Home/Past Papers/Federal / FMDC/Federal Mdcat Mock Paper 2
Federal Mdcat Mock Paper 2 — Solved Past Paper with Answers
All 179 MCQs from Federal Mdcat Mock Paper 2, solved with the correct answer highlighted and a full explanation for every question. This is a free MDCAT Federal / FMDC past paper — no signup, no ads. Practise it interactively in timed mode, drill more with free MDCAT MCQs, or browse all Federal / FMDC papers.
Attempt this paper interactively →Q1. Identify the word or phrase that needs to be changed for the sentence to be correct:The stories that she makes out for her children ought to be written down and published.
- A. That
- B. Makes out✓
- C. Ought to
- D. Written down
- E. No error
Explanation: "That" is correctly placed as a demonstrative pronoun.To "make out" means to manage with some difficulty to see or hear someone or something so it is incorrectly used here. "Makes" would be the correct word for the blank."Ought to" can be used to indicate light responsibility or urgency. It is correctly used in the sentence.It means to record something by writing down.An error was present in the sentence.
Why the other options are wrong
- A. "That" is correctly placed as a demonstrative pronoun.
- C. "Ought to" can be used to indicate light responsibility or urgency. It is correctly used in the sentence.
- D. It means to record something by writing down.
- E. An error was present in the sentence.
Q2. Choose the correct sentence from the following options:
- A. The government should accrue taxes for strengthen the economy of the country.
- B. The government should accrue taxes in strengthen the economy of the country
- C. The government should accrue taxes to strengthen the economy of the country.✓
- D. The government should accrue taxes by strengthen the economy of the country.
Explanation: By comparing all four sentences ,you notice there is only one difference i.e. PREPOSITION and for fact the best suited is 'to strengthen'.
Why the other options are wrong
- A. Option A: Incorrect - "for strengthen" is grammatically incorrect. It should be "to strengthen" to indicate purpose or intention.
- B. Option B: Incorrect - "in strengthen" lacks proper grammar and structure. It should be "to strengthen" for clarity and correctness.
- D. Option D: Incorrect - "by strengthen" lacks proper grammar. It should be "by strengthening" to use the gerund form of the verb after "by."
Q3. Each sentence below has a blank indicating that something has been omitted. Choose the word that best fits in with the meaning of the sentence as a whole.The air in a room that contains several houseplants can be more _ oxygen than in a room that contains no plants.
- A. Complicated by
- B. Exhausted with
- C. Obscured by
- D. Saturated with✓
Explanation: The word "saturated" most accurately indicates the density of the oxygen in the room. The other answer choices do not fit the context of the sentence.
Why the other options are wrong
- A. "Complicated by" means made more complex or difficult, which does not make sense in the context of describing the oxygen content of the air.
- B. "Exhausted with" means depleted or used up, which is the opposite of what is meant here, as plants increase oxygen levels.
- C. "Obscured by" means made unclear or hidden, which does not relate to the oxygen content in the air.
Q4. In the following question, a sentence is given with blanks to be filled in with an appropriate word. Four alternatives are suggested. Choose the correct alternative, out of the four as your answer.Ravens appear to behave _, actively helping one another to find food.
- A. Mysteriously✓
- B. Warily
- C. Aggressively
- D. Defensively
Explanation: Ravens appear to behave mysteriously, showing puzzling or clever actions, such as actively helping one another to find food.
Why the other options are wrong
- B. "Warily" means in a cautious or suspicious manner, which does not fit in the context of the sentence.
- C. Aggressively" means in a forceful or hostile manner, which is the opposite of what the sentence suggests.
- D. The word "defensively" means in a manner intended to protect oneself or one's interests.
Q5. Select the option which fits appropriately in the blank:Everyone _ done his or her homework.
- A. Has✓
- B. Have
- C. Had
- D. None
Explanation: This is the correct form. "Has" is used with the indefinite pronoun "everyone," which is singular. In English, indefinite pronouns like "everyone," "somebody," "anybody," etc., are treated as singular subjects and require a singular verb form. Therefore, "has" agrees with "everyone" in number.
Why the other options are wrong
- B. This option is incorrect because "have" is the plural form of the verb and does not agree with the singular subject "everyone."
- C. This option is incorrect because "had" is the past tense form of the verb "have" and does not fit the present tense context of the sentence.
- D. This option is not a valid choice.
Q6. Jack is six years old, but he _ French and Spanish.
- A. Speaking
- B. Is speaking
- C. Speaks✓
- D. Speak
Explanation: The correct verb form to use in the sentence "Jack is six years old, but he _ French and Spanish" is speaks. The present simple tense is used to talk about things that are always true or that happen regularly. In this case, we are talking about Jack's ability to speak French and Spanish, which is something that he does regularly. Here is the correct sentence:Jack is six years old, but he speaks French and Spanish.
Why the other options are wrong
- A. The verb speaking is in the present participle form, which is used to describe actions that are happening at the moment of speaking.
- B. The verb is speaking is the present continuous tense, which is also used to describe actions that are happening at the moment of speaking.
- D. The verb speak is in the present simple tense, which is the correct verb form to use in this context. It is a simple, straightforward way to say that Jack can speak French and Spanish.
Q7. Select the most suitable synonym for the given word:JUXTAPOSE:
- A. Justify
- B. Compare✓
- C. Expose
- D. Jettison
Explanation: Juxtapose means to compare two contrasting things/traits.
Why the other options are wrong
- A. justify means to show something to be reasonable
- C. Expose means to uncover something.
- D. Jettison means to abandon or discard
Q8. Which one is grammatically correct? Read carefully.
- A. Both are correct
- B. Speak up! I can't hear you because your dog is making too much noise.✓
- C. Both are wrong
- D. Speak up! I can't hear you because your dog is making much too noise.
Explanation: Too much is used as a determiner with singular (uncountable) nouns while much too is used with comparatives and adjectives. As noise is a noun, therefore too much noise is grammatically correct.
Why the other options are wrong
- A. This is incorrect because option C is wrong.
- C. This is incorrect because option B is correct.
- D. Incorrect. The phrase "much too noise" is not grammatically correct. The correct phrasing is "too much noise."
Q9. Choose the related word for Rat on the analogy of "Elephant : Stride".
- A. Scamper✓
- B. Loiter
- C. Whimper
- D. Gallop
Explanation: Elephants take long steps while walking which is known as a stride. Similarly, a rat scampers which means it runs in quick, light movements.
Why the other options are wrong
- B. Loiter refers to lingering or moving slowly without a purpose, which does not match the active movement style of a rat.
- C. Whimper refers to a sound rather than a style of movement, making it unrelated to the analogy of movement styles.
- D. Gallop is a fast-paced, bounding movement typical of horses, not small animals like rats.
Q10. The process of RNA interference (RNAi) has been used in the development of plants resistant to:
- A. Nematodes✓
- B. Fungi
- C. Viruses
- D. Insects
Explanation: Many nematodes live in plants and animals including human beings. A nematode Meloidogyne incognita infests the roots of tobacco plants and causes a great reduction in yield. A novel strategy was adopted to prevent this infection that was based on the process of RNA interference (RNAi). RNA interference (RNAi) is the phenomenon of inhibiting the activity of a gene by the synthesis of RNA molecules complementary to the mRNA. The normal (in vivo synthesized) mRNA of a gene is said to be “sense” because it carries the codons that are “read” during translation. Normally, the complement to the mRNA “sense” strand will not contain a sequence of codons that can be translated to produce a functional protein; thus, this complementary strand is called “anti-sense RNA”. The anti-sense RNA and mRNA molecules will anneal to form duplex RNA molecules (or double-stranded RNA) and the duplex RNA molecules can not be translated. Thus, the presence of antisense RNA will block translation of the mRNA of the affected gene.
Why the other options are wrong
- B. Fungi are generally decomposers, meaning they get their nourishment from decomposing or dead organic materials (usually plants). Insoluble polysaccharides, such as cellulose and lignin in dead wood, can be broken down by fungal exoenzymes into readily absorbable glucose molecules.
- C. A virus is an infectious microorganism made up of a nucleic acid segment (DNA or RNA) encased in a protein coat. A virus cannot replicate on its own; instead, it must infect cells and use host cell components to replicate itself.
- D. Any little creature has six legs and three segments to its body Insects frequently have wings as well.Insects include ants, bees, and flies.Any member of the largest class of the phylum Arthropoda, which is itself the largest of the animal phyla, is an insect (class Insecta or Hexapoda).
Q11. Which one of the following correctly explains the function of a specific part of the human nephron?
- A. Podocytes: create minute spaces (slit pores) for the filtration of blood into the Bowman’s capsule✓
- B. Henle’s loop: most absorption of the major substances from the glomerular filtrate
- C. Distal convoluted tubule: reabsorption of K + ions into the surrounding blood capillaries
- D. Afferent arteriole: carries the blood away from the glomerulus towards renal vein.
Explanation: The visceral layer of Bowman’s capsule surrounds the glomerulus and is composed of special type of cells, the podocytes. The podocytes are so called because they possess foot like processes (projection), the pedicels. The space between pedicels are called slit pores (filtration slits) through which the glomerular filtrate filters.
Why the other options are wrong
- B. This is incorrect. Henle's loop is crucial for the concentration of urine and reabsorption of water and ions, but the majority of reabsorption of major substances occurs in the proximal convoluted tubule (PCT), not in Henle's loop.
- C. The distal convoluted tubule (DCT) is involved in the fine-tuning of sodium, chloride, and calcium reabsorption, as well as the secretion of certain ions. Potassium reabsorption mainly occurs earlier in the nephron.
- D. This is incorrect. The afferent arteriole carries blood to the glomerulus; the efferent arteriole carries blood away from the glomerulus. The renal vein transports filtered blood away from the kidney.
Q12. Detoxification of drugs is the function of _ in a cell.
- A. Rough Endoplasmic Reticulum
- B. Smooth Endoplasmic Reticulum✓
- C. Liver cells
- D. Lysosome
Explanation: The smooth endoplasmic reticulum is a part of the endoplasmic reticulum which does not possess ribosomes studded on its membrane. It is involved in the detoxification of many poisons and drugs such as lipid soluble drugs, aspirin, insecticides (DDT), petroleum products and pollutants and converting them to safer water-soluble products.
Why the other options are wrong
- A. RER is involved in protein synthesis because they have ribosomes on their surface which helps them in protein synthesis which is the passed to SER and then to golgi complex for modification.
- C. Liver cells detoxify drugs from the whole body. Liver cells helps in the detoxification of urea mainly and other harmful material from the body but not in a cell.
- D. Lysosomes are involved in intracellular digestion. They are vesicles released from golgi complex.
Q13. Holoenzyme is?
- A. Protein part of enzyme
- B. Non-protein part of enzyme
- C. Complete enzyme✓
- D. Inactive enzyme
Explanation: A holoenzyme is the complete, active form of an enzyme. It is composed of an apoenzyme, which is the protein portion, and one or more cofactors, which can be metal ions or organic molecules known as coenzymes. These components together allow the holoenzyme to perform its catalytic function. Option A and B are incorrect because they describe only parts of the enzyme system, not the complete active form. Option D is incorrect because it describes an inactive enzyme, which is an apoenzyme, not a holoenzyme.
Why the other options are wrong
- A. This refers to the apoenzyme, which is the protein part of an enzyme, but not the complete active form. Holoenzyme includes both the protein and non-protein parts needed for activity.
- B. This refers to cofactors or coenzymes, which are non-protein components that assist enzyme activity. However, a holoenzyme includes both the protein and non-protein parts.
- D. This refers to an apoenzyme, which is the inactive protein part of an enzyme. A holoenzyme is the active form.
Q14. A non-proteinaceous enzyme is:
- A. Lysozyme
- B. Ribozyme✓
- C. Ligase
- D. Deoxyribonuclease
Explanation: The correct answer is Ribozyme. Ribozymes are unique because they are RNA molecules with catalytic properties, unlike typical enzymes, which are proteins. Ribozymes can catalyze reactions such as RNA cleavage and ligation, and they play crucial roles in the function of ribosomes. The other options, Lysozyme, Ligase, and Deoxyribonuclease, are all protein-based enzymes; hence, they do not fit the description of a non-proteinaceous enzyme.
Why the other options are wrong
- A. Lysozyme is a protein-based enzyme that functions as an antimicrobial agent by breaking down bacterial cell walls. It is not non-proteinaceous.
- C. Ligase is a protein enzyme that facilitates the joining of DNA strands during replication and repair processes. It is proteinaceous.
- D. Deoxyribonuclease (DNase) is a protein enzyme that cleaves DNA molecules. It is not a non-proteinaceous enzyme.
Q15. Which of the following is the least likely to be involved in stabilizing the three dimensional folding of most proteins?
- A. Hydrogen Bonds
- B. Electrostatic Interaction
- C. Hydrophobic Interaction
- D. Ester Bonds✓
Explanation: Protein folding is the process by which a protein structure assumes its functional shape or conformation by allowing interaction between amino acids by various bond formations. All protein molecules are heterogeneous unbranched chains of amino acids. Different types of weak interactions hold the interacting segments together in protein. Hydrophobic interaction, H bonds, and electrostatic interactions are the weak ones and stabilize the tertiary structure of proteins, while ester bonds are covalent bonds and are least likely to be involved in stabilizing the three-dimensional folding of most proteins.
Why the other options are wrong
- A. Hydrogen bonds stabilize the secondary structure of proteins and is a weak one. Hydrogen bonds are weak because they involve partial charges from an electrostatic attraction, not a full sharing or transfer of electrons as in covalent or ionic bonds. These bonds form between molecules rather than within them, making them more transient and easily broken compared to the strong intramolecular bonds. However, despite being individually weak, a large number of hydrogen bonds acting together can create significant collective strength, as seen in the stability of DNA and proteins.
- B. Electrostatic interactions in proteins are forces between charged or polar amino acid side chains that influence protein structure, folding, stability, and function. These interactions include ion pairs (salt bridges) between oppositely charged amino acids, hydrogen bonds, and long-range electrostatic forces that attract or repel molecules, affecting protein-protein binding and overall activity.
- C. Hydrophobic interaction stabilize the tertiary structure of proteins and is a weak one.Hydrophobic interactions are a major force driving protein folding, where non-polar amino acid side chains cluster together in the protein's interior to minimize their contact with water.
Q16. In which type of cells, cell wall is not present?
- A. Plant cells
- B. Fungal cells
- C. Bacterial cells
- D. Liver cells✓
Explanation: A cell wall is a structural layer surrounding some types of cells, just outside the cell membrane. It can be tough, flexible, and sometimes rigid. It provides the cell with both structural support and protection, and also acts as a filtering mechanism. No cells in the human body have a cell wall, hence liver cells will not have one either. Plant cell walls are primarily made of cellulose, which is the most abundant macromolecule on Earth. The cell wall is a characteristic structure of fungi and is composed mainly of glucans, chitin, and glycoproteins. The bacterial cell wall consists of peptidoglycan, an essential protective barrier for bacterial cells that encapsulates the cytoplasmic membrane.
Why the other options are wrong
- A. Plant cells have a cell wall made of cellulose, which provides rigidity and support.
- B. Fungal cells have a cell wall made of chitin, which gives structure and protection.
- C. Bacterial cells have a cell wall made of peptidoglycan (in most bacteria), providing strength and shape.
Q17. The bulk of carbon dioxide (CO2 ) released from body tissues into the blood is present as:
- A. Bicarbonate in blood plasma and RBCs✓
- B. Free CO2 in blood plasma
- C. 70% carbaminohaemoglobin and 30% as bicarbonate
- D. Carbaminohaemoglobin in RBCs
Explanation: Most of the carbon dioxide released from body tissues into the blood is transported as bicarbonate ions in both the plasma and red blood cells. A smaller amount binds with hemoglobin to form carbaminohemoglobin, and only a tiny fraction remains as free CO₂ in the plasma.
Why the other options are wrong
- B. Free CO2 in blood plasma: While some CO2 is transported as free CO2 molecules in blood plasma, it is a relatively smaller proportion compared to the bicarbonate form. The majority of CO2 is carried as bicarbonate ions and carbamino compounds.
- C. 70% carbamino-hemoglobin and 30% as bicarbonate:This option presents an inaccurate distribution of CO2 forms. Carbamino-hemoglobin refers to CO2 bound to hemoglobin within red blood cells, which is a smaller fraction compared to bicarbonate transport. The majority of CO2 is transported as bicarbonate ions, while some is bound to hemoglobin.
- D. Carbamino-hemoglobin in RBCs:While CO2 can bind to hemoglobin within red blood cells (carbamino-hemoglobin), it is not the primary form of CO2 transport. The primary method is the conversion of CO2 to bicarbonate ions, as explained in option A.
Q18. The diagram is taken from an electron of a cell, name the organelle labeled D:
- A. Nucleus
- B. Lysosomes
- C. Golgi complex
- D. Mitochondria✓
- E. Endoplasmic reticulum
Explanation: Mitochondria are bean- shaped membrane bounded organelles. Cristae is the fold in the inner membrane of mitochondria which is visible in the picture.
Why the other options are wrong
- A. This is not correct.it is not nucleus
- B. A is lysosomes originating from golgi complex.
- C. B is golgi complex. Golgi complex helps in the modification of proteins into glycoprotein or lipoprotein.
- E. C is endoplasmic reticulum in diagram
Q19. Commonly used vectors for human genome sequencing are:
- A. T-DNA
- B. Bacterial artificial chromosome & Yeast artificial chromosome✓
- C. Expression vectors
- D. TA cloning vectors
Explanation: Bacterial artificial chromosome (BAC) vectors are based on the natural, extra-chromosomal plasmid of E. coli. BAC vector contains genes for replication and maintenance of the F-factor, a selectable marker and cloning site. These vectors can accommodate up to 300-350 kb(kilo base) of foreign DNA and are also being used in genome sequencing project. Yeast artificial chromosome (YAC) vectors are used to clone DNA fragments of more than 1Mb in size. Therefore, they have been exploited extensively in mapping the large genomes, e.g., in the Human Genome Project. These vectors contain the telomeric sequence, the centromere and the autonomously replicating sequence from yeast chromosomes.
Why the other options are wrong
- A. The term "T-DNA" stands for "transfer DNA," and it is associated with Agrobacterium tumefaciens, a soil-dwelling bacterium known for its ability to transfer a segment of its DNA, called T-DNA, into the plant cells it infects. This natural genetic transformation process is crucial in plant biotechnology and genetic engineering.
- C. An expression vector, otherwise known as an expression construct, is generally a plasmid that is used to introduce a specific gene into a target cell. transcription: The synthesis of RNA under the direction of DNA.
- D. Expression vectors, also known as expression plasmids, are specialized types of cloning vectors used in molecular biology and genetic engineering to facilitate the expression of genes in a host organism, typically a bacterial or eukaryotic cell. The primary purpose of expression vectors is to provide the necessary elements for transcription and translation of a target gene, allowing the production of a specific protein of interest.
Q20. In which of the following is the organic compound COOH (carboxyl) group found? (I) Carbohydrate (II) Lipid (III) Protein
- A. I only
- B. II only
- C. I and II only
- D. II and III only✓
- E. I , II and III
Explanation: Carboxyl groups are commonly found in amino acids, fatty acids, and other biomolecules. Whereas carbohydrates only contain atoms of carbon hydrogen and oxygen they don't have any functional group.
Why the other options are wrong
- A. Carbohydrates usually contain a carbonyl (=O) and hydroxyl (−OH) functional group.
- B. Although the compositions of lipids vary, the most common functional groups are ester (both carboxylate and phosphate) and alcohol groups.
- C. Carbohydrates usually contain a carbonyl (=O) and hydroxyl (−OH) functional group. Although the compositions of lipids vary, the most common functional groups are ester (both carboxylate and phosphate) and alcohol groups.
- E. 1 does not contain carboxylic group.
Q21. What forms the basis of DNA fingerprinting?
- A. The relative proportions of purines and pyrimidines in DNA
- B. The relative difference in the DNA occurrence in blood, skin, and saliva
- C. The relative amount of DNA in the ridges and grooves of the fingerprints
- D. Satellite DNA occurring as highly repeated, short DNA segments✓
Explanation: DNA fingerprinting is a technique of determining nucleotide sequences of certain areas of DNA which are unique to each individual. The difference of about 0.1% or 3 × 106 base pairs (out of 3 × 10 9 bp) provides individuality to each human being. The human genome possesses numerous small noncoding but inheritable sequences of bases that are repeated many times. These sequences occur near telomere, centromeres, Y chromosome, and heterochromatic area. The area with the same sequence of bases repeated several times is called repetitive DNA. It is separated as a satellite from the bulk DNA during density gradient centrifugation and hence called satellite DNA where repetition of the bases is in tandem. Satellite DNAs show polymorphism (the occurrence of mutations in a population at high frequency), which is the basis of genetic mapping of human genome as well as DNA fingerprinting. While mutations in genes produce alleles with different expressions, mutations in noncoding repetitive DNA have no immediate impact. These mutations which have piled up with time form the basis of polymorphism.
Why the other options are wrong
- A. DNA fingerprinting is not based on the relative proportions of purines (adenine and guanine) and pyrimidines (cytosine and thymine) in DNA. It focuses on specific DNA sequences.
- B. While DNA can be obtained from blood, skin, and saliva for DNA fingerprinting, this option does not directly address the basis of DNA fingerprinting, which involves analyzing specific DNA sequences, not the source of the DNA.
- C. This option is not related to the basis of DNA fingerprinting. It seems to refer to the physical impressions of fingerprints rather than the genetic analysis of DNA.
Q22. A disease caused by an autosomal primary non-disjunction is:
- A. Klinefelter’s syndrome
- B. Turner’s syndrome
- C. Sickle cell anaemia
- D. Down’s syndrome✓
Explanation: Down syndrome is trisomy 21, an autosomal nondisjunction event producing an extra chromosome 21. Klinefelter and Turner involve sex chromosomes; sickle cell is single-gene.
Why the other options are wrong
- A. Klinefelter’s syndrome is a sex chromosome disorder characterized by the presence of an extra X chromosome in males (XXY). It results in phenotypic males with some female characteristics. It is not caused by autosomal non-disjunction.
- B. Turner’s syndrome is a sex chromosome disorder where there is a missing X chromosome (45, X). It affects females and is not related to autosomal non-disjunction.
- C. Sickle cell anemia is an inherited blood disorder caused by a mutation in the hemoglobin gene. It involves a single amino acid change and is not due to chromosomal non-disjunction.
Q23. The mechanism that causes a gene to move from one linkage group to another is called:
- A. Inversion
- B. Duplication
- C. Translocation✓
- D. Crossing over
Explanation: Translocation transfers chromosome segments between non-homologous chromosomes, relocating genes to different linkage groups.
Why the other options are wrong
- A. Inversion involves a chromosome segment being reversed end to end within the same chromosome, not between linkage groups or different chromosomes.
- B. Duplication refers to the repetition of a chromosome segment within the same chromosome, increasing the number of copies of that segment, but it does not move a gene between linkage groups.
- D. Crossing over occurs during meiosis between homologous chromosomes and involves the exchange of genetic material, but it does not result in genes moving between different linkage groups or chromosomes.
Q24. The external solution having more concentration than the cell sap is known:
- A. Hypertonic solution✓
- B. Hypotonic solution
- C. Isotonic solution
- D. None of these
Explanation: The correct answer is a hypertonic solution. In osmoregulation, when a cell is placed in a hypertonic solution, the external environment has a higher concentration of solutes compared to the inside of the cell. This concentration difference causes water to move out of the cell through osmosis, leading to a decrease in cell volume and potential plasmolysis. Conversely, a hypotonic solution would cause water to move into the cell, and an isotonic solution would result in no net water movement. None of these is incorrect because the correct term for a solution with higher solute concentration than the cell sap is indeed a hypertonic solution.
Why the other options are wrong
- B. A hypotonic solution has a lower solute concentration than the cell sap, leading to water moving into the cell, causing it to swell and possibly burst.
- C. An isotonic solution has an equal solute concentration compared to the cell sap, resulting in no net water movement across the cell membrane, maintaining cell size.
- D. This option is incorrect as it does not describe a solution with a higher solute concentration than the cell sap, which is known as a hypertonic solution.
Q25. The antigen-antibody complexes formed in the body are taken up by:
- A. Phagocytes✓
- B. Lymphocytes
- C. Monocytes
- D. Leukocytes
Explanation: Phagocytes, such as neutrophils and macrophages, are crucial for the immune system's function of engulfing and digesting foreign particles, including antigen-antibody complexes. These cells are equipped to identify and internalize these complexes, aiding in their removal from the body. While lymphocytes are vital for recognizing antigens and initiating immune responses, they do not perform phagocytosis. Monocytes can differentiate into macrophages, which are phagocytic, but the term 'monocytes' itself does not directly imply phagocytic activity. Leukocytes encompass a broader category of white blood cells, not all of which are phagocytic.
Why the other options are wrong
- B. A lymphocyte is a type of white blood cell in the immune system of most vertebrates. Lymphocytes include T cells, B cells, and Innate lymphoid cells, of which natural killer cells are an important subtype.
- C. Monocytes are a type of leukocyte or white blood cell. They are the largest type of leukocyte in blood and can differentiate into macrophages and monocyte-derived dendritic cells. As a part of the vertebrate innate immune system monocytes also influence adaptive immune responses and exert tissue repair functions.
- D. White blood cells, or leukocytes (Greek; leucko=white and cyte = cell), are part of the immune system participating in both the innate and humoral immune responses. They circulate in the blood and mount inflammatory and cellular responses to injury or pathogens.
Q26. In the following human pedigree, the filled symbols represent the affected individuals. Identify the type of given pedigree.
- A. Autosomal recessive✓
- B. X-linked dominant
- C. Autosomal dominant
- D. X-linked recessive
Explanation: The correct answer is Autosomal recessive. In the pedigree, the trait appears in individuals who are homozygous recessive, meaning they have inherited two copies of the recessive allele, one from each parent. This pattern typically skips generations, as carriers (heterozygous individuals) do not express the trait but can pass it to their offspring. Other options, such as X-linked dominant, autosomal dominant, and X-linked recessive, do not match the inheritance pattern shown in the pedigree. X-linked dominant would affect all daughters of an affected male, autosomal dominant would appear in every generation, and X-linked recessive would predominantly affect males.
Why the other options are wrong
- B. X-linked dominant traits would typically appear in every generation and be passed from affected fathers to all daughters. This pattern is not observed in the given pedigree.
- C. Autosomal dominant traits are typically seen in every generation and affect both males and females equally. The pedigree does not show this consistent pattern.
- D. X-linked recessive traits are more common in males and require two copies of the gene in females to be expressed. The pattern in the pedigree does not match this inheritance mode.
Q27. The area on the left hemisphere related to speech is called?
- A. Amygdala
- B. Broca's area✓
- C. Hypothalamus
- D. Occipital lobe
Explanation: Option A: The amygdala is commonly thought to form the core of a neural system for processing fearful and threatening stimuli (4), including detection of threat and activation of appropriate fear-related behaviors in response to threatening or dangerous stimuli. Option B: Broca’s area is also known as the motor speech area. It is near the motor cortex and utilized in speech production, located in the inferior frontal gyrus. This area regulates breathing patterns while speaking and vocalizations required for normal speech. Option C: The Hypothalamus is a structure deep in your brain, acts as your body's smart control coordinating center. Its main function is to keep your body in a stable state called homeostasis. It does its job by directly influencing your autonomic nervous system or by managing hormones. Option D: The occipital lobes sit at the back of the head and are responsible for visual perception, including colour, form, and motion. Damage to the occipital lobe can include: Difficulty with locating objects in the environment
Why the other options are wrong
- A. The amygdala is commonly thought to form the core of a neural system for processing fearful and threatening stimuli (4), including detection of threat and activation of appropriate fear-related behaviors in response to threatening or dangerous stimuli.
- C. The hypothalamus is a structure deep in your brain, acts as your body's smart control coordinating center. Its main function is to keep your body in a stable state called homeostasis. It does its job by directly influencing your autonomic nervous system or by managing hormones
- D. The occipital lobes sit at the back of the head and are responsible for visual perception, including colour, form, and motion. Damage to the occipital lobe can include: Difficulty with locating objects in the environment.
Q28. The diencephalon comprises of:
- A. Pons of medulla
- B. Thalamus and limbic system✓
- C. Pons and medulla
- D. Hypothalamus and limbic system
Explanation: The diencephalon is a part of the brain that is located between the cerebrum and the midbrain. It is made up of four main parts, i.e. thalamus, the hypothalamus, the epithalamus, and the subthalamus. The hypothalamus is also a part of the limbic system.
Why the other options are wrong
- A. The pons and medulla are parts of the brainstem, which is located below the diencephalon.
- C. The pons and medulla are parts of the brainstem, which is located below the diencephalon.
- D. This option is partially correct because the hypothalamus is part of the limbic system, but it does not mention the thalamus, which is part of the diencephalon.
Q29. A woman with normal colour vision, whose father was red green colour blind, married a red green colour blind man. What is the probability of her born child being red green colour blind?
- A. 1.0
- B. 0.75
- C. 0.50✓
- D. 0.25
Explanation: Males have 1 X chromosome and 1 Y chromosome, and females have 2 X chromosomes. The genes that can give you red-green colour blindness are passed down on the X chromosome.The woman’s father is red-green colour blind. Since the woman got one of her X chromosomes from her father this means that she is a carrier. As it can be seen from the table the probability of having a colourblind child is 0.5%
Why the other options are wrong
- A. a) 1.0 (100%):This means that there is a 100% probability of the child being red-green color blind. However, this is not necessarily true. The inheritance of color blindness is not guaranteed, and other factors come into play.
- B. b) 0.75 (75%):This means that there is a 75% probability of the child being red-green color blind. This option suggests a high likelihood of inheritance since both parents have a form of color blindness.
- D. d) 0.25 (25%):This means that there is a 25% probability of the child being red-green color blind. This option suggests a lower likelihood of inheritance.
Q30. Gigantism in human beings is caused due to over secretion of:
- A. Thyrotropin
- B. Corticotropin
- C. Somatotropin✓
- D. Prolactin
Explanation: Gigantism occurs when a child’s pituitary gland makes too much growth hormone, which is also known as somatotropin. Corticotropin-releasing hormone (CRH), also called corticotropin-releasing factor (CRF), is a peptide hormone that activates the synthesis and release of adrenocorticotropic hormone (ACTH) from the pituitary gland. In this way, CRH affects our response to stress, addiction and depression, amongst others. Prolactin is a hormone made by the pituitary gland, a small gland at the base of the brain. Prolactin causes the breasts to grow and make milk during pregnancy and after birth. Thyroid-stimulating hormone/Thyrotropin is a hormone produced by anterior pituitary gland that stimulates the thyroid gland to produce thyroxine, and then triiodothyronine which stimulates the metabolism of almost every tissue in the body. Therefore, the correct answer is C.
Why the other options are wrong
- A. Thyroid-stimulating hormone is a pituitary hormone that stimulates the thyroid gland to produce thyroxine, and then triiodothyronine which stimulates the metabolism of almost every tissue in the body.
- B. Corticotropin-releasing hormone (CRH), also called corticotropin-releasing factor (CRF), is a peptide hormone that activates the synthesis and release of adrenocorticotropic hormone (ACTH) from the pituitary gland. In this way, CRH affects our response to stress, addiction and depression, amongst others
- D. Prolactin is a hormone made by the pituitary gland, a small gland at the base of the brain. Prolactin causes the breasts to grow and make milk during pregnancy and after birth. Prolactin levels are normally high for pregnant women and new mothers.
Q31. A structure established between the uterine and foetal tissues for the exchange of oxygen, carbon dioxide, waste, nutrients and other materials is:
- A. Amnion
- B. Placenta✓
- C. Endometrium
- D. Uterus
Explanation: The placenta is defined as temporary intimate mechanical and the physiological connection between foetus and maternal tissue for the nutrition, respiration and excretion of the foetus. Human placenta consists of chorion only. The placenta is fully formed by the end of the third month and maintains pregnancy. In the placenta, the foetal blood comes very close to the maternal blood and this permits the exchange of material between the two. Food, water, mineral salt, vitamins, hormone antibodies and oxygen pass from the maternal blood into the foetal blood, and foetal metabolic waste, such as carbon dioxide, and urea, also water and hormones, pass into the maternal blood.
Why the other options are wrong
- A. Lined with ectoderm and covered with mesoderm (both are germ layers), the amnion contains a thin, transparent fluid in which the embryo is suspended, thus providing a cushion against mechanical injury. The amnion also provides protection against fluid loss from the embryo itself and against tissue adhesions.
- C. Endometrium is a layer of tissue that lines the uterus.
- D. The organ in the lower body of a woman or female mammal where offspring are conceived and in which they gestate before birth; the womb.
Q32. RNA interference involves the:
- A. Synthesis of complementary DNA and RNA using reverse transcriptase
- B. Silencing of specific mRNA due to complementary RNA✓
- C. Interference of RNA in the synthesis of DNA
- D. Synthesis of mRNA from DNA
Explanation: RNA interference (RNA) is the phenomenon of inhibiting the activity of a gene through the production of both sense and anti sense RNA. RNA takes place in all eukaryotic organisms as a method of cellular defense. This method involves specific mRNA silencing. It is due to a complementary dsRNA molecule that binds to and prevents translation of the mRNA causing its silencing.
Why the other options are wrong
- A. cDNA synthesis is a process of producing complementary DNA (cDNA) by reverse transcription. The process utilizes mRNA or miRNA as a template, reverse transcriptase enzyme, and a thermostable primer, complementary to the 3' end of the RNA template.
- C. RNA interference (RNAi) is a phenomenon in which small double-stranded RNA molecules induce sequence-specific degradation of homologous single-stranded RNA (1). In plants and insects, RNAi activity plays a role in host-cell protection from viruses and transposons (2, 3).
- D. The process of making mRNA from DNA is called transcription, and it occurs in the nucleus. The mRNA directs the synthesis of proteins, which occurs in the cytoplasm. mRNA formed in the nucleus is transported out of the nucleus and into the cytoplasm where it attaches to the ribosomes.
Q33. A fall in glomerular filtration rate (GFR) activates:
- A. Juxtaglomerular cells to release renin✓
- B. Adrenal cortex to release aldosterone
- C. Adrenal medulla to release adrenaline
- D. Posterior pituitary to release vasopressin
Explanation: Low GFR triggers renin release to maintain blood pressure.
Why the other options are wrong
- B. The release of aldosterone from the adrenal glands is regulated via the renin-angiotensin II-aldosterone system. This system is initially activated via a decrease in the mean arterial blood pressure to increase the blood pressure.
- C. Adrenaline is produced in the adrenal glands, which release adrenaline into the body during times of stress or danger. It prepares your body to face a stressful “fight or flight” situation.
- D. Vasopressin release is regulated by osmoreceptors in the hypothalamus, which are exquisitely sensitive to changes in plasma osmolality. Under hyperosmolar conditions, osmoreceptor stimulationleads to vasopressin release and stimulation of thirst. These two mechanisms result in increased water intake and retention.
Q34. A large proportion of oxygen remains unused in the human blood even after its uptake by the body tissues. This O2 _.
- A. Acts as a reserve during muscular exercise✓
- B. Raises the pCO2 of blood to 75 mmHg
- C. Is enough to keep oxyhaemoglobin saturation at 96%
- D. Helps in releasing more O2 to the epithelial tissues
Explanation: The unused oxygen in the blood acts as a reserve, which can be utilized during physical activities such as exercise when the body's oxygen demand increases. This ensures sufficient oxygen supply to the muscles.
Why the other options are wrong
- B. This statement is incorrect. Oxygen levels do not influence the partial pressure of carbon dioxide (pCO2) in the blood. pCO2 is regulated by cellular respiration and the elimination of CO2, independent of unused oxygen.
- C. This statement is misleading. Oxyhemoglobin saturation is maintained primarily by the normal binding of oxygen to hemoglobin, not solely by the presence of unused oxygen.
- D. This statement is inaccurate. Oxygen release to tissues is influenced by factors such as the oxygen gradient and hemoglobin affinity rather than directly by the presence of unused oxygen in the blood.
Q35. Erythropoiesis starts in:
- A. Spleen
- B. Red bone marrow✓
- C. Kidney
- D. Liver
Explanation: Erythropoiesis is the formation of red blood cells (erythrocytes) which occurs in the red bone arrow. Proerythroblast is the earliest precursor which gives rise successively to the early erythroblast, intermediate erythroblast and late erythroblast. Then, the nucleus is forced out and a biconcave, enucleated cell called reticulocyte is formed, which is released into blood. In blood, it develops into mature erythrocytes. Red bone marrow, found in certain bones of the body, is the primary site for erythropoiesis. It is responsible for producing red blood cells (erythrocytes), along with other blood cell types like white blood cells and platelets. Red bone marrow contains stem cells known as hematopoietic stem cells that give rise to various blood cell lineages, including red blood cells.
Why the other options are wrong
- A. The spleen is an organ located in the upper left abdomen. While the spleen does play a role in the immune system and the removal of old or damaged red blood cells from circulation, it is not the site where erythropoiesis (formation of red blood cells) primarily occurs.
- C. While the kidney plays an important role in the regulation of erythropoiesis, it does not directly initiate the process. The kidney produces and secretes a hormone called erythropoietin (EPO), which stimulates the production of red blood cells in the bone marrow. EPO is released in response to low oxygen levels in the blood. Therefore, the kidney indirectly influences erythropoiesis by regulating the production of erythropoietin.
- D. The liver also plays a role in the production of blood cells, but it is not the primary site of erythropoiesis. The liver is involved in the production of certain blood components, such as clotting factors, and it can contribute to erythropoiesis in certain circumstances. However, the liver's contribution to erythropoiesis is minimal compared to the role of red bone marrow.
Q36. Read the following four statements.(A) The first transgenic buffalo, Rosie, produced milk that was human alpha lactalbumin enriched.(B) Restriction enzymes are used in the isolation of DNA from other macromolecules.(C) Downstream processing is one of the steps of rDNA technology.(D) Disarmed pathogen vectors are also used in the transfer of rDNA into the host.Which of the two statements have mistakes?
- A. B and C
- B. C and D
- C. A and C
- D. A and B✓
Explanation: In 1997, the first transgenic cow, Rosie, produced human protein enriched milk. The milk contained the human alpha lactalbumin and was nutritionally a more balanced product for human babies than natural cowmilk. Isolation of DNA from other macromolecule is achieved by treating the bacterial cells/plant or animal tissue with enzymes such as lysozyme (bacteria), cellulase (plant cells), chitinase (fungus).
Why the other options are wrong
- A. B. Restriction enzymes are the enzymes produced by certain bacteria that have the property of cleaving DNA molecules at or near specific base sequences. So, it is used in the isolation of a part of DNA from the whole DNA macromolecule. It is not used to isolate DNA from other macromolecules. Enzymes like proteinase K are used to separate DNA from other macromolecules like histone proteins. So, the statement that restriction enzymes are used in the isolation of DNA from other macromolecules is wrong. C. Downstream processing refers to the series of unit operations used to isolate, purify, and concentrate the product obtained by r DNA. Downstream processing includes the separation and purification process. Thus, downstream processing is one of the steps of rDNA technology.
- B. C. Downstream processing refers to the series of unit operations used to isolate, purify, and concentrate the product obtained by r DNA. Downstream processing includes the separation and purification process. Thus, downstream processing is one of the steps of rDNA technology.D. Disarmed pathogens are created by removing the genes that are responsible for virulence and adding genes of our interest instead so that when the disarmed pathogen is used to infect the host, it does not cause disease but transfers the recombinant DNA into the host.
- C. A. The first transgenic cow was Rosie, developed in 1997, in which the gene introduced was Human-alpha-lactalbumin milk at 2.4 grams per liter. As a result, the milk produced had a better content of protein and was nutritionally more apt for human infants. This was because the milk was a nutritionally more balanced product compared to the natural bovine milk and could be served to the elderly or babies having special digestive or nutritive requirements. Hence, the statement given in the question that Rosie was the first transgenic buffalo is wrong. Rosie was a cow.C. Downstream processing refers to the series of unit operations used to isolate, purify, and concentrate the product obtained by r DNA. Downstream processing includes the separation and purification process. Thus, downstream processing is one of the steps of rDNA technology.
Q37. All of the following statements about arteries are true except:
- A. They are thick-walled
- B. They pulsate
- C. They contain much elastic fiber tissue
- D. They carry blood away from the heart
- E. They contain valves✓
Explanation: Unlike arteries, veins contain valves that ensure blood flows in only one direction. (Arteries don't require valves because pressure from the heart is so strong that blood is only able to flow in one direction.)
Why the other options are wrong
- A. This statement is true. Arteries have thick walls to withstand the high pressure of blood being pumped from the heart.
- B. This statement is true. Arteries pulsate due to the rhythmic pumping of blood by the heart.
- C. This statement is true. Arteries have more elastic fibers in their walls to allow them to stretch and accommodate the surge of blood with each heartbeat.
- D. This statement is generally true. Arteries carry blood away from the heart, except for the pulmonary artery, which carries blood to the heart.
Q38. The rate of breathing is controlled by the:
- A. Lungs
- B. Cerebellum
- C. Pons
- D. Medulla oblongata✓
- E. Diaphragm
Explanation: The respiratory center is located in the medulla oblongata and is involved in the minute-to-minute control of breathing.
Why the other options are wrong
- A. The lungs are crucial for gas exchange but do not regulate the rate of breathing.
- B. The cerebellum manages balance and coordination, not breathing regulation.
- C. The pons assists the medulla oblongata in controlling breathing, but it is not the primary center.
- E. The diaphragm is a muscle that facilitates breathing but does not control the rate itself.
Q39. The joints that allow movement in two directions are called:
- A. Ball and Socket joint
- B. Hinge joint✓
- C. Cartilaginous joint
- D. Fibrous joint
Explanation: Hinge joints are the ones that allow the movement in only 2 directions. Elbow and knee joints are the examples of hinge joints.
Why the other options are wrong
- A. Ball and socket joints, such as the shoulder and hip, allow movement in multiple directions, not just two.
- C. Cartilaginous joints feature bones entirely joined by cartilage, allowing limited movement, such as in the spine.
- D. Fibrous joints are connected by dense connective tissue and allow minimal to no movement, such as the sutures in the skull.
Q40. _ accepts hydrogen from malate
- A. COQ
- B. FMN
- C. FAD
- D. NAD✓
Explanation: Oxidation(Dehydrogenation -IV) is one of the steps of Krebs cycle, in which Malate is oxidized by removal of hydrogen and oxalo-acetate gets regenerated. The hydrogen removed in this reaction is taken up by the coenzyme NAD to form NADH2.
Why the other options are wrong
- A. Since NAD is the correct answer, hence this option is incorrect.
- B. Since NAD is the correct answer, hence this option is incorrect.
- C. Since NAD is the correct answer, hence this option is incorrect.
Q41. The absorption and use of calcium are regulated by:
- A. Parathormone✓
- B. Adrenaline
- C. Thyroxin
- D. Thiamin
- E. Prolactin
Explanation: Circulating parathyroid hormone targets the distal convoluted tubule and collecting duct, directly increasing calcium reabsorption.
Why the other options are wrong
- B. Option B: Adrenaline, also known as epinephrine, is not directly involved in the regulation of calcium absorption or use in the body. Its primary functions are related to the fight-or-flight response, such as increasing heart rate and blood pressure.
- C. Option C: Thyroxin, or thyroxine, is a hormone produced by the thyroid gland that regulates metabolism. While thyroid hormones play a role in overall metabolic regulation, they are not directly involved in the regulation of calcium absorption or use.
- D. Option D: Thiamin, also known as vitamin B1, is an essential nutrient involved in energy metabolism. However, it does not directly regulate calcium absorption or use in the body.
- E. Option E: Prolactin is a hormone primarily associated with lactation and milk production in females. It does not have a direct role in the regulation of calcium absorption or use.
Q42. Enzymes that are functioning within the cell are called:
- A. Endoenzymes✓
- B. Exoenzymes
- C. Holoenzymes
- D. Both A & C
Explanation: Endoenzymes are enzymes that act within the cell, and their catalytic activity is confined to the interior of the cell. They are involved in intracellular processes, catalyzing reactions within the cell's cytoplasm or organelles. Enzymes involved in glycolysis, the Krebs cycle, or other metabolic pathways taking place inside the cell are considered endoenzymes.
Why the other options are wrong
- B. Exoenzymes are enzymes that act outside the cell. They are synthesized within the cell but are then released into the extracellular environment to catalyze reactions there. They play a role in breaking down large molecules into smaller ones outside the cell, facilitating the uptake of nutrients. Digestive enzymes, such as amylases and lipases, are often exoenzymes. They are produced by cells in the pancreas or salivary glands but function in the extracellular space of the digestive system.
- C. Holoenzyme is a complete, functional enzyme, which is catalytically active. Holoenzyme consists of an apoenzyme together with its cofactors. Holoenzyme contains all the subunits required for the functioning of an enzyme, e.g. DNA polymerase III, RNA polymerase. Holoenzyme = Apoenzyme + Cofactor.
- D. Endoenzymes are enzymes that act within the cell, and their catalytic activity is confined to the interior of the cell. They are involved in intracellular processes, catalyzing reactions within the cell's cytoplasm or organelles. Enzymes involved in glycolysis, the Krebs cycle, or other metabolic pathways taking place inside the cell are considered endoenzymes. A holoenzyme is a fully functional enzyme that consists of both a protein component, known as the apoenzyme, and a non-protein component, referred to as the cofactor. The term "holoenzyme" reflects the complete and active form of the enzyme.
Q43. Lack of relaxation between successive contractions is called :
- A. Spasm
- B. Tetany✓
- C. Arthritis
- D. Fatigue
Explanation: Tetany = sustained contraction without relaxation due to continuous stimul.
Why the other options are wrong
- A. A spasm is a sudden, involuntary muscle contraction that can be painful. Unlike tetany, spasms are usually brief and do not imply sustained contraction.
- C. Arthritis is an inflammation of the joints that causes pain and stiffness but is not directly related to muscle contraction or the lack of relaxation between muscle contractions.
- D. Fatigue refers to a state of physical or mental exhaustion that can lead to decreased performance but does not specifically describe a sustained contraction of muscles.
Q44. Which of the following most appropriately describes haemophilia?
- A. Chromosomal disorder
- B. Dominant gene disorder
- C. Recessive gene disorder
- D. X-linked recessive gene disorder✓
Explanation: Hemophilias (e.g, factor VIII/IX defects) are caused by mutations on the X chromosome and show recessive inheritance — classic X-linked recessive.
Why the other options are wrong
- A. Chromosomal disorders involve abnormalities in chromosome number or structure, often due to nondisjunction during meiosis. Haemophilia is not caused by such chromosomal abnormalities, but by specific gene mutations, so this option is incorrect.
- B. Dominant gene disorders occur when a single copy of a mutated dominant gene causes the disorder. Haemophilia, being an X-linked recessive gene disorder, requires two recessive alleles in females or one in males, hence this option is incorrect.
- C. While haemophilia is a recessive disorder, this option lacks specificity. It must be clarified that haemophilia is an X-linked recessive disorder, which affects inheritance patterns, making this option incomplete.
Q45. Which of the following restriction enzymes produces blunt ends?
- A. Sal I
- B. EcoRV✓
- C. Xho I
- D. Hind III
Explanation: EcoRV is a type II restriction endonuclease isolated from certain strains of E.coli. It creates blunt ends.SalI, XhoI and HindIII restriction enzymes produce sticky ends.
Why the other options are wrong
- A. Sal I is a restriction enzyme that produces sticky ends by making staggered cuts in DNA.
- C. Xho I is a restriction enzyme that produces sticky ends by making staggered cuts in DNA.
- D. Hind III is a restriction enzyme that produces sticky ends by making staggered cuts in DNA.
Q46. The DNA molecule to which the gene of interest is integrated for cloning is called:
- A. Template
- B. Carrier
- C. Transformer
- D. Vector✓
Explanation: Vector is a DNA molecule that carries a foreign DNA segment and replicates inside a host cell. The vector DNA and foreign DNA carrying gene of interest are cut by the same restriction endonuclease enzyme to produce complementary sticky ends. With the help of DNA ligase enzyme, the complementary sticky ends of the two DNAs are joined to produce a recombinant DNA (rDNA), which is then introduced into the host cell.
Why the other options are wrong
- A. A template in molecular biology is a single-stranded DNA or RNA molecule used as a guide for synthesizing a complementary strand during processes like DNA replication or transcription. It is not the DNA molecule used for cloning.
- B. Carrier in molecular biology does not typically refer to the DNA molecule used for cloning. It might refer to methods or mechanisms for transporting genes, but the common term for the DNA molecule used is vector.
- C. A template in molecular biology is a single-stranded DNA or RNA molecule used as a guide for synthesizing a complementary strand during processes like DNA replication or transcription. It is not the DNA molecule used for cloning.
Q47. _ is involved in lipid synthesis/metabolism.
- A. Smooth endoplasmic reticulum✓
- B. Rough endoplasmic reticulum
- C. Mitochondria
- D. Vacuoles
Explanation: The smooth endoplasmic reticulum is an organelle that plays a role in lipid synthesis and metabolism. It is involved in the synthesis of lipids, including fatty acids, phospholipids, and steroids, and is also involved in the metabolism of drugs and toxins.
Why the other options are wrong
- B. The rough endoplasmic reticulum (ER) is involved in protein synthesis. It is covered with ribosomes on its surface, giving it a "rough" appearance under a microscope. The rough ER is responsible for producing proteins, modifying them, and preparing them for transport to other parts of the cell or outside the cell.
- C. Mitochondria are known as the powerhouses of the cell because they generate energy in the form of ATP through cellular respiration. While mitochondria play a vital role in energy production, they are not directly involved in lipid synthesis or metabolism.
- D. Vacuoles are membrane-bound organelles found in plant and fungal cells. They have various functions, including storing water, ions, and nutrients, maintaining cell turgor pressure, and serving as a site for the degradation and recycling of cellular components. Vacuoles are not directly involved in lipid synthesis or metabolism.
Q48. Which of the following animals can survive without drinking water?
- A. Kangaroo rat✓
- B. Pig
- C. Kangaroo
- D. Camel
Explanation: The kangaroo rat is almost perfectly adapted to life in the desert. They can survive without ever drinking any water, getting needed moisture from their seed diet.
Why the other options are wrong
- B. This option is incorrect. Pigs are not specifically adapted to survive without drinking water.
- C. This option is incorrect. Kangaroos are not adapted to survive without drinking water. They typically obtain water through drinking, as well as by consuming moist vegetation.
- D. This option is incorrect. While camels have remarkable water conservation abilities and can survive longer than many other animals without drinking water, they still require water for hydration.
Q49. The part of the nephron involved in active reabsorption of sodium is:
- A. Distal convoluted tubule
- B. Ascending loop of Henle✓
- C. Bowman’s capsule
- D. Descending limb of Henle’s loop
Explanation: The correct answer is the ascending loop of Henle, which is crucial for the active reabsorption of sodium ions from the filtrate back into the bloodstream. This segment utilizes active transport mechanisms to move sodium ions against their concentration gradient, which is essential for maintaining osmotic balance and blood pressure.The distal convoluted tubule causes gradual osmotic outlow of water from the iltrate back to kidney as it passes downward in the descending loop of Henle. Bowman's capsule serves a different function by filtering blood but does not participate in sodium reabsorption. Finally, the descending limb of Henle's loop is primarily involved in the passive reabsorption of water, making it ineffective for sodium reabsorption.
Why the other options are wrong
- A. The distal convoluted tubule (DCT) causes gradual osmotic outlow of water from the iltrate back to kidney as it passes downward in the descending loop of Henle.
- C. Bowman's capsule is responsible for the filtration of blood to produce filtrate but does not play a role in the reabsorption of sodium or other substances.
- D. The descending limb of Henle’s loop primarily facilitates water reabsorption due to its permeable nature but does not engage in active sodium reabsorption.
Q50. At which site does digestion of starches begin?
- A. 3✓
- B. 7
- C. 8
- D. 12
- E. 13
Explanation: In the mouth, as the chewing begins, saliva is released which has the amylase enzyme. The amylase starts breaking down starch to maltose.
Why the other options are wrong
- B. Oesophagus does not participate in the digestion of starches.
- C. The liver is involved in various metabolic processes, but it does not directly participate in the digestion of starches.
- D. While the stomach plays a crucial role in digestion, the digestion of starches does not primarily occur in the stomach.
- E. These are small intestine and here the last digestive activity takes place and all the food is digested and absorption takes place
Q51. An antibody molecule consists of:
- A. Two identical light chains only
- B. Two identical heavy chains only
- C. Two identical light and two identical heavy chains✓
- D. Two identical light chains and two non-identical heavy chains
Explanation: An antibody molecule, also known as an immunoglobulin, is a Y-shaped protein that plays a critical role in the immune response by recognizing and binding to antigens. Its structure includes two identical light chains and two identical heavy chains, which are connected by disulfide bonds. This configuration allows antibodies to specifically bind to antigens. Option A is incorrect because it only mentions light chains. Option B is incorrect because it only mentions heavy chains. Option D is incorrect because it suggests the heavy chains are non-identical, which is not the case.
Why the other options are wrong
- A. This option is incorrect because an antibody molecule consists of more than just light chains; it also includes heavy chains.
- B. This option is incorrect because an antibody molecule not only has heavy chains but also includes light chains.
- D. This option is incorrect because both the light chains and the heavy chains in an antibody molecule are identical to each other.
Q52. Which of the following explains the binding of inorganic components in structures found in erythrocytes?
- A. CO with organic portion of haem
- B. CO2 with NH2 group of haemoglobin
- C. O2 with Fe of haem✓
- D. H+ with COOH group of haemoglobin
Explanation: Oxygen binds to the iron (Fe) in haem groups of haemoglobin, forming oxyhaemoglobin to transport oxygen from lungs to tissues.
Why the other options are wrong
- A. Carbon monoxide (CO) can bind to haemoglobin in a similar manner to oxygen, but it forms a much stronger bond with haemoglobin. This can lead to carbon monoxide poisoning, as it reduces the ability of haemoglobin to bind and transport oxygen effectively. The option is incorrect in saying that it binds to an "organic" portion because it binds to Fe that is inorganic.
- B. Carbon dioxide (CO2) is mainly transported in the blood in the form of bicarbonate ions (HCO3-) rather than directly binding to haemoglobin.
- D. Hydrogen ions (H+) do not directly bind to haemoglobin. However, they can influence the oxygen-haemoglobin dissociation curve and affect the affinity of haemoglobin for oxygen.
Q53. Nutrition refers to the processes involved in:
- A. Taking in of food
- B. Utilization of food elements
- C. Growth, repair, and maintenance
- D. All of the above options are correct✓
Explanation: Nutrition is the process of taking in food and converting it into energy and other vital nutrients required for life. Nutrients are the substances that provide energy and biomolecules necessary for carrying out the various body functions. All living organisms need nutrients for proper functioning and growth.
Why the other options are wrong
- A. Nutrition is the process of taking in food and converting it into energy and other vital nutrients required for life. Nutrients are the substances that provide energy and biomolecules necessary for carrying out the various body functions. All living organisms need nutrients for proper functioning and growth.
- B. Nutrition involves the utilization of food elements. Nutrition is the process of taking in food and converting it into energy and other vital nutrients required for life. Nutrients are the substances that provide energy and biomolecules necessary for carrying out the various body functions. All living organisms need nutrients for proper functioning and growth.
- C. Nutrition is the process of taking in food and converting it into energy and other vital nutrients required for life. Nutrients are the substances that provide energy and biomolecules necessary for carrying out the various body functions. All living organisms need nutrients for proper functioning and growth.
Q54. Which of the following is true in case of induced fit model?
- A. The substrate changes its shape slightly.
- B. The enzyme changes its shape slightly.✓
- C. None of them changes shape.
- D. Both changes shape.
Explanation: Correct option B Since according to the induced fit model presented by koshland the binding of substrate or other molecules to enzyme causes changes in enzyme to enhance or inhibit its activity.
Why the other options are wrong
- A. Option A is incorrect because according to the induced fit model the substrate doesn't change its shape slightly when interacted with enzymes.
- C. Option C is also incorrect because only the shape of enzyme slightly changes when enzyme and substrate interact.
- D. Option D is also incorrect because according to the induced fit hypothesis only the shape of enzyme gets changed slightly when enzyme and substrate interact.
Q55. A metal cofactor which is used in synthesis of glycolysis is?
- A. Fe3+
- B. Mn2+
- C. Co2+
- D. Mg2+✓
Explanation: "Mg2+" is an inorganic cofactor used in glycolysis to convert glucose into glucose 6-phosphate.
Why the other options are wrong
- A. Fe3+ is an iron supplement indicated in the treatment of iron deficiency anemia.
- B. The metal cofactors Mn2+, appear to stabilize two distinct conformational states of the enzyme which differ in response to varying substrate and effector concentrations
- C. Co2+ isn't a cofactor
Q56. The nephrons arranged along the cortex are called:
- A. Cortical✓
- B. Juxtamedullary
- C. Juxtacortical nephron
- D. Medullary
Explanation: Nephrons that are arranged along the cortex of the kidney are called "cortical nephrons." Cortical nephrons are one of the two main types of nephrons found in the human kidney, with the other type being juxtamedullary nephrons. These two types of nephrons have distinct features and functions within the kidney. Cortical nephrons are primarily located in the outer part of the renal cortex, and they do not extend deeply into the renal medulla. They play essential roles in the initial filtration of blood, reabsorption of nutrients and electrolytes, and regulation of overall body homeostasis. Unlike juxtamedullary nephrons, cortical nephrons do not have long loops of Henle that extend deeply into the renal medulla, and they do not play a primary role in the concentration of urine.
Why the other options are wrong
- B. Nephrons that are arranged along the medulla of the kidney are called "juxtamedullary nephrons." Juxtamedullary nephrons are one of the two main types of nephrons found in the human kidney, with the other type being cortical nephrons. Juxtamedullary nephrons are primarily located in the inner part of the renal cortex and extend deep into the renal medulla. These nephrons have long loops of Henle that reach deep into the medulla, and they play a critical role in the regulation of water balance and the production of concentrated urine. The specialized features of juxtamedullary nephrons make them well-suited for tasks related to maintaining osmotic gradients in the kidney and facilitating water conservation in the body.
- C. The term "juxtacortical nephron" is not a commonly used or recognized term in the field of renal physiology or nephrology. The two primary types of nephrons found in the human kidney are cortical nephrons and juxtamedullary nephrons, as previously explained.
- D. A "medullary nephron" typically refers to a juxtamedullary nephron, which is one of the two primary types of nephrons found in the human kidney. Medullary nephrons are so named because they are located near the renal medulla, the inner part of the kidney.
Q57. The optimum pH for the functioning of enzyme pepsin is:
- A. 2✓
- B. 3
- C. 4
- D. 5
Explanation: The optimum pH for the functioning of the enzyme pepsin is 2. Pepsin is a digestive enzyme produced in the stomach It plays a crucial role in the digestion of proteins.
Why the other options are wrong
- B. This option is incorrect. The optimum pH for the functioning of the enzyme pepsin is 2. Pepsin is a digestive enzyme produced in the stomach It plays a crucial role in the digestion of proteins.
- C. This option is incorrect. The optimum pH for the functioning of the enzyme pepsin is 2. Pepsin is a digestive enzyme produced in the stomach It plays a crucial role in the digestion of proteins.
- D. This option is incorrect. The optimum pH for the functioning of the enzyme pepsin is 2. Pepsin is a digestive enzyme produced in the stomach It plays a crucial role in the digestion of proteins.
Q58. Which of the following is the correct statement?
- A. The descending limb of loop of Henle is impermeable to water.
- B. The ascending limb of loop of Henle is permeable to water.
- C. The descending limb of loop of Henle is permeable to electrolytes.
- D. The ascending limb of loop of Henle is impermeable to water.✓
Explanation: The key difference between ascending and descending loop of Henle is that the ascending loop of Henle is the thicker segment of the loop of Henle located just after the sharp bend of the loop while descending loop of Henle is the thinner segment located just before the sharp bend of the loop. The descending limb of the loop of Henle is permeable to water. Water diffuses into the hyperosmolar medullary interstitium.
Why the other options are wrong
- A. This statement is incorrect. The descending limb of the loop of Henle is permeable to water, allowing water to diffuse out into the surrounding hyperosmolar medullary interstitium.
- B. This statement is incorrect. The ascending limb of the loop of Henle is impermeable to water, but it actively transports ions out into the medullary interstitium.
- C. This statement is incorrect. The descending limb is primarily permeable to water, not electrolytes. Electrolyte permeability is a feature of the ascending limb.
Q59. A person who is on a long hunger strike and is surviving only on water, will have:
- A. Less amino acids in his urine
- B. More glucose in his blood
- C. Less urea in his urine✓
- D. More sodium in his urine.
Explanation: During starvation, the body must rely on body proteins for the amino acids. On high protein diets the carbon skeletons of the amino acids are oxidized for energy or stored as fat and glycogen, but the amino nitrogen must be excreted. To facilitate this process, enzymes of the urea cycle are controlled at the gene level. When dietary proteins increase significantly, enzyme concentrations rise. On return to a balanced diet, enzyme levels decline. Under conditions of starvation, enzyme levels rise as proteins are degraded and amino acid carbon skeletons are used to provide energy, thus increasing the quantity of nitrogen that must be excreted in the form of urea.
Why the other options are wrong
- A. This is incorrect because starvation leads to the breakdown of body proteins, increasing amino acid breakdown products in the urine.
- B. This is incorrect because during prolonged fasting, blood glucose levels tend to decrease as glycogen stores are depleted to provide for the decreasing energy levels.
- D. This is incorrect because sodium levels are typically conserved during fasting to maintain electrolyte balance.
Q60. Some enzymes require the presence of a non protein molecule to behave catalytically. An enzyme devoid of this molecule is called a(n):
- A. Holoenzyme
- B. Apoenzyme✓
- C. Coenzyme
- D. Zymoenzyme
Explanation: Enzyme with a non-proteinous part is called Holoenzyme; without that non-proteinous part, it is called Apoenzyme.
Why the other options are wrong
- A. Holoenzyme is an enzyme with an cofactor and prosthetic group attached this is fully active enzyme.
- C. Coenzyme is an non-protein part of an enzyme which is lovely bonded to an enzyme and may and may not be required for proper functioning of an enzyme.
- D. This is not correct as there not a thing as such as zymoenzyme.
Q61. The diagram given here is the standard ECG of a normal person. The P-wave represents the:
- A. Beginning of the systole
- B. End of systole
- C. Contraction of both the atria✓
- D. Initiation of the ventricular contraction
Explanation: P-wave represents the electrical excitation (or depolarisation) of the atria, which leads to the contraction of both the atria. The QRS complex represents the depolarisation of the ventricles, which initiates the ventricular contraction. The contraction starts shortly after Q and marks the beginning of the systole. The T wave represents the return of the ventricles from excited to normal state. (repolarisation). The end of the T-wave marks the end of systole.
Why the other options are wrong
- A. The systole refers to the phase of the cardiac cycle when the heart muscle contracts. The P-wave on an electrocardiogram (ECG) represents the electrical depolarization and subsequent contraction of the atria, not the beginning of systole. The P-wave indicates the initiation of the electrical activity that leads to the contraction of the atria, rather than the beginning of systole itself.
- B. The end of systole is not represented by the P-wave on an ECG. Systole encompasses both atrial contraction and ventricular contraction, and the P-wave specifically represents atrial depolarization and contraction, rather than the end of systole.
- D. The initiation of ventricular contraction is not represented by the P-wave on an ECG. The ventricular contraction is initiated by the electrical activity that follows the P-wave, specifically the QRS complex. The QRS complex represents the depolarization and subsequent contraction of the ventricles, leading to the ejection of blood from the heart.
Q62. Given below are four statements (i-iv) regarding human blood circulatory system. (i) Arteries are thick-walled and have narrow lumen as compared to veins. (ii) Angina is acute chest pain when the blood circulation to the brain is reduced. (iii) Persons with blood group AB can donate blood to any person with any blood group under ABO system. (iv) Calcium ions play a very important role in blood clotting. Which two of the above statements is/are correct?
- A. (i) and (iv)✓
- B. (i) and (ii)
- C. (ii), (iii) and (iv)
- D. (iii), (iv) and (i)
Explanation: The correct statements (i)and (iv) are correct.(i) Arteries are thick-walled and have narrow lumen as compared to veins. Arteries are blood vessels that carry oxygenated blood away from the heart to various parts of the body. They have thick walls containing smooth muscle and elastic fibers, which allow them to withstand the high pressure generated by the heart's pumping action. Arteries also have a smaller lumen (the central opening through which blood flows) to maintain the blood pressure and ensure proper blood flow to the tissues. (iv) Calcium ions play a very important role in blood clotting.The statement about calcium ions is correct. Calcium ions play a crucial role in the process of blood clotting or coagulation. When there is an injury or damage to blood vessels, a series of complex reactions involving various clotting factors take place, ultimately leading to the formation of a blood clot to prevent excessive bleeding. Calcium ions are essential for the activation of clotting factors and the formation of a stable blood clot.
Why the other options are wrong
- B. (i) This statement is correct. Arteries are thick-walled and have narrow lumen as compared to veins.Arteries are thick-walled and have narrow lumen as compared to veins. Arteries are blood vessels that carry oxygenated blood away from the heart to various parts of the body. They have thick walls containing smooth muscle and elastic fibers, which allow them to withstand the high pressure generated by the heart's pumping action. Arteries also have a smaller lumen (the central opening through which blood flows) to maintain the blood pressure and ensure proper blood flow to the tissues.(ii) The statement regarding angina is not correct. Angina is not related to reduced blood circulation to the brain but is a condition caused by reduced blood flow to the heart muscles due to narrowed or blocked coronary arteries. It results in acute chest pain or discomfort due to inadequate oxygen supply to the heart.
- C. (ii) The statement regarding angina is not correct. Angina is not related to reduced blood circulation to the brain but is a condition caused by reduced blood flow to the heart muscles due to narrowed or blocked coronary arteries. It results in acute chest pain or discomfort due to inadequate oxygen supply to the heart. (iii) The statement about blood group AB is not correct. Persons with blood group AB are universal recipients, meaning they can receive blood from any ABO blood group. However, they cannot donate blood to any person with any blood group. Blood group AB individuals can donate blood only to other individuals with blood group AB. (iv) Calcium ions play a very important role in blood clotting.The statement about calcium ions is correct. Calcium ions play a crucial role in the process of blood clotting or coagulation. When there is an injury or damage to blood vessels, a series of complex reactions involving various clotting factors take place, ultimately leading to the formation of a blood clot to prevent excessive bleeding. Calcium ions are essential for the activation of clotting factors and the formation of a stable blood clot.
- D. (i) Arteries are thick-walled and have narrow lumen as compared to veins. Arteries are blood vessels that carry oxygenated blood away from the heart to various parts of the body. They have thick walls containing smooth muscle and elastic fibers, which allow them to withstand the high pressure generated by the heart's pumping action. Arteries also have a smaller lumen (the central opening through which blood flows) to maintain the blood pressure and ensure proper blood flow to the tissues. (iv) Calcium ions play a very important role in blood clotting.The statement about calcium ions is correct. Calcium ions play a crucial role in the process of blood clotting or coagulation. When there is an injury or damage to blood vessels, a series of complex reactions involving various clotting factors take place, ultimately leading to the formation of a blood clot to prevent excessive bleeding. Calcium ions are essential for the activation of clotting factors and the formation of a stable blood clot. (iii) The statement about blood group AB is not correct. Persons with blood group AB are universal recipients, meaning they can receive blood from any ABO blood group. However, they cannot donate blood to any person with any blood group. Blood group AB individuals can donate blood only to other individuals with blood group AB.
Q63. An example of competitive inhibition of an enzyme is the inhibition of:
- A. Succinic dehydrogenase by malonic acid✓
- B. Cytochrome oxidase by cyanide
- C. Hexokinase by glucose
- D. Carbonic anhydrase by carbon dioxide
Explanation: The inhibition of succinic dehydrogenase by malonic acid is an example of competitive inhibition. Succinic dehydrogenase is an enzyme involved in the citric acid cycle (also known as the Krebs cycle) and plays a role in the conversion of succinate to fumarate. Malonic acid serves as a competitive inhibitor in this context. It structurally resembles the substrate (succinate) and competes with it for binding to the active site of succinic dehydrogenase. Malonic acid binds to the active site of the enzyme, preventing the normal substrate (succinate) from binding and undergoing the catalytic reaction. The presence of malonic acid decreases the rate of the succinic dehydrogenase-catalyzed reaction by interfering with the binding of succinate.
Why the other options are wrong
- B. Cyanide is a potent inhibitor of cytochrome c oxidase, also known as complex IV, which is a crucial enzyme in the electron transport chain of cellular respiration. Cytochrome c oxidase is responsible for the final step in the electron transport chain, where electrons are transferred to molecular oxygen, resulting in the production of water.
- C. Hexokinase is an enzyme that catalyzes the phosphorylation of glucose to form glucose-6-phosphate. This reaction is the first step in the glycolytic pathway, a central metabolic pathway that involves the breakdown of glucose to produce energy.
- D. Carbonic anhydrase is an enzyme that catalyzes the reversible hydration of carbon dioxide (CO2) to form bicarbonate ions (HCO3-) and protons (H+). This reaction is an essential part of various physiological processes, particularly in the transport of carbon dioxide in the blood and the regulation of acid-base balance.
Q64. First infectious disease against which effective method of prevention developed was a _:
- A. Bacterial disease
- B. Viral disease✓
- C. Protozoan disease
- D. Viroid disease
Explanation: b. Viral disease: This option is correct. The smallpox vaccine, developed in the late 18th century by Edward Jenner, is a landmark achievement in the prevention of viral diseases. It played a crucial role in the eventual global eradication of smallpox. c. Protozoan disease: Protozoan diseases are caused by single-celled organisms (protozoa). Prevention methods for these diseases often involve medications (antiprotozoal drugs) rather than vaccines. Malaria, caused by the Plasmodium protozoan, is an example of a protozoan disease with preventive measures like antimalarial drugs and bed nets. d. Viroid disease: Viroids are infectious agents consisting of small, circular RNA molecules. They cause diseases in plants. Preventive methods for viroid diseases typically involve plant hygiene and control measures, as there are no widely recognized vaccines for viroids. Correct Answer: b. Viral disease Explanation: The smallpox vaccine is a historic example of the first effective prevention method developed against a viral disease, marking a significant milestone in the history of infectious disease control. Summary: The correct answer is b. Viral disease. The smallpox vaccine, developed for the prevention of smallpox caused by the variola virus, is a groundbreaking achievement in the history of infectious disease prevention. While bacterial diseases also saw early success with vaccination, the smallpox vaccine stood out as a pivotal moment in addressing viral infections and contributed to the eventual global eradication of smallpox.
Why the other options are wrong
- A. This is not correct as against bacterial diseases usually antibiotics are used and it is an effective treatment for it although long term use of antibiotics can produce resistance in bacteria against that specific disease.
- C. Protozoan diseases are caused by single-celled organisms (protozoa). Prevention methods for these diseases often involve medications (antiprotozoal drugs) rather than vaccines. Malaria, caused by the Plasmodium protozoan, is an example of a protozoan disease with preventive measures like antimalarial drugs and bed nets.
- D. Viroids are infectious agents consisting of small, circular RNA molecules. They cause diseases in plants. Preventive methods for viroid diseases typically involve plant hygiene and control measures, as there are no widely recognized vaccines for viroids.
Q65. Vaccines for all of these have been developed except
- A. Polio
- B. Mumps
- C. Measles
- D. Cancer✓
Explanation: Vaccine is a preparation that is used to stimulate the body's immune response against diseases
Why the other options are wrong
- A. Vaccine is The primary vaccine used to prevent polio is called the polio vaccine, which comes in two different forms: the inactivated polio vaccine (IPV) and the oral polio vaccine (OPV). 1. Inactivated Polio Vaccine (IPV): IPV is an injectable vaccine that contains killed poliovirus strains. It is given in a series of doses usually administered at ages 2 months, 4 months, 6-18 months, and a booster dose between 4-6 years of age. IPV is considered very safe and is the only polio vaccine used in countries where polio has been eradicated. 2. Oral Polio Vaccine (OPV): OPV is an oral vaccine that contains live, weakened poliovirus strains. It is given as drops in the mouth and is more commonly used in countries where polio is still endemic or poses a higher risk. OPV has the advantage of also providing immunity in the intestines, which can help interrupt the transmission of the virus. However, in very rare cases, the weakened virus in OPV can revert to a form that can cause paralysis, leading to a condition called vaccine-associated paralytic polio (VAPP). Both IPV and OPV are highly effective in preventing polio and have played a crucial role in reducing the number of polio cases worldwide. The choice between IPV and OPV depends on the specific circumstances and recommendations of national immunization programs. It's important to note that as of my knowledge cutoff in September 2021, polio remains endemic in Afghanistan and Pakistan, with occasional outbreaks reported in a few other countries.
- B. The vaccine used to prevent mumps is called the MMR vaccine, which stands for measles, mumps, and rubella. The MMR vaccine is a combination vaccine that protects against all three of these viral infections. The MMR vaccine contains weakened forms of the mumps virus, along with the measles and rubella viruses. It is typically given as a two-dose series, with the first dose administered around 12-15 months of age and the second dose given between 4-6 years of age. In some cases, a single-dose MMR vaccine schedule may be used for certain individuals. The MMR vaccine is very effective in preventing mumps, as well as measles and rubella. It stimulates the immune system to produce protective antibodies that recognize and fight the mumps virus, providing long-lasting immunity. Vaccination is important for preventing mumps outbreaks and complications associated with the disease, such as orchitis (inflammation of the testicles) in males, meningitis, and deafness. It's worth noting that no vaccine provides 100% protection, but the MMR vaccine is highly effective. In rare cases, individuals who have received the vaccine may still contract mumps, but the illness is typically milder and with fewer complications compared to those who are unvaccinated. As always, it's advisable to consult with a healthcare professional or your local health authorities for the most up-to-date and specific vaccination recommendations regarding mumps.
- C. Vaccine used to prevent measles is the MMR vaccine, which stands for measles, mumps, and rubella. The MMR vaccine is a combination vaccine that protects against all three of these viral infections. The MMR vaccine contains weakened forms of the measles virus, along with the mumps and rubella viruses. It is typically given as a two-dose series, with the first dose administered around 12-15 months of age and the second dose given between 4-6 years of age. In some cases, a single-dose MMR vaccine schedule may be used for certain individuals. The MMR vaccine is highly effective in preventing measles. It stimulates the immune system to produce protective antibodies that recognize and fight the measles virus, providing long-lasting immunity. Vaccination is crucial for preventing measles outbreaks and the associated complications of the disease, which can include severe respiratory infections, pneumonia, encephalitis (inflammation of the brain), and in rare cases, even death. The MMR vaccine is safe and has been widely used for many years. Serious side
Q66. The function of nasal cavity is:
- A. Protection
- B. Moisten
- C. Temperature regulation
- D. All A, B and C✓
Explanation: The nasal cavity is a part of the respiratory system located behind the nose. It performs three important functions: Moistening: The nasal cavity produces mucus to moisten the air we breathe, preventing the respiratory tract from drying out. Protecting: Mucus in the nasal cavity traps dust, allergens, and other particles, keeping them from reaching the lungs. Regulating Temperature: The nasal cavity warms the inhaled air to body temperature, preventing discomfort from breathing in cold air. These functions are crucial for the proper functioning and protection of the respiratory system.
Why the other options are wrong
- A. The nasal cavity provides protection by trapping dust, microbes, and other harmful particles in the mucus.Tiny hair-like structures called cilia help sweep these trapped particles away from the respiratory tract.This prevents pathogens from entering deeper parts of the lungs.The mucous lining also contains immune cells that destroy invading microorganisms.Thus, protection is one of the primary functions of the nasal cavity.
- B. The nasal cavity helps moisten the incoming air before it reaches the lungs.The mucous membrane secretes fluids that add humidity to the air.This prevents dryness in the respiratory tract.Moist air is better for gas exchange at the alveoli.Hence, moisturizing the air is another key function of the nasal cavity.
- C. The nasal cavity adjusts the temperature of inhaled air to match body temperature.Cold air is warmed as it passes over the blood-rich mucous membranes.Similarly, very hot air is cooled slightly to avoid damaging the respiratory lining.This process ensures that air entering the lungs is safe for delicate tissues.Therefore, temperature regulation is also a function of the nasal cavity.
Q67. Various factors of pathological and chemical nature may progressively destroy the nephron, particularly its:
- A. Glomerulus✓
- B. Convoluted Tubule
- C. Loop of Henle
- D. Bowman's Capsule
Explanation: The correct answer is the glomerulus because it is the primary site of filtration within the nephron, making it particularly vulnerable to damage from pathological and chemical factors. These factors can impair the glomerulus's ability to filter blood effectively, leading to progressive destruction. In contrast, the convoluted tubules and loop of Henle are more involved in reabsorption and concentration of urine, respectively, and while they can be affected, they are not the primary sites of initial damage. The Bowman's capsule surrounds the glomerulus and can also be impacted, but the glomerulus itself is more directly involved in the filtration process and therefore is more susceptible to progressive damage.
Why the other options are wrong
- B. While various pathological and chemical factors can affect the convoluted tubules, they primarily play a role in reabsorption and secretion rather than filtration. The convoluted tubules are responsible for reabsorbing valuable substances, such as glucose, electrolytes, and water, back into the bloodstream.
- C. The loop of Henle plays a crucial role in establishing the concentration gradient in the kidney, allowing for the reabsorption of water and electrolytes. It is involved in concentrating urine. While various factors can impact the function of the loop of Henle, it is not the primary site of progressive destruction within the nephron.
- D. The Bowman's capsule, along with the glomerulus, forms the renal corpuscle. It serves as the initial site of filtration, receiving the filtrate from the glomerulus. Pathological and chemical factors can damage the Bowman's capsule, but it is not the primary focus of progressive destruction in the nephron.
Q68. The number of spinal nerves along the spinal cord is:
- A. 16 pairs
- B. 20 pairs
- C. 31 pairs✓
- D. 33 pairs
Explanation: There are 31 pairs of spinal nerves in the human body. These nerves emerge from the spinal cord and pass through openings between adjacent vertebrae, distributing to various regions of the body.
Why the other options are wrong
- A. This option is incorrect. There are 31 pairs of spinal nerves in the human body. These nerves emerge from the spinal cord and pass through openings between adjacent vertebrae, distributing to various regions of the body.
- B. This option is incorrect. There are 31 pairs of spinal nerves in the human body. These nerves emerge from the spinal cord and pass through openings between adjacent vertebrae, distributing to various regions of the body.
- D. This option is incorrect. There are 31 pairs of spinal nerves in the human body. These nerves emerge from the spinal cord and pass through openings between adjacent vertebrae, distributing to various regions of the body.
Q69. The brain is protected by:
- A. Sacrum
- B. Cranium✓
- C. Humerus
- D. Scapula
Explanation: The brain is produced by the "b) Cranium," which forms the protective bony enclosure for this vital organ. The cranium, also known as the skull, is the bony structure that forms the protective enclosure for the brain. It is a complex structure made up of several bones that fuse together during development to provide a solid and robust casing for the brain. The cranium not only safeguards the brain from external injuries but also provides support and structure to the head. The brain is a vital organ of the central nervous system, responsible for controlling various bodily functions, cognitive processes, emotions, and voluntary and involuntary actions. It is encased within the cranium to shield it from mechanical damage and to maintain a stable and protective environment.
Why the other options are wrong
- A. The sacrum is a triangular-shaped bone located at the base of the spine, forming part of the vertebral column. It is not involved in producing the brain; its primary function is to support the weight of the upper body and transmit it to the pelvic girdle.
- C. The humerus is a long bone in the upper arm, connecting the shoulder joint to the elbow joint. It is not involved in producing the brain; its main function is to facilitate arm movement and serve as an attachment site for muscles.
- D. The scapula, also known as the shoulder blade, is a flat, triangular bone located on the back of the shoulder. Like the humerus, it is not involved in producing the brain; its main function is to provide support and attachment points for muscles that control shoulder movement.
Q70. The shape of grey matter is:
- A. Spherical
- B. Mosquito
- C. Butterfly✓
- D. Rectangular
Explanation: Grey matter is shaped like the letter "H" or a "butterfly". The grey matter consists of neuron cell bodies and non-myelinated parts of the fibres. The white matter is made up of bundles of myelinated fibres.
Why the other options are wrong
- A. Grey matter is shaped like the letter "H" or a "butterfly", not spherical.
- B. Grey matter is not shaped like a mosquito.
- D. Grey matter is not shaped like a rectangle; rather, it is 'H' shaped.
Q71. Hypothalamus initiates the release of hormones, by their releasing factors, while _ is directly produced by it.
- A. TSH
- B. Oxytocin✓
- C. ACTH
- D. FSH
- E. GH
Explanation: Option A: TSH (thyroid-stimulating hormone) is released by the anterior pituitary gland in response to a releasing factor called thyrotropin-releasing hormone (TRH) from the hypothalamus. Option B: Oxytocin is released directly by the hypothalamus into the bloodstream. It is involved in childbirth, breastfeeding, and social bonding. Option C: ACTH (adrenocorticotropic hormone) is released by the anterior pituitary gland in response to a releasing factor called corticotropin-releasing hormone (CRH) from the hypothalamus. ACTH stimulates the release of cortisol from the adrenal glands. Option D: FSH (follicle-stimulating hormone) and LH (luteinizing hormone) are released by the anterior pituitary gland in response to releasing factors called follicle-stimulating hormone-releasing hormone (FSHRH) and luteinizing hormone-releasing hormone (LHRH) from the hypothalamus. FSH and LH are involved in the regulation of reproduction. Option E: GH (growth hormone) is released by the anterior pituitary gland in response to a releasing factor called growth hormone-releasing hormone (GHRH) from the hypothalamus. GHRH stimulates the release of GH, which is involved in growth and development.
Why the other options are wrong
- A. TSH (thyroid-stimulating hormone) is released by the anterior pituitary gland in response to a releasing factor called thyrotropin-releasing hormone (TRH) from the hypothalamus.
- C. ACTH (adrenocorticotropic hormone) is released by the anterior pituitary gland in response to a releasing factor called corticotropin-releasing hormone (CRH) from the hypothalamus. ACTH stimulates the release of cortisol from the adrenal glands.
- D. FSH (follicle-stimulating hormone) and LH (luteinizing hormone) are released by the anterior pituitary gland in response to releasing factors called follicle-stimulating hormone-releasing hormone (FSHRH) and luteinizing hormone-releasing hormone (LHRH) from the hypothalamus. FSH and LH are involved in the regulation of reproduction.
- E. GH (growth hormone) is released by the anterior pituitary gland in response to a releasing factor called growth hormone-releasing hormone (GHRH) from the hypothalamus. GHRH stimulates the release of GH, which is involved in growth and development.
Q72. PCR and restriction fragment length polymorphism (RFLP) are the methods for?
- A. Study of enzymes
- B. Genetic transformation
- C. DNA sequencing
- D. Genetic fingerprinting✓
Explanation: Polymerase chain reaction (PCR) is used to amplify a small DNA fragment to obtain its large quantity. PCR is very helpful in DNA fingerprinting in such cases where the culprit has to be identified from a very small blood, semen or another cell sample from a crime scene. Restriction fragment length polymorphism(RFLP) is used to determine or confirm the source of DNA sample such as in paretnity tests or criminal investigtaions In genetic mapping to determine recombination rates that show the genetic distance between the loci. To identify a carrier of a disease-causing mutation in a family.
Why the other options are wrong
- A. The study of enzymes is a critical area within biochemistry and molecular biology. Enzymes are biological molecules, typically proteins, that act as catalysts in various biochemical reactions. They play a fundamental role in all living organisms, facilitating and regulating a wide range of chemical processes. The study of enzymes encompasses various aspects, including their structure, function, regulation, and applications.
- B. Genetic transformation is a process in which the genetic material (usually DNA) of an organism is altered by the introduction of external DNA. This external DNA can come from the same species or a different one. Genetic transformation is a fundamental technique in molecular biology and genetics and has numerous applications in various fields, including biotechnology, agriculture, and medicine.
- C. DNA sequencing is the process of determining the precise order of nucleotides (adenine, thymine, guanine, and cytosine) in a DNA molecule. It is a fundamental technique in molecular biology and genetics, with a wide range of applications, including studying genetic variation, diagnosing genetic diseases, and understanding the genetic basis of various biological processes.
Q73. Serum differs from blood in:
- A. Lacking globulins
- B. Lacking albumins
- C. Lacking clotting factors✓
- D. Lacking antibodies.
Explanation: Serum is plasma without clotting proteins like fibrinogen, which are consumed during coagulation.
Why the other options are wrong
- A. Globulins are proteins in the blood, including antibodies, and are present in both serum and plasma. Serum contains globulins, so this option is incorrect.
- B. Albumins are vital proteins for maintaining osmotic pressure and are present in both serum and plasma. Serum is not lacking albumins, making this option incorrect.
- D. Serum contains antibodies, which are important immune proteins and a type of globulin. Antibodies are present in serum, so this option is incorrect.
Q74. Venous blood enter route from the kidneys to the heart must pass through the:
- A. Iliac vein
- B. Inferior vena cava✓
- C. Liver
- D. Hepatic vein
- E. Pulmonary vein
Explanation: The kidneys receive unfiltered blood directly from the heart through the abdominal aorta which then branches to the left and right renal arteries. Filtered blood then returns by the left and right renal veins to the inferior vena cava and then the heart.
Why the other options are wrong
- A. The iliac vein collects blood from the lower limbs and pelvis, not directly from the kidneys.
- C. The liver is an organ involved in detoxification and metabolism, not a blood vessel or pathway for venous return from the kidneys.
- D. The hepatic vein drains blood from the liver, not the kidneys, into the inferior vena cava.
- E. The pulmonary vein carries oxygenated blood from the lungs to the heart, which is unrelated to the venous return from the kidneys.
Q75. Premature birth or miscarriage is usually caused by the disturbance in secretion of which of the following hormone?
- A. Estrogen
- B. Progesterone✓
- C. Lactogen
- D. Luteinizing Hormone (LH)
Explanation: Progesterone is one of the sex hormones closely associated with pregnancy and the menstrual cycle. It can also play a role in recurrent miscarriages or premature birth.
Why the other options are wrong
- A. Estrogen is crucial for early pregnancy as it prepares the uterine lining. However, once the placenta forms, progesterone takes over the role of maintaining the pregnancy.
- C. Lactogen, specifically human placental lactogen, is involved in preparing the breasts for lactation and does not play a direct role in preventing miscarriage or premature birth.
- D. Luteinizing Hormone is involved in the regulation of the menstrual cycle and ovulation but is not directly linked to maintaining pregnancy or preventing miscarriage.
Q76. Suggest which among the following is not a function attributed to endoplasmic reticulum?
- A. Detoxification of poisons and drugs
- B. Digestion/egestion of foreign materials outside the cell✓
- C. Manufacture of fat and lipid molecules
- D. Biogenesis of membrane proteins
Explanation: The endoplasmic reticulum is involved in the detoxification of the poisons and the drugs. This is the main function of the endoplasmic reticulum in the liver. The manufacturing of the lipids and fat molecules take place in the smooth ER. The membrane proteins are synthesised on the ribosomes which are present on the surface of the ER. The digestion and egestion of the foreign materials which enter the cells take place in the lysosomes. Thus, the correct answer is option B.
Why the other options are wrong
- A. The endoplasmic reticulum is involved in the detoxification of the poisons and the drugs. This is the main function of the endoplasmic reticulum in the liver. The manufacturing of the lipids and fat molecules take place in the smooth ER. The membrane proteins are synthesized on the ribosomes which are present on the surface of the ER.
- C. The endoplasmic reticulum is involved in the detoxification of the poisons and the drugs. This is the main function of the endoplasmic reticulum in the liver. The manufacturing of the lipids and fat molecules take place in the smooth ER. The membrane proteins are synthesized on the ribosomes which are present on the surface of the ER.
- D. The endoplasmic reticulum is involved in the detoxification of the poisons and the drugs. This is the main function of the endoplasmic reticulum in the liver. The manufacturing of the lipids and fat molecules take place in the smooth ER. The membrane proteins are synthesized on the ribosomes which are present on the surface of the ER.
Q77. Which property of water helps to maintain the integrity of lipid membranes?
- A. Specific heat capacity
- B. Cohesion and adhesion
- C. Hydrogen bonding
- D. Hydrophobic exclusion✓
Explanation: The correct answer is Hydrophobic exclusion. This property is critical for the formation and stability of lipid membranes, as lipid molecules are hydrophobic and tend to exclude water. This exclusion leads to the formation of a lipid bilayer, creating a barrier between the aqueous environments inside and outside the cell. The other options, such as specific heat capacity, cohesion and adhesion, and hydrogen bonding, are important properties of water but do not directly contribute to the structural integrity of lipid membranes.
Why the other options are wrong
- A. Specific heat capacity is the amount of energy required to change the temperature of a substance. While water's high specific heat capacity plays a role in temperature regulation, it does not directly affect the structural integrity of lipid membranes.
- B. Cohesion and adhesion are properties of water that contribute to surface tension and capillary action. These properties involve interactions between water molecules and other substances, but they do not play a direct role in maintaining the structure of lipid membranes.
- C. Hydrogen bonding is responsible for many unique properties of water, such as high surface tension and solvent capabilities. However, it is not the primary factor in preserving the structural integrity of lipid membranes, which rely on interactions between hydrophobic molecules.
Q78. Which of the following is correct for the given structure?
- A. These are small structures which work like oars
- B. It is covered with plasma membrane
- C. It's core is called axoneme
- D. All of the above✓
Explanation: Cilia and flagella are hair-like outgrowths of the cell membrane. Cilia are small structures working like oars, causing the movement of either the cell or the surrounding fluid. Flagella, in comparison, is longer and is responsible for cell movement. Both cilium and flagellum are covered with plasma membrane. Their core, called axoneme, possesses a number of microtubules running parallel to the long axis.So, the correct answer is 'All of the above'.
Why the other options are wrong
- A. Cilia and flagella are hair-like outgrowths of the cell membrane. Cilia are small structures working like oars, causing the movement of either the cell or the surrounding fluid. Flagella, in comparison, is longer and is responsible for cell movement. Both cilium and flagellum are covered with plasma membrane. Their core, called axoneme, possesses a number of microtubules running parallel to the long axis.
- B. Cilia and flagella are hair-like outgrowths of the cell membrane. Cilia are small structures working like oars, causing the movement of either the cell or the surrounding fluid. Flagella, in comparison, is longer and is responsible for cell movement. Both cilium and flagellum are covered with plasma membrane. Their core, called axoneme, possesses a number of microtubules running parallel to the long axis.
- C. Cilia and flagella are hair-like outgrowths of the cell membrane. Cilia are small structures working like oars, causing the movement of either the cell or the surrounding fluid. Flagella, in comparison, is longer and is responsible for cell movement. Both cilium and flagellum are covered with plasma membrane. Their core, called axoneme, possesses a number of microtubules running parallel to the long axis.
Q79. HIV is also known as:
- A. AIDS✓
- B. HAV
- C. HTLV
- D. HBV
Explanation: AIDS is merely an advanced form of HIV.
Why the other options are wrong
- B. Option B is wrong because HAV is the hepatitis A virus
- C. Option C is wrong because The human T-lymphotropic virus type 1 is also known by the acronym HTLV-1, or as human T-cell leukaemia virus type 1. The virus can cause a type of cancer called adult T-cell leukaemia/lymphoma
- D. Option D is wrong because HBV is hepatitis B virus.
Q80. Blood analysis of a patient reveals an unusually high quantity of carboxyhaemoglobin content. Which of the following conclusions is most likely to be correct? The patient has been inhaling polluted air containing unusually high content of:
- A. Oxygen
- B. Chloroform
- C. Carbon dioxide
- D. Carbon monoxide✓
Explanation: Carboxyhaemoglobin is formed when hemoglobin binds to carbon monoxide (CO), a process that occurs when polluted air containing high levels of carbon monoxide is inhaled. This can occur due to the incomplete combustion of fuels.
Why the other options are wrong
- A. This option is incorrect. While oxygen binds with hemoglobin to form oxyhemoglobin, it does not form carboxyhaemoglobin. Carboxyhaemoglobin is specifically formed when hemoglobin binds to carbon monoxide (CO), not oxygen.
- B. This option is incorrect. Chloroform exposure does not result in the formation of carboxyhaemoglobin. Carboxyhaemoglobin is formed when hemoglobin binds to carbon monoxide, not chloroform.
- C. This option is incorrect. Carbon dioxide binds with hemoglobin to form carbamino compounds, not carboxyhaemoglobin. Carboxyhaemoglobin is specifically the result of carbon monoxide binding to hemoglobin.
Q81. Tay Sach's disease is caused by absence of enzyme required to breakdown _.
- A. Lipids✓
- B. Glycogen
- C. Glucose
- D. Proteins
Explanation: Tay-Sachs disease is a inherited disorder that progressively destroys nerve cells (neurons) in the brain and spinal cord. It is caused due to the mutation in the gene which is responsible for producing enzyme involved break down of fatty substance.
Why the other options are wrong
- B. Option B is wrong because glycogen storage disease is caused due to absence of enzymes required to break glycogen.
- C. Option C is wrong because von Gierke disease is caused due to absence of enzymes required to break glucose.
- D. Option D is wrong because Urea cycle disorder is caused due to absence of enzymes required to break protein.
Q82. A combination of alpha interferon and ribavirin is used for the treatment of hepatitis:
- A. Hepatitis B
- B. Hepatitis A
- C. Hepatitis D
- D. Hepatitis C✓
Explanation: The combination of alpha interferon and ribavirin has been used in the treatment of hepatitis, particularly in the context of hepatitis C. Both alpha interferon and ribavirin have antiviral properties, and their combination was historically a standard treatment for chronic hepatitis C infection. Here's a brief overview of each component: Alpha Interferon: interferons are proteins that the body naturally produces in response to viral infections. They have antiviral properties and can modulate the immune response. Alpha interferon is a specific type of interferon that has been used as part of antiviral therapy. It was administered as an injection. Ribavirin: Ribavirin is an antiviral medication that inhibits the replication of viruses. It is a nucleoside analog and can interfere with the synthesis of viral genetic material. Ribavirin was often administered orally as part of the treatment regimen.
Why the other options are wrong
- A. Hepatitis B is a vaccine-preventable liver infection caused by the hepatitis B virus (HBV). Hepatitis B is spread when blood, semen, or other body fluids from a person infected with the virus enters the body of someone who is not infected. Alpha interferon and some nucleoside analogies are effective against Hepatitis B.
- B. Hepatitis A can be spread from close, personal contact with an infected person, such as through certain types of sexual contact. Hepatitis A is very contagious. Proper hygiene is one of the measures taken against Hepatitis A.
- C. Hepatitis D only occurs in people who are also infected with the hepatitis B virus. Hepatitis D is spread when blood or other body fluids from a person infected with the virus enters the body of someone who is not infected. Hepatitis D can be an acute, short-term infection or become a long-term, chronic infection.
Q83. “Zymase”- a group of 14 enzymes used in the fermentation of starch, is present in:
- A. Bacteria
- B. Yeast✓
- C. Fungi
- D. Algae
- E. Virus
Explanation: Zymase is an enzyme complex that catalyzes the fermentation of sugar into ethanol and carbon dioxide. It occurs naturally in yeasts. Zymase activity varies among yeast strains. Zymase is also the brand name of the drug pancrelipase.
Why the other options are wrong
- A. While the enzyme complex historically referred to as zymase is famously found in yeast, bacteria also possess the necessary enzymes to carry out alcoholic fermentation and other forms of glycolysis.
- C. Option C is incorrect, as although zymase is present in yeast, which belongs to fungi, we cannot say that all fungi contain zymase.
- D. Option D is incorrect as algae also do not contain zymase enzymes. Algae are photosynthetic organisms that produce carbohydrates (starches and sugars) but do not ferment them using zymase.
- E. Option E is incorrect as viruses have entirely different sets of enzymes that are involved in transcription and cell division. Zymase enzymes are not present in viruses.
Q84. Match the parts of the human brain listed under Column I with the functions given under Column II. Choose the answer which gives the correct combination of alphabets of the two columns.
- A. A=r, B=q, C=p, D=s
- B. A=r, B s, C=q, D=t,
- C. A=t, B=p, C=q, D=r✓
- D. A=t, B=q, C=p, D=s
Explanation: Your cerebral hemisphere plays a key role in memory, intelligence, thinking, learning, reasoning, problem-solving, emotions, consciousness, and functions related to your senses. (so A=T, hence options A and B are incorrect). The thalamus is your body's information relay station. All information from your body's senses (except smell) must be processed through your thalamus before being sent to your brain's cerebral cortex for interpretation (so B=P, hence options A, B, and D are incorrect). The cerebellum controls voluntary movements such as walking, posture, balance, coordination, eye movements, and speech (C=Q). Neurons in the medulla also control arousal and sleep (D=R).
Why the other options are wrong
- A. Your cerebral hemisphere plays a key role in memory, intelligence, thinking, learning, reasoning, problem-solving, emotions, consciousness, and functions related to your senses so A=T. The thalamus is your body's information relay station. All information from your body's senses (except smell) must be processed through your thalamus before being sent to your brain's cerebral cortex for interpretation, so B=P. This makes option A incorrect.
- B. Your cerebral hemisphere plays a key role in memory, intelligence, thinking, learning, reasoning, problem-solving, emotions, consciousness, and functions related to your senses so A=T. The thalamus is your body's information relay station. All information from your body's senses (except smell) must be processed through your thalamus before being sent to your brain's cerebral cortex for interpretation, so B=P. This makes option B incorrect.
- D. All information from your body's senses (except smell) must be processed through your thalamus before being sent to your brain's cerebral cortex for interpretation, so B=P. This makes option D incorrect.
Q85. Which of the following neurotransmitters function, both as neurotransmitter and hormones, decreasing our perception of pain?
- A. Epinephrine
- B. Serotonin
- C. Dopamine
- D. Endorphins✓
Explanation: Neurotransmitters are chemical messengers that transmit a message from a nerve cell across the synapse to a target cell. Hormones are chemical messengers that are secreted directly into the blood, which carries them to organs and tissues of the body to exert their functions. All the options are both, a hormone as well neurotransmitters. Epinephrine, commonly referred to as Adrenaline, relaxes the airway muscles, making it easier for the person to breathe. At the same time, it constricts blood vessels, helping to improve blood pressure. It also increases the heart rate. However, it does not decrease the response to pain. Hence Option A is rejected. Serotonin, on the other hand, is used by the body to send messages between nerve cells. It appears to play a role in mood, emotions, appetite, and digestion. As the precursor for melatonin, it helps regulate sleep-wake cycles and the body clock. Since it is not used to decrease pain response, Option B is rejected. Dopamine is a neurotransmitter that plays a role in how we feel pleasure. It's a big part of our unique human ability to think and plan. However, it plays no role in the pain response. Hence Option C is rejected. Endorphins are substances produced by the nervous system to cope with pain or stress. They are often called “feel-good” chemicals because they can act as pain relievers and happiness boosters. Hence, Option D is correct.
Why the other options are wrong
- A. Epinephrine, commonly referred to as Adrenaline, relaxes the airway muscles, making it easier for the person to breathe. At the same time, it constricts blood vessels, helping to improve blood pressure. It also increases the heart rate. However, it does not decrease the response to pain. Hence Option A is rejected.
- B. Serotonin, on the other hand, is used by the body to send messages between nerve cells. It appears to play a role in mood, emotions, appetite, and digestion. As the precursor for melatonin, it helps regulate sleep-wake cycles and the body clock. Since it is not used to decrease pain response, Option B is rejected.
- C. Dopamine is a neurotransmitter that plays a role in how we feel pleasure. It's a big part of our unique human ability to think and plan. However, it plays no role in the pain response. Hence Option C is rejected.
Q86. In a typical compound microscope the resolution is 2 μm. Which is about _ that of naked eye.
- A. 100 x
- B. 300 x
- C. 400 x
- D. 500 x✓
Explanation: Resolution is the measurement of the number of pixelsNaked eye resolution is 576 Megapixels which is 500 times the resolution of compound microscopeThe resolution of the naked eye refers to its ability to distinguish and perceive fine details or distinguish between two closely spaced objects. The resolution of the human eye is limited by several factors, including the number of photoreceptor cells in the retina and the optics of the eye.On average, the human eye can resolve objects that are approximately 1 arcminute apart. This means that if two objects are separated by an angle of 1 arcminute (which is 1/60th of a degree), a person with normal vision would be able to perceive them as separate entities rather than a single object.
Why the other options are wrong
- A. Naked eye resolution is 576 Megapixels which is 500 times the resolution of compound microscope
- B. Naked eye resolution is 576 Megapixels which is 500 times the resolution of compound microscope
- C. Naked eye resolution is 576 Megapixels which is 500 times the resolution of compound microscope
Q87. Which one of the following combinations is NOT part of an animal cell?
- A. Central Vacuole, Cell Membrane, Ribosomes
- B. Chloroplast, Ribosome , Mitochondria
- C. Cell wall, Chloroplast, Central vacuole✓
- D. Ribosome, Mitochondria, Cell wall
Explanation: Animal cells do not have a Cell wall and Chloroplasts. They have temporary small vacuoles; unlike plant cells which have large, permanent, central vacuoles.In the other options, at least one feature is present in the animal cells instead of all the three features pertaining to animal cells. The idea is to choose the better answer.The diagram presented below shows the major organelles in an animal cell; Flexibility and Mobility: Animal cells are often required to move and change shape, which is facilitated by their flexible cell membrane. The absence of a rigid cell wall allows animal cells to have more flexibility and mobility compared to cells with a cell wall. This flexibility is essential for various cellular processes, including cell migration, muscle contraction, and the ability to form complex tissues and organs.Intercellular Communication: Animal cells rely on direct cell-to-cell communication through specialized structures like gap junctions and tight junctions. These junctions facilitate the exchange of signals, ions, and molecules between neighboring cells, allowing for coordinated responses and tissue organization. A cell wall would hinder the direct interaction between animal cells and impede the efficient communication required for their complex physiological processes.Structural Support: In the absence of a cell wall, animal cells utilize the cytoskeleton, a network of protein filaments, to maintain their structural integrity and provide support. The cytoskeleton allows animal cells to maintain their shape, organize their internal components, and carry out cellular functions. This dynamic framework provides mechanical strength while allowing flexibility and shape changes.Adaptation to Environment: Animals have evolved to inhabit diverse environments and face varying physical conditions. The absence of a rigid cell wall enables animal cells to adapt to different osmotic pressures, temperature changes, and other environmental factors. Animal cells can regulate their volume and shape in response to external stimuli, allowing them to survive and function effectively in their respective environments.It's important to note that while animal cells lack a cell wall, they still possess a cell membrane (plasma membrane) that separates the cell's internal environment from the external environment. The cell membrane is a selectively permeable barrier that controls the passage of substances in and out of the cell.
Why the other options are wrong
- A. Ribosomes and cell membrane are present in animal cell but central vacuole is not
- B. chloroplast is not present in animal cell but ribosomes and mitochondria are
- D. Ribosomes and mitochondria are present in animal cell but cell wall is notcell wall is a rigid structure found in plant cells, bacteria, fungi, and some protists. It is a tough and protective layer located outside the cell membrane. While the cell wall serves important functions in organisms that possess it, animal cells do not have a cell wall. Here are a few reasons why animal cells lack
Q88. For the reaction: N2 + 3H2 ⇌ 2NH3 .The production of NH3 will be favored at:
- A. High pressure and catalyst✓
- B. Low pressure only
- C. Low pressure and catalyst
- D. High pressure only
- E. Catalyst only
Explanation: The forward reaction forms fewer moles of gas (4 → 2), so high pressure shifts equilibrium toward NH₃. A catalyst increases the reaction rate but does not change equilibrium position. Therefore, maximum ammonia production is achieved using high pressure along with a catalyst.
Why the other options are wrong
- B. To determine the favored conditions, you can apply Le Chatelier's Principle. Increasing pressure favors the side with fewer moles of gas. Since there are fewer moles on the right (2 moles of NH3) compared to the left (4 moles of N2 and 6 moles of H2), higher pressure would favor the production of NH3. There this option is not correct.
- C. To determine the favored conditions, you can apply Le Chatelier's Principle. Increasing pressure favors the side with fewer moles of gas. Since there are fewer moles on the right (2 moles of NH3) compared to the left (4 moles of N2 and 6 moles of H2), higher pressure would favor the production of NH3. Therefore this option is not correct.
- D. To determine the favored conditions, you can apply Le Chatelier's Principle. Increasing pressure favors the side with fewer moles of gas. Since there are fewer moles on the right (2 moles of NH3) compared to the left (4 moles of N2 and 6 moles of H2), higher pressure would favor the production of NH3.
- E. To determine the favored conditions, you can apply Le Chatelier's Principle. Increasing pressure favors the side with fewer moles of gas. Since there are fewer moles on the right (2 moles of NH3) compared to the left (4 moles of N2 and 6 moles of H2), higher pressure would favor the production of NH3. Therefore this option is not correct.
Q89. When does a gas deviate the most from its ideal behavior ?
- A. At low pressure and high temperature
- B. At high pressure and high temperature
- C. At low pressure and low temperature
- D. At high pressure and low temperature✓
Explanation: At high pressure and low temperature, a gas deviates the most from its ideal behaviour.Under these conditions, the gas molecules are close to each other and they exert significant intermolecular forces on each other. Also, the volume of gas molecules becomes a significant portion of total volume and cannot be neglected.Hence, the correct option is D.
Why the other options are wrong
- A. At high pressure and low temperature, a gas deviates the most from its ideal behaviour.Under these conditions, the gas molecules are close to each other and they exert significant intermolecular forces on each other. Also, the volume of gas molecules becomes a significant portion of total volume and cannot be neglected.Hence, the correct option is D.
- B. At high pressure and low temperature, a gas deviates the most from its ideal behaviour.Under these conditions, the gas molecules are close to each other and they exert significant intermolecular forces on each other. Also, the volume of gas molecules becomes a significant portion of total volume and cannot be neglected.Hence, the correct option is D.
- C. At high pressure and low temperature, a gas deviates the most from its ideal behaviour.Under these conditions, the gas molecules are close to each other and they exert significant intermolecular forces on each other. Also, the volume of gas molecules becomes a significant portion of total volume and cannot be neglected.Hence, the correct option is D.
Q90. Listed below are four respiratory capacities (i–iv) and four jumbled respiratory volumes of a normal human adult. Which one of the following is the correct matching of two capacities and volumes?
- A. (ii) 2500 mL, (iii) 4500 mL
- B. (iii) 1200 mL, (iv) 2500 mL
- C. (iv) 3500 mL, (i) 1200 mL✓
- D. (i) 4500 mL, (ii) 3500 mL
Explanation: All options are explained below:a)(ii) 2500 mL, (iii) 4500 mL:This option pairs capacity (ii) with 2500 mL and capacity (iii) with 4500 mL. This is an incorrect match. It doesn't align with the jumbled respiratory volumes provided in the question.B. (iii) 1200 mL, (iv) 2500 mL: This option pairs capacity (iii) with 1200 mL and capacity (iv) with 2500 mL. It also accurately pairs the capacities with their respective volumes.C. (iv) 3500 mL, (i) 1200 mL (Correct Option):This option pairs capacity (iv) with 3500 mL and capacity (i) with 1200 mL. If this is the correct option, it means that capacity (i) has a volume of 1200 mL, and capacity (iv) has a volume of 3500 mL, as per the question.D. (i) 4500 mL, (ii) 3500 mL:This option pairs capacity (i) with 4500 mL and capacity (ii) with 3500 mL. This is an incorrect match and doesn't align with the jumbled respiratory volumes provided in the question.Summary: The correct match is option C, which pairs capacity (iv) with 3500 mL and capacity (i) with 1200 mL, as indicated by the jumbled respiratory volumes provided in the question. The other options provide incorrect pairings of respiratory volumes with capacities.
Why the other options are wrong
- A. a)(ii) 2500 mL, (iii) 4500 mL:This option pairs capacity (ii) with 2500 mL and capacity (iii) with 4500 mL. This is an incorrect match. It doesn't align with the jumbled respiratory volumes provided in the question.
- B. B. (iii) 1200 mL, (iv) 2500 mL: This option pairs capacity (iii) with 1200 mL and capacity (iv) with 2500 mL. It also accurately pairs the capacities with their respective volumes.
- D. (i) 4500 mL, (ii) 3500 mL:This option pairs capacity (i) with 4500 mL and capacity (ii) with 3500 mL. This is an incorrect match and doesn't align with the jumbled respiratory volumes provided in the question.
Q91. Which one of the following statements is incorrect?
- A. Eggs in the ovaries ripen when they meet a sperm✓
- B. Girls are born with thousands of eggs in their ovaries
- C. Hormones control the release of the egg from the ovary
- D. One egg is released from the ovary about every month
Explanation: Eggs in the ovaries are already fully developed when they are released. They do not need to meet a sperm in order to ripen. Once an egg is released from the ovary, it can be fertilized by a sperm and become a baby. If an egg is not fertilized, it will break down and results in mensturation.
Why the other options are wrong
- B. Correct: Females are born with a finite number of immature eggs called primary oocytes. These eggs are present at birth and do not increase in number during a woman's lifetime.
- C. Correct: Hormones such as luteinizing hormone (LH) and follicle-stimulating hormone (FSH) regulate the menstrual cycle and control the release of eggs from the ovaries.
- D. Correct: Typically, one egg is released from the ovary each month during the process of ovulation, which is part of the menstrual cycle.
Q92. Which factor does affect the equilibrium constant Kc for a reaction?
- A. Temperature✓
- B. Pressure
- C. Catalyst
- D. Initial concentrations
Explanation: Changing the temperature shifts the equilibrium position based on whether the reaction is endothermic (absorbs heat) or exothermic (releases heat), according to Le Chatelier's Principle.3 Since the ratio of products to reactants changes, the value of K must also change.
Why the other options are wrong
- B. B is incorrect because pressure changes shift equilibrium position, not the Kc value, which depends only on temperature for a given reaction.
- C. C is incorrect because catalysts speed up reaching equilibrium but do not alter the Kc value, which is temperature‑dependent only in chemistry.
- D. D is incorrect because initial concentrations determine the reaction quotient, not the Kc, which is a fixed temperature‑dependent constant for each reaction.
Q93. Many elements have fractional atomic masses. This is because:
- A. Mass of atom is itself reactional
- B. Atomic masses are average masses of isobars
- C. Atomic masses are average masses of isotopes
- D. Atomic masses are average masses of isotopes proportional to their abundance✓
Explanation: Atomic masses are typically reported as weighted averages that take into account the abundance of each isotope of an element. Most elements exist as a mixture of isotopes, and these isotopes have different masses. The atomic mass of an element listed on the periodic table is a weighted average of the masses of its naturally occurring isotopes. The weighting is based on the abundance of each isotope in nature. Since isotopes have different masses, the atomic mass is not a whole number, and it may appear as a fractional value.
Why the other options are wrong
- A. The mass of an atom is not reactional. There is no such mass to be said as reactional. Hence, this option is incorrect.
- B. Isobars are atoms that have the same mass number but a different number of protons. The fractional atomic mass of an element is not due to the average masses of isobars. But due to the average masses of its isotopes.
- C. Isotopes are the atoms having same proton but different neutron numbers. The fractional atomic mass of an element is not due to the average masses of isotopes. But due to the average masses of its isotopes.
Q94. The best standard for the calculation of relative atomic masses is:
- A. Hydrogen - 1.008
- B. Carbon - 12✓
- C. Carbon - 13
- D. Oxygen - 16
Explanation: The best standard for the calculation of relative atomic masses is based on the International Union of Pure and Applied Chemistry (IUPAC) recommendation. The current standard is based on the carbon-12 isotope. The relative atomic mass of an element is determined by comparing the mass of its atoms to the mass of carbon-12 atoms. Carbon-12 is defined as having a relative atomic mass of exactly 12 atomic mass units (amu). This means that one atom of carbon-12 is assigned a mass of exactly 12 amu.Using carbon-12 as the reference, the relative atomic mass of other elements is calculated by comparing the masses of their atoms to the mass of a carbon-12 atom. This is done by measuring the mass of isotopes of the element and their relative abundance in nature. Isotopes are atoms of the same element that have different numbers of neutrons in their nuclei and, therefore, different masses.The atomic masses of elements are expressed relative to the carbon-12 scale using a unit called the atomic mass unit (amu). One atomic mass unit is defined as 1/12th of the mass of a carbon-12 atom.It's important to note that the relative atomic masses of some elements are not whole numbers because they are calculated based on the average masses of the isotopes present in nature and their relative abundances.The IUPAC periodically reviews and updates the atomic masses of elements based on new experimental data and advances in measurement techniques. This ensures that the atomic masses remain accurate and consistent over time.Atomic mass is defined as the mass of an atom of an element compared with the mass of an atom of carbon 12 (the stable light isotope of carbon). Atomic mass is a ratio and therefore has no units. It may be given any unit of measure, but generally, atomic masses are expressed in atomic mass units (a.m.u). One atomic mass unit equals exactly 1/12th the mass of a carbon 12 atom.Therefore, the most common standard for measuring an atom is the mass of carbon-12 and hence, option B is the correct answer.
Why the other options are wrong
Q95. At 1489 mm of Hg, water will boil at:
- A. 120 oC✓
- B. 110 oC
- C. 100 oC
- D. 90 oC
Explanation: At a pressure of 1489 mmHg (millimeters of mercury), water will boil at approximately 120 degrees Celsius (212 degrees Fahrenheit). The boiling point of a substance, such as water, depends on the pressure applied to it. Under normal atmospheric pressure at sea level, which is around 760 mmHg, water boils at 100 degrees Celsius (212 degrees Fahrenheit). However, when the pressure is increased, as in the case of 1489 mmHg, the boiling point of water also increases. At higher pressures, the boiling point of water increases because the additional pressure on the water molecules raises the energy required for them to overcome the intermolecular forces and transition from the liquid phase to the gaseous phase (vaporization). This results in an increase in the boiling point temperature. It's important to note that the boiling point of water can vary with altitude and atmospheric conditions, as the atmospheric pressure changes with elevation. Additionally, impurities and dissolved substances in the water can also affect its boiling point. The value mentioned above (100 degrees Celsius at 1489 mmHg) is an approximate estimation based on the relationship between pressure and boiling point. Although you are not expected to know the calculation of boiling points at various pressures, you must understand that at pressures higher than atmospheric pressure, the boiling point must also be higher than that at atmospheric pressure. This is because the boiling point is defined as the temperature at which the vapor pressure equals the external pressure. So, the higher the pressure, the higher the required temperature to evaporate enough liquid to equal the external pressure. Since 1489 mm of Hg>760 mm of Hg(atmospheric pressure), the boiling point must also be greater than 100. The best option in this case is, therefore, option A. If you have read the book thoroughly, this may just be a factual recall for you:
Why the other options are wrong
- B. This option is incorrect. At 1489 mmHg, the boiling point of water is higher than 110°C
- C. The boiling point of water is 100°C at standard atmospheric pressure (1 atm or 760 mmHg), but at 1489 mmHg, it will be higher than 100°C.
- D. The boiling point of water at 1489 mm Hg is higher than 90°C.
Q96. Which one of the following has the highest lattice energy?
- A. NaCl
- B. KCl
- C. KBr
- D. LiCl✓
Explanation: The lattice enthalpy is the enthalpy change involved in the formation of an ionic compound from gaseous ions (an exothermic process).The Lattice energy is directly proportional to the charges of the ions but inversely proportional to the radii of the ions or more generally the distance between ions. Lattice Energy α (charge of ion/radius of the ion).As we go down in a group (Group 1 and 7 in this case), ionic radius increases, and as the net charge is constant (+1 and -1 respectively), the lattice energy of their compounds decreases.Order of cation radius: K+> Na+> Li+Order of anion radius: Br-> Cl-Hence, the compound LiCl will have the greatest Lattice energy as both the ions have the least radius.Note: Across a period from left to right as the charge on ion increases, lattice energy increases.
Why the other options are wrong
- A. The lattice enthalpy is the enthalpy change involved in the formation of an ionic compound from gaseous ions (an exothermic process).The Lattice energy is directly proportional to the charges of the ions but inversely proportional to the radii of the ions or more generally the distance between ions. Lattice Energy α (charge of ion/radius of the ion).As we go down in a group (Group 1 and 7 in this case), ionic radius increases, and as the net charge is constant (+1 and -1 respectively), the lattice energy of their compounds decreases.Order of cation radius: K+> Na+> Li+Order of anion radius: Br-> Cl-Hence, the compound LiCl will have the greatest Lattice energy as both the ions have the least radius.Note: Across a period from left to right as the charge on ion increases, lattice energy increases.
- B. The lattice enthalpy is the enthalpy change involved in the formation of an ionic compound from gaseous ions (an exothermic process).The Lattice energy is directly proportional to the charges of the ions but inversely proportional to the radii of the ions or more generally the distance between ions. Lattice Energy α (charge of ion/radius of the ion).As we go down in a group (Group 1 and 7 in this case), ionic radius increases, and as the net charge is constant (+1 and -1 respectively), the lattice energy of their compounds decreases.Order of cation radius: K+> Na+> Li+Order of anion radius: Br-> Cl-Hence, the compound LiCl will have the greatest Lattice energy as both the ions have the least radius.Note: Across a period from left to right as the charge on ion increases, lattice energy increases.
- C. The lattice enthalpy is the enthalpy change involved in the formation of an ionic compound from gaseous ions (an exothermic process).The Lattice energy is directly proportional to the charges of the ions but inversely proportional to the radii of the ions or more generally the distance between ions. Lattice Energy α (charge of ion/radius of the ion).As we go down in a group (Group 1 and 7 in this case), ionic radius increases, and as the net charge is constant (+1 and -1 respectively), the lattice energy of their compounds decreases.Order of cation radius: K+> Na+> Li+Order of anion radius: Br-> Cl-Hence, the compound LiCl will have the greatest Lattice energy as both the ions have the least radius.Note: Across a period from left to right as the charge on ion increases, lattice energy increases.
Q97. Industrially water gas is converted into methanol by using catalyst:
- A. CuO + ZnO✓
- B. CuO + Cr2O3
- C. Al2O3 + ZnO
- D. ZnO + Cr2O3
Explanation: Water gas (CO+H2) is converted to methanol (CH3OH) industrially using a catalyst. A mixture of copper oxide (CuO) and zinc oxide (ZnO) is commonly used as the catalyst. This catalyst facilitates the hydrogenation of CO to methanol efficiently under high temperature and pressure.
Why the other options are wrong
- B. This option is incorrect. While CuO is a common catalyst, chromium oxide (Cr2O3) is not typically used in the methanol synthesis process from water gas.
- C. This option is incorrect. Although aluminum oxide (Al2O3) and zinc oxide (ZnO) are used in various catalytic processes, they are not the specific catalyst combination used for converting water gas into methanol.
- D. This option is incorrect. Zinc oxide (ZnO) is a component of the correct catalyst combination, but chromium oxide (Cr2O3) does not play a role in the methanol synthesis from water gas.
Q98. The nature of Lysine is:
- A. Acidic
- B. Basic✓
- C. Neutral
- D. Weakly acidic
Explanation: The chemical nature of an amino acid depends on its variable ‘R’ group. The R group of lysine contains the NH2 group which is basic as it can accept a proton to form NH3+.Therefore, lysine is considered to be a basic amino acid and hence option B is correct.
Why the other options are wrong
Q99. Reaction of CH3CH2MgBr with ethylene epoxide gives:
- A. Ethanal
- B. 1 - butanol✓
- C. 2 - butanol
- D. Butane
Explanation: The reaction of CH3CH2MgBr (ethylmagnesium bromide) with ethylene oxide (ethylene epoxide) typically results in the formation of 1,2-propanediol. This reaction is an example of a nucleophilic substitution reaction in which the nucleophilic carbon of the organometallic reagent attacks the electrophilic carbon of the epoxide, leading to the formation of an alcohol.The reaction can be represented by the following equation:CH3CH2MgBr + C2H4O-> CH3CH2CH2OHIn this reaction, the ethylmagnesium bromide acts as a nucleophile, attacking the epoxide ring and displacing the bromide ion. The resulting intermediate is an alkoxide ion, which quickly protonates to form the corresponding alcohol, 1,2-propanediol.It's important to note that the reaction conditions, such as temperature, solvent, and presence of any catalysts, can influence the outcome of the reaction. However, under typical conditions, the reaction described above is the most common result.Ethylene epoxide reacts with Grignard’s Reagent to produce an additive product, which upon hydrolysis yields a primary alcohol. The type of primary alcohol depends upon the number of C atoms in the grignard reagent’s ‘R’ group (RMgX).Since we have two C in Grignard’s Reagent and two in ethylene epoxide, the total number of carbon atoms in primary alcohol will be four, so the name of the alcohol formed is 1-butanol.
Why the other options are wrong
- A. Option A and D are incorrect because alkanes are not formed.
- C. Option C is incorrect because 2-butanol is a secondary alcohol. They are not formed by this reaction.
- D. Option A and D are incorrect because alkanes are not formed.
Q100. Which of the following has six isotopes?
- A. Manganese
- B. Tin
- C. Calcium✓
- D. Carbon
Explanation: Calcium has six stable isotopes: 40, 42, 43, 44, 46, 48Manganese has four stable isotopes: 52, 53, 54, 55Tin has ten isotopes: 112, 114, 115, 116, 117, 118, 119, 120, 122, 124Carbon has three isotopes: 12, 13, 14.So option C is correct.
Why the other options are wrong
- A. Manganese has 27 isotopes. Hence, this option is incorrect.
- B. Tin has 11 isotopes. Hence, this option is incorrect.
- D. Carbon has 3 isotopes. Hence, this option is incorrect.
Q101. At 0°C what is the physical state of water?
- A. Ice
- B. Liquid
- C. Vapour
- D. Both ice and liquid✓
Explanation: 0 degree C at 1 atm pressure is the freezing point of pure water where its solid-state and liquid state coexist in an equilibrium.
Why the other options are wrong
- A. Below 0 degree C, water exists in the form of ice
- B. Between 0 degree and 100 degree C, water exists in the form of liquid
- C. Above 100 degrees C , water exists in the form of vapours
Q102. What is the correct demonstration of general gas equation?
- A. PV/RT=n
- B. PV=mRT
- C. V=nRT/P
- D. PV=nRT✓
Explanation: In the general gas equation, volume is directly proportional to number of moles and temperature, and volume is inversely proportional to pressure.If R is universal gas constant, this relation is given by the equation:PV=nRTwhereP= PressureV= volumen= number of molesR= Ideal gas constantT= Temperature
Why the other options are wrong
- A. False! PV = nRT. This equation, known as the ideal gas law, relates the pressure (P), volume (V), number of moles (n), and temperature (T) of a gas sample. It states that the product of pressure and volume is directly proportional to the number of moles and the absolute temperature of the gas.
- B. False! PV = nRT. This equation, known as the ideal gas law, relates the pressure (P), volume (V), number of moles (n), and temperature (T) of a gas sample. It states that the product of pressure and volume is directly proportional to the number of moles and the absolute temperature of the gas.
- C. False! PV = nRT. This equation, known as the ideal gas law, relates the pressure (P), volume (V), number of moles (n), and temperature (T) of a gas sample. It states that the product of pressure and volume is directly proportional to the number of moles and the absolute temperature of the gas.
Q103. Which of the following is/are allotrope(s) of Sulphur?
- A. Monoclinic S and Rhombic S✓
- B. Rhombic S
- C. Triclinic S
- D. Monoclinic S
Explanation: Allotropy is the existence of an element in more than one crystalline forms. These forms are known as allotropes. Sulphur exists in both rhombic and monoclinic forms which are in equilibrium with one another at 95.5 C.
Why the other options are wrong
- B. False!Allotropy is the existence of an element in more than one crystalline forms. These forms are known as allotropes. Sulphur exists in both rhombic and monoclinic forms which are in equilibrium with one another at 95.5 C.
- C. False!Allotropy is the existence of an element in more than one crystalline forms. These forms are known as allotropes. Sulphur exists in both rhombic and monoclinic forms which are in equilibrium with one another at 95.5 C.
- D. False!Allotropy is the existence of an element in more than one crystalline forms. These forms are known as allotropes. Sulphur exists in both rhombic and monoclinic forms which are in equilibrium with one another at 95.5 C.
Q104. The property of a crystal to grow in its usual shape is called as:
- A. Symmetry
- B. Habit of crystal✓
- C. Isomorphism
- D. Polymorphism
Explanation: The shape in which a crystal usually grows is called the habit of the crystal. If the conditions for crystallization remain the same, then the crystal will grow in the same shape (habit).
Why the other options are wrong
- A. Symmetry refers to a balanced arrangement or pattern that exhibits similarity or correspondence on opposite sides or parts. It is a concept found in various fields, including mathematics, art, and nature.
- C. Isomorphism is a concept that can be applied in different fields, such as mathematics, chemistry, and computer science. In mathematics, isomorphism refers to a mapping or relationship between two mathematical structures that preserves certain properties or structures. It essentially means that two objects or systems are structurally or functionally equivalent in some way.
- D. Polymorphism is a concept in object-oriented programming where an object can take on many forms. It allows different objects to be treated as if they belong to the same class, even if they are instances of different subclasses. This enables flexibility and extensibility in programming, as different objects can share common behaviors and methods while also having their own unique implementations.In simpler terms, polymorphism allows objects to be used interchangeably, providing a way to write more flexible and reusable code. It's like having a single method that can be applied to different types of objects, based on their specific implementations.
Q105. Gases are non-ideal at high pressure due to:
- A. Intermolecular forces
- B. Decrease in volume occupied by gas
- C. All of these✓
- D. Decrease in compressibility of gas
Explanation: Ideal gases are those that have no intermolecular forces, their molecular volume is negligible as compared to the volume of the entire gas and are infinitely compressible.As the pressure on a gas increases, the gas molecules are brought closer together. This decrease in the total volume of the gas brings the molecules so close that intermolecular forces of attraction develop between them. Moreover, the individual volume of a gas molecule is not negligible compared to the now decreased total volume of the gas. Due to the increase in pressure, the gas is already compressed, making further compression more difficult. So, its compressibility decreases.
Why the other options are wrong
- A. Ideal gases are those that have no intermolecular forces, their molecular volume is negligible as compared to the volume of the entire gas and are infinitely compressible.As the pressure on a gas increases, the gas molecules are brought closer together. This decrease in the total volume of the gas brings the molecules so close that intermolecular forces of attraction develop between them. Moreover, the individual volume of a gas molecule is not negligible compared to the now decreased total volume of the gas. Due to the increase in pressure, the gas is already compressed, making further compression more difficult. So, its compressibility decreases.
- B. Ideal gases are those that have no intermolecular forces, their molecular volume is negligible as compared to the volume of the entire gas and are infinitely compressible.As the pressure on a gas increases, the gas molecules are brought closer together. This decrease in the total volume of the gas brings the molecules so close that intermolecular forces of attraction develop between them. Moreover, the individual volume of a gas molecule is not negligible compared to the now decreased total volume of the gas. Due to the increase in pressure, the gas is already compressed, making further compression more difficult. So, its compressibility decreases.
- D. Ideal gases are those that have no intermolecular forces, their molecular volume is negligible as compared to the volume of the entire gas and are infinitely compressible.As the pressure on a gas increases, the gas molecules are brought closer together. This decrease in the total volume of the gas brings the molecules so close that intermolecular forces of attraction develop between them. Moreover, the individual volume of a gas molecule is not negligible compared to the now decreased total volume of the gas. Due to the increase in pressure, the gas is already compressed, making further compression more difficult. So, its compressibility decreases.
Q106. HF has a higher boiling point than HCl because of:
- A. Dipole-dipole interactions
- B. Ion-dipole interactions
- C. Hydrogen bonding✓
- D. London-dispersion forces
Explanation: HF has a higher boiling point than HCl because of the hydrogen bonding that exists between HF molecules. HCl has dipole-dipole intermolecular interactions. Out of the two, hydrogen bonding is stronger, hence, the greater boiling point of HF.
Why the other options are wrong
- A. Dipole-dipole interactions occur between polar molecules. These interactions arise due to the attraction between the positive end of one molecule and the negative end of another molecule. Unlike London dispersion forces, which are temporary and occur in all molecules, dipole-dipole interactions are more permanent and specific to polar molecules.In a polar molecule, such as water (H2O), the distribution of electrons is uneven, creating a partial positive charge on one side of the molecule and a partial negative charge on the other side. When two polar molecules come close to each other, the positive end of one molecule is attracted to the negative end of the other molecule, resulting in a dipole-dipole interaction.These interactions are stronger than London dispersion forces and play a significant role in determining the physical properties of polar substances, such as higher boiling points and stronger intermolecular attractions.
- B. False!HF has a higher boiling point than HCl because of the hydrogen bonding that exists between HF molecules. HCl has dipole-dipole intermolecular interactions. Out of the two, hydrogen bonding is stronger, hence, the greater boiling point of HF.
- D. London dispersion forces, also known as van der Waals forces, are a type of intermolecular force that occurs between atoms or molecules. These forces arise due to temporary fluctuations in electron distribution, leading to the creation of temporary dipoles.In simpler terms, London dispersion forces occur when two molecules come close to each other, and the electrons in one molecule temporarily shift to create a slight positive charge on one side and a slight negative charge on the other side. This temporary charge imbalance induces a corresponding charge in the neighboring molecule, resulting in an attractive force between the two.London dispersion forces are the weakest type of intermolecular force, but they still play a significant role in determining the physical properties of substances, such as boiling points and melting points. They are present in all molecules to some extent, although their strength varies depending on the size and shape of the molecules involved.
Q107. The maximum number of electrons that an orbital can accommodate is/are:
- A. 0
- B. 1
- C. 2✓
- D. 3
- E. 4
Explanation: The maximum number of electrons in a single orbital is two. The maximum number of electrons an orbital can accommodate is 2. As in an orbital two electrons can never have the same values of all 4 quantum no.s according to Pauli’s exclusion principle. So to follow this rule, an orbital can accommodate 2 electrons only.
Why the other options are wrong
- A. Option A is wrong as this is not the maximum amount of electrons that an orbital can accomadate.
- B. Option B is wrong as this is not the maximum amount of electrons that an orbital can accomadate.
- D. Option D is wrong as the number of electrons are beyond that an orbital can accomadate.
- E. Option E is wrong as the number of electrons are beyond that an orbital can accomadate.
Q108. In a reaction:A+B < - > 2C When equilibrium was attained, the concentration was [A] = [B] = 4 moles/dm3[C]= 6 moles/dm3The equilibrium constant Kc of this reaction is:
- A. 1.25
- B. 2.25✓
- C. 3.25
- D. 2.75
- E. 3.75
Explanation: The equilibrium constant Kc is calculated using the expression: Kc = [C]² / [A][B]. For the reaction A + B < - > 2C, substitute the equilibrium concentrations: [C] = 6 moles/dm3, [A] = [B] = 4 moles/dm3. Thus, Kc = (6)² / (4)(4) = 36 / 16 = 2.25, confirming Option B as correct. Options A, C, D, and E result from errors in calculation or misinterpretation of the equilibrium constant formula.
Why the other options are wrong
- A. This option is incorrect. Double-check your calculation using the formula: Kc = [C]² / [A][B].
- C. This option is incorrect. Review the stoichiometry and ensure correct substitution of concentrations.
- D. This option is incorrect. Verify the concentration values and apply the equilibrium expression accurately.
- E. This option is incorrect. The result does not align with the equilibrium expression based on the balanced equation.
Q109. When two moles of H2 and one mole of O2 react to form H2O, -484 KJ heat is evolved. What is Δ Hf for one mole of H2O?
- A. -484 KJmol-1
- B. -242 KJmol-1✓
- C. -121 KJmol-1
- D. +242 KJmol-1
Explanation: To determine the enthalpy change of formation (ΔHf) for one mole of H2O, we can use the given information about the heat evolved in the reaction.The balanced equation for the reaction is:2H2(g) + O2(g) → 2H2O(g)According to the given information, when two moles of H2 and one mole of O2 react, 484 kJ of heat is evolved. This heat change represents the enthalpy change of the reaction.Since two moles of H2O are formed in the reaction, we need to find the enthalpy change for one mole of H2O. To do that, we divide the heat evolved by the stoichiometric coefficient of H2O:ΔHf (H2O) = (484 kJ) / 2ΔHf (H2O) = 242 kJTherefore, the enthalpy change of formation for one mole of H2O is 242 kJ.Firstly, since heat is evolved, the formation of water is an exothermic reaction and so the sign of enthalpy change will be negative. Secondly, enthalpy of formation is the change in enthalpy when one mole of a substance is formed from its constituent elements under standard conditions.When 2 moles of H2 and 1 mole of O2 react, 2 moles of H2O will be formed:2H2 + O2 —------------------------> 2H2O ΔH=-484 kJ/mol (given)Now, for the formation of one mole of H2O, we can simply divide the entire equation by 2:H2 + ½ O2 —-----------------------> H20 ΔH= -242 kJ/molSo, the enthalpy change of formation is –242 kJ/mol, which corresponds to option B, hence that is the correct answer.
Why the other options are wrong
- A. Firstly, since heat is evolved, the formation of water is an exothermic reaction and so the sign of enthalpy change will be negative. Secondly, enthalpy of formation is the change in enthalpy when one mole of a substance is formed from its constituent elements under standard conditions.When 2 moles of H2 and 1 mole of O2 react, 2 moles of H2O will be formed:2H2 + O2 —------------------------> 2H2O ΔH=-484 kJ/mol (given)Now, for the formation of one mole of H2O, we can simply divide the entire equation by 2:H2 + ½ O2 —-----------------------> H20 ΔH= -242 kJ/molSo, the enthalpy change of formation is –242 kJ/mol, which corresponds to option B, hence that is the correct answer.
- C. Firstly, since heat is evolved, the formation of water is an exothermic reaction and so the sign of enthalpy change will be negative. Secondly, enthalpy of formation is the change in enthalpy when one mole of a substance is formed from its constituent elements under standard conditions.When 2 moles of H2 and 1 mole of O2 react, 2 moles of H2O will be formed:2H2 + O2 —------------------------> 2H2O ΔH=-484 kJ/mol (given)Now, for the formation of one mole of H2O, we can simply divide the entire equation by 2:H2 + ½ O2 —-----------------------> H20 ΔH= -242 kJ/molSo, the enthalpy change of formation is –242 kJ/mol, which corresponds to option B, hence that is the correct answer.
- D. Firstly, since heat is evolved, the formation of water is an exothermic reaction and so the sign of enthalpy change will be negative. Secondly, enthalpy of formation is the change in enthalpy when one mole of a substance is formed from its constituent elements under standard conditions.When 2 moles of H2 and 1 mole of O2 react, 2 moles of H2O will be formed:2H2 + O2 —------------------------> 2H2O ΔH=-484 kJ/mol (given)Now, for the formation of one mole of H2O, we can simply divide the entire equation by 2:H2 + ½ O2 —-----------------------> H20 ΔH= -242 kJ/molSo, the enthalpy change of formation is –242 kJ/mol, which corresponds to option B, hence that is the correct answer.
Q110. Which of the following metals does NOT liberate hydrogen in reaction with acids?
- A. Mg
- B. Pt✓
- C. Zn
- D. Ca
Explanation: The metal that does not liberate hydrogen in reaction with acids is gold (Au). Gold is a noble metal and is generally unreactive with most acids, including hydrochloric acid (HCl) and sulfuric acid (H2SO4), which are commonly used in acid-metal reactions. Unlike more reactive metals like zinc (Zn) or magnesium (Mg), gold does not undergo a displacement reaction with acids to produce hydrogen gas. Metals exhibit displacement reactions based on their reactivity. All the metals Mg, Zn, and Ca in options A, C, and D respectively are above Hydrogen in the reactivity series and therefore will displace it from acid. Platinum, however, is below hydrogen and so will not displace it and will not liberate H2 gas on reaction with an acid. Therefore option C is the correct answer. The reactivity series of metals is given below:
Why the other options are wrong
- A. Mg does not liberate hydrogen.
- C. Zn does not liberate hydrogen.
- D. Ca does not liberate hydrogen.
Q111. The rate of a gaseous reaction Is given by K [A] [B]. If the volume of the vessel containing these gases is reduced to 1/4th of the initial volume, the rate of reaction relative to the original rate would be:
- A. 16/1✓
- B. 1/16
- C. 4/1
- D. 1/8
- E. 8/1
Explanation: If the volume of the vessel is reduced by 1/4th that means according to formula C=n/V concentration of each gas in the flask increases by a factor of 4 times. Since concentrations of two gases are increased by this factor that increases the overall rate by 4x4=16.
Why the other options are wrong
- B. If the volume of the vessel is reduced by 1/4th that means according to formula C=n/V concentration of each gas in the flask increases by a factor of 4 times. Since concentrations of two gases are increased by this factor that increases the overall rate by 4x4=16.
- C. If the volume of the vessel is reduced by 1/4th that means according to formula C=n/V concentration of each gas in the flask increases by a factor of 4 times. Since concentrations of two gases are increased by this factor that increases the overall rate by 4x4=16.
- D. If the volume of the vessel is reduced by 1/4th that means according to formula C=n/V concentration of each gas in the flask increases by a factor of 4 times. Since concentrations of two gases are increased by this factor that increases the overall rate by 4x4=16.
- E. If the volume of the vessel is reduced by 1/4th that means according to formula C=n/V concentration of each gas in the flask increases by a factor of 4 times. Since concentrations of two gases are increased by this factor that increases the overall rate by 4x4=16.
Q112. A term in which no two electron can have the same set of four Quantum numbers is stated by
- A. Heisenberg's principle
- B. Pauli's exclusion principle✓
- C. Aufbau principle
- D. Hund's rule
Explanation: The heisenberg uncertainty principle states that certain pairs of physical properties, such as position and momentum, cannot be precisely determined simultaneously with arbitrary accuracy. Mathematically, the uncertainty principle is expressed as follows: (Δx . Δp ≥ h/4π) Hence, this is the incorrect answer. This is the correct answer because, The Pauli exclusion principle states that each electron in an atom must have a unique combination of quantum numbers. The four quantum numbers that describe an electron are: The principal quantum number (n) which determines the energy level or shell of the electron. The azimuthal quantum number (l) which specifies the subshell or orbital angular momentum of the electron. The magnetic quantum number (mₗ) which specifies orientation in space of a given orbital of particular energy and shape. The spin quantum number (mₛ) which specifies the spin state of an electron. The Aufbau principle, also known as the "building-up principle". According to the Aufbau principle, electrons occupy the lowest energy orbitals available first before moving to higher energy levels. The principle is based on the idea that electrons exist in discrete energy levels or shells surrounding the nucleus of an atom. Hence, this is the incorrect answer. Hund's rule states that when electrons are filling degenerate orbitals (orbitals with the same energy), they will occupy separate orbitals within the subshell before pairing up. In other words, electrons will try to maximize the number of unpaired electrons in a subshell or orbital before pairing begins. This principle is based on the concept of electron-electron repulsion. Hence, this is the incorrect answer.
Why the other options are wrong
- A. The heisenberg uncertainty principle states that certain pairs of physical properties, such as position and momentum, cannot be precisely determined simultaneously with arbitrary accuracy. Mathematically, the uncertainty principle is expressed as follows: (Δx . Δp ≥ h/4π) Hence, this is the incorrect answer
- C. The Aufbau principle, also known as the "building-up principle". According to the Aufbau principle, electrons occupy the lowest energy orbitals available first before moving to higher energy levels. The principle is based on the idea that electrons exist in discrete energy levels or shells surrounding the nucleus of an atom. Hence, this is the incorrect answer.
- D. Hund's rule states that when electrons are filling degenerate orbitals (orbitals with the same energy), they will occupy separate orbitals within the subshell before pairing up. In other words, electrons will try to maximize the number of unpaired electrons in a subshell or orbital before pairing begins. This principle is based on the concept of electron-electron repulsion. Hence, this is the incorrect answer
Q113. The unit of rate of reaction is:
- A. Mole (dm3) sec
- B. Mole (dm3) sec-1
- C. Mole(dm-3) sec -1✓
- D. Mole(dm3) sec-2
- E. Mole (dm3)-1 sec -2
Explanation: Reaction rates are usually expressed as the concentration of reactant consumed or the concentration of product formed per unit time. The units are thus moles per decimeter cube per unit time [Mole (dm-3) sec-1 ].
Why the other options are wrong
- A. Incorrect as it doesn't involve the concept of time (sec) in the unit of rate.
- B. Incorrect because the rate is typically expressed as concentration per unit time, so sec-1 represents 1/second, which means change in concentration per second.
- D. Incorrect as it includes a second-order term (sec-2) in the unit, which doesn't represent the rate of a reaction.
- E. Incorrect because it includes an inverse term for volume (dm3)-1, which doesn't represent the unit for rate.
Q114. The rate of a chemical reaction is directly proportional to the product of active masses of the reactants, it is referred to as:
- A. Law of conservation of energy
- B. Law of mass action✓
- C. Law of conservation of mass
- D. Active mass law
Explanation: The rate of a chemical reaction being directly proportional to the product of the active masses of the reactants is described by the law of mass action. Therefore this option is correct.
Why the other options are wrong
- A. The rate of a chemical reaction being directly proportional to the product of the active masses of the reactants is described by the law of mass action. Therefore this option is not correct.
- C. The rate of a chemical reaction being directly proportional to the product of the active masses of the reactants is described by the law of mass action. Therefore this option is not correct.
- D. The rate of a chemical reaction being directly proportional to the product of the active masses of the reactants is described by the law of mass action. Therefore this option is correct.
Q115. The charge on one proton is:
- A. 1.602 x 10-31 C
- B. 1.602 x 10-27 C
- C. 1.602 x 10-19 C✓
- D. 1.602 x 10-11 C
Explanation: This is a factual recall question. The charge on a proton is equal to +1e, where e is the elementary charge having a value of 1.602 x 10-19 coulombs. This is the same as the charge on an electron but has a different polarity, i.e. positive instead of negative for electrons.
Why the other options are wrong
- A. This option is incorrect as the value of the charge of the proton is a fact.
- B. This option is incorrect as the value of the charge of the proton is a fact.
- D. This option is incorrect as the value of the charge of the proton is a fact.
Q116. Hybridization of carbon in -CHO group is:
- A. sp
- B. sp2✓
- C. sp3
- D. dsp
Explanation: In the CHO group, - HC=O, the carbon is double bonded to an oxygen and single bonded to hydrogen and another R group, which may be an alkyl or some other group. It has no lone pairs remaining. In other words, the central atom Carbon is bonded to three other groups only. Therefore the hybridisation that it corresponds to is sp2, as can be confirmed from the table below:
Why the other options are wrong
- A. In the CHO group, - HC=O, the carbon is double bonded to an oxygen and single bonded to hydrogen and another R group, which may be an alkyl or some other group. It has no lone pairs remaining. In other words, the central atom Carbon is bonded to three other groups only. Therefore the hybridisation that it corresponds to is sp2.
- C. In the CHO group, - HC=O, the carbon is double bonded to an oxygen and single bonded to hydrogen and another R group, which may be an alkyl or some other group. It has no lone pairs remaining. In other words, the central atom Carbon is bonded to three other groups only. Therefore the hybridisation that it corresponds to is sp2.
- D. In the CHO group, - HC=O, the carbon is double bonded to an oxygen and single bonded to hydrogen and another R group, which may be an alkyl or some other group. It has no lone pairs remaining. In other words, the central atom Carbon is bonded to three other groups only. Therefore the hybridisation that it corresponds to is sp2.
Q117. Dehydration of ethanol at 140 oC in the presence of concentrated H2SO4 gives:
- A. Ethene
- B. Ethane
- C. Ethyne
- D. Ether✓
Explanation: Dehydration of alcohol at 140°C gives etherreference # ftb 162
Why the other options are wrong
- A. When the temperature of about 180° C then it will give an alkenes otherwise it will give an ether as an product.
- B. Ethane is not a product of the dehydration of ethanol. Ethane is an alkane, meaning it has only single bonds between carbon atoms. It does not form directly from the dehydration process.
- C. Ethyne, commonly known as acetylene, is also not a product of the dehydration of ethanol. Ethyne is an alkyne with a triple bond between the two carbon atoms. It does not form directly from the dehydration process.
Q118. Which of the following is the worst conductor of electricity?
- A. Hg
- B. Distilled water✓
- C. NaCl(l)
- D. Dilute sugar solution
Explanation: Pure distilled water is a poor conductor of electricity. Water itself is a good electrical insulator, but it can conduct electricity when it contains dissolved ions or impurities. These ions, such as sodium (Na+), chloride (Cl-), or other dissolved salts, increase the conductivity of water by allowing the flow of electric current. In order to conduct electricity, a substance must possess charged particles, either ions or electrons. Distilled water has neither of those as it does not dissociate into H+ or OH- ions unless it is dissolved with some other polar substance. Hence it does not conduct electricity and therefore option B is the correct answer.
Why the other options are wrong
- A. Option A is incorrect because Hg being a metal has a metallic lattice whereby there is a sea of electrons that enable it to conduct electricity. Mercury (Hg) is not the worst conductor of electricity, but it is a poor conductor. It is classified as a metal, and as such, it does conduct electricity to some extent. However, compared to other metals like copper or silver, mercury has a relatively high electrical resistance. This means that it is less efficient at conducting electricity. Additionally, mercury is a liquid at room temperature, which further limits its practical use as a conductor. Therefore, while mercury is not the worst conductor overall, it is not commonly used or considered among the best conductors of electricity.
- C. No, NaCl (sodium chloride), when dissolved in water or in molten form, is actually a good conductor of electricity. When NaCl dissolves in water, it dissociates into sodium ions (Na+) and chloride ions (Cl-), which are responsible for conducting the electric current. The presence of these ions in solution allows for the movement of charged particles, facilitating the flow of electricity. As a result, NaCl solution (commonly known as saltwater) can conduct electricity relatively well compared to pure water or other non-ionic substances. Option C is incorrect because NaCl being an ionic compound, has free ions in the liquid state thus possessing free ions to conduct electricity.
- D. A dilute sugar solution, in general, is a poor conductor of electricity. Sugar, or sucrose, is a non-ionic compound, which means it does not readily dissociate into charged particles (ions) when dissolved in water. As a result, a dilute sugar solution does not contain enough ions to facilitate the conduction of electric current.While water molecules can interact with sugar molecules and form weak hydrogen bonds, these interactions do not result in the formation of free-moving charged particles that can conduct electricity. Therefore, compared to ionic compounds like NaCl, a dilute sugar solution has significantly lower conductivity. It's important to note that highly concentrated sugar solutions or solutions that contain other ionic impurities can exhibit some level of electrical conductivity. However, in general, a dilute sugar solution would be considered a poor conductor of electricity. Option D could also be correct since sugar solution, although polar, does not possess any free ions so it cannot conduct electricity. However, in such questions, it is best to prefer water as the first choice.
Q119. In an adiabatic process:
- A. Pressure is maintained constant
- B. The gas is isothermally expanded
- C. There is perfect heat insulation✓
- D. System exchanges heat with the surroundings
Explanation: During an adiabatic process, the system is completely insulated from its surroundings. Thus, it takes place without heat entering or leaving the system, i.e.,q=0. During an isobaric process, the pressure of the system is kept constant (ΔP=0). During the isochoric process, the volume of the system is kept constant. (ΔV=0). During an isothermal process. the temperature of the system is kept constant (ΔT=0 but q≠0).
Why the other options are wrong
- A. This is done in an isobaric process
- B. This is done in an isothermal process.
- D. During an adiabatic process, the system is completely insulated from its surroundings. Thus, it takes place without heat entering or leaving the system, i.e.,q=0. During an isobaric process, the pressure of the system is kept constant (ΔP=0). During the isochoric process, the volume of the system is kept constant. (ΔV=0). During an isothermal process. the temperature of the system is kept constant (ΔT=0 but q≠0).
Q120. Catenation is a process in which carbon shows the properties of:
- A. Making single bond
- B. Hybridization
- C. Making chains or rings of carbon atoms✓
- D. Isomerism
- E. Breaking of bonds
Explanation: Catenation is the process by which an atom is able to form a bond with another atom of its kind. Carbon possesses this ability hence is able to form ringed structures.
Why the other options are wrong
- A. Catenation is the process by which an atom is able to form a bond with another atom of its kind. Carbon possesses this ability hence is able to form ringed structures.Option A is incorrect as catenation is the property of forming all kinds of bonds with the same kind of atoms either single, double or triple.
- B. Option B is incorrect as hybridization is the process in which atomic orbitals mix to form new hybrid orbitals suitable for the pairing of electrons to form chemical bonds.
- D. Option D is incorrect as isomerism is the phenomena exhibited by organic compounds in which compounds have the same molecular formula but different structural formula.
- E. Option E is incorrect as catenation does not involve breaking of bonds.
Q121. Primary Alcohol is produced by reactions of Grignard's reagent with _ followed by hydrolysis in an acidic medium.
- A. Carbon dioxide
- B. Formaldehyde✓
- C. Acetaldehyde
- D. Ketone
- E. Methyl chloride
Explanation: The Grignard Reaction involves the addition of an organomagnesium halide (Grignard reagent) to carbonyl compounds. When Grignard reagents react with formaldehyde, a primary alcohol is produced upon hydrolysis in an acidic medium. Formaldehyde is unique as it is the simplest aldehyde, thus allowing the formation of a primary alcohol. Other aldehydes and ketones lead to secondary and tertiary alcohols, respectively. Carbon dioxide reacts with Grignard reagents to form carboxylic acids, not alcohols, and methyl chloride does not react to form an alcohol.
Why the other options are wrong
- A. Grignard reagents react with carbon dioxide followed by acidic hydrolysis to produce carboxylic acids, not primary alcohols. The reaction adds a carbon atom to the original chain.
- C. Reacting a Grignard reagent with acetaldehyde or any aldehyde other than formaldehyde results in a secondary alcohol, not a primary alcohol.
- D. Grignard reagents react with ketones to form tertiary alcohols after acidic hydrolysis, not primary alcohols.
- E. Methyl chloride does not undergo a reaction to form an alcohol in the presence of a Grignard reagent. It serves as a precursor in the formation of the Grignard reagent itself.
Q122. The diagram below represents the process of:
- A. Hydrolysis
- B. Condensation✓
- C. Neutralization
- D. Metabolism
Explanation: When two monomers join together to form a single product, with the removal of H2O, the process is called the condensation process. Hence, option B is correct.
Why the other options are wrong
- A. Option A is wrong as hydrolysis is the opposite of condensation; it is the breakdown into smaller molecules by the addition of H2O.
- C. Option C is wrong as neutralization is the process by which acid neutralizes base to form salt and water.
- D. Metabolism is the breakdown of substances. That makes option D incorrect.
Q123. Valence electronic configuration Cu+2 is (29Cu)
- A. 5d6
- B. 3d9✓
- C. 3d8
- D. 3d7
Explanation: The valence electronic configuration of Cu+2 is derived from the neutral atom of copper (Cu), which has an atomic number of 29. The electronic configuration of neutral copper (Cu) is 1s² 2s² 2p⁶ 3s² 3p⁶ 4s¹ 3d¹⁰. When copper loses two electrons to form the Cu+2 ion, the two outermost electrons from the 4s orbital are removed. Therefore, the valence electronic configuration of Cu+2 is 1s² 2s² 2p⁶ 3s² 3p⁶ 3d⁹.Cu is an element of d-block. Its electronic configuration is anomalous owing to the stability associated with half filled and as in the case of Cu, completely filled d-subshell. One electron from the 4s subshell jumps to 3d subshell, thereby making the electronic configuration:1s2, 2s2, 2p6, 3s2, 3p6, 4s1, 3d10Now, for the formation of Cu2+ ion, the Cu atom must lose 2 electrons from the highest energy level. The important thing here is that the 4s orbital of an atom usually fills before electrons go into its 3d orbitals because the 4s orbital is slightly lower in energy than the empty 3d orbitals (n+l rule). However, once electrons are in the 3d orbital, the 4s is no longer lower in energy, it becomes higher in energy than 3d so when ionisation occurs electrons are lost from the 4s orbital before they're lost from the 3d orbitals.Hence, the first electron is lost from 4s and the one after that, from 3d. So the new electronic configuration from Cu2+ is:1s2, 2s2, 2p6, 3s2, 3p6, 4s0, 3d9Therefore, option B is the correct answer.
Why the other options are wrong
- A. As per the explanation, this option is incorrect.
- C. As per the explanation, this option is incorrect.
- D. As per the explanation, this option is incorrect.
Q124. The total number of transition elements is:
- A. 58✓
- B. 48
- C. 30
- D. 25
Explanation: This is a factual recall question. There are 58 transition metals in the periodic table of elements, of which 30 are outer transition elements (d-block) and 28 are inner transition elements (f-block). Therefore option A is correct. (Source: FTBB book 2 page 64)
Why the other options are wrong
- B. As per the explanation, this option is incorrect.
- C. As per the explanation, this option is incorrect.
- D. As per the explanation, this option is incorrect.
Q125. Which of the following does not act as ligand in the formation of complexes?
- A. CH3NH2
- B. OH-
- C. Cl-
- D. NH4+✓
Explanation: Ligand is a species that donates a lone pair of electrons by forming a dative coordinate bond with a central metal atom/ion. NH4+ has no lone pair of electrons because 4 of the valence electrons of nitrogen are involved in forming covalent bonds with hydrogen and 1 electron has been lost by it, being an ion of +1 charge. Therefore it cannot form a dative bond and hence cannot act as a ligand. The correct answer is therefore option D.
Why the other options are wrong
- A. CH3NH2 is the chemical formula for methylamine, which is a simple organic compound. Ligands are typically molecules or ions that can donate electron pairs to form coordinate bonds with a central metal atom or ion in coordination complexes. These ligands usually have one or more lone pairs of electrons available for bonding. Examples of common ligands include water (H2O), ammonia (NH3), chloride ion (Cl-), and cyanide ion (CN-). Option A is incorrect because CH3NH2 can act as ligand by using the lone pair on Nitrogen.
- B. Yes, OH- (hydroxide ion) is considered a ligand in coordination chemistry. It is a common ligand that can donate a lone pair of electrons to form coordinate bonds with a central metal atom or ion. The hydroxide ion has a lone pair of electrons on the oxygen atom, which can form a coordinate bond with a metal ion by donating this electron pair. Coordination complexes containing OH- ligands are often referred to as hydroxido complexes. Option B is incorrect because OH- can act as ligand by using the lone pairs on Oxygen.
- C. Yes, Cl- (chloride ion) is considered a ligand in coordination chemistry. It is a common ligand that can donate a lone pair of electrons to form coordinate bonds with a central metal atom or ion. The chloride ion has a lone pair of electrons, and it can form a coordinate bond with a metal ion by donating this electron pair. Coordination complexes containing Cl- ligands are often referred to as chlorido complexes. Option C is incorrect because Cl- can act as ligand by using its lone pairs.
Q126. The ratio of σ to π bonds in benzene is:
- A. 4:1✓
- B. 1:4
- C. 1:3
- D. 3:1
Explanation: The structure of benzene reveals that it has 3 C-C double bonds, hence it has three π bonds for each double bond that it makes. It also possesses 6 C-C single bonds and 6 C-H single bonds, making a total of 12 σ bonds.Ratio of σ:π = 12:3 = 4:1Therefore option A is the correct answer. OIP.kJ8bRcHGdSByWKiFdeWugwHaHa (474×474) (bing.com)
Why the other options are wrong
- B. It is written opposite.Therefore incorrect.
- C. This option is incorrect.
- D. This option is incorrect.
Q127. Which of the following alcohol does not get oxidized when it reacts with K₂Cr₂O₇/H₂SO₄?
- A. CH₃C(CH₃)₂OH✓
- B. CH₃CH(CH₃)OH
- C. CH₃OH
- D. C₂H₅OH
Explanation: Option A is a tertiary alcohol which cannot be oxidized with K2Cr2O7 as the central carbon atom has no free hydrogens.Option B is a secondary alcohol which oxidizes to a ketone. Option C is methanol which oxidizes to carbondioxide. Option D is ethanol which oxidizes to ethanal first then ethanoic acid.
Why the other options are wrong
- B. Option B is a secondary alcohol which oxidizes to a ketone.
- C. Option C is methanol which oxidizes to carbondioxide.
- D. Option D is ethanol which oxidizes to ethanal first then ethanoic acid.
Q128. The classification of monohydric alcohols is due to
- A. Hydrogen atom
- B. Carbon atom✓
- C. Hydroxyl group
- D. Carbonyl group
Explanation: The classification of monohydric alcohols is based on the type of carbon atom to which the –OH group is attached.Therefore:Primary alcohol: –OH on a carbon attached to one other carbon.Secondary alcohol: –OH on a carbon attached to two other carbons.Tertiary alcohol: –OH on a carbon attached to three other carbons.
Why the other options are wrong
- A. This is also not correct as every organic compound contains an hydrogen atom.
- C. The classification of monohydric alcohols is based on the type of carbon atom to which the –OH group is attached.Therefore:Primary alcohol: –OH on a carbon attached to one other carbon.Secondary alcohol: –OH on a carbon attached to two other carbons.Tertiary alcohol: –OH on a carbon attached to three other carbons.
- D. Carbonyl group is generally present in aldehyde and ketones.
Q129. Acyclic hydrocarbons are also called:
- A. Closed chain hydrocarbons
- B. Open chain hydrocarbons✓
- C. Ring compounds
- D. Alicyclic compounds
Explanation: OPTION A: Closed-chain hydrocarbons are also called cyclic or alicyclic hydrocarbons. In these, the carbon atoms are arranged in closed-chain forms.OPTION B: In open-chain hydrocarbons, carbon atoms are linked to each other in open chains, which may be a straight chain or a branched chain. It is also called Acyclic hydrocarbons.Hence, B is the correct option.
Why the other options are wrong
- A. Closed-chain hydrocarbons are also called cyclic or alicyclic hydrocarbons. In these, the carbon atoms are arranged in closed-chain forms.
- C. False.In open-chain hydrocarbons, carbon atoms are linked to each other in open chains, which may be a straight chain or a branched chain. It is also called Acyclic hydrocarbons.Hence, B is the correct option.
- D. False.In open-chain hydrocarbons, carbon atoms are linked to each other in open chains, which may be a straight chain or a branched chain. It is also called Acyclic hydrocarbons.Hence, B is the correct option.
Q130. How many molecules of H2 are added in acetylene to form ethane?
- A. 1
- B. 3
- C. 4
- D. 2✓
Explanation: Acetylene, C2H2, can be converted to ethane, C2H6, by a process known as hydrogenation. One molecule of H2 when added to acetylene forms ethene. The addition of another molecule of H2 results in the formation of ethane. A total of 2 molecules of H2 are hence required Option A,B and C are incorrect
Why the other options are wrong
- A. Acetylene, C2H2, can be converted to ethane, C2H6, by a process known as hydrogenation.One molecule of H2 when added to acetylene forms ethene. The addition of another molecule of H2 results in the formation of ethane. A total of 2 molecules of H2 are hence required.
- B. Acetylene, C2H2, can be converted to ethane, C2H6, by a process known as hydrogenation.One molecule of H2 when added to acetylene forms ethene. The addition of another molecule of H2 results in the formation of ethane. A total of 2 molecules of H2 are hence required.
- C. Acetylene, C2H2, can be converted to ethane, C2H6, by a process known as hydrogenation.One molecule of H2 when added to acetylene forms ethene. The addition of another molecule of H2 results in the formation of ethane. A total of 2 molecules of H2 are hence required.
Q131. The equation shows the reaction between element X and dilute hydrochloric acid: X(s) + 2HCl(aq) -> XCl2(aq) + H2(g) What types of bonding is present in element X and in compound XCl2?
- A. Option A
- B. Option B
- C. Option C
- D. Option D✓
Explanation: Metallic bonding is a type of chemical bonding that arises from the electrostatic attractive force between conduction electrons (in the form of an electron cloud of delocalized electrons) and positively charged metal ions. The element X is metal as Metals react with halogens to form salts.The compound XCl2 is a salt and has ionic bonds. As two chlorine atoms are attached, this shows the central metal has two valence electrons in free states, so it is a metal of group II A[Be, Mg, Ca, Sr, Ba].
Why the other options are wrong
- A. It is incorrect as the compound X has metallic bonds, whereas the compound XCl2 has ionic bonds.
- B. It is incorrect as the compound X has metallic bonds, whereas the compound XCl2 has ionic bonds.
- C. It is incorrect as the compound X has metallic bonds, where as the compound XCl2 has ionic bonds.
Q132. The enthalpy change accompanying the gain of an electron by a neutral gaseous atom to form a negative ion is called:
- A. Ionization potential
- B. Electronegativity
- C. Electron affinity✓
- D. Lattice energy
- E. Potential energy
Explanation: When an electron is added to a neutral gaseous atom to convert it into a negative ion, the enthalpy change accompanying the process is called Electron affinity enthalpy. Ionization potential, in chemistry, is the amount of energy required to remove an electron from an isolated atom or molecule. Electronegativity is a measure of the tendency of an atom to attract a bonding pair of electrons. Lattice energy is defined as the energy required to separate a mole of an ionic solid into gaseous ions. Potential energy is energy that is stored – or conserved - in an object or substance.
Why the other options are wrong
- A. Option A is wrong as the ionization potential, in chemistry, is the amount of energy required to remove an electron from an isolated atom or molecule.
- B. Option B is wrong as the electronegativity is a measure of the tendency of an atom to attract a shared pair of electrons.
- D. Option D is wrong as the lattice energy is defined as the energy required to separate a mole of an ionic solid into gaseous ions.
- E. Option E is wrong as the potential energy is energy that is stored or conserved in an object or a substance.
Q133. Lithium and Beryllium are unique in such a way that they have higher charge densities which produce strong polarizing effects due to:
- A. Non-metal
- B. Solubility
- C. Small Size✓
- D. Large size
Explanation: Smaller size is the main cause of high charge density and increasing polarizing effect. The polarizing power of a cation is inversely proportional to its size. Smaller is the size of the cation and higher will be its charge density, which means greater concentration of charge on a smaller area. The more will be the charge density, higher will be its polarising power.
Why the other options are wrong
- A. Lithium and Beryllium are not non-metals.
- B. Solubility has no link with this scenario.
- D. Large size molecules have less polarizing power.
Q134. Order of the reactivity of halogens during halogenation of alkanes is:
- A. Cl2 > I2 > Br2
- B. Br2 > I2 > Cl2
- C. I2 > Cl2 > Br2
- D. Cl2 > Br2 > I2✓
Explanation: The chlorine radical is the most reactive of the among the given halogen molecules and it reacts easily with alkanes. In contrast, the iodine radical is the least reactive of the halogen radicals. In fact, it is so unreactive that it is unable to abstract a hydrogen atom from an alkane.So, (D) option is correct.
Why the other options are wrong
- A. This is not correct order.
- B. This is not correct order.
- C. This is not correct order.
Q135. If the temperature is increased from 200K to 800K, then what would be the change in pressure at constant volume?
- A. Increases by factor 4✓
- B. Decreases by factor 4
- C. Increases by factor 2
- D. Decreases by factor 2
Explanation: PV=NRΔT V=constant ;R=constant; N=constant so P is directly proportional to T as the temperature increases 4 times as it increases from 200K to 800K so the pressure will also increase 4 times.Just be careful that the units (especially temperature) are absolute.
Why the other options are wrong
- B. This option is incorrect as an increase in temperature leads to an increase in pressure, not a decrease.
- C. This option is incorrect. The increase in temperature from 200K to 800K corresponds to a factor of 4, not 2.
- D. This option is incorrect. As an increase in temperature leads to an increase in pressure, not a decrease.
Q136. Assume that you have two balls of Identical volume, one weighing 2 Newtons and the other 10 Newtons. Both are falling freely after being released from the same point simultaneously. Which of the following will then be true: I. The 10 N ball falling freely from rest will be accelerated at a greater rate than the 2 N ball II. At the end of the 4s of freefall, the 10 N ball will have 5 times the momentum of the 2 N ball III. At the end of the 4s of free fall, the 10 N ball will have the same kinetic energy as the 2 N ball IV. The 10 N ball possesses greater inertia than the 2 N ball
- A. I, Il and Ill only
- B. I and II only
- C. II and IV only✓
- D. IV only
- E. None of these
Explanation: Acceleration of free fall acts equally on all masses, this is why both objects despite having different masses have the same speed at any point in time. Statement II is correct because two objects have the same velocity but one having 5 times more mass than the other will have 5 times more momentum than the other object. Statement IV is also correct because inertia depends upon mass since a 10N ball has a higher mass it will have greater inertia. Statement III is wrong because objects have different masses so their kinetic energy can not be the same. Statement I is wrong because objects accelerate irrespective of their masses as mentioned before.
Why the other options are wrong
- A. Acceleration of free fall acts equally on all masses, this is why both objects despite having different masses have the same speed at any point in time. Statement II is correct because two objects have the same velocity but one having 5 times more mass than the other will have 5 times more momentum than the other object. Statement IV is also correct because inertia depends upon mass since a 10N ball has a higher mass it will have greater inertia. Statement III is wrong because objects have different masses so their kinetic energy can not be the same. Statement I is wrong because objects accelerate irrespective of their masses as mentioned before.
- B. Acceleration of free fall acts equally on all masses, this is why both objects despite having different masses have the same speed at any point in time. Statement II is correct because two objects have the same velocity but one having 5 times more mass than the other will have 5 times more momentum than the other object. Statement IV is also correct because inertia depends upon mass since a 10N ball has a higher mass it will have greater inertia. Statement III is wrong because objects have different masses so their kinetic energy can not be the same. Statement I is wrong because objects accelerate irrespective of their masses as mentioned before.
- D. Acceleration of free fall acts equally on all masses, this is why both objects despite having different masses have the same speed at any point in time. Statement II is correct because two objects have the same velocity but one having 5 times more mass than the other will have 5 times more momentum than the other object. Statement IV is also correct because inertia depends upon mass since a 10N ball has a higher mass it will have greater inertia. Statement III is wrong because objects have different masses so their kinetic energy can not be the same. Statement I is wrong because objects accelerate irrespective of their masses as mentioned before.
- E. Acceleration of free fall acts equally on all masses, this is why both objects despite having different masses have the same speed at any point in time. Statement II is correct because two objects have the same velocity but one having 5 times more mass than the other will have 5 times more momentum than the other object. Statement IV is also correct because inertia depends upon mass since a 10N ball has a higher mass it will have greater inertia. Statement III is wrong because objects have different masses so their kinetic energy can not be the same. Statement I is wrong because objects accelerate irrespective of their masses as mentioned before.
Q137. The quantity of heat required to raise the temperature of one mole of a substance through 1 K is called:
- A. Carnot engine
- B. Molar specific heat✓
- C. Kinetic specific heat
- D. General gas law
- E. Boyle's law
Explanation: Specific heat is the amount of heat needed to raise the temperature of one kilogram of mass by 1 degree. The molar heat capacity is the heat capacity per unit amount (SI unit: mole) of a pure substance, and the specific heat capacity often called simply specific heat, is the heat capacity per unit mass of material. Option B is correct.
Why the other options are wrong
- A. A Carnot engine is a theoretical engine that operates on the Carnot cycle. It estimates the maximum possible efficiency that a heat engine during the conversion process of heat into work and, conversely, working between two reservoirs can possess. Hence incorrect
- C. The specific heat capacity is defined as the quantity of heat (J) absorbed per unit mass (kg) of the material when its temperature increases 1 K (or 1 °C). Hence incorrect.
- D. The ideal gas law is the equation of state of a hypothetical ideal gas. It is a good approximation of the behavior of many gases under many conditions, although it has several limitations. The equation is; PV = nRT. Hence incorrect
- E. A law stating that the pressure of a given mass of an ideal gas is inversely proportional to its volume at a constant temperature. Hence incorrect.
Q138. Identify the example/s of Static Equilibrium:I. A book lying on a horizontal tableII. A buildingIII. A bridge
- A. I only
- B. II and III only
- C. I and III only
- D. III only
- E. I, II and III✓
Explanation: Static equilibrium occurs when the sum of all forces and torques acting on an object is zero, meaning the object is at rest or its center of mass is not accelerating. In the given examples:I. A book lying on a horizontal table is in static equilibrium as it is at rest and the forces acting on it, such as gravity and the normal force, are balanced.II. A building is in static equilibrium if it is stationary and not experiencing any net forces or torques that would cause motion.III. A bridge is in static equilibrium when the forces acting on it, including its own weight and any supporting forces, are balanced to prevent motion.Thus, option E is correct as all examples satisfy the conditions for static equilibrium, while the other options incorrectly omit one or more examples.
Why the other options are wrong
- A. The book is indeed in static equilibrium, but this option neglects the building and the bridge, both of which also meet the criteria for static equilibrium.
- B. Both the building and the bridge are in static equilibrium, but this choice mistakenly excludes the book, which also satisfies the conditions for static equilibrium.
- C. This choice recognizes the book and the bridge as examples of static equilibrium but incorrectly omits the building, which is also in static equilibrium.
- D. While a bridge is in static equilibrium, this option ignores the book and the building, both of which are also in static equilibrium.
Q139. A student is performing a lab experiment on simple harmonic motion. He has two different springs (with force constants k1 and k2) and two different blocks (of masses m1 and m2). If k1 =2k2, and m1 = 2m2, which of the following combinations would give the student the spring-block simple harmonic oscillator with the shortest period?
- A. The spring with force constant k1 and the block of mass m1
- B. The spring with force constant k1 and the block of mass m2✓
- C. The spring with force constant k2 and the block of mass m1
- D. The spring with force constant k2 and the block of mass m2
- E. All the combinations above would give the same period
Explanation: The period of the spring-block simple harmonic oscillator is given by the equation T =2π√m/k so, to make T as small as possible, we want m to be as small as possible and k to be as large as possible. Since m2 is the smaller mass and k1 is the larger spring constant, this combination will give the oscillator the shortest period.
Why the other options are wrong
- A. In this option, we use the heavier block m1 with the spring of force constant k1. While the force constant is higher due to k1=2k2, the mass is also higher due to m1=2m2. As the mass term is inside the square root, the larger mass m1 contributes to a longer period compared to the combination in option B.
- C. In this option, we use the heavier block m1 with the spring of force constant k2. While the mass term is lower, the force constant is also lower due to k1=2k2. As both the mass and force constant contribute to the period, the combination in option B with the lighter block and the higher force constant would result in a shorter period.
- D. In this option, we use the lighter block m2 with the spring of force constant k2. The force constant remains the same as in option A (k2), and the mass is lighter (m2). Similar to option C, the combination in option B with the lighter block and the higher force constant would result in a shorter period.
- E. As per the explanation, this option is incorrect.
Q140. Some water at 0°C is placed in a large insulated enclosure (vessel). The water vapour formed is pumped out continuously. What fraction of the water will ultimately freeze, if the latent heat vaporization is seven times the latent heat of fusion?
- A. 7/8✓
- B. 8/7
- C. 3/8
- D. 5/8
Explanation: In an insulated system, the energy lost by the water that freezes must equal the energy required to vaporize the remaining water. Let m be the mass of the water and f the fraction that freezes. The heat lost by the frozen part is mfL2 and the heat gained by the vaporized part is m(1-f)L1. Given that L1 = 7L2, we have mfL2 = m(1-f)7L2. Solving for f gives f = 7/8. Therefore, 7/8 of the water freezes. The other options do not satisfy this energy balance.
Why the other options are wrong
- B. This option is incorrect. The fraction greater than 1 does not make sense in this context as it would imply more freezing than the available water.
- C. This option is incorrect. This fraction does not satisfy the energy balance equation derived from the latent heats given.
- D. This option is incorrect. This fraction also does not adhere to the correct energy relationship between freezing and vaporization.
Q141. Law of Conservation of Momentum states that total linear momentum of system remains constant if:
- A. Balanced external forces are applied to a system.
- B. No external force is applied to a system.
- C. Only linear force is applied in a system is zero.
- D. Sum of external forces are applied to a system is zero.✓
Explanation: This is a statement of the conservation of linear momentum, thus, it is a fact. For the sake of explanation, an external force would disturb the equilibrium of the system and produce an acceleration in the objects being tested.
Why the other options are wrong
- A. This option is not correct. The conservation of momentum is not dependent on balanced external forces. Even if there are balanced forces, momentum can still be conserved as long as there are no net external forces acting on the system.
- B. This option is partially correct. The Law of Conservation of Momentum is most applicable when no external forces are applied to a closed system. In this case, the total linear momentum of the system remains constant.
- C. This option is not correct. The presence or absence of linear forces alone does not determine the conservation of momentum. The key factor is the net external force acting on the system.
Q142. What is true about the electric field and electric force?
- A. Electric field lines are towards negative and electron flow in same direction
- B. Electric field lines are towards positive and electron flow in opposite direction
- C. Electric field lines are towards the negative and electrons flow in the opposite direction.✓
- D. Electric field lines are positive and electrons flow in the same direction.
Explanation: Electric field lines always point away from a positive charge and towards a negative point. In fact, electric fields originate at a positive charge and terminate at a negative charge.This shows that OPTION B and D ARE INCORRECT. Electrons flow from lower potential terminal to higher potential terminal being negatively charged particles it flows from negative to positive poles hence it is the opposite direction as the electric field.So,OPTION C is incorrect.
Why the other options are wrong
- A. Electric field lines always point away from a positive charge and towards a negative point. In fact, electric fields originate at a positive charge and terminate at a negative charge.This shows that OPTION B and D ARE INCORRECT. Electrons flow from lower potential terminal to higher potential terminal being negatively charged particles it flows from negative to positive poles hence it is the opposite direction as the electric field.So,OPTION C is incorrect.
- B. Electric field lines always point away from a positive charge and towards a negative point. In fact, electric fields originate at a positive charge and terminate at a negative charge.This shows that OPTION B and D ARE INCORRECT. Electrons flow from lower potential terminal to higher potential terminal being negatively charged particles it flows from negative to positive poles hence it is the opposite direction as the electric field.So,OPTION C is incorrect.
- D. Electric field lines always point away from a positive charge and towards a negative point. In fact, electric fields originate at a positive charge and terminate at a negative charge.This shows that OPTION B and D ARE INCORRECT. Electrons flow from lower potential terminal to higher potential terminal being negatively charged particles it flows from negative to positive poles hence it is the opposite direction as the electric field.So,OPTION C is incorrect.
Q143. Two capacitors C1 = 2µ and C2 = 4µ F are connected in series across in a 100V supply. Find the effective capacitance.
- A. ½ µF
- B. 3/2 µF
- C. 5/2 µF
- D. 4/3 µF✓
- E. 2 µF
Explanation: Recall that the effective capacitance of capacitors in series is the reciprocal of the sum of reciprocals of individual capacitors (just like resistors in parallel)Therefore,1/Ceffective = 1/C1 + 1/C21/Ceffective = ½ +¼ 1/Ceffective = ¾C effective= 4/3 µF Hence option D is the correct answer.
Why the other options are wrong
- A. This option is incorrect.Recall that the effective capacitance of capacitors in series is the reciprocal of the sum of reciprocals of individual capacitors (just like resistors in parallel)Therefore,1/Ceffective = 1/C1 + 1/C21/Ceffective = ½ +¼ 1/Ceffective = ¾C effective= 4/3 µF
- B. This option is incorrect. Recall that the effective capacitance of capacitors in series is the reciprocal of the sum of reciprocals of individual capacitors (just like resistors in parallel)Therefore,1/Ceffective = 1/C1 + 1/C21/Ceffective = ½ +¼ 1/Ceffective = ¾C effective= 4/3 µF
- C. This option is incorrect. Recall that the effective capacitance of capacitors in series is the reciprocal of the sum of reciprocals of individual capacitors (just like resistors in parallel)Therefore,1/Ceffective = 1/C1 + 1/C21/Ceffective = ½ +¼ 1/Ceffective = ¾C effective= 4/3 µF
- E. This option is incorrect. Recall that the effective capacitance of capacitors in series is the reciprocal of the sum of reciprocals of individual capacitors (just like resistors in parallel)Therefore,1/Ceffective = 1/C1 + 1/C21/Ceffective = ½ +¼ 1/Ceffective = ¾C effective= 4/3 µF
Q144. Coal and petrol are stores of chemical energy when are burnt, chemical energy is converted into heat energy i.e chemical energy = heat energy + _:
- A. Electrical energy
- B. Losses✓
- C. Gains
- D. Wind energy
- E. Nothing
Explanation: When coal or petrol is burned, the chemical energy stored in the fuel is primarily converted into heat energy. However, not all of this energy conversion is perfectly efficient; some energy is inevitably lost to the surroundings as waste heat, which is why 'Losses' is the correct answer. Electrical energy is not directly produced from combustion without additional equipment. Gains are incorrect because energy is not gained but redistributed with losses. Wind energy is unrelated to burning fuels. 'Nothing' is incorrect because energy transformations usually accompany some degree of energy loss.
Why the other options are wrong
- A. Electrical energy is not a direct result of burning coal or petrol; it requires a generator or similar device to be produced.
- C. The energy conversion process in burning coal or petrol does not lead to a net energy gain but rather a redistribution of energy forms with some losses.
- D. Wind energy is derived from atmospheric conditions and not from burning fuels like coal or petrol.
- E. This option is incorrect because energy transformations typically involve some loss, often as waste heat.
Q145. When there is an increase in the length of the simple pendulum then its time period will:
- A. Remain the same
- B. Decrease
- C. First decrease then increase
- D. Increase✓
Explanation: The time period T of a simple pendulum is given by the formula T = 2π√(l/g), where l is the length of the pendulum and g is the acceleration due to gravity.From this formula, we can see that T is directly proportional to the square root of the length l. Therefore, if the length of the pendulum increases, the time period will also increase.Option A is incorrect because the time period does not remain constant. Option B is incorrect because the time period does not decrease with an increase in length. Option C is incorrect as the time period does not first decrease and then increase; it continuously increases with an increase in length. Option D is correct as it accurately describes the relationship.
Why the other options are wrong
- A. This option is incorrect. The time period of a simple pendulum depends on its length and will change if the length changes.
- B. This option is incorrect. According to the formula for the time period of a pendulum, an increase in length results in an increase in the time period, not a decrease.
- C. This option is incorrect. The relationship between length and time period is direct and continuous; it does not fluctuate in this manner.
Q146. When frequency of applied periodic Force is equal to the natural frequency of harmonic oscillator then the _ of oscillator _.
- A. amplitude : decreases
- B. Amplitude : increases✓
- C. Frequency : increases
- D. Frequency : decreases
Explanation: This question refers to the phenomenon of resonance. During resonance, the amplitude keeps on increasing after every subsequent oscillation, provided the system is undamped.
Why the other options are wrong
- A. The amplitude increases rather than decreasing.
- C. The frequency remains the same.
- D. The frequency remains the same.
Q147. The wavelength of the electromagnetic wave having frequency of 3 kHz will be?
- A. 120 km
- B. 100 km✓
- C. 80 km
- D. 140 km
Explanation: λ = v / fInputting speed of light or 3 x 108 m/s as v and 3 x 103 Hz as f gives us 1 x 105 m or 100 km.
Why the other options are wrong
- A. This option is incorrect λ = v / fInputting speed of light or 3 x 108 m/s as v and 3 x 103 Hz as f gives us 1 x 105 m or 100 km
- C. This option is incorrect λ = v / fInputting speed of light or 3 x 108 m/s as v and 3 x 103 Hz as f gives us 1 x 105 m or 100 km
- D. This option is incorrectλ = v / fInputting speed of light or 3 x 108 m/s as v and 3 x 103 Hz as f gives us 1 x 105 m or 100 km
Q148. Laser light is?
- A. Multi-directional.
- B. Bi-directional.
- C. Uni-directional.✓
- D. None of these options is correct.
Explanation: The waves emitted from a laser are all in-phase and coherent. They are focused at one point and do not emit at an angle.
Why the other options are wrong
- A. The waves emitted from a laser are all in-phase and coherent. They are focused at one point and do not emit at an angle.
- B. The waves emitted from a laser are all in-phase and coherent. They are focused at one point and do not emit at an angle.
- D. This is not correct.
Q149. The sum of all forms of molecular energies (kinetic and potential) of a substance is termed as:
- A. Elastic energy
- B. Absolute energy
- C. Internal energy✓
- D. Heat energy
Explanation: Elastic energy is a form of potential energy. Absolute energy does not exist. By definition, Internal energy is the sum of total kinetic and potential energy as defined in 1st law of thermodynamics.
Why the other options are wrong
- A. Elastic energy refers to the potential energy stored in an object when it is deformed under stress but then returns to its original shape once the stress is removed. This type of energy is associated with materials that exhibit elastic properties, such as springs or rubber bands. It is not directly related to molecular energies or the sum of kinetic and potential energies in a substance.
- B. There isn't a widely recognised concept of "absolute energy" in physics. Energy measurements typically refer to specific forms of energy or total energy within a system. Therefore, this option doesn't accurately describe the concept referred to in the question.
- D. Heat energy refers specifically to the transfer of thermal energy between two bodies due to a temperature difference. It is a form of energy transfer, not a property of a substance itself. While heat energy can contribute to changes in a substance's internal energy, it does not encompass the total internal energy of the substance, which includes both kinetic and potential molecular energies.
Q150. The rate at which work is being done is called:
- A. Power✓
- B. Energy
- C. Density
- D. Force
Explanation: The rate at which work is done is called power. It is expressed as the amount of work per unit of time.
Why the other options are wrong
- B. In physics, energy is the quantitative property that is transferred to a body or to a physical system, recognizable in the performance of work and in the form of heat and light.
- C. Density is the measurement of how tightly a material is packed together. It is defined as the mass per unit volume.
- D. A force can cause an object with mass to change its velocity, i.e., to accelerate.
Q151. Which one of the following requires no medium?
- A. Beta rays
- B. Alpha rays
- C. Gamma rays✓
- D. All of these
Explanation: Out of all these, Gamma rays are an example of electromagnetic waves, which require NO medium to travel and propagate from one place to the other or even through a vacuum.On the other hand, mechanical waves require a medium to travel and propagate from one place to the other and can NOT pass through the vacuum. Examples of mechanical waves are sound waves, alpha rays, beta rays, etc.The picture attached represents the 'Electromagnetic Spectrum', of which 'Gamma Rays' are a part of.
Why the other options are wrong
- A. Beta rays consist of high-energy electrons or positrons emitted from the nucleus of certain radioactive atoms during beta decay.Beta rays are charged particles and require a medium to propagate. They can travel through a vacuum but interact with matter, causing ionization and energy loss.
- B. Alpha rays are composed of alpha particles, which are helium-4 nuclei consisting of two protons and two neutrons.Similar to beta rays, alpha particles are charged and require a medium to propagate. They have a relatively low penetration ability and can be stopped by a few centimeters of air or a sheet of paper.
- D. This option is incorrect as per the explanation
Q152. An electric bulb is rated at 220 V, 100 W. What is its resistance?
- A. 250 Ohms
- B. 350 Ohms
- C. 450 Ohms
- D. 484 Ohms✓
Explanation: In this case, we are given the voltage (V) of the bulb, which is 220 V, and the power (P) of the bulb, which is 100 W. We can use the formula for power:Power (P) = V2/RR = V2/P= (220)2/100= 22 x 22= 484 Ohms
Why the other options are wrong
- A. This option is incorrect as per the formula and calculations
- B. This option is incorrect as per the formula and calculations
- C. This option is incorrect as per the formula and calculations
Q153. The fractional change in resistance per kelvin is known as:
- A. None
- B. Temperature coefficient of resistance✓
- C. Thermal coefficient
- D. Volumetric coefficient of expansion
- E. Linear coefficient of expansion
Explanation: The fractional change in resistance per kelvin is called the temperature coefficient.The temperature coefficient of resistance is a measure of how much the electrical resistance of a material changes with temperature. It is expressed in units of ohms per ohm per degree Celsius (Ω/Ω/°C) or ohms per ohm per kelvin (Ω/Ω/K). This coefficient is denoted by the symbol α (alpha) and is an important factor in understanding and designing electronic circuits, particularly when dealing with components like resistors whose resistance can vary with temperatureResistance coefficient, abbreviated as K, a dimensionless number, is how much resistance to the flow an obstacle has. Volumetric coefficient increases in volume per unit original volume per Kelvin rise in temperature is called the coefficient of volumetric expansion.The ratio increase in length original length for the 1-degree rise in temperature is called the coefficient of linear expansion
Why the other options are wrong
- A. This option is incorrect
- C. The statement "The fractional change in resistance per kelvin is known as Thermal coefficient" is not entirely accurate. The correct term is the "temperature coefficient of resistance."
- D. the "volumetric coefficient of expansion" typically refers to a measure of how the volume of a material changes with temperature. It is not directly related to the change in electrical resistance with temperature.
- E. The "linear coefficient of expansion" typically relates to the change in length (dimension) of a material with temperature. It is a measure of how much a material expands or contracts linearly with changes in temperature. This concept is not directly related to changes in electrical resistance.
Q154. Which of the following is the pair of isobars?
- A. 1H1 and 2H1
- B. 12C6 and 13H6
- C. 2H1 and 3H1
- D. 30H15 and 30Si14✓
Explanation: Isobars are atomic species that have the same mass number (A), but a different atomic number (Z). This can only be seen in option D. Isobars should not be confused with isotopes, which share the same atomic number, and therefore belong to the same chemical element, but have varying mass numbers.
Q155. Electrons are emitted in the production of X-rays by the process of:
- A. Conduction
- B. Convection
- C. Thermionic emission✓
- D. None of the above
Explanation: Electrons are emitted in the production of X-rays by heating a filament and this process is called thermionic emission and electrons themselves are called thermions.
Why the other options are wrong
- A. This option is incorrect. Conduction is the transfer of internal energy by microscopic collisions of particles and movement of electrons within a body.
- B. This option is incorrect. Convection is the transfer of heat from one place to another due to the movement of fluid.
- D. This is incorrect. Electrons are emitted in the production of X-rays by heating a filament and this process is called thermionic emission and electrons themselves are called thermions.
Q156. Due to the magnetic force, a positively charged particle executes uniform circular motion within a uniform magnetic field ‘B’. If the charge is ‘q’ and radius of its path is r, which of the expressions gives the magnitude of the particle’s linear momentum:
- A. qBr✓
- B. qB/r
- C. q/(Br)
- D. B
Explanation: Here the centripetal force will balance the magnetic force. So, mv2/r=qvB or mv=qBr Thus, linear momentum, p=mv=qBr
Why the other options are wrong
- B. This is not correct formula.In this case magnetic force = centripetal force Hence, Bqv = mv2/r where v is cancelled on both sides of the equation Bq = mv/r where mv= p Bq = p/r P = Bqr (hence option A is the correct option)
- C. This is not correct formulaIn this case magnetic force = centripetal force Hence, Bqv = mv2/r where v is cancelled on both sides of the equation Bq = mv/r where mv= p Bq = p/r P = Bqr (hence option A is the correct option)
- D. This is not correct formulaIn this case magnetic force = centripetal force Hence, Bqv = mv2/r where v is cancelled on both sides of the equation Bq = mv/r where mv= p Bq = p/r P = Bqr (hence option A is the correct option)
Q157. The half-life of 14C is approximately 5,730 years, while the half-life of 12C is essentially infinite. If the ratio of 14Cto 12C in a certain sample is 25% less than the normal ratio in nature, how old is the sample?
- A. Less than 5,730 years✓
- B. Approximately 5,730 years
- C. Significantly greater than 5,730 years, but less than 11,460 years
- D. Approximately 11,460 years
- E. Approximately 15,730 years
Explanation: Because the half-life of carbon-12 is essentially infinite, a 25 percent decrease in the ratio of carbon-14 to carbon-12 means the same as a 25 percent decrease in the amount of carbon-14. If less than half of the carbon-14 has deteriorated, then less than one half-life has elapsed. Therefore, the sample is less than 5730 years old. Be careful with the wording here—the question states that the ratio is 25% less than the ratio in nature, not 25% of the ratio in nature, which would correspond to choice (D).
Why the other options are wrong
- B. Because the half-life of carbon-12 is essentially infinite, a 25 percent decrease in the ratio of carbon-14 to carbon-12 means the same as a 25 percent decrease in the amount of carbon-14. If less than half of the carbon-14 has deteriorated, then less than one half-life has elapsed. Therefore, the sample is less than 5730 years old. Be careful with the wording here—the question states that the ratio is 25% less than the ratio in nature, not 25% of the ratio in nature, which would correspond to choice (D). C14:C12 is >25% more than the normal ratio in nature. So it would mean the age of C14= >5730 years as the decayed mass is lesser than the standard of ½ decayed atoms every half-life.Thus, only Option A is correct.
- C. Because the half-life of carbon-12 is essentially infinite, a 25 percent decrease in the ratio of carbon-14 to carbon-12 means the same as a 25 percent decrease in the amount of carbon-14. If less than half of the carbon-14 has deteriorated, then less than one half-life has elapsed. Therefore, the sample is less than 5730 years old. Be careful with the wording here—the question states that the ratio is 25% less than the ratio in nature, not 25% of the ratio in nature, which would correspond to choice (D). C14:C12 is >25% more than the normal ratio in nature. So it would mean the age of C14= >5730 years as the decayed mass is lesser than the standard of ½ decayed atoms every half-life.Thus, only Option A is correct.
- D. Because the half-life of carbon-12 is essentially infinite, a 25 percent decrease in the ratio of carbon-14 to carbon-12 means the same as a 25 percent decrease in the amount of carbon-14. If less than half of the carbon-14 has deteriorated, then less than one half-life has elapsed. Therefore, the sample is less than 5730 years old. Be careful with the wording here—the question states that the ratio is 25% less than the ratio in nature, not 25% of the ratio in nature, which would correspond to choice (D). C14:C12 is >25% more than the normal ratio in nature. So it would mean the age of C14= >5730 years as the decayed mass is lesser than the standard of ½ decayed atoms every half-life.Thus, only Option A is correct.
- E. Because the half-life of carbon-12 is essentially infinite, a 25 percent decrease in the ratio of carbon-14 to carbon-12 means the same as a 25 percent decrease in the amount of carbon-14. If less than half of the carbon-14 has deteriorated, then less than one half-life has elapsed. Therefore, the sample is less than 5730 years old. Be careful with the wording here—the question states that the ratio is 25% less than the ratio in nature, not 25% of the ratio in nature, which would correspond to choice (D). C14:C12 is >25% more than the normal ratio in nature. So it would mean the age of C14= >5730 years as the decayed mass is lesser than the standard of ½ decayed atoms every half-life.Thus, only Option A is correct.
Q158. Which of the following statements is not consistent with Bohr's set of postulates regarding the hydrogen atom model with regard to the emission and absorption of light?
- A. Energy levels of the electrons are stable and discrete.
- B. An electron emits or absorbs radiation only when making a transition from one energy level to another.
- C. To jump from lower energy to higher energy, an electron must absorb a photon of precisely the right frequency such that the photon's energy equals the energy difference between the two orbits.
- D. To jump from a higher energy to a lower energy, an electron' absorbs a photon of frequency such that photon's energy is exactly the energy difference between the two orbits.✓
- E. None of the above
Explanation: Bohr's model describes that energy levels are quantized and electrons transition between these levels by absorbing or emitting photons. Option D is incorrect because it incorrectly states that an electron absorbs a photon when moving from a higher to a lower energy level, which contradicts Bohr's model. Instead, the electron emits a photon in such transitions. Options A, B, and C are consistent with the model as they correctly describe the stability of energy levels, the conditions for emission and absorption of radiation, and the requirement for precise photon energy during transitions.
Why the other options are wrong
- A. This is correct as the energy revolving in an orbit will always has an specific amount of energy in that orbit.
- B. This is correct assumption as electron in lower orbit has low energy and if it need to jump to higher orbit it will need to absorb an specific amount of energy.
- E. This is incorrect because one of the options does not align with Bohr's postulates.
Q159. Sodium nucleus consists of 11 protons and 12 neutrons. The conventional symbol of this nucleus is?
- A. 11Na11
- B. 12Na12
- C. 11Na23✓
- D. 12Na23
- E. 12Na11
Explanation: The conventional symbol of the element contains the proton number(number of protons) and the mass number(proton number+number of neutrons), which is 11 and (11+12=)23, in this case. So the correct option is C. The conventional symbol of a sodium nucleus is 11Na23.
Why the other options are wrong
- A. As per the explanation, this option is incorrect.
- B. As per the explanation, this option is incorrect.
- D. As per the explanation, this option is incorrect.
- E. As per the explanation, this option is incorrect.
Q160. In free states, the mass of the nucleus is always:
- A. Greater than the mass of its constituents
- B. Equal to the mass of its constituents
- C. Less than the mass of its constituents✓
- D. Far greater than the mass of its constituents
Explanation: The correct answer is that the mass of the nucleus is less than the mass of its constituents. This is due to the mass defect, where some mass is converted into binding energy. Binding energy is crucial as it holds the nucleus together. The other options are incorrect because they do not account for the mass defect and the role of binding energy in nuclear physics.
Why the other options are wrong
- A. According to nuclear physics, when a nucleus is formed, there can be a release of energy due to the conversion of mass into binding energy. This is governed by Einstein's famous equation E=mc^2, where E represents energy, m represents mass, and c represents the speed of light. The mass of the nucleus is slightly less than the sum of the masses of its individual constituents (protons and neutrons). Therefore, the mass of the nucleus is not greater than the mass of its constituents. Hence, option (a) is not correct.
- B. According to the principles of mass defect and binding energy, the mass of the nucleus is slightly less than the sum of the masses of its individual constituents. This is because some mass is converted into binding energy during the formation of the nucleus. The mass defect is the difference between the mass of the nucleus and the sum of the masses of its constituents. However, for practical purposes, the difference in mass is extremely small and often not considered significant. Therefore, the mass of the nucleus is considered to be unequal to the mass of its constituents. Hence, option (b) is incorrect.
- D. The mass of the nucleus is not far greater than the mass of its constituents. In fact, the mass of the nucleus is slightly less than the sum of the masses of its individual constituents. This is due to the conversion of mass into binding energy. Hence, option (d) is not correct.
Q161. For the first time in 1914, Henry Moseley used X-rays for the determination of:
- A. Atomic Number✓
- B. Atomic Mass
- C. Molecular Mass
- D. Equivalent mass
Explanation: In 1914, he observed and measured the X-ray spectra of various chemical elements using diffraction in crystals. Through this, he discovered a systematic relation between wavelength and atomic number. This discovery is now known as Moseley's Law. He found that certain lines in the X-ray spectrum of elements move by the same amount each time when we increase the atomic number by one.
Why the other options are wrong
- B. Atomic mass is the mass of an atom, typically measured in atomic mass units (amu). While X-ray spectroscopy can provide valuable information about the electronic structure and atomic properties of elements, it is not primarily used for determining atomic mass. Atomic mass is usually determined through techniques such as mass spectrometry or by analysing the isotopic composition of elements.
- C. Molecular mass refers to the mass of a molecule, which is the sum of the masses of the atoms in the molecule. X-ray spectroscopy is not typically used for determining molecular mass. Instead, molecular mass is often calculated based on the atomic masses of the constituent atoms in a molecule.
- D. Equivalent mass is a concept primarily used in the context of chemical reactions and stoichiometry, representing the mass of a substance that reacts with or is equivalent to one mole of hydrogen ions (H⁺) in a chemical reaction. X-ray spectroscopy is not directly related to determining equivalent mass. Equivalent mass is typically calculated based on the stoichiometry of a reaction and the molar masses of the substances involved.
Q162. Ohm time’s farad is equivalent to:
- A. Time✓
- B. Charge
- C. Distance
- D. Capacitor
Explanation: The formula for charging and discharging capacitor is RC=T R: resistance C: capacitance T: time for charging/ discharging
Q163. e/m for an electron is _, when the charge of an electron is 1.6 x 10-19C and mass of electron is 9.1 x 10-31kg.
- A. 1.67 x 10-11 C/kg
- B. 1.76 x 1011 C/kg✓
- C. 16.7 x 1011 C/kg
- D. 1.76 x 10-11 C/kg
Explanation: The specific charge is being asked here. The formula for that is:Q/m {where Q is the charge of the electron and m is the mass.}Substitute Q= 1.6x10-19 and m=9.1x10-31 into the equation:=1.6x10-19/9.1x10-31= 1.76x1011
Why the other options are wrong
- A. Incorrect as per formula
- C. Incorrect as per formula
- D. Incorrect as per formula
Q164. If the velocity of a charged particle and magnetic field are at a fixed angle that is not 90 degrees, then the path will be:
- A. Circular
- B. Straight line
- C. Spherical
- D. Helical✓
Explanation: Force is given by F = qvBsinθ, where F, q, v and B are the force, charge on particle, velocity of particle and magnetic field strength respectively. θ is the angle between v and B.If θ = 0 or 180, there is no force on the particle and it continues to move with uniform velocity.If θ = 90, the force acting on the particle is maximum and perpendicular to the path of the particle. (force acts as a centripetal force and the particle moves along a circular path)When θ has a value other than 0, 90 or 180, the direction of velocity is either perpendicular or parallel to B. If the component of velocity is parallel to B it will not be affected by the magnetic field. However if the component of velocity is perpendicular to B it will be subject to a force of the magnetic field which would result in uniform circular motion. Hence the particle would have a component along a straight line as well as a circular component. Therefore the path would be in the form of a helix. And so option D is correct.
Why the other options are wrong
- A. The path will be circular when the angle between velocity of a charged particle and magnetic field is 90°. Hence, this option is incorrect.
- B. A charged particle moves in a straight line when the angle between the velocity of the particle and magnetic field is 0° or 180°. It is not complimenting the given situation. Hence, this option is incorrect.
- C. A spherical path is not observed when a charged particle interacts with a magnetic field. Hence, this option is incorrect.
Q165. What is the SI Unit of EMF?
- A. Ohm
- B. Ampere
- C. Volt✓
- D. Newton
Explanation: This is a standard answer. The SI unit of EMF is Volts. Volts is also the SI unit of Potential difference. 1 Volt = Joule/Coulomb
Why the other options are wrong
- A. Ohm is not the SI Unit of EMF. So, it is not correct.It is SI unit of resistance.
- B. Ampere is not the SI Unit of EMF. So, it is not correct. It is an SI unit of current.
- D. Newton is not the SI Unit of EMF. So, it is not correct. It is an S.I unit of Force
Q166. Magnetic field lines have a property that lines are _.
- A. Non intersecting✓
- B. Intersect near south pole
- C. Intersect near north pole
- D. Intersect everywhere
Explanation: The magnetic field lines do not intersect, under normal conditions, without any external influences.
Why the other options are wrong
- B. This option suggests that magnetic field lines intersect near the south pole of a magnet. However, this is not correct. Magnetic field lines emerge from the north pole of a magnet and re-enter at the south pole, forming closed loops. They do not intersect each other at the south pole or anywhere else.
- C. This option suggests that magnetic field lines intersect near the north pole of a magnet. Similar to option (b), this is not correct. Magnetic field lines do not intersect each other at the north pole or anywhere else. Instead, they emerge from the north pole and re-enter at the south pole.
- D. This option suggests that magnetic field lines intersect at every point around a magnet. However, this is not correct. Magnetic field lines never intersect each other. They always form closed loops, and they do not cross.
Q167. When electron series terminates on the 4th orbit _ series is obtained.
- A. Balmer
- B. Pfund
- C. Paschen
- D. None of these options is correct✓
Explanation: Bracket series is obtained when all transition of electron terminates on 4th orbit.Option A; balmer series is obtained when all transition of electron terminates on 2nd orbit.Option B: pfund series is obtained when all transition of electron terminates on 5th orbit.Option C: paschen series is obtained when all transition of electron terminates on 3rd orbit.
Why the other options are wrong
- A. Balmer series is obtained when all transition of electron terminates on 2nd orbit
- B. Pfund series is obtained when all transition of electron terminates on 5th orbit.
- C. Paschen series is obtained when all transition of electron terminates on 3rd orbit
Q168. The series limit for the Balmer series of hydrogen spectrum occurs at 3664 A°. Calculate Ionization energy of hydrogen atom.
- A. 21.7 x 10-19 J
- B. 6.626 x 10-34 J
- C. 5.425 x 10-19 J✓
- D. 3664 x 10-10 J
- E. 3 x 108 J
Explanation: The Balmer emission lines correspond to transitions down to the level for which n=2. Given series is the Balmer series, so n1=2 and n2=∞ λ=3664A° Change in ionisation energy= Einfinity−E2= −E2 -E2 =-hc/λ -E2=6.626×10-34 ×3×10⁸/(3664x10-10) -E2 =−5.42×10−19 J so option C is the only correct option.
Why the other options are wrong
- A. The Balmer emission lines correspond to transitions down to the level for which n=2. Given series is the Balmer series, so n1=2 and n2=∞ λ=3664A° Change in ionisation energy= Einfinity−E2= −E2 -E2 =-hc/λ -E2=6.626×10-34 ×3×10⁸/(3664x10-10) -E2 =−5.42×10−19 J
- B. The Balmer emission lines correspond to transitions down to the level for which n=2. Given series is the Balmer series, so n1=2 and n2=∞ λ=3664A° Change in ionisation energy= Einfinity−E2= −E2 -E2 =-hc/λ -E2=6.626×10-34 ×3×10⁸/(3664x10-10) -E2 =−5.42×10−19 J
- D. The Balmer emission lines correspond to transitions down to the level for which n=2. Given series is the Balmer series, so n1=2 and n2=∞ λ=3664A° Change in ionisation energy= Einfinity−E2= −E2 -E2 =-hc/λ -E2=6.626×10-34 ×3×10⁸/(3664x10-10) -E2 =−5.42×10−19 J
- E. The Balmer emission lines correspond to transitions down to the level for which n=2. Given series is the Balmer series, so n1=2 and n2=∞ λ=3664A° Change in ionisation energy= Einfinity−E2= −E2 -E2 =-hc/λ -E2=6.626×10-34 ×3×10⁸/(3664x10-10) -E2 =−5.42×10−19 J
Q169. The phenomena in which certain metals emit electrons when exposed to high-frequency light is known as?
- A. Photoelectric Effect✓
- B. Compton’s Effect
- C. Henry's Effect
- D. Principle of Relativity
- E. Coulomb's Law
Explanation: When a metal surface is exposed to a monochromatic electromagnetic wave of sufficiently short wavelength (or equivalently, above a threshold frequency), the incident radiation is absorbed and the exposed surface emits electrons. This phenomenon is known as the photoelectric effect.
Why the other options are wrong
- B. Compton's effect, also known as Compton scattering, is a phenomenon in which X-ray or gamma-ray photons undergo a scattering interaction with electrons. This effect demonstrates that photons can behave as particles and exhibit characteristics of both particles and waves. It is not directly related to the emission of electrons by metals due to high-frequency light.
- C. There is no widely recognized scientific phenomenon known as "Henry's Effect." It does not pertain to the emission of electrons by metals due to high-frequency light.
- D. The principle of relativity is a fundamental concept in physics introduced by Albert Einstein. It states that the laws of physics are the same in all inertial reference frames. It does not directly relate to the emission of electrons by metals due to high-frequency light.
- E. Coulomb's Law describes the electrostatic interaction between charged particles. It states that the force between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. While Coulomb's Law is an important principle in electromagnetism, it does not explain the emission of electrons by metals due to high-frequency light.
Q170. Minimum frequency below which no electrons are emitted from the metal surface is called _ frequency.
- A. Minimum
- B. Angular
- C. Maximum
- D. Threshold✓
Explanation: The correct answer is the 'threshold frequency', which is the minimum frequency of electromagnetic radiation necessary to dislodge electrons from the surface of a metal. This concept is fundamental to the photoelectric effect, where no electrons are emitted if the incident light's frequency is below this threshold, regardless of its intensity. The other options, 'minimum', 'angular', and 'maximum', either lack specificity or pertain to different contexts within physics.
Why the other options are wrong
- A. Option A is incorrect because 'minimum frequency' is a vague term and does not specifically refer to the frequency needed to cause photoelectric emission.
- B. Option B is incorrect because 'angular frequency' relates to rotational systems and is not used in the context of photoelectric emission in metals.
- C. Option C is incorrect because 'maximum frequency' would imply an upper limit, which is not relevant to the emission of electrons from a metal surface.
Q171. Suppose in a certain language MADRAS is coded as NBESBT. Then BOMBAY is coded in that language as:
- A. CPNCBZ✓
- B. CPNCBX
- C. CPOCBZ
- D. CQOCBZ
Explanation: As we can see the code exchanges each letter with the letter that follows it, so A becomes B, B becomes C, C becomes D, and so on. We will do this for each letter in Bombay and will arrive to: CPNCBZ.
Why the other options are wrong
- B. As we can see the code exchanges each letter with the letter that follows it, so A becomes B, B becomes C, C becomes D, and so on. We will do this for each letter in Bombay and will arrive to: CPNCBZ.
- C. As we can see the code exchanges each letter with the letter that follows it, so A becomes B, B becomes C, C becomes D, and so on. We will do this for each letter in Bombay and will arrive to: CPNCBZ.
- D. As we can see the code exchanges each letter with the letter that follows it, so A becomes B, B becomes C, C becomes D, and so on. We will do this for each letter in Bombay and will arrive to: CPNCBZ.
Q172. Choose the odd one out:
- A. Eagle
- B. Cloud
- C. Squirrel✓
- D. Plane
Explanation: All Options excluding C refers to animals and objects that are involved in flying. Squirrel is the only option that is present on the ground.
Why the other options are wrong
- A. All Options excluding C refers to animals and objects that are involved in flying. Squirrel is the only option that is present on the ground.
- B. All Options excluding C refers to animals and objects that are involved in flying. Squirrel is the only option that is present on the ground.
- D. All Options excluding C refers to animals and objects that are involved in flying. Squirrel is the only option that is present on the ground.
Q173. Statements: 1. Blueberries cost more than strawberries. 2. Blueberries cost less than raspberries. 3. Raspberries cost more than strawberries and blueberries. If the first two statements are true, the third statement is:
- A. True✓
- B. False
- C. Uncertain
- D. None of these
Explanation: From the first two statements, we can establish the cost order: Raspberries > Blueberries > Strawberries. This directly confirms that raspberries cost more than both of the other fruits, making the third statement true.
Why the other options are wrong
- B. The third statement about raspberries being the most expensive is correct, making this option incorrect.
- C. The third statement about raspberries being the most expensive is correct, making this option incorrect.
- D. The third statement about raspberries being the most expensive is correct, making this option incorrect.
Q174. The Emporium Mall has more stores than the Pakages Mall.The Amanah Mall has fewer stores than the Pakages Mall.The Emporium Mall has more stores than the Amanah Mall.If the first two statements are true, the third statement is
- A. True✓
- B. FALSE
- C. Uncertain
- D. None of these
Explanation: ExplanationFrom the first two statements, you know that the Emporium mall has the most stores, so the Emporium Mall would have more stores than the packages Mall.
Why the other options are wrong
- B. From the first two statements, you know that the Emporium mall has the most stores, so the Emporium Mall would have more stores than the packages Mall.
- C. From the first two statements, you know that the Emporium mall has the most stores, so the Emporium Mall would have more stores than the packages Mall.
- D. From the first two statements, you know that the Emporium mall has the most stores, so the Emporium Mall would have more stores than the packages Mall.
Q175. Statement:I. The school authority has asked the FSC students to attend special classes to be conducted on Sundays.II. The parents of the FSC students have withdrawn their wards from attending private tuitions conducted on Sundays.
- A. Statement I is the cause and statement II is its effect.✓
- B. Statement II is the cause and statement I is its effect
- C. Both the statements I and II are independent causes
- D. Both the statements I and II are effects of some common cause
Explanation: The reason why parents have withdrawn their wards from attending private tuitions on Sunday is that the students had to attend special classes conducted by the school on Sunday. If there were no classes conducted by the school on Sunday then the parents wouldn’t have had to make their kids leave their Sunday tuitions.
Why the other options are wrong
- B. The two statements are unrelated and independent of each other. There is no clear cause-and-effect relationship between them based on the information provided.Statement I:"The school authority has asked the FSC students to attend special classes to be conducted on Sundays."This statement indicates that the school authority has scheduled special classes for FSC students on Sundays. It does not provide any information about why these special classes are being conducted or how it relates to private tuitions.Statement II:"The parents of the FSC students have withdrawn their wards from attending private tuitions conducted on Sundays."This statement states that the parents of FSC students have decided to stop sending their children to private tuitions that were previously conducted on Sundays. However, it does not mention anything about the reason for this decision or whether it is related to the special classes organized by the school.Without additional information or context, we cannot determine any direct connection between the school's special classes and the parents' decision to withdraw their children from private tuitions on Sundays. The two statements might be independent events or have separate reasons behind them.
- C. The two statements are unrelated and independent of each other. There is no clear cause-and-effect relationship between them based on the information provided.Statement I:"The school authority has asked the FSC students to attend special classes to be conducted on Sundays."This statement indicates that the school authority has scheduled special classes for FSC students on Sundays. It does not provide any information about why these special classes are being conducted or how it relates to private tuitions.Statement II:"The parents of the FSC students have withdrawn their wards from attending private tuitions conducted on Sundays."This statement states that the parents of FSC students have decided to stop sending their children to private tuitions that were previously conducted on Sundays. However, it does not mention anything about the reason for this decision or whether it is related to the special classes organized by the school.Without additional information or context, we cannot determine any direct connection between the school's special classes and the parents' decision to withdraw their children from private tuitions on Sundays. The two statements might be independent events or have separate reasons behind them.
- D. The two statements are unrelated and independent of each other. There is no clear cause-and-effect relationship between them based on the information provided.Statement I:"The school authority has asked the FSC students to attend special classes to be conducted on Sundays."This statement indicates that the school authority has scheduled special classes for FSC students on Sundays. It does not provide any information about why these special classes are being conducted or how it relates to private tuitions.Statement II:"The parents of the FSC students have withdrawn their wards from attending private tuitions conducted on Sundays."This statement states that the parents of FSC students have decided to stop sending their children to private tuitions that were previously conducted on Sundays. However, it does not mention anything about the reason for this decision or whether it is related to the special classes organized by the school.Without additional information or context, we cannot determine any direct connection between the school's special classes and the parents' decision to withdraw their children from private tuitions on Sundays. The two statements might be independent events or have separate reasons behind them.
Q176. From the following which word does not belong to the others:
- A. Index
- B. Book✓
- C. Glossary
- D. Chapter
Explanation: An index, glossary, and chapter are all parts of a book. Option A does not belong because the book is the whole, not a part.
Why the other options are wrong
- A. An index, glossary, and chapter are all parts of a book. Option A does not belong because the book is the whole, not a part.
- C. An index, glossary, and chapter are all parts of a book. Option A does not belong because the book is the whole, not a part.
- D. An index, glossary, and chapter are all parts of a book. Option A does not belong because the book is the whole, not a part.
Q177. How many rectangle and square are there in the given figure?
- A. 15✓
- B. 16
- C. 25
- D. 13
Explanation: This is the correct total count of rectangles and squares found by methodically analyzing each part of the figure.
Why the other options are wrong
- B. This count includes an extra shape. Closely review the figure to ensure that each shape is counted once.
- C. This number is too high, likely due to counting errors such as double-counting or including nonexistent shapes.
- D. This count is too low, indicating that some rectangles or squares may have been overlooked.
Q178. Directions: In the following question, a number sequence is given with one term missing. Choose the correct term that will continue the same pattern and replace the question mark in the given sequence.1,2,4,7,?,16
- A. 8
- B. 11✓
- C. 9
- D. 13
Explanation: To solve the sequence 1, 2, 4, 7, ?, 16, observe the differences between consecutive terms: +1, +2, +3. The pattern indicates that the differences are increasing sequentially by 1. Thus, the next difference should be +4. Adding 4 to 7 results in 11, completing the sequence as 1, 2, 4, 7, 11, 16. Therefore, the correct answer is 11. The other options 8, 9, and 13 do not follow this established pattern, making them incorrect choices.
Why the other options are wrong
- A. The differences between consecutive terms do not follow a pattern that leads to 8. Hence, 8 is not the correct number.
- C. Although 9 is a possible number, the difference between 7 and 9 is 2, which does not align with the established pattern of increasing differences. Therefore, 9 is not the correct choice.
- D. Choosing 13 results in a difference of 6 from the previous term 7, which disrupts the increasing pattern of differences. Hence, 13 is incorrect.
Q179. Find the missing symbol: *, @, *, @, *, ?
- A. *
- B. @✓
- C. $
- D. &
Explanation: The sequence alternates between '*' and '@'. Observing the pattern: *, @, *, @, *, ?, the missing symbol should continue this alternation. After '*', the next symbol should be '@', making Option B correct. Options A, C, and D do not follow the observed pattern of alternating between '*' and '@'.
Why the other options are wrong
- A. Choosing this would imply that the pattern repeats the same symbol consecutively, which is not observed in the series.
- C. This symbol does not appear in the given sequence, and thus does not fit into the observed pattern.
- D. This symbol is not part of the initial sequence and does not match the alternating pattern.
More Federal / FMDC Solved Papers
Biology
Federal Mdcat 2022
200 solved MCQs
Biology
Federal Mdcat 2023
200 solved MCQs
Chemistry
Federal Mdcat 2025
180 solved MCQs
Chemistry
Federal Mdcat Mock Paper 1
195 solved MCQs
Chemistry
Federal Mdcat Mock Paper 2
199 solved MCQs
Chemistry
Federal Mdcat Mock Paper 3
179 solved MCQs
Chemistry
Federal Mdcat Mock Paper 3
199 solved MCQs
Biology
Federal Mdcat Mock Paper 4
179 solved MCQs
Chemistry
Federal Mdcat Mock Paper 4
199 solved MCQs