Why the other options are wrong
  • B. The "Lamarck Equation" is not a term typically associated with a specific mathematical formula in biology. However, it likely refers to the principles of inheritance proposed by Jean-Baptiste Lamarck, a French naturalist. Lamarck is best known for his theory of "inheritance of acquired characteristics," also called Lamarckism.
  • C. There is no specific "Darwin Equation" like there is for Hardy-Weinberg, but Charles Darwin's contributions to biology revolve around the theory of evolution by natural selection. Darwin's theory, outlined in On the Origin of Species (1859), explains how species evolve due to the differential survival and reproduction of individuals with traits better suited to their environment.
  • D. James Hutton, often considered the "father of modern geology," did not propose a specific mathematical equation associated with his work, but he is renowned for his theory of uniformitarianism. This principle suggests that the Earth's features were shaped by the same slow, continuous processes (like erosion, sedimentation, and volcanic activity) that operate today, occurring over vast periods. Hutton’s famous phrase, "The present is the key to the past," encapsulates this idea.

Q36. Due to the process of follicle atresia:

  • A. Follicles reach maximum size
  • B. Follicle degenerates
  • C. Graafian follicle ovulates
  • D. The follicle starts to mature

Explanation: The follicle that is not selected for ovulation begins to break down. The oocyte and surrounding granulosa cells undergo apoptosis (programmed cell death).

Why the other options are wrong
  • A. In follicle atresia, the follicles do not reach maximum size. Instead, atresia occurs when developing follicles begin to mature but fail to complete their growth and eventually degenerate.
  • C. Triggered by a surge in luteinizing hormone (LH), the Graafian follicle ruptures, releasing the mature oocyte into the fallopian tube. This event occurs typically around the midpoint of the menstrual cycle.
  • D. The Graafian follicle is the dominant follicle that has reached full maturity during the menstrual cycle. It is characterized by a large size, a fluid-filled antrum, and a well-developed layer of granulosa cells surrounding the oocyte.

Q37. The idea of inheritance of acquired characteristics was presented by:

  • A. Jean Baptist Lamarck
  • B. Charles Darwin
  • C. Thomas Malthus
  • D. Alfred Wallace

Explanation: Jean-Baptiste Lamarck (1744–1829) was a French naturalist known for his early ideas on evolution, articulated in Philosophie Zoologique (1809). He proposed that organisms adapt to their environments through the use or disuse of traits, a concept summarized as the "inheritance of acquired characteristics." For instance, he suggested that giraffes developed long necks because their ancestors stretched to reach higher leaves. Although his theories were later discredited in favor of Darwin's natural selection, Lamarck's work was significant in the history of evolutionary thought, introducing the idea that species can change over time.

Why the other options are wrong
  • B. Charles Darwin (1809–1882) was an English naturalist and biologist best known for his contributions to the theory of evolution. His seminal work, On the Origin of Species (1859), introduced the concept of natural selection, explaining how species evolve through the survival and reproduction of individuals with advantageous traits. Observations from his voyage on the HMS Beagle, especially studies of finches in the Galápagos Islands, were pivotal in shaping his theories. Darwin's ideas challenged traditional views of species and laid the foundation for modern evolutionary biology, influencing many fields and establishing him as a key figure in science.
  • C. Thomas Robert Malthus (1766–1834) was an English cleric and economist best known for his theory of population growth. In An Essay on the Principle of Population (1798), he argued that populations grow exponentially while food production increases arithmetically, leading to inevitable overpopulation and resource shortages. Malthus emphasized the need for checks on population growth, such as moral restraint, to prevent societal collapse. His ideas significantly influenced economics, demography, and biology, impacting thinkers like Charles Darwin and Alfred Wallace. Despite criticisms, Malthus's insights into population dynamics remain relevant in discussions of sustainability today.
  • D. Alfred Russel Wallace (1823–1913) was a British naturalist and biologist best known for independently developing the theory of evolution through natural selection alongside Charles Darwin. He conducted significant fieldwork in the Amazon rainforest and the Malay Archipelago, where he observed species distribution and collected specimens. In 1858, Wallace formulated his theory of natural selection, prompting Darwin to publish their findings together. He also proposed "Wallace's Line," a biogeographical boundary. Beyond evolution, Wallace advocated for social reforms, including land nationalization and women's rights. He is remembered as a key figure in the development of evolutionary theory.

Q38. Main function of the epididymis is to:

  • A. Transport sperms
  • B. Connect with urethra
  • C. Produce semen
  • D. Hold the process of spermatogenesis

Explanation: During ejaculation, sperms are transported from the epididymis through the vas deferens and into the urethra for expulsion.

Why the other options are wrong
  • B. The epididymis does not directly connect to the urethra; instead, it connects to the vas deferens, which then transports sperm to the urethra during ejaculation.
  • C. The epididymis does not produce semen; instead, it stores and matures sperm, while semen is produced by accessory glands like the seminal vesicles and prostate gland.
  • D. Spermatogenesis occurs in the seminiferous tubules of the testes, not in the epididymis.

Q39. According to endosymbiosis theory, flagella may have been derived by the ingestion of prokaryotes similar to:

  • A. Amoeboid prokaryote
  • B. Aerobic bacterium
  • C. Spirochete
  • D. Spirillum

Explanation: In the context of the endosymbiotic theory, spirochetes are interesting because some scientists hypothesize that certain spirochetes may have played a role in the evolution of eukaryotic cells. This theory suggests that early eukaryotic ancestors may have engulfed spirochete-like bacteria, leading to the development of complex cellular structures. This relationship could have contributed to the evolution of unique cellular processes seen in modern eukaryotes, illustrating the potential impact of these prokaryotic organisms on the evolution of life.

Why the other options are wrong
  • A. Amoeboid prokaryotes is not a widely recognized term in biology, as amoeboid movement and characteristics are typically associated with eukaryotic organisms, particularly amoebas (such as Amoeba proteus). However, there are some contexts where the term might refer to certain prokaryotic bacteria that exhibit similar movement or behaviors.
  • B. Aerobic bacteria are a group of bacteria that require oxygen for their survival and growth. They use oxygen for cellular respiration, allowing them to generate energy (ATP) more efficiently than anaerobic bacteria, which do not require oxygen.
  • D. Spirillum refers to a genus of Gram-negative bacteria characterized by their rigid, spiral shape and motility, facilitated by polar flagella at both ends, allowing them to move in a rotary motion. They are commonly found in aquatic environments and soil and are notable for their ecological roles. An example is Spirillum minus, associated with rat-bite fever. While spirilla are not directly linked to the endosymbiotic theory, studying their characteristics and behaviors can enhance our understanding of microbial diversity and the evolutionary history of bacteria, contributing to insights into the evolution of more complex life forms.

Q40. Immediate next stage of spermatogonia differentiation is:

  • A. Secondary spermatocyte
  • B. Spermatids
  • C. Primary spermatocytes
  • D. Sperms

Explanation: Primary spermatocytes are diploid cells in the testes formed from spermatogonia. They undergo meiosis I to produce two haploid secondary spermatocytes. Primary spermatocytes are located in the seminiferous tubules and are essential for sperm production.

Why the other options are wrong
  • A. A secondary spermatocyte is a haploid cell formed from a primary spermatocyte during meiosis I in the process of spermatogenesis. Each primary spermatocyte undergoes meiosis I to produce two secondary spermatocytes, which then proceed to undergo meiosis II, resulting in the formation of spermatids. Secondary spermatocytes are found in the seminiferous tubules of the testes and are essential for the production of mature sperm.
  • B. Spermatids are the haploid cells that are formed after the second meiotic division (meiosis II) of secondary spermatocytes during spermatogenesis.
  • D. Sperms (spermatozoa) are the male gametes produced through spermatogenesis. They consist of a head (with genetic material), a midpiece (for energy), and a tail (flagellum) for motility. Their primary function is to fertilize the female egg during reproduction, and they are motile, using their flagella to swim through the female reproductive tract.

Q41. Insulin converts glucose into:

  • A. Vitamins
  • B. Minerals
  • C. Lipids
  • D. Cortisone

Explanation: Lipids are organic compounds that include fats, oils, and waxes. They are key for energy storage, forming cell membranes, and insulating the body.

Why the other options are wrong
  • A. Vitamins are organic compounds essential for various bodily functions. They are required in small amounts and cannot be synthesized by the body.
  • B. Minerals are inorganic nutrients essential for various bodily functions, such as building bones, regulating metabolism, and maintaining nerve function.
  • D. Cortisone is a steroid hormone produced by the adrenal cortex. It is commonly used as an anti-inflammatory medication to treat conditions like arthritis, allergies, and skin diseases. Cortisone helps reduce inflammation and suppress the immune system.

Q42. Which of the following is included in paired cranial bones?

  • A. Temporal
  • B. Occipital
  • C. Frontal
  • D. Vomer

Explanation: The temporal bones are located on the sides and base of the skull, near the ears.

Why the other options are wrong
  • B. The occipital bone is located at the back and base of the cranium. It forms the posterior part of the skull and encloses the back part of the brain. The occipital bone contains the foramen magnum, a large opening that allows the spinal cord to pass through and connect to the brain. It also helps protect the cerebellum and occipital lobe of the brain.
  • C. The frontal bone of the cranium forms the front part of the skull, including the forehead and the upper part of the eye sockets (orbits). It protects the brain and supports the structures of the face. The frontal bone also contributes to the formation of the cranial cavity.
  • D. The vomer is a thin, flat bone located in the nasal cavity. It forms the lower part of the nasal septum, which divides the left and right airways in the nose. The vomer plays a role in supporting the structure of the nasal passages.

Q43. About 70% of the carbon dioxide is carried in blood as:

  • A. Carbonate
  • B. Bicarbonate
  • C. Tricarbonate
  • D. Carbonic anhydrase

Explanation: About 70 percent of CO2 is transported in the form of Bicarbonate ions.

Why the other options are wrong
  • A. Approximately 70% of carbon dioxide in the blood is transported as bicarbonate ions (HCO₃⁻), not carbonate ions.
  • C. Approximately 70% of carbon dioxide in the blood is carried as bicarbonate ions (HCO₃⁻), not as tricarbonate ions. This form allows CO₂ to be efficiently transported from the tissues to the lungs for removal.
  • D. Carbonic anhydrase is an enzyme that catalyzes the conversion of CO₂ and water into carbonic acid (H₂CO₃), but it is not the primary form in which CO₂ is transported in the blood. Instead, about 70% of CO₂ is carried as bicarbonate ions (HCO₃⁻) in plasma.

Q44. Which of the following skeletal disorders is an example of an autoimmune disorder?

  • A. Sciatica
  • B. Spondylosis
  • C. Rheumatoid arthritis
  • D. Rickets

Explanation: Rheumatoid arthritis (RA) is an autoimmune disorder that causes chronic inflammation of the joints. It occurs when the immune system mistakenly attacks the synovium (the lining of the joints), leading to pain, swelling, stiffness, and eventual joint damage. RA can also affect other organs in the body. Treatment includes medications to reduce inflammation, manage pain, and slow joint damage, as well as physical therapy.

Why the other options are wrong
  • A. Sciatica is a condition characterized by pain radiating along the sciatic nerve, which runs from the lower back through the hips and down each leg. It is usually caused by a herniated disc, bone spur, or spinal stenosis compressing the nerve. Symptoms include sharp pain, numbness, or tingling in the leg. Treatment includes pain relief, physical therapy, and, in severe cases, surgery.
  • B. Spondylosis refers to the degeneration of the spine, often due to aging. It affects the vertebrae, discs, and joints, leading to stiffness, pain, and limited movement, especially in the neck (cervical spondylosis) or lower back (lumbar spondylosis). Treatment focuses on pain management, physical therapy, and sometimes surgery in severe cases.
  • D. Rickets is a condition that affects bone development in children, causing soft and weak bones. It is usually caused by a deficiency of vitamin D, calcium, or phosphate, which are essential for healthy bone formation. Common symptoms include delayed growth, bone pain, and deformities such as bowed legs. Rickets can be treated by increasing vitamin D and calcium intake.

Q45. Range of normal total lung capacity in humans is:

  • A. 5-6 liter.
  • B. 8-9 liter
  • C. 10-11 liter
  • D. 12-13 liter

Explanation: The normal lung capacity of an average adult human is about 5 to 6 liters. This total lung capacity (TLC) includes various volumes, such as tidal volume, inspiratory reserve volume, expiratory reserve volume, and residual volume. However, individual capacities can vary based on factors like age, gender, and fitness level.

Why the other options are wrong
  • B. The normal total lung capacity (TLC) in adult humans typically ranges between 5 to 6 liters, depending on factors such as age, sex, body composition, and physical conditioning. A TLC of 8 to 9 liters is considered above average and is generally observed in individuals with exceptional pulmonary function, such as elite athletes.
  • C. A total lung capacity (TLC) of 10 to 11 liters is significantly higher than the average range of 5 to 6 liters observed in healthy adults. Such elevated TLC values are typically associated with elite athletes or individuals with exceptional pulmonary function.
  • D. Total lung capacity (TLC) in healthy adults typically ranges from 4.2 to 6 liters. Values of 12 to 13 liters are significantly higher and are generally not observed in the general population.

Q46. Which feature is possessed by smooth muscles?

  • A. Voluntary
  • B. Branched
  • C. Uninucleate
  • D. Striated appearance

Explanation: Muscles that are uni-nucleate, meaning they contain a single nucleus per cell, primarily include cardiac muscle and smooth muscle. Cardiac muscle cells, or cardiomyocytes, are typically uninucleate, although some may have two nuclei. These involuntary muscles are found in the heart and are responsible for pumping blood, with their uni-nucleate structure aiding in the coordinated contraction through intercalated discs. Similarly, smooth muscle fibers are also uninucleate and are located in the walls of hollow organs, such as the intestines and blood vessels. Smooth muscles are involuntary as well, regulating essential functions like peristalsis in the digestive tract and controlling blood flow. Together, cardiac and smooth muscles play crucial roles in various physiological processes due to their uninucleate characteristics.

Why the other options are wrong
  • A. Voluntary muscles refer primarily to skeletal muscles, which are under conscious control and enable movements of the body. These muscles are attached to bones and work in pairs to facilitate actions such as walking, running, and lifting. Skeletal muscle fibers are long, cylindrical, and striated, allowing for precise and coordinated movements. Unlike involuntary muscles, which operate automatically (like cardiac and smooth muscles), voluntary muscles are activated through the nervous system, allowing individuals to decide when to move and how forcefully to contract the muscles. This control is essential for activities requiring skill and coordination.
  • B. Muscles that are branched include the cardiac muscle. Cardiac muscle fibers are unique in that they have a branched structure, allowing for a network of interconnected cells. This branching facilitates synchronized contractions essential for effective heart function. Each cardiac muscle cell, or cardiomyocyte, typically contains one or two nuclei and is connected to neighboring cells via intercalated discs, which contain gap junctions that enable rapid communication between cells. This branching structure is crucial for maintaining a coordinated heartbeat, enabling the heart to pump blood efficiently throughout the body. In contrast, skeletal muscle fibers are long and cylindrical but do not exhibit branching.
  • D. Muscles with a striated appearance include skeletal muscles and cardiac muscles. Skeletal muscles, which are attached to bones, facilitate voluntary movements and exhibit a distinct striated pattern due to the organized arrangement of actin and myosin filaments. Cardiac muscle, found only in the heart, also displays striations, although they are less pronounced than in skeletal muscle. Cardiac muscle is involuntary and is responsible for pumping blood throughout the body, featuring intercalated discs that connect the cells to ensure synchronized contractions. Both muscle types are characterized by their organized structure of contractile proteins, which contribute to their striated appearance.

Q47. Respiration in Pseudomonas bacteria is:

  • A. Aerobic
  • B. Anaerobic
  • C. Facultative
  • D. Microaerophill

Explanation: Aerobic organisms are microorganisms and other living beings that require oxygen for their survival and growth. They use oxygen in the process of aerobic respiration, a metabolic pathway that generates energy efficiently by oxidizing organic substrates.

Why the other options are wrong
  • B. Anaerobic organisms are microorganisms that thrive in environments devoid of oxygen. They can obtain energy through anaerobic respiration or fermentation, utilizing alternative electron acceptors such as sulfate, nitrate, or organic compounds.
  • C. Facultative anaerobes are microorganisms that can grow in both the presence and absence of oxygen. They can switch between aerobic respiration when oxygen is available and anaerobic respiration or fermentation when it is not. This adaptability allows facultative anaerobes to thrive in a variety of environments.
  • D. Microaerophiles are microorganisms that require low levels of oxygen for growth, typically between 1% to 10%, which is significantly lower than atmospheric oxygen levels (approximately 21%). These organisms thrive in environments where oxygen is limited but are unable to grow in completely anaerobic conditions (absence of oxygen).

Q48. The accumulation of ‘lactic acid’ in the muscles results in:

  • A. Extreme fatigue
  • B. Muscle contraction
  • C. Paralysis
  • D. Convulsion

Explanation: Extreme fatigue, or severe tiredness, is an overwhelming sense of exhaustion that isn't relieved by rest. It can be caused by various factors, including physical exertion, stress, sleep disorders, medical conditions (like anemia or thyroid issues), or mental health disorders (like depression). It may impact daily activities and overall quality of life.

Why the other options are wrong
  • B. Muscle contraction is the process by which muscle fibers shorten or tighten, resulting in movement. It occurs when nerve signals stimulate muscle cells, leading to the interaction of proteins actin and myosin within the muscle. This process is essential for all voluntary and involuntary movements in the body.
  • C. Paralysis is the loss of ability to move one or more muscles, often due to nerve damage, injury, or disease. It can be partial (paresis) or complete and may affect specific body parts, such as limbs (limb paralysis) or the entire body (quadriplegia). Causes include strokes, spinal cord injuries, and certain medical conditions.
  • D. A convulsion is a sudden, uncontrolled electrical disturbance in the brain, leading to changes in behavior, movements, or feelings. It's often associated with epilepsy, but can occur due to other medical conditions. Symptoms may include shaking, loss of consciousness, or unusual sensations.

Q49. Autotrophic mode of nutrition in an organism depends upon:

  • A. Saprotrophic mode
  • B. Parasitic mode
  • C. Photosynthesis mode
  • D. Obligate mode

Explanation: Photosynthesis is the process by which green plants, algae, and some bacteria convert light energy into chemical energy, using carbon dioxide and water to produce glucose and oxygen. This process is vital for life on Earth, as it provides oxygen and is the foundation of the food chain. Autotrophic mode of nutrition in an organism depends upon the photosynthetic mode.

Why the other options are wrong
  • A. The saprotrophic mode refers to a nutritional strategy where organisms obtain their nutrients by decomposing dead organic matter. Saprotrophs break down complex organic materials, recycling nutrients back into the ecosystem.
  • B. The parasitic mode refers to a relationship where one organism (the parasite) benefits at the expense of another organism (the host). Parasites rely on their hosts for nutrients and shelter, often causing harm in the process. This mode of life is common in many biological systems and can be seen in various ecosystems.
  • D. The obligate mode refers to a relationship in which an organism relies entirely on another organism (the host) for survival, reproduction, or both. Obligate organisms cannot complete their life cycle or function properly without their host.

Q50. Thick filaments in skeletal muscles are composed of:

  • A. Actin
  • B. Myosin
  • C. Tropomyosin
  • D. Troponin

Explanation: The thick muscle filament is primarily composed of myosin proteins. In muscle fibers, thick filaments work together with thin filaments (actin) to facilitate muscle contraction.

Why the other options are wrong
  • A. Actin is a protein that forms the thin filaments in muscle fibers and plays a crucial role in muscle contraction and cell movement.
  • C. Tropomyosin is a protein that plays a key role in muscle contraction. It is a long, coiled molecule that binds along the length of actin filaments in both skeletal and cardiac muscle.
  • D. Troponin is a protein complex found in cardiac and skeletal muscle that plays a crucial role in muscle contraction.

Q51. Prokaryotic cells lack:

  • A. Mesosomes
  • B. Ribosomes
  • C. Storage bodies
  • D. Membrane bound organelles

Explanation: Prokaryotic cells, such as bacteria and archaea, lack membrane-bound organelles like a nucleus, mitochondria, or endoplasmic reticulum. Their cellular processes occur directly in the cytoplasm or at the plasma membrane. However, they do have structures like ribosomes and storage bodies, which are not membrane-bound. This simplicity distinguishes them from eukaryotic cells, which contain complex organelles.

Why the other options are wrong
  • A. Mesosomes are inward foldings of the plasma membrane observed in some bacterial cells. They were initially thought to increase surface area for respiration and aid in cell division. However, many scientists now consider them artifacts formed during chemical fixation in microscopy. Despite this, they are still described as membrane infoldings associated with various cellular processes.
  • B. Ribosomes are the sites where amino acids are assembled into proteins according to the sequence carried by mRNA. They read the codons on mRNA and match them with the appropriate tRNA molecules. Ribosomes exist freely in the cytoplasm or attached to the endoplasmic reticulum. They function in both prokaryotic and eukaryotic cells, although their sizes differ slightly.
  • C. Storage bodies are cellular structures that store nutrients, energy reserves, or other important molecules. In prokaryotes, they may contain glycogen, polyphosphate, or lipids, while in eukaryotes they can include lipid droplets, starch granules, or vacuoles. These structures help the cell survive periods of nutrient scarcity. By storing essential substances, storage bodies support metabolism and overall cellular function.

Q52. Bacterial genome becomes diploid:

  • A. After fertilization of gametes
  • B. Before spore formation
  • C. During binary fission
  • D. After binary fission

Explanation: The circular bacterial genome is replicated. The process begins at the origin of replication, where the DNA unwinds and new complementary strands are synthesized, resulting in two identical copies of the genome.

Why the other options are wrong
  • A. This doesn't happen in bacteria.
  • B. Before the formation of spores, the genome is replicated to ensure that each spore will inherit a complete set of genetic material. This is critical for the viability of the spore.
  • D. Each daughter cell receives a complete copy of the parental genome, ensuring that both cells have the necessary genetic information to function and replicate in the future.

Q53. In the journey of electrons from photosystem II to photosystem I plastocyanin is reduced by:

  • A. Plastoquinone
  • B. Cytochrome complex
  • C. P700
  • D. Primary electron acceptor of PS1

Explanation: Plastocyanin is reduced when it accepts an electron from the cytochrome b6f complex, and this electron reduces the copper ion in plastocyanin from Cu²⁺ to Cu⁺. This process is essential for transferring electrons between photosystem II and photosystem I in the electron transport chain of photosynthesis.

Why the other options are wrong
  • A. Plastoquinone is involved in transferring electrons from photosystem II to the cytochrome complex, not directly reducing plastocyanin.
  • C. P700 is the reaction center of photosystem I, where electrons are ultimately transferred, but it doesn't reduce plastocyanin.
  • D. The primary electron acceptor in photosystem I accepts electrons, not reducing plastocyanin.

Q54. Enzyme NADP reductase is responsible for:

  • A. Reducing NADP+
  • B. Oxidizing NADP+
  • C. Reducing Ferredoxin
  • D. Reducing P700

Explanation: NADP reductase is an enzyme that plays a key role in the light-dependent reactions of photosynthesis. It is responsible for transferring electrons from ferredoxin to NADP+, reducing it to NADPH.

Why the other options are wrong
  • B. Oxidizing NADP+ would imply turning NADP+ into NADP (which isn't the process happening in photosynthesis). Instead, NADP+ is reduced to NADPH.
  • C. Ferredoxin is already reduced during the electron transport process and donates electrons to NADP reductase, so it is not reduced by NADP reductase.
  • D. P700 is part of photosystem I and gets oxidized, not reduced, during the light-dependent reactions.

Q55. The PS II, during light reaction,s receives electrons from splitting:

  • A. Water
  • B. Plastoquinone
  • C. Plastocyanin
  • D. Ferredoxin

Explanation: Water is the true source of electrons for PS II, where photolysis (splitting of water) provides the electrons to start the chain.

Why the other options are wrong
  • B. Plastoquinone accepts electrons from PS II and transfers them to the cytochrome b6f complex in the electron transport chain. It acts as a mobile electron carrier after PS II, not before.
  • C. Plastocyanin transfers electrons between cytochrome b6f complex and Photosystem I (PS I). It carries electrons to PS I, not PS II. Plastocyanin comes into play after electrons have been excited and moved through the chain, starting from PS II.
  • D. Ferredoxin is involved later in the electron transport chain, specifically in Photosystem I (PS I), where it accepts electrons and helps reduce NADP⁺ to NADPH. It does not donate electrons to PS II; instead, it acts downstream in the process.

Q56. Mono-saccharides have a general formula represented by:

  • A. (CH2O)n
  • B. C(H2O)n
  • C. C2(H2O)n
  • D. C2(H2O)n

Explanation: A monosaccharide is the most basic form of carbohydrates.Monosaccharides can be combined through glycosidic bonds to form larger carbohydrates, known as oligosaccharides or polysaccharides.The general formula for Mono-saccharides is (CH2O)n. Note that A and B are NOT the same. A is made up of n carbon atoms and n H₂O molecules. B is made up of 1 carbon atom and n molecules of H₂O.

Why the other options are wrong
  • B. A monosaccharide is the most basic form of carbohydrates. Monosaccharides can be combined through glycosidic bonds to form larger carbohydrates, known as oligosaccharides or polysaccharides.The general formula for Mono-saccharides is (CH2O)n.
  • C. A monosaccharide is the most basic form of carbohydrates. Monosaccharides can be combined through glycosidic bonds to form larger carbohydrates, known as oligosaccharides or polysaccharides.The general formula for Mono-saccharides is (CH2O)n.
  • D. A monosaccharide is the most basic form of carbohydrates. Monosaccharides can be combined through glycosidic bonds to form larger carbohydrates, known as oligosaccharides or polysaccharides.The general formula for Mono-saccharides is (CH2O)n.

Q57. What is the percentage of H₂O in bone cells?

  • A. 70%
  • B. 20%
  • C. 99%
  • D. 60%

Explanation: Bone cells are composed of approximately 20% water, which is essential for facilitating cellular functions and maintaining the hydration of the bone matrix. The majority of a bone's composition is mineral-based, primarily calcium phosphate, along with proteins and collagen. Option A (70%) and Option D (60%) are incorrect because they overestimate the water content. Option C (99%) is excessively high as bones are not soft tissues like muscles, which contain more water.

Why the other options are wrong
  • A. This is incorrect. Bone cells contain about 20% water, which is essential for maintaining cell function and hydration, but the majority of bone mass is minerals and collagen.
  • C. This is far too high. Bones are primarily composed of minerals, not water. The water content in bone cells is around 20%.
  • D. This is incorrect. Although bones require water for cellular activities, their primary composition includes minerals and collagen, making the water percentage around 20%.

Q58. When glycerol reacts with fatty acid, which type of chemical bond will form?

  • A. Ester bond
  • B. Ether linkage
  • C. Hydrogen bond
  • D. Ionic bond

Explanation: When glycerol (a type of alcohol) reacts with fatty acids (which contain carboxyl groups), an ester bond is formed through a dehydration synthesis reaction. This is the key bond found in triglycerides, which are fats and oils.

Why the other options are wrong
  • B. An ether linkage forms when two alcohol molecules react, but it does not form in the reaction between glycerol and fatty acids. Instead, glycerol reacts with fatty acids to form ester bonds, not ether bonds.
  • C. Hydrogen bonds are a type of weak attraction between molecules, not a covalent bond formed during the reaction between glycerol and fatty acids. Ester bonds are the primary bonds formed in this reaction.
  • D. Ionic bonds form between positively and negatively charged ions, which does not occur in the reaction between glycerol and fatty acids. The reaction forms covalent ester bonds, not ionic bonds.

Q59. Polysaccharides in plants are synthesized by the process of:

  • A. Hydrolysis
  • B. Oxidation
  • C. Condensation
  • D. Glycolysis

Explanation: Condensation is a chemical reaction in which two molecules combine to form a larger molecule, releasing a small molecule, often water, as a byproduct.

Why the other options are wrong
  • A. Hydrolysis is a chemical reaction in which water is used to break down a compound, resulting in the separation of its molecules into smaller units.
  • B. Oxidation is a chemical process in which a substance loses electrons, often accompanied by an increase in oxidation state, and can involve the addition of oxygen or the removal of hydrogen.
  • D. Glycolysis is a metabolic pathway that converts glucose into pyruvate, producing ATP and NADH in the process, and occurs in the cytoplasm of cells.

Q60. Which of the following process is involved in breakdown of protein into Amino acids?

  • A. Condensation
  • B. Hydrolysis
  • C. Glycolysis
  • D. Fixation

Explanation: Hydrolysis is a chemical reaction where water is used to break down a compound, resulting in the separation of the compound into its constituent parts.

Why the other options are wrong
  • A. Condensation is a chemical reaction in which two molecules combine to form a larger molecule while releasing a smaller molecule, typically water, as a byproduct.
  • C. Glycolysis is a series of enzymatic reactions that convert glucose into pyruvate, producing ATP and NADH as energy carriers, and occurs in the cytoplasm of cells.
  • D. Fixation is a process in biology where carbon dioxide is converted into organic compounds, such as sugars, typically during photosynthesis or nitrogen fixation in plants.

Q61. Sarcomere is part of myofibril between:

  • A. Two I bands
  • B. Two A bands
  • C. Two M lines
  • D. Two Z lines

Explanation: A sarcomere is the basic structural and functional unit of a muscle fiber, specifically within striated muscle such as skeletal and cardiac muscle. It is defined as the segment of the myofibril that lies between two adjacent Z-discs (or Z-lines).

Why the other options are wrong
  • A. A sarcomere is the functional unit of a myofibril, defined as the segment between two Z-lines (or Z-discs), not between two I bands. The I bands are lighter regions flanking the Z-lines, containing only thin actin filaments, while the A bands are darker regions containing overlapping thick (myosin) and thin (actin) filaments.
  • B. A sarcomere is the fundamental contractile unit of striated muscle fibers, defined as the segment between two Z-lines (or Z-discs). Each sarcomere contains a single A-band, which corresponds to the length of the thick (myosin) filaments. Therefore, a sarcomere cannot span between two A-bands, as each A-band is contained within its sarcomere.
  • C. A sarcomere is defined as the segment between two Z-lines (or Z-discs) in a myofibril. The M-line is located at the center of the sarcomere, within the A-band, and serves as the attachment site for thick (myosin) filaments.

Q62. Chloroplast are membrane bound bodies containing:

  • A. Enzymes
  • B. Cisternae
  • C. Pigment
  • D. Cristae

Explanation: Chloroplasts are pigmented organelles, i.e, they contain some kind of pigment, which is chlorophyll.

Why the other options are wrong
  • A. Both chloroplasts and mitochondria contain enzymes essential for energy-related processes. In mitochondria, enzymes in the matrix participate in the Krebs cycle to produce ATP. In chloroplasts, enzymes in the stroma (analogous to the matrix) are involved in the Calvin cycle for synthesizing carbohydrates. These enzymes enable the organelles to carry out their specific metabolic functions efficiently.
  • B. Cisternae are flattened, membrane-bound sacs that make up the Golgi apparatus. They function as the main sites for modifying, sorting, and packaging proteins and lipids received from the endoplasmic reticulum. Each cisterna contains enzymes that carry out specific chemical modifications. This organized structure allows efficient processing and transport of cellular molecules.
  • D. Cristae are the inward folds of the inner mitochondrial membrane. They increase the surface area available for enzymes involved in the electron transport chain and ATP production. This structural feature allows mitochondria to generate energy efficiently through oxidative phosphorylation. The number and shape of cristae can vary depending on the energy needs of the cell.

Q63. Which of the following is the function of Golgi Complex?

  • A. Intracellular digestion
  • B. Autophagy
  • C. Autolysis
  • D. Processing of cell secretions

Explanation: The Golgi apparatus processes and packages cell secretions by receiving proteins and lipids from the endoplasmic reticulum in transport vesicles, modifying them through post-translational changes such as glycosylation, sorting them based on destination signals, and then packaging them into membrane-bound vesicles. These vesicles can become secretory vesicles for export, lysosomes for intracellular digestion, or other types. Once packaged, the vesicles bud off from the Golgi and are transported to their target locations, where they fuse with membranes to deliver their contents, playing a crucial role in the secretion and distribution of cellular molecules.

Why the other options are wrong
  • A. Lysosomes are membrane-bound organelles that contain hydrolytic enzymes capable of breaking down proteins, lipids, carbohydrates, and nucleic acids. They digest materials brought into the cell through endocytosis or recycle worn-out organelles in a process called autophagy. By performing intracellular digestion, lysosomes help maintain cellular health and prevent the accumulation of waste.
  • B. Autophagy is a process in which cells degrade and recycle their own damaged or unnecessary components. Lysosomes play a central role by fusing with the vesicles containing these cellular materials and breaking them down with their enzymes. This process helps maintain cellular homeostasis, provides energy during nutrient shortage, and removes potentially harmful structures. It is an essential mechanism for cell survival and renewal.
  • C. Autolysis is the process of self-digestion in which a cell breaks down its own components, usually after damage or death. Lysosomes carry out autolysis by releasing their hydrolytic enzymes into the cytoplasm. This helps in removing defective or dead cells and recycling their components. Autolysis is an important mechanism for tissue remodeling and maintaining cellular health.

Q64. The hydrophilic end of the phospholipid molecule is polar because of the presence of:

  • A. Glycerol
  • B. Amine group
  • C. Fatty Acid
  • D. Phosphate group

Explanation: The phosphate group (-PO₄³⁻) in phospholipids is part of the molecule's hydrophilic head. It connects the glycerol backbone to a polar group (like choline, serine, or ethanolamine) and carries a negative charge, making it highly polar. This polarity allows the phosphate group to interact with water and other polar substances, contributing to the formation of the lipid bilayer in cell membranes. The phosphate group plays a key role in maintaining membrane structure and function.

Why the other options are wrong
  • A. Glycerol is a three-carbon molecule that serves as the backbone in triglycerides and phospholipids. In triglycerides, each of the three hydroxyl groups (-OH) of glycerol bonds with a fatty acid through an ester linkage. In phospholipids, two of the hydroxyl groups bond with fatty acids to form the hydrophobic tails, while the third bonds with a phosphate group, which forms the hydrophilic head.
  • B. The amine group contributes to the hydrophilic properties of the phospholipid head, making it interact well with water.
  • C. The combination of saturated and unsaturated fatty acids in phospholipids affects the flexibility and permeability of cell membranes.

Q65. Nissl’s granules are groups of:

  • A. Mesosomes
  • B. Lysosomes
  • C. Ribosomes
  • D. Chromosome

Explanation: Nissl granules are primarily made up of rough endoplasmic reticulum (rER) and ribosomes. The rough endoplasmic reticulum is involved in the synthesis of proteins, while the ribosomes are the sites of protein translation. Together, these components contribute to the production of neurotransmitters and other proteins necessary for neuronal function and maintenance. The abundance of rER and ribosomes gives Nissl granules their characteristic granular appearance when stained.

Why the other options are wrong
  • A. Incorrect, as mesosomes are foldings of the plasma membrane in prokaryotic cells, not related to Nissl’s granules.
  • B. Incorrect, because lysosomes are involved in digestion, whereas Nissl’s granules are linked to protein synthesis.
  • D. Incorrect, since chromosomes contain genetic material but are not related to Nissl’s granules.

Q66. Which monosaccharide will from a gluco-pyranose ring in solution?

  • A. Fructose
  • B. Glucose
  • C. Ribose
  • D. Deoxyribose

Explanation: Typically, glucose forms a six-membered ring called a pyranose. This ring consists of five carbon atoms and one oxygen atom.

Why the other options are wrong
  • A. It can form either a five-membered furanose ring or a six-membered pyranose ring, though the five-membered furanose form is more common in solution.
  • C. Also forms a five-membered ring called a furanose in RNA, with four carbon atoms and one oxygen atom in the ring.
  • D. Forms a five-membered ring called a furanose in DNA. The ring consists of four carbon atoms and one oxygen atom.

Q67. The nucleus takes dyes due to the presence of:

  • A. Chromatin
  • B. Lipid
  • C. Metal ions
  • D. Thylakoids

Explanation: This option is correct. Chromatin is composed of DNA and proteins, and it is present in the nucleus. It can take up certain dyes, especially those that bind to nucleic acids, allowing visualization of the nucleus under a microscope.

Why the other options are wrong
  • B. Lipids form the structural framework of cell membranes but are not responsible for staining the nucleus. The uptake of dyes in the nucleus is mainly due to nucleic acids, like DNA and RNA, which bind strongly to basic dyes. Lipids, being nonpolar, do not interact significantly with these dyes. Therefore, they do not contribute to nuclear staining.
  • C. While metal ions can sometimes bind to biological molecules, they do not play a direct role in nuclear staining. Nuclear dyes, such as hematoxylin, specifically bind to nucleic acids like DNA and RNA. The staining occurs because of the chemical affinity between the dye and the negatively charged phosphate groups in nucleic acids, not due to metal ions.
  • D. Thylakoids are membrane-bound structures within chloroplasts that carry out the light-dependent reactions of photosynthesis. They contain chlorophyll and other pigments but have no role in the nucleus or in nuclear staining. Nuclear staining depends on nucleic acids, not chloroplast components like thylakoids.

Q68. The organelles only found at seeding stage in oil seed plants are:

  • A. Peroxisomes
  • B. Glyoxysomes
  • C. Microbodies
  • D. Vacuoles

Explanation: Microbodies, which include organelles like peroxisomes and glyoxysomes, are present in plant cells during their normal metabolic processes, particularly in tissues involved in lipid metabolism and photosynthesis.

Why the other options are wrong
  • A. Peroxisomes are found in plant cells at all stages of growth and development and are involved in various metabolic processes, including the breakdown of fatty acids and detoxification of hydrogen peroxide.
  • C. Microbodies, which include organelles like peroxisomes and glyoxysomes, are present in plant cells during their normal metabolic processes, particularly in tissues involved in lipid metabolism and photosynthesis.
  • D. Vacuoles are typically present in plant cells throughout their life cycle, playing crucial roles in storage, maintaining turgor pressure, and waste disposal. They are especially prominent in mature plant cells.

Q69. Posterior lobe of pituitary produce:

  • A. Antidiuretic Hormone (ADH)
  • B. Thyroid Stimulating Hormone (TSH)
  • C. Adreno Corticufrotric Hormone (ACH)
  • D. Follicle Stimulating Hormone (FSH)

Explanation: ADH is synthesized in the posterior side of the pituitary gland. It regulates water retention by the kidneys, promoting water reabsorption and helping maintain blood pressure.

Why the other options are wrong
  • B. TSH is produced in the anterior pituitary gland. It stimulates the thyroid gland to produce and release thyroid hormones (T3 and T4), which regulate metabolism in the body.
  • C. Acetylcholine is synthesized in the nerve terminals of cholinergic neurons. It acts as a neurotransmitter in both the central and peripheral nervous systems, facilitating communication between nerve cells and their target cells.
  • D. FSH is produced in the anterior pituitary gland. In females, it stimulates the development of ovarian follicles, while in males, it promotes spermatogenesis.

Q70. In human myelinated fibres nerve impulse travels at _ meters per second.

  • A. 100-120
  • B. 130-150
  • C. 160-180
  • D. 190-210

Explanation: Option A is correct, as nerve impulses in human myelinated fibers typically travel within a 100-120 range due to saltatory conduction.

Why the other options are wrong
  • B. Incorrect, as this speed is slightly higher than the normal range observed in humans.
  • C. Incorrect, as such high speeds are uncommon in human myelinated neurons.
  • D. Incorrect, since no human myelinated fiber reaches this extreme speed.

Q71. One of the following is CORRECT regarding flagella:

  • A. Made up of microfilaments
  • B. Contains centriole
  • C. Originates from basal bodies
  • D. They are immotile

Explanation: Flagella originate from basal bodies, which are protein structures located at the base of these appendages. Basal bodies serve as microtubule-organizing centers, anchoring and initiating the assembly of the axoneme—the core structural component of flagella. Structurally similar to centrioles, basal bodies consist of nine peripheral microtubule triplets arranged in a cylindrical pattern. In cells destined to have a single primary cilium, the mother centriole differentiates into the basal body upon entry into the G1 phase or during quiescence. In multiciliated cells, basal bodies can be generated de novo from a specialized structure called the deuterosome. This transformation is crucial for the proper formation and function of flagella, facilitating cell motility and sensory functions.

Why the other options are wrong
  • A. Basal bodies are composed of microtubules, not microfilaments, because they serve as microtubule-organizing centers essential for the assembly and anchorage of flagella.
  • B. Flagella are anchored in the cell by basal bodies, which are modified centrioles.The basal body serves as the foundation for flagellum assembly and anchorage, while the centriole's primary role is in organizing microtubules during cell division.Therefore, while centrioles themselves are not part of the flagella structure, their modified forms, the basal bodies, are integral components of flagella.
  • D. Flagella are typically motile structures that enable cells to move. They function by rotating or whipping, propelling the cell through its environment. Flagella can become immotile due to genetic disorders such as primary ciliary dyskinesia (PCD), which affects the structure and function of cilia and flagella, leading to impaired movement. In males, this can result in reduced sperm motility, known as asthenozoospermia, contributing to infertility.

Q72. During the non-conducting state, the neuron membrane is permeable to the efflux of:

  • A. K+
  • B. Na+
  • C. Ca+
  • D. Cl-

Explanation: During the non-conducting state (resting state) of a neuron, the neuronal membrane is primarily permeable to the efflux of potassium ions (K⁺). This permeability is due to the presence of potassium channels that allow K⁺ to flow out of the cell, contributing to the resting membrane potential, which is typically around -70 mV. The efflux of K⁺ ions occurs because of their higher concentration inside the neuron compared to the outside, leading to a net outward movement and a negative charge inside the neuron.

Why the other options are wrong
  • B. Incorrect, as Na⁺ influx is restricted due to low permeability at rest.
  • C. Incorrect, since Ca⁺ channels remain mostly closed at the resting state.
  • D. Incorrect, though Cl⁻ can move, it is not primarily responsible for resting membrane potential regulation.

Q73. Medulla Oblongata is a part of:

  • A. Forebrain
  • B. Mid brain
  • C. Hind brain
  • D. Hippocampus

Explanation: The hindbrain is the posterior part of the brain that plays a vital role in controlling essential bodily functions and motor activities. It consists of three main components: the medulla oblongata, which regulates autonomic functions such as heart rate, breathing, and reflexes; the pons, which serves as a bridge between different parts of the brain and is involved in regulating sleep and respiration; and the cerebellum, which coordinates voluntary movements, balance, and motor learning. Together, these structures ensure smooth and precise motor control while maintaining critical life-sustaining functions, making the hindbrain essential for overall health and functionality.

Why the other options are wrong
  • A. The forebrain, or prosencephalon, is the largest and most intricate region of the brain, responsible for a wide array of higher cognitive functions, sensory processing, and emotional regulation. It includes the cerebrum, which is divided into two hemispheres and further subdivided into lobes (frontal, parietal, temporal, and occipital) that facilitate advanced functions such as reasoning, problem-solving, memory, language, and voluntary muscle movements. The thalamus, located atop the brainstem, serves as the primary relay station for sensory information, directing signals to the appropriate areas of the cerebral cortex for processing. Below the thalamus lies the hypothalamus, which regulates critical bodily functions such as temperature, hunger, thirst, sleep-wake cycles, and hormonal release from the pituitary gland, playing a key role in maintaining homeostasis and emotional responses. Additionally, the limbic system, encompassing structures like the hippocampus and amygdala, is vital for memory formation and emotional regulation. Overall, the forebrain is essential for coordinating sensory input and emotional responses, enabling the complex behaviors and cognitive processes that define human experience.
  • B. The midbrain, or mesencephalon, is a vital region situated between the hindbrain and forebrain, playing essential roles in sensory processing and motor coordination. It consists of two main parts: the tectum, which contains the superior and inferior colliculi responsible for visual and auditory processing, respectively, and the tegmentum, which includes important nuclei such as the red nucleus and substantia nigra that are involved in motor control and the regulation of consciousness. The cerebral peduncles, large bundles of nerve fibers, connect the forebrain to the hindbrain, facilitating communication between these brain regions. Overall, the midbrain is crucial for integrating sensory information, coordinating reflexive movements, and regulating alertness and attention, making it a key player in both motor control and sensory perception.
  • D. The hippocampus is a critical structure in the brain primarily associated with memory and learning.

Q74. Which option is CORRECT about endospore?

  • A. Has a short dormant period
  • B. Contains moisture for survival
  • C. Metabolically active
  • D. Endures extreme condition

Explanation: Endospores are incredibly resilient to extreme environmental conditions, including high temperatures, desiccation, radiation, and chemical disinfectants. This resistance is due to their tough outer layers.

Why the other options are wrong
  • A. Some bacterial spores have been recovered from ancient sediments or permafrost, demonstrating their ability to remain dormant for thousands of years and still retain viability.
  • B. Endospores contain very little water, which helps them withstand extreme conditions. The dehydration process contributes to their stability and longevity.
  • C. Endospores exhibit minimal metabolic activity, entering a dormant state that allows them to survive until conditions become favorable for germination and growth.

Q75. Which of the following is NOT a bone of upper limb?

  • A. Humerus
  • B. Ulna
  • C. Femur
  • D. Radius

Explanation: The femur extends from the hip joint to the knee joint, forming the upper leg. It connects the pelvis to the tibia (shinbone).

Why the other options are wrong
  • A. The humerus is the long bone of the upper arm, extending from the shoulder to the elbow.
  • B. The ulna is one of the two long bones in the forearm, the other being the radius.
  • D. The radius is one of the two long bones in the forearm, the other being the ulna.

Q76. Bacteria divide at exponential rate during which growth phase!

  • A. Lag
  • B. Log
  • C. Stationary
  • D. Decline

Explanation: In this phase, bacteria divide rapidly by binary fission, where each cell splits into two identical daughter cells. The population grows exponentially, doubling at a constant rate. This is the period of maximum growth and optimal conditions for cell division.

Why the other options are wrong
  • A. During this phase, bacteria are not dividing. Instead, they are adapting to their new environment, synthesizing necessary enzymes and molecules for growth. Although there is little to no increase in cell numbers, metabolic activity is high as the cells prepare for division.
  • C. Division slows down as nutrients become depleted and waste products accumulate. The rate of bacterial cell death equals the rate of new cell formation, leading to a stable population size. Although some cells may continue to divide, overall growth halts due to resource limitations.
  • D. In this phase, the number of dying cells exceeds the number of new cells being produced. The bacteria start to die off due to nutrient exhaustion, toxic waste accumulation, or other environmental stresses, leading to a gradual decline in the population.

Q77. Bone forming cells are:

  • A. Osteoblasts
  • B. Osteocytes
  • C. Osteoclasts
  • D. Osteons

Explanation: Osteoblasts are cells responsible for bone formation. They synthesize and secrete the bone matrix, which is primarily composed of collagen and other proteins. Once the matrix mineralizes and the osteoblasts become trapped within it, they differentiate into osteocytes. Osteoblasts are crucial for bone growth and repair.

Why the other options are wrong
  • B. Osteocytes are mature bone cells that originate from osteoblasts. They are embedded within the bone matrix and maintain bone tissue by regulating mineral content and communicating with other bone cells to help with bone remodeling and repair. Osteocytes reside in small cavities called lacunae and extend through tiny channels called canaliculi to exchange nutrients and waste.
  • C. Osteoclasts are large, multinucleated cells responsible for bone resorption, the process of breaking down bone tissue. They dissolve the mineral matrix of bone by secreting acids and enzymes, playing a key role in bone remodeling and calcium regulation.
  • D. Osteons (or Haversian systems) are the fundamental structural units of compact bone. They consist of concentric rings of bone tissue called lamellae surrounding a central canal (Haversian canal) that contains blood vessels and nerves. Osteons help provide strength and support to bones, allowing them to withstand stress.

Q78. Example of viruses having a polyhedral capsid that is with 252 capsomeres is:

  • A. Adenovirus
  • B. Tobacco Mosaic Virus
  • C. Influenza virus
  • D. Bacteriophage

Explanation: The capsid of adenovirus typically contains 52 capsomeres. This includes 240 hexon capsomeres and 12 penton capsomeres at the vertices.

Why the other options are wrong
  • B. The Tobacco Mosaic Virus (TMV) has a helical capsid made up of 2,130 capsomeres, which are protein subunits that form a spiral around the RNA genome.
  • C. The Influenza virus does not have a defined number of capsomeres because it has a helical capsid. Its structure consists of multiple RNA segments encapsulated by nucleoproteins, rather than a single capsid with a fixed number of capsomeres like icosahedral viruses.
  • D. The number of capsomeres in a bacteriophage capsid can vary depending on the specific type of phage. For example, T4 bacteriophage (a common model): Its icosahedral head typically contains about 152 capsomeres. Different bacteriophages may have different capsomere counts, depending on their structure.

Q79. The chromosomes was first observed by:

  • A. T. H Morgan
  • B. Griffith
  • C. Walther
  • D. Mendel

Explanation: Walther Flemming first observed chromosomes in 1879 during his studies on cell division (mitosis) using a light microscope.

Why the other options are wrong
  • A. Thomas Hunt Morgan was an American geneticist who is best known for his work with the fruit fly, Drosophila melanogaster. In the early 20th century, he discovered that genes are located on chromosomes and provided the first solid evidence for the chromosome theory of inheritance.
  • B. Frederick Griffith was a British bacteriologist who, in 1928, discovered the phenomenon of bacterial transformation. In his famous experiment, he worked with two strains of Streptococcus pneumoniae: a virulent (S) strain and a non-virulent (R) strain.
  • D. Gregor Mendel was an Austrian monk who is known as the "father of modern genetics." In the mid-19th century, through his experiments with pea plants, he discovered the fundamental laws of inheritance.

Q80. The complete, mature & infectious particle of virus is known as:

  • A. Genome
  • B. Capsomere
  • C. Virion
  • D. Envelope

Explanation: A virion is the fully assembled, infectious form of a virus when it’s outside a host cell. It includes the genetic material along with its protective protein coat, and sometimes an envelope, allowing it to survive in the environment and infect new cells.

Why the other options are wrong
  • A. A genome is the complete set of genetic material (DNA or RNA) present in an organism or virus. It includes all the genes and non-coding sequences that contribute to the organism's structure, function, and development.
  • B. A capsomere is a protein subunit that makes up the capsid of a virus. Capsomers are arranged in a specific way to form the protective shell that encases and protects the viral genetic material (DNA or RNA).
  • D. The envelope in viruses is a lipid membrane that surrounds the viral capsid. It is derived from the host cell's membrane during the viral budding process.

Q81. The causative organism of measles is:

  • A. Poxivirus
  • B. Paporivirus
  • C. Picornovirus
  • D. Paramyxovirus

Explanation: Measles is caused by the measles virus, which is an RNA virus belonging to the Morbillivirus genus within the Paramyxoviridae family. The virus primarily infects the respiratory tract and can spread throughout the body, leading to the characteristic symptoms of measles, including fever, cough, runny nose, conjunctivitis, and the distinctive rash.

Why the other options are wrong
  • A. Poxviruses are responsible for several significant diseases in humans and animals, with notable examples including smallpox, monkeypox, cowpox, orf, and tanapox. Smallpox, caused by the variola virus, was characterized by fever and a distinctive rash, leading to its eradication in 1980 through successful vaccination efforts.
  • B. Papoviruses are a group of viruses that include papillomaviruses and polyomaviruses, which are known to cause various diseases in humans and animals. Human papillomavirus (HPV) is the most notable, with certain strains causing genital warts and others linked to cancers such as cervical, anal, and oropharyngeal cancer, making it one of the most common sexually transmitted infections.
  • C. Picornaviruses are responsible for a range of diseases in humans and animals. Notably, poliovirus can cause poliomyelitis, leading to paralysis and long-term disabilities, primarily affecting children. Rhinoviruses are the main culprits behind the common cold, which is characterized by symptoms such as a runny nose, sore throat, and cough.

Q82. In the life cycle of a bacteriophage, the lysozymes are required in which of the following steps of the infection process?

  • A. Genome injection
  • B. Penetration
  • C. Replication
  • D. Adsorption

Explanation: Penetration in the context of bacteriophages refers to the process by which the phage injects its genetic material into a bacterial host cell after successfully adsorbing to the bacterial surface. This step is critical for the viral life cycle as it enables the phage to hijack the host's cellular machinery to replicate and produce new phage particles. L ysozyme hydrolyzes the peptidoglycan layer in bacterial cell walls, leading to cell lysis and death

Why the other options are wrong
  • A. Once close to the bacterial cell, the phage punctures the bacterial cell wall using specialized proteins or enzymes in the tail. This allows the phage to inject its genetic material (DNA or RNA) through the tail tube into the bacterial cytoplasm.
  • C. Replication in the context of bacteriophages refers to the process by which a phage reproduces itself within a bacterial host following the successful adsorption of the phage to the bacterial cell. This process can occur through two primary pathways: the lytic cycle and the lysogenic cycle.
  • D. Adsorption in the context of bacteriophages refers to the initial step in the viral infection process, where a phage attaches itself to the surface of a bacterial cell. This process is crucial for the successful infection of the bacteria.

Q83. _ is transmitted through infected blood and hypodermic syringes.

  • A. HIV
  • B. Influenza virus
  • C. Morbilli virus (Measles)
  • D. Vibrio Cholerae (Cholera)

Explanation: HIV (Human Immunodeficiency Virus) is primarily transmitted through several key routes. The most common mode of transmission is through unprotected sexual contact with an infected individual, where the virus can enter the body through mucous membranes. Additionally, sharing needles or syringes among intravenous drug users poses a significant risk, as it allows for direct blood-to-blood contact. HIV can also be transmitted from an infected mother to her child during childbirth or breastfeeding, highlighting the importance of preventive measures for pregnant women living with HIV. Lastly, although less common, transmission can occur through blood transfusions or organ transplants from an infected donor, particularly in areas where blood screening is inadequate. Understanding these transmission routes is crucial for implementing effective prevention strategies to reduce the spread of HIV.

Why the other options are wrong
  • B. Influenza (the flu) spreads mainly through respiratory droplets produced when an infected person coughs, sneezes, or talks. It can also be transmitted by touching surfaces contaminated with the virus and then touching the face, particularly the mouth, nose, or eyes.
  • C. Measles is highly contagious and spreads through respiratory droplets when an infected person coughs or sneezes. It can also be transmitted by direct contact with nasal or throat secretions. The virus can remain infectious in the air for up to two hours after the infected person has left the area.
  • D. Cholera is primarily transmitted through the fecal-oral route, often due to the consumption of contaminated water or food. The bacterium Vibrio cholerae, which causes the disease, can thrive in unsanitary conditions, especially in areas with poor sanitation and inadequate access to clean drinking water.

Q84. In the Calvin cycle, CO2 reacts with RuBP to produce _.

  • A. 3-PGA
  • B. G3P
  • C. 6-Carbon unstable intermediate
  • D. 1,3 bisphosphoglycerate

Explanation: The reaction in the Calvin cycle where CO₂ reacts with RuBP produces a 6-carbon unstable intermediate because of the way carbon fixation occurs during the process.

Why the other options are wrong
  • A. 3-PGA is the product of the breakdown of the 6-carbon unstable intermediate, not the direct product of the CO₂ + RuBP reaction.
  • B. 3-PGA is the product of the breakdown of the 6-carbon unstable intermediate, not the direct product of the CO₂ + RuBP reaction.
  • D. 3-PGA is the product of the breakdown of the 6-carbon unstable intermediate, not the direct product of the CO₂ + RuBP reaction.

Q85. Which option is correct about a chlorophyll a molecule?

  • A. Chemical formula C55H70O6N4Mg
  • B. Porphyrin ring with nitrogen in centre
  • C. Methyl group on second pyrrole ring
  • D. Aldehyde group on second pyrrole ring

Explanation: The statement "Methyl group on the second pyrrole ring" in the context of chlorophyll a is correct.The presence of a methyl group on the second pyrrole ring is a correct part of the chlorophyll structure and plays a role in its overall function in photosynthesis.

Why the other options are wrong
  • A. The chemical formula C55H70O6N4Mg is incorrect for chlorophyll a because chlorophyll a contains a magnesium ion (Mg²⁺) coordinated within its structure, but the correct molecular formula should be C55H72O5N4Mg.
  • B. The statement "Porphyrin ring with nitrogen in the center" is incorrect for chlorophyll a because the central atom of the porphyrin ring in chlorophyll a is magnesium (Mg), not nitrogen.
  • D. The statement "Aldehyde group on the second pyrrole ring" is incorrect because chlorophyll a does not have an aldehyde group attached to the second pyrrole ring.

Q86. Which of the following alcohol can give a lodoform reaction?

  • A. Methanol
  • B. 1-Butanol
  • C. 1-Propanol
  • D. Ethanol

Explanation: The iodoform reaction occurs with compounds that have a methyl group attached to a carbon bearing a hydroxyl group (-OH) or a carbonyl group (-C=O). Ethanol (CH₃CH₂OH) meets this requirement because it can be oxidized to acetaldehyde (CH₃CHO), which has the necessary structure for the iodoform reaction.

Why the other options are wrong
  • A. Methanol cannot give the iodoform test because it doesn't have a methyl group attached to the carbon with the hydroxyl group.
  • B. 1-Butanol cannot give the iodoform test because it is a primary alcohol and lacks the required structure to form a methyl ketone.
  • C. 1-Propanol cannot give the iodoform test because it's a primary alcohol and doesn't have the methyl ketone structure after oxidation.

Q87. Which of the following is the correct Arrhenius equation?

  • A. K-Ae^-Ea/QT
  • B. K=Ae^-Ea/RT
  • C. K=Ae^-Ea/ST
  • D. K=Ae^-Ea/UT

Explanation: Option B is the correct Arrhenius equation, where A is the pre-exponential factor, Ea is the activation energy, R is the gas constant, and T is the temperature.

Why the other options are wrong
  • A. Incorrect. The correct form uses RT (not QT) for temperature in the denominator.
  • C. Incorrect. The equation uses T (temperature), not S.
  • D. Incorrect. The equation should use RT (not UT).

Q88. Which of the following electronic configurations is correct for carbon?

  • A. 1s2, 2s2, 2p3
  • B. 1s2, 2s2, 2P4
  • C. 1s2, 2s2, 2p2
  • D. 1s2, 2s2, 2p1

Explanation: This option is correct. This is the correct configuration for carbon.

Why the other options are wrong
  • A. This configuration is for nitrogen (N), which has 7 electrons, not carbon.
  • B. This configuration is for oxygen (O), which has 8 electrons.
  • D. This configuration is for boron (B), which has 5 electrons.

Q89. Common name of 2-hydroxy propanoic acid is

  • A. Tartaric acid
  • B. Lactic acid
  • C. Phthalic acid
  • D. Formic acid

Explanation: 2-hydroxypropanoic acid is commonly known as lactic acid. It has a hydroxy group (-OH) attached to the second carbon of propanoic acid, giving it the name 2-hydroxypropanoic acid.

Why the other options are wrong
  • A. Tartaric acid is a different compound, specifically 2,3-dihydroxybutanedioic acid, and is found in grapes.
  • C. Phthalic acid is benzene-1,2-dicarboxylic acid and has no hydroxy group.
  • D. Formic acid is methanoic acid and contains a -COOH group, not a hydroxy group.

Q90. In endothermic reaction,the heat content of the:

  • A. Reactants and products is equal
  • B. Reactants is more than that of products
  • C. Products is more than that of reactants
  • D. Reactants & Products will not change

Explanation: This is the correct statement. In endothermic reactions, the products have greater energy (or heat content) than the reactants because heat is absorbed during the reaction.

Why the other options are wrong
  • A. In an endothermic reaction, the heat content is not equal; the products have a higher heat content than the reactants.
  • B. This statement is incorrect for endothermic reactions. In these reactions, the products absorb heat, leading to a higher heat content.
  • D. This is not true, as the heat content changes during the reaction.

Q91. Intermolecular forces between molecules of ideal gas are:

  • A. Strong
  • B. Moderate
  • C. Weak
  • D. Absent

Explanation: In an ideal gas, it is assumed that the intermolecular forces between gas molecules are absent. This is a key assumption in the ideal gas law (PV = nRT).

Why the other options are wrong
  • A. Ideal gas molecules do not experience strong intermolecular forces.
  • B. Ideal gas molecules do not experience moderate intermolecular forces either.
  • C. Ideal gas molecules do not experience weak intermolecular forces.

Q92. Which of the following is correct regarding phenol?

  • A. Phenol and water are equally acidic
  • B. Phenol is less acidic than carboxylicacid
  • C. Phenol is less acidic than water
  • D. Phenol is less acidic than ethanol

Explanation: Because the conjugate base of a carboxylic acid is more stable than that of phenol, carboxylic acids are stronger acids than phenols, meaning phenol is less acidic than carboxylic acids.

Why the other options are wrong
  • A. Incorrect. Phenol is more acidic than water. Water has a very weak dissociation (H₂O ⇌ H⁺ + OH⁻), whereas phenol dissociates more easily due to the resonance stabilization of its conjugate base.
  • C. Incorrect. Phenol is more acidic than water.
  • D. Incorrect. Phenol is more acidic than ethanol. Ethanol (CH₃CH₂OH) is a very weak acid compared to phenol.

Q93. The correct ideal gas equation is

  • A. qV=nRt
  • B. pV=nRt
  • C. gV=nRt
  • D. yV=nRt

Explanation: PV=nRTP = Pressure of the gasV = Volume of the gasn = Number of moles of gasR = Universal gas constant (8.314 J/mol·K)T = Temperature in KelvinThis equation describes the relationship between pressure, volume, and temperature for an ideal gas.

Why the other options are wrong
  • A. The equation qV = nRt is incorrect because "q" is not a term in the ideal gas law (it should be P for pressure), and "t" should be uppercase (T for temperature in Kelvin). The correct ideal gas equation is PV = nRT, which accurately describes the relationship between pressure, volume, temperature, and moles of an ideal gas.
  • C. The equation gV = nRT is incorrect because "g" is not a part of the ideal gas law. The correct equation is PV = nRT, where P (pressure) should be used instead of g. Pressure represents the force exerted by gas particles, which is essential in the equation.
  • D. The equation yV = nRT is incorrect because "y" is not a part of the ideal gas law. The correct equation is PV = nRT, where P (pressure) should be used instead of y, as pressure is a fundamental variable in describing the behavior of an ideal gas.

Q94. The real gases show deviation from ideal behaviour at:

  • A. Low temperature and low pressure
  • B. High temperature and high pressure
  • C. Low temperature and high pressure
  • D. High temperature and low pressure

Explanation: Deviation from ideal gas behavior occurs primarily under high pressure and low temperature conditions. At high pressures, gas molecules are forced closer together, making the volume of the gas significantly less than predicted by the ideal gas law due to the finite volume of the molecules and intermolecular interactions. Conversely, at low temperatures, the kinetic energy of gas molecules decreases, enhancing the influence of intermolecular forces, which can lead to condensation into liquids. These factors highlight that real gases do not always follow the ideal gas law, especially near their boiling points or under conditions close to liquefaction, necessitating more complex equations of state, such as the van der Waals equation, to better describe their behavior.

Why the other options are wrong
  • A. Real gases behave ideally at low pressures due to increased molecular spacing, reducing intermolecular forces, and at high temperatures, where increased kinetic energy minimizes the impact of these forces.
  • B. At high pressures, gas molecules are closer together, making intermolecular forces and molecular volume significant, leading to deviations from ideal gas behavior. Conversely, increased kinetic energy at high temperatures reduces the impact of intermolecular attractions, causing gases to behave more ideally.
  • D. At high temperatures, increased molecular kinetic energy diminishes the effect of intermolecular forces, and at low pressures, increased molecular spacing reduces these interactions; both conditions lead real gases to approximate ideal gas behavior.

Q95. To boil water at 110℃, external pressure should be:

  • A. 200-760 torr
  • B. 760-1200 torr
  • C. 665-670 torr
  • D. 660-700 torr

Explanation: To boil water at 110 °C, the external pressure should be approximately 1.4 atm, which is equivalent to 1,064 torr.

Why the other options are wrong
  • A. To boil water at 110 °C, the external pressure must be approximately 1,433 torr (1.886 atm). Pressures between 200 and 760 torr correspond to boiling points below 100 °C, insufficient to achieve boiling at 110 °C.
  • C. At pressures between 665 and 670 torr, water boils at approximately 95 to 96 °C, which is below the desired 110 °C boiling point.
  • D. At pressures between 660 and 700 torr, water boils at approximately 94 to 96 °C, which is below the desired 110 °C boiling point.

Q96. Which of the following is not basic in nature

  • A. Aluminum oxide
  • B. Magnesium oxide
  • C. Potassium oxide
  • D. Sodium oxide

Explanation: Aluminum oxide (Al₂O₃) is amphoteric, meaning it can exhibit both acidic and basic properties depending on the environment. It can react with acids, forming aluminum salts and water, and it can also react with strong bases to form aluminate ions. This dual behavior makes aluminum oxide versatile in various chemical reactions and applications, including catalysts and adsorbents.

Why the other options are wrong
  • B. Magnesium oxide (MgO) is considered a basic oxide. When it reacts with water, it forms magnesium hydroxide (Mg(OH)₂), which is also basic. This basicity allows MgO to neutralize acids, making it useful in various applications, such as antacids in medicine and as a pH regulator in agricultural soils.
  • C. Potassium oxide (K₂O) is a chemical compound formed from potassium and oxygen. It appears as a white, hygroscopic solid that reacts with water to form potassium hydroxide (KOH). Potassium oxide is primarily used in agriculture as a source of potassium for fertilizers, contributing to plant growth and development. It also has applications in the glass and ceramics industries, where it can improve melting and physical properties. In terms of chemical behavior, K₂O is a basic oxide and can react with acids to form salts.
  • D. Sodium oxide (Na₂O) is a white, crystalline inorganic compound classified as a basic oxide. It forms when sodium reacts with oxygen and consists of sodium ions (Na⁺) and oxide ions (O²⁻), creating strong ionic bonds that give it a high melting point. Sodium oxide is highly reactive, particularly with water, where it forms sodium hydroxide (NaOH) in an exothermic reaction, highlighting its strong basicity. It is soluble in water, resulting in a basic solution, and is commonly used in the production of glass and ceramics and as a catalyst in various chemical reactions.

Q97. The solubility of sulphates of alkaline earth metals generally

  • A. Increase down the group
  • B. Decrease down the group
  • C. Increase then decrease down the group
  • D. Doesn't change down the group

Explanation: The solubility of alkaline earth metal sulfates varies down the group and generally decreases as you move from beryllium to barium.

Why the other options are wrong
  • A. The solubility of alkaline earth metal sulfates decreases down the group due to a more rapid decrease in hydration enthalpy compared to lattice enthalpy.
  • C. The solubility of alkaline earth metal sulfates decreases down the group, primarily due to a more rapid decrease in hydration enthalpy compared to lattice enthalpy. This trend is consistent and does not exhibit an initial increase followed by a decrease.
  • D. The solubility of alkaline earth metal sulfates decreases down the group due to the decreasing hydration enthalpy of the metal cations, which outweighs the lattice energy considerations. This trend is consistent and does not exhibit an initial increase followed by a decrease.

Q98. The atomic masses of elements depend upon:

  • A. Atomic number
  • B. Number of electrons
  • C. Number of isotopes & their abundance
  • D. None of the above

Explanation: Atomic mass depends on the number of isotopes and their abundance because:Isotopes of an element have the same atomic number but different masses due to varying numbers of neutrons.The atomic mass is an average of the masses of all isotopes weighted by their natural abundance.Variations in isotopic abundance lead to different average atomic masses for elements.

Why the other options are wrong
  • A. Atomic mass depends on both protons and neutrons, while atomic number only counts protons. Isotopes of an element have the same atomic number but different masses due to varying neutrons. Hence, atomic mass is not solely determined by atomic number but by the total number of nucleons (protons + neutrons).
  • B. Atomic mass is determined by protons and neutrons, as electrons have negligible mass. The number of electrons does not affect atomic mass, as it only influences the atom’s charge, not its mass.
  • D. This option is incorrect.

Q99. Which one of the following DO NOT have a tendency to form hydrogen bonding?

  • A. Ammonia
  • B. Ethyl alcohol
  • C. Carboxylic acids
  • D. Hydrocarbon

Explanation: Hydrocarbons, which include alkanes, alkenes, and alkynes, do not form hydrogen bonds because they consist solely of carbon and hydrogen atoms without any highly electronegative elements like nitrogen, oxygen, or fluorine. The C–H bonds in hydrocarbons are relatively nonpolar, meaning there is no significant dipole moment to facilitate hydrogen bonding. As a result, the predominant intermolecular forces in hydrocarbons are van der Waals forces (London dispersion forces), which are much weaker than hydrogen bonds. This leads to lower boiling and melting points compared to substances capable of hydrogen bonding.

Why the other options are wrong
  • A. The presence of the lone pair on nitrogen allows ammonia molecules to form hydrogen bonds with other ammonia molecules or with other electronegative atoms (like oxygen or fluorine) in different molecules. The hydrogen atoms bonded to nitrogen can attract the lone pairs of nearby electronegative atoms, creating hydrogen bonds.
  • B. The hydrogen atom in the hydroxyl group can form hydrogen bonds with the lone pairs of electrons on the oxygen atoms of nearby ethanol molecules. This intermolecular hydrogen bonding contributes to ethanol's relatively high boiling point compared to other hydrocarbons of similar molecular weight.
  • C. The hydrogen atom of the hydroxyl group can form hydrogen bonds with the oxygen atoms of neighboring carboxylic acid molecules or with other electronegative atoms in different compounds. Additionally, the carbonyl oxygen can also participate in hydrogen bonding, leading to strong intermolecular interactions.

Q100. Which of the following is an example of substituent group which release electrons to benzene ring

  • A. -CN
  • B. -NR3+
  • C. -NH2
  • D. -NO2

Explanation: This group is an electron-donating group due to its ability to donate a lone pair of electrons to the benzene ring, increasing the electron density of the ring and activating it toward electrophilic substitution reactions.

Why the other options are wrong
  • A. The cyano group is an electron-withdrawing group because the carbon in the cyano group is sp-hybridized and has a strong electronegativity, pulling electron density away from the benzene ring through resonance and induction.
  • B. This is also an electron-withdrawing group due to its positive charge, which destabilizes the benzene ring by drawing electron density away from it.
  • D. The nitro group is a strong electron-withdrawing group due to both resonance and inductive effects. It pulls electron density away from the benzene ring, making it less reactive towards electrophiles.

Q101. Which type of isomerism is displayed by compounds having the same structural formula but different positions of atoms on both sides of the carbon bond?

  • A. Chain
  • B. Metamerism
  • C. Geometric
  • D. Tautomerism

Explanation: Geometric isomerism, also known as cis-trans isomerism, is a form of stereoisomerism where molecules have the same molecular formula but differ in the spatial arrangement of atoms or groups around a rigid structure, such as a double bond or a ring.In the official UHS 2024 paper, option C was marked as correct. Therefore, we will retain option C here to maintain alignment with the original key for authenticity.

Why the other options are wrong
  • A. Chain isomerism is a form of structural isomerism where compounds with the same molecular formula differ in the arrangement of their carbon chain, meaning they can have different branching patterns.
  • B. Metamerism is a type of structural isomerism where compounds have the same molecular formula but differ in the arrangement of atoms around a functional group, typically involving different alkyl groups on either side of a functional group (like oxygen, sulfur, or nitrogen).
  • D. Tautomerism is a chemical phenomenon where compounds, called tautomers, exist in equilibrium and can readily interconvert. Tautomers typically differ in the placement of a hydrogen atom and a double bond.

Q102. Which of the following is NOT an Alloy?

  • A. steel
  • B. brass
  • C. bronze
  • D. graphite

Explanation: Graphite is not an alloy. It is pure carbon. It is an allotrope.

Why the other options are wrong
  • A. Steel is an alloy of iron, carbon, chromium, and nickel. Sometimes, it can also contain vanadium for extra strength and stability.
  • B. Brass is an alloy of copper and zinc.
  • C. Bronze is an alloy of copper and tin.

Q103. Electronic configuration of chromium (proton number 24) is:

  • A. [Ar] 3d4 4s2
  • B. [Ar] 3d2 4s2
  • C. [Ar] 3d5 4s1
  • D. [Ar] 3d5 4s2

Explanation: Chromium(Cr) and Copper(Cu) are two special cases in which electron from 4s orbital jumps to 3d so 4s orbital has only a single electron in it. In options there is only one option that has a single electron in 4s orbital which is C. A is a wrong form to write Cr electronic configuration because technically when 3d has 4 electrons a single electron will jump from 4s to 3d to make it 5 in 3d, as it is a more stable state. B and D cannot be right because they correspond to electronic configuration of atoms having a proton number 25.

Why the other options are wrong
  • A. According to the explanation, this option is incorrect. Chromium(Cr) and Copper(Cu) are two special cases in which electron from 4s orbital jumps to 3d so 4s orbital has only a single electron in it. In options there is only one option that has a single electron in 4s orbital which is C.
  • B. According to the explanation, this option is incorrect. Chromium(Cr) and Copper(Cu) are two special cases in which electron from 4s orbital jumps to 3d so 4s orbital has only a single electron in it. In options there is only one option that has a single electron in 4s orbital which is C.
  • D. According to the explanation, this option is incorrect. Chromium(Cr) and Copper(Cu) are two special cases in which electron from 4s orbital jumps to 3d so 4s orbital has only a single electron in it. In options there is only one option that has a single electron in 4s orbital which is C.

Q104. Which step is irrelevant concerning the balancing of redox equations by the oxidation number method?

  • A. Split the reaction into two half reactions.
  • B. Assign an oxidation number to all the atoms involved in the equation.
  • C. Identify the element changing oxidation number
  • D. Equalize the number of electrons lost and gained

Explanation: Option A is correct. That step belongs to the ion–electron (half-reaction) method, not the oxidation number method.In the oxidation number method, you:Assign oxidation numbers.Identify atoms changing oxidation state.Equalize the total increase and decrease in oxidation number.Balance the remaining atoms and charges.So, splitting into half-reactions is not required here.

Why the other options are wrong
  • B. This is an essential step for identifying which atoms are undergoing oxidation and reduction, as you need to know the changes in oxidation numbers to balance the equation properly.
  • C. Identifying the element that changes oxidation number is fundamental for understanding which species are being oxidized and reduced. This helps in determining the half-reactions and balancing the overall reaction.
  • D. In the oxidation number method, you:Assign oxidation numbers.Identify atoms changing oxidation state.Equalize the total increase and decrease in oxidation number.Balance the remaining atoms and charges.So, splitting into half-reactions is not required here.

Q105. Which of the following is NOT a correct feature of electrolytic cells?

  • A. Reduction occurs at cathode
  • B. Oxidation occurs at anode
  • C. Alternating current source is connected to electrodes
  • D. Electrochemical reaction takes place

Explanation: This is an Incorrect feature of an electrolytic cell because electrolytic cells use direct current (DC), not alternating current (AC).

Why the other options are wrong
  • A. Correct feature of an electrolytic cell as in electrolytic cells, cations gain electrons at the cathode.
  • B. Correct feature of an electrolytic cell because anions lose electrons at the anode in electrolytic cells.
  • D. Correct feature of an electrolytic cell, as electrolytic cells drive non-spontaneous redox reactions using electrical energy.

Q106. Which of the following has a coordinate bond?

  • A. NaCl
  • B. CaO
  • C. NH3BF3
  • D. H2O

Explanation: The nitrogen atom in NH₃ donates its lone pair to the boron atom in BF₃, forming a coordinate covalent bond where both electrons in the bond come from nitrogen. This bond stabilizes BF₃ by completing its octet.

Why the other options are wrong
  • A. Sodium chloride has an ionic bond between Na⁺ and Cl⁻, not a coordinate bond.
  • B. Calcium oxide forms an ionic bond between Ca²⁺ and O²⁻, not a coordinate bond.
  • D. Water has covalent bonds between hydrogen and oxygen but no coordinate bond.

Q107. Which of the following is NOT a feature of Valence Shell Electron Pair Repulsion theory?

  • A. It determines the shape of molecule
  • B. Pairs of electrons repel each other.
  • C. It helps in understanding the interaction of medicinal drug molecules.
  • D. Only lone pairs participate in determining geometry of molecules.

Explanation: No, both bonding pairs and lone pairs of electrons contribute to determining the geometry of molecules. According to the Valence Shell Electron Pair Repulsion (VSEPR) theory, electron pairs—whether bonding or lone—repel each other and try to maximize their distance apart. This influences the molecular geometry.

Why the other options are wrong
  • A. Correct, as VSEPR theory predicts molecular geometry based on electron pair repulsions.
  • B. Correct, because both bonding and lone pairs repel each other to minimize repulsion.
  • C. Correct, as molecular shape influences drug interactions with biological receptors.

Q108. The range of projectile will be maximum if the factor sin20 becomes

  • A. Zero
  • B. 1
  • C. -1
  • D. 2

Explanation: The range of a projectile is maximized when sin(2θ)=1. This occurs at an angle θ=45.

Why the other options are wrong
  • A. Incorrect, because if sin⁡2θ=0\sin 2\theta = 0sin2θ=0, the range becomes zero, meaning no horizontal motion.
  • C. – Incorrect, as a negative value would not be physically meaningful for projectile range.
  • D. Incorrect, because sin 2θ can only range between -1 and 1, never reaching 2.

Q109. Which of the following has smallest atomic radius:

  • A. Mg
  • B. S
  • C. P
  • D. Na

Explanation: S will have the smallest atomic radius because it lies at the end among the mentioned elements. Across the period, the atomic radius decreases.

Why the other options are wrong
  • A. It has a larger radius as it is a metal in Group 2 and has fewer protons than sulfur.
  • C. Slightly larger than sulfur since it is to the left of sulfur in the periodic table.
  • D. The largest radius is here, as it is a Group 1 metal, meaning it has the weakest nuclear attraction and the most shielding.

Q110. The difference of lithium from the other alkali metals is mainly because of:

  • A. Large radius and low charge density
  • B. Small radius and low charge density
  • C. Large radius and high charge density
  • D. Small radius and high charge density

Explanation: Correct, as lithium has the smallest atomic size in the alkali metal group, leading to high charge density, which makes it behave differently from other alkali metals (e.g., stronger covalent character in compounds and diagonal relationship with magnesium).

Why the other options are wrong
  • A. Incorrect, as lithium has the smallest atomic radius among alkali metals.
  • B. Incorrect, because a small radius leads to a high charge density, not low.
  • C. Incorrect, since high charge density is associated with small size, not large.

Q111. Boiling point of a liquid is a temperature at which:

  • A. Surface tension is greater than the atmospheric pressure
  • B. Viscosity is less than the atmospheric pressure
  • C. Vapor pressure equals the atmospheric pressure
  • D. Viscosity equals the atmospheric pressure

Explanation: The temperature at which vapor pressure becomes equal to atmospheric pressure is called the boiling point.

Why the other options are wrong
  • A. The boiling point of a liquid is the temperature at which its vapor pressure equals the surrounding atmospheric pressure, allowing bubbles to form within the liquid
  • B. A liquid's boiling point is determined by its vapor pressure reaching atmospheric pressure, not by its viscosity. Viscosity measures a liquid's resistance to flow and does not directly influence the boiling process.
  • D. A liquid's boiling point is determined by its vapor pressure reaching atmospheric pressure, not by its viscosity. Viscosity measures a liquid's resistance to flow and does not directly influence the boiling process.

Q112. Which of the following is NOT a property of transition elements?

  • A. High melting points
  • B. Good conductors of electricity
  • C. Hard metals
  • D. Ions and compounds are colorless

Explanation: Transition elements form colored complexes due to d-d transitions except Zn²⁺, Sc³⁺, and Cu⁺.

Why the other options are wrong
  • A. Transition metals are characterized by their high melting points due to strong metallic bonds facilitated by delocalized d-electrons, which require significant energy to break. Their closely packed crystal structures further enhance bonding strength, contributing to higher melting points. Additionally, many transition metals can exist in multiple oxidation states, influencing their bonding characteristics. For instance, metals like tungsten and molybdenum exhibit exceptionally high melting points, making them suitable for high-temperature applications in industries such as aerospace and manufacturing. These properties make transition metals valuable for materials requiring durability under extreme conditions.
  • B. Transition metals are considered good conductors of electricity due to a structure with delocalized d-electrons that move freely, facilitating the flow of electric current.
  • C. Transition metals like tungsten and molybdenum are known for their exceptional hardness, making them suitable for cutting tools and industrial applications.

Q113. 1-Butene and two Butene are showing which type of isomerism?

  • A. functional group
  • B. positional
  • C. metamerism
  • D. chain

Explanation: Position isomerism is a type of structural isomerism where compounds have the same molecular formula and the same functional group but differ in the position of that functional group or substituent on the carbon chain. This can occur with various functional groups, such as alcohols, amines, and halides.

Why the other options are wrong
  • A. Functional group isomerism occurs when compounds have the same molecular formula but differ in the type of functional group present. This type of isomerism results in distinct chemical properties and reactivity due to the different functional groups involved.
  • C. Metamerism is a type of structural isomerism that occurs when two or more compounds have the same molecular formula but differ in the distribution of functional groups or atoms across the carbon chain. This results in isomers known as metamers, which typically have different physical and chemical properties despite having the same molecular formula.
  • D. Chain isomerism is a type of structural isomerism that occurs when compounds have the same molecular formula but differ in the arrangement of the carbon chain. This can involve variations in the length of the carbon chain or the branching of the carbon atoms. For example, butane (C₄H₁₀) can exist as straight-chain n-butane or as branched-chain isobutane (2-methylpropane).

Q114. Whenever the crystalline solids are broken they do so along definite planes known as:

  • A. Cleavage planes
  • B. Refractory planes
  • C. Sagittal planes
  • D. Coronal planes

Explanation: In the context of crystalline solids, cleavage planes refer to specific planes along which a crystal can break or split easily. These planes are determined by the arrangement of atoms within the crystal lattice and reflect the internal structure of the crystal.

Why the other options are wrong
  • B. Refractory planes, more commonly referred to in a medical context as refractory periods, describe the phases during which a neuron or muscle cell is unable to respond to stimuli after being excited.
  • C. Sagittal planes are anatomical planes that divide the body into left and right sections.
  • D. Coronal planes, also known as frontal planes, are anatomical planes that divide the body into anterior (front) and posterior (back) sections.

Q115. Homocyclic organic compounds are subdivided into two types namely:

  • A. Alicyclic and Aromatic
  • B. Alkenes and alkynes
  • C. Aromatic and Non aromatic
  • D. Saturated and Unsaturated

Explanation: Alicyclic and aromatic compounds are both types of cyclic hydrocarbons but differ significantly in structure and properties. Alicyclic compounds consist of one or more carbon rings that do not have delocalized pi electrons, making them non-aromatic; they can be saturated or unsaturated, with examples like cyclohexane and cyclopentene. In contrast, aromatic compounds feature a cyclic structure with a conjugated system of alternating double bonds that follows Huckel's rule (4n+2 pi electrons), resulting in enhanced stability and distinct reactivity, such as undergoing electrophilic substitution; benzene is the most famous example. Thus, while both are cyclic, their electronic characteristics lead to different chemical behaviors and applications.

Why the other options are wrong
  • B. Alkenes and alkynes are unsaturated hydrocarbons distinguished by their carbon- carbon bonds. Alkenes contain at least one carbon-carbon double bond (C=C) and have the general formula CnH2n, making them more reactive than alkanes; common examples include ethene and propene. In contrast, alkynes have at least one carbon-carbon triple bond (C≡C) and follow the general formula CnH2n-2, with examples like ethyne (acetylene) and propyne. Alkynes are even more reactive than alkenes, engaging in various addition reactions and serving crucial roles in organic synthesis and industrial applications.
  • C. Aromatic compounds are characterized by having a cyclic structure with a conjugated system of pi electrons that follows Huckel's rule.(4n+2 pi electrons), resulting in enhanced stability and unique chemical properties, such as undergoing electrophilic substitution (e.g., benzene). In contrast, non-aromatic compounds lack this cyclic conjugation and do not meet the criteria for aromaticity, which can include open-chain structures or rings without the requisite electron configuration (e.g., cyclohexane). As a result, non-aromatic compounds typically exhibit different reactivity patterns, often favoring addition reactions rather than substitution.
  • D. Compounds that have no double or triple bonds between carbon atoms. All carbon atoms are fully "saturated" with hydrogen atoms. Compounds that contain one or more double or triple bonds between carbon atoms, leading to fewer hydrogen atoms.

Q116. One of the following is NOT an example of amorphous solids

  • A. Plastic
  • B. Glass
  • C. Glucose
  • D. Rubber

Explanation: Glucose is a molecular solid.

Why the other options are wrong
  • A. Plastic is an amorphous solid.
  • B. Glass is an amorphous solid.
  • D. Rubber is an amorphous solid.

Q117. In graphite the carbon atoms are arranged in which of the following structure?

  • A. Rhombic
  • B. Hexagonal
  • C. Tetragonal
  • D. Trigonal

Explanation: Graphite is hexagonal because its carbon atoms form hexagonal rings in flat layers, with each atom sp² hybridized and bonded to three neighbors in a trigonal planar arrangement. The layers stack in an ABAB pattern, characteristic of the hexagonal crystal system.

Why the other options are wrong
  • A. In graphite, carbon atoms are arranged in a hexagonal layered structure, where each atom is sp² hybridized and bonded to three others in flat sheets. It is not rhombic because the bonding favors planar hexagonal symmetry rather than a rhombic crystal arrangement.
  • C. Graphite is not tetragonal because its carbon atoms form hexagonal rings in flat layers due to sp² hybridization, creating a trigonal planar geometry. Tetragonal structures require a different bonding arrangement with a four-sided unit cell, which does not match graphite’s layered hexagonal symmetry.
  • D. Graphite is not purely trigonal because, at the atomic level, carbon atoms form a hexagonal planar structure within each layer. However, the overall crystal system of some types of graphite (like rhombohedral graphite) can be classified as trigonal, but the dominant form is hexagonal graphite due to its layer stacking pattern.

Q118. The principle that states that if a stress is applied to a system at equilibrium, the system nullifies the effect of stress as far as possible is:

  • A. Haber's
  • B. Le-Chatelier
  • C. Boyle's
  • D. Charles'

Explanation: The principle is Le Chatelier's Principle. It states that if a stress is applied to a system at equilibrium, the system will adjust to counteract the effect of the stress, shifting the equilibrium to minimize the disturbance.

Why the other options are wrong
  • A. The Haber process is a chemical reaction used to synthesize ammonia from nitrogen and hydrogen gases. It involves optimizing temperature, pressure, and the use of a catalyst to favor ammonia production.
  • C. The pressure of a given mass of gas is inversely proportional to its volume at a constant temperature.
  • D. The volume of a gas is directly proportional to its temperature (in Kelvin) at constant pressure.

Q119. In Friedel Craft acylation an acyl group is introduced in benzene ring in the presence of catalyst:

  • A. AICl3
  • B. H2SO4
  • C. Sunlight
  • D. V2O5

Explanation: The catalyst used in Friedel-Crafts acylation is typically Aluminum chloride (AlCl₃). It acts as a Lewis acid, helping to generate the acylium ion from the acyl chloride or anhydride, which then reacts with the aromatic ring to form the acylated product.

Why the other options are wrong
  • B. H₂SO₄ is a Bronsted acid, not a Lewis acid, and it cannot effectively generate the required acylium ion (RCO⁺) from acyl chlorides or anhydrides. In contrast, AlCl₃ (a strong Lewis acid) coordinates with the acyl compound, facilitating the formation of the highly reactive acylium ion, which then undergoes electrophilic substitution with benzene.
  • C. Sunlight (UV light) is not used in Friedel-Crafts acylation because the reaction follows an electrophilic aromatic substitution (EAS) mechanism, which requires the formation of a strong electrophile (acylium ion, RCO⁺). This ion is generated using a Lewis acid catalyst like AlCl₃, not by light energy.Sunlight is typically used for free radical reactions, such as halogenation of alkanes (e.g., chlorination of methane), but Friedel-Crafts acylation does not proceed via a radical mechanism, so UV light would not help in this reaction.
  • D. V₂O₅ (Vanadium pentoxide) is not used as a catalyst in Friedel-Crafts acylation because it is a heterogeneous catalyst primarily used in oxidation reactions, such as the conversion of SO₂ to SO₃ in the Contact Process for sulfuric acid production.

Q120. Identify the CORRECT option required for the maximum yield of ammonia by Haber's Process:

  • A. High pressure, low temperature, continual removal of ammonia
  • B. Low pressure, low temperature, continual removal of ammonia
  • C. High pressure, high temperature, continual removal of ammonia
  • D. High pressure, low temperature, continual addition of ammonia

Explanation: The maximum yield of ammonia in the Haber process is theoretically limited to about 15% under typical conditions of high temperature (around 400-500°C) and high pressure (150-300 atmospheres). However, in practice, the yield is often lower due to factors like equilibrium constraints and reaction kinetics. To increase the yield, unreacted gases can be recycled back into the reactor, making the process more efficient.

Why the other options are wrong
  • B. High pressure is required in the Haber Process because it shifts equilibrium toward ammonia formation, as fewer gas molecules are present on the product side. Low pressure reduces yield, while moderate temperature (~450°C) and continual removal of ammonia help maximize production.
  • C. High pressure increases ammonia yield, but high temperature reduces it because the reaction is exothermic, shifting equilibrium backward. A moderate temperature (~450°C) balances yield and reaction rate, making high temperature unsuitable despite continual removal of ammonia.
  • D. High pressure and low temperature favor ammonia formation, but the continual addition of ammonia shifts equilibrium backward, reducing yield. Instead, continual removal of ammonia drives the reaction forward, maximizing production.

Q121. Which one of the following represents nitration of benzene correctly?

  • A.
  • B.
  • C.
  • D.

Explanation: Benzene reacts with concentrated nitric acid (HNO₃) in the presence of concentrated sulfuric acid (H₂SO₄) at 50–55°C. Sulfuric acid acts as a catalyst and generates the electrophile (NO₂⁺, nitronium ion), which attacks the benzene ring via electrophilic aromatic substitution, forming nitrobenzene and water as a by-product.

Why the other options are wrong
  • A. Benzene reacts with concentrated nitric acid (HNO₃) in the presence of concentrated sulfuric acid (H₂SO₄) at 50–55°C. Sulfuric acid acts as a catalyst and generates the electrophile (NO₂⁺, nitronium ion), which attacks the benzene ring via electrophilic aromatic substitution, forming nitrobenzene and water as a by-product.
  • C. Benzene reacts with concentrated nitric acid (HNO₃) in the presence of concentrated sulfuric acid (H₂SO₄) at 50–55°C. Sulfuric acid acts as a catalyst and generates the electrophile (NO₂⁺, nitronium ion), which attacks the benzene ring via electrophilic aromatic substitution, forming nitrobenzene and water as a by-product.
  • D. Benzene reacts with concentrated nitric acid (HNO₃) in the presence of concentrated sulfuric acid (H₂SO₄) at 50–55°C. Sulfuric acid acts as a catalyst and generates the electrophile (NO₂⁺, nitronium ion), which attacks the benzene ring via electrophilic aromatic substitution, forming nitrobenzene and water as a by-product.

Q122. The number of moles in an element is directly proportional to:

  • A. Mass of an element
  • B. Empirical formula mass
  • C. Molar mass of an element
  • D. Formula mass

Explanation: ​Since molar mass is constant for a given element, increasing the mass increases the number of moles proportionally. For example, doubling the mass of an element doubles the number of moles, making them directly proportional.

Why the other options are wrong
  • B. It is directly proportional to the mass of the element but not to the empirical formula mass because:Empirical formula mass represents the simplest ratio of atoms in a compound, not the actual molar mass.The number of moles depends on the total molar mass of the substance, not just its empirical formula mass.
  • C. The number of moles is inversely proportional to the molar mass, not directly proportional. If molar mass increases, the number of moles decreases for the same mass of the element, which is why it is not directly proportional to molar mass.
  • D. It is not directly proportional to the formula mass because:Formula mass is the sum of atomic masses in a chemical formula but does not determine the number of moles.The number of moles depends on the actual mass of the substance, not just its formula mass.If the formula mass increases, the number of moles decreases for a fixed mass, making it inversely proportional, not directly proportional.

Q123. Identify the correct ascending order of reactivity of alkyl halides:

  • A. Cl, Br, I, F
  • B. F, CI, Br, I
  • C. Br, I, F, CI
  • D. I, F, Cl, Br

Explanation: The correct reactivity order of alkyl halides is R-F < R-Cl < R-Br < R-I because the C-F bond is the strongest (making fluorine the least reactive), and the C-I bond is the weakest (making iodine the most reactive).The order F, Cl, Br, I is correct because reactivity increases as bond strength decreases, meaning fluorine is the least reactive, and iodine is the most reactive due to its weak C-I bond and excellent leaving group ability.

Why the other options are wrong
  • A. The reactivity of alkyl halides depends on the C-X bond strength and leaving group ability.C-F bond is the strongest (due to high bond energy and small size of F), making R-F the least reactive.C-I bond is the weakest, making R-I the most reactive because iodine is the best leaving group.The correct order should be F < Cl < Br < I, not Cl < Br < I < F.
  • C. The correct reactivity order is R-F < R-Cl < R-Br < R-I because the C-F bond is the strongest (making F the least reactive), and the C-I bond is the weakest (making I the most reactive). The order Br, I, F, Cl is incorrect because F should be the least reactive, and I should be the most reactive.
  • D. The correct reactivity order is R-F < R-Cl < R-Br < R-I because bond strength decreases from C-F (strongest) to C-I (weakest), making I the most reactive and F the least reactive. The order I, F, Cl, Br is incorrect because F should be the least reactive, not in the middle, and Br should be more reactive than Cl.

Q124. Consider the following reaction in equilibrium and tell addition of which chemical will turn the cloudy solution into clear solution?BiCl3+H2O…>BiOCl+2HCl

  • A. BiCL3
  • B. H2O
  • C. BiOCI
  • D. HCl

Explanation: If you want to turn the cloudy solution (which indicates the presence of BiOCl) into a clear solution, you can add an excess of HCl. This addition will cause the equilibrium to shift to the right, reducing the amount of BiOCl and potentially dissolving it, thereby clarifying the solution.

Why the other options are wrong
  • A. Adding BiCl₃ will increase the concentration of Bi³⁺ ions, which may push the equilibrium right, forming more BiOCl precipitate and making the solution even cloudier. Instead, adding HCl increases Cl⁻ ions, shifting the equilibrium left, dissolving BiOCl, and turning the solution clear.
  • B. Adding H₂O will not significantly affect the equilibrium because water is already present in excess and does not shift the reaction direction. Instead, adding HCl increases Cl⁻ ions, shifting the equilibrium left, dissolving BiOCl, and making the solution clear.
  • C. Adding BiOCl will increase the amount of the solid precipitate, but it will not shift the equilibrium toward dissolving it. Instead, adding HCl increases Cl⁻ ions, shifting the equilibrium left, dissolving BiOCl, and making the solution clear.

Q125. The type and relative amount of each isotope in an element can be found by:

  • A. R spectroscopy
  • B. U.V spectroscopy
  • C. Mass Spectrometry
  • D. N.M.R

Explanation: Mass Spectrometry (MS) is an analytical technique used to measure the mass-to-charge ratio of ions. It provides detailed information about the molecular weight and structure of compounds

Why the other options are wrong
  • A. Raman Spectroscopy is an analytical technique used to provide information about molecular vibrations, which can be used to identify molecular structures and analyze chemical compositions.
  • B. Ultraviolet (UV) Spectroscopy is an analytical technique used to measure the absorption of ultraviolet light by a substance. It is widely used for the analysis of organic compounds, particularly those containing conjugated double bonds and aromatic systems.
  • D. Nuclear Magnetic Resonance (NMR) is a powerful analytical technique used primarily to determine the structure of organic compounds, study molecular dynamics, and analyze complex mixtures.

Q126. Identify the correct statement related to substitution and elimination of alkyt halides:

  • A. Strong bases causes substitution in preference to elimination
  • B. Role of leaving groups in elimination is simitar to substitution
  • C. Substitution is favored more than elimination by decreasing solvent polarity
  • D. Decrease in temperature will favor elimination more than substitution

Explanation: This statement is correct. In both substitution and elimination reactions, the effectiveness of the leaving group plays a crucial role; a better leaving group facilitates both types of reactions.

Why the other options are wrong
  • A. This statement is incorrect. Strong bases generally favor elimination reactions over substitution, especially in the case of unhindered substrates.
  • C. This statement is misleading. Generally, polar protic solvents favor substitution reactions (particularly SN1), while less polar or nonpolar solvents can favor elimination reactions (especially E2).
  • D. This statement is incorrect. Generally, elimination reactions are endothermic, so lower temperatures tend to favor substitution reactions (which are often exothermic) over elimination.

Q127. Identify the correct formula to calculate the rate of reaction.

  • A. Change in concentration of substance/Time taken for the change
  • B. Time taken for the change+ Change in concentration of substance
  • C. Time taken for the change+ Change in concentration of substance x 100
  • D. Time taken for the change x Change in concentration of substance

Explanation: The rate measures how fast a reaction occurs, which means we need to determine how much the concentration of a reactant or product changes per unit of time.Dividing the change in concentration by time gives the rate in correct units (e.g., mol/L·s), showing how quickly reactants are consumed or products are formed.

Why the other options are wrong
  • B. Rate is determined by division, not addition; adding time and concentration has no meaningful physical interpretation.The rate measures how quickly the concentration changes over time, which requires division, not summation.
  • C. The rate is a ratio (change in concentration per unit time), so it involves division, not addition or multiplication by 100.Adding time and concentration is not mathematically or scientifically meaningful because they have different units.Multiplying by 100 is unnecessary unless calculating a percentage, which is not how reaction rate is defined.
  • D. A rate is a ratio, meaning it involves division, not multiplication.Multiplying time taken by change in concentration gives a meaningless value with incorrect units.The rate should express how much concentration changes per unit time, which requires division, not multiplication.

Q128. Alkyl Halides involving -C-X bond breakage and- C-Nu bond formation simultaneously.

  • A. SN1
  • B. SN2
  • C. E1
  • D. E2

Explanation: In organic chemistry, the reaction involving the simultaneous breaking of a carbon-halogen bond (-C-X) and the formation of a carbon-nucleophile bond (-C-Nu) is characteristic of nucleophilic substitution reactions, particularly the S_N2 (bimolecular nucleophilic substitution) mechanism.

Why the other options are wrong
  • A. The reaction mechanism described, where the C-X bond breaks and the C-Nu bond forms simultaneously, follows the SN2 (bimolecular nucleophilic substitution) mechanism, not SN1.
  • C. The reaction described involves simultaneous C-X bond breakage and C-Nu bond formation, which is characteristic of SN2 (substitution nucleophilic bimolecular), not E1 (elimination unimolecular).
  • D. The reaction described involves simultaneous C-X bond breakage and C-Nu bond formation, which is characteristic of SN2 (nucleophilic substitution), not E2 (elimination).

Q129. CnH2nO is the general formula of:

  • A. Option A: Ether
  • B. Option B: Carboxylic acid
  • C. Option C: Ketones
  • D. Option D: Carbolic acid

Explanation: The correct answer is ketones, which have the general formula R2C=O. In this case, 'Rn' represents hydrocarbon groups that can vary in size but always adhere to the formula CnH2nO. In contrast, ethers and carboxylic acids do not match the formula due to their distinct structures and functional groups. Ethers (R-O-R') have a different connectivity, and carboxylic acids (RCOOH) incorporate both a carbonyl and a hydroxyl group, leading to a different ratio of hydrogens. Carbolic acid, or phenol, contains a hydroxyl group bonded to a benzene ring (C6H5OH), which deviates from the given formula.

Why the other options are wrong
  • A. Ethers have the general formula R-O-R', where R and R' are hydrocarbon groups. This formula does not match CnH2nO, as ethers lack both carbonyl groups and the specific hydrogen count.
  • B. Carboxylic acids have the general formula RCOOH or RCO2H, which includes a carbonyl and a hydroxyl group. This does not fit the formula CnH2nO, as it implies a different hydrogen count.
  • D. Carbolic acid typically refers to phenol, which has the formula C6H5OH. This does not correspond to the general formula CnH2nO, as it involves a different structure and hydrogen count.

Q130. Consider the hypothetical equation aA+bB…>cC+Dd: Which of the following represents the correct rate equation?

  • A. Rate=k[A](B)
  • B. Rate= k[A]^a[B]^b,
  • C. Rate=k[A]a
  • D. Rate=k[B]b

Explanation: Option B is correct.Reaction orders (a and b) are determined experimentally and do not necessarily match the stoichiometric coefficients a and b.Rate laws depend on the reaction mechanism, specifically the slowest (rate-determining) step, not just the overall equation.k is the rate constant, and [A] and [B] represent the reactant concentrations raised to their respective experimentally determined exponents.Thus, the correct rate law follows Rate = k[A]^a[B]^b, where a and b must be determined through experiments.

Why the other options are wrong
  • A. Rate = k[A](B) is incorrect because reaction orders are experimentally determined and should be written as Rate = k[A]^a[B]^b, where a and b may not be 1.
  • C. Rate = k[A]^a is incorrect because the reaction order (m) is determined experimentally and does not always match the stoichiometric coefficient a from the balanced equation. The correct rate law is Rate = k[A]^a[B]^b, where a and b are found through experiments, not reaction coefficients.
  • D. Rate = k[B]ᵇ is incorrect because the reaction order (n) is determined experimentally and does not necessarily match the stoichiometric coefficient b from the balanced equation. The correct rate law is Rate = k[A]a[B]b, where a and b are found through experiments, not from reaction coefficients.

Q131. The blue color of Fehling solution is changed to red when warmed with an aldehyde due to the formation of which of the following?

  • A. CO2
  • B. Cu2O
  • C. AgO
  • D. SO2

Explanation: The blue color of Fehling's solution changes to red when warmed with an aldehyde due to the formation of Cu₂O (copper(I) oxide) because of the reduction of Cu²⁺ ions present in the solution.

Why the other options are wrong
  • A. CO₂ is not the primary product when an aldehyde reacts with Fehling's solution; instead, the aldehyde is oxidized to a carboxylate ion, while Cu²⁺ is reduced to Cu₂O
  • C. The blue color of Fehling's solution changes to red due to the reduction of Cu²⁺ ions to Cu₂O (copper(I) oxide), not the formation of AgO.
  • D. The blue color of Fehling's solution changes to red when warmed with an aldehyde due to the reduction of Cu²⁺ ions to Cu₂O (copper(I) oxide), not the formation of SO₂.

Q132. If a reaction rate does not change with concentration, then it is

  • A. 3rd order
  • B. 2nd order
  • C. Ist order
  • D. Zero order

Explanation: The rate of a zero-order reaction is constant and does not depend on the concentration of the reactants. Thus, changing the concentration will not affect the rate of reaction.

Why the other options are wrong
  • A. The rate is proportional to the cube of the concentration of one reactant (if it’s a single reactant) or to the product of the concentrations in a manner corresponding to their stoichiometry. Doubling the concentration will increase the rate by a factor of eight. Halving the concentration will decrease the rate by a factor of eight.
  • B. The rate is proportional to the square of the concentration of one reactant (if it’s a single reactant) or to the product of the concentrations of two reactants (if there are two). If the concentration is doubled, the rate will increase by a factor of four. If the concentration is halved, the rate will decrease by a factor of four.
  • C. The rate is directly proportional to the concentration of one reactant. Doubling the concentration of the reactant will double the rate of reaction. If the concentration is halved, the rate will also be halved.

Q133. The reaction of formaldehyde with HCN is:

  • A. Nucleophilic substitution
  • B. Nucleophilic addition
  • C. Electrophilic substitution
  • D. Free radical addition

Explanation: The reaction of formaldehyde (HCHO) with hydrogen cyanide (HCN) involves a nucleophilic addition rather than a nucleophilic substitution.In a nucleophilic addition reaction, a nucleophile adds to a molecule, typically at a carbon-carbon double bond (as in alkenes and carbonyl compounds), resulting in the formation of a new compound.In the case of formaldehyde and HCN, the oxygen atom of formaldehyde's carbonyl group (C=O) acts as the electrophilic site, while the cyanide ion (CN⁻) acts as the nucleophile. The CN⁻ attacks the carbon atom of the carbonyl group, and the reaction results in the formation of a hydroxynitrile compound (a cyanohydrin). This addition reaction leads to the creation of a new carbon-carbon bond and the replacement of the oxygen atom with the cyanide group.Nucleophilic substitution reactions, on the other hand, involve the replacement of a leaving group in a molecule by a nucleophile. In the case of formaldehyde and HCN, no leaving group is being substituted by the cyanide ion, so it is not a nucleophilic substitution reaction.In summary, the reaction of formaldehyde with HCN is an example of nucleophilic addition.

Why the other options are wrong
  • A. A) Nucleophilic substitution: This type of reaction involves the replacement of one group with another. In the reaction of formaldehyde with HCN, a group is not replaced; instead, the nucleophile adds to the molecule, breaking the double bond.
  • C. C) Electrophilic substitution: This reaction typically occurs with aromatic compounds like benzene, where an electrophile replaces a hydrogen atom on the ring. It is not characteristic of aldehydes and ketones.
  • D. D) Free radical addition: This type of reaction involves species with unpaired electrons (free radicals). The reaction between formaldehyde and HCN proceeds via a nucleophile and an electrophile, not free radicals. Free radical addition is more common in the polymerization of alkenes.

Q134. No individual atom in the sample of 1 mole of Neon has a mass of 20.18 a.m.u. Because it is:

  • A. Overall mass of an isobar
  • B. It is a fractional mass.
  • C. It is molar mass of Ne
  • D. The average atomic mass of Ne

Explanation: The atomic mass of an element like Neon (Ne) is typically expressed as an average atomic mass because neon exists as a mixture of isotopes, each with its mass. The atomic mass of 20.18 amu represents the weighted average of the masses of these isotopes, not the mass of a single atom.

Why the other options are wrong
  • A. Isobars are atoms of different elements that have the same mass number, and this concept does not apply to neon's atomic mass.
  • B. The atomic mass of neon is a whole number for each isotope but is averaged based on the isotope distribution, not a fractional concept in this context.
  • C. The atomic mass of neon is a whole number for each isotope but is averaged based on the isotope distribution, not a fractional concept in this context.

Q135. The p orbital has:

  • A. 2 lobes
  • B. 3 lobes
  • C. 4 lobes
  • D. 5 lobes

Explanation: The p orbital has 2 lobes because its wavefunction solution to the Schrödinger equation has a single node at the nucleus, leading to two regions of high electron probability on opposite sides of the nucleus. This shape corresponds to l = 1, the quantum number for p orbitals.

Why the other options are wrong
  • B. The p orbital has two lobes, not three, because of its specific shape and the way it's defined mathematically in quantum mechanics.
  • C. The p orbital has only two lobes, not four, due to its specific shape defined by the quantum mechanics governing atomic orbi
  • D. The p orbital has only two lobes, not five, because of the way atomic orbitals are defined by their quantum numbers.

Q136. All of the following steps are used to calculate the lattice energy in the Born-Haber cycle EXCEPT:

  • A. Atomizing the metal
  • B. lonizing the metal
  • C. Deionize the metal
  • D. lonize non metal

Explanation: Deionizing metal is not part of the Born-Haber cycle. It would involve turning ions back into atoms, which is not necessary for calculating lattice energy.

Why the other options are wrong
  • A. This step involves converting the solid metal into individual metal atoms in the gas phase, which is part of the Born-Haber cycle.
  • B. This step involves removing an electron from a metal atom to form a metal ion, which is required to calculate lattice energy.
  • D. This step involves adding an electron to a non-metal atom to form a negative ion, which is also part of the Born-Haber cycle.

Q137. The enthalpy change when 1 Mole of water is formed by the reaction of acid with an alkali under standard conditions is known as:

  • A. Enthalpy of formation
  • B. Enthalpy of reaction
  • C. Enthalpy of combustion
  • D. Enthalpy of neutralization

Explanation: The enthalpy of neutralization is the specific enthalpy change when one mole of water is formed from the reaction of an acid and a base (alkali) under standard conditions.

Why the other options are wrong
  • A. Enthalpy of formation is the enthalpy change when one mole of a compound is formed from its elements in their standard states. When water is formed, the reaction involves an acid and a base, not just the elements of water (hydrogen and oxygen).
  • B. Enthalpy of reaction is a general term for the enthalpy change that occurs during any chemical reaction. It doesn't specifically refer to the formation of water from an acid-base reaction.
  • C. Enthalpy of combustion is the enthalpy change when one mole of a substance is completely burned in oxygen. This is not relevant to the reaction of an acid and a base.

Q138. When carboxylic acid is heated with alcohol in the presence of sulphuric acid, one of the following is formed.

  • A. Amides
  • B. Acyl chloride
  • C. Esters
  • D. Acid anhydride

Explanation: When a carboxylic acid reacts with an alcohol in the presence of sulfuric acid, an ester is formed through a process called esterification. Sulfuric acid acts as a catalyst to speed up the reaction.

Why the other options are wrong
  • A. Amides are formed by the reaction of carboxylic acids with amines or ammonia, not alcohols, so this is not the correct product in this reaction.
  • B. Acyl chlorides are typically formed by reacting carboxylic acids with chlorinating agents like thionyl chloride (SOCl₂), not alcohols in the presence of sulfuric acid.
  • D. Acid anhydrides are typically formed by the dehydration of carboxylic acids, not by reacting with alcohols in the presence of sulfuric acid.

Q139. The oxidation number of 'Mn' in KMnO4, is

  • A. 0
  • B. +1
  • C. -7
  • D. +7

Explanation: In KMnO₄, Mn has an oxidation number of +7. This is determined by balancing the oxidation states of the other elements (K and O) in the compound, and it is one of the highest oxidation states Mn can achieve in compounds.

Why the other options are wrong
  • A. This would be the oxidation number of Mn in its elemental form (Mn), like when Mn is not part of a compound. However, in KMnO₄, Mn is in an oxidized state, not elemental, so this is incorrect.
  • B. This would be the oxidation number of Mn in compounds like MnCl₂ (where Mn is in a +2 oxidation state), but in KMnO₄, Mn is in a much higher oxidation state, so this is not correct.
  • C. This is not a valid oxidation state for manganese. Manganese can have positive oxidation numbers ranging from +1 to +7, but it does not go as low as -7 in typical compounds, so this option is incorrect.

Q140. Which one of the following is not an amino acid

  • A. Folic acid
  • B. Glutamic acid
  • C. Glycine
  • D. Lysine

Explanation: Folic acid is a B vitamin (B9) crucial for DNA synthesis, repair, and cell division and is essential during pregnancy for fetal development.

Why the other options are wrong
  • B. Glutamic acid is a non-essential amino acid that functions as a neurotransmitter in the brain and is involved in protein synthesis and metabolism.
  • C. Glycine is the simplest amino acid, serving as a building block for proteins and playing a key role in neurotransmission and the synthesis of various biomolecules.
  • D. Lysine is an essential amino acid important for protein synthesis, hormone production, and calcium absorption, primarily found in meat, dairy, and legumes.

Q141. In an elastic collision, the total kinetic energy

  • A. Dissipates after collision
  • B. Increases after the collision
  • C. Reduces after the collision
  • D. Before and after collision remains the same

Explanation: In an elastic collision, the total kinetic energy before the collision is equal to the total kinetic energy after the collision, meaning that kinetic energy is conserved throughout the process.

Why the other options are wrong
  • A. Incorrect, because in an elastic collision, kinetic energy is conserved and does not dissipate.
  • B. Incorrect, as no external force adds energy; kinetic energy remains constant.
  • C. Incorrect, since energy loss happens only in inelastic collisions, not elastic ones.

Q142. Which one of the following is NOT a feature of electric forces?

  • A. They act on charges
  • B. They act on masses
  • C. They can be attractive.
  • D. They can be repulsive

Explanation: Option B is Incorrect because electric forces act on charge, not mass (gravitational forces act on mass). And it is not a feature of electric forces.

Why the other options are wrong
  • A. Correct, as electric forces act on charged particles like electrons and protons.
  • C. Correct, as opposite charges (+ and -) attract each other.
  • D. Correct, as like charges (+ and + or - and -) repel each other.

Q143. The two-dimensional motion under constant acceleration due to gravity is called:

  • A. Circular motion
  • B. Rotational motion
  • C. Projectile motion
  • D. Vibratory motion

Explanation: Projectile motion is a specific example of two-dimensional (2D) motion. In projectile motion, an object is launched into the air and moves under the influence of gravity, following a curved trajectory known as a parabola.

Why the other options are wrong
  • A. Circular motion refers to the movement of an object along the circumference of a circle or a circular path. This motion can be uniform (constant speed) or non-uniform (changing speed)
  • B. Rotational motion refers to the movement of an object around a fixed axis. Unlike linear motion, which involves movement in a straight line, rotational motion involves angular displacement, velocity, and acceleration.
  • D. Vibratory motion refers to the oscillatory or repetitive movement of an object around an equilibrium position.

Q144. A charge of 90 C passes through a wire for 30 seconds. Then the current in the wire will be:

  • A. З А
  • B. 0.3 A
  • C. 3 mA
  • D. 0.3 mA

Explanation: Explanation is given as an image.

Why the other options are wrong
  • B. That's not the correct option as per calculation.
  • C. That's not the correct option as per calculation.
  • D. That's not the correct option as per calculation.

Q145. The magnitude of the current in metals is proportional to the potential difference across it as long as the temperature of the conductor is kept constant is known as:

  • A. Joule's Law
  • B. Gauss Law
  • C. Ohm's Law
  • D. Ampere's Law

Explanation: The current (I) flowing through a conductor between two points is directly proportional to the voltage (V) across the two points and inversely proportional to the resistance (R) of the conductor.

Why the other options are wrong
  • A. The heat generated by an electric current passing through a conductor is proportional to the square of the current (I²), the resistance (R) of the conductor, and the time (t) the current flows.
  • B. The total electric flux out of a closed surface is proportional to the enclosed electric charge.
  • D. The magnetic field (B) around a closed loop is proportional to the total electric current (I) passing through the loop. In integral form, it states that the line integral of the magnetic field around a closed path is equal to the permeability of free space (μ₀) times the current enclosed.

Q146. In a velocity-time graph, the area under the graph is equal to the

  • A. Speed of an object
  • B. Velocity of an object
  • C. Distance covered by object
  • D. Acceleration of an object

Explanation: The distance covered by an object is given by the area under the v-t graph.

Why the other options are wrong
  • A. This is the slope of the distance-time graph.
  • B. This is the slope of the displacement time graph.
  • D. This is the slope of the velocity-time graph.

Q147. When length of copper wire is doubled then resistivity becomes:

  • A. Double
  • B. Half
  • C. Remains same
  • D. Four times

Explanation: Resistivity of wire remains constant. As the length of wire gets doubled, the cross-sectional area will become half of its previous value because volume of wire remains constant

Why the other options are wrong
  • A. That's an incorrect option. The resistivity of material does not depend on the length and area of the wire
  • B. That's an incorrect option. The resistivity of material does not depend on the length and area of the wire
  • D. That's an incorrect option. The resistivity of material does not depend on the length and area of the wire

Q148. The resistance of semi-conductor with rise in temperature:

  • A. Increases
  • B. Decreases
  • C. Remain same
  • D. Infinite

Explanation: The electrons get excited and jump from the valance band into the conduction band and thereby increases conductance resulting in the decrease of resistance

Why the other options are wrong
  • A. It can't be increased in semiconductors because they don't have free electrons as in metals to create hindrance during the rise in temperature
  • C. Incorrect
  • D. When the temperature is 0K in semiconductor then the resistance will be infinite so incorrect

Q149. Volt × Ampere is the measure of:

  • A. Current
  • B. Volt
  • C. Resistance
  • D. Power

Explanation: Current is measured in Amperes (A), representing the flow of electric charge.Volt is a measure of electric potential difference.Resistance is measured in Ohms and is the opposition to the flow of current.Power is measured in Watts (W) and is calculated as the product of voltage (Volts) and current (Amperes).Thus, the correct answer is that Volt × Ampere measures Power.

Why the other options are wrong
  • A. Current is measured in Amperes (A), representing the flow of electric charge.Volt is a measure of electric potential difference.Resistance is measured in Ohms and is the opposition to the flow of current.Power is measured in Watts (W) and is calculated as the product of voltage (Volts) and current (Amperes).Thus, the correct answer is that Volt × Ampere measures Power.
  • B. Current is measured in Amperes (A), representing the flow of electric charge.Volt is a measure of electric potential difference.Resistance is measured in Ohms and is the opposition to the flow of current.Power is measured in Watts (W) and is calculated as the product of voltage (Volts) and current (Amperes).Thus, the correct answer is that Volt × Ampere measures Power.
  • C. Current is measured in Amperes (A), representing the flow of electric charge.Volt is a measure of electric potential difference.Resistance is measured in Ohms and is the opposition to the flow of current.Power is measured in Watts (W) and is calculated as the product of voltage (Volts) and current (Amperes).Thus, the correct answer is that Volt × Ampere measures Power.

Q150. According to Newton's Law of Motion, the mass of the object is a quantitative measure of its.

  • A. Weight
  • B. Inertia
  • C. Speed
  • D. Acceleration

Explanation: According to Newton's second law the mass of a body is the quantitative measure of its inertia.

Why the other options are wrong
  • A. Incorrect, as weight is the force due to gravity (W=mgW = mgW=mg), which depends on both mass and gravitational acceleration.
  • C. Incorrect, as mass does not directly measure speed; speed depends on velocity and external forces.
  • D. Incorrect, as acceleration depends on force and mass (a=F/ma = F/ma=F/m), but mass itself is not a measure of acceleration.

Q151. The formula Φ = B.A represents:

  • A. Electric flux
  • B. Magnetic flux
  • C. Electric flux density
  • D. Gravitational flux

Explanation: Magnetic flux is a measure of the total magnetic field passing through a given area. It quantifies how many magnetic field lines penetrate a surface. The concept is crucial in electromagnetism, especially in understanding electromagnetic induction. Mathematically, magnetic flux (Φ𝐵) through a surface can be expressed as:Φ𝐵=∫𝐵𝑑𝐴.

Why the other options are wrong
  • A. Electric flux is a measure of the electric field passing through a given surface area. It quantifies how many electric field lines intersect that surface and is an important concept in electromagnetism, especially in relation to Gauss's Law. Mathematically, electric flux (Φ𝐸) can be expressed as:Φ𝐸=∫E⋅𝑑𝐴
  • C. Electric flux density, also known as electric displacement field (D), describes how electric field lines distribute themselves in a medium. It accounts for free and bound charge within materials, making it especially useful in dielectric materials.The relationship is given by:𝐷=𝜀E
  • D. Gravitational flux refers to the quantity of gravitational field lines passing through a given surface area. It’s analogous to electric or magnetic flux but applies to gravitational fields.In a mathematical context, gravitational flux (Φ g) through a surface can be expressed as:Φ𝑔=∫𝑔⋅𝑑𝐴

Q152. 1KWh= _ J?

  • A. 3.6J
  • B. 3.6KJ
  • C. 3.6MJ
  • D. 3.6 GJ

Explanation: C is the correct option since 1 MJ = 10⁶ J, and we calculated 1 kWh = 3.6 × 10⁶ J = 3.6 MJ.

Why the other options are wrong
  • A. Incorrect, because 1 kWh is much larger than just 3.6 J.
  • B. Incorrect, as 1 kJ = 1000 J, so 3.6 kJ = 3600 J, which is far less than 1 kWh (3.6 × 10⁶ J).
  • D. Incorrect, because 1 GJ = 10⁹ J, which is much larger than 1 kWh (3.6 × 10⁶ J).

Q153. Which of the following statement is incorrect for any magnetic field lines?

  • A. Lines start at north pole and ends at south pole
  • B. Lines never touch or cross each other
  • C. The lines are curved
  • D. The magnetic field is strongest when the lines are farthest.

Explanation: Option D is Incorrect because the magnetic field is strongest where the lines are closest together, indicating a higher field strength. The following statement is incorrect for any magnetic field lines.

Why the other options are wrong
  • A. Correct, because outside a magnet, magnetic field lines emerge from the north pole and enter the south pole.
  • B. Correct, because if they did, it would imply multiple directions of the magnetic field at the same point, which is not possible.
  • C. Correct, since magnetic field lines always form closed curves, extending from the north pole to the south pole externally and continuing inside the magnet.

Q154. The unit of magnetic flux density is;

  • A. Wbm⁻¹
  • B. Wbm
  • C. Wbm-2
  • D. Wb

Explanation: Option C is Correct, as it correctly represents Weber per square meter (Wb/m² or Tesla, T).

Why the other options are wrong
  • A. Incorrect, as this unit does not match the correct formula (should be Wb/m²).
  • B. Incorrect, as this does not correctly represent flux density (it implies Weber multiplied by meter).
  • D. Incorrect, because Weber (Wb) is the unit of magnetic flux, not flux density.

Q155. Which of the following is a non-conservative force?

  • A. Frictional force
  • B. Effort + distance
  • C. Effort-distance
  • D. Effort +distance

Explanation: Frictional force is a non-conservative force.due to its energy-dissipating nature and the path-dependent work it entails. This contrasts with conservative forces like gravity and spring force, which store energy and have potential energy associated with them.

Why the other options are wrong
  • B. Incorrect, as this does not describe a physical force directly.
  • C. Incorrect, as it is not a standard force classification.
  • D. Incorrect, as it resembles work done (W=F×dW = F \times dW=F×d), not a force type.

Q156. The induced current flow in such a direction so as to oppose the cause that produces it. The statement is:

  • A. Ampere’s Law
  • B. Faraday’s Law
  • C. Lenz’s Law
  • D. Joule’s Law

Explanation: Lenz's law, in electromagnetism, states that an induced electric current flows in a direction such that the current opposes the change that induced it.

Why the other options are wrong

    Q157. In an AC generator the emf will be maximum when factor sinωt is equal to:

    • A. Zero
    • B. 2
    • C. 1
    • D. 1/2

    Explanation: B is the correct option. This option is correct. The emf will be maximum when the value of the sine function is at its maximum. The sine function sin⁡(θ) reaches its maximum value of 1.

    Why the other options are wrong
    • A. Incorrect, because when sin(ωt) = 0, the emf is also zero.
    • B. Incorrect, since sin(ωt) always stays between -1 and 1, so it can never be 2.
    • D. Incorrect because sin(ωt) = 1/2 gives a partial emf, not the maximum.

    Q158. When a force of 1N displaces its point of application by 1m in the direction of the force, the work done is

    • A. 1J
    • B. 10J
    • C. 0J
    • D. 100J

    Explanation: The formula for work done (W) is:W=F×d×cos⁡θW = F \times d \times \cos\thetaW=F×d×cosθWhere:W = Work done (in Joules)F = Force (in Newtons)d = Displacement (in meters)θ\thetaθ = Angle between force and displacementGiven:Force = 1NDisplacement = 1mDirection of force = direction of displacement, so θ=0∘\theta = 0^\circθ=0∘ and cos(0) = 1W=1×1×1=1JW = 1 \times 1 \times 1 = 1JW=1×1×1=1J

    Why the other options are wrong
    • B. Incorrect, since the work done is 1J, not 10J.
    • C. Incorrect, as work is zero only if force or displacement is zero, or if the force is perpendicular to displacement (θ=90∘\theta = 90^\circθ=90∘).
    • D. This is not correct as per Calculations

    Q159. Electric generators and transformers are based on the principles of:

    • A. Coulomb's law
    • B. Faraday's Law
    • C. Ampere's law
    • D. Hook's law

    Explanation: Transformers and generators work on the principle of Faraday s Law.

    Why the other options are wrong
    • A. Incorrect, as Coulomb’s Law deals with electrostatic forces between charges, not electromagnetic induction.
    • C. Incorrect, as Ampere’s Law relates magnetic fields to electric currents but does not directly govern induction.
    • D. Incorrect, because Hooke’s Law is about elastic forces in materials, not electricity or magnetism.

    Q160. An electric motor is used to lift the weight of 2.0N through a vertical distance of 100 cm in 4 sec. What is the power output of the motor?

    • A. 25 W
    • B. 0.5 W
    • C. 0.75 W
    • D. 1 W

    Explanation: W=2.0N×1.0m=2.0JNext, the time taken to lift the weight is 4 seconds. Now we can find the power:P =work/time=2/4=0.5Watt

    Why the other options are wrong
    • A. Incorrect, as the given force and displacement do not result in such high power.
    • C. Incorrect, as it overestimates the power output.
    • D. Incorrect, as the actual power output is lower than this value

    Q161. In an ideal transformer:

    • A. Power input is equal to Power output.
    • B. Power input is less than half of the power output.
    • C. Power input is greater than Power output
    • D. Power input is more than half of the power output.

    Explanation: A is Correct, as an ideal transformer operates with 100% efficiency, meaning no energy is lost

    Why the other options are wrong
    • B. Incorrect, because in an ideal transformer, power cannot be created or increased beyond input.
    • C. Incorrect, since an ideal transformer has no energy loss, making input and output power equal.
    • D. Incorrect, as this suggests some power loss, which only happens in a real (non-ideal) transformer.

    Q162. The conversion of A.C into D.C is called rectification and circuit is called rectifier, Which component of electronics acts as a rectifier?

    • A. Diode
    • B. Transistor
    • C. Transformer
    • D. Inductor

    Explanation: A diode is a semiconductor device that allows current to flow in one direction while blocking it in the opposite direction. This unidirectional behavior is essential in various applications, such as rectification, signal modulation, and voltage regulation.

    Why the other options are wrong
    • B. A transistor is a semiconductor device that can act as a switch, amplifier, or signal modulator. It consists of three layers of semiconductor material, each forming a region known as the emitter, base, and collector.
    • C. Transform steps up or steps down the current flowing through its coils.
    • D. An inductor converts DC into AC.

    Q163. The centripetal acceleration of an object moving along a circle of radius 'r' with an angular speed 'w' is given by the formula:

    • A. a= r W2
    • B. a= r W
    • C. a = r² W
    • D. a= r² W²

    Explanation: Centripetal acceleration increases with radius and is also affected more significantly when angular speed increases, as it is squared.

    Why the other options are wrong
    • B. This suggests a direct proportionality between acceleration and angular speed, but in reality, angular speed has a greater effect due to squaring.
    • C. Squaring the radius incorrectly exaggerates its influence on acceleration, which is not how circular motion works.
    • D. Both the radius and angular speed are squared, which incorrectly overestimates acceleration, as only angular speed should be squared.

    Q164. Full wave rectification is given by:

    • A. One diode connected in bridge-type arrangements
    • B. Two diodes connected in bridge-type arrangements
    • C. Three diodes connected in bridge type arrangements
    • D. Four diodes connected in a bridge type arrangement

    Explanation: For a full wave rectification, four diodes connected in a bridge type arrangement are needed.

    Why the other options are wrong
    • A. Incorrect, as a single diode only allows half-wave rectification, blocking the negative half-cycle of AC.
    • B. Incorrect, because two diodes are used in a center-tap full-wave rectifier, not a bridge rectifier.
    • C. Incorrect, since a bridge rectifier requires four diodes to properly convert both halves of the AC waveform.

    Q165. A diode characteristic curve is a plot between:

    • A. Current and time
    • B. Voltage and time
    • C. Voltage and current
    • D. Reverse voltage forward voltage

    Explanation: B is the correct option. A diode characteristic curve, also known as the I-V (current-voltage) curve, illustrates the relationship between the current flowing through the diode and the voltage across it.This curve helps in understanding the behavior of the diode in different operating conditions, including forward bias (where current flows) and reverse bias (where very little current flows).Thus, the correct answer is that a diode characteristic curve is a plot between Voltage and current.

    Why the other options are wrong
    • A. A diode characteristic curve, also known as the I-V (current-voltage) curve, illustrates the relationship between the current flowing through the diode and the voltage across it.This curve helps in understanding the behavior of the diode in different operating conditions, including forward bias (where current flows) and reverse bias (where very little current flows).Thus, the correct answer is that a diode characteristic curve is a plot between Voltage and current.
    • B. A diode characteristic curve, also known as the I-V (current-voltage) curve, illustrates the relationship between the current flowing through the diode and the voltage across it.This curve helps in understanding the behavior of the diode in different operating conditions, including forward bias (where current flows) and reverse bias (where very little current flows).Thus, the correct answer is that a diode characteristic curve is a plot between Voltage and current.
    • D. A diode characteristic curve, also known as the I-V (current-voltage) curve, illustrates the relationship between the current flowing through the diode and the voltage across it.This curve helps in understanding the behavior of the diode in different operating conditions, including forward bias (where current flows) and reverse bias (where very little current flows).Thus, the correct answer is that a diode characteristic curve is a plot between Voltage and current.

    Q166. An air craft makes a turn in a horizontal circle of radius100m. It is travelling with a velocity of 250m/sec. The angular velocity of the air craft will be:

    • A. 1.5 rad/sec
    • B. 2.5 rad/sec
    • C. 3 rad/sec
    • D. 3.5 rad/sec

    Explanation: ω=v/r=250m/s/10m=2.5rad/s

    Why the other options are wrong
    • A. Incorrect, as it underestimates the correct angular velocity.
    • C. Incorrect, as the actual angular velocity is lower than 3 rad/sec.
    • D. Incorrect, as it overestimates the angular velocity.

    Q167. The value of Planck constant is:

    • A. 6.63×10⁻³⁴ Js
    • B. 6.63×10³⁴ Js
    • C. 6.63×10-36 Js
    • D. 6.63×10³⁴ Js⁻¹

    Explanation: . 6.63×10−34js ✅ – Correct, as this is the well-known value of Planck’s constant, used in quantum mechanics to relate energy and frequency

    Why the other options are wrong
    • B. Incorrect, because the exponent should be negative (-34), not positive (34).
    • C. Incorrect, as the exponent is too small, making the value incorrect.
    • D. Incorrect, because not only is the exponent wrong, but the unit Js⁻¹ is incorrect; Planck’s constant has the unit Js (Joule-seconds).

    Q168. The de-Broglie wavelength associated with a particle moving at 10⁶ m/s and having mass 10⁻³⁰ kg:

    • A. 6.6 X 10-10 m
    • B. 1.5×10⁶ m
    • C. 1.9×10⁻⁵ m
    • D. 7.2×10⁻⁸ m

    Explanation: Step 1: Calculate the momentum (p)p=mv=10-24kgm/sStep 2: Calculate the de Broglie wavelengthNow, substitute p into the de Broglie wavelength formula:λ=hp=6.626×10−34 Js10−24 kg m/s=6.6x10-10m

    Why the other options are wrong
    • B. Incorrect, as it is an unrealistically large wavelength, not typical for microscopic particles.
    • C. – Incorrect, as this value is too large for a particle with such a small mass and high speed.
    • D. Incorrect, because although it's closer to the correct range, it does not match the expected de Broglie wavelength.

    Q169. Light propagates through space as a wave is evident by all of the following EXCEPT:

    • A. Interference
    • B. Photoelectric effect
    • C. Diffraction
    • D. Polarization

    Explanation: The photoelectric effect is a phenomenon in physics where electrons are emitted from a material (usually a metal) when it absorbs light or electromagnetic radiation of sufficient energy. This effect was crucial in the development of quantum mechanics and provided evidence for the particle-like properties of light.

    Why the other options are wrong
    • A. Evidence of wave nature, as light waves overlap and produce constructive or destructive patterns.
    • C. Evidence of wave nature, as light bends around obstacles and spreads through small openings.
    • D. Evidence of wave nature, as only specific light wave orientations pass through polarizing filters.

    Q170. A particle of mass 'm' is moving on a circular path of radius 'r' with velocity 'v', then centripetal force acting on it is F. if the velocity of particle increases by 2 times and radius of circular path increases by 4 times then new centripetal force F' will be;

    • A. F' = 2F
    • B. F’ = 1/2 * F
    • C. F’ = 4F
    • D. F’ = F

    Explanation: Despite both the velocity and the radius changing, the net effect on the centripetal force remains the same. The increase in velocity and the increase in radius cancel each other out in such a way that the force does not change.

    Why the other options are wrong
    • A. Incorrect, because increasing velocity and radius in the given manner does not double the force.
    • B. Despite both the velocity and the radius changing, the net effect on the centripetal force remains the same. The increase in velocity and the increase in radius cancel each other out in such a way that the force does not change.
    • C. Incorrect, as the increase in velocity is balanced by the increase in radius.

    Q171. Which series falls in ultra violet region?

    • A. Lyman
    • B. Brackett
    • C. Pfund
    • D. Paschen

    Explanation: Lymann series falls in the UV region.

    Why the other options are wrong
    • B. The wavelengths of the Brackett series lines fall within the infrared range.
    • C. The wavelengths of the Pfund series lines fall within the infrared region.
    • D. The wavelengths of the Paschen series lines fall within the infrared range,

    Q172. The potential through which an electron should be accelerated, so that, on collision it can lift the electron in the atom from its ground state to some higher state is known as:

    • A. Ionization potential
    • B. Excitation potential
    • C. String potential
    • D. Acceleration potential

    Explanation: Excitation potential refers to the minimum energy required to excite an atom or molecule from its ground state to a higher energy state, typically an excited state. This concept is crucial in fields like atomic physics, quantum mechanics, and spectroscopy.

    Why the other options are wrong
    • A. This is the minimum potential required to completely remove an electron from an atom, not just excite it to a higher energy level.
    • C. – This term is not relevant to atomic physics and electron excitation.
    • D. While electrons are accelerated by a potential, this term does not specifically refer to energy level transitions in atoms.

    Q173. A roller coaster is moving with 30m * s ^ - 1 on a circular track of radius 30m. the net mass of coaster + passengers is 'm' the centripetal force acting on it is;

    • A. 900m
    • B. 10 m
    • C. 450m
    • D. 30m

    Explanation: Fc= mv2/r=m(30)2/r=30m

    Why the other options are wrong
    • A. This option is incorrect as per calculations.
    • B. This option is incorrect as per calculations
    • C. This option is incorrect as per calculations

    Q174. Which of the following regarding X Rays is INCORRECT:

    • A. Have higher wavelength than visible light
    • B. They are part of electromagnetic spectrum
    • C. They are highly penetrating in soft body tissues
    • D. They are high energy photons

    Explanation: This statement is incorrect. X-rays have a shorter wavelength than visible light, typically in the range of 0.01 to 10 nanometers, while visible light wavelengths range from about 400 to 700 nanometers.

    Why the other options are wrong
    • B. This statement is correct. X-rays are indeed part of the electromagnetic spectrum, which includes a range of electromagnetic radiation types, from radio waves to gamma rays.
    • C. This statement is correct. X-rays can penetrate the soft tissues of the body, which is why they are used in medical imaging.
    • D. This statement is correct. X-rays consist of high-energy photons, which allows them to penetrate materials more effectively than lower-energy photons like visible light.

    Q175. The unit of decay constant is;

    • A. m
    • B. s
    • C. s-1
    • D. m-¹

    Explanation: The unit of decay constant is per second.

    Why the other options are wrong
    • A. A unit of length, not relevant to decay constant.
    • B. A unit of time, but decay constant is measured in the inverse of time,
    • D. A unit of reciprocal length, unrelated to decay processes.

    Q176. Amplitude in the following figure is given as:

    • A. 2m
    • B. 1/2m
    • C. 4 m
    • D. 1m

    Explanation: In the figure, the wave reaches a maximum displacement of 1 meter above and below the equilibrium line. Amplitude is defined as the maximum displacement from the mean (equilibrium) position, so: Amplitude = 1 m

    Why the other options are wrong
    • A. In the figure, the wave reaches a maximum displacement of 1 meter above and below the equilibrium line. Amplitude is defined as the maximum displacement from the mean (equilibrium) position, so: Amplitude = 1 m
    • B. In the figure, the wave reaches a maximum displacement of 1 meter above and below the equilibrium line. Amplitude is defined as the maximum displacement from the mean (equilibrium) position, so: Amplitude = 1 m
    • C. In the figure, the wave reaches a maximum displacement of 1 meter above and below the equilibrium line. Amplitude is defined as the maximum displacement from the mean (equilibrium) position, so: Amplitude = 1 m

    Q177. An artificial radioactive element can be made by bombarding.

    • A. High-energy particles on unstable elements
    • B. Low-energy particles on unstable elements
    • C. High-energy particles on stable elements
    • D. Low-energy particles on stable elements

    Explanation: Artificial radioactive elements are created by bombarding high-energy particles (neutrons, protons, α-particles) on stable elements. These particles penetrate the nucleus, causing nuclear reactions that form new radioactive isotopes. Stable elements do not decay naturally, so high-energy bombardment is needed to induce artificial radioactivity, as seen in nuclear reactors and particle accelerators.

    Why the other options are wrong
    • A. An artificial radioactive element can be made by bombarding high-energy particles on stable elements, not unstable ones.
    • B. Artificial radioactive elements are created by bombarding high-energy particles on stable elements, not low-energy particles on unstable elements.
    • D. Artificial radioactive elements are created by bombarding high-energy particles on stable elements, not low-energy particles on stable elements.

    Q178. If we have "N₀" number of any radioactive element then after a period of "n" half-lives the number of atoms left behind is:

    • A. 2ⁿN₀
    • B. (1/2)nN0
    • C. (½ N₀)ⁿ
    • D. (2N₀)ⁿ

    Explanation: A half-life is the time it takes for half of the radioactive substance to decay.After one half-life, half of the original quantity remains, so there will be N0\​​.2After two half-lives, half of the remaining half will decay, leaving N0\4Continuing this process, after "n" half-lives, the remaining quantity can be expressed as:N=N0(1/2)nThis means that the number of atoms left after "n" half-lives is (1/2)nN0

    Why the other options are wrong
    • A. A half-life is the time it takes for half of the radioactive substance to decay.After one half-life, half of the original quantity remains, so there will be N0\​​.2After two half-lives, half of the remaining half will decay, leaving N0\4Continuing this process, after "n" half-lives, the remaining quantity can be expressed as:N=N0(1/2)nThis means that the number of atoms left after "n" half-lives is (1/2)nN0So this option Is incorrect.
    • C. A half-life is the time it takes for half of the radioactive substance to decay.After one half-life, half of the original quantity remains, so there will be N0\​​.2After two half-lives, half of the remaining half will decay, leaving N0\4Continuing this process, after "n" half-lives, the remaining quantity can be expressed as:N=N0(1/2)nThis means that the number of atoms left after "n" half-lives is (1/2)nN0So this option Is incorrect.
    • D. A half-life is the time it takes for half of the radioactive substance to decay.After one half-life, half of the original quantity remains, so there will be N0\​​.2After two half-lives, half of the remaining half will decay, leaving N0\4Continuing this process, after "n" half-lives, the remaining quantity can be expressed as:N=N0(1/2)nThis means that the number of atoms left after "n" half-lives is (1/2)nN0So this option Is incorrect.

    Q179. Which of the following is NOT the Somatic biological effect of radiation?

    • A. Skin burn
    • B. Loss of hair
    • C. Induction of cancer
    • D. Gene Mutation

    Explanation: Gene mutation – NOT a somatic effect, as it affects reproductive (germ) cells and can be passed to offspring.

    Why the other options are wrong
    • A. A somatic effect caused by radiation damaging skin tissues.
    • B. A somatic effect due to radiation affecting hair follicles.
    • C. A somatic effect as radiation exposure can lead to cancerous cell growth.

    Q180. Which one of the following is INCORRECT about the nodes when the string is plucked?

    • A. Amplitude of vibration is zero.
    • B. Do not move along the string.
    • C. Produced at the fixed ends of strings
    • D. The distance between consecutive nodes is 1 wavelength.

    Explanation: Incorrect, the distance between consecutive nodes is half a wavelength (λ/2), not a full wavelength.

    Why the other options are wrong
    • A. Correct, as nodes are points of no displacement.
    • B. Correct, nodes remain stationary.
    • C. Correct, fixed ends are always nodes.

    Q181. In transverse waves the portion above the mean level is called:

    • A. Wave front
    • B. Wave crest
    • C. Wave trough
    • D. Wavelength

    Explanation: A wave crest is the highest point of a wave. In ocean waves, it's where the water rises before it breaks and crashes back down. In a more general context, it can refer to the peak of any wave-like phenomenon, such as sound waves or electromagnetic waves.

    Why the other options are wrong
    • A. A wavefront is an imaginary surface that connects all the points in a wave that are at the same phase of oscillation. In simpler terms, it represents the leading edge of a wave as it propagates through a medium. For instance, in water waves, the wave front could be seen as the line where the waves are cresting at the same time. In sound waves, it would represent the surface where the sound pressure is at a similar point in its cycle. Wave fronts can be straight, curved, or even spherical, depending on the type of wave and its source
    • C. A wave trough is the lowest point in a wave cycle, occurring between two successive crests (the highest points). In a wave, the trough represents the point of maximum negative displacement from the equilibrium position.
    • D. Wavelength (λ) is the distance between successive points of a wave that are in phase, such as from crest to crest or trough to trough.

    Q182. Which one of the following does not cause stationary waves?

    • A. Two waves of equal frequency
    • B. Two waves of the same speed
    • C. Two waves of unequal amplitude
    • D. Two waves travelling in opposite directions

    Explanation: When waves have unequal amplitudes, they do not form stationary waves.

    Why the other options are wrong
    • A. Can cause stationary waves if they interfere properly.
    • B. It can still form stationary waves if other conditions are met.
    • D. Essential for forming stationary waves through interference.

    Q183. Select the appropriate Doppler equation when source is approaching the stationary observer where f₀ is the observed frequency, fₛ is frequency of source, v is the speed of sound, vₛ is the speed of source relative to observer:

    • A. f₀ = fₛ (v + vₛ)/v
    • B. f₀ = fₛ v/(v + vₛ)
    • C. f₀ = fₛ v/(v - vₛ)
    • D. f₀ = fₛ (v + vₛ)/(v - vₛ)

    Explanation: Correct. This equation applies when the source is moving toward a stationary observer, causing the observed frequency to increase.

    Why the other options are wrong
    • A. Incorrect. This is used when the observer is moving toward a stationary source, not when the source is moving.
    • B. Incorrect. This is used when the source is moving away from a stationary observer.
    • D. Incorrect. This is not a standard Doppler shift equation and mixes both source and observer movement terms improperly.

    Q184. The distance between two successive particles which are exactly in the same state of vibration is called:

    • A. Frequency
    • B. Amplitude
    • C. Wavelength
    • D. Time period

    Explanation: Wavelength is the distance between successive crests (or troughs) of a wave.

    Why the other options are wrong
    • A. Frequency is the number of cycles or oscillations that occur in a unit of time.
    • B. Amplitude refers to the maximum extent of a vibration or oscillation, measured from the position of equilibrium (or rest) to the peak (or trough) of the wave.
    • D. The time period refers to the duration of one complete cycle of a periodic motion or oscillation.

    Q185. During the isothermal process, the temperature:

    • A. Remains constant during the initial phase of the process
    • B. Remains constant throughout the process
    • C. Alters throughout the process
    • D. Increases throughout the process

    Explanation: In an isothermal process, the temperature of the system remains constant. For an ideal gas, this means that any heat added to the system is used to do work, rather than changing the internal energy.

    Why the other options are wrong
    • A. Incorrect, as temperature remains constant at all times, not just initially.
    • C. – Incorrect, as temperature does not change in an isothermal process.
    • D. Incorrect, since the temperature remains unchanged.

    Q186. What is the value of heat energy (Q) in an adiabatic process?

    • A. 1
    • B. 0
    • C. -1
    • D. 2

    Explanation: In an adiabatic process, the value of heat energy (\(Q\)) is zero. This is because, by definition, an adiabatic process is one in which no heat is exchanged between the system and its surroundings, meaning the system is perfectly insulated. Therefore, \(Q = 0\) in an adiabatic process, and any changes in internal energy are due solely to work done by or on the system.

    Why the other options are wrong
    • A. In an adiabatic process, the value of heat energy (\(Q\)) is zero. This is because, by definition, an adiabatic process is one in which no heat is exchanged between the system and its surroundings, meaning the system is perfectly insulated. Therefore, \(Q = 0\) in an adiabatic process, and any changes in internal energy are due solely to work done by or on the system.
    • C. In an adiabatic process, the value of heat energy (\(Q\)) is zero. This is because, by definition, an adiabatic process is one in which no heat is exchanged between the system and its surroundings, meaning the system is perfectly insulated. Therefore, \(Q = 0\) in an adiabatic process, and any changes in internal energy are due solely to work done by or on the system.
    • D. In an adiabatic process, the value of heat energy (\(Q\)) is zero. This is because, by definition, an adiabatic process is one in which no heat is exchanged between the system and its surroundings, meaning the system is perfectly insulated. Therefore, \(Q = 0\) in an adiabatic process, and any changes in internal energy are due solely to work done by or on the system.

    Q187. The instantaneous velocity along the curved path is;

    • A. Along the tangent
    • B. Perpendicular to the slope
    • C. Parallel to the radius
    • D. Anti-parallel to the radius

    Explanation: The instantaneous velocity of an object moving in a circle is directed along the tangent to the circle at the object's position. This tangential velocity indicates the direction in which the object would move if it were to continue in a straight line at that instant, following the path of the tangent.

    Why the other options are wrong
    • B. Incorrect, as velocity is not necessarily perpendicular to the slope; it follows the direction of motion.
    • C. Incorrect, because in circular motion, velocity is always perpendicular to the radius, not parallel.
    • D. Incorrect, as velocity is not directed opposite to the radius; rather, it is tangential to the curve.

    Q188. An artificial radioactive element can be made by bombarding.

    • A. Neutron
    • B. Electron
    • C. Proton
    • D. Anti-neutrino

    Explanation: Neutrons are used to create artificial radioactive elements because of their unique properties that make them highly effective at interacting with atomic nuclei.

    Why the other options are wrong
    • B. An artificial radioactive element is typically created by bombarding a stable nucleus with high-energy particles like neutrons or alpha particles, not by bombarding it with an electron.
    • C. Protons can be used to create artificial radioactive elements, but neutrons are generally more effective for this purpose.
    • D. An antineutrino is not used to create artificial radioactive elements because it interacts very weakly with matter, making it ineffective for inducing nuclear reactions.

    Q189. The Coulomb's law states:

    • A. Force between two point charges is inversely proportional to the product of the charges and directly proportional to the square of the distance between them.
    • B. Force between two point charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.
    • C. Force between two point charges is directly proportional to the sum of the charges and inversely proportional to the square of the distance between them.
    • D. Force between two point charges is directly proportional to the product of the charges and to the square of the distance between them.

    Explanation: Coulomb's law describes the electrostatic interaction between charged particles. It states that the force (F) between two point charges (q1 and 𝑞2) is directly proportional to the product of the magnitudes of the charges and inversely proportional to the square of the distance (r) between them

    Why the other options are wrong
    • A. Incorrect, because force is directly proportional to the product of charges, not inversely.
    • C. Incorrect, because force depends on the product, not the sum, of charges.
    • D. Coulomb's law describes the electrostatic interaction between charged particles. It states that the force (F) between two point charges (q1 and 𝑞2) is directly proportional to the product of the magnitudes of the charges and inversely proportional to the square of the distance (r) between them

    Q190. The formula V = W / q₀ represents:

    • A. Electric intensity
    • B. Electric power
    • C. Electric potential
    • D. Electric field gradient

    Explanation: V=W/q is the formula of electric potential.

    Why the other options are wrong
    • A. Incorrect, as electric intensity (electric field) is given by E=F/q
    • B. Incorrect, because electric power is given by P=VI
    • D. Incorrect, as the electric field gradient refers to how the field changes in space, not work per charge.

    Q191. The S.I unit of capacitance of a capacitor is:

    • A. A: Coulomb
    • B. B: Volt
    • C. C: Farad
    • D. D: Ampere

    Explanation: The S.I unit of capacitance is the Farad (F). This unit quantifies how much electric charge a capacitor can store per volt applied across its plates. One Farad is equivalent to one coulomb of charge stored per one volt of potential difference. The other options represent different electrical units: Coulomb measures charge, Volt measures potential difference, and Ampere measures current. None of these units relate directly to the ability of a capacitor to store charge, making Farad the correct choice.

    Why the other options are wrong
    • A. Coulomb is the unit of electric charge, not specifically related to capacitance.
    • B. Volt is the unit of electric potential difference and does not represent capacitance.
    • D. Ampere is the unit of electric current, which is distinct from capacitance.

    Q192. Electric intensity between two oppositely charge plates in the middle region is:

    • A. Non-uniform
    • B. Uniform
    • C. Cannot be predicted
    • D. Variable

    Explanation: The electric intensity (or electric field strength) between two oppositely charged plates, such as in a parallel plate capacitor, is uniform.

    Why the other options are wrong
    • A. Incorrect, because the electric field between two large, oppositely charged parallel plates is uniform.
    • C. Incorrect, as the field can be easily determined using electrostatic principles.
    • D. Incorrect, because the field remains the same everywhere in the middle region between the plates (except near the edges, where fringing occurs).

    Q193. Find the potential difference in moving a 2 C charge, which requires 600 J of work between two points.

    • A. 1200V
    • B. 300V
    • C. 150V
    • D. 2400V

    Explanation: The potential difference V can be found using the formula = W/q=600/2=300 V

    Why the other options are wrong
    • A. If the work done were 2400J instead of 600J, the voltage would be 1200V
    • C. The potential difference V can be found using the formula = W/q=600/2=300 V
    • D. The potential difference V can be found using the formula = W/q=600/2=300 V

    Q194. Work-done is equal to:

    • A. Effort x distance
    • B. Effort + distance
    • C. Effort - distance
    • D. Effort + distance

    Explanation: Since work done is the product of force and distance, and effort is also a force,o effort X force gives work done.

    Why the other options are wrong
    • B. Work is not the sum of effort and distance; multiplication, not addition, is needed.
    • C. Work is not calculated by subtracting distance from effort.
    • D. Work is not the sum of effort and distance; multiplication, not addition, is needed.

    Q195. Read the following and choose the correct answer : “ P, Q and R are one-digit, non-negative numbers. P is the smallest even number. Q is the largest odd number. R is 5.”

    • A. P+Q+R= 16
    • B. P+Q +R =12
    • C. (Q+R) ×P= 30
    • D. (Q+R) ×P= 8

    Explanation: Let's determine the values of P, Q, and R first:P is the smallest even number → P = 2Q is the largest odd number → Q = 9R is given as 5So adding them makes 16

    Why the other options are wrong
    • B. Let's determine the values of P, Q, and R first:P is the smallest even number → P = 2Q is the largest odd number → Q = 9R is given as 5 Adding them doesn't give 12
    • C. Let's determine the values of P, Q, and R first:P is the smallest even number → P = 0Q is the largest odd number → Q = 9R is given as 5 Adding them doesn't give 30
    • D. Let's determine the values of P, Q, and R first:P is the smallest even number → P = 0Q is the largest odd number → Q = 9R is given as 5 Adding them doesn't give 8

    Q196. The government has increased the taxes on all businesses in Pakistan.Many small businesses will have to close their operation in Pakistan.

    • A. Statement I is the cause and Statement II is the effect.
    • B. Statement II is the cause and Statement I is the effect.
    • C. Both statements I and II are independent causes.
    • D. Both the statement I and II are the effects of independent causes.

    Explanation: Here by reading out the two statements, it’s clear that because the government has increased taxes on all businesses in Pakistan (1), as a result, many small businesses will have to close their operation. Majorly because small businesses do not have capital large enough to pay increased taxes. Hence, Statement 2 here is the effect of Statement 1 i.e. the cause.

    Why the other options are wrong
    • B. As per the explanation, this option is incorrect.
    • C. As per the explanation, this option is incorrect.
    • D. As per the explanation, this option is incorrect.

    Q197. Read the passage and the following statements below. Then choose the correct option,basing your answer only on the information provided. Pakistan is rich in wildlife and culture. It is home to many sorts of wildlife,from the Ibex to the Indus River Dolphin ;and people from most countries in the world have made their home here. Statements :i. Pakistan is rich countryii. People from all nationalities of the world live in Pakistan.iii. Pakistan is home to at least one dolphin species.

    • A. Only iii statement is correct
    • B. Only i and ii are correct
    • C. Only i and iii are correct
    • D. Only ii and iii are correct

    Explanation: Let's evaluate each statement based only on the passage:Statement i: "Pakistan is rich country" Incorrect. The passage says "Pakistan is rich in wildlife and culture", not in terms of wealth.Statement ii: "People from all nationalities of the world live in Pakistan." Incorrect. The passage says "people from most countries", not all nationalities.Statement iii: "Pakistan is home to at least one dolphin species." Correct. The passage specifically mentions the Indus River Dolphin, confirming this.Correct answer: Only statement iii is correct.

    Why the other options are wrong
    • B. Let's evaluate each statement based only on the passage:Statement i: "Pakistan is rich country" Incorrect. The passage says "Pakistan is rich in wildlife and culture", not in terms of wealth.Statement ii: "People from all nationalities of the world live in Pakistan." Incorrect. The passage says "people from most countries", not all nationalities.Statement iii: "Pakistan is home to at least one dolphin species." Correct. The passage specifically mentions the Indus River Dolphin, confirming this.Correct answer: Only statement iii is correct.
    • C. Let's evaluate each statement based only on the passage:Statement i: "Pakistan is rich country" Incorrect. The passage says "Pakistan is rich in wildlife and culture", not in terms of wealth.Statement ii: "People from all nationalities of the world live in Pakistan." Incorrect. The passage says "people from most countries", not all nationalities.Statement iii: "Pakistan is home to at least one dolphin species." Correct. The passage specifically mentions the Indus River Dolphin, confirming this.Correct answer: Only statement iii is correct.
    • D. Let's evaluate each statement based only on the passage:Statement i: "Pakistan is rich country" Incorrect. The passage says "Pakistan is rich in wildlife and culture", not in terms of wealth.Statement ii: "People from all nationalities of the world live in Pakistan." Incorrect. The passage says "people from most countries", not all nationalities.Statement iii: "Pakistan is home to at least one dolphin species." Correct. The passage specifically mentions the Indus River Dolphin, confirming this.Correct answer: Only statement iii is correct.

    Q198. Observe the pattern and select the next term, in the sequence: JEQ, HEO, FEM.

    • A. GFN
    • B. DEK
    • C. GEL
    • D. DFK

    Explanation: The pattern follows (-2, 0, -2) for the first, second, and third letters respectively, so the next term is DEK.

    Why the other options are wrong
    • A. The pattern follows (-2, 0, -2) for the first, second, and third letters, respectively, so the next term is DEK.
    • C. The pattern follows (-2, 0, -2) for the first, second, and third letters, respectively, so the next term is DEK.
    • D. The pattern follows (-2, 0, -2) for the first, second, and third letters, respectively, so the next term is DEK.

    Q199. Read the following and choose the correct answer.X, Y and Z are three whole numbers less than 24 but greater than 11. X is the smallest prime number. Y is the largest number divisible by 3. Z is the smallest number divisible by 11.

    • A. X is 13, Y is 24, Z is 11
    • B. X is 13, Y is 21, Z is 22
    • C. X is 11, Y is 21, Z is 11
    • D. X is 11, Y is 24, Z is 22

    Explanation: As the question states, the whole number is less than 24, hence options A and D are eliminated. Let's list the numbers in question, 12,13,14,15,16,17,18,19,20,21,22,23. X is the smallest prime number. Among the numbers listed 13 is the smallest prime number so X is 13. Y is the biggest number divisible by 3. 21 is the largest number among these but it is divisible by 3. So Y is 21. Z is the number divisible by 11. Amongst all these numbers only 22 is divisible by 11. This is what makes option B the most appropriate choice.

    Why the other options are wrong
    • A. As the question states, the whole number is less than 24, hence A is eliminated.
    • C. Option C seems to be the answer but as it is mentioned at the start of the question, the whole numbers are less than 24 and greater than 11. This is what makes option B the most appropriate choice. So, option C is incoorect.
    • D. As the question states, the whole number is less than 24, hence D is eliminated.

    Q200. All hammers are tools. Some tools are useless things. All useless things are trash. Which of the following is NECESSARILY TRUE given only the information above?ConclusionsI. Some hammers are trash. II. Some tools are trash.III. All useless things are tools.

    • A. I and III
    • B. I and II
    • C. II and III
    • D. II

    Explanation: Now look at the conclusions provided, For I, if we look at the diagram some hammers are not trash hence I is wrong. For II, Some tools are trash as indicated in the yellow-shaded region hence II is correct. For III, Not ALL useless things are tools rather some useless things are tools so III is also wrong. The only option correct according to the above analyses is D ( only conclusion II).

    Why the other options are wrong
    • A. As per the explanation, this option is incorrect.
    • B. As per the explanation, this option is incorrect.
    • C. As per the explanation, this option is incorrect.

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