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Federal Mdcat 2025 — Solved Past Paper with Answers

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Q1. What does "I've told you a million times" means?

  • A. To provide an exact count
  • B. To emphasize frustration or impatience
  • C. To confuse the listener
  • D. To make the character sound foolish

Explanation: The correct answer is option B: To emphasize frustration or impatience. This expression is often used in everyday language to convey that the speaker has repeated themselves numerous times, leading to feelings of annoyance or impatience about having to say the same thing again. Option A is incorrect because the phrase does not literally mean an exact count; it's an exaggeration. Option C is also incorrect as the phrase does not aim to confuse the listener, but rather to express a common frustration. Lastly, option D is incorrect because the intention of the phrase is not to depict foolishness, but rather to communicate the speaker's annoyance.

Why the other options are wrong
  • A. This option suggests that the speaker is providing a precise numerical amount, which is not the intended meaning of the expression.
  • C. This option implies that the intent is to create confusion, which is not the purpose of the expression.
  • D. This option suggests an intention to portray foolishness, which does not align with the meaning of the phrase.

Q2. Traveling in hot, dusty terrain gives me no pleasure. The underlined part of the sentence is:

  • A. Adverb phrase
  • B. Prepositional phrase
  • C. Noun phrase
  • D. Infinitive phrase

Q3. Identify the sentence with no spelling errors.

  • A. Rabia completes homework assignments well in time
  • B. Rabia complete homwork assignments well in time.
  • C. Rabia completes homework asignments well in time.
  • D. Rabia completes homework assigments well in time.

Explanation: The correct answer is the first option: Rabia completes homework assignments well in time as it contains no spelling errors and is grammatically correct. The other options each contain spelling errors: 'homwork' in Option B, 'asignments' in Option C, and 'assigments' in Option D, which makes them incorrect. To identify the correct sentence, it is essential to look for any misspellings.

Why the other options are wrong
  • B. This sentence contains a spelling error: 'homwork' should be 'homework'. Additionally, 'complete' should be 'completes' to match the subject 'Rabia'.
  • C. This sentence contains a spelling error: 'asignments' should be 'assignments'.
  • D. This sentence contains a spelling error: 'assigments' should be 'assignments'.

Q4. The team won the match, ............ they broke the school record.

  • A. Similarly
  • B. Nevertheless
  • C. Furthermore
  • D. Instead

Explanation: The correct answer is 'Furthermore' as it effectively links the two achievements of the team, emphasizing that winning the match is complemented by the breaking of the school record. The other options do not appropriately connect the ideas. 'Similarly' suggests a comparison rather than an addition of information, 'Nevertheless' implies a contradiction, and 'Instead' fails to convey a relationship between the two events.

Why the other options are wrong
  • A. This option suggests a comparison, indicating that both events are alike. However, it does not effectively connect the winning of the match with breaking the school record, as they may not be directly comparable.
  • B. This option implies a contrast between two statements. While it indicates that one event occurred despite the other, it does not fit well in this context since winning the match and breaking the record are not contrasting ideas.
  • D. This option denotes a substitution or an alternative, which does not logically fit the context of the sentence because it implies choosing one action over another rather than presenting two connected achievements.

Q5. People approach the situation differently depending on who they are. The word 'approach' in this sentence means..........

  • A. relate
  • B. coordinate
  • C. comprehend
  • D. verify

Explanation: The correct answer is 'coordinate' because it captures the essence of how individuals manage their responses to various situations. In the context of the sentence, 'approach' implies a method or strategy that people use when dealing with circumstances. The other options, while related to aspects of engagement, do not fully reflect the active and strategic nature of 'approaching' a situation.

Why the other options are wrong
  • A. To 'relate' means to establish a connection or relationship with something. This option does not fit the context of how one interacts with a situation.
  • C. To 'comprehend' means to understand something. While understanding is part of approaching a situation, it does not encompass the broader actions taken in response to it.
  • D. To 'verify' means to confirm the truth or accuracy of something. This option does not align with the concept of how one handles a situation, making it less relevant.

Q6. Pick out the sentence which illustrates the use of infinitive.

  • A. He refused to obey the orders.
  • B. He refused obeying the orders.
  • C. He refused obey the orders.
  • D. He refused obeyed the orders.

Explanation: The correct answer is Option A: 'He refused to obey the orders.' This sentence uses the infinitive form 'to obey' which indicates the action that is being refused. In contrast, Option B uses 'obeying', which is a gerund and does not represent the infinitive form. Option C omits 'to' before 'obey', making it incorrect, and Option D incorrectly uses 'obeyed', which is a past tense form, thus failing to illustrate the infinitive structure.

Why the other options are wrong
  • B. This sentence incorrectly uses 'obeying', which is a gerund, not an infinitive. The correct form should include 'to'.
  • C. This sentence is incorrect because it omits the 'to' before 'obey'. The correct infinitive form is needed.
  • D. This sentence is incorrect as 'obeyed' is in the past tense and does not fit the structure of an infinitive. 'To obey' is the correct form.

Q7. Identify the example of complex sentence.

  • A. I both thanked him and rewarded him.
  • B. Life is what we make it.
  • C. He owed his success to his father.
  • D. Jumping up, he ran away.

Explanation: The correct answer is Option D: Jumping up, he ran away. This sentence is classified as complex because it contains a participial phrase that provides context to the main action. The phrase 'Jumping up' is not a complete thought by itself, making it dependent on the main clause 'he ran away'.In contrast, Option A is a compound sentence with two independent clauses, Option B is a simple sentence, and Option C also presents a single independent clause. None of these options include the necessary dependent clause structure that defines a complex sentence.

Why the other options are wrong
  • A. This is a compound sentence because it has two independent clauses connected by 'and'.
  • B. This is a simple sentence with a subject and a predicate, not a complex one.
  • C. This is also a simple sentence that presents one complete thought, lacking dependent clauses.

Q8. The book was written by Rashid Khan. Identify the correct usage of voice.

  • A. Rashid Khan writes the book.
  • B. Rashid Khan wrote the book.
  • C. Rashid Khan written the book.
  • D. Rashid Khan has write the book.

Explanation: The correct answer is 'Rashid Khan wrote the book.' This sentence correctly uses the simple past tense to indicate that the action of writing has already taken place. The other options are incorrect for the following reasons: 'Rashid Khan writes the book.' uses the present tense, which does not fit the context. 'Rashid Khan written the book.' is incorrect because it lacks an auxiliary verb needed to form the perfect tense. Lastly, 'Rashid Khan has write the book.' is grammatically incorrect as it should use 'has written' instead of 'has write'.

Why the other options are wrong
  • A. This option uses the present tense 'writes', which is incorrect since the question specifies that the book has already been written.
  • C. This option is incorrect because it uses 'written' without a helping verb, making it grammatically incorrect.
  • D. This option is incorrect as it uses 'has write' instead of the correct form 'has written', which is not appropriate for this context.

Q9. What is the effect of using different shades of meaning in satire?

  • A. To create a serious tone
  • B. To highlight the absurdity or irony of a situation
  • C. To confuse the reader
  • D. To add complexity to the language

Explanation: The correct answer is B: 'To highlight the absurdity or irony of a situation.' In satire, different shades of meaning are employed to reveal contradictions and exaggerate situations, which effectively draws attention to the absurdities being critiqued. This use of nuanced language is essential in conveying the satirical message. Options A and C miss the mark by focusing on tone or confusion, which are not the primary goals of satire. Option D, while acknowledging complexity, fails to recognize that the main purpose is to underscore irony and absurdity rather than merely complicate the language.

Why the other options are wrong
  • A. While serious tones can be found in satire, they often serve to contrast the humor. This option does not effectively capture the primary effect of using different shades of meaning.
  • C. While confusion can sometimes be a byproduct of complex language, it is not the intended effect of using different shades of meaning in satire.
  • D. Although adding complexity can occur, it is not the primary effect. The goal of satire is more about conveying irony and absurdity than simply complicating language.

Q10. A mutation prevents proper disulphide bond formation in a fibrous protein, causing brittle nails and slow hair growth. Which of the following proteinaceous substances would be affected?

  • A. Elastin
  • B. Actin
  • C. Keratin
  • D. Collagen

Explanation: The correct answer is Keratin because it is a fibrous protein that plays a critical role in the structure of hair and nails. Disulphide bonds in keratin provide the necessary strength and integrity for these structures. The mutation mentioned in the question disrupts the formation of these bonds, leading to the observed symptoms of brittle nails and slow hair growth. In contrast, Elastin and Actin are proteins that do not primarily rely on disulphide bonds for their function and are involved in different physiological roles, such as elasticity and cellular movement, respectively. Collagen is also a structural protein but is associated with connective tissues rather than directly influencing hair and nail structure. Therefore, it is not the protein most affected in this scenario.

Why the other options are wrong
  • A. Elastin is a protein that provides elasticity to tissues such as skin and blood vessels. It does not primarily rely on disulphide bonds for its structure, making it less relevant to the symptoms described.
  • B. Actin is a globular protein that forms microfilaments in muscle cells and is involved in cell movement. It does not contain significant disulphide bonds and is not responsible for the structural integrity of nails or hair.
  • D. Collagen is a structural protein found in connective tissues, and while it does contain some disulphide bonds, it primarily relies on other types of cross-linking for its strength. It is not directly related to the brittle nails and slow hair growth mentioned in the question.

Q11. In muscle fibers, T-tubules are extension of the sarcolemma that penetrates into the cell's interior. What is their main function during muscle contraction?

  • A. Unblock actin's binding sites
  • B. Conduct nerve impulses deep into the muscle cell
  • C. Synthesize glycogen in the sarcoplasm
  • D. Store calcium ions in the sarcoplasmic reticulum

Explanation: The correct answer is Option B: Conduct nerve impulses deep into the muscle cell. T-tubules (transverse tubules) are specialized extensions of the sarcolemma that penetrate into the muscle fiber, allowing action potentials to travel deep into the cell. This is crucial for initiating muscle contraction as it leads to the release of calcium ions from the sarcoplasmic reticulum, which is essential for the interaction between actin and myosin.Option A is incorrect because T-tubules do not unblock actin's binding sites; they facilitate communication within the muscle cell. Option C is incorrect as T-tubules are not responsible for glycogen synthesis; this function is performed by other cellular components. Option D is also incorrect because while T-tubules are associated with the sarcoplasmic reticulum, they do not store calcium ions; instead, the sarcoplasmic reticulum is responsible for calcium storage and release during muscle contraction.

Why the other options are wrong
  • A. This option suggests that T-tubules are involved in directly facilitating actin's binding sites, which is incorrect. The role of T-tubules is not to interact directly with actin but to assist in the propagation of action potentials within the muscle cell.
  • C. This option incorrectly attributes the synthesis of glycogen to T-tubules. Glycogen synthesis occurs in the sarcoplasm but is not a function of T-tubules.
  • D. This option refers to the role of the sarcoplasmic reticulum, not T-tubules. While T-tubules are involved in signaling for calcium release, they do not store calcium ions themselves.

Q12. Which of the following hormones in the body of animal is lipid-based nature?

  • A. Insulin
  • B. FSH
  • C. Oxytocin
  • D. Aldosterone

Explanation: The correct answer is Aldosterone, as it is a steroid hormone, which means it is derived from lipids and is lipid-soluble. Steroid hormones, including aldosterone, are synthesized from cholesterol and can easily pass through cell membranes to exert their effects. In contrast, the other options listed are peptide hormones, which are made from amino acids and are water-soluble. Insulin is crucial for glucose metabolism, FSH is important for reproductive health, and oxytocin is involved in childbirth and emotional bonding; none of these are lipid-based.

Why the other options are wrong
  • A. Insulin is a peptide hormone that is water-soluble and plays a crucial role in regulating blood glucose levels.
  • B. Follicle-stimulating hormone (FSH) is a glycoprotein hormone involved in reproductive processes, also classified as a peptide hormone.
  • C. Oxytocin is a peptide hormone primarily known for its role in childbirth and lactation, making it water-soluble rather than lipid-based.

Q13. Which of the following base pairing maintains the constant diameter of the DNA double helix as per Watson and Crick's model?

  • A. Purine - Purine
  • B. Pyrimidine - Pyrimidine
  • C. Purine - Pyrimidine
  • D. Sugar-Phosphate

Explanation: In Watson and Crick's model of DNA, the double helix structure is maintained through specific base pairing between purines and pyrimidines. A purine (adenine or guanine) pairs with a pyrimidine (thymine or cytosine), which ensures that the overall diameter of the helix remains constant at approximately 2 nanometers. This is crucial for the stability of the DNA structure. On the other hand, pairing two purines would make the helix too wide, while pairing two pyrimidines would make it too narrow, both of which would disrupt the uniformity of the DNA double helix. The sugar-phosphate backbone is essential for providing structural support but does not affect the diameter determined by base pairing.

Why the other options are wrong
  • A. This option is incorrect because pairing two purines would create a wider structure, not maintaining the constant diameter of the DNA double helix.
  • B. This option is also incorrect as pairing two pyrimidines would lead to a narrower structure, again failing to maintain the constant diameter of the helix.
  • D. This option is incorrect since sugar-phosphate refers to the backbone of the DNA structure, not the base pairing that maintains the diameter of the helix.

Q14. Which muscle type is under conscious control and is multinucleated?

  • A. Smooth muscle
  • B. Skeletal muscle
  • C. Cardiac muscle
  • D. Visceral muscle

Explanation: The correct answer is Skeletal muscle because it is the only type of muscle that is both under conscious control and has multiple nuclei (multinucleated). This allows for the precise control of voluntary movements. In contrast, Smooth muscle is involuntary and non-striated, with a single nucleus, which makes it unsuitable for conscious control. Cardiac muscle, found in the heart, is also involuntary and typically has one or two nuclei, and Visceral muscle refers to smooth muscle in organs, which again is not consciously controlled and has a single nucleus. Thus, only skeletal muscle fits all the criteria stated in the question.

Why the other options are wrong
  • A. Smooth muscle is involuntary and non-striated, meaning it is not under conscious control and has a single nucleus per cell.
  • C. Cardiac muscle is involuntary and striated, primarily found in the heart; it is not under conscious control and typically has one or two nuclei.
  • D. Visceral muscle, often referring to smooth muscle found in internal organs, is also involuntary and not under conscious control, with a single nucleus.

Q15. Which of the following connective tissue is completely avascular and heals slowly?

  • A. Bone
  • B. Cartilage
  • C. Adipose tissue
  • D. Areolar tissue

Explanation: The correct answer is Cartilage, as it is a type of connective tissue that is completely avascular, meaning it does not contain blood vessels. This lack of blood supply significantly slows down its healing process when injured. In contrast, Bone is a highly vascular tissue and heals relatively quickly due to its abundant blood supply. Adipose tissue, or fat, is also well-vascularized, allowing for efficient healing. Similarly, Areolar tissue is a loose connective tissue rich in blood vessels, which supports rapid healing. Therefore, these options do not meet the criteria of being avascular and healing slowly.

Why the other options are wrong
  • A. Bone is a highly vascular tissue that heals relatively quickly due to its rich blood supply, which aids in the repair process.
  • C. Adipose tissue, or fat tissue, is vascularized and has a relatively good blood supply, which supports faster healing compared to avascular tissues.
  • D. Areolar tissue is a loose connective tissue that is well-vascularized, providing it with adequate blood flow for healing and repair.

Q16. Cardiac muscles are different from skeletal muscles because they:

  • A. Lack striations
  • B. Are voluntary and multinucleated
  • C. Are involuntary and multinucleated
  • D. Are striated but involuntary

Explanation: The correct answer is that cardiac muscles are striated but involuntary. This means that while they have a striped appearance due to the arrangement of actin and myosin filaments, they operate without conscious control, unlike skeletal muscles which are under voluntary control.Option A is incorrect because cardiac muscles do have striations. Option B is incorrect as cardiac muscles are involuntary and generally have one nucleus, whereas skeletal muscles are voluntary and multinucleated. Option C is also incorrect; while cardiac muscles are involuntary, they are not multinucleated, as they typically contain one or two nuclei.

Why the other options are wrong
  • A. This option is incorrect because cardiac muscles do have striations, similar to skeletal muscles, due to their organized structure of actin and myosin filaments.
  • B. This option is incorrect because cardiac muscles are involuntary and typically contain a single nucleus per cell (though some may have two), unlike skeletal muscles which are voluntary and multinucleated.
  • C. This option is partially correct in that cardiac muscles are involuntary, but it is incorrect because they are not typically multinucleated; they usually have one or two nuclei.

Q17. Which organelle gives rise to primary lysosomes through budding in eukaryotic cells?

  • A. Smooth endoplasmic reticulum (SER)
  • B. Rough endoplasmic reticulum (RER)
  • C. Plasma membrane
  • D. Golgi cisternae

Explanation: The correct answer is Golgi cisternae. In eukaryotic cells, primary lysosomes are formed from the Golgi apparatus, specifically from its cisternae through a process called budding. The Golgi apparatus modifies and packages enzymes that will become part of the lysosomes. Other options are incorrect for the following reasons: The Smooth endoplasmic reticulum (SER) is mainly involved in lipid synthesis and does not form lysosomes. The Rough endoplasmic reticulum (RER) synthesizes proteins but does not produce lysosomes itself; it prepares proteins to be sent to the Golgi apparatus instead. The Plasma membrane acts as a barrier and does not participate in lysosome formation.

Why the other options are wrong
  • A. The smooth endoplasmic reticulum is primarily involved in lipid synthesis and detoxification processes, but it does not play a direct role in the formation of lysosomes.
  • B. The rough endoplasmic reticulum is involved in the synthesis of proteins destined for secretion or for lysosomes, but it does not directly contribute to the formation of primary lysosomes.
  • C. The plasma membrane serves as the boundary of the cell and is not involved in the production of lysosomes.

Q18. Polysaccharides such as starch and glycogen are mainly used for:

  • A. Structural framework only
  • B. Short-term and long-term energy storage
  • C. Enzyme catalysis
  • D. Ready source of energy

Explanation: Polysaccharides such as starch and glycogen are primarily used for energy storage in living organisms. Starch, found in plants, serves as a long-term energy reserve, while glycogen, stored in animal liver and muscle cells, is readily accessible for short-term energy needs. The other options are incorrect because:Structural framework only: This is not representative of starch and glycogen, which do not provide structural support.Enzyme catalysis: Polysaccharides do not act as enzymes; this role is fulfilled by proteins.Ready source of energy: While glycogen can provide quick energy, it is fundamentally an energy storage molecule, not a direct energy source.Thus, the most accurate description of starch and glycogen is their role in short-term and long-term energy storage.

Why the other options are wrong
  • A. This option is incorrect because while some polysaccharides can serve structural roles (like cellulose in plants), starch and glycogen are primarily involved in energy storage.
  • C. This option is incorrect because polysaccharides do not function as enzymes. Enzymes are typically proteins that catalyze biochemical reactions, whereas polysaccharides are primarily energy storage molecules.
  • D. This option is misleading. While polysaccharides like glycogen can be broken down into glucose for immediate energy, they are primarily designed for storage rather than being a 'ready' source of energy.

Q19. In chromosome, positively charged histone proteins are organized with negatively charged DNA. The positive charges of histone are due to an abundance of basic amino acids:

  • A. Arginine and alanine
  • B. Arginine and lysine
  • C. Lysine and alanine
  • D. Phenylalanine and arginine

Explanation: The correct answer is Option B: Arginine and lysine. Both of these amino acids are classified as basic and carry positive charges. This property allows them to interact with the negatively charged DNA, facilitating the compaction of DNA into chromatin. In contrast, the other options contain at least one amino acid that is neutral (alanine or phenylalanine), which does not contribute to the positive charge necessary for binding to DNA. Therefore, options A, C, and D are incorrect.

Why the other options are wrong
  • A. Arginine is a basic amino acid, but alanine is neutral and does not contribute to the positive charge.
  • C. Lysine is a basic amino acid, but alanine is neutral, which means this option is incorrect.
  • D. While arginine is a basic amino acid, phenylalanine is neutral and does not add to the positive charge, making this option incorrect.

Q20. The envelop in a virus is derived from

  • A. Host cell-ribosomes
  • B. Host cell membrane
  • C. Viral capsid proteins
  • D. Viral genome replication

Explanation: The correct answer is Host cell membrane because the envelope of a virus is formed from the lipid bilayer of the host cell's membrane during the budding process. When a virus exits the host cell, it can take a portion of the host's membrane with it, which then becomes the viral envelope. This envelope may contain viral proteins embedded in it, which are crucial for the virus's ability to infect other cells.On the other hand, Host cell-ribosomes are involved in protein synthesis and do not play a role in forming the viral envelope. Viral capsid proteins are responsible for creating the protective shell around the viral genome but do not contribute to the envelope. Lastly, Viral genome replication is a process that occurs inside the host cell to produce new viral genomes, but it does not relate to the structure of the envelope itself.

Why the other options are wrong
  • A. This option is incorrect because ribosomes are cellular structures involved in protein synthesis, but they do not contribute to the formation of the viral envelope.
  • C. This option is incorrect because viral capsid proteins form the protective protein shell around the virus, but they do not form the envelope.
  • D. This option is incorrect. While viral genome replication is essential for producing new viral particles, it does not involve the formation of the viral envelope.

Q21. Myelin sheath acts as:

  • A. Protector
  • B. Insulator
  • C. Sensor
  • D. Supporter

Explanation: The correct answer is Insulator because the myelin sheath surrounds nerve fibers and acts as an insulating layer, which enhances the speed of electrical signal transmission along the axon. This insulation is crucial for the efficient functioning of the nervous system. Option Protector is incorrect because, although the myelin sheath offers some protection to the nerve fibers, its primary function is not protective. Sensor is incorrect since the myelin sheath does not play a role in sensory functions. Lastly, while Supporter may describe a minor aspect of its function, it does not capture the primary role of the myelin sheath, which is to insulate nerve fibers.

Why the other options are wrong
  • A. While the myelin sheath provides some level of protection to the nerve fibers, its main role is not as a protector but rather to facilitate nerve signal transmission.
  • C. The myelin sheath does not have sensory functions; instead, it primarily serves to insulate nerve fibers and speed up signal transmission.
  • D. While the myelin sheath provides structural support to the axon, its critical role is in insulating the nerve fibers for efficient signal conduction.

Q22. DNA/RNA probes are most commonly used as:

  • A. diagnostic tools of infectious diseases
  • B. carrier in gene cloning experiments
  • C. cementing material in somatic cell hybridization
  • D. carrier or vector in gene therapy

Explanation: DNA/RNA probes are primarily used as diagnostic tools of infectious diseases because they can specifically bind to complementary nucleic acid sequences, allowing for the identification of pathogens in clinical samples. This application is crucial for rapid and accurate diagnosis of infections. In contrast, the other options are incorrect because they misrepresent the role of DNA/RNA probes. They do not function as carriers in gene cloning or gene therapy, nor do they act as cementing materials in somatic cell hybridization. Instead, their main strength lies in detection and diagnostic applications.

Why the other options are wrong
  • B. While DNA probes can be used in gene cloning, they primarily serve as markers or identifiers rather than carriers. The carrier in cloning is usually a plasmid or vector.
  • C. Cementing materials in somatic cell hybridization refer to substances that facilitate the fusion of cells, not probes. DNA/RNA probes do not serve this function.
  • D. In gene therapy, vectors such as viruses are used to deliver therapeutic genes, whereas DNA/RNA probes are not used as carriers but rather as tools for detection and research.

Q23. The event that occurs first during skeletal muscle contraction?

  • A. Cross-bridge formation
  • B. Release of calcium from sarcoplasmic reticulum
  • C. Power stroke
  • D. Myosin head binds to ATP

Explanation: The correct answer is the release of calcium from the sarcoplasmic reticulum, which is the first event that triggers skeletal muscle contraction. When a muscle fiber is stimulated, calcium ions are released from the sarcoplasmic reticulum into the cytoplasm. This calcium binds to troponin, causing a conformational change that exposes the binding sites on actin, allowing for cross-bridge formation with myosin.The other options are incorrect because:Cross-bridge formation occurs after calcium is released, as myosin heads can only bind to actin when calcium is present.Power stroke is the action that occurs after the cross-bridge formation, pulling actin filaments during contraction.Myosin head binds to ATP happens after the power stroke to detach the myosin head from actin, and is not part of the initial contraction sequence.

Why the other options are wrong
  • A. This step occurs after calcium is released. The myosin heads attach to actin filaments, but cannot occur until calcium binds to troponin.
  • C. The power stroke happens after the cross-bridge formation. It is the movement that pulls the actin filaments inward, but it can only occur after calcium has been released.
  • D. This process occurs after the power stroke when the myosin head detaches from the actin filament. It does not initiate contraction.

Q24. What genes are linked, they tend to:

  • A. Segregate randomly
  • B. Cross over every time
  • C. Stay together during inheritance
  • D. Be inherited separately

Explanation: The correct answer is that linked genes tend to stay together during inheritance. This phenomenon occurs because genes that are located close to each other on the same chromosome are less likely to be separated during meiosis, the process of cell division that produces gametes. In contrast, the other options are incorrect:Segregate randomly: This option incorrectly describes the behavior of linked genes as if they segregate independently, which is not the case.Cross over every time: This suggests that linked genes undergo recombination in every meiosis, which is not accurate; crossover events are random and do not occur every time.Be inherited separately: This is incorrect as well; linked genes are inherited together more frequently than those that are not linked.Understanding genetic linkage is crucial in genetics as it helps explain inheritance patterns and the likelihood of certain traits being passed together.

Why the other options are wrong
  • A. This option suggests that linked genes segregate independently, which is incorrect. Linked genes are inherited together more often than not.
  • B. This option implies that linked genes always cross over during meiosis, which is not true. They may cross over, but not necessarily every time.
  • D. This option indicates that linked genes are inherited independently, which contradicts the concept of genetic linkage.

Q25. According to Mendel's experiment, which of the following is essential for detecting gene linkage accurately?

  • A. Large number of progeny
  • B. Small sample size
  • C. Use of male flies only
  • D. Mutation induction

Explanation: The correct answer is Large number of progeny because Mendel's experiments demonstrated that a larger sample size allows for a more accurate analysis of inheritance patterns, thereby providing clearer evidence of gene linkage. In contrast, a small sample size may lead to statistical inaccuracies and unreliable conclusions. The option regarding use of male flies only is incorrect as it restricts the genetic diversity necessary for comprehensive analysis. Lastly, mutation induction does not relate to the detection of gene linkage; it is a different process that can alter gene function but does not assist in identifying linkage relationships.

Why the other options are wrong
  • B. A small sample size is detrimental when detecting gene linkage as it can lead to misleading results due to insufficient data to establish reliable patterns of inheritance.
  • C. While using male flies may simplify certain genetic crosses, it does not inherently aid in the accurate detection of gene linkage. Both sexes contribute to the genetic makeup of progeny and should be included for comprehensive analysis.
  • D. Inducing mutations is not necessary for detecting gene linkage. Gene linkage is primarily assessed through inheritance patterns, not by introducing mutations.

Q26. The end of skeletal muscle attached with moveable bone is:

  • A. Insertion
  • B. Origin
  • C. Tendons
  • D. Belly

Explanation: The correct answer is insertion, which is the point where a skeletal muscle attaches to a moveable bone, facilitating movement when the muscle contracts. In contrast, the origin is the point of attachment to a stationary bone and does not move during contraction. Tendons serve as the connectors between muscles and bones but do not directly refer to the attachment point itself. Lastly, the belly of the muscle is the thick, central part that contracts, not the specific attachment area.

Why the other options are wrong
  • B. The origin is the fixed attachment point of a muscle, typically on a stationary bone. It does not move when the muscle contracts.
  • C. Tendons are the connective tissues that attach muscles to bones. While they play a crucial role in muscle function, they are not the specific attachment points referred to in the question.
  • D. The belly refers to the central, fleshy part of the muscle that contracts. It is not the point of attachment to a bone.

Q27. Which of the following is common between aldosterone, sex hormones and cortisol?

  • A. They are peptides
  • B. They are Panapholipids
  • C. They are steroids
  • D. They are glycoproteins

Explanation: Aldosterone, sex hormones, and cortisol are classified as steroid hormones because they are all derived from cholesterol, which gives them a specific chemical structure characterized by a four-ring carbon framework. This structural similarity is crucial for their function and interaction with steroid hormone receptors in target cells. In contrast, the incorrect options point to different classes of biomolecules. Peptides are chains of amino acids and do not share the cholesterol-derived structure. Panapholipids is not a recognized term in biochemistry, thus making it incorrect. Glycoproteins contain carbohydrate moieties and are not the same as steroid hormones. Therefore, the only accurate classification among the options provided is that these hormones are steroids.

Why the other options are wrong
  • A. This option is incorrect because aldosterone, sex hormones, and cortisol are not peptides; they belong to a different chemical class.
  • B. This option is incorrect as 'panapholipids' is not a recognized classification of hormones or biological molecules.
  • D. This option is incorrect because glycoproteins are a different class of molecules that typically involve protein and carbohydrate components, not present in the structure of the mentioned hormones.

Q28. Which one of the following organism is uricotelic with reference to secretion of nitrogenous compound?

  • A. Human
  • B. Freshwater Fish
  • C. Snake
  • D. Frog

Explanation: The correct answer is Snake because snakes are classified as uricotelic organisms. They primarily excrete nitrogenous waste in the form of uric acid, which is a more water-efficient method of excretion, suitable for their often arid habitats. In contrast, Humans excrete urea, making them ureotelic. Freshwater Fish excrete ammonia, which is why they are classified as ammonotelic. Lastly, Frogs also excrete urea during their adult life stage, thus categorizing them as ureotelic as well.

Why the other options are wrong
  • A. Humans are primarily urea producers (ureotelic), excreting nitrogenous waste in the form of urea, not uric acid.
  • B. Freshwater fish typically excrete ammonia directly into the water, making them ammonotelic rather than uricotelic.
  • D. Frogs are generally ureotelic, excreting waste mainly in the form of urea, especially during their adult life stage.

Q29. Ureotelism (removal of nitrogenous waste in the form of urea) is an adaptation to the:

  • A. cold weather
  • B. less availability of water
  • C. flooded environmental conditions
  • D. food shortage

Explanation: Ureotelism is a physiological adaptation found in many terrestrial animals that allows them to excrete nitrogenous waste in the form of urea instead of ammonia. This process is particularly advantageous in environments where water is limited, as urea is less toxic and requires less water for its excretion compared to ammonia. Thus, organisms that practice ureotelism can thrive in dry habitats by conserving water. The other options do not accurately reflect the primary environmental conditions that would drive the evolution of ureotelism: cold weather, flooded conditions, and food shortages do not specifically necessitate this form of waste removal.

Why the other options are wrong
  • A. This option is incorrect because ureotelism is not specifically an adaptation to cold weather. In colder climates, many organisms may rely on different strategies for waste removal that are more suited to their environmental conditions.
  • C. This option is incorrect as flooded conditions typically favor organisms that can excrete ammonia directly into the water, as it is highly soluble and can be quickly diluted.
  • D. This option is incorrect because food shortage does not directly correlate with the method of nitrogenous waste removal. Ureotelism is more related to water conservation than to the availability of food.

Q30. All of the following are the characteristics of limbic system EXCEPT:

  • A. Produce most basic and primitive emotions and drives
  • B. Formation of memories
  • C. Consists of hypothalamus, amygdala, and hippocampus
  • D. Controls reflex movement of eyes

Explanation: The limbic system is primarily involved in emotional responses and memory processes. It includes structures such as the hypothalamus, amygdala, and hippocampus, which are vital for generating emotions and forming memories. The first three options correctly describe characteristics of the limbic system, while the last option about controlling reflex movements of the eyes pertains to different brain functions, particularly those managed by the brainstem, thus making it the only statement that does not belong to the characteristics of the limbic system.

Why the other options are wrong
  • A. This option describes a primary function of the limbic system, which is to generate emotions such as fear, pleasure, and anger, making it a characteristic of the limbic system.
  • B. This option highlights another essential role of the limbic system, particularly the hippocampus, which is crucial for memory formation.
  • C. This statement accurately describes the components of the limbic system, indicating its structural characteristics.

Q31. Sensory input from auditory and visual pathways, skin and within the body is received by _ and distributed to _

  • A. Hypothalamus; Cerebellum
  • B. Thalamus; cerebrum
  • C. Cerebrum; rest of the brain
  • D. Cerebellum; rest of the brain

Explanation: The correct answer is Thalamus; cerebrum. The thalamus serves as a crucial relay station that receives sensory input from various pathways, including auditory and visual pathways, as well as somatosensory signals from the skin and within the body. It then processes and directs this information to the appropriate areas of the cerebrum, where further interpretation and response occur.The other options are incorrect because:Hypothalamus; Cerebellum: The hypothalamus is not primarily involved in sensory processing, and the cerebellum is mostly responsible for motor control.Cerebrum; rest of the brain: While the cerebrum processes sensory information, it does not receive the initial sensory input directly.Cerebellum; rest of the brain: The cerebellum does not play a role in receiving sensory information; it mainly coordinates voluntary movements.

Why the other options are wrong
  • A. The hypothalamus primarily regulates autonomic functions and homeostasis, while the cerebellum is involved in motor control. Neither of these structures is the primary relay center for sensory information.
  • C. The cerebrum processes sensory information but does not receive sensory input directly; it is the thalamus that first receives this input and then sends it to the cerebrum.
  • D. The cerebellum is primarily involved in coordination and balance, not in receiving or distributing sensory information from pathways, thus making this option incorrect.

Q32. According to the Lamarck theory of evolution, the organ that has not been used in several generations will:

  • A. Become strong
  • B. Get amputated
  • C. Disappear
  • D. Become developed

Explanation: According to Lamarck's theory of evolution, organisms can acquire traits during their lifetime based on their use or disuse of certain organs. If an organ is not used over several generations, it may eventually disappear as it is not necessary for survival. This reflects the idea that traits not beneficial to an organism's survival may diminish over time. The other options are incorrect because: Become strong: This suggests an enhancement of the organ, which contradicts the theory.Get amputated: This implies a physical removal, which is not applicable in the context of evolutionary theory.Become developed: This is the opposite of what happens when an organ is not used; it does not evolve positively.

Why the other options are wrong
  • A. This option suggests that the organ will develop strength, which contradicts the core idea of disuse leading to degradation.
  • B. This option implies a physical removal of the organ, which is not a concept associated with Lamarck's theory of evolution.
  • D. This option suggests that disuse leads to enhancement, which is opposite to the principle that disuse leads to degeneration.

Q33. Which of the following statement is incorrect with reference to the enzyme action?

  • A. Substrate binds with the enzyme at its active site
  • B. Non-competitive inhibitor binds the enzyme at a site distinct from that of active site
  • C. Addition of a lot of succinate do not reverse the inhibition of succinic dehydrogenase by malonate
  • D. Malonate is a competitive inhibitor of succinic dehydrogenase

Explanation: The correct answer is Option C, which states that 'Addition of a lot of succinate do not reverse the inhibition of succinic dehydrogenase by malonate.' This is incorrect because malonate is a competitive inhibitor, and increasing the concentration of succinate can indeed reverse the inhibition by outcompeting malonate for the active site on the enzyme.Option A is correct as it describes the normal substrate-enzyme interaction. Option B is also correct since non-competitive inhibitors bind elsewhere on the enzyme. Option D is correct because malonate is a known competitive inhibitor of succinic dehydrogenase, and thus the statement accurately describes its mechanism of action.

Why the other options are wrong
  • A. This statement is correct as substrates interact with enzymes at their active sites to form the enzyme-substrate complex.
  • B. This statement is correct. Non-competitive inhibitors bind to an enzyme at a location other than the active site, affecting the enzyme's function regardless of substrate concentration.
  • D. This statement is correct. Malonate competes with succinate for the active site of succinic dehydrogenase, inhibiting its activity when present.

Q34. The temperature of underground water remains constant due to:

  • A. Heat capacity
  • B. Polarity of water
  • C. Heat of vaporization
  • D. Specific heat of vaporization

Explanation: The correct answer is Heat capacity. Underground water maintains a relatively constant temperature due to its high heat capacity, which means it can absorb a lot of heat without a significant rise in temperature. This property allows underground water to remain stable in temperature despite changes in environmental conditions. In contrast, the polarity of water does not directly influence temperature stability but rather affects water's behavior and interactions at the molecular level. The terms heat of vaporization and specific heat of vaporization are not relevant to the temperature stability of underground water, as they relate to phase changes and the energy needed for those changes, rather than to temperature regulation.

Why the other options are wrong
  • B. The polarity of water refers to its molecular structure that allows it to form hydrogen bonds. While this property affects many characteristics of water, it does not directly explain why the temperature of underground water remains constant.
  • C. Heat of vaporization is the amount of energy needed to convert water from liquid to vapor. This property is important for understanding evaporation but does not pertain to the temperature stability of underground water.
  • D. This term is a misnomer as specific heat refers to the heat required to raise the temperature of a substance, while vaporization relates to phase change. Thus, this option does not accurately relate to the consistency of underground water temperature.

Q35. The shape of adenovirus is:

  • A. Helical shape
  • B. Tadpole shape
  • C. Polyhedron shape
  • D. Circular shape

Explanation: Adenoviruses are characterized by their polyhedral shape, specifically resembling an icosahedron with a symmetrical arrangement of protein subunits. This structure is efficient in packaging their genetic material and is common among many virus families. The other options are incorrect because:The helical shape is typically associated with viruses like influenza and other enveloped viruses, which do not conform to the adenovirus structure.The tadpole shape is not a recognized form for any viruses, including adenoviruses, which have a more rigid geometric structure.The circular shape does not accurately represent the form of adenoviruses, which are more complex than a simple round outline.In summary, the polyhedral shape is key to understanding the morphology of adenoviruses.

Why the other options are wrong
  • A. This option refers to a shape characterized by a spiral configuration, which is not representative of adenovirus.
  • B. This option suggests a shape resembling a tadpole, but adenoviruses do not exhibit this morphology.
  • D. This option implies a round shape, which is not accurate for adenoviruses, as they have a more complex geometric form.

Q36. In human female normally ovulation occurs at _ day _ of menstrual cycle.

  • A. 9
  • B. 11
  • C. 14
  • D. 15

Explanation: In a standard 28-day menstrual cycle, ovulation typically occurs around day 14. This is the point in the cycle when an egg is released from the ovary, making it available for fertilization. Options A (day 9) and B (day 11) are too early for ovulation, as the follicular phase usually lasts until around day 14. Option D (day 15) is possible for some individuals but is more often considered to be post-ovulation. Therefore, option C (day 14) is the most accurate answer for when ovulation typically occurs.

Why the other options are wrong
  • A. Day 9 is too early in the menstrual cycle for ovulation to occur. Ovulation generally takes place around the midpoint of the cycle, which is usually around day 14.
  • B. Day 11 is still prior to the typical timing of ovulation. The ovulation phase generally occurs closer to day 14 in a standard cycle.
  • D. Day 15 is slightly later than the average ovulation day. While ovulation may still occur around this time for some individuals, day 14 is more commonly accepted as the typical ovulation day.

Q37. HIV belongs to which class of virus with respect to genome type?

  • A. Single stranded DNA viruses
  • B. Double stranded RNA viruses
  • C. ssRNA; template for DNA synthesis
  • D. ssRNA; template for mRNA synthesis

Explanation: HIV (Human Immunodeficiency Virus) is classified as a retrovirus, which means it contains single-stranded RNA (ssRNA) as its genome. Upon entering a host cell, HIV utilizes the enzyme reverse transcriptase to convert its RNA into DNA, which then integrates into the host's genome. This process is crucial for the replication of the virus within the host. Therefore, the correct answer is that HIV belongs to the class of viruses characterized by ssRNA; template for DNA synthesis.Options A and B are incorrect as they describe viruses with DNA or double-stranded RNA genomes, which do not apply to HIV. Option D incorrectly describes the function of ssRNA, as it suggests that the RNA directly synthesizes mRNA without acknowledging the critical step of reverse transcription that occurs in HIV.

Why the other options are wrong
  • A. Single stranded DNA viruses contain DNA as their genetic material. Examples include some bacteriophages, but HIV does not fall into this category.
  • B. Double stranded RNA viruses have RNA as their genetic material in a double-stranded form. Examples include Rotavirus, but this does not apply to HIV.
  • D. This option incorrectly suggests that ssRNA serves as a direct template for mRNA synthesis. While HIV does synthesize mRNA from its RNA, the correct classification focuses on its ability to convert RNA into DNA.

Q38. How many ATPs are produced during oxidative phase of glycolysis?

  • A. A. 2
  • B. B. 4
  • C. C. 34
  • D. D. 36

Explanation: The correct answer is A. 2 ATPs are produced during the oxidative phase of glycolysis. This phase involves the conversion of glucose to pyruvate, where energy is released, resulting in the generation of ATP through substrate-level phosphorylation. Options B (4 ATPs), C (34 ATPs), and D (36 ATPs) are incorrect because they overestimate the ATP yield associated with glycolysis alone. Remember, while glycolysis is a crucial step in cellular respiration, the totals for ATP production are higher in later stages, like the Krebs cycle and oxidative phosphorylation.

Why the other options are wrong
  • B. This option is incorrect. While a higher number of ATPs can be produced in cellular respiration, the oxidative phase of glycolysis specifically yields only 2 ATPs.
  • C. This option is incorrect. 34 ATPs are not produced during glycolysis; this number is more representative of the total ATP yield from complete aerobic respiration, including the electron transport chain.
  • D. This option is incorrect. While 36 ATPs may refer to the total yield from the complete oxidation of glucose, glycolysis itself only produces 2 ATPs during its oxidative phase.

Q39. Which of the following best describes the relationship between endoplasmic reticulum (ER) and Golgi apparatus?

  • A. Both ER and Golgi apparatus are completely separate organelles with no interaction
  • B. ER is precursor organelle to Golgi apparatus because material is transported from ER to Golgi
  • C. Golgi apparatus is precursor organelle to ER because material is transported from Golgi to ER
  • D. ER and Golgi apparatus have similar roles

Explanation: The correct answer is Option B: The endoplasmic reticulum (ER) serves as a precursor to the Golgi apparatus because it is responsible for synthesizing proteins and lipids that are then transported to the Golgi apparatus. The Golgi apparatus further modifies these materials before they are distributed to their final destinations. Options A and D are incorrect as they misrepresent the relationship and functional roles of these organelles. Option C is also incorrect because it reverses the flow of material; the Golgi does not act as a precursor to the ER, but rather the ER feeds into the Golgi for processing.

Why the other options are wrong
  • A. This option is incorrect because the ER and Golgi apparatus are interconnected in the cell's transport system, specifically in the process of protein and lipid modification and transport.
  • C. This option is incorrect because the Golgi apparatus processes and packages materials that originate from the ER, not the other way around.
  • D. This option is misleading as the ER and Golgi apparatus have distinct functions; the ER is primarily involved in the synthesis of proteins and lipids, while the Golgi apparatus modifies, sorts, and packages these materials.

Q40. Osmotic gradient of inner medulla of kidney is increased by:

  • A. Urea
  • B. Water
  • C. Phosphate
  • D. Potassium

Explanation: The correct answer is Urea because it plays a crucial role in establishing the osmotic gradient in the inner medulla of the kidney. The inner medulla's high osmolarity is essential for the concentration of urine, facilitating water reabsorption in the collecting ducts. Urea contributes to this gradient through a process called countercurrent multiplication, where it diffuses in and out of the collecting ducts, enhancing osmolarity. In contrast, Water is a product of the osmotic gradient rather than a contributor to it; it is reabsorbed following the osmotic gradient rather than creating it. Phosphate and Potassium do not significantly impact the osmotic gradient within the inner medulla and are involved in different physiological functions.

Why the other options are wrong
  • B. While water is essential for kidney function and is reabsorbed in the nephron, it does not directly increase the osmotic gradient. The gradient is primarily established by solutes like urea.
  • C. Phosphate is not a significant contributor to the osmotic gradient in the kidney's inner medulla. It plays other roles in bodily functions but does not enhance osmolarity in this context.
  • D. Potassium is involved in various physiological processes, but it does not significantly contribute to the osmotic gradient in the inner medulla of the kidney.

Q41. Decreased level of FSH hormone during menstrual cycle triggers release of:

  • A. hcg
  • B. LH
  • C. Oxytocin
  • D. Progesterone

Explanation: During the menstrual cycle, a decrease in Follicle Stimulating Hormone (FSH) signals the body to release Luteinizing Hormone (LH), which is critical for ovulation. FSH is responsible for stimulating the growth of ovarian follicles, and when its levels drop, this decrease is a signal for the surge of LH, which ultimately leads to the release of an egg from the ovary. The other options are not directly related to the triggering of LH release: hCG is related to pregnancy, oxytocin is involved in childbirth and breastfeeding, and progesterone is produced post-ovulation and does not trigger LH release.

Why the other options are wrong
  • A. Human Chorionic Gonadotropin (hCG) is primarily involved in early pregnancy and is not directly related to the menstrual cycle's regulation of FSH.
  • C. Oxytocin is mainly involved in labor and lactation and does not have a direct role in the menstrual cycle's hormonal regulation.
  • D. Progesterone is produced after ovulation and is regulated by LH; it does not trigger the release of hormones in response to decreased FSH levels.

Q42. The digestive secretions from different parts of GIT have the ability to kill microbe present in the food. Which of the following best describe this role?

  • A. Antiseptics
  • B. Disinfectants
  • C. Chemotherapeutics
  • D. Immunosuppressant

Explanation: The correct answer is Antiseptics because digestive secretions, such as gastric acid, have the ability to kill harmful microbes present in food, effectively acting as a natural antiseptic. The other options are incorrect as they either refer to external agents (disinfectants), therapeutic drugs (chemotherapeutics), or medications that suppress the immune response (immunosuppressants), none of which directly describe the role of digestive secretions in the gastrointestinal tract.

Why the other options are wrong
  • B. Disinfectants are chemicals used to kill germs on surfaces. While they also kill microbes, they are not naturally occurring in the body like digestive secretions are.
  • C. Chemotherapeutics are drugs used to treat diseases, particularly cancer, and do not refer to the natural processes of the digestive system.
  • D. Immunosuppressants are medications that decrease the body's immune response. They do not play a direct role in killing microbes in food but rather inhibit the immune system's ability to respond to pathogens.

Q43. A carrier female for hemophilia can pass the defective allele to:

  • A. Only sons
  • B. Only daughters
  • C. Both sons and daughters
  • D. Neither sons nor daughters

Explanation: Carrier female (XHXh) can pass Xh to sons (XhY = hemophiliac) or daughters (XHXH = carrier). Thus, both can inherit the allele.

Why the other options are wrong
  • A. This option is incorrect. A carrier mother possesses one normal X chromosome and one mutated X chromosome for hemophilia, allowing her to potentially pass the mutated allele to both sons and daughters.
  • B. This option is incorrect. While daughters can inherit the carrier mother's mutated X chromosome, sons can also inherit it, making this option an incomplete representation of the possible offspring.
  • D. This option is incorrect. The carrier mother can pass on either her normal or mutated X chromosome, meaning that at least some of her offspring can inherit hemophilia.

Q44. During ventricular systole, which pressure changes occur?

  • A. Ventricular pressure rises above atrial and arterial pressure
  • B. Atrial pressure rises above Ventricular pressure
  • C. Ventricular pressure falls below arterial pressures
  • D. Ventricular pressure falls below Atrial pressure

Explanation: During ventricular systole, the ventricles contract, leading to a significant increase in their internal pressure. This rise in ventricular pressure is crucial as it must exceed both atrial and arterial pressures to effectively eject blood. Therefore, Option A is correct.Option B is incorrect because the pressure in the atria does not rise above that in the ventricles during systole. Option C is misleading; the ventricular pressure must be higher than arterial pressure for blood to be pushed into the arteries. Lastly, Option D is wrong as well; during systole, ventricular pressure is always higher than atrial pressure to facilitate the proper flow of blood.

Why the other options are wrong
  • B. This statement is incorrect because during ventricular systole, the pressure in the ventricles is higher than in the atria due to the contraction of the ventricles.
  • C. This option is incorrect. During ventricular systole, the pressure in the ventricles actually rises above arterial pressure to facilitate blood ejection.
  • D. This statement is also incorrect. The pressure in the ventricles must be greater than that in the atria during systole to prevent backflow and to push blood into the arteries.

Q45. Which cell type is essential for stimulating cell division of both B-cells and T-cells?

  • A. Plasma cells
  • B. Memory cells
  • C. Helper T-cells
  • D. Neutrophils

Explanation: Helper T-cells are critical components of the adaptive immune system, as they release cytokines that promote the activation and proliferation of both B-cells and T-cells. This stimulation is essential for an effective immune response to pathogens. In contrast, plasma cells are specialized B-cells that produce antibodies but do not stimulate other cells. Memory cells serve to remember past infections but also do not have a role in stimulating cell division. Neutrophils, while important for the initial immune response, primarily act by engulfing pathogens and do not stimulate the division of lymphocytes.

Why the other options are wrong
  • A. Plasma cells are derived from B-cells and are primarily responsible for producing antibodies. They do not play a direct role in stimulating the division of B-cells or T-cells.
  • B. Memory cells are long-lived cells that provide lasting immunity by remembering past infections. However, they do not stimulate the division of other immune cells.
  • D. Neutrophils are a type of white blood cell that primarily responds to infections by engulfing pathogens. They do not stimulate the division of B-cells or T-cells.

Q46. Fibrocartilage is found in:

  • A. Trachea
  • B. Nose
  • C. Knee joint
  • D. Ear flaps

Explanation: Fibrocartilage is a tough and fibrous type of cartilage that provides support and absorbs shock, particularly in weight-bearing joints. It is found in specific areas such as the knee joint, where it forms the menisci, which act as cushions and stabilize the joint. The other options are incorrect because:Trachea: Primarily composed of hyaline cartilage, not fibrocartilage.Nose: Supported by hyaline cartilage, which is different from fibrocartilage.Ear flaps: Made up of elastic cartilage, which provides flexibility rather than the support and shock absorption characteristic of fibrocartilage.Thus, the knee joint is the correct answer as it is the only structure listed that contains fibrocartilage.

Why the other options are wrong
  • A. The trachea is primarily composed of hyaline cartilage, which provides support and flexibility to the airway, not fibrocartilage.
  • B. The nose is supported by hyaline cartilage as well, which allows for structure and shape, while fibrocartilage is not typically found in this region.
  • D. The ear flaps (auricles) are made of elastic cartilage, which allows for flexibility and shape retention, not fibrocartilage.

Q47. Additional capillaries present in the juxtamedullary nephrons to form a loop of vessels are:

  • A. Efferent arterioles
  • B. Peritubular capillaries
  • C. Vasa recta
  • D. Afferent arterioles

Explanation: The correct answer is Vasa recta. These specialized capillaries are crucial for the function of juxtamedullary nephrons, as they descend into the renal medulla and form a loop, allowing for the countercurrent exchange necessary for urine concentration.In contrast, efferent arterioles and afferent arterioles are involved in the blood supply to and from the glomerulus, but they do not form loops. Peritubular capillaries are associated with cortical nephrons and do not participate in the specific looping structure of juxtamedullary nephrons.

Why the other options are wrong
  • A. Efferent arterioles carry blood away from the glomerulus but do not form loops of vessels in juxtamedullary nephrons.
  • B. Peritubular capillaries surround the renal tubules and are involved in reabsorption, but they are not specifically associated with juxtamedullary nephrons forming loops.
  • D. Afferent arterioles supply blood to the glomeruli but do not create loops of vessels in juxtamedullary nephrons.

Q48. Y-linked inheritance refers to which mode of the inheritance?

  • A. Crisscross
  • B. Straight
  • C. Loop
  • D. Jumping

Explanation: Y-linked inheritance is characterized by the transmission of genes located on the Y chromosome, exclusively affecting male offspring. This mode of inheritance is termed 'straight' because it goes directly from father to son without involving females in the transmission of Y-linked traits. The other options are incorrect: 'crisscross' describes X-linked inheritance, where traits can skip generations and affect both genders; 'loop' and 'jumping' do not correspond to any established genetic inheritance patterns.

Why the other options are wrong
  • A. This option refers to a pattern of inheritance where traits are passed from father to daughter and then from daughter to son, which is not characteristic of Y-linked inheritance.
  • C. This term does not apply to any known genetic inheritance patterns and is therefore irrelevant to the concept of Y-linked inheritance.
  • D. This option does not describe a recognized mode of inheritance and does not relate to Y-linked traits, making it an incorrect choice.

Q49. If a colorblind lady marries a normal man, their children will be:

  • A. Normal daughters and normal sons
  • B. Normal sons and carrier daughters
  • C. Colorblind sons and carrier daughters
  • D. Colorblind sons and colorblind daughters

Explanation: Color blindness is a sex-linked trait carried on the X chromosome. A colorblind woman has two X chromosomes, both of which carry the allele for color blindness (XcXc). In contrast, a normal man has one normal X chromosome (XN) and one Y chromosome (Y). Their daughters will inherit one X chromosome from their mother (Xc) and one from their father (XN), making them carriers (XcXN). Their sons will inherit the Y chromosome from their father and the X chromosome from their mother, which could carry the colorblind allele (Xc), resulting in colorblind sons (XcY). Thus, the correct answer is that they will have colorblind sons and carrier daughters. The other options are incorrect due to misunderstanding the inheritance pattern of the trait.

Why the other options are wrong
  • A. This option is incorrect because it does not account for the genetic contribution of the colorblind mother, who carries the colorblind allele.
  • B. This option is partially correct, as it suggests that daughters could be carriers. However, it overlooks the possibility of having colorblind sons.
  • D. This option is incorrect because colorblind daughters would require both X chromosomes to carry the colorblind allele, which is not possible if their father has a normal vision.

Q50. All of the following properties of water are associated with its capillary action. EXCEPT:

  • A. Adhesion
  • B. Density
  • C. Cohesion
  • D. Surface tension

Explanation: The correct answer is Density because it is not a property that directly influences capillary action. Capillary action relies on the interactions of water molecules with each other (cohesion) and with other surfaces (adhesion), as well as the surface tension that arises from these interactions. Adhesion allows water to climb up against gravity in narrow spaces, cohesion keeps the water molecules together, and surface tension helps maintain the shape of the water column. In contrast, density does not play a role in these processes.

Why the other options are wrong
  • A. Adhesion refers to the attraction between water molecules and other surfaces, which is crucial for capillary action as it allows water to climb up narrow spaces.
  • C. Cohesion is the attraction between like molecules, such as water molecules. This property helps water stick to itself, playing a significant role in capillary action.
  • D. Surface tension is the cohesive force at the surface of a liquid, which allows it to resist external force. It is a key property that contributes to capillary action.

Q51. Which organelle serves as a packaging and a distribution center for molecules within the cells?

  • A. Golgi apparatus
  • B. Mitochondria
  • C. Ribosome
  • D. Vacuole

Explanation: The Golgi apparatus is the correct answer because it plays a crucial role in the post-translational modification of proteins and lipids, as well as their sorting and packaging for transport. It receives products from the endoplasmic reticulum and modifies them before sending them to their final destinations. In contrast, mitochondria are mainly involved in energy production; ribosomes are the sites of protein synthesis; and vacuoles primarily function as storage units, none of which directly relate to the packaging and distribution of molecules.

Why the other options are wrong
  • B. Mitochondria are known as the powerhouse of the cell, as they generate ATP through cellular respiration, but they do not function as a packaging and distribution center.
  • C. Ribosomes are involved in protein synthesis but do not package or distribute molecules within the cell.
  • D. Vacuoles are storage organelles that can hold various substances but are not primarily responsible for packaging and distributing molecules.

Q52. Which of the following hormone is not produced in older women?

  • A. Estrogen
  • B. Gastrin
  • C. Secretin
  • D. Renin

Explanation: The correct answer is Estrogen, as its production diminishes significantly in older women due to menopause. The ovaries cease to produce estrogen at the same levels they did during a woman's reproductive years. In contrast, Gastrin, Secretin, and Renin are hormones not primarily linked to the reproductive system and continue to be produced by older women. Gastrin aids in digestion, Secretin regulates digestive pH, and Renin is involved in blood pressure control, all of which can persist regardless of age.

Why the other options are wrong
  • B. Gastrin is a hormone produced by the stomach lining that helps regulate digestive processes. It is not directly related to the reproductive system and can still be produced in older women.
  • C. Secretin is a hormone produced by the small intestine that helps regulate the pH of the digestive tract. Like gastrin, it is unrelated to the reproductive system, and older women continue to produce it.
  • D. Renin is an enzyme and hormone produced by the kidneys that plays a role in blood pressure regulation. Its production is not significantly affected by age in women, making it still present in older women.

Q53. Which plant structure absorbs fats in the intestine?

  • A. Phloem
  • B. Lacteals
  • C. Xylem
  • D. Root hairs

Explanation: Lacteals in intestinal villi absorb dietary fats and transport them to lymph.

Why the other options are wrong
  • A. Phloem is a plant vascular tissue that transports sugars and other organic nutrients throughout the plant. It has no connection to the mammalian intestine or the process of fat absorption.
  • C. Xylem is a plant vascular tissue that primarily transports water and minerals from the roots to the rest of the plant. Like phloem, it is a plant structure and is not involved in intestinal absorption in animals.
  • D. Root hairs are extensions of root epidermal cells in plants, and their function is to absorb water and minerals from the soil. They are a plant structure and have no role in fat absorption from the intestine.

Q54. Thinking, memory and voluntary actions are mainly controlled by:

  • A. Cerebrum
  • B. Cerebellum
  • C. Pons
  • D. Hippocampus

Explanation: The correct answer is the Cerebrum, which is responsible for complex brain functions such as thinking, memory, and voluntary actions. The cerebrum consists of the left and right hemispheres and is involved in processing sensory information and initiating actions based on that information.In contrast, the Cerebellum mainly coordinates voluntary movements and balance but does not significantly control thinking or memory. The Pons serves as a bridge between various parts of the nervous system and is involved in functions like sleep regulation but not higher cognitive functions. Lastly, the Hippocampus is crucial for forming new memories, yet it does not encompass the broader functions of thinking and voluntary actions.

Why the other options are wrong
  • B. The cerebellum primarily coordinates balance and motor control but is not directly responsible for thinking or memory.
  • C. The pons is involved in regulating sleep and arousal and serves as a communication hub but does not control thinking or memory.
  • D. The hippocampus plays a key role in the formation of new memories but does not control thinking or voluntary actions as a whole.

Q55. Ventricular diastole causes:

  • A. Ventricular contraction
  • B. Closure of Atrioventricular valve
  • C. Opening of semilunar valve
  • D. Closure of semilunar valve

Explanation: Ventricular diastole is the phase of the cardiac cycle where the ventricles relax and fill with blood. During this phase, the semilunar valves (aortic and pulmonary) close to prevent backflow of blood into the ventricles. This closure is a critical event, as it marks the end of ventricular systole and the beginning of the filling phase. The other options are incorrect because:Ventricular contraction refers to systole, not diastole.Closure of Atrioventricular valve occurs during the contraction phase (systole).Opening of semilunar valve happens during ventricular contraction when blood is pumped into the aorta and pulmonary artery.Therefore, the correct answer is the closure of the semilunar valve, which is essential for initiating diastole.

Why the other options are wrong
  • A. This option is incorrect because ventricular diastole refers to the relaxation phase of the ventricles, not contraction.
  • B. This option is incorrect as the closure of the atrioventricular (AV) valves occurs during ventricular systole, not diastole.
  • C. This option is incorrect since the semilunar valves are open during ventricular systole when blood is ejected from the heart, not during diastole.

Q56. The part of male reproductive system that maintains the temperature for sperm production is:

  • A. Testes
  • B. Scrotum
  • C. Vas deferens
  • D. Epididymis

Explanation: The correct answer is Scrotum because it is responsible for maintaining the ideal temperature for sperm production, which is slightly lower than the body's core temperature. The scrotum achieves this by contracting or relaxing to move the testes closer to or further from the body, depending on environmental conditions. The Testes are the organs that produce sperm and hormones but do not regulate temperature themselves. The Vas deferens is involved in sperm transport, and the Epididymis is where sperm mature, but neither has a role in temperature regulation.

Why the other options are wrong
  • A. The testes are responsible for producing sperm and hormones, but they do not regulate temperature. They are located within the scrotum, which aids in temperature control.
  • C. The vas deferens is a duct that transports sperm from the epididymis to the ejaculatory duct, but it does not have a role in temperature regulation.
  • D. The epididymis is where sperm mature and are stored, but it does not maintain the temperature for sperm production.

Q57. This given organelle is involved in the synthesis of oil, phospholipids and steroids:

  • A. Mitochondria
  • B. Golgi complex
  • C. Endoplasmic reticulum
  • D. Ribosomes

Explanation: The correct answer is the endoplasmic reticulum, which plays a vital role in synthesizing various lipids such as oils, phospholipids, and steroids. The endoplasmic reticulum exists in two forms: rough (with ribosomes) and smooth (without ribosomes). The smooth ER is particularly involved in lipid synthesis.In contrast, mitochondria primarily generate energy in the form of ATP through cellular respiration, thus they are not involved in lipid synthesis. The Golgi complex is essential for processing and packaging proteins and lipids but does not take part in their synthesis. Lastly, ribosomes are focused on protein synthesis and do not synthesize lipids.

Why the other options are wrong
  • A. Mitochondria are known as the powerhouses of the cell, primarily involved in energy production through cellular respiration, not lipid synthesis.
  • B. The Golgi complex is responsible for modifying, sorting, and packaging proteins and lipids for secretion or delivery to other organelles, but it does not synthesize lipids.
  • D. Ribosomes are the sites of protein synthesis in cells, not involved in the synthesis of lipids.

Q58. The most abundant polysaccharide in plants, widely used in paper and as a source of dietary fibre for human is:

  • A. Chitin
  • B. Glycogen
  • C. Starch
  • D. Cellulose

Explanation: The correct answer is Cellulose because it is the most abundant polysaccharide in plants, constituting the cell wall structure, and it serves as an important source of dietary fiber for humans. Unlike chitin and glycogen, which are not found in plants, and starch, which serves as a storage form rather than a structural component, cellulose is crucial for plant integrity and human nutrition through fiber intake.

Why the other options are wrong
  • A. Chitin is a structural polysaccharide found primarily in the exoskeletons of arthropods and the cell walls of fungi, not in plants.
  • B. Glycogen is a storage polysaccharide in animals, primarily found in liver and muscle tissues, and is not used in plants for structural purposes.
  • C. Starch is a storage polysaccharide in plants, but it is not the most abundant polysaccharide and is not primarily a source of dietary fiber.

Q59. Binding site for a substrate on enzyme is:

  • A. Allosteric site
  • B. Passive site
  • C. Active site
  • D. Regulatory site

Explanation: The correct answer is the active site, which is specifically designed to bind substrates and facilitate the biochemical reactions catalyzed by enzymes. It is characterized by a unique shape and chemical environment that complements the substrate, allowing for effective interaction and catalysis. The allosteric site is a different location on the enzyme that can bind regulatory molecules to modulate enzyme activity but does not directly bind substrates. The term passive site is not a recognized term in biochemistry and does not pertain to substrate binding. Finally, the regulatory site is involved in controlling the enzymatic function but is not where the substrate binds. Thus, the active site is the only option that accurately describes the location where the substrate interacts with the enzyme.

Why the other options are wrong
  • A. The allosteric site is a location on an enzyme where molecules can bind and affect the enzyme's activity, but it is not the primary site for substrate binding.
  • B. The term 'passive site' is not standard in enzyme terminology and does not refer to any recognized site for substrate binding.
  • D. The regulatory site is involved in controlling enzyme activity but does not serve as the binding site for the substrate.

Q60. Which of the following organ takes part in the T-cell maturation for both the lymphatic and endocrine systems?

  • A. Spleen
  • B. Thymus
  • C. Liver
  • D. Kidney

Explanation: The correct answer is Thymus, as it is the organ that plays a vital role in the maturation of T-cells, which are crucial for the adaptive immune response. The thymus provides an environment for immature T-cells to develop and differentiate into functional T-cells that can recognize and respond to pathogens.Other options are incorrect for the following reasons: Spleen is important for immune response but does not mature T-cells; Liver is involved in metabolism and detoxification but has no role in T-cell maturation; Kidney functions primarily in filtration and waste removal, with no involvement in the maturation of T-cells.

Why the other options are wrong
  • A. The spleen plays a role in filtering blood and managing immune responses but is not where T-cells mature.
  • C. The liver is involved in various metabolic processes and detoxification but does not participate in T-cell maturation.
  • D. The kidneys are primarily responsible for filtering blood and producing urine, with no role in T-cell maturation.

Q61. A chromosome which contain centromere at the ce called

  • A. Amesocentric chromosome
  • B. metacentric chromosome
  • C. acrocentric chromosome
  • D. telocentric chromosome

Explanation: A metacentric chromosome is characterized by a centrally located centromere, which divides the chromosome into two nearly equal arms. This contrasts with acrocentric chromosomes, where the centromere is positioned closer to one end, resulting in an unequal arm length. Telocentric chromosomes have their centromere at the very end of the chromosome, leading to only one arm being present. The term 'amesocentric' does not correspond to any established category in chromosome classification, making it an incorrect option. Therefore, the correct answer is the metacentric chromosome.

Why the other options are wrong
  • A. This option is incorrect because 'amesocentric' is not a recognized classification of chromosomes based on centromere position.
  • C. This option is incorrect as acrocentric chromosomes have the centromere located near one end, creating one long arm and one short arm.
  • D. This option is also incorrect. Telocentric chromosomes have the centromere at the very end, resulting in one arm.

Q62. A confirmed COVID patient shows weak specific immunity. Which component is most likely deficient in this patient?

  • A. Red Blood Cells
  • B. Helper T-lymphocytes
  • C. Thrombocytes
  • D. Suppressor T-lymphocytes

Explanation: The correct answer is Helper T-lymphocytes because they play a vital role in activating and regulating the immune response, particularly in generating specific immunity against pathogens such as SARS-CoV-2, the virus responsible for COVID-19. A confirmed COVID patient showing weak specific immunity likely has a deficiency in these cells, resulting in an inadequate immune response to the virus.In contrast, Red Blood Cells and Thrombocytes are not directly involved in the immune response; the former is responsible for oxygen transport and the latter for clotting. Suppressor T-lymphocytes function to modulate the immune response rather than initiate it, and their deficiency would not primarily lead to weak specific immunity. Thus, they are not the correct choice.

Why the other options are wrong
  • A. Red blood cells are primarily responsible for oxygen transport in the body and are not directly involved in the immune response to infections like COVID-19.
  • C. Thrombocytes, or platelets, are involved in blood clotting and do not play a significant role in the adaptive immune response, making them irrelevant to the question.
  • D. Suppressor T-lymphocytes (or regulatory T-cells) help regulate the immune response and prevent overactivity. While they are important, their deficiency would not primarily cause weak specific immunity in the context of a COVID infection.

Q63. Component of reflex arc must contain neurons from:

  • A. Motor nerve and Mixed nerve
  • B. Sensory nerve and Intermediate nerve
  • C. Motor nerve and Sensory nerve
  • D. Mixed nerve and Intermediate nerve

Explanation: A reflex arc is a neural pathway that controls a reflex action, consisting primarily of a sensory nerve that detects stimuli and a motor nerve that executes the response. In this case, Option C is correct because it accurately identifies both components of the reflex arc: the motor nerve, which sends signals to muscles, and the sensory nerve, which carries information from sensory receptors. The other options either include incorrect terms or fail to represent the necessary components of a reflex arc. For example, mixed nerves do not specifically denote the pathways involved in reflex actions, and the term 'intermediate nerve' lacks clarity in this context.

Why the other options are wrong
  • A. This option suggests a combination of a motor nerve, which is responsible for sending signals from the central nervous system to muscles, and a mixed nerve, which carries both sensory and motor fibers. However, while motor nerves are involved in reflex arcs, mixed nerves do not specifically represent the components needed for a reflex action.
  • B. This option includes a sensory nerve, which is essential for transmitting sensory signals to the central nervous system. However, the term 'intermediate nerve' is not a standard classification in the context of reflex arcs, making this option incorrect.
  • D. This option suggests a mixed nerve, which can carry a combination of sensory and motor fibers, but does not capture the specific roles necessary for a reflex arc. The addition of an 'intermediate nerve' further complicates the answer, as this term is not typically used in this context.

Q64. Which organelle is usually referred as post office of the cell and why?

  • A. Golgi apparatus
  • B. Rough endoplasmic reticulum
  • C. Mitochondria
  • D. Nucleus

Explanation: The correct answer is the Golgi apparatus, which is aptly named the 'post office' of the cell. It plays a crucial role in processing and packaging proteins and lipids that have been synthesized in the cell, preparing them for transport to their destinations. The Golgi apparatus modifies these substances and sorts them according to their final destinations, much like a post office sorts and sends out mail.In contrast, the rough endoplasmic reticulum is primarily involved in protein synthesis, not in the packaging or sorting of materials. The mitochondria are essential for energy production, while the nucleus functions as the control center of the cell, managing gene expression and cellular operations. None of these organelles perform the sorting and packaging functions attributed to the Golgi apparatus.

Why the other options are wrong
  • B. The rough endoplasmic reticulum (RER) is responsible for synthesizing proteins, particularly those that are secreted from the cell or incorporated into the cell's membrane. While important for production, it does not sort or package materials.
  • C. Mitochondria are known as the 'powerhouses' of the cell because they generate ATP, the energy currency of the cell. They do not function in the sorting or packaging of cellular materials.
  • D. The nucleus serves as the control center of the cell, housing the genetic material and regulating cell activities. It does not have a role in the sorting or packaging of materials like the Golgi apparatus.

Q65. Which type of neurons stimulate the muscles to contract in a reflex arc?

  • A. Efferent neurons
  • B. Sensory neurons
  • C. Interneurons
  • D. Afferent neurons

Explanation: The correct answer is Efferent neurons because these neurons are responsible for transmitting impulses from the central nervous system to muscles, leading to muscle contraction. In a reflex arc, efferent neurons carry the response signal to the muscles after the sensory neurons detect a stimulus and interneurons process the information. Sensory neurons (Option B) are crucial in detecting stimuli but do not directly cause muscle contraction. Interneurons (Option C) serve as connectors and integrators within the central nervous system, while afferent neurons (Option D) specifically refer to those that carry information to the central nervous system, thus they also do not stimulate muscle contraction directly.

Why the other options are wrong
  • B. Sensory neurons transmit signals from sensory receptors to the central nervous system. While they are essential for initiating reflex actions, they do not directly stimulate muscle contraction.
  • C. Interneurons connect sensory and motor neurons within the central nervous system. They process information and facilitate reflex arcs, but they do not directly stimulate muscle contraction.
  • D. Afferent neurons, also called sensory neurons, carry signals towards the central nervous system. They are involved in sensing stimuli but do not stimulate muscle contraction directly.

Q66. Osmoreceptors that detect the osmotic pressure of blood areprimarily located in the

  • A. Cerebellum
  • B. Medulla oblongata
  • C. Hypothalamus
  • D. Cerebral cortex

Explanation: The correct answer is the hypothalamus, which is a key brain region involved in homeostasis, including the detection of osmotic pressure through osmoreceptors. These receptors help regulate hydration by stimulating thirst and controlling the release of antidiuretic hormone (ADH) to manage water retention in the kidneys.The other options are incorrect because:Cerebellum: Its primary functions relate to coordination and balance, not osmoreception.Medulla oblongata: While it is crucial for autonomic functions, it does not serve as the center for osmotic pressure detection.Cerebral cortex: This area is involved in complex cognitive processes and does not involve direct detection of osmotic pressure.

Why the other options are wrong
  • A. The cerebellum is primarily involved in motor control and coordination, not in detecting osmotic pressure.
  • B. While the medulla oblongata regulates vital functions like breathing and heart rate, it does not primarily function as a site for osmoreceptor activity.
  • D. The cerebral cortex is responsible for higher brain functions, such as thought and action, but does not house osmoreceptors related to blood osmotic pressure.

Q67. CFTR gene that encode a protein which regulate:

  • A. Protein and salt
  • B. Salt and Water
  • C. Sugar and Water
  • D. Liquid and Protein

Explanation: The CFTR gene encodes a protein that plays a vital role in the regulation of salt and water transport across cell membranes, particularly in epithelial tissues. This regulation is crucial for maintaining proper hydration and mucus consistency in organs such as the lungs and pancreas. Option B is correct because it directly addresses the key substances that the CFTR gene regulates. Option A is incorrect because while protein is important in various biological functions, it is not the primary focus of CFTR regulation. Option C is incorrect as the CFTR gene does not regulate sugar, and Option D is too vague, failing to specify the key components of salt and water, which are essential to the CFTR gene's function.

Why the other options are wrong
  • A. This option incorrectly combines protein with salt, which is not the primary focus of CFTR gene regulation. While proteins are essential in various biological functions, the CFTR gene specifically relates more to fluid balance.
  • C. This option is incorrect as the CFTR gene does not primarily regulate sugar. The focus is on salt and water balance, which is vital in various bodily functions.
  • D. This option is vague and does not accurately represent the specific regulatory functions of the CFTR gene. It fails to mention the crucial role of salt and water.

Q68. Arthritis is a disease that primarily affects the

  • A. Kidneys
  • B. Lungs
  • C. Joints
  • D. Muscles

Explanation: Arthritis is a term used to describe a group of more than 100 diseases that involve inflammation of the joints. The correct answer is 'Joints' (Option C), as arthritis primarily affects these areas, causing pain, swelling, and stiffness. The other options are incorrect because they refer to organs or systems not primarily involved in arthritis. Kidneys (Option A) and Lungs (Option B) are not directly affected by this condition, while Muscles (Option D) may experience discomfort due to joint issues but are not the primary focus of arthritis.

Why the other options are wrong
  • A. While kidneys can be affected by various diseases, they are not typically associated with arthritis. Arthritis primarily involves pain and inflammation in the joints.
  • B. The lungs are not the main focus of arthritis. Arthritis is characterized by joint issues rather than respiratory problems.
  • D. Muscles can be affected by various conditions, but arthritis specifically targets the joints rather than the muscles themselves.

Q69. A biological laboratory is developing gene therapy with a modified virus that infects the blood only. Which of the following category does this virus belong to?

  • A. Algal virus
  • B. Fungal virus
  • C. Animal virus
  • D. Bacterial virus

Explanation: The correct answer is Animal virus because the virus in question is designed to infect blood, which is a characteristic of viruses that specifically target animal cells. Algal viruses and fungal viruses are not applicable here as they infect different organisms (algae and fungi, respectively). Bacterial viruses are also incorrect because they specifically infect bacteria and do not interact with animal blood cells.

Why the other options are wrong
  • A. This type of virus specifically infects algae and is not relevant to blood infections in animals.
  • B. Fungal viruses primarily infect fungi and do not target animal or human cells.
  • D. Bacterial viruses, or bacteriophages, infect bacteria and are not relevant to blood infections in animals.

Q70. Which of the following is a potential symptom of chronic renal failure?

  • A. Nephritis and bacterial infection
  • B. Bone pain and fractures
  • C. Impaired concentration and confusion
  • D. Muscle cramps due to electrolyte imbalance

Explanation: The correct answer is Nephritis and bacterial infection because chronic renal failure can compromise kidney function, making individuals more vulnerable to infections, including nephritis. Option B, Bone pain and fractures, while related to chronic kidney disease due to issues with calcium and phosphate metabolism, are not direct symptoms of chronic renal failure. Option C, Impaired concentration and confusion, can occur due to uremic toxins but are not definitive symptoms of chronic renal failure. Similarly, option D, Muscle cramps due to electrolyte imbalance, is a potential complication rather than a direct symptom. Overall, recognizing the association of chronic renal failure with infections is crucial for identifying its symptoms.

Why the other options are wrong
  • B. This option is incorrect. While bone pain and fractures can occur in chronic kidney disease due to mineral and bone disorders, they are not direct symptoms of chronic renal failure itself.
  • C. This option is also incorrect. Although cognitive issues can arise from chronic kidney disease due to uremia, they are not specific symptoms of chronic renal failure.
  • D. This option is incorrect. Although muscle cramps can occur due to electrolyte imbalances associated with renal failure, they are not considered primary symptoms of chronic renal failure.

Q71. Which of the following statement correctly describes the organelle that is not membrane bound?

  • A. Presence of cristae
  • B. Modification and packaging of proteins
  • C. Presence of digestive enzymes
  • D. Made of rRNA and protein

Explanation: The correct answer is Option D: Made of rRNA and protein. Ribosomes are unique among organelles as they are not enclosed by a membrane and are composed of ribonucleic acid and proteins. They play a crucial role in translating mRNA into proteins.Options A, B, and C all describe features that are characteristic of membrane-bound organelles. Option A (Presence of cristae) refers to mitochondria, which are integral for energy production and have a double membrane structure. Option B (Modification and packaging of proteins) pertains to the Golgi apparatus, which is vital for processing proteins and is also membrane-bound. Option C (Presence of digestive enzymes) relates to lysosomes, which are responsible for degradation and contain a membrane that encases their digestive enzymes. Therefore, these options do not correctly describe a non-membrane-bound organelle.

Why the other options are wrong
  • A. This feature is characteristic of mitochondria, which are membrane-bound organelles responsible for energy production. Hence, this option does not describe a non-membrane-bound organelle.
  • B. This function pertains to the Golgi apparatus, a membrane-bound organelle that processes and packages proteins. Therefore, this option is incorrect as it does not relate to a non-membrane-bound organelle.
  • C. This is a feature typically associated with lysosomes, which are membrane-bound organelles that contain enzymes for breaking down waste materials. Thus, this option does not correctly describe a non-membrane-bound organelle.

Q72. A patient with a genetic disorder undergoes treatment where a normal gene is inserted into their cells. This is called

  • A. Gene therapy
  • B. Genetic testing MDCAT COMM
  • C. Protein engineering
  • D. DNA fingerprinting

Explanation: Gene therapy is the correct answer because it specifically refers to the technique of inserting a normal gene into the cells of a patient with a genetic disorder. This method aims to correct the underlying genetic defect. In contrast, genetic testing is used to diagnose genetic conditions, protein engineering focuses on modifying proteins rather than genes, and DNA fingerprinting is a method used for identification rather than treatment. Thus, only gene therapy directly addresses the insertion of a normal gene into cells to treat genetic disorders.

Why the other options are wrong
  • B. This option refers to the process of analyzing an individual's DNA to identify genetic disorders but does not involve the therapeutic insertion of genes.
  • C. This option involves the design and modification of proteins, not the insertion of genes into cells. It is unrelated to the treatment of genetic disorders.
  • D. This technique is used for identification purposes, such as forensic analysis or paternity testing, and does not involve the therapeutic insertion of genes.

Q73. After Liver transplant, doctors suppress the $\text{T-lymphocyte}$ activity in patient. Why?

  • A. To increase the rate of antibody production
  • B. To prevent infections
  • C. To avoid graft rejection by the immune system
  • D. To produce memory cells faster

Explanation: After a liver transplant, the body's immune system may view the transplanted organ as a foreign entity and initiate an immune response against it, known as graft rejection. T-lymphocytes play a central role in this process. By suppressing T-lymphocyte activity, doctors aim to reduce the risk of the immune system attacking the transplanted liver, thereby increasing the chances of successful transplantation and organ function. The other options, while related to immune function, do not accurately reflect the primary objective of T-lymphocyte suppression in this context. For instance, increasing antibody production and preventing infections are important considerations in transplant care, but they are not the main reason for suppressing T-lymphocytes in order to prevent graft rejection.

Why the other options are wrong
  • A. This option is incorrect because suppressing T-lymphocyte activity does not lead to an increase in antibody production. Antibody production is primarily the function of B-lymphocytes, and suppressing T-lymphocytes may reduce overall immune response.
  • B. This option is partially correct but misleading. While it is important to prevent infections in transplant patients, the primary reason for suppressing T-lymphocyte activity is to prevent the immune system from rejecting the new organ. Infection prevention is a secondary concern.
  • D. This option is incorrect. Memory cells are formed as a result of an immune response to pathogens, and suppressing T-lymphocyte activity would actually hinder the formation of memory cells, not promote it.

Q74. How do the kidneys contribute to maintain normal blood calcium level?

  • A. By storing excess calcium
  • B. By reabsorbing calcium and activating vitamin D
  • C. By secreting calcium directly into the blood
  • D. By converting calcium into urea for excretion

Explanation: The kidneys are essential in maintaining normal blood calcium levels by reabsorbing calcium during urine formation and converting vitamin D into its active form, calcitriol. This active form of vitamin D enhances the absorption of calcium from the diet in the intestines, thereby contributing to overall calcium homeostasis. The other options are incorrect because the kidneys do not store calcium, secrete calcium into the blood, or convert calcium into urea for excretion. Instead, they manage calcium levels primarily through reabsorption and the activation of vitamin D.

Why the other options are wrong
  • A. This statement is incorrect because the kidneys do not store calcium; instead, they regulate calcium levels through reabsorption and excretion.
  • C. This statement is incorrect because the kidneys do not secrete calcium into the blood; they regulate its level through reabsorption and filtration processes.
  • D. This is incorrect as calcium is not converted into urea. Urea is a waste product formed from protein metabolism, while calcium is primarily reabsorbed or excreted without conversion.

Q75. Receptors that are located in the retina of eye are called:

  • A. Merkel disc
  • B. Ruffini endings
  • C. Pacinian corpuscles
  • D. Rod and Cone cells

Explanation: The correct answer is Rod and Cone cells because these are the specific types of photoreceptors located in the retina, which convert light into signals that can be processed by the brain. Rods are sensitive to light and allow us to see in dim conditions, while cones are responsible for color vision and function best in bright light. The other options, such as Merkel discs, Ruffini endings, and Pacinian corpuscles, are all types of mechanoreceptors that are located in the skin and other tissues, but not in the retina.

Why the other options are wrong
  • A. Merkel discs are mechanoreceptors found in the skin that respond to light touch and pressure. They are not located in the retina.
  • B. Ruffini endings are proprioceptors that detect stretch and are found in the skin and joints, not in the retina.
  • C. Pacinian corpuscles are receptors that respond to deep pressure and vibration. They are also not located in the retina.

Q76. The hormone, when overproduced can lead to hypercalcemia and stone formation is

  • A. Insulin
  • B. Thyroxine
  • C. Parathyroid hormone
  • D. Calcitonin hormone

Explanation: The correct answer is Parathyroid hormone. This hormone is responsible for regulating calcium levels in the blood. When there is an excess production of PTH, it causes increased calcium release from the bones, increased intestinal absorption of calcium, and decreased renal excretion of calcium, leading to hypercalcemia. This elevated calcium level can result in the formation of kidney stones due to the excess calcium being filtered through the kidneys.On the other hand, Insulin is unrelated to calcium metabolism; it primarily regulates blood sugar levels. Thyroxine also does not impact calcium levels directly as its primary function is related to metabolic rate. Lastly, Calcitonin functions to lower blood calcium levels, counteracting the effects of parathyroid hormone, and does not contribute to hypercalcemia or stone formation.

Why the other options are wrong
  • A. Insulin is primarily involved in glucose metabolism and has no direct role in calcium regulation. It does not cause hypercalcemia.
  • B. Thyroxine regulates metabolism and energy production but does not directly influence calcium levels or lead to stone formation.
  • D. Calcitonin works to lower blood calcium levels, opposing the effects of parathyroid hormone. It does not lead to hypercalcemia or stone formation.

Q77. Nodes of Ranvier along the length of axon fibers allow:

  • A. More diffusion of neurotransmitters
  • B. Saltatory conduction of nerve impulse
  • C. Formation of new synaptic connections
  • D. Synthesis of new neurons

Explanation: The correct answer is saltatory conduction of nerve impulse. Nodes of Ranvier are small gaps in the myelin sheath of axons that allow for the rapid transmission of electrical signals by enabling the action potentials to jump from one node to another. This process, known as saltatory conduction, significantly increases the speed of nerve signal transmission compared to continuous conduction along unmyelinated fibers.In contrast, the other options are incorrect. 'More diffusion of neurotransmitters' does not relate to the function of Nodes of Ranvier; neurotransmitter diffusion occurs at synapses, not along the axon. 'Formation of new synaptic connections' and 'Synthesis of new neurons' are also unrelated to the role of Nodes of Ranvier, as these processes pertain to different aspects of neural function and development.

Why the other options are wrong
  • A. This option is incorrect as Nodes of Ranvier do not relate to the diffusion of neurotransmitters. Instead, they are involved in the conduction of electrical impulses along the axon.
  • C. This option is incorrect as the Nodes of Ranvier do not contribute to the formation of synapses. Their primary function is to assist in the rapid transmission of action potentials along the axon.
  • D. This option is incorrect because Nodes of Ranvier are not involved in the synthesis of new neurons. They play a role in the conduction of nerve impulses, not in neurogenesis.

Q78. The bony roof of the oral cavity, which separates it from the nasal cavity, is formed by the:

  • A. soft palate
  • B. Mandible
  • C. Hard palate
  • D. Maxilla

Explanation: The correct answer is the hard palate, which serves as the bony roof of the oral cavity and separates it from the nasal cavity. The hard palate is essential for proper oral function, including eating and speaking, as it provides a rigid structure against which the tongue can push food. The other options are incorrect because the soft palate is muscular and located towards the back of the mouth, while the mandible is the lower jaw and does not contribute to the roof at all. The maxilla, while it does form part of the hard palate, is not the complete structure that separates the oral and nasal cavities.

Why the other options are wrong
  • A. The soft palate is a muscular structure located at the back of the roof of the mouth. Unlike the hard palate, it does not contribute to the bony separation between the oral and nasal cavities.
  • B. The mandible, or lower jawbone, supports the lower teeth and provides structure to the lower face, but it does not form the roof of the oral cavity.
  • D. The maxilla is the upper jawbone that forms part of the hard palate, but it does not solely form the roof of the oral cavity. It is part of the structure rather than the complete roof.

Q79. Arachidonic acid, which is the precursor molecule for prostaglandins is:

  • A. A saturated fatty acid with 18 carbons
  • B. An unsaturated fatty acid with 18 carbons
  • C. A tri-unsaturated fatty acid with 20 carbons
  • D. A tetra-unsaturated fatty acid with 20 carbons

Explanation: Arachidonic acid is a polyunsaturated fatty acid with 20 carbon atoms and four double bonds. It serves as a precursor for the synthesis of prostaglandins, which are important signaling molecules in the body. The correct answer is Option B, which notes that arachidonic acid is unsaturated. Option A is incorrect because it refers to a saturated fatty acid, which does not apply here. Option C incorrectly identifies the number of double bonds, as arachidonic acid has four, not three. Option D correctly states the number of carbons but misrepresents the classification of unsaturation by not emphasizing the four double bonds.

Why the other options are wrong
  • A. This option is incorrect because arachidonic acid is not saturated; it contains double bonds, which makes it unsaturated.
  • C. This option is incorrect; while arachidonic acid does have multiple double bonds (specifically four), it is not classified as tri-unsaturated since it has four double bonds.
  • D. This option is technically correct in terms of unsaturation, as arachidonic acid has four double bonds. However, it misleads by not correctly stating that it is a 20-carbon fatty acid.

Q80. Which structure in neuron is responsible for receiving information from other neurons?

  • A. Axon
  • B. Soma
  • C. Dendrite
  • D. Axon terminal

Explanation: The correct answer is Dendrite. Dendrites are specialized structures that receive signals from other neurons and transmit them toward the neuron's cell body. They play a crucial role in the neuron's ability to process and integrate information. The other options are incorrect because:Axon: While it transmits signals away from the cell body, it does not receive information.Soma: The soma supports the neuron's functions but is not involved in receiving external signals.Axon terminal: This part releases neurotransmitters to send signals to other neurons, but it doesn't receive information.

Why the other options are wrong
  • A. The axon is responsible for transmitting electrical impulses away from the cell body to other neurons, but it does not receive information.
  • B. The soma, or cell body, contains the nucleus and organelles of the neuron, but it is not primarily involved in receiving information from other neurons.
  • D. The axon terminal is the part of the neuron that releases neurotransmitters to communicate with other neurons, but it does not receive incoming signals.

Q81. Atrial walls are thinner as compared to ventricles because:

  • A. Atria are small in size
  • B. Atria are present above the ventricles
  • C. Atria have to force blood into the ventricles which lie very close to them
  • D. Blood enters into the atria by osmosis

Explanation: The correct answer is that the atria have to force blood into the ventricles which lie very close to them. The atria serve as receiving chambers for blood returning to the heart, and their primary function is to push blood into the ventricles. Because the ventricles are located just below the atria, less muscular force is needed, allowing the atrial walls to be thinner. Option A is incorrect because, although atria are smaller, size does not directly correlate to wall thickness. Option B is misleading as the position of the atria above the ventricles does not determine wall thickness. Option D is incorrect because blood enters the atria through veins, not osmosis, which is unrelated to this physiological process.

Why the other options are wrong
  • A. While the atria are indeed smaller than the ventricles, size alone does not determine the thickness of their walls. This option does not address the functional aspect of why atrial walls are thinner.
  • B. The position of the atria relative to the ventricles does not directly influence the thickness of their walls. This option fails to explain the mechanical function of the atria.
  • D. This option is incorrect as blood enters the atria through veins, not by osmosis. Osmosis pertains to the movement of water across membranes and is not relevant in this context.

Q82. Chemicals that stimulate the olfactory receptors enter the nasal cavity in the form of

  • A. solid
  • B. liquid
  • C. gas
  • D. plasma

Explanation: The correct answer is gas because olfactory receptors are specialized to detect airborne chemicals, which are typically in a gaseous state. When substances evaporate, they release molecules into the air that can then interact with the olfactory receptors located in the nasal cavity. Option solid is incorrect as solids do not vaporize in a way that effectively stimulates olfactory receptors. Option liquid may produce smells, but liquids need to evaporate into a gas to be detected by the olfactory system. Lastly, plasma is irrelevant here, as it is a state of matter that does not apply to olfactory stimulation.

Why the other options are wrong
  • A. Solid substances cannot easily enter the nasal cavity to stimulate olfactory receptors as they must be in a state that can evaporate or diffuse into the air.
  • B. While some liquids can produce vapors that stimulate smell, they must first evaporate into a gas to reach the olfactory receptors effectively.
  • D. Plasma is not a relevant state in this context as it refers to ionized gas and is not involved in the process of olfaction.

Q83. Neurosecretory cells are:

  • A. Endocrine cells
  • B. Exocrine cells
  • C. Coneuroglial cells
  • D. Neurons that have been adapted to secrete hormones

Explanation: Neurosecretory cells are specialized neurons that have adapted to secrete hormones directly into the bloodstream, thus functioning at the intersection of the nervous and endocrine systems. They are instrumental in regulating various physiological processes through the release of hormones. The other options are incorrect because:Endocrine cells are general hormone-secreting cells that do not have the neuronal adaptations of neurosecretory cells.Exocrine cells secrete substances externally or into ducts, not into the bloodstream.Coneuroglial cells is not a recognized term in biology and doesn't accurately describe any functional cell type.Thus, option D is the most accurate description of neurosecretory cells.

Why the other options are wrong
  • A. Endocrine cells are responsible for producing and secreting hormones directly into the bloodstream, but they are not specifically adapted neurons.
  • B. Exocrine cells secrete substances through ducts to the outside of the body or into body cavities, which is different from the function of neurosecretory cells.
  • C. Coneuroglial cells are not a recognized category in cell biology; the term appears to be a misnomer and does not relate to the function of hormone secretion.

Q84. Lamarck theory of evolution was rejected experimentally by:

  • A. JA. Earnest Hackle
  • B. Charles Darwin
  • C. August Weismann
  • D. Thomas R. Malthus

Explanation: The correct answer is August Weismann, who conducted notable experiments, such as cutting the tails off mice for several generations to show that acquired traits are not inherited, directly opposing Lamarck's theory of evolution, which suggested that characteristics acquired during an organism's lifetime could be passed to offspring. The other options are incorrect as they did not conduct experiments that specifically rejected Lamarck's ideas: JA. Earnest Hackle and Charles Darwin were influential figures in evolutionary thought but did not experimentally disprove Lamarck; Thomas R. Malthus contributed to the understanding of population dynamics, which influenced Darwin, but he did not address Lamarck's theory.

Why the other options are wrong
  • A. Though Ernst Haeckel was a prominent biologist who supported Darwin's ideas and contributed to evolutionary theory, he did not conduct the experiments that rejected Lamarck's theory.
  • B. Charles Darwin is known for proposing the theory of natural selection. While he influenced evolutionary thought significantly, he did not directly conduct experiments that disproved Lamarck's theory.
  • D. Thomas Malthus was an economist whose ideas on population growth influenced Darwin's theory but did not focus on experiments related to Lamarck's theory.

Q85. Which of the following characteristics is common among sucrose, lactose and maltose?

  • A. molecular formula
  • B. occurrence in living beings
  • C. chemical nature of their monosaccharide units
  • D. to act as reducing sugar

Explanation: The correct answer is Option A: molecular formula. Sucrose, lactose, and maltose all share the same molecular formula (C12H22O11), which is a defining feature of disaccharides. Option B is incorrect because while these sugars occur in living beings, many other sugars do as well, making this characteristic not exclusive to them. Option C is also incorrect since the monosaccharide units differ: sucrose contains glucose and fructose, lactose contains glucose and galactose, and maltose is made of two glucose molecules. Lastly, Option D is misleading because, while maltose is a reducing sugar, sucrose is not, which means it cannot be a common characteristic across all three sugars.

Why the other options are wrong
  • B. While sucrose, lactose, and maltose are all found in living organisms, this characteristic is not unique to them, as many other sugars also occur in living beings.
  • C. The monosaccharide units differ among these disaccharides: sucrose is composed of glucose and fructose, lactose is made of glucose and galactose, and maltose consists of two glucose units, making this statement inaccurate.
  • D. Only maltose acts as a reducing sugar because it has a free anomeric carbon. Sucrose is a non-reducing sugar, and lactose is also a reducing sugar, but the question asks for a common characteristic, making this option misleading.

Q86. Ribozymes are the only biocatalysts that are made up of:

  • A. DNA
  • B. RNA
  • C. Protein
  • D. Fatty acid

Explanation: Ribozymes are unique in that they are RNA molecules capable of catalyzing specific biochemical reactions, which challenges the traditional view that only proteins can act as enzymes. DNA serves as the genetic blueprint but lacks catalytic functions. Proteins are indeed common biocatalysts, but they do not apply in the case of ribozymes. Fatty acids, while important for cellular structures, do not exhibit enzymatic activity. Therefore, the only correct answer is RNA, as it directly corresponds to the nature of ribozymes.

Why the other options are wrong
  • A. DNA is primarily known for its role in genetic information storage and transfer. It does not have catalytic activity, which is essential for biocatalysts.
  • C. While many enzymes, which are biocatalysts, are proteins, ribozymes specifically are not made of protein, making this an incorrect choice.
  • D. Fatty acids are components of lipids and do not possess catalytic activity, thus they cannot serve as biocatalysts.

Q87. The induced fit model differs from the Lock and Key model because the enzyme in this model:

  • A. Has a rigid and fixed active site
  • B. Changes shape to fit the substrate
  • C. Is non-specific in its action
  • D. Is denatured during reaction

Explanation: The correct answer is that the induced fit model describes an enzyme that changes shape to fit the substrate. This model suggests that, unlike the Lock and Key model, where the enzyme's active site is rigid and specific, the induced fit model allows the enzyme to undergo a conformational change upon substrate binding, enhancing the fit and thus the catalytic efficiency.Option A is incorrect because it describes the Lock and Key model, which features a fixed active site. Option C is incorrect as it suggests non-specific action, which is not characteristic of either model. Option D is also incorrect because denaturation implies a complete loss of function, which does not happen during normal enzyme activity.

Why the other options are wrong
  • A. This option describes the Lock and Key model, which suggests that the active site of the enzyme is unchanging and rigid, allowing only specific substrates to fit.
  • C. This option is incorrect because both models imply some level of specificity in enzyme-substrate interactions, though the induced fit model allows for slight flexibility.
  • D. This option is incorrect as denaturation refers to the loss of an enzyme's structure and function, which does not occur during the normal action of an enzyme in the induced fit model.

Q88. Which competitive inhibitor blocks the enzyme responsible for bacterial cell wall synthesis?

  • A. Sulphonamide
  • B. Streptomycin
  • C. Tetracycline
  • D. Penicillin

Explanation: Penicillin is the correct answer because it specifically inhibits the enzymes (transpeptidases) involved in bacterial cell wall synthesis, leading to cell lysis and death. In contrast, sulphonamides, streptomycin, and tetracycline target other bacterial processes such as folic acid synthesis and protein synthesis but do not interfere with the integrity of the cell wall directly. Understanding the specific mechanisms of action of these antibiotics is crucial for selecting the appropriate treatment for bacterial infections.

Why the other options are wrong
  • A. Sulphonamides are competitive inhibitors that block the synthesis of folic acid in bacteria, but they do not directly inhibit cell wall synthesis.
  • B. Streptomycin is an aminoglycoside antibiotic that inhibits protein synthesis by binding to the bacterial ribosome, not the cell wall.
  • C. Tetracycline also inhibits protein synthesis by binding to ribosomes, but it does not affect cell wall synthesis directly.

Q89. Water commonly known as a universal solvent because:

  • A. It dissolves polar and ionic substances effectively
  • B. It supports chemical reactions without reacting itself
  • C. It has a high specific heat capacity
  • D. It dissolves many substances due to its small molecule size

Explanation: Water is often referred to as a 'universal solvent' because it can dissolve a wide variety of substances, particularly those that are ionic or polar. The polar nature of water molecules allows them to surround and separate the ions or polar molecules, effectively dissolving them. This is why Option A is correct. Option B mentions water's role in supporting chemical reactions, but this does not explain its solvent properties. Option C discusses water's high specific heat capacity, which relates to temperature stability rather than solubility. Finally, Option D incorrectly attributes water's dissolving ability to its small molecule size, ignoring the critical role of polarity. Therefore, the best choice is Option A.

Why the other options are wrong
  • B. This statement is true for water, but it does not explain why water is called a 'universal solvent.' It highlights water's role as a medium for reactions rather than its dissolving capabilities.
  • C. This characteristic of water refers to its ability to absorb heat without a significant change in temperature, but it does not relate to its solvent properties.
  • D. While water molecules are small, the main reason for its solvent capabilities lies in its polarity, not just its size. Thus, this statement is misleading.

Q90. Number of electron with 1=2 in an atom having atomic number 23 is:

  • A. 2
  • B. 3
  • C. 4
  • D. 5

Explanation: The atomic number of an atom indicates the total number of protons and, in a neutral atom, it also equals the number of electrons. For an atom with atomic number 23, there are 23 electrons in total. The configuration '1=2' implies that there are 3 electrons specifically in the outermost shell (1s and 2p orbitals). Therefore, option B is correct. Options A (2), C (4), and D (5) do not correctly represent the number of electrons in the given configuration for an atom with atomic number 23.

Why the other options are wrong
  • A. This option suggests that there are only 2 electrons with the configuration of 1=2, which does not account for the total number of electrons in an atom with atomic number 23.
  • C. This option incorrectly states that there are 4 electrons with the configuration of 1=2. This does not match the atomic configuration for an atom with atomic number 23.
  • D. This option suggests 5 electrons, which is also incorrect for an atom with atomic number 23. It exceeds the correct configuration.

Q91. Reaction having high activation energy are:

  • A. Spontaneous
  • B. Fast
  • C. Slow
  • D. Always exothermic

Explanation: Reactions with high activation energy are typically slow because they require a significant amount of energy to initiate. The activation energy is the minimum energy required for the reactants to form products. Thus, options indicating 'spontaneous', 'fast', or 'always exothermic' are incorrect because:Spontaneous: This option does not relate to the speed of the reaction but rather whether it can occur without external energy.Fast: High activation energy means that a reaction is slow, not fast.Always exothermic: High activation energy can be present in both exothermic and endothermic reactions.Therefore, the correct answer is 'slow', as high activation energy indicates a slower reaction rate.

Why the other options are wrong
  • A. Spontaneous reactions can occur without external energy, but they do not necessarily correlate with activation energy. High activation energy usually indicates that the reaction will require significant energy input to proceed.
  • B. Fast reactions typically have low activation energy, allowing them to proceed quickly. High activation energy indicates the reaction is likely to be slow.
  • D. Exothermic reactions release energy, but not all reactions with high activation energy are exothermic. High activation energy can occur in both endothermic and exothermic reactions.

Q92. Which of the following reagents is used to convert benzene to 2-chloro methyl benzene?

  • A. CH₃Cl/AlCl₃ followed by Cl₂ in the presence of anhydrous FeCl₃
  • B. CH₃Cl/AlCl₃ followed by Cl₂ in the presence of diffused sunlight
  • C. Cl₂/FeCl₃ followed by CH₃Cl in the presence of diffused sunlight
  • D. Cl₂/UV followed by CH₃Cl in the presence of anhydrous FeCl₃

Explanation: The correct answer is Option D: Cl₂/UV followed by CH₃Cl in the presence of anhydrous FeCl₃. This sequence begins with chlorination of benzene to form chlorobenzene under UV light, which is necessary to initiate the electrophilic aromatic substitution. The second step involves a Friedel-Crafts alkylation with CH₃Cl in the presence of anhydrous FeCl₃, which allows for the introduction of the methyl group at the ortho or para position relative to the chlorine, ultimately yielding 2-chloro methyl benzene.Options A, B, and C do not follow the correct sequence or conditions necessary for the desired transformation. Option A and B incorrectly place the Friedel-Crafts reaction before the chlorination, while option C uses the wrong order of reactions and conditions, making them unsuitable for producing 2-chloro methyl benzene.

Why the other options are wrong
  • A. This option suggests using a Friedel-Crafts alkylation followed by chlorination. While the initial step is correct, the order of reactions is not ideal for achieving the desired product.
  • B. This option indicates a Friedel-Crafts alkylation followed by chlorination using diffused sunlight. The sunlight may lead to radical reactions, which are not suitable for the desired transformation.
  • C. This option suggests a chlorination step followed by another alkylation step. However, the order is not suitable for achieving the desired product of 2-chloro methyl benzene.

Q93. According to the Kinetic molecular theory, the kinetic energy of gas molecules increases when they are

  • A. Melted from solid to liquid state
  • B. Mixed with other molecules at lower temperature
  • C. Frozen into solids
  • D. Condensed into liquids

Explanation: According to the Kinetic Molecular Theory, the kinetic energy of gas molecules is directly related to their motion. When gas molecules are melted from a solid to a liquid state, they absorb heat, which increases their kinetic energy and allows them to move more freely. This is why Option A is correct. In contrast, when gas molecules are mixed at lower temperatures (Option B), frozen into solids (Option C), or condensed into liquids (Option D), they lose kinetic energy due to reduced motion and closer molecular arrangements, making those options incorrect.

Why the other options are wrong
  • B. Mixing at lower temperatures typically results in decreased kinetic energy, as the molecules have less thermal energy to move.
  • C. When molecules freeze, they lose kinetic energy and become more ordered, resulting in reduced motion.
  • D. During condensation, gas molecules lose energy and come closer together, which decreases their kinetic energy.

Q94. According to Le Chatelier's principle, in Haber's process yield of ammonia can be increased by:

  • A. Decreasing pressure and increasing temperature
  • B. Increasing pressure and decreasing temperature
  • C. Increasing volume and decreasing temperature
  • D. Decreasing concentration of H₂

Explanation: According to Le Chatelier's principle, a system at equilibrium will adjust to counteract changes made to it. In the Haber process, the reaction is: N₂(g) + 3H₂(g) ⇌ 2NH₃(g) This reaction shows that 4 moles of gas (1 mole of nitrogen and 3 moles of hydrogen) produce 2 moles of ammonia. Thus, increasing the pressure will shift the equilibrium to the right, toward the production of ammonia, which has fewer moles of gas. Additionally, the Haber process is exothermic, so decreasing the temperature will also favor the formation of ammonia. Therefore, the correct choice is to increase pressure and decrease temperature (Option B). Options A, C, and D are incorrect for the reasons explained. Option A decreases pressure and increases temperature, both of which lead to a lower yield of ammonia. Option C increases volume, which effectively reduces pressure and shifts the equilibrium left. Option D decreases hydrogen concentration, shifting the equilibrium left as well, thereby reducing ammonia yield.

Why the other options are wrong
  • A. This option is incorrect because decreasing pressure would shift the equilibrium to the left, reducing the yield of ammonia, and increasing temperature would also favor the endothermic direction, which does not favor ammonia production.
  • C. This option is incorrect because increasing volume would decrease pressure, shifting the equilibrium to the left and reducing ammonia yield. Decreasing temperature does favor ammonia production, but the increase in volume has a counteracting effect.
  • D. This option is incorrect. Decreasing the concentration of hydrogen gas (H₂) would shift the equilibrium to the left to produce more reactants, thereby reducing the yield of ammonia.

Q95. Hyperbola isotherm is obtained when graph is plotted between:

  • A. P and 1/V
  • B. PV and V
  • C. P and V
  • D. V and 1/P

Explanation: The correct answer is P and V (Option C) because the hyperbola isotherm arises from the ideal gas law when pressure (P) is plotted against volume (V) at a constant temperature. In this relationship, as volume increases, pressure decreases, forming a hyperbolic curve.Other options are incorrect for the following reasons: Option A (P and 1/V) implies a different relationship that does not represent an isotherm. Option B (PV and V) suggests a product of variables that does not yield a hyperbolic shape. Option D (V and 1/P) also does not correspond to the characteristics of a hyperbola isotherm.

Why the other options are wrong
  • A. This option suggests a relationship between pressure and the reciprocal of volume, which does not correspond to the hyperbola isotherm.
  • B. This option implies a plot of the product of pressure and volume against volume, which does not yield the hyperbolic shape characteristic of isotherms.
  • D. This option suggests a relationship between volume and the reciprocal of pressure, which does not fit the definition of a hyperbola isotherm.

Q96. Highest energy for one quantum among radiation is:

  • A. Microwave
  • B. Infrared
  • C. Ultra violet
  • D. Visible

Explanation: The correct answer is ultraviolet radiation, which has the highest energy among the options provided. In the electromagnetic spectrum, energy is inversely related to wavelength: as the wavelength decreases, the energy of each quantum increases. Therefore, ultraviolet radiation, with its shorter wavelength, possesses greater energy than microwaves, infrared, and visible light.Microwaves and infrared radiation have longer wavelengths, resulting in lower energy quanta. While visible light is more energetic than microwaves and infrared, it is still less energetic than ultraviolet radiation, which is why it is not the correct answer.

Why the other options are wrong
  • A. Microwaves have longer wavelengths and lower energy compared to ultraviolet radiation, making them less energetic.
  • B. Infrared radiation is also characterized by longer wavelengths than ultraviolet and therefore has lower energy.
  • D. Visible light has higher energy than microwaves and infrared, but lower energy than ultraviolet radiation.

Q97. If the equilibrium expression of a reversible reaction is [C]²/[A][B].The balanced chemical equation should be

  • A. C⇌A+B
  • B. 2C⇌A+B
  • C. A+B⇌C
  • D. A+B⇌2C

Explanation: The correct balanced chemical equation is A+B⇌2C. This reflects the stoichiometry needed to yield the equilibrium expression [C]²/[A][B]. Each mole of A and B produces two moles of C, which is consistent with the squared term in the expression. The other options do not yield the correct relationship between the concentrations of reactants and products as stated in the equilibrium expression. For example, C⇌A+B would give a different equilibrium expression, and similarly for 2C⇌A+B and A+B⇌C, which also do not satisfy the required form.

Why the other options are wrong
  • A. This equation suggests that one mole of C decomposes into one mole of A and one mole of B. The equilibrium expression would be [A][B]/[C], which does not match the given expression.
  • B. This equation indicates that two moles of C decompose into one mole of A and one mole of B. The equilibrium expression would be [A][B]/[C]², which is also not correct.
  • C. This equation shows that one mole of A and one mole of B react to form one mole of C. The equilibrium expression would be [C]/[A][B], which is not the same as the given expression.

Q98. Which species contain an element with an oxidation number of +4?

  • A. CrO₄²⁻
  • B. MnO₄²⁻
  • C. H₂SO₄
  • D. Na₂CO₃

Explanation: The correct answer is Na₂CO₃, where carbon has an oxidation state of +4. To determine this, we can analyze the compound's structure: sodium (Na) has an oxidation state of +1 and oxygen (O) has an oxidation state of -2. In Na₂CO₃, there are two sodium ions contributing +2, and three oxygen ions contributing -6, which means the carbon must be +4 to balance the overall charge to zero.The other options are incorrect because:CrO₄²⁻: Chromium has an oxidation state of +6.MnO₄²⁻: Manganese has an oxidation state of +6.H₂SO₄: Sulfur has an oxidation state of +6.

Why the other options are wrong
  • A. In chromate (CrO₄²⁻), chromium has an oxidation state of +6, not +4.
  • B. In manganate (MnO₄²⁻), manganese has an oxidation state of +6, which is also not +4.
  • C. In sulfuric acid (H₂SO₄), sulfur has an oxidation state of +6, not +4.

Q99. The rate of reaction

  • A. Increases as the reaction proceeds
  • B. Decreases as the reaction proceeds
  • C. Remains the same as the reaction proceeds
  • D. May decrease or increase as the reaction proceeds

Explanation: The correct answer is Option C: Remains the same as the reaction proceeds. In specific types of reactions, such as zero-order reactions, the rate does not depend on the concentration of reactants, thus remaining constant throughout the reaction. In contrast, Option A is incorrect because most reactions slow down as reactants are consumed. Option B is also misleading; while many reactions do decrease in rate, not all do so consistently. Option D is too ambiguous and does not clarify that some reactions can maintain a constant rate, which is not applicable to the question's intent.

Why the other options are wrong
  • A. This option suggests that the rate of reaction accelerates over time, which is typically not the case for most reactions. Generally, as reactants are consumed, the concentration decreases, leading to a slower reaction rate.
  • B. This option implies that the rate of reaction diminishes over time, which can be true for many reactions as reactants are used up. However, it does not account for reactions that can maintain a constant rate under certain conditions.
  • D. This option suggests variability in the rate of reaction, which is possible in some cases. However, it is too vague and does not provide a definitive answer about the general behavior of reaction rates.

Q100. The order of chemical reaction is defined as:

  • A. The number of reactants involved in balanced equation
  • B. The number of products formed in balanced equation
  • C. The power to which the concentration of a reactant is raised in the rate equation
  • D. The rate constant of the reaction

Explanation: The correct answer is Option C: The power to which the concentration of a reactant is raised in the rate equation. The order of a chemical reaction is determined by the exponents of the concentration terms in the rate law, representing how the rate of the reaction is influenced by changes in reactant concentrations. Options A and B focus on the number of reactants and products, which do not define reaction order. Option D refers to the rate constant, which is a different concept that characterizes the speed of the reaction but does not indicate the reaction order.

Why the other options are wrong
  • A. This option is incorrect because the order of a reaction is not simply defined by the number of reactants, but rather how their concentrations affect the rate of the reaction.
  • B. This option is also incorrect as the order of a reaction pertains to reactants and their concentrations, not the products formed.
  • D. This option is incorrect because the rate constant is a proportionality factor in the rate equation, but it does not define the order of reaction.

Q101. Real gases show more positive deviation as pressure increases because of

  • A. Ionic nature
  • B. Repulsive force
  • C. Attractive forces
  • D. Non polar nature

Explanation: Real gases deviate from ideal behavior due to intermolecular forces. At high pressures, the volume occupied by gas molecules becomes significant, and repulsive forces between closely packed molecules dominate. This leads to a positive deviation from the ideal gas law, as the observed pressure is higher than predicted by the ideal gas equation. Option A is incorrect because ionic nature does not pertain to the behavior of real gases. Option C is misleading because attractive forces typically cause negative deviations at lower pressures. Option D is also incorrect as the non-polar nature of a gas does not directly dictate its deviation from ideal behavior; rather, it is the intermolecular forces at play that are more crucial.

Why the other options are wrong
  • A. This option refers to the presence of ionic bonds, which is not applicable to real gases as they primarily consist of covalent bonds and intermolecular forces.
  • C. This option is misleading. While attractive forces do play a role in gas behavior, they typically lead to negative deviation at lower pressures, not positive deviation at higher pressures.
  • D. This option suggests that non-polar gases have a unique behavior. However, the deviation from ideal behavior is not predominantly influenced by whether a gas is polar or non-polar; rather, it is the balance of attractive and repulsive forces that matters.

Q102. Common name of 1,3 benzene diol is:

  • A. Pyrogallol
  • B. Cresol
  • C. Resorcinol
  • D. Catechol

Explanation: The correct answer is Resorcinol because it specifically refers to 1,3-benzenediol, where the two hydroxyl (-OH) groups are attached to the benzene ring at the 1 and 3 positions. The other options are incorrect for the following reasons:Pyrogallol has three hydroxyl groups and is not a diol.Cresol has only one hydroxyl group and is not a diol.Catechol has its hydroxyl groups at the 1 and 2 positions, which does not match the requirement of the question.

Why the other options are wrong
  • A. Pyrogallol, also known as 1,2,3-benzenetriol, contains three hydroxyl groups on the benzene ring and is not the correct answer since it does not match the diol structure.
  • B. Cresol refers to a methylphenol with a single hydroxyl group and therefore does not fit the criteria of a diol, making it an incorrect choice.
  • D. Catechol, also known as 1,2-benzenediol, has hydroxyl groups at the 1 and 2 positions and does not match the 1,3 configuration, so it is not the correct answer.

Q103. Addition of three molecules of chlorine intro benzene prove that benzene has

  • A. 3 double bonds
  • B. Non polar
  • C. Polar
  • D. Non planar

Explanation: The correct answer is that benzene has 3 double bonds, which are part of its resonance structure. When three chlorine molecules are added, they replace the three double bonds through electrophilic aromatic substitution, confirming that benzene had these double bonds to begin with. The other options are incorrect because: Non polar: While benzene is indeed nonpolar, this does not address the question about its bonding structure.Polar: Benzene is not polar, which does not correctly describe its properties.Non planar: Benzene is a planar molecule due to its structure, making this option false.

Why the other options are wrong
  • B. While benzene is generally considered nonpolar due to its symmetrical structure, this option does not directly relate to the addition of chlorine molecules.
  • C. Benzene is not polar as it lacks a significant dipole moment; thus, this option is incorrect in the context of its chemical structure and reactions with chlorine.
  • D. Benzene is a planar molecule due to its sp2 hybridization. This option is incorrect since the planar nature of benzene is essential to its stability and reaction mechanism.

Q104. How many sigma and pi bonds are present in maleic anhydride?

  • A. 5 sigma 3 pi
  • B. 6 sigma 3 pi
  • C. 7 sigma 2 pi
  • D. 9 sigma 3 pi

Explanation: Maleic anhydride has a total of 7 sigma bonds and 2 pi bonds. Each of the carbon-carbon single bonds and carbon-oxygen single bonds contributes to the sigma count, while the double bonds between carbon atoms contribute one sigma and one pi bond each. Therefore, the count of bonds is as follows:4 C-H bonds (4 sigma)2 C=C double bond (2 sigma and 2 pi)1 C=O double bond (1 sigma and 1 pi)Summing these, we find a total of 7 sigma bonds and 2 pi bonds. The other options miscount either the sigma or pi bonds, leading to incorrect totals.

Why the other options are wrong
  • A. This option underestimates the number of sigma bonds present in maleic anhydride. While it correctly identifies the presence of pi bonds, the total count of sigma bonds is too low.
  • B. This option also undercounts the sigma bonds. It correctly identifies the number of pi bonds, but the total count of sigma bonds does not match the actual structure of maleic anhydride.
  • D. This option overestimates the number of sigma bonds. While it correctly counts the pi bonds, the total number of sigma bonds exceeds that present in maleic anhydride.

Q105. Which of the following reagent is commonly used to prepare alkyne form vicinal dihalide?

  • A. H₂ and catalyst
  • B. KOH/NaNH₂
  • C. KMnO₄
  • D. LiAlH₄

Explanation: The correct answer is LiAlH₄, which is a reducing agent that is effective in various organic reactions. However, the original question appears to have a misleading correct answer. The typical reagent used to convert alkynes into vicinal dihalides is actually Br₂ or Cl₂ in an addition reaction, not LiAlH₄. The other options, such as H₂ and catalyst, KOH/NaNH₂, and KMnO₄, do not facilitate the formation of vicinal dihalides from alkynes. H₂ with a catalyst is used for hydrogenation, KOH/NaNH₂ is used for deprotonation, and KMnO₄ is an oxidizer rather than a halogenating agent.

Why the other options are wrong
  • A. This combination is typically used for hydrogenation reactions, converting alkynes into alkenes or alkanes, rather than forming vicinal dihalides.
  • B. These strong bases are often utilized in elimination reactions or deprotonation processes but are not typically used to directly prepare vicinal dihalides from alkynes.
  • C. While KMnO₄ is a strong oxidizing agent that can oxidize alkenes and alkynes, it does not directly facilitate the formation of vicinal dihalides.

Q106. In a standard hydrogen electrode, the platinum electrode:

  • A. Reacts with hydrogen
  • B. Provides a surface for oxidation and reduction
  • C. Acts as a salt bridge
  • D. Provides voltage to the circuit

Explanation: The correct answer is that the platinum electrode provides a surface for oxidation and reduction. In a standard hydrogen electrode, the platinum serves as an inert conductor that facilitates the electrochemical reactions involving hydrogen ions and electrons. It does not react with hydrogen itself, but rather enables the oxidation of hydrogen gas to protons and the reduction of protons back to hydrogen gas. The other options are incorrect because:The electrode does not chemically react with hydrogen (Option A).It is not a salt bridge, which serves a different function in maintaining ionic balance (Option C).While it is part of the circuit, it does not generate voltage on its own (Option D).

Why the other options are wrong
  • A. This option is incorrect because the platinum electrode does not chemically react with hydrogen. Instead, it serves as a catalyst for the reaction without being consumed.
  • C. This option is incorrect because a salt bridge is a different component in electrochemical cells that maintains charge balance, whereas the platinum electrode is involved directly in the redox reactions.
  • D. This option is misleading. The platinum electrode does not provide voltage; it helps facilitate the reactions that generate voltage in the cell.

Q107. Propyne is allowed to react with hydrochloric acid two times then final product is

  • A. 1,1-dichloropropane
  • B. 1,2-dichloropropane
  • C. 2,2-dichloropropane
  • D. 1,2-dichloropropene

Explanation: When propyne (an alkyne) reacts with hydrochloric acid (HCl), the first step involves the addition of HCl across the triple bond, leading to the formation of a vinyl halide. In this case, the major product of the first addition is 1-chloropropene. On the second addition of HCl, the chlorine atom adds to the more substituted carbon atom, resulting in the formation of 1,2-dichloropropane. The other options are incorrect because:1,1-dichloropropane would require both chlorine atoms to add to the same carbon.2,2-dichloropropane would also require a similar addition pattern, which does not occur in this reaction.1,2-dichloropropene implies the presence of a double bond, which is not the case after full saturation by HCl addition.Thus, the final product after two additions of HCl to propyne is 1,2-dichloropropane.

Why the other options are wrong
  • A. This product would result if both chlorine atoms added to the same carbon atom, which is not the case in this reaction sequence. The addition occurs at different positions on the carbon chain.
  • C. This product would require both chlorine atoms to add to the same carbon atom, which contradicts the mechanism of electrophilic addition in this case.
  • D. This product suggests the presence of a double bond in the final product, which is incorrect as the reaction leads to a fully saturated alkane instead.

Q108. Reduction of carboxylic acid by using lithium aluminohydride produce

  • A. Alcohol
  • B. Acid halide
  • C. Ester
  • D. Alkane

Explanation: The correct answer is Alcohol. Lithium aluminum hydride (LiAlH4) is a powerful reducing agent that reduces carboxylic acids (RCOOH) to primary alcohols (RCH2OH) by donating hydride ions (H-) to the carbonyl carbon, effectively transforming the carbonyl (C=O) into a hydroxyl (–OH) group. The other options are incorrect because:Acid halide: This compound is formed from carboxylic acids through reaction with halogenating agents, not through reduction.Ester: Esters are synthesized through esterification, which is a condensation reaction between carboxylic acids and alcohols.Alkane: While it is possible to create alkanes from carboxylic acids, this typically requires different reagents or more complex pathways, which are not applicable here.

Why the other options are wrong
  • B. Acid halides are typically formed through the reaction of carboxylic acids with reagents like thionyl chloride, not by reduction with lithium aluminum hydride.
  • C. Esters are formed through the reaction of carboxylic acids with alcohols via esterification, not through reduction with lithium aluminum hydride.
  • D. While alkanes can be produced from carboxylic acids, this typically requires a more complex reduction process, and lithium aluminum hydride does not convert carboxylic acids directly to alkanes.

Q109. In separate vessel of volume 2000 cm³ and 1500cm³, 6g of bydrogen and 28g of nitrogen are mixed in each vessel at 25°C, ammonia formed is?N2+ 3H2⇌2NH3

  • A. More in 2 L vessel
  • B. More in 1500 cm³ vessel
  • C. Equal in both vessel
  • D. Cannot be predicted

Explanation: In this problem, we analyze the reaction of nitrogen and hydrogen to form ammonia, represented by the equation: N2 + 3H2 ⇌ 2NH3. The amounts of reactants in each vessel are critical to determining how much ammonia can be produced. In the 1500 cm³ vessel, the amounts of hydrogen (6g) and nitrogen (28g) are in a more favorable ratio for complete reaction, leading to a greater yield of ammonia. In contrast, the 2000 cm³ vessel has excess volume which can lead to unreacted nitrogen. Therefore, more ammonia is produced in the 1500 cm³ vessel. The other options are incorrect because they either misinterpret the stoichiometry or suggest an equal production without considering the limiting reactant.

Why the other options are wrong
  • A. This option suggests that the larger vessel produces more ammonia, but it doesn't take into account the limiting reactants based on the amount of hydrogen available for the reaction.
  • C. This option assumes that the reaction will produce the same amount of ammonia regardless of the volume, which is incorrect as the limiting reactant plays a crucial role in determining the yield.
  • D. This option implies that there is not enough information to determine the amount of ammonia produced, which is false as the stoichiometry of the reaction can be analyzed based on the given data.

Q110. The weakest intermolecular force fresent in liquid is?

  • A. Dipole dipole forces
  • B. Induced dipole force
  • C. Instantaneous dipole induced dipole force
  • D. Hydrogen bonding

Explanation: The correct answer is Instantaneous dipole induced dipole force, commonly known as London dispersion forces. These forces are the weakest intermolecular forces, resulting from the temporary dipoles that occur when electron density fluctuates in a molecule. In contrast, dipole-dipole forces involve permanent dipoles in polar molecules and are stronger than dispersion forces. Induced dipole forces, while weak, can vary in strength and are generally not considered weaker than instantaneous dipole-induced dipole forces. Lastly, hydrogen bonding is a much stronger interaction compared to any of the forces mentioned and is not the correct answer.

Why the other options are wrong
  • A. Dipole-dipole forces occur between polar molecules and are stronger than London dispersion forces. They are not the weakest intermolecular force.
  • B. Induced dipole forces, also known as London dispersion forces, arise from temporary shifts in electron density. While they are relatively weak, they can still be stronger than instantaneous dipole-induced dipole forces depending on the molecules involved.
  • D. Hydrogen bonding is a strong type of dipole-dipole interaction that occurs when hydrogen is bonded to highly electronegative atoms like nitrogen, oxygen, or fluorine. It is much stronger than the forces in question.

Q111. Number of sigma bond in acetylene and ethylene are?

  • A. 3 & 5
  • B. 3 & 3
  • C. 6 & 5
  • D. 5 & 6

Explanation: Acetylene (C2H2) contains 3 sigma bonds: one sigma bond between the two carbon atoms and one sigma bond each between the carbon atoms and the two hydrogen atoms. Ethylene (C2H4) also contains 3 sigma bonds: one sigma bond between the two carbon atoms and one sigma bond each between the carbon atoms and the four hydrogen atoms. The only correct option is 3 & 3, as the other options incorrectly count the number of sigma bonds in both molecules.

Why the other options are wrong
  • A. This option suggests that acetylene has 3 sigma bonds and ethylene has 5. However, ethylene only has 3 sigma bonds as well, making this option incorrect.
  • C. This option states that acetylene has 6 sigma bonds and ethylene has 5. This is incorrect because acetylene has only 3 sigma bonds, and ethylene has 3, not 5.
  • D. This option claims that acetylene has 5 sigma bonds and ethylene has 6. This is not possible as acetylene only has 3 sigma bonds and ethylene also has only 3.

Q112. Diethyl ether and Methyl n-propyl ether are

  • A. Position isomers
  • B. Functional group isomers
  • C. Metamers
  • D. Tautomer

Explanation: Diethyl ether (C4H10O) and Methyl n-propyl ether (C4H10O) have the same molecular formula but differ in the arrangement of their alkyl groups around the ether functional group. This categorizes them as metamers. In contrast, position isomers differ in the position of functional groups, which is not the case here, and functional group isomers differ in the types of functional groups, which also does not apply. Lastly, tautomerism involves isomers that rapidly interconvert, which is not relevant to these two ethers.

Why the other options are wrong
  • A. Position isomers are compounds that differ in the position of a functional group on the same carbon skeleton. Diethyl ether and Methyl n-propyl ether do not fit this definition as they are not variations of the same structure.
  • B. Functional group isomers have the same molecular formula but differ in the functional groups present. Diethyl ether and Methyl n-propyl ether do not fit this definition as they both contain ethers.
  • D. Tautomers are isomers that are in rapid equilibrium and differ in the position of protons and electrons. Diethyl ether and Methyl n-propyl ether do not exhibit tautomerism as they do not have this characteristic.

Q113. Which of the following has smallest bond angle?

  • A. C₂H₂
  • B. NH₃
  • C. H₂S
  • D. BeCl₂

Explanation: The correct answer is H₂S, which has a bond angle of approximately 104.5 degrees due to its bent molecular geometry. This angle is smaller than the bond angles in the other options. C₂H₂ has a linear structure with a bond angle of 180 degrees, NH₃ has a trigonal pyramidal shape resulting in a bond angle of about 107 degrees, and BeCl₂ also exhibits a linear geometry with a bond angle of 180 degrees. Thus, H₂S exhibits the smallest bond angle among the given choices.

Why the other options are wrong
  • A. C₂H₂ (ethyne) has a linear geometry with a bond angle of 180 degrees. Therefore, it does not have the smallest bond angle.
  • B. NH₃ (ammonia) has a trigonal pyramidal geometry with a bond angle of approximately 107 degrees, which is larger than the smallest bond angle.
  • D. BeCl₂ (beryllium chloride) has a linear structure with a bond angle of 180 degrees, which is not the smallest bond angle in this context.

Q114. Which one of the following has highest ionic character?

  • A. AlCl₃
  • B. BCl₃
  • C. PCl₃
  • D. NaH

Explanation: NaH (sodium hydride) has the highest ionic character because it consists of sodium, a highly electropositive metal, and hydrogen, which has a relatively high electronegativity compared to other elements in the options. The large difference in electronegativity leads to strong ionic bonding. In contrast, AlCl₃, BCl₃, and PCl₃ are predominantly covalent compounds. Although AlCl₃ has some ionic character due to aluminum's ability to form ionic bonds, it does not compare to the strong ionic nature of NaH. BCl₃ and PCl₃ are primarily covalent due to the similar electronegativities of boron and phosphorus with chlorine, resulting in weaker ionic character.

Why the other options are wrong
  • A. AlCl₃ is a covalent compound with some ionic character due to the presence of aluminum and chlorine. However, the ionic character is not the highest among the given options.
  • B. BCl₃ is primarily covalent in nature and has low ionic character because boron and chlorine have similar electronegativities.
  • C. PCl₃ also exhibits covalent bonding and has low ionic character, as phosphorus and chlorine have comparable electronegativities.

Q115. In the given reaction CH₃OH → HCOOH, oxidation state of carbon changes from:

  • A. -2 to 0
  • B. -2 to +2
  • C. -3 to +2
  • D. 0 to +2

Explanation: The reaction CH₃OH → HCOOH involves the oxidation of methanol to formic acid. In methanol (CH₃OH), the carbon atom has an oxidation state of -2. Upon oxidation to formic acid (HCOOH), the oxidation state of carbon increases to +2. Therefore, the change in oxidation state is from -2 to +2, which is correctly represented by Option B. Other options are incorrect because:Option A states a change from -2 to 0, which does not occur.Option C suggests a change from -3 to +2, which misidentifies the oxidation state in methanol.Option D indicates a change from 0 to +2, which is not accurate as the starting oxidation state is -2.

Why the other options are wrong
  • A. This option suggests that the oxidation state of carbon changes from -2 to 0, which is incorrect. In methanol (CH₃OH), the oxidation state of carbon is -2, but in formic acid (HCOOH), it does not reach 0.
  • C. This option incorrectly states that the oxidation state changes from -3 to +2. The carbon in methanol has an oxidation state of -2, not -3.
  • D. This option is incorrect because it suggests that the oxidation state changes from 0 to +2. The carbon in methanol has an oxidation state of -2, not 0.

Q116. For endothermic reaction, enthalpy change is:

  • A. ΔHreactant > ΔHproduct
  • B. ΔHreactant < ΔHproduct
  • C. ΔHreactant = ΔHproduct
  • D. ΔHreactant = ΔHproduct = 0

Explanation: In an endothermic reaction, the heat absorbed by the system results in products that have a greater enthalpy than the reactants. Thus, the correct relationship is ΔHreactant < ΔHproduct, indicating that energy was absorbed during the reaction. The other options are incorrect as they imply either a release of energy (Option A), no change in energy (Option C), or a nonexistent state of zero enthalpy (Option D). Understanding the energy dynamics in chemical reactions is crucial for identifying the correct answer.

Why the other options are wrong
  • A. This option suggests that the enthalpy of the reactants is greater than that of the products, which is characteristic of exothermic reactions where energy is released. Therefore, this is incorrect for endothermic reactions.
  • C. This option implies that there is no change in enthalpy between reactants and products, which is not characteristic of endothermic reactions. It suggests an isothermal process, which is incorrect here.
  • D. This option suggests that both the reactants and products have zero enthalpy, which is not applicable in this context. Endothermic reactions involve a positive change in enthalpy, so this option is incorrect.

Q117. The structure of four Chloroalkanes W X, Y and Z are shown:(CH₃)₂CHCH(Cl)CH₃ WCH2(Cl)CH3 X(CH₃)3CHCH₂Cl Y(CH₃)₂CHC(CH₃)₂Cl ZSelect the Chloroalkane classified as tertiary

  • A. W only
  • B. X only
  • C. Y only
  • D. Z only

Explanation: The correct answer is Z only. In Z, the carbon atom that carries the chlorine is attached to three other carbon atoms, making it a tertiary carbon. In contrast, W and Y are secondary chloroalkanes, as their chlorine-bearing carbon atoms are attached to two other carbon atoms. X is a primary chloroalkane, where the chlorine atom is attached to a carbon connected to only one other carbon atom. Understanding the classification of carbon atoms based on their bonding is crucial for solving this question.

Why the other options are wrong
  • A. W is a secondary chloroalkane, as the chlorine atom is attached to a carbon that is connected to two other carbon atoms.
  • B. X is a primary chloroalkane, as the chlorine atom is attached to a carbon that is connected to only one other carbon atom.
  • C. Y is a secondary chloroalkane, as the chlorine atom is attached to a carbon that is connected to two other carbon atoms.

Q118. Which one has highest bond energy?

  • A. sp-s
  • B. sp³-s
  • C. sp²-s
  • D. sp³-p

Explanation: The correct answer is sp-s because sp hybridization exhibits the highest bond energy due to its linear arrangement, allowing for maximum orbital overlap and a stronger bond. In contrast, sp³ (tetrahedral) and sp² (trigonal planar) hybridizations involve more orbitals and less effective overlap, resulting in lower bond strengths. Therefore, sp³-s, sp²-s, and sp³-p do not achieve the bond energy seen in sp-s.

Why the other options are wrong
  • B. This option involves sp³ hybridization, which has a tetrahedral geometry. While it provides a good overlap, it is generally weaker than sp due to the increased number of orbitals involved, leading to lower bond energy.
  • C. This option features sp² hybridization, which forms trigonal planar bonds. Although it has stronger bonds than sp³, it is still weaker than the sp-s bond due to less effective orbital overlap compared to the sp hybridization.
  • D. This option represents a bond between sp³ hybridized and p orbital. The sp³ hybridization decreases the bond strength compared to sp hybridization due to its geometry and the nature of the overlap, resulting in lower bond energy.

Q119. What is the IUPAC name of C₆H₅OCH₃?

  • A. Methoxybenzene
  • B. Phenoxymethane
  • C. Methyl phenyl ether
  • D. Phenyl methyl ether

Explanation: The ether has a methoxy group (CH₃O-) attached to a phenyl group (C₆H₅), so it is methoxybenzene.

Why the other options are wrong
  • B. This name is misleading as it suggests a different structure involving a phenyl group connected to a methane, rather than the correct methoxybenzene structure.
  • C. This term is not a standardized IUPAC name and can lead to confusion, as it does not reflect the proper nomenclature for the structure represented by C₆H₅OCH₃.
  • D. This option incorrectly uses 'benyl' instead of 'phenyl' and does not follow the IUPAC naming standards, leading to potential misinterpretation.

Q120. During reaction of aldehyde with HCN, the hybridization of carbon atom of carbonyl group changes to:

  • A. sp → sp²
  • B. sp³ → sp²
  • C. sp² → sp³
  • D. dsp² → sp³

Explanation: In this reaction, the carbonyl carbon in the aldehyde is initially sp² hybridized due to the presence of a double bond with oxygen. When HCN reacts with the aldehyde, the carbon atom forms a new bond with the cyanide ion, converting the double bond to a single bond. This process requires the carbon to undergo hybridization change from sp² to sp³, as it now has four single bonds (three to hydrogen or another substituent and one to the cyanide). The other options are incorrect because they either misidentify the starting hybridization of the carbon or suggest hybridizations that do not apply to aldehydes.

Why the other options are wrong
  • A. This option suggests that the carbon atom changes from sp hybridization to sp². However, this is incorrect because carbon in an aldehyde is initially sp² hybridized, not sp.
  • B. This option indicates a change from sp³ to sp² hybridization, which does not apply here. Carbon in an aldehyde is not sp³ hybridized to begin with.
  • D. This option implies a change from dsp² to sp³ hybridization. However, aldehydes do not involve dsp² hybridization, so this option is incorrect.

Q121. Acetone reacts with water in presence of catalyst produces:

  • A. propan-2-ol
  • B. propan-1,2-diol
  • C. propan-2,2-diol
  • D. propanol

Explanation: When acetone reacts with water in the presence of a catalyst, it undergoes hydration to produce propan-1,2-diol, also known as propylene glycol. This reaction involves the addition of a water molecule across the double bond of the carbonyl group in acetone, resulting in a compound with two hydroxyl groups. The other options are incorrect because propan-2-ol is not formed from this reaction; propan-2,2-diol is unrelated to the reaction of acetone with water; and 'propanol' is too vague, as it could refer to either isomer (propan-1-ol or propan-2-ol) that are not formed in this specific reaction.

Why the other options are wrong
  • A. This is an alcohol formed from the hydration of propene, not from the reaction of acetone with water.
  • C. This compound is a tertiary alcohol and does not result from the reaction of acetone with water.
  • D. This term generally refers to propan-1-ol or propan-2-ol; neither is the product of the reaction in question.

Q122. Which one show positive test with Fehling solution:

  • A. Acetophenone
  • B. Metaformaldehyde
  • C. Acetaldehyde
  • D. Benzaldehyde

Explanation: The correct answer is Acetaldehyde because it contains a reactive aldehyde group (-CHO) that readily reduces the copper(II) ions in Fehling's solution, leading to a positive result, typically indicated by a color change. In contrast, Acetophenone is a ketone and lacks the aldehyde functionality needed for this test. Metaformaldehyde, while a form of formaldehyde, is not commonly tested with Fehling's solution and does not yield a strong positive reaction. Benzaldehyde, although an aldehyde, tends to show a weaker reaction due to steric hindrance and the nature of its aromatic ring, making it less reactive in this context.

Why the other options are wrong
  • A. Acetophenone is a ketone and does not have a reactive aldehyde group. Therefore, it will not give a positive test with Fehling's solution.
  • B. Metaformaldehyde, although a form of formaldehyde, is not typically tested with Fehling's solution and does not show a clear positive reaction. It is better known for its use in other types of reactions.
  • D. Benzaldehyde is also an aldehyde; however, it does not react as strongly with Fehling's solution as acetaldehyde does. It may give a weak or no positive result.

Q123. Oxidation state of Tungsten in Na₂W₄O₁₃.H₂O is:

  • A. +5
  • B. +6
  • C. +8
  • D. Zero

Explanation: In the compound Na₂W₄O₁₃.H₂O, the sodium ions (Na+) contribute a total charge of +2. The three oxygen atoms (O) in the oxide group typically have an oxidation state of -2 each, contributing a total of -6. Water (H₂O) contributes no additional charge for the calculation related to the oxidation state of Tungsten. To balance the total charge of the compound, where the overall charge is neutral, the oxidation state of Tungsten must be +6. This means Tungsten's contribution (+6) along with the contributions from sodium (+2) and oxygen (-6) leads to a balanced charge of 0. Therefore, the correct oxidation state is +6, and the other options either miscalculate the balance or suggest incorrect states based on the context of the compound.

Why the other options are wrong
  • A. This oxidation state does not correctly account for the total charge balance in the compound. If Tungsten had an oxidation state of +5, the total oxidation state would not match that of the overall compound.
  • C. An oxidation state of +8 is too high for Tungsten in this compound, leading to an imbalance in the overall charge when considering the other elements present.
  • D. An oxidation state of zero indicates that Tungsten is in its elemental form, which does not apply here as it is part of a compound and must exhibit a positive oxidation state.

Q124. The relationship of (+) tartaric acid and (-) Tartaric acid are:

  • A. Geometric isomers
  • B. Enantiomers
  • C. Diastereomers
  • D. Planar

Explanation: The correct answer is enantiomers because (+) tartaric acid and (-) tartaric acid are non-superimposable mirror images of each other due to their chiral centers. This characteristic defines them as enantiomers. The other options are incorrect because geometric isomers pertain to different arrangements around a double bond or ring, which is not applicable here, and diastereomers are not mirror images. Additionally, while the term 'planar' describes a structural aspect, it does not relate to the concept of stereoisomer classification.

Why the other options are wrong
  • A. Geometric isomers, also known as cis-trans isomers, differ in the spatial arrangement of atoms or groups around a double bond or a ring structure. However, tartaric acid does not exhibit this type of isomerism as it does not have such structural features.
  • C. Diastereomers are stereoisomers that are not mirror images of each other and have different physical properties. Since (+) and (-) tartaric acid are mirror images, they cannot be classified as diastereomers.
  • D. The term 'planar' refers to molecules that lie in the same geometric plane. While tartaric acid has a planar structure, this term does not accurately describe the relationship between the two forms of tartaric acid.

Q125. Which of the following compound has lower Lattice Energy?

  • A. LiCl
  • B. KCl
  • C. CaCl₂
  • D. C₆H₁₂O

Explanation: The correct answer is KCl, as it has the lowest lattice energy among the compounds listed. Lattice energy is influenced by the size and charge of the ions involved; smaller ions and higher charges generally lead to greater lattice energies. In the case of KCl, potassium (K⁺) is larger than lithium (Li⁺) in LiCl, resulting in lower lattice energy. CaCl₂ has a much higher lattice energy due to the presence of the divalent calcium ion (Ca²⁺), which has a higher charge and thus creates a stronger ionic bond with the chloride ions. C₆H₁₂O, being a molecular compound, does not have lattice energy in the context of ionic compounds, which makes it irrelevant to the question.

Why the other options are wrong
  • A. LiCl consists of lithium and chloride ions. Lithium is a small cation, which usually results in a relatively high lattice energy. Therefore, it is not the compound with the lowest lattice energy.
  • C. CaCl₂ has calcium as a divalent cation (Ca²⁺) and two chloride ions. The presence of the Ca²⁺ ion, with its greater charge, results in a much higher lattice energy compared to KCl.
  • D. C₆H₁₂O (glucose) is a molecular compound that does not have a lattice structure like the ionic compounds listed. Hence, it does not have lattice energy in the same context, making it an incorrect choice for this question.

Q126. Which statement applies to both ideal and real gases

  • A. Collision between molecules are elastic
  • B. Molecules are in constant random motion
  • C. Molecules attract each other
  • D. Molecules have zero size

Explanation: The correct answer is Option B: Molecules are in constant random motion, which applies to both ideal and real gases. This behavior is a fundamental property of gases, regardless of their idealized or real nature.Option A is incorrect because, while elastic collisions are a characteristic of ideal gases, real gases do not always exhibit this behavior due to intermolecular forces.Option C is incorrect as this statement applies to real gases but not to ideal gases, which are defined by the absence of intermolecular attractions.Option D is also incorrect because ideal gas theory assumes molecules are point particles with no volume, but real molecules have a finite size and volume.

Why the other options are wrong
  • A. This statement is true for ideal gases but does not apply to real gases, as real gas molecules experience intermolecular forces that can lead to inelastic collisions.
  • C. This statement is generally true for real gases due to intermolecular forces; however, ideal gases are defined to have no such attractions. Therefore, it does not apply to both.
  • D. This statement holds for ideal gases, but in reality, molecules do have volume, making this statement false for real gases.

Q127. Reaction of 2-Bromobutane with alcoholic KOH yields:

  • A. 2-Butanol
  • B. 2-Butene
  • C. 2-Butyne
  • D. 1-Butanol

Explanation: The reaction of 2-Bromobutane with alcoholic KOH is an elimination reaction that predominantly follows an E2 mechanism. In this reaction, KOH acts as a base, abstracting a proton from the β-carbon, leading to the formation of the alkene, 2-Butene, while eliminating HBr. The other options are incorrect because:2-Butanol: This would only form through a substitution reaction, which is not favored in this context.2-Butyne: While it is possible to form alkynes through elimination, this specific reaction does not lead to 2-Butyne as the major product.1-Butanol: Similar to 2-Butanol, this alcohol would result from substitution, not elimination, making it an incorrect choice.Overall, 2-Butene is the major product formed under the conditions described.

Why the other options are wrong
  • A. This option represents an alcohol that would form through a substitution reaction with KOH. However, since KOH is in alcoholic solution, elimination is favored, making this option incorrect.
  • C. This option suggests the formation of an alkyne. While elimination reactions can lead to alkyne formation under certain conditions, the specific reaction of 2-Bromobutane with alcoholic KOH primarily yields alkenes, making this option incorrect.
  • D. This option represents a primary alcohol that would result from a nucleophilic substitution reaction. However, since alcoholic KOH promotes elimination, this option is also incorrect.

Q128. The smallest repeating pattern from which the lattice is built in a crystalline solid is called

  • A. Crystallite
  • B. Amorphous region
  • C. Unit cell
  • D. Crystal lattice

Explanation: The correct answer is Unit cell, as it is defined as the smallest repeating pattern from which the entire lattice structure of a crystalline solid is constructed. Each unit cell represents the entire symmetry and arrangement of the atoms or molecules within the crystal. Crystallite refers to a small, ordered region within a material, but it is not the fundamental repeating unit. Amorphous region indicates an area without a defined structure, which contradicts the concept of a repeating pattern. Crystal lattice describes the overall structure formed by many unit cells, but it is not the smallest repeating unit itself.

Why the other options are wrong
  • A. A crystallite is a small region within a material that has a uniform structure, but it is not the smallest repeating unit itself. Instead, it is made up of multiple unit cells.
  • B. An amorphous region lacks a defined crystalline structure and does not exhibit a repeating pattern, making it the opposite of what is described in the question.
  • D. A crystal lattice refers to the three-dimensional arrangement of atoms or molecules in a crystalline solid, but it is not the smallest repeating unit; rather, it is made up of many unit cells.

Q129. Keeping temperature constant, if pressure is increased, density of gas will

  • A. Increases
  • B. Decreases
  • C. Gets doubled
  • D. Remains same

Explanation: According to the ideal gas law, which states that PV = nRT, if temperature (T) is held constant and pressure (P) is increased, the volume (V) must decrease. Since density (ρ) is defined as mass (m) divided by volume (V), an increase in pressure results in a decrease in volume, thereby increasing density. Therefore, the correct answer is that the density of the gas will increase. Options B, C, and D are incorrect because: Option B: Density does not decrease with increased pressure at constant temperature.Option C: There is no fixed ratio or doubling effect applicable in this case.Option D: Density will not remain the same, as pressure changes will affect the gas volume.

Why the other options are wrong
  • B. This option is incorrect because increasing pressure does not lead to a decrease in density when temperature remains constant. Instead, it causes the gas to compress, resulting in higher density.
  • C. This option is misleading as it suggests a specific quantitative change without basis. While density increases with pressure, it doesn't necessarily double; the relationship is not linear but rather described by the ideal gas law.
  • D. This option is incorrect because maintaining constant temperature while increasing pressure will cause the gas to condense, leading to an increase in density rather than keeping it the same.

Q130. Orientation of molecule is more important in following cases except:

  • A. High Pressure
  • B. Complex molecules
  • C. Polyatomic molecules
  • D. Low pressure

Explanation: The correct answer is Low pressure (Option D) because, under low pressure conditions, the molecules are farther apart, leading to fewer collisions and interactions. As a result, the orientation of molecules has less impact on the reaction outcomes compared to conditions of high pressure, where increased molecular interactions make orientation more critical. High Pressure (Option A), Complex molecules (Option B), and Polyatomic molecules (Option C) all involve scenarios where molecular orientation plays a significant role in determining reaction pathways and efficiencies, thus making them incorrect choices.

Why the other options are wrong
  • A. At high pressure, the orientation of molecules can significantly impact reaction rates and outcomes due to increased collision frequency and energy. Thus, orientation is important.
  • B. In complex molecules, the orientation is crucial because the arrangement of functional groups can influence reactivity and interactions, making it an important factor.
  • C. Polyatomic molecules often have multiple bonds and angles that dictate their behavior in reactions, emphasizing the importance of orientation in their interactions.

Q131. IUPAC name of chloroform is:

  • A. Methylchloride
  • B. Methyltrichloride
  • C. Trichloromethane
  • D. Chloromethane

Explanation: The correct IUPAC name for chloroform is trichloromethane, which indicates that the compound has three chlorine atoms bonded to a single carbon atom in the methane structure. The other options are incorrect because:Methylchloride refers to chloromethane, which only contains one chlorine atom.Methyltrichloride is not a recognized IUPAC name and incorrectly combines terminology.Chloromethane is another name for methyl chloride, which, like methylchloride, has only one chlorine atom and does not describe chloroform accurately.Thus, trichloromethane is the only name that accurately represents the chemical structure of chloroform.

Why the other options are wrong
  • A. This name refers to chloromethane, which has only one chlorine atom. It does not accurately describe chloroform, which has three chlorine atoms attached to a methane molecule.
  • B. This name suggests a compound with a methyl group and three chlorine atoms, which is misleading and not in standard IUPAC nomenclature. The correct name does not include 'methyl' as a prefix.
  • D. This name refers to a different compound, chloromethane (or methyl chloride), which has only one chlorine atom attached to the methane. Therefore, it does not apply to chloroform.

Q132. Which among the following will react with ammonical cuprous chloride:

  • A. 1-butene
  • B. 1-butyne
  • C. 2-butene
  • D. 2-butyne

Explanation: Ammonical cuprous chloride is known to react with terminal alkynes to form a complex through nucleophilic attack. Among the options, 1-butyne is the only terminal alkyne that can react with this reagent, while the other options are either alkenes (1-butene and 2-butene) or an internal alkyne (2-butyne), which do not exhibit the same reactivity. Therefore, 1-butyne is the correct answer.

Why the other options are wrong
  • A. 1-butene is an alkene and does not react with ammonical cuprous chloride. Alkenes generally do not undergo the same types of reactions as alkynes with this reagent.
  • C. 2-butene is also an alkene and, like 1-butene, does not react with ammonical cuprous chloride due to its lack of terminal alkyne characteristics.
  • D. 2-butyne is an internal alkyne and does not react with ammonical cuprous chloride in the same manner as terminal alkynes. Its internal structure hinders the reaction.

Q133. Which of the following is not a crystalline solid?

  • A. KCl
  • B. Fe metal
  • C. Glass
  • D. Rhombic S

Explanation: The correct answer is Glass, as it is an amorphous solid and does not exhibit the ordered structure characteristic of crystalline solids. In contrast, KCl, Fe, and Rhombic S are all examples of crystalline solids. KCl forms a lattice structure of ions, Fe has a regular arrangement of atoms in its metallic structure, and Rhombic S has a defined crystalline form. Thus, the other options are not correct as they all exhibit the properties of crystalline solids.

Why the other options are wrong
  • A. Potassium chloride (KCl) is an ionic compound that forms a crystalline structure, characterized by its orderly arrangement of ions.
  • B. Iron (Fe) is a metallic element that forms a crystalline solid with a regular arrangement of atoms, typically exhibiting a body-centered cubic structure.
  • D. Rhombic sulfur (Rhombic S) is a crystalline form of sulfur that has a well-defined, ordered structure, making it a crystalline solid.

Q134. Which of the following structural change in water molecule leads to the low density of ice?

  • A. Formation of ionic bonds
  • B. Expansion due to hydrogen bonding
  • C. Increased kinetic energy
  • D. Loss of polarity in molecules

Explanation: When water freezes, the molecules form a crystalline structure maintained by hydrogen bonds, which causes them to be arranged further apart compared to when they are in liquid form. This expansion results in ice having a lower density than liquid water, allowing ice to float. The incorrect options do not accurately describe the behavior of water molecules during freezing: ionic bonds do not play a role, increased kinetic energy is associated with the liquid state, and the polarity of water molecules remains intact and is crucial for hydrogen bonding.

Why the other options are wrong
  • A. This option is incorrect because water molecules primarily form hydrogen bonds, not ionic bonds, which do not significantly affect the density of ice.
  • C. This option is incorrect because increased kinetic energy typically leads to a state of matter that is less structured (liquid) rather than the orderly lattice structure found in ice.
  • D. This option is incorrect because water retains its polarity even in solid form. The polarity of water molecules is essential for the formation of hydrogen bonds.

Q135. Which of the following reaction will move backward by decreasing pressure?

  • A. A ⇌ T + S
  • B. 2A ⇌ 3C
  • C. K ⇌ L
  • D. H + 2M ⇌ 2B + 2D

Explanation: The correct answer is A ⇌ T + S. According to Le Chatelier's principle, when pressure is decreased, the equilibrium will shift towards the side with fewer moles of gas. In this case, the left side has only 1 mole (A), while the right side has 2 moles (T + S). Therefore, decreasing the pressure will cause the reaction to shift backward to the left.For option B (2A ⇌ 3C), the reaction would shift to the right (forward) because the right side has more moles (3) than the left (2). In option C (K ⇌ L), we cannot determine the effect of pressure without knowing the number of moles on each side. Finally, in option D (H + 2M ⇌ 2B + 2D), there are 3 moles on the left and 4 on the right, so a decrease in pressure would also favor the forward reaction.

Why the other options are wrong
  • B. In this case, decreasing pressure will favor the side with more moles of gas, which is the right side (3 moles). Therefore, the reaction would move forward, not backward.
  • C. This reaction does not specify the number of moles on either side, making it impossible to determine the direction of the shift without additional information. Thus, it does not clearly move backward when pressure decreases.
  • D. This reaction has 3 moles of gas on the left (1 + 2) and 4 moles on the right (2 + 2). A decrease in pressure would favor the side with more moles, hence it would move forward.

Q136. If voltage across a resistor is doubled then its resistance will become: (temperature and physical state of the conductor remains constant).

  • A. Doubled
  • B. Half
  • C. Four Times
  • D. Remains Constant

Explanation: The correct answer is that the resistance remains constant. According to Ohm's Law, defined as V = I * R (where V is voltage, I is current, and R is resistance), the resistance (R) is a characteristic of the material and does not change with the voltage applied, as long as temperature and physical conditions are stable. The other options incorrectly suggest that resistance is affected by changes in voltage. For example, doubling the voltage does not imply a doubling of resistance, nor does it imply any other changes in resistance. Thus, the resistance remains the same.

Why the other options are wrong
  • A. This option suggests that if the voltage is doubled, the resistance would also double. However, according to Ohm's Law, resistance is a property of the material and does not change with voltage.
  • B. This option indicates that doubling the voltage would halve the resistance. This is incorrect because resistance remains constant regardless of voltage changes, provided other conditions are stable.
  • C. This option implies that resistance would quadruple if the voltage is doubled. This is not true; resistance does not change with voltage in a linear system.

Q137. A particle is moving in a uniform circular path whoseprojection is executing simple harmonic motion on horizontal diameter. The ratio of instantaneous velocity to the maximum velocity of the projection while passing through the center is:964

  • A. 1:1
  • B. 1:2
  • C. 2:1
  • D. 1:4

Explanation: In the context of a particle moving in a uniform circular path, the maximum velocity is reached at the center of the motion. At this point, the instantaneous velocity is equal to the maximum velocity, leading to a ratio of 1:1. Other options suggest incorrect relationships, as they imply that the instantaneous velocity is either less than or greater than the maximum velocity at the center, which contradicts the principles of uniform circular motion and simple harmonic motion.

Why the other options are wrong
  • B. This ratio suggests that the instantaneous velocity is half of the maximum velocity, which is not true, as the instantaneous velocity at the center is equal to the maximum velocity.
  • C. This ratio implies that the instantaneous velocity is double the maximum velocity; this is incorrect, as the maximum velocity is the highest value reached.
  • D. This ratio suggests that the instantaneous velocity is a quarter of the maximum velocity, which is incorrect for this scenario.

Q138. The option that shows the conditions used by Laplace for connecting the velocity of sound is options medium used thermodynamics process1 solid adiabatic 2 liquids isobaric 3 gas adiabatic 4 gas isothermal

  • A. 1 solid adiabatic
  • B. 2 liquids isobaric
  • C. 3 gas adiabatic
  • D. 4 gas isothermal

Explanation: The correct answer is option 3: gas adiabatic. Laplace's conditions for the velocity of sound specifically apply to gases when they undergo adiabatic processes, meaning no heat is exchanged with the environment during the sound propagation. In contrast, option 1 refers to solids, which are not the focus of Laplace's conditions, and option 2 mentions liquids under isobaric conditions, which also do not align with Laplace's primary work. Option 4, while relevant to gas behavior, pertains to isothermal conditions rather than the adiabatic ones that Laplace described.

Why the other options are wrong
  • A. This option refers to sound propagation in solids under adiabatic conditions. While sound can travel in solids, Laplace's conditions specifically relate to gases.
  • B. This option describes sound propagation in liquids under isobaric (constant pressure) conditions. However, Laplace's conditions do not primarily focus on liquids.
  • D. This option refers to sound propagation in gases under isothermal (constant temperature) conditions. While sound can propagate under isothermal conditions, Laplace's primary focus was on adiabatic processes.

Q139. If different colored light beams have same total energy, which color beam will contain the smallest number of photons?

  • A. Violet
  • B. Blue
  • C. Green
  • D. Red

Explanation: In this question, we are asked to determine which color of light beam, given the same total energy, would consist of the smallest number of photons. Since the energy of a photon is inversely proportional to its wavelength (E = hc/λ), shorter wavelengths correspond to higher energy. Therefore, violet light, which has the shortest wavelength, will have the highest energy per photon. This means that for a constant total energy, fewer photons are required to make up that energy. Other colors like blue, green, and red have longer wavelengths, resulting in lower energy per photon, thus requiring more photons to equal the same total energy. Hence, the correct answer is violet.

Why the other options are wrong
  • B. Blue light has a shorter wavelength than green and red light but longer than violet, implying it contains more photons than violet for the same total energy.
  • C. Green light has a longer wavelength than blue and violet, indicating it has lower energy per photon. Thus, it would have more photons than violet for the same total energy.
  • D. Red light has the longest wavelength among the options, meaning it has the lowest energy per photon. Therefore, red would contain the largest number of photons for the same total energy, not the smallest.

Q140. A patient is injected with a radioactive isotope to trace blood flow and detect circulation issues. The isotope used is more likely to be:

  • A. Iodine-131
  • B. Phosphorus-32
  • C. Cobalt-60
  • D. Sodium-24

Explanation: The correct answer is Sodium-24, as it is commonly used in medical imaging to trace blood flow and detect circulation issues. Its emission of gamma rays allows for effective imaging. In contrast, Iodine-131, while useful in thyroid diagnostics, does not serve the purpose of tracing blood flow. Phosphorus-32 is primarily used for treating blood disorders rather than for imaging, and Cobalt-60 is mainly associated with cancer treatment. Therefore, Sodium-24 is the most appropriate choice for the scenario described.

Why the other options are wrong
  • A. Iodine-131 is primarily used in thyroid function tests and treatments, not typically for tracing blood flow.
  • B. Phosphorus-32 is used mainly in the treatment of certain blood disorders and not for imaging blood flow or circulation.
  • C. Cobalt-60 is utilized in cancer treatment and radiation therapy, rather than in diagnosing circulation issues.

Q141. Water flows through a pipe of 0.02 m2 with a speed of 3 m/s. The pipe narrows to 0.01 m2. The speed in narrower section is:

  • A. 1.5 m/s
  • B. 3 m/s
  • C. 6 m/s
  • D. 9 m/s

Explanation: To solve this problem, we can apply the principle of continuity, which states that the product of the cross-sectional area (A) and the velocity (v) of a fluid must remain constant along a streamline. This can be expressed mathematically as A1v1 = A2v2. In this case, we have:A1 = 0.02 m2, v1 = 3 m/s, A2 = 0.01 m2We need to find v2. Plugging the values into the equation:0.02 m2 * 3 m/s = 0.01 m2 * v2This simplifies to:0.06 = 0.01 * v2Solving for v2 gives us v2 = 6 m/s. Therefore, the correct answer is option C.Options A, B, and D are incorrect because they do not adhere to the principle of continuity in fluid dynamics.

Why the other options are wrong
  • A. This option is incorrect. It suggests a decrease in speed that does not comply with the principle of continuity, which states that if the area decreases, the speed must increase.
  • B. This option is also incorrect. It indicates that the speed remains constant, which is not possible since the area of the pipe has decreased.
  • D. This option is incorrect. It suggests an increase in speed that is too large given the change in cross-sectional area.

Q142. In the human circulatory system, turbulent blood flow is mostlikely to occur when the:

  • A. Vessel diameter is very small
  • B. Velocity of blood is very low
  • C. Blood flows through a clogged vessel
  • D. Blood viscosity increases

Explanation: Turbulent blood flow occurs when the flow of blood becomes chaotic and irregular, which is often the result of obstructions or changes in velocity. In this case, when blood flows through a clogged vessel, the obstruction disrupts the regular flow pattern, increasing turbulence. The other options describe conditions that either promote laminar flow or are less conducive to turbulence. Specifically, small vessel diameter and low blood velocity both favor laminar flow, while increased blood viscosity also tends to stabilize the flow, reducing turbulence.

Why the other options are wrong
  • A. Turbulent flow is less likely in small diameter vessels, as laminar flow predominates due to the lower velocity and smooth surface. This option does not promote turbulence.
  • B. Low blood velocity typically leads to laminar flow rather than turbulence. Turbulence is generally associated with higher velocities and disruptions in flow patterns.
  • D. Increased viscosity typically results in a more stable and laminar flow, as thicker fluids resist changes in flow patterns. This option would not lead to turbulent flow.

Q143. A conducting ring is placed near a current-carrying coil. As the current in the coil increases, the induced current in the ringflows:

  • A. In the direction of magnetic field
  • B. To increases the magnetic flux
  • C. To oppose increasing magnetic flux
  • D. Randomly without a definite direction

Explanation: The correct answer is C: 'To oppose increasing magnetic flux'. According to Lenz's Law, when the current in a coil increases, the magnetic field it produces increases, leading to a change in magnetic flux through the conducting ring placed nearby. The induced current in the ring will flow in a direction that creates a magnetic field opposing this increase, thereby attempting to decrease the overall magnetic flux through the ring.Option A is incorrect as it suggests the induced current flows in the same direction as the magnetic field, which contradicts Lenz's Law. Option B is misleading since the induced current does not flow to increase magnetic flux but rather to oppose its increase. Option D is incorrect because induced currents have a definite direction based on the principles of electromagnetic induction.

Why the other options are wrong
  • A. This option is incorrect because the induced current does not flow in the direction of the magnetic field. Instead, it flows in opposition to the change in magnetic flux according to Lenz's Law.
  • B. This option is misleading. While induced current can affect magnetic flux, it does not flow to increase magnetic flux; rather, it flows to oppose changes in it.
  • D. This option is incorrect as induced currents have a specific direction dictated by the change in magnetic flux, not a random one.

Q144. In progressive waves, energy is transferred from one point toanother through:

  • A. Circular motion of particles
  • B. Oscillatory motion of particles
  • C. Rotation of particles
  • D. Translation of particles

Explanation: In progressive waves, energy is transmitted through oscillatory motion of particles, which means that the particles move back and forth around an equilibrium position without permanently displacing from their original location. This oscillation allows the energy to travel through the medium, enabling the wave itself to propagate. Option A (Circular motion of particles) is incorrect because it does not describe the energy transfer mechanism in progressive waves. Option C (Rotation of particles) is also incorrect, as rotation does not facilitate energy transfer in wave motion. Option D (Translation of particles) is misleading, as it suggests a straight-line movement instead of the necessary oscillatory behavior required for energy transfer in progressive waves.

Why the other options are wrong
  • A. This option refers to a type of motion typically seen in circular waves or orbits, which does not describe the mechanism of energy transfer in progressive waves.
  • C. This option suggests a fixed rotation, which does not align with how energy is propagated in progressive waves, as energy transfer does not rely on rotational movement.
  • D. This option implies a linear movement of particles, which is not characteristic of how energy is conveyed in progressive waves, where oscillation is key.

Q145. A capacitor is connected to an ac source. If theffrequency of fthe AC source is doubled the current in a purely capacitive circuit will

  • A. Be doubled
  • B. Remains Unchanged
  • C. Become Half
  • D. Becomes zero

Explanation: In a purely capacitive circuit, the relationship between current (I) and frequency (f) can be described by the formula I = V * ω * C, where V is the voltage, ω (angular frequency) is related to the frequency by the equation ω = 2πf, and C is the capacitance. When the frequency of the AC source is doubled, the angular frequency (ω) also doubles, directly leading to a doubling of the current (I). Therefore, the correct answer is that the current will be doubled.Other options are incorrect because:Remains Unchanged: This is incorrect because increasing frequency affects current directly.Become Half: This is incorrect as it contradicts the direct proportionality of current to frequency.Becomes zero: This is also incorrect since doubling frequency does not lead to a cessation of current.

Why the other options are wrong
  • B. This option is incorrect. The current in a capacitive circuit is dependent on the frequency of the AC source. If the frequency increases, the current cannot remain the same.
  • C. This option is also incorrect. If the frequency is doubled, the current would not decrease; instead, it would increase. Therefore, the current cannot become half.
  • D. This option is incorrect as well. Doubling the frequency does not lead to the current becoming zero; rather, it increases the current in a capacitive circuit.

Q146. When thermal energy is transferred from a hot object to acold one, the change occurs in the hot object as

  • A. Increases in internal energy
  • B. Decrease in internal energy
  • C. Increase in temperature
  • D. Increase in heat content

Explanation: The correct answer is Option B: Decrease in internal energy. When thermal energy is transferred from a hot object to a cold one, the hot object loses thermal energy, which results in a decrease in its internal energy. This is consistent with the second law of thermodynamics, which states that heat flows from a hotter object to a cooler one until thermal equilibrium is reached.Option A is incorrect because it suggests that the hot object gains internal energy, which contradicts the heat transfer process. Option C is also incorrect, as the temperature of the hot object actually decreases during this process, not increases. Lastly, Option D is misleading; the hot object does not increase its heat content, but rather decreases it as it loses energy to the cold object.

Why the other options are wrong
  • A. This option suggests that the hot object gains energy, which contradicts the principle of heat transfer where thermal energy flows from hot to cold.
  • C. This option is incorrect because the temperature of the hot object would actually decrease as it loses thermal energy to the cold object.
  • D. This is incorrect because the hot object is losing heat content when thermal energy is transferred, not gaining it.

Q147. The electric potential at a point due to a point charge is 100J/C. If a test charge of magnitude 1C placed at that point is replaced with a 2C charge, then the physical quantity that will change is

  • A. Electric Field at that point
  • B. Electric potential at that point
  • C. Electric Potential Energy of the system
  • D. Temperature

Explanation: The correct answer is Electric potential at that point. The electric potential at a specific point in space due to a point charge is defined as the work done per unit charge in bringing a small positive test charge from infinity to that point. In this case, even though the test charge is replaced from 1C to 2C, the potential due to the source charge remains constant. Therefore, the electric potential itself does not change.On the other hand, the Electric Field at that point does not change as it is a property of the source charge. The Electric Potential Energy of the system will change because it is calculated as the product of the electric potential and the charge, which will increase when the 1C charge is replaced with a 2C charge. Finally, Temperature is unrelated to the electrical properties being discussed and thus remains unchanged.

Why the other options are wrong
  • A. The electric field is related to the force experienced by a charge in an electric field, but it does not directly change with the magnitude of the test charge placed at that point. The electric field is determined by the source charge, not the test charge itself.
  • C. The electric potential energy will change because it depends on both the electric potential at that point and the magnitude of the charge placed there. Replacing a 1C charge with a 2C charge will increase the potential energy due to the increased charge.
  • D. Temperature is not directly related to electric potential or the charges involved in this scenario. It remains unchanged regardless of the changes made to the electric charges.

Q148. When two identical waves arrive in phase at same poin a region at the same time the resultant displacement isequal to

  • A. Displacement of a single wave
  • B. Difference of their displacements
  • C. Sum of their displacements
  • D. Product of their displacements

Explanation: When two identical waves arrive in phase at the same point, their displacements combine through the principle of superposition. This means that instead of remaining equal to just one wave's displacement (Option A), or being the difference (Option B) or the product (Option D) of their displacements, the correct resultant displacement is the sum of their displacements (Option C). This results in a wave with greater amplitude, demonstrating how constructive interference works in wave mechanics.

Why the other options are wrong
  • A. This option is incorrect because when two identical waves are in phase, their displacements add together rather than remaining equal to just one of the waves.
  • B. This option is incorrect as it suggests subtracting the displacements, which does not apply in the case of in-phase waves. In-phase waves combine their effects additively.
  • D. This option is incorrect because the resultant displacement of waves is not calculated by multiplying their displacements. Instead, it is determined by their sum when they are in phase.

Q149. Two spectral lines in the Hydrogen atom spectrum are close together. This likely means:

  • A. The energy difference is zero
  • B. The energy difference is small
  • C. The light intensity is low
  • D. The atom becomes unstable

Explanation: In the Hydrogen atom spectrum, spectral lines represent transitions between different energy levels. When two spectral lines are close together, it indicates that the energy difference between the two levels involved in these transitions is small. This is because the energy levels are quantized and can be very close for certain transitions, especially in hydrogen where the energy levels converge at higher levels. Therefore, option B is correct. Option A is incorrect because a zero energy difference would mean the lines overlap instead of being distinct. Option C incorrectly associates light intensity with line spacing, and option D is misleading as the mere presence of closely spaced lines does not imply instability in the atom.

Why the other options are wrong
  • A. This option is incorrect because if the energy difference were zero, the two lines would overlap completely rather than appear as two close lines.
  • C. This option is incorrect because the intensity of the light does not directly relate to the spacing of the spectral lines; it refers to the brightness of the observed spectrum.
  • D. This option is incorrect; the proximity of spectral lines does not imply instability in the atom. Stability pertains to the overall configuration and energy states, not merely the closeness of spectral lines.

Q150. What will potential difference, if a wire has resistance of 10 ohms and current 2A flow through it:

  • A. 5V
  • B. 10V
  • C. 20V
  • D. 40V

Explanation: To find the potential difference across a wire, we can use Ohm's law, which states that Voltage (V) equals Current (I) multiplied by Resistance (R). For this question, we have:Resistance (R) = 10 ohms and Current (I) = 2A.Applying Ohm's Law: V = I × R = 2A × 10Ω = 20V.Therefore, the correct answer is 20V (Option C). The other options are incorrect because:5V and 10V do not correspond to the correct calculations based on the given resistance and current.40V suggests a higher current than is provided, making it impossible under the given conditions.

Why the other options are wrong
  • A. This option represents a potential difference calculated incorrectly. Using Ohm's law, this value does not correspond to the given resistance and current.
  • B. This option also represents an incorrect calculation. It is the product of a lower current value than given, hence does not reflect the proper application of Ohm's law.
  • D. This option is incorrect as it suggests a potential difference that would require a current of 4A, which exceeds the given current of 2A with the provided resistance.

Q151. According to the particle model of light, a photon is:

  • A. A Particle with mass and charge
  • B. A quantum of energy with zero rest mass and zero charge
  • C. A continuous energy wave
  • D. A particle that travels slower than light

Explanation: The correct answer is that a photon is a quantum of energy with zero rest mass and zero charge. This is supported by the principles of quantum mechanics, which state that photons exhibit both particle-like and wave-like behavior. Importantly, photons are massless, allowing them to travel at the speed of light, which is approximately 299,792 kilometers per second in a vacuum.Option A is incorrect because it incorrectly attributes mass and charge to photons, which they do not possess. Option C, while touching on the wave nature of light, fails to recognize that photons are discrete packets of energy rather than a continuous wave. Finally, Option D is incorrect since it states that a photon travels slower than light, which contradicts the fundamental properties of light as described in physics.

Why the other options are wrong
  • A. This option is incorrect because a photon is defined as a massless particle and does not carry any charge.
  • C. This option is incorrect as it describes the wave nature of light, not its particle aspect. The photon is a discrete packet of energy, not a continuous entity.
  • D. This option is incorrect because photons travel at the speed of light in a vacuum, which is the maximum speed limit in the universe.

Q152. The current in forward biased PN junction is mainly due to:

  • A. Majority carriers
  • B. Minority carriers
  • C. leakage carrier
  • D. Thermionic emission

Explanation: In a forward-biased PN junction, the external voltage reduces the potential barrier, allowing majority carriers (electrons in n-type and holes in p-type) to move across the junction, resulting in a flow of current. This is why option A, which refers to majority carriers, is correct. Option B (minority carriers) is incorrect, as they contribute little to the current in this condition. Option C (leakage carrier) is not a standard term in semiconductor discussions, thus it does not apply here. Option D (thermionic emission) is also incorrect as it describes a different phenomenon related to electron emission from heated surfaces, not the current flow in a PN junction.

Why the other options are wrong
  • B. This option is incorrect because minority carriers play a minimal role in the conduction process of a forward-biased PN junction compared to majority carriers.
  • C. This option is incorrect since 'leakage carriers' are not a recognized term in semiconductor physics; they do not specifically describe the charge carriers responsible for current in a forward-biased junction.
  • D. This option is incorrect because thermionic emission refers to the emission of electrons from a heated surface, which is not the primary mechanism for current flow in a forward-biased PN junction.

Q153. Stationary waves are formed in a stretched string of 2m length, such that two vibrating loops are formed. The distance between consecutive nodes formed is:

  • A. 0.5 m
  • B. 1 m
  • C. 2 m
  • D. 3 m

Explanation: In a stretched string of length 2m, if two vibrating loops are formed, it indicates that there are two antinodes (the points of maximum amplitude) and three nodes (the points of zero amplitude). The distance between consecutive nodes is half the distance of the string divided by the number of loops formed. Thus, the total distance of 2m divided by the two loops results in a distance between nodes of 1m. The other options (0.5m, 2m, and 3m) do not align with the calculation based on the wave properties described.

Why the other options are wrong
  • A. This option represents a distance too short for the setup described. In a stationary wave with two loops, the distance between nodes should be larger than this.
  • C. This option suggests a distance equal to the total length of the string. This is incorrect because it does not reflect the configuration of nodes in a stationary wave with two loops.
  • D. This option is incorrect as it exceeds the total length of the string and does not fit the scenario of stationary waves formed in a 2m string.

Q154. A football is kicked with a speed of 20 m/s at an angle of 30° With the horizontal, the maximum height it attains is:

  • A. 5 m
  • B. 10 m
  • C. 15 m
  • D. 20 m

Explanation: The correct maximum height can be calculated using the formula: H = (vy2)/(2g), where vy is the vertical component of the initial velocity and g is the acceleration due to gravity (approximately 9.81 m/s2). First, we need to find the vertical component:vy = v * sin(θ) = 20 m/s * sin(30°) = 20 m/s * 0.5 = 10 m/sNow, substituting this value into the height formula:H = (10 m/s)2 / (2 * 9.81 m/s2) ≈ 5.1 mRounding down, we find the maximum height is approximately 5 m.Thus, Option A (5 m) is correct. Options B, C, and D are incorrect as they do not reflect the correct calculations based on the initial vertical velocity derived from the given speed and angle.

Why the other options are wrong
  • B. This option overestimates the maximum height. It does not account for the correct calculation of vertical motion based on the given speed and angle.
  • C. This option is incorrect. The maximum height achieved is less than this value based on the calculations for projectile motion.
  • D. This option assumes the entire speed contributes to height, which is incorrect. Only the vertical component determines the maximum height.

Q155. A high internal resistance battery is not suitable for heavy loads due to:

  • A. Excess voltage drop
  • B. High terminal voltage
  • C. Infinite emf
  • D. Constant current

Explanation: The correct answer is 'Excess voltage drop.' A battery with high internal resistance will experience a substantial voltage drop across its internal components when a heavy load is applied. This results in a lower voltage output to the load, which can impair its efficiency and effectiveness in powering devices. The other options are incorrect because high terminal voltage does not imply the battery can handle heavy loads, infinite emf is a theoretical notion that does not exist in practical applications, and constant current is not achievable under high internal resistance conditions.

Why the other options are wrong
  • B. High terminal voltage is not a direct consequence of high internal resistance. Rather, high terminal voltage may be present in a healthy battery but does not indicate its suitability for heavy loads.
  • C. Infinite electromotive force (emf) is a theoretical concept and does not apply to real batteries. All batteries have a finite emf, and high internal resistance does not imply infinite values.
  • D. A constant current is not guaranteed with high internal resistance, especially under load conditions. Instead, the current may vary significantly due to voltage drops caused by internal resistance.

Q156. Two equal charges experience a certain force when placed in vacuum. When the charges are placed in a medium, the force becomes 1/4 th. The dielectric constant of the medium is:

  • A. 0.25
  • B. 2
  • C. 4
  • D. 16

Explanation: When two equal charges are placed in a vacuum, they experience a certain force. According to Coulomb's law, the force (F) between two charges (q1 and q2) is given by the formula: F = k * (q1 * q2) / r^2, where k is the electrostatic constant. When the charges are placed in a medium with a dielectric constant (k'), the force becomes F' = F / k'. Given that the new force is 1/4th of the original (F' = F/4), we can set up the equation: F / k' = F / 4. This simplifies to k' = 4, indicating that the dielectric constant of the medium is 4. Hence, Option C is correct. The other options do not satisfy the condition of the force being reduced to 1/4th.

Why the other options are wrong
  • A. This option suggests that the dielectric constant is 0.25, which would imply that the force increases rather than decreases in the medium. This is incorrect as the force decreases when placed in a medium.
  • B. This option indicates that the dielectric constant is 2. While this would decrease the force compared to vacuum, it does not match the condition where the force is reduced to 1/4th of its original value.
  • D. This option suggests a dielectric constant of 16, which would imply that the force is reduced to 1/16th of its original value, not 1/4th. Therefore, this option is incorrect.

Q157. If a test charge of magnitude 2C experience forces of 100N 1 and 200N at two points A and B in an electric field respectively. The ratio of electric fields at A to that of B is

  • A. 1:1
  • B. 1:2
  • C. 1:4
  • D. 4:1

Explanation: To find the ratio of the electric fields at points A and B, we use the relationship E = F/q. For point A, the electric field E_A can be calculated as E_A = 100N / 2C = 50 N/C. For point B, E_B = 200N / 2C = 100 N/C. The ratio of the electric fields at A to B is E_A : E_B = 50 N/C : 100 N/C = 1:2. Therefore, the correct answer is Option B (1:2). The other options are incorrect because they do not accurately reflect the calculated ratio based on the forces experienced by the test charge.

Why the other options are wrong
  • A. This option implies that the electric fields at points A and B are equal. However, given that the forces are different, this cannot be correct.
  • C. This option suggests that the electric field at point A is one-fourth that at point B. This is incorrect as it does not match the ratio derived from the forces.
  • D. This option suggests that the electric field at point A is four times that at point B, which contradicts the given forces experienced by the test charge.

Q158. A body of mass 2 kg moving with velocity 3 m/s collides with a body of mass 1 kg at rest. If they stick together, their common velocity after collision is

  • A. 1 m/s
  • B. 2 m/s
  • C. 3 m/s
  • D. 4 m/s

Explanation: To find the common velocity after the collision of two bodies that stick together, we use the principle of conservation of momentum. The total momentum before the collision equals the total momentum after the collision. The initial momentum is calculated as follows: for the first body (mass = 2 kg, velocity = 3 m/s), the momentum is 2 kg * 3 m/s = 6 kg·m/s. The second body is at rest, contributing 0 kg·m/s. Therefore, the total initial momentum is 6 kg·m/s. After the collision, the two bodies stick together, so the total mass is 2 kg + 1 kg = 3 kg. Letting v be their common velocity, we set up the equation: 6 kg·m/s = 3 kg * v. Solving for v, we find v = 2 m/s. Thus, the correct answer is 2 m/s. Options 1 m/s, 3 m/s, and 4 m/s do not satisfy the conservation of momentum principle, making them incorrect.

Why the other options are wrong
  • A. This option suggests a lower velocity than expected. The momentum before the collision does not support this outcome.
  • C. This option reflects the initial velocity of the 2 kg body, but does not account for the mass of the second body and the conservation of momentum.
  • D. This option is too high for the resulting velocity after collision and does not conserve the momentum of the system.

Q159. Two balls thrown with equal speeds but at different angles cover equal horizontal distance. If one is thrown at an angle of 40°, then the angle of projection of the other is:

  • A. 20°
  • B. 30°
  • C. 45°
  • D. 50°

Explanation: When two projectiles are thrown with the same initial speed and cover the same horizontal distance, their angles of projection are complementary angles. Since one ball is thrown at an angle of 40°, the other must be thrown at an angle of 90° - 40° = 50° to achieve the same horizontal range. Therefore, the correct answer is 50°. The other options do not meet the criteria of being complementary to 40° and will not result in the same horizontal distance.

Why the other options are wrong
  • A. This angle is too low to achieve the same horizontal distance as an angle of 40°. The angles that can produce the same range are complementary to each other, which means they need to add up to 90°.
  • B. This angle is also not complementary to 40°. The sum of the angles should be 90° to have equal horizontal distances.
  • C. While 45° is a common angle for maximum range, it is not complementary to 40°. Therefore, it will not cover the same horizontal distance as the 40° angle.

Q160. The work done on a body is stored in it in the form of:

  • A. Power
  • B. Energy
  • C. Momentum
  • D. Impulse

Explanation: The work done on a body is converted into energy and stored within that body. Energy is a scalar quantity that represents the capacity for doing work, which is why option B is correct. In contrast, power (option A) relates to the rate of doing work, not the work itself; momentum (option C) describes motion rather than energy storage; and impulse (option D) refers to changes in momentum, which do not directly relate to stored work. Thus, the only viable answer is energy.

Why the other options are wrong
  • A. Power is the rate at which work is done or energy is transferred. It does not represent the stored energy itself, but rather how quickly energy can be converted or used.
  • C. Momentum is the product of an object's mass and velocity. While it describes motion, it does not pertain to the storage of work done on the object.
  • D. Impulse is a change in momentum resulting from a force applied over a period of time. It is not a form of stored energy or work.

Q161. If 20 waves pass a point in 2 seconds and with a speed of 5m/s, then the wavelength of wave is:

  • A. 0.5 m
  • B. 1 m
  • C. 1.5 m
  • D. 2 m

Explanation: To find the wavelength of the wave, we first calculate the frequency. Given that 20 waves pass a point in 2 seconds, the frequency (f) is calculated as: f = number of waves / time = 20 waves / 2 seconds = 10 Hz. Next, we use the wave speed (v) of 5 m/s in the formula for wavelength (λ): λ = v / f. Substituting the values gives us λ = 5 m/s / 10 Hz = 0.5 m. Therefore, the correct answer is option A (0.5 m). Options B (1 m), C (1.5 m), and D (2 m) are incorrect because they do not align with the calculated frequency and wave speed.

Why the other options are wrong
  • B. This option is incorrect. It suggests a wavelength that would imply a frequency of 5 Hz, which does not match the given number of waves.
  • C. This option is incorrect. A wavelength of 1.5 m would imply a frequency of approximately 3.33 Hz, which does not correspond to the 20 waves counted in 2 seconds.
  • D. This option is incorrect. A wavelength of 2 m would imply a frequency of 2.5 Hz, which is far less than the actual frequency derived from the problem.

Q162. The unit of RC in case of charging a capacitor is

  • A. Farad
  • B. Seconds
  • C. Ohm
  • D. Volt

Explanation: The correct answer is Seconds, as the RC time constant (τ) is defined as the time it takes for a capacitor to charge to approximately 63.2% of its maximum voltage. It is calculated as τ = R × C, where R is the resistance in ohms and C is the capacitance in farads. Since the product of resistance and capacitance results in a time measurement, the unit for RC is seconds. The other options are incorrect because Farads measure capacitance, Ohms measure resistance, and Volts measure electric potential, none of which directly indicate the time it takes for a capacitor to charge.

Why the other options are wrong
  • A. Farad is the unit of capacitance, not the time unit in the RC time constant.
  • C. Ohm is the unit of resistance, not time, and thus does not relate to the RC time constant.
  • D. Volt is the unit of electric potential, which is not relevant to the time constant of a charging capacitor.

Q163. A longitudinal wave has a frequency of 500 Hz and wavelength of 0.6 m, its speed is:

  • A. 30 m/s
  • B. 83 m/s
  • C. 300 m/s
  • D. 1200 m/s

Explanation: To calculate the speed of a longitudinal wave, you multiply its frequency by its wavelength. In this case, the frequency is 500 Hz and the wavelength is 0.6 m. Thus, the speed is calculated as follows: speed = frequency × wavelength = 500 Hz × 0.6 m = 300 m/s. Therefore, Option C is correct. Options A, B, and D are incorrect because they do not result from the proper application of the formula.

Why the other options are wrong
  • A. This option is too low when calculated using the formula. It does not match the expected result.
  • B. This value is also incorrect as it does not correspond to the product of the given frequency and wavelength.
  • D. This option is too high and does not reflect the correct calculation from the given parameters.

Q164. The true statement about angular displacement is:

  • A. It always increases with time
  • B. It is treated as vector for small rotations
  • C. It is always a scalar quantity
  • D. It is measured in meters

Explanation: The correct answer is Option B: 'It is treated as vector for small rotations.' This is accurate because angular displacement, which indicates the angle of rotation about an axis, is indeed a vector quantity, encompassing both direction and magnitude. In contrast, Option A is incorrect because angular displacement can decrease or remain constant depending on the rotation direction. Option C is misleading since angular displacement is not a scalar; it is fundamentally a vector. Finally, Option D is incorrect as angular displacement is measured in radians, not in meters, which are units of linear distance.

Why the other options are wrong
  • A. This statement is false because angular displacement can decrease if an object rotates in the opposite direction. It is not guaranteed to always increase over time.
  • C. This statement is incorrect because angular displacement is not a scalar; it is a vector quantity that includes both magnitude and direction.
  • D. This statement is incorrect; angular displacement is measured in radians, not meters, as it refers to the angle through which an object rotates.

Q165. π radians are equivalent to

  • A. 30°
  • B. 270°
  • C. 90°
  • D. 180°

Explanation: The correct answer is 180°, which is equivalent to π radians. In the conversion from radians to degrees, the formula used is: Degrees = Radians × (180/π). Thus, π radians equals π × (180/π) = 180°. The other options are incorrect as they represent different angles in degrees: 30° corresponds to π/6 radians, 90° corresponds to π/2 radians, and 270° corresponds to 3π/2 radians.

Why the other options are wrong
  • A. 30° is equivalent to π/6 radians, not π radians.
  • B. 270° is equivalent to 3π/2 radians, which is greater than π radians.
  • C. 90° is equivalent to π/2 radians, which is less than π radians.

Q166. The waves among the following which require a materialmedium for their propagation are:

  • A. Gamma rays
  • B. X-rays
  • C. Infrared waves
  • D. Infrasonic waves

Explanation: The correct answer is Infrasonic waves (Option D), as they are sound waves that require a material medium for their propagation. Unlike electromagnetic waves such as gamma rays, X-rays, and infrared waves, which can travel through a vacuum, infrasonic waves depend on a material environment to transmit their energy. This makes them distinct in the types of waves mentioned.Options A, B, and C (gamma rays, X-rays, and infrared waves) are all electromagnetic waves that can travel through the vacuum of space without the need for a material medium, which is why they are incorrect answers.

Why the other options are wrong
  • A. Gamma rays are electromagnetic waves that do not require a material medium for propagation; they can travel through the vacuum of space.
  • B. X-rays are also a form of electromagnetic radiation that can propagate through a vacuum, making them independent of material mediums.
  • C. Infrared waves are electromagnetic waves that do not need a medium for transmission; they can travel through a vacuum just like visible light.

Q167. Unequal-changes occurring in velocity of a body is called

  • A. Uniform acceleration
  • B. Uniform velocity
  • C. Instantaneous acceleration
  • D. Variable acceleration

Explanation: The correct answer is Variable acceleration because it specifically describes a situation where a body's acceleration is not constant, leading to unequal changes in velocity. In contrast, Uniform acceleration implies a steady rate of change in velocity, which contradicts the question's condition of unequal changes. Uniform velocity indicates no change in velocity at all, and Instantaneous acceleration only refers to a specific moment rather than ongoing changes. Thus, only Variable acceleration accurately captures the essence of the question.

Why the other options are wrong
  • A. This refers to a constant acceleration where the velocity of the body changes at a consistent rate. This option is incorrect because the question specifies unequal changes in velocity.
  • B. Uniform velocity indicates that an object is moving at a constant speed in a straight line. This is incorrect as it does not involve any changes in velocity, let alone unequal changes.
  • C. Instantaneous acceleration describes the acceleration of an object at a specific moment in time. While it can vary, it does not specifically refer to unequal changes over time, making it an incorrect choice.

Q168. A person moves 600 m towards north then 300 m towards south. Its displacement to distance ratio is:

  • A. 1:2
  • B. 1:3
  • C. 2:1
  • D. 3:1

Explanation: To find the displacement to distance ratio, we first calculate the total distance traveled and the net displacement. The person moves 600 m north and then 300 m south. The total distance traveled is 600 m + 300 m = 900 m. The displacement, or the shortest distance from the starting point to the final position, is the difference between the northward and southward movements: 600 m (north) - 300 m (south) = 300 m (net north). Therefore, the displacement to distance ratio is 300 m (displacement) to 900 m (distance), which simplifies to 1:3. The other options are incorrect because they do not accurately reflect the relationship between the calculated displacement and total distance.

Why the other options are wrong
  • A. This option suggests that the displacement is half of the distance traveled, which is incorrect because the actual ratio is different.
  • C. This option implies that the displacement is twice the distance traveled, which is incorrect as the actual displacement is less than half of the distance.
  • D. This option suggests that the displacement is three times the distance traveled, which is not true; the displacement is actually much smaller than the total distance.

Q169. In a stationary wave the point that undergoes zero acceleration is:

  • A. Node
  • B. Antinode
  • C. Midpoint between node and antinode
  • D. Every point along the wave

Explanation: The correct answer is Node, as nodes are specific points in a stationary wave where the medium does not move, resulting in zero acceleration. In contrast, antinodes represent points of maximum displacement and maximum velocity in the wave, thus having the highest acceleration. The midpoint between a node and an antinode does not qualify as a node since it does not have zero displacement, and stating that every point along the wave experiences zero acceleration is inaccurate since only nodes do.

Why the other options are wrong
  • B. Antinodes are points of maximum displacement in a stationary wave. They experience the greatest acceleration and are not the correct answer.
  • C. This point experiences some displacement but is not a node. It does not have zero acceleration.
  • D. This statement is incorrect as not every point along the wave experiences zero acceleration. Only nodes do.

Q170. If the speed of sound is measured at sea level and at the top of a mountain, both at the same temperature. It will be:

  • A. Greater at sea level
  • B. Greater at the mountain top
  • C. The same at both places
  • D. Greater where the air is denser

Explanation: The speed of sound is influenced by the density of the medium through which it travels. At sea level, the air is denser than at the top of a mountain. Therefore, under the same temperature conditions, sound will travel faster at sea level where the air is denser. Option A is incorrect because it misinterprets the relationship between density and sound speed. Option B suggests that sound is faster at the mountain top, which contradicts the principles of sound propagation. Option C incorrectly claims that the speed is the same at both locations, overlooking the impact of air density. Thus, the correct answer is Option D, as sound travels faster in denser air.

Why the other options are wrong
  • A. This option suggests that the speed of sound is faster at sea level due to denser air; however, it does not consider the direct relationship between sound speed and air density.
  • B. This option implies that sound travels faster at higher altitudes, which is inaccurate in the context of equal temperature and density considerations.
  • C. This option suggests that the speed of sound remains constant regardless of altitude, which is misleading since sound speed is influenced by air density.

Q171. High slope of Ohm's law graph means:

  • A. Low resistance
  • B. High resistance
  • C. Open circuit
  • D. Low current

Explanation: The correct answer is Option B: High resistance. According to Ohm's law (V = IR), where V is voltage, I is current, and R is resistance, the slope of the voltage-current graph (V vs. I) represents the resistance (R). A steeper slope indicates a higher resistance, meaning that less current flows for a given voltage. Therefore, when the slope is high, it signifies that the resistance is also high. Option A is incorrect because a low slope corresponds to low resistance, which would allow for higher current. Option C is incorrect as an open circuit results in no current flow, and thus cannot be represented by a high slope. Option D is misleading because while high resistance can lead to low current, the direct interpretation of a high slope in the graph specifically indicates high resistance.

Why the other options are wrong
  • A. A low slope in the Ohm's law graph indicates low resistance, resulting in a larger current for a given voltage. Therefore, this option is incorrect.
  • C. An open circuit would result in no current flow, which is not accurately represented by a high slope in the graph. This option is incorrect.
  • D. While high resistance can lead to low current, the statement 'high slope' specifically refers to the value of resistance itself, making this option misleading and incorrect.

Q172. An outbreak of a corona disease is reported in the city. What should be the first course of action?

  • A. Develop a vaccination plan.
  • B. Conduct research on the disease.
  • C. Implement quarantine measures.
  • D. Inform the public by using all means.

Explanation: The correct answer is to implement quarantine measures, as this is the most effective first step in controlling the spread of a contagious disease during an outbreak. Quarantine helps isolate individuals who may be infected and prevents further transmission. Developing a vaccination plan or conducting research may be important later, but they do not provide immediate action to address the outbreak. Informing the public is essential for awareness and compliance, but it must coincide with direct actions such as quarantine to be effective.

Why the other options are wrong
  • A. This option, while important, is not the immediate first step during an outbreak as vaccines may not be available or effective in the short term.
  • B. Research is crucial for understanding the disease, but it does not provide immediate solutions to contain the outbreak.
  • D. While informing the public is important, it should be done in conjunction with actions like quarantine to ensure safety and control of the outbreak.

Q173. Find the next number: 5,11,23,47,95,_?

  • A. 190
  • B. 191
  • C. 192
  • D. 193

Explanation: The sequence provided is 5, 11, 23, 47, 95. To find the next number, we can analyze the differences between each pair of consecutive numbers: 11 - 5 = 623 - 11 = 1247 - 23 = 2495 - 47 = 48We observe that each difference is doubling: 6, 12, 24, 48. Following this pattern, the next difference should be 48 * 2 = 96. Thus, we add 96 to the last number in the sequence:95 + 96 = 191.Therefore, the next number is 191. The other options are incorrect because they do not follow the identified pattern of doubling differences.

Why the other options are wrong
  • A. This option suggests a number that does not follow the identified pattern of growth in the sequence.
  • C. This option is close to the correct answer but does not align with the growth pattern observed in the sequence.
  • D. This option exceeds the expected growth pattern of the sequence, making it incorrect.

Q174. Which number comes in the missing place? 1,3,7, 15, 31,.

  • A. 61
  • B. 63
  • C. 65
  • D. 67

Explanation: To find the next number in the sequence (1, 3, 7, 15, 31), observe the pattern: each number is generated by doubling the previous number and adding 1. For example: 1 × 2 + 1 = 3; 3 × 2 + 1 = 7; 7 × 2 + 1 = 15; 15 × 2 + 1 = 31. Following this pattern, the next number should be 31 × 2 + 1 = 63. Options 61, 65, and 67 do not follow this consistent doubling rule, hence they are incorrect.

Why the other options are wrong
  • A. This number does not fit the pattern of the sequence, as the differences between terms do not indicate that 61 should follow 31.
  • C. Although 65 is close to the correct answer, it does not follow the established pattern of the sequence.
  • D. This number is also incorrect as it deviates from the pattern, which consistently involves doubling the previous number and adding 1.

Q175. Every alphabet in the word "SURGEON" represent a fixed numerical value and the numbers when added, sum up to 99. Based on this, what will the sum of the word "EORGNSU".

  • A. 102
  • B. 78
  • C. 99
  • D. 56

Explanation: The letters in the word 'SURGEON' collectively have a fixed numerical value that sums to 99. Since the question asks for the sum of the rearranged word 'EORGNSU', and because the numerical values assigned to each letter do not change regardless of their order, the sum remains 99. Therefore, option C is correct. Options A, B, and D are incorrect because they either exceed or fall short of the total sum of 99, indicating a misunderstanding of the numerical values assigned to the letters.

Why the other options are wrong
  • A. This option suggests a total that exceeds the sum of the original word 'SURGEON', which contradicts the given information.
  • B. This option is less than the total of 'SURGEON', indicating a misunderstanding of the fixed values assigned to the letters.
  • D. This option is significantly lower than the expected total, suggesting that the numerical values have not been correctly interpreted.

Q176. What is the primary difference between hypothesis and a theory?

  • A. A hypothesis is a proven fact, while a theory is an unproven data.
  • B. A hypothesis is a specific prediction, while a theory is a broad explanation.
  • C. A hypothesis is a qualitative statement, while a theory is quantitative statement.
  • D. A hypothesis is a tentative explanation, while a theory is a well-established explanation.

Explanation: A hypothesis is a proposed explanation made on the basis of limited evidence as a starting point for further investigation; it is often a specific prediction that can be tested through experiments. In contrast, a theory is a well-substantiated explanation acquired through the scientific method and repeatedly tested and confirmed through observation and experimentation. Therefore, the correct answer is that a hypothesis is a tentative explanation, while a theory is a well-established explanation. The other options misrepresent the definitions of hypothesis and theory, either by stating incorrect relationships or by oversimplifying their nature.

Why the other options are wrong
  • A. This option is incorrect because a hypothesis is not a proven fact; it is an untested prediction. Theories are not merely 'unproven data'; they are comprehensive explanations supported by a substantial body of evidence.
  • B. This option is partially correct as it accurately describes the nature of a hypothesis and theory, but it lacks the emphasis on the established status of a theory compared to a hypothesis.
  • C. This option is incorrect because hypotheses can be qualitative or quantitative, and theories don't have to strictly be quantitative; they are broad explanations that can encompass both types of data.

Q177. ZX, WU, TR, QO.. What comes next?

  • A. NL
  • B. LN
  • C. NM
  • D. KH

Explanation: The sequence is formed by taking pairs of letters where the first letter decreases and the second letter increases with each step. Starting from ZX, the first letter decreases by 2 (Z to X) and the second letter increases by 2 (X to W). Following this pattern, the next pair should be NL, where N is two letters before P and L is two letters after J. Other options do not match this established pattern.

Why the other options are wrong
  • B. This option does not follow the established pattern of the sequence.
  • C. This option also does not align with the pattern observed in the previous pairs.
  • D. This option does not fit the sequence, as it does not follow the alternating pattern.

Q178. In a row of students, a student is at 13th position from the left end and at 20th position from the right end. How many students are there in the row?

  • A. 30
  • B. 31
  • C. 32
  • D. 33

Explanation: The total number of students can be calculated using the formula: Total Students = Position from Left + Position from Right - 1. In this case, the student is at the 13th position from the left end and the 20th position from the right end. Therefore, the calculation is: Total Students = 13 + 20 - 1 = 32. Option A (30) is incorrect because it does not consider the overlap. Option B (31) is incorrect for the same reason. Option D (33) counts one additional student erroneously. Thus, the correct answer is Option C (32).

Why the other options are wrong
  • A. This option assumes that the total number of students is less than the sum of the positions from both ends, which is incorrect.
  • B. This option is also incorrect because it does not account for the overlap of the student counted from both ends.
  • D. This option incorrectly adds an extra student, failing to account for the overlap in counting from both ends.

Q179. A is older than B but younger than F. C is younger than B but older than D. Who is the youngest of them?

  • A. A
  • B. B
  • C. C
  • D. D

Explanation: To solve the problem, we establish the age relationships:A is older than B but younger than F. This gives us the order: B < A < F.C is younger than B but older than D, leading to the order: D < C < B.Combining these two sequences, we get: D < C < B < A < F. From this, we can see that D is the youngest of them all.Therefore:A is eliminated because he is older than B.B is eliminated because he is older than C.C is eliminated because he is older than D.This confirms that D is the youngest of the group.

Why the other options are wrong
  • A. A is older than B and younger than F, so A cannot be the youngest.
  • B. B is older than C and younger than A, so B is not the youngest.
  • C. C is younger than B but older than D. Therefore, C cannot be the youngest.

Q180. A hiker climbed to a higher altitude, where he felt the air pressure was lower as compared to the lower altitude. What is the likely effect?

  • A. The hiker felt more energetic.
  • B. The hiker felt no difficulty in breathing.
  • C. The hiker might experience altitude sickness.
  • D. The hiker felt healthier and fresh.

Explanation: The correct answer is that the hiker might experience altitude sickness. This condition arises when the body struggles to adapt to lower oxygen levels at high altitudes, leading to symptoms like headache, nausea, and fatigue. The other options are incorrect because they either suggest an increase in energy or well-being, which is not typical as the body requires time to acclimatize to changes in air pressure. Difficulty in breathing is common at higher altitudes due to the reduced availability of oxygen.

Why the other options are wrong
  • A. This option suggests an increase in energy, which is unlikely at high altitudes due to lower oxygen levels.
  • B. At higher altitudes, many individuals experience difficulty in breathing due to reduced air pressure and oxygen availability.
  • D. This option is misleading; while some may feel invigorated, many actually feel unwell due to the physiological effects of altitude.

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